#help-10

1 messages · Page 505 of 1

timid silo
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A 'nice' function would have f'(x)=0 at critical points

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and (local) minima and (local) maxima are critical points

trim island
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so if we derive the derivate of an e^ax function

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what does that show ?

timid silo
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take the second derivative?

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or the first

trim island
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yes

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second

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and the first actually

timid silo
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Ok, let's talk about continuous (at least twice) differentiable functions here

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the first derivative is positive when the function increass

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and negative when it decreases

trim island
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yep

timid silo
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0 when it is flat

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so if you know that your function is, say, quadratic

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then by finding f'(x)=0 you find the tip of the parabola for example

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which is the minimum if x^2 coefficient is positive

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and maximum if it's negative

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can you see that?

trim island
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this is for the 2nd derivative no ?

timid silo
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for the first

trim island
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the first is always = 0

timid silo
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no

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bro

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please talk to your math teacher

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But for now

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what does a 0 derivative mean?

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when it's 0 for all inputs?

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.

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tell me

trim island
timid silo
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okay

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but you said always 0

trim island
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for a quadratic

timid silo
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ok

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forget about quadratics

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for a sec

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think in the abstract

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what does a der = 0 on the entire domain mean ?

trim island
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okok

trim island
timid silo
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ok

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so what type of function is that

trim island
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linear

timid silo
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ok

trim island
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no ?

timid silo
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but more specifically constant

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slope = 0

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it's not quadratic

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well, aside from the degenerate case where all coefficients are 0

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with the constant being anything

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so 0x^2+0x+c

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but nobody means that when they say quadratic in general

trim island
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right

timid silo
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so derivative of a linear function is what

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kx where k is constant

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it's k

trim island
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yep

timid silo
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what about x^2 ?

trim island
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2x

timid silo
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great

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so as you can see the derivative of a quadratic is nowhere near 0 for all values

trim island
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i just remember the dy/dx of x^2 = 0 is something that we put in to find the minimum/maximum point

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dy/dx is not = 0

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whoops

timid silo
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no

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look

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it's 0 for that specific point

timid silo
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the point is that it's 0 at the tip of the parabola

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could you tell me why?

trim island
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bc the rate of change at that point is 0

timid silo
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graphically

trim island
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a straight line

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linear

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so = 0

timid silo
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ok

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but you just used the definition

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ok

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but what happens around the point

trim island
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it can increase or decrease

timid silo
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more specifically for a parabola

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yeah

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it first goes one way

trim island
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if u go slightly up or slightly back

timid silo
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and then the other

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so if we know this property of the parabola

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and the graphical definition of der

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we can deduce that when der = 0, it's the max/min of the parabola

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which is not necessarily true for other functions

trim island
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so e^2x has no parabola so therefore this does not apply to it

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so what is the derivative of e^2x showing then

timid silo
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the derivative of e^2x is never 0

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as you can see

trim island
timid silo
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it approaches 0 for -inf

trim island
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right, its an exponential

timid silo
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the derivative of this function is itself times 2. and graphically it's exactly what we see

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it just shows that the rate at which it grows is related to the input

trim island
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okai okai

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can i ask u something about functions

timid silo
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but more simply it just means that the function decreases fast to the left and increases fast to the right

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ask

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but then I leave to other questions :))

trim island
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a function can only give u 1 answer

timid silo
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output

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yes

trim island
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so in the sinx and cosx graph

timid silo
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per 1 input

trim island
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is it limited

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in the same way the inverse graphs are

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or no

timid silo
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huh

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I am not sure I understand

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The inverses of sin and cos will have infinite solutions for each input (or no real solutions at all)

trim island
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so the sin cos and tan graphs have 1 output which can have many inputs

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?

timid silo
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correct

trim island
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okai makes sense :3

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thanks

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.close

obtuse pebbleBOT
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timid silo
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bro wait

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just a sec

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I highly recommend reading this slowly

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a function is necessarily injective by definition

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meaning each input has exactly ONE output

obtuse pebbleBOT
#
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timid silo
#

but not necessarily surjective

obtuse pebbleBOT
timid silo
#

.close

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trim island
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dunno what that means

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shall read

timid silo
trim island
#

its not really even something i need to learn for school more out of interest

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thanks

obtuse pebbleBOT
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tardy abyss
#

How can I graph sum of these two vectors without them touching each other? I thought that I could just add the components but if I do that how could I know the initial point of the vector (since the question didn't specify from the origin of the plane or not)?

spiral maple
long sinew
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I remember this from the beginning of the year (In physics)

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You just translate them over

tardy abyss
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So, I could use the triangle law of vector addition, and get something like this?

