#help-10

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obtuse pebbleBOT
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static pebble
obtuse pebbleBOT
static pebble
#

Not sure what to do

static pebble
warm shaleBOT
light raft
#

let d be the total distance travelled. then, we have that 24 = a(1) + b(d-1). then we just solve for d

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do you understand how i got this equation?

static pebble
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Oohh

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I think i get it

light raft
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cool

static pebble
#

Tyy

light raft
#

nwnw

static pebble
#

.close

obtuse pebbleBOT
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tropic lantern
obtuse pebbleBOT
steel parcel
#

it seems like you rotate the shape clockwise then perform a reflection across the y axis

obtuse pebbleBOT
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earnest cairn
#

can someone help me with 11b

obtuse pebbleBOT
#

@earnest cairn Has your question been resolved?

earnest cairn
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.close

obtuse pebbleBOT
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sweet lake
obtuse pebbleBOT
light raft
#

have you done sums of arithmetic sequences?

sweet lake
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Yes

light raft
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letting a_n = -4n -3, there are 2 formulae that we can use, (i) n/2(a_1 + a_n), and (ii)n/2(2a_1 + (n-1)d), where in this case n = 31

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have you seen these formulae before?

sweet lake
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Yes the first one

light raft
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okay cool, so lets use that

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we have that n = 31 (summing 31 terms), now we need to find a_1 and a_31

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how should we do that

sweet lake
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A1 is 1 right

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Wait no

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A1 is -7

light raft
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correct

sweet lake
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Then we use a of 1 to find a of 31

light raft
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we can just directly sub in 31 into the a_n equation

sweet lake
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372?

light raft
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what were your steps?

sweet lake
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Used the equation

light raft
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a_31 = -4(31) - 3

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so a_31 = -127

sweet lake
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Nvm I see how I messed up

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Wait would that be the sum?

light raft
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nah we have found a_1 and a_31

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now we use the formula

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the sum from n=1 to n=31 is 31/2(a_1+a_31), which is...

sweet lake
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2077

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?

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-2077*

light raft
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sounds correct

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yeah

sweet lake
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tyyy

light raft
#

nw

obtuse pebbleBOT
#

@sweet lake Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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meager silo
#

Before i go any further, have i set this up correctly?

obtuse pebbleBOT
#

@meager silo Has your question been resolved?

meager silo
#

<@&286206848099549185>

meager silo
#

<@&286206848099549185>

mighty jacinth
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yo

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idk actually

obtuse pebbleBOT
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obtuse pebbleBOT
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short ore
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The answer i want is the smallest number HIJ

obtuse pebbleBOT
#

@short ore Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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chilly gate
obtuse pebbleBOT
chilly gate
#

can someone help

bronze tinsel
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Guys help please ****

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I urgently need

dark stirrup
obtuse pebbleBOT
dark stirrup
obtuse pebbleBOT
# chilly gate
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
chilly gate
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3

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<@&286206848099549185>

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pls someone

#

.close

obtuse pebbleBOT
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shrewd drift
#

Does this look right? The red question marks are where I’m not confident

pine sail
#

sin(x)/x is wrong, yes.

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You're going to have to open another channel, this one's closing soon.

shrewd drift
#

Ok

obtuse pebbleBOT
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atomic compass
#

How does D(ln5) become 0

obtuse pebbleBOT
pine sail
#

ln(5) is a constant.

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It's just like if you had something like 5 in place of ln(5)

atomic compass
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So you dont need to know what the answer is?

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What if its some infinite decimal number

pine sail
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it is some infinite decimal number.

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But even as it is, it's a constant.

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Like those infinite decimal places won't ever change.

atomic compass
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So just e becomes 0 too

pine sail
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yeah.

atomic compass
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If its just e

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Thx

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For helping

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.close

obtuse pebbleBOT
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timid silo
#

How do I determine the convergence/divergence of the following sum

timid silo
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I know that the sequence converges to 1

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Can I directly affirm that the series is divergent?

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,w sum from 1 to infinity (k(k+2))/(k+3)^2

warm shaleBOT
timid silo
#

.close

obtuse pebbleBOT
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half lodge
obtuse pebbleBOT
half lodge
#

why is my answer here incorrect?

