help-10

[glass spindle]

.close

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[nocturne wagon]

If each side of a cube is doubled, how many times will its surface area increase?

[clever spoke]

4 times

[nocturne wagon]

how ?

[clever spoke]

if length of a side is x, then the area is 6 * x^2 right

if we double the x, then it's $$6 * (2x)^2$$ so $$4 * 6 * x^2$$

[warm shale]

szahu420

[clever spoke]

does that make sense?

[nocturne wagon]

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[smoky vigil]

What is the multiplicative inverse of 7 mod 33

I.e. 7 times what gets you 1 mod 33

,calc mod(7*19,33)

[warm shale]

Result:

1

[smoky vigil]

Ye

Also

Is this (7x+10) mod 33 or 7x + (10 mod 33)

I assume the former

If so you should write 7x mod 33 on the other side

[wintry swift]

what do you mean with "in terms of x"? i would think y =7x+10 is "in terms of x"

[smoky vigil]

So in terms of y

But if you have (y-10) mod 33= 7x mod 33 if you multiply both sides by 19 you get

719x mod 33 but as we showed 7*19 is 1 mod 33

So we just get x

Well technically x mod 33 but x is already supposed to be a number mod 33

The coefficient of x to be absolutely clear

[obtuse pebble]

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[burnt linden]

just looking for an answer here

I understand the first info, just not the second one

<@&286206848099549185>

[rich frigate]

Let me. Try

[burnt linden]

thanks

[rich frigate]

It is saying if f'<0 then f''>0 means f' is increasing

And f'>0 then function f' is decreasing

[burnt linden]

right

I gotta learn that second derivative thing, I don't really get it yet

[rich frigate]

You know when the theta increase of tangent then tan thehta increase

And f' increase

[burnt linden]

right

[rich frigate]

Let's follow C

From left

If you draw tangent in 3rd quadrant

You find is positive

[burnt linden]

yes got that

[rich frigate]

But as you goin upward theta is decreasing

So f' is decreasing

[burnt linden]

yes got it

theta is like the slope of the tangent line

correct?

[rich frigate]

Ya angle it makes with x axis

[burnt linden]

ahh yes got it now

[rich frigate]

Slope make angle

[burnt linden]

ok so its positive at first and the it's decreasing

[rich frigate]

Ya then it becomes 0

[burnt linden]

yes

becomes zero and then goes negative

[rich frigate]

Then f' start negative

Because angle is more then 90

[burnt linden]

correct

[rich frigate]

But as we go theta is decreasing in minus

Means that f' is increasing

[burnt linden]

ok

[rich frigate]

So f' is negative and its increasing so f'' positive

It's satisfy your conditions

[burnt linden]

so it's C?

[rich frigate]

Ya

[burnt linden]

f' being negative and f'' being positive means f'(x)*f''(x)<0 ?

[rich frigate]

Ya

[burnt linden]

ok thank you

[rich frigate]

Try one more time I just guessed it by looking

If you try it on paper you get right result

[burnt linden]

first condition rules out A correct?

[rich frigate]

Ya

See in B

I f we start in 2nd quadrant

f' <0 you can see it

[burnt linden]

yes it's negative

[rich frigate]

And afterwards angle is increasing in minus

So it's decreasing

Means f'' also negative

They both negative

[burnt linden]

both negative so the product is positive

[rich frigate]

Ya ok good luck

[burnt linden]

thanks a lot

.close

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[timid silo]

,rccw

[glacial obsidian]

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[burnt linden]

1

[glacial obsidian]

Try writing f(x)+x as (f(x)-2x+5)+2x-5+x

[burnt linden]

what would that get me?

oh sorry

just noticed

didnt see that was the bottom of the fraction

ok let me try that

I can just write it as that?

or do I have to change anything else?

[glacial obsidian]

What do you mean?

[glacial obsidian]

This?

[burnt linden]

yes

[glacial obsidian]

f(x)+x is the same thing as (f(x)-2x+5)+2x-5+x

I just added and subtracted 2x-5

[burnt linden]

ah ok

ok done

now

[glacial obsidian]

If instead of $\dfrac{x}{(f(x)-2x+5)+2x-5+x}$ you had $\dfrac{x}{2x-5+x}$, what would you do next?

[warm shale]

d

[burnt linden]

simplify to $\dfrac{x}{3x-5}$

[warm shale]

angelina

[glacial obsidian]

And then?

