help-10

[spiral maple]

Just run through the RRT options

then apply factor theorem until you find one

[stable kernel]

ohh right ty!

.close

[obtuse pebble]

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[obtuse pebble]

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[timid silo]

is this correct?

[hushed moat]

Yes

[timid silo]

thanks

.close

[obtuse pebble]

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[jagged pebble]

hello

[jagged pebble]

which equation should i use?

i mean funciton

function lmao

[static spade]

look at the values in h( )

there is a condition for each function within the piecewise function

[jagged pebble]

yeah but couldnt t be negative?

[static spade]

t? you mean x

[jagged pebble]

in which case 2+t is less than 2

[static spade]

oh\

im an diot i saw that u needed help with e

that problem is just taking the derivative from the negative side

you would use the function that makes up the left part of the graph

[jagged pebble]

fank u

.close

[obtuse pebble]

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[static spade]

wait

no

[jagged pebble]

😮

[static spade]

im just checking if i was right

i think you take the derivative from the negative side but to be sure ask someone else

[obtuse pebble]

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[torpid tapir]

hey

[torpid tapir]

can i get help with this

just 2 and 3

[static spade]

first get it in vertex form(y = a(x-h)^2 + k)

Locate the vertex

[torpid tapir]

the vertex is 64

[static spade]

(8,64)

ok

so now you just have to figure out the scaling value

choose a given point(like the origin for example)

Find the change in y and then the change in x going from the vertex to that point

[torpid tapir]

64 to 0 is 16??? and 64 to 16 is 48??

[static spade]

well not exactly

[torpid tapir]

how do i find the chnage

[static spade]

what i meant is, by what has the x value and the y value changed when you go from the vertex to the origin

it goes back by 8(or forward by -8) and down by 64(or up by -64)

im sorry ik i didn't really explain what i was doing well

[torpid tapir]

ohhh

i get it now

[static spade]

now consider the parent function of the parabola

[torpid tapir]

okay

[static spade]

what would be the y coordinate of the point with the x coordinate of 8 on the parabola y = x^2?

wait

this is the dumbest method

theres a faster way

remember this?

(the y is cut off)

h and k are the coordinates of the vertex

so as i said before, the function is reduced to y = a(x-8)^2 + 64

and now we have to find a

[torpid tapir]

and how do we do that

[static spade]

plug in one point

the origin

or just take its coordinates and putt hem into their respective parts of the equation

you will get 0 = a*(0-8)^2 + 64

now solve for a

[torpid tapir]

solve for a on this

okay hold on

would that be 3

[static spade]

do it carefully

it would be a good idea to simplify (0-8)^2 first

[torpid tapir]

oh

it’s -1

[static spade]

yes

now that is your A term

[torpid tapir]

so

[static spade]

i mean coefficient

so now

this is your equation

y = -1(x-8)^2 + 64

[torpid tapir]

well you made that easy

thank you

[static spade]

now all you have to do here is expand

[torpid tapir]

alright

how do i expand@it

[static spade]

simplify (x-8)^2

then multiply it by -1

then add 64

[torpid tapir]

x^2 - 16x + 64

[static spade]

yes

now you have y = -1(x^2 - 16x + 64) + 64

distribute then combine like terms

then you will be done

[torpid tapir]

okay hold on

y = -x^2 + 16x

is that right

[static spade]

yes

[torpid tapir]

alright bet thank u

now can u help me with 2

3*

[static spade]

you already have the vertex

(8,64)

i do not like this question because the speed of an object on a parabolic trjectory changes

and derivatives exist

but whatever

[torpid tapir]

lol i think it’s all dumb

for part a wouldnt it be 64 miles

[static spade]

depends on the scale of the graph

if its in miles then yes

anyways i have to go

[torpid tapir]

oh

can u just quickly help me on the last b and c please

[obtuse pebble]

@torpid tapir Has your question been resolved?

[obtuse pebble]

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[tulip yarrow]

Hi guys can anyone describe what is Wolfram

[hushed moat]

Ask Wolfram

,w Wolfram

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Frosty_#7210

[obtuse pebble]

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[obtuse pebble]

@karmic whale Has your question been resolved?

[karmic whale]

<@&286206848099549185>

[obtuse pebble]

@karmic whale Has your question been resolved?

[quaint glen]

hint: notice that the input of the second square root is the negation of the input of the first square root.

So, it might help to make a substitution (2008x+2009)/(2010x-2011)=u. Then y=sqrt(u)+sqrt(-u)+2010, and y and u are real. What can you say about this equation now?

[obtuse pebble]

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[west rock]

i want to find the number of possible combinations
we have 680 characters in the combination, and each one of those characters can be either a letter of the alphabet, or a number from 0-9

[west rock]

@tall arrow @frozen willow

<@&286206848099549185>

[tall arrow]

<@&286206848099549185>

[frozen willow]

My gut says (not really but it's all I have)

[west rock]

Can you give me an answer

Idk how to do all that and plus idek how to read the equasion so

[frozen willow]

Is the question asking for an actual number?

[west rock]

yess

do u have the answer @frozen willow

[frozen willow]

I'm working on it

[frozen willow]

Sorry I was editing my bookmarks. I'll be with you in a second.

[west rock]

kk

[west rock]

anything?

[frozen willow]

436116003068178632599586304885865102436987283273192588087066946205825385420102245537617641171508064231363006853389201952225629937253532766998346708022315458543404066186915809029438078922052852453720811267502691138577239348756804955313693393091406303393978608038048294775593159201377364139187142305434603252709617151318958922901417601677040658907901408937709530384849660728157676437361951488873238454079633326062998564370475129597220298716911739158299214865235291416480348618758676919027696256066573122899301892912081375412160180698274455765997411725112824776559729034126511125728785207316456433746195093026529168420804699808556231371820824328024241019054519605469721555033733292097536/619714851639436418890014132388232229721055870199514672029713148485510155785548673195822182557094494798400485855314018664115518201608296685973696255017718008860040532123882524974640383546972703334250180071289663434135544958849656523081985248650710343202769470217342391253807976629911471752642447788061663944930276641968987762346638120586560511839027435547150981527833225197175924454374035224307681127771766486576057171905208746524480477725129525199567421707397449049063936891779349738354845631072739123214648019547232581118055342755748414269684011304463045987462994690350948128879310152454660263721486248365600435867499900568391454522508666342914028219335005414329126288445145585206396142668389065269978552797679745659901210486853677748890443865391315271920611969308829960200739772083995738927977257540817810677902203676197079603108363889883830099921139511939267811608215117467525741569440368274163296398231782452971855716790343353095564135925989874375234096101328009195610968860734989320967538188120338052495839373498804671998259523511143084795636885698967653407941732643846659592297648481775853082691658914854805644687773899052556517467961272533326685470524128608922559065696262234373778617027011172553071983798674460807790202905576126823916638386435806751251220703125

