help-10

[timid silo]

oh

idk how to do the question..

u can't even use calculator to solve this

so idk

[obtuse pebble]

@timid silo Has your question been resolved?

[halcyon sparrow]

so ur saying u worked out i got 26+/- 4root39 without a calculator?

[royal mulch]

@timid silo I can help if you would like

I agree with you that the roots using the quadratic formula are $x = 26 \pm 4\sqrt{39}$

[warm shale]

twitch.tv/pencenter

[royal mulch]

As decimal numbers I got about 1.02 and 50.98

So the smallest integer is in the neighborhood of 1

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[red cipher]

Hi I have a question about choosing the U-substitution for Calc 2

[red cipher]

here is my attempt to the question by choosing ln(w) for my u

but the final answer has a negative which I do not where it comes from

[meager glade]

Chain rule

[red cipher]

ouh

yeah right ok thx

i get it now

haha

[meager glade]

:D

[red cipher]

waitwait

so we also do chain rule when we do antiderivatives?

[meager glade]

Yes

If you write down the chain rule

Then isolate f(x) instead of f'(x)

Youll see it

[unreal musk]

(it also may make it a tiny bit neater, though not anywhere near essential, if you chose u = 1 - ln(w) instead!)

[obtuse pebble]

@red cipher Has your question been resolved?

[chrome crypt]

The point of u-substitution is that it unwinds the chain rule where we write the integral in terms of its composition thereby making it easier to solve for the antiderivative.

Also don’t forget the +C

[obtuse pebble]

Channel closed

Closed by @red cipher

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jolly swift]

Set theory... I need to prove this, but I have no idea where to even start. I have tried using venn diagram but got stuck almost immediately. If anyone could help, that would be amazing!

[meager glade]

How would you usually start a proof to show two sets are equal?

[obtuse pebble]

@jolly swift Has your question been resolved?

Channel closed

The owner is missing!

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fiery smelt]

after solving for the hypotenuse i got √45, which i simplified down to 3√5

[fiery smelt]

but in the answers, the hypotenuse is listed as 5

and for some reason, the a and b are wrong to

in the question it seems like angle A is opposite to 6

but sinA lists the opposite as 2√5

[plain stag]

i think, rather than them saying the hypotenuse is 5, they just rationalized the denominator

try rationalizing 6/(3√5) and see if you get the same thing they got

[fiery smelt]

alright

[tidal gazelle]

there is no way that the hypotenuse of that triangle is 5, even when 3sqrt(5) is rationalized you will bet 15/sqrt(5) which is clearly not 5

[fiery smelt]

6/(3√5) ratonalized to 2√5/5 which is the answer but

where do you get 6 from

[plain stag]

6 is the side opposite angle A

[remote dune]

6 is the length

[fiery smelt]

ah right right

[plain stag]

even when 3sqrt(5) is rationalized you will bet 15/sqrt(5)

no you will not

try again

[fiery smelt]

thank you

.close

[obtuse pebble]

Channel closed

Closed by @fiery smelt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glossy trail]

Hey I was just wondering how I would complete this? This makes absolutely no sense to me and I kind of need help please and thank you.

[glossy trail]

So I started with CSC and I noticed that if you put the opposite it would be two over 1 which would make it two.

So then I went on to the next problem part B and I noticed that it was 60 degrees and not 30 degrees so I put the two in front of the square root of 3 over 3.

And I don't really understand how COT 60 degrees is equal to the square root of three over 3?

[hexed agate]

The double angle identities would help here

Or hmm

Can you find cos(30)

Nvmd

[glossy trail]

Sorry for my late response, the cosine of 30 degrees is the square root of three over 3

[hexed agate]

But can you find like cos 60 and sin 60?

[glossy trail]

Also do you have any tips of how I could remember almost everything on that sheet paper?

[hexed agate]

Given the question not sure you are allowed to use unit circle

[glossy trail]

Well technically we're supposed to have this remembered by now but it's only been three days since I've learned about this and I don't know how that's possible

[glossy trail]

Okay so the cosine for 60* is 1/2 and the sine of 60* is the square root of 3/2.

[hexed agate]

Yes and cot is cos/sin iirc

[glossy trail]

irc?

[hexed agate]

If I remember correctly

[glossy trail]

ohhh

I think I get it- nvm

[hexed agate]

What's cos60/sin60?

[glossy trail]

1/2, square root of 3/2

[hexed agate]

(1/2) / (√3/2)

Simplify this

[glossy trail]

I got the sqrt of 3 over 3.

[obtuse pebble]

@glossy trail Has your question been resolved?

[halcyon sparrow]

why’d u say it’s not resolved

[obtuse pebble]

@glossy trail Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fiery ingot]

Hello

[obtuse pebble]

@fiery ingot Has your question been resolved?

