#help-10

1 messages · Page 460 of 1

tacit root
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if you get (f(-x) = f(x)), then the function is even

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otherwise, it is neither

warm shaleBOT
tacit root
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so evaluate ( \dfrac{(-x)^2 - 9}{(-x)-5} ) and check if it is equal to (- \left(\dfrac{x^2 - 9}{x-5} \right))

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@karmic plover as above

karmic plover
warm shaleBOT
tacit root
#

great, so are you able to sketch the curve?

karmic plover
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siince the negative on the denom x moves out

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oh yeah i did it, and confirmed with the help of desmos

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.close

obtuse pebbleBOT
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sonic coyote
#

a+b+c=0 also means that a^3 + b^3 + c^3 = 3abc ?

fervent cradle
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no

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wait

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maybe

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no

stuck owl
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expanding (a+b+c)^3 we get a bunch of terms so probably not

fervent cradle
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because let a = 1, b = 0, c = -1

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then you get 1 + -1

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and 3 * -1

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so it doesn't work

stuck owl
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b = 0

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RHS becomes 0 so try like b = 1

fervent cradle
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what

stuck owl
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and c = -2

fervent cradle
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what are you on about

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wait fuck

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yes

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you're right

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ok

sonic coyote
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thanks

fervent cradle
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wait

sonic coyote
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.close

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stuck owl
#

rip (a,b,c) = (1, 1, -2) doesn't work

obtuse pebbleBOT
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stuck owl
#

if anyone was wondering about the previous problem

stuck owl
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wise holly
#

how do I know if they specify a function

obtuse pebbleBOT
cold thistle
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There’s a neat trick called the vertical line test

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If you can draw a vertical line at any point and it touches the curve more than once, it is NOT a function

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Because every input in a function has exactly one output

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So in 16. for example, you can draw a vertical line anywhere and it will only ever touch that line once

wise holly
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so if I understand that correctly, then only 17 and 18 don't specify functions

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is that correct?

cold thistle
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Mhm

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If you plug 0 into the function in 17, you get three answers

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Which violates intergalactic law or someth

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It’s because the way functions are defined, each input can only have one output

cold thistle
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Aleph this channel is being used for a different question

wise holly
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thanks for your answer

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sick mantle
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Is 4 a multiple of 4?

obtuse pebbleBOT
rugged kite
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yes

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4 = 4*1

sick mantle
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Alright, thanks, that's it! :D

timid silo
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are adjacent angles supplementry?

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yes rite

cold thistle
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Angles are supplementary when their measures add up to 180°

covert river
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f(x)=1/x differentiated is -1/x^2?

obtuse pebbleBOT
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obtuse pebbleBOT
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@steady marsh Has your question been resolved?

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ebon agate
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what does taking a linearization of a function mean?
same as differentiating a function?

ebon agate
#

num 1.

obtuse pebbleBOT
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@ebon agate Has your question been resolved?

ebon agate
#

<@&286206848099549185>

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austere folio
#

?

obtuse pebbleBOT
austere folio
#

.close

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austere folio
#

lol

obtuse pebbleBOT
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steady marsh
#

For this function, is there no easier way to find any Inflection Points? I found the second derivative, and I'm not sure if I'm doing this correctly...

steady marsh
#

This is the work I've done
and I'm not sure how to proceed... since the denominator goes to 0 at x=0, am I allowed to just see when the numerator is 0?
and so I guess there are no points of inflection since x=0 and x=6 are both disallowed in the denominator
I'm not sure

obtuse pebbleBOT
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steady marsh
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timid silo
#

The vector k · v → has a length of 1.
Calculate the length v → and the number k, if v → = (6, 8)

timid silo
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<@&286206848099549185>

atomic hemlock
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hey i might look dumb but is √108 + √12 is √130 right?

steady marsh
steady marsh
timid silo
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not really

steady marsh
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Okay, so imagine you're going to the store

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and you see a 6 pack of eggs for 12 dollars

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How much would you be paying for one egg?

timid silo
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12 dollars

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wai no

steady marsh
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one egg

timid silo
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i pay 12 dollar*6

steady marsh
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it's a 6 pack

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6 eggs for 12 dollars

timid silo
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ahaaaaa

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XDD

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wait

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so for 1 egg its 2 dollars

steady marsh
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yeah, and how did you find that out?

