#help-10

1 messages · Page 487 of 1

balmy mortar
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no idea what you mean by that

wary sail
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like 2.10

balmy mortar
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im saying

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that since the graph doesnt have units labelled

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1 grid square could be any size

nocturne minnow
balmy mortar
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1 by 1

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10 by 10

wary sail
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it’s one probably

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it’s what’s it’s been all year

nocturne minnow
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I'm pretty sure that the assumption is each grid is a unit of 1

wary sail
#

ye

balmy mortar
#

Does the factor theorem work if f is non-polynomial

wary sail
#

but still how do u determine the equation

balmy mortar
#

surely not, right

balmy mortar
#

I think you're meant to assume f is a polynomial

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and use the factor theorem

wary sail
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but u need it to find remainder

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oh

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does it work

balmy mortar
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try 🙂

wary sail
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i don’t have any numbers tho

nocturne minnow
balmy mortar
#

You have a graph

wary sail
#

not sure u just looked up a calculator

balmy mortar
#

huh?

wary sail
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but it’s decimal values

balmy mortar
#

Have you seen this

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For a polynomial P(x)

wary sail
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the root on the right is (2.10,0)

nocturne minnow
#

You doing too much

wary sail
nocturne minnow
balmy mortar
#

im typing it

nocturne minnow
#

That should help

balmy mortar
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oh ok ^

nocturne minnow
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A lot

wary sail
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how would u proceed in my probelm

balmy mortar
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read carefully

nocturne minnow
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Function evaluated at c

balmy mortar
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If P(x) = (x-a)Q(x) + b

Then P(a) = b

For polynomials P and Q

wary sail
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i’ve never done practice problems using it so doing it first time will be hard

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so i do f(x-1)

nocturne minnow
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So back to your problem, x - 1, what would c be?

wary sail
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1

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f(1) but i don’t have a f(x) equation

nocturne minnow
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So then evaluate at f(1)

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But you have the plot

wary sail
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oh

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-9?

nocturne minnow
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Yes

wary sail
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that’s the remainder?

nocturne minnow
#

Yep

wary sail
#

thank you

#

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obtuse pebbleBOT
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obtuse pebbleBOT
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@regal tendon Has your question been resolved?

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regal tendon
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haughty stratus
#

1/x-1 - 2/x^2-1

obtuse pebbleBOT
haughty stratus
#

how do i do this?

balmy mortar
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factorize x^2 - 1

haughty stratus
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yep i did that

nocturne minnow
haughty stratus
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i factorised x^2-1

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made the denominator on the other side the same by timesing the top and bottom by (x+1)

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then subtracted the fraction

balmy mortar
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are you not done?

haughty stratus
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which left me with

x+1-2/(x-1)(x+1)

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i dont know what further to do

balmy mortar
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ah theres some more simplifying actually

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x+1-2, what is this

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then see if you can spot something else

haughty stratus
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oh i got it

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thanks lmao

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1/x+1 is the answer

haughty stratus
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idek where to start

balmy mortar
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same idea

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except this time you have to factorize 1-x3

haughty stratus
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yeah idk how to factorise that

balmy mortar
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do u know the factor theorem

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or remainder theorem

nocturne minnow
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There are formulas

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I don't remember them but you can Google it

haughty stratus
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oh its the (a-b)(smth) one

balmy mortar
#

you could as well

nocturne minnow
haughty stratus
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timid silo
#

why is this incorrect?

obtuse pebbleBOT
timid silo
#

phi = atan(a/b) = atan(1.5/7.6)

nocturne minnow
obtuse pebbleBOT
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timid silo
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.reopen

obtuse pebbleBOT
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nocturne minnow
#

But does that matter? Isn't addition commutative so the order shouldn't matter meaning that the value should still be +11

timid silo
#

the reason i think its -11 cuz in the formula it has - sign in front of phi

nocturne minnow
#

It's been a while since I did trig identities, sorry

timid silo
#

phi = atan (a/b) = atan (1.5/7.6) = 11

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

can i get help

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oblique glacier
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.close

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proper raptor
#

−17−x^2−9x^7, can this be factored?

obtuse pebbleBOT
timid silo
proper raptor
#

Okay!

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ty

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!close

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marble ibex
#

Hey, if the modulus of a complex number is defined as |z| = sqrt(x^2 +y^2), is the modulus of z = 1 + i not sqrt(1 + (-1)) = sqrt(0) = 0?

marble ibex
#

Ahh nvm i see the issue now

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Its not sqrt(1^2 +i^2), its sqrt(a^2 + b^2) for z = a +bi

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modern ridge
#

factor x^2+2x+1

obtuse pebbleBOT
modern ridge
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how to do it

unborn valley
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Split the middle term

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X^2 + x +x+1. ...

