#help-10

1 messages · Page 433 of 1

robust moon
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220 divisor

woeful edge
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mhm

robust moon
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7 quotient

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35 remainder

woeful edge
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perfect

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so 1575 = 220 × 7 + 35

robust moon
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okay

woeful edge
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now do the euclidean division of the divisor by the remainder

robust moon
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ah I see where I fucked it

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I divided the dividend

woeful edge
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not only that

robust moon
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Should have done 220 / 35

woeful edge
#

u did smt else wrong

robust moon
#

buddy I have only been doing this a week

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yer going to have to spell it out

woeful edge
#

im gonna confuse u like that

woeful edge
robust moon
#

okay 220 is the divisor right

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and 35 is the remainder

woeful edge
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yes

robust moon
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so I'm supposed to divide those

woeful edge
#

yes

robust moon
#

220 / 35 = 6 R 10

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220 = 35*6 R 10

woeful edge
#

220 = 35×6 + 10

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goodjob

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now

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do the euclidean division of the divisor by the remainder yet again

robust moon
#

35/6 = 6*5 +5

woeful edge
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is 6 the remainder?

robust moon
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5/5 = 1

woeful edge
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U divided 35 by 6, thats wrong

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6 isnt remainder

robust moon
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....dicks

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35/5 = 7

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no remainder

woeful edge
#

.

robust moon
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wait

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fuck

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10

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35/10 = 3 R 5

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10/5 = 2

woeful edge
#

35 = 10 × 3 + 5

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10 = 5 × 2 + 0

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gj

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so we reached the remainder 0

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yes?

robust moon
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yup

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and it's 5

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GCD = 5

woeful edge
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tgen, the gcd is

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the last remainder that comes before reaching 0 as the remainder

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which is 5, yes, good job

robust moon
#

okay

woeful edge
#

so eucludean algorithm

robust moon
#

well I'm glad we unfucked that lol

woeful edge
#

is js the succession of eucludean divisionsb

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1575 = 220×7 + 35
220 = 35×6 + 10
35 = 10×3 + 5
10 = 5×2 + 0

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thats what weve been doing

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dividing the divisor by the remainder until u reach remainder 0

woeful edge
robust moon
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okay so what's the linear expression of that then?

woeful edge
#

now that

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i honestly have never heard of it

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leave it to smn else

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sorry man

jaunty stirrup
robust moon
jaunty stirrup
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is it the process of combining after the euclidean theorem or forming it into an actual for ex 5 Equivalent to 2 (mod 3)

robust moon
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I thiiink it's the bottom part in the notes

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I hadcovid

woeful edge
#

oh

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should be easy then

jaunty stirrup
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not a 100% certain but this looks like combining

robust moon
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yeah

jaunty stirrup
#

which then in order to do it, you reformulate all the euclidean theorem logic into what gives you your remainder

so if you have 22 = 7 * 3 +1

make that become 1 = 22 - 7(3)

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and do that for all the remainders until the remainder of 1

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neglect the remainder of 0 in this case b/c you will never use it

robust moon
#

okay

jaunty stirrup
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then, one at a time, you expand one of the 2 terms,

robust moon
#

and reduce them down to primes?

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wait, that doesn't look right here

jaunty stirrup
robust moon
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not with the answer she posted

jaunty stirrup
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might be doing something similar but different lol

robust moon
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for her example problem

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sighs My professor has a PHD in the stuff

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and I get the feeling

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that that much math

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makes you a little insane

jaunty stirrup
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no no fair,

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htinkikng about it now

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i may have been thinking of relatively prime gcds

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which is why this happened

robust moon
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this is the simplest equation she has

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so maybe we can decode this

jaunty stirrup
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ok ok yeah, not 1 =

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the actual gcd

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so after you find the gcd, you do as i said earlier with making all the euclidean work, become num = something - something

robust moon
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okay

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so we have GCD of 5

jaunty stirrup
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for which

robust moon
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for 1575 and 220

jaunty stirrup
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did you work it out with the euclidean theorem?

robust moon
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yeah I think we that's what we did

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divisor / remainder right?

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and then on down

jaunty stirrup
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but since we know the gcd is 5

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now we can say that 5 = 35-3(10)

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and then looking at all the other remainders, we either expand the left or the right, one at a time and combine , up until there are no remainders to to expand from.

robust moon
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I'm gonna do a little research myself

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but I appreciate the assist

jaunty stirrup
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For sure

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good luck

obtuse pebbleBOT
#

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dry panther
#

Linear regressions don't seem to mix well with horizontal lines. Is this normal ? I am trying to detect whether points form a line or not. For slanted lines, I seem to get a high rvalue, but for horizontal its extremely low. I'm led to believe that I don't understand rvalue, pvalue and standard deviation.

cold thistle
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Think about what a horizontal line implies in the context of a correlation between two variables graphed on the xy plane

dry panther
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Well if I view it as f(x) = y and y was a constant then I'd say that the parameter x has no impact

cold thistle
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Exactly

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And the correlation coefficient (r) in a linear regression is measuring to what extent the correlation between the two variables is linear

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So if there's little to no correlation between x and y (intuitively, x has no impact on y), what would you expect the r value to be---where closer to 0 is less correlation and closer to 1 is more

dry panther
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Then what kind of "test" could I use to verify if some x,y points can "fit" around a line ?

cold thistle
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Somewhere in the calculations for the linear regression, if I recall correctly, changes in x and y coordinates are multiplied within a summation, and if the changes in y are very small or zero, the resulting r value is very low

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I guess they fit around a horizontal line but the correlation coefficient in that situation suggests that there's little correlation between the two variables

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Said horizontal line could be used to predict unknown values but it seems to be messed up a bit by how little impact x has on y

dry panther
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Yes that's somewhat been my observation I've seen with my previous lack of understanding of r

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I could easily detect those slanted lines(with the blue marker) with line regression and checking rvalue, but for the horizontal lines I've had no luck

obtuse pebbleBOT
#

@dry panther Has your question been resolved?

dry panther
#

Is there a method for me to detect if a segment of data is a line, whether its near horizontal or slanted ?

