help-10

[grizzled mural]

(b)(0,1,a0,a1,a2,...)
(c)(0·a0,1·a1,2·a2,...)
(d)(a0,0,a1,0,a2,0,...)

[grizzled mural]

I did a

I know b and c should be quite easy, but I'm having trouble seeing which uses derivative

.close

[obtuse pebble]

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@leaden ginkgo Has your question been resolved?

[compact shadow]

By definition…

By definition… I don’t know what to say

You exam whether it satisfies transitive , anti-symmetric… by definition

Unless you didn’t read their definition at all?

Then you read your textbook…

Okay then I give up.false false false true

Yeah

Read your textbook next time

[obtuse pebble]

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[timid silo]

need help for number 11-15 i have no clue answering this

[timid silo]

<@&286206848099549185>

[lucid flame]

,rotate

[lucid flame]

what's your answer for 9 and 10?

apply the same thing for 11 and 12

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

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[inner raft]

14 x 13 x 12 ... (2)(1) / 5! 9!

[hollow sun]

what is the formular?

[lucid flame]

what do you need help with?

[flat anvil]

So you should get 1413121110 / 5!

Then just be smart with how you break the numerator up

[hollow sun]

$\binom{14}{5}=\frac{14!}{(14-5)!\cdot 5!}$

[inner raft]

do i cancel out the 5! or 9!

[high lily]

how exactly is that leading to 48048

[inner raft]

with the top

[flat anvil]

E.g. 12 = 4*3

[warm shale]

Big xdddd

[high lily]

are you doing this by hand or with a calc

[flat anvil]

9! Cuz it makes it easier

[inner raft]

hand

i cancel out 9! first

which left
14(13)(12)(11)(10)/5!

[hollow sun]

$\frac{10\cdot 11\cdot 12\cdot 13\cdot 14}{2\cdot 3\cdot 4\cdot 5}$

[warm shale]

Big xdddd

[high lily]

what did yuo do after that

[inner raft]

i think thats where i messed up. I multiply the top and divide by 5

got 2,002

14(13)(12)(11)(10)/ 5(4)(3)(2)(1)

then cancel out the bottom with top

7(13)(11)(2) = 2002 ?

[obtuse pebble]

@inner raft Has your question been resolved?

[inner raft]

<@&286206848099549185>

.close

[obtuse pebble]

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[runic tide]

hi i want to know if i've gotten the answer right for this q.
my ans: (B ∩ C) - A is what covers 011, 101, 100

[civic zealot]

so you're saying (B ∩ C) - A contains the elements 011, 101, 100?

[runic tide]

ys

yes

trying to find area compromised by thse elemenets

[civic zealot]

Then no.

(B ∩ C) - A is just the element 011

[runic tide]

uh hmm ok, what would contain all of those elements?

[civic zealot]

You've got 011 in the set you gave, union that with something that contains 100 and 101

[runic tide]

ok thank u

.close

[obtuse pebble]

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[winter pewter]

d and e only

[restive ridge]

what's your question

[winter pewter]

having a hard time in d and e

[restive ridge]

that's not a question

[winter pewter]

This is my question

[restive ridge]

that is also not a question

[winter pewter]

Umm it is

[restive ridge]

that's an assignment task

[winter pewter]

What?!?!?

[restive ridge]

not a math question in a clear, concise manner

if you want us to help you with that task

[winter pewter]

Dudes thats algebra

[restive ridge]

then you have to show what you've done so far

[winter pewter]

Someone help me

[restive ridge]

we won't just do it for you

[winter pewter]

I already know a to c

A = 1

B = -7/2

C = DNE

.close

[obtuse pebble]

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[fair wing]

prove ad/bd == ac/dc

<@&286206848099549185>

[civic zealot]

what have you tried?

[fair wing]

Sine rule

I don't think I did it right tho

[civic zealot]

sin rule should work

[fair wing]

Alr

Lemme try again

Yh I need help

Idk how to use sine rule for It

[civic zealot]

Law of sines says $\frac{a}{b} = \frac{\sin A}{\sin B}$ right?

[warm shale]

Zybikron

[civic zealot]

So, $\frac{ab}{bd} = \frac{\sin \angle ADB}{\sin x}$

[fair wing]

Yh

Is that all or

[civic zealot]

wait, are you sure this is written correctly?

[fair wing]

Probably

Is there an error

In yhe question

[civic zealot]

are you trying to prove ad/bd == ac/dc or ab/bd == ac/dc?

[fair wing]

Didn't you just type the same thing twice

Nvm I'm dumb

1st one

Ad/bd = ac/dc

If it doesn't make sense it's probs the second cause i memorised it from the test I had

[civic zealot]

the first one isn't true

[fair wing]

Oh so it's orobs the second one

[civic zealot]

okay

[warm shale]

Zybikron

[civic zealot]

how could you rewrite ac/dc with law of sines then?

