help-10

[pearl nymph]

fr bruh

i wrote

[timid silo]

dude i dont know how to

[pearl nymph]

2 pi rh + 2 pi r^2 = s.a

#help-15

go there

talk there

and wait for help

[raven spire]

Yeah ^^" get your s.a. right ✓

[pearl nymph]

ok i got it then

ok now for my derivative

i got

[raven spire]

Now, write S.A. in terms of one variable

[pearl nymph]

oh i already did all that stuff

[raven spire]

show me

[pearl nymph]

h = 8/(pi * r^2)

plug that into the equation im minimizing

and when simplified i get

16/r + 2pi*r^2

so thats my final equation of S.A

and next i get the derivative

can you confirm taht is correct

[raven spire]

(@_@;)

[pearl nymph]

what

did i do sum wrong

[raven spire]

$S(r) = \frac{2(\pi r^3 + 8)}{r}$

[warm shale]

Ansh

[raven spire]

nope it's correct

[pearl nymph]

ok cool

ok from there

the derivative i got is

-16/r^2 + 4pi *r = S.A'

[raven spire]

lastly what's the third equation!?

[pearl nymph]

what

[raven spire]

hmm

[pearl nymph]

oh the derivative

well thats what i got

[raven spire]

well

S' = 0

._.

[pearl nymph]

wat

howd u get that

[raven spire]

R u high!? lmao

[pearl nymph]

nah this just doesnt make sense

[raven spire]

Minimum or maximum occurs when first derivative is 0

[pearl nymph]

yes i know

so you plug in 0 to find the critical points

[raven spire]

obv

[pearl nymph]

but im having trouble

finding the critical points

[raven spire]

HOW EXACTLY

[pearl nymph]

ok so

through simplification

ive gotten to

[raven spire]

there's only 1 critical point

[pearl nymph]

4(-4/r^2 + pi*r)

[raven spire]

= 0

[pearl nymph]

im not quite sure how to make that portion in parentheses = 0

yes correct

im not sure how to make it equal -

0*

[raven spire]

bruh equate to zero!?

[pearl nymph]

i am

oh wait

1 sce

[raven spire]

$-\frac{4}{r^2} + \pi r = 0$

[warm shale]

Ansh

[raven spire]

⁉️

[pearl nymph]

would you

move pi*r to other side

so its

• 4/r^2 = - pi*r

and then simplify from there..?

[raven spire]

obviously

since we're equating to zero

who'd want to factorize that b.s.

[pearl nymph]

true

1 sec lemme figure it out

is it

cbrt(4/pi)

is that the crit pt

@raven spire

[raven spire]

oh srry.. I meant: except possibly you :o

Since you'd rather figure the c.p. on one side than use the equation

[raven spire]

and yes.

[pearl nymph]

ok so what do you do man

oh lets go

lets fucking go

[raven spire]

I just equate to zero and get the critical point rather than messing with only one side of the derivative

[pearl nymph]

ohhh ok fair

thats a good strat

@raven spire thx for the help

i preciate it

[obtuse pebble]

@pearl nymph Has your question been resolved?

[obtuse pebble]

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[shy jasper]

Find the volume of the solid whose base is bounded by the given graph and the cross sections perpendicular to the x-axis are squares. a) x^2+y^2=9

[shy jasper]

hello! i'm not quite sure what the question is talking about. what does it mean by cross sections perpendicular to the x-axis are squares?

is it like riemann sum?

[brave bramble]

A cross section is the 2D shape made by cutting your solid

Like, if you look directly into the cut

So any cut will give you a square cross section

[shy jasper]

ah i see

so how would i apply that to this problem

x^2+y^2=9 is a circle

[brave bramble]

So the base is a circle, but a vertical cut gives a square cross section

Definitely an odd solid, but it is possible

[shy jasper]

haha i guess i just cant wrap my head around it

[brave bramble]

It's kind of like a semi-sphere except it has two corners on the top

[shy jasper]

so if i want to find the area

[brave bramble]

And the walls are vertical

[shy jasper]

i find the integral of sq. rt. (9-x^2)

but then where does the square come in...

[brave bramble]

So area of a square is the square of the side length

[shy jasper]

yes

[brave bramble]

And the volume of the solid is the integral of "all such areas"

[shy jasper]

uh huh

[brave bramble]

So, if you take a cut at x, what's the area of the cross section?

[shy jasper]

x^2

?