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Now you can take common?

modern ridge
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uhh i think u got it wrong

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but ok ill solve it

timid silo
worthy drum
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from x^2+x+x+1 you can get (x^2+x) + (x+1)

short spruce
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doesn't really require factoring by grouping

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can be done in your head

unborn valley
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Now you have to take common

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X(x+1) +1(x+1)

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(x+1)^2

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??

timid silo
modern ridge
obtuse pebbleBOT
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@modern ridge Has your question been resolved?

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fervent comet
#

For question b. Why is the first position 4?

formal trout
fervent comet
#

Is that good enough?

#

<@&286206848099549185>

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For question b. Why is the first position 4?

formal trout
#

hmm

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because there are 4 possibilities for that position

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read it carefully

fervent comet
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Isn’t there 5 excluding the 0

quaint glen
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Choose the last number first, and one of the odd numbers can't be chosen for the first place

formal trout
#

lemme think

fervent comet
#

OHHHHH

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Thanks sneaky

quaint glen
#

no worries mate

obtuse pebbleBOT
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abstract magnet
#

Given that C is a set of cities in England and x,y∈C. R is a relation on set C defined as (x,y)∈R if x is close to y, i.e. the straight line distance is less than 50km.
The relation R is?

reflexive / not reflexive?
symmetric / not sysmmetric / antisymmetric ?
transitive / not transivive?

anyone has any idea on this question?

quaint glen
#

What part of it are you struggling with?

abstract magnet
#

i am struggling to identify whether the relation is reflexive , sysmmetric and transitive

royal basin
#

can you write out what "R is reflexive" would mean

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@abstract magnet

obtuse pebbleBOT
#

@abstract magnet Has your question been resolved?

abstract magnet
royal basin
#

well your relation is "x R y iff the straight-line distance between x and y is less than 50km"

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so what does x R x mean

abstract magnet
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the distance betwwen x and x is less than 50km(if it is reflexive)

obtuse pebbleBOT
#

@abstract magnet Has your question been resolved?

royal basin
#

is it true that a city is always less than 50 km away from itself

abstract magnet
#

Yes

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Oh so it is reflexive!! Wowww

royal basin
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apologies for the delay on my part

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i had intended for you to figure this out yourself

abstract magnet
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yeah, i just noticed, really thank you man

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so i think the answer is reflexive, not symmetric and transitive, is it correct @royal basin ?

royal basin
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no

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why do you think the relation is not symmetric?

abstract magnet
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sorry i meant it is reflexive, symmetric and transitive

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because x is close to y, then y is also close to x

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my bad 🙂

royal basin
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so why do you think it is transitive?

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do you think that if A is less than 50km away from B, and B is less than 50km away from C, this means A must be less than 50km away from C? @abstract magnet

abstract magnet
#

sorry i made a mistake again

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it should be not trainsitive, because if A is 50km away from B, and B is 30 km from Z, then A is actually 80km from Z , hence A is not close to Z, hence it is not transitive, is my logic correct or still wrong @royal basin ? 🙂

royal basin
#

yes now it's correct

abstract magnet
#

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abstract magnet
#

may i know why is this question 31 C 12? shouldn't it be 20 C 12?

obtuse pebbleBOT
#

@abstract magnet Has your question been resolved?

royal basin
#

it would be 20C12 if you were only allowed to take at most one donut of each type

abstract magnet
royal basin
#

no

#

it doesn't say we "select 12 different TYPES OF donuts"

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it says we select 12 different donuts

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which means we can have two or more of the same type as well

abstract magnet
#

but is the 12 different donuts considered distinct over here?

royal basin
#

yes they are distinct between types but donuts within one type are identical

abstract magnet
royal basin
#

yes

obtuse pebbleBOT
#

@abstract magnet Has your question been resolved?

abstract magnet
#

Thanks 🙏

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royal basin
#

what do to have after converting the lhs to sin and cos?

#

okay

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can you turn 1/cos(x) - sin(x)/cos(x) into a single fraction

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also the other parenthesis

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do you know how to add fractions

#

it's just that, nothing else

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glossy yew
#

.close

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timid silo
obtuse pebbleBOT
timid silo
#

Is there a simpler way at understanding poly

#

Polynomes

#

I can't understand it, especially yhe multiplication

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I jsut started understanding addition, but my class has moved onto multiplication

scarlet arrow
#

I see that ur French

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Is it okay helping him in French?