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i took the antiderivative of each term and plugged in 5

obtuse pebbleBOT
#

@half lodge Has your question been resolved?

half lodge
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.close

obtuse pebbleBOT
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fallow cove
#

So 0 isn't a purely imaginary number right?

obtuse pebbleBOT
fallow cove
#

just checking

kind hawk
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depends a bit on your definition of "purely imaginary"

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I would generally count it because most stuff that is true for purely imaginary numbers should also be true for zero

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except for the usual problems with zero like division

dense imp
fallow cove
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ok

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thx

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.close

obtuse pebbleBOT
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last anvil
#

someone answer these for me i can't wait till the grade comes out wiggle360

last anvil
#

wymmmm

stone spoke
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Bruh y more than 1 question it’s too much for my brain to process sully

plain stag
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We don't answer questions, we help you answer them yourself

last anvil
#

i already did i just need to get em checked

last anvil
#

plsssssssssssssssssss

plain stag
#

Post your answers and we'll verify, then

last anvil
#

alr alr

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just tell me if its correct or not

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the grade won't come out until Thursday and i cant wait that long

obtuse pebbleBOT
#

@last anvil Has your question been resolved?

pine sail
#

Look right to me.

obtuse pebbleBOT
#

@last anvil Has your question been resolved?

obtuse pebbleBOT
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lilac matrix
obtuse pebbleBOT
lilac matrix
#

Im supposed to calculate the angle cfd.
Aefg and adbc are squares

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Im not sure what to do I'd appreciate your help.
I speak German and English

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This is what I've thought of so far

winter jacinth
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i have been trying it for like 15min isnt there any other information?

obtuse pebbleBOT
#

@lilac matrix Has your question been resolved?

lilac matrix
#

It's 2c
It says
We have 2 squares abcd and aefg
D is on the extension of side fg
And b is on the extension of ef

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Right now we're at the topic of
circumferential angle theorem (I google translated that I'm not sure if it's the right term)
If that helps

sinful plover
#

interesting ques.

past sand
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Let P be the intersection between AD and EF, can you say something about the triangles AEP and DFP?

lilac matrix
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The angle dpf and the angle EPA are the same?

past sand
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Yes

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Anything else?

winter jacinth
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they are simmilar triangles but what do you get from that?

lilac matrix
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EPD and apf are also the same of course but I'm not sure about what else

past sand
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What about the lines AE and FD?

lilac matrix
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They are parallel!

past sand
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Yes

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Well actually you already know AEP is a right angle and you should see PFD is too

lilac matrix
past sand
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What does that mean for the triangles?

lilac matrix
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I don't know the English word but the 2 other angles are the same size

past sand
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Yes, so all angles are equal, that's called similar triangles

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What about side lengths?

sinful plover
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wow I figured it out finally.. damn this is a really good question

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@lilac matrix try to focus on the quadrilateral BFDC

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that's your hint

lilac matrix
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Ok thank you I'm thinking

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I don't have it yet but is FDC= 135°?

past sand
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No

sinful plover
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it might be but am not sure

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do you know cyclic quadrilateral?

lilac matrix
sinful plover
#

check this out and let me know whether you know this or not

lilac matrix
#

I think we did do something like that

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But how do I know that all those points even are on the circle?

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Or are they always gonna be on a circle?

sinful plover
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ok

sinful plover
lilac matrix
past sand
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We have two very different ways of solving this

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@lilac matrix which one do you want to go for?

sinful plover
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which means when opposite angles of a quadrilateral sum up to 180 degree then the quadrilateral becomes cyclic or in other words all 4 points lie on a circle

lilac matrix
#

Which ever one is easier to understand

past sand
#

Arguably his is easier if you memorize this cyclic quadrilateral thing

lilac matrix
#

Am I allowed to take a break and ask for help later again?

sinful plover
#

channel gets closed due to inactivity I think

past sand
#

Of course lol

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Just open a new one

sinful plover
#

you can do that..but I rarely open discord

lilac matrix
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Ok thank you for all the help I'll try on my own and come back later if I don't understand

sinful plover
#

@past sand you can explain her the solution if you are present at that time

past sand
#

Sure

obtuse pebbleBOT
#

@lilac matrix Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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opaque galleon
#

Can someone explain to me how this was turned into the second line?

pseudo swift
#

what's R_X anyway ?

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@opaque galleon

opaque galleon
#

Autocorrelation function

pseudo swift
#

idk crap about this subject but it seems like
the 3R(0) corresponds to X(1)^2 + X(2)^2 + X(3)^2 (as they mentioned in a, E(X(t)^2) = 3 = R(0) for any t)
2R_X(-1) corresponds to 2X(1)X(2) (delta in time of -1)
2R_X(-2) corresponds to 2X(1)X(3) (delta in time of -2)
2R_X(-1) again corresponds to 2X(2)X(3) (delta in time of -1)

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but don't ask me what it means, I just tried to pattern match the start with the end

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@opaque galleon

opaque galleon
pseudo swift
#

they said at time t

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the only thing it can mean is that the formula works for any time

opaque galleon
#

ohh okok

obtuse pebbleBOT
#

@opaque galleon Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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brazen gorge
#

a semigroup with an identity is a monoid right

brazen gorge
#

ah okay yes

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lol

#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
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violet rapids
#