[west rock]

Ok so

One more question

[west rock]

if theres 3133507531 combinations that are correct, what is the percentage that we'll get a working combination

Can you do it

Please

[frozen willow]

https://tenor.com/view/bart-simpson-i-cant-promise-ill-try-the-simpsons-gif-16779648

[west rock]

<3 Ily ( im not gay btw )

[frozen willow]

48547028867118042879688248613373917690196264963548442433752530163726682938274999710654166169487810923235706229542136346347013393467679349439522982075112897979931543309385832924183280646529186453732543737287306931332976315083612095296016902676947711223136819874573064744983895679942489915004971982354137896595754778188080345544000719584741837530870178225065367655287682431684242980241702631655684826875485088371487138811288330634038241320354277879082469846559569625135765868772483109885444708382721891284785912469137212578549870414998098741384067860320602212822865636150692724870841923820035901810443081144163635178192336414320145082558122874957183397770818981943152313437323549290891112560518689291538208585000265058786625194414304393029883318653410916663963760998948988627186208689910605312568165077521978741453469262521485859413663731450985908330684329169084002557505782301313538978605028836062604049691111634998524080490198601125018559565439923249613499000537226397892105576782989480811408927975129350544039650575620656480113275895365960465642494431977533521979580861217051216041451777780883797214096974014520531479261241407660490307224742467488065435128890887831784815703789036749028059134522608490404788960456410268964373606816021882413847432502507217577658593654632568359375/109029000767044658149896576221466275609246820818298147021766736551456346355025561384404410292877016057840751713347300488056407484313383191749586677005578864635851016546728952257359519730513213113430202816875672784644309837189201238828423348272851575848494652009512073693898289800344341034796785576358650813177404287829739730725354400419260164726975352234427382596212415182039419109340487872218309613519908331515749641092618782399305074679227934789574803716308822854120087154689669229756924064016643280724825473228020343853040045174568613941499352931278206194139932258531627781432196301829114108436548773256632292105201174952139057842955206082006060254763629901367430388758433323024384

[west rock]

thats the percent?

48547028867118042879688248613373917690196264963548442433752530163726682938274999710654166169487810923235706229542136346347013393467679349439522982075112897979931543309385832924183280646529186453732543737287306931332976315083612095296016902676947711223136819874573064744983895679942489915004971982354137896595754778188080345544000719584741837530870178225065367655287682431684242980241702631655684826875485088371487138811288330634038241320354277879082469846559569625135765868772483109885444708382721891284785912469137212578549870414998098741384067860320602212822865636150692724870841923820035901810443081144163635178192336414320145082558122874957183397770818981943152313437323549290891112560518689291538208585000265058786625194414304393029883318653410916663963760998948988627186208689910605312568165077521978741453469262521485859413663731450985908330684329169084002557505782301313538978605028836062604049691111634998524080490198601125018559565439923249613499000537226397892105576782989480811408927975129350544039650575620656480113275895365960465642494431977533521979580861217051216041451777780883797214096974014520531479261241407660490307224742467488065435128890887831784815703789036749028059134522608490404788960456410268964373606816021882413847432502507217577658593654632568359375/109029000767044658149896576221466275609246820818298147021766736551456346355025561384404410292877016057840751713347300488056407484313383191749586677005578864635851016546728952257359519730513213113430202816875672784644309837189201238828423348272851575848494652009512073693898289800344341034796785576358650813177404287829739730725354400419260164726975352234427382596212415182039419109340487872218309613519908331515749641092618782399305074679227934789574803716308822854120087154689669229756924064016643280724825473228020343853040045174568613941499352931278206194139932258531627781432196301829114108436548773256632292105201174952139057842955206082006060254763629901367430388758433323024384%?

[frozen willow]

.

[west rock]

i feel bad for you 😭

but yes, i need a percentage

[tall arrow]

3133507531 out of how many total combinations?

[frozen willow]

Out* of our answer from the first part 🚶‍♂️

[tall arrow]

what?

[west rock]

I think zim got it

Zim u can do it right?

[tall arrow]

48547028867118042879688248613373917690196264963548442433752530163726682938274999710654166169487810923235706229542136346347013393467679349439522982075112897979931543309385832924183280646529186453732543737287306931332976315083612095296016902676947711223136819874573064744983895679942489915004971982354137896595754778188080345544000719584741837530870178225065367655287682431684242980241702631655684826875485088371487138811288330634038241320354277879082469846559569625135765868772483109885444708382721891284785912469137212578549870414998098741384067860320602212822865636150692724870841923820035901810443081144163635178192336414320145082558122874957183397770818981943152313437323549290891112560518689291538208585000265058786625194414304393029883318653410916663963760998948988627186208689910605312568165077521978741453469262521485859413663731450985908330684329169084002557505782301313538978605028836062604049691111634998524080490198601125018559565439923249613499000537226397892105576782989480811408927975129350544039650575620656480113275895365960465642494431977533521979580861217051216041451777780883797214096974014520531479261241407660490307224742467488065435128890887831784815703789036749028059134522608490404788960456410268964373606816021882413847432502507217577658593654632568359375/109029000767044658149896576221466275609246820818298147021766736551456346355025561384404410292877016057840751713347300488056407484313383191749586677005578864635851016546728952257359519730513213113430202816875672784644309837189201238828423348272851575848494652009512073693898289800344341034796785576358650813177404287829739730725354400419260164726975352234427382596212415182039419109340487872218309613519908331515749641092618782399305074679227934789574803716308822854120087154689669229756924064016643280724825473228020343853040045174568613941499352931278206194139932258531627781432196301829114108436548773256632292105201174952139057842955206082006060254763629901367430388758433323024384%?

how is this a valid percentage

literally above 100%

not just above

more than 10 million times higher than that

[frozen willow]

https://tenor.com/view/ryan-gosling-laugh-laughing-lol-giggle-gif-4925536

[west rock]

he got it wrong

@frozen willow are u retrying it?

