help-10

[raven spire]

[dusk osprey]

right

[obtuse pebble]

Channel closed

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[dusk osprey]

.reopen

[obtuse pebble]

✅

[dusk osprey]

negate the following and simplify

I am dying

[timid silo]

De Morgan's Law

[dusk osprey]

I just expand this??

[timid silo]

You mean using the distribution property?

Sorry, I'm not entirely sure what they mean by simplify

[dusk osprey]

need to get this in the end

[dusk osprey]

idk anymore

pls help

<@&286206848099549185>

[timid silo]

I think I solved it.

if you still need help

[dusk osprey]

yeah

I do

do you know if commutative law still applies if the operators are not hte same

[timid silo]

If you are talking about step 3 then yes that looks about right

[timid silo]

Sorry I'm slow af but it looks like you forgot to flip the signs on (neg(p) or neg(q) or r)

[dusk osprey]

Yeah

Im stuck

[raven spire]

👀 where are you stuck tho?

[dusk osprey]

see #discrete-math main thread is there

here ppl kinda dead

[raven spire]

$[(p\land q) \lor (p\land r)] \land [\neg(p \land q) \lor r]$

[warm shale]

Ansh

[raven spire]

$[s \lor (p\land r) ] \land [\neg s \lor r]$

[warm shale]

Ansh

[raven spire]

distribute from here n simplify as much as possible

then do the negation

instead of negating n simplifying

[dusk osprey]

I see

how does this transformation happen?

[raven spire]

$(\neg q \land \neg r) \lor (q \land \neg r) = (\neg q \lor q ) \land \neg r$

[warm shale]

Ansh

[raven spire]

You can show that by applying distributive property on right hand side

[dusk osprey]

oh shit right

you can do distributive backwards

[raven spire]

btw, can you show: $(p \land q) \lor p = p$?

[warm shale]

Ansh

[dusk osprey]

i think that's one of the laws we learned

so we can use it without proof

i think

[raven spire]

what's the name

[dusk osprey]

negation

wait

no

"absorption"

mb

[raven spire]

Are you still stuck?

[dusk osprey]

no solved it. But still confused about mindset to have when solving these kinds of problems

what I have down so far is just group variables together

[raven spire]

How did you do it?

[raven spire]

Right

[raven spire]

Yes. Like you saw here, the negation p in $p \land (\neg p \lor \neg q \lor r)$ was just there to make things complicated

[warm shale]

Ansh

[raven spire]

*look complicated

so once you simplify it, the question simply becomes to negate $p \land r$

[warm shale]

Ansh

[dusk osprey]

I think I tried simplifying at first before doing negation

I should have tried harder

[dusk osprey]

is what I am doing correct?

@raven spire (please tell me if you want me to stop pinging you)

[raven spire]

nope. no worries

[raven spire]

?

[dusk osprey]

oh

wait

i need to put a bracket around different operators

?

[raven spire]

I mean....... $q \lor (p \land r)$ is not the same as $(q \lor p) \land r$

[warm shale]

Ansh

[dusk osprey]

i see

[dusk osprey]

Does this fix the problem?

@raven spire

[raven spire]

hm +_+ lemme seeeee

[dusk osprey]

i did more stuff

wait

[raven spire]

yep this is fieen

[dusk osprey]

i messed up on the more stuff part

distributive

yeah i think I solved

it

[raven spire]

although you could've simplified this more after the last step

[dusk osprey]

how do i do that?

[raven spire]

$q \lor (\neg q \land r ) \lor p = (T_0 \land (q \lor r) ) \lor p$

[warm shale]

Ansh

[raven spire]

$= p \lor q \lor r$

[warm shale]

Ansh

[dusk osprey]

yeah nice

[obtuse pebble]

@dusk osprey Has your question been resolved?

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[untold mica]

I don’t know where to start

[wide aurora]

hi

[untold mica]

Hi

[wide aurora]

how can i assist you

ok

my jit

ok

1+cscx

is same as

1+1/sinx

which is

sinx+1/sinx

bro how to do division on thsi thing

uhh

ok but basically

1+sinx/sinx+1/sinx

which becomes

1+sinx * sinx/sinx+1

that equals sinx

i think i did that right

dk

[untold mica]

How do you get from 1+sinx/(1+1/sinx) to 1+sinx*sinx/sinx+1

[wide aurora]

ok um

OH SHOOT I GTG

MB MAN

TTYL

GL

[untold mica]

Np. Thanks

.close

[obtuse pebble]

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[cerulean nest]

How do i find P(D)?

[obtuse pebble]

@cerulean nest Has your question been resolved?

