help-10

[subtle wasp]

well done

[modern bison]

Thanks

Another question is to find AB how can we do it?

@subtle wasp

[subtle wasp]

yes

[modern bison]

.

[subtle wasp]

in ur picture it seems like AFC is a right triangle ?

is it right ?

[modern bison]

It's not mentioned in question

[subtle wasp]

ok doesn't matter

[modern bison]

I made the figure like that

CE is 18 but it's wrong here it's written 11

This was the question that I received

[subtle wasp]

did u get some equations or ratio in which AC appears ?

during ur reasoning

[modern bison]

Yea I found AC is 16

[subtle wasp]

so

look into the link i sent i think u already solve it

[modern bison]

Ahhh

Thank you very much

.close

[obtuse pebble]

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[obtuse pebble]

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[olive blaze]

Hi. I have a problem with linear approximation. I know how to do it with natural logaritms and roots, but not with eulers. Ill post the problem with formula i have to use it to get the result (the way ive learned and its easiest for me). Ive tried multiple solutions, but i cant seem to find the f(xo) and other elements so i implement my problem to formula

[astral silo]

1 question first, where is x in the equation

[olive blaze]

There is no x, the task is to get approximate result of this task by using the formula below

[astral silo]

uh

it looks like the one where u approximate the area but without x

[olive blaze]

I can show u the simpler task done if u dont understand what they want from me...

[astral silo]

dw i wont be able to help

im in pre-uni

[olive blaze]

Oh

I rly need help with this hahh... im having an exam next week, i dont know with eulers...

So ummm do i ping the helpers to check my problem?

[astral silo]

wait for 15 mins

[olive blaze]

okay..

Btw where do i ping them

[astral silo]

just @ helpers

in here

[olive blaze]

<@&286206848099549185>

[obtuse pebble]

@olive blaze Has your question been resolved?

[obtuse pebble]

@olive blaze Has your question been resolved?

[obtuse pebble]

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[empty pewter]

could someone help me w with number 3 please?

[high lily]

what have you thought about

[empty pewter]

I’ve tried to switch up combinations but B always ends up being the midpoint

[high lily]

what if A,B,C aren't collinear?

[empty pewter]

but it says line AC so wouldnt they have to be on the same line?

[high lily]

line AC would only refers to the line joining points A and C
says nothing about the position of B

[empty pewter]

would this work?

[high lily]

no

you're using B to name what seems to be two different points

think isosceles triangle

[empty pewter]

like this ?

[high lily]

yes

[empty pewter]

ohh ok I thought I had to actually include AC so I wasnt thinking abt that

thank you!

[obtuse pebble]

@empty pewter Has your question been resolved?

[obtuse pebble]

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[velvet portal]

so i see where i went wrong on part B, but i still don't know what i did wrong on part A and C

[velvet portal]

(screenshots are in backwards order)

ohh wait okay i think i see what happened in part A, i just completely dropped the 3

i still fail to see how the work that i did in C is wrong

[fallen pine]

it looks right to me

[velvet portal]

chatgpt also said so, i might have to email her and ask

[obtuse pebble]

@velvet portal Has your question been resolved?

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[crisp spruce]

I’ve tried this qhestion 10 times, and none of the answers are right

[junior granite]

!show

[obtuse pebble]

Show your work, and if possible, explain where you are stuck.

[junior granite]

3rd line

1/5 and 6 do not have those exponents

you can't take them inside those parenthesis

[crisp spruce]

I can’t? I thought that u had to multiple like “nx^n-1”

[junior granite]

that's 2nd line

and it is fine

but the problem is in 3rd

a(b^5) is not equal to (ab)^5

[crisp spruce]

Wait so how am I supposed to multiply the 3

[plucky scroll]

You dont

anything to the power a / b becomes
b root (blah) ^ a

@crisp spruce does this make sense

[obtuse pebble]

@crisp spruce Has your question been resolved?

[obtuse pebble]

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[split trail]

!help

[obtuse pebble]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[split trail]

the equation of a vertical line in a coordinate system is given by x=c but with the relation y=mx+c the slope comes out to be 1 but we know that the slope of vertical line is infinity
i know i am doing dumb thing somewhere
but please help me

<@&286206848099549185>

[kindred elk]

?

[worn yoke]

in y = mx + c there is a y in the equation. where would the y go?

[split trail]

y is 0

[worn yoke]

,w graph x = 5

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by cloudedhorizons

[thorn summit]

the problem with y = mx +b formap is that we dont have a single y

we have all values of y

[worn yoke]

clearly this is true for any value of y

not just y = 0

[thorn summit]

there is no "single" y at any point x

we cant say that y = mx + c for a vertical line, because the equation doesn't even change when we move x

[split trail]

pls explain more i cant understand 🙏

[worn yoke]

they are just completely different equations. trying to put them together is confusing and doesn't mean anything