[tardy epoch]

Don't open help channels without a question

.close

[obtuse pebble]

Channel closed

Closed by @tardy epoch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brisk matrix]

im hitting a wall with a big (O) problem. i have the following expansions
\begin{align*}
f(\tilde{t}) &= \left(\sum_{n=0}^N f_n(t)\varepsilon^n\right) + O(\varepsilon^{N+1}),\ 0 < \varepsilon << 1,\ \tilde{t} = \varepsilon t\
x(\hat{t},\tilde{t}) &=\left(\sum_{n=0}^Nx_n(\hat{t},\tilde{t})\varepsilon^n\right) + O(\varepsilon^{N+1}),\ \hat{t} = \int_0^t f(\tilde{\varepsilon t}), d\tau
\end{align*}
and we use them to compute approximations of the following pde
[
f^2\pdv{^2x}{\hat{t}^2} + 2f\varepsilon\pdv{^2x}{\hat{t}\partial\tilde{t}} + f'\varepsilon\pdv{x}{\hat{t}}+\varepsilon^2\pdv{^2x}{\tilde{t}^2}+f_0^2x = 0
]

[azure anchor]

i didnt know you could use brackets like this for latex.

[brisk matrix]

use what brackets

like the []

[azure anchor]

[ ]

[warm shale]

maximo

[brisk matrix]

ok this should be the proper setup

now i computed the O(epsilon) approximation to this, in two different ways

and they give different approximations

one way, as suggested by the paper im going off of, is to divide by f^2 and then apply the binomial theorem

this essentially gives you that the final term becomes
[
\frac{f_0^2}{f^2}x \approx f_0^2\frac{x_0 + \varepsilon x_1}{f_0 + \varepsilon f_1} \approx
f_0^2\frac{1}{f_0^2}(1 - 2 \frac{\varepsilon f_1}{f_0})(x_0 + \varepsilon x_1)
]

[warm shale]

maximo

[cerulean jay]

https://tenor.com/view/great-good-gif-24557505

too many 0s lol

[warm shale]

maximo

maximo

[brisk matrix]

so we just "lost" the eps * x_0 term?

[warm shale]

maximo

[brisk matrix]

which is very similar, but completely changes the process by which we approximate the solution to the pde. im not sure if something is going wrong, or if im "required" to divide by f^2

wait

oh im such an idiot

the O(1) term gives us that (\pdv{^2x_0}{\hat{t}^2} + x_0 = 0), so the expressions are the same

kill me

[warm shale]

maximo

[brisk matrix]

.close

[obtuse pebble]

Channel closed

Closed by @brisk matrix

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[red cipher]

hi

[red cipher]

doing calc 2 integrals

what should I do when I run into the problem when there is still an x variable under my du (red box)

i mean whats causing this to not work out perfectly by cancelling everything out

[low patio]

Ideally, this would not happen. However, you have a relation between u and x, so you can rewrite e^-x in terms of u

[red cipher]

am i suppose to try a different value for U? or idk

oh i see ok let me try that

so

after rewritin that x term ill just combine it with u^3 and the take the antiderivative?

[low patio]

In this case, it is definitely a better choice to do u = e^x

That might not seem obvious though

[red cipher]

is there any trick for picking the best value for U

or is it just experience and try

[low patio]

LIATE is the best first step

which you've done implicitly

[low patio]

yep, an unfortunate expansion upcoming but then basic product rule

[red cipher]

haha ok

[obtuse pebble]

@red cipher Has your question been resolved?

Channel closed

Closed by @red cipher

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[azure wren]

I need help with my geomotry hw i need to solve for x but i dont know how to set up the problem , its in a triangle

[royal basin]

well show us your problem

[azure wren]

89-92

[royal basin]

ok

what do you know about the angles in any triangle?

[azure wren]

What do you mean

[royal basin]

ok let me be more direct

what do the angles in any triangle add up to?

[azure wren]

180

[royal basin]

right

that's what you're gonna use in all of these

[azure wren]

So add everything and = to 180

?

[royal basin]

yes exactly

[azure wren]

So A. Is x=-7

[royal basin]

you mean #89?

[azure wren]

Yeah

[plucky sentinel]

Helper

Help

Help

[royal basin]

!occupied

[obtuse pebble]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[royal basin]

@azure wren yes, #89 is x=-7.

[azure wren]

Alright thanks i understand now

[plucky sentinel]

@azure wren

Are you availaible

[azure wren]

Im not a helper

I just got helped

.close

[obtuse pebble]

Channel closed

Closed by @azure wren

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wise lake]

<@&286206848099549185>

[light raft]

!15m

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[light raft]

anyways, start by trying to get rid of the log_1/2 first, how would you go about doing that?

[wise lake]

Oh yeah thanks

I can do that

I'll be good after this

.close

[obtuse pebble]

Channel closed

Closed by @wise lake

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warm shale]

Mycobacterium

[serene dawn]

No

And the derivative is simply 1/sqrt(1 + u^2) because it is the derivative of the antiderivatibe of 1/sqrt(1 + u^2)

So it cancels out

You can basically strike a line through the integral

[warm shale]

Mycobacterium

[obtuse pebble]

Channel closed

Closed by @broken flint

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[normal glade]

Need some help with this one, answers ain't matching

How should I proceed 🤔

<@&286206848099549185>

[hazy sundial]

yes

which class are you in, if may i know?

