#help-10

1 messages · Page 289 of 1

timid silo
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xt + 4t?

tardy epoch
#

no

timid silo
#

...

tardy epoch
#

xt becomes x(x+4)

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because t=x+4

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so xt + t becomes ?

timid silo
#

it becames..

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hmm

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hmmmmm

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it becames xt + 4t..?

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I'm sorry if I'm dumb

tardy epoch
timid silo
#

..

tardy epoch
#

t seems to be tripping you up too much

timid silo
#

it is...

tardy epoch
#

(x+4)(x+1) = (x+4) * x + ?

#

can you fill in the quesitonmark

timid silo
#

hmmm

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1!?

tardy epoch
#

no

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(x+4) * x + (x+4) * 1

timid silo
#

hmm

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I'm trying to wrap my head around this

tardy epoch
#

it's not different than

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$a(b+c) = ab + ac$

warm shaleBOT
#

riemann

tardy epoch
#

have you seen that before?

timid silo
#

YES

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I SEEN THAT..

tardy epoch
#

maybe it'd help to plug in some numbers for x and see the pattern

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try x=1 and x=2

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in here and

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in here

timid silo
#

I do the sum??

tardy epoch
#

1 * (1 + 4) + 1 + 4 = ?

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and (1 + 4) * (1 + 1) = ?

timid silo
#

$1 * (1 + 4) + 1 + 4$

warm shaleBOT
#

! Diva

timid silo
#

wait..

tardy epoch
#

i'm asking if you can calculate that as a single number

timid silo
#

it comes as

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$(1+4)(1+4)$

warm shaleBOT
#

! Diva

timid silo
#

right

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the result I mean

timid silo
timid silo
#

then the rest is also 1 + 4

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so then tis 1+4 1+4

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and it's double so

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oh wait

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nevamind..

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it's (1 + 4)^2

tardy epoch
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which is 10

timid silo
#

OHHH

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youe eight

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yes it's 10..

tardy epoch
timid silo
#

o

tardy epoch
timid silo
warm shaleBOT
#

! Diva

timid silo
#

soo

#

22

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I THINK it's 22

tardy epoch
#

,calc 2 * (2+4) + 2 + 4

warm shaleBOT
#

Result:

18
tardy epoch
#

it usually helps to do smaller calculations first

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so like 2 + 4 = 6

tardy epoch
timid silo
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I did

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2 + 4

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first

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I meanoo

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oops

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I mean I did 2 times 2 and 4 first

tardy epoch
#

ummm maybe this is a pemdas problem

timid silo
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isn't it multiplication first..

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then.

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addition..

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OH

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Oh

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Oh

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OH

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PARENTHESIS

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SORRY

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I forgot about it

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that's 18.

timid silo
tardy epoch
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correct

timid silo
#

..

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I understand neow..

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But..

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BUT.

timid silo
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what I learnt is that u take the term and then

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like

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u take x + 4

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then u

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devide it

tardy epoch
timid silo
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by x

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and then

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x + 4

timid silo
#

$x+4(x+1) = x+4 * x + x + 4 * 1$

warm shaleBOT
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! Diva

timid silo
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I give up

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how to close..

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.close

obtuse pebbleBOT
#
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tardy epoch
#

review that

obtuse pebbleBOT
#
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wanton temple
#

Is there an easy way to find this’ tangent/derivative

wanton temple
#

y = 2sin(Pi*x - y)

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at (1,0)

tardy epoch
#

easier than what?

empty cypress
#

kinda ugly derivative, but thats surely the best way

obtuse pebbleBOT
#

@wanton temple Has your question been resolved?

wanton temple
obtuse pebbleBOT
#

@wanton temple Has your question been resolved?

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final thunder
#

!15m

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

final thunder
#

what have u tried

honest reef
#

what have you tried?

#

is this statement even true bruh

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If the derivative tends to − ∞ as x approaches 0 from the right, it would suggest that the function is decreasing without bound as it approaches 0 from the right, so f(x) would be tending to − ∞

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@final thunder AM i Trolling

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I see, that's a good point

warm canopy
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this example has the derivative approaching infinity but in your question its approaching -infinity

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oh but just take -lnx

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gotcha

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well what kind of tools do you have at your disposal

obtuse pebbleBOT
#

@hybrid steppe Has your question been resolved?

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celest radish
#

Hello. I didn't quite understand how to solve these problems at class, could anyone explain the algorithm? Very appreciated. (You can use first task as an example)

celest radish
#

Also ping me when you're answering please.

obtuse pebbleBOT
#

@celest radish Has your question been resolved?

warm shaleBOT
final thunder
#

@celest radish

celest radish
#

Someone has already explained it in my dms, but still thanks!

