#help-10

1 messages · Page 425 of 1

obtuse pebbleBOT
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@dire violet Has your question been resolved?

obtuse pebbleBOT
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@dire violet Has your question been resolved?

obtuse pebbleBOT
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timid silo
obtuse pebbleBOT
timid silo
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ok im not sure why.. i got a different answer

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the other root is. 2+5i

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so

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i did

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  1. 2+5i + 2-5i + a + b = 4
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and

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  1. ab(9) = -29/4
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  1. 4 + a + b = 4
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a + b = 0

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a = -b

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  1. ab = -29/36
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a^2 = 29/36

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a = +/- sqrt 29 / 6

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what went wrong?!

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the answer was 1/2

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HELP

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<@&286206848099549185>

supple coral
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You can divide the quartic by the root expressions you know to get a quadratic, then just solve that. Not sure what b is trying to say. As in don't use the insane radical solution?

normal cairn
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i think what dapro did is he found 2 solutions and tried to find the other two by creating a system with vietta

wary meadow
timid silo
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oops

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thanks!

wary meadow
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(2+5i)(2-5i)=29

wary meadow
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maybe thatll clear thingd up

wary meadow
timid silo
wary meadow
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nwws

timid silo
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.close

obtuse pebbleBOT
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old hollow
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Can someone explain how to get the horizontal asymptote?

supple coral
#

Take a limit as x -> infinity.

obtuse pebbleBOT
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@old hollow Has your question been resolved?

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obtuse pebbleBOT
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@past gazelle Has your question been resolved?

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sharp sequoia
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i need help with chromatic polynomial

obtuse pebbleBOT
sharp sequoia
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i know you can divide the below graph to two small graph like you can seen above

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y(y-1)(y-2) function above. But i do not know how to continue

obtuse pebbleBOT
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@sharp sequoia Has your question been resolved?

sharp sequoia
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no

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<@&286206848099549185>

heavy bramble
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Try to simplify

obtuse pebbleBOT
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lusty tide
#

Hello, I need help with this problem. I understand the meaning behind it all is, that if ∂(a,b,c,d) = ad - dc = 0 the line vectors or column vectors are collinear. Which is why the three conditions are equivalent. However, I do not understand how to prove it. I was told to prove equivalency by showing 1 => 2 => 3 => 1, but nothing else about how to prove something like this and have been trying for several hours at this point.

lusty tide
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This was one of my attempts for showing 1 => 2.

obtuse pebbleBOT
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@lusty tide Has your question been resolved?

lusty tide
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<@&286206848099549185>

obtuse pebbleBOT
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@lusty tide Has your question been resolved?

obtuse pebbleBOT
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@lusty tide Has your question been resolved?

lusty tide
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.close

obtuse pebbleBOT
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timid silo
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This is one of the questions on my math hw and we weren't taught how to do this so i'm completely lost

timid silo
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Like

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I got that the perimeter is 8w + 4h

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but i don't know how to write all of that in terms of only L

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I can get h = (1/4)(L-8w) and the reverse with w =

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but how do i write the whole thing in terms of only h i don't get it

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Am I supposed to write it like this so that it's technically still about L?

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Also I just have no clue what the first derivative test has to do with this

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oh wait

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
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@timid silo Has your question been resolved?

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round stratus
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Hi guys ! I need some help making sure of something

round stratus
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So if E is a vector space of finite dimension

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And f is a linear application on E

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We’ve got kerf^k+1 included in kerf^k+2

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Where k in an integer

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But do we have that

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Alright I’ll design the first ker as N and the second as M to make writing things easier

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So do we have f^k(N) included in f^(k+1)(M)

vale pelican
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yes, because f^k(N) = {0}

round stratus
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No

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N is the ker of f^k+1

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Not f^k

vale pelican
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word

round stratus
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Word?

vale pelican
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my bad lol

round stratus
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Oh alright

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I’ve been stuck on it for a while now and I know it’s true because of another inequality of dimensions I have but can’t use that cause I have to use this to prove it so I am stuck there

vale pelican
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f^k(N) ought to just be ker(f) then, right?

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hmm I might be being silly

round stratus
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It is included in it

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Don’t know about the other way tho lemme check

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Doesn’t seem like it’ll work

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Is there anything we can use based on knowing that kerf^k is an increasing sequence while imf^k is a decreasing one

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Switched to trying to prove that f^k(N) is included in Imf^k+1

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If I prove this I’ll be able to use it to prove an inequality I have and then use it to prove the first problem

obtuse pebbleBOT
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@round stratus Has your question been resolved?

round stratus
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That doesn’t seem to be correct

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So back to the first step

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I’m gonna stop here

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And try later

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!close

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.close

obtuse pebbleBOT
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obtuse pebbleBOT
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patent mortar
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In how many ways can four men and eight women be seated at a round table if
there are to be two women between consecutive men around the table?