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what calculation did you do?

timid silo
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i did

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wait

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i like

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took a amout of eggs

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and did this

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egg/price

steady marsh
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Well, egg/price or price/egg?

timid silo
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price/egg

steady marsh
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yeah! and you found out that one egg costs 2 dollars by doing 12/6, right?

timid silo
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yes

steady marsh
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so calculating a unit vector is the same idea, really

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you take a vector and divide it by it's own magnitude

timid silo
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but how im supposed to divaide this The vector k · v → has a length of 1.
Calculate the length v → and the number k, if v → = (6, 8)

steady marsh
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so if I had a vector of length 6, and I divided it by its own length, then I'd be doing 6/6

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which would give me a length of 1, right?

timid silo
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yea

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so i do 6/6 and 8/6

steady marsh
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Not quite

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How do you calculate the magnitude of a vector?

timid silo
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wait

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a=(a1,a2)

steady marsh
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the magnitude is a single number

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it's a scalar

timid silo
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yes

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so

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wait i still dont get it

steady marsh
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okay, so the magnitude of a vector is given by

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$\sqrt{a^{2}+b^{2}}$

warm shaleBOT
#

QLightningWolf44

timid silo
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aaa

steady marsh
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where a, and b, are the components of the vector

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so how would you calculate the magnitude

timid silo
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wait now im lost

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in school we use

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$\sqrt{x^{2}+y^{2}}$

warm shaleBOT
steady marsh
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yeah yeah it's the same thing!

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(x, y) and (a, b) are just different variables that are the same idea

timid silo
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aha

steady marsh
timid silo
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i just got a little bit lost sorry

steady marsh
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no worries!

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so what's the magnitude then?

timid silo
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and 8 is y^2

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?

steady marsh
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not quite, a is 6 and b is 8

timid silo
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aha

steady marsh
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you must square them and take the square root of them added together

timid silo
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wait

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3.74165738677

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so we can basically say 3.74

steady marsh
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what

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how are you getting that?

timid silo
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wait

steady marsh
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6^2 + 8^2 is 100

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and the square root of 100 is 10

timid silo
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ytes

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yes

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it is

steady marsh
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so the unit vector would be (6/10, 8/10)

timid silo
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aha

steady marsh
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because remember, you're dividing the vector by its own magnitude

timid silo
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yea

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so its 0,6 and 0,8?

steady marsh
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yep

timid silo
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so what now

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that is all?

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but wait

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its wrong

steady marsh
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k is 1/10

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that should be it

timid silo
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its not wrong

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u are right

steady marsh
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the unit vector is 1/10 (6, 8)

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1/10 is a scalar

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it scales the vector

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hence, scalar

timid silo
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oki doki

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thanks for help

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how do i close it?

steady marsh
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.close

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just type that

timid silo
#

oki

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thanks

#

.close

obtuse pebbleBOT
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topaz forge
#

I don’t understand

obtuse pebbleBOT
topaz forge
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I don’t under stand this**

forest sinew
#

do you have any idea about part a?

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i mean how to start or any thinking about it

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can you think of a way given some amount of money how many things you can buy?

obtuse pebbleBOT
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@topaz forge Has your question been resolved?

topaz forge
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timid silo
#

$$\begin{aligned}xy'=2y\ y=x^{2}\end{aligned}$$

warm shaleBOT
#

BadBanana

timid silo
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so why is the bottom expression not a solution to the differential equation at x = 0

spiral maple
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because y=0 is the equilibrium solution

timid silo
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The book I'm using says "Be sure to state the common interval for which the solution and diffeq make sense"

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what does that mean

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sorry if thats a dumb question the book hasnt used that term

spiral maple
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if y=0, y'=0 so 0=0 means it's a solution for initial condition y(0)=0

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equilibrium solutions are constant solutions.

timid silo
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if its a constant solution why is it excluded from the interval

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im not following

spiral maple
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cause you start on an equilibrium, so you stay on the equilbrium

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instead of following a curved path

timid silo
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sorry you need to dumb this down more. Is it similar to how in a piecewise function there can be a solution to both "parts" of the function but a discontinuity still exists?

spiral maple
#

alternatively when you actually solve the DE you have to divide by x, so you remove the fact x=0 from the y=x^2 solution

spiral maple
timid silo
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do you have a visual example?

spiral maple
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sure

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$xy'=2y$

warm shaleBOT
spiral maple
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if y=0, then you can easily check it's a solution. and this solution has y(0)=0, so if the IVP had y(0)=0 as the condition, then you know the solution is just y=0

timid silo
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okay what is the IVP

spiral maple
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initial value problem

timid silo
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so the y = x^2

spiral maple
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no

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that's a solution.

timid silo
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y = 0 then?

spiral maple
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y=0 is also a solution.

timid silo
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oh man

spiral maple
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IVP is the DE and initial condition...

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$f(x,y,y')=g(x,y,y') \ y(0)=y_0$

warm shaleBOT
spiral maple
#

or whatever initial condition you have

timid silo
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hmm I havent seen any of this yet in the book. I might need to plug away and return when I have more of the vocabulary down.

spiral maple
#

Ok

timid silo
#

I have a note on the some of the term you used so when they come up all have something to refer back to

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thank though

#

.close

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raven plume
#

''Find the probability of different numbers' fall when a pair of standard dice is thrown twice repeatedly ''
I apologize for my poor language, can someone explain me how can I solve that problem?

obtuse pebbleBOT
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@raven plume Has your question been resolved?

tired shell
#

go through it one dice at a time

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if you want the different* numbers on the dice, what numbers can the first one be?

