#help-10

1 messages · Page 348 of 1

honest forum
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So what can I do?

brave bramble
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I'm not sure! At this point, I want to try examples.

I'm looking at 41 = 16 + 25

Double that is 82, which is 9² + 1²

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A way to go from 5² + 4² to 9² + 1²...

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I mean 5-4 = 1 so your subtraction method seems lit. 5+4 = 9 too

honest forum
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I looked at 13, which is 3^2 + 2^2, and 26, which is 5^2 + 1^2

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Which gives the same pattern

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However, if you start with 10, which is 3^2 + 1^2, you get that 20 = 4^2 + 2^2, which breaks any ideas of a pattern

brave bramble
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3+1 = 4, 3-1 = 2

honest forum
#

hmm

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so can we prove it using some sort of diff of squares?

brave bramble
#

I'm about ready to check out
(n - k)² + (n + k)²

honest forum
#

ohhhhhhhhhhhhhhhhhhhhhhhhhhhh

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thats crazy

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So any ideas for 5q?

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Taking similar examples, we get 65, which is 5(3^2 + 2^2)

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Which is 8^2 + 1^2

brave bramble
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I don't know off-hand, but again I think we can determine a pattern here

honest forum
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Taking 145, which is 5(5^2 + 2^2), we get 12^2 + 1^2

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hmmmm

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seems to be some pattern

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So WLOG, assume that $n \ge k$

warm shaleBOT
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Dork9399

honest forum
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Can we prove that 5(n^2 + k^2) = 2*n^2 + k^2 + 1?

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so 5n^2 + 5k^2 = 2n^2 + k^2 + 1

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3n^2 + 4k^2 = 1

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wait waht

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oh whoops

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it should be that 5(n^2 + k^2) = (2n+k)^2 + 1

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5n^2 + 5k^2 = 4n^2 + 4nk + k^2 + 1

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n^2 + 4k^2 - 4nk = 1

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or only when $n - 2k = \pm 1$

warm shaleBOT
#

Dork9399

honest forum
#

Which coincidentally fits both my examples

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Damn

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obtuse pebbleBOT
#
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obtuse pebbleBOT
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dry tulip
#

Okay this question is really screwing me over

obtuse pebbleBOT
dry tulip
#

I dont understand how I got this wrong

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Ive reviewed my work so many times

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can someone tell me where I made the mistake, because I cant see it

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<@&286206848099549185>

obtuse pebbleBOT
#

@dry tulip Has your question been resolved?

obtuse pebbleBOT
#

@dry tulip Has your question been resolved?

glacial wasp
#

do you need help

dry tulip
#

I literally

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got no idea why my answer is wrong

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I have my work up if you have any questions

glacial wasp
#

what is the question you are working on?

dry tulip
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its this

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My answer is 8040 but for some reason, its still incorrect

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heres my work to show for it

glacial wasp
#

Is this financial math?

dry tulip
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yes

glacial wasp
#

algebra based or business calculus based?

dry tulip
#

algebra based

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heres my work to show for it

glacial wasp
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Is there a formula?

dry tulip
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uhhh I guess

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?

glacial wasp
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I have no idea, you might try someone else who is better in finite math.

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so ping again.

dry tulip
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oh okay

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<@&286206848099549185>

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😔

#

.close

obtuse pebbleBOT
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red trench
#

does $f'(x^2)$ mean you plug in $x^2$ into $f'(x)$ or is it $(f(x^2))'$?

warm shaleBOT
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lunchbox

twilit fable
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f'(x) @red trench

red trench
#

so plug in $x^2$ into $f'(x)$ right?

warm shaleBOT
#

lunchbox

twilit fable
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yes

red trench
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thanks

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graceful marten
obtuse pebbleBOT
graceful marten
#

Now you can get,

3a + lna - ln2a -> 3a + ln (a/2a)

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Or

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3a - (ln2a + lna)

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a is positive

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which one do I use

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Or can i still use both

fickle turret
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What's a/(2a)?

graceful marten
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1/2

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true

graceful marten
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3a - ln (2a^2)

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no?

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but a has to be positive, so there will be a + and - answer for a via 2nd method?

fickle turret
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Where does the a^2 come from?

graceful marten
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well i dont even know how to do it

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(ln2a + lna)

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= 2a x a

zenith raft
fickle turret
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But the two ln got different signs here?

graceful marten
fickle turret
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-ln a

graceful marten
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where?

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how

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-ln2a - - lna

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-ln2a + lna

fickle turret
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Yes, and if you move a - out it becomes -(ln 2a - ln a)

graceful marten
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right oh yeah

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smart basic math smart

fickle turret
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Happens 👍

graceful marten
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-ln2a/a = - ln 2

3a - ln2 =

zenith raft
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when do we get an error_5507

graceful marten
#

Oh wait so -ln2 is the same as + ln1/2

fickle turret
graceful marten
#

okokokokokkoko

fickle turret
graceful marten
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sippy ill try it out

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ty !

fickle turret
#

You're welcome

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Can we close the channel?

#

.close

obtuse pebbleBOT
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solar meadow
#

Could anyone sort them out please. It make take a while but I am doing it too.