For this problem, why is my solution of 4! * 8! / 12 wrong?

drifting wraith
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hmm

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oh ok

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like, if you don't divide by 12 you have 4! × 8!, but how is that a seating arrangement

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usually the part before / 12 would already count something

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idk, i'm confused

patent mortar
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My logic going in was to consider the positions for men

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and then consider the possible sequences of the women in between the men afterr

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and then divide by 12 since you can start from any of them to get an equivalent permutation as this is circular

drifting wraith
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yeah so like you count arrangements that start with a man

patent mortar
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yeah

drifting wraith
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so there would be 4 repeats of each one

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not 12

patent mortar
drifting wraith
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like if there's 3 people

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you would count 3!

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and divide by 3 because clearly there's 2 aragnements that repeat 3 times

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amd if you imagine what 4! × 8! looks like, it wouldn't have all 12 versions, only those that start with a man

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so that's why, i can't explain any better

patent mortar
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That makes sense

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So you are saying that the order depends on the man that we hold fixed?

drifting wraith
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you're not holdng anyone fixed

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if you did, there wouldn't be an issue in the first place

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with 3 people you would get 2! immediately, because there 2 unfixed people

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and here you would get 3! × 8! because there's 3 unfixed men and 8 women

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it's because you allow all people to move, division appears

patent mortar
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like thats what I didnt do

drifting wraith
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if you do 3(4! × 8!) you would count all arrangements

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times 3 because there's 3 ways it could look like

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then / 12 works

obtuse pebbleBOT
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@patent mortar Has your question been resolved?

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patent mortar
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.reopen

obtuse pebbleBOT
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patent mortar
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like the smaller ones?

drifting wraith
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they are men

hazy flicker
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indeed

drifting wraith
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could be blocks too

obtuse pebbleBOT
#

@patent mortar Has your question been resolved?

obtuse pebbleBOT
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light drift
#

Consider the transformation L : V → R3 give by
L(x ) = (x1, x2, x4 + x3).
where
V = {⃗x = (x1, x2, x3, x4) ∈ R4 | x4 = x3 − x2}.

  1. Prove that V is a vector subspace of R4 and determine its dimension

I've proven it is a vector subspace as it is closed under addition + scalar multiplication, but I don't understand how to determine V's dimension

brave bramble
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Basically:
It's 3. R4 has dimension 4, and putting one restriction on it reduces the dimension by 1.

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However, you should want to prove it:
You can find a span for V. Typically done by putting this into a matrix
x1 = x1
x2 = x2
x3 = x3
x4 = x3 - x2
And reducing

light drift
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so if we had another restriction

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say x1 = x2+2x3

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would that reduce it further?

obtuse pebbleBOT
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@light drift Has your question been resolved?

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quaint radish
#

I hate to ask this vague of a question as my first question here, but I’m genuinely so lost on Inverse trig functions. I pretty much get sin^-1(wtv) means what angle gives you a sin of wtv. I got number 13, inverse sin of 0 is 0, but I’m already lost on 15.

orchid wind
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here

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it helps to draw a reference drawing

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what this tells us

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is arccos is from [0,pi]

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and arcsin is from [-pi/2,pi2]

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so for your example

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15

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we draw this

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not what angle is at that x

quaint radish
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-pi/2

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Is that the same has 3pi/2 or no ☹️

orchid wind
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yes

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it is

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3pi/2 = -pi/2 essentially

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but remember

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the range of arcsin

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[-pi/2,pi/2]

quaint radish
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oh ok

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yea iirc teacher said q1 or q4

orchid wind
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ye remember

quaint radish
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ah ok

orchid wind
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arrcos is q1, q2
arcsin is q1, q4
arccot is q1, q2
arctan is q1,q4

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and so on

quaint radish
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is it easier &/or better to remember the points on the unit circle >pi as negative fractions or improper ones?

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Like is -pi/2 easier to remember than 3pi/2

orchid wind
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no

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remember 3pi/2

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then look at q1 for the negative values

quaint radish
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ah ok

orchid wind
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so whats the x

quaint radish
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7pi/6

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Or -pi/6

orchid wind
quaint radish
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Wait

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Oh

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I’m tripping

orchid wind
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7pi/6 is q3

quaint radish
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ok

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I’ll try the problems & come back if I need help w the third section

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Cus it looks like an extra concept

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ok I thing I got the first kind

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the second kind I think you’d Js cancel cos & inverse cos out but I remember teacher saying theres situations you can’t do that. & i don’t know what I’d do w 4pi/5 after I cancelled anyway

obtuse pebbleBOT
#

@quaint radish Has your question been resolved?