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once you've answered that question and picked a number, do the same for the other dice

raven plume
#

$\frac{6}{6}\frac{5}{6}=\frac{5}{6}$ and for the second time, $\frac{5}{6}\frac{4*3}{36}$

warm shaleBOT
tired shell
#

yup!

raven plume
#

thanks for help mate

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I appraciate that

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.close

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austere drum
#

Hi, could somebody please help me with the following problem?

Where I am right now is I think the recurrence relation could be something like: a(n) = a(n-2) + a(n-1) because a(n-2)-1 would be all the steps needed to turn off the light at position n (-1 because you don't have to turn off the first light in this case) plus 1 (because you do have to turn off the light at position n)

austere drum
#

But I think I am going in the wrong direction and am quite lost

unique solstice
#

Say that each light if its on or off is just represented as a 0 or 1

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So this is the five lights initially

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11111

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So just thinking about how many turns itd take to turn off light n and all before assuming theyre all on

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n=1
11111
01111
One switch

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n=2
11111
00111
Two switches

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n=3
11111
01111
01011
11011
10011
00011
Six switches

obtuse pebbleBOT
#

@austere drum Has your question been resolved?

unique solstice
#

n=4
11111
10111
00111
00101
10101
11101
01101
01001
11001
10001
00001
Eleven switches

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It kinda looks like it adds on 2 more to the rate each time

austere drum
#

So because the rate of change was 5 switches when n=4 when n=5 the rate of change will be 7 switches and so
n=5
Eighteen switches?

unique solstice
#

Thats my thinking

austere drum
#

So could the recurrence relation be described as something like:
a(n) = [a(n-1) - a(n-2)] + 2 ?

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Wait

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I think it would be a(n) = a(n-1) + [a(n-1) - a(n-2)] + 2

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YEAH THATS IT

#

THANK YOU

unique solstice
#

Epic

austere drum
#

.close

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terse yoke
#

can someone please tell me if the cross product would satisfy the cartesian equation?

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@terse yoke Has your question been resolved?

terse yoke
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<@&286206848099549185>

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.close

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dense stone
#

.reopen

obtuse pebbleBOT
dense stone
#

help i don’t understand

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i did 38+90

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which is 128

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then did 180-128 and got 52

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and it’s wrong

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idk how to do it

brave bramble
#

Why 38 + 90?

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Remember the angles in a triangle sum to 180.

slender badge
#

52 is the interior angle, x is the exterior

dense stone
#

oh

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so how do i get the exterior

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like how do i set it up

jagged marsh
dense stone
#

yeah

slender badge
#

52+x = 180

jagged marsh
#

So if the sum of all interior angles is 180°, x interior would be 52°

brave bramble
#

Well, you'll want the interior angle first. The interior angles in a triangle sum to 180.

dense stone
#

how do i find c

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X

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**

slender badge
brave bramble
#

Before finding x, you should find the interior angle

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Gotta take more than one step on this one

dense stone
#

ok so the interior is 128

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right?

jagged marsh
brave bramble
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The interior angles in a triangle sum to 180.

dense stone
#

oh

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ok

dense stone
brave bramble
#

So, consider calling that angle "c" or something, and write an equation

dense stone
#

ok

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so

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x+52=180? and x would be 128 i’m so confused

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??

jagged marsh
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yup

dense stone
#

oh woah

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so is 128 the answer or?-

jagged marsh
#

yup

dense stone
#

tysm!!

jagged marsh
#

It’s the exterior angle

dense stone
#

this rlly helped

#

.close

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dim cairn
#

how would i solve this quickly?

obtuse pebbleBOT
whole scroll
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ruby minnow
#

Sorry for asking too many questions
Prove that equation 3x^5 -x^3 =1 has at least one solution

Sorry someone told me to use IVT

So I decided to set interval as [0,2]

f(0)=0
f(2)= 88

ruby minnow
#

What should I do next? I'm confused pls help

spiral maple
#

so not sure how you got f(0)=0...

#

$f(x):=3x^5-x^3-1$

warm shaleBOT
ruby minnow
#

Oh

#

I ignored that -1

#

Because I thought

#

Something else

#

Okay

#

-1 and 87

#

But

#

Why did I take interval as 0 and2

spiral maple
#

idk

ruby minnow
#

Oh

spiral maple
#

you just provided me with an interval

ruby minnow
#

Nope I thought I can use 0 and 2 because there was 1 on the RHS

#

How else can i prove it?

spiral maple
#

you just find any interval that works for IVT

#

it's an odd degree polynomial, so it has at least 1 R root

ruby minnow
#

I watched YouTube video but in that they had interval specified

#

Already in the questions

#

And my teacher didnt teach this ;-;

spiral maple
#

trial and error

ruby minnow
#

Oh okay, I just need to find the values of x that make the equation equal to zero

#

Sorry if I sound dumb

spiral maple
#

No, you're showing that there's at least one solution

#

you're never asked to find the solution cause you likely cant algebraically

ruby minnow
#

Oh

#

Ok

#

Thank you so muchh!

