help-10

[halcyon horizon]

i came across this when i was working on some ai stuff

[oak plover]

You can get constants out of derivative actions

[halcyon horizon]

ah ok

[oak plover]

Do you know how derivatives work

Or do you just want an answer

[halcyon horizon]

I know how regular derivatives work

not how partials work

[oak plover]

They are similar

Just everything else is a constant except for the variable

[halcyon horizon]

ah ok

so most of the things will just kinda get removed from the derivative?

[oak plover]

Not really

What is U and b

[halcyon horizon]

they're separate

none of the variables are related to each other by anything other than that equation

[oak plover]

Then just plug in y hat

[halcyon horizon]

ok

[oak plover]

The rest will act like a normal derivative

[halcyon horizon]

so the +c part will just disappear?

[oak plover]

Yes

[halcyon horizon]

ok give me a minute let me work it out

so im getting -2Uxy(sech^2(Wx+b)) for the first part

like -2y y hat part

.close

[obtuse pebble]

Channel closed

Closed by @halcyon horizon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[magic geyser]

yo

[magic geyser]

can someone explain this to me

x is 20 because log 6 is same

but how did they get that equation

nvm its just one of the rules

.close

[obtuse pebble]

Channel closed

Closed by @magic geyser

Use .reopen if this was a mistake.

[magic geyser]

!close

.close

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty trench]

this is as far as i can get

in ax+bx+c=0 idk what a is and what b is, or how to get them

<@&286206848099549185>

can anyone perchance tell me what a, b and c represent so i can try to solve?

[fathom tapir]

I can help you with that

y = mx + q is your typical formula

move everything to lhs

y - mx - q = 0

[lofty trench]

whats lhs?

[fathom tapir]

left side

of the equals sign

[lofty trench]

yeah but what about ax+bx+c=0

[fathom tapir]

rearrange as follows

-mx + y - q = 0

compare with ax+by+c = 0

a = -m , b = 1 , c = -q

so if you can solve using mx+q you can move to the ax+by+c form

[lofty trench]

this is all i know how to do (with derivatives)

so idk what q is 😭

[fathom tapir]

oh sorry q is c

I'm used to calling it q

[lofty trench]

oh ok

[fathom tapir]

it's the term with no x or y

[lofty trench]

ok lemme try rq

[fathom tapir]

aight

[lofty trench]

ok so now what?

[fathom tapir]

hold on

I haven't done this in a while

but I think it should be:

[lofty trench]

take ur time

[fathom tapir]

find the derivative of the function

y = 2x^2
y' = 4x

gradient = y'(2) = 8
gradient for normal = -1/y' = -1/8

formula for line:

y - py = -1/8 (x - px)

px = 1
py = 2

y - 2 = -1/8 (x - 1)

y = -1/8x +(-1/8+2)

using previous identity:

a = -m , b = 1 , c = -q

a = 1/8 b = 1 c = -(1/8+2) which is 9/8). so the solution should be 1/8x+y+9/8=0

can you verify it's correct? I'm a bit rusty

[lofty trench]

what does y' mean

[fathom tapir]

y' is the derivative of the the function

[lofty trench]

im afraid it isnt 😦

[fathom tapir]

hold on let me double check

oh

I'm silly

I think I found it

find the derivative of the function

y = 2x^2
y' = 4x

gradient = y'(1 (not 2) ) = 4
gradient for normal = -1/y' = -1/4

formula for line:

y - py = -1/4 (x - px)

px = 1
py = 2

y - 2 = -1/4 (x - 1)

y = -1/4x +1/4+2 = y = -1/4x + 9/4

using previous identity:

a = -m , b = 1 , c = -q

a = 1/4 b = 1 c = -9/4 -> 1/4x+y-9/4 = 0 multiply everything by 4 to make it look cleaner = x+4y-9 = 0

[lofty trench]

oohh

now i get it

thanks bro

.close

[obtuse pebble]

Channel closed

Closed by @lofty trench

Use .reopen if this was a mistake.

[fathom tapir]

you welcome haha

[fathom tapir]

probably there's a faster way but I only remember these formulas

so like solving without using the y = mx +c form

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton oar]

could someone please explain this q to me, Im stuck on what to do

if I had to guess it would be (0.8+0.06)/2 but Idk how to explain it in the proper way

[obtuse pebble]

@wanton oar Has your question been resolved?

[obtuse pebble]

@wanton oar Has your question been resolved?

[drifting wraith]

there are 2 ways this can happen

1. they have it and the test is right

2. they dont have it and the test is wrong

you find probabilities and add

please do the guessing again, with this new knowledge

[wanton oar]

I think you meant test is right

[drifting wraith]

i meant test is wrong

[wanton oar]

so like I have, I should just add? like 0.8*0.1 + 0.06*0.9

[drifting wraith]

that's perfect

[wanton oar]

okay cool

[obtuse pebble]

@wanton oar Has your question been resolved?

Channel closed

Closed by @wanton oar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dawn bane]

Unsure of where to start for this particular problem?

[plain stag]

drawing it is usually a safe start

[plain stag]

this is pretty improper

[dawn bane]

Yeah I got a little lazy, let me try and fix it

(I might've drawn it wrong again, I'm terrible at visualizing these things and for some reason it's throwing me off rn)

[plain stag]

why have you written "v=4"?

[dawn bane]

Oh, I forgot to write it as specifically magnitude of v = 4

Fixed it

[plain stag]

you should probably write that properly

now what does "magnitude of v = 4" mean graphically?