[fair wing]

Where did you get the right side of the eqasion from

[civic zealot]

law of sines

[fair wing]

I see

So is ac/dc also sin adb/sin x

[civic zealot]

yep

[fair wing]

Why angle adb

[civic zealot]

oh sorry, should be ADC

[fair wing]

Oh alr

[civic zealot]

so $\frac{ac}{dc} = \frac{\sin \angle ADC}{\sin x}$

[warm shale]

Zybikron

[fair wing]

What's the proof for thaf as a sentence

For the last part

[civic zealot]

?

law of sines

[fair wing]

Oh yh I understand now thanks

[civic zealot]

so we're just taking this and rearranging to get the parts we care about

Now, since <ADB and <ADC are angles on the same line, what do you know about them?

[fair wing]

I'll get back to you in a couple of minutes I need to pray

I'm back @civic zealot

[fair wing]

Are they the same

I'm still kind of confused about how you got sin adc/sin x

Like how does that equate to ac/dc

Nvm I understand that part now

Acc I need a bit of help understanding some parts

[obtuse pebble]

@fair wing Has your question been resolved?

[civic zealot]

@fair wing they are the same, but why?

[fair wing]

Idk why

[civic zealot]

When you have supplementary angles $\alpha, \beta$ then $\alpha+\beta = 180^\circ$

[warm shale]

Zybikron

[civic zealot]

and, $\sin\alpha = \sin\beta$

[warm shale]

Zybikron

[fair wing]

Yh

But wouldn't it be ac/sin x

[civic zealot]

so since <ADC and <ACB are supplementary, you know sin ADC = sin ADB. How can you use this, with the equations from before, to get the equality you need?

[fair wing]

Plug it in??

[fair wing]

@civic zealot

[civic zealot]

You have $\sin \angle ADC = \sin \angle ADB$, what can you says about $\frac{\sin\angle ADC}{\sin x}$ and $\frac{\sin \angle ADB}{\sin x}$?

[warm shale]

Zybikron

[fair wing]

I don't know what I can say about it

[civic zealot]

If $a=b$ what can you say about $a/c$ and $b/c$?

[warm shale]

Zybikron

[fair wing]

That they are the same

[civic zealot]

yes

[civic zealot]

now use that same reasoning here

[fair wing]

Oh yhhhhhhh

So they are the same right

[civic zealot]

yes

Now if those are the same

[royal solar]

0.5ab sin(x)

[civic zealot]

what does that tell you about this?

[civic zealot]

and this

[royal solar]

oh nvm, it’s a different q

[fair wing]

Does it say that they are both the same?

[civic zealot]

yes

[fair wing]

Is that it or

[civic zealot]

so everything here is equal

that's it

[fair wing]

Can I repeat it to u

[civic zealot]

sure

[fair wing]

So I'm sure I understand

So If a/b = sina/sinb then ab/db =sin adc/sinx

And since adc and adb are tge same

I dk about whats next

[civic zealot]

the angles aren't the same

sin of the angles are the same

[fair wing]

Oh I see

So what do I do with it next

Or can you do the full working out so I can understand it better

[civic zealot]

scroll through the convo, piece it together. It'll help your understanding

[fair wing]

Oh I get it

Since the sine adc and adb are the same

It proves thar they are equal as they both equal to sinadc /sinx

@civic zealot am I right

[civic zealot]

yup

[fair wing]

Ok I think I'm done

Thanks for the help

[obtuse pebble]

@fair wing Has your question been resolved?

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[obtuse pebble]

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[indigo hedge]

How many ways to get 2 pair poker

[tardy epoch]

For a hand of 5 cards?

[indigo hedge]

Ye

[tardy epoch]

Did you try counting?

[indigo hedge]

Lol

[tardy epoch]

What's funny? Do you need help counting ?

[indigo hedge]

It is over 100000

It should be 13choose 2 ways to pick rank of each pair 4choosr2 ways to pick suits of 1 pair 4choose2 ways to pick suit of the second rank pair and 11choosr1 ways to pick rank of the single card from the remainjng ranks and then 4choose1 to pick the suit of the single card

So I don’t feel like counting

[obtuse pebble]

@indigo hedge Has your question been resolved?

[obtuse pebble]

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[timid silo]

"Linearity of Expectation" I asked this question before few minutes and someone answered me with this phrase, but I searched in youtube and could not understand the relationship, maybe he did not understand the question correctly, so I will ask again, sorry

[timid silo]

the answer is 100 because the mean of the sampling distribution is the same as the mean of the population.