Elementary Algebra
Abstract Algebra
Linear Algebra
Universal Algebra
Advanced Algebra
Classical Algebra
Structural Algebra
Commutative Algebra
Pre – Algebra
Boolean Algebra
Algebra 1
Algebra 2
College Algebra
Algebraic …
Associative Algebra
Unital Algebra
Zero Algebra
Non - Associative Algebra
Monoid theory
Group theory
Ring theory
Module Theory
Galois Theory
Field Theory
Category theory
Topos theory
Quaternions and Quadratic Forms
Lattice Theory
L-group Theory
Group theory
Representation theory
Homological Algebra
Number theory
Ring Theory
Advanced linear algebra
Field and Galois Theory
Category Theory.
Lie Algebra
Clifford Algebras
Tensor Calculus
Trigonometry
Calculus I
Calculus II
Calculus III

graceful marten
#

Have you tried chat gpt

kind hawk
#

wdym, "sort them out"

graceful marten
#

Alphabetically

solar meadow
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From Zero to Hero

brisk matrix
#

i would seriously ask chatgpt to sort that

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a lot of those are branches too which dont really compare like that

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and a lot are intertwined as well

solar meadow
brisk matrix
#

yes

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chatgpt is able to describe and interpret the names of those fields

obtuse pebbleBOT
#
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viral robin
obtuse pebbleBOT
viral robin
#

for cosx in the last part i dont get how cos -1 get pi /6

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how do u convert the degrees into pi

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i forgot it was somethin g to do with radians

woeful lintel
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multiply the angle in degrees with pi/180

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u get radian equivalent

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for eg

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60 degrees

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is

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60*pi/180

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=pi/3

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ok'?

viral robin
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so cos inverse is 30

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them x pi/180

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is 30pi /180

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then

viral robin
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pi/6

woeful lintel
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yes bro.

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yes

viral robin
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how do u get the 11 pi/6

woeful lintel
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hmm

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lemme see'

viral robin
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i need to add some sort of degrees or something

brisk matrix
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but there are more angles on the unit circle which have cos(x) = sqrt(3)/2

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the other one is 11pi/6

viral robin
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how do i find the other valie 11pi /6

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ik its between 0 and 360 degrees on the unit circle

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i need to add 180 deggres

brisk matrix
viral robin
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or something like that

brisk matrix
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and convert that to radians

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or 2pi - the other angle in radians

viral robin
#

oh yea

woeful lintel
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which grade u guys in?

viral robin
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9

woeful lintel
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cool me too/

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do they teach diff calculus in your school?

viral robin
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i havent got up to calc

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this is tutor work

woeful lintel
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ohh cool.

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did u give pre-sat?

viral robin
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idk what that is

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i live in aus

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so 2pi -pi/6 i get 5.759...

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how does this lead to 11pi/6

woeful lintel
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2pi - pi/6

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is

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12pi/6 - pi/6

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=

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11pi/6

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ok?

viral robin
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oo

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thanks

woeful lintel
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welcome

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how are d kangaroos btw?

viral robin
#

delicious

woeful lintel
#

☠️

viral robin
#

Its great the sausages are great if u ever come down u should try some

woeful lintel
obtuse pebbleBOT
#

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fathom flicker
whole halo
#

Hi, I need help with Question 14

obtuse pebbleBOT
cyan oxide
#

Use ai calculators like mathway and photomath

whole halo
#

wdym

#

just type it in?

cyan oxide
#

No not you

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I replied to austin

whole halo
#

mb

cyan oxide
#

I havent the fucking slightest what you just sent, looks like an 18th century thesis about isaac newton

whole halo
#

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spare spruce
#

Hey i need help with a question

obtuse pebbleBOT
spare spruce
#

Can i send it here?

zenith raft
#

yes

spare spruce
#

also forgot to ask, will you be sending the answers as an image?

#

are you working out questions?

obtuse pebbleBOT
#

@spare spruce Has your question been resolved?

young sonnet
#

@spare spruce for a

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young sonnet
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D < 330

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young sonnet
#

. close

#

.close

inland matrix
#

It's closed

young sonnet
#

ight

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flat lance
#

general steps to solve a double sigma problem ?
∑∑ij types ?

slender kraken
#

such as?

#

this is p vague as theres plenty of problems you could come up with that involve double sums

obtuse pebbleBOT
#

@flat lance Has your question been resolved?

swift stream
#

Yeah, too vague

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That being said double summations are just like any other summation

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There is no need of anything that new. Other than switch the order of summation if it is more convenient, there are not that many tricks when it comes to double sums

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worn gazelle
#

How would i do this

obtuse pebbleBOT
worn gazelle
#

but using the mpmath python?

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I'm confused how to input the 1, 1/2 , 1/2 part

obtuse pebbleBOT
#

@worn gazelle Has your question been resolved?

obtuse pebbleBOT
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@worn gazelle Has your question been resolved?

obtuse pebbleBOT
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@worn gazelle Has your question been resolved?

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dull pilot
#

Any hint

obtuse pebbleBOT
dull pilot
#

How to Solve That inequality ?

