help-10

[rigid flare]

Yes, I'm good with it

[astral ivy]

so what are the "concepts with circles learned in this unit"

like what did u learn with circles

[rigid flare]

We labeled the lines intersecting the circle.. like secant, tangent, etc..

We also measured circles

[astral ivy]

oh

I do graphic design

this'll be cake

ok what do you wanna do, this logo could be literally anything

let's do a circle representing the globe, and maybe the secant line or chord could represent something else idk

[rigid flare]

Maybe an NGO for mental health? Or whats like going on rn

[astral ivy]

we could do that yeah

hmm

[rigid flare]

Any suggestions for the graphic design?

[astral ivy]

well

ok hmm

this has tangents and secants

and the lines resemble a sash going across the earth, you could say it's "uniting everyone" or something lol

@rigid flare

[obtuse pebble]

@rigid flare Has your question been resolved?

[rigid flare]

Thank you! This is a smart and good idea

And srry I was afk for a bit

[astral ivy]

np

there's the png if u wanna edit it or smth

[rigid flare]

Thank you so much once againn

[obtuse pebble]

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[timid silo]

is my solution correct?

the question ask wether to if the equation diverges or converges

[obtuse pebble]

@timid silo Has your question been resolved?

[knotty nebula]

Isn’t that a contradiction since you’re saying that when n= n you get log(1) which equals 0 thus convergent

However it’s asking if your summation is convergent or divergent whereas you just took a particular case of n

Use Method of differences

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

ahh alright thanks

[obtuse pebble]

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[hushed birch]

what am i supposed to do here?

[obtuse pebble]

@hushed birch Has your question been resolved?

[alpine raven]

find the base in which the numbers are written

I guess it's what they mean

[hushed birch]

so this a and 2a is not multiplication?

what do you mean by base

[sudden fox]

uh

let's say

binary

thats base 2

decimal

thats base 10

etc.

[hushed birch]

oh i got you

thanks

.close

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[wanton dagger]

I don’t get how to proceed this question.

[vernal sky]

since they are similar, the ratio of their sides are the same

length/width is the same for both

with that you can solve the question

[wanton dagger]

How would I set the ratios up?

[vernal sky]

length/width

[wanton dagger]

Ok

X:1

Is that one ratio?

[vernal sky]

yes

[wanton dagger]

What would the other be? I’m confused in that one

[vernal sky]

the smaller paper

it is just half of the big paper

and you have the dimensions of the big paper

[wanton dagger]

X:1=x/2:1

Is that the ratio?

[vernal sky]

partially wrong

both has to be either lenght/width or width/length

dont swap their positions

[wanton dagger]

Oh ok

But for the second ratio x/2 is the length

[vernal sky]

length as in the longer side

[wanton dagger]

Yes

And 1 for the width?

[vernal sky]

longer side of smaller paper isnt x/2

[wanton dagger]

Oh

Mmm. I’m confused about what is the length of the longer side in the small paper

[vernal sky]

look at the original paper

[wanton dagger]

Length of the original paper is x

[vernal sky]

smaller paper is half of original

[wanton dagger]

X/2

That’s what I think is the length

[vernal sky]

its 1

the length of the smaller paper is just the width of the bigger one since its not changed

[wanton dagger]

I’m confused a little here

[vernal sky]

just rotate the paper

[wanton dagger]

Yh ok I got it

So now we have x:1=1:x/2

Now what would I do?

[royal basin]

x/1 = 1/(x/2)

[vernal sky]

^

[wanton dagger]

Wait why is it divide

[vernal sky]

their ratios are the same

ratio of x to 1 is the same as 1 to x/2

[wanton dagger]

And also a ratio compares two quantities by division

So probably that’s why

[vernal sky]

yes

[wanton dagger]

Ok right I got it thanks

[vernal sky]

good job

[wanton dagger]

.close

[obtuse pebble]

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[unkempt jewel]

I've managed to show the relationship but am stuck on finding the second derivative

[unkempt jewel]

First I differentiated both sides w.r.t x but I couldn't simplify the right side

then I rewrote the equation in this form and tried taking the derivative w.r.t y but it ended up being super messy so I stopped

[obtuse pebble]

@unkempt jewel Has your question been resolved?

[unkempt jewel]

<@&286206848099549185>

[robust sleet]

so y=x

dy/dx=1

2x(dy/dx)=2x

or 2e^(2t)

dy/dt= e^(2t)*2

which are same

wouldnt the second derivative of y in respect to x be 0?

[unkempt jewel]

sorry but could you explain where you got this from?

[robust sleet]

doesnt variable y depend on x means y=x?

[unkempt jewel]

no the question deliberately avoids giving you y in terms of x

its saying y is a function of x

[obtuse pebble]

@unkempt jewel Has your question been resolved?

[obtuse pebble]

@unkempt jewel Has your question been resolved?