T

obtuse pebbleBOT
violet rapids
#

Problem 69

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idk what it’s looking for or idk what “determine the numbers so that their product is the greatest” means

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is it looking for the x intercepts ?

high lily
#

ultimately you want the vertex
the average of the x-intercept/roots tell you the location

violet rapids
#

ok

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I did it right then ok

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I thibk

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was it when it said “their product is the greatest” = looking for vertex ?

high lily
#

after getting a quadratic after expressing the product in terms of a single variable, pretty much

violet rapids
#

oooook

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ty

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@high lily

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are u familiar with

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synthetic divison

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division

high lily
#

yeh

violet rapids
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y = -f (x)

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we flip over the x axis

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nvm got it

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y=1/2f(x)

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it getting wider ?

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or smaler

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nvm

#

got it

obtuse pebbleBOT
#

@violet rapids Has your question been resolved?

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hidden sparrow
#

Help

obtuse pebbleBOT
hidden sparrow
#

I don’t know how to work out all parts of question 3

cosmic tulip
#

nerd

hidden sparrow
cosmic tulip
#

joke

hidden sparrow
#

Ok

cosmic tulip
#

i am gonaa live sirver

hidden sparrow
#

If I was a nerd I wouldn’t be asking for help lol

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Anyway I do need help

#

<@&286206848099549185>

obtuse pebbleBOT
#

@hidden sparrow Has your question been resolved?

hidden sparrow
#

<@&286206848099549185>

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lol I’m not getting help anytime soon it seems

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<@&286206848099549185>

timid silo
#

what is your problem with this exercise?

hidden sparrow
#

And my approach is incorrect

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So I’m lost

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No help….

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<@&286206848099549185>

hidden sparrow
#

I’m struggling how to start 3

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<@&286206848099549185>

lilac torrent
#

Are you familiar with what the modulus/argument are for a complex number and what an Argand diagram is?

obtuse pebbleBOT
#

@hidden sparrow Has your question been resolved?

obtuse pebbleBOT
#
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feral acorn
obtuse pebbleBOT
feral acorn
#

can someone please explain how 1 - 1/e approx equals to -1/e

obtuse pebbleBOT
#

@feral acorn Has your question been resolved?

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hot horizon
#

if you miltiply by 0 you can just get rid of that whole term

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0n = 0

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am i missing something?

azure badger
#

so it would just be:

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1/2n^2 + 1/2n + 1/8 i believe

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oops

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didnt see the original question

hot horizon
#

it does, 1/8 just means remainder was 1 when you divided by 8

azure badger
#

yeah

#

wait\

#

yeah

hot horizon
#

although idk how to feel about the 1/2 in the answer, i think since they are both odd it can be written to add the two 0.5s

azure badger
#

0n + 8 = 8

#

4n^2/8 = 1/2n^2

#

4n/8 = 1/2n

#

1/8 = 1/8

#

basically just dividing by 8

#

and multiplying by 8 to see the remainder of 1

hot horizon
#

½n² + ½n + ⅛
8 / (4n^2 + 4n + 1)
4n + 0 + 0
4n + 0
1

#

and since we have half an odd number plus half another there must be some way to put them together so that we aren't halving anything

azure badger
#

yep

hot horizon
#

so we have
½(4n² + 4n + 1) + ½(2n + 1) + ⅛
which is
2n² + 2n + ½ + n + ½ + ⅛
combine like terms
2n² + 3n + 1 + ⅛

still ⅛ which is a remainder 1 after division by 8

azure badger
#

ok lets put this as a number

#

3
3 * 3 = 9
9/8 = (1 * 8) + 1

hot horizon
#

R1*

#

^

#

(1 * 8) + 1 is 9

#

because remember n is our odd number so n = (2n + 1) (yeah should probably change variable names lol)

#

actually we could san n = 2p + 1

#

so then we have p^2 / 8 = 2p² + 3p + 1 + ⅛ when p is odd

#

hang on

#

no i think im wrong actually

#

actually now im just confused

#

:|

#

ok, lets say n is our odd number. n = (2p + 1).
then we square n and get 4p² + 4p + 1
we divide by 8 and get ½p² + ½p + ⅛

#

ok, so we have ½p² + ½p + ⅛
½p² + ½p must necessarily be a whole number because if you half two whole numbers and add them together the 0.5 parts will add back together into a whole 1. this means that the answer is (some whole number) + ⅛ which proves that if you divide an odd number squared by 8 you get a remainder of 1.

#

im just not sure how to put it in figures

#

yw :)

#

hmm?