[cerulean nest]

<@&286206848099549185>

[tardy epoch]

Bayes theorem

[cerulean nest]

but i have P(C|D) and P(C|D')

do you mind explaining how i use the formula here?

@tardy epoch

[tardy epoch]

actually i was wrong

use law of total probability

[cerulean nest]

how do i apply the formula?

[tardy epoch]

What's $P(A \cap B_n)$ equal to?

in terms of things you have

[warm shale]

riemann

[cerulean nest]

so would i make P(A)=P(D) in my question?

@tardy epoch

[tardy epoch]

Try both

One of them you have values for, the other you don't

[obtuse pebble]

@cerulean nest Has your question been resolved?

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[broken maple]

i gotta prove that the limit doesnt exist. But on wolfram alpha it shows that the limit exist on (0,0) I used the path y=sinx and tried to resolve it using Lhopital rule .

[tardy epoch]

what did you input into wolf?

,w plot (x^3 + y^3) / (x-y)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[tardy epoch]

doesn't look like it exists

[tardy epoch]

oh you're just proving continuity not derivative

[broken maple]

yup just the limit

[tardy epoch]

maybe there's a mistake in your work

i'd actually just try to prove the limit exists directly for any path

[broken maple]

i am not able to resolve it ..

hint is given as: use y=x-mx^3

[tardy epoch]

that hint is supposed to prove it doesn't exist ? because a single path doesn't prove the limit exists

[broken maple]

actually i used y=sinx and after resolving using L hoptial the expression was approaching infi. which proves that it doesnt exist

but my problem is that wolfram shows it exist

[tardy epoch]

you probably have a mistake?

another option is to switch to polar coordinates

[broken maple]

they would work if the denominator would not become a function of theta(as there would just be an r to conclude the limit) but it isnt the case here

[tardy epoch]

hmm that wouldn't get you anywhere in the denominator

[obtuse pebble]

@broken maple Has your question been resolved?

[obtuse pebble]

@broken maple Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[obtuse pebble]

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[broken maple]

how do i approach this problem

[sage geode]

I guess I'd suggest breaking it up into a product of two limits

(hint: siny/y and the rest)

[broken maple]

tnx fr the suggestion

.close

[sage geode]

The channel is already closed/closing

[timid silo]

do .close

[broken maple]

👍

[obtuse pebble]

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[fathom dune]

Hey,
I'm doing this analysis question, and I got to a solution, but I don't think I've been concrete enough in the way that i've written it. Can anyone give any tips/suggestions?

[obtuse pebble]

@fathom dune Has your question been resolved?

[obtuse pebble]

@fathom dune Has your question been resolved?

[fathom dune]

The extreme value theorem?

@agile leaf

hm, okay

[fathom dune]

.close

[obtuse pebble]

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[winged kayak]

chinese

[winged kayak]

I cant understand adjacency matrixes potencies...any good video tutorial??

what is the translation for adjacency matrixes potencies?

[obtuse pebble]

@winged kayak Has your question been resolved?

[winged kayak]

also, do adjacency matrixes double the entrance value for loops? does it happen in directed and non directed graphs?

<@&286206848099549185>

[obtuse pebble]

@winged kayak Has your question been resolved?

[obtuse pebble]

@winged kayak Has your question been resolved?

[obtuse pebble]

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[dawn fable]

i need help with geometry

[obtuse pebble]

Please don't occupy multiple help channels.

[dawn fable]

this one

[strong vale]

hm no translation?

[cerulean tulip]

Im assuming you need to find r

[dawn fable]

ABCD IS A SQUARE THE RED CIRCLE HAS RADIUS

yes

[nocturne minnow]

Don't open multiple channels

[dawn fable]

thats correct

the radius

thats what i need help with

[nocturne minnow]

Close the other channel you have open

[dawn fable]

anybody helper who knows how to solve this?

[dawn fable]

this

[nocturne minnow]

Are you reading what I am telling you?

Close the other channel you have and don't use multiple channels

[dawn fable]

im waiting on any helper to help me on this math problem anybody just help when u are not busy

[balmy mortar]

Look, we can help you

[nocturne minnow]

So? That doesn't mean that you should open multiple channels

[balmy mortar]

Just communicate with us (and follow the rules)

[dawn fable]

ok

[balmy mortar]

Like what's the issue

[balmy mortar]

What have you tried

[dawn fable]

i cant solve it

[balmy mortar]

Have you got no idea at all how to start

surely you must have marked some stuff

[dawn fable]

so EF

can be solved

with pythagoras

i dont remmebr how to do this

so i need help

...

[balmy mortar]

A marked diagram would have helped us a lot

[dawn fable]

so u mean cm?