[burnt linden]

oh right, I would $\dfrac{x}{3x}$

[warm shale]

angelina

[burnt linden]

and do the limit

it would be a third

[glacial obsidian]

But $\dfrac{x}{3x-5}$ is not the same as $\dfrac{x}{3x}$

[warm shale]

d

[glacial obsidian]

You can't just change from one to the other

[burnt linden]

it's not but when I solve limits when x tends to infinty I often solve them like that

[glacial obsidian]

Well, that's not a correct way to do it

In general, for polynomials, you should divide by the largest power of x

$\dfrac{x}{3x-5}=\dfrac{x/x}{(3x-5)/x}$

[warm shale]

d

[glacial obsidian]

$=\dfrac{1}{3-\tfrac{5}{x}}$

[warm shale]

d

[glacial obsidian]

And now you take the limit

5/x -> 0

And the limit is 1/3

[burnt linden]

,rccw

[burnt linden]

pretty sure this is correct tho

[glacial obsidian]

I think it is not
It gives the correct result, but it is not a good justification

Anyway, for the question you asked in the first place, you can do what I said

Divide by x

And obtain $\dfrac{\tfrac{x}{x}}{\tfrac{f(x)-2x+5}{x}+\tfrac{2x}{x}-\tfrac{5}{x}+\tfrac{x}{x}}$

[warm shale]

d

[burnt linden]

ok

[glacial obsidian]

Now try to continue from here

[burnt linden]

honestly I don't know, tha's not something I am used to

[glacial obsidian]

Well, try to find the limit of each term (x/x, (f(x)-2x+5)/x, et cetera) and then substitute what you obtain

For example

$\lim_{x\to+\infty}\dfrac{1}{3+\tfrac{5}{x}}$ is 1/3 because $\lim_{x\to+\infty}1$ is 1, $\lim_{x\to+\infty}3$ is 3 and $\lim_{x\to+\infty}\dfrac{5}{x}$ is $\dfrac{5}{\infty}=0$, so $$\lim_{x\to+\infty}\dfrac{1}{3+\tfrac{5}{x}} = \dfrac{1}{3+0} = \dfrac{1}{3}$$

[warm shale]

d

[burnt linden]

ok right

[glacial obsidian]

Have you ever found a limit that way, or is it new for you?

[burnt linden]

no I understand that

in class we usually do the way I did, it's the limit of the highest order of x

but I understand that

ok so limit of x/x is 1

[rich tapir]

at infinity they are equivalent

[glacial obsidian]

The problem with this method is that it does not work when you have something that is not a polynomial, like this f(x)

[glacial obsidian]

Yes

[burnt linden]

yes so

the one that has f(x) I dont know

then its 2, 0 and 1

[glacial obsidian]

At least that fact should be mentioned. I think that just writing lim x/(x+1) = lim x/x without any further explanation is not enough

[glacial obsidian]

Now use the information in the question

[burnt linden]

OH

ok so thats

,crrw

,rccw

[burnt linden]

that one is 0

[glacial obsidian]

Yes

[burnt linden]

0+3?

its a third?

[glacial obsidian]

Correct

[rich tapir]

hmm maybe, for me (or at least in my uni), it's like a given after taking finite expansion/tylor series

[burnt linden]

high school in europe and its the way I learned

[glacial obsidian]

Yes, there is a point at late university from which it is no longer necessary to precisely say everything

But at high school it is important to say all the details

[rich tapir]

true true

[burnt linden]

thanks a lot @glacial obsidian

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[obtuse pebble]

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[cosmic veldt]

how to show that a ~ b = a+b+ab with G=R\{-1} is closed ?

[blissful bane]

@cosmic veldt

we say, an operatior * is closed in a set A, if operating any two elements ends up back in A

[cosmic veldt]

Agreed

The issue for me is doing it for all

It will take forever to list all right?

Unles I use common sense?

[blissful bane]

the elements are from R-{-1}

[cosmic veldt]

But is that even a proof

[latent walrus]

you basically want to show that if a+b+ab=-1, then a and b are not in R \ {-1}
which can perhaps be done by assuming a+b+ab=-1 and seeing what a and b are

[cosmic veldt]

Oh shit

[blissful bane]

use you have to check if the operation a~b ends up at -1

[cosmic veldt]

wait ur right

can i do contradiction

to assume it equal -1

[latent walrus]

yeah

[frosty grove]

(y2+3/2)(y2-3/2)

what is answer of this

[latent walrus]

!occupied

[obtuse pebble]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[cosmic veldt]

so i got a = -1 and b = -1 can u check my algebra is correct?

and i also think this means its not in set

cuz R\{-1}

this feels wack cuz even though i contradicted the = -1 case dont i have to check everything else just incase i get -1

like, it makes sense mathematically but not intuitively if u get my pt

oh wait

[latent walrus]

alright
a,b in G=R\ {-1}
then a~b=a+b+ab

suppose a+b+ab=-1, then a(1+b)+b=-1
a=(-1-b)/(1+b)=-1
therefore a is not in G, so contradiction reached

could probably stop here though really, but can do b as well ig
a+b(1+a)=-1 b=(-1-a)/(1+a) = -1
so b also isnt in G, another contradiction

[cosmic veldt]

am i gucci

cuz the a and b represent all the stuffs

[latent walrus]

a and b are arbitrary elements of G

[cosmic veldt]

wait why can i stop there

[latent walrus]

because we supposed a was in G, which we showed it cant be

thats enough really

[cosmic veldt]

oh tru that makes sense

[obtuse pebble]

@cosmic veldt Has your question been resolved?