#

we still haven't figured out the first one

#

it depends if an explanation via text is accepted as opposed to figures

#

but it probably is

#

so i guess you could say we have

#

its basically remainders again, your proving that a^2 mod 10 cant be 3

#

because if a number ends in 3 then when you divide it by 10 the remainder will be 3

#

for example 13 / 10 = 1 remainder 3

azure badger
#

yeah same idea

obtuse pebbleBOT
#

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void parcel
obtuse pebbleBOT
drifting wraith
#

neat

#

not neat

#

i think you kinda just fill it manually, i'll draw it

hot horizon
#

all paths which go down by a row at each step are shortest paths, so it would start with 3 options, then in all cases have 3 options again. so its 3^<how many rows are there - 1>

drifting wraith
#

you add up the triangles above

#

that's not true

hot horizon
#

what isnt

drifting wraith
#

there are 3 options, but also there are 5 options and all kinds of options

hot horizon
#

oh man i didnt see that lol

#

yeah its more complicated than that

#

i dont understand what numbers your putting in, but this isnt my help channel and i should be doing school, so bye for now

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untold flower
#

In need of help.

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

untold flower
#

Regarding sectors

#

<@&286206848099549185>

brazen gorge
untold flower
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untold flower
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/end

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spice chasm
#

is it true that $v(t)=v(0)+\int_0^t a(s)ds$

obtuse pebbleBOT
warm shaleBOT
brazen gorge
#

looks correct

#

matches with suvats lmao

spice chasm
brazen gorge
#

oh

#

wait

spice chasm
#

,w does f(5)=f(0)+integrate from 0 to 5 of f'(x)

brazen gorge
#

but you already have v(0)

#

idk

warm shaleBOT
spice chasm
#

bro

obtuse pebbleBOT
#

@spice chasm Has your question been resolved?

brazen gorge
#

this looks very ftc-y

brazen gorge
#

ftc 2

spice chasm
#

ty

#

.close

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tough parcel
#

forgot how to do these

obtuse pebbleBOT
tough parcel
#

just a) is fine

#

i remember a formula

#

but

latent walrus
#

you multiply the frequencies by the midpoints, and sum them

#

then divide by the total frequency

#

i believe anyway, its been a long time

tough parcel
#

how do i find the midpoint 🥹

latent walrus
#

midpoint of 20 to 25 is 22.5 for example

tough parcel
#

oh

latent walrus
#

you can just find the average of the boundary numbers

tough parcel
#

alright, thank you!

#

🤝

#

.close

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dim quest
#

Hi can someone prove this formula to help me understand it better for my exam?

obtuse pebbleBOT
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brittle plover
obtuse pebbleBOT
brittle plover
#

is there a method for finding the eular path or is a lot of it just trial and error

#

I know you have to start and end with an odd node

#

which in this case is Z and Y

obtuse pebbleBOT
#

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.close

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rough mango
#

help

obtuse pebbleBOT
rough mango
stone spoke
#

Have you made any progress so far? Or is there anything from the original problem you don’t understand?

rough mango
#

no progress made

#

nd i dont understand any of it

#

this class was not worth taking

stone spoke
#

Maybe you could start by understanding what it means to be in Thom class (&Thom Space) and the normal bundle before you start the problem

rough mango
#

Okay

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minor harness
#

trying to expand this log expression, not sure where I'm going wrong:

minor harness
#

.close

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inland thistle
#

can someone explain how the ^15 turned into those?

empty cypress
#

complex analysis class?

#

theres a "trick" for computing powers of complex numbers

inland thistle
#

maths 1 but yea it includes it

empty cypress
#

you can either convert it to the e^(i theta) form, or you can use this equation

#

sec lemme type it

fathom flicker
#

You should rewrite it into polar form like bunny suggested

#

or use the binomial theorem if you hate yourself

empty cypress
#

$(a+bi)^n = \sqrt{a^2+b^2}^n(\cos(n\theta) + i \sin(n\theta))$

warm shaleBOT
empty cypress
#

did i get this first try?

fathom flicker
#

nth power of the square root?

#

or nth root

empty cypress
#

and of course $\tan(\theta) = \frac ba$

warm shaleBOT
empty cypress
#

lemme check that i wrote this out correctly though, see if it matches the work above

#

yeah i think this works out

#

@fathom flicker have you checked?

#

but like either way the "easier" way is surely just use polar form unless you want to memorize this

inland thistle
#

gotcha ill try both and see how it goes

#

thanks guys

empty cypress
inland thistle
#

.close

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fathom flicker
#

Seems plausible though

empty cypress
#

oh i meant to ping the question asker, my bad

#

im pretty sure it directly derives from the polar form method anyways

obtuse pebbleBOT
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worldly plover
#

is that graph a rational graph?

obtuse pebbleBOT
obtuse pebbleBOT
#

@worldly plover Has your question been resolved?

zenith raft
#

what is a rational graph?

worldly plover
#

is that not a thing?