[balmy mortar]

cm?

[dawn fable]

nvm

ok so what do we do next

[balmy mortar]

Ok, as you said BEF is right angled

$$a^2 + b^2 = c^2$$

[warm shale]

Shuri2060

[balmy mortar]

That's pythagoras.

EF is c

The other two are 1 and 2

[dawn fable]

ok

so how do i write that

1+2= EF

or?

[balmy mortar]

no

Do you recognise what the 2 means

in the formula

[hot mortar]

What is the partial derivative with respect to x of 6x(x^2+y)^2 ?

[balmy mortar]

#❓how-to-get-help

Why are u just randomly asking in someone elses channel

[hot mortar]

ohhh sorry hahah i am new

[dawn fable]

read the rules i did the sdame mistake

[dawn fable]

ïs it the b*2?

[balmy mortar]

the exponent 2

means you square

a squared plus b squared equals c squared

If you don't know this, I think this question is probably too hard

[dawn fable]

i know

[balmy mortar]

This question is already not a simple geometry problem

[dawn fable]

but i wrote it without the exponents

bc my keyboard cant write thast up thing

[balmy mortar]

EF is sqrt 5

You get that?

[dawn fable]

yeah

but how can i write that

whats the form

[balmy mortar]

^

?

idk what you mean???

[dawn fable]

how do i write thing

[balmy mortar]

what

[dawn fable]

the question and the answer

[balmy mortar]

sqrt 5

?

[dawn fable]

so

[balmy mortar]

Also, I don't even see how this helps (yet).

[dawn fable]

what i mean is

how do i get to know that its 5

i want to write it so i know how i get 5

thats what i mean

[balmy mortar]

?

You understand this yes?

[dawn fable]

thats the form

yes

[balmy mortar]

$1^2 + 2^2 = EF^2$

[warm shale]

Shuri2060

[balmy mortar]

You understand this yes?

???

[dawn fable]

thats what i was asking u the whole time

yes

now what do i do

or how do i write it now since its 5

[balmy mortar]

sqrt 5

square root 5

???

$\sqrt 5$

[warm shale]

Shuri2060

[balmy mortar]

?

[dawn fable]

yeah

alright

[balmy mortar]

Why are you asking

[dawn fable]

making sure i do it correct

its 25 now

since we do squre root

[balmy mortar]

??????????????

[dawn fable]

arent we supposed to take square root 5

[balmy mortar]

Man how do I put it

[dawn fable]

and the square root of 5 is 25

5 times 5 is 25

[balmy mortar]

If you aren't familiar with elementary arithmetic/algebra

You shouldn't be doing this question

[dawn fable]

i just need to do it

[balmy mortar]

5 squared is 25

square root of 5 is different

I'm going to find it incredible hard to guide you to the answer

[dawn fable]

wait what

if u take square root of 5 the answerr is 5 or 25

[balmy mortar]

$\sqrt 5 \neq 5$

[warm shale]

Shuri2060

[balmy mortar]

$\sqrt5 \neq 25$

[dawn fable]

ohhh

[warm shale]

Shuri2060

[balmy mortar]

??????????

[dawn fable]

u mean like that

[balmy mortar]

What

I'll give you this hint and leave it at this sry. Maybe it's the language barrier or you haven't done enough algebra/arithmetic, but I feel this question is too hard.

You should draw lines EH, FG, GH

[dawn fable]

bro i ned help with this

cant let it stay

man please help with this

[dawn fable]

i need help this is important for me

i knew it was 25 you didntr understand

i wa telling u its 25

its 25

u said ????????????????

bro i ned help

[strong vale]

What do you need help with?

[dawn fable]

you dont even know how to solve it

🤣

[dawn fable]

dude i need help

[obtuse pebble]

@dawn fable Has your question been resolved?

[obtuse pebble]

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[weary cove]

$$"Determine the value(s) of h such that the
matrix is the augmented matrix of a consistent linear system."$$ANSWER is "all h"

[warm shale]

CAT

[weary cove]

"Determine the value(s) of h such that the
matrix is the augmented matrix of a consistent linear system." i dont see how "all h" would be true since if h=-12 we get "0/0"??

[obtuse pebble]

@weary cove Has your question been resolved?

[tardy epoch]

Plug in h into the matrix before dividing

[obtuse pebble]

@weary cove Has your question been resolved?