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[sour lantern]

what is $max[f(x)]$ for $x \in [0;1]$?

[warm shale]

Erzis エルジス

[uneven hamlet]

Don’t you have the answer from the plot?

[lusty cedar]

where's problem mate?

[sour lantern]

well yes, I'd say 0 and 1

but let me dig deeper

okay I'm just stupid I thought the wrong way

nvm guys

.close

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[rich spear]

Can some1 help

[rich spear]

so

[drowsy girder]

Ask

[rich spear]

so

x^2-6x+9

i need to roots

and how

not tryna bug but i need it like right now

[spiral maple]

why the urgency?

[rich spear]

well its kinda for homework and i have to out and eat with family

like soon

thats why

[spiral maple]

If it's homework, just do it when you get home

[rich spear]

but the problem is after i eat im meeting at familys house since its my cousin bday and ima get home late

and prob fall asleep

[spiral maple]

If it's only 1 question, do it in the morning then

[rich spear]

k

then

[spiral maple]

But sure, if you're so insistent on getting it done asap, what have you tried?

[rich spear]

ive tried putting the points in the equation

but ive got nothing

like

idk

now

[lucid flame]

do you know how to factor polynomials

[spiral maple]

"the points"

what points?

You've not listed any points

and you also haven't given an equation that would warrant plugging in points

[obtuse pebble]

@rich spear Has your question been resolved?

[obtuse pebble]

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[hushed swift]

How would I do this? And what topic is this?

[lucid flame]

similar triangles

[hushed swift]

I did that and got 20cm^2

But that is wrong

[teal prawn]

if two triangles are similar the ratio of their areas is equal to the square of the ratio of their sides

[hushed swift]

Yes I know.

But that is wrong.

[teal prawn]

then apply it

[hushed swift]

Look.

It is 4 marks but you only get 1 for that.

[teal prawn]

and whats the right answer?

[hushed swift]

The mark scheme doesn't make sense to me.

[teal prawn]

hmm well I dont understand the mark scheme

[empty hull]

i understand it but i cant explain it lol

[teal prawn]

but I can tell you that the answer is indeed 50

[empty hull]

the scale factor is 5/2

[teal prawn]

well what did you get the ratio of AB:AC as?

[empty hull]

and because youre scaling in 2 dimensions its (5/2)^2 is the best way i can explain it

[hushed swift]

2:5.

[teal prawn]

yeah so you square it and get 4/25 = 8/x right?

and you solve for x

[hushed swift]

Yeah

[teal prawn]

how are you getting 20?

[hushed swift]

Then what do you do?

[teal prawn]

well thats your answer

[hushed swift]

25x=1/2

[teal prawn]

The area of ACD

[hushed swift]

x=12.5?

[teal prawn]

uhh

no

[hushed swift]

That doesn't equal 50.

[teal prawn]

youre solving it wrong

its a simple equation ..

[hushed swift]

4x=200

x=50

[teal prawn]

yes there you go

[hushed swift]

Sorry I read it the wrong way around

[teal prawn]

ahk

[obtuse pebble]

@hushed swift Has your question been resolved?

[obtuse pebble]

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[wispy plinth]

Ho there

[wispy plinth]

Hi

So I need help with questions d

[lucid flame]

we can't see the problem

[wispy plinth]

The equation of the right bisector is 8/4x - 12

[wispy plinth]

How do I found those 2 points

Where the circle meets with the bisector

[lucid flame]

yeah, about that

[wispy plinth]

That's what I'm asking and I'm doing question 3 d

[high lily]

we can't see the problem

[lucid flame]

can't see

[wispy plinth]

Oh is it loading

??

[lucid flame]

the top

[high lily]

half the info is cut off

[wispy plinth]

Oops

I didn't mean to send that

[wispy plinth]

Oh okay

[wispy plinth]

Here's the whole thing

^

[high lily]

,rotate

[wispy plinth]

I am doing d btw

I have solved for everything else

[lucid flame]

so whats the answer to c?

[wispy plinth]

Y =8/4x - 12

[high lily]

how are you getting that?

[lucid flame]

you mean (8/4)x?

[wispy plinth]

Yea

[lucid flame]

so 2x

[wispy plinth]

Oh help

I forgot to simplify

[high lily]

where's -12 coming from

[wispy plinth]

Wdym how did get -12

Oh

[high lily]

mmmk

you can substitute this into the equation of the circle

and then solve for x

[wispy plinth]

Uh how

😭

[high lily]

how would you usually find where two curves intersect?