#

Ig I mean't rational function

latent walrus
#

its not really a function either

#

what is it you really want to know?

worldly plover
#

I mean I just wanted to take one of those lines into account

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@worldly plover Has your question been resolved?

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@worldly plover Has your question been resolved?

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@worldly plover Has your question been resolved?

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uneven sedge
#

can anyone help me with a few questions on my pre-test? i have an exam coming up tomorrow and i really need to understand all this cuz im not confident at all

uneven sedge
obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
uneven sedge
#

I don't know where to begin.

winter jacinth
#

try to bring it to a simpler form

#

then you substitute (2x + pi/3) with u

#

and it turns into

#

sin(u) = 1

uneven sedge
#

wait so

#

what does the question mean by solutions

winter jacinth
#

ok so since sine is a periodic function (meaning it repeats) there could be multiple solutions for example the solution is x = 90 deg but x = 360 + 90 could also be a solution

#

but after you get it into the form that i said, then u can be 90 deg, 350 deg, 610 deg etc, then you solve like 2 or 3 equations like 2x + pi/3 = pi/2 and check if x is in the [0, 3pi] range

uneven sedge
#

i am trying to understand

#

gimme a sec

#

im still kinda confused

#

how do i find how many solutions

#

there are

winter jacinth
#

you try it until x gets out of the range thats given to you

#

if you still dont understand we can go on a call

uneven sedge
#

alright

#

sure

winter jacinth
#

so should i call you?

uneven sedge
#

yeah

winter jacinth
#

okay

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#

@uneven sedge Has your question been resolved?

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sinful iron
#

Did I do this right?

obtuse pebbleBOT
winter jacinth
#

wait isnt the decks corner where the two lines intersect?

sinful iron
#

Ah?

winter jacinth
#

y = x-2 intersects y at -2 and x at 2

#

you made it intersect x at 1

#

also the other one y = -2x +1 is wrongly drawn

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#

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violet rapids
obtuse pebbleBOT
violet rapids
#

Why did he get two different answers using synthetic division versus polynomial divisions

#

Omg name

#

Nvm

#

.close

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graceful marten
#

Hia

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

graceful marten
#

Short question

#

How do you know just because PX = 1/3 of PR, that the rest are 1/3 each

.

#

Also if you wanted to calculate XY would it just be -1/3a +1/3b

#

Becuase 'apparently' its split into 3

obtuse pebbleBOT
#

@graceful marten Has your question been resolved?

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@graceful marten Has your question been resolved?

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.close

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weary nacelle
#

How do i solve this

obtuse pebbleBOT
weary nacelle
#

What steps do i do first

heavy seal
#

Y=mx+c

weary nacelle
#

Oh

#

it is 2x - 3y = 6

#

Do i need to change it to y =mx + b

heavy seal
#

Also product of slopes of this one and perpendicular line is -1

weary nacelle
#

Will it be 3y = 2x + 6?

weary nacelle
#

How do i know if it’s -1

heavy seal
weary nacelle
#

Is it always negative 1 for perpendicular

#

?

boreal cliff
#

it is

#

yes

weary nacelle
#

Will it be

#

Y = 2/3x + 2

#

?

boreal cliff
heavy seal
#

2/3 times m2 is -1

weary nacelle
#

What

#

What is m2

#

Slope 2

#

?

heavy seal
#

For perpendicular line...y=m2 x + c

weary nacelle
#

Oh

heavy seal
#

Slope of perpendicular line

weary nacelle
#

Yes

#

How do i find m2

#

is it 2/3

heavy seal
weary nacelle
#

oh

#

i neee to find m2?

heavy seal
#

Ye

weary nacelle
#

How do i do that

#

calculator?

#

-1 divided 2/3?

#

Or is there a way to find

heavy seal
#

Ye

weary nacelle
#

Ok

heavy seal
#

-3/2

weary nacelle
#

Oh

#

Oh so just flip it

heavy seal
#

So for like two..y=(-3/2)x+c

weary nacelle
#

Do i foil the sign

#

Flip

heavy seal
#

Ye

weary nacelle
#

Will 3/2 be positive then

heavy seal
#

Flip sign?

weary nacelle
#

like it’s 2/3

heavy seal
#

Why flip sign

weary nacelle
#

Idk

#

someone told me that

heavy seal
#

No need

weary nacelle
#

Ok

#

So m2 is 3/2

#

Now what

heavy seal
#

-3/2

weary nacelle
#

ye

heavy seal
weary nacelle
#

y = -3/2x + b

#

right

heavy seal
#

Now (6,-1) lies on both lines

weary nacelle
#

Oh

#

We replace y and x

#

Right

heavy seal
#

We substitute

weary nacelle
#

Oh

#

-1y = -3/2(6) + b

#

?

boreal cliff
#

alright that seems unneccessary

#

just use slope point form

weary nacelle
#

how i do that

#

slope@point form is y = mx + b?

heavy seal
boreal cliff
#

do you know slope point form of a line

weary nacelle
#

Yes

heavy seal
#

Of course u can derive standard results

weary nacelle
#

i think

#

ax + b

#

?