#

.close

obtuse pebbleBOT
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pale coral
#

<@&286206848099549185>

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

pulsar quarry
#

!1c

obtuse pebbleBOT
#

Please stick to your channel.

pulsar quarry
#

!15m

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

final thunder
#

.close

obtuse pebbleBOT
#
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final thunder
obtuse pebbleBOT
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full oar
#

is the volume 481.76 or 4847.22

#

because is the formula for volume, 1/3pi(r^2)(h) or pi*(r^2)(h/3)

obtuse pebbleBOT
#
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full oar
#

huh

#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
timid silo
#

.clode

#

.close

obtuse pebbleBOT
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stone gorge
#

i need help with finding the domain for this

obtuse pebbleBOT
thorny veldt
#

(0, Inf) is what im coming up with

stone gorge
#

i thought that as well

#

its not correct

#

<@&286206848099549185>

robust raven
#

x > 0 and 40 - x >0, then find intersection

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$x\in \left( 0,40 \right)$

warm shaleBOT
#

Joanna Angel

stone gorge
#

0<x<40?

robust raven
#

nods

stone gorge
#

?

#

yes?

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alr thank you

#

how would i go ab solving the domain for this?

frank dome
#

the change of base thing could be helpful here

stone gorge
#

huh?

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how would i find the domain?

obtuse pebbleBOT
#

@stone gorge Has your question been resolved?

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pure nacelle
obtuse pebbleBOT
pure nacelle
#

I need someone to explain how in aN 0-1 is -t and 0- -1 =t

#

I have no idea what is going on here

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like I understand everything up until aN is calculated

#

<@&286206848099549185>

obtuse pebbleBOT
#

@pure nacelle Has your question been resolved?

pure nacelle
#

<@&286206848099549185>

obtuse pebbleBOT
#

@pure nacelle Has your question been resolved?

obtuse pebbleBOT
#

@pure nacelle Has your question been resolved?

pure nacelle
#

<@&286206848099549185>

obtuse pebbleBOT
#
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obtuse pebbleBOT
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oblique sun
obtuse pebbleBOT
oblique sun
#

Hello,

I tried to make a tangent, but I'm not sure if I made the intersections correctly and if overall it's right. Thank you very much for any advice and correction.

#

The problem was that I could not cancel 2x + 6, and 2x+3 so it made it more difficult for me to find the intersections

#

It’s the point 5 in the picture

obtuse pebbleBOT
#

@oblique sun Has your question been resolved?

obtuse pebbleBOT
#

@oblique sun Has your question been resolved?

atomic dust
#

what is the question

#

i cant see a single thing

oblique sun
#

To the function

atomic dust
#

well that depends

#

do you have any questions in particular

#

The tangent to the graph of a function y = f(x) at the point (a, f(a)) is the line that passes through the point with the same gradient.

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-thats what our teacher told us

oblique sun
#

Would you help me how to find the points so that I can graph it

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I did it this way..

atomic dust
#

i'm sick and my temp is like 39 degrees but i'll do my best

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😔

oblique sun
#

But I could not cancel 2x+6 and 2x+3

oblique sun
atomic dust
#

thanks for your kindness

#

do you know desmos btw?

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thats quite helpful

#

to find a point you can find the x and y intercepts

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oh wait i think you did that

oblique sun
#

Like I used the rule yeah

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But usually then I can cancel it

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But in this one it’s different and it for me confused

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If that makes sense

atomic dust
#

ok so i got the x and y ints

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(1,0)

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(0, -1/3)

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have you learnt what a "normal" is ?

oblique sun
#

Not sure… how did you get (0,-1/3) please

atomic dust
#

i'm so sorry if thats not what you asked for

#

also i think i might know how to find the tangent for a hyperbola

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y-b= -b/a(x-a)

oblique sun
atomic dust
#

i think a and b might be points not sure tho havent learnt that one very well

oblique sun
#

Thank you though a lot!!

#

It did help

atomic dust
#

no worries

oblique sun
#

:)get well

atomic dust
#

did you still have any questions ?

oblique sun
#

No!

atomic dust
atomic dust
oblique sun
#

Thank you!

#

.end

#

.close

obtuse pebbleBOT
#
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mint nebula
#

Find rational numbers x and y for this ecuation

mint nebula
#

I'm kinda stuck, although I can see some similarities between x^2 + y^2 + 2x* sqrt(2) and (a+b)^2

#

Although it's not quite

sour jacinth
#

Try making whole squares

#

Do you know about the circle equation?

mint nebula
#

No, not really.

sour jacinth
#

Ok

#

Try making something like (x-a)² +(y-b)²=c

mint nebula
#

Hm...

#

I can't seem to be finding something like that

high lily
#

have you learned about completing the square?