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in place with heart i feel like i have problems

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with right

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estimaton

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i wanted to get

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to use

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but i feel lke it aint work

full cloud
#

Is your question the inequality at the beginning?

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@dull pilot

dull pilot
#

that's the questin

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and i wanted to use jensen

full cloud
#

I am pretty sure you can directly use AM-GM

warm shaleBOT
full cloud
#

@dull pilot hope that made sense

dull pilot
#

Thanks i will try using soon

obtuse pebbleBOT
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digital badger
obtuse pebbleBOT
digital badger
#

Is this right?

reef topaz
#

What is the problem about?

inland hill
#

Area?

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Oh volume lol

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I guess

digital badger
#

Yup

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So I have to find the surface area

reef topaz
#

Is it given that the base is a regular hexagon?\

digital badger
#

Yup

reef topaz
#

Right, so a regular hexagon is made out of 6 equilateral traingles

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You can use this information to find the base area

digital badger
#

I did but the answer key says smt diff

#

Their answer was 165.6mm

obtuse pebbleBOT
#

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brisk sedge
#

This is the work of a friend. Not sure if the answers are correct but I need someone to explain how to do them.

brisk sedge
#

<@&286206848099549185>

#

Someone save me please

serene crane
#

what are you confused about

#

which one?

brisk sedge
#

All of them

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tropic locust
#

Of the circled part, where did the right side of the equation come from?

tropic locust
#

<@&286206848099549185>

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fluid gulch
#

How do i do b

obtuse pebbleBOT
fluid gulch
tired shell
#

one way would be to subtract from (a) all the arrangements with BB next to each other yea

#

to help with that count how many ways you can place BB amongst the other 4 circles and count how many ways you can arrange ARER

fluid gulch
#

What would the together equation be

fluid gulch
#

Would the final answer be 60

tired shell
#

ummm I can check but it should look like 180-something for most ways of doing it

#

I get 120 doing 180-(ways to place the BB)(ways to arrange ARER)

fluid gulch
#

Isnt total 6! /2!x2!

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And together 5!

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So you subtract it then it would be 60

tired shell
#

oh by together you mean consider BB as one item? that's cool

#

you'd do 5!/2 because of the double R's still

fluid gulch
#

Oh ok

fluid gulch
#

I dont understand

tired shell
#

there's an idea called the pigeonhole principle that deals with this sort of guaranteeing something has at least n things

#

if n = km + 1 objects are distributed among m sets, the pigeonhole principle asserts that at least one of the sets will contain at least k + 1 objects.

steep pivot
#

Isn't it just 25?

#

Is there a minimum number of seeds a pigeon must get?

fluid gulch
#

Is it?

tired shell
#

nah you could do 7+7+7+4 like evenly distribute them

steep pivot
#

Oh, 'guarantee'

tired shell
#

you can really just think of the worst case scenario and add 1

fluid gulch
#

Huh

#

I dont get the question

steep pivot
#

Guarantee requires worst case, which is even distribution

tired shell
#

like if I hand out 1000 seeds some pigeon is going to have a lot

fluid gulch
#

Yea

#

So whats the answer?

#

Wait why wouldnt it be 25

tired shell
steep pivot
#

Worst case is even distribution, which would be 6+7+6+6 for 25

tired shell
#

it's asking about when there's no choice but for one bucket to have 25

steep pivot
#

Because of the word 'guarantee'

fluid gulch
#

So is the answer 6?

steep pivot
#

Why would the answer be 6?

fluid gulch
#

Wait what

#

What would the answer be

steep pivot
#

Maybe think less random, and more if some jerk was purposefully distributing your seeds so that none of the pigeons would be full

fluid gulch
#

Oh

#

So would the answer be 0

steep pivot
#

no?

tired shell
fluid gulch
#

Nah im lost

#

Does everyone need seeds

tired shell
#

the answer is close to 100 because that's when it's around 25 seeds per pigeon

fluid gulch
#

Ohhhhh

steep pivot
#

24+24+24+25

fluid gulch
#

I see

#

I get it now

#

Bc u dont need to do the full round back

steep pivot
#

(n-1)*(bins-1)+n

fluid gulch
#

I got you

#

Thx so much

#

.close

obtuse pebbleBOT
#
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obsidian oar
#

what equation represents the construction cost of a square based box with no top (open lid), where the cost to construct the base is double the cost to build the 4 sides

latent walrus
#

you tell me

obsidian oar
#

is it 4a + 2a...

latent walrus
#

technically sure, it probably wants it in terms of the box's dimensions though

obsidian oar
#

yeah my brain isnt working i cant figure it out.

#

ive labeled box height = y, length and width both = x

#

since square base

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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sudden frost
#

Alright let's hope I get the formatting right this time

sudden frost
#

Hey! I have an exact different equation here that I'm trying to solve but I'm getting stuck when it comes to integration constants (...yes, really.)