#

Which one

boreal cliff
heavy seal
boreal cliff
weary nacelle
#

y-y1?

#

?

weary nacelle
#

-1y = -3/2(6) + b

#

So is this right

heavy seal
weary nacelle
#

i replace y and x

weary nacelle
#

But i renember some of it

boreal cliff
#

you could think of it as rise over run for this line is ofc -3/2

weary nacelle
#

What’s the easiest way to do

boreal cliff
#

assume a point x,y

weary nacelle
#

I’m confused what are we talking about

heavy seal
weary nacelle
boreal cliff
#

x-6/y-(-1)=-3/2

#

there you go

weary nacelle
#

What

boreal cliff
#

thats the line

weary nacelle
heavy seal
weary nacelle
#

-1 = -3/2(6) + b

#

?

#

is this rifht

#

then

#

Or what is the right equarion

boreal cliff
#

what

weary nacelle
#

Oh

boreal cliff
weary nacelle
#

So first you found the m2

#

-3/2

#

Then u used the points

weary nacelle
#

How do i solve this

#

That’s the answer?

heavy seal
weary nacelle
#

-1 = -3/2(6) + b

#

-1 = -9+ b

heavy seal
heavy seal
#

B is 8

weary nacelle
#

Now i do

#

He’s

boreal cliff
#

you can simplify

weary nacelle
#

Oh

heavy seal
#

so y=-3/2x+8

weary nacelle
#

Which equarion is easier

heavy seal
#

Over

weary nacelle
#

Percy or this one

heavy seal
#

Percy

weary nacelle
#

Oh

boreal cliff
#

slope point form is a derived result

weary nacelle
#

Whag is derived

heavy seal
#

Percy's form

#

Lol

weary nacelle
#

Oh

#

Let me redo but

#

Let me try to do the steps

#

So first i change the equation to

heavy seal
#

bruh

#

I'll send u a video lecture

weary nacelle
#

Let me try and i will see if i get 8

heavy seal
#

That's better

weary nacelle
#

Ok

#

3y = 2x + 6

heavy seal
weary nacelle
#

Ok

#

.close

obtuse pebbleBOT
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tribal tide
obtuse pebbleBOT
tribal tide
#

What will i do now?

#

im stuck

heavy seal
#

Lighting...

tribal tide
#

U need a better picture?

heavy seal
#

Yea or send the question

tribal tide
#

når means when

#

Maximise the function

obtuse pebbleBOT
#

@tribal tide Has your question been resolved?

tribal tide
#

<@&286206848099549185>

obtuse pebbleBOT
#

@tribal tide Has your question been resolved?

tribal tide
#

<@&286206848099549185>

#

is it possible to get some help or?

#

been waiting for over an hour

hot sonnet
# tribal tide

Hello. Notice that it's 1/2 -1 = -1/2, so the exponent in x and y is -1/2

obtuse pebbleBOT
#

@tribal tide Has your question been resolved?

tribal tide
hot sonnet
#

also use 3000-x-5y = 0

#

for example, x = 3000-5y

tribal tide
#

How do i isolate the lambda?

hot sonnet
#

you have

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50/sqrtx - lambda = 0

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and

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50/sqrty - 5lambda = 0

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you can isolate lambda in one of these 2 eqs

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and replace in the other one

tribal tide
#

oh okay and then use the 3000-x-5y after

hot sonnet
#

yes

tribal tide
#

Okay thanks

#

.close

obtuse pebbleBOT
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north quarry
#

ln method

#

not allowed to give u the solution

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!nosols

obtuse pebbleBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

north quarry
#

sorry, plus u wont get better if i give u the answer

obtuse pebbleBOT
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high python
obtuse pebbleBOT
#

Please don't occupy multiple help channels.

high python
#

help me please

dark stirrup
#

Stay in your original channel please

high python
#

didn't you get an answer ?

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I closed the other one that's why

dark stirrup
#

You closed it after i sent my message. Also, you should generally stay in the channel you first opened instead making a new one just because no one came to help you quickly enough.

high python
#

idgaf

dark stirrup
#

People are less likely to help you if you abuse the system or act hostile

high python
#

.close

obtuse pebbleBOT
#
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vague isle
#

I'm trying to understand this part of linearizing.
I'm not sure what is happening here

vague isle
#

why they make that substitution y = p+u ?