[tall arrow]

of course i misunderstood again

[frozen willow]

Yes

[west rock]

Ok

[frozen willow]

Need a quick break though

[tall arrow]

3133507531 out of how many total posibilities (that includes wrong too

if we know that 3133507531 is the amount of right posiblities, how many posiblities are wrong @west rock do you know how many wrong posiblities

[west rock]

436116003068178632599586304885865102436987283273192588087066946205825385420102245537617641171508064231363006853389201952225629937253532766998346708022315458543404066186915809029438078922052852453720811267502691138577239348756804955313693393091406303393978608038048294775593159201377364139187142305434603252709617151318958922901417601677040658907901408937709530384849660728157676437361951488873238454079633326062998564370475129597220298716911739158299214865235291416480348618758676919027696256066573122899301892912081375412160180698274455765997411725112824776559729034126511125728785207316456433746195093026529168420804699808556231371820824328024241019054519605469721555033733292097536/619714851639436418890014132388232229721055870199514672029713148485510155785548673195822182557094494798400485855314018664115518201608296685973696255017718008860040532123882524974640383546972703334250180071289663434135544958849656523081985248650710343202769470217342391253807976629911471752642447788061663944930276641968987762346638120586560511839027435547150981527833225197175924454374035224307681127771766486576057171905208746524480477725129525199567421707397449049063936891779349738354845631072739123214648019547232581118055342755748414269684011304463045987462994690350948128879310152454660263721486248365600435867499900568391454522508666342914028219335005414329126288445145585206396142668389065269978552797679745659901210486853677748890443865391315271920611969308829960200739772083995738927977257540817810677902203676197079603108363889883830099921139511939267811608215117467525741569440368274163296398231782452971855716790343353095564135925989874375234096101328009195610968860734989320967538188120338052495839373498804671998259523511143084795636885698967653407941732643846659592297648481775853082691658914854805644687773899052556517467961272533326685470524128608922559065696262234373778617027011172553071983798674460807790202905576126823916638386435806751251220703125

Thats the amount of possible possibilitys

[tall arrow]

and there are 3133507531 correct ones

[west rock]

yes

[tall arrow]

what the actual hell

well ez

3133507531 / 436116003068178632599586304885865102436987283273192588087066946205825385420102245537617641171508064231363006853389201952225629937253532766998346708022315458543404066186915809029438078922052852453720811267502691138577239348756804955313693393091406303393978608038048294775593159201377364139187142305434603252709617151318958922901417601677040658907901408937709530384849660728157676437361951488873238454079633326062998564370475129597220298716911739158299214865235291416480348618758676919027696256066573122899301892912081375412160180698274455765997411725112824776559729034126511125728785207316456433746195093026529168420804699808556231371820824328024241019054519605469721555033733292097536/619714851639436418890014132388232229721055870199514672029713148485510155785548673195822182557094494798400485855314018664115518201608296685973696255017718008860040532123882524974640383546972703334250180071289663434135544958849656523081985248650710343202769470217342391253807976629911471752642447788061663944930276641968987762346638120586560511839027435547150981527833225197175924454374035224307681127771766486576057171905208746524480477725129525199567421707397449049063936891779349738354845631072739123214648019547232581118055342755748414269684011304463045987462994690350948128879310152454660263721486248365600435867499900568391454522508666342914028219335005414329126288445145585206396142668389065269978552797679745659901210486853677748890443865391315271920611969308829960200739772083995738927977257540817810677902203676197079603108363889883830099921139511939267811608215117467525741569440368274163296398231782452971855716790343353095564135925989874375234096101328009195610968860734989320967538188120338052495839373498804671998259523511143084795636885698967653407941732643846659592297648481775853082691658914854805644687773899052556517467961272533326685470524128608922559065696262234373778617027011172553071983798674460807790202905576126823916638386435806751251220703125

the chance of you getting the right answer is the following mess above

[west rock]

i need a percent

[pliant hull]

https://tenor.com/view/why-whatever-gif-23592041

[tall arrow]

well we can simplify the follwing shit above by saying
3*10^9
/
3.6 * 10^29

i don't care if it isn't accurate

the website/ guy who gave you that question needs medical threatment anways

3*10^9
/
3.6 * 10^29

8.3333333e+37

[west rock]

Give percent

[tall arrow]

[tall arrow]

try 0.0000000000000000001

[west rock]

I need real percent

Please

[tall arrow]

what do you mean real percent

0.0000000000000000001% is a percent

you can't convert it into an actual integer

[west rock]

is that the actual percent?

[tall arrow]

where did you get the question from

tell me for god sake

[west rock]

My own question

For something im making

idk if its against tos or anything so i cant say

[tall arrow]

against what tos

[west rock]

idk

it guesses roblox tokens

really fast

like lighting fast

[tall arrow]

oh that thing

[frozen willow]

https://tenor.com/view/monkey-bruh-weak-sick-gif-16818912

[obtuse pebble]

@west rock Has your question been resolved?

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[sick crystal]

Could someone helpme with chemistry? or tell me anywhere someone could help me with it

[jolly ginkgo]

Check network servers

[obtuse pebble]

@sick crystal Has your question been resolved?

[sick crystal]

thanks

[obtuse pebble]

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[meager osprey]

Hello, I am given a cube of each side = 2 and asked to find the points M where

[meager osprey]

So I understand that this just means that the point has to pass by C and be perpendicular to HG

[jolly ginkgo]

What bout CB?

[meager osprey]

Oh

Yea, you're right

what I wrote initially is that it is any line that is perpendicular to HG so any line that passes by any of the sides but that's wrong because then it won't always be crossing C

the answer is that it's all points in the plane (CBF)

But that's just a triangle?

Don't really understand

or how it's any in the plane CBF

[meager osprey]

CB works as you said but if you take the line CF, it won't ever be perpendicular to HG unless I'm missing something?

[jolly ginkgo]

Why not

[meager osprey]

Why would it be?

this doesn't seem perpendicular at all

[jolly ginkgo]

Is that CF?

[meager osprey]

Yea but moved

[jolly ginkgo]

I mean making such figures won't do any good right

I'll tell you how to visualize this

[meager osprey]

Please do

[jolly ginkgo]

Keep the cube such that FGCB is the base

Or just think comparatively how BF is to the base ABCD

[meager osprey]

BF will always be perpendicular

But CF ?

Why is it a triangle :(

[jolly ginkgo]

.

[meager osprey]

I don't understand sorry

[jolly ginkgo]

HG is to BCGF what BF is to ABCD

Right?

[meager osprey]

yes

[jolly ginkgo]

So think about AC and BF, are they perpendicular?

[meager osprey]

ah they are

because it's on perpendicular planes

[jolly ginkgo]

Yeah just think it as plane and line relation

[meager osprey]

Wait

So

It's a misstype right?

from the teacher

[jolly ginkgo]

Which one

[meager osprey]

He said the answer is the plane CBF

but it should be the plane CBFG

because CG is obviously perpendicular

[jolly ginkgo]

I mean it's just notational difference

I bet he meant the same thing just used some different format to say it

[meager osprey]

Oh CBF means the entire plane and not just the area delimited by the triangle?

[jolly ginkgo]

Yeah

[meager osprey]

If i recall you can make limited planes too

which was confusing

[jolly ginkgo]

By limited planes you mean having some specific length

[meager osprey]

well kind of, like a plane of just a triangle area in space as opposed to the entire plane which has no bounds

is what I mean

[jolly ginkgo]

Yes thats no issue

Do you want parametric equation for that?