[dawn bane]

The size of the vector itself?

[plain stag]

on your graph specifically

that's the physical interpretation of magnitude in general

[dawn bane]

I don't believe I understand the question, sorry. On my graph specifically I would assume it means the size of the vector that I drew, which is 4.

[plain stag]

what does "size of the vector" mean?

please indicate on your graph exactly how you're illustrating the magnitude of the vector

[dawn bane]

The length of the vector?

[plain stag]

ok now we're getting somewhere

what you've illustrated is the magnitude (which means size or length, so you can stop repeating those) of the x-component of the vector, not the vector itself

[obtuse pebble]

@dawn bane Has your question been resolved?

Channel closed

Closed by @dawn bane

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[undone halo]

Hello!

[undone halo]

Can anyone give me a run down of how to solve special right triangles?

Im in geometry and doing a trig unit right now. But I dont really understand how to solve them

pls ping me when you respond btw

[humble wave]

it would be more helpful if you described the problem first

[undone halo]

sure

let me get a screen shot!

something like this

[urban lichen]

ok

so

in a 30-60-90 triangle

[undone halo]

btw, can you also explain a 45 90 45 when your done?

[urban lichen]

alright

[undone halo]

thank you

[urban lichen]

say the shorter leg of a 30-60-90 triangle is x

[undone halo]

yeah

[urban lichen]

the longer leg is $x \sqrt{3}$ and the hypotenuse is $2x$

[warm shale]

Gamer Sans The Gamer Skeleton

[urban lichen]

in a 45-90-45

the leg (both legs are same size) is $x$, and the hypotenuse is (by pythag) $x \sqrt{2}$

[warm shale]

Gamer Sans The Gamer Skeleton

[undone halo]

wait so how would you solve them after that?

[urban lichen]

what do you mean

[undone halo]

for this one, how did they get 11 for x and 11 square toot of 3 for y?

[urban lichen]

$x$ is the shorter leg

since (by the ratio) $2x = 22$ (the hypotenuse), $x = 11$

same goes for $y$

[warm shale]

Gamer Sans The Gamer Skeleton

[undone halo]

ohhh

im kind of getting it

Do you know anywhere where I can get practice problems for this subject?

[urban lichen]

uhhhhhh
not exactly

just kinda stick it in your head

[undone halo]

wait

so for the 45 90 45

actually let me send a screen shot

so both of the legs would be 10 square root of 2 right?

[urban lichen]

yep

sorry for being late

[undone halo]

wait so what would that be

like in a whole number form

and no problem lol

or how would i figure that out

[urban lichen]

wdym by whole number form

[undone halo]

dont you have to solve that

[urban lichen]

no
you only have to solve for x which is $10 \sqrt{2} \cdot \sqrt{2} = 10(2) = 20$

[warm shale]

Gamer Sans The Gamer Skeleton

[undone halo]

ohhh

[urban lichen]

by the formula ofc

[undone halo]

so for 45 90 45

what if the current x was a number and one of the other sides was x?

like this kinda

btw thx for the help :)

have a math test tomorrow and needed last minute help lol

[urban lichen]

if the hypotenuse was a set value, then the leg would (taking the ratio opposite way) $\frac{x}{\sqrt{2}}$

[warm shale]

Gamer Sans The Gamer Skeleton

[urban lichen]

the hypotenuse is x there sorry for confusion

and np

[undone halo]

no problem!

so if the hypotenuse was 16

i would do 16/square root 2

[urban lichen]

the leg would be $\frac{16}{\sqrt{2}} = 8 \sqrt{2}$

pretty much

[warm shale]

Gamer Sans The Gamer Skeleton

[undone halo]

wait so without a calculator how would I solve that? Just divide 16 by 2?

[urban lichen]

here's something better:

$\frac{x}{\sqrt{2}} = \frac{x \sqrt{2}}{2}$ is better

[warm shale]

Gamer Sans The Gamer Skeleton

[undone halo]

wait so how would I solve that? Srry lol. Would I just do 16 square root 2 divided by 2?

[urban lichen]

yeah

more like $\frac{16}{2} \sqrt{2}$ (by taking the root 2 out of the numerator)

[warm shale]

Gamer Sans The Gamer Skeleton

[undone halo]

so I would divide 16 by two and find the square root of 8?

[urban lichen]

divide 16 by 2

multiply that by square root of 2

thats it

[undone halo]

and the square root of 2 is just 2 right?

[urban lichen]

how is $\sqrt{2} = 2$?

by definition that means $2 \cdot 2 = 2$ XD

[warm shale]

Gamer Sans The Gamer Skeleton

[undone halo]

ok lol

let me practice for one more and see if i get it right

so for this one

hmmm

[urban lichen]

its a little more complicated here

[undone halo]

wait so what would I do?

[urban lichen]

so
$x$ is the number we depend on
by the ratio (1 : sqrt(3) : 2), $15 = x \sqrt{3}$

$x = 5\sqrt{3}$

[warm shale]

Gamer Sans The Gamer Skeleton

[urban lichen]

texit formatting

[undone halo]

💀

can you explain that in a bit simpler forms lol

[urban lichen]

alright

the ratio between shorter leg : longer leg : hypotenuse is
1 : sqrt(3) : 2

15 would be the longer leg
so x would be 15/sqrt(3)

which (by some quick calculations) is 5sqrt(3)

we know x is 5sqrt(3)

by the ratio, y is double that
so y is 10sqrt(3)

ya getting it?