[wispy plinth]

Oh so like x^2 + ((8/4x) - 12)^2 = 100

[wispy plinth]

Uh substitution

Or elimination

[high lily]

1 sec

[wispy plinth]

What's a gradient

😭

Mb

[high lily]

you didn't find the gradient of AB properly

slope

[wispy plinth]

Wait i can't see my messages

Wat

😭

Hold on

Brb

[high lily]

you mixed up your x and y coordinates

[wispy plinth]

Er how

[high lily]

literally as I described

the 2 and 1 should also be subscripts

$x_1,x_2,y_1,y_2$

[warm shale]

ℝamonov

[wispy plinth]

They are i just wrote the subscription at t5he top

I'm not using it as an exponent

[high lily]

what's the y coordinate of (6,8)

[wispy plinth]

8

[high lily]

what's the y coordinate of (10,0)

[wispy plinth]

0

[high lily]

same questions for the x coordinates

[wispy plinth]

6 and 10

[high lily]

hence how should you have been using those values in the slope formula

[wispy plinth]

Whats wrong with switching up b and then a

[high lily]

They are i just wrote the subscription at t5he top
subscripts mean that you should be writing them at the bottom

if your write them at the top they are superscripts

[wispy plinth]

Okay

[high lily]

Whats wrong with switching up b and then a
wdym

[wispy plinth]

Like whats the difference of x1 - x2 was 10-6 or 6-10

Compared with the rest of the formula

[high lily]

which point you set as 1 or 2 doesn't really matter

[wispy plinth]

OH

[high lily]

what does matter is that you are using the correct values

[wispy plinth]

Oh so this is not about how I got th answer just the way i wrote in the expression

[high lily]

and I don't want to asking you what the x,y coordinates are again

there are issues with both

[wispy plinth]

Oops continue

[high lily]

and I don't want to ask you what the x,y coordinates are again

[wispy plinth]

Got it

[high lily]

set one point as point 1, the other as point 2

[wispy plinth]

Okay

[high lily]

y_1 denotes the y coordinate of your first point

[wispy plinth]

Alr

[wispy plinth]

So that would be 6

[high lily]

how are you getting 6

[wispy plinth]

Because its an x value for a

😭

[high lily]

read what I'm asking

[wispy plinth]

Oh

[high lily]

did I ask you about the x-coord just now?

[wispy plinth]

Wait now I see what I did wrong lol

Brb

[wispy plinth]

Sorry so the slope was -8/4

[high lily]

the slope of your chord, yes.

[wispy plinth]

Yea

Okat so now that us fixed

U can rewrite my equation which is still y = 2x - 12

[high lily]

no

[wispy plinth]

Wdym no

[high lily]

your original slope was wrong, so you need to redo all the work after that

[wispy plinth]

Yea and I found the negative reciprocal of that slope

Which is 4/8

[high lily]

huh?

[wispy plinth]

Yea

[high lily]

4/8 isn't 2

[wispy plinth]

Yes

[high lily]

so where's

U can rewrite my equation which is still y = 2x - 12
coming from

[wispy plinth]

Oh

[obtuse pebble]

@wispy plinth Has your question been resolved?

[obtuse pebble]

@wispy plinth Has your question been resolved?

[obtuse pebble]

@wispy plinth Has your question been resolved?

[obtuse pebble]

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[delicate root]

For a corpus of 1 million documents of 100 words each, what is the maximum number of non-zero entries in the term-document matrix with 50,000 distinct terms?

The term document matrix looks something like this:

   1000000 
 5
 0
 0
 0
 0

Where each column is a document (1000000) and each row is a term (50000), if the term is in the document the cell value is 1, otherwise it is 0

Of the 100 million possible terms we have only 50000 terms, a reduction of 1/2000.
I would assume that this means that 1999/2000 of the entries are non-zero.

However the only acceptable answers are:

a. 5 000 000
b. 50 000 000 000
c. 1 000 000
d. 100 000 000

[delicate root]

All entries simply cannot be non-zero because the documents are only 100 terms and not 50000
But I still can't figure out how many entries are zero

If all entries were non-zero then b would be the correct answer.

Maybe given that each document can only match at most 100 terms that means that there is at most 100 000 000 non-zero entries?

<@&286206848099549185>

[delicate root]

The counter reasoning as to why the answer would not be d would be that each document cannot match 100 terms because that would mean we would have 100000000 terms instead of 50000, there is an overlap of terms that appear on more than 1 document

But I think that has to be wrong, it ultimately does not matter that there is a 95% term overlap in between the documents, because every column will match with 100 different terms

Can a helper please review my reasoning? thank you

[obtuse pebble]

@delicate root Has your question been resolved?

[obtuse pebble]

@delicate root Has your question been resolved?

[obtuse pebble]

@delicate root Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

@haughty maple Has your question been resolved?

[true rain]

So like

factor of a polynomial

p(x) = whatever = r(x)(x+a)^2

Obviously since it's a polynomial of degree 3 r(x) = (bx+c) for some b,c

So your job is to solve for b,c

it's saying it's non-unique, with 2 possible answers

[obtuse pebble]

@haughty maple Has your question been resolved?

[obtuse pebble]

@haughty maple Has your question been resolved?

[daring rock]

@haughty maple you still here?