#

.close

obtuse pebbleBOT
#
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leaden bay
obtuse pebbleBOT
leaden bay
#

how should I approach proving this?

leaden bay
#

i have tried squeeze theorem but i a stuck, i think i need to make an epsilon somwóehow

#

<@&286206848099549185>

sour mortar
#

well, to proof, you'd need to investigate the properties of the functions you don't even know

#

but there is a way to calculate it

#

if f, g are continuous and well behaved

sour mortar
upbeat plinth
#

f,g are sequences not functions on R

sour mortar
leaden bay
#

I am certain that this holds true

#

But i can't show it properly

#

Math prof: homework is going to be easy

#

Homework 1st exercise: prove the Riemann hypothesis

sour mortar
#

2nd exercise: solve the Navier Stokes problem

leaden bay
#

Hilbert's twenty-fourth problem is a mathematical problem that was not published as part of the list of 23 problems known as Hilbert's problems but was included in David Hilbert's original notes. The problem asks for a criterion of simplicity in mathematical proofs and the development of a proof theory with the power to prove that a given proof is the simplest possible.[1

sour mortar
#

so, if you still want to solve that question

#

then I can try help you

#

I'm just not sure if it'll be the correct way

leaden bay
#

I made like

#

Cooked up proofs lmao

#

But they're far from academically correct omes

sour mortar
#

I see

#

I mean, most likely this questions is not just to show the limit evaluates to e^k algebraically

dim cairn
#

wait. what do i do now KEK

leaden bay
#

Yeah i eill do that thank!

#

.close

obtuse pebbleBOT
#
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#
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astral siren
#

Hi

obtuse pebbleBOT
astral siren
clear inlet
#

what have you tried ? what do you want help with? show your work

astral siren
clear inlet
#

have you learned matrix multiplication

astral siren
#

Is it juts to 2,2 or while matrices

#

Yes

#

I got 1/4g

#

But not sure how to do hd

#

@clear inlet

#

Is -15/8

#

?

clear inlet
#

don't ping me

astral siren
#

?

#

Is it correct or

#

Not

#

Hello??

spiral maple
astral siren
#

But is it correct

spiral maple
#

idk how you expect to get help without giving everything that's relevant.

astral siren
spiral maple
#

can I see the working?

#

cause that's what is being asked by the people trying to help you

#

If you dont want help that's less work for me to do, so I'm fine with not helping.

astral siren
#

I figured nvm

spiral maple
#

ok...

astral siren
#

I have another question

#

I don’t get how to do

#

Can u help

spiral maple
#

is it a test..?

astral siren
#

No

spiral maple
#

ok... what have you tried then?

timid silo
spiral maple
#

???

timid silo
#

if they can't abstractly think about the question, then try using some defined matrix

spiral maple
#

I mean sure, but that wont answer the question

#

also I was waiting for a response from them instead of talking to the void...

timid silo
#

there was a guy like that last night 😔

spiral maple
#

Cool

astral siren
#

What

spiral maple
astral siren
#

I don’t get it

spiral maple
#

What have you attempted?

astral siren
#

I don’t understand what to do

spiral maple
#

Find A^(-1) if it exists.

astral siren
#

Ok

#

Then

obtuse pebbleBOT
#

@astral siren Has your question been resolved?

astral siren
#

@spiral maple

#

Is it option 2?

spiral maple
#

no.

plain owl
#

It isn’t unique right?

astral siren
#

4?

spiral maple
#

Yes..

obtuse pebbleBOT
#
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timid silo
obtuse pebbleBOT
timid silo
#

I'm tryna learn induction before I actually learn it in class so I understand it better then, so I'm not entirely sure how to start this

#

How would I get the LHS?

#

do I use the sums of arithemtic formula?

#

i know i substitute (1) in

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
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timid silo
#

.reopen

obtuse pebbleBOT
#

timid silo
#

<@&286206848099549185>

sour mortar
#

on both sides and you find they're indeed equal

timid silo
#

yeah but just in the (2n-1) part?