I need to find a solution for this:

$2 \frac{x}{y} dx + \left(1 - \frac{x^2}{y^2}\right) dy = 0$

#

Where x and y are non-zero. My step by step got me this far:

$2 \frac{x}{y} dx = - \left(1 - \frac{x^2}{y^2}\right) dy$

warm shaleBOT
sudden frost
#

$\text{Find } \phi(x, y) \text{ s.t. } \frac{\partial \phi}{\partial x} = \phi_x = 2\frac{x}{y}, \ \frac{\partial \phi}{\partial y} = \phi_y = 1 - \frac{x^2}{y^2}$

warm shaleBOT
sudden frost
#

$\phi = \int \phi_x dx = \int 2 \frac{x}{y} dx = \int \phi_y dy = \int 1 - \frac{x^2}{y^2} dy$

warm shaleBOT
sudden frost
#

$\phi = \frac{x^2}{y} + g(y) = y + \frac{x^2}{y} + h(x)$

warm shaleBOT
sudden frost
#

$g(y) = y + h(x)$

warm shaleBOT
sudden frost
#

And then I got stuck. The expected answer is $\phi(x, y) = y + \frac{x^2}{y} + K$ where K is a constant. What I don't understand, however, is how on earth g(y) and h(x) became K. Can anyone enlighten me please?
From my understanding, both g(y) and h(x) are functions, not necessarily constants

warm shaleBOT
sudden frost
#

last message is actually the first message. sorry for that, \\ doesnt seem to break latex into different lines and I had to fix the first msg.

#

ah, i figured it out!
well, since phi of (x, y) can be found by integrating either partial derivative, we can stick to a single one

#

.close

obtuse pebbleBOT
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proven cape
#

7 and 8 please

obtuse pebbleBOT
wary badger
#

what have you tried

#

are you familiar with separation of variables

proven cape
#

I tried 100=something

wary badger
#

what

#

8 looks good

proven cape
#

oh 6 and 7, sorry

wary badger
#

using the initial condition after you integrate

#

to find an equation for y

#

the amount of grams

#

then t=1 hour

proven cape
#

y=Ce^(-0.6t)

#

C=100, t=1

#

so 7

#

V=Ce^([-1/40]t)?

#

ok so V=(1/10)Y sub 0

#

it is 9/10 sorry

#

ok it is done

#

.close

obtuse pebbleBOT
#
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proven cape
#

Thanks @wary badger for help with 7

obtuse pebbleBOT
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empty mantle
#

Determine the value(s) of the local extrema you identified in the previous step. Write DNE for all extrema that do not exist. Separate multiple answers with a comma, if necessary.

empty mantle
#

i dont even know what the hell this is

#

the asnwer box is "local minimum values" and "local maximum values"

civic socket
empty mantle
#

yes but that doesnt help me

#

i know what they are but what does it mean values

civic socket
#

you need to choose the highest number and the lowest

#

in the graph

empty mantle
#

ive done that, like the x value that they are at and it said they were wrong

high lily
#

for the min/max values they want the y value

empty mantle
#

so thats what it means by the value

#

just the y

#

okay that was correct

#

thanks

#

.close

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#
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ember frost
#

Given a regular cyclic polygon with 20 sides. Calculate how many trapezoids (US) can be constructed whose vertices are of the cyclic polygon.

ember frost
#

if it were asking how many trapeziums (US), its easy, there would be 20C4 trapeziums (US)

#

but im stumped on how to eliminate non-trapezoids (US)

obtuse pebbleBOT
#

@ember frost Has your question been resolved?

ember frost
#

<@&286206848099549185>

ember frost
#

trapezoid has different definition in the US and the UK

#

so i added that to avoid ambiguity

#

trapezoid US is trapezium UK, and trapezium US is trapezoid UK

versed stratus
#

hmm, so a quad with one pair of sides parallel?

ember frost
#

yea

versed stratus
#

hmm

#

find the set of points parallel to each otehr I guess

#

each pair of two points will have one anothe pair parallel to it

ember frost
versed stratus
#

hmm

#

for any two points you join, there will exist a side parallel to it

#

so they are c(20,2) such shapes

#

,w c(20,4)-c(20,2)

versed stratus
ember frost
ember frost
#

shouldnt it be C(10, 2)?

versed stratus
#

oh yeah

#

right

obtuse pebbleBOT
#

@ember frost Has your question been resolved?

obtuse pebbleBOT
#
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#
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next slate
#

Hi there I am having trouble with this question, could I please get some help on it? Cheers!

next slate
#

I tried equating the left and right of -1, getting 1/2 as an answer but that was not correct

next slate
#

-6x-3/36x^2-9 = x+a

#

and calculating for a when x=-1/2

fierce elbow
#

for the function to be continuous

#

THe left hand limit should be equal to the right hand limit

#

not the functions itself

#

LHL = RHL

next slate
#

ahh okay let me have a look

#

Just wanted to ask one thing since were on the topic.