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To be more specific.

long sinew
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One sec

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Or it might be the other way

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Whatever

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This is how I always did it

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OK yeah I did it right

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@tardy abyss

tardy abyss
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So does it matter which tip I put to which tail?

long sinew
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Yes

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@tardy abyss I haven't done this in a while forgive me, but I think it somewhat matters which one you put to which

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@spiral maple Help me out here lol physics minor

obtuse pebbleBOT
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@tardy abyss Has your question been resolved?

obtuse pebbleBOT
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@tardy abyss Has your question been resolved?

tardy abyss
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I figured I'd just ask my teacher and she said that either tip to either tail would work just fine for solving these. Thanks.

obtuse pebbleBOT
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stable sedge
obtuse pebbleBOT
stable sedge
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is the angle A bisected when we draw median

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from A to BC

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hmm i think no we can not prove ABD ADC congruent

long sinew
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I think not, but it is possible if its like an isosceles triangle where its the angle created by the congruent sides (Also for equilateral triangles)

worthy comet
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in general no: AD is a bisector if AB:AC=BD:DC

raven spire
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which means BC = 0

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which means, your right triangle is a ... uhmm

stable sedge
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sides bisected ratio = sides containing the angle ratio

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i almost forgor

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thanks all

stable sedge
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.close

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wanton kraken
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help

obtuse pebbleBOT
wanton kraken
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In triangle ABC, symmetrical bisector of AC crosses AB at point Q

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Find perimeter of triangle ABC, if triangle QBC = 22 cm and AC = 9

raven spire
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Diagram where?

wanton kraken
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ugh I don't have discord on my phone

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and I use a touchpad

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for drawing

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so it's hell rn

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pls help xD

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I can do a scuffed

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af

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one

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through paint

raven spire
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use pen n paper :O

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how you solving these questions then?

wanton kraken
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AC=9

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P(QBC)=22

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ABC=AC+AB+BC

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AC=9

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ABC=9+AB+BC

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AB=AQ+BQ

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AQ=QC

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ABC=9+AQ+BQ+BC=9+QC+BQ+BC

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PQBC=QC+BQ+BC

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9+22

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ffs

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.close

obtuse pebbleBOT
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trail hemlock
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Hi, can someone explain how this is solved?

trail hemlock
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I tried this for a while now and I just couldn't get it done

tardy epoch
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use trig identity for $\sin^2(x)$ and then use the quadratic formula

warm shaleBOT
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riemann

trail hemlock
tardy epoch
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look in your notes or textbook

trail hemlock
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I'm not studying maths in english

unique solstice
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sin(x)=cos(x-pi/2) would be a trig identity for example

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Not the one you use

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But a trig identity

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Just a rule ig

trail hemlock
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I think ik what you mean, thanks

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i'll try that

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I tried to mess around with it but I got nowhere

pine sail
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No man he meant cosx= sin(π/2-x) is an example but he even said you don't use this one here.

timid silo
royal solar
royal solar
pine sail
trail hemlock
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Oh

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I feel very stupid rn

pine sail
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$sin²x+cosx-sin²x-cos²x=0$

warm shaleBOT
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Sakata Yaksha

pine sail
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I hope you will solve this now by yourself now.

timid silo
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that works, you could have also substituted sin^2(x) = 1 - cos^2(x)

pine sail
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Yes, what I did was more simple Ig but anything works.

trail hemlock
pine sail
#

Nice.

obtuse pebbleBOT
#

@trail hemlock Has your question been resolved?

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obtuse pebbleBOT
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kindred nacelle
#

I don't know how to do these

obtuse pebbleBOT
short spruce
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factor and use zero product property

kindred nacelle
#

alright thank you

#

.close

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jade eagle
obtuse pebbleBOT
jade eagle
#

this is what i’ve done so far but im keep getting stuck and idk what im doing wrong

tardy epoch
#

how'd you get from the top line to the bottom? there should be a summation of $i^2$ term. did you already substitute that formula?

warm shaleBOT
#

riemann

obtuse pebbleBOT
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@jade eagle Has your question been resolved?

jade eagle
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ohhhh was i supposed to do the summation for i^2?

tardy epoch
#

what is (-1 + 6i/n)^2

jade eagle
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that’s when you plug it into f(xi)

tardy epoch
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expand it

main halo
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Hi how do y'all start practicing maths

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like how is the discipline brought

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and what are your study habits

jade eagle
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im confused about the whole process

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<@&286206848099549185>

raven spire
#

Hey sanao

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sorry I keep forgetting the limit definition for definite integral, could you write it for me please?

warm shaleBOT
jade eagle
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here ya go

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@raven spire

raven spire
# jade eagle

tyvm. you might want to redo the whole conversion thing because the expression you've arrived to at the second step itself looks incorrect

jade eagle
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yeah i figured it was wrong but idk what im doing wrong 😬

raven spire
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that's when you try it again. not already start looking for help

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can you spot the mistake in 2nd step?

jade eagle
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the sigma 2?