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

mint nebula
#

Thank you anyways!

obtuse pebbleBOT
#
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sacred anchor
#

I'm reading Velleman's How to Prove It and came across a statement I don't understand. I'm reading this as "x is an element of the integers such that x equals itself" which seems universally true and I would have expected the truth set to be the integers. Is this a mistake in the book or am I missing something important?

sacred anchor
obtuse pebbleBOT
#

@sacred anchor Has your question been resolved?

wary bobcat
#

looks like a misprint

#

presumably they meant something like ${x\in\mathbb{Z}|x\ne x}$

warm shaleBOT
obtuse pebbleBOT
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dense geyser
obtuse pebbleBOT
dense geyser
#

Find the range in which x lies

obtuse pebbleBOT
#

@dense geyser Has your question been resolved?

dense geyser
#

<@&286206848099549185>

dense geyser
#

<@&286206848099549185>

austere panther
#

@dense geyser So I do not exactly know how you get the solution for that manually, but using my Calculator I got thishttps://cdn.discordapp.com/attachments/758338411852857385/1175386995380469840/72199727301__949FCB7A-413A-49BB-9ECD-E7124464B615.mov?ex=656b0b71&is=65589671&hm=903dbb14452f8c82f4be9589cb5e1182009e8062b582c8a1ed1c78bd2b00268e&

#

Dunno if that even helps at all

dense geyser
austere panther
#

Yeah no worries, sorry I can not do any more :/

dense geyser
#

Its ok

willow crater
#

@dense geyser

#

U open the bracket first

#

Hey?

dense geyser
#

Yes

dense geyser
willow crater
#

What did u try can u show?

#

! status

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
willow crater
#

can u show what step u reached on paper or type it?

dense geyser
#

Ok

#

@willow crater

true summit
#

yo

#

this implies 0.3?

dense geyser
#

Yes

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0.3 is 3/10

true summit
#

did you take it to lhs

dense geyser
#

Yes

true summit
#

1 sec

#

lemme try myself

#

then giving suggestions would be better

dense geyser
#

Yes

willow crater
#

Factorizing the cubic there is the real Problem

dense geyser
#

Yes

willow crater
#

Is calculator allowed?

cinder lintel
#

Cubic?

dense geyser
#

No

cinder lintel
#

Just factor the x²-3x-4

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And cancel x-1

dense geyser
#

What

cinder lintel
dense geyser
#

Yes

#

Let me give it a shot

cinder lintel
#

Factor the denominator

true summit
#

not helping

#

nothing is cancelling

#

wait lemme check i think i did calc wrong

cinder lintel
#

It is cancelling

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If i didnt fsctor wrong

true summit
#

hast did you get?

cinder lintel
#

I did infact factor wronf

true summit
#

i got x-4, x+ 1

dense geyser
#

Yes

#

Same

cinder lintel
#

Ye

true summit
#

numerator is x-1 , x-1 , x-2

dense geyser
#

X+2

true summit
#

oof i think gotta introduce 0.3

dense geyser
#

Not x-2

true summit
#

wasnt x-2 given?

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oh mb eyes

#

its x+2

willow crater
#

Thats just before we made rhs 0

dense geyser
#

Yes

willow crater
#

We gotta find what happens after all the lcm stuff

true summit
#

yeah

dense geyser
#

Can you find 0 of the polynomial

dense geyser
willow crater
true summit
#

gotta simplify

#

imma try to do that ig

dense geyser
#

Im very sure its cprrect

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Correct

willow crater
#

10x3+3x2-39x+8

#

?

dense geyser
#

Yes

willow crater
#

Ok

cinder lintel
#

Should be a 10 in the denominator isnt it

dense geyser
#

If we multiply both sides by 10

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It cancels out

cinder lintel
#

Eh true

willow crater
#

the zeroes of the numerator on calc are not simple

dense geyser
#

What are they

true summit
#

does x = 4 satisfy the numerator?

willow crater
#

Nope

true summit
#

nvm

#

this shouldnt be this then we doing something unnessary

#

you sure thats 0.3..

dense geyser
#

Yes

true summit
#

cool

dense geyser
#

Its in book

true summit
#

ofc

#

and we have to find range and not domain.

dense geyser
#

Yes

true summit
#

cool

willow crater
#

whats the soln

#

i mean answer

dense geyser
#

(- Infinity,-2) U (-1,4)

true summit
#

wow.

dense geyser
#

It might be wrong because there are many wrong answers in book

bright moth
true summit
#

and not 0.3

willow crater
#

What is the name of this book

true summit
#

thats crazy

#

i smell missprint perhaps?