[golden night]

porbably 11th grade

[hazy sundial]

yeah thought so

however, i am in class 9 so i am not properly sure how to solve this one...

but ill try

yeah, cant..... guss ill have to do limts all over again

[normal glade]

It's technically not a limit question tho.... Like I'm trying to find 1/Tr right now

A good expression for it

I got an answer but apparently not matching 🤦‍♂ that's why looking for some help

The second part is done

First part is being a little annoying

[hazy sundial]

ooo

I'm sorry..

i cant solve it

[timid silo]

i got on the first one 0

idk if its right

@normal glade what did you get

[fathom flicker]

@fierce lagoon

[normal glade]

Yea I got 0 as well

The answer is 1

[timid silo]

oh

[normal glade]

In the key

What did you do?

[normal glade]

It's alr

@timid silo

[timid silo]

?

[normal glade]

.

[timid silo]

wait i am trying to get 1 somehow

[normal glade]

I tried a bunch... Ain't happening

[serene dawn]

I've found an expression for the individual terms t_n and T_n but I'm not sure how it's useful and you've probably figured that out already

[fierce lagoon]

I'm playing geometry dash

[timid silo]

i got infinite

and i got 1/4

but not 1

[normal glade]

💀

I didn't get 1/4

Just got infinite

Can you show what you did?

[timid silo]

i tried using tn * Tn = 1

and wrote the lim in terms of that relation

this implies 4 things

tn = Tn = 1

or

tn = Tn = -1

or

tn = 1/Tn

or Tn = 1/tn

[normal glade]

Yea

But how did you get 1/4

[timid silo]

factor n^4

wait actually

i think i accomplished 1

nvm

[normal glade]

💀

[timid silo]

i got it!!!

i got 1

[normal glade]

Send it damnn

[tropic terrace]

i think its actually 1/4

[timid silo]

i got 1/4 before but since he said his notebook said 1

[normal glade]

Yeah I'm getting 1/4 as well now

[tropic terrace]

i got it

i got the function t(n)

[normal glade]

Yea same

By doing

Sn - s(n-1)

Then summed it up

[tropic terrace]

what function did you get?

[normal glade]

Tr = (n+1) (n+2) (n+3)

[tropic terrace]

t(n) equals that

its easy now

just calculate the limit from the formula

[normal glade]

Yea so 1/4 is the right ans ig

Wrong key

[tropic terrace]

yeah

[timid silo]

anyone curious of seeing how i got 1 ?:)))

[normal glade]

Yea me

Lemme try to get the answer key from another student

If there's something wrong in mine

[timid silo]

can i dm you?

[normal glade]

Yea

Correct answer key

[obtuse pebble]

@normal glade Has your question been resolved?

Channel closed

Closed by @normal glade

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

I need help

[cyan sinew]

what did you try

[timid silo]

I tried to find the the radius then count the area

But failed

Rn i have no clue how do it

[dry grail]

U could just substract the area of the quarter circle from the entire circle, couldn't u?

[timid silo]

Well i didnt know how to do it-

Which is why im here asking for help

[timid silo]

How do i find the area of the quarter?

[dry grail]

That quarter circle is 1/4 of the entire circle

use this

[timid silo]

Substract is -

Rigth?

[dry grail]

yes

[timid silo]

If so then i only got 419.75

[dry grail]

it should be 420 - (1/4 * 420)

the quarter circle is one forth of the entire circle
Not just 1/4 which is approximately 0.25

[timid silo]

Ty

But no need to be harsh

.close.

[dry grail]

[silent anvil]

bro is trying to help u =.=
and he is not harsh at all

[robust bloom]

area of remaining shape is (3/4)*420

answer is 315cm^2

[silent anvil]

for this type of question u can try to form equation with the sentence

[robust bloom]

imagine using calculator

[silent anvil]

chill 😭

not everyone can do mental calculation (untrained)

[robust bloom]

Bruh dividing 420 by 4 and multiplying by three, damn mental calc bruh wtf

[golden night]

for you

[robust bloom]

its so hard to just multiply and divide just visualising

[golden night]

it is basic but do chill

[robust bloom]

bruh

[silent anvil]

nah the people nowadays scroll social media 26 hours a day what do u expect

but still is that guy closing or not

im 17 and i admit it

jesus

@timid silo

close channel

u din close it properly

[golden night]

it will time out if we stopped talking

[robust bloom]

u cant

[silent anvil]

😭 ok

[robust bloom]

bruh, ppl do this in 1 and 2 grade ig

[golden night]

.