#

For this one I equated x^3+7/x^2+1 = bcos 3(x-2) and got it right

#

All I did was substitute 2

next slate
# next slate

So I thought it would be the same here for this qn?

next slate
obtuse pebbleBOT
#

@next slate Has your question been resolved?

ember frost
#

left hand limit = right hand limit = function value at that point

fierce elbow
#

oh I didnt mention the function value

#

mb

obtuse pebbleBOT
#
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tawdry pewter
obtuse pebbleBOT
tawdry pewter
#

bruh no idea

#

how to differentiate this

green epoch
#

product rule

obtuse pebbleBOT
#

@tawdry pewter Has your question been resolved?

obtuse pebbleBOT
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untold mirage
#

$$\frac{\left(\left(x\cos\left(R_{97}\right)-y\sin\left(R_{97}\right)\right)-c_{97}\right)^{2}}{z_{97}}+\frac{\left(\left(x\sin\left(R_{97}\right)-y\cos\left(R_{97}\right)\right)-d_{97}\right)^{2}}{z_{97}}=r_{97}^{2}$$

warm shaleBOT
#

Ayayon

untold mirage
#

Hi, im using this equation to create a circle and to be able to move it around

#

i am also able to dialate it to make a ellipse

#

but im not sure how i can rotate the ellipse (preferebly at its centre point)

obtuse pebbleBOT
#

@untold mirage Has your question been resolved?

untold mirage
#

this is in desmos btw

untold mirage
#

<@&286206848099549185>

obtuse pebbleBOT
#

@untold mirage Has your question been resolved?

untold mirage
#

<@&286206848099549185>

obtuse pebbleBOT
#

@untold mirage Has your question been resolved?

untold mirage
#

<@&286206848099549185>

cinder basalt
#

rotate towards what direction

brazen viper
untold mirage
cinder basalt
#

nevermind it was in 2D plane

untold mirage
#

how abbout translating it then?

brazen viper
untold mirage
#

cant seem to copy it properly?

brazen viper
#

Because it's typeset with mathml, just retype it

untold mirage
cinder basalt
#

okay maybe not

#

I don't know why it rotates counterclockwise

#

my bad

#

i mean

#

counterclockwise

#

fkwaokfo

#

clockwise*

#

nevermind

#

its ok

#

positive t --> clockwise

#

negative t --> counterclockwise

#

just change this bounds

untold mirage
#

okay

cinder basalt
#

ok to be honest i dont know why it rotates clockwise

cinder basalt
#

oh the problem is that f(x) = y is not f(X) = Y

#

ok still it works going backwards

obtuse pebbleBOT
#

@untold mirage Has your question been resolved?

#
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obtuse pebbleBOT
#
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timid silo
#

Hello

obtuse pebbleBOT
paper dome
#

YO

#

Whatsyourquestion

timid silo
#

I have some math questions I need help with. I just got into a uni and I'm lost,can I send photos here?

#

I'll send It here, wait a seconr

#

If 10^2x = 25, then 10^-x is equal to:

#

Simplify the expression
Simplify the expression

#

I'd like help in these three questions

#

Someone there? 😭

latent walrus
#

hello

#

any ideas for 6

hexed gull
#

you can start modifying the exponent

#

eg. by taking (...)^(1/2) on both sides

timid silo
#

I dont get It...

hexed gull
timid silo
#

The teacher gave these questions to us study potentiation

hexed gull
#

thereby we got rid of the 2

#

now we can do the same again for the -

#

(...)^-1

timid silo
#

Its not 25

hexed gull
hexed gull
timid silo
#

I'm terrible at math Man

hexed gull
#

I'm certain the above the right

#

are the steps in the images somewhat clear?

timid silo
#

They are

#

So

#

So It is basically a association? It doesnt mean that the value is literally that?

hexed gull
#

10^2x = 25

#

x is a variable

#

so we don't know its value yet

timid silo
#

But 10^2=100

#

Does It mean the x change the end result?

hexed gull
#

ofc 10² = 100, x changes the value

#

10^(2x), if x = 2 for example, then it's 10^(2*2) = 10^4 = 10000

timid silo
#

Oh, i finally got it

#

Só I need to find the value of 10^-x using 10^2x?

#

But How do I do It?

#

And why do i use 1/2

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

#
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obtuse pebbleBOT
#
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ruby elm
obtuse pebbleBOT
ruby elm
#

.close

obtuse pebbleBOT
#
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cerulean sapphire
#

The information given here is that the distance between AC is the same as the circles radius. We're supposed to decide what the angle v is. I have been stuck on this issue since I am not quite sure how to proceed with the problem.

wispy wadi
#

They give AC = radius so you know what kind of triangle MAC is

cerulean sapphire
#

.close

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#
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forest coyote
#

how can i prove this series is convergent?

obtuse pebbleBOT
forest coyote
#

[\sum \frac{(n+1)!n!}{4^n}]

warm shaleBOT
#

diiegorgueez

worn yoke
#

ratio test is a good place to start

wispy wadi
#

(n+1)!n! > 4^n for n >= 3

#

can't be convergent

obtuse pebbleBOT
#

@forest coyote Has your question been resolved?