[undone halo]

ohhh mostly lol

let me get one more problem to practice with lol

so this one

the hypotenuse is 16

so I would do 16 (sqrt) 2?

[urban lichen]

16 divided by sqrt(2)

dont forget

which is 8sqrt(2)

[undone halo]

wait why is it divided again?

[urban lichen]

1. the hypotenuse is the longest side of a right triangle
2. the ratio from leg to hypotenuse is 1 : sqrt(2)

[undone halo]

ohhh ok

so one I have 8 sqrt(2)

that is x?

[urban lichen]

yep

[undone halo]

oh ok

thank you for the help!

have a great rest of your day / night!

i think the command is .close

.close

[obtuse pebble]

Channel closed

Closed by @undone halo

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting wraith]

um

why does it look like a challenge

problem of the week?

how does it take a week

the circle is 9 times larger

it means the circumference is 3 times larger

[obtuse pebble]

@unborn stream Has your question been resolved?

Channel closed

Closed by @unborn stream

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lethal ice]

i think i know the formula but im not sure how to use it

[lethal ice]

i thought it was just (1/35)(integral from 0 to 5 integral from 0 to 7 of 5e^y sqrt(x+e^y) dx dy)

@me if you reply cuz im doing other problems tysmmm

[stable hill]

you may want to switch order of integration

its easier if you do y first

@lethal ice

[lethal ice]

but is the setup right?

[stable hill]

yeah it looks good

[lethal ice]

oh ok thanks

[lethal ice]

ill do that, i always have a hard time knowing which to do first

[stable hill]

generally if the first order doesnt work, try the other one lol

[lethal ice]

Lol

thats real

thanks

.close

[obtuse pebble]

Channel closed

Closed by @lethal ice

Use .reopen if this was a mistake.

[stable hill]

youre welcome

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lethal ice]

not sure what part 2 is asking

[lethal ice]

also why is 3 wrong?

[latent walrus]

D will be a function of x

[lethal ice]

ohoh

-5x/6 +1/2

and part 2 is the same but with x coming first and H being a function of y?

but x is a straight line

or maybe not wait

im not sure

[latent walrus]

i believe H will be the function still yes, in terms of y

[lethal ice]

should i use the y = -5x/6 +1/2 and solve for x?

[latent walrus]

can do

[lethal ice]

i tried that but it said it was wrong

[latent walrus]

perhaps try putting it for G

[lethal ice]

sorry i shouldve clarified

everything is correct except H

[latent walrus]

ahh

okay give me a mo, been a while since i did this stuff

[lethal ice]

youre ok no worriesss

i have another question after this one it's a lot easier i just forget how to set it up

[latent walrus]

might be able to just use this but swap x and y

unless im tripping

[lethal ice]

ill try it one sec it loads

nah

i also tried just using the exact same equation lol

[latent walrus]

think im going out on a limb here

but maybe x=-6y/5+3/5

[lethal ice]

i tried that it was my first guess

my computer has 6% i have to return to my room ill be back in a moment

we can abandon this question

[latent walrus]

oh dear oh dear

[lethal ice]

g1 was wrong, can you help me find out why?

[obtuse pebble]

@lethal ice Has your question been resolved?

Channel closed

Closed by @lethal ice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[merry jetty]

how does a second order derivative give us the concavity

[merry jetty]

how does it work

[ruby path]

look at the slopes of the tangent lines

[twin sandal]

second derivative tells us how fast the rate of change is changing, or how fast the slope is changing

[ruby path]

if the slope is increasing, the graph curves upwards, and the second derivative is positive.
if the slope is decreasing, the graph curves downwards, and the second derivative is negative

[obtuse pebble]

@merry jetty Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[azure viper]

I can try

do you have a picture of the problem

Is it like triangles or quadrilaterals

a tip for triangles is that the 3 angles always add up to 180

so if you get a right triangle and it only tells you 2 angles you can use that to get the third

can you send an example problem of something youve done in class recently

[latent walrus]

youre being too general for anyone to give you anything

[azure viper]

yeah

[latent walrus]

well

[azure viper]

well

[latent walrus]

<@&268886789983436800>

[azure viper]

its underlined in the rules bro

impossible to miss

rip

[hot hazel]

.close

[obtuse pebble]

Channel closed

Closed by @hot hazel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[past walrus]

Hey guys, I am a little confused as to what x is

[latent walrus]

you mean for the x=...

[past walrus]

yes

[latent walrus]

just rearrange u=1-x, dont overthink it

[past walrus]

is that just du?

[latent walrus]

no

[past walrus]

So like this essentially?

[upper kindle]

Yeah

Ohk it's right

[past walrus]

wouldn't du be negative 1? Cuz x is negative?

[upper kindle]

Yeah right

[latent walrus]

it wanted x, not -x, but sure

du=-dx

[obtuse pebble]

@past walrus Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich vale]

Question a

answer^

[latent walrus]

okay

do you have a question

[rich vale]

well

yes

i did send one

[latent walrus]

you sent a question, and its answer

you never said what your issue is

[rich vale]

i have the answers but not sure how to get to it

[latent walrus]

its undoing a binomial expansion if youre familiar with those

[rich vale]

not entirely, brandnew to the topic

[latent walrus]

ah, the main thing to look out for are the coefficients
in a
you have 1+3a+3a^2+a^3
the coefficients follow the ncr for n=3
3c0=1 3c1=3 2c2=3 3c3=1

and the r values match the power of a, so one can recognise this as the expansion of (1+a)^3

you know its a + because the sign never changes between terms

[rich vale]

Ohhhhh ok

i get you

but the question says without expanding the equation

[latent walrus]

that doesnt expand it

youre doing the opposite really

[rich vale]

oh ok ok

tysm

[latent walrus]

np

[rich vale]

🙏

.close

[obtuse pebble]

Channel closed

Closed by @rich vale

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bright basin]

100 < 22 + 51 + x

[last pilot]

it's pretty easy

[bright basin]

Find x

[last pilot]

no no no

@bright basin TOTAL cost is $100

[cyan thicket]

?