[robust bloom]

u could do some rough work

ok

[golden night]

#discussion

[silent anvil]

but i think u learn this level of math at primary school right 😭

welp lets shut up before we get warned

[robust bloom]

yes

[dry grail]

let's just not judge otherrs, shall we @robust bloom?

[robust bloom]

u could multiply by 3/4 💀

[dry grail]

Obviously

[robust bloom]

Ok

[dry grail]

I thought that'd be hard to visualize for someone
So I took the other way around for better understanding

@timid silo Remember to close the channel

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pastel wraith]

So in a book I found 8 axioms for vector spaces. Do I have to show each axiom for this specific set V and then I have proven that set V is a vector space or what am I supposed to do here?

[kind hawk]

yes show all axioms

[pastel wraith]

ok thank you for clarification this seemed to simple for me so I wanted to ask

have a great day!

.close

[obtuse pebble]

Channel closed

Closed by @pastel wraith

Use .reopen if this was a mistake.

[compact current]

@kind hawk

Plz help

.reopen

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dim breach]

help

[obtuse pebble]

Please don't occupy multiple help channels.

[dim breach]

help

[royal basin]

!1c

[obtuse pebble]

Please stick to your channel.

[royal basin]

#help-1

.close

[obtuse pebble]

Channel closed

Closed by @royal basin

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[willow depot]

is there anyone who knows how to solve this kind of questions?

[obtuse pebble]

@willow depot Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tender portal]

how to make it diagonally (45 degree)with wave as it is this function? please tag me

[kind hawk]

its unclear what you mean

can you draw a picture?

@tender portal

[narrow ember]

x+sin(x) maybe

[tender portal]

@kind hawk

LMAO , thanks guys XD

[narrow ember]

https://www.youtube.com/watch?v=h9OWnuarYuc&ab_channel=RedBeanieMaths

it is not rotated

but it looks like it is

but there is how you do it

[tender portal]

thank you

[obtuse pebble]

@tender portal Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[loud shell]

This is the equation for the Fourier equation the boundary conditions for X and X’ are 0.

[loud shell]

And I have to use this particular equation to solve for this problem

Find the temperature 𝑢 (𝑥,𝑡) at any point of the metal rod of
length 25 cm, that is insulated on the ends as well as on the
sides and whose initial temperature distribution is 𝑢 (𝑥, 0) = 𝑥, for 0 < 𝑥 < 25

Right?

Am i not using the general equation with the sin function because of this statement: "insulated on the ends as well as on the sides"

[obtuse pebble]

@loud shell Has your question been resolved?

[loud shell]

need help ;-;

[obtuse pebble]

@loud shell Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[versed heath]

I’m not sure how we obtain the highlighted line

[gilded needle]

just use gamma = x in the contrapositive of the previous sentence

not sure why they used gamma in that sentence, tbh

[versed heath]

ah thank you!

.close

[obtuse pebble]

Channel closed

Closed by @versed heath

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[left hollow]

can you solve this system of equations

[viral blade]

Where is this problem from?

[left hollow]

I don't know how to solve this

[tardy epoch]

,tex .log rules

[warm shale]

riemann

[slender scroll]

You'll probably need the base change one

[left hollow]

.close

[obtuse pebble]

Channel closed

Closed by @left hollow

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sweet mason]

You have organized a lottery to raise funds for the charity organization where you work. You sold 5,000 tickets for $20 each. There is one grand prize of $25,000, 20 first-place prizes of $1,000, 50 second-place prizes of $600, 100 third-place prizes of $300, and 400 fourth-place prizes of $150. The remaining tickets receive no prize.

What is the expected value of a randomly selected lottery ticket?
Please help if you know.

[lone dirge]

Hi

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[lone dirge]

!show

[obtuse pebble]

Show your work, and if possible, explain where you are stuck.

[sweet mason]

1/5000 * 25000 + 20/5000 * 1000 + 50/ 5000 * 600 + 100 / 5000 * 300 + 400/5000 * 150 = 33 dollars

But i think something wrong

[lone dirge]

almost right

you need to subtract the cost of the ticket

So, if you win, you win (prize - ticket price)

and if you don't, you just pay the ticket price

[sweet mason]

But there's no 13 dollar answer in test )

33 - 20 is it correct?

[lone dirge]

,w 1/5000 * 25000 + 20/5000 * 1000 + 50/ 5000 * 600 + 100 / 5000 * 300 + 400/5000 * 150 - 20

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by cain0196

[sweet mason]

Maybe test is wrong(
Thanks.

[lone dirge]

what are the possible answers?

[sweet mason]

9.5
13.5
15
20

[lone dirge]

That's odd

[sweet mason]

Yeah actually

Thanks anyway

[lone dirge]

yw

[obtuse pebble]

@sweet mason Has your question been resolved?

[sweet mason]

. close

.close

[obtuse pebble]

Channel closed

Closed by @sweet mason

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pastel wraith]

This is more of a understanding question but the task is to "show". Is this considered showing the cancellation laws for rings?