[meager osprey]

I briefly covered them, just need to brush up on them

But I know them. Dont need them for thsi question though

thanks for your help

[jolly ginkgo]

You're welcome

[meager osprey]

-close

wait

.close

[obtuse pebble]

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[merry rock]

How could I formally prove that A and (A or B) is equivalent to A?

No truth tables. I want to manipulate the expression so it reduces to A

[spiral maple]

x in A implies x in An(AUB)
x in B implies x in An(AUB)

[merry rock]

What

Okay, I'm not just looking to prove it. I'm looking specifically to reduce the equation to just 'A'

I guess it would help to introduce 'not B' somehow, but I'm not sure how to do it

[merry rock]

Optimally, I would get it down to A and (B or not B) or something

[unique solstice]

A(A+B)
(AA+AB)
(A+AB)
A(1+B)
A

[obtuse pebble]

@merry rock Has your question been resolved?

[obtuse pebble]

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[sinful beacon]

1. Find the set of definitions of the function.
2. Investigate the parity, oddness, periodicity of the function, points of intersection with the coordinate axes, intervals at which f (x)> 0 or f (x) <0.
3. Investigate the continuity of the function, find the breakpoints, if any, determine them
   type and find the magnitude of the jump function at breakpoints.
4. Find the boundaries of left and right at the boundary points of the domain and at the points
   rupture.
5. Determine whether the asymptotes have a graph of the function; if asymptotes exist, write them down
   equation.
6. Make a preliminary sketch of the graph.
7. Find df
   dx. Identify critical points and find extremes, growth intervals and
   decrease.
8. Find d
   2
   f
   dx2
   . Find the points where d
   2
   f
   dx2
   does not exist or is zero. Find points
   inflection, convexity intervals.
9. Make a table to include the intervals of growth and decline, convexity and concavity, points of extremum and inflection, extreme values.
10. Draw a graph

I think that this function is neither odd nor even and that's all.

[obtuse pebble]

@sinful beacon Has your question been resolved?

[obtuse pebble]

@sinful beacon Has your question been resolved?

[obtuse pebble]

@sinful beacon Has your question been resolved?

[mild ocean]

[obtuse pebble]

@sinful beacon Has your question been resolved?

[obtuse pebble]

@sinful beacon Has your question been resolved?

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[timber pivot]

If x, y, z > 0 and x + y+ z = xyz probe that
I don't know how to start

[obtuse pebble]

@timber pivot Has your question been resolved?

[timber pivot]

<@&286206848099549185>

[obtuse pebble]

@timber pivot Has your question been resolved?

[winged coral]

My guess is use x+y+z -xyz =0 (eqn 1). Multiply out (x-1)(y-1)(z-1), make eqn 1 look like that on the LHS. You'll have nonzero terms on the RHS, deduce an inequality base on x,y,z>0

[timber pivot]

So i multiply that then cancel like this?

[glad lynx]

That's a division by zero. x + y + z - xyz = 0, so you can't divide by it.

[timber pivot]

I see

[glad lynx]

What I think they mean is
x + y + z = xyz
x + y + z - yz = (x-1)yz

and then do the same with y and z

until you have your (x-1)(y-1)(z-1)

[timber pivot]

-yz? How?

[glad lynx]

expand (x-1)(y)(z)

and then replace xyz with x + y + z

you can do it all in one go that way, actually

[timber pivot]

I don't know how you get that by multiplying x-1 in both sides, i get squares

[glad lynx]

you don't multiply x-1 on both sides, you replace x with x-1

which is the equivalent of substracting xy from both sides

xyz - 1yz

(x-1)yz

[timber pivot]

Oh, i get it know

And with y-1 or z-1 i need to susbtract xy or xz now?

Or i need to make 3 ecuation like a system?

[glad lynx]

try writing out (x-1)(y-1)(z-1) and then expanding that

start by multiplying (x-1) and (y-1), and then multiply the result with (z-1)

[timber pivot]

.close

[obtuse pebble]

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[timid silo]

y=-x^2-6x-8

[timid silo]

trying to find x

I got 8=-x(x+6)

[short spruce]

what

trying to find the zeroes?

[timid silo]

so x must be 4 and -8

yeah

[short spruce]

quadratic formula?

[timid silo]

no with factoring

[short spruce]

then factor it

[timid silo]

I did

[short spruce]

you didn't

[timid silo]

Ok well how do I solve it from 8=-x(x+6)

[short spruce]

you don't

[timid silo]

Why

[short spruce]

because you didn't factor properly

[timid silo]

I just took the 8 from one side

[short spruce]

which does absolutely nothing for you

[timid silo]

Now it can be 8=-x

And 8=(x+6)

That’s how I got 4 and -8

What’s my mistake

[short spruce]

that's not how that works

[timid silo]

Why

[short spruce]

you're using the zero product property on something equal to 8

[timid silo]

Ok so where do I go from 0=-x(x+6)+8

[short spruce]

you go back to step 1 and factor it properly

[timid silo]

What two numbers mulipky to -8 and equal to -6 tho

[short spruce]

that's not what you're trying to do

you have a negative a

[fluid lake]

remember the equation is = 0 you can do smth about the negative equation

[short spruce]

factor the negative and try again

[timid silo]

Ok I’m lost

How do I solve this

[short spruce]

factor it

[timid silo]

Yeah I tried

[fluid lake]

you notice that the equation is negative right?

[timid silo]

Yeah

[fluid lake]

And you can't factor negatives

[short spruce]

what

"the equation" isn't negative and you most definitely can factor negative coefficients

[uncut robin]

yeah

[fluid lake]

I mean you can't factor -x^2.... atm

[short spruce]

yes you can

[uncut robin]

yeah

you can

[timid silo]

Ight what’s the correct way

[fluid lake]

yea by removing ---

[timid silo]

I’m confused

[uncut robin]

but I don't understand why you've written y here

is y=0

[timid silo]

Yeah sorry

[uncut robin]

ok

[short spruce]

looks like he just wrote the function and wants the roots

[fluid lake]

same but whatever

[timid silo]

I want the x intercepts

[short spruce]

.

[timid silo]

How do I do that

[fluid lake]

remove the negative out of the equation first

[short spruce]

by factoring a negative 1?

[fluid lake]

U did that, but try another way

[short spruce]

i trust you can factor a -1 out

[fluid lake]

by including +8 also

[timid silo]

No I don’t know how

Pls explain

[fluid lake]

You did factor -x right?