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dapper wing
#

how do I find the equation for this summation?

worn yoke
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can you classify the type of sum this is?

dapper wing
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im not sure

wary badger
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ggggggg

dapper wing
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the exponent ones I can't seem to identify

wary badger
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what class do you usually take after algebra 1?

worn yoke
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well what classifications of sums have you learned?

dapper wing
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so like for the natural numbers manipulation, I could base that off of n(n+1) / 2

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but I cant find the one for exponents

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and I don't know how to google it

worn yoke
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two classifications of sums you may have encountered are arithmetic and geometric sums

dapper wing
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hm

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like multiplication vs sums?

worn yoke
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no, they are both types of sums

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an arithmetic sum is the sum of an arithmetic sequence, where the difference between each term and the next term is constant

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a geometric sum is the sum of a geometric sequence, where the ratio of each term and the next term is constant

dapper wing
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oh

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i found the sum of geometric sequences, but my teacher used it for an induction process instead of defining what it even is to begin with

worn yoke
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well if we apply that here, are the terms we're adding part of an arithmetic or geometric sequence?

dapper wing
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geometric

worn yoke
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so we can apply the formula for that

dapper wing
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actually thats not the summation

dapper wing
worn yoke
#

well it should be a formula like [ \sum_{k = 0}^n r^k = \frac{r^{n+1} - 1}{r-1}]

warm shaleBOT
dapper wing
worn yoke
#

note that [ \frac{a^n}{b^n} = \ab(\frac ab)^n ]

warm shaleBOT
dapper wing
worn yoke
obtuse pebbleBOT
#

@dapper wing Has your question been resolved?

obtuse pebbleBOT
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cosmic raven
#

Why does my teacher multiply the perimeter and area together here?

cosmic raven
safe haven
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you want A as a function of r

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A = something something r

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but your A function has a h in it, we dont want it

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so you get h in terms of r from the perimeter, then replace it with that

cosmic raven
safe haven
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if it just asked for that then no

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but it specifically asked it as a function of r

cosmic raven
#

ok I see

safe haven
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so you gotta remove any other variables that is not r

cosmic raven
#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
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silk monolith
obtuse pebbleBOT
silk monolith
#

Are my steps correct?

#

Ok

#

.close

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obtuse pebbleBOT
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hasty lily
#

Let $A \subset 2^\mathbb{R}$ be a countable collection of sets of real numbers such that every finite subset of $\mathbb{R}$ is a subset of some set in A.

Show that there exists a chain $S_1 \subset S_2 \subset S_3 ...$ of subsets of $\mathbb{R}$ such that $\bigcup_{i \in \mathbb{N}} S_i = \mathbb{R}$ and $\forall i \in \mathbb{N}, \exists a \in A | S_i \subset a$.

warm shaleBOT
patent osprey
#

what have you done so far?

hasty lily
#

well pretty much nothing. i dont have any ideas

obtuse pebbleBOT
#

@hasty lily Has your question been resolved?

obtuse pebbleBOT
#

@hasty lily Has your question been resolved?

spare jungle
hasty lily
#

yep

obtuse pebbleBOT
#

@hasty lily Has your question been resolved?

obtuse pebbleBOT
#

@hasty lily Has your question been resolved?

hasty lily
#

its not true

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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frosty fractal
obtuse pebbleBOT
frosty fractal
#

What exactly do they mean by A* is a polynomial in A?

#

I think I am having a brain dead moment

kind hawk
#

A* = p(A) for some polynomial p

frosty fractal
#

so like it can be written as a function of A?

kind hawk
#

yes

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but just as a function of A is not interesting

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the interesting part is that this function is a polynomial

frosty fractal
#

Why does that make it more interesting?

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It's just kinda thrown in there

kind hawk
#

trivially A* is a function of A, namely take A, transpose it and conjugate each entry

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but now it could be for example that A* = 13A^2-7A+3I

frosty fractal
#

Okay that makes some more sense on why it's relevant, thank you. That's actually pretty cool

#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
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signal yacht
#

Please help

obtuse pebbleBOT
signal yacht
#

ill be honest I dont relly know how to go about this

alpine bison
#

$\log_2(2^{-n})=-n$

warm shaleBOT
signal yacht
#

... im not sure what you mean

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how do I get to that?

old lily
#

u wanna split the integral into parts where u know the value of the floor(log_2(x))

alpine bison
#

$(0,2]=\bigcup_{n\ge -1} (2^{-n-1},2^{-n}]$

warm shaleBOT
signal yacht
#

oh my

old lily
#

floor(log_2(x)) = -n iff -n <= log_2(x) < -n+1

signal yacht
#

i dont think Ive learnt this integration technique

old lily
#

it's ok

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can u solve -n <= log_2(x) < -n+1 for x

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i'm using -n cuz on (0,2) log_2(x) is negative

signal yacht
#

yes

old lily
#

it goes from -inf to 0 if u think about it

signal yacht
#

okay

signal yacht
alpine bison
#

you have to use $\log_b(b^n)=n$

warm shaleBOT
alpine bison
#

in this case b=2

old lily
#

do you understand the floor function

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like floor(x) = 2 iff 2 <= x < 3

alpine bison
signal yacht
alpine bison
#

of calc.

signal yacht
#

oh wow

old lily
signal yacht
#

i think I might be doomed for this test lmao

alpine bison
old lily
#

C^2 functions ig

alpine bison
#

oo I see

old lily
old lily
#

what's floor(2.5)

signal yacht
#

i

old lily
#

huh

signal yacht
#

i think this might be too advanced, sorry i didnt realise when I asked the question

old lily
#

like the complex number?

signal yacht
old lily
#

ohh haha

signal yacht
#

while I have your attention, woudl you mind if I asked a different question instead?

old lily
#

okay

signal yacht
#

am I right in saying that the discriminant should be 0 if I factor out an x?

