help-10

[timid silo]

ok

so you said when i pick an x1

oh wait

could you breifly explain the meaning of convergence?

[warm shale]

KurtDee

[timid silo]

ohh i see

how many values of x1 am i trying to find?

im kinda slow at calc ngl

okok ill try it

hold up im just confused how to pick my first x1... do i just pick something random?

nah this is calc lol

lmao k

indeed

so could i start with say, 1?

this is legit simple dk why im thinking so much

aight thanks for the help👍

.close

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[compact prawn]

Can anyone help with b?

[obtuse pebble]

@compact prawn Has your question been resolved?

[compact prawn]

<@&286206848099549185>

[toxic linden]

can someone help me

I NEED HELP??

[obtuse pebble]

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[empty hull]

i feel like you could google that one tbh

just like 'what is response bias' and 'what is non-response bias'

[obtuse pebble]

@paper garden Has your question been resolved?

[obtuse pebble]

@paper garden Has your question been resolved?

[nocturne minnow]

Why did you ping helpers in every channel?

[hybrid gull]

Nope

#❓how-to-get-help

[nocturne minnow]

read #❓how-to-get-help

[oblique glacier]

@unkempt harness don't do that. First warning. Next one is a ban. Read #❓how-to-get-help

[vital pasture]

Help

[obtuse pebble]

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[viral summit]

Each side of a square is lengthened by 4cm. The area of the new larger square is 169cm. Write the polynomial for the area of the larger square using the variable of “s” to represent the length of the original side.

[junior inlet]

so

the new square has sides

s+4

right?

[viral summit]

Sorry, yes that’s correct

[junior inlet]

uh

i'll draw a diagrm real quick

[viral summit]

I am struggling hahah.

I know the length of the side is s+4

But I’m struggling translating it into the polynomial itself

Equation*

[junior inlet]

find the area of each part

and then add them up

[viral summit]

X+4=13

[junior inlet]

uh

no

they're asking for the polynomial

right?

[viral summit]

Right and I’ve got the area of the larger square being 169

[junior inlet]

now

[viral summit]

Therefore 13-4=s=9?

[junior inlet]

calculate the area of each part in this terrible drawing i made here
and add them up

[viral summit]

X2+2(4)+yellow?

[junior inlet]

this might hwlp

uh

the total area of all the parts is 169

[viral summit]

Okay

[junior inlet]

calculate the red area first

[viral summit]

81cm^2

[junior inlet]

no

i mean

in terms of x

[viral summit]

X^2?

[junior inlet]

it's a square with sides x

x^2

right

now calculate the area of the orange part

[viral summit]

4(9)^2+4(4)^2?

[junior inlet]

uh

no

in terms of x

[viral summit]

Fuck im dumb

[junior inlet]

the orange part is a rectangle with sides x and 4

[viral summit]

Okay

Im struggling man

[junior inlet]

for the yellow area

just calculate it 😉

[viral summit]

Yellow area is 4cm2

[junior inlet]

no?

it has sides = 4

so it should be 4*4

[viral summit]

4^2*

[junior inlet]

and that is?

[viral summit]

16

[junior inlet]

right

so

the total area is 169

it's equal to the red area + 2*orange area + yellow area

= x^2 + 2*(4*x)+16

expand the second term

and that's your polynomial

[viral summit]

Ok

So c^2+8x+16=169

[junior inlet]

why c^2?

[viral summit]

Sorry.

X

My bad fat fingers

[junior inlet]

yeah

that's right

[viral summit]

Awesome okay

So the x^2 is smaller area

The coefficient is those outside rectangles

And the plus is the smaller one

[junior inlet]

i can't unerstand a single word in this

[viral summit]

My bad man hahah I’m new

But this

Thanks that actually helped so@much

Cheers

.closed

[junior inlet]

.close

[obtuse pebble]

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[wary sun]

Hey, so I'm trying to do this one without guessing, but having a bit of a trouble finding what the right n value should be if anyone can help

[wary sun]

Here's what I tried so far:

I just saw that it says 4 decimal places but my question still stands, it's just that I'm supposed to have 1/10000 instead of 1/100

[obtuse pebble]

@wary sun Has your question been resolved?

[brave bramble]

Not certain what you're up to here. Why not start summing terms?

Are you allowed a calculator?