[obtuse pebble]

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[edgy needle]

excuse me

[edgy needle]

for the thing where it says

"where k...."

like the rule

what does it mean?

[river needle]

k does not equal 0

[versed stratus]

k is an arbitrary scalar that isn;t zero

[royal basin]

u and v are parallel if and only if there exists a nonzero scalar k such that u = kv.

[edgy needle]

oh ok

are u viet?

[river needle]

ye

[edgy needle]

same :D

for the example

how do i knopw if theyre parallel or not

[river needle]

if (x2 / x1) = (y2 / y1)

like in this case (-6)/(-2) = 9/3 = 3

[versed stratus]

if one vector can be expressed as a scalar multiple of another, they are parallel

[edgy needle]

ah i see!

do the positives and negatives matter?

[edgy needle]

so in this example, yes they are parallel?

[versed stratus]

yes

[river needle]

yes they are

[edgy needle]

because the first one is multiplied by 3?

[white shard]

k is 3

[edgy needle]

and they are going in the same direction

[white shard]

so that proves that statement u = kv

[edgy needle]

ah ok thanks guys :D

[versed stratus]

that isn;t a necessity, they can be in opposite directions too, and still be parallel

[edgy needle]

ahhhhhhhhhh yes yes

[versed stratus]

atleast that's the definition I learnt

[edgy needle]

makes sense

[river needle]

if k is negative, it move in the opposite direction

so if you only want to know if it is parallel, the k being positive or negative does not matter

[edgy needle]

what the heck is this gibberish?

where does m n p and q come from

[white shard]

no idea

but should be proven right

[edgy needle]

oh ok

.close

[obtuse pebble]

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[edgy needle]

hello

[edgy needle]

i dont understand this

how did they get to the third step?

[glacial obsidian]

Do you refer to the k(xi+yj)?

[edgy needle]

yes

[glacial obsidian]

It is a different thing from the above

[edgy needle]

in the first step, do they rearrange?

i mean second step

[glacial obsidian]

The third step does not follow from the second

[edgy needle]

ohh yes i see

but to get to the second step, did they rearrange the equation?

to make it (xi+ mi) + (yj+nj)

[glacial obsidian]

The text is essentially saying that you are allowed to rearrange terms

[edgy needle]

ah ok

[glacial obsidian]

These are vectors, not numbers

[edgy needle]

thank u :P

oh

[glacial obsidian]

So the basic rules of algebra do not apply here

[glacial obsidian]

You have to use these new ones

[glacial obsidian]

Some of them work, like those two

[edgy needle]

it seems like algebra tho?

[glacial obsidian]

Some others don't

[edgy needle]

ohh :/

thats so confusing

[glacial obsidian]

For example there are two different ways to multiply vectors, and each one has its own rules

[glacial obsidian]

Yes, at the beginning it can be confusing

But it is not too difficult

[edgy needle]

yeah its so hard for me to understand this new concept :(((( ͡° ͜ʖ ͡°)

oops

i loved algebra

btw

is i going along the x axis?

and j going along the y axis?

[glacial obsidian]

Yes

i is in the x axis, goes to the right and has length 1

And j is in the y axis, goes upwards and has length 1

And for example i+j goes in this diagonal

[edgy needle]

how come they are using the pythagorean theorm

when its not a right angle triangle?

[glacial obsidian]

It is

[edgy needle]

oh what

my diagram looked like this

oh i drew OB wrong

but it still not right angle to me?

[glacial obsidian]

AOB is not

[glacial obsidian]

But this one is

[edgy needle]

what the heck!

i hate math

why is it so confusing

[glacial obsidian]

New math is always confusing

[edgy needle]

what happened to the 2i - j?

[edgy needle]

some of my classmates get it instantly

i wish i was like them mannnnnnnnnnnnnnnnnnnnnnnnnnnnnn

[glacial obsidian]

2i-j was OB, but then they are asking about |2i-3j|, which is a different vector

[edgy needle]

oh.

BRUH

its 1:26 am

forigve me..

.CLOSE

awkward

[glacial obsidian]

You have to write .close instead of .CLOSE

[edgy needle]

haha...

.close

[obtuse pebble]

Channel closed

Closed by @edgy needle

Use .reopen if this was a mistake.