#

nevermind

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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rain yoke
#

How do i calculate what percent an amount is from a total? Like 256 out of 280. I did read you do 256/280x100 but i don't understand why x100

tardy epoch
#

just definition of percentage

last pilot
#

100% = 1

#

and technically it's not x100, but rather x100% = 1

tardy epoch
rain yoke
#

Okay, thanks i'll read that it's so long since i studied so i've forgotten some

#

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heavy anvil
#

Hey this is mr cook typing

#

Uh no problems ?

#

Boring

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clear cosmos
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dense schooner
#

can you help me in 2b

obtuse pebbleBOT
dense schooner
#

i did everything above

#

but i have no idea how to prove 2b

obtuse pebbleBOT
#

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dense schooner
#

<@&286206848099549185>

velvet spoke
obtuse pebbleBOT
#

@dense schooner Has your question been resolved?

dense schooner
velvet spoke
#

find √(x+1)

dense schooner
#

It equal to find √tan^2+1

#

And just use it on the first f(x)?

velvet spoke
#

yeah so sec theta

#

obviously

#

since you have to prove f is something

dense schooner
#

Alr ty

#

Imma lock at it rn

velvet spoke
#

now f becomes 4/pi arctan(sec - tan)

#

im sure you can take it from there

#

using this

dense schooner
#

Oh yeah i can

#

Tysm

#

Bruh the result is so simple yet i couldnt do it

#

.solved

obtuse pebbleBOT
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dark orchid
#

Is this right?

obtuse pebbleBOT
restive acorn
#

Looks ok

#

The exact answer would be in terms of logarithms

#

x = log(3)/log(8) - 11

dark orchid
#

hm

red ice
#

$x = \frac{\log 3}{\log 8} - 11$

warm shaleBOT
#

south's secret twin brother

dark orchid
#

yeah

red ice
#

the -11 doesn't go in the denominator

#

so you just typed it wrong

dark orchid
#

thanks for the helps

#

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timid silo
#

Are here any ways to prove that A, C, and D Is 0 in the partial fraction of 1=a/x+b/x^2+c/(4-x)+d/(4-x)^2+e/(4-x)^3

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boreal pier
#

can anyone help me setting up this integral please

boreal pier
#

<@&286206848099549185>

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#

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worn coyote
warm shaleBOT
#

EQUENOS

boreal pier
worn coyote
#

Tbh this particular volume can be calculated without any integrals

worn coyote
#

S = (area of the ellipse with axis 1 and 3) = 3 pi

#

h1 = 2

#

h2 = 2

#

V = 2 * 3pi + 3 pi = 9 pi

boreal pier
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strange wraith
#

How do I know if something is exponential growth or decay when a is negative

strange wraith
#

Videos and sources states rules only about b

#

So I’m confused on questions like these

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toxic oyster
#

i need help finding critical numbers

merry stratus
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drowsy pollen
obtuse pebbleBOT
drowsy pollen
#

This is the original question

#

I understand why we have -3 and 5x^2, but I don't understand how the middle term is 2x

orchid wind
#

remember

worn yoke
#

2x^(1/2) = 2x^(1 - 1/2) = 2x * x^(-1/2)

orchid wind
#

power rules

#

1/2 - (-1/2)

#

=

#

1/2 + 1/2

#

=1

drowsy pollen
#

Oh we are dividing the powers

#

Ahh that makes sense

#

Okay ty

#

.solved

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timid silo
#

when does this not work?

obtuse pebbleBOT
thorny idol
obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

so only if ∫∑|f_n(x)|dx < ∞?

#

is: ∑|f_n(x)| < ∞ enough too?

obtuse pebbleBOT
#

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stable yew
#

i need help

obtuse pebbleBOT
stable yew
#

with questions on homework

#

pleaes

#

please

meager mural
#

hi

stable yew
#

hiiiiiiiiiiiiiiiiiiiiiiii

meager mural
#

type ur qn

stable yew
#

How many 4-digit numbers can be formed from the digits 0 through 9 if no digit can be
repeated and the number should contain digits 2 and 6?

meager mural
#

for the purpose of this question, is 0123 a 4-digit number?

stable yew
#

yes

meager mural
#

The hard naive way: ((ways to choose 1 digit from 2-6) x (ways to choose 3 digits from 0,1,7,8,9)x(ways to interleave 1 digit with 3 digits)) + ((ways to choose 2 digits from 2-6) x(ways to choose 2 digits from 0,1,7,8,9) x (ways to interleave 2 digits with 2 digits)) + ((ways to choose 3 digit from 2-6) x (ways to choose 1 digits from 0,1,7,8,9) x (ways to interleave 3 digits with 1 digits)) + (ways to choose 4 digits from 2-6)

#

The trick:

#

(ways to choose 4 digits from 0-9) - (ways to choose 4 digits from 0,1,7,8,9)

stable yew
#

how would I find those?