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bump. If not for r^2 in a linear regression, what should I look for ?

dry panther
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Bumpx3

obtuse pebbleBOT
#

@dry panther Has your question been resolved?

obtuse pebbleBOT
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rare terrace
#

I need help

obtuse pebbleBOT
#
What step are you on?
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7. None of the above
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@rare terrace Has your question been resolved?

rare terrace
#

2

obtuse pebbleBOT
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@rare terrace Has your question been resolved?

obtuse pebbleBOT
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calm kayak
#

how do i do b) after i use the question before

obtuse pebbleBOT
red ice
#

try writing cos(4t) = cos(2t + 2t) and then trying to simplify

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use the double angle identity cos(2t) = 2 cos^2 t - 1 and sin(2t) = 2 sin t cos t

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once you make a solid attempt, if you're still stuck from there, show what steps you have done and then we can talk

calm kayak
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alr ty ill try that

red ice
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np!

fallow wharf
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I think you can just expand the binomial for part b an dnot use part a at all

red ice
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I hate the framing of the question

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yes it's like that sorry for misleading you haha

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it's just that

fallow wharf
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all good haha

calm kayak
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oh but i thought i was memant to use the question before

red ice
#

I remember doing this in HS and now it's clicked

fallow wharf
#

I guess it doesn't matter which way you go, I like the idea of just using the binomial theorem to prove a trig identity though

obtuse pebbleBOT
#

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worldly bay
#

how tf i do this

obtuse pebbleBOT
worldly bay
#

arent i not even able to do this cuz i dont have x

tough reef
tough reef
worldly bay
#

on the answer key to this (doesnt show the process just answers) it just says a=1/2

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how r they getting an entire number when x or tanx or anything like that isnt given

tough reef
#

Which means through identities the trigonometric functions will cancel

worldly bay
tough reef
#

Try isolating a first

red ice
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also (2 tan x)/(1 - tan^2 x) is just the double angle identity for tan

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oh wait you've already done it I see

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yeah then you should sub u = tan x

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and then you can isolate a, just makes it easier to keep track of stuff

worldly bay
tough reef
#

Almost

worldly bay
tough reef
#

Almost

worldly bay
#

??

tough reef
#

One sign is wrong

worldly bay
tough reef
#

Right

worldly bay
void holly
warm shaleBOT
#

convergence

worldly bay
#

oh

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yea

tough reef
void holly
worldly bay
#

??

void holly
# worldly bay mb

try this $a=\frac{1-\frac{2\tan x}{1-\tan ^{2}{x}}\tan^2{x}-2\tan x\left(1-\frac{1}{1-\tan ^{2}{x}}\right)}{2}$

warm shaleBOT
#

convergence

void holly
#

$-2\tan x +\frac{2\tan x }{1-\tan ^{2}{x}} =-2\tan x\left(1-\frac{1}{1-\tan ^{2}{x}}\right)$

warm shaleBOT
#

convergence

worldly bay
#

how

void holly
#

distributive property

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-a+ab=-a(1-b)

worldly bay
#

o

void holly
#

try now solving the () part

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that is $1-\frac{1}{1-\tan ^{2}{x}}$

warm shaleBOT
#

convergence

worldly bay
#

(-tan^2x) / 1-tan^2x

void holly
#

yep now multiply that with -2tan x what will you get?

worldly bay
void holly
#

so we now have $a=\frac{1-\frac{2\tan x}{1-\tan ^{2}{x}}\tan^2{x}+2\tan x\left(\frac{\tan ^2 {x}}{1-\tan ^{2}{x}}\right)}{2}$

warm shaleBOT
#

convergence

void holly
#

i think you know what to do next @worldly bay

worldly bay
#

ngl man

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idk

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do i just subtract 1-(fraction with the tanx's on the left) or smth

void holly
warm shaleBOT
#

convergence

worldly bay
#

0

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i think

void holly
#

so what will a be

void holly
worldly bay
#

if ur putting the 1 then 1/2

void holly
#

yes

obtuse pebbleBOT
#

@worldly bay Has your question been resolved?

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obtuse pebbleBOT
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feral pike
#

I need some help

obtuse pebbleBOT
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hollow condor
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bleak gust
obtuse pebbleBOT
bleak gust
#

i dont understand how to solve these questions. they just twist my brain

obtuse pebbleBOT
#

@bleak gust Has your question been resolved?

bleak gust
#

<@&286206848099549185>

#

can someone exlplain how to solve these type of questions

obtuse pebbleBOT
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@bleak gust Has your question been resolved?

obtuse pebbleBOT
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@bleak gust Has your question been resolved?

tardy epoch
bleak gust
#

but i get what you mean

obtuse pebbleBOT
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bleak gust
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.close

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swift canyon
#

Guys can someone explain payoff functions to me please catking

hollow gate
#

Hii

swift canyon
#

Hello!

#

@hollow gate <@&286206848099549185> guys 😦

hollow gate
#

Going to sleep 😴 maybe tomorrow

swift canyon
#

sweet dreams

obtuse pebbleBOT
#

@swift canyon Has your question been resolved?

wintry swift
#

whats your question?

swift canyon
#

Can you please explain what is a payoff function and how it works

serene fossil
#

Never heard of a payoff function do you have a definition?