[gilded needle]

yes

your proof looks fine and yes, this is showing the cancellation law holds under the given conditions

[pastel wraith]

ok thank you for clarifying

.close

[obtuse pebble]

Channel closed

Closed by @pastel wraith

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oblique void]

<@&286206848099549185>

[wary badger]

u have to post a question first

and wait 15 minutes

[oblique void]

Oh sorry 😂

[wary badger]

then ping helpers if u don’t get an answer

[brisk arrow]

Send the question!!

[wary badger]

use a graphing calculator

it should have the linear regression function

if u go to stat

and make a list in the edit menu

[oblique void]

I need someone to help me do the@

Them

I don’t have a calculator

[wary badger]

they make u do it by hand?

[oblique void]

Yup

Kinda shit right ?

And this is extra credit for my final

I only have 13 questions left and I have 0 idea how to do any of the@

[wary badger]

yes that’s awful

calculate the averages of each column

you’ll need that

the slope is like r *sy/sx

[oblique void]

Dude I have no idea what to do

[wary badger]

no way they make u calculate the standard deviation by hand

😭😭😭

u know how long that would take?

[oblique void]

I get your trying to help but I was in an accident that threw me out of school for quarter 2

So I have no idea of anything

[wary badger]

r u sure u can’t use a calculator

i can use it for u

[oblique void]

I was honestly going to pay a friend to do it for me

[wary badger]

if u don’t have to show work

[oblique void]

I don’t have to show work

[wary badger]

i gotchu

[oblique void]

Just fill in the boxes

Do I owe you anything ?

I don’t mind

There’s only 13 questions left 😂 and I’m screwed if they aren’t done by 8am

[wary badger]

ok

so

it’s

y=963+19x

[oblique void]

That’s the equation?

[wary badger]

for the equation

answer would be 9.4

1142=963+19x

x=9.4

[oblique void]

It says wrong

[wary badger]

😳

[oblique void]

It says equation is right

But final answer is wrong

[wary badger]

9.4 is wrong?

[oblique void]

Yeah

[wary badger]

oh wait

it says the calendar year

not how many years after

my bad

[oblique void]

It’s making me do a whole new one

[wary badger]

so 2020?

😭

[oblique void]

I hate online shit dude

[wary badger]

y=987.1+17.6x

2018

[oblique void]

2018 is final answer ?

[wary badger]

or 2017

wait

don’t do it yet

[oblique void]

Okay

I’m sorry that this is gonna take forever dude

[wary badger]

i think 2017 actually

yea

it’ll be sometime in 2017

[oblique void]

That was right

[wary badger]

ok good

[oblique void]

There’s only 4 more of these type of questions

[wary badger]

67.1+20.1x

y=

[oblique void]

Since this is gonna take longer do you wanna call if that would make it easier

[wary badger]

nah it’s fine

2012

[oblique void]

Alr

That was right

[wary badger]

do u not have a calculator

[oblique void]

I don’t 😅

I just order one on Amazon

Ordered*

[wary badger]

yea u need the ti84

[oblique void]

Yep

[wary badger]

wait

[wary badger]

it says statistics calculator

that probably is what u can use

[oblique void]

Dude your helping me greatly dude

[wary badger]

yea no worries

[oblique void]

Well it’s turned off for the assignment

[wary badger]

oh fr!

[oblique void]

She disabled it

[wary badger]

?

[oblique void]

🥲

[wary badger]

wack

[oblique void]

Well it’s what happens when you get a booty ass teacher 🤣

I’m at a tech school and this is what she got us learning

[wary badger]

58.9+0.2x

wait

it says nearest integer

[oblique void]

What to change ?

[wary badger]

or no the equation is fine

[oblique void]

Okay okay had me worried

[wary badger]

wait

no if messed it up in my calculator

i hit 2 instead of 72 gimme a minute

[oblique void]

lol all good 😂

Atleast h got a calculator

You*

[wary badger]

ok 20.6+0.7x

[oblique void]

Alr

Final?

[wary badger]

then 33

[oblique void]

Correct

You don’t gotta help man I feel bad

Even though it’s crucial 😂

[wary badger]

121.52+10.86x

219

[wary badger]

yea i got my own work to do i jsuy feel bad because u don’t have a calculator

if u want

i can help u out later at night

i gotta write an essay

english is wack

[oblique void]

Alr here 1 sec

There is one more of these and a few more of the other ones it shouldn’t be more than like 15 minutes

If you wanna stick it out rq ?

[wary badger]

few more of what

[oblique void]

Just calculating the regressions

[wary badger]

799.80+31.00x

idk if she wants the zeros or not but whatever that’s to the hundredths place technically

2022

[oblique void]

lol

[wary badger]

what

[oblique void]

There is only these left

Are these easier for you ?