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#
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ionic shore
#

hey

obtuse pebbleBOT
ionic shore
#

when we use newtons method

civic socket
#

what about it

#

do you have a question about it

ionic shore
#

nah

#

i just want to understand the science behind newtonsm ethods

ionic shore
#

if I could have understand from that
why would then I ask on discord

#

whats newtons method for you

#

what or how can you describe it

civic socket
#

using py

#

In numerical analysis, Newton's method, also known as the Newton–Raphson method, named after Isaac Newton and Joseph Raphson, is a root-finding algorithm which produces successively better approximations to the roots (or zeroes) of a real-valued function. The most basic version starts with a real-valued function f, its derivative f′, and an ini...

ionic shore
#

wait a second

#

you got and solve newtons method using programming

#

that so amazing

#

how you do that

civic socket
#

if you are good at py, you can get used to it

ionic shore
#

i know py

civic socket
#

ok then you should be fine

ionic shore
#

been making games using it
(lmodule -pygame)

civic socket
#

ill provide you an example, hold on

ionic shore
#

dude
i got newtons matheod but for what reason should i use

#

it

ionic shore
subtle sinew
civic socket
# ionic shore ok
def f(x):             
  return x**3 - 5   # f(x) = x^3 - 5

def f_prime(x):
  return 3*x**2     # f'(x) = 3x^2
# define the newtons method here
def newtons_method(x0, f, f_prime, tolerance=1e-6, max_iterations=100):
  for _ in range(max_iterations):
      y = f(x0)
      yprime = f_prime(x0)
      if abs(yprime) < tolerance:       
          break
      x1 = x0 - y / yprime            
      if abs(x1 - x0) <= tolerance:   
          return x1                   
      x0 = x1                         
  return None                         

# here's an example
initial_guess = 2 
root = newtons_method(initial_guess, f, f_prime)
print("Approximate root:", root)
obtuse pebbleBOT
#

@ionic shore Has your question been resolved?

ionic shore
civic socket
ionic shore
#

Ok

#

So it’s an inbuilt function

civic socket
#

yep

ionic shore
#

And y prime is the differencial

#

Dude
You are a genius

#

.close

obtuse pebbleBOT
#
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summer pond
obtuse pebbleBOT
summer pond
#

Can I get any help to get started? Im not sure what it is asking 🥲

safe haven
#

,rccw

warm shaleBOT
smoky hound
obtuse pebbleBOT
#

@summer pond Has your question been resolved?

smoky hound
#

they give u really nice numbers to work with here. i would try making fractions with units and see where u get from there

summer pond
#

Alright!

#

thank you!

obtuse pebbleBOT
#
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formal turtle
#

Could I walk through part a with a helper?

obtuse pebbleBOT
#

@formal turtle Has your question been resolved?

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wispy canyon
#

How does one find the decimal answers to 6cos(x)+9=7 in the interval of [0,2pi)

wispy canyon
#

I got to cos(x) = -2/6 but that’s where I’m stuck

brisk matrix
#

have you heard of arccos

wispy canyon
#

Yes

#

Do you have to reference the properties?

brisk matrix
#

what do you mean

wispy canyon
#

Like do I have to reference arccos(cos(x))

#

Or am i going on a tangent rn

brisk matrix
#

well the idea is x = arccos(-2/6) and x = 2pi - arccos(-2/6)

#

those are the only two possible answers between 0 and 2pi

wispy canyon
#

You lost me

brisk matrix
#

can you tell me what arccos(0) is

wispy canyon
#

Arccos of 0 is 1 right?

brisk matrix
#

no

#

arccos(1) is 0, but not the other way around

wispy canyon
#

Then I’m not sure

brisk matrix
#

do you know what arccos(0) means

wispy canyon
#

Wait is the 0 a reference to the range?

brisk matrix
#

neither

#

do you know what arccos(0) means

wispy canyon
#

Shoot

#

No, I don’t then

brisk matrix
#

it should return an angle on the unit circle where cos(that angle) = 0

#

can you look at the unit circle and give me an angle that does that

wispy canyon
#

And angle that gives 0 would be pi/2 then

brisk matrix
#

yes, but there is also another

wispy canyon
#

Oh

#

Pi/2 and 3pi/2

brisk matrix
#

yes, but you could also say 5pi/2

#

and 7pi/2

#

and -pi/2

#

and so on

wispy canyon
#

Ok

brisk matrix
#

the idea now is that arccos gives you an angle specifically between 0 and pi

#

so out of all the options

#

arccos(0) = pi/2

wispy canyon
#

Ok ok

brisk matrix
#

but if we want to find every solution to cos(x) = 0 between 0 and 2pi

#

we need to also include 3pi/2

wispy canyon
#

Right

brisk matrix
#

the way to do this is to count
arccos(0) = pi/2, and 2pi - arccos(0) = 3pi/2

wispy canyon
#

Ah ok

brisk matrix
#

in general you'd do arccos(whatever) and 2pi-arccos(whatever)

wispy canyon
#

Ok

brisk matrix
#

and that will give you all the solutions between [0,2pi]

wispy canyon
#

Ok

#

I got that

#

Im just not understanding the problem I guess

#

Because I tried what you explained to me and I still haven’t gotten the right answer

#

At least I don’t think I did

obtuse pebbleBOT
#

@wispy canyon Has your question been resolved?

wispy canyon
#

How does one find the decimal answers to 6cos(x)+9=7 in the interval of [0,2pi)

#

.close

obtuse pebbleBOT
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vague isle
#

why dr/dt = dr/ds ds/dt ?

obtuse pebbleBOT
vague isle
#

it's the chain rule, but applied to what?
is r a function of s ?

civic socket
#

does dt represents time, dr represents velocity and ds the speed?