[brave bramble]

x is where we're cutting, not the length of the side

Though it is definitely related

[shy jasper]

(9-y^2)^2

LOL thats probabaly really wrong sorry

[brave bramble]

You're on the right track. Good intuition, the height of the circle is exactly what we need

,w graph sqrt(9 - x^2)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kaynex#7520

[brave bramble]

Basically that's half of the length of the square, no matter where we cut

[shy jasper]

is it only half?

[brave bramble]

The square's length is given by:
2√[9 - x²]

The area of the square is then:
4(9 - x²)

Finally, the volume is given by:
∫ 4(9 - x²) dx

[shy jasper]

can i ask why it is half

[brave bramble]

Nice picture of the solid btw, where's that from?

[shy jasper]

i just found it on google 🙂

[brave bramble]

The graph I made is only half of the base, since I made a semi-circle

The whole base is the whole circle

[shy jasper]

OHHHHH

i get it now

this makes a lot of sense

that helps a bunch

thank you so much

[brave bramble]

Np, feel free to ask if you have anything else!

[shy jasper]

okie imma try solving this!

haha sorry i have another question

what would the intervals be?

would it be [-3, 3]?

[obtuse pebble]

@shy jasper Has your question been resolved?

[shy jasper]

.close

[obtuse pebble]

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[obtuse pebble]

Please don't occupy multiple help channels.

[spare oracle]

<@&286206848099549185>

[gilded needle]

What is your question?

[spare oracle]

fill in the blank

part 2 of 3

[gilded needle]

What do you think it should be? Which factors have you not yet accounted for with the parts that are already filled in?

[spare oracle]

i dont really know

i tried x^n, but that was wrong

[gilded needle]

There's also a 1/x factor, where did it go?

[spare oracle]

and also, after putting (14/9x) into the equation, the denominator became 9n!

yea i dont know where it went

i dont know where the x in the denomionator went

[gilded needle]

Can you combine (1/x) with x^n?

[spare oracle]

if you have

14 * x^n

does the n get distributed to the 14

making it 14^n?

i dont think so ....

[gilded needle]

No, that would be true if it was (14 * x)^n

[spare oracle]

yea okay

[gilded needle]

But with 14 * x^n, the n is only applied to the x.

[spare oracle]

ok

the x's cancel each other

thats how the x in the denominator disappeared

[gilded needle]

OK, and what are you left with?

[spare oracle]

im left with just 14

[gilded needle]

When you divide x^n by x

[spare oracle]

in the numerator

[copper latch]

Nope

[warm shale]

Deep Hariya

$\frac{x^n} {x} = x^n * x^{-1}$

[copper latch]

$\frac{x^n} {x} = x^n * x^{-1}= x^{n-1}$

[warm shale]

Deep Hariya

[copper latch]

Get it?

[spare oracle]

o yea

because when you're dividing exponents of the same base, you subtract

okay

[copper latch]

Get it?

[spare oracle]

yup

.close

[obtuse pebble]

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[spare oracle]

tysm @copper latch

[obtuse pebble]

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[errant grove]

I got Q = (7,11) for question C but when I use that for question D, i dont end up with the same lenght

[obtuse pebble]

@errant grove Has your question been resolved?

[obtuse pebble]

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[fathom harbor]

i havent learned about this "mod" thing yet and my teacher still told me to find the value of this equation

[fathom harbor]

i dont know what is "mod"

cant seems to find the answer on the internet anywhere

[royal basin]

is that a screenshot of the question exactly as it was given to you by the teacher

[fathom harbor]

yeah

[royal basin]

cause this seems not to make much sense at all

[fathom harbor]

how??

[royal basin]

is that "how??" as in "how does this not make any sense??" or "how do i solve it??"

[fathom harbor]

how does this not make any sense??

also idk how to solve it since i havent learned this

[fathom harbor]

both i guess

[royal basin]

well ok like, assuming mod is meant in the operational sense, i.e. a mod b is interpreted as "the remainder of a on division by b, lying between 0 and b-1 inclusive"

then 6 mod 28 = 6 and 32 mod 431 = 32

so you have 6 + 32 = x + 7

[fathom harbor]

uh

ok

[royal basin]

which just makes this an incredibly obtuse way to write down a simple linear equation

[fathom harbor]

um

idk

[fathom harbor]

so this maen 38 = x + 7

so x is 31??

[royal basin]

if you're so desperate for an "answer", then that'd have to be it.

[fathom harbor]

ok ill tell my teacher

1 minute

brb

wtf

she says its wrong

[timid silo]

The mod does nothing cause the number on the right is larger then the left

[fathom harbor]

i am confused

[timid silo]

Ikr

[fathom harbor]

why is the answer wrong

bruh

um

my teacher told me the answer is 0

wtf

[royal basin]

so your teacher is either unable or unwilling to communicate what she wants from you.

or she's intentionally setting you up for failure.