willow crater
#

if rhs is 0 then -2 should be included in range

#

not excluded

true summit
#

true missed that

willow crater
#

this is a scam question

true summit
#

lmao

cinder lintel
#

💀

true summit
#

na but like crazy cubic in range

#

hella fishy

willow crater
#

Its purpose is to waste our time

#

bye

true summit
#

it feels wrong

#

compedition breaker

dense geyser
#

No

#

No

true summit
#

?

dense geyser
#

Its lokmat kaun banega ramanujan

#

Its a competition preparation booklet

true summit
#

thats the name?

dense geyser
#

Yes

#

Its not available online

true summit
#

"lomat kaun banega ramnujan"

dense geyser
#

Yes

true summit
#

cool.

dense geyser
#

They might have put these questions on purpose

true summit
#

na man ask your teacher

dense geyser
#

To waste the participants time and trick them

true summit
#

something feels wrong

dense geyser
#

I am not going to get trapped

true summit
#

..

dense geyser
#

Ok my time is wasted anyway

#

Ill ask my teacher too

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And waste his time

#

Hehe

#

I should leave this channel open to see if anyone knows how to solve it if it can be

dense geyser
#

Ok

#

.close

obtuse pebbleBOT
#
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swift bloom
obtuse pebbleBOT
swift bloom
#

ive expanded the brackets

#

im at

#

y^2 + a^2 + 2ay = y^2 + 10y + b

#

now what

frigid harness
#

you can compare coefficients

swift bloom
#

thats what i struggle to understand 😭

#

coefficients and constants

frigid harness
#

and notice they are equal

#

so we can say that 2a = 10

#

as both are coefficients of y

swift bloom
#

yh

#

a = 5

frigid harness
#

yes

swift bloom
#

then how do i get b

frigid harness
#

now can you notice anything else about how a and b are related?

swift bloom
#

both positive integers?

frigid harness
#

what else

swift bloom
#

erm

frigid harness
#

note for a we did:
2ay = 10y
2a = 10
a=5

we can do something similar for a and b

swift bloom
#

a^2 = b?

frigid harness
#

yes

swift bloom
#

oh so b = 25

frigid harness
#

yes

swift bloom
#

and the y^2 cancels each other out

#

right?

frigid harness
#

yes, but you don't really have to think much of that

#

I suggest you watch some videos about comparing coefficients to understand it better

swift bloom
#

boss

#

ive ran into another problem

#

its not right

frigid harness
#

oh we forgot to subtract 4 for b

#

so b should be 21

swift bloom
#

ohhh

#

thanks

#

,close

#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
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crude mountain
#

Hii, i need help with this. I found that triangle ABC is similar to DEC but i can’t continue.

obtuse pebbleBOT
#

@crude mountain Has your question been resolved?

glossy yacht
#

what's $$\int 2x dX$$

warm shaleBOT
#

Xetrov

timid silo
#

x^2

drifting roost
obtuse pebbleBOT
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Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

glossy yacht
crude mountain
indigo oyster
crude mountain
#

can you please explain the part where you get EF=8

indigo oyster
#

Wait to transalte whit goolge transalte upcoming parts im not know good english

#

Using the 30 degree theorem yielded that it is 8 because we know that the cathet opposite the hypotenuse is half of the hypotenuse

crude mountain
#

Yes i understand that but im still confused on how we know it is a 30-60-90 triangle because I used the similarity rule and found a few same angles and sides and DE resulted 6 cm because I found that triangle DEC is isosceles too but Im not sure how correct I am.

crude mountain
#

@indigo oyster

obtuse pebbleBOT
#

@crude mountain Has your question been resolved?

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brave juniper
obtuse pebbleBOT
#

Please don't occupy multiple help channels.

rich plume
robust raven
#

Let F be the middle of the AB, then due to Pithagor , FD can be computed, and let G be the common poinf of FD and semicircle AB, etc. that is a plan of solution

obtuse pebbleBOT
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timid silo
obtuse pebbleBOT
timid silo
#

How?

#

Why is there a 4 on top?

#

I know the bottom it's multiplying

#

The top shouldn't have an S?

final thunder
#

okay my student's apprentice is here

pulsar quarry
#

nah im not

final thunder
#

ur time to shine help xigma bro

final thunder
# timid silo

well basically u know how when we add fractions you need a common denominator

timid silo
#

Nvm

#

I understood it

final thunder
#

well done

timid silo
#

I just bugged a bit

#

Thanks

#

.close

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final thunder
obtuse pebbleBOT
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full oar
obtuse pebbleBOT
full oar
#

Find the volume

#

idk what the formula is or how to start

obtuse pebbleBOT
#

@full oar Has your question been resolved?

full oar
#

<@&286206848099549185>

civic socket
warm shaleBOT
#

Akira (fumo)

full oar
#

ohh

full oar
civic socket
#

yes

full oar
obtuse pebbleBOT
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high stag
#

can someone help me with understanding the proof? I can translate if necessary

high stag
#

spur(A) is the same as tr(A)

#

whenever i calculate this my result is n-1 = tr(A) for t going to 0 but that doesnt seem right

versed pier
#

the only german word I know is eigen 😭

high stag
#

ok so we have the function of the determinant and it is to show that the uniform Matrix I_n (the one with only ones on the main diagonal) and some random Matrix A if u calculate the differential quotient of the determinant funktion in respect to A gives you the trace tr(A).Is that understandable?