#

@sour mortar

#

sorry for the ping idk how to get your attention

sour mortar
sour mortar
timid silo
#

yeah i got the RHS

#

just (1)^2

#

but im confused on the LHS

sour mortar
#

oh, I messed up

#

LHS indeed on the 2n -1 part

#

then it will be equal to 1

timid silo
#

ty

sour mortar
#

the thing is, when n = 1, then the 3, 5 kinda DNE

#

because they appear when n assumes greater values

#

it is just a form of representing the sum

timid silo
#

tysm that makes sense

#

appreciate you

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

#
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#
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ember glacier
#

need help on what to do on this question

obtuse pebbleBOT
ember glacier
#

<@&286206848099549185>

sour mortar
ember glacier
#

no i don't think i know it

sour mortar
#

so, I recommend you doing it like a tree

#

then you can use the values given by the table and solve the question

ember glacier
#

ok im going to attempt it

#

@sour mortar

#

i got 3p+rd

#

is that correct?

sour mortar
#

but I can try

ember glacier
#

can you check to see if i did it correct

sour mortar
#

it is correct

ember glacier
#

oh sweet

#

is it ok for me to ask u another similar question or do i have to go into a different channel

#

its a question i already did but i have doubts if my answer is correct or not

sour mortar
#

I need to sleep now

#

but you can post on this same channel since it is still ocuppied by you

#

maybe use .close and .reopen

ember glacier
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @ember glacier

Use .reopen if this was a mistake.

ember glacier
#

.reopen

obtuse pebbleBOT
#

sour mortar
#

now post the question

#

wait for someone to answer

ember glacier
sour mortar
#

ping helpers if not answered in 15 minutes

ember glacier
#

alright thanks

sour mortar
#

calc 1 thing

ember glacier
#

yeah so i was really worried because my answer is negative

sour mortar
#

since when you find a negative rate, it means the volume is decreasing

ember glacier
#

This is my work

sour mortar
#

I'll just help you with that one

ember glacier
sour mortar
ember glacier
#

oh ok and since we're on implicit differentiation

#

can u just check 1 more question for me please xD

#

@sour mortar

#

.close

obtuse pebbleBOT
#
Channel closed

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Use .reopen if this was a mistake.

ember glacier
#

.reopen

obtuse pebbleBOT
#

ember glacier
#

is my implicit differentiation correct?

obtuse pebbleBOT
#

@ember glacier Has your question been resolved?

ember glacier
#

<@&286206848099549185>

ember glacier
#

<@&286206848099549185>

plain owl
ember glacier
#

hey euclid!

#

yo i was wondering if u could check another answer i had

plain owl
#

I’ll try

ember glacier
#

i got that as my answer

#

but im not sure if i did it correctly tbh

#

did u get an answer like that?

plain owl
#

What did you try though?

ember glacier
#

this is what i did

plain owl
#

Ok did the same so far. I’ll try to evaluate

#

I am getting something like $\frac{\sqrt{73^3}-1}{6}$

warm shaleBOT
#

Euclid31415

ember glacier
#

hmm ok

plain owl
#

Substituted the entire thing under sqrt =u

ember glacier
#

are u sure

#

that it should be that

plain owl
#

I think I did it properly

ember glacier
#

alright thanks man i appreciate it

#

also btw

#

i couldn't respond to your dm

#

the one u sent

plain owl
#

It’s no problem

plain owl
# ember glacier

The square root should be multiplied by entire of (18t+36t^3) here… I think that’s what led you to the answer 66.2339

ember glacier
#

ah i see

#

thanks

plain owl
#

Type .close when you are finished @ember glacier

ember glacier
#

.close

obtuse pebbleBOT
#
Channel closed

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ember glacier
#

oops haha forgot to

obtuse pebbleBOT
#
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timid silo
#

whenever there is -ve in power, in order to make in positive, we reciprocate the fraction.

#

that's correct

obtuse pebbleBOT
#
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quartz jacinth
obtuse pebbleBOT
quartz jacinth
#

can somone pls help me

rocky schooner
#

Hint: join AB.

quartz jacinth
#

what do you mean by join

#

sry im new to this topic

rocky schooner
#

Draw a straight line from A to B

quartz jacinth
#

ok

rocky schooner
#

What can you tell about angle CAB

quartz jacinth
#

umm

#

idk

rocky schooner
#

Something related to CB is the diameter?

#

So that it forms a semi circle?

#

Any theorem related to semicircle?

quartz jacinth
#

yeah im prett sure there is one but i still didnt learn the theorems

#

our teacher didnt teach us the theorems but she is giving us homework about it

#

soo

#

is a 90 degrees?

rocky schooner
#

Yep it's 90°

#

Your good! Even your teacher didn't teach you you can figure it out!