[fathom harbor]

wha

im a failure

my life

so

is the answer "0" possible

like

in any way

that u can do this

and get 0

[timid silo]

nope

[fathom harbor]

wtf

my teacher liar

im reporting her to the principal

[royal basin]

just to be clear, i was not calling you a failure and did not intend for my message to be read as such.

[fathom harbor]

ok cool

ty for help

[timid silo]

if if u reverse 28 % 6 | 431 % 32
still u cant

[fathom harbor]

principal time

.close

[obtuse pebble]

Channel closed

Closed by @fathom harbor

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[fathom harbor]

.reopen

[obtuse pebble]

✅

[fathom harbor]

good news

[royal basin]

since you asked so brazenly: no

[fathom harbor]

the teacher

is getting fired tomorrow for teaching false stuff

[timid silo]

why be so noob and complain

[fathom harbor]

yayyyyyyyyyyyyyyyyyy

[fathom harbor]

wut

she is getting fired tomorrow

ok thats all

[timid silo]

lol stop making this kind of shit up and close the channel Lol

[fathom harbor]

what

she is getting fired

do u not believe me

[timid silo]

Wow thats great!

[fathom harbor]

yes

[timid silo]

but very unfortunate that I didnt ask

[fathom harbor]

no need to be rude

[timid silo]

anyways have a bad day

[fathom harbor]

u have a good day

byeeee

.close

[obtuse pebble]

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[lethal grail]

5x(y-3) - 3xy - 3y(x+3)=

[lethal grail]

so yea

i am not sure on how i should solve this

i thought

it would be 5xy-15x-3xy-3yx+9y=

but then i dont even know if i got this right

and i cant make it up in my head

[gloomy trellis]

After adding +15x to other side you can factor out y

[lethal grail]

What

[gloomy trellis]

You can solve for y.

2xy-15x+9y=0

Add 15x to other side

2xy+9y=15x

Factor out y

[lethal grail]

How does that work

it makes no sense how that would be 6x?

[gloomy trellis]

??? 6x?

[lethal grail]

?

[gloomy trellis]

Oh my bad

[lethal grail]

isnt 2xy just 6x then?

[gloomy trellis]

I didn't even saw 3yx lmao

[lethal grail]

it makes it so much harder tbh

[tulip kestrel]

You want to seperate the variables

[lethal grail]

how do i do that then

[tulip kestrel]

You can do this by using the distributive property of addition and multiplication

Lets say for example you have 2xy +3x+ 4y

=0

[lethal grail]

yea

so i seperate 2xy to x and y?

[tulip kestrel]

Lets use the commutative propertie to rearrange the terms

[lethal grail]

what words are you using lmao

[tulip kestrel]

commutative propertie is

a+b=b+a

basically you can rearrange the terms because that wouldnt change the result

so with rearrangement

2xy +4y +3x= 0

[lethal grail]

but often of the times i mess it up with the "+" and "-"

[tulip kestrel]

what do you mean

[gloomy trellis]

Xy and yx same

[tulip kestrel]

x*y = y*x

commutative property but then with multiplication

[lethal grail]

ahh i got it now

my teacher helped me

.close

[obtuse pebble]

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[obtuse pebble]

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[long roost]

$x_{1,n} = 1000x_{3,n-1}\ x_{2,n}=0.02x_{1,n-1}\ x_{3,n}=0.05*x_{2,n-1}$ did i get the right difference equations for this?

[warm shale]

fall

[obtuse pebble]

@long roost Has your question been resolved?

[long roost]

<@&286206848099549185>

[obtuse pebble]

@long roost Has your question been resolved?

[obtuse pebble]

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[long roost]

.reopen

[obtuse pebble]

✅

[long roost]

Do my equations look right for the question?

[jolly ginkgo]

Seems about right

[long roost]

ah thanks

time to turn it into a matrix and get some eigenvalues

[obtuse pebble]

@long roost Has your question been resolved?

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[obtuse pebble]

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[restive turret]

shouldnt it be -x^3 in the fourth line

im pretty sure this solution is wrong because if you simply use the calculator you get a different answer

[obtuse pebble]

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[obtuse pebble]

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[lost spindle]

Suppose g is an even function and f is any function. Show that "f o g" is an even function.

[raven spire]

welp

what's an even function?