[haughty maple]

I found the solution about an hour ago so am good now

[daring rock]

Oh okay

[hybrid gull]

@haughty maple .close

[royal basin]

.close

[obtuse pebble]

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[timid silo]

Can someone walk me through how to solve for X in the question

7.5= (x-0.036)^2
-------------
(0.036)^2 (0.018)

[drowsy girder]

,calc 1/7.5

[warm shale]

Result:

0.13333333333333

[drowsy girder]

What is 0.018?

[timid silo]

Wdym?

[drowsy girder]

0.018

You put that number there

[timid silo]

1 sec

[hybrid gull]

$7.5 = \frac{(x - 0.036)^2}{(0.036)^2 \cdot (0.018)}$

[warm shale]

Shen
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

Shen

[drowsy girder]

Oh its like that

[hybrid gull]

Next time type it out in LaTeX or write it out nicely on a piece of paper so we can more easily understand it.

To solve it, just clear the denominator, simplify, take the square root, add the ± and solve for x

[timid silo]

Sorry will do

So clear the denominator as in multiply (0.036)^2 and (0.018) together then multiply the sum of that with 7.5?

[hybrid gull]

yup

no sum tho - just multiply

[timid silo]

Uh

[hybrid gull]

sum -> addition

No addition

[timid silo]

1.7496×10^-4

What do you mean by add the +/-?

I tried to square root -0.036 after raising it to the ^2 but it didnt work

[obtuse pebble]

@timid silo Has your question been resolved?

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[teal nova]

yo just wanted to ask how do you get the p(x) in this one

[teal nova]

there's no given table btw

[obtuse pebble]

@teal nova Has your question been resolved?

[obtuse pebble]

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[timid silo]

I am taking calculus 1, and was looking at ways to study and stumbled upon this,

this is essentially me. I learned how to take derivatives and done quite a few practice problems and working on limits

but outside of the context of doing problems, i really don't know what these mean

is there something I can refer to that can help me?

I am so bad at this even the 1blue3brown? video on calculus didn't really help me be able to understand

i dont really know what 'finds the instant rate of change' really means although ive heard that and that its to find a slope of a tan line

[royal basin]

3blue1brown

have you tried watching khanacademy's videos

[timid silo]

3blue1brown*

i have, it just seems i can't really fully mentally grasp

like yeah i get that limit is asking whats approaching on the graph

and derivatives for tan lines

but i fail to see the real world connection to any of these

like what is the graph even representing in real life?

i feel like if i can understand those, calc will be less daunting

as right now it feels like im doing more pattern recognition and following rules

[royal basin]

i mean

derivatives have lots of real world applications

the derivative of position wrt time is velocity

by definition

so there's that at the very least

[timid silo]

okay, i will try to see some khan videos and try again with 3blue1brown, but typically on a test

it usually just is practice problems right?

they don't really test ur understanding of what a derivative or limit really is right?

not that this matters, as i still want to learn for my own sake

[royal basin]

tests tend to test your understanding of procedure more than understanding of concepts

[timid silo]

okay, thank you.

cheers

also is wolfram alpha pro worth it?

instead of chegg?

its only 5 bucks and i want to see step by step solutions for derivative problems

[brave bramble]

Honestly, very confident way to state the limit. Are you sure you don't understand them?

[timid silo]

i guess i get that much, but when i was watching 3blue1brown videos

on calculus

man he was drawing triangles and all sorts of things on those graphs

im like wtf is going on

and i figure its something with me

as those videos are known to be great

i have a huge gap of knowledge somewhere..

[brave bramble]

Yeah that's a difficult step for a lot of students haha. I assume he was creating the definition of the derivative there

Have you learned how to approximate the rate of change with a secant line?

[timid silo]

nope

wait

isnt that just rise over run?

y2 - y1 / x2 - x1?

i mean

[brave bramble]

Find two points on your curve, then get the slope between them

If those points are close together, this is a strong approximation for the slope of the tangent line

[timid silo]

okay, thats useful to know. can i ask your opinion on wolfram alpha pro? 5 bucks a month

to simply see step by steps to derivative problems

[brave bramble]

Sorry haha I don't know

[timid silo]

okay haha thanks anyways

i'll definitely try to watch more videos

discrete math feels so much easier and fun

[brave bramble]

So calculus takes these two points and asks the question "what happens if we add a limit to the process?"

[timid silo]

compared to calc

[brave bramble]

"If the distance between the two points approaches 0 with a limit, what happens to the slope?"

[royal basin]

"what happens if we consider the average velocity over smaller and smaller time intervals?"

[timid silo]

it gets more accurate

?

[brave bramble]

That's a good intuition

But the addition of the limit changes things. It goes from "more accurate" to "exact"

[timid silo]

ur saying as it gets smaller and smaller at some point it will be exact?

right?

[royal basin]

no, it won't be exact at any finite point

[timid silo]

but it will be very very close?