#

Next consider angle ACB and angle BAT

quartz jacinth
#

ok

rocky schooner
#

Hint: something about tangent

#

Something like alternate segments

quartz jacinth
#

ok

#

i couldnt do it

rocky schooner
#

It's okay, lemme grab something online real quick

quartz jacinth
#

is bat 29

#

?

rocky schooner
rocky schooner
quartz jacinth
#

than cat is 119

rocky schooner
#

Yep

#

And then x is easy

quartz jacinth
#

is x 32

#

?

rocky schooner
#

I didn't calculate ,lemme get it the answer with my calculator

#

Yea

#

32

#

Very good!

quartz jacinth
#

btw

#

what do the lines mean on ce and oc

#

yk theres a small line

#

@rocky schooner

rocky schooner
#

They mean those two lines are equal in length

quartz jacinth
#

ok thanks

rocky schooner
#

Good luck and have a nice day!

quartz jacinth
#

u too!

night igloo
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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timid silo
#

How many ovens are needed to bake 6 million loaves of bread if it takes 2 hours to bake bread and you only have the ovens for 4 years? Aka 6 million Jews

obtuse pebbleBOT
#

@hexed oak Has your question been resolved?

obtuse pebbleBOT
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modern sierra
#

If we’re talking sets, does A/B and A-B mean the same thing?

rugged kite
#

If you meant to write A\B then yes

#

they're two notations for the same thing

#

A/B is very different however

modern sierra
rugged kite
#

There are multiple ways to see it

#

The easiest example is the integers modulo n. Ever heard of that?

modern sierra
#

Nope

rugged kite
#

It's like the numbers on a clock

#

You can add or multiply them, but it always wraps back around to be less than 12

modern sierra
#

Okay

rugged kite
#

(well, technically on a clock you have all numbers from 1 to 12 inclusive, but usually in math it makes more sense to consider all the numbers from 0 to 12 or 11 inclusive, 0 is important to have)

modern sierra
#

Alright

rugged kite
#

So for example the integers modulo 12 are 0 through 11

modern sierra
#

Oh okay

rugged kite
#

And if I write 6+6, that's 12 usually

#

But in modular arithmetic, we always loop back around

#

So 6+6=0 mod 12

#

Another way to say this is that the remainder of dividing 6+6 by 12 is 0

#

That remainder is also called the modulus, hence "mod" and "modular"

modern sierra
#

Oh okay

#

Yeah I think I get it

#

Thanks

rugged kite
#

Well, that's the first part

#

You asked about A/B

#

For example, the set of all integers modulo 12 might be written as ℤ/12ℤ

modern sierra
#

Yeah but I think this is above what I’m studying right now, I was just curious because I thought it might be related to what I’m doing lol

rugged kite
#

I see

modern sierra
#

But thanks anyways

rugged kite
#

This notation comes when studying group theory, which, who knows, you might do some day

modern sierra
#

Yeah I probably will

#

But thanks I’m gonna close this now

#

.close

obtuse pebbleBOT
#
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long yoke
#

How do i solve this??

obtuse pebbleBOT
unique solstice
#

Do you know how to calculate that at 1 second?

#

So like if the question read

#

"It starts with 1200 g and is reduced by 12% each second, whats the mass after 1 second"

#

So just a normal question asking you to make a number 12% less than its original self

timid silo
#

exactly

obtuse pebbleBOT
#

@long yoke Has your question been resolved?

obtuse pebbleBOT
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hearty estuary
obtuse pebbleBOT
hearty estuary
#

Is this working correct

#

I am a bit confused by the trapezium

#

Oh wait I see the trapezium

#

But I didn’t do it that way

obtuse pebbleBOT
#

@hearty estuary Has your question been resolved?

pallid summit
hearty estuary
#

It’s printed out dr frost

#

And I wouldn’t be doing a test at home lol

obtuse pebbleBOT
#

@hearty estuary Has your question been resolved?

ripe carbon
#

How to find a natural number n such that n mod x = y mod n ?

fervent cradle
#

ax+n = bn + y

#

ax - y = bn - n

#

n = (ax-y)/(b-1)

#

for some a and b

#

ok that's non-trivial

#

idk

rugged kite
#

that's not quite right

#

you have n=px+r and y=qn+r'

#

We're interested in n such that r=r'

#

i.e n-px=y-qn i.e n(1+q)=px+y i.e n=(px+y)/(q+1) for some q and p

ripe carbon
rugged kite
#

yeah that's the thing, there need to be some extra conditions on n

ripe carbon
#

x, y are even

rugged kite
#

for example, if you try x=5,y=2,p=q=0, you'll get the invalid solution n=2

#

which doesn't work because 2 mod 5 = 2 ≠ 0 = 2 mod 2

ripe carbon
#

x=4 , y=8, then n can be 4

obtuse pebbleBOT
#
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ripe carbon
#

.reopen

obtuse pebbleBOT
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toxic elm
#

is my calculation for this question correct?

obtuse pebbleBOT
brisk grove
#

It seems correct yes

obtuse pebbleBOT
#

@toxic elm Has your question been resolved?

obtuse pebbleBOT
#
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timid silo
#

hey i dont need math help, but theres this really cute girl in class and i was wondering how would i go around to asking her out

nocturne minnow
#

Go ahead and close this channel
.close

timid silo
#

but its math class bro

#

.close

obtuse pebbleBOT
#
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

meager osprey
#

How come in this inequation, the teacher doesn't simplify the m's? so it's x >= 3m. Time and time again I see them doing it this way (they leave the m and the m^2 factors), for what reason?

meager osprey
#

Another question, for the same inequality. So the sign depends on m. But why is this true?