#

Maybe there’s another term for it

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Oh is it a game theory thing?

#

I guess a payoff function is just a model of the award granted to a given player at the end of the game if a given set of moves/decisions are made

obtuse pebbleBOT
#

@swift canyon Has your question been resolved?

swift canyon
#

How is differnet from game theory

obtuse pebbleBOT
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wanton dune
#

for my homework i need to determine verity of these statemens
\begin{enumerate}[1)]
\item From every real sequence $\left(a_j\right){j \in \mathbb{N}}$ satisfying $\sup \left{\left|a_j\right| \mid j \in \mathbb{N}\right}<\infty$, it is possible to select a subsequence that has its own limit.
\item Let $f: \mathbb{R} \rightarrow \mathbb{R}$ and $\left(x_n\right)
{n \in \mathbb{N}}$ be a sequence such that $\lim _{n \rightarrow \infty} x_n=0$. If $\lim _{n \rightarrow \infty} f\left(x_n\right)=5$, then $\lim _{x \rightarrow 0} f(x)=5$ also holds.
\item If a function $g:[1,4] \rightarrow \mathbb{R}$ attains its maximum and minimum on the interval $[1,4]$, then it is continuous on this interval.
\item If $h: \mathbb{R} \rightarrow \mathbb{R}$ is such that the function $(\arctan \circ \ h)$ has a negative derivative at every point of $\mathbb{R}$, then $h$ is decreasing.
\item No function defined on $\mathbb{R}$ whose range is a two-element set is continuous.
\end{enumerate}

warm shaleBOT
#

Slowaq
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

wanton dune
#

.close

obtuse pebbleBOT
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gritty raft
#

whats blue divide by orange?

obtuse pebbleBOT
gritty raft
#

maths teacher was going through this but i dont understand it

alpine raven
timid silo
#

Looks like the answer is Green based off the left part

worthy birch
#

(x+1)(5x- ?

dim burrow
obtuse pebbleBOT
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obtuse pebbleBOT
timid silo
cursive tangle
#

Alors bien vous voulez décomposer la fraction en une différence et puis vous allez appliquer une formule d’angles composés sur la différence. Ici on peut utiliser sin(a-b) = sin(a)*cos(b) - cos(a)*sin(b) et puis on doit utiliser le cercle unité pour trouver les valeurs de sin(a) et sin(b). J’espère que cet indice est suffisant

obtuse pebbleBOT
#

@tulip fulcrum Has your question been resolved?

tulip fulcrum
#

and what angles do I use

cursive tangle
#

This seems like the easiest combination to me but maybe you will find one better if you try several things

tulip fulcrum
#

Okay I see thank you

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cursive tangle
obtuse pebbleBOT
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@cursive tangle Has your question been resolved?

cursive tangle
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What

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frozen zenith
#

Hi, For these questions I'm quite a bit confused. Shouldn't be the squareroot(f1²+f²) should be the thing to determine if the first two forces are equilibrium to the third? f1+f2=f3 How is the answer C?

drifting wraith
#

@frozen zenithwhich one

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9?

frozen zenith
#

The problem is the others have the same idea technically

drifting wraith
#

i'm confused

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what are the 3 answers?

frozen zenith
#

9: c

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10 c

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11 c

opal fractal
#

sorry for the bad drawing but it looks something like that i think

frozen zenith
#

f1 = 8

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f2 = 8

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f3 = ~12

opal fractal
#

where did you get 12

frozen zenith
#

% TeXit only accepts code which belongs inside the document

% Mathematical expression in the document body
[
\sqrt(f1^2+f2^2+2f1f2cosx)
]

warm shaleBOT
frozen zenith
#

this one

#

but for equilibrium we usually use only f1 and f2 only

#

@opal fractal

#

and how is it 60 when it isnt mentioned

opal fractal
#

my bad i think its 30

drifting wraith
#

ok so, 11 is c because 10 and 4 mean it must be a straight line

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and 3 is wrong for some other reason

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idk

frozen zenith
frozen zenith
#

"because it's not a straight line we shouldn't get the sum for them and we should treat it as lines of a triangle"

drifting wraith
#

the two smallest numbers together are larger than the thifrd

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that's the rule for whether triangle exists

frozen zenith
#

i don't get it

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what's the relation with equilibrium

drifting wraith
#

so yeah only (c) 5 does that

frozen zenith
#

for example 5 explains

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f1+f2=f3

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with the rule

warm shaleBOT
#

harue

% TeXit only accepts code which belongs inside the document

% Mathematical expression in the document body
\[
\sqrt(f1²+f2²)
\]
frozen zenith
#

why is a triangle associated with equilibrium

drifting wraith
#

i don't know

frozen zenith
#

it's confusing

#

it's not a smooth plane inclined to a horizontal that's why it's not a triangle either

#

it should be like the drawing epic made

opal fractal
#

ok so F1 + F2 = F3
all of them are 8 newtons so
for the y direction 8sin + 8sin = 8 sin
for the x direction - 8cos + 8cos = 8 cos

drifting wraith
#

so we have this

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if we focus on the vertical component