[brave bramble]

So we typically use h for "distance between the two points"

If h is a real number, then the slope between the two points will never be exactly the same as the slope of the tangent line

But adding in the limit is exactly the step we need. Now we're asking "what happens to the slope as we allow h to be smaller than any real number?"

Which, I know, is weird haha

We often say that h gets "arbitrarily small"

[timid silo]

is h just a random thing?

no other meaning?

is it like using i, j, k etc in programming for for loops?

[brave bramble]

Just the variable we often use for "distance between the two points"

h = x2 - x1

Nothing special otherwise

I get that with text alone this probably won't sit quite right. If the videos help, go for those. With a combination the idea will eventually make sense

[timid silo]

okay i wrote that down

and will watch a few videos

thank you for the help

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[fair cave]

I understand the quotient rule but I don’t know how to find the derivative of ln cot and sin x

[obtuse pebble]

@fair cave Has your question been resolved?

[fair cave]

<@&286206848099549185>

Is this set up right

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[jade ember]

it says to approximate the area under the curve using 4 left endpoint triangles. The answer is 30 but I keep getting 26

[jade ember]

I found delta X to be 2, then I did f(-4) * 2 + f(-2) * 2 + f(0)*2 + f(2) * 2

nevermind, something went wrong with my calculations

sorry

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[coral wing]

how do i describe the gradient of a curve if there are no points given?

[spiral maple]

wdym

If you don't have a function, you can't find gradient/slope

[coral wing]

like there are no coordinates given

[spiral maple]

Yeah, but you can describe which would have a large slope

or a 0 slope

or a negative slope

[coral wing]

so in this case it would be

the gradient of the curve from point a to point b is a positive large slope, the gradient of the curve from point a to point b is a negative slope and etc?

[spiral maple]

the gradient at a is positive, gradient at b is 0

[coral wing]

ok ty!

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[coral wing]

.reopen

[obtuse pebble]

✅

[coral wing]

whoops

.close

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[coral wing]

why is it still in occupied wth

[spiral maple]

it takes time to rotate

[obtuse pebble]

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[swift river]

can someone confirm if my answer here is correct

[swift river]

before i submit

[obtuse pebble]

@swift river Has your question been resolved?

[swift river]

<@&286206848099549185>

[obtuse musk]

is this an exam?

[swift river]

no its HW

[obtuse musk]

ok

[swift river]

is it correct tho

[obtuse musk]

i dont know, but you can increase your chances of an answer by posting how you arrived at that answer

[swift river]

ok

[lusty cedar]

will you be sending?

i am there to help

[swift river]

yeah

its just too much and i deleted it i'll have to rewrite it here ig

[lusty cedar]

are you willing to?

maybe just write and send, idk about you but i prefer writing to typing

[swift river]

so i got
a^2 + x^2 = d^2
and by taking the Dv with respect to t it becomes

d/dt (1) + d/dt(x(t))^2 =(d(t))^2

0 + 2x * dx/dt = 2d * dd/dt

0 + 2(7)(75) = 2d * d'

1050/2√50 = d'

525/√50 km/h = d'

i didnt point out how i got d which is 1^2 + 7^2

[lusty cedar]

ig i'm smart enough to figure that out

[lusty cedar]

well, you've worked hard

it's great

but you could have just calculated the velocity component along the line joining the two points

[swift river]

is it correct tho

im not sure this my first time doing it

[lusty cedar]

ya it is mate

@swift river

[swift river]

thnx

lemme try

yeah its says correct thanks

.closer

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[lusty cedar]

great

[obtuse pebble]

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[timid silo]

there is a formula for this one but i forgot it 😦 $\int(u'*ln(u))$

[warm shale]

seif

[timid silo]

$\int(u'*ln(u))$

[warm shale]

seif

[timid silo]

$\int(u'ln(u))$

[warm shale]

seif

[obtuse pebble]

@timid silo Has your question been resolved?

[robust sleet]

?

[timid silo]

u

is a function

!close

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[lost radish]

Hi

[delicate root]

@lost radish

[lost radish]

Part 3 please

[lost radish]

I know just wait

[delicate root]

not sure if it is my screen but the image quality and photo angle make it impossible to read what is the actual function

[lost radish]

Wait

Now?

@delicate root this one is clear

[delicate root]

have you tried to solve g(a)=0?

[lost radish]

No

Since I don't know thats it's between two numbers@delicate root

[delicate root]

what?

a=x

g(a)=0

just write down g(a)=0 and solve for x

[lost radish]

Wait 1 min

I want to try

@delicate root

?

<@&286206848099549185> anyone please

Please anyone

Anyone please!!!

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[urban kiln]

the question specifically says that the conical area is taken out, which obviously means that one base of cylinder doesnt exist...so shdnt the base area be subtracted instead of being added?

[urban kiln]

this shd b subtracted

[teal prawn]

it refers to the lower base

not the upper one

[urban kiln]

huh?