#

They give us the hint that th characteristic polynomial might be useful here but i dont see a way how i can implement that here :/

robust raven
#

you want to prove the another formula for the trace of the matrix, it is clear

high stag
robust raven
high stag
#

ah okay yes so basically the equality of the main statement dA(I_n)=...=tr(A) is to prove yea

robust raven
#

🙂

#

$detA=\prod_{i}^{}\lambda_{i}$

warm shaleBOT
#

Joanna Angel

robust raven
#

lambdas are eigen values

#

and also

#

$trA=\sum_{i}^{}\lambda_{i}$

warm shaleBOT
#

Joanna Angel

robust raven
#

those are hints

high stag
#

okay thank you verymuch i will try this rn

#

but i always get sth wrong out of it

#

how can i use the eigenvalues correctly maybe im doing it wrong?

#

cause det(tA+I_n) would just be t^n * the product of th eigenvalues + n or am i wrong?

#

and for the limit if t goes to 0 then 0*product of eigenvalues cancels out and we are just there with n for the tr(A)

robust raven
#

have you heard, in matrix calculs, about Jacobi's formula ?

high stag
#

we havent had that :/

robust raven
#

the formula you need to prove is the another form of this Jacobi's formula

high stag
#

oh okay, i see i googled it, i will try this over the next few days then and come back if this doesnt work out thank you very much 🙂

robust raven
#

yes sure, i do not want totake a satisfaction from you )

#

it is worth to work on it )

high stag
#

nice xd have a great day ^^

#

.close

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woeful portal
#

true or false

obtuse pebbleBOT
woeful portal
#

can this be done?

warm canopy
#

Yeah that's fine

woeful portal
#

ty

#

what about the f is homogenous of 3rd degree

#

ignore it

warm canopy
#

Seems like you don't need it

woeful portal
#

thx

#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
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timid silo
#

Can somebody help me with this proof? i kinda have no idea how to do it, i tried just writing everything with epsilon N definition by it didn't led me to anything.

Sequence $a_n$ where $a_n \neq 0$ fulfills the condition that $\lim{n\to\infty} |\frac{a_{n+1}}{a_n}}| = q$ where q < 1. Show that $\lim{n\to\infty} a_n = 0$

warm shaleBOT
#

MrTrim
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

robust raven
#

as a hint please read the proof of d'Alemebert criterion fo rserieses

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delicate estuary
obtuse pebbleBOT
delicate estuary
#

I'm reviewing my notes right now and I came across this question. Does anyone know what type of limit this is called?

#

I know how to solve it though

#

.close

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limpid plume
#

Hi,

obtuse pebbleBOT
limpid plume
#

I need to create a word problem to give the reader enough information to formulate two quadratic equations, in order to find their intersection points.

y = x^2 - 6x + 11
y = -x^2 + 4x + 3

The first equation represents an investment prediction on the stock market, with x being time in months and y being yield in %. The second equation represents Certificate of Deposite (CD) predictions, with the same variables. They intersect at points (1,6) and (4,3) and the reader needs to set up the equations and then figure out when they produce the same amount of yield percentage. Can anyone help me with setting up the word problem to give hints? This is what I have so far:

#

Pythagoras, a Stock investor, and Euclid, a Certificate of Deposit (CD) investor decided to use AI to predict the future of their preferred markets.

#

Also, here's an example of a word problem for a circle equation and a linear equation intersecting with the same concept of setting up and solving.

Mateo runs straight through the circular path of a sprinkler in a game to avoid getting wet. The path of the sprinkler has a radius of 5 ft from its head. If he first enters the path of the circle at a point 1 ft to the west and 8 ft to the south of the sprinkler heads and exits the path at 4 ft to the east and 7 ft north of the sprinkler head, what system of equations would model the paths of Mateo and the sprinkler? When will he cross the sprinkler's path?

#

Ping me if you can help.

#

No it's not

#

It's y = x^2-6x+11 and y = -x^2+4x+3

#

I made the equations

#

Whoever can help please ping me.

#

I just need help setting up a word problem.

slim cove
#

Please don't interrupt other people's help channels if you're not helping.

obtuse pebbleBOT
#

@limpid plume Has your question been resolved?

obtuse pebbleBOT
#

@limpid plume Has your question been resolved?

limpid plume
#

Should I just give 3 points for each parabola and then call it a day?