raven spire
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yeah

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any reasoning why it became 2?

jade eagle
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i distributed the 2 wrong in f(x)

raven spire
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function in consideration here is: 2(x²) + 1 I suppose

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kay

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next mistake is 3rd step

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the sum was computed incorrectly, plus you didn't even expand (-1 + 6i/n)² correctly

jade eagle
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yeah i see where i went wrong

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for some reason idk why i distributed wrong 🤔

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i was following a video to help with a similar problem and they distributed the 2 to the whole thing

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ty for your help tho

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i think i can figure it out if i spend 2 hours on it 💀

#

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obtuse pebbleBOT
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rocky cosmos
obtuse pebbleBOT
rocky cosmos
#

How do I determine the constants A and B?

tired shell
#

think of what numbers sin^2(x) on its own goes between

rocky cosmos
#

We know that sin(x) has the amplitude 1, so the minimum value is -1, and the maximum value is one.

tired shell
#

A stretches that and B changes the height

raven spire
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A scales the min, max value of your function accordingly while B shifts the entire graph upwards by B.

rocky cosmos
#

Okay

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so, to find b, we only put X equals zero, and then isolate the variable b

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y(0) = A sin^2(0) + B

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Sin(0) = 0

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y(0) = A*0+B => B.

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Okay so what does this tell us? that -3 = B?

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So the vertical shift is -3.

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Now how do we find the amplitude?

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Is it ((max+min)/2)?

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In which case we have 1+(-3)/2 = -2

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The way someone else explained it was:

We know that sin (x) will vary between -1 and 1. If we square it, we can think that sin² (x) will vary between 0 and 1, because it can no longer be negative (real squares are never negative) but the maximum can be 1² = 1.
The curve y = sin² (x) thus has the height 1. If we want to influence this, we adjust the function with A. This tells how high your function can be in total. In your case, you want the curve to be 1 - (- 3) = 4 units high, so how much should A be to transform from a function with height 1 to one with height 4?

Then you can very accurately calculate B in the way you tried to do in your comment.

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Anyone could give Give me any advice?

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I didn’t get the part where he says “… you want the curve to be 1- (-3) = 4 units high.”

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Where is that formula from?

obtuse pebbleBOT
#

@rocky cosmos Has your question been resolved?

obtuse pebbleBOT
#

@rocky cosmos Has your question been resolved?

obtuse pebbleBOT
#

@rocky cosmos Has your question been resolved?

obtuse pebbleBOT
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mystic saffron
#

woop#3112

obtuse pebbleBOT
mystic saffron
#

oops

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not that

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im confused on what to do here

crimson berry
#

What is the question

mystic saffron
#

find variables

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i'm trying to use special triangle rules but not working

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do i have to draw some auxillary line?

keen cave
#

Looking at it to see if there a faster way.

mystic saffron
#

i thought that but i don't think we have done systems with exponents.. or does that even matter?

keen cave
#

nope.

mystic saffron
#

i dont think system of equations is the way to do this

keen cave
#

yeah.

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still looking at it.

mystic saffron
#

i cant find any other way

keen cave
#

nvm it system of equation but it just algebra. We have x^2 + y^2 = 15^2, that implies y^2 = 15^2 - x^2. Also notice we also have (18-x)^2 + y^2 = 12^2. The rest follows from that.

mystic saffron
#

i got x=11.25

keen cave
#

yep.

mystic saffron
#

did you get that as well

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ok

#

thanks

#

.close

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inland spoke
#

Hi

obtuse pebbleBOT
inland spoke
#

So for b I got sin (5pi/12)

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Idk if that's right

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and I dont understand what it means by exact form

onyx moss
#

if it’s asking for exact values it wants an answer in radians

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so in terms of pi

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with no trigonometric function

crude cloud
#

Yeah sin (pi-thetha ) is sin thetha

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So sin (pi-7pi/12)

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Will be sin(5pi/6

inland spoke
crude cloud
#

By 12*

inland spoke
#

I did that

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but like how does that make sense

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how is sin(5pi/12)=sin(7pi/12)

crude cloud
#

Yeah that also work .

inland spoke
crude cloud
#

It's sine (pi-theta) so in the XY plane it means that it'll lie in the 2bd quadrant

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Where sin is +

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In the second quadrant sin is + so if u do pi - thetha there will be no changes but if u do sin pi + theta ull get a minus sign.

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Here u need to find the valur of sin(105,°)

inland spoke
long sinew
inland spoke
#

so basically it's the same thing as adding pi/2 to pi/4 to get 3pi/4

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where the sin functions are the same?