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the top two forces must be larger than the third, the sums of them.
if they are equal, this is a straight line, so has to be larger
yeah sorry i don't get it

frozen zenith
#

% TeXit only accepts code which belongs inside the document

% Mathematical expression in the document body
[
\sqrt(f1^2+f2^2+2f1f2cosx)
]

warm shaleBOT
frozen zenith
#

this should equal f3

opal fractal
#

im not sure how to explain how to find the angles but its
8sin30 + 8sin30 = 8sin90
8 = 8 for the y direction
and
-8cos60 + 8cos60 = 8cos90
0 = 0 for the x direciton

opal fractal
frozen zenith
#

or the resultant

opal fractal
#

yeah that equals f3

#

you can plug in the angles and magnitude and it should give you F3

frozen zenith
#

squareroot(f1²+f2²) should be the resultant if no angle is specified

#

it should equal 12

opal fractal
#

well think of it like there is, but you just dont know that angle
you know theres an angle where two forces are equal to the third force

frozen zenith
#

what if the third force is vertical

#

and there's an angle which equals 90

frozen zenith
opal fractal
#

no i mean the two forces summed up

#

for equilibrium

#

just picture this

#

just that the magnitudes or angles might differ

frozen zenith
#

I know

#

but how it can be 8, 8 8

opal fractal
#

theres 3 forces on an object, they are all 120 degrees relative to each other like a triangle. if they are all the same magnitude can you see that they cancel each other out

obtuse pebbleBOT
#

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obtuse sage
obtuse pebbleBOT
obtuse sage
#

hi help pls

#

in induction

#

i reach here

#

then i don't know how to continue

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full elm
obtuse sage
#

it in N

#

n>0

obtuse sage
full elm
#

one second

obtuse sage
#

ok

full elm
#

I think induction wont work because the function is not constantly decreasing so P(n+1)<P(n) will not be true always

obtuse sage
#

its not a sequence ?

full elm
# obtuse sage

One idea that I got could be to replace h with 1-h as they have the same domain

obtuse sage
#

mmmm

#

is that possible ?

#

like why i can do this

#

this sounds illegal

full elm
#

You can think of it like every y = 1-h will correspond to a value of h

#

basically if you plot a graph with h as the variable then itll just get flipped but the values from 0 to 1 stay that place only

obtuse sage
#

this sounds weird i can't think about it actually

#

like we can't do this with induction ?

full elm
#

maybe we can with some manipulation

obtuse sage
#

how

full elm
#

Ok I did it

#

Is this correct?

#

@obtuse sage

#

basically when n < h/1-h, I proved using inequalities and then took it as base cases for induction, then when n > h/1-h, proved using induction

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vagrant breach
#

Hello, I am working on a research project, and once I have reached the result, I have to calculate the uncertainties, there comes the problem, I would like someone who knows how to find the uncertainty of the slope of a line. I'm desperate and all help is welcome.

vagrant breach
#

I would like to calculate the uncertainty of the first number, that is, the slope of the line.

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vast tree
#

I need help too

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spare sorrel
obtuse pebbleBOT
velvet spoke
spare sorrel
velvet spoke
#

sin(x) = opposite/hypotenuse

spare sorrel
#

how do i write it into the calculator

#

wait nvm

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verbal musk
obtuse pebbleBOT
verbal musk
#

how do I use the system of equations on the left to describe the solution set in terms of z

worn yoke
#

use the equations you are given from gauss-jordan to solve for x and y in terms of z

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mellow skiff
#

Note that
A= 28%
B= 8%
C= 13%
D= 18%
E=13%

obtuse pebbleBOT
mellow skiff
#

I solved it but i just want someone to double check it for me

#

Assumptions:
• Q1 sales start at RO 2,500.
• Sales double every quarter:
• Q2: 2,500 \times 2 = 5,000
• Q3: 5,000 \times 2 = 10,000
• Q4: 10,000 \times 2 = 20,000

a) Total Sales (Quarterly and Yearly)

•    Q1: RO 2,500
•    Q2: RO 5,000
•    Q3: RO 10,000
•    Q4: RO 20,000
•    Yearly Total:  2,500 + 5,000 + 10,000 + 20,000 = RO 37,500 

b) Cash Sales (Yearly and Quarterly)

•    Cash sales =  A\%  of total sales (A = 28%).
•    Q1:  2,500 \times 0.28 = RO 700 
•    Q2:  5,000 \times 0.28 = RO 1,400 
•    Q3:  10,000 \times 0.28 = RO 2,800 
•    Q4:  20,000 \times 0.28 = RO 5,600 
•    Yearly Total:  700 + 1,400 + 2,800 + 5,600 = RO 10,500 

c) Credit Sales (Yearly and Quarterly)

•    Credit sales =  B\%  of total sales (B = 8%).
•    Q1:  2,500 \times 0.08 = RO 200 
•    Q2:  5,000 \times 0.08 = RO 400 
•    Q3:  10,000 \times 0.08 = RO 800 
•    Q4:  20,000 \times 0.08 = RO 1,600 
•    Yearly Total:  200 + 400 + 800 + 1,600 = RO 3,000 
  1. Cost of Sales (Quarterly and Yearly)

a) Material Cost

•    Material cost =  C\%  of total sales (C = 13%).
•    Q1:  2,500 \times 0.13 = RO 325 
•    Q2:  5,000 \times 0.13 = RO 650 
•    Q3:  10,000 \times 0.13 = RO 1,300 
•    Q4:  20,000 \times 0.13 = RO 2,600 
•    Yearly Total:  325 + 650 + 1,300 + 2,600 = RO 4,875 

b) Labor Cost

•    Labor cost =  D\%  of total sales (D = 18%).
•    Q1:  2,500 \times 0.18 = RO 450 
•    Q2:  5,000 \times 0.18 = RO 900 
•    Q3:  10,000 \times 0.18 = RO 1,800 
•    Q4:  20,000 \times 0.18 = RO 3,600 
•    Yearly Total:  450 + 900 + 1,800 + 3,600 = RO 6,750
chilly plover
#

Is RO a currency?

mellow skiff
#

Overheads

•    Overheads =  E\%  of total sales (E = 13%).
•    Q1:  2,500 \times 0.13 = RO 325 
•    Q2:  5,000 \times 0.13 = RO 650 
•    Q3:  10,000 \times 0.13 = RO 1,300 
•    Q4:  20,000 \times 0.13 = RO 2,600 
•    Yearly Total:  325 + 650 + 1,300 + 2,600 = RO 4,875 
  1. Depreciation

    • Depreciation = 8% of the machine cost (RO 4,000).
    • Depreciation = 4,000 \times 0.08 = RO 320 .