[edgy needle]

.close

.reopen

uh

[obtuse pebble]

✅

[edgy needle]

how did they do that to A

[glacial obsidian]

It is a new definition

a is a vector, and â is another vector

It might be the same

It might not

[edgy needle]

oh?

so they just made it up

[glacial obsidian]

Yes

[edgy needle]

WHY ARE THEY MAKING LIFE SO HARDD MAN

10th grade wasnt this hard

this is straight up gibberish

does it get easier?

[glacial obsidian]

All this about vectors will make more sense when you study other things like physics

[edgy needle]

oh im studying physics later this year

[glacial obsidian]

Right now it is just a bunch of symbols and rules to manipulate them which has no use

[edgy needle]

can u pls tell me what the easiest thing in here is?

im learning ahead for grade 11

[glacial obsidian]

No, it doesn't

[glacial obsidian]

Maybe chapters 1 and 11

In chapters 11 and 12 vectors will make more sense

[edgy needle]

and from my other textbook

[edgy needle]

ok thanks :D

[versed stratus]

that depends on how matrices is taught , when I first learnt matrices I just learnt it as an array of numbers.

[glacial obsidian]

Well this is actually true

[edgy needle]

the introduction looks like this

[glacial obsidian]

And 12?

[edgy needle]

chapter 12?

[glacial obsidian]

Yes

[edgy needle]

wtf theres matricesi n chapter 12

\

[glacial obsidian]

Yes, here vectors will have more geometric meaning

[glacial obsidian]

Of course

Matrices are like vectors, they follow some rules of algebra but not all of them, however they have a very important interpretation in geometry

[edgy needle]

are u serious.

i have to go through this pain all over again

[glacial obsidian]

Maybe by the time you get to chapter 11 you will already be familiar with vectors, and things which are not numbers in general

[edgy needle]

how did math go from this

to THAT

BRUHHH

[glacial obsidian]

Actually most modern math (the one that is studied nowadays) is about things which are not numbers

[edgy needle]

...

is that complex numbers?

[glacial obsidian]

It's harder but more useful

[glacial obsidian]

No

[edgy needle]

im studying software engineering

will i have to do that

[glacial obsidian]

No

[edgy needle]

ok good

thank the lord

[glacial obsidian]

Complex numbers are not hard

[edgy needle]

what if i change to electrical engineering

bc im between electrical or software

[glacial obsidian]

It's just numbers, but there is a new number which is called i, and i times i equals -1

[glacial obsidian]

I think it would not be too different math

[edgy needle]

its not difficult when u say it lik dat but i have to learn the concept very carefully

like understand it well

cuz in exams

they really like tricking u

do u want to see an example?

[versed stratus]

electrical engineering requires phasors which are basically vectors though, right?

and that would mean a lot of matrices too

[edgy needle]

wroong one

https://senior-secondary.scsa.wa.edu.au/__data/assets/pdf_file/0006/1042368/2022-MAS-Examination-Calculator-Assumed.PDF

[glacial obsidian]

And complex numbers too probably

[versed stratus]

yup

[glacial obsidian]

Yes, this is true, the following chapters will usually require you to understand all the previous ones

Complex numbers require understanding vectors

[edgy needle]

oh dammm

is the 2i the same as vector 2i?

[glacial obsidian]

No

No, they are very different

[edgy needle]

oh.

[glacial obsidian]

But you will eventually identify the complex number a+bi with the vector ai+bj

[versed stratus]

2i would essentially be the vector 2j

[edgy needle]

WHAT

THE

HECK

WHY THEY MAKE IT CONFUSINGGGG

who made math up

[rich tapir]

[glacial obsidian]

A lot of people, and that's why it is so confusing

Each mathematician who invented something made up a notation and now they are all mixed

[edgy needle]

bruh.

im gonna make my own mathematics

[edgy needle]

what are u studying?

that requires so much math

[glacial obsidian]

Mathematics

[edgy needle]

oh.

were u good at math

growing up?

[glacial obsidian]

Yes

[edgy needle]

oh.

thanks.

im very bad at maths

do u have any tips on how to be good at math

or is it just natural

[rich tapir]

like everything, it's practice

[glacial obsidian]

^

[versed stratus]

not the person you were talking to but PRACTICE, A LOT

[edgy needle]

yeah but some people get math instantly

[glacial obsidian]

I like math a lot and I studied it a lot

[edgy needle]

Y DO I HAVE TO STUDY FOr hoURS WHEN SOMEONE CAN DO IT WITHOUT

theres literally a 12 year old in my class

A 12 YEAR OLD

OMD

[versed stratus]

at a college class? There will always be a few geniuses everywhere

[edgy needle]

no im in grade 11

i accelerated one year

i skipped grade 8

BIGGEST REGRET OF MY LIFE

😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭

[edgy needle]

how do i become a genius

[glacial obsidian]