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[steep charm]

trying to write a polynomial function that matches this graph
I tried writing it out in factored form and expanding it but the graph is not correct
would appreciate it if anyone could explain how i could go about this

[haughty coyote]

what did you write out ? How is it wrong ?

finding the roots and their multiplicities and the right leading coefficients does look like the right way to go

[steep charm]

i tried writing it out y = x(x+5)(x+2)(x-3)(x-6)
then when i expanded it i got x^5 -2x^4 -35x^3 +36x^2 +180x

[haughty coyote]

shape looks ok to me

if you graphed this and got a bunch of vertical lines, divide by something like 1000 to get a reasonable scale

[balmy mortar]

Roots do not uniquely determine the polynomial @steep charm

$$y = (x-1)(x+1)$$
$$y = -10(x-1)(x+1)$$

[warm shale]

Shuri2060

[balmy mortar]

different quadratics, same roots.

[steep charm]

thx i did that and it worked

[steep charm]

yeah i changed the x at the start to x/100

in factored form

[idle thunder]

@steep charm How did you get 1/100

Did you just pick a random number

Or did you plug in values and solve for a

[haughty coyote]

conveniently lines up with the values on the graph. The people who wrote the problem chose a convenient value and he probably found it by accident

otherwise unless you find a nice value you can only approximate the coefficient

[obtuse pebble]

@steep charm Has your question been resolved?

[obtuse pebble]

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[worldly cypress]

Help

[obtuse pebble]

Please don't occupy multiple help channels.

[hazy marlin]

[obtuse pebble]

@worldly cypress Has your question been resolved?

[worldly cypress]

@hazy marlin #help-22

[obtuse pebble]

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[worldly cypress]

.reopen

[obtuse pebble]

✅

[worldly cypress]

<@&286206848099549185>

[short spruce]

you haven't asked a question and have multiple channels

read the rules

[worldly cypress]

.close

[obtuse pebble]

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[dull crypt]

just checking, if I have 1030/2x^2, is that the same as 515x^-2 ?

[quaint glen]

yes

[dull crypt]

brilliant, thank you

[quaint glen]

assuming the full 2x^2 is on the denominator

[dull crypt]

yessir

thank you again

.close

[obtuse pebble]

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[dull crypt]

alas.. i have another question

.reopen

[obtuse pebble]

✅

[dull crypt]

so closed cuboid with base 2x * x & height h

all in cm

capacity (volume) is 1030cm^3

express h in terms of x

volume = (2x*x)*h

aka (2x^2)h

(2x^2)h = 1030

h = 1030/2x^2

so i took h to equal 515x^-2

however in a later question i'm asked to show the surface area is given by A = 4x^2 + 3090/x

got the 4x^2 fine but I get 4120 instead of 3090

as in 8x * 515x^-2 = 4120/x

ah

i multiplied the area of 1 'long' face of the cuboid 2xh by 4 (as 4 'long' faces) to get my 8xh

though interestingly if I divide 3090 by 515 I get 6

the number of faces, guessing that's not luck

but why does my multiplying 2xh by 4 to get 8xh not work?

as in not why does it equal 4120 but rather why is that not the way to do it (in my head it seemed logical though clearly not)

looking back I feel this is worded pretty poorly so my apologies if it's unintelligible, it's late haha 😬

to simplifiy

h is equal to 1030 / 2x^2

I've simplified h to be 515x^-2

OH

smol brain moment

figured it out

.close

[obtuse pebble]

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[trim island]

if cos (lnx) = 0

[trim island]

why is lnx = pi/2

and not lnx = 1

if you inverse the cos function on both sides

havent worked it out but gonna sleep

.close

[obtuse pebble]

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[timid silo]

i^{60}-i^{112}+10i^{93}-6i^{36}
i
60
−i
112
+10i
93
−6i
36

[timid silo]

woah

wrong thing

hold on

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[fallow granite]

Hello

[fallow granite]

I need help with this question

How would I start

[alpine raven]

by writing both expression of n! and (n+1)!

[balmy mortar]

Try for a few small n

Like n = 5

3

8

[obtuse pebble]

@fallow granite Has your question been resolved?

[fallow granite]

what does that mean

[alpine raven]

n! = ???
(n+1)! = ???

[fallow granite]

I am not getting it

[fallow granite]

is n! = 1,2,3,4 ...

[alpine raven]

n! is equal to what ._.

[fallow granite]

idk

[fallow granite]

is it that?

[alpine raven]

if you dont know what factorial are, then do an other exercise

[alpine raven]

no it doesnt make any sense

[fallow granite]

so what does n! equal to

[raven spire]

(ヘ･_･)ヘ┳━┳

[spiral maple]

$n!=n(n-1)(n-2)...(2)(1)$ cause it's hard to google

[warm shale]

Mosh

Ansh

[fallow granite]

oh ok

[fallow granite]

is the answer to this question 1/n+1?