[wary badger]

they’re all easy questuons

[wary badger]

it’s just tedious

[oblique void]

Yeah I know especially without a calculator 😐

[wary badger]

yea that’s not bad

it skips a step

[oblique void]

Awesome

There are 9 of these then I’m done

😱

[wary badger]

y=-0.58x^2+19.81x-86.45

[oblique void]

How do I put this I. ?

[wary badger]

same way i did

[oblique void]

I don’t have ^

On my laptop

[wary badger]

ur kidding

is there a way to superscript

[oblique void]

One sec

That was right

I’m stupid

I found it 🤦‍♂️

[wary badger]

all good

it’s the 6

[oblique void]

And what time zone did you say ?

Or I meant to ask you

[wary badger]

y=(8669.5)(0.9)^x

only the 0.9 is raised to the x power

[wary badger]

east coast america

it’s 1050 pm

[oblique void]

Like that ?

Okay same for me then

[wary badger]

yea

[oblique void]

Alright

[wary badger]

y=(401.8)(x^1.6)

idk if the exponent being inside or outside matters

hopefully not

[oblique void]

Wait how exactly do I put that in

[wary badger]

i’d put it like this actually

(401.8)(x)^1.6

same way u did before just the x and the constant term switched basically

in this case the constant term is 1.6

[oblique void]

Okay it was right lol

Makes sense

7

[wary badger]

14.708+-5.338x

7 more??

is this a different assignment or something

[oblique void]

Yeah then I’m done fully

[wary badger]

hurry up then

[oblique void]

No it’s all one giant extra credit assignment

[wary badger]

(3137.011)(x)^1.595

[wary badger]

(7336.227)(x)^1.608

[wary badger]

(107.1)(1.1)^x

[oblique void]

3 more

[wary badger]

-8.68x^2+166.39-419.72

wait

put an x on the 166 term

[oblique void]

Wdym ?

[wary badger]

like

[oblique void]

Like 166.39x

[wary badger]

yes

[oblique void]

Didn’t wanna put it in wrong and not know what I did wrong

[wary badger]

-0.1x^2+6.4x-50.2

[oblique void]

Last one

Again man your awesome dude you literally saved me from not doing my extra credit

And saved my exam grade 👍👍👍

[wary badger]

-3.658x^2+102.933x-341.829

[wary badger]

thanks

ur welcome

is there one more

[oblique void]

Nah dude your good

[wary badger]

it says 9/10

[oblique void]

Thanks man

[wary badger]

was one wrong?

no problem

[oblique void]

Didn’t mean to send you the question

[wary badger]

oh ok good

ur welcome

have a nice night

[oblique void]

Yeah man good luck on your exams

Bless you dude

[wary badger]

u too

[obtuse pebble]

@oblique void Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sage dagger]

I’m confused did I already set this up wrong

[sage dagger]

I can’t go any further lol

[royal basin]

wym

[sage dagger]

I can’t do 5x^3 + 4x^2

Like

Am I done already?

[boreal jay]

yeah i think that's basically it

[royal basin]

well, you might want to pad with zeros

like x^4 + 0x^3 + 2x^2 + 8x + 5 for your divisor

and then all the terms should line up nicely again

[boreal jay]

that too

u kept the x^2 term underneath the x^3 term

and the following after that messes it up

[sage dagger]

Hm okay

[rich fable]

yeah dont forget to include the powers of x with coefficients of zero. you need to put them in. like you have have to write in 0x^3 into the divisor as well for example so that long division works. of course, you dont have to put it in when writing out the dividend or disviisor in some regular situation

[sage dagger]

Like this?

[royal basin]

yes

[sage dagger]

How do I know when I’m done with long division again?

I know it has something to do with the degree being lower than something else

[royal basin]

deg(remainder) < deg(divisor)

[sage dagger]

Oh okay

So (5x^3 + 17x + 6)/ divisor is my remainder right

Why the warning

[royal basin]

there is a bit of doublespeak in what "remainder" might mean coming from you

the equation for euclidean division of polynomials can be either:
f(x) = g(x)*q(x) + r(x)
with r(x) as the remainder
or
f(x)/g(x) = q(x) + r(x)/g(x)
with r(x)/g(x) as the "remainder"

[sage dagger]

Well the quotient on the right is my remainder I believe

[kind hawk]

note that in the integers, when you divide 30 by 7, you would say that the remainder is 2 and not 2/7

[sage dagger]

yeah

By the way would it be wise to expand and simplify this

I’m not quite sure

[kind hawk]

that is one of the standard ways to compute partial fractions

expand and then compare coefficients

[sage dagger]

because I’m not trying to solve a systems of equations with this (I’d like to avoid it if possible)

[kind hawk]

well good luck avoiding it

[sage dagger]

I mean I have a general idea of how

The other PFD integrals I could easily solve using a different method

Of choosing certain values of x to make for example A or B disappear and then solving for either A or B depending on what I chose

has always worked so far but we’ll see I guess

[kind hawk]

yes you can do that here to find some of the values at least

but not all of them

[sage dagger]

I see

[obtuse pebble]

@sage dagger Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hexed violet]

so 3/ (square root 5x) - 3

i did try to rationalize and got 5x - 3(square root 5x) - 3(square root 5x) + 9

that doesnt seem right, cuz i wanted to get rid of the square root

[inland matrix]

$\frac{3}{\sqrt{5x}-3}$

[warm shale]

Lorentz

[inland matrix]

This your q?