[short spruce]

if you can't factor a constant out, you should not be factoring polynomials

[fluid lake]

try factoring -1 out

[short spruce]

no

there is no "removing" -1

[fluid lake]

i mean factoring out***

factoring* out

[timid silo]

Do u divide

[short spruce]

you factor

[uncut robin]

lol

[fluid lake]

You did 0=-x(x+6)+8, but this time try factoring -1 out, and include 8 in the process

so from 0=-x^2-6x-8,

[timid silo]

Yeah I don’t know

[short spruce]

https://www.youtube.com/watch?v=-VKAYqzRp4o

[fluid lake]

how did u get -x(x+6)?

[timid silo]

Because x is the common factor

Between the two

[fluid lake]

so, between the three, why not try -1

[timid silo]

What 3?

[fluid lake]

-x^2, -6x, -8

[timid silo]

?

[fluid lake]

factor out -1 from those three, because they are the common factors

[timid silo]

oh wait thank you

I got the answer

[fluid lake]

what is it?

[timid silo]

-2 -4

because it adds to -6

and multiplies to -8

I was saying this earlier but the other dude kept saying factor factor so I didn't get it

[fluid lake]

now you know when -x^2 is negative right?

[timid silo]

how do u mean

[uncut robin]

bro

[fluid lake]

i mean, now you know when an equation that needs factoring is negative

[fluid lake]

oh yeah bro

[timid silo]

what do you mean bro

[fluid lake]

I'll just take that as a typo

[timid silo]

I meant thunder

[uncut robin]

I won't

[short spruce]

factor the damn negative

how hard is it

[timid silo]

it is lmao

[uncut robin]

lmao

[short spruce]

no it's not

[timid silo]

what r u talkin about

[uncut robin]

this is sad

[short spruce]

i'm talking about your answer

[fluid lake]

I mean for us it's not, for him/her it is

[timid silo]

wait what yogurt

[uncut robin]

watch this

[timid silo]

it is -2, -4

[uncut robin]

learn

[fluid lake]

yes it is, but do you know why you need to factor out a "-1"?

[timid silo]

because -1*-8 = 8

[fluid lake]

hm not really, i want you to think bigger

[timid silo]

that's just the way u factor tho

what do u mean

[fluid lake]

why did we factor out -1 from the -x^2-6x-8?

[timid silo]

I don't know apart from that's how u factor

can u explain

[fluid lake]

it is to make things easier finding x

[timid silo]

and why is this wrong

thunder said bro

why is this incorrect

[fluid lake]

cause when it is -x^2, you have to find x and -x smth

[timid silo]

oh wait

[fluid lake]

because (-4)x(-2)

[timid silo]

?

[fluid lake]

it's not -8

[timid silo]

oh right

[short spruce]

just factor the negative and your way works

[fluid lake]

the original equation was -x^2-6x-8=0

[timid silo]

frick I still don understand

[fluid lake]

But since it's hard to find the factor of x when dealing -x^2 blah blah

so you gotta factor out -1, so you have a new equation which is

[timid silo]

how do u factor the -1

[fluid lake]

how did u find the answers then?

[timid silo]

I I thought it was +8

[fluid lake]

yeah how is it +8 when you didn't factor out the -1

[fluid lake]

this was the original eq right? so when you factor out -1 what happens

[timid silo]

.

[fluid lake]

just follow this motto when you're dealing a -x^2 or so, it's hard to explain why you gotta factor -1 out

[timid silo]

pls explain it to me

[short spruce]

it's not hard

[timid silo]

not why but how

[short spruce]

you're factoring a constant out

it's just like factoring literally anything else out

factor 2 from 2x+4

just like that

[timid silo]

wait am I not correct

the -8 becomes +8

because -1 * -8 = 8

[fluid lake]

can you write out the whole equation when -1 is factored out?

[timid silo]

wait gimme some min

I;m in class

[fluid lake]

np take your time

[timid silo]

(x-4)(x-2)

@fluid lake

wait no

[fluid lake]

oh sike

[timid silo]

is it correct

[fluid lake]

that;s wrong

[fluid lake]

no

let's take a step back

write the equation when -1 is factor out

[timid silo]

(-x^2-2x)(-4x-8)

[fluid lake]

that's wrong, and don't separate it yet

[timid silo]

-x(x+2)-4(x+2)

(X+2)(-x-4)

X+2=0

-x-4=0

X=-2

[fluid lake]

don't separate it

[timid silo]

X=-4

[fluid lake]

just factor out -1 from -x^2-6x-8

[timid silo]

I just did

I got the answer right?

[fluid lake]

you didn't, you factor out -x

oh you got the answer right, yes, but that's a hard way of doing it

[timid silo]

But you can still solve without factoring

Oh i learn this way

[nocturne minnow]

You realize that's factor by grouping

[fluid lake]

I just did

[timid silo]

Yeah ik

Is there other way

I don’t know what u mean factor -1

[fluid lake]

yes

[nocturne minnow]

AC method

[timid silo]

What is ac

Pls tell

[nocturne minnow]

The A term times C term

[timid silo]

I did that?

[fluid lake]

is it FOIL method right?

[timid silo]

-1*-8

[nocturne minnow]

It's a modified version of factor by grouping

[timid silo]

Which way better

[fluid lake]

depends, but most of the time u do AC or FOIL idk if it's the same

[nocturne minnow]

FOIL is to expand

[fluid lake]

AC is reversed?

[nocturne minnow]

Doesn't matter, it all results in the same answer

[fluid lake]

but in kind of the same terms

[nocturne minnow]

Yes

[fluid lake]

thx

[timid silo]

Ok ty

.close

[obtuse pebble]

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[earnest mirage]

i say its not a polynomial

is that right?

[nocturne minnow]

Don't give out answers, not the purpose of the server

[earnest mirage]

then what should i do

[spiral maple]

Try and help them....

[nocturne minnow]

You teach

[earnest mirage]

ohh i see

[nocturne minnow]

Distribute

Yes, that's what distribution is

[obtuse pebble]

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[humble moon]

the eigenvector corresponding to eigenvalue +1 should be [1,i] whereas the vector im calculating is [i,1] which i don't believe can be scaled to the correct vector. i'm unsure what's going on here as wolfram is returning my value

[humble moon]

wow im an idiot, misplaced negative in the Y operator

.close

[obtuse pebble]

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[autumn lintel]

4b) what should my respons be?

[autumn lintel]

i have some idea on maybe converting the equation to quadratic and seing if a>0 or a<0 to see if the graph intersects the x axis

but is there like a easier method

is there a way to derive an answer just based on the vertex form?

[obtuse pebble]

@autumn lintel Has your question been resolved?

[tired shell]

what's the question?