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but instead of adding we're subtracting

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doing it in reverse?

crude cloud
#

I got it....u just need to simplify see ...u can write 7 pi/12 as 4pi/12+3pi/12

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Now just appl sin(a+b)

onyx moss
crude cloud
#

Root3-1 /root 8

short spruce
#

why use the bot if you're just making your text a picture lmao

onyx moss
#

my bad

short spruce
#

\sin flonshed

inland spoke
#

so

warm shaleBOT
#

lgargaro

onyx moss
#

😂

inland spoke
#

sin(5pi/12)=sin(7pi/12)

flat anvil
#

if you wanted to show it you could use the additive identity

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of sin(x)

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sin(a+b) = sin(a)cos(b) + sin(b)cos(a)

inland spoke
#

is it when y is the same value

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on both sides

obtuse pebbleBOT
#

@inland spoke Has your question been resolved?

obtuse pebbleBOT
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brisk arrow
#

I have a question

obtuse pebbleBOT
brisk arrow
#

The formula that the math teacher using to calculate students grade is: usual test has the proportion of 30% then test A and test B is 20% and 30% respectively

#

It’s solved

#

.close

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red lark
#

How are irrational numbers not integers?

obtuse pebbleBOT
flat anvil
#

what

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by definition?

obtuse pebbleBOT
#

@red lark Has your question been resolved?

red lark
#

Well no, actually I was watching this video on proving an irrational number, and there they said that irrational numbers are not actually integers.

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That's what got me thinking

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<@&286206848099549185>

sudden fox
#

but all integers could

red lark
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so to frame it in other words, because a and b are not integers, the number is irrational?

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is that what it is?

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@sudden fox

sudden fox
#

hmmm wait a minute

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A real number that can NOT be made by dividing two integers (an integer has no fractional part).
well its not because a and b are not integers, but its because there doesn't exist an a and b that are integers to express the number

red lark
#

ohh wait it makes sense now

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Thanks a lot!

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@sudden fox

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.close

obtuse pebbleBOT
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timid silo
#

How to prove that the areas of the small triangles inside the big triangle are equal to each other?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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novel elm
#

Hello, can anyone help me here <@&286206848099549185>

raven spire
#

After 15 mins?

novel elm
#

Oh sorry

raven spire
#

Lol isn't it a marked quiz or something?

novel elm
#

It is a homework

raven spire
#

Anyways,

#

My hint is to convert it to a form where you'll have an expression in negative x exponents of "5" so that their individual limits all turn 0

novel elm
#

ok

#

.close

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plain basin
#

hello

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

plain basin
#

If 2x + y = 5, then 4x + 2y is equal to _______.

#

pls help me

#

im a highschool student

#

<@&286206848099549185>

worthy drum
#

15 min flew by

plain basin
#

BHAHAAHA

#

pretty much'

#

:/

#

anybody

flat anvil
#

compare the left hand side first off

#

do you notice any relationship between

#

2x + y and 4x + 2y?

plain basin
#

YES

#

4x and 2x

plain basin
#

ARE u there

flat anvil
#

okay

#

so how would you get from

#

$2x + y \to 4x + 2y$?

warm shaleBOT
#

M.E.G. Yottachad

plain basin
#

uhh

flat anvil
#

do you add something? multiply by something?

plain basin
#

add the similar variables i guess

#

2x and 4x

flat anvil
#

no

plain basin
#

since x is 1

flat anvil
#

can you see how 2(2x+y) = 4x + 2y

plain basin
#

oh

#

:/

flat anvil
plain basin
#

WOAH

plain basin
#

i understood

#

this is linear algebra right

plain basin
#

it is 2x=y

stable gale
plain basin
#

wait we can do that

#

just simply multiply numbers out of thin air\

#

yea

stable gale
#

If we multiply that by 2

plain basin
#

4

stable gale
#

U get 4x +2y = 10

plain basin
#

THANKU SO MUCH BRO

#

i love math

#

.close

obtuse pebbleBOT
#
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plain basin
#

luv u no homo

#

.close

obtuse pebbleBOT
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#

@lavish zinc Has your question been resolved?

tardy epoch
#

what's the first order definition?

#

Can you write down $f(x_1, x_2)$? and $\nabla f(x_1, x_2)$ ?

warm shaleBOT
#

riemann

tardy epoch
#

let $X_0 = (a_1, a_2)$. can you write down $f(X_0) + \nabla f(X_0) \cdot (X-X_0)$?

warm shaleBOT
#

riemann

tardy epoch
#

why

tardy epoch
#

and why can't you show it's bounded above by $f(X)$ ?

warm shaleBOT
#

riemann

tardy epoch
#

expand this

tardy epoch
#

,w plot x^2 + xy

obtuse pebbleBOT
#

@lavish zinc Has your question been resolved?

obtuse pebbleBOT
#

@lavish zinc Has your question been resolved?

obtuse pebbleBOT
#

@lavish zinc Has your question been resolved?

night igloo
#

what's D

obtuse pebbleBOT
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night vault
#

hhey

obtuse pebbleBOT
night vault
#

why -6?