[teal prawn]

youre adding the area of the lower base

[urban kiln]

but u removed the conical portion

didnt the base get removed as well

how can u add it

[teal prawn]

yes and that affects only 1 base

but there are 2 bases

[urban kiln]

ohhh i see

got it got it

for some reason i assumed that thing is kept on floor or smthn

my bad

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[safe mantle]

Hi can anyone help me on how to find the inequality that describes the unshaded region of this graph

[teal prawn]

ig we can start by figuring out what the equation of the line itself is

[safe mantle]

Ok thanks for the tip I will work on it now

Yes

[teal prawn]

its y not -y

[safe mantle]

Oh sorry thats =

Now I just input coordinates from the unshaded area to find what sign I should use right?

[teal prawn]

yeah

[safe mantle]

Okay thanks Alot I forgot about this now I remember how to do it again have a good day bye!

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[wicked scarab]

Does anyone know discrete math (I guess it is)

[wicked scarab]

I have no clue what R is here

[balmy mortar]

3rd paragraph

It defines what R is?

[wicked scarab]

A set of tuples

I meant I have no idea what properties it has

[balmy mortar]

It defines R precisely

https://i.imgur.com/mrZNfIK.png

that last sentence says exactly what R is

[wicked scarab]

Yes, I understand

[balmy mortar]

Then explain what is the issue

[wicked scarab]

The issue is I don't know what properties it has

I would say

[balmy mortar]

I don't understand what is your confusion

If you understood the definition

In words, explain what R is

[wicked scarab]

A set of tuples (s,c) from SxC

Nvm

[balmy mortar]

A specific set of tuples

[obtuse pebble]

@wicked scarab Has your question been resolved?

[obtuse pebble]

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[compact gate]

Can someone show me how to evaluate this limit analytically without Hopital's Rule?

[warm shale]

Goose on a Moose

[wet drift]

this is not defined on x to -2

[compact gate]

yes, but we can still evaluate the limit. Wolfram gives me -∞

[wet drift]

yes it is right though

[compact gate]

How do I show this?

[sinful kraken]

Find the limit when it aproches 2 on the right and left

if the answer is the same then thats your limit for 2 and if its not then the limit doesn’t exist

[wet drift]

when you approches to x = 2 then (x-2)^2 will give you always positive values but that negative in numerator will make it negative

so - infity

[compact gate]

So in essence, we are taking the fact that 1/(0+) = ∞ as a given.

[wet drift]

sort of

as you approches to zero form positive side then it will goes to +infity

[compact gate]

Thanks I get it now.

thats what I meant by 1/0+ btw.

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[versed cave]

why does a function change if we multiply both sides by x?

[inland skiff]

Linear inequalities??

[versed cave]

?

[pine sail]

Wdym

[inland skiff]

You may multiply both sides of an equation by the same number. Of course multiplying both sides by zero gives 0 = 0, which is true but is of almost no practical use in solving problems. You may divide anything by any number that is not zero

[versed cave]

For example,
y = x^2
Becomes
y x = (x^2)x

[glossy ibex]

the function y(x) didn't change

[versed cave]

And why can't we simplify?

?

[glossy ibex]

you cant solve for y without dividing by 0 at x=0

$yx = (x^2)x \implies y = x^2, x \neq 0$

[warm shale]

DETOX (143 🍓)

[versed cave]

what's going on on the y axis?

[glossy ibex]

loss of information by multiplying both sides by 0

[high lily]

by multiplying both sides of the equation by x, you are creating extraneous solutions

[wanton isle]

Looks like a gawddamn trident

[versed cave]

So I end up with 0 = 0, as you said, but still, why the straight line on the y axis?

shouldn't I end up with an empty y axis?

[glossy ibex]

everywhere satisfies 0 = 0, because its true

but your equation only asks if 0 = 0 on the y axis

elsewhere it asks if y = x^2 is true

[versed cave]

Oh I got it

I also tried doing plugging in the same equation in desmos and it doesn't have that line

[versed cave]

This was geogebra

Anyway

Thanks a lot

Bye!

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[glossy ibex]

geogebra looks more accurate then. desmos labels the point as "undefined" if you click on it, but that only happens after you divide by 0.

[obtuse pebble]

Please don't occupy multiple help channels.

[glossy ibex]

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[harsh creek]

So i have a piston that can give me a torque of 10

[harsh creek]

10Nm

Which is .01Ncm

If my area is 120cm^2

How much force do i get?

Is that $.01^{2}/120$

[warm shale]

Fay

[harsh creek]

Will that give me N ?

[robust sleet]

what's the figure

is it a swuare

square

[harsh creek]

?

I dont understand the question sorry

[robust sleet]

we need to find radius

[harsh creek]

The question is a piston goes on the x-plane. The total force that can be applied is is 10N-m. What is the torque applied to a 120cm^2 area.