  2. Gross Profit and Net Profit

a) Gross Profit (Quarterly and Yearly)

•    Gross Profit = Total Sales - (Material Cost + Labor Cost + Overheads)
•    Q1:  2,500 - (325 + 450 + 325) = RO 1,400 
•    Q2:  5,000 - (650 + 900 + 650) = RO 2,800 
•    Q3:  10,000 - (1,300 + 1,800 + 1,300) = RO 5,600 
•    Q4:  20,000 - (2,600 + 3,600 + 2,600) = RO 11,200 
•    Yearly Total:  1,400 + 2,800 + 5,600 + 11,200 = RO 21,000 

b) Net Profit (Quarterly and Yearly)

•    Net Profit = Gross Profit - Depreciation (depreciation distributed equally over quarters).
•    Quarterly Depreciation:  320 / 4 = RO 80 
•    Q1:  1,400 - 80 = RO 1,320 
•    Q2:  2,800 - 80 = RO 2,720 
•    Q3:  5,600 - 80 = RO 5,520 
•    Q4:  11,200 - 80 = RO 11,120 
•    Yearly Total:  1,320 + 2,720 + 5,520 + 11,120 = RO 20,680
mellow skiff
chilly plover
#

Just curious

mellow skiff
chilly plover
mellow skiff
#

College

chilly plover
#

Oh

#

Ok

chilly plover
mellow skiff
#

What about the methods that have been used to calculate each question

#

@chilly plover

obtuse pebbleBOT
#

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proven mirage
#

hi can somoene explain me this

obtuse pebbleBOT
proven mirage
#

if u need more context, h is the hypotunese, L is the base

#

so how do we take that error in l is estimated by delta l / delta h

#

shouldnt we calculate it from the ratios of L/h, then using that ratio to calcualtion delta L

obtuse pebbleBOT
#

@proven mirage Has your question been resolved?

proven mirage
#

<@&286206848099549185>

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@proven mirage Has your question been resolved?

proven mirage
#

<@&286206848099549185>

obtuse pebbleBOT
#

@proven mirage Has your question been resolved?

proven mirage
#

btw h and l are distances

#

<@&286206848099549185>

desert light
#

use a^2 + l^2 +- 2ldl = h^2 +- 2hdh

#

so 2hdh = 2ldl

#

so in this case you would be right

proven mirage
#

ohhh

#

i finally get it

#

tysm

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inland hill
#

Does the fundamental theorem of algebra only apply over C and it's isomorphic sets? Not to it's supersets?

kind hawk
#

the fundamental theorem of algebra is specifically about C

inland hill
#

Thanks

wild swallow
#

isomorphic sets?

inland hill
#

Ones isomorphic to C

#

I meant

wild swallow
#

but as fields you mean

sage geode
#

Maybe fields?

#

For a counterexample consider the roots of x^2 + 1 in quaternions btw

inland hill
wild swallow
#

not a field Xd

sage geode
#

Whoops

wild swallow
sage geode
#

hmmcat What question

inland hill
#

So

wild swallow
inland hill
#

The theorem is only over C

sage geode
#

Yeah

inland hill
#

💯 thanks

#

Later

#

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heavy sedge
#

This is a tiny semantic thing for set theory for analysis. For x = y does {{x},{x,y}} simplify to {x} or {{x}}. Or does it not matter?

brazen gorge
#

it does matter

#

x ≠ {x} ≠ {{x}}

heavy sedge
#

That's what I thought.

#

Do you know of anywhere that this concept is explained in depth?

#

I guess it's pretty straightforward

brazen gorge
#

thing and a set that has the thing aren't the same

heavy sedge
#

Fair enough then. That's all

#

Thanks 🙂

#

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kind hawk
#

sets are bags

heavy sedge
#

.reopen

obtuse pebbleBOT
#

kind hawk
#

a bag with a bag with something in it is different than just a bag with something in it

heavy sedge
#

Yea I remember this concept from {∅} containing one object

#

ok

#

I think that's all

heavy sedge
#

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median carbon
#

$\lim_{n\rightarrow \infty} (\frac{3^n+2^n}{3^n-2^n})^{3^{n}} = \lim_{n\rightarrow \infty} (1+\frac{1}{\frac{3^n-2^n}{22^n}})^{3^{n}}=\lim_{n\rightarrow \infty} ((1+\frac{1}{\frac{3^n-2^n}{22^n}})^{\frac{3^n-2^n}{22^n}})^{x_n}=\lim_{n \rightarrow \infty} e^{x_n}$
where $x_n = 3^n \frac{2
2^n}{3^n-2^n}}=2 \frac{6^n}{3^n-2^n}$
so $\lim_{n \rightarrow \infty} x_n = +\infty$, so $\lim_{n \rightarrow \infty} e^{x_n} = \lim_{n \rightarrow \infty} e^{+\infty} = +\infty$

warm shaleBOT
#

Lambda
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

median carbon
#

Ok, my question is if I made any mistake

#

Cuz desmos shows me that the limit is 1

median carbon
# median carbon

But it looks like it's having problems graphing this function, so maybe it's desmos' fault

#

<@&286206848099549185>

desert light
#

u r right

#

the answer is +inf

median carbon
#

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twilit meteor
#

can someone help with the 5th question

obtuse pebbleBOT
radiant patrol
#

x^3+3x+2=0 can help to solve it

obtuse pebbleBOT
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clever tundra
#

i'm going insane are the final two options not the same answer?