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idk if talking in another language is against rules

timid silo
#

I don't think it matters if its french, since the actual equation is there

balmy mortar
#

since it helps

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but idk about rules

timid silo
#

It's easier for me in english

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My first language isn't French

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It was just saying what type of equation it is

scarlet arrow
#

oh alright

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
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@timid silo Has your question been resolved?

obtuse pebbleBOT
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@timid silo Has your question been resolved?

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fossil sandal
obtuse pebbleBOT
fossil sandal
#

what am I doing wrong?

spiral maple
fossil sandal
#

yes

spiral maple
#

when it clearly isn't an equilateral triangle

fossil sandal
#

i think its right

spiral maple
#

it isnt

fossil sandal
#

How?

spiral maple
#

it isnt an equilateral triangle

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Read what I am saying.

fossil sandal
#

No how is it not Right

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Right triangle

spiral maple
#

what?

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it is a right triangle

fossil sandal
#

ok thank you.

spiral maple
#

That was evident from the right angle marking

foggy heart
#

Need some help

fossil sandal
#

Yes

foggy heart
#

Anyone know how to do this

fossil sandal
#

:/

#

Can I please just have help

foggy heart
#

Do the sin of the 45 degree

fossil sandal
#

wdym

foggy heart
#

To find the x

fossil sandal
#

ok I thought that X and Y are also going to be 30

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Arent they all =

foggy heart
#

Ok this is fairly simple, lemme do it

fossil sandal
#

ok..

royal basin
foggy heart
#

Why

royal basin
#

we don't give out answers here

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neither should you

foggy heart
#

Oh

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Ok

#

Can u help me do mine

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I sent it above

#

A bit confused on how to set it up

high lily
fossil sandal
#

someone just please help me

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😦

foggy heart
#

@fossil sandal

#

Solve for x and y

fossil sandal
#

I dont know how?

high lily
#

Arent they all =
no, this was already addressed by Mosh

fossil sandal
#

what?

foggy heart
#

Bruh I literally put it in simple terms for u to solve

high lily
#

consider the ratios of a 45°-45°-90° triangle
and/or set up some trig equations

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or even properties of an isosceles right triangle (and apply pythagoras)

foggy heart
#

Still confused

#

?

#

@fossil sandal

obtuse pebbleBOT
#

@fossil sandal Has your question been resolved?

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acoustic pawn
#

is the union of the subspaces that make up the x and the y axis in R^2 a subspace of R^2?

acoustic pawn
#

or wait a better question, what even is the union the axes, is it all ordered pairs (so the plane spanned by the two axis) or litteraly just the two axes

river briar
#

the union of the axis is just the two axes

balmy mortar
#

The union of 2 subspaces is not necessarily a subspace.

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As you've just demonstrated

acoustic pawn
#

Alright

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is the union of the x and y axes a vectorspace tho?

river briar
#

if so, the sum of two vectors; for ex one in the x and the other in the y axes should be in the union

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is it true ?

acoustic pawn
#

no

river briar
#

you have your answer

acoustic pawn
#

thanks for the help! lol

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acoustic pawn
#

whats the span of the set of the union of the x and y axes? (im guessing the x-y plane but i wanne be sure)

balmy mortar
#

what u said

#

no need to guess, you can figure it

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span {(1,0,0,0,...),(0,1,0,0,...)}={(x,y,0,0,0...) for x, y real}

acoustic pawn
#

hmmm okey

acoustic pawn
#

What about the span of the x, y and z axes? it should be R^3 right?

#

since a.(1,0,0)+b.(0,1,0)+c.(0,0,1) spans the entire R^3 space

balmy mortar
#

yes

acoustic pawn
#

thankq

#

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neat flare
#

actually nvm

obtuse pebbleBOT
neat flare
#

i need more help

#

<@&286206848099549185>

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neat flare
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.close

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bronze talon
obtuse pebbleBOT
#

@bronze talon Has your question been resolved?

obtuse pebbleBOT
#

@bronze talon Has your question been resolved?

obtuse pebbleBOT
#

@bronze talon Has your question been resolved?

obtuse pebbleBOT
#

@bronze talon Has your question been resolved?

cyan pagoda
#

then just plot the points

obtuse pebbleBOT
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latent panther
obtuse pebbleBOT
latent panther
#

Can anyone help me with this?

young tartan
#

isnt that basically f'(3)?

balmy mortar
#

no.