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what's that u ?

balmy mortar
#

I think you need to give more context yh

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yh ok

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dont think i can help out myself

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ok so i understabnd something just reading the screenshot

vague isle
#

it's a recap of diff equations studied so far in the course basically, in the form of a conversation

balmy mortar
#

The idea is to center at your equilibrium

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so, redo the axes and make the equilibrium the origin

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thats the effect y = p + u has

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p is your new origin

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u will be the relative change from that origin

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Don't know if that made any sense

vague isle
#

mmmm kinda but still forming the image in my head

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p would be the value at equilibrium basically

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cause i don't care what happens in the transient

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right?

balmy mortar
#

To give an analogy

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,,\lim_{x\to 1}\frac{x - 1}{x^2 - 2x + 1}

warm shaleBOT
balmy mortar
#

If you were to compute this, a sensible thing would be to 'center' the limit at 0

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that is making the substitution u = x - 1

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I think the same idea is being used here

vague isle
#

mm ok

balmy mortar
#

is another way to write this

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and thats just like the y = p + u here

vague isle
#

i'm not used to think this way but i understand

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i mean never had to recenter to compute the limit

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but ok

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not sure why it would make more sense

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i think i understand the parallel now.

vague isle
balmy mortar
#

Whenever you focus on a random point

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isnt it better to make it the new origin

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In this particular case, try and you will see it makes things a bit easier

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This is a bit of intuition that makes sense to me though, having encountered the same idea in many places.

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Topology, algebra, analysis etc etc

vague isle
#

im trying yes

balmy mortar
#

If you only care about the change relative to a point

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then that point is essentially your origin

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If you only write down the change

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then it is.

vague isle
#

why u = x-1 ? that 1 is from the limit or from the numerator?

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i'm not sure i understand the processing of ideas here

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you see that function and you see ... something, the makes you think , i can shift this to origin!
what do you see?

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cause even if i have just u in the numerator the denominator becomes messier.. how am i shifting this?

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this is super interesting i didn't find it explained so far...

vague isle
remote skiff
#

I think you're overly worrying about the change of variables and missing the point that is interesting to begin with.

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You have some function y(1-y/p) = y- y^2/p and as y tends to p. This tends to 0 as y tends to p, but that doesn't really give you any insight into what's going on near p.

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If your limit was near 0 instead, you could use an approximation by dropping the highest power of the polynomial, so any change of variables that accomplishes that would achieve the same goal

#

From y(1-y/p) you could just use u = 1-y/p so that y = 1-u/p. All I did was choose a linear function of y that was easy to substitute into the equation, then you have (1-u/p)u and as y tends to p u tends 0 so that you can drop leading terms.

#

The whole point was the strategy of changing the equation to study a polynomial near 0 so you can drop a leading term to simplify. The substitution itself wasn't particularly magical

vague isle
#

thanks for taking the time!
i don't understand what you mean by
"that doesn't really give you any insight into what's going on near p."

#

what sort of insight you mean?

remote skiff
#

It's not obvious what the behavior of the differential equation looks like near p

vague isle
#

so in the end i would get this

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and you say "as y tends to p u tends 0 so that you can drop leading terms."

#

why y tends to p?

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ok i think i see, its for the substitution you made
u = (1-y/p)

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i think i see what's happening here now, can you confirm @remote skiff ?

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i'll look up for linearization i think that's just a topic that has not been explained yet

obtuse pebbleBOT
#

@vague isle Has your question been resolved?

obtuse pebbleBOT
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mystic bough
#

D is middle point of AC, and i need to find DEBC area

mystic bough
#

But kinda stuck on what to do next

#

Its simillar triangles

#

Bc of 2 corners

lilac pebble
#

is 12 the length of AD or AC

mystic bough
#

Ac

obtuse pebbleBOT
#

@mystic bough Has your question been resolved?

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@mystic bough Has your question been resolved?

fervent cradle
obtuse pebbleBOT
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@mystic bough Has your question been resolved?