[robust sleet]

is this hydraulics

[harsh creek]

I have no idea

Thats the math question. Its a conversion problem

[robust sleet]

Nm isn't force

it's torque

[harsh creek]

The last 5 questions were like inches to ft to m

[robust sleet]

is there a picture or formula given

[harsh creek]

No

Oh smacks it does say torque i messed that up

Fixed the problem

Did i do the conversion right ?

[robust sleet]

send correct question again or send picture

[harsh creek]

The question is a piston goes on the x-plane. The total torque that can be applied is is 10N-m. What is the torque applied to a 120cm^2 area.

Im pretty sure its $(.01)^{2}N-cm^{2} *1/120cm^{2}$

[warm shale]

Fay

[harsh creek]

$.0001N/120$

[warm shale]

Fay

[harsh creek]

Can someone verify

[obtuse pebble]

@harsh creek Has your question been resolved?

[obtuse pebble]

@harsh creek Has your question been resolved?

[obtuse pebble]

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[fervent mortar]

Im looking up solutions to this question and it contains an almost clear mistake here

But the final answer obtained with the mistake corresponds with the 'correct' answer in the textbook

I just need confirmation that the final answer in the textbook is indeed incorrect

[fervent mortar]

Oh and this is some of my working

[fading silo]

4Wy^2 + Wy^2 = 5Wy^2

[fervent mortar]

Where's the other wy^2- oh!!

Wait what?

[fading silo]

Just ignore the last message

There is other wy^2

[fervent mortar]

Oh.
Oh I see it

Thank you so much 😭

[fading silo]

No worries

[fervent mortar]

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[fervent mortar]

((wasn't the bot supposed to move this to the available category?))

((did I use the command wrongly I'm so sorry about that if so-))

[obtuse pebble]

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[timid silo]

That one is suppose to be 4

Not 1

Bottom

It's the domain of the function is all values except for 2

That would be option 3

[obtuse pebble]

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[mortal spruce]

Hey!
More likely need explaination about vectors spaces / vectors subspaces
I do know those 3 conditions but I'm struggling to solve when doing exercices

[spiral maple]

You just check if all 3 properties hold

[mortal spruce]

And last question: how do I prove the sum of 2 subspaces (let say F, G) is a subspace of E?

[spiral maple]

.

[mortal spruce]

Alright thanks you!

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[balmy sluice]

can i get help here

[balmy sluice]

the critical points i got were 0,1,-1 in which all resulted to 0 so i used -4 and 3 (given)

[obtuse pebble]

@balmy sluice Has your question been resolved?

[balmy sluice]

<@&286206848099549185>

[tardy epoch]

show your work

[balmy sluice]

only 0,1,-1 makes it 0

got me $-20^{\frac{2}{3}}$

[warm shale]

Hecker

[balmy sluice]

at -4

i also tried $-\left(\left(3\right)^2-\left(3\right)\right)^{\frac{2}{3}}$

[warm shale]

Hecker

[balmy sluice]

it got me $-6^{\frac{2}{3}}$

[warm shale]

Hecker

[balmy sluice]

but it says wrong for some reason

<@&286206848099549185>

[tardy epoch]

the derivative is right, the next step is wrong.

write it out like $\frac{(-2/3) \cdot (2x-1)}{(x^2-x)^{1/3}}$

[warm shale]

riemann

[balmy sluice]

okat

y

but still i have to make (2x-1) = 0

and i cant

so once again i had to use the given intervals

<@&286206848099549185>

[tardy epoch]

why not?

Do you know what interval [-4, 3] means?

[balmy sluice]

what?

[tardy epoch]

why can't you solve for x in (2x-1) = 0 ?

[tardy epoch]

and do you understand what "over the interval [-4, 3]" means?

[balmy sluice]

no

so 1/2?

[tardy epoch]

[-4, 3] is notation for all values $x$ such that $ -4 \le x \le 3$

[warm shale]

riemann

[tardy epoch]

so yes $x = 1/2$ is in the interval $[-4, 3]$ because $-4 \le 1/2$ AND $ 1/2 \le 3$

[warm shale]

riemann

[balmy sluice]

so i should plug in 1/2 to the original formula

like this $-\left(\left(\frac{1}{2}\right)^2-\left(\frac{1}{2}\right)\right)^{\frac{2}{3}}$

[tardy epoch]

do you understand why?

[warm shale]

Hecker

[balmy sluice]

$-\frac{1}{4^{\frac{2}{3}}}$

[warm shale]

Hecker

[balmy sluice]

cause its in between?

[tardy epoch]

nope

You solved for x in $f'(x) = 0$

[warm shale]

riemann

[tardy epoch]

Let's call it $a$, so $f'(a) = 0$

[warm shale]

riemann

[balmy sluice]

oh boy

[tardy epoch]

Plugging that back into $f(x)$ tells you the local minimum or maximum

[warm shale]

riemann

[tardy epoch]

oh it's a local min

[tardy epoch]

go back and check when the denominator equals zero separately.