[worthy comet]

f is even if f(x)=f(-x)

[lost spindle]

I wrote this down

[raven spire]

right

✅

[lost spindle]

It's prolly not the right convention

[raven spire]

nah adding a couple lines introducing f and g would've been okay but

the math part's there

[lost spindle]

so it seems reasonable?

[raven spire]

mhmm

[lost spindle]

is that a yes lmao

[raven spire]

yeah

[lost spindle]

aight

.close

[obtuse pebble]

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[timid silo]

I’m confused on how to do this

[timid silo]

,rotate

[balmy mortar]

what have u tried

any ideas

@timid silo

[timid silo]

Well

Oh couldn’t find a root that worked for both the numerator and denom

[balmy mortar]

this is not about roots

[timid silo]

No?

[spiral maple]

No.

[balmy mortar]

If I give you a y value

can you give me the x?

That is what the question wants

[timid silo]

Ah, so inverse

pls help me in help 5

[balmy mortar]

indeed

[spiral maple]

Be patient.

[timid silo]

I got to 2xy-1=-4x but I don’t know how to continue

When finding the inverse

[spiral maple]

finding inverses:
Swap x and y
solve for y.

[timid silo]

That is what I was doing

[spiral maple]

So.... keep doing it then

"solve for y."

[timid silo]

The double variable

In one term

I don’t know how to proceed with that

[spiral maple]

get y=

like solving any other linear equation

[timid silo]

No

I’m getting x=

I solve for x in terms of y

[spiral maple]

ok you didn't switch x and y.

[timid silo]

And then swap

[spiral maple]

the order of those steps don't matter but sure

How would you solve a linear equation

[timid silo]

Solve for the variable

[timid silo]

I don’t know how to move the 2x to the other side

[spiral maple]

subtract from both sides...

[timid silo]

If I multiply or divide, I still have an x

[spiral maple]

again, like any other linear equation

[timid silo]

Ah

Let me try

[spiral maple]

The process of isolating for a variable doesn't magically change like you think it does.

[timid silo]

Now I can’t get rid of the y

Oh wait

I think I have it

I got the inverse

What do I do with it?

[spiral maple]

range of f is the domain of its inverse

[timid silo]

Ok

[spiral maple]

so find the values not in the range of f

[timid silo]

How can I find those values

Without randomly trying things

[spiral maple]

...

[spiral maple]

.

[timid silo]

Domain of y I think is all real numbers

[spiral maple]

Domain of the function is clearly not all of R.

[timid silo]

No

I don’t know

You are right

So 1/2 is not in the range of the original function?

It was wrong

[spiral maple]

Yeah

[timid silo]

I don’t know what to do

[spiral maple]

what did you get for the inverse......

Or is posting your work still something you're adverse to?

[timid silo]

y=(-3x+1)/(2x+1)

[spiral maple]

yes, so what's not in the domain of the inverse?

[timid silo]

-1/2

[spiral maple]

yes.

so what not in the range of the original function?

[timid silo]

-1/2

It worked

Thanks

[balmy mortar]

Remember what you want to do in the original question. I ask you to find an x for my y. When is this not possible?

^ just so you can make sense of this entire process

[timid silo]

When the root is the same for both the num and denom

.close

[obtuse pebble]

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[balmy mortar]

eh?

🤔 no i think ur confusing roots

[spiral maple]

"This was the answer last time, so it must be the answer this time, cause every question is the exact same"

[obtuse pebble]

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[mellow crane]

Hello, and thanks in advance for helping
TL;DR
I have a group of points, and need to find circles with radius r that have x points inside it. How do I find these circles?
Context:
I'm working on a project for a simulation of people, cars, and other entities, and need a function to determine an area where the density of entities is above a certain value; for example, Find where 3 people are within 3 metres of each other, and then put a ball on the place so they are all inside the ball. Input radius = r, input amount of ppl = p
For this, my approach is to find possible areas first, then determine the centre point of the circle.
Finding possible areas:
I think of looking around each person and see if it can find other persons in a radius of r. These build possible groups where I then can try to find an area inside.
Finding point of circle:
This is the tricky part, and the one my question entails.
Solution attempt and also problem:
Within the area where I suspect a possible circle:
I am thinking of using the intersection of circles, gradually adding the circle of a person to the already processed group of circles, until I either can't add the circle because there would be no intersection, or every circle has been added. The problem then remains in determining the area of the intersection. Once I have the area, I can just use the middle point or something like that. But I don't know how to describe the area on the coordinate system, and then keep using it for potential intersection.
Alternative:
The alternative is to just see if all the circles intersect, and then bruteforce my way towards it once I know a solution MUST exist. As in, I create a circle, and slightly nudge it until it finds the point. This is bruteforce and inefficient.
I am open to other implementations, this is just what I thought of during the past hour(s)

[mellow crane]

There is also a problem with finding the radius around the people

Because using the radius of the circle means that I might miss things like this

And using 2r I might have too many circles

[unique solstice]

You could do it entity by entity ig

[mellow crane]

This is why I need to find the intersection of the circles after this initial guess

[mellow crane]

That is my current attempt. Yes.