[spiral maple]

it isn't $\frac{1}{n}+1$

[warm shale]

Mosh

[fallow granite]

what did I do wrong

[spiral maple]

You fucked up typing it.

[fallow granite]

?

[spiral maple]

1/n+1 is not 1/(n+1)

[fallow granite]

oh ok

yea my fault

1/(n+1)

that is correct right

[spiral maple]

yes

[fallow granite]

ok ty

how would I do this

[harsh lantern]

$\cos^2 x + \sin^2 x = 1$

[warm shale]

Pealover

[fallow granite]

ok

but the thing is

isnt there no solution for cos theta = -3/4

[harsh lantern]

no?

[fallow granite]

hmm

[fallow granite]

so what would I do with this info

[harsh lantern]

you know what is cosx

you wanna find sinx

[fallow granite]

would I square -3/4

[harsh lantern]

yes

[fallow granite]

does that look correct

[harsh lantern]

The last lane is incorrect

[fallow granite]

how

+-

?

[harsh lantern]

$\sin^2 x = a \implies \sin x = a$ or $\sinx = -a$

[warm shale]

Pealover
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[fallow granite]

so just -rad7/4

[harsh lantern]

yes

[fallow granite]

ok

ty

[harsh lantern]

and the fact that its in the third quadrant permits to know it is negative

[fallow granite]

yea I just realized

sin is negative in 3rd and 4th

[harsh lantern]

yes

[fallow granite]

ok got it

tysm

[harsh lantern]

np gamer

[obtuse pebble]

@fallow granite Has your question been resolved?

[obtuse pebble]

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[fervent apex]

would someone be willing to check my work on an integral ?

[timid silo]

Sure

Send it

[fervent apex]

my instructor doesnt require full simplification if it seems incomplete

[short spruce]

1.) you wouldn't multiply by two to get (1/x^3)dx
2.) change your bounds on a u sub, makes everything easier
3.) the -2 would be distributed throughout on the left side of your paper (always use parenthesis)

note that the -2 isn't right, so it's not gonna need to be distributed, but the correct number will

[fervent apex]

is it -1/2 ?

if i were to leave the bounds in terms of x would this be correct?

i recognize that changing the bounds to u bounds is easier, this is just the way ive done it for a while

[raven spire]

tbh, the bounds on the integral in steps 2 and 3 don't make sense if you're equating with the previous and after math

but if you're talking about whether you evaluated it right, yeah.. altho you could change the negative powers into reciprocals to simplify stuff

[fervent apex]

yeah she prefers we dont simplify

what do you mean by your other message though

if you dont mind rewording it

[short spruce]

on the left hand side, what you wrote is integrating your function with respect to u but you're using the bounds as if it were still in terms of x

if you're gonna end up replacing u back with x (which again i don't recommend, it's more work) just leave the bounds off and make it an indefinite integral

when it's in terms of u

[fervent apex]

oh okay i understand, so i should put x back in the substitution before evaluating at all?

[short spruce]

you did that much correctly

it's this part specifically

you have your integrand in terms of u but your bounds are still in terms of x

so there, if you're adamant on going back to in terms of x, make what i took a screenshot of an indefinite integral

get rid of the bounds

integrate normally

then go back to a definite integral in terms of x when you replace u

but again i really do recommend changing your bounds

[fervent apex]

when i integrate it with the indefinite integral do i include the +c

-1/2(e^u+c)

[short spruce]

no

[obtuse pebble]

@fervent apex Has your question been resolved?

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[obtuse pebble]

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[warm tree]

is the answer 96

[obtuse pebble]

@warm tree Has your question been resolved?

[obtuse pebble]

@warm tree Has your question been resolved?

[obtuse pebble]

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[cinder badge]

sorry for the inconvienience i have another question

[sleek briar]

Distribute the h

And the 9

[cinder badge]

what does distribute mean'

[sage geode]

How'd you factor ha + 9a

[sleek briar]

So if the letter is next to some number it means multiply

Here it mean multiply h by (5+k)

[cinder badge]

is the answer (5+k) (h+9) or not

[sage geode]

I don't think you need to expand

Yes it is

[cinder badge]

can i give another question

i need help with

[sage geode]

Surely

[sage geode]

And what's the question?

[cinder badge]

that

factorise

[sage geode]

Uh, difference of squares could work I guess

View 56 as sqrt(56)^2

[cinder badge]

what is the square root of 56]

[sage geode]

Well you could find its prime factors in order to simplify it

[cinder badge]

what

[sage geode]

sqrt(56) = sqrt(14*4) = 2sqrt(14)

[cinder badge]

what

[sage geode]

There's no further simplification

[cinder badge]

sorry im dumb

[sage geode]

You know what square root means, right?