[bright basin]

Awh shoot you’re right. My b

[last pilot]

all good

[cyan thicket]

its alr

[last pilot]

@cyan thicket just a question, what grade/level is this

[cyan thicket]

7th grade austrlian

[bright basin]

This make it any better?

[last pilot]

yep

[cyan thicket]

yes it soes

[last pilot]

look, profit is basically the selling price minus the cost

[bright basin]

Isolate x and you’re done, Goodluck!

[cyan thicket]

shoot i have 20 mins left

[last pilot]

because you have to pay off your debts (your cost) as well.

[bright basin]

You probably got it wrong since you were using = instead of > or something similar

[cyan thicket]

thats my question

[last pilot]

so as bulbasaur said, the cost is $100
in order to make a profit, the selling price must be larger than the cost--so $22 + $51 +$x must be LARGER than $100

[last pilot]

that's what he's answering

[cyan thicket]

ok oh

[bright basin]

Just curious could you help me with mine? I’m in help 41

[obtuse pebble]

Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, so advertising can quickly turn into spam.

[last pilot]

and yes i saw ur question, be there in a sec.

[bright basin]

Ah, got it. Won’t do that in the future

[cyan thicket]

so i need to finish this by tomorrow

[last pilot]

anyway, as bulbasaur said: that can be expressed as $22 + $51 + $x > $100
that can be simplified into $73 + $x > $100

[last pilot]

all g

[cyan thicket]

yes he did

[last pilot]

so u got it?

[cyan thicket]

still no

im in the second worst math class

[last pilot]

sighs

[cyan thicket]

so u know

[last pilot]

this isn't really that hard

okay let's see, i'll explain again.

let's say you have $0: you're broke

[cyan thicket]

yea

[last pilot]

now, you make three pots for $100. now, you don't have that money, so you promise to pay the dude who sells u clay and stuff $100 back later out of the money u get from selling the pots

this is cost: the $100 is cost

[cyan thicket]

so its more than $27 the answer

Thanks so much

[last pilot]

now you sell two pots for $22 and $51, that makes $73. if you want a profit, that means you want some money LEFT OVER for yourself--so you must sell the third pot so that the total selling price is larger than $100--which is the amount u need to pay

np

[cyan thicket]

U helped me

[last pilot]

yes more than $27

np np

!done

[obtuse pebble]

If you are done with this channel, please mark your problem as solved by typing .close

[cyan thicket]

.close

[obtuse pebble]

Channel closed

Closed by @cyan thicket

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Is this the correct channel? When did discord become completely insane? I just have a theory question I dont need help with math homework

[timid silo]

Okay I CAN read let me type this out

I was reading about n-body problems and it is stated that the 2 body problem is "solved" and the 3 body problem is "unsolved", which on wikipedia is explained as:

There is no general solution that can be expressed in terms of a finite number of standard mathematical operations.

I remember learning trig and finding out the actual sin cosin and tangent equations your calculator is approximating involve hypothetically infinitely recursive equations.

My question is, what does this really mean? I assume it doesnt mean trig is unsolved, I am just confused about these terms

If this is just a case of wikipedia being wrong that would also figure

[obtuse pebble]

@brisk glade Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spring steeple]

I don't understand the hint, why it says common divisors are less than or equal to n-m, shouldn't it be less than or equal to m? If gcd(m,n) = 1 then less than m

[brittle vessel]

Why should it be that instead?

[spring steeple]

Common divisors of m,n can't be greater than m if m < n

[white urchin]

both of that are true actually

[brittle vessel]

You're right, the gcd can't be greater than m. Although, all it says is that any common divisor is less than or equal to n-m

[spring steeple]

How's common divisor less than or equal to n-m true though?

[white urchin]

it's probably from euclidean algorithm

you can search about it

[spring steeple]

Ahh alright

Thanks

[white urchin]

np

[fiery olive]

In fact you can say more:

(if n > m, then) any common divisor of m and n is also a divisor of n-m

In particular gcd(n,m) is less than or equal to n-m

[spring steeple]

Alright thanks

.close

[obtuse pebble]

Channel closed

Closed by @spring steeple

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone fulcrum]

need some help with 2b.

[lone fulcrum]

This is what i have already

but I am not sure about one thing. Is the bird path only describing the x coordinate of the bird when it hits a building? or the horizontal line it flies across and not neccesarily where the bird hits a building?

[obtuse pebble]

@lone fulcrum Has your question been resolved?

[obtuse pebble]

@lone fulcrum Has your question been resolved?

[lone fulcrum]

<@&286206848099549185>

[brittle vessel]

My understanding from the problem description is that a bird path is the horizontal line traveled by the bird, regardless of whether it hits a building.

[obtuse pebble]

@lone fulcrum Has your question been resolved?