The problem is that I need the intersections and I don't know how to determine that area

[unique solstice]

I'd just use the distance

If it's less than your radius sample size thing then +1

Then see if numInside/size is worse than max dens

[mellow crane]

What do you mean

I'm sorry, I don't think I follow

Are you saying to uhh

Split up the map into blocks based on the radius

Then check the amount of entities in each?

Or are you saying to do distance around each entity

Because that's basically what I'm trying to do here but I don't know how to calculate the intersection of the circles based on the entities that are out of distance, but still within a possible area

center M for r cannot be determined unless I create triangle OR

Draw a circle around each entity

Find where every circle intersects

And choose a point from the intersection

I just don't know how to calculate that intersection, and am asking if i.e. you know any way to calculate it

Because suddenly there are 3 circles instead of 2

Added obligatory r

[glossy ibex]

look into BVHs and quadtrees

[mellow crane]

What does BVHs stand for? I'm getting unrelated google results

[glossy ibex]

https://en.wikipedia.org/wiki/Bounding_volume_hierarchy

this would allow you to search efficiently for bounds with x points

[mellow crane]

Looks promising

I need time to read through stuff

Though on further thinking... A bit scary, because the entities are moving

So I'd need one where you can insert and remove relatively fast

[glossy ibex]

yes and thats one of its strengths as well

[mellow crane]

No actually

Lemme look

[glossy ibex]

since things dont move very far per frame

this is common for resolving collisions in physics sims

[mellow crane]

It looks promising

I'm just still unsure about the actual implementation

From the way I understand it

You set a bounding shape, i.e. a square

I guess that's what you use the quadtree for

To determine the squares and find squares with entites inside

[glossy ibex]

you can construct a bounding sphere around N points by (arbitrarily) choosing a center C, sorting all points by distance to C and choosing the Nth as the radius for the sphere

[mellow crane]

I mean I think we can also do squares, I would have to worry less about circles intersecting then

[glossy ibex]

absolutely

so you want a box that contains N points? i think BVH will serve you well

[mellow crane]

Yeah, except for the BVH it doesn't look like they save the distance themselves

THey are just sorted based on distance

https://www.scratchapixel.com/lessons/advanced-rendering/introduction-acceleration-structure/bounding-volume-hierarchy-BVH-part2 I skimmed through this

[glossy ibex]

do you want a sphere or box?

[mellow crane]

Whatever is easier to implement / run

I'm still worried about performance

But I think this is already more efficient than my previous attempt

[glossy ibex]

a box is better

its more compact and easier to work with

[mellow crane]

This does look pretty good. I just am worried that the map is too big

Ya, I think this is solved for now

Thank you very much!

[glossy ibex]

np

[mellow crane]

Completely forgot about this in the context of the other thing

Wanna chat a bit or should I close now

[glossy ibex]

bvh doesn't care how big your map is, only how many objects there are

[mellow crane]

Ok, means I still slightly misunderstood it but I now have somewhere to look at

[glossy ibex]

its great

[mellow crane]

And do research and ask ppl about

[glossy ibex]

u can close

[mellow crane]

Thanks again!

.close

[obtuse pebble]

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[wicked cedar]

Can someone help me with this

anyone their?

.close

[obtuse pebble]

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[spring vale]

Hello

[spring vale]

Find two functions f and g such that ( f g) (x) =h(x)

a) h(x)=(x-3)^3

[cyan pagoda]

what does the composition f(g(x)) mean?

like in words

[spring vale]

Does that help?

[cyan pagoda]

no

im asking you what does f(g(x)) mean

in words

[spring vale]

Am counfused sorry

[cyan pagoda]

im asking you to tell me what happens if i put in the input x in f(g(x))

f o g means f(g(x))

[spring vale]

.close

[obtuse pebble]

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[main cargo]

not a question from there but a general question

e.g for b

distribution Y, what would the new expectation be?

i know that var(2x) = 4var(x) so ik the answer

so for distribution Y

would the expectation be 2*expectation(x)

do 1/6(n^2-1)

[tardy epoch]

Can you prove it?