#

if h->0, then yes, but irrelevant for question

balmy mortar
latent panther
#

im confused

#

what do I plug in for h?

balmy mortar
#

h is h

#

its a constant

#

just leave it

junior inlet
#

(same with 3)

balmy mortar
#

$$f(3+h) = 4 + 4(3+h) - (3+h)^2$$

warm shaleBOT
#

Shuri2060

balmy mortar
#

To help you out

latent panther
#

I ended up with 7-2h-h^2

#

@balmy mortar

balmy mortar
#

?

#

I mean idk what it is

#

If you want to check

#

try some trivial values

#

h = 0, h = 1

obtuse pebbleBOT
#

@latent panther Has your question been resolved?

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delicate brook
obtuse pebbleBOT
delicate brook
#

I am just really confused on how to do this

#

and I need to know how to get it right

frozen willow
delicate brook
#

really thanks

delicate brook
#

even that method

frozen willow
delicate brook
#

ok

#

I am confused on how that works

#

can you like explain it a bit further

#

@frozen willow

frozen willow
delicate brook
#

yes

frozen willow
#

From the picture

delicate brook
#

yes

frozen willow
#

Then we set either QP or MQ as x
The other will be MP - x

#

from there, we can look at triangles MNQ and NPQ

#

and use pythagorean theorem to set up two equations.

#

Two equations with one variables, x

frozen willow
delicate brook
#

ok

#

continue

frozen willow
#

That's all sadly

delicate brook
#

oh

frozen willow
#

If you're familiar with trig functions we could use those to calculate NQ

delicate brook
#

ok am trying it right now

frozen willow
#

Ok

delicate brook
#

just learned the sine cosine thing in class yesterday

frozen willow
#

Ok. Then we can stick to basic geometry

delicate brook
#

ok

delicate brook
frozen willow
#

That equation right under the diagram

#

Actually, if you're still not satisfied, we could use the fact that triangle PQN and triangle PNM are similar to calculate NQ

delicate brook
#

pmq is a straight line

frozen willow
#

Sorry

delicate brook
#

i think you ment pnq

#

it’s cool

#

but then

#

no

#

then those are the same triangle

#

I’m still not able to understand this

#

@frozen willow can you use that equation that you made to solve this question

#

and can i see that work

#

so i can understand each step that you made

frozen willow
#

We can express MQ in terms of PQ, or vice versa (PQ in terms of MQ)

#

If you do that, you're left with a simultaneous equation with 2 variables

#

This is the key to solving your problem. At least with this approach.

obtuse pebbleBOT
#

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celest copper
obtuse pebbleBOT
celest copper
#

The answer says 53 degrees

subtle quartz
#

the force is like this

celest copper
#

oh howcome? Wouldn't that force be acting to the left then?

#

Or are the forces generally acting towards the object?

#

.close

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weak wind
#

How is a family of functions different from a function with 2 parameters?
it seems to me like every function from a family of functions just has an additional parameter

weak wind
#

nvm

#

.close

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#

@edgy dagger Has your question been resolved?

obtuse pebbleBOT
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@edgy dagger Has your question been resolved?

obtuse pebbleBOT
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@edgy dagger Has your question been resolved?

obtuse pebbleBOT
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jaunty bear
#

how do i solve this?
(substitution method)

obtuse pebbleBOT
unborn valley
#

substitute y in the second equation?

#

what is y given ?

jaunty bear
#

i found x= 1/2

#

but i keep getting the wrong answer for y

obtuse pebbleBOT
#

@jaunty bear Has your question been resolved?

obtuse pebbleBOT
#

@jaunty bear Has your question been resolved?

jaunty bear
#

<@&286206848099549185>

royal basin
#

can you show how you got x = 1/2

#

that doesnt sound right to me at first glance

solid gazelle
#

4x+2(3x+2)=-1
4x+6x+4=-1
10x=-5
X=-1/2

#

y=-3/2+2
y=1/2

#

@jaunty bear

drowsy iris
#

wait

solid gazelle
#

Hm?

drowsy iris
#

-3x+y = 2-- (1)
4x+2y = -1-- (2)
(1)*2: -6x+2y=4 --(3)
(3)-(1) -10x=5
x = -1/2
sub x = -1/2 into (2)
-2+2y=-1
y=1/2

#

@solid gazelle

solid gazelle
#

I have the same answer

drowsy iris
#

yep

#

so ure correct

#

dont worry

solid gazelle
#

👍

jaunty bear
solid gazelle
#

Maybe you mean -3/2

#

y=3x+2
y=3(-1/2)+2

#

y=-3/2+2

#

@jaunty bear

obtuse pebbleBOT
#

@jaunty bear Has your question been resolved?