#

helloo

bleak nest
#

Because the line falls by 6, and since it is falling it becomes negative

night vault
#

ok so if the line for example... starts att +8 and then ends at -5

#

oh wait i got that wrong...

bleak nest
#

The calculation would look like this: -5-8=-13

night vault
#

ah

bleak nest
#

You always start with the end value and minus the start value

night vault
#

like for exampple, what they did here?

bleak nest
#

They started on a 4 and ended on a -2: -2-4=-6

night vault
#

so you subtract the y's

#

?

bleak nest
#

Yes, and after that you do the same with the x-values and divede them

night vault
#

ohhh

#

its like y-y

#

x-x

#

and then y/x

#

i'v heard that before

#

thank you man

bleak nest
#

When you subtract the end value with the start value you usually note it with a Δ

night vault
#

ok

#

aother thing

#

sorry for bothering pls gimme a sec..

bleak nest
#

alright

night vault
#

here on the graph i showed, y= (0,4)

bleak nest
#

Wdym?

night vault
#

hmmnn

#

is it that i chose a random point on the graph?

bleak nest
#

Yea it can be Any two points on the graph

night vault
#

will it change the answer?

#

any 2 point's who are going to meet together when gone in a rise/run direction

#

i heard that if the upper one is in an order, then the lower one should be in the same order?

bleak nest
#

Give me some time, i need to walk a short distance

night vault
#

oh sorry

bleak nest
#

I didn't mean it to sound harsh, i just needed to get to my destination, before i could get my pc out

#

What do you mean by order? English isn't my first langauge, so i dont know all math terms.

obtuse pebbleBOT
#

@night vault Has your question been resolved?

obtuse pebbleBOT
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snow pewter
#

greetings

obtuse pebbleBOT
snow pewter
#

i have a problem: i am given the equation for a line in the cartesian plane, the x coord of a point A, and the x coord of a point B

#

i need to find the length of the line segment AB without using the distance theorem

#

i cannot use sqrt(Δx^2 + Δy^2)

royal solar
#

can i see the question please

snow pewter
#

it's in italian but here it is

sage geode
#

They already stated the question

royal solar
#

ouch, might need translation

royal solar
sage geode
#

You sure there's a way without using Pythagorean theorem?

snow pewter
royal solar
#

or not

#

what if i found the vector a

#

that travels from one point to another

#

and found the magnitude of the vector

sage geode
#

Yeah, and magnitude is sqrt of sum of squares

royal solar
#

still pythagorean theorem

snow pewter
#

"given the line r of equation y = 2x + sqrt5 and given points A and B such that x_A = 1 and x_B = -3, calculate the length of the line segment of AB without using the formula for the distance between two points"

royal solar
#

but still not using the distance formula

sage geode
#

Yeah I mean if you consider Pythagorean theorem to be different from the distance formula then do that

#

You could show that visually

snow pewter
#

we never used vectors in math

royal solar
#

y = 2x +c
so delta y = 2 delta x, right?
so what if i found…

#

oh

#

can i still use pythagorean theorem?

snow pewter
#

idk it does use a sqrt there

#

i do know how it kinda works

royal solar
#

and squares?

high lily
#

distance formula is pretty much an application of pythag

snow pewter
#

it factors out Δx

#

but the problem is reasoning it

snow pewter
#

my teacher doesn't really want the solution

#

i need to write down the explanation

royal solar
#

does what i said there make sense???

#

y = 2x +c

#

so change in y = 2 * change in x

snow pewter
#

hold on

#

i did use the deltas there

royal solar
#

yeah

snow pewter
#

but only for the sake of not typing out the whole thing

royal solar
#

but idk how to on mine

snow pewter
#

we do not work with changes

royal solar
#

that’s the only way to find the length of a line,

snow pewter
#

this channel is taken

royal solar
#

use another help channel my friend

snow pewter
#

but if i do it your way

raven spire
#

👀 Hey Hugger

snow pewter
#

how'd i do it

royal solar
#

also, add equation 1 and 2 to 3

royal solar
snow pewter
#

what

#

i'm actually confused

royal solar
#

delta x is literally x1-x2

raven spire
#

mhmm

snow pewter
#

oh i get it

royal solar
#

yeah

snow pewter
#

i get delta y and delta x

#

square them and sum them

royal solar
#

yep

snow pewter
#

and then take the root

royal solar
#

and pythagorean theorem

royal solar
snow pewter
#

in other words, using the distance theorem

#

nope

royal solar
#

no, i’ve not used the theorem at all here. i’ve done it all myself

#

i didn’t need to calculate a single y value

snow pewter
#

first off, look at the solution in the photo

royal solar
#

in distance theorem, you have to individually calculate the y value

snow pewter
#

secondly, it's just as if you calculated the difference of y values

royal solar
snow pewter
#

the distance theorem is both the difference and the delta

#

the one that has two dots on ti

royal solar
#

yeah, difference is delta

snow pewter
#

yeah

#

which is why we had both forms

#

under the name of distance theorem

#

so no, it won't work

#

again, seeing the solution i could just say "factor out x_B - x_A"