[main cargo]

oh wait i think it would be

it would be 1/n sum from 1 to n of 2r

right?

which would just be 2 x e(x)

[tardy epoch]

Right

[main cargo]

ok so for part 3

expectation(x) = n+1/2

so for n=100

expectation(x) = 50.5

so expectation of Y should = 101 right?

mark scheme says 57.73 though idk where they got that from

[tardy epoch]

this is true only for $X = r$ and $2X = 2r$

[warm shale]

riemann

[main cargo]

i dont understand what that means

[tardy epoch]

Your $Y$ is a little more complicated

[warm shale]

riemann

[tardy epoch]

$X = {1,2,3, \ldots, n}$ Your statement would be true for $2X = {2,4,6, \ldots, 2n}$

[warm shale]

riemann

[tardy epoch]

But your $Y \neq 2X$

[warm shale]

riemann

[main cargo]

oh the -1

so expectation of (2x-1) = 2ex(x) -1 ???

doesn't that mean expectation is 100

oh, as it should be. i read somethign slightly wrong

aha that works

so back to this question

p(100-57.75k <= Y <= 100+57.73k) = 1

so the probability of y being between a number and another number is 100%

which means y is between the lowest value and highest value of the distribution?

which is 1 and 199?

omg

its that easy?

.close

[obtuse pebble]

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[glossy ibex]

Pythagoras gives y

similar triangles gives x and z

[obtuse pebble]

@mint hazel Has your question been resolved?

[obtuse pebble]

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[violet heath]

Hi, I'm not sure if this is the right way to do this, I need to find angle AOC, so I imagine a 360° circle inside the triangle and do some basic math.

[tardy epoch]

feel free to .close

[violet heath]

Alright thanks

.close

[obtuse pebble]

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[rough bough]

(B)

Why is it circular ?

[spiral maple]

cause you follow the slopes

[obtuse pebble]

@rough bough Has your question been resolved?

[obtuse pebble]

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[grizzled nimbus]

There are 10k lockers the first person opens all of them the second person opens every second locker and the third does the opposite for every third locker, how many lockers are opened and closed

[obtuse pebble]

Please don't occupy multiple help channels.

[grizzled nimbus]

<@&286206848099549185>

need help

[tardy epoch]

read

• After 15 minutes, feel free to ping @Helpers.```

[grizzled nimbus]

k

[bitter frost]

the first and second person are just opening lockers?

[obtuse pebble]

@grizzled nimbus Has your question been resolved?

[obtuse pebble]

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[mental grove]

Hello!

[mental grove]

I need help with this

1a and 1b

[nocturne minnow]

Which 1a and 1b?

[mental grove]

the top one :D

calculating missing angles

[mental grove]

hey?

ya vanished :D

[nocturne minnow]

I don't know that

That's why I left

[mental grove]

seriously?

is is that hard?

i asked so many people

no one is able to help

lol

ty tho, tysm

[nocturne minnow]

I don't do geometry

[mental grove]

<@&286206848099549185>

bump <3

[grizzled nimbus]

no also other

ppl

10k ppl

[obtuse pebble]

@mental grove Has your question been resolved?

[random spoke]

I think I can help

[mental grove]

SERIOUSLY?

[random spoke]

maybe idk

with 1a at least

[mental grove]

damn- ty

[random spoke]

so the easiest angle to find first on 1a is the complementary angle to 116 degrees

do you know how to find htat?

[mental grove]

nope

im a moron and its 1 am

[random spoke]

thats completely fair

[mental grove]

ty

[random spoke]

tryna figure out how to explain this, it's been a few years

do you at least know which angle I'm referring to

[mental grove]

i think so

the one

that forms 180 with 116?

[random spoke]

yeah

[mental grove]

alr gotcha

64?

[random spoke]

Yeah

[mental grove]

alrighty

[random spoke]

quick quesiton, what does the angle in the bottom right of 1a say

i can't read it

[mental grove]

82

[random spoke]

Oh sweet it does give you that

[mental grove]

you said on the right

thats 116

sorry :/

[random spoke]

I meant left

[mental grove]

alright

[bitter frost]

I'm invested in this now

[mental grove]

lol

[bitter frost]

my guy anakin has been waiting for over half an hour

[mental grove]

LMFAO

yeah

[bitter frost]

even changed your pfp

[mental grove]

watch an idiot struggle

[mental grove]

my gf forced me to :(

[bitter frost]

I am stuck as well

[random spoke]

sorry its taking me so long, I'm tryna figure it out myself

[bitter frost]

yeah

[mental grove]

I get it man

i get it

no worries, i respect you both gentlemen

[bitter frost]

furthest I got was a = 34 - b
not sure where to go from there

[random spoke]

so I haven't figured out how to solve it yet, but do you know the sum of interior angles of a square

[mental grove]

I DID

I JUST DID

I KNOW WHAT A IS

A IS

180-64

because opposite angles

in an inscribed shape

form 180

[bitter frost]

that's a thing? huh

[mental grove]

right?