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left needle
#

for which values of x is the sixth term of (sqrt(2^(log(10-3^x)))+5throot(2^((x-2)log3)))^n equal to 21 if the double binomial coefficient of the 3rd term is equal to the sum of binomial coefficients of the second and fourth term.
i got that n=8
but then i get this and i dont know how to solve that

left needle
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left needle
#

<@&286206848099549185>

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carmine mulch
obtuse pebbleBOT
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carmine mulch
#

<@&286206848099549185>

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surreal arch
#

Ok, I have come to a question I cannot do myself. I do not know what a slope field is. Could I get some help?

surreal arch
surreal arch
#

Thank you very much, I never would have thought to use khan academy

#

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sudden sage
#

i'm supposed to find the radius of convergence for this power series

sudden sage
#

i got |x|<1/3 but when i subbed it into wolfram i got this

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sudden sage
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verbal musk
#

For 10: how do I know which one it’s increasing at

obtuse pebbleBOT
visual onyx
#

increasing just means that as you go further right, does the function go up, or down?

#

parabolas go in one direction until they reach their vertex, at which point the switch, and go on for infinity

#

so on that parabola, when you're to the right of the vertex, is the function going up or down?

verbal musk
#

it keeps going up

visual onyx
#

and to the left of the vertex it's going down

verbal musk
#

right

visual onyx
#

so if the vertex is at x=3, and after that it increases forever, what interval would "starting at 3, and going forever" correspond to?

verbal musk
#

D

#

why wouldn't it be a

visual onyx
#

because an interval is made of 2 parts, where it starts, and where it ends, respectively

#

both A and D have infinity as their second component, which is correct

#

but A has -2 as its first

#

which would mean that the function starts increasing after x=-2

#

but if you look at the graph, from x=-2, until x=3, it's still decreasing

#

which isn't increasing

verbal musk
#

ohhhhh

#

I see

#

what about 11?

#

I have to put it in y = mx+b form right

visual onyx
#

yes

verbal musk
#

so add 18 both sides

#

no

visual onyx
#

you could do that

verbal musk
#

add 6y to both sides

visual onyx
#

but adding 6y is quicker

#

yes

verbal musk
#

then divide by 6

#

right

visual onyx
#

yes, as you want it in the form of y alone equalling something

verbal musk
#

should I leave it as a fraction

#

actually it isn't too ugly of numbers

visual onyx
#

you can simplify the y and constant terms, but since on the x term you'll be dividing 3 by 6, you'll end up with 1/2

verbal musk
#

yeah so it can be 0.5x

#

-3

#

would it move left 0.5x then down 3

#

@visual onyx

visual onyx
#

wdym move left?

verbal musk
#

left of 0,0

visual onyx
#

the constant term provides the y intercept, so since the constant term is -3 here, it will hit the y-axis at y=-3

#

and the slope is 1/2, and from the concept of rise over run, that means that for every 2 units you "run" to the right, you will rise 1 unit

#

so usually it's easy to build a linear equation from its y intercept and its slope

verbal musk
#

so start at -3

visual onyx
#

and go right 2 units, then up 1

#

which comes from the 1 and 2 in the slope of 1/2

verbal musk
#

2 units?

#

ohh I see

visual onyx
#

just whatever scale the graph is in

#

"unit" just being a vague term for distance when you don't have actual units given like meters or feet

verbal musk
#

no wait shouldn't it be -1/2x+3=y

#

since we divide by -6

visual onyx
#

when you moved the 6y over to the other side, you were adding 6y to both sides

#

that cancels out the -6y on the left

#

but then on the right you have just 6y

#

so you only need to divide by 6 to get it in terms of y=mx+b

verbal musk
#

oh yeah

#

I wrote it as 3x+6y on my paper

#

would that make 12 a straight line

#

going through 4

#

yeah ok

#

what about 13?

visual onyx
#

12 would be a perfectly vertical line, at x=4, yes

verbal musk
#

and 13?

visual onyx
#

i'm not really sure what that one's asking

verbal musk
#

I guess use the coordinates to write the equation in point slope form lol

#

which is y - y1 = m(x-x1)

visual onyx
#

sorry but i never did that, and i can't really understand what the question is asking

verbal musk
#

yeah

#

I kinda get it after searching it up

#

thanks for clarifying the first 3

#

.close

obtuse pebbleBOT
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ember crescent
#

Need help with this question

obtuse pebbleBOT
ember crescent
#

13a is 54°
13b is 41°
13c is 26°
13d is 9°

But I don’t know what to do next to determine the triangle with the greatest area

obtuse pebbleBOT
#

@ember crescent Has your question been resolved?

ember crescent
#

Unfortunately not yet

#

<@&286206848099549185>

#

Oh well

#

.close

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wide oracle
#

what does dx and du really mean here?

obtuse pebbleBOT
lost zenith
#

Du is the same

#

The thing is, the function you’re integrating isn’t straight forward so you want to simplify using u-substitution

#

When you do that you need all variables to be to respect to u

#

Let me walk you through your example problem

lost zenith
#

x*e^x^2, you chose u to be x^2

Now you need to change the integration from being with respect to dx to being with respect to du, to do that you need differentiate both sides of u = x^2 with respect to x

It will equal du/dx = 2x

You need dx alone in one side to know how much du is it equal to.

du/dx = 2x, multiply by dx then divided by 2x

You reach du/2x = dx

Now replace dx in the integral with du/2x and replace x^2 with u, to finish what we started.