#

If mx >= 3m^2, then mx will be a negative quantity and 3m^2 will always be positive so why are there solutions at all?

#

I assume that it's because then x >= 3m^2/m, so x>= an overall negative quantity but then why do we flip the sign? If we flip the sign then shouldn't it then become -x >= -3m^2/m ? :(

obtuse pebbleBOT
#

@meager osprey Has your question been resolved?

meager osprey
#

<@&286206848099549185>

#

anyone? is there something about the question that makes it difficult to solve? Can I provide more info?

meager osprey
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Ahh merci, vous me sauvez là

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certes, mais si on change pas les signes de l'équation elle-même? Je comprends pas comment on peut changer les signes si on change pas l'équation. On "suppose" que x est négatif mais...

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oui...

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🤔

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mais je vois toujours pas

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car ici y a les - qui s'ajoutent

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en gros, ce qui me gène c'est qu'on ne modifie pas l'équation

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Ah merde

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yes

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c'est vrai

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j'ai fait ça aussi au premier coup

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un truc du genre

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Je sais pas si on peut raisonner comme j'ai fait

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En gros je comprends pas vraiment, je m'embrouille toujours avec les notations

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mais est-ce qu'on peut simplement substitioner des trucs au bol et après voir quelle égalité tient la route?

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en gros -1 n'est pas superieur à 3 donc ça doit être de l'autre sens, l'égalité

obtuse pebbleBOT
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@meager osprey Has your question been resolved?

obtuse pebbleBOT
#

@meager osprey Has your question been resolved?

obtuse pebbleBOT
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terse yoke
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can i please get help on A

obtuse pebbleBOT
nocturne minnow
terse yoke
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i dont really know how to solve the question

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@nocturne minnow

nocturne minnow
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So you know w, correct?

terse yoke
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yeah

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sqrt3+i/2

nocturne minnow
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It just wants powers of w

terse yoke
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so do i just

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power w?

nocturne minnow
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Think about it like this, if w = 2, what is w^2?

terse yoke
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4

nocturne minnow
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Or 2^2?

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Right?

terse yoke
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yea

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so i basically power it

nocturne minnow
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What about w^3

terse yoke
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okay ty

nocturne minnow
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It'd be 2^3

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And so on

terse yoke
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ahh

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okay ty

nocturne minnow
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But you're given sqrt3+i/2

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As w

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Just do the same process

terse yoke
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how about this

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?

nocturne minnow
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Looks complicated, wish I could help sorry

terse yoke
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ahh so you know w^4

terse yoke
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since it is a reflection of w^2 in the imaginary axis

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would that mean it would be

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1-sqrt(3)i/2

nocturne minnow
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Looks like it

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I could be wrong though

terse yoke
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yeah all good

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ty anyways

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.close

obtuse pebbleBOT
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obtuse pebbleBOT
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wicked wigeon
obtuse pebbleBOT
spiral maple
nocturne minnow
wicked wigeon
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im trying but no ones helped for my past 5 questions lol

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ill remove the other

spiral maple
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yeah cause you havent posted what you've tried

wicked wigeon
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i posted this

obtuse pebbleBOT
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@wicked wigeon Has your question been resolved?

wicked wigeon
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.close

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violet sentinel
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I can't remember, how do I find the max distance between any two pairs of points between two functions?
For example, I have f(x) = x^3 and g(x)=x/2.
I want to find at what points do f(x) and g(x) create the maximum distance between the two functions? And where is the point on f(x) and on g(x) respectively?

violet sentinel
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example here:

unique solstice
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Just use Pythagorean theorem

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Then derivate it and find the critical points epicly

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Then see which ones a max

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And bam

drifting wraith
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epicness is optional, it still works if you do it mediocrily

unique solstice
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Optional but highly recommended*

violet sentinel
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I'm gonna feel dumb once you I understand what you mean haha

unique solstice
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More like

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sqrt((x_2-x_1)^2 + (g(x_2)-f(x_1))^2)

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I think

violet sentinel
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I'll give it a shot!

unique solstice
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I might be a bit wrong on my process

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But its along those lines

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I mean I would personally use like dot product or something

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Solely because the second function is a straight line

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But thats by absolutely no means a "general solution"

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Well actually

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Does the problem go into more detail?

violet sentinel
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oh no it's just me experimenting

unique solstice
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Oh

violet sentinel
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I'm messing with Chebyshev polynomials

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and for the equation above it states that the maximum error between them is 1/2

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so I was verifying that!

unique solstice
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So youre looking only for vertical error?

violet sentinel
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oh I'm an idiot... I just need the vertical error

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yeah

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derp

unique solstice
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Yeah thats way easier

violet sentinel
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haha

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yeah it is

unique solstice
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Do you know how to do it?