[split trail]

wait a sec pls

this is the question

here i found dy/dx on the curve and put y=0 as it is a vertical line

then with the comparison of y=mx +c with x=any constant i equated dy/dx=1

by solving i got x coordinate as 2

but the ans says y coordinate as 2

pls correct me 😦

[worn yoke]

slope = (change in y)/(change in x)
vertical = no change in x
therefore vertical slope = (change in y)/0
which approaches infinity

therefore you should be finding the vertical asymptotes of the derivative

[split trail]

asymptotes?

see i know that the slope is infinity for a vertical line but y=mc+c is saying something else

x-c=0 for x=c line

x coeff is 1

y is 0

[worn yoke]

the formulas are completely incompatible! y = mx + c is only for lines that are not vertical, and x = c is only for lines that are vertical

so trying to combine them does not work

[split trail]

but y=mx+c is a general straight line equation

[thorn summit]

it's for lines that change over x

you cant have mx +c if there is no multiple values of x

there is no derivative. m means nothing because there is no dx for a dy

[split trail]

thats not actually true x+y=0 is also a straight line

[thorn summit]

it's a straight line that changes with x

[split trail]

yes

[thorn summit]

x=3 does not change with x

[split trail]

ohh ok

[worn yoke]

remember that "m", the coefficient of x in y = mx + c is the slope. if the slope is infinite, now i have the formula y = ∞x + c, which is nonsensical

[split trail]

yes i got that

so what will you guys do in that question just tell me the algorithm

[thorn summit]

sure, the line does get steeper and steeper the higher m you go, but it will never actually ever approach an entirely vertical line if we're in mx + b, because by definition it's a function. you cant have more than one y per x

that's why infinity breaks that and we cant say y is based on x, because infinity is arbitrary

[thorn summit]

do you know how to do implicit differentiation?

[split trail]

yes that -(partial differention of x...etc)

[thorn summit]

start by doing that then

[split trail]

i got x/2

[thorn summit]

whar

[split trail]

if i put y=0

[thorn summit]

that's not what we're solving for

we want to know the asymptotes

dont put anything in, what is your equation

[split trail]

dy/dx=-6x/3y^2-12

[thorn summit]

okay so

[split trail]

sorry

[thorn summit]

no dw

when would the graph be undefined?

[split trail]

what

[thorn summit]

here's a hint: factor the denominator

[split trail]

i can take out 3 common

[thorn summit]

okay good

now we have something like

$\frac{6x}{3(y^2-4)}$

yes?

[split trail]

yes

[warm shale]

Serphic

[split trail]

no

yes

[thorn summit]

lmfao mb

now aside from cancelling out the three from numerator and denominator, do you see how y^2 -4 is a difference of squares?

[split trail]

ohh yes'

y+2 into y-2

[thorn summit]

yep

so we now have

$\frac{2x}{(y-2)(y+2)}$

[warm shale]

Serphic

[split trail]

yes

[thorn summit]

when y is equal to positive or negative two, dy/dx shoots off to infinity

[split trail]

yes

[thorn summit]

so we know that y is either negative 2 or positive 2, we just need to check which of these end up working out (not giving us complex values of x, im assuming)

[split trail]

ok so we will put the values on the curve to give the x coordinate

[thorn summit]

unless i've messed up somewhere, yep!

[split trail]

well you are right actually

[thorn summit]

nice

[split trail]

by putiing y=-2 the values comes out to be imaginary

[thorn summit]

which means the tangent line interpretation doesnt work (imaginary values are weird 💀 )

[split trail]

thank you so much

[thorn summit]

np!

[split trail]

pls accept my request 🙏

.close

[obtuse pebble]

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[obtuse pebble]

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[slate grotto]

I don't really understand how to input it as answer...

[slate grotto]

I thought I would just solve for t, sub it into y equations and that's it. But it doesn't seem to work?

[timid silo]

Solve t in terms of x, and solve y in terms of x

[slate grotto]

one sec, I'll send my work

But like even if i then solve y in terms of x, it shows "y- {blank}"

unless it means it as
x= 2/3 y - 1?

oh that kinda makes sense

i think i got it, im just dumb, thank you

.close

[obtuse pebble]

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[obtuse pebble]

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[naive obsidian]

hello, i am not sure about a conclusion i made, this is very simples geometry, school level, or high school as americans would say

[naive obsidian]

i might be completely wrong about this but i went for

sin 45 = square root 2 divided by 2 = 20 divided by x

which in my head came out as 40 square root 2

i am very much a newbie on this stuff so pardon me for any errors

i do not have a phone rn which is why i used microsoft paint

[warm shale]

faiyrose

[naive obsidian]

accurate representation of my process

x = 2.20 squareroot 2

its still at a beginners level so theres no nned to delve into an answer much more complicated than this, if its correct that is

hello?

its already complicated when you dont speak math english so ill do my best

i thought to cross multiply (?)

2 for 20

and x for sqr2

since sin 45 is sqr2/2

as far as im concerned

[warm shale]

faiyrose

[naive obsidian]

so, my answer is correct?

teacher taught us to put the x just aside for now, and when the math is finished that x aside is now the value of that

[naive obsidian]

so hed just take this = and put it between the x and sqrt2

again, very much beginner math so, it doesnt evolve to much more than this

im really just thinking if the math that i did sums up to the correct value

divison

divisoon

division

[warm shale]

faiyrose

[naive obsidian]

oh

yeah thats what i did

so my result is correct infact

so this is what i was supposed to write

ooooooohhhhhh

thank you very much

excuse me for taking your time

how do i close this now

.ckose

bro

.close

[obtuse pebble]

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[obtuse pebble]

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[gaunt meteor]

Help

[obtuse pebble]

Please don't occupy multiple help channels.