[lone fulcrum]

mmmhh that would make the algorithm quite complicated wouldnt it?

how would i need to change my code?

it is psuedo code btw

[brittle vessel]

Not sure why it would be that complicated. If bird paths only consisted of paths that hit buildings, then the algorithm would never return NIL

[lone fulcrum]

Well consider the following scenario, the root of the RB-tree has a x coordinate less then the x coordinate of the path of the bird and a y coordinate smaller than the y coordinate of the bird path

that would mean you would have to search the left and right subtree

[brittle vessel]

The algorithm would be the following:

• Iterate through the redblack tree in order of x (i.e., start with the smallest x and iterate upwards).
• In every node, check if bird y >= node.y: if so, return the node and delete it from the tree.
• If after iterating through the entire tree, no building is hit, return NIL.
  Looking at your pseudocode, this is already what you had in mind

[lone fulcrum]

Does this take into consideration that the x coordinate of the birdpath could be less than the x coordinate of the building?

[brittle vessel]

Presumably you would have the bird travel as you do the search. The bird travels from (0,bird.y) to (bird.x, bird.y). So, in every iteration, update the bird.x along with the node

Actually, maybe don't update it if it is possible that the bird doesn't traverse the entire x-line, instead just make sure that bird.x <= T.x

[lone fulcrum]

I changed it to this. I think this is correct @brittle vessel.

if you initially call it on the root node

[brittle vessel]

hmm, we never traverse right here though?

[lone fulcrum]

oh oops the last line is supposes to be node.right

my bad

[brittle vessel]

Great 👍

Don't have it in me to go through the algorithm step by step, but you seem to have the idea figured out

[lone fulcrum]

Thats alright

thanks for your time anyway

.close

[obtuse pebble]

Channel closed

Closed by @lone fulcrum

Use .reopen if this was a mistake.

[brittle vessel]

no worries, gl!

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet yoke]

Hello. Im struggling with a question calc 1

[scarlet yoke]

Can someone help me as to what steps i should take to solve this?

[obtuse pebble]

@scarlet yoke Has your question been resolved?

[scarlet yoke]

<@&286206848099549185>

[civic socket]

solve this question by f(-x)

thats a start

wait since this is calc 1 then i believe they want the derivative first right? I dunno

[scarlet yoke]

yes thats what my teacher tells us to do

[civic socket]

okay

use the power rule where $$nx^{n-1}$$

[warm shale]

アキラ (>_<)

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warm flame]

Can anyone guide me with this one? Don't know where to start

[obtuse pebble]

@warm flame Has your question been resolved?

[somber bone]

which problem specifically do you need help with?

[warm flame]

First one and second one I think is just 3/10 and 5/10

But the 3rd question

I am particularly struggling

Can you help me?

[somber bone]

I see, I will take a look

im confused as to what you mean by the third question (sorry) can you type the question specifically in the chat?

[warm flame]

A multiple of 3 and a multiple of 2

[somber bone]

okay so basically you're combining (adding) the probability of the spinner landing on a multiple of 3 and the probability of the spinner landing on a multiple of 2

[warm flame]

The ones with green mark are already answered

[warm flame]

3+5?

anyways I'm not even sure if my solution for H and R is correct

But H is 3/10 and R is 5/10

[somber bone]

your answers for the first questions are correct

[warm flame]

Okay thank tou

You

[somber bone]

so you just add them together: 3/10 + 5/10 = 8/10

and then you need to subtract overlaps

[warm flame]

It's not on the choices

💀

[warm flame]

Oh

[somber bone]

did you subtract overlaps?

[warm flame]

How do you that?

[somber bone]

like for example, 6 is both a multiple of 2 and 3

[warm flame]

Sorry I haven't listened to my math teacher for awhile

[somber bone]

so you should do 8/10 - 1/10 = 7/10

i believe that's the general idea, is that on the answers?

and does this process sort of make sense?

[warm flame]

Yeah it is

Yeah it does make sense

[somber bone]

OH SHIT I JUST REALIZED I DID THIS WRONG

[somber bone]

did it ask for AND in the problem

[warm flame]

You're a lifesaver

Yeah it said AND

[somber bone]

okay let's back up

[warm flame]

Another question

What if it said OR?

[somber bone]

okay so i accidentally did the problem after (multiple of 3 OR a multiple of 2)

so for the AND problem

[warm flame]

Oh so 7/10 is the or problem?

[somber bone]

you would only count the overlap (the 1/10 probability from the 6)

[somber bone]

i am very sorry for the confusion, let me know if you need me to explain anything

[warm flame]

Oh yeah it is lmao for mutually exclusive

[somber bone]

yeah exactly

[warm flame]

Nah its fine you are helping me

[somber bone]

3rd problem: 7/10, 4th problem: 1/10

[warm flame]

Can you elaborate how you did the 4th problem?

I want to learn

Not mutually right?

[warm flame]

Wait no

3rd problem

💀

[warm flame]

I think you did a mistake, I thought 7/10 was the 4th problem though

[somber bone]

insert profanities, 3rd problem: 1/10, 4th problem 7/10

yeah you're right

[obtuse pebble]

@warm flame Has your question been resolved?

[warm flame]

.close

[obtuse pebble]

Channel closed

Closed by @warm flame

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[untold mountain]

hello, my question is on the second part of this question, circled in red. my work is in blue. Ive completed the first part of the question, but struggle to understand this second part, would someone be able to help me with this, or link material such as a page or video that will help with this exact second part?

[untold mountain]

i actually also need assistance with the line right above whats circled, where it says write the signal turned on at t=a

[obtuse pebble]

@untold mountain Has your question been resolved?