100 is the right answer

but my answer is SE = (std / sqrt(n)) >> 20 / 2 = 10, but 10 is wrong answer

even if I would say zscore = (meanOfTheSample - meanOfThePopulation) / SE >> zscore = (meanOfTheSample / 100) / 10, this is wrong as well because I do not know the meanOfTheSample

[brave bramble]

You don't know the mean of any sample, but you know what the mean of the mean will be

You expect means to gravitate around 100

[timid silo]

because its the Central limit theorem
right ?, when we increases the sample its will get closer to the population means ?

so how should I know its 100 ? is their a formula or something I should use ?

should I always assume its the same as the population mean ?

[timid silo]

"Linearity of Expectation" is this related to my question ? someone told me but I could not understand, so I want to ask if its related or not

descriptive statistics should be easy, but I found it very difficult, so I guess when I start Statistical inference I will probably stuck for months to understand it

[tardy epoch]

linearity of expectation is the same as saying the sum of expectations is equal to the expectation of the sum

you already know it from calculus

$\int (f(x)+g(x)) dx = \int f(x) dx + \int g(x) dx$

[warm shale]

riemann

[timid silo]

may I forget this, because I feel like I never study this before, what grade is this ?

12 ?

I could not understand but I will close this, so others can use it, Thanks Riemann and Kaynex

.close

[obtuse pebble]

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[opal totem]

Order the following numbers from least to greatest:

[opal totem]

Without a calculator btw

4 to the power of 300

7 to the power of 200

3 to the power of 400

9 to the power of 100

[proper coyote]

Thats hard without a calculator dang

[carmine bear]

surprise surprise this question came up in the maths challenge that i did this year

[proper coyote]

Oh wow

[opal totem]

its this wierd way i forgot

[high lily]

do you know your exponent laws?

[opal totem]

probably but i dont know them off the top of my head

[high lily]

are you familiar with the power law?

[opal totem]

maybe

[high lily]

if you don't know or not sure if you know which imo is just a no

[tardy epoch]

somebody already did an identical problem

[high lily]

then look it up

[tardy epoch]

oh it was you
#help-5 message

[opal totem]

yeah i forgot the channel and had to go

so now im back

[tardy epoch]

the answer was laid out there. read and ask a more specific question

[opal totem]

oh ill read it thanks

@tardy epoch i did what was said and got

3 to the power of 400

[main lodge]

$a^{b \cdot c} = (a^b)^c$

[warm shale]

Olly

[main lodge]

That might be useful

Oh and also

[tardy epoch]

start here
#help-5 message

[main lodge]

$\frac{a^c}{b^c} = (\frac{a}{b})^c$

[lost ermine]

teach me maths :>

[warm shale]

Olly

[opal totem]

rieman i got everything to that form

[tardy epoch]

this is wrong then

[high lily]

what's that supposed to be?

that's just one of the expressions

you were being asked to order them

[opal totem]

oh i forgot the question

first was 3 to 400 then 4 to 300 then 7 to 200 then 9 to 100

oh no

least to greatest so oppisite

[compact shadow]

Someone answered that already right? Compare 4^3,7^2,3^4,9

X^100 is monotonic

[main lodge]

That's correct

[opal totem]

yeah ive got i think im gonna close

!close

,close

.close

[obtuse pebble]

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[midnight zephyr]

I've been trying to solve this equation for a few hours, changing variables, using logarithms. I tried calculating it in Wolfram Alpha but for some reason it doesn't show the exact value and only shows a decimal approximation. How can I find the exact value of x?

[warm shale]

NeoManu

[main lodge]

Wolfram alpha might have used a method like newton-rhapson method, it's possible you cannot find the answer analytically

[tardy epoch]

,w solve x^(x+1) -250 = 0

[warm shale]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by riemann#2529

[main lodge]

,w solve x^(x+1) = 250 for x

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Olly#2605

[main lodge]

Yeah I assume it is using some iterative method

Such as newton-rhapson or possibly something more sophisticated

[tardy epoch]

,w ProductLog(250/e)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[tardy epoch]

,calc 3.3211498^(4.3211498)

[warm shale]

Result:

178.88154843048

[tardy epoch]

oh nvm i had algebra mistakes

[midnight zephyr]

And how could you find the exact value of x?

the problem of this equation is in x+1, since it makes the calculation difficult

[obtuse pebble]

@midnight zephyr Has your question been resolved?

[main lodge]

I don't think that you can

The best you can hope for is to find an approximate value

[obtuse pebble]

@midnight zephyr Has your question been resolved?

[midnight zephyr]

when I have a more advanced level, I will try to solve this equation again, I think that it is possible to calculate the exact value only that for now I do not have the knowledge to do it. I'll see my face with the equation in a few years

[obtuse pebble]

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Use .reopen if this was a mistake.

[midnight zephyr]

.close

[obtuse pebble]

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[cinder schooner]

Idk how to do this

Can someone guide me through the problem?

This is geometry hw I gotta do

And i don’t remember how to solve it

<@&286206848099549185>

[brisk oracle]

what have u tried

[cinder schooner]

Guessing.