[gaunt meteor]

Help

[wooden turtle]

with what

[gaunt meteor]

Area of this

sorry

I mean perimeter of this

Someone helped me with the area then left

[wooden turtle]

do you know the formula to get the perimeter of a rectangle

[gaunt meteor]

No I am so bad to geometry

[subtle sinew]

Try using google for that formulas if you don't know it

[wooden turtle]

2(l+w) is the formula i use, so your length is 20 and width is 15 so add them together and multiply it by 2

or add 15+15+20+20 and that will be your rectangles perimeter

[gaunt meteor]

Ok so

70 for the rectangle what about the triangle

10+10+20+20?

So 130ft for the perimeter

?

[wooden turtle]

for the triangle you have to do 2a + b so 2(10)+20 or 10+10+20 im pretty sure

[gaunt meteor]

I have another composite shape but instead it’s a rectangle and a half circle I think. What would I do for that

[wooden turtle]

then add both of the rectangle and triangle perimeter together

[subtle sinew]

Also why perimeter, that question asks for area of the composite shape

[wooden turtle]

he asked for the perimeter

[subtle sinew]

Why are you looking for the perimeter of that shape? The question states to find the area

[gaunt meteor]

She also wants the perimeter

[subtle sinew]

For bonus

[gaunt meteor]

It’s not required but I am trying to learn how to do it cause geometry makes no sense to me and it’s on the test tomorrow

[wooden turtle]

u might have to ask someone else im not good with circles and half circled sorry, i suggest looking up the formula on google though

[gaunt meteor]

How do I ask someone else post it in another help?

[subtle sinew]

Btw I don't suggest you to do it because the perimeter is harder than you think and if it's not required, you shouldn't spend too much time on it

[gaunt meteor]

It’s on the test tomorrow

And I don’t know how to do it

[subtle sinew]

It's bonus

[gaunt meteor]

This is the pratice test

None of its worth anything I just don’t know how to do it

[subtle sinew]

That's what brownie points mean, it's a bonus, extra credit

[gaunt meteor]

Idk why she said that

[subtle sinew]

If your teacher is going to put a similar question like that, she's either going to make it a bonus or not ask for the perimeter

[wooden turtle]

do @Helpers or just wait

[gaunt meteor]

Okay thanks

<@&286206848099549185>

[thorn summit]

hello!

[thorn summit]

lets start with area.

easier one would obvi be the rectangle

so

what is the area of the rectangle?

[gaunt meteor]

Okay

25*20?

[thorn summit]

yep

now for the area of the half-circle

[gaunt meteor]

25*12.5 for the top part?

[thorn summit]

not quite

okay so

[gaunt meteor]

Oh

[thorn summit]

what's the area formula for a whole circle?

[gaunt meteor]

No idea

[thorn summit]

ohh shit

[gaunt meteor]

Pie r ^2?

[thorn summit]

yep

[thorn summit]

now, we want just haalf of that

[gaunt meteor]

So what do I do w that info

Half c what

[thorn summit]

the total area of a circle is pi r ^2

[thorn summit]

the portion of the circle up here is a half-circle

[gaunt meteor]

12.5 is half of the circle ?

[thorn summit]

no

pi r^2 is the formula for the area of a full circle

if we divide that by two, we get the area of a half circle

[gaunt meteor]

So pi(12.5)^2 is the answer ? For the top part… then divide by 2 ?

After your times by 25cm

[thorn summit]

that's for if it were a whole circle

you dont times it by 25 jiskjdhnjfjn

okay

so

[gaunt meteor]

Then why did I do that for the last problem.

I had to times 20 the base by 10 then divide by 2

[thorn summit]

the difference here is that this is a portion of a circle

there is no unique length or width for a circle, because the area is based on the radius

[subtle sinew]

Because that's the formula to finding area of triangle

[gaunt meteor]

Okay That kinda of makes sense

[thorn summit]

you can describe a circle using only its radius, but you cant just telll me a triangle has a height of 3 and tell me to solve the area for it

because the only thing describing the circle is the distance from the center to the outside

[gaunt meteor]

On the left is already said 12.5

[thorn summit]

yeah

[gaunt meteor]

So if half of its 12.5 is that whole circle 25?

[subtle sinew]

Do you know what radius and diameter means?

[gaunt meteor]

I have heard of it not exactly sure

[subtle sinew]

I suggest looking it up

[gaunt meteor]

Okay

I did

But what do I do now

[subtle sinew]

Do you know what it means now?

[gaunt meteor]

Yes

[subtle sinew]

What does it mean? How are radius and diameter related?

[obtuse pebble]

@gaunt meteor Has your question been resolved?