[wary sun]

yes I am, this is what I was going off of: https://math.stackexchange.com/a/2965367

[obtuse pebble]

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[chrome orbit]

does this refer to the laplace transform?

[craggy iron]

yes

[chrome orbit]

the entire function description is not given

[craggy iron]

It's the whole problem

[chrome orbit]

is the function periodic?

[craggy iron]

i mean

it doesn't make sense to me

[chrome orbit]

it has to be periodic

or you have the question wrong

[craggy iron]

so then lets assume it's periodic, what should ido

[chrome orbit]

https://math.stackexchange.com/questions/358784/laplace-transform-of-a-periodic-function

and f(t+1)=f(t) in your case

i think

[craggy iron]

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[daring wind]

help with 2x+1=7

[daring wind]

.close

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[chrome orbit]

@daring wind please occupy only one channel at once

[timid silo]

@daring wind stop spamming for help

[ocean topaz]

.close

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[oak pond]

hello

[jolly ginkgo]

No repost

[obtuse pebble]

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[oak pond]

no

[obtuse pebble]

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[radiant cobalt]

hi guys does anyone know how to simplify

[naive fossil]

One method would be to find the Lcd of top and bottom and multiply all terms by it

[obtuse pebble]

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[wet dove]

i dont get how to expand two algebraic expressions

[unique solstice]

Wdym

[wet dove]

like (y+1)(y-3)

[unique solstice]

You distribute each term in the first one to each term in the second one

[wet dove]

so yxy, then yx3?

then 1xy and 1x3?

[unique solstice]

-3

But yes

[wet dove]

oh yea

[unique solstice]

Its the same for even bigger expressions

You just distribute each in the first to each in the second

[wet dove]

and at the end add all of them together?

[unique solstice]

Ye

Just like normal distribution

[wet dove]

alright thanks!

.close

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[unique solstice]

Np

[obtuse pebble]

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[fathom lion]

Hello

[fathom lion]

If you have two equations I know you can solve them simultaneously by adding and subtracting but can you divide them?
for example If I divide equation 2 by equation 1 it will remove P
leaving me with tan(alpha) but im not sure if that's possible

https://cdn.discordapp.com/attachments/791204354757361684/913093792322699344/unknown.png

The question is can you solve simultaneous equations with dividing and multiplication ?

[chrome orbit]

you can

[fathom lion]

ty

.close

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[teal jay]

Hi i was wondering if someone could help me with this question?

[spiral maple]

What have you tried?

[teal jay]

okay so i think i have an idea

so pie/6 simplieis to 1/√3

and ik about this relationship

[spiral maple]

Yes, apply that first

[teal jay]

so it becomes

[spiral maple]

Then evaluate

[teal jay]

tan (2 * √1/3) = 2tan(1√3)/1-tan^2(1√3)

[spiral maple]

No

[teal jay]

oh

[spiral maple]

You have the RHS of the double angle, what is it evaluated at?

[teal jay]

rhs means right hand side right

[spiral maple]

Yes.

[teal jay]

so ur talking about the 2tan(x)/1-tan^2(x) right

[spiral maple]

Yes, and compare that with what you have to evaluate

What is x?

[teal jay]

x = pie/6

[spiral maple]

Yes

So what does the LHS of the identity become if x=pi/6

[teal jay]

wait so

it isn't tan(2 * pie/6) you said right

[spiral maple]

Yes

And what's tan(pi/3)

[teal jay]

tan(pie/3) = √3

wait okay so

would the LS just be tan(2pie/6) which is just tan(pie/3) = √3

[spiral maple]

Yes

So your expression simplifies to sqrt(3)

[teal jay]

ye

alright bet

do you mind

if you can help me with another question im kind of stuck at

or should i just use the help channel again for a diff question?

.close

[obtuse pebble]

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[obtuse pebble]

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[bright cosmos]

Hi there : )

Just want a sanity check, please. In an optimization problem, is maximizing an objective the same as minimizing the negative of that objective, and vice versa?

[zinc flax]

u mean to maximize a function ?

[bright cosmos]

correct

Specifically, I have a dual optimization problem where I need to maximize one objective and minimize another objective simultaneously. I've already written the code to minimize the second objective. In order to avoid work I want to just negate (times by -1) each objective function value and minimize the objective with these negated values.