#

also they've used the chain rule

#

without seeing the full question whatsoever asking I think they wanted derivative of speed which is ds/dt

vague isle
#

dt time
dr is the position of the point along a curve
ds is the length of the displacement along the curve

#

my question is
why dr/dt = dr/ds ds/dt ?

civic socket
#

chain rule

vague isle
#

yes it's what i've said above

#

but, what am i chaining?

obtuse pebbleBOT
#

@vague isle Has your question been resolved?

obtuse pebbleBOT
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@vague isle Has your question been resolved?

vague isle
#

.close

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.close

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random quiver
#

how do I solve this: (x+3)/(x^2sqrt(2x+3))

obtuse pebbleBOT
fallow cove
#

cuz we can't solve that if we don't have a = sign

random quiver
#

srry i meant integrate it

fallow cove
#

ahh

teal turret
#

$\int \frac {x+3}{x^2\sqrt {2x+3}}$

warm shaleBOT
#

Stephen

teal turret
#

$\int \frac {0.5 (\frac {u-3}{2} + 3)}{\sqrt{u} \cdot (\frac {u-3}{2})^2}$

fallow cove
warm shaleBOT
#

Stephen

teal turret
#

maybe that doesnt help

fallow cove
#

or subbing u=sqrt(2x+3)?

teal turret
#

oh yea perhaps

fallow cove
#

I don't have a pen and pencil rn

#

And also @random quiver here's a tip

#

If you are integrating something that has a square root, there is a high percentage that u-sub is needed and you u-sub the square root

random quiver
#

yeah i did that and then i could split the integral and the first part was easy but im stuck on the second part

#

$\int \frac {dt}{{(t^2 -3)}^2}$

warm shaleBOT
#

ouwedouwe

random quiver
#

this

fallow cove
#

Huh so you got this?

random quiver
#

12 times that and also another integral I already solved

granite dragon
#

The working out is SUPER long

fallow cove
random quiver
random quiver
fallow cove
#

Partial fractions maybe?

random quiver
#

yeah im doing that now

#

I did sub with u and v and now I have 2 integrals and for the second one i have to do partial fractions

fallow cove
#

Cool

obtuse pebbleBOT
#

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summer cliff
#

can someone tell me the answer

obtuse pebbleBOT
minor belfry
#

try first

summer cliff
#

I did

#

I need to confirm

teal turret
#

tell us what u got

#

@summer cliff

summer cliff
#

I got 6^5 but I dont think its correct

#

@teal turret

high lily
#

can you show your work

summer cliff
#

@high lily

high lily
#

you're misapplying the relationship between radicals and exponents

#

$\cbrt{x} = x^{\frac13} \redneq (\sqrt{x})^{\frac13}$

warm shaleBOT
#

ℝαμΩℕωⅤ

summer cliff
#

ohhh

#

Let me retry it

#

@high lily this time I got 6

teal turret
#

yea

obtuse pebbleBOT
#

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fleet stag
obtuse pebbleBOT
fleet stag
#

I don’t know how to do 10 b

#

I subbed in got an equation and don’t know what to do from there

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violet compass
#

what software is best for drawing figures for a dissertation paper?

kind hawk
#

well depends on the figures

#

but shouldnt really matter too much. use software that you can use

violet compass
#

i see.

#

.close

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fossil crag
#

just saw this <@&268886789983436800> jic they're not banned yet

last pilot
#

been going on for like 20 mins

#

they opened two separate channels; pinged mods in both. no response

warm canopy
#

Only blues are online rn so we can't ban

#

They're muted but we have to hunt down the links

#

And I'm on mobile sadcat

last pilot
#

wait what?

#

blues can't ban??

fossil crag
#

If there's not enough mods I could be one but sometimes not that active

last pilot
#

ERIC

warm canopy
#

Ty eric

last pilot
#

OUR SAVIOR

#

yu

fossil crag
last pilot
#

*ty

obtuse pebbleBOT
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cerulean maple
obtuse pebbleBOT
cerulean maple
#

How do I do the

#

This

#

Ignore my working out

balmy cosmos
#

x will be 1.6

#

you got 2 rectangles which are mathematically equivalent right?

cerulean maple
#

I think

balmy cosmos
#

well you first need to know what they are tellin you

#

im not gonna know

cerulean maple
#

But like how do I write the working bc my teacher will kill me

#

1.6 is correc

balmy cosmos
#

im gonna tell you how

#

so first you need to bring down the problem to 2 separate rectangles, and it will be easier if you draw them one next to the other

#

in the same position

#

one rectangle, the biggger one is 10x4

#

10 on base, 4 tall

#

right?

cerulean maple
#

Yep

balmy cosmos
#

the other one, in the same position, with base 4 and x tall ,right?