#

erm hello?

meager mural
#

sorry

#

yeah

#

look up your textbook for permutations

#

what's the formula

meager mural
# stable yew how would I find those?

check your textbook, course materials, or chatgpt for "permutations", or "ordered choosing without replacement". What is the formula that they give you?

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#

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vestal forge
#

what does mathematically tractable mean

obtuse pebbleBOT
vestal forge
#

what makes a range not tractable mathematically?

gilded needle
#

wdym by range in this context

vestal forge
#

statistics, highest minus lowest value in data set

#

this a bit confusing, i tried scouring the internet but all i see is mathematically tractable being used in more complex situations

timid silo
worn yoke
#

can you show a picture of the full context?

vestal forge
#

It's just a sentence from my book. It's under the properties of a range. "Finally, the range is not tractable mathematically." Which just felt like it came out of left field

vestal forge
timid silo
#

I mean if your just analyzing it wouldn't it mean that range can't be solved with simple math solutions idk

vestal forge
#

what does simple math methods entail? is subtraction not a simple math method? im sorry, im really too stupid for this i guess i should stop fixating on this part and move on

worn yoke
#

it's difficult to really comment on it without further context

vestal forge
#

I see. That's all the context I could give. It's an elementary statistics books for freshmen, under a chapter for measures of dispersion with range being the first example for measure of absolute dispersion. I guess the author just randomly threw the term out

worn yoke
#

,rccw

warm shaleBOT
vestal forge
#

sorry! didnt know u could do that

trail musk
#

it just means "it's not easy to work with"

worn yoke
#

even though if you are given a data set it is easy to calculate, when you are considering more abstract properties of data samples, other measures of dispersion are easier to work with

vestal forge
#

ah! that i can work with

#

tysm ❤️ i love this community

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#

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sinful falcon
#

How do I sketch a graph of f(x) if f’ = 0 and f’’ = 4?

ember onyx
#

can you show the entire problem

sinful falcon
#

Uhhh yea I’ll be back then I was trying to recollect the question from memory lemme find it

#

.close

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gloomy pelican
#

May i get a hint for this pls? Let ( f : \mathbb{R} \to \mathbb{R} ) be a non-increasing function. Let ( a_0 \in \mathbb{R} ) and define ( a_{n+1} = f(a_n) ) for ( n \geq 0 ). Prove that the sequence ( (a_n) ) has at most two distinct limit points.

warm shaleBOT
gloomy pelican
#

so I have to do probably something like this: suppose there are some three limit points $L_1 < L_2 < L_3$, we have $f(L1 ) \geq f(L2) \geq f(L3)$

warm shaleBOT
gloomy pelican
#

aand idk how to proceed from here

#

I can suppose that this sequence is divergent

#

otherwise we wouldnt have three limit points

#

<@&286206848099549185>

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#

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@gloomy pelican Has your question been resolved?

obtuse pebbleBOT
#

@gloomy pelican Has your question been resolved?

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#

@gloomy pelican Has your question been resolved?

gloomy pelican
#

.close

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#
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short leaf
#

Does it always beacome 1 if you divide when its even number and add 1 when its odd number

timid silo
#

Huh

marsh glen
#

huh

timid silo
#

Whats

#

The context

marsh glen
#

the question

timid silo
#

?

#

😞

marsh glen
#

🤷‍♂️

timid silo
#

Aiyayayai

short leaf
#

For exempel 3 is odd so 3+1=4 and 4 is even 4÷2=2 2÷2=1

short leaf
short leaf
timid silo
#

💀💀💀 idk

short leaf
marsh glen
#

the way you worded the question is bad

timid silo
#

Okay like I don't get why ur doing this for

#

Like

#

What is it for

marsh glen
#

i get what ur saying now tho with the example and the answer is yes

#

cause by definition, an odd number is just an even number plus 1

short leaf
marsh glen
#

your wording is bad but yes

short leaf
marsh glen
#

by adding 1 to an odd number, you make it even.
if u keep dividing an even number by 2, you will eventually get 1

#

no idea what that is

short leaf
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timid silo
#

For odd number multiply by 3 and add 1??

obtuse pebbleBOT
timid silo
#

That thing??

short leaf
short leaf
timid silo
#

Okay

short leaf
timid silo
#

Isn't this like an unsolved problem

short leaf
#

I think so

timid silo
#

Wtf was Lothar collz thinking when he introduced this 😭

short leaf
timid silo
#

But it's still unsolved

#

.close

obtuse pebbleBOT
#
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marsh glen
#

ill look into the conjecture in a bit cause im helping someone else in another chat

timid silo
#

Bc it's under my name idk why 💀

#

.reopen

obtuse pebbleBOT
#

short leaf
# timid silo Bc it's under my name idk why 💀

If the one i said, even= divide 2, odd= +1, always makes to 1 and the colletz thing is that when its an odd number you just multiply by 3 which always gives you an odd number and then add 1 to make it even so this would too always be 1?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

marsh glen
#

just saw a vid on it

#

collatz conjecture is slightly different to the first problem you stated

#

and the answer is idk

#

for the new question

#

there is a video you might be interested in that goes over the things in mathematics that are logically impossible to be proven or disproven https://www.youtube.com/watch?v=HeQX2HjkcNo

Not everything that is true can be proven. This discovery transformed infinity, changed the course of a world war and led to the modern computer. This video is sponsored by Brilliant. The first 200 people to sign up via https://brilliant.org/veritasium get 20% off a yearly subscription.