[zinc flax]

let function be f(x)
f'(x)= 0 let the point u get is a
then
f''(a)>0 --> minima
f''(a)<0 --> maxima
if u get multiple values u can put back in the main f(x) and check too

this is the main stuff we do

got it ?

[bright cosmos]

I think I get that, ok cool, thanks. However, my data values are from a database. I don't have the actual function.

[zinc flax]

oh k
u can plot graphs to check too

[bright cosmos]

true that! Thanks

[zinc flax]

Ik only with functions so only

sorry

[bright cosmos]

I see

ok thanks

[zinc flax]

u can dm me if u hv doubt on it (funct)

[bright cosmos]

Thanks a lot !

.close

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[rapid glacier]

Hey

[rapid glacier]

just need some help understanding this problems solution given in my ebook

I dont understand whats happening in step 2

[zinc flax]

ok see
first they find the line eq ig u understood that

[rapid glacier]

yea

[zinc flax]

integration as work = f.dr ( for small dist )

so work is a f(x,y) which integration is not know to u

[rapid glacier]

okay

[zinc flax]

so uk the relation b/w x and y from that line eqn ryt ?

[rapid glacier]

yes

[zinc flax]

so when u put that into that u get integral in 1 variable

which is known to integrate

[rapid glacier]

you mean a known intergal ?

[zinc flax]

see the fun which we need to integrate is 2 variable ie f(x,y)
we know the relation b/w x and y so we can convert f(x,y)-->g(x)
right ??

[rapid glacier]

yea

[zinc flax]

that only

[rapid glacier]

so were converting from f(x,y) to g(x), which gives us (x+y)dx?

[zinc flax]

we are converting that 2 variable function into a one variable one

[rapid glacier]

okay, thank you

.close

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[low saffron]

this one is a toughy

this is where i got stuck

this is for calculus 3

i tried converting everything to cylindrical coordinates but the integral i ended up with was not possible

so now im thinking of trying to do part of it in spherical coordinates and the other part in cylindrical coordinates

im in the mathematics voice chat if anyone is interested

[obtuse pebble]

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[obtuse pebble]

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[low saffron]

.reopen lol

[obtuse pebble]

✅

[low saffron]

so im getting closer

ive split it up into two triple integrals

the first in spherical coordinates and the second in cylindrical

just need to find the limits now

[obtuse pebble]

@low saffron Has your question been resolved?

[obtuse pebble]

@low saffron Has your question been resolved?

[low saffron]

this is as far as i could get

i got setup of the mass of the partial sphere but i cant figure out how to get the rest

.close

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[timid silo]

i’ve differentiated y but i’m stuck with how to factor it

what i’ve got so far

[warm shale]

KurtDee

[timid silo]

yes

because of the negative power mainly

idk how to factor

no but i’ll try now lol

got this

can i multiply this by 2 to make it easier to factor

how would u factor this

ah yh put straight into calc?

[timid silo]

i jus remember that i can do this

one sec ill do it now

got that

yeah i get the rest i only was stuck on the factoring prt

but actually

uno for part (ii)

would it just be that when i find the point of inflection it doesnt change from convex to concave or vice versa on either side?

[near yoke]

@low saffron u in college?

[timid silo]

wait actually scrap that

is it that d2y/dx^2 when set equal to 0 has no solutions?

[low saffron]

ye what about u

[near yoke]

nah high school but triple integrals look juicy wanna self learn them ngl

[timid silo]

what grade?

can someone help me on (ii)

[near yoke]

inflection point when f``(x) = 0

probably an asymptote

in that function

[timid silo]

ye so what i was thinking was to say that f’’(x) has no solutions

this is what i got for it

but idk where to go from here

[near yoke]

,w second derivative of x^(-1) - x^2 + 3x

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Syphax#3869

[near yoke]

well its gonna have some solutions

because there are infact points of inflection

[timid silo]

so how would i answer it

[near yoke]

uhh honestly i forgot how to answer questions like this so idk

[timid silo]

okay i solved it and got x=1

i think thats how i answer it

i say that d2y/dx^2 has one solution of x=1

and so has only one point of inflection

then i say that at x=1 dy/dx does equal 0

and so it is a stationery point of inflection

and so there are no non stationery ones

[near yoke]

ye

i agree

[timid silo]

thanks

[low saffron]

yeah theyre pretty epic
i have recordings of the lectures if you ever want to look into them

[near yoke]

sure send em in dm

[timid silo]

.close

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[worldly violet]

Need help understanding the relation between parseval's equality and closedness

[worldly violet]

.close

.close

[obtuse pebble]

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[ripe sleet]

.open

Lets say i had an enormous number such as 1 followed by 3 hundred quadrillion 9s, how would i modulo that?