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tired dust
#

Im not sure if i set this up right

obtuse pebbleBOT
sage geode
#

(a + b)sqrt(ab) isn't the same as a + bsqrt(ab)

tired dust
#

Okay, i’ll remove that step

#

so (a+b)sqrt(ab) is right?

obtuse pebbleBOT
#

@tired dust Has your question been resolved?

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woeful scarab
#

Hey

obtuse pebbleBOT
woeful scarab
#

Just had a quick question

#

How does the top number turn into the. Bottom one exactly?

azure lake
#

U factorise it and take as single any number that is in a pair of three

woeful scarab
#

Ahhh

#

Alright

#

Makes more sense

#

Thx

#

.close

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neat flare
#

i need help

obtuse pebbleBOT
neat flare
unique solstice
#

What's the graph

obtuse pebbleBOT
#

@neat flare Has your question been resolved?

obtuse pebbleBOT
#

@neat flare Has your question been resolved?

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trim island
#

Is there anyway to simplify this

obtuse pebbleBOT
unique solstice
#

Yeah

#

Either multiply top and bottom by x

#

Or treat the division as multiplying by the reciptocal

obtuse pebbleBOT
#

@trim island Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

so when im rounding a digit that is followed by five, which is an insignificant digit
do i always round up, or does it depend on whether the last digit is even or odd?
i mean that some sources tell me that 3.65 rounded to two significant figures will be 3.7
others say that it's 3.6 because 6 is even and the 5 is not followed by other digits

high lily
#

depends on what rounding system you're applying

timid silo
#

i will swear

high lily
#

the most common is to see whether the following digit is less than 5, (where you'd round down)
or greater than/equal to 5, (where you'd round up)

timid silo
#

ty

#

.close

obtuse pebbleBOT
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split wigeon
#

A triangle with sides 25cm, 52 cm, and 63cm has a second triangle drawn inside it with all its sides a distance of 3 cm from the sides of the original triangle. The area of the inner triangle, in cm^2, is

obtuse pebbleBOT
#

@split wigeon Has your question been resolved?

balmy mortar
#

draw a picture?

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split wigeon
#

.close

simple herald
#

2d +4 = 10 + 2.5d the reason i am confused because i thought first we have to get rid of the smaller x. so i did, i got rid of 2d on each side gigving 0.5d = -6 but the awnser is not -3 = d and aparently i had to remove 2.5d? for some reason i dont understand why i would do that, is there any logic to this? because this is so simple but i just cant wrap my head around why its 2.5d and not 2d

simple herald
#

If somone (anyone) can explain what certain order i have to follow to solve these type of equations

#

because lets say 1/2x -2 = 4x +9 is simple because you just get rid of the smaller x which is 1/2x and move it to the right but when i tried to do what i usally do on this type of problem it didint work. why?

upbeat island
#

0.5d = -6 is correct

#

but from there?

#

how can we get rid of the 0.5?

balmy mortar
#

Everything up to that step is fine btw

#

just small mistake

simple herald
#

they said i had to take the 2.5d and put it to the other side

balmy mortar
#

you can do that

simple herald
upbeat island
#

that's just a different way; not wrong

balmy mortar
#

either way is fine

simple herald
#

hmmm

balmy mortar
#

what you did is fine

upbeat island
balmy mortar
simple herald
#

oh

#

oh my gosh lol

#

OHHH

#

ITS -12

#

OMGGG

upbeat island
#

😄

simple herald
#

dudeee

#

u guys are such amazing people

#

for helping me

#

I cant imagine what id do without yall

#

i would've deff broke my monitor

#

or burned my house down

#

maybe cause a riot

#

okie bye bye lol

upbeat island
#

math be like that lmao

simple herald
#

fr bro

#

but i love it

#

hate love relationship

#

but its okay

#

cuz its so satisfying

#

when u get the right awnser

#

and you know how to do things

#

idk lol

#

ok now i offically go

#

adios

#

.close

obtuse pebbleBOT
#
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rotund pecan
obtuse pebbleBOT
rotund pecan
#

Is 21 correct?

#

I am not expert on integration

#

rules

spiral maple
#

no

rotund pecan
#

I am thinking this because the bounds are the same

spiral maple
#

apply linearity of integration

rotund pecan
#

I don't know what that means

spiral maple
#

$\int af(x)+bg(x)\dd{x}=a\int f(x)\dd{x}+b\int g(x)\dd{x}$

warm shaleBOT
rotund pecan
#

i still dont get it

#

18 + 3

#

21

#

Is correct

#

I have to find the integral of 3?

spiral maple
#

yes.

rotund pecan
#

Ur saying

#

But that would be 3x

spiral maple
#

yeah, and?

rotund pecan
#

the options are all constants

spiral maple
#

yeah, and?