[obtuse pebble]

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• After 15 minutes, feel free to ping <@&286206848099549185>.
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[neon spade]

Can someone please help me with this 😭 I’m really struggling finding the domain #61 a)

[neon spade]

A) f o g and state the domain

[vale pelican]

what's f o g explicitly?

[haughty stump]

I think that means f(g(x))

[vale pelican]

I was asking the op but thanks

[glossy basalt]

i like the answer 😆

[vale pelican]

that's also not the explicit form I was looking for

[haughty stump]

it looks simple enough, sin(2x)/(1+sin(2x))

and the denominator can not be zero

and just go from there

[vale pelican]

I still wasn't asking you, sorry

[haughty stump]

i wasnt talking to you either there

[vale pelican]

so why'd you give the answer to my question?

[glossy basalt]

Let's ask op

[haughty stump]

i didnt reply to you

[vale pelican]

you answered my question, which was incorrect to do

[glossy basalt]

@neon spade what have you tried?

[neon spade]

For the fog I got sin2x/1+sin2x

And I need to find the domain of that

And i don’t have a good idea of the concept of finding the domain

…?

[glossy basalt]

?

[neon spade]

😃

I’m js confused lol in the chat

[haughty stump]

^

[stuck finch]

when is domain undefined

for example what is domain of 1/x

[vale pelican]

the domain of a function is the collection of all inputs for which your function gives you a valid output

[neon spade]

Yeah I know so far that 0 is a number that works

[haughty stump]

Think about it, what makes a fraction like this one undefined?

[neon spade]

Uhh

-1?

[stuck finch]

yes

[neon spade]

Oh yay

[stuck finch]

sin2x=-1

[neon spade]

The sin is messing me up 😭

[haughty stump]

which you get from setting the denominator to 0

because anything divided by zero is undefined

[stuck finch]

do you know what is 7/0?

[neon spade]

0 DNE?

Yes

[neon spade]

DNE

[stuck finch]

no

yes

[neon spade]

SORRY LOL

[haughty stump]

thats like the most niche use of divided by zero

[neon spade]

😭😭

I’m tired man

So I have it doesn’t equal -1

Is it everything but -1?

[stuck finch]

nope

[haughty stump]

Alright so look at it this way

you have a thing

[stuck finch]

the domain you have to write with values of x

[haughty stump]

that thing is this function

you want to find the domain of this function

the domain is dictated by the denominator

[neon spade]

Oh okay

So focus on the denominator

[haughty stump]

you want to find all the times where the denominator is equal to 0 because that is when the function is undefined

[stuck finch]

sinx not equal to -1 then what is x not equal to

[neon spade]

-1

[haughty stump]

So if you solve the equation 1 + sin2x = 0, which is the denominator equal to 0, then you will get where the domain is NOT

[haughty stump]

remember, youre trying to find x, not sin2x

so what is the double angle formula for sin2x

[neon spade]

2sinxcosx

Plug this in?

[stuck finch]

no

[neon spade]

Oh

[stuck finch]

think of it as siny not=-1 y=2x

[haughty stump]

actually that was on me, I had a little brain fart mb

alright so how do you cancel out sin on both sides?

you now have sin2x = -1

[neon spade]

Oh😭

I’m sooo confused

Yes

I think

[haughty stump]

the next logical step is to get rid of the sin

[neon spade]

Get rid of sin?

[haughty stump]

well yes because you want x by itself

[neon spade]

-1/sin2

[haughty stump]

thats not how sin works

ANYWAYS

what is the opposite of sin?

[neon spade]

Csc

[haughty stump]

opposite operation, not reciprocal

[stuck finch]

khale i suggest you review all the basics first

[neon spade]

Bro chill year js started

[haughty stump]

as to why this is wrong, sin is something that encases an angle, if you want to understand this better try and always type it using parenthesis: sin(2x)

[haughty stump]

have you not learned inverse trig functions yet?

[stuck finch]

do you remember all standard trig values?

[neon spade]

O ok

[neon spade]

My teacher didn’t go over them

So no I didn’t refresh on that

[haughty stump]

dang the same thing happened to me when i learned them

anyways basically what they do is get rid of their respective uninversed trig functions

so sin^-1 (sin(x) is just x

this means that if you apply a similar logic to the problem sin2x = -1

you will have to figure out sin^-1 (-1)

[neon spade]

Hm

[stuck finch]

for now just find the value in (0,2pi)

[haughty stump]

which is basically saying where is sin equal to -1

[stuck finch]

sin of which angle yields the result -1 ?

[neon spade]

Oh

[neon spade]

3pi/2

[haughty stump]

correctomondo

[neon spade]

Yay

[haughty stump]

so what equation do you end up with?

[neon spade]

Wait what do I do with 3pi/2

[haughty stump]

that was your answer to sin^-1 (-1)

[neon spade]

Yeah so it’s js sin^-1(-1)=3pi/2?