[drifting wraith]

the normal way

there's no special extra way

[ripe sleet]

wdym

all of the numbers have one digit followed by a known amount of nines

there has to be a way to easily compute them

[drifting wraith]

it's not a thing

[ripe sleet]

.-.

[spiral maple]

Modulo also has a parameter you're lacking

Ie what you mod by

[obtuse pebble]

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[surreal oxide]

Hey

[surreal oxide]

Need help with this

[short spruce]

i cannot read that

[surreal oxide]

So do I use the z table for this ?

[obtuse pebble]

@surreal oxide Has your question been resolved?

[obtuse pebble]

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[surreal oxide]

Nope

[surreal oxide]

<@&286206848099549185>

I’ve tried using excel too won’t work

[chrome orbit]

https://www.mathsisfun.com/data/standard-normal-distribution.html

[forest sinew]

just use your calculator

you need to find the z score

[surreal oxide]

@forest sinew I got .2091

[forest sinew]

for what

[surreal oxide]

Is that 20.91%

[forest sinew]

,calc (190-173)/21

[warm shale]

Result:

0.80952380952381

[forest sinew]

,w z-score -0.8095

[warm shale]

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Requested by jan Niku#2119

[forest sinew]

idk if percent makes sense

looks like the number is good though

its a probability

[surreal oxide]

So leave the answer in decimal ?

[forest sinew]

yea

[surreal oxide]

That’s what I was thinking too

@forest sinew can it be 79.1?

[forest sinew]

well interpret that number

what do you think its saying?

what sorts of values are included in that portion of the distribution?

are they higher than 173? lower?

[surreal oxide]

0.7910

It should be lower

[forest sinew]

so the mean is 190

and our value is 173

[surreal oxide]

Yea

And we have the z score

[forest sinew]

and theyre asking us in the question

less than 173 minutes, yea?

[surreal oxide]

Yup

[forest sinew]

so imagine a normal distribution in your head

,w normal distribution graph

[warm shale]

Wolfram Alpha doesn't understand your query!
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Requested by jan Niku#2119

[forest sinew]

sad

,w normal distribution

[surreal oxide]

Rip

[warm shale]

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Requested by jan Niku#2119

[forest sinew]

bleh

you should have drawn one before right

draw it or do it in your head

[surreal oxide]

Never did

[forest sinew]

😮

okay lets do it

[surreal oxide]

I learned how to do this thru discord in the sever

[forest sinew]

heres your standard drawing

i know this is poor but

itll do

here uhh

so normal distribution, hump looking thing

mu is right in the center, the mean

given as 190

you agree 173 is to the left of this?

[surreal oxide]

Yea

[surreal oxide]

Since less than 190

On the left

[forest sinew]

so

what is the problem asking?

they ask for a probability but

what kind of values are included

[surreal oxide]

I’m between 173-190?

[forest sinew]

"what is the probability that ... in less than 173 minutes"

lets test a few points

is 200 part of this region theyre asking about

is 180 part of it

and is 160 part of it

[surreal oxide]

200 no

The other 2 yes

[forest sinew]

if i complete the race in 180 minutes

have i completed it in less than 173 minutes

[surreal oxide]

Nope

[forest sinew]

right

so not included, yea?

[surreal oxide]

Yup

[forest sinew]

i mean

if were less than 173 minutes

in should be any value less than 173

make sense?