royal solar
#

ahh, they’ve done unit vectors. well. same idea

snow pewter
#

but i have to motivate otherwise teacher not happy

#

they what

royal solar
#

yeah, unit vector is like doing Pythagoras to the slope

#

2 and 1 in this case

#

and multiplying that to delta x

snow pewter
#

that

#

makes sense

royal solar
#

yeah

snow pewter
#

yes yes i got it

#

thanks

#

finally

royal solar
#

no worries mate

#

that’s still the same idea

#

but you will come across that again when you get unit vectors

#

@snow pewter close the page if you’re done :))

snow pewter
#

ah right

#

s.close

#

.close

obtuse pebbleBOT
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oblique sage
#

If I have the function f(x)=sqrt(x) and g(x)=x^2 + 4, and h(x) = f(g(x)), is h(x)’s domain XER or no

spiral maple
#

x^2+4>0 so yes

drifting jay
#

No

#

f(x) is sqrt (x)

#

Sqrt cannot take negative values

reef grotto
#

yeah but x^2+4 is always positive

spiral maple
#

tell me when x^2+4<0 @drifting jay

#

for x in R

drifting jay
#

Wait hold on my bad

reef grotto
#

so the domain is all real numbers

drifting jay
#

I was looking at it like independently but they're linked

spiral maple
reef grotto
#

but no complex numbers so it ok

drifting jay
#

Yeah it is XER

night vault
bleak nest
#

No then it doesnt work

#

Then you dont find the difference

obtuse pebbleBOT
#

@oblique sage Has your question been resolved?

obtuse pebbleBOT
#
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true kraken
#

60% of cookies is made sugarfree, 40% is cookies saltfree. 5% of sugarfree is broken and 3% of saltfree is broken

true kraken
#

What are the odds the cookie is broken if 1 is randomly picked

#

Please help

spiral maple
#

it's either broken and sugarfree or broken and saltfree

true kraken
#

I mean what are the odds the cookie is broken in percentages

spiral maple
#

Yeah

true kraken
#

I thought it was 8% but incorrect

spiral maple
#

P(Broken and Sugarfree)=P(Broken|Sugarfree)P(Sugarfree)

true kraken
#

Sugar has a 5% of breaking, Salt has a 3% of breaking

#

Why is it not 8

#

I dontgtet it

true kraken
#

Whats p

spiral maple
#

probability

#

You pick a cookie and want to know the probability it's broken and sugar free

#

therefore it needs to be a sugarfree cookie, and be broken

#

ie probability you get a sugarfree cookie (60%) times the probability it's broken (5%)

#

so 3%

true kraken
#

How did u get 3%

#

What was the way

#

You count

spiral maple
#

Literally just said.

true kraken
#

P(60|5)P(60)

true kraken
#

Did u divide 60 by 5

spiral maple
#

No

#

.6*.05

#

like I said

#

You multiply the probabilities

spiral maple
#

P(Broken|Sugarfree)=5%

true kraken
#

So broken and saltfree is 0.4*0.03

spiral maple
#

yes.

true kraken
#

Which is 0.012

spiral maple
#

yes.

true kraken
#

But how do i calculate if 1 cookie is randomly picked whata the odd of it being broken

spiral maple
#

sum them together.

true kraken
#

0.042

spiral maple
#

Yes.

#

which is 4.2%

true kraken
#

How

#

I see

#

Thanks tho

#

Yeah that makes sense

#

Thx

#

I nearly thought it would be 0.042%

#

So the broken cookie for saltfree is 1.2% right

#

Not 0.012

#

Cuz have to times 100

#

Right

#

Yea

#

Okie

#

.closed

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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crimson charm
obtuse pebbleBOT
crimson charm
#

hey guys can anyone point me in the right direction for this proof?

tardy epoch
#

what's RLM?

#

Does that follow from matrix multiplication?

#

First write down the definition of $\bf{X}$ and then calculate $\bf{X^T}\bf{X}$.

warm shaleBOT
#

riemann

crimson charm
#

RLM is regularized loss minimization

#

yes it does

obtuse pebbleBOT
#

@crimson charm Has your question been resolved?

tardy epoch
# warm shale **riemann**

actually it's probably easier to calculate $\bf{Xw}$ first, then multiply on the left by $\bf{X^T}$

warm shaleBOT
#

riemann

crimson charm
#

@tardy epoch hey just wondering

#

Does a matrix transposed * itself give something special?