[hexed violet]

yup

[timid silo]

Show your work. Fully.

[high lily]

when rationalising stuff like this, you'd want to use
conjugates, applying the difference of two squares identity

[hexed violet]

I multiplies both num and dem by (square root 5x) - 3

[high lily]

which is why it didn't work

[inland matrix]

Do it + 3 instead

[hexed violet]

bet

5x - 9 (so i rationalize with the opposite sign?)

[inland matrix]

Yes

What you multiplied with is the conjugate
In this case it was sqrt(5x) + 3

[timid silo]

[
\f c{a\pm b} \c b{\cd \f{a\mp b}{a\mp b}} = \f{c(a\mp b)}{a^2 - b^2}
]
is the general procedure, as an fyi

[hexed violet]

ah bet makes sense

@timid silo @inland matrix thx so much

.close

[obtuse pebble]

Channel closed

Closed by @hexed violet

Use .reopen if this was a mistake.

[inland matrix]

Np

[timid silo]

dont forget @high lily smh

[hexed violet]

mb @high lily thx

[high lily]

would prefer not to get pinged

but ty

[hexed violet]

...mb

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lethal breach]

hello, i made this question yesterday, but still couldn't get to understand the equation, I was trying to understand how the 2 divisions circled in blue ended as 1/1, i was told that they factor out, but i don't understand how they do so, the one circled in green shows that the division doesn't end in a 1/1, since 2^98/2^99=2^0 which is 1, and 2^1 which is 2, so how did they blue divisions ended as a 1/1? i don't get it, can anyone walk me through it?

[royal basin]

circled in BLUE?

they didn't do any cancellation to the terms that you put in blue...

[high lily]

factoring out:
pq + pr + ps = p(q +r + s)
p was factored out, which in your case is 2^98 for the numerator
and 2^99 for the denominator

$\gray{1} \cdot \red{2^{98}} + \blue{2^2} \cdot \red{2^{98}} - \violet{2^4} \cdot \red{2^{98}} = \red{2^{98}}(\gray{1} + \blue{2^2} - \violet{2^4})$

[warm shale]

ℝαμΩℕωⅤ

[high lily]

the above shows what is happening in the factorisation process for the numerator

[lethal breach]

i see what they did, but i don't understand how they can get the result of 1 out of it; Did they divided both 2^98's by each other? what calculus did they did between the 2(2^98's) that resulted in 1?

[high lily]

where

$2^{98} \times \what = 2^{98}$

[warm shale]

ℝαμΩℕωⅤ

[lethal breach]

it's 1

[high lily]

yes

that's where that gray 1 above comes from

if that's the 1 you're referring to

[lethal breach]

but there is 3 2^98's you can't just remove the other 2 can you?

[high lily]

do you know how to expand stuff?

e.g.
how would you expand
p(q + r+ s)

[lethal breach]

pq+pr+ps?

[high lily]

yes

and factorisation is the process of going from stuff like
pq + pr + ps
back to
p(q +r + s)

p was factored out here, the same was done with the 2^98 above (coded in red)

[lethal breach]

oh i think i see, so it was like, wait...it's because the 2^98 is multiplying the 2^2 and the -2^4, so they just retracted or factored to represent anew? they just rewrote that bit they didn't really solved anything in that part just yet, that's what happened...?

not sure i phrased it very clearly

but i think i get it

[high lily]

all that can be summarisesd as factorisation

but yeh, that's what factoring does

takes out the common product and expresses the sum as a product

[lethal breach]

i just don't understand how to know that was the right way to do the calculus, i just went straight to division, but i thank you a lot for the explanation, i was having a hard time figuring this out.

[high lily]

you could divided numerator and denominator directly by 2^98 directly if you wanted without explicitly factoring

result will be the same, skips a step too

[lethal breach]

ok, i did the calculus and could understand it, so this one is closed, thanks again.

.close

[obtuse pebble]

Channel closed

Closed by @lethal breach

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

If you have a right-angled triangle and you need to find the delta. The hypothoses is 7 and adjecent side is 3 and you solve delta with cos like normal can you also use pythagoras to get the opposite side and then do like sin(0)=_/58 ÷ 7

[high lily]

you need to fix your values though

you didn't apply pythagoras properly

how are you getting sqrt(58)

[royal basin]

!original

[obtuse pebble]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[royal basin]

also

• don't write theta as zero
• don't write square root as _/
• don't write division as ÷

[obtuse pebble]

@timid silo Has your question been resolved?