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final matrix
obtuse pebbleBOT
final matrix
#

is my proof correct? the instructions were:

grizzled basin
#

looks good but you carry (k+1)/(k+2) the entire way through

#

you dont have that equality from the start, so only write it at the bottom when you show it

#

otherwise it seems like you're assuming its true, which is what you're supposed to show

fossil crag
#

I don’t understand the line where there's (1/k+1) on the left, where are the parentheses ?

final matrix
#

Ah, ok, sweet thank you! I feel great right now because I haven't been able to understand induction for the last couple of days

fossil crag
#

And how do you go from that line to the next ?

final matrix
fossil crag
final matrix
fossil crag
fossil crag
final matrix
#

Ahhh I see what you mean now

fossil crag
#

The way to do it : put everything on the same denominator

final matrix
#

my factored term is my +1, not the (1/k+2), correct?

fossil crag
#

Ill write it with parentheses so we all agree

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$\frac{1}{k+1}\Big(k + \frac{1}{k+2}\Big)$

warm shaleBOT
#

rafilou2003

fossil crag
#

This is your 2nd to last line rewritten with parentheses

#

Now try to put everything on the same denominator

final matrix
#

$\frac{k}{1} + \frac{1}{k+2} = \frac{k^2+3}{k+2}$

fossil crag
#

You didn't do it properly

final matrix
#

Am I dumb am I failing algebra rn

fossil crag
#

What formula did you use?

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Not like that

#

You multiply k by the denominator

final matrix
#

yeah

fossil crag
#

$k = \frac{k(k+2)}{k+2}$

final matrix
#

k(k+2) = k^2 + 2k

warm shaleBOT
#

rafilou2003

fossil crag
#

And then you add it to the other fraction

final matrix
#

damn I am forgetting all kinds of things

fossil crag
final matrix
#

$\frac{k(k+2)}{k+2} \cdot \frac{1}{k+1} = \frac{k(k+2)}{(k+2)(k+1)}$

warm shaleBOT
final matrix
#

$\frac{k(k+2)}{k+2} \cdot \frac{1}{k+1} = \frac{k(k+1)+1}{(k+2)(k+1)}$

warm shaleBOT
fossil crag
#

Why did it become a multiplication instead of addition?

final matrix
#

I dont know 😭

fossil crag
#

Complete this statement: $\frac{k(k+2)}{k+2} + \frac{1}{k+2} = ...$

warm shaleBOT
#

rafilou2003

final matrix
#

k(k+2)+1/(k+2)

fossil crag
#

Yes, can you expand the numerator?

final matrix
#

k^2+2k+1

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/k+2

fossil crag
#

Yes, does this seem familiar?

final matrix
#

No to be honest

fossil crag
#

look at your quadratic identities

#

Try to factor the numerator is what I'm hinting at

final matrix
#

(k+1)(k+1)

fossil crag
#

Yes

final matrix
#

then (1/k+1)[(k+1)(k+1)/(k+2)] becomes k+1/k+2

fossil crag
#

Yes

final matrix
#

Wow my algebra is rusty, thank you so much

#

ngl I was like "why so much rigor when can I start handwaving" 😭

#

.close

obtuse pebbleBOT
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hallow owl
#

Does anyone know anything about the college classes: Topics math and Contemporary math

hexed agate
#

What is your question bro

unreal musk
#

Possibly, though you'll probably have much better luck if you have specific questions related to stuff within those classes... JustAsk

hexed agate
unreal musk
#

@warm canopy Hiii

unreal musk
obtuse pebbleBOT
#

@hallow owl Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

i have no clue how to do this

obtuse pebbleBOT
inner stratus
#

thales ?

regal parcel
#

we can use the fact that T and W are midpoints of the legs

#

meaning, the increment in length from SR to TW is the same increment as from TW to UV, afaik

#

here we can see that on the right, the addition green length is twice the additional blue length

#

same works for the left side

obtuse pebbleBOT
#

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obtuse pebbleBOT
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hallow owl
hallow owl
#

I want to know which is simpler

hallow owl
#

I have no clue what the classes consist of

obtuse pebbleBOT
#

@hallow owl Has your question been resolved?

hallow owl
#

<@&286206848099549185>

unreal musk
obtuse pebbleBOT
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@hallow owl Has your question been resolved?

obtuse pebbleBOT
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quick estuary
#

Sorry for the pic in spanish. I've been trying with a group of friends to solve this, however we just get constantly stuck. There's no intersection between S and v or H and v, and we need to somehow get a 3 vector subspace to transform into a 2 vector subspace, while having that second subspace transform into a single vector.

obtuse pebbleBOT
#

@quick estuary Has your question been resolved?

quick estuary
#

<@&286206848099549185>

quick estuary
#

What really bothers me is that you cannot do something like SintH to Sintv

quick estuary
#

<@&286206848099549185>

quick estuary
#

<@&286206848099549185>

obtuse pebbleBOT
#

@quick estuary Has your question been resolved?

quick estuary
#

<@&286206848099549185>

quick estuary
#

.close

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rugged plume
#

help

obtuse pebbleBOT
rugged plume
#

can someone help me understand and list all of the steps properly

forest sinew
#

how awful that they make you write this using text

#

it doesnt really seem like youve used enough parens

#

not that this will make it more legible

obtuse pebbleBOT
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