[brisk oracle]

know any theorems

?

[cinder schooner]

Oof about that.

[brisk oracle]

alright, you have to use the pythagorean theorem

do you know it?

[cinder schooner]

a + b = c

Squared*

[brisk oracle]

alright so you have to apply it to this specific triangle

[cinder schooner]

🤔

The right sided one?

[brisk oracle]

yes, pythagorean theorem talks about right triangles

[cinder schooner]

True..

The smallest leg is a right? Or it doesn’t matter which one

[brisk oracle]

doesn't matter

but c is always the large side

aka the hypotenuse

[cinder schooner]

Yes

I got a as 7

For my answer

[brisk oracle]

that's bc you forgot about the squares

[cinder schooner]

o

Hmm 3 is 9 and 4 is 16

Squared*

[brisk oracle]

yes yes

and then?

[cinder schooner]

Don’t I subtract them?

They give me 7

[brisk oracle]

alright. and what is this 7?

[cinder schooner]

The other leg

But if it’s squared then it won’t equal to 16

[brisk oracle]

hmmm how to explain this to you

well. you have to write the pyth. theorem equation again

you're so close 😄

[cinder schooner]

Bro 💀

7+9=16

Wait.

[brisk oracle]

hahaha saw it??

write the equation with symbols, before you plug the numbers in

[cinder schooner]

Ok

It’s 3.5

[brisk oracle]

no guessing

[cinder schooner]

🤔

[brisk oracle]

write the equation with symbols

[cinder schooner]

a + 3 = 4

[brisk oracle]

but you know that the theorem talks about squares of lengths

not just lengths

[cinder schooner]

Oh

I thought it was just about lengths

[brisk oracle]

but you told me: "squared"

[cinder schooner]

Bro idk 💀

The teacher got me confused

What the

Is that perimeter?

[brisk oracle]

good gif but it's too fast

no. the perimeter is very easy

but to get to the perimeter you have to understand the pythagorean theorem

[cinder schooner]

a + b = c squared

a + 3 = 4

a + 9 = 16

[brisk oracle]

alright. so since they are squared why not write them as squares?

you know what a square is right

[cinder schooner]

a^2

That

[brisk oracle]

yep 💯

[cinder schooner]

Wait a minute

[brisk oracle]

so: a^2 + 3^2 = 4^2

[cinder schooner]

Yeah

[brisk oracle]

you forgot that you were talking about a^2, and thought you were talking about a

so.... now you have the equation written correctly

what next

[cinder schooner]

Find what a is

[brisk oracle]

well. you have some information about a^2. so you have to find a^2 first

[cinder schooner]

🤔

All I can see is the bottom triangle

It’s cut in half

[brisk oracle]

wdym the bottom triangle

[cinder schooner]

I meant the side

[brisk oracle]

ok

yea. we are talking about the side triangle

you see that the large triangle is cut into two equal triangles

and those triangles are right triangles

[cinder schooner]

Yes

[brisk oracle]

so we can apply pythagorean theorem to one of them. to find the bottom side

[cinder schooner]

it’s 7

A is 7

[brisk oracle]

ok ok. hold on

pause

[cinder schooner]

But since it’s cut in half

[brisk oracle]

it's not 7

or 3.5

[timid silo]

3^2 + a^2 = 4^2. this may help

[brisk oracle]

yes

@cinder schooner how are you with equations?

[cinder schooner]

probably a 5/10

[brisk oracle]

alright.

if i tell you to take the equation None wrote and solve for a^2 do you know what to do?

[cinder schooner]

I don’t think so.

Idk what a is

[timid silo]

3^2 + (missing value)^2 = 4^2

[brisk oracle]

ok but you know that a is the bottom length of the side triangle

[cinder schooner]

Yeah

[brisk oracle]

ok so. when we say "solve for a^2" we mean: make the equation say " a^2 = something"

[cinder schooner]

🤨

Oh

[brisk oracle]

you know that we can add or subtract numbers from both sides of the equation right?

[cinder schooner]

Yeah

16-9

Subtract 9 from both sides

[brisk oracle]

correct

ok so write None's equation. but after you have substracted 9 from both sides

[timid silo]

6^2 + 8^2 = 10^2
36 + 64 = 100

[cinder schooner]

a^2 = 7

W a i t

Hold up

It doesn’t make any sense

Wtf

[brisk oracle]

you got it bro

almost there

[cinder schooner]

My teacher hasn’t taught me this wtf

[brisk oracle]

you're so frigging close

[cinder schooner]

Man.

Ik I’m stressing you guys badly aren’t I

Sorry

[brisk oracle]

haha don't worry about it

[cinder schooner]

Ok so a^2 = 7

[brisk oracle]

so. congrats you solved for a^2

[cinder schooner]

🗿

[brisk oracle]

you know what a^2 is. now you have to find out what a is

[cinder schooner]

Yay

It’s

I hate decimals.