See if any thing cancels with 2x, sure enough 2x before “e” cancels with it, now you’re left with the integration e^u with respect to du, which is straightforward

#

Any confusion?

#

Of course you can change u to its value 2x after the integration is done if you wish to, or if the question asks you to

obtuse pebbleBOT
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full moss
obtuse pebbleBOT
full moss
#

anyone know how to do 9

alpine raven
#

,r

#

.

#

,rotate

warm shaleBOT
timid silo
full moss
#

What

obtuse pebbleBOT
#

@full moss Has your question been resolved?

obtuse pebbleBOT
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@full moss Has your question been resolved?

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modern sentinel
#

Hi please help

obtuse pebbleBOT
modern sentinel
#

9x+54=90 Right omfg-

#

Idk how to do this im in dumb math

wooden slate
#

not 90

modern sentinel
#

Is it x

wooden slate
#

what angle is a straight line

modern sentinel
#

Omfg,, idk 😭💋

ember frost
#

they are supplementary angles

modern sentinel
#

Straight

#

180? x

ember frost
#

can you draw a 90deg angle for me

modern sentinel
#

I_

wooden slate
modern sentinel
#

💋 😭 💔 Omffg tysm

#

True queen

wooden slate
#

just to be clear, x does not equal 180

#

but thats what you set the sum to

modern sentinel
thorny idol
modern sentinel
#

How do I be smart omfg,, 😭

#

I wanna be in honors math its my dream 😍

modern sentinel
#

Omg-

#

<@&286206848099549185> xx

obtuse pebbleBOT
subtle sinew
modern sentinel
#

Omg sory

modern sentinel
subtle sinew
#

What

#

You're asked to evaluate f(6), and I'm asking if you know what that means

modern sentinel
#

Oh yess

subtle sinew
#

What does it mean?

modern sentinel
#

5.5

subtle sinew
#

What

modern sentinel
#

Im just as confused 😭💋

subtle sinew
#

I'm just asking what f(6) means

modern sentinel
#

Ohh

subtle sinew
#

From what it looks like in the previous problem, you knew what f(1) and f(2) meant

#

So I'm asking you what f(6) means

modern sentinel
#

Oh I entered a random number and got it tysm 😭

#

Im trying to get into honors x

subtle sinew
#

You won't make it far into honors if you just guess and not understand the concept

modern sentinel
#

U ruining my confidence

#

💔

subtle sinew
#

For you to achieve far, you should understand the concept, not just randomly guess

modern sentinel
#

I honeastly dont even know what f means omfg,,,, x

#

Were u in honors queen? x

subtle sinew
modern sentinel
#

I asked chat gbt

subtle sinew
#

That's probably still not going to really help you get far

#

Since you're not understanding what to do

modern sentinel
#

I was accepted into honors anyway- 💋
Chat gpt will save me x

#

Omfgggg im gonna get into yale 💋😍 xx

#

University of Talia Queen

#

Lasrt word omfg-- 💋

ember frost
#

quick question, how old are you?

subtle sinew
obtuse pebbleBOT
#

@modern sentinel Has your question been resolved?

obtuse pebbleBOT
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daring zodiac
#

f(x)={x^2)+2x x>0
{x^3)-x x<=0

obtuse pebbleBOT
daring zodiac
#

is it just 0

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@daring zodiac Has your question been resolved?

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daring zodiac
#

lim x->0 sin3x/5x^3)-4x

obtuse pebbleBOT
daring zodiac
#

how do i go on about solving it

obtuse pebbleBOT
#

@daring zodiac Has your question been resolved?

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rancid fjord
#

How do I find the minimum

obtuse pebbleBOT
zenith raft
#

oh hi @surreal forge

rancid fjord
#

wsg

#

this is the 3rd time this is happening

#

and I ain't actually Mqnic :c

#
  1. I got since roots are imaginary and the equation will be imaginary only when x^2+2x+3 is imaginary which is not possible for real roots
#

but now how do I find the min

worthy birch
#

Lol

surreal forge
#

oh hi @zenith raft

surreal forge
zenith raft
#

oh hi mark

void ember
obtuse pebbleBOT
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@rancid fjord Has your question been resolved?

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fathom basin
#

This is a determinant 3x3

obtuse pebbleBOT
fathom basin
#

How i can solve this

pallid basin
#

Do you know how to do cofactor expansion?

fathom basin
#

I need triangular

#

31 need be 0

frigid burrow
#

nah we got chill guy

fathom basin
#

How we can solve this

pallid basin
fathom basin
#

For gauss

#

Is more easy

#

I need be 0

#

Thid is true?

obtuse pebbleBOT
#

@fathom basin Has your question been resolved?

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timid silo
obtuse pebbleBOT
timid silo
#

Pls help with this!

#

According to me geometric image should be (-5π/6,-2π/3) in complex plane

#

<@&286206848099549185>

#

!15min

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

worthy birch
#

arg(-z) + arg(z) = π

#

@timid silo

obtuse pebbleBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

timid silo
#

Thanks!