Special thanks to Prof. Asaf Karagila for consultation on...

▶ Play video
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short leaf
obtuse pebbleBOT
marsh glen
#

in the first one u said
get a number n
if even /2
if odd add 1
in this case. yes, it will always reach 1

short leaf
marsh glen
#

because u dont scale it by a large factor like 3

#

or maybe i might be wrong, idk

#

ill have to check in depth but rn im not up for thta

#

its almost 11

short leaf
#

👍

marsh glen
#

ye, the conjecture is cool tho

#

keep exploring it

short leaf
#

@tardy epoch

tardy epoch
#

What

short leaf
# tardy epoch What

Does it always beacome 1 if you divide by 2 when its even number and add 1 when its odd number

short leaf
tardy epoch
#

What is the question

#

"it"

short leaf
tardy epoch
#

Alright just stop pinging me if you can't ask a coherent question

tardy epoch
#

So am i

short leaf
#

Maybe my english is bad

short leaf
tardy epoch
#

Definitely stop pinging me

short leaf
#

Do you?

short leaf
# tardy epoch .

When i apply theses rules, rules: even number= ÷2, odd number=+1, and if i do it with any number will it be 1, for example 3 is odd so 3+1=4 4÷2=2 2÷2=1

obtuse pebbleBOT
#

@short leaf Has your question been resolved?

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#

@short leaf Has your question been resolved?

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#
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timid silo
#

@dusk widget sorry I took so long wanna continue?

dusk widget
#

well uhh.. a couple things

#
  1. you really shouldn't ping individual users for help, and that goes for me too
  2. I can try to keep it going, but I also have to be off to bed sometimes soon
#

let's go for now, shall we?

ionic oar
#

hi

dusk widget
#

oh Copter is here too

timid silo
#

yoo i didn't know this server had custom emojis

ionic oar
#

wait it does?

#

o

timid silo
dusk widget
#

well yes, but I thought you were coming back before the channel closed cat_happycry

timid silo
#

I was just following orders from you pepe_crying

dusk widget
#

you shouldn't open a new channel by pinging me ded

timid silo
#

Oh okeh

dusk widget
#

it should be a channel where I've already helped you

timid silo
#

Okeh

#

Uhh let's continue with a new thing shall we?

#

It's the same thing but just the function of the formula

dusk widget
#

@thorny idol my apologies, but may you please stop bnuuy reacting every message 😭

dusk widget
timid silo
#

For now I kinda understand most parts of this

dusk widget
#

sure

timid silo
#

Lets move on

#

How does the area work?

dusk widget
#

alright

#

let's start with uhh, rectangle, shall we?

timid silo
#

Sure

dusk widget
#

it'll be easier to explain triangle and square later

timid silo
#

Okk

dusk widget
#

the area of a rectangle is given by A = lw, where l is its length and w is its width

#

do you want me to explain where this comes from? eeveethink

timid silo
#

2 × 3?

dusk widget
#

yeah

timid silo
dusk widget
#

yes, though I should've added units to this problem

#

say that it's 2m x 3m

#

then the area is ...

fathom flicker
timid silo
#

6m

dusk widget
#

Austin, not now please

timid silo
#

^2

dusk widget
#

the meters also have to multiply

#

so it's 6m**^2**

timid silo
#

Oh

#

3m + 2m
6m²

dusk widget
#

not +, *

timid silo
#

Multiply sorry

dusk widget
#

you're fine

dusk widget
#

do you just want to accept it, or do I need to explain where this comes from? kongouderp

timid silo
#

Eh accept it

dusk widget
#

sure...

#

we can do that

#

I'll just drop this picture here though thumbsupanimegirl

#

do you want to move onto the square or the triangle now

#

which one?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

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dusk widget
#

@timid silo I have to go to bed now, so if you have further questions, please open a new help channel and wait for somebody else to respond thumbsupanimegirl

obtuse pebbleBOT
#
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rare sail
#

if a system of linear equations has the matrix

a b c
a b c
a b c

if they're the exact system of 3 linear equations, what would the eigenvector be and why?

gilded needle
#

well you know (1,1,1) is one eigenvector, right?

gilded needle
#

are you asking for others? probably depends on a,b,c

#

you do know something about the eigenvalues though

rare sail
#

eigenvalue is 0 here is it not?

gilded needle
#

yea, because?

rare sail
#

because the system is consistent with infinite solutions

#

am i getting it right 😭

fossil crag
#

(bc,ac,-2ab) should be another

gilded needle
#

and what's the eigenvalue that goes with (1,1,1) eigenvector?

gilded needle
fossil crag
#

and (-2bc,ac,ab)

rare sail
fossil crag
#

or -2abc + abc + abc

gilded needle
#

(usual caveat that eigenvectors have to be nonzero, so depending on a,b,c these may or may not qualify)

fossil crag
#

anyways if all of a,b,c are non zero, there are at least two LI eigenvectors among (bc,ac,-2ab), (-2bc,ac,ab) and (bc,-2ac,ab)