In many cases it is about reading the correct thing, or talking to the right person about the right thing
I had a subject which was about something called differentiable manifolds and I found it quite confusing for a few months, then I read something about where the notation came from and then a lot of things made sense

[edgy needle]

hmm yes makes sense

im self learning right now

bc i wanna be ready next year

cuz last year i failed badly

[glacial obsidian]

Sometimes just one idea can help you understand a whole subject in one or two minutes

[glacial obsidian]

You can't, but you can read a lot, which is better

[edgy needle]

when i read

i cant like envision stuff

so i hate reading

like some people can SEE MATH??

[glacial obsidian]

Yes

[glacial obsidian]

Then try something different, like asking people or drawing things

[edgy needle]

yeah i am a visual learner when it comes to math

[glacial obsidian]

For example vectors make more sense with drawings

[edgy needle]

ok thanks for the help

its very late

,time

[warm shale]

The current time for nutgun. is 01:59 AM (AWST) on Mon, 22/01/2024.

[edgy needle]

can i pls message u in dms sometime?

[glacial obsidian]

Yes

[edgy needle]

ok thank u :D

.close

[obtuse pebble]

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[steel urchin]

This is the same as a is subset of b right

[dusk widget]

yes

[obtuse pebble]

@steel urchin Has your question been resolved?

[steel urchin]

Tyty

.close

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[obtuse pebble]

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[rotund crater]

Def

[rotund crater]

3 square foot 48 + square foot 12 - square foot 47

[median dome]

??

!xy

[obtuse pebble]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[royal basin]

🟦 🦶

[rotund crater]

Is it 11 square root 3

[royal basin]

can you maybe show us a picture of the problem

[royal basin]

so you mistyped it

[rotund crater]

Pretty sure it’s 11 square of 3

[royal basin]

anyway, square roots are typed as sqrt().

[rotund crater]

oh my bad

[robust bloom]

foot?!?! xD

[royal basin]

also square root isnt the same thing as square.

[rotund crater]

IS IT RIGHT THI

IM TIMED

[royal basin]

timed?

[rotund crater]

timed

[robust bloom]

a test?

[royal basin]

you're trying to get help on a timed test?

[rotund crater]

not a test

A review practice quiz

[robust bloom]

Caught in 4k

[royal basin]

thats prob still against server rules.

<@&268886789983436800> we got a maybe test cheater

[rotund crater]

oh thought it only applied to actual grades

[royal basin]

gonna let the mods sort that out

[robust bloom]

save it for the mods kid

[rotund crater]

👍

[warm canopy]

If its a timed quiz i don't think you should be getting outside help from others

[fierce vale]

i don't think u should be playing valorant while taking a test either :p

[rotund crater]

oh

How’d u know

I have it opened LMAO

okay I finished can u guys check and see if I got any wrong

[rotund crater]

oh yeah i sometime forget that square foot isnt square root

[obtuse pebble]

@rotund crater Has your question been resolved?

[rotund crater]

.close

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[wide ice]

I'm guessing the professor just had a typo?

for the second term of the equation to the left of "or" on the bottom

because shouldn't it be d/dy in that case for the second term?

[warm canopy]

No you're differentiating both sides with respect to x

You can't differentiate some terms with respect to x and others with respect to y

[wide ice]

so if you are differentiating with respect to x, then why does it become 2y?

are you differentiating with respect to x and also differentiating implcitly at the same time?

[warm canopy]

You use the chain rule (twice) on y²

Since y is a function of x

Implicit differentiating just means you're differentiating an implicit equation (I.e. not one that looks like y = ...)

[wide ice]

I guess I'm kind of confused why its not 0

[warm canopy]

Because y is a function of x

You're really differentiating (y(x))² with respect to x

[wide ice]

hmm oh ok

so you could just write is as 2y'?

instead of 2y (dy/dx)

I guess I was maybe getting confused with partial derivative versus implicit derivative

[warm canopy]

Sure yeah

Wait no

[wide ice]

no?

[warm canopy]

Would have to be 2yy'

[wide ice]

oh yeah

so it is implicit differentiation

but if it was a partial derivative it would be 0

[warm canopy]

If partial wrt x then yes

[wide ice]

alright thank you

.close

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[woeful herald]

How to make a canonical form matrix?

[woeful herald]

Should I simply go for solving until I have 1s on main diagonal and 0s everywhere else?

The matrix is 3x4 so its not square

Or should I do it by adding 2 more P and Q which are both diagonal matrixes

[obtuse pebble]

@woeful herald Has your question been resolved?