[cinder badge]

a number multiplied by itself that gets another?

[sage geode]

Kind of, if a^2 = 56 (where a is positive), then a = sqrt(56)

[cinder badge]

wait so it can't be factorised anymore?

[sage geode]

It can

It's just that you'll have (x + 5 - sqrt(56))(x + 5 + sqrt(56))

[cinder badge]

oh so thats the final answer?

[sage geode]

Yes, you could write 2sqrt(14) instead of sqrt(56) since it looks nicer

[cinder badge]

tysm

.close

[obtuse pebble]

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[stiff oracle]

can I ask help here?

[royal basin]

dont ask to ask

[stiff oracle]

im assuming so

lemme send a screenshot

brb

anyone able to help?

should be easy, but Im terrible at word problems

[royal basin]

which part are you stuck on?

[stiff oracle]

honestly still at A

I understand that x^2 + x^2 + 2 = 164

[royal basin]

no

[stiff oracle]

hmm

[royal basin]

that equation is incorrect and i'm willing to bet you tried to write that down while skipping several steps

[stiff oracle]

honestly

im not sure

[royal basin]

all you're asked in part a is:
if x is the first of two consecutive even integers, then what is the second?

do you know what an even integer is, and do you know what the word "consecutive" means?

[stiff oracle]

x+2

[stiff oracle]

yeah

[royal basin]

okay there we go great

there's your part a

you were able to answer it just fine just now

it's x+2, as you said

[stiff oracle]

alright

and then B should be x + x + 2 = 164?

[royal basin]

no

please read the problem carefully

[stiff oracle]

Determine the equation that represents the problem

[royal basin]

no

what it says before part a

[stiff oracle]

oh

[royal basin]

the whole setup

[stiff oracle]

The product of two consecutive even integers plus twice their sum is 164. Find the integers

[royal basin]

yes

do you know what the word "product" means?

[stiff oracle]

sum

[royal basin]

no, product does not mean sum.

[stiff oracle]

in this case sum

[royal basin]

no.

[stiff oracle]

huh

[royal basin]

product means the result of multiplication.

[stiff oracle]

right

[royal basin]

e.g. the product of 3 and 4 is 12.

your integers are x and (x+2).

[stiff oracle]

so that would be

x times (x+2)

[royal basin]

yes, the product of your integers is x(x+2)

however that's not the only thing in your equation

[stiff oracle]

hmm

x(x+2)=164

is that the complete equation?

[royal basin]

no

as i just said

the problem does NOT say "The product of two consecutive even integers is 164"

it says

The product of two consecutive even integers plus twice their sum is 164

[stiff oracle]

okay

so

x^2(x+2)^2 = 164

or is it

x(x+2) + x(x+2)

[royal basin]

no

i have a feeling you're trying to overthink things here

[stiff oracle]

possible

[royal basin]

when in fact the worded statement can (and should) be translated into an equation almost word for word

do you know what the word "twice" means?

it means "two times"

i.e. multiplication by 2

The product of two consecutive even integers [x(x+2)] plus [+] twice [2 * ] their sum [(x + x + 2)] is [=] 164 [164]

[stiff oracle]

ah

I get mixed up by twice and squared

so then

that would be

x(x+2) + 2(x+x+2) = 164?

[royal basin]

there we go

congratulations, you managed to read it off from my message

[stiff oracle]

okay

so thats B

[royal basin]

yes that is part b

[stiff oracle]

and in C

we simply just solve it

so x^2 + 2x + 2x + 2x + 4 = 164

x^2 + 6x + 4 = 164

ty

wait but first

we

x^2 + 6x +4 - 164 = 0 correct?

[royal basin]

that is legal to do

would rather you didn't confuse 'can' with 'must'

if you want to subtract 164 from both sides then by all means do it

[stiff oracle]

got it

bc its quadratics and factorization homework

and i think my teacher

would want me to do that

so i'll go ahead and do that

and then that would lead to

x = 16 or x = -10

thanks ann

yo I got another question Ann

[royal basin]

i assume you are able to do parts c and d of the previous question yourself

[stiff oracle]

yes! Thanks

[royal basin]

mkay

are you able to construct the equation for part a?

[stiff oracle]

not really

let me try

so

the old man

is x^2 + 4

and the son is

x + 4

[royal basin]

no

[stiff oracle]

but x^2 + 4 is double x + 4

[royal basin]

read the problem again

it doesn't say "In 4 years, ..."

[stiff oracle]

hmm it says 4x

so

[royal basin]

yes, it says 4x, not 4.

[stiff oracle]

so the son is 5x

and the old man is x^2 + 4x

[royal basin]

the son will be 5x years old.