[haughty stump]

which was becuase you wanted to get rid of sin on both sides of the equation sin2x = -1

so if you cancel out the sign on the left, and you got that as an answer on the right

you there?

lol

[neon spade]

Yeaa

[glossy basalt]

lol

[haughty stump]

ngl i was half expecting you to answer when i stopped typing

[neon spade]

Ok I looked at my answer but it says 3pi/4 + npi

[neon spade]

LMAO I’m here js very lost and tired

[haughty stump]

alright well you got that right, but you still have 2x on the left

and you want it by itself

[haughty stump]

supposed to be 2npi btw

[neon spade]

Wait what’s the eq so far

[neon spade]

O ok

[haughty stump]

are you not writing this down? xd

anyways

[neon spade]

Ima be honest I was in a cafe but I left cuz it was getting late and I still wanna understand 😭

Sorry sorry

U don’t have to help me 😭😭

I feel bad LMAO

[haughty stump]

2x = 3pi/4 + 2npi because you are accounting for every possible place where the domain of sin isnt

thats kinda why everyone who is helping is here

gives us superiority dopamine ykyk

[neon spade]

LOL

[neon spade]

O okay

Divide by 2?

[haughty stump]

well its good that you at least know how to generalize a domain equation

[haughty stump]

indeed

[neon spade]

X=3pi/2

[haughty stump]

forgot something

[neon spade]

+2npi!

[haughty stump]

forgot something again

[stuck finch]

you made a mistake

[haughty stump]

what did you just do

[neon spade]

Oh man

[haughty stump]

cough cough

[neon spade]

OH

[haughty stump]

harshly worded coughs

[neon spade]

JS npi

[haughty stump]

eyyyy

you got it

[neon spade]

LMAO

yay

[haughty stump]

but 1 more thing

you have to specify what n is

[neon spade]

Integer

[haughty stump]

not just an integer

n is ALL integers

[neon spade]

3pi/2 +npi and n is integer

ALL

[haughty stump]

woooooooooooooooooooooooooooooooo

alright now

[neon spade]

X is not that

YAY oh my

[haughty stump]

what is the domain

[haughty stump]

walp you beat me to it

congrats

you have figured it out

[neon spade]

Isn’t it all real number but that equation

Yay

[haughty stump]

si

very cool stuff amiright

[neon spade]

No not cool at all tbh I hate math

But thank you for ur time

[haughty stump]

lol everyone does at some point

anyways ".close" if you dont have anything else

[neon spade]

Kk

.close

[obtuse pebble]

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[uncut niche]

how the hell do i do this

[uncut niche]

algebra 1 consecutive integers

my thought process was divide 70 by 4 and then subtract or add if they ask for least or highest

but the amount i subtract or add by idk

i did 0.5 once and it worked

[teal turret]

Call the smallest integer g

[uncut niche]

alright

[teal turret]

How can we represent the next consecutive integer in terms of g

(The next whole number after g)

[uncut niche]

idk how to get the smallest number

i dont know where to start lol

[teal turret]

Reread my messages

[uncut niche]

g + 1 ?

[teal turret]

Yes

How about the one after that

[uncut niche]

g + 1 + 1 or g + 2

[teal turret]

Yes

How about the one after that

[uncut niche]

g + 1 + 1 + 1 or g + 3

[teal turret]

Yes

So what’s our sequence?

(In terms of g)

[uncut niche]

g , g + 1 , g + 2 , g + 3?

i think

idk

[teal turret]

Yes

Why’d u say idk

[uncut niche]

because i dont

i am just now learning this

[teal turret]

What aren’t u understanding

What consecutive integers are?

For example: 6,7,8,9

Consecutive integers

1008, 1009, 1010

[uncut niche]

i understannd

[teal turret]

Ok, so we have

g, g+1, g+2, g+3

[uncut niche]

g , g + 1 , g + 2 , g + 3?

yse

yes

[teal turret]

What does the problem tell us about this sequence

[uncut niche]

x=16

its 16

16 17 18 19

70

this can be done with python bro i could write a script that does this easily

and runs through every letter until the sum is equal to the thing we need

[teal turret]

Well python is fake math

[uncut niche]

basically

[teal turret]

This is more essential and fundamental

[uncut niche]

how do i get x though

instead of just looping through every number

[teal turret]

Answer this

[uncut niche]

new question

i need 3 consecutive integers

[teal turret]

Nah answer my question

[uncut niche]

g + 1 g + 2

and they need to total to 225

so ((x)+ (x + 1) + (x + 2)) = 225

?

[teal turret]

Idk what those commas mean

[uncut niche]

sorry lol

i was seperating them

[teal turret]

Ok

[uncut niche]

so ((x)+ (x + 1) + (x + 2)) = 225

[uncut niche]

that i need three integers that add up to 225

[teal turret]

U literally made an equation

Solve it

[uncut niche]

so i just guess for x?

[teal turret]

Do u not know how to solve a one variable equation

How would u solve 3x + 5 = 8

[uncut niche]

subtract 5 from 8 | 3x = -3 | 3 / -3 | x = -1

i think?

[teal turret]

How did u get -3

[uncut niche]

5 - 8

[teal turret]

So u subtracted 8 from both sides?