[untold mountain]

<@&286206848099549185> ^

[obtuse pebble]

@untold mountain Has your question been resolved?

Channel closed

Closed by @untold mountain

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nocturne pulsar]

help please: Prove that the sum of the diameters of the incircle and the circumcircle of a right triangle is equal to the sum of the legs. I made a diagram, but could not solve it

[nocturne pulsar]

<@&286206848099549185>

[obtuse pebble]

@nocturne pulsar Has your question been resolved?

[obtuse pebble]

@nocturne pulsar Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deft fable]

id do it via the squares surrounding

[spring yacht]

Like how the semicircles are in the squares

[deft fable]

yh so that big one is 10 squares

nvm 8

nvm 10

then use the area of the circle equation

[obtuse pebble]

@spring yacht Has your question been resolved?

Channel closed

Closed by @spring yacht

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brisk arrow]

r and w are vectors

[brisk arrow]

r dot w could be considered as the projection of w on r’s span or the projection of r on w’s span

Right

And the value of the dot product would be the parallelogram that form by r and w

**Dot product could be negative right? **

[brisk arrow]

How do I determine whether a dot product of some certain vectors would be positive or negative

[brave bramble]

Dot product itself isn't a projection. It's pretty closely related to projections!

[brisk arrow]

Sorry

[brave bramble]

r•w = |r||w|cosθ

[brisk arrow]

Yes

[brisk arrow]

Yes

[brave bramble]

Or, it's the sum of the components, each multiplied together

[brave bramble]

This is largely why we pay attention to the dot product. It's very easy to calculate.

[brisk arrow]

Can it be negative

[brave bramble]

Yes, if cosθ is negative

That is, if there's more than 90 degrees between the vectors

[brisk arrow]

Are there any other ways that is more intuitive

[brave bramble]

I personally think of the dot product as "how well the vectors line up"

The dot product is large when the vectors are aligned, and large.

The dot product is small when the vectors are perpendicular, or small.

The dot product is negative, if the vectors are pointing in opposite directions

[brisk arrow]

Terrific

[obtuse pebble]

@brisk arrow Has your question been resolved?

Channel closed

Closed by @brisk arrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dim ocean]

Can someone explain to me how I can show if a set of polynomials is linearly dependent, I know how to do a set of 3 polynomials but I dont understand how to do it with 5 since you can get an augmented matrix with 3.

With the particular question I am working on I have 5 polynomials to the 3rd degree, meaning x^3, I have collected all the like terms but it just seems to be a 4x5 matrix which I don't understand how to solve. am I even doing it correctly with a 4x5?

[narrow vault]

do basically the same thing, perform row reduction and show one of the polynomials get reduced to 0 -> it's a linear combination of other polynomials

well if you're doing it as 4x5 i guess column reduction, but same thing

[dim ocean]

so you can do it the same as a common 3x3?

[narrow vault]

yes
the whole point is the techniques works for any collection of vectors (or in your case polynomials) of any size

so arbitrary nxk matrix

[dim ocean]

thanks a lot

.close

[obtuse pebble]

Channel closed

Closed by @dim ocean

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lime magnet]

Im having a hard time proving this, could someone help me out?

[lime magnet]

https://proofwiki.org/wiki/Subset_of_Finite_Set_is_Finite

I found this page, but I dont understand:

and here is the book's thm proof for a similar problem

[obtuse pebble]

@lime magnet Has your question been resolved?

[lime magnet]

<@&286206848099549185>

[upbeat plinth]

whats unclear about this?

[lime magnet]

I got it actually! was just confused about how it applies to the inductive case later on but I see it now

.close

[obtuse pebble]

Channel closed

Closed by @lime magnet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid hare]

can someone help

[pliant tide]

😂

[solid hare]

yar

help

[pliant tide]

what u tryna find

[solid hare]

x and y

[pliant tide]

i dont even know what im looking at

where is ur y angle

[solid hare]

ur supposed to find it

[pliant tide]

no but where is it on the diagram

[solid hare]

on the line

[warped notch]

since its supplimentry its gonna equal 180

you have other angles to your disposal

[solid hare]

what

💀

[warped notch]

this is a weird question

wouldnt y be 68

and x be

112

is that what its asking

[pliant tide]

💀

[warped notch]

i am not gonna freakin help if i cant figure it out

[hollow solstice]

Is it like QR is 68 on centre and is asking y= Q T R , T being poi ?

[solid hare]

okay then how to do this

[warped notch]

again thats suppimentry

now it gives you 128

which i think personally might be m angle 2

1

1 i meant

[obtuse pebble]

@solid hare Has your question been resolved?

[obtuse pebble]

@solid hare Has your question been resolved?

[obtuse pebble]

@solid hare Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wispy acorn]

how do I solve the third question

[wispy acorn]

got the answers for the mew + 2 sigma

and the mew - 2 sigma

how do I caculate

and please quick

its due midnight

[latent walrus]

from my perspective you have a solid 13 hours then, no need to worry

[wispy acorn]

no in my time

[latent walrus]

if youve done what you said, then you have everything you need

[wispy acorn]

its in 11 minutes

[latent walrus]

thanks, i didnt think of that one, silly me

[wispy acorn]

like how do I enter them as "Enter answer as an interval using square-brackets only with whole numbers."