[brisk oracle]

yea. it's not a pretty decimal

[cinder schooner]

It ain’t

[brisk oracle]

so. don't write it as a decimal

[cinder schooner]

It’s 2.645 something

Oh my bad

[brisk oracle]

the exercise mentions a radical form

[cinder schooner]

Oh

OH

WHAT

So ✅7

[brisk oracle]

2.645 something is correct

[brisk oracle]

hahaha yes

[cinder schooner]

Bro 🗿

[brisk oracle]

$\sqrt{7}$

[warm shale]

elyaguaro

[cinder schooner]

I’m gonna need to learn my stuff

[brisk oracle]

yea ok. it looks weird

but it's just a number. it's 2.645 something like you said

[cinder schooner]

✅7 = 2.645

Now that I found that

What now

Oh crap this is special right triangles isnt it.

[brisk oracle]

well. you found the side of the side triangle

[brisk oracle]

correct

[cinder schooner]

Wait

My assignment never had a name cause I had to redo a problem from it

Ok this is good cause I need to learn about this lesson

[brisk oracle]

by the way. the large triangle is made of two side triangles as you said

are those two side triangles equal?

[cinder schooner]

Yes?

[brisk oracle]

haha duh, ofc they are

[cinder schooner]

God I thought I was wrong

Didn’t wanna look stupid 🗿

[brisk oracle]

but! you have to know why! it's important

[cinder schooner]

Why what

They’re equal?

[brisk oracle]

yes. why are they equal? how do you know?

[cinder schooner]

🧐

[brisk oracle]

ok. the exercise doesn't ask that.

[cinder schooner]

True

Thank god.

The thing is about perimeter and area

[brisk oracle]

so let's pretend that we just know they're equal. look at those 2 triangles bro. they're friggin equal

[cinder schooner]

Frfr

[brisk oracle]

ok.

perimeter

you know what perimeter is?

[cinder schooner]

=

Adding

[brisk oracle]

yea. you walk around the triangle, how much distance did you walk

so. add it all up

[cinder schooner]

3 + 4 = 7

🗿 ironic.

7 + ✅7 = 9.64

[brisk oracle]

hmmm. but. that's the perimeter of the small triangle

[cinder schooner]

Oh tru

Forgot about that

[brisk oracle]

we want the perimeter of the large one

[cinder schooner]

12.29

[brisk oracle]

no decimals!

[cinder schooner]

🗿 ok

Wait do I count the 3?

Or just the outside numbers

[brisk oracle]

you know it's the outside

[cinder schooner]

true 🗿

Is it 15?

[brisk oracle]

no because 2*sqrt(7) does not equal 7

[cinder schooner]

It’s decimals

[brisk oracle]

sqrt(7) * sqrt(7) equals 7

[cinder schooner]

._ .

[brisk oracle]

i think you'll find it helpful if you try to write down your thoughts more clearly

you are about to find the perimeter of the large triangle. that means add the lengths of the three sides

so... write it down. what are you adding?

[cinder schooner]

4 + ✅7 + ✅7 + 4 =

[brisk oracle]

alright. that is correct

go on........

[cinder schooner]

13.29

[brisk oracle]

also correct. but the exercise asks for 'simplest radical form'

[cinder schooner]

Sheesh.

Wait

8 ✅7

[brisk oracle]

haha nope 😄

[cinder schooner]

If there’s 2 of them

8_2 ✅7

[brisk oracle]

what's that _ mean 🤔

[cinder schooner]

No clue 💀

So I have to put it in radical form

[brisk oracle]

no

[cinder schooner]

It already is 😢

[brisk oracle]

yes

[cinder schooner]

Wait

Simplest radical form

[brisk oracle]

so. you add the 4's together. so far so good

[cinder schooner]

Only thing I can think of is 8+2 ✅7

[brisk oracle]

then there are two sqrt(7)'s that remain to be added

yep. that's it

[cinder schooner]

💀

🗿

[brisk oracle]

simple right

x + x = 2x

[cinder schooner]

So that’s the perimeter…

[brisk oracle]

sqrt(7) + sqrt(7) = 2* sqrt(7)

[cinder schooner]

Ok I’ll need to remember that

[brisk oracle]

yes. that's the perimeter

[cinder schooner]

It makes no sense

[brisk oracle]

hahaha it will

trust me

[cinder schooner]

Man

Now for the area

Do I have to multiply

Each side

[brisk oracle]

you know the formula for the area of a triangle?

[cinder schooner]

Isn’t it

1/2bh

[brisk oracle]

yes

[cinder schooner]

The base is ✅ 7

The height is 3

3✅7

1/2
3✅7

[brisk oracle]

what's the final answer?