[uncut niche]

no i subtracted 5 from both sides

[teal turret]

Then why is the 8 after the minus sign

That means 8 is being subtracted

[uncut niche]

x = 1 ?

sorry for my bad handwriting

i cant write on mouse

[teal turret]

Yea x = 1

[teal turret]

Back to this

How would u solve this

[uncut niche]

3x + 1 + 2 = 225

3x + 3 = 225

3x = 222

holy shit the puzzle pieces

neuron activation

74

x = 74

[teal turret]

Did u have later elementary/middle school during covid

[uncut niche]

yes basically

[uncut niche]

i also was stuck with no math teacher for a while because of a teacher shortage

sorry if im slow 😔

im trying to learn

[teal turret]

Sorry to hear that

[teal turret]

It’s fine

Do what u can with what u have now

[uncut niche]

yay

[teal turret]

Before u do more coding, make sure to have ur math fundamentals down

[uncut niche]

yes

[teal turret]

Otherwise ur coding will take a hit in the future

[uncut niche]

yes ik

thank you for all the help

[uncut niche]

okay so

3x + 3 = 195

right?

[teal turret]

U don’t need me

[uncut niche]

i just wanna make sure my work is right

befoer you go

let me solve, and then can you review?

[teal turret]

Be confident and just do it. Even if it’s wrong, you’ll learn

[uncut niche]

3x + 3 = 195
3x = 192
192 / 3 = 64
x = 64
x + 1 = 65
x + 2 = 66
64 + 65 + 66 = 195

lets gooo

ty

ty stephen

.close

[obtuse pebble]

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[obtuse pebble]

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[fathom light]

Eric wants to make y=0?

What does get an output of 0 means?

[shut kelp]

for both machines

[violet nest]

you input x you get an output y

[fathom light]

So basically you want to know
x²+3=0
√x-7=0

[fathom light]

So get an output y=0 I am guessing

[fathom light]

Well check this and answer

x² =-3
√x =7

Are both of them possible, one of them, or none of them

[obtuse pebble]

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[limpid ether]

hey anyone wanna help me solve an online test thats a uni maths level?

[thorn summit]

!da2a

[obtuse pebble]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[thorn summit]

like

1. if you need help with a test, we cant really solve those for you here

2. if you're going to ask a question, please ask the actual question

we're not really allowed to straight up solve anything for you

[limpid ether]

oh aight i see, its not like an official test, but homework

what i need to know for this?

[thorn summit]

which interval do you think x = -5 would fall into?

is -5 less than -2, between -2 and 2, or greater than 2

[limpid ether]

-5 is less

[thorn summit]

mhm

[limpid ether]

so its 1?

[thorn summit]

yep!

[limpid ether]

oh damn, thx bro

how do i close it

[thorn summit]

.close

[limpid ether]

thx

you a W

[thorn summit]

np

[limpid ether]

.close

[obtuse pebble]

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[thorn summit]

fyi make sure for these type of questions if the interval also includes the number (ex: 2 ≤ x includes 2, but 2<x does not)

[quartz atlas]

In beginning my calculus undergrad class in my electrical engineering route and my teacher did something that I somewhat understand besides one part

The original equation was 3x^2+15x+6

We factored it to be 3(x^2+5x+2)

Afterwards, he stated that since the formula (a+b)^2=a^2+2ab+b^2 we can add a zero in by dividing the b term by two (in this case the b term was 5x) and then subtracting it by the same value, therefore Turning the equation into 3(x^2+5x+(5/2)^2-(5/2)^2+2)

Then he turned it into a perfect square place which resulted in
3((x+5/2)^2- 17/4

I understand he basically just reverse factored it, but why and how was he allowed to just do all of that? And why did he divide by 2?

Do I need to .reopen

[tardy epoch]

#help-18 is open

[obtuse pebble]

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[autumn estuary]

How do I find if the function is surjective or injective or both?

[autumn estuary]

I know the rules

But sometimes it doesnt work for me

Like for example f: Z->Z where g(x) = x^3 - x

x(x-1)(x+1

And lets say to check for injective function

How would I find out?

How do I check if x = y

ye

or no

Idk

[restive acorn]

So injective function means one to one

In other words, each x value has a unique y value

The definition you use to check for injective is as follows:

So if you can show that for 2 different x values that f has the same value, you can disprove injective

Well i know this one is not injective

Because

1 and -1 give the same value

[autumn estuary]

is this enough proof that x!=y

[restive acorn]

Going by this sorry

In that function

g(1) = g(-1)

Therefore 2 distinct x.values had the same y value

Therefore not injective

[autumn estuary]

ok

thank you

.close

[obtuse pebble]

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[rain chasm]

i have to write this in parametric form. I get the answer (x,y,z)= (4,0,0) + t(1,1/2,1/3) but the correct answer from the book is (x,y,z)= (4,0,0) + t(6,3,2) isnt this the same line ?