violet sentinel
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iirc it should be f(x)-g(x)
then you find the derivative to find critical points

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similar process

unique solstice
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Ye

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Youd prob want |f(x)-g(x)| technically ig

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Which throws a small wrench into things

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But it shouldnt be that bad

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Just split it into two functions

violet sentinel
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yep!
So it'd be a(x)=|x^3 - (1/2)x|
a'(x) = { 3x^2 - (1/2) if x > 0
{ -3x^2 + 1/2 if x <0
?

unique solstice
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Yeah

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Or wait

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Check your bounds

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Its a bit nastier than I thought

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You have to find exactly where the specific function is negative

violet sentinel
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oh I see

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the bounds will be the critical points it looks like?

unique solstice
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Itll be the zeroes of the original function

violet sentinel
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oh yeah my b that's right

unique solstice
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And depending if its positive or negative between the zeroes is whether or not its reversed

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Ye its all confusing

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With all the different zeroes meaning all kinds of stuff

violet sentinel
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well damn this became more complicated than I assumed 😮

unique solstice
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Yeah

violet sentinel
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*first assumed

unique solstice
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Well after you figured out it was vertical distance

violet sentinel
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that's fine tho

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this is part of a numerical analysis course

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so it seems this is on par with how this section of math goes

unique solstice
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Reasonable

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I learned the way to do it in precalc by plotting the zeroes on a number line

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And testing values between all of the zeroes if its positive or negative

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Its really simplistic but oftentimes thats whats useful

violet sentinel
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oh yeah I remember that too, that made it fairly easy!

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well thank you for the help, I appreciate it!

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.close

obtuse pebbleBOT
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unique solstice
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Np

obtuse pebbleBOT
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hallow cedar
obtuse pebbleBOT
hallow cedar
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i have a brainfart

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may someone guide me through the steps o_O

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is this good so far @_@

craggy flame
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Call ab = W.
Then Right side = W

hallow cedar
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hm yea just another constant really

craggy flame
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That is ... sqrt(...) = x + W

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square the thing...

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cancel stuff

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... do you see?

hallow cedar
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uh

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sqrt(x^2 + 1) = ab + x

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hm

craggy flame
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yup.. now, square both sides...

hallow cedar
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x^2 + 1 = (ab)^2 + 2(ab)(x) + x^2

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oh there's a remaining x

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thanks

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weird

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when I would keep the other x on the left side i wouldnt find it

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o_O

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.close

obtuse pebbleBOT
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obtuse pebbleBOT
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toxic elm
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is my calculation correct?

obtuse pebbleBOT
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@toxic elm Has your question been resolved?

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lilac grove
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how will I factor this, its so hard
\
$(a + b)(p + q + r) + (b + c)(p + q + r) + (c + a)(p + q + r)$

warm shaleBOT
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JUGisMUG🎃

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@lilac grove Has your question been resolved?

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glad sleet
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L = 0.5((A1 -Y)^2) -> Y = constant
A1 = σ(P1) -> sigma = sigmoid function
P1 = X.W1 + B1

∂L/∂B1 = (∂L/∂A1) * (∂A1/∂P1) * (∂P1/∂B1)
(this is correct right?)

if this is correct I get that ∂L/∂B1 = (A1-Y) * A1(1-A1) * 1
now, every variable except sigma are matrices, but the result I get from the final partial gives me a 6x20 matrix in my example whilst I should get a 1x20 matrix
so I must have done something wrong

obtuse pebbleBOT
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@glad sleet Has your question been resolved?

obtuse pebbleBOT
#

@glad sleet Has your question been resolved?

obtuse pebbleBOT
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@glad sleet Has your question been resolved?

glad sleet
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Still waiting btw

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pls

fiery venture
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maybe write it out a little more clearly @glad sleet . I'm assuming you're trying to do something with neural networks, and I know how backprop works pretty well, but I can't make heads or tails of your question at all.

glad sleet
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so I have a simple network with an input matrix X and that propagates to the output Y

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I just wanted to find ∂L/∂B1 since I want to initialize my bias' and update them after each cycle

fiery venture
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how many layers are in your network?

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and what loss function are you using?

glad sleet
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just 1 hidden layer

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loss function is 0.5((A1 -Y)^2)

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sorry

fiery venture
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and A1 is your target?

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or your output layer?

glad sleet
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A1 is the output

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Y is the target

fiery venture
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hmm

glad sleet
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granted I just summed all my weights so it becomes a (1,20) matrix as desired

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but I guess that's not really a good way

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cuz it works perfectly

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I'm just curious to what I might have missed

fiery venture
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the full equation for the loss of your network will be $L(y; \theta) = L(W_{2} \sigma(W_{1} x + b_{1}) + b_{2}$ right?

warm shaleBOT
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yoohoo

glad sleet
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I don't have the second weight/bias

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but yes