[surreal oxide]

Yea

[forest sinew]

so we can shade

[surreal oxide]

Mhmm

[forest sinew]

this is the normal sketch

sometimes, if your number is really really close to a nice value, you can use some sanity checking

from something like this

[surreal oxide]

Yea

[forest sinew]

we know half of the values are above the mean

and half below

[surreal oxide]

Mhmm

[forest sinew]

hmm

so

we move one std dev to the left of the mean

we land just below our x

[surreal oxide]

Yea

[forest sinew]

we know it should be about .84 here, from 169 to infinity

then from 173 to infinity should be a little less than .84

so an answer of .20~ makes sense

do you see why we dont use the .79~ number?

it doesnt make sense for a lot of reasons

[surreal oxide]

Yea

[forest sinew]

😄

[surreal oxide]

If I were to represent it as a percentage

I’m not sure what my teacher wants

Would it be 20%

[forest sinew]

yea

but

[surreal oxide]

Because it’s asking what is the probability

[forest sinew]

theyre asking for a probability

probabilities are normally given as decimals

[surreal oxide]

Oh trueeee

[obtuse pebble]

@surreal oxide Has your question been resolved?

[obtuse pebble]

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[timid silo]

how did he assign u=x^2

hmm can someone explain me please

[obtuse pebble]

@timid silo Has your question been resolved?

[signal mango]

It must have been his substitution earlier as well

[timid silo]

no

he started integrate with u=x^2

integrate is x^4*sin(x^2)

[signal mango]

Yes, so it was his substitution earlier

du=2xdx and putting that all in gets you progress

The original integral must have been x^5 though not ^4

To get that stuff in the picture.

[timid silo]

yea i was wrong

but u substitution is not allowing you to do that stuff.

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

u=x^2 so all x^2 can be changed to u

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

yeah i got it but it's x^4

not x^2

[short spruce]

x^4=(x^2)^2

[obtuse pebble]

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[heady dove]

hello?

[obtuse pebble]

@heady dove Has your question been resolved?

[heady dove]

<@&286206848099549185>

[obtuse pebble]

@heady dove Has your question been resolved?

[sage bluff]

please do not use more than one channel

[heady dove]

k

.close

[obtuse pebble]

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[flint kelp]

hey all, why am I wrong with these answers?

[junior inlet]

you're adding the exponents together

for a

and for b you're multiplying the together

for a, your method is equivalent to multiplying the 2 numbers

[swift copper]

Is GCD is it the maximum/min exponent?

I felt like I learnt it from somewhere, might be wrong.

[junior inlet]

gcd = largest number that both numbers are divisible by

lcm = smallest number that is divisible by both numbers

[flint kelp]

hmm

so should, for the second part, it be X = 1, Y = 1

for lcm

because p^1 divides p^whatever

[junior inlet]

no

no

[flint kelp]

Not sure how I'm supposed to be solving this

[junior inlet]

i didnt mean that

lcm = smallest number that is divisible by both numbers

[flint kelp]

so would that not be p^15

[swift copper]

You don’t have to multiply anything, I believe. For x, it’s either 5 or 3.

[flint kelp]

but does p^3 divide p^5 or vice versa?

[swift copper]

LCM = $p^{max(x_{1},x_{2})}$

[warm shale]

RESIDGE

[flint kelp]

so it's X = 5

for LCM

[swift copper]

Believe so.

[flint kelp]

Y = 2

Z = 1?

[swift copper]

GCM is vice versa where it takes the minimum.

[flint kelp]

ahh right you are

that checks out

thanks!

.close

[obtuse pebble]

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[static pebble]

How do I justify that c = y intercept in the equation y = mx + c

[junior inlet]

right.

we can have f(x) = mx+c

and y = f(x), right?

[static pebble]

yep

[junior inlet]

(i'm probably just overcomplicating this)

but for x=0

we have mx+c = c

so the point (c,0) is on the graph

[static pebble]

i..i.. dont get it

I'm in 9th grade btw

[junior inlet]

not a great excuse
i'm in 7th grade

[static pebble]

omg what

[junior inlet]

y=mx+c

take x=0
m0 + c = c

[static pebble]

makes a little bit sense

thx

.close

[obtuse pebble]

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[timid silo]

i do not get these 2 questions, can someone help me understand?

[visual kelp]

Does this help?

[junior inlet]

do you know how to find a line perpendicular to another line?

[timid silo]

we arent supposed to solve it with graphs 😓 only algebriacly

[timid silo]

m1m2=-1?

[visual kelp]

I'm not telling you to solve it with graphs

If you can understand the graph

You should be able to solve the algebra

They are not different from each other

[junior inlet]

that's right

[timid silo]

sorry i do not understand the graph

[junior inlet]

so how can you have m2 from m1?