[autumn lintel]

state the type of root for f(x) = 0

then justify your answer

[tired shell]

well it has a minimum above the x-axis, and it has a positive coefficient in front of x^2, so it never hits the x-axis

so the roots are imaginary

[autumn lintel]

ah okay gotcha

i thought i had to do sum else

thanks lots

.close

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[mellow fulcrum]

a small addition

[obtuse pebble]

@mellow fulcrum Has your question been resolved?

[mellow fulcrum]

<@&286206848099549185>

[feral saffron]

I would rather not open the pdf, is that picture what's in it?

[mellow fulcrum]

yes

[feral saffron]

You want to check that?

[mellow fulcrum]

I made a mistake but cannot find it.

[feral saffron]

Let me see if I can find it

On the last line, shouldn't it be $2^{2n-1+1}$?

[warm shale]

pastalover69

[mellow fulcrum]

the +1 comes from the 1 infront and the +1 and -1 cancel out and at the end $x^(2n)*2^(2n)=(x2)^{2n}$

[warm shale]

Jason Gadewoltz

[feral saffron]

yes

[mellow fulcrum]

if this is what you meant?

did i make a mistake there I can not see it

[feral saffron]

But I still don't see where the +1 comes from

[mellow fulcrum]

the 2 infront of the sigma
the one that was there from the beginning

[feral saffron]

you wrote $2^{n-1+1}$, but it should be $2^{2n-1+1}$, and to the right of the equal sign it should be $2^{2n}$

[warm shale]

pastalover69

[feral saffron]

Yeah, I mean the plus one that should come in the conclusion

[mellow fulcrum]

yes you are correct

thank you
but that still will not solve the problem

[feral saffron]

Yeah, I will look at it one more time

[feral saffron]

I am going to try to do it the other way around

I might be wrong, but starting from the RHS gives C(2x)=2C(x)^2 still

[mellow fulcrum]

hm thank you

[feral saffron]

yeah sorry if I couldn't be more helpful

[mellow fulcrum]

no problem thank you for you help

[feral saffron]

Ok

I think I know

that formula for the binomial coefficient doesn't work for n=0

[mellow fulcrum]

thank you

[feral saffron]

Yeah, I guess that the natural numbers don't consider 0 in this case

Because if n=0, the binomial coefficient should be equal to 1, but the formula would give 1/2

So if we consider n=0 separately, we have the 0 term $2*(-1)^0x^0*1=2 +\sum_{n=1}^{\infty} (what you have)$

[warm shale]

pastalover69

[feral saffron]

But the first term in C(2x) is 1, so we need to add 1 to compensate

also, in the next to last equal, you shoul have $2^{2n}$, not $2^n$

[warm shale]

pastalover69

[feral saffron]

Does this make sense?

[mellow fulcrum]

yes I think so
how do you then at the end go back to n=0?

[feral saffron]

You separate the 2 into 1+1

you add the one as the n=0 term of the sum

[mellow fulcrum]

ah thank you

[feral saffron]

You are welcome

[mellow fulcrum]

like this?

.closed

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[obtuse pebble]

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[feral saffron]

Yeah that is fine

[obtuse pebble]

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[inland parrot]

Can anyone help me?

[earnest mirage]

Uk what reflexive, symmetric and transitive means right?

[inland parrot]

Yes....but Idk how to prove it

[inland parrot]

What does it mean for you??

[earnest mirage]

A relation is reflexive if x is related to x

Symmetric if x related to y implies y related to x

Transitive if xRy and yRz implies xRz

[inland parrot]

and how we do know to prove it?

[earnest mirage]

x is related to x is (x,x) lies in the relation

so check that

[inland parrot]

how about x = 3?

[earnest mirage]

the relation between x and y is given, all you have to do is replace y with x

[earnest mirage]

you could do that, but it isnt really a way of proving

[earnest mirage]

to check if x is related to x

r u getting what i m saying

[inland parrot]

A little , can u tell me how to prove it

[earnest mirage]

k ill do the 1st one

to check if it is reflexive, replace y with x

so u get x=x^2

but this isnt true for all real numbers

hence R is not reflexive

understood?

[inland parrot]

Ohh cool

[earnest mirage]

for symmetric, assume that xRy is true

i.e. x=y^2 is true

then check if that implies that y=x^2 is true

we can write x as y^2

so then we get y=y^4

clearly this isnt true for all real numbers

so R is not symmetric

[inland parrot]

what is anti symmetry btw?

[earnest mirage]

for transitive assume that xRy and yRz are true and check if that implies xRz is true

if a relation is antisymmetric it means that the existence of xRy implies that yRx doesnt exist in the relation

[inland parrot]

how can I implies xRz

[earnest mirage]

Check if u can get the expression for xRz from the expressions for xRy and yRz

[obtuse pebble]

@inland parrot Has your question been resolved?

[inland parrot]

i dont know how to check it

[earnest mirage]

Similar to how i checked for symmetric

Do the same thing

[inland parrot]

z = y^8?

[obtuse pebble]

@inland parrot Has your question been resolved?

[earnest mirage]

Im a bit busy rn, ill get back to it later

[inland parrot]

okay

[obtuse pebble]

@inland parrot Has your question been resolved?

[earnest mirage]

Ok so we want to check transitivity
That means that xRy and yRz are true statements
So x=y^2 and y=z^2
We can replace y with z^2 in 1st eqn
So x=(z^2)^2
Hence x=z^4

Now we wanna know if x=z^2
We now know that x=z^4
So we can write z^2=z^4
This is clearly not true for all real numbers

Hence R is not transitive

@inland parrot

[inland parrot]

what about the "combination" ?

[royal glacier]

Equivalence relation

I think

[inland parrot]

So, a is not equivalence then right

[earnest mirage]

True

[inland parrot]

how about b and c?

[earnest mirage]

Im not doing those for you

Go ahead and face them with the knowledge thay u have gained

[inland parrot]

okay, but we dont need to use any prove right?

like using x = 3 or something

[earnest mirage]

You can use that to verify, but i wouldnt call it a proof

[inland parrot]

Ok thanks

btw, can u explain more about anti symmetry?

[earnest mirage]

Well idk much about antisymmetry lol

All i learnt is reflexive, symmetric and transitive lol

[inland parrot]

Ahh okay

<@&286206848099549185> anyone?

[obtuse pebble]

@inland parrot Has your question been resolved?

[inland parrot]

Hello??

I just want to know about anti symmetry

[inland parrot]

GG

[obtuse pebble]

@inland parrot Has your question been resolved?

[zinc stump]

A relation R is antisymetric if "aRb and bRa implies a=b"

[obtuse pebble]

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[proven musk]

Minimun amount of numbers you have to check to find factos of a number?

[orchid ibex]

From 1 to half the number

[proven musk]

oh

the reason why I ask is how do you find out if a number is a prime number

sieve of erathonesis

I forgot how to spell it

needs you to start at a prime number and that’s inefficient

with large numbers

[solar ember]

primes below square root of the number is enough

[proven musk]

to check if a number is prime?