[cinder schooner]

1/2 3 ✅7

I have to divide them by 1/2 don’t I

[brisk oracle]

ok. but that is the area for the side triangle

[cinder schooner]

OH

w

T

F

I’m so stupid

So it’s 3✅7

[brisk oracle]

correct. how did you find out

[cinder schooner]

It already is the half

The area

[brisk oracle]

so you added the areas of the side triangles together

[cinder schooner]

Cause it’s asking for the figure

No I just skipped to the 3 and the 7

[brisk oracle]

not sure what you mean but you got it right so congratulations 😄

[cinder schooner]

Wew

I still need a bit more understanding

But at least I got it

[brisk oracle]

yep. that's fundamental stuff, it will be very helpful if you understand it

what grade is this hw?

[cinder schooner]

I’m a sophomore

I got a 90 on it

The teacher doesn’t give out sheets often, she just assigns us on it online

I find it stupid cause there’s problems that she hasn’t even taught in class

I’m already on trigonometry and I get the stuff thanks to this server

.close

[obtuse pebble]

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[dense loom]

I can change the bottom to vertex form which gives me the following

wait i might've accidentally used a brain cell and figured out my problem

[hybrid gull]

I feel that bro

[odd stag]

hahaha

[hybrid gull]

I would have never guessed that - my first guess would have been:

1. Factoring out a 3 in the denominator
2. Factor the denominator to set up for PFD

I think what you've done is probably the most optimal

[dense loom]

I was about to ask how I'd trig sub with the 3 in the bottom, then realized I could just factor it out

after looking at it for like 15 minutes but thats besides the point

[hybrid gull]

You don't actually need a trig-sub

Test $u = x - 1$ and see what happens 🙂

[warm shale]

Shen

[dense loom]

I have to do 3 methods, I've already done normal substitution

I can do a double sub but I don't think that counts. And I'm assuming the last method is going to be partial fractions

[hybrid gull]

What if you started with PFD?

I'd just experiment at this point

Having to use 3 integration techniques is strange

[dense loom]

practice questions

not sure what PFD stands for

[spiral maple]

partial fractions

[dense loom]

because I didnt have enough room on my page to start with partial fractions

[obtuse pebble]

@dense loom Has your question been resolved?

Channel closed

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Remember:
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

so for question A would i set F(x) and g(x) = x = -2 for both functions and sub them in the Quadratic? my awnser came out to be f(x) = 20 and g(x) to be 5, so for b i would just sub these 2 and make d(x) = 15?

[azure glacier]

Yeah you just plug in the number for every x in the equation

f(-2) just means replace every x with -2 and so on

So you find what g(-2) is and f(-2) is and then subtract from eahc other

for b thoguh you have to like subtract them without puting numbers in (so they will be in terms of x)

[dense loom]

then c just plug in -2 instead of x

[timid silo]

ohhh ok i get it now

thank you ppl

.close

[obtuse pebble]

Channel closed

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[dense loom]

I know damn well I fucked up somewhere

I got this as my answer through trig sub

[hybrid gull]

Post in a new channel - someone else is using it now

[dense loom]

he closed it?

[hybrid gull]

I'm blind - forgive me

[dense loom]

all good, I was too fast for it to update

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[crude temple]

i need help

[crude temple]

.close

[obtuse pebble]

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[drowsy agate]

i need help on how to find m

<@&286206848099549185>

[spare oyster]

Mhm

[drowsy agate]

using pythagoras

[spare oyster]

Ye

A2+b2=c2

[drowsy agate]

i know but how do i find m

i need to find what m is

[spare oyster]

Can I help u THEN?

Sry caps

[timid silo]

ok

we know that 13 is the hypothenus

now we need to find the other 2 sides

[drowsy agate]

okay i need to find out this

[timid silo]

do you know a way to findy any of the 2 sides

i have a easier way

remeber that pytha only works on right triangles

you have to make a right triangle

[spare oyster]

Ye

[timid silo]

you can make a square on the bottom

and a triangle on top

do you see that bit?

do you see a square on the bottom and a triange on top?

[spare oyster]

Like this right?

[drowsy agate]

yes

[timid silo]

now do you know a way we can find the length of the triangle

since the square is 12

17 -12 = 5

[spare oyster]

Ye

[timid silo]

ye

[spare oyster]

U got it 👏

[timid silo]

square has all 4 sides that are the same length

so m = 12

[neon grove]

Just first make in square will be side =12 and then 5 and 13 will be the traingle.

(17-12 =5)

And solve it

Is answer 12

M=12

[obtuse pebble]

@drowsy agate Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[analog pasture]

Simple and Familiar

The medians of a triangle are the line segments that connect each vertex to the midpoint of the opposite sides.

In the given triangle ABC, the point D is the midpoint of line AB and therefore, the line CD is a median of the triangle. Find the Coordinates of point D and hence find the length of the line CD.

<@&286206848099549185>

pls help I dont understand cordinate geometry

<@&286206848099549185>

[hybrid gull]

Please read this. It's not that hard.