[timid silo]

m1 is -1 so m2 should be 1

[junior inlet]

ehh...

nevermind

if there is a line y = mx + c

the line perpendicular to it would have equation y = -1/mx - c/m

right?

according to your equation

[timid silo]

yes

oh i think i got the asnwer to the first one, it should be b)

for the 21st quest i also got y=-2x

[visual kelp]

Seems correct.

[timid silo]

great i understand now, ty both

oh almost forgot

.close

[obtuse pebble]

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[humble wind]

i need help with 1b

<@&286206848099549185>

[junior inlet]

solve for logx 16 and log9 y

[humble wind]

nvm lol i figured it out im so dumb 😅

[junior inlet]

:\

[humble wind]

.close

[obtuse pebble]

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[vague knoll]

how do u do this

[lethal crest]

what's (a+b)²

[vague knoll]

is it a²+b²?

[supple quest]

nope

try again

[humble wind]

do it step by step man

first find a

then b

then 4(a+b)^2

[supple quest]

not necessary

just plug it in the binomial theorem's 2nd term

[vague knoll]

huh

[vague knoll]

idk

oh

a² + 2ab + b²

[supple quest]

now, put those values from your question

[vague knoll]

huh wdym

[vague knoll]

ah

[supple quest]

use these values and put them there

[vague knoll]

ok

[supple quest]

what's the number you got?

[vague knoll]

1040

is that correct?

[supple quest]

How you got it?

[supple quest]

nope

[vague knoll]

oh

ok

this what i did

4(a² + 2ab + b²)

[humble wind]

alr

[supple quest]

oh

[humble wind]

yeah it's right

[supple quest]

ok, you're right

[vague knoll]

oh ok

so the answer is 1040?

okok

tysm

[supple quest]

you may close this channel

@vague knoll

[vague knoll]

ok

.close

[obtuse pebble]

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[humble wind]

2

need help with that

<@&286206848099549185>

[supple quest]

Ok

[humble wind]

can u join vc ?

@supple quest

[supple quest]

wait a minute then

[humble wind]

okk

[obtuse pebble]

@humble wind Has your question been resolved?

[humble wind]

@supple quest dude need the picture

[supple quest]

yep... I am trying it

[humble wind]

ohk

[supple quest]

sorry

I m struck

[obtuse pebble]

@humble wind Has your question been resolved?

[humble wind]

my brain hurts

.close

[obtuse pebble]

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[obtuse pebble]

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[willow stirrup]

how do i solve 9x²-40=-81

[willow stirrup]

i removed -81 already

so i have 9x²-121=0

[bright scaffold]

+121

and divide by 9

and then sqrt

[willow stirrup]

what

what does that mean

[bright scaffold]

sqrt is square root :p

[willow stirrup]

oh

i thought it meant shooting liquod

so its x²=13,44

[bright scaffold]

yea

and square root of that

[willow stirrup]

so x = 0 or sqrt 13,44

[bright scaffold]

it equals sqrt 13,44

[willow stirrup]

its wrong

[bright scaffold]

tf

thats impossible lmao

hold on

what did u get as answer?

[willow stirrup]

it says 11/3 or -11/3

[bright scaffold]

its cause

Try doing 11/3 on ur calculator

what does it say, and then chek what u got for an answer^^

[willow stirrup]

i cant

[bright scaffold]

oh u dont have acces to calculator?

[willow stirrup]

its not an option

[bright scaffold]

Hmmm well

[willow stirrup]

its 13,44 right

[bright scaffold]

yeah

but um

121/9

11 * 11 = 121

11/3 * 11/3 = 121/9

Which we said above^^

sqrt of 121/9 = 11/3

Since 11/3 mulitplied by itself is 121/9

[willow stirrup]

ok

thank you

.close

[obtuse pebble]

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[jagged trellis]

take the negative too

[obtuse pebble]

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[north acorn]

(a_{1} , a_{2} , ... ,a_{n^{2}+1}) is a sequence of (n^{2}+1) different real numbers, prove that there exists a subsequence that is either increasing or decreasing whose length is at least (n+1)

[warm shale]

fefe

[timid silo]

https://en.wikipedia.org/wiki/Erdős–Szekeres_theorem

[north acorn]

thank you very much

.close

[obtuse pebble]

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[kindred silo]

hey guys, is this solution valid? i feel like where i underlined is kinda illegal to do, but i cant think of a case where it doesnt work either

[hexed raven]

yeah its valid though you could writer it better

I mean that the validity "breaks" around line 3

you can't just take down exponents like that

A better way to go about it would be to divide both sides by (2^3 + 1) after step 2

This will directly give you 2^x = 2^5

[kindred silo]

okay thanks

sus moves but seems like it worked

.close

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[sterile tusk]

Am I doing this correctly? Or should I be setting s equal to an equation in terms of t first

[quaint glen]

That's fine. You've showed (skipping a few steps) that they aren't parralel. now you can determine whether they're skew or intersecting.