[obtuse pebble]

@woeful herald Has your question been resolved?

[woeful herald]

I did it but I'm not sure if it's correct

[obtuse pebble]

@woeful herald Has your question been resolved?

[obtuse pebble]

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[swift latch]

How would I do this one?

[swift latch]

I understand nothing in this one

[zenith raft]

draw a picture

[swift latch]

Hold up, lemme switch accounts rq

[south lantern]

It’s 2x collectively

[zenith raft]

,rotate

[south lantern]

I just wanted to write x and x on both

Like this maybe

[zenith raft]

ok, can you write expressions for the area of the photo and the border?

[swift latch]

I think the area of photo would be (2x-6)(2x-6)

Wait

[zenith raft]

also not sure this picture is right

[swift latch]

oH

Nvm then

[zenith raft]

the question is a little unclear to me

[swift latch]

It's okay

(SAME)

😭 I honestly am gonna skip that one and ask my teacher

Thanks tho!

[zenith raft]

if this picture is right then the inside border walls should be 6-2x

[swift latch]

Idk if it's right

.close

[obtuse pebble]

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[hushed drum]

is it not 31.3?

<@&286206848099549185>

<@&286206848099549185>

[obtuse pebble]

@hushed drum Has your question been resolved?

[hushed drum]

<@&286206848099549185>

[obtuse pebble]

@hushed drum Has your question been resolved?

[hushed drum]

.close

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[keen ingot]

can someone give me a hint for this? I don't know how to solve for two variables

[subtle sinew]

You can make two equations

A pot of water is boiling, the heat is turned off at t = 0

[keen ingot]

ahhh

[subtle sinew]

Do you see what the other equation is now?

[keen ingot]

yeah

[obtuse pebble]

@keen ingot Has your question been resolved?

[keen ingot]

@subtle sinew I solved it

thanks for the good hint

.close

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[unborn dew]

Uh

[unborn dew]

I need help

Nvm

.close

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[burnt thunder]

this is vertical comp by 0.3

righr

is it?

[obtuse pebble]

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[spare solstice]

how do i find the value of W? i have no clue how to start

[gilded needle]

similar triangles?

[spare solstice]

ye i think so

im taking the class in spanish

[gilded needle]

hay solo un variable

[spare solstice]

si

so uh 😭 anyone know how to help me

rip

.close

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[round stone]

Helps please

[round stone]

I am stuck with d) i)

<@&286206848099549185>

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

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[fickle fractal]

how to do

[crude coral]

use sin,cos,tan functions to solve

[fickle fractal]

im in geometry

idk trig

[shut lagoon]

This is a trig question though.

[fickle fractal]

bro idk

its on my review

ik its liek a 30 60 90

[shut lagoon]

You've never seen sin(x) = opposite / hypothenuse?

[fickle fractal]

nope

wait whats 21 root 3 over 3

is my school autistc

[shut lagoon]

Maybe you learned some specific techniques for 30, 60, 90 triangles then

[fickle fractal]

yea

it says y=2x

its like long side is x root 3

i found answer but does the math work

[shut lagoon]

Yes, in those triangles, the short side is the long side /sqrt(3)

Then you can use pythagora's theorem to solve for y

Or whatever technique you've learned

[fickle fractal]

yea

bro we got the same nam

how do u resolve

/close

.close

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[formal turtle]

can i talk through

[obtuse pebble]

@formal turtle Has your question been resolved?

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[timid silo]

How do I find x? X^2-5x+1=0

[rich tapir]

do you know quadratic formula

[timid silo]

Yes

Do I use that?

[rich tapir]

well assuming it's x^2 and not X^2, ofcourse

[timid silo]

So x=-1 and x=4?

[rich tapir]

etto... no...

[dense imp]

how did you get that? try plugging the values into the original equation, do they satisfy it?

[timid silo]

Or is it x=1 and x=-4?

Since its =0

[dense imp]

you're going to have to explain how you are trying to think of it, because all that is wrong

[timid silo]

I used the quadratic formula

[dense imp]

ill put it here for a reminder

[timid silo]

Thanks

[dense imp]

so with a = 1, b = -5, c = 1, did you use those values correctly?

[timid silo]

Yes

[dense imp]

$\frac{5\pm\sqrt{25-4(1)(1)}}{2(1)}$

[warm shale]

Soosh

[dense imp]

so you get $\frac{5\pm\sqrt{21}}{2}$

[warm shale]

Soosh

[dense imp]

you can't really simplify any more than this, you can write decimal approximations if you want but leaving this answer in exact form is best

[timid silo]

Ohh I see I got 5 and 2 cuz I square root both the numbers that’s where I was wrong

[timid silo]

So x= this?

[timid silo]

This?