[random spoke]

uhhhhhh

i'm not so sure about that one

[mental grove]

i am

search it up lol

[bitter frost]

yeah I did

I never learned that rule lol

[random spoke]

I thought those angles only worked if the lines are parallel

[bitter frost]

since it's inscribed in a circle

that's the kicker

[mental grove]

apparently yes

[random spoke]

OH

I never learned any circle rules

[bitter frost]

yeah same lol

[random spoke]

kinda wack

[bitter frost]

ok 1b

[mental grove]

ye

wait

still the B

LOLOLOL

[random spoke]

Oh B is the easiest part, once you have the other angles

that much I know

[random spoke]

do you know this

[mental grove]

ye

[random spoke]

what is it?

just want to make sure

[mental grove]

counting

sorry

82?

[random spoke]

what

[mental grove]

cus

the other part of b

[random spoke]

If you add all the interior angles (angles inside the square), how many degrees do you get

[mental grove]

360..

[random spoke]

oh

Yeah

[mental grove]

wait listen

[random spoke]

Alright i'm listening

[mental grove]

the other part of the b

is 98

because

180-82

and then

180-98

giving you 82

[random spoke]

i mean

it checks out ig

[mental grove]

alright

now 1b

i hate it already

[random spoke]

i think i'm on to something for this one

[gloomy valve]

notice how there are basically 2 triangles?

which are just rotated by 180 deg?

[mental grove]

ye?

[gloomy valve]

what does that tell you?

[mental grove]

nothing.

[random spoke]

lol

[gloomy valve]

if you rotate a triangle

[mental grove]

i am a dumb piece of useless shit.

[gloomy valve]

does that change the angles?

[mental grove]

idk, does it?

[random spoke]

hey you basically solved 1a by yourself

[gloomy valve]

lol i couldnt solve 1a for some reason either

[mental grove]

LMFAO

i grew a beard

whilst waiting for an answer

[random spoke]

I THINK I GOT IT

[mental grove]

srsly?

[random spoke]

Ok ok so you know how I was talking about parallel lines

[mental grove]

ye?

[random spoke]

do you know the rule for that

[mental grove]

ye ye ye

corresponding

alternating

[random spoke]

Yeah so you got another angle then, the one corresponding with x

like this

[mental grove]

how is that useful though....

[random spoke]

you'll see

this one is wacky

[mental grove]

okay

[bitter frost]

here's something

the lines are tangent right

so that makes them equal

[mental grove]

yep

[bitter frost]

in lenght

[random spoke]

No

[mental grove]

they are tangents

[random spoke]

I considered that, but they don't have to be equal I don't think

[bitter frost]

the picture disagrees 👁️👁️

[random spoke]

hmmm

yeah you right

[bitter frost]

yeah ok so

[random spoke]

well darn, that makes this problem way easier

[mental grove]

;-;

[random spoke]

I was pretty proud of the way I found it out

[bitter frost]

haha

[mental grove]

lmfao

what do you do all day

[random spoke]

me? either games or school stuff

[mental grove]

sit in the math discord server and help other dumb shits like me?

[random spoke]

or friends

Nah, rarely use this

[mental grove]

then im lucky

[random spoke]

Oh don't get me wrong I could use the help

But people don't help with calc 4 all that often

[mental grove]

makes sense

[random spoke]

Do you know how to solve it now

[mental grove]

nope

c = x?

[random spoke]

nah

[mental grove]

;-;

[random spoke]

Ok so sum of angles in a triangle is 180

[mental grove]

yee

[random spoke]

If the 2 side lengths are equal, then so are the 2 angles touching the non-equal side

[mental grove]

whats dat?

[random spoke]

isosceles triangle, it's what you got

[mental grove]

yep

[random spoke]

unless i'm being dumb rn

which actually

[mental grove]

it is.