[stiff oracle]

right

[royal basin]

and the old man will be x^2 + 4x years old.

[stiff oracle]

yes

right

[royal basin]

the dad's future age is two times that of the son.

are you able to write this as an equation

[stiff oracle]

hmm

but

if the dad's future age is two times that of the son

then

isn't it two times of the son already?

oh wait

i'm looking at it wrong

nevermind

[royal basin]

you're overthinking it

[stiff oracle]

so (x^2 + 4x)^2

wait

no 16x

wait no the son will be 5x

so 25x = x^2 + 4x?

[royal basin]

no

again

TWO TIMES

not squared

two times

means two times

[stiff oracle]

right

10x = x^2 + 4x

[royal basin]

(not only that but you weren't squaring correctly by the looks of it

yes good now you have it

[stiff oracle]

okay

so the quadratic equation would be

x^2 + 4x -10x = 0?

[royal basin]

10x = x^2 + 4x already is a quadratic equation

[stiff oracle]

oh

[royal basin]

but yes, converting that to standard form would probably have x^2 + 4x - 10x = 0 as an intermediate step

[stiff oracle]

it's fine

thank you

nevermind

it's not fine

how do I solve x^2 + 4x - 10x?

[royal basin]

you should not forget the =0 at the end.

anyway, i would suggest simplifying 4x - 10x

[stiff oracle]

alright

thanks

now B

b) Find how old the man and his son are now.

so his son is 6

and the man is 36?

hmm

bc I got x = 6 or x = 0

[royal basin]

yes this is correct

[stiff oracle]

oh

okay

thank you!

[obtuse pebble]

@stiff oracle Has your question been resolved?

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[obtuse pebble]

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[rocky sierra]

Hi everyone this is for odd one out

[rocky sierra]

this is all 4 areas so what should i do

this is very easy but i feel like it's e

[balmy mortar]

symmetry

[rocky sierra]

oh ok

so than it can be e

right

[balmy mortar]

yh

[rocky sierra]

huh

yh?

[balmy mortar]

yes

[rocky sierra]

ok

thansk

.close

[obtuse pebble]

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[west sierra]

,w limit of (h-h)/h as h tends to 0+

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ji Ning#8861

[west sierra]

How do you solve this limit, isn't it 0/0 form?

do you divide h-h over h to make it 1-1 which is 0?

.close

[obtuse pebble]

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[rancid leaf]

Hello, I have a question. Consider the logarithm function ln : (0, ∞) → R. Why is not injective?

[hazy marlin]

not injective ?

[rancid leaf]

Oh, so, is injective?

[balmy mortar]

maybe

What does injective mean?

[rancid leaf]

I don’t sure, on internet I find that it is surjective but nothing about injective, so I supposed that is not injective, but, why? Is not one-to-one?

[hazy marlin]

also, you might wanna consider the fact that lnx is the inverse of e^x

[balmy mortar]

Not sure? You should look up the definition first

before attempting the q

[rancid leaf]

Yes, you have reason

.close

[obtuse pebble]

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[high lily]

not identifying the choice that best represents your result

[balmy mortar]

For which x is
x less than/equal to 2

and greater than/equal to 8

You tell me one 🙂

Just think about some numbers

does 0 work?

[high lily]

consider graphing this on a number line if it isn't immediately clear to you

does NOT correctly represent

x≤2 and x≥8

yes you are

can you think of any numbers that are less than or equal to 2 but are also greater or equal to 8?

what's 6 supposed to be

also not answer my question

can you think of a number (any number) less than or equal to 2

infinity isn't a number

but yes, 1 is less than 2

is 1 greater or equal to 8?

you mean no?
$$1\not\geq8$$

[warm shale]

ℝamonov

[high lily]

can you think of another number less than or equal to 2

.close

[obtuse pebble]

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[dire agate]

Hello everyone! I wonder if here a channel (or a server) for lower level math students? I was trying to find some practice. You see, I kinnda re-studied school math and want to do some practice. I believe I shouldn't go further until I used to solve basic(easier) problems. But here in chats you discuss a lot more complicated things then I know. So please, give me any links, also books are fine. It has to bee school level and with problem solving tasks.
sorry for grammar – English isn't my mother tongue.

[exotic oak]

You just open a channel like this asking for what you need help.

It can be lower level math aswell

Someone will definitely help.

[balmy mortar]

#book-recommendations

[dire agate]

Thanks.

@exotic oak thank you too. I just was a little scared with others people cool questions. I will try to ask my dummy questions too. 🙂

[exotic oak]

Don't worry about it I will be happy to answer what I know

[obtuse pebble]

@dire agate Has your question been resolved?