[dense imp]

erm yeah square roots \ exponents dont distribute over addition\subtraction, careful there

[dense imp]

yes

[timid silo]

Aight thank you!

.close

[obtuse pebble]

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[cosmic veldt]

how to show that P(A U B | B) = 1 using a venn diagram?

[cosmic veldt]

i can explain it easily: if we know b happened, obviously A or B happened

but how do i show it visually?

[obtuse pebble]

@cosmic veldt Has your question been resolved?

[shut lagoon]

We know $P(X | Y) = \frac{P(X\cap Y)}{P(Y)}$

[warm shale]

Azyrashacorki

[shut lagoon]

You can probably draw a Venn diagram and see that P(X n Y) in this case is just P(Y), so the probability is 1.

[cosmic veldt]

how

wut does it look like

[shut lagoon]

Draw A and B as sets

THat intersect

Then it should be clear that (A u B) n B = B

[cosmic veldt]

wher did u get that eq from

[shut lagoon]

That's X n Y

Where X is AuB

And y is B

[shut moat]

So just X = X u Y and Y = Y

[obtuse pebble]

@cosmic veldt Has your question been resolved?

[obtuse pebble]

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[timid silo]

is 15/tan28 not the correct equation?

I did Tan(28)15/x and then cancelled out the x and got 15 over tan(28)

[dense imp]

can't really tell, is that marked wrong on your paper?

[timid silo]

yeah it was marked wrong on the website i put it in

[dense imp]

maybe, because the question is to "write an equation," so maybe it expects the whole rigamarole of: CD = 15/tan28 instead of just the answer?

[timid silo]

;/

i tried that already earlier

wait

it worked nevermind

sorry

thanks

[dense imp]

these sites are a pain

[timid silo]

ye

.close

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[nimble iris]

how do i find where the rate of change of y with respect to x is increasing / decreasing given this?

[nimble iris]

is the answer a point or a range?

[tacit scarab]

A range

[rich tapir]

when the question is increasing or decreasing, it's always a range

[tacit scarab]

Also graphically the rate is the slope of the graph

[nimble iris]

oh i got it

ty

.close

[obtuse pebble]

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[pastel bough]

I'm curious how these values were derived

And how were they specifically positioned to that spot

why isn't x the hypotenuse

[obtuse pebble]

@pastel bough Has your question been resolved?

[pastel bough]

<@&286206848099549185>

[pastel bough]

<@&286206848099549185>

[rich frigate]

We put x=2sint

So sint=x/2 =P/H

[obtuse pebble]

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[lethal blaze]

How do I solve this?

[safe haven]

,rccw

[lethal blaze]

I mean how do I factor it

[lethal blaze]

Because if I directly subtitute it the answer will be 0/0

Which is wrong

Because it is one of the deadly sin

[safe haven]

is the graph below for the equation above

[unreal musk]

(Also may be worth using the piecewise definition of the absolute value function…)

[lethal blaze]

our teacher say we should not base on the graph

but wait I will send it as well

[safe haven]

then just check the limit from the left and right to see if it exists or not

from the graph above it should be easy to see whether the limit exists

[lethal blaze]

can I just answer that the limit does not exist because it suppose to be two-sided limits?

[safe haven]

left limit does not equal right limit

[lethal blaze]

huh?

wdym?

[safe haven]

basically what you said here

im supposing what you meant by two sided limits is that the left and right limits should be the same

[lethal blaze]

yess

[safe haven]

now since you can see that its not the same

so the limit doesnt exist

[lethal blaze]

yes

thank youuu

.close

[obtuse pebble]

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[real coral]

How do I integrate sin^3(x) cos^4(x) dx?
I'm getting cos^5(x)/5 - cos^7/7 + C but apparently it's not right

[ashen dove]

sin³x =(1-cos²x)sin x

Take cos x =u

Wait

U did that only ig

[real coral]

I did that already

Ye

?

[high lily]

can you show your work

looks like you made a sign error

[obtuse pebble]

@real coral Has your question been resolved?

[obtuse pebble]

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[gaunt raft]

I need to find the perimeter

[brazen gorge]

construct the height like that

[gaunt raft]

oh ok

So I js need to use the Pythagorean theorem

[brazen gorge]

yes

[gaunt raft]

ty

can you help me with another one?