#

next to it

cerulean maple
#

It’s 4 tall and base x

#

I think

balmy cosmos
#

no

#

i want you to extract it

#

i know that in the image is 4 tall

#

but i want you to extract it, and imagine it or draw it with base 4, meaning, rotate it

cerulean maple
#

Got it

balmy cosmos
#

so its EQUIVALENT to the other one. This way its easier for you to see it

#

okay, when 2 rectangles are equivalent

#

usually, they are not the same size

#

but there are certain RATIOS

#

that hold between them

cerulean maple
#

Like the scale factor

balmy cosmos
#

in this case

#

the scale will be the same

#

meaning that 10/4 will be equal to 4/x

#

the RATIOS

#

hold

#

now there you have it

#

10/4 = 4/x

cerulean maple
#

Kk

#

Tysm

balmy cosmos
#

keep it upo

obtuse pebbleBOT
#

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obtuse pebbleBOT
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urban kiln
obtuse pebbleBOT
urban kiln
#

here's my attempt^

#

i did get m=c=0 and a=b but im unable to find what a or b is equal to

#

<@&286206848099549185>

#

bruh

torpid pasture
#

try sin²x=(1-cos(2x))/2

wintry swift
#

you need to find a and b such that $\lim_{x\rightarrow 0^{-}}(\frac{a-b \cdot cos(2x)}{x^2})=2$

warm shaleBOT
torpid pasture
#

Since you got a=b, this means (a-bcos(2x))/x² is actually a 0/0 form which is supposed to equal to 2 on the right hand side

wintry swift
torpid pasture
#

true its circular logic

urban kiln
#

oh wait i got my mstk

#

tysm yall

#

.close

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rotund kite
#

In a simple random sample of 70 automobiles registered in a certain state, 24.00 of them were found to have emission levels that exceed a state standard.

Find a 95% confidence interval for the proportion of automobiles in the state whose emission levels exceed the standard. (Round the final answers to three decimal places.)

The 95% confidence interval is ( , ).

rotund kite
#

I got 0.232 and 0.454, and I do not understand why it is wrong, I also tried a few other answers I got including 0.2335, 0.4660. Still not right. I can't seem to get any of these confidence intervals right no matter what I do, including through chegg, calculators, or ai lol.

#

my calculations being

p= 24/70
n=70
z=1.96 (for 95%)
SE = 0.0567
ME= 0.111132

So then applying the Margin Of Error to my sample proportion it is 24/70 ± 0.111132 = 0.231657 (Rounded to 0.232), 0.454057 (Rounded to 0.454)

obtuse pebbleBOT
#

@rotund kite Has your question been resolved?

rotund kite
#

I also checked with my friend who's done engineering stats before and they with a calculator got the same exact answer so idk

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rotund kite
#

.reopen

obtuse pebbleBOT
#

twin sandal
rotund kite
#

I emailed him basically what I put here n hopes he looks at it lol

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#

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timid silo
#

.reopen

rotund kite
obtuse pebbleBOT
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steep cloak
#

So I need help with this task

obtuse pebbleBOT
steep cloak
#

So I know about the binomial coefficient but I have tried many times and didn't get the correct result.
(I have an answer sheet but unfortunately it has no calculation method) The answer for 1) should be ||7.4%|| and for 2) it should be ||30.02%||
Thank you in advance!

#

<@&286206848099549185>

#

<@&286206848099549185> happyb

tired shell
#

for 1) what's the probability for the first digit being a letter? multiply that by itself 8 times
for 2) you need to add to 1) the chance of exactly 1 digit for that you can do:
(ways to place the single digit in 8 slots)*(chance of digit)*(chance of letter)^7

obtuse pebbleBOT
#

@steep cloak Has your question been resolved?

steep cloak
tired shell
#

👍 correct

steep cloak
#

Thank you so much! :D happy

#

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hardy pike
obtuse pebbleBOT
hardy pike
#

i have this, i dont know how to do with a ordered pair. I end with the same.

queen briar
#

f(g(x)) is wrong

#

you have to replace all Xs in f(x) with $\sqrt{x}$

warm shaleBOT
#

dqvidutzul

hardy pike
#

the question say whenever its possible, how can i compose the codomain R x R with N?

obtuse pebbleBOT
#

@hardy pike Has your question been resolved?

obtuse pebbleBOT
#

@hardy pike Has your question been resolved?

obtuse pebbleBOT
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@hardy pike Has your question been resolved?

obtuse pebbleBOT
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@hardy pike Has your question been resolved?

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hollow island
#

Consider a digit sequence, an infinite list of digits between 0-9. The 'sequence product' is calculated by multiplying the corresponding entries of each sequence and adding them up. For example, if you had a_i=1234500000...... and b_i=678900000......, then the sequence product would be a_i*b_i which will be 1 x 6 + 2 x 7 + 3 x 8 +4 x 9 + 5 x 0 + 0 x 0 + 0 x 0 +.... = 6+14+24+36=80. If the sequence product of two digit sequences is 2024, is there anything that we can say about either of them?

tired shell
drifting wraith
#

we can say there's 25+ non zeroes

hollow island
hollow island
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#

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covert palm
#

Hello i have a trigonometry question

obtuse pebbleBOT
covert palm
#

Revising for GCSE