[royal basin]

@timid silo show us the problem as it was originally stated please

[timid silo]

There was no problem

I did it my self

[royal basin]

then tell us what you're doing in a way we can understand

maybe a diagram

right now i personally don't understand what you're going for at all

[final thunder]

From what you said, you didn't use the pythagorean theorem properly.

[3^2 + x^2 = 7^2]

[warm shale]

Pure

[timid silo]

.close

[obtuse pebble]

Channel closed

Closed by @inner hinge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hybrid glade]

i need help finding x and y

[hybrid glade]

i think i sort of understand the first one but the second one im not sure about

[obtuse pebble]

@hybrid glade Has your question been resolved?

[robust bloom]

What grade are you in?

[untold badge]

what do the interior angles of a quadrilateral add up to?

[hybrid glade]

9

[robust bloom]

Ok

find x in fig b by asp of quad

assuming the lamp posts are parallel

angle y will form corresponding interior angles

with angle 40+75

[hybrid glade]

oh so 65°

cause it's a z right

like this

cause don't u do 40+75 = 115

and then 180-115

[robust bloom]

Yeah

@hybrid glade

type .close

[hybrid glade]

wait

but how do I find x

[short ore]

quadrilateral angles add to 360

[short ore]

@hybrid glade

[obtuse pebble]

@hybrid glade Has your question been resolved?

[robust bloom]

@hybrid glade

yes?

use angle sum property of quadrilateral

all angles in a quad add up to 360 deg

[hybrid glade]

ohh so I do 75+80+95 = 250 and then 360-250 =110

so x is 110?

[short ore]

yes

[robust bloom]

@hybrid glade type .close

[hybrid glade]

.close

[obtuse pebble]

Channel closed

Closed by @hybrid glade

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Hell

[timid silo]

Hello

Steps please

[robust bloom]

ok

q?

[timid silo]

?

I just need to know what steps to do

I’m confused with it

[robust bloom]

all q?

[timid silo]

The top 2

Only

[short ore]

you can cut the shape into 2 shapes

[robust bloom]

Find area of each individual rectangles

[short ore]

and work out the area for both of them

and add

[robust bloom]

and add them up

[robust bloom]

its already done

[timid silo]

Is that for area

[short ore]

yes

[timid silo]

Area u add them

And perimeter u times the answer u get

[short ore]

perim is just all of the side lengths added

[timid silo]

wait the picture I sent what number do I add first

For the first one

[short ore]

for the perimeter

add all the numbers together

it doesnt matter what order you do it in

[timid silo]

Okay

And the area ?

What u do

[short ore]

do the perimeter first

[timid silo]

Okay

I got 34.5

For perimeter

Is that right

I just added the

Them

[short ore]

how did you get that?

[timid silo]

I did 12.5 plus 7.9 plus 5.3 plus 8.8

I got 34.5

How you do it then

[short ore]

13.2 is still left

and theres another length

[timid silo]

OH

[short ore]

theres another line too

between 7.9 and 5.3

[timid silo]

Yeah ik but u said I need I to do perimeter first so imma add them

[short ore]

you need to add that line too

well i shouldve said

first u need to solve every unknown line

[timid silo]

Oh so I do 7.9 plus 5.3

[short ore]

then add all the lines together

[robust bloom]

@timid silo what grade are you in?

[timid silo]

I’m in year 10 😭

Maths in trying to get better

I’m

I’m in set 2

1 in higher

Is

[robust bloom]

?

what grade?

[timid silo]

10

[robust bloom]

age?

[timid silo]

15

[robust bloom]

wtf

[timid silo]

This is just tuition homework I’m struggling on this only

[robust bloom]

I believe you are lying

[timid silo]

Nope I ain’t

I show u

[short ore]

this is a perimeter trick

[timid silo]

25.7?

[short ore]

these 2 shapes have the same perimeter

so solve the bigger rectangle

[timid silo]

12.5 + 13.2 ?

[short ore]

you need to add both twice

[timid silo]

Alr

[short ore]

cus u need to add every line

(this doesnt work for all shapes)

[timid silo]

12.5 + 12.5 + 13.2 + 13.2

[short ore]

yes

do you see how they have the same perimeter though?

[timid silo]

12.5+12.5+13.2+13.2=51.4

Yes i understand

Because the shape has the same number on each sides

[short ore]

yeah. i didnt change any of the line lengths only changed where they are

[short ore]

correct

[timid silo]

Where do I put 51.4

[short ore]

thats the perimeter

[timid silo]

51.4?

[short ore]

because its all side lengths added together its the perimeter

[timid silo]

Okay

What’s area

Don’t understand why

That

[short ore]

for the area split the shape into 2 rectangles (which u or ur teacher has already done)

[timid silo]

Yeah teacher

Done it for me

[short ore]

and you find the area of both

then add

[timid silo]

Alr thank you

[obtuse pebble]

@timid silo Has your question been resolved?

Channel closed

Closed by @sly silo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.