[obtuse pebble]

@sterile tusk Has your question been resolved?

[sterile tusk]

Alright thanks

[obtuse pebble]

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[agile ravine]

if I had the parametric curve r(t) = it^3+j2t, how would I find the tangent vector at the point (1, 2)

[agile ravine]

The only thing I've seen that resembles this is with a given value for t

[spiral maple]

So find the t value and follow that

[agile ravine]

this is what I'm stuck on, I'm not sure how to get the t value from the points (1, 2)

[spiral maple]

[1,2]=[t^3,2t]

t is clearly 1

[agile ravine]

Oh god I understand now. I didn't know the relation. Thank you very much.

[spiral maple]

You didn't know how parameterizations work..?

[rocky isle]

can someone help me pls i don't get it

[spiral maple]

#❓how-to-get-help

[rocky isle]

oops sorry

[agile ravine]

the original question asks for the directional derivative at the same point in the direction of the tangent vector, also at the point (1, 2), I misunderstood

But it makes sense now, I should read carefully.

Thank you. 🙂

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[chilly idol]

Im trying to find the values of x when the function is increasing

[chilly idol]

I've tried the intervals

[1,4)U(5,6]

I feel like the square brackets aren't needed? or the numbers are just wrong im not 100% sure

[obsidian isle]

the square brackets are not needed

the endpoints are stationary points

because the derivative at that point is 0.

[chilly idol]

What about the local minimum as well?

how is just 5 not right?

would 1 be a local minimum? I thought that counted as a global minimum

[timid silo]

Usually you don't care about global minimums for caculus

But every global min is also a local min

[chilly idol]

I've tried 1,5 but it is incorret

would 7 also count as a local minimum?

[timid silo]

No

[chilly idol]

.close

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[brave bramble]

Either x - 2 = 3
Or x - 2 = -3

[rotund pecan]

ty

[obtuse pebble]

@rotund pecan Has your question been resolved?

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[buoyant horizon]

I don't understand what tthe question is asking

Is it asking ffor derivative?

If so isn't it suppose to be dy/dx

or d/dx?

[dim root]

@buoyant horizon

[buoyant horizon]

Oh ok

Thanks

[dim root]

Np

[obtuse pebble]

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[solar brook]

Can someone help me answer this?
<@&286206848099549185>

[unique solstice]

Youre writing equations based on those details?

[solar brook]

yeah

[unique solstice]

Do you know your different forms

[rotund pecan]

i can help you

its so easy

y= mx+b

[solar brook]

I was absent for the past few weeks

[rotund pecan]

slope formula is y2-y2 / x2-x1

dividede by

1. You have the slope so u know that m is negative 1

[solar brook]

wait, so how do we apply this in the questions?

[rotund pecan]

y= -1 x + b

They gave you x, and y

(-3,4)

So you can solve for B

[rotund pecan]

This is the formula for slope, you should know

that's the general formula

u dont need it for all questions unless they ask for slope

[solar brook]

ahh

[rotund pecan]

just know that formula

Do u know how to do basic algebra

[solar brook]

so wait, how do we get the B when we have the everything else?

[rotund pecan]

Because they are asking for the equation of the line right?

[solar brook]

yeah, I was absent for the most part of this topic

[rotund pecan]

The question isn't specified, but im assuming it is

[solar brook]

yes, it is

[rotund pecan]

basically u need to know this

[solar brook]

wait, one last, how do we get the B?