[brazen gorge]

ok

[gaunt raft]

on b it says 5cm of radius

[brazen gorge]

that means that lines with two stripes are of length 5

[gaunt raft]

ok

[brazen gorge]

b is thus 17-d = 17-5 = 12

[gaunt raft]

ok

but what abt the like piece of circle at the end

[brazen gorge]

the perimeter of that quarter circle is quarter of the whole circumference

[gaunt raft]

ok

so I just divide by 4

[brazen gorge]

yep

[gaunt raft]

what about for question c

[brazen gorge]

same thing

look at the double striped lines

the whole length is 10

and it's divided into two equal parts -> the double striped line is 5 cm

so you can find the quarter circle again

and for the triangle is pythagoras

[gaunt raft]

ok ty

.close

[obtuse pebble]

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[brisk arrow]

Can someone help me to take the derivative of this

Let me know if there’s something wrong in the process

[wanton isle]

looks good

[brisk arrow]

Is it correct, can it be simplified further

Ohh

[wanton isle]

yeah its simplified enough

[brisk arrow]

I missed the t into the trig function

[wanton isle]

oh ye

damn

but anyways perfectly used chain rule

[wanton isle]

and finished the answer clean.

nice

[brisk arrow]

I wonder if the red underlined possessing any information

[wanton isle]

hm?

[brisk arrow]

I shouldn’t adding this fraction up, right?

[wanton isle]

i mean

its perfect as itis

[brisk arrow]

I see

[wanton isle]

its your choice

[brisk arrow]

I see thank you

.close

[obtuse pebble]

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[spiral hedge]

1-3+5-7+9-11……-2015+2017

[spiral hedge]

i don’t really know where to begin

[timid silo]

whats the objective

calculate the sum?

[spiral hedge]

ya

[high lily]

you could do something like group the terms in pairs

[timid silo]

use the sum of arithmetic series formula

S=(n/2)(a+l)

n is the number of terms

a is the first term

l is the last term

S then is the sum

[timid silo]

am i wrong?

[brazen gorge]

it's not an arithmetic series in the current shape

because the sign is alternating

[timid silo]

ah my bad

[brazen gorge]

after the grouping tho it's possible

[wanton isle]

its 2 arethmetic sequences

if u think ab it

[high lily]

you "could" split this into 2 arith series if you wanted

[timid silo]

technically, so you can split it

that is what im saying

[wanton isle]

grouping on top

[timid silo]

you can do it faster

just by splittting

[brazen gorge]

1+(-3+5)+(-7+9)...+(-2015+2017)

same thing

[spiral hedge]

thanks

.close

[obtuse pebble]

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[brisk arrow]

Is it able to know what would t equals to without a calculator

I know the value of cos 30, 45, 60 but none of them are equivalent to 4/5

I have no clue

For those who are curious, this is physics-related question.

it is about S.H.M specifically

[whole dew]

$cos(\frac{\pi}{2} t + \frac{\pi}{3})=\frac{4}{5}$

is that correct

[warm shale]

adumb

[brisk arrow]

yes

sorry for my harsh handwriting

[whole dew]

yeah sorry man idk how i would solve that im stuck as well

[obtuse pebble]

@brisk arrow Has your question been resolved?

[brisk arrow]

it is fine, i think it require a calculator

[rich tapir]

maybe complex numbers can be used somehow, but i don't see any obvious easy way

[brisk arrow]

I see

[brisk arrow]

Also im not respond to your DM about my earlier question is because i cannot understand them.

I will let my teacher check on them tomorrow.

[rich tapir]

all good, if you want additional help with help, hit me up

[obtuse pebble]

@brisk arrow Has your question been resolved?

[nocturne wagon]

jai shree ram

[obtuse pebble]

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[timid silo]

A spherical balloon of radius r subtends an angle θ at the eye of an observer. If the angle of elevation of its centre is φ, find the height of the centre of the balloon.

subtends an angle θ at the eye of an observer - how? like is there a chord or what

[timid silo]

i cant rlly visualise that part im stupid?? 💀

[obtuse pebble]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[timid silo]

2

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

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[glass pasture]

how can i solve this
"K" = 10
"A" = 0

[rich frigate]

12

[obtuse pebble]

@glass pasture Has your question been resolved?

[glass pasture]

I didn't understand

i think it will be like this
3x10 + a = 0
a = -30 ( +26 )
a = -4 ( + 26 )
a = 22
right ?

[rich frigate]

Ya you right my answer wrong sorry 👍

[glass pasture]

thanks

.close

[obtuse pebble]

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[topaz rapids]

<@&286206848099549185> can anyone help me with indirect proportion and direct please

[silver torrent]

whats the problem you’re working on

[rich frigate]

Can I help

[topaz rapids]

If u want

[rich frigate]

You tried something

[topaz rapids]

I haven’t done anything yet

[rich frigate]

Let 'C' be cost of cloth and 'L' be its length

[topaz rapids]

Ok

[rich frigate]

Then the are proportional

So there is a constant let's say k

Such that C=kL

[topaz rapids]

Constant is always k right?

[rich frigate]

Ya k constant

[topaz rapids]

Ok

[rich frigate]

Now can you figure out k