#

A^TA for example

obtuse pebbleBOT
#
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tardy epoch
#

.reopen

#

bad bot

obtuse pebbleBOT
#

tardy epoch
obtuse pebbleBOT
#

@crimson charm Has your question been resolved?

obtuse pebbleBOT
#
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tardy epoch
#

Don't ping until 15 minutes after posting question

tardy epoch
obtuse pebbleBOT
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noble berry
#

how do i factor this?

obtuse pebbleBOT
noble berry
#

I can factor like

6x+30 and stuff but htisi s just kinda confusing me

raven spire
#

hey ballerina

#

how do you factor 6x + 30?

noble berry
#

6(x+5)?

raven spire
#

:O

#

then, how would you factorize y + 5xy?

noble berry
#

y(1+5x)

raven spire
#

and.. p - 7p?

noble berry
#

p(1-7)??

raven spire
#

which is -6p (@_@;) but yes

#

so, when you replace p with (3x - 2z), you get: \ $(3x - 2z) - 7(3x-2z)$

warm shaleBOT
raven spire
#

just slightly more intimidating, but you can obviously factorize p - 7p right?

noble berry
#

yesh but now I'm lie confused but not exactly sure what in confused on which makes it harder

raven spire
#

:c firstly, were you able to successfully replace p with 3x - 2z in the factorization of p - 7p?

#

$(3x - 2z) - 7(3x - 2z) \equiv p - 7p$

warm shaleBOT
noble berry
#

wait what-

raven spire
#

hmm? 👀

noble berry
#

what dies replacing have to do with it

nocturne minnow
#

Ansh was showing an equivalent expression

noble berry
#

hows it equivalent?

nocturne minnow
#

I would have said, distribute the 7, combine like terms, then factor

nocturne minnow
nocturne minnow
#

Yes

noble berry
#

I always was to told to just factor them before...

#

so li simplify it then factor?

nocturne minnow
#

It's honestly better to simplify, in my opinion

noble berry
#

so it'd become
-6(3x+2z)?

nocturne minnow
#

Looks like it

raven spire
noble berry
#

says its wrong

raven spire
#

=_=

nocturne minnow
balmy mortar
#

why are there congruences here

noble berry
#

We were learning like factoring by grouping so is that lie another solutoint hats different

raven spire
#

ofc it'd be wrong 🤦‍♂️ you replace "p" with the wrong thingyy

balmy mortar
#

oh nvm

raven spire
#

you were meant to replace "p" with "3x - 2z" and not "3x + 2z"

nocturne minnow
nocturne minnow
noble berry
nocturne minnow
#

You realize that -7 * -2z isn't -14z

noble berry
#

OH

#

so 6(-3+2z)?

nocturne minnow
#

No

#

You made the x disappear, that's the first thing

noble berry
#

wait typo

nocturne minnow
#

Second, factor out -6 instead

noble berry
#

-6(3x+2z)?

nocturne minnow
#

No

noble berry
#

-6(3x-2z)?

nocturne minnow
#

Yes but also notice the similarity that Ansh was demonstrating about

noble berry
#

I'm still kidna confused about that

nocturne minnow
#

p = (3x - 2x)

#

So then p - 7p

#

Which was then -6p

#

And because p = 3x - 2z, replace that back in

noble berry
#

Oh that makes more sense

nocturne minnow
#

That's why they were equivalent looking

noble berry
#

thanks for the help ^^

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @noble berry

Use .reopen if this was a mistake.

noble berry
#

.reopen

obtuse pebbleBOT
#

noble berry
#

just relized I have this, is there a msarter way than multiplying and adding/subtracting

spiral maple
#

factoring probably

noble berry
#

like facorte the 2.7*6.2 or the 6.2-9.3 ones?

nocturne minnow
#

Multiplication takes priority

#

So you can't do 6.2 - 9.3

#

You can move terms around because addition is commutative

noble berry
#

so should I factor the multiplication sets first?

nocturne minnow
#

Move the terms around so you can them factor the common term

noble berry
#

wdym?

#

since theres one addition

nocturne minnow
#

No, there's not

#

There's multiple additions

noble berry
#

I got it to here but I don’t know any common factors for the second parentheses

nocturne minnow
#

You realize that the common factor is 1.2

#

That makes it easier

#

Because then that becomes a 1

#

Also, why did you factor it per number?