#

.close

obtuse pebbleBOT
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umbral moth
#

need help with this question.

obtuse pebbleBOT
umbral moth
#

<@&286206848099549185>

obtuse pebbleBOT
#

@umbral moth Has your question been resolved?

umbral moth
#

<@&286206848099549185>

#

: (

rain forge
#

use cauchy product

#

for the first one

umbral moth
#

ohhh

rain forge
#

and for the second you have the convergence with special critera (dunno the name in english)

umbral moth
#

thanks you for responding

#

leibniz one right?

rain forge
#

ye

#

leibniz

umbral moth
#

u german?

rain forge
#

french

umbral moth
#

ohh ok

#

aight

#

lemme give it a try

#

please don't leave

rain forge
#

ye

umbral moth
#

@rain forge i think I actually tried applying the cauchy product to the first one here

#

but I think I made a mistake

#

can you take a look?

rain forge
#

what is your (a_k) and (b_k) here ?

umbral moth
#

i set my b_k as 2^k/(k+1)(k+2) and my a_k as 1/2^n

rain forge
#

a_k depending of n

umbral moth
#

i didn't do my selections based on anything

rain forge
#

don't think so

#

you want something which has a : "n-k" in your sum

umbral moth
#

i just bunched the ones that have k as index as b_k and the ones that have n as index as 2^n

rain forge
#

don't you see something similar

umbral moth
#

ohhh

#

2^(k-n) ?

rain forge
#

$2^{k}/2^{n} = ..$

warm shaleBOT
#

phoestaclies

rain forge
#

ye

umbral moth
#

aighthth WAIT WAIT

#

lemme try again

#

one moment

wide oracle
#

@umbral moth what does your name mean?

umbral moth
wide oracle
#

amireza

#

i see

umbral moth
#

yuhh

wide oracle
umbral moth
#

yeah+#

wide oracle
#

im smart opencry

umbral moth
#

@rain forge this look good?

rain forge
#

ye

#

seems good, gj

umbral moth
#

@rain forge and for the second one, just use leibniz-crit

#

can I dm you I run into any other problems?

obtuse pebbleBOT
#

@umbral moth Has your question been resolved?

obtuse pebbleBOT
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split drum
#

can someone please explain this point to me?

obtuse pebbleBOT
tardy epoch
#

left f(x) is continuous at a, middle and right are not continuous at a

split drum
#

what's the dot thing in the first one?

tardy epoch
#

dots are just values of the function but highlighted for emphasis

#

just like how the italics don't mean anything in the previous sentece, just used for emphasis

little pelican
#

hi can i get help here? im just in 9th grade though

obtuse pebbleBOT
little pelican
#

ty

split drum
#

but wait

#

how do we tell if a function is continuous or not just by looking at it?

#

if that makes sense

tardy epoch
#

some teachers let you assume most functions are continuous

#

also depends what you were taught

split drum
#

ah, okay

#

thank you 🌸

#

.close

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crystal hamlet
#

Knowing that a+b+c=6p ,how do I prove that a^2+b^2+c^2 is greater or equal to 12p^2 <@&286206848099549185>

alpine bison
#

$a^2+b^2+c^2=(a+b+c)^2-2(ab+bc+ac)=36p^2-2(ab+bc+ca)\ge 12p^2 \iff (ab+bc+ca)\le 24p^2$

warm shaleBOT
crystal hamlet
#

Thank you

#

.close

obtuse pebbleBOT
#
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lime garnet
obtuse pebbleBOT
lime garnet
#

got an answer its wrong but not sure where i went wrong

cedar mantle
#

ok im not looking through your integration, but have you realized the surface you are given isn't "closed"??

#

i.e. it doesn't encapsulate the whole sphere

#

instead, we take the hemisphere

#

however, this isn't clsoed

#

so what we do, is we take the integral of the upper half of the sphere

#

and the integration upon the volume will be equivalent through the flux out of the top sphere, and also the unit sphere lying on the xy-plane

#

so we need to then subtract the flux of the unit sphere on the xy-plane

lime garnet
#

im confused what integral did i calculate in my working out ?

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chilly lichen
#

can someone help

obtuse pebbleBOT
fallen pine
#

I'm guessing turning points refers to critical points here

#

as in where the graph changes from increasing to decreasing or vice versa

chilly lichen
#

i do think so yes

fallen pine
#

Is this calculus?

#

If not then just make a rough guess

chilly lichen
#

it is

fallen pine
#

Do you remember how to find critical points then

chilly lichen
#

ermm

#

no

chilly lichen
#

when i put this tho it got one mark closer

fallen pine
#

Solve $f^{\prime}(x) = 0$

warm shaleBOT
chilly lichen
#

uh

#

the second one is 0.5

gloomy brook
#

basically means, do the derivitive of the function and set the value to 0

chilly lichen
#

wym that doesnt make sences can you explain

fallen pine
#

buddy you said you were in calculus.. you should know what a derivative is

gloomy brook
#

as in the derivative of x^3 is 3x^2 forexample

#

now do the rest

chilly lichen
#

listen im not the brightest i skipped most of school and just jumped in to gcse

gloomy brook
#

otherwise take a step back and learn about derivatives, you wont progress further without knowing how they work

obtuse pebbleBOT
#

@chilly lichen Has your question been resolved?

flat rune
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@chilly lichen Has your question been resolved?

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nova iron
#

How would you find an explicit formula for the local inverse of the manifold $F(x,y,z) = x^2 + y^4 - 2z^2 - 2 = 0$ near the point $(3,1,2)$? I've tried things with the implicit function theorem but I keep getting lost.

warm shaleBOT
#

klausliker421

obtuse pebbleBOT
#

@nova iron Has your question been resolved?

obtuse pebbleBOT
#

@nova iron Has your question been resolved?

nova iron
#

<@&286206848099549185>

nova iron
#

besties

obtuse pebbleBOT
#

@nova iron Has your question been resolved?

obtuse pebbleBOT
#

@nova iron Has your question been resolved?

misty dagger
#

if you wanna write F(x,y,z)=0, as z=f(x,y), then yea you can do it

obtuse pebbleBOT
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stoic smelt
#

2 vertical poles have heights of 7ft and 12ft. A rope is stretched from the top of each pole to the bottom of the other. How far above the ground do the ropes cross

stoic smelt
#

Can anyone help me solve this?