#

For the word problem

#

But then the user has to do that for each parabola

obtuse pebbleBOT
#

@limpid plume Has your question been resolved?

limpid plume
#

.close

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neon pecan
#

Would it be possible to set this up as a definite integral from 2 to 1. My friend did this method but i did a indefinite integral and solved in terms of C

shut lagoon
#

f(2)-f(1) = int f'(x) dx from 1 to 2 (using FTC).

#

Then you can solve for f(1)

#

You'll end up doing the same operations though so I feel like both methods are fine.

neon pecan
#

Okay then thanks

#

.close

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hot mango
#

how do i solve: which line is parallel to y-3x=-4

hot mango
high lily
#

convert the given line to slope-intercept form to identify its slope

hot mango
#

what is slope intercept form?

timid silo
#

Fr

high lily
#

y = mx + b

hot mango
#

oh am i meant to rearange this equation?

high lily
#

solve for y

timid silo
#

U don’t need to solve for y

high lily
#

doing algebraic manipulation

#

!occupied

obtuse pebbleBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

hot mango
#

so am i meant to get y on its own?

high lily
#

yes

timid silo
#

Yeah just don’t solve for it

hot mango
#

so i add 3x

#

and do it on the other side?

high lily
#

the result of getting y on its own will give you the slope-intercept form equation

#

yeh, you add 3x to both sides in the same step

hot mango
#

so this give me y=-4+3x?

high lily
#

first step would be claiming your own personal channel (following directions above instead of invading someone elses channel)

high lily
hot mango
#

oh yes

#

gradient is 3 and y intercept is -4

#

is that correct?

high lily
#

yeh

#

<@&268886789983436800> (z monster was being intrusive with annoying gifs, deleted now)

hot mango
#

thanks

#

.close

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fringe quest
#

are we squaring both sides on the first step to cancel out the square root operation?

outer needle
#

looks like it yes

fringe quest
#

ok ty, just wanted to make sure there wasent more to it

#

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harsh remnant
#

Hello

obtuse pebbleBOT
harsh remnant
#

What did I do wrong here?

#

For which integral?

robust raven
#

second, i jst write this formula in diff way, i mean symbols

harsh remnant
#

How should I fix it?

robust raven
#

you know that ln e = 1 ?

harsh remnant
#

Yes

robust raven
#

on right side

#

-e + 1

#

beucase you have - (e - 1)

harsh remnant
#

Oh wait

#

I see

robust raven
#

so finally you get =

#

e - 2

#

but all is very well

harsh remnant
#

Thank you so much 🙂

robust raven
#

when i use trick with function 1, i callit as g' = 1

#

haha so that was my eventual concern

#

but you can name it as you wish

#

🙂

harsh remnant
#

xD

#

.close

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oak knot
obtuse pebbleBOT
oak knot
#

hi can someone please help me find the error

#

supposedly the answer is

#

ive been staring at it for ages now

empty cypress
timid silo
#

literally teh same thing

empty cypress
#

yeah simplify the supposed answer and you get yours 👍

oak knot
#

Bro no way 😭 im terrible at this

#

THANK YOU

#

all

#

.close

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verbal bane
#

Need help with this

obtuse pebbleBOT
empty cypress
obtuse pebbleBOT
# verbal bane Need help with this
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
verbal bane
#

3

empty cypress
#

which answer, and what did you get

#

and show your work, if available

verbal bane
#

a) [pi/2,pi]

empty cypress
#

cos(pi/2) is 0, which is not less than 0

verbal bane
#

So (pi/2,pi)?

empty cypress
verbal bane
#

Cool

#

.Close

#

.close

obtuse pebbleBOT
#
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swift latch
#

How would we do part c? We have the answer 200/ w(w+1) but we dont get why there are two widths

shut lagoon
#

What is the initial length of the board?

swift latch
#

200/w

shut lagoon
#

Good

#

Now it you add 1 to the width

#

What is the new length?

swift latch
#

200/w+1

shut lagoon
#

Ok

#

So the variation is 200/w - 200/(w+1) correct?

#

Put those on a common denominator.

swift latch
#

Wait wait-

swift latch
shut lagoon
#

The change in length

swift latch
#

Okay

#

Makes sense

shut lagoon
#

Is the difference between the initial length and the final length

swift latch
#

sorry, that was a stupid question

shut lagoon
#

It's ok

#

It is worded weirdly tbf

swift latch
#

200/w - 200/(w+1) = l

#

Right?