#

otherwise if exactly one is zero, suppose it's c for example

#

then (b,-a,0) and (0,0,1) work

rare sail
#

ohhhhhhhhhhh

#

i think im getting it

fossil crag
#

if exactly two are zero (for example b and c), then (0,1,0) and (0,0,1)

#

if all three are zero... pretty easy

rare sail
gilded needle
#

no

#

quite the opposite

fossil crag
rare sail
#

oh uh 0 0 0

fossil crag
#

nah

#

every non zero vector is an eigenvector

gilded needle
#

for the zero matrix, everything is an eigenvector (except (0,0,0))

fossil crag
#

since Ox = 0

rare sail
#

hm

#

ok so what if the matrix is

2 -1 1
-1 2 -1
1 -1 2

and i had to find its eigenvector given that an eigenvalue is 1?

cuz when i tried to solve (A-lambdaI)v=0

i ended up getting

x -y + z = 0
x -y + z = 0
x - y + z = 0

fossil crag
#

anyways the challenge is if a+b+c = 0, how to find the non zero eigenvalue

rare sail
fossil crag
#

x-y+z = 0

#

z = y-x

#

(x,y,z) = (x,y,y-x) = x(1,0,-1) + y(0,1,1)

rare sail
#

wait so its fine if i get more than one eigenvector from this eigenvalue?

fossil crag
#

it's never not been fine

rare sail
#

damnnn ok i got it then

fossil crag
#

there are eigenvalues with geometric dimension > 1

#

meaning eigenspace bigger than just a line

rare sail
#

whats an eigenspace

fossil crag
#

it's a subspace

rare sail
#

ahhh vector spaces

#

ok

#

yea i think i got it, dont need any help now

fossil crag
rare sail
#

ok nvm

fossil crag
#

the set of all eigenvectors of eigenvalue 1

#

is {x(1,0,-1) + y(0,1,1)} = span((1,0,-1),(0,1,1))

rare sail
#

wait that makes so much sense

#

cuz the eigenvectors of that eigenvalue would ultimately span in R3

#

ok i got it ty

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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patent socket
#

In here I thought it didn't had a vertical asymptote. I refactored it was 2(x+1)/(x+1)(x+1) = 2/(x+1). Here it would have a vertical asymptote if i would say that x = -1 (which is the correct answer). But when setting in x in the original function that would return 0/0. After refactoring the function, do we still look at what the original function looks like or not?

obtuse pebbleBOT
#

@patent socket Has your question been resolved?

warm shaleBOT
#

bruhmoment

patent socket
#

Yeah because it's basically the same, right? Does that mean that it wouldnt really matter?

#

Because before refactoring if we set in -1 it becomes 0/0, but after it would become 2/0

warm shaleBOT
#

bruhmoment

patent socket
#

So what really is the difference between a asymptote and discontinuity? Looks like they're quite the same

#

.close

obtuse pebbleBOT
#
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#
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runic arrow
obtuse pebbleBOT
runic arrow
#

Shouldn’t it be C+lna?

tardy epoch
#

ln(a) = constant

runic arrow
#

but you want to multiply right

#

to simplify

#

so why isnt it +lna

tardy epoch
#

multiply what?

#

who wants to multiply?

runic arrow
#

ok no i get it

#

ughghfdxhjhdf$

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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restive ginkgo
#

Hello I need help with building a circuit - I am still an amateur when it comes to programming and etc

restive ginkgo
#

Here is the table and the question, I was wondering how to get it an answer and what to do first and how to solve

#

Here it is in English, sorry

digital yew
#

Hey

restive ginkgo
#

Hello

digital yew
#

If I post 5 questions will you guys answer em?

restive ginkgo
#

No you need to go to a different server for help

#

I’m asking for help too lol

digital yew
#

Ok

zenith raft
restive ginkgo
#

Hey

zenith raft
#

@patent crag look

restive ginkgo
#

Look where

zenith raft
#

sorry i will stop griefing this channel

restive ginkgo
#

Ah can someone please help

#

<@&286206848099549185>

#

What do I do here?

#

I know I am supposed to build a circuit but I don’t know how to get to the outcome, how to set it up and what to do and etc

#

<@&286206848099549185>

#

What do I do when I get no response?