[solar ember]

yep

[proven musk]

thanks

uhh

.close

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[frail dune]

Need help solving?

[obtuse pebble]

@frail dune Has your question been resolved?

[obtuse pebble]

@frail dune Has your question been resolved?

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[celest gorge]

I only got two solutions for part 2

48.19 and 131.81

how do I get thr othet two

[short spruce]

cos^2(x) is positive in all quadrants

[celest gorge]

?

[short spruce]

you have a solution in each quadrant

you have the solutions in quadrants 1 and 2, you need the solutions in quadrants 3 and 4

[celest gorge]

can you show me

where quadrant 3 and 4 are

[short spruce]

you've never seen the unit circle?

also you did not graph cos^2(x)

[celest gorge]

mb

wait but I still dont understand what u mean by quadrants

I got the 2 values where are the other 2

[short spruce]

.

[celest gorge]

I've seen it breifly

not much in detail

[short spruce]

that might be of importance when learning about trig functions

[celest gorge]

Well for now can I solve this question without knowing about the unit circle?

[short spruce]

if you understand the quadrants, yeah

[celest gorge]

can you explain

i did square root of 4/9 to get +-2/3

then did inverse cos(+-2/3)

to get my two valeus

how do I get the other 2

[short spruce]

by getting the angles in the third and fourth quadrants with the same reference angle

[celest gorge]

how do i do that..

[short spruce]

it's not really of service if i just tell you how to do it while you have no understanding of what it means

[celest gorge]

k...

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[short spruce]

https://www.youtube.com/watch?v=_gE2aE9OPl8

[obtuse pebble]

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[rich dove]

Hi everyone, i need some help understanding my homework. Is anyone familiar with natural deduction proofs?

[rich dove]

I need to proof this f.e. ∀x(Ax ∧ Bx) ⊢ ∀xAx ∧ ∀xBx

[obtuse pebble]

@rich dove Has your question been resolved?

[rich dove]

How do i ping <@&286206848099549185> ?

[nocturne spruce]

You just did, little fella

[nocturne spruce]

Well i cant help you with this,sorry. But please wait for another help to come along.

[rich dove]

Alright thnx mate

[rich dove]

<@&286206848099549185> anyone?

[fathom wren]

What's ⊢ in this context?

[rich dove]

Thats the symbol that splits the statements

You gotta read it like =

[fathom wren]

Oh so ≡ (logically equivalent)?

[rich dove]

Yeah

[fathom wren]

What's A and B? Sorry, I find this whole statement is in a weird notation to read.

(from the usual logic and proof that is)

[rich dove]

It is predicate logic natural deduction

[fathom wren]

What I'm used to is: ∀x:[A(x)∧B(x)]≡[∀x:A(x)]∧[∀x:B(x)]. I think this question is a simple truth table sort of thing.

[rich dove]

No its not

Answer needs this format

[fathom wren]

Yeah I haven't dealt with these kind of questions so I might not be of help either. My take on it would be "∀x:A(x)∧B(x)⇒∀x:A(x)" and "∀x:A(x)∧B(x)⇒∀x:B(x)", combining them would naturally yield:
"∀x:A(x)∧B(x)⇒∀x:A(x)∧∀x:B(x)". I'll let someone else help since my way probably isn't the way to go about it.

[rich dove]

Np Thnx for the effort bro!

Anyone else <@&286206848099549185> ?

[obtuse pebble]

@rich dove Has your question been resolved?

[obtuse pebble]

@rich dove Has your question been resolved?

[obtuse pebble]

@rich dove Has your question been resolved?

[obtuse pebble]

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[pearl condor]

I was confused on what is asking me to do because its asking me to solve for f(x) but i dont know the values to use or steps to take

[pearl condor]

the answer choices are : f'(x), g(x), e^x, 0, and 1

[royal basin]

h(x) = f(x)g(x)

differentiate both sides of this

see what you get

[pearl condor]

f(x)g'(x)+g(x)f'(x)

=h'

[pearl condor]

so then you would set this equal to the other equation h'x is listed as?

and simplify?

lol nvm i got it👍

.close

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[oblique basin]

I need to find out all x ∈ R for this power series. And the solution should be an interval and I need to clarify if the interval borders belong to the solution.

[novel knoll]

Where are you stuck?

[oblique basin]

i dont know what criteria i should use

and how i'd even get an interval as a result

[novel knoll]

Definition of radius of convergence

And how to calculate it

[oblique basin]

ahh and the circle with the radius defines the interval the series converges towards?

so basically the diameter is the interval range

[novel knoll]

Not sure what you mean with “towards”

But yes

[oblique basin]

sorry i have to roughly translate everything

but thanks!

i'll try that criteria

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[vital pasture]

Help

[vital pasture]

Circle F has a central angle of 3pi/4 with radius 9 m. Find the area of the segment.
66.79 sq. m.
7.42 sq. m
133.58 sq. m
93.76 sq. m

[short spruce]

what have you tried

[obtuse pebble]

@vital pasture Has your question been resolved?

[obtuse pebble]

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[sleek galleon]

Hi

[short spruce]

hola

[sleek galleon]

Can you help me?

[short spruce]

i do not speak italian

[sleek galleon]

Okay

PROBLES 1 A COMPANY FOR THE PRODUCTION OF A DETERMINED GOOD, IT WILL BENEFIT THE FOLLOWING COSTS IN A YEAR. RARE FIXED COSTS AT • COST D150 euro FOR EACH UNIT PRODUCED • EXPENSES EQUAL TO F5% OF THE SQUARE OF THE NUMBER OF UNIT PRODOWE 1687500 euzo DETERMINES THE FUNCTION THAT EXPRESSES THE COST HÊNO RIO UNIT, SPECIFYING FOR WHICH PRODUCTION THIS COST AND THE AVERAGE RININO COSTS WHEN MINIKO PROBLEM 2 IS A COMPANY, IN ORDER TO PRODUCE A DETERMINED GOOD, IT BENEFITS THE FOLLOWING COSTS IN A PRODUCTIVE CYCLE: FIXED COSTS COST OF. MAINTENANCE EXPENSES EQUAL TO 0.2% OF THE SQUARE 5000 € 8 € FOR EACH KA PRODOWO OF THE NUMBER De kQ PRODUCTS THE GOOD IS SOLD AT 15 € per ka. IN LOSS OR THE QUANTITY OF Ka TO PRODUCE AND SELL FOR THE MAX UTI LE OBTAIN OR THE LIMITS OF PRODUCTION TO ENSURE THAT THE PROFIT DOES NOT DROP BEYOND 4 OF THE MAXIMUM PROFIT

[short spruce]

i understood that less than the italian

[royal basin]

this looks like it was OCR'd and then google translated

Problem 1

A company incurs the following costs for the production of a certain good in one year:
- Fixed cost of €1,687,500
- €150 for every unit produced
- An extra cost of 0.75 times the square of the number of units produced

Determine the function that expresses the average cost per unit produced and the production volume for which this cost is minimized; find also the value of the minimized unit cost.

problem 2 has the same ish setup with different numbers, but now we also have a sale price (15€/kg) and we want to find the range of production volumes at which we don't sell at a loss, the volume at which profit is maximized, and the range in which we make at least 4/5 of max profit.

that's how i understand it anyway

[obtuse pebble]

@sleek galleon Has your question been resolved?