[balmy sluice]

$:\frac{\left(-2/3\right)}{\left(\frac{1}{2}^2-\frac{1}{2}\right)^{1/3}}$

[warm shale]

Hecker

[balmy sluice]

$=\frac{2\sqrt[3]{4}}{3}$

[warm shale]

Hecker

[balmy sluice]

i dont think theres a 0 for this one

[tardy epoch]

do this

[balmy sluice]

i cant find a value that gives me 0 for both

@tardy epoch

[tardy epoch]

I mean solve for where the denominator is zero here. Then plug that into f

[balmy sluice]

but if the denominator its not a real number??

[tardy epoch]

I don't understand

[crystal sigil]

?

irrational number ?

or what

[balmy sluice]

yeah

[crystal sigil]

round it

[balmy sluice]

okay so $x^2-x = 0, if , x=1,0$

[warm shale]

Hecker

[crystal sigil]

x^2-x=x

[balmy sluice]

what

[crystal sigil]

what is the question

original

[balmy sluice]

look here

[tardy epoch]

plug these into f and see if they're max/mins

[balmy sluice]

its gonna be 0 no matter what

[tardy epoch]

right

so does your function have maxima or minima there?

[balmy sluice]

it does have min yes

this

<@&286206848099549185> could it be 0?

[tardy epoch]

You still haven't checked 0 and 1 for max/min

[tardy epoch]

Oh right here

[balmy sluice]

nvm i got it its 0

0,1 =x

[tardy epoch]

0 is both the x and y value

And 1 is the other x value

[balmy sluice]

.close

[obtuse pebble]

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[white garden]

would the answer just be 38

[white garden]

and would this be 140

<@&286206848099549185>

anyone there? I rlly need help on these

thanks I guess.

.close

[obtuse pebble]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[noble heath]

guys i need help

[broken night]

whats up?

[noble heath]

child mass is 50kg and g=10 H/kg

how to find gravitational force to this child

[broken night]

could you repost the full question i cant see it and want to be sure before i give the wrong answer

[hybrid gull]

^^

[hybrid gull]

Read this.

[broken night]

I may be glitching I see the mods pin for claiming a channel but i dont see your question

[hybrid gull]

It says “Guys I need help”

So he’s not following the rules

It’s whatever

[broken night]

oh yea myb i thought i did smth wrong

[noble heath]

whats the rule

oh sorry

[broken night]

im new to this channel im just here to answer questions idk about the exact rules

[noble heath]

mass is 50 kg, find mass force. (g=10 H/kg)

its this question

[hybrid gull]

They’re just posted by @obtuse pebble

[hybrid gull]

Looks like this

[broken night]

thanks

[hybrid gull]

Not sure what H is

But Fg = mg

[broken night]

is the person on an incline or flat surface?

[hybrid gull]

Fg: force of gravity
m: mass of the object the force acts on
g: acceleration due to gravity

Fg units: Newtons (N)
m units: kilograms (kg)
g units: meters per second² (m/s^2)

[obtuse pebble]

@noble heath Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

@stark acorn Has your question been resolved?

[obtuse pebble]

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[coral shale]

<@&286206848099549185>

[coral shale]

Is this true?

[quaint glen]

yeah. you coulda used a calculator to check that though.

[coral shale]

I mean it will add the exponent?

It will have the same answer

[tardy epoch]

Yes

[coral shale]

Thank you

[obtuse pebble]

@coral shale Has your question been resolved?

[timid silo]

a^x * b^y = a^(x+y) ,** IF ** a = b

This will help I hope

[coral shale]

Thank you

[timid silo]

and also , please close the channel if your problem is solved

by typing
.close

[coral shale]

Oh sorry

.close

[obtuse pebble]

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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse pebble]

@bleak steppe Has your question been resolved?

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✅

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[bleak steppe]

If twice a number x increased by 6 is between 2 and 10 then what are the integers that x could possibly have?

[sinful kraken]

What did you try ?

[bleak steppe]

2<(2x+6)<10

[sinful kraken]

Ok then solve for x

[bleak steppe]

then that would be "-2<x<2"

so all possible numbers yould be "between" the intergers given

is that right?

[sinful kraken]

Probably

[bleak steppe]

would that be {-1, 0,1 }

or still { -2,-1, 0 , 1,2 }

[sinful kraken]

No the 2 aren’t included

[bleak steppe]

Oh, so you're not sure either

[bleak steppe]

So, this?

[sinful kraken]

u cant include the 2

since its <

and >

[bleak steppe]

yeah and not <=

[sinful kraken]

its not greater or EQUAL

[stuck trout]

yeah open circle means not included

[bleak steppe]

oh I get it now! So, all possible integers whould just be {-1, 0,1 }

[sinful kraken]

Yhea

[bleak steppe]

Thank you so much!

[sinful kraken]

np