[weary reef]

Yes, they describe the same line

[rain chasm]

ok. thanks

.close

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[whole warren]

i dont get this

[solemn basin]

dam that's alot of hardwork

[whole warren]

i got this answer but i cant see whats wrong

[solemn basin]

5x and x² both tend to 0 at 0

Ohh it's undefined at 0 mb

[whole warren]

yea

[solemn basin]

Should be none of the above

Since x = 8 is also a point of discontinuity

[whole warren]

oh yea forgot about that option

but its usually never that so i never even consider it

[solemn basin]

tru lol same here

[whole warren]

well i got it wrong

[solemn basin]

How

[whole warren]

idek

[solemn basin]

What's the ans then?

[whole warren]

it doesnt tell me

i can take the quiz as much as i want but its diff questions each time

[solemn basin]

Fck 7 isn't a point of discontinuity cause at 7 we take the other function
So it was a

[whole warren]

wait wym

[solemn basin]

At x = 7
F(x) = x/x-6

[dusk widget]

[solemn basin]

Smart guy wsp

[dusk widget]

let's try again then...

what do you think?

[whole warren]

im trying

0,5,6,8

[dusk widget]

how did you come to that conclusion?

[whole warren]

x/x-7 dont matter cuz its not within its piecewise domain

right?

[dusk widget]

I don't really understand what you mean by that

well, we can go through each possible discontunity one by one

ah, let me see the picture

[dusk widget]

I mostly agree with this

the main issue I have is with 0, because the function isn't even defined at 0

[whole warren]

so is discontinous there

[dusk widget]

since it's not defined there, it can't possibly be continuous or discontinous there, technically

BUT

in a lot of high schools, you treat that as a discontinuity still

[whole warren]

if its not defined there, then doesnt it mean that its gonna be a hole

[dusk widget]

so I'm on the fence

[whole warren]

meaning that it will be discontinous

[dusk widget]

but it's not part of the domain

you can't speak of smth being continuous or not outside its domain

like how you wouldn't say that sqrt(x) is continuous or discontinuous at x = -100

[whole warren]

oh

[dusk widget]

but...

like I said

that might be treated as a discontinuity still...

[whole warren]

ig the math im doign rn isnt that deep yet

thanks

[dusk widget]

I'm not comfortable with it, but I think they want you to say it is one

[solemn basin]

We should consider 0

[dusk widget]

hm?

[solemn basin]

even though it's not a part of the domain

[dusk widget]

but this is just wrong

@whole warren I say put 0 as one yeah

[solemn basin]

Like take the function 1/x
It's discontinuous at x = 0
But x = 0 isn't a part of it's domain

[dusk widget]

it is not

discontinuous at 0

it is not defined at 0

so it is not discont there

[timid silo]

just draw a graph bro

[dusk widget]

1/x is a continuous function

[solemn basin]

potato tomato same thing

[dusk widget]

no

there is a difference here

1/x is not a function from R to R, it's a function from R / {0} to R

[dusk widget]

a function is continuous at $a$ if $\lim_{x \to a}f(x) = f(a)$

[warm shale]

higher!

[dusk widget]

f needs to be defined at a

[solemn basin]

Yea so since f isnt defined at 0 it can be called discontinues

[dusk widget]

no

read point 1

f(x) is defined, that is, exists, at x = a

[whole warren]

since a dont exist, then isnt it not continous

[dusk widget]

riemann help

[solemn basin]

Vaguely u can argue that u will have to take off the pencil while graphing it at 0 altho it's rigorously wrong

[dusk widget]

this is not the formal definition of continuity!

[solemn basin]

in layman terms we can say

[dusk widget]

but it is just not correct

are you gonna say that f(x) = sqrt(x) is discontinuous at x = -10?

[tardy epoch]

read more books, argue less

[dusk widget]

by the other logic, sqrt(x) is discont here

[solemn basin]

books are boring I prefer a teacher

[dusk widget]

there is no difference between one point and infinitely many points

if you're gonna claim that a function not being defined at one point means it is discont there, then you have to accept that a function not being defined at infinitely many points must be discont at all of them

there is no in between

[tardy epoch]

skill issue

[solemn basin]

Its not undefined for that
It just switches to a complex valued function

[dusk widget]

no???

that's not what a function is

you need to state the domain and codomain before writing down your rule

[tardy epoch]

you're just getting trolled now @dusk widget

[dusk widget]

it doesn't suddenly switch mid-way

[dusk widget]

idts, Display has been pretty nice to work with before

[solemn basin]

U win bro (I have physics homework mechanics 200 que)

[dusk widget]

[solemn basin]

I mean thats what I was taught

[dusk widget]

what on Earth were your teachers smoking

[solemn basin]

My teacher said that if they ask in exam that the point of discontinuity for 1/x just quietly mark 0 and say that altho it's not rigorous it's vaguely true

[dusk widget]

"vaguely true"?

are we doing maths based on vibes or what

hi Platypus

I don't even know anymore

[pseudo swift]

don't we all ?

[dusk widget]

damn, you have a point

anyways... @whole warren have you entered your answer yet?

hello Bungo

[gilded needle]

as usual, you can read what chatgpt has to say and assume the opposite

[dusk widget]

[whole warren]

yea i got it right

[gilded needle]

^ "a point in the domain" and yet it may have "an undefined value" hahaha

[solemn basin]

Was zero included?