[rotund pecan]

Y= MX + B or Y=MX+C depending on what country you are from

You need to do algebra

y = -1x + b for y, plug in -3 and for x plug in 4

[solar brook]

I'll try to watch the past sessions, but thanks for the help @rotund pecan

[rotund pecan]

they gave u X and Y

just plug into the equation

and solve

If u dont know basic algebra learn it because

This stuff u are learning is extremely important

Im telling you

im in calculus and u still need it

so learn it

[solar brook]

damn, this is hard

at least for me

[rotund pecan]

bro

y = -1x +b

solve for b given the points

-3,4

so you get

-3 = -1 (4) +b

-3 = -4 +b

add four to both sides to isolate b

-3 + 4 = b

1 = b

so the equation final

y = -1x + 1

[solar brook]

wait, hmm, i get it a little better now (?)

[rotund pecan]

Watch some youtube videos

dude

make sure u know this stuff

im telling u, u dont realize it now but its very important

Trust me

[solar brook]

thanks

[rotund pecan]

its simple just practice more

and learn basic algebra

Watch some youtube videos

[solar brook]

I'll try to watch some videos

[rotund pecan]

Organiz Chemistry Tutor has some

[solar brook]

oh thanks for this

anyway, thanks again\

I'll be closing the channel

.close

[obtuse pebble]

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[dire pollen]

I think the question here is asking me to use products-to-sum to deduce this, but I can't figure out how they might be used

[spiral maple]

what was part a?

[dire pollen]

here's the whole question

[spiral maple]

Yeah use part a

[dire pollen]

Can you elaborate? I've already worked out part a btw

[spiral maple]

part a has cos(2x)+cos(4x)+cos(6x)

so evaluate a at a specific value

@dire pollen

[obtuse pebble]

@dire pollen Has your question been resolved?

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[sturdy delta]

Hi could someone help me with this exercise?

[sturdy delta]

I don't know how to define the set

[obtuse pebble]

@sturdy delta Has your question been resolved?

[sturdy delta]

<@&286206848099549185>

[sturdy delta]

<@&286206848099549185>

[obtuse pebble]

@sturdy delta Has your question been resolved?

[sturdy delta]

<@&286206848099549185>

[lament raft]

yeah i dont think questions of that level can be solved by people on this server (at least definitely not me)

[sturdy delta]

Oh ok thanks😅

.close

[obtuse pebble]

Channel closed

Closed by @sturdy delta

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[obtuse pebble]

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Remember:
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[ancient vigil]

it is known that the value for the Basic Statistics course is normally distributed with an average of 76
and variance 64.
a. What is the probability that a student's score is below 60
b. If the score is between 65 and 74 gets a C grade, and if there are 40 students following
exam, how many students got a C
c. If the highest 10% score gets an A, what is the limit for the lowest score to get A?

[ancient vigil]

I cant solve C

[obtuse pebble]

@ancient vigil Has your question been resolved?

[ancient vigil]

<@&286206848099549185>

[chrome orbit]

@ancient vigil what is C

[ancient vigil]

If the highest 10% score gets an A, what is the limit for the lowest score to get A

[jolly ginkgo]

What's the range for grade A

[ancient vigil]

no range I think (?)

[jolly ginkgo]

There must be

[ancient vigil]

why?

[jolly ginkgo]

Highest 10% of score is for A right

[ancient vigil]

yes

[jolly ginkgo]

So what will be the desired interval

[ancient vigil]

I dont understand

[signal mango]

find the right z value for the highest 10%

work backwards to the right number that guarantees an A

[ancient vigil]

How?

Im lost

[obtuse pebble]

@ancient vigil Has your question been resolved?

[ancient vigil]

<@&286206848099549185>

[obtuse pebble]

@ancient vigil Has your question been resolved?

[jolly ginkgo]

The max score is 100 and 10% of 100 is 10 , so A graders are scoring above 90

So you have to find the lowest score is between 90 to 100

[ancient vigil]

how did u get that?

is there any method?

[jolly ginkgo]

Just calculated 10% of 100

[ancient vigil]

okay

[ancient vigil]

thanks a lot

.close

[obtuse pebble]

Channel closed

Closed by @ancient vigil

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[karmic socket]

Anyone can help me in here?

[karmic socket]

My teacher is asking for the constant term

He said something about that there should be a constant term and my factored one should be different

Pls help me

[obtuse pebble]

@karmic socket Has your question been resolved?

Channel closed

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Remember:
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[woeful talon]

Given 12 consecutive integers, in how many ways can three of these integers be selected to give a sum which divides by 4

[woeful talon]

I can't do this