@latent walrus

[latent walrus]

what values do you actually have

[drifting roost]

Minimum usual value: mu - 2sigma

Maximum usual value: mu + 2sigma

You already have the values for mu and sigma (assuming they're right)

[wispy acorn]

mew 2 sigma postive: 231.16

Mew 2 sigma negative: 182.04

[latent walrus]

part of me says round them to nearest whole number

other part says round them to the nearest whole number within the bounds they set

[obtuse pebble]

@wispy acorn Has your question been resolved?

[wispy acorn]

so how do I round those numbers to whole numbers?

had to contact my professor late at night

thank god he's chill

and extended it for me

<@&286206848099549185>

[inner jolt]

can I help you?

[thorny stag]

ya

wht is ur question

[wispy acorn]

how can I solve the third question

I have the answers caculated from mew - 2 sigma and mew + 2 sigma

also @inner jolt

[latent walrus]

You dont know how to round?

[wispy acorn]

like I'm too dumb rn to round to whole number I forgot what it is

I know rounding to other decimal places

[latent walrus]

I mean, its an integer

[wispy acorn]

so like the positive is 231 and the negative is 182 as a whole number

[latent walrus]

Could be 183 since 182 isnt inside the bounds, thats up to your own judgement

[wispy acorn]

Aight so I laid it out

Referring to the rule of thumb

[obtuse pebble]

@wispy acorn Has your question been resolved?

[wispy acorn]

.close

[obtuse pebble]

Channel closed

Closed by @wispy acorn

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[leaden locust]

How do I solve these 2 please provide full working out

[fathom flicker]

!noans

[obtuse pebble]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[leaden locust]

i do not know how to solve these questions and need help

[fathom flicker]

What have you tried?

[leaden locust]

dont know where to strt

[obtuse pebble]

@leaden locust Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cyan thicket]

<@&286206848099549185>

[crisp abyss]

Yeh

[cyan thicket]

its my last question i need help

[crisp abyss]

Tell

[cyan thicket]

i dont know how to solve

it

[crisp abyss]

This one ?

[cyan thicket]

ye

[crisp abyss]

@helper I need help 😞

💀💀

[cyan thicket]

<@&286206848099549185>

[cyan thicket]

i called others

[crisp abyss]

Ur 7th class right ?

[cyan thicket]

ye

grade yes

[crisp abyss]

Damn me too

[civic socket]

!15m

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[crisp abyss]

I have finished my exam so I don't know noe

[cyan thicket]

😭

ihave 1 day left

[crisp abyss]

Check on yt all solutions are there

[cyan thicket]

the thing is not allowd

teach said

[inner jolt]

2331000

$

[cyan thicket]

ok

[signal tendon]

Explain the process

[cyan thicket]

thats wrong

[cyan thicket]

sooooo i dont know

[inner jolt]

what?

[signal tendon]

You can't just give answers

You gotta guide them through the answer Nick

[cyan thicket]

so the example says

calculating a 10 perecnt dicount

means following thing:

[inner jolt]

2590000*0.9=2331000

[cyan thicket]

sorry but thats wrong

[inner jolt]

so... what is answer?

[cyan thicket]

@signal tendon

this was the example

[signal tendon]

...

That's literally what Nick did though

[inner jolt]

what? my answer is true

[cyan thicket]

and i me help understanding

how to solve my question

[signal tendon]

Wait. It says "Enter your next step here"

[cyan thicket]

BUT ITS worng 😭

[signal tendon]

Is it asking for you put in an equation and not the value?

[cyan thicket]

asking foir the ANSWER

[signal tendon]

Try typing 2590000 - 259000

[inner jolt]

yeah

[cyan thicket]

no like 1 plus 1 + 2 like 2

[signal tendon]

?

Huh

[cyan thicket]

this is australia

so wording is different

enter ur next step meaning whats the answer

[signal tendon]

Question, have you put in what I've said though

Also, is there an online link to this

[cyan thicket]

https://mathspace.co/work/TopicCustomWorkout-15247279/Problem-1475464494?state=problem

this it the link

[signal tendon]

I don't have a class 💀

[cyan thicket]

ill give me user aand password in dms

is that fine?

[signal tendon]

That sounds like a terrible move. No

[cyan thicket]

😭 im dead

[signal tendon]

@inner jolt Your answer should be right. I don't see why it's wrong

[cyan thicket]

I ALR TRIED NICKS

[signal tendon]

Try 2590000 * 9/10

[cyan thicket]

ok

@signal tendon my frickin question changed

[signal tendon]

So it worked

?

[signal tendon]

It's literally the same thing

[cyan thicket]

im stupid

im in the worst math class

[signal tendon]

It's

literally

the same as the previous one

Not even the percentage changed

[signal tendon]

...

You've gotta be kidding me

[cyan thicket]

thats what im thinking

[signal tendon]

Plug in the values man

[cyan thicket]

i have -100iq

fr

[signal tendon]

I think you're just not reading the question

[cyan thicket]

just plz give the answer

i need to go to the bathroom and i cant leave without finishing this

[signal tendon]

I can't do that.

[cyan thicket]

no wonder why this server is bad

.close

[obtuse pebble]

Channel closed

Closed by @cyan thicket

Use .reopen if this was a mistake.

[civic socket]

!noans

[obtuse pebble]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[cyan thicket]

i dont give a shit

[civic socket]

lmao

[cyan thicket]

im leaving this goofy shitty server

fuck u guys

[signal tendon]

Make sure you learn percentages on your way out

[civic socket]

bud go upset

[cyan thicket]

shut up for the last time @civic socket

[cyan thicket]

i will

[civic socket]

welcome to my block list

[cyan thicket]

thanks for the helping though

[cyan thicket]

fuck off

[balmy mortar]

<@&268886789983436800>

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Blud rly called mods

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half urchin]

hii can someone please explain how this question works?