#

you evaluate the integral still..

rotund pecan
#

oh i have to plug in

#

21 - 15

#

16

#

6

#

SO 3+6

spiral maple
#

🤨

#

3(7-5)=6

#

18+6 is..?

rotund pecan
#

is 24 the answer

spiral maple
#

yes.

rotund pecan
#

Thy ty

#

yo btw

#

If the integral has a blank lower bound

#

Like from a to b

#

and there is no a number

#

what do u assume the lower bound is

spiral maple
#

a..

#

cause the lower bound is a, you just said it was

rotund pecan
#

nvm

#

I misread this graph

#

i misread this

#

Mb

obtuse pebbleBOT
#

@rotund pecan Has your question been resolved?

timid silo
#

Help

#

How do u do the bot

obtuse pebbleBOT
#
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smoky zenith
#

What do them mean when they ask
8th degree polynomial with a positive coefficient
im suppose to find the end behavior (i know what end behavior is)

short spruce
#

highest degree is ax^8 where a is positive

smoky zenith
#

wait typo
8th degree polynomial with a Negative coefficient
so just ax^-8

short spruce
#

no

#

-ax^8

smoky zenith
#

k

#

how can i move this to the left
i want it at -2

thick finch
#

enter

#

(-2(x+2))^3

#

adding to the x will make it go left and subtracting makes it go to the right

#

adding outside the parentheses you have will make it go up, vice versa goes down

#

hope this helps @smoky zenith

smoky zenith
#

k thanks

thick finch
#

make sure to do .close if you are done

smoky zenith
#

k

#

.close

obtuse pebbleBOT
#
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timid silo
#

hii can someone explain why the answer of this is 4? looking off class notes and teacher never got time to explain

timid silo
#

nevermind figured it out

#

.close

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fresh heath
#
  1. x^2 + y^2 - 2x - 16y = -49
    A) (x - 8)^2 + (y - 1)^2 = 16
    (-8, -1), r = 16
    C) (x - 1)^2 + (y - 8)^2 = 16
    (1, 8), r = 4
    B) (x - 8)^2 + (y - 1)^2 = 16
    (8, 1), r=4
    D) (x - 1)^2 + (y - 8)^2 = 16
    (-1, -8), r = 16
fresh heath
#

Complete the square and write the equation in standard form. Then give the center and radius of the circle.

thick finch
#

is this multiple choice

fresh heath
#

yes

thick finch
#

because the answers say a, c, b, d

fresh heath
#

it is

thick finch
#

typo lol

fresh heath
#

lol

thick finch
#

so group the x and y

#

(x-2)x + (y-16)y = -49

#

make it a quadratic equation

#

x^2+(y-16)y+49=2x

fresh heath
#

then what?

thick finch
#

It simplifies to

#

(x-1)^2 + (y-8)^2 - 16 = 0

#

So its C

#

actually wait

#

theres radius

fresh heath
#

yeah

thick finch
#

its still c

fresh heath
#

how do u get the radius

thick finch
#

so you have

#

(x-1)^2 + (y-8)^2 = 16

#

that 16 part is radius^2

#

so square root of 16 is 4

fresh heath
#

kk

thick finch
#

does it all make sense?

fresh heath
#

enough to code a program for it for the test yes

#

.close

obtuse pebbleBOT
#
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tropic anchor
obtuse pebbleBOT
coarse badge
#

what does the area of a given parallelogram equal?

#

@tropic anchor

tropic anchor
#

doesnt give me the area

#

the picture I sent is the entire question

#

thats what Im confused with

timid silo
#

Ok

tropic anchor
#

I have the base but no height?

timid silo
#

Height is 12 mm

tropic anchor
#

could you explain?

timid silo
#

The two 8mm sides of the quadrilateral are parallel right ?

tropic anchor
#

yes

timid silo
#

So for parallel lines they have the property that perpendicular distance between them is always equal

#

Just shift the 12mm line till it meets one of the vertices and u have it

coarse badge
balmy mortar
tropic anchor
#

oh okay

balmy mortar
#

A base doesnt always have to be flat on the ground (and as a result, the height doesnt always have to point vertically upwards)

tropic anchor
#

ohh

#

okay I can solve it now thank you!