#

😭 I am so sorry, idk why I am struggling with this so much

shut lagoon
#

It's ok

#

Let's call the initial length L1

#

and the final length L2

#

Question C is asking for the change in length

#

So L1 - L2

#

This is what you are trying to express in terms of w

swift latch
#

Yeah

shut lagoon
#

Now we saw that L1 - L2 = 200/w - 200/(w+1). However, this can be simplified further.

swift latch
#

Yes

#

It's 200(w+1) - 200(w) right?

#

Oj wait nvm

shut lagoon
#

That would be the numerator

#

You're missing the denominator there.

swift latch
#

Right 😭

#

Okay I did it

#

Tysm 😭

shut lagoon
#

No worries!

swift latch
#

.close

obtuse pebbleBOT
#
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sharp hare
obtuse pebbleBOT
sharp hare
#

I determined the eigenvalues and found the bases for the eigenspaces

#

everything looks fine, and it can indeed be diagonalized

#

for the matrix Q i tried setting up a matrix with the 3 vectors from the eigenspaces

#

but it doesnt work

#

QAQ^-1 doesnt equal a diagonal matrix when I try?

#

<@&286206848099549185>

timid silo
obtuse pebbleBOT
#

@sharp hare Has your question been resolved?

obtuse pebbleBOT
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glacial agate
obtuse pebbleBOT
glacial agate
#

<@&286206848099549185>

fathom flicker
#

!15mins

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

fathom flicker
#

!status

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
glacial agate
#

1

fathom flicker
#

Explain what you have tried

glacial agate
#

nothing because i've never done scale of enlargement before

fathom flicker
#

You could then start by finding a video on the topic, like youtube or khan academy

#

and if you then still do not understand and are stuck, explain here why

glacial agate
#

okay

#

solved it

#

(3, 5)

fathom flicker
#

great, .close the channel if you're question has been resolved then

glacial agate
#

i had to work out how to get point a to x then multiply it by the scale factor

#

.close

obtuse pebbleBOT
#
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wild shoal
#

Could someone please confirm if Q2 a is correct

pulsar quarry
#

,rccw

warm shaleBOT
wild shoal
#

and could I also have some help with part c please

obtuse pebbleBOT
#

@wild shoal Has your question been resolved?

wild shoal
#

<@&286206848099549185>

robust raven
#

there are following rules:

#
  1. shift to the left a units means you write : y = f(x+a)
#
  1. shift to the right a units means you write : y = f(x-a)
#
  1. shift b units upward means you write : y = f(x) + b
#
  1. shift b units downward means you write : y = f(x) - b
#
  1. stretch it in the vertical direction by a scale factor of A , you write y = Af(x)
#
  1. stretch it in the horizontal direction by a scale factor of B, you write y= f(x/B)
#

and that is all

#

please apply it

#

to yoru c.

#

and show me

#

certainly, you can apply few rules in same time,

wild shoal
robust raven
#

moemt i write and i show you comparison too

wild shoal
#

Yeah I just want to clarify one thing when I do a dilation with the original (x-2) I take out 1/5 for both of them then add 3?

#

BTW thank you for writing all those out

robust raven
#

🙂

#

$y=\frac{1}{3}\cdot \frac{1}{\frac{1}{5}\cdot \left( x+3 \right)-2}-2$

warm shaleBOT
#

Joanna Angel

robust raven
#

plz compare it with your case

#

i wrote it fo royu, with all 4 rules

wild shoal
#

ok cool so the horizontal just gets subbed in for x

robust raven
#

and when you want to give it as an aswer, then rather you should simplify tis form

#

at least i require it

wild shoal
#

yeah so it becomes 5/3(x-7) -2

robust raven
#

let me check it

#

yes all correct)

wild shoal
#

ok cool thank you very much for your help

robust raven
#

plz write in all thos erules in soem exercise book to not lose it )

#

your very welcome )

wild shoal
#

.close

obtuse pebbleBOT
#
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spice solstice
#

someone who knows about this can tell or teach me what to do?

spice solstice
#

<@&286206848099549185>

robust raven
#

the first way is:

#

$A\bigtriangleup B = \left( A\cup B \right)\smallsetminus \left( A\cap B \right)$

warm shaleBOT
#

Joanna Angel

robust raven
#

the second way is:

#

$A\bigtriangleup B =\left(A\smallsetminus B \right)\cup \left(B\smallsetminus A \right)$

warm shaleBOT
#

Joanna Angel

robust raven
#

so plz use them for yoru sets

dense pebble
#

Hey guys, do you have any recommendations for free books/questions/exercises with solutions in Linear Algebra, Analysis or Calculus which I can download online? Or any good websites? i'd like to solve more problems. It can be anything, from PDFs to online books to a website - share anything! Level: undergraduate, first semester math.

obtuse pebbleBOT
#

@spice solstice Has your question been resolved?