[dusk widget]

that actually makes me upset

that the "correct" answer included 0

[whole warren]

yea

[tardy epoch]

e^{i pi} + 1 = zeta(2) based on vibes

[solemn basin]

Btw for that proof
that other guy was talking about the last term of the sequence

[dusk widget]

ah?

[solemn basin]

Tomm go and argue with your teacher also give us his no we will talk to him CALMLY

[dusk widget]

you know, Display, do you accept this?

[solemn basin]

If xn converges to l then |xn| converges to |l|

[gilded needle]

what the hell, this function isn't even well defined

try that formula with x=6

[dusk widget]

I know

but it's a discontinuity for them

[solemn basin]

What level of infinities are we talking abt

[gilded needle]

and yet it's not

[dusk widget]

uncountable, in the case of sqrt(x)

[gilded needle]

i could go along with "the function is not continuous at x=6" (since it's not even defined there), but you shouldn't say that x=6 is a point of discontinuity

[solemn basin]

Ok ok I accept my defeat ur the smarter guy I never had a chance

[dusk widget]

I don't want praise

that makes me feel weird

[solemn basin]

K

[dusk widget]

the whole "sqrt(x) suddenly switches up to become a complex-valued function when x < 0" was kinda insane though

[solemn basin]

K

[dusk widget]

@whole warren if you're done here, you may close the channel btw

[solemn basin]

yea mb

[dusk widget]

issok

no hard feelings

[whole warren]

.close

[obtuse pebble]

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[woeful lynx]

could be done in a math or a physics way

im in honors multivar and vector calc

not quite sure how to handle this one

[tranquil geyser]

Total upward force(vertical componentof tension) - total downward force(weight) =0

Hint 2:||apply Lami's theorem||

@woeful lynx

[obtuse pebble]

@woeful lynx Has your question been resolved?

[obtuse pebble]

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[drowsy stirrup]

On page 42/44, how did he get f prime(2) = -3? https://www.mathsgenie.co.uk/alevel/as-level-pure-oct2021ans.pdf

[opaque dome]

Can you ss ?

[opaque dome]

They said it in given

The second trait

[drowsy stirrup]

oh right, ty

.close

[obtuse pebble]

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[plain cosmos]

https://cdn.discordapp.com/attachments/1272655785377398796/1279199192476160213/IMG_4635.jpg?ex=66d39295&is=66d24115&hm=6cfc23a574c3af3445364e753f1ed31be3fbe8e6bb703a42a993bc9e740a29ab&

[plain cosmos]

i need help with 2

.close

[obtuse pebble]

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[high ermine]

hey i need help with some statistic questions

<@&286206848099549185>

[tardy epoch]

what the hell is this question

[high ermine]

its part b

can i send thw whole thing

[tardy epoch]

oh yes probably why no one's helped yet

[high ermine]

ahah sorru

sorry

@tardy epoch

is this enough

[tardy epoch]

yea someone should be able to help

[high ermine]

you ??? please

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[vast crystal]

How did they assume that multiplying the (x,y) coordinates at Q and R is A and B in the pythageron Therom respectively? I thought A and B were the side lengths

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[whole warren]

how would i do this

[stoic shell]

l'hopital

[whole warren]

with out that

[dusty grove]

have u tried trig angle addition

[whole warren]

no whats that

[whole warren]

that works for the numerator

you cant do that for denominator right

[dusty grove]

just do it twice

first 2x + x

then x + x

[stoic shell]

sin is approx linear with small angles is also a valid approach

2/3 🤔

[daring sorrel]

I am thinking you should try multiplying by x/x

[whole warren]

what would that do

[daring sorrel]

You can individually find the limits of sin(2x)/x and x/sin(3x)

[whole warren]

i got 2/3

thanks that works

[daring sorrel]

np

[whole warren]

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[storm ridge]

Find all the real values of K (refer to the first equation written in the paper) such that the equation has exactly one solution

[storm ridge]

I converted the original equation to quadratic form but afterwards I’m not sure what to do

[storm ridge]

Also asked this yesterday but I was too tired and lost track 🥲

[candid yarrow]

Recall that the discriminant is 0 iff the equation has exactly one solution

[candid yarrow]

So, you can calculate the discriminant of this equation

[storm ridge]

b^2 - 4ac right

[storm ridge]

a = 1, c = -3

I’m not sure what’s the value of b

please correct me if I’m wrong I really want to get this right 🥲

[candid yarrow]

No

since the variable of the quadratic is x

oh right

I didn't see that

I'll edit my message

[storm ridge]

So a=k and c=-3 ?

how do I get b

[candid yarrow]

No

Do you understand why a is k?

[candid yarrow]

b is the coefficient of x

[storm ridge]

Could you explain why

I’m having a hard time discerning the values

[candid yarrow]

can you see that the coefficient of x^2 is a?

[candid yarrow]

c is the sum of all the terms that aren't multiplied by x

[storm ridge]

when comparing kx^2 to standard form ax^2, a would correspond to k right?

[candid yarrow]

yes

And you can also compare to see what b and c are

[storm ridge]

b would be (2k-4) ?