[royal basin]

@sleek galleon it would be great if you could show us the work you've done so far, if any
and also please tell us exactly where you are getting stuck

[sleek galleon]

ok after I send the photos of what I did

[royal basin]

okay, yes, please send that

[obtuse pebble]

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[obsidian pine]

what is the antiderivative of 1/x, different sources keeps giving different answers

[brisk grove]

ln|x|

we have the absolute value because we want it to be defined on the negative numbers aswell, just like 1/x

also think about it this way:
derivative of ln(x) is 1/x
but the derivative of ln(-x) is also 1/x

therefore the answer is ln|x|

[obsidian pine]

ok thanks, just that most of the derivative calculators in the internet gives me log ://

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[obsidian pine]

.reopen

[obtuse pebble]

✅

[obsidian pine]

this is basically wrong then?
and if I did use ln instead of log, will I have solve for the definite form through the process underlined, and not ln(e^1+e + (1+e) - ln [substitute 1] like its normally done?

[brisk grove]

Well, I think that since your bounds are positive, they just use ln(x) and not ln|x|

Also in this case, log is referring to ln.

[obsidian pine]

why does it do log(1+e) or ln(1+e) on substitution and not use ln(x+e^x) since u=x+e^x

[brisk grove]

From this question, I see that the originals bounds were 0 and 1, right?

But after we subbed in u, those bounds change.

Let's say we have x+1 on the bounds 0 and 1.
We substitute u = x + 1, so our expression is now just u.

We can not plug in 0 and 1 anymore, because those are the values we wanted to plug in for x and not for u.
So we check what we need to plug into u, like this:

0 + 1 = 1, and 1 + 1 = 2

So our new bounds are 1 and 2, instead of 0 and 1.

In the question, you either replace u back with xs and plug in 0 and 1, or you check what the bounds are for u and plug those in.

I hope you understand my explanation, I'm not very good at this

They ask for the arena between x = 0 and x = 1

And that's equal to the area between u = 1 and u = e + 1

[obsidian pine]

yeah ok understand that part now thank you

but for the evaluate the antiderivative, they didn't substituted the u properly isn't it supposed to be u=x+e^x

[brisk grove]

They never substituted u back again.

They got ln(u), and they evaluated that from u = 1 to u = 1 + e.

[obsidian pine]

is that allowed?

[brisk grove]

What do you mean?

The bounds for u are 1 and 1 + e.

So they just do ln(1 + e) - ln(1)

[obsidian pine]

ohh

i get it now ty ty

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[kind summit]

how do i find newtons approximation for just 1 variable?

is its just L(t)= dt+r(t)?

then plug in values?

or do i make this: tln(t) i + (t) j + (e^(-t))k

and then do L(x,y,z)?

<@&286206848099549185>

[obtuse pebble]

@kind summit Has your question been resolved?

[kind summit]

<@&286206848099549185>

<@&286206848099549185>

[obtuse pebble]

@kind summit Has your question been resolved?

[obtuse pebble]

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[brave river]

the range of csc theta and sec theta is (-infinity, -1] U [1, inifity), explain why.

[obtuse pebble]

@brave river Has your question been resolved?

[naive fossil]

Yes, depending on the interval. Looking at a graph in desmos or something like that may be helpful.

[brave river]

ya but like why is it like that 🤨😼

[naive fossil]

https://www.dummies.com/article/academics-the-arts/math/pre-calculus/how-to-graph-a-secant-function-166718

You're trying to go into depth, which I applaud. Understanding trigonometry is important if you want to understand why a trig function looks the way it does.

[brave river]

Alright thanks

.close

[obtuse pebble]

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Use .reopen if this was a mistake.

[obtuse pebble]

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Remember:
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[vernal root]

if a is congruent with b(modc), is a(modc) congruent with b?

[livid osprey]

Write a as nb +c and vice versa and look at the congruences and see how they work out

[vernal root]

im just wondering in general

[livid osprey]

Also I that’s not how congruence is expressed

it’s a is congruent to b in mod c

And b is congruent to a in mod c

[vernal root]

you write a(modc)

[livid osprey]

Can I give the answer

[livid osprey]

Yes but while writing congruence u write it as a congruent symbol bmodc

[vernal root]

well yeah of course

but im just wondering if bmodc is congruent to a if b is congruent to amodc

[livid osprey]

Ya it is

[vernal root]

this

oke

what does 4modulo5 mean

its equal to 4 apparently

[livid osprey]

Yes

Modulo is the remainder function

[vernal root]

remainder when 4 is divided by 5

[livid osprey]

Ya that’s 4

[vernal root]

oh so its 4

cuz it cant be divided once

[livid osprey]

Ya

[vernal root]

but why do you write that a is congruent to bmodc

[livid osprey]

Also modulo can also be represented as congruent tonegative number

[vernal root]

doesnt congruent mean same?

[livid osprey]

It means they have the same reminder

[vernal root]

when divided by c?

[livid osprey]

Ya

[vernal root]

oke

thx

!close

.close

[obtuse pebble]

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• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crystal plinth]

.reopen

oh

[vital dew]

@crystal plinth do you have a question?

[crystal plinth]

im looking for the picture one sec

if anyone knows how i get 6 and 3 and 2

thats what i need

i cant find a server where i can get help with electrical engineering but i think you guys can understand this too

[vital dew]

Do you know about Lowest Common Multiple

LCM

[crystal plinth]

well i know of it

[vital dew]

That’s what’s been done there

[crystal plinth]

but idk how i can apply it here

[vital dew]

Wait

For example to add 1/10 + 1/20 + 1/30 what is the answer

[warm shale]

......................

[vital dew]

@crystal plinth

[crystal plinth]

3 for 30, 2 for 20

and 6 for 10? i dont understand it

[vital dew]

What’s the answer in fractions

[crystal plinth]

actually no cause 2 applies to 30 as well

ohhh one sec

[vital dew]

What’s the lowest common multiple of 30 , 20 and 10

[crystal plinth]

dont you get 7 from 10 and not 6 though?