obtuse pebbleBOT
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warm slate
#

hi i need help with making a venn diagram im a bit stuck

warm slate
#

wait im trying to find the screenshot

#

pls help im stuck with this venn diagram 🙏🙏🙏🙏

#

<@&286206848099549185> venn diagram help pleasee!!

brazen gorge
warm slate
#

yeah im just stuck on what the values for each set is

brazen gorge
#

suppose A is coastal resort, B is interstate and C is overseas

warm slate
#

mhmm

brazen gorge
#

going condition by condition:

  • 5 just A
  • 2 just B
  • 2 intersection of A B C
  • 8 just intersection of A and C
  • 20 A (including intersections)
  • ≥4 just C
  • ≥13 B (including intersections)
brazen gorge
#

this is what you are looking for

warm slate
brazen gorge
brazen gorge
warm slate
#

oh wait

#

ignore that

brazen gorge
#

okay lol

warm slate
#

wait

#

is it 4

#

@brazen gorge

brazen gorge
#

the whole 'circle' of coastal is 20

#

the part that belongs to coastal and no other set is 5

warm slate
brazen gorge
#

oh

#

uh let me check

warm slate
#

okk

obtuse pebbleBOT
#

@warm slate Has your question been resolved?

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obtuse pebbleBOT
#
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neon cypress
#

hey can someone help me convert a standard form equation into a slope intercept equation please

severe river
#

what have you tried so far?

neon cypress
#

havent tried much

severe river
#

Ill try to guide you, write down what you have to start with and your goal. That is, the standard form equation and slope interception equation

neon cypress
#

i have to do a simultaneous equation and both equations are in standard form now

#

i want to convert them to slope intercept form instead cuz i work easier with them

#

wait nvm i got it

#

.close

obtuse pebbleBOT
#
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steady lodge
#

guys i have a quiz going on , i need this , can yall please be helling me.............

steady lodge
#

ill be posting the qs i cant do here

#

pls help

obtuse pebbleBOT
#

@steady lodge Has your question been resolved?

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mint nebula
#

ABCD is a square of side a, and the point M belongs to DC so that MD = MC and MB intersected with AC = {N}. Find the area of ​​triangle ANB. I need a solve without triangle similarities, please

mint nebula
#

Drawing DB helps, I think.

#

And the fact that the area of BMC is equal to the area of BMD

#

Median's theorem

spice citrus
#

I guess you can put everything in a coordinate system

#

A = (0, 0), B = (a, 0), C = (a, a), D = (0, a)

tacit scarab
#

yeah just find y-coordinate of N

mint nebula
spice citrus
#

Have you ever done linear equations?

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

mint nebula
spice citrus
#

this is just the same

#

AC is just the line y = x

#

and MB is the line that goes through (a, 0) and (0.5a, a)

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

quiet spire
#

the answer is (a^2)/3

#

done

#

solved

civic socket
quiet spire
#

I am new to the server

civic socket
#

you're here for a week

#

have you read the rules

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

mint nebula
obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

obtuse pebbleBOT
#
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vagrant kite
obtuse pebbleBOT
vagrant kite
#

For 1D, is this right?

#

I did 10x4 and got 40

latent walrus
#

my eyes cant zoom so far

azure anchor
#

is this a screenshot for ants?

latent walrus
azure anchor
#

perimeter = outer boundary

minor furnace
#

^

vagrant kite
#

Oh I didn't know my screenshot was bad

azure anchor
#

add up all the boundaries, subtract the inner boundaries

vagrant kite
#

Wait subtract the inner boundaries???

azure anchor
latent walrus
#

every square is one unit, could just count them if you want to be speedy

vagrant kite
#

Oh its 48 right

#

Ok thanks

#

.close

obtuse pebbleBOT
#
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vagrant kite
#

I mean 44

obtuse pebbleBOT
#
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fathom echo
obtuse pebbleBOT
fathom echo
#

Help pleasr

latent walrus
#

hello again

#

!onechannel

obtuse pebbleBOT
#

Please stick to your channel.

latent walrus
#

.close

obtuse pebbleBOT
#
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pulsar quarry
#

dont ping blud

pale flume
#

mb fam

obtuse pebbleBOT
#
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tawdry patrol
#

how on earth do I do this

obtuse pebbleBOT
tawdry patrol
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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junior bone
#

This would be false I think

#

If alpha was .05, the confidence level would be 95%

mossy fjord
#

Is there more to this question, or is this all that is written?

junior bone
#

But p value is what you compare to alpha to make a decision about the hypothesis

#

Idk I have a test on this stuff tomorrow lol

mossy fjord
#

If your alpha was like 0.04, then you'd reject both. I also have a test on this tomorrow lol.