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[simple rampart]

Area = 12 and AB = 15. Calculate x by using a ratio. Can anyone help?

[misty terrace]

the area of ABCD = 12?

[simple rampart]

Yup

[misty terrace]

are CD and EF parallel?

[simple rampart]

Yes

[brave bramble]

Can you find an algebraic expression for the area, in terms of lengths on the diagram?

May have to add a few more letters to be able to

[misty terrace]

yeah, i think it turns out a bit ugly :(

[simple rampart]

AE = 1/3hsquare root of 3

[brave bramble]

I suggest writing it out so you can be sure of your algebra

[misty terrace]

wait, surely i've done something wrong here?

that for sure isn't a nice answer :/

but it seems to check out...

[simple rampart]

I have this now

[misty terrace]

surely you're not meant to solve this by hand, right?

[simple rampart]

No. But if I put the 2 expressions on the bottom in my graphic calculator and check where they intersect it's says x = 13,02 and x = -13,02.

So I guess x = 13,02

[misty terrace]

well yeah, that's how you're meant to solve the problem, probably :P

[simple rampart]

Awesome, thanks guys🙂

.close

[obtuse pebble]

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[untold heart]

i need help

[untold heart]

how do i start

Hello

im not good at math but how can i do this question

3x + 5 = 17

i rlly dont understand

what is x

?

i dont understand

[raven spire]

can you stop trolling?

[untold heart]

what is he saying i dont understand

hello

please help

please help

im being trolled

[formal aurora]

i need help with the rashed law of action

[untold heart]

excuse me this is my channel

please can i get a helper + mod

[formal aurora]

ARITHMATIC

lets goooo

when u clap ukmt ez

[obtuse pebble]

@untold heart Has your question been resolved?

[untold heart]

hELPPP

<@&286206848099549185>

these guys are trolling me

<@&286206848099549185>

[ocean topaz]

please don't interrupt other people's help channels

[untold heart]

can u help

[ocean topaz]

i recommend you close this channel, which got kind of cluttered, and open a new one. in the new one, put your question as the first message so that the bot pins it and people can help you more easily

[untold heart]

.close

[obtuse pebble]

Channel closed

Closed by @untold heart

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[proven juniper]

What is the process to find f'(50) ?

This is calculus 1 (chapter 2.7 in my book) by the way

Does it have something to do with finding the "instantaneous rate of change"?

Pretty much I just need to find the slope at x=50. Right?

[sage geode]

What they want you to do is probably imagine a tangent line at x = 50 and just guess the value of its slope

As I can see it should be a little above 1

And definitely not beyond 1.5

[proven juniper]

y/x correct?

[sage geode]

Yes change in y/change in x

[proven juniper]

400/50 = 8... I tried this answer before. It is not correct

For the change in x how do I calculate that with only 1 x value?

[sage geode]

400/50 is just value of y divided by value of x at that point, it's not the slope

[sage geode]

That's the point of the limit

[proven juniper]

Oops. Thanks I just realized that

How do I calculate the change in x with only 1 x value?

[sage geode]

I don't think you're supposed to do that in this problem

Since you're only shown the graph I assume you're asked to just guess the slope

Consider imagining a tangent line at x = 50

[proven juniper]

Here is an example question

So for this example question the tangent line is 25?

lol I just entered 25 into the real question and it is correct.

But how is 25 calculated?

[frank shell]

just use the theorem

[proven juniper]

This one?

[sage geode]

Oh wait right I forgot that the axis aren't on the same scale as well

[proven juniper]

Beans its ok. I appreciate the help

[sage geode]

But yeah the question still seems to be about guessing

[proven juniper]

is the instantaneous rate of change the theorem @frank shell is referring to?

for guessing should I just try to find the slope from x=40 to x=50 ? Then x=50 to x=60. Then guess what it looks like based off those numbers?

<@&286206848099549185>

f'(50) = 25 but how is this calculated?

anyone there?

Thank you everyone for your help. I think I understand it now.

.close

[obtuse pebble]

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[narrow fable]

Is the output of a Fourier Transform periodical?

[narrow fable]

always?

[obtuse pebble]

@narrow fable Has your question been resolved?

[unique solstice]

Probably not as n approaches infinity

I dont know though

[obtuse pebble]

@narrow fable Has your question been resolved?

[obtuse pebble]

@narrow fable Has your question been resolved?

[obtuse pebble]

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic oak]

I'm stuck at the indetermination 1^+oo

[raven spire]

Hey pinto

[exotic oak]

Hello again my friend

[raven spire]

Have you had any previous examples relevant to 1^+infty type indeterminate form?