#

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obtuse pebbleBOT
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wraith barn
#

pls help-

obtuse pebbleBOT
hot steppe
#

hi

wraith barn
#

hi

hot steppe
#

oh nvm

#

i was gonna ask something

#

haha

wraith barn
timid silo
#

just fact the x

#

then do formula 01

junior inlet
#

(oops sry cookie)

timid silo
timid silo
wraith barn
#

i cant use a calculator -w-

junior inlet
timid silo
#

idk it's my first day on here

timid silo
wraith barn
#

i cant use that cause I need to show all of my working out

timid silo
#

oh

#

uh then use the classic one wait

junior inlet
timid silo
#

ok i got it sry

balmy mortar
#

To factor cubics and quartics

timid silo
#

use factor theorium

balmy mortar
#

You are always expected to find some 'easy' roots

wraith barn
#

i need o use quadratic formula-

balmy mortar
#

and then do that

#

You are never expected to factor anything above degree 2 without easy roots

timid silo
#

try sub x like 1,-1,2,-2

wraith barn
#

hmmm

#

im so confused ww

balmy mortar
#

Factor/remainder theorem

#

Look it up if u dont know it

timid silo
#

like this

wraith barn
#

I need to use quadratic formula tho

balmy mortar
#

sure

#

Once you have a quadratic

timid silo
#

u fact out x-1, then u can use quad

wraith barn
#

idk how to get to the quadratic

#

wait

#

let me think

balmy mortar
#

factor theorem

#

and then polynomial long division

timid silo
wraith barn
#

i think im supposed to do it differently but- idk

balmy mortar
#

No.

#

This is pretty much the only way

timid silo
#

yup, or use program

balmy mortar
#

i mean ok, if you spotted all 4 roots, then no

#

since all 4 are simple integers

timid silo
#

it's a grey area but u can insert program on ur calculator that instant calculate 3 roots

wraith barn
#

o nvm i got it

#

.close

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coral cloak
#

straightforward question here, I just don't understand what this definition for the norm of a matrix entails, the notation is confusing me. To be clear, max=sup (it's in spanish)

balmy mortar
#

The maximum row sum (if I didn't get that the wrong way round)

coral cloak
#

oh, yeah, makes sense

#

thanks

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versed oracle
obtuse pebbleBOT
versed oracle
#

A-

#

Dont im just in 8th. I suck at math

junior inlet
versed oracle
#

Right so now since bases are same we can simply add the powers innit.

junior inlet
#

yeah

versed oracle
#

(2/9)^9.

junior inlet
#

yep

#

and that is....?

formal trout
#

u will get linear equation iin one variable

versed oracle
#

Since (2/9)^9 = (2/9)^2m-3

2 x m - 3 = 9?

junior inlet
versed oracle
#

I see. So basically just use algebra to solve

balmy mortar
#

🙂

versed oracle
#

Wow I feel kinda stupid now.

#

THanks.

exotic zephyr
#

Need help with B

obtuse pebbleBOT
#

@versed oracle Has your question been resolved?

obtuse pebbleBOT
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exotic zephyr
#

.

#

need help on this one (part B)

obtuse pebbleBOT
exotic zephyr
#

<@&286206848099549185>

#

@alpine crown i already got this channel

alpine crown
#

o

#

mb

obtuse pebbleBOT
#

@exotic zephyr Has your question been resolved?

obtuse pebbleBOT
#

@exotic zephyr Has your question been resolved?

obtuse pebbleBOT
#

@exotic zephyr Has your question been resolved?

timid silo
#

@exotic zephyr idk much about integral but

#

find the area under the graph

#

then add the initial number of ppl

#

compare both number

obtuse pebbleBOT
#

@exotic zephyr Has your question been resolved?

junior inlet
#

@exotic zephyr can you send the question again?

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lament comet
#

so for this question do i rearrange equation 2 in terms of x and then sub into equation 1?

balmy mortar
#

yh

young tartan
#

You should have done that in the first place... Making sure that your method is correct before using it should be avoided in general

balmy mortar
#

u mean try and only ask when ur stuck

young tartan
#

If you have an idea apply it.. If it doesnt work then think why... If you cant figure it out then ask

young tartan
lament comet
#

yeah see i tried that

young tartan
#

Did you get an answer?

lament comet
#

i think i know what to do

#

but i can’t figure out if my method was wrong or my working out is

balmy mortar
#

theres a magical a

#

that appears on the bottom of one of your fractions

#

line 3

lament comet
#

shouldn’t the ‘a’ be multiplied to the denominator tho

balmy mortar
#

$$2\times\frac{2}{4} = \frac{4}{8}$$

#

?

warm shaleBOT
#

Shuri2060

balmy mortar
#

?

lament comet
#

ohhhh ok ok

#

i get it now

#

thank you

#

so for future references:

#

when substituting a fractional value for a variable

#

only multiply by the numerator

#

??