[random spoke]

i might be

[mental grove]

its isosceles

[random spoke]

yeah yeah it is

alright

[random spoke]

so you can find angle alpha in this diagram (alpha being the weird a with two tails)

[mental grove]

how tf do i find it lmfao

[random spoke]

180 = 52 + alpha + alpha

[mental grove]

oh yeah

right

im a dipshit

sorry

[random spoke]

dw

so you got alpha then

[mental grove]

and c

is 52?

we dont know what c is

so we cant know what d is

[random spoke]

wait how did you find c

nonono

https://media.discordapp.net/attachments/903430332324405288/941468099197149264/unknown.png

go back to this

[mental grove]

ye

[random spoke]

alright

so you know the colored angles

[mental grove]

ye

[random spoke]

so you can find out d

[mental grove]

yep, wait a sec please

64?

[random spoke]

yessir

[mental grove]

is d 64?

YEEEE

FINALLY

alr

now i can get c

53

52*

c is 52

i said it from the start

[random spoke]

uhh maybe idk i haven't done it yet

[mental grove]

I said it from the start

x is c

[random spoke]

lemme verify that

[mental grove]

the answer is right there

the triangle

to the right

is the same

as the inscribed one

i think

someone said it earlier

[random spoke]

uhhhhh

[mental grove]

is that right?

[random spoke]

still working on it

[mental grove]

im pretty sure it is

i still have to write 3 essays

[random spoke]

oh jeez

ok

[mental grove]

and study for a spanish exam lmfao

and a science thing

lol

[bitter frost]

still trucking along?

[random spoke]

he thinks he got the answer

my brain has stopped functioning

[bitter frost]

lmao

[random spoke]

which sucks because i have to take a quiz

[bitter frost]

tragic

hmm I also am supposed to take a quiz tomorrow

[mental grove]

when quiz?

oh

that sucks

[random spoke]

my quiz is whenever I want today

but im planning to take it after this

[bitter frost]

what time is it for ya

[mental grove]

this is a warmup

[random spoke]

6 pm

[bitter frost]

fun

[mental grove]

1 am 13 minutes

[random spoke]

kinda, except nothing I'm doing here is applicable

this was just to pass the time

[mental grove]

tbh

[bitter frost]

mood

[mental grove]

i dont care all that much, i dont like my cousin thaaat much

this isnt even my homework lmfao

[random spoke]

BRuh

[bitter frost]

wait then what even is it?!?

[mental grove]

my cousins homework

[bitter frost]

I-

[mental grove]

and i thought it was complete bullshit

[random spoke]

wyd then, just have them do it

[bitter frost]

I feel betrayed

[random spoke]

yeah

[mental grove]

so i challenged him i could do it faster than him

[random spoke]

bruh

[mental grove]

and it became my homework

;-;

[bitter frost]

this is the most tragic plot twist of the century

[random spoke]

im going to go do my math quiz now

you have fun

[bitter frost]

gl

[mental grove]

you too

[random spoke]

ty

[mental grove]

good luck

I DONT EVEN TAKE MATH LMFAOO

see ya

.close

[obtuse pebble]

Channel closed

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[obtuse pebble]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[outer widget]

how do i do 0,4³

[outer widget]

i know it might be simple but i'm lost

plz help

[idle thunder]

@outer widget Is this $0.4^3$

[warm shale]

sills

[outer widget]

yes

i think

what

[idle thunder]

$x^3 = x \cdot x \cdot x$

[warm shale]

sills

[outer widget]

yes but how do i do 0,4 . 0,4 . 0,4

thats the part i'm lost

[idle thunder]

Multiply normally, ignoring the decimal points.
Then put the decimal point in the answer - it will have as many decimal places as the two original numbers combined.

[outer widget]

so 4x4 then put 0,016?

@idle thunder ?

[idle thunder]

It's to the power of 3

So multiply 4 by itsself 3 times

[outer widget]

yes

ok thx

i know i'm in 9th grade but teachers in brazil are wild

thank you so much

.close

[obtuse pebble]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[gloomy valve]

@lone shore Call the width x and the length y, then convert the two sentences into equations

[lone shore]

so x2 - 150?

Im so confused

[gloomy valve]

perimeter is 2 * length + 2 * width

[gloomy valve]

maybe draw a rectangle and label the sides x and y, for example

[lone shore]

it's not going to help

so 6 will be x and y for the width

but how tf am I going to find the length

if theres no width

<@&286206848099549185>

[obtuse pebble]

@lone shore Has your question been resolved?

[idle thunder]

@lone shore Do you still need help?

[lone shore]

yes

[idle thunder]

Okay

P = 2W + 2L correct?

So you might be thinking

150 = 2W + 2L

We know L in terms of W

Because of how the problem explains the length

the length of a rectangle is 6m less than twice its width

@lone shore

[obtuse pebble]

@lone shore Has your question been resolved?