[half urchin]

i dont understand the question 😭

answer

**

[wraith solstice]

I think its just finding the value of it

like this

[half urchin]

we cant use calculators for it thoo so idkk

[wraith solstice]

then i have no idea sorry😭

[half urchin]

HAHAH its okayy 😭

thanks for trying thoo

[glossy yew]

Have you looked at your study materials/books/references?

[half urchin]

yeahh but our teacher hasnt taught us anything like this

so

im not sure why its in our worksheet

[glossy yew]

Let me see if I can find a relevant Khan Academy video

[half urchin]

okayy trhank youu

[glossy yew]

I cannot seem to find anything on KA, so I'll have to look up for some other reference

[half urchin]

ahh okayyy

thank u smm

[glossy yew]

https://www.mathsisfun.com/algebra/trig-four-quadrants.html

If you have specific questions from this, feel free to follow up

[half urchin]

hmm

im sorry but i still dont think i understand it 😭

[glossy yew]

This will take some time and practice, I don't think this is something you're supposed to get instantly

[half urchin]

hmm okkayy

ill just have to ask my teacher about it tomorrow i guesss

thank you guyss though

🫶

.close

[obtuse pebble]

Channel closed

Closed by @half urchin

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[muted ember]

Hello, does anyone know how to solve this trigonometric equation?

[muted ember]

According to the book this is the solution

[pastel wren]

should there be y on the right side?

[muted ember]

yes

[muted ember]

if you notice, the solution is a point (x, y)

[obtuse pebble]

@muted ember Has your question been resolved?

[muted ember]

?

[obtuse pebble]

@muted ember Has your question been resolved?

[obtuse pebble]

@muted ember Has your question been resolved?

[muted ember]

It occurred to me to find the range of the left side of the equation and the right side and then intersect them and see what comes out. Can you help me find the range of f(x)? I don't really know how to get it.

sen is sin

<@&286206848099549185>

[royal pawn]

i dont think it works. i have only seen it work in very rare situations.
lemme think a little bit more

or maybe it works ?

yeh maybe it does

lemme test it

its like very hard to find the range of f

yeh i died

i couldnt

lemme think

nope it doesnt have a finite range

[muted ember]

[royal pawn]

bro how does it have a very simple answer

we are missing sth

[muted ember]

I don't know, I asked in several servers and nobody knows how to do it xD

I didn't imagine it would be so difficult

yesterday I was graphing and saw that both functions intersect with 17/2

[royal pawn]

wait lemme see

oh wait

yeh but its not enough

[muted ember]

equating both functions to 17/2 gives the values of x and y

but I don't know why

xd

[royal pawn]

like to solve equation using inequality we need sth like this in their range :
a <= 1
b >= 1

[muted ember]

yes

[royal pawn]

WAIT THEY ACTUALLY HAVE

[muted ember]

then?

[royal pawn]

f(x) range is literally

25/2 <= f(x)

and g(x) range is <= 25/2

but the problem is

finding f(x) range 💀

[muted ember]

intersection at 25/2?

[royal pawn]

no contiguous

so basically if a = b

and we want to solve it if a >= x and b <= x then answer will occour at a = b = x

[muted ember]

why?

[royal pawn]

graphed it 💀

[royal pawn]

yeh

yeh you subtracted 4

your f(x) and mine are different

i didnt change the original equation

i was talking according to that

brb

1h

[muted ember]

ok

[royal pawn]

yeh solved it

[muted ember]

show me pls

[royal pawn]

https://imgur.com/n0eiFoN

proved that its range is >= 25/2

my friend helped me in this 💀

[muted ember]

why?

[royal pawn]

its a trivial thing :
(a-b)^2 >= 0

[muted ember]

subtracted both equations and squared both members?

[royal pawn]

there are some inequalities that can help us find ranges easier

[royal pawn]

yeh

[royal pawn]

for example if a > 0 then a + 1/a >= 2

[muted ember]

hmm?

[royal pawn]

you shouldnt do this

that was the whole point of defining a and b

you should avoid extra calculations

and follow along that trivial

sorry imma go

[muted ember]

:c

[obtuse pebble]

@muted ember Has your question been resolved?

[muted ember]

.close

[obtuse pebble]

Channel closed

Closed by @muted ember

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vagrant kite]

How do I do the square root of 2 to the power of 4?

[civic socket]

think about it like this $(\sqrt{2}) \times (\sqrt{2}) \times (\sqrt{2}) \times (\sqrt{2})$

[warm shale]

アキラ (>_<)

[vagrant kite]

Oh ok thanks I get it now

[civic socket]

np

[vagrant kite]

thumb 👍

.close

[obtuse pebble]

Channel closed

Closed by @vagrant kite

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[honest forum]

Prove that if a number q can be expressed as the sum of two integer squares, then so can 2q and 5q.

[honest forum]

Assuming that q = n^2 + k^2, where n and k are integers

We have that 2q = 2n^2 + 2k^2

Or, we have that q = (n-k)^2 + 2nk

and 2q = 2(n-k)^2 + 4nk

But I don't know how to show that 2(n-k)^2 is a perfect square

(if it even is one)

[brave bramble]

It's never one, as you're taking a perfect square, then adding 2 as a factor

[honest forum]

hmm, you are right