balmy mortar
#

$$a\times\frac{b}{c} = \frac{ab}{c}$$

warm shaleBOT
#

Shuri2060

lament comet
#

ok ok thank you sm

#

.close

obtuse pebbleBOT
#
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tender sun
#

Hi, how can I find the radius of a cylinder by having the volume (3000) and the length (2)

west sierra
#

Imagine the rectangular paper

#

With length 2 units

#

When you fold it, it become hollow cylinder

#

Then fill the vacant up and bottom

#

But in any case

#

Volume of hollow cylinder=volume of proper cylinder

#

Do you just need to know volume's formula here

#

Which pi r^2 h

#

Length will be the height of cylinder

tender sun
#

okay

west sierra
#

Pi r^2 is the area of circle

#

Imagine buncha of circle filling the cylinder all the way from bottom to top of hollow opening

tender sun
#

yes

west sierra
#

So is the volume formula of cylinder justified

royal basin
#

not pi^2 r

west sierra
#

ohh

tender sun
#

r * r * pi

west sierra
#

Yes

tender sun
#

okay

west sierra
#

So you understand how the volume formula of cylinder is made

tender sun
#

yes

west sierra
#

This is called concept

#

With this you don't remember formulas

tender sun
#

but I have to find the R of the circle

west sierra
#

Yes

#

You know the value of pi

#

22/7

#

And h aka length is already given

#

Just substitute the values and form the equation then solve it

#

R is found then.

#

Pi=22/7 or 3.14
I genrally use 22/7 because it's easier with this to simplify

tender sun
#

wait

royal basin
tender sun
#

the exercise is

#

A tank, cylindrical in shape, has a capacity of 3000 liters. What is its radius knowing that its length is 2 m?

royal basin
#

pi, 22/7 and 3.140 are three different numbers that happen to be close to each other

west sierra
#

Always use 22/7 for pi unless specified another value @tender sun

royal basin
#

...

#

good job completely ignoring what i said...

#

pi is not equal to 22/7 and should not be treated as interchangeable with 22/7

tender sun
#

in switzerland i use 3.141592653 for Pi

mild ocean
#

if you’re able to use that, just use the actual value at that point

mild ocean
west sierra
mild ocean
#

22/7 really isn’t even close to pi

royal basin
#

so all this time, you thought that pi was exactly equal to 22/7..

west sierra
#

Yes

royal basin
#

well then you learned something new today.

west sierra
#

Yes

tender sun
#

can you help me to this " A tank, cylindrical in shape, has a capacity of 3000 liters. What is its radius knowing that its length is 2 meter ? "

mild ocean
#

not your channel

royal basin
#

it is XZY's channel actually

tender sun
#

yes

west sierra
#

Or

mild ocean
#

oops

high lily
#

what have you tried so far xzy?

tender sun
#

nothing

#

because i understand nothing

high lily
#

first consider that
1m^3 = 1kL

#

so it'd be helpful to first convert 3000L to kL

tender sun
#

it's 1 litre=1dm^3

west sierra
tender sun
#

ok

high lily
#

i consider using the conversion

1kL = 1m^3
simpler to apply here

tender sun
#

yes

high lily
#

less decimals etc (though other valid conversions are fine too)

#

so it'd be helpful to first convert 3000L to kL

tender sun
#

okaaay

#

it's 3 kL

#

@high lily?

high lily
#

now convert 3kL to m^3

tender sun
#

3m^3 ?

high lily
#

yes

#

now do you know the formula for the volume of a cylinder

tender sun
#

yes

#

and for find the radius with the volume and length ?

west sierra
high lily
#

and for find the radius with the volume and length
bad wording, can't decipher what you mean

tender sun
high lily
#

try fix the wording or clearly show me what you're doing using math

west sierra
tender sun
#

i have found

#

thx you

obtuse pebbleBOT
#

@tender sun Has your question been resolved?

obtuse pebbleBOT
#
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rancid leaf
#

Hi, I have a question
Suppose that A union B = A union C, then B = C?

sage geode
#

No

#

For example {1, 2}U{1} = {1, 2} = {1, 2}U{2}

wary vigil
#

there could be overlap of A with B

#

and similarly of A with C

#

such that B is not C

#

even though the union of A with B = union of A with C

rancid leaf
rancid leaf
#

thank you both ❤️

#

another question, when A - B = B - A? I think is when for example B = empty, it's right?

sage geode
#

It's B is the empty set, then B - A would be the empty set as well

#

And A - B would be A

#

I think A - B = B - A is true when A = B

wary vigil
#

that might be the only way for that to be true i think

rancid leaf
wary vigil
#

i can't see another way