#

<@&286206848099549185>

obtuse pebbleBOT
#

@restive ginkgo Has your question been resolved?

restive ginkgo
#

<@&286206848099549185>

#

.close

obtuse pebbleBOT
#
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#
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torpid maple
#

how do i swap the double integral from dydx to dxdy? ive drawn the graph but Im not sure whats the upper bound for x. For now my lower bound for x is 0 but not sure if thats right

torpid maple
#

So far this is what I got, not sure if I’m on the right track though

deft ginkgo
#

Doing it with the dydx approach would be the way since it's simpler to compute, and that integral is properly set-up, you're on the right track

torpid maple
#

ah i cant do it with dydx approach cause the question specifically asked to reverse the order of integration ;-;

#

im just stuck on how to get the upper bound for x

deft ginkgo
#

MB I didn't see the question XD

torpid maple
deft ginkgo
#

I'd say u would have to do 2 integrals

#

One for the upper triangle

#

And one for the lower one

torpid maple
#

oohh

deft ginkgo
#

That would make it easier

torpid maple
#

then add them up?

deft ginkgo
#

Yee

torpid maple
#

oooohhh.... that makes more sense

deft ginkgo
#

The game is to make the bounds easier to swallow, if it looks painful it's probably wrong XD

torpid maple
#

ahhh... thats fair enough, thanks alot!

torpid maple
deft ginkgo
#

You're welcome 😁

obtuse pebbleBOT
#

@torpid maple Has your question been resolved?

#
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#
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white gull
obtuse pebbleBOT
white gull
#

How doci find the area

#

Of this

spark monolith
#

is it parallel

white gull
#

It doesnt say

timid silo
#

sieht so aus

spark monolith
#

did it mention what shape

timid silo
#

looks like it

white gull
#

Nope

timid silo
#

looks like a parallelogram

#

to me

white gull
#

it just says geometry: write an expression for the area of each figure

spark monolith
#

looks like straightup a^2b*b^3 to me

timid silo
#

if it is then the area is just

A = $$\text{base} \cdot \text{height}$$

warm shaleBOT
#

Edmund Cloudsley

white gull
#

Wait what

spark monolith
#

$A=b\cdot h$

warm shaleBOT
white gull
#

its b times h and not side times side

timid silo
#

the area of a parallelogram is just base times its height

timid silo
#

yeah

#

and both are given

white gull
#

i didnt know

#

I thought its side times side

timid silo
#

so effectively you need to evaluate

$$b^3 \times a^2b$$

warm shaleBOT
#

Edmund Cloudsley

timid silo
white gull
#

Yeah i got it thanks.

white gull
#

Everything with 4 sides that has parallel sides

#

😭

timid silo
#

u cud use this as a referenece

#

*reference

white gull
#

alrr

#

thanks alot

timid silo
#

cheers goood day

white gull
#

u too

#

What ab this one

#

Do we use pythagorean

#

Or smt

#

Cuz right angle

#

And we need height

obtuse pebbleBOT
#

@white gull Has your question been resolved?

obtuse pebbleBOT
#
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#
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timid silo
#

how do i do this

obtuse pebbleBOT
timid silo
#

<@&286206848099549185>

past valve
#

what have you tried?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

past valve
#

Like if the radius of the circles is r the side of the square is 2r right, then just calculate the area of the 4 circles and the of the square to determine the area of the grey area

timid silo
#

So one side of the square is 4x cm

#

The area of the square is 4x•4x= 16x²

#

And rhe area of the circle is

#

4 • pi • x²= 4pix²

#

well like take side of square to be r then circle radius is r/4 then total area of all the circles will be 4 * pi * r^2/16

#

right?

#

total area of square is r^2

#

that works

#

oh shit i said radius

#

for diameter

#

😅

timid silo
#

side is comin 13.65

#

answer in the end

#

so yeah

timid silo
#

tysm

#

.close

obtuse pebbleBOT
#
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timid silo
obtuse pebbleBOT
#
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winter crescent
#

What's ab+b/b

obtuse pebbleBOT
ember onyx
#

show the entire problem pls

timid silo
#

ab+b/b = ab/b + b/b = a + 1

winter crescent
#

ab+b/b
b(a+1)/b
(a+1)×b/b
(a+1)×1
(a+1)

#

So I'm correct

#

Wait till that sucker knows

tardy epoch
#

,w simplify (ab+b) / b

trim portal
winter crescent
#

cosa/1+sina - cosa/1-sina

#

,w simplify cosa/1+sina - cosa/1-sina

tardy epoch
winter crescent
winter crescent
# tardy epoch why

Because I'm trying to help a friend of mine and he has a little time left

tardy epoch
#

why does he have little time left

winter crescent
#

Because the exam is in the next hour

tardy epoch
#

oh it's not even your own work

#

just tell your friend to join discord then

winter crescent
winter crescent
tardy epoch
obtuse pebbleBOT
#

@winter crescent Has your question been resolved?

obtuse pebbleBOT
#

@winter crescent Has your question been resolved?

obtuse pebbleBOT
#
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#
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queen dragon
#

Hey, I want to find a reference to a method for solving nonlinear PDEs literally 10 years ago, and forgot how it is even called. I used it for the non-linear heat equation with both heat capacity and conductivity dependant on temperature.

After going into dimensionless variables you would end up with dimensionless temperature \theta(t,x), and equation for it. Next I specifically seem to remember taking a transform of the equation with the dependant function (I don't remember steps before or after) to produce a number of algebraic equations which when solved gave an approximate solution dependant only on how many sin (n\theta) transforms you calculated.

I might be just remembering wrong, but if I am not crazy, could you help me remember the method name, or even better some reference books and articles?

obtuse pebbleBOT
#

@queen dragon Has your question been resolved?