[analog pasture]

I suck

Im sorrry

I have adhd

I have a disorder

please help me

[hybrid gull]

Read this, show what you've tried.

[analog pasture]

I dont know how to do it

Im tryna learn

I have 13 questions that I got for homework i read them and tried

I still dont know

yoo man this is easy for u it isnt for me so please

[hybrid gull]

Given that D is the midpoint of AB, what can you determine about AD and BD?

It's also the same problem that @deft hornet posted

[analog pasture]

so how do I determine it

[analog pasture]

yes he's my friend

[hybrid gull]

That doesn't answer the question

Given that D is the midpoint of AB, what can you determine about AD and BD?

[analog pasture]

idk

still

[hybrid gull]

They are the same. (This can be Googled as well)

What's the relationship between AD, BD, and AB?

What can we say about their lengths

[analog pasture]

so what will i get in this question

as a and d

[hybrid gull]

A and D are points . . . .

[analog pasture]

umm

ok

i still dont get it

so whats the lenght of c and d

[hybrid gull]

C and D are points, they don't have lengths . . . . . . .

You may need to review a bunch

[analog pasture]

like whats the length between them

like the line c,c

d

[analog pasture]

.

can u resolve this for me please

[hybrid gull]

Length CD?

[analog pasture]

yea

[hybrid gull]

Do you know the pythagorean theorem?

If not, you'll have to review it

[analog pasture]

i do but as u know I get numbers mixed up

[hybrid gull]

You should find the coordinates of point D and then the length of CD afterward

[analog pasture]

How tho

[hybrid gull]

You can find the coordinates of point D by using the midpoint formula

[analog pasture]

whats the midpoint formula

[hybrid gull]

Once you've found the coordinates of D, then you can use Pythag with C and D

[analog pasture]

bro can u just pls tell me

I dont get it

[analog pasture]

but pls

but like with workinf

so I understand plssss

[hybrid gull]

I'm telling you how to do it - you want me to not respond?

[analog pasture]

no like

[halcyon tulip]

What abt working? He sent you formula too, you can atleast do efforts to plug in values

[analog pasture]

what are the valuesssss

idk

Im learnig fr

idk

how to do it my lifes frustrsting af

i can't read or write stuff

so I get bullied its hard I just wanna look smart for once

[halcyon tulip]

Okay we are here to learn something ( looking smart doesn't help)

[analog pasture]

r u ready to help me learn then??

[halcyon tulip]

Okay here it says point D is the mid point of line AB

[analog pasture]

itll take super long

[halcyon tulip]

And you are given coordinates of AB

[analog pasture]

yea

i have a and b

[halcyon tulip]

Here is your formula to find mid point

[analog pasture]

where do I plug it in

[hybrid gull]

Thank you.

Thank you.

[halcyon tulip]

Let coordinates of A be (x1, y1) and coordinates of B be (X2,y2)

[analog pasture]

ok

imma try now

[halcyon tulip]

[analog pasture]

i got - 0.5 and 3

Is it right??

[halcyon tulip]

Yup

Good work

[analog pasture]

then c and d

the length

soo

how do i plug this in

[halcyon tulip]

Now we have to find length of CD

Do you know distance formula?

[analog pasture]

umm idk

maybee

2d or 3d?

[halcyon tulip]

2d

[analog pasture]

then do I put the same values as before

for x,1 and y^1

[halcyon tulip]

If you are given two points, how will be determine distance between them using their Cartesian coordinates(

[halcyon tulip]

Nope that formula won't work here

[analog pasture]

oh ok

different formula

but same values right?

[halcyon tulip]

Nether same values

[analog pasture]

oh so we just go d value throught he midpoint

and we have c

so its easy now

right?

[halcyon tulip]

Here you can take any one end of line as x1,Y1 and other one as X2,y2

[analog pasture]

is it like that

[halcyon tulip]

Yeah

[analog pasture]

less go

thanks

[halcyon tulip]

No problem

Tho you need to work on your basics, so start with Khan academy, just a suggestion, would help

[analog pasture]

i got

this

5.590

is it right??

yoo hoi

Am i right?

[halcyon tulip]

,w calc √(5.5^2+1)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by hoi#0323

[analog pasture]

les go

[halcyon tulip]

Yeah you are

[analog pasture]

nice

so i have another question

is that fine

[halcyon tulip]

^

It's fine to ask doubts, but you gotta learn first then ask.