#

It's similar to a * b - d * a = a(1 * b - d * 1) = a(b - d)

obtuse pebbleBOT
#

@noble berry Has your question been resolved?

noble berry
nocturne minnow
#

I was referring to the first set

#

You could have factored 1.2

noble berry
#

Oh ok

#

For the second is there a commen factor? Other than 1

nocturne minnow
#

Yes

noble berry
#

I’m just going to do it the longer way since factoring it is making brain go brrr and confuse itself rn… welp

nocturne minnow
#

It's just factoring the common term

#

If you can factor p - 7p or -9.3p - 2.7p, it's the same process

obtuse pebbleBOT
#

@noble berry Has your question been resolved?

obtuse pebbleBOT
#
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magic cairn
#

how can i determine slope of tangent to curve y=x^2 - x, x = 3

magic cairn
#

point is (3, 6)

short spruce
#

what have you tried

magic cairn
#

i dont know what to try

short spruce
#

have you learned derivatives?

magic cairn
#

no

#

learning limits today

short spruce
#

so you know the limit definition of a derivative?

magic cairn
#

this is the hw

magic cairn
#

lol

short spruce
#

well that might be a problem

burnt jungle
#

L'hopital?

short spruce
#

no?

magic cairn
#

idk what a derivative is

burnt jungle
#

Which are you talking about then

short spruce
#

$\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}$

warm shaleBOT
#

a disappointing son

burnt jungle
#

This is it

magic cairn
#

o yea that equation

#

wiat im a dumbass

burnt jungle
#

What

magic cairn
#

i thought u need two points for that

magic cairn
#

.close

obtuse pebbleBOT
#
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bright plinth
#

How can I find the reference angle for 20pi/3?

short spruce
#

determine quadrant

bright plinth
#

Ok thx

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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dark orchid
#

E

obtuse pebbleBOT
dark orchid
#

Gud,

#

y = -(x-2)^2-1

#

y = x - 5

#

How to graph it

stiff halo
#

Can you make a table?

dark orchid
#

Maybe?

#

Not sure what im supposed to do to solve it.

stiff halo
#

Solve or graph?

dark orchid
#

Something about vertex?

#

Graph

stiff halo
#

You know what graphed equations do when they are equal?

dark orchid
#

No.

stiff halo
#

Did you try to graph them?

dark orchid
#

Trying to figure out where i went wrong

stiff halo
#

The top graph?

dark orchid
#

Yes

stiff halo
#

How do you solve for -(0-2)^2-1?

dark orchid
stiff halo
#

You need more than the vertex

dark orchid
#

Teacher just showed me that, didnt have time to clarify thro

stiff halo
#

The easiest way is to plug in values. Like, y=-(0-2)^2-1 at x=0 and y=-(1-2)^2-1 at x=1

#

Since it is quadratic, you need more than the slope and the vertex to graph

#

Equations with exponents on x are not straight lines

dark orchid
#

🤔

#

Hm.

#

So y= -(2-2)^2-1

#

Would be x = 2

#

?

#

Then i plug it, 2 into y = x - 5

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To get y ?

#

Yes? Or no?

stiff halo
dark orchid
#

I plug in 2 in there.

#

Need help on 4 too

stiff halo
#

But what steps do you take to get 2?

dark orchid
#

I just insert a random number into x

#

Seems to work, work better if i stick close to 0

stiff halo
#

I mean how do you get 0^2-1=2?

dark orchid
#

Whut

stiff halo
#

Oh never mind

#

I see what you mean, that is right

dark orchid
#

Ye. : )

stiff halo
#

You need to solve for y

dark orchid
#

Yes

stiff halo
#

Sorry

#

What values are you getting?

timid silo
#

dont you find x first and then plug it back in to find y? sorry if im wrong

dark orchid
#

Ur right

timid silo
#

subtract 50x from left, so you end up with x^2 - 50x + 616

#

then, you can factor

stiff halo
#

Also, y=-(1-2)^2-1=x=1 is supposed to be y=-(1-2)^2-1 when x=1

dark orchid
#

🤔

timid silo
#

here, this is what i did

#

I'm not sure if this is the best way though...

#

it's quite annoying to factor

stiff halo
#

Looks good to me, except for the missing =0

timid silo
#

oh right, i should include that

obtuse pebbleBOT
#

@dark orchid Has your question been resolved?

obtuse pebbleBOT
#
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lone shore
#

I need help guys been studying for my exams and we were given a practice sheet(not graded) and I just cant find the answer
The length of a rectangle is 12 m more than thrice its width. The perimeter of the rectangle is 200 m. Find the length of the rectangle.
its been almost an hour

short spruce
#

what have you tried

lone shore
short spruce
#

i ask again

#

what have you tried

lone shore
#

tried finding the formula

nocturne minnow
#

The question was what you tried, not repost the question

short spruce
#

so... what did you do in that attempt

#

if it's been almost an hour i assume you have a paper somewhere

lone shore
#

no I dont use paper I'm trying to solve it mentally

astral ivy
#

@lone shore do u know what perimeter is

lone shore
#

since the time limit for the exam is very limited

astral ivy
#

Yeah don’t clog your mind with formulas to memorize

nocturne minnow
short spruce
#

<@&268886789983436800>

hot hazel
#

they say they're studying.

short spruce
hot hazel
astral ivy
#

They’re studying for it