[analog pasture]

ok

[halcyon tulip]

Yup

[analog pasture]

Point E is a median that bisects line AC, find the value of m and n if E is expressed a (3m,n/2)

so what does this mean

[halcyon tulip]

What is a median

[analog pasture]

the line segment from a vertex to the midpoint of the opposite side

so what formula do i use here

[halcyon tulip]

That's y I said first look it up in your textbook or google

[astral ivy]

Wait

[analog pasture]

so if n is even or odd

[astral ivy]

point E is a median

[halcyon tulip]

It can be both

[analog pasture]

so 3m x n/2

will give me the median

[halcyon tulip]

Nope

[analog pasture]

oh then how

[astral ivy]

I don’t understand, it says point E is a median

Isn’t a median a line segment, not a point

[halcyon tulip]

https://www.khanacademy.org/math/geometry-home/geometry-coordinate-plane

[analog pasture]

soo

umm can u tell me the formula so i can try plsssss

[astral ivy]

Do you have the coordinates for A and C

[analog pasture]

yea

[astral ivy]

What about their midpoint

[analog pasture]

-0.5 and 3

[astral ivy]

Do you have those coordinates

Awesome

So they tell you (3m, n/2) = (-0.5, 3)

Does that make sense

[analog pasture]

yea

so i multiply -0.5 x 3

and 3/2

[astral ivy]

Why, no no

3m equals -0.5

So m = -0.5/3

[analog pasture]

oh

[astral ivy]

Similarly n = 6

[analog pasture]

ooh

[astral ivy]

Right?

[analog pasture]

umm

yes

[astral ivy]

Do you get it or nah

[analog pasture]

so n= 6

and

[astral ivy]

Well m is -0.5/3 which equals -1/6

[analog pasture]

yea

that what i got

[astral ivy]

Cool

[analog pasture]

so thats it

[astral ivy]

Yeah you’ve got m and n

That’s all there is to it

[analog pasture]

damn so easy

[astral ivy]

Haha yup

[analog pasture]

so now

centroid

he three medians of a triangle intersect in a single point called the centroid. Find the Centroid of this triangle.

so how is this done we have all the values

abcd

[astral ivy]

Wdym

You have all the values

The coordinates of the three points?

[analog pasture]

yea

3 points

[astral ivy]

Hm

[analog pasture]

so what do we consider the first point

[astral ivy]

That’s an interesting question

[analog pasture]

ik the formula

[astral ivy]

Ok what are the coordinates of the points

(These are the vertices of the triangle, correct?)

[analog pasture]

yes

so the a is point 1 right?

[astral ivy]

Sure

Wait why do you have a formula

Throw out the formula that’s lame

Let’s figure this out for real, it sounds fun

[analog pasture]

so I got

1.333 , 2.667

idk

Me dumb

[astral ivy]

That’s point A?

What are the coordinates of A, B, and C?

[analog pasture]

no

point a is

1,5

b is -2,1

and c is 5,2

idk if its right tho

[astral ivy]

Ok

Let’s do this

So if we can find the equation of two medians

Then we can find where those intersect

And that will be our centroid

[analog pasture]

umm

[astral ivy]

What

[analog pasture]

is the centroid

1.333 , 2.667

this??

[astral ivy]

Idk lol

Why don’t we figure it out

[analog pasture]

so its an isoscelese triangle right?

im more curious bout that lmao

[astral ivy]

Maybe

[analog pasture]

or scalene

[astral ivy]

Not really sure tho

It doesn’t matter anyway

[analog pasture]

this is scalene right?

or equilateral

idk

[astral ivy]

That’s like way off scale lmao

[analog pasture]

like yollo it

like is it tho?

according to values

[astral ivy]

Those are the points when you draw them

[analog pasture]

oh

so scalene

lmao

[astral ivy]

Yeah probably

[analog pasture]

less go

[astral ivy]

Lol

[analog pasture]

I knew it

[astral ivy]

Ok so

[astral ivy]

Do you get this reasoning here

[analog pasture]

yea

i do

[astral ivy]

Ok

[analog pasture]

thank u0 ur so smart

like damn

An altitude is a perpendicular line dropped from one of the vertices to the opposite side. Here, AM is an altitude of ∆ABC. Find the Equation of AM.

[astral ivy]

Bruh what

We’re not done lmao

[analog pasture]

yessirski

lmao

[astral ivy]

Ok

[analog pasture]

I have 8 more to go

[astral ivy]

So let’s find the median for B first. Point B is at (-2,1) and intersects the midpoint of A(1,5) and C(5,2).

Jeez

Ok so we need to find the midpoint of A and C, which is easy

[analog pasture]

yea

it is thats the easiest part of this

lmaop

[astral ivy]

It’s just (3, 3.5)

[analog pasture]

fr

[astral ivy]

Lit

[analog pasture]

like srsly

I think I got it right

[astral ivy]

So our line goes through (-2,1) and (3, 3.5)

The slope is 2.5/5 = 1/2

[analog pasture]

yea ik that

part

[astral ivy]

So using point-slope form the equation is y - 1 = 1/2(x + 2), which is y = 1/2 x + 2

Cool so that’s the median for B

Now let’s do C at (5,2) going through the midpoint of A and B