#help-10

1 messages · Page 280 of 1

woeful fulcrum
#

oh

severe reef
#

the rate of change of volume is constant

#

implying the height is changing at a constant rate as well

woeful fulcrum
#

ohh so if i think logically about it the rate of the height stays the same as it decreases

severe reef
#

since volume is proportional to height

woeful fulcrum
#

so the same answer would apply if i was looking for the rate when the height is 4m for example

#

right

severe reef
#

yes

woeful fulcrum
#

ok

#

im gonna test my answer

#

it was right yay

#

tysm

severe reef
#

np

woeful fulcrum
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @woeful fulcrum

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shadow lava
obtuse pebbleBOT
shadow lava
#

AX = XB + C

#

B = 2I

#

AX = X(2I) + C

#

not sure where to go from here?
Can I do this?

(A^-1)AX = (A^-1)X(2I) + C

#

or am I forgetting about C when I do that

royal basin
#

well you are

#

but also left-multiplying by A^-1 won't help much here

shadow lava
#

Oh, I thought it could remove A from the LHS

royal basin
#

so you're fucking up both planning and execution

#

this is as unhelpful as dividing both sides by 7 in the equation 7x = 2x + 9

shadow lava
#

OK

royal basin
#

anyway what you want to notice here is that $X \cdot 2I = 2I \cdot X = 2X$

warm shaleBOT
#

AnnGhost

shadow lava
#

so I'm on the right track here, but I'm stuck on next step..
AX = X(2I) + C

royal basin
#

the identity matrix and all scalar multiples thereof commute with everything

shadow lava
#

because all matrices are 2x2?

#

how do we know that X is 2x2?

fervent cradle
#

in order for the addition on the RHS to make sense, we need X(2I) to be 2x2

#

and we also need AX on the LHS to be 2x2

#

so X must be 2x2

shadow lava
#

but do we know that X is 2x2? or just assuming

fervent cradle
#

ok

#

so on the RHS we know that X(2I) is 2x2

royal basin
fervent cradle
#

so therefore we know that the number of rows of X is 2

#

similarly on the LHS we know that AX is 2x2

royal basin
#

but you do know that X is 2×2 from the equation.

fervent cradle
#

where A is 2x2

shadow lava
fervent cradle
#

yes

#

basically you can't add matrices unless they're the same dimension

#

but we have like X(2I) + C

shadow lava
#

AH

#

that's the giveaway

#

OK

shadow lava
#

but X could either be

  • a scalar
  • 2x2 matrix
royal basin
#

no, X cannot be a scalar

#

it's said to be a matrix

fervent cradle
#

ok look it wants a matrix it just says that in the question

shadow lava
#

oh right

#

ty

#

AX = X(2I) + C

#

so the identity disappears?

#

AX = X2 + C

#

AX = 2X + C

#

all 3 of these equations are equal?

fervent cradle
#

yeah

shadow lava
#

huh.. interesting

#

and the identity goes away because it doesnt' change anything when multiplying same size matrix

#

so it's kinda irrelevant

fervent cradle
#

sure

shadow lava
#

OK

#

so now we are cooking with fire

#

AX = 2X + C

#

AX - 2X = C

#

is that a good next step?

fervent cradle
#

yes

shadow lava
#

then I can factor out the X on LHS?

fervent cradle
#

yes

shadow lava
#

X(A - 2) = C

#

wait

#

sorry

#

wrong side

#

needs to be (A - 2)X = C

fervent cradle
#

good catch

shadow lava
#

now I divide both sides by A-2

fervent cradle
#

one more thing, you should really say

#

(A - 2I)X = C

shadow lava
#

no division in matrices

fervent cradle
#

because you're doing matrix subtraction

shadow lava
shadow lava
fervent cradle
#

yes

shadow lava
#

damn

fervent cradle
#

because A - 2 doesn't really make sense

#

matrix minus a scalar

shadow lava
#

oh right

#

good call

#

(A - 2I)X = C

#

now I multiply both sides by 1/(A-2I)

fervent cradle
#

well

shadow lava
#

X = C/(A-2I)

fervent cradle
#

(A-2I)^-1 is the way we usually put it

#

inverse

shadow lava
#

oh right, same thing as reciprocal

fervent cradle
#

the equivalent, yeah

shadow lava
#

interesting..

#

that's so neat

past sand
#

Probably show that it exists first?

shadow lava
#

so it cancels out the (A - 2I)

fervent cradle
#

yes

shadow lava
#

on the LHS

#

and I'm left with X = [(A-2I)^-1]C

fervent cradle
#

yeah

#

and now you just need to find what that actually is with like matrix multiplication and inversion and stuff

shadow lava
#

I can't do thisX = C/(A-2I) because it's not clear if (A-2I) is on left or right side

fervent cradle
#

essentially yeah

shadow lava
#

but X = [(A-2I)^-1]C is very clear it's on left side of C

#

OK tyvm

#

now I just calculate

shadow lava
#

since B = 2I

fervent cradle
#

sure

#

it's the same

shadow lava
fervent cradle
#

cool

#

you can just try it out to see if it works

shadow lava
#

My A|I ~ I|A^-1 method might be using a chainsaw to cut a matchstick in half, but it gets the job done

fervent cradle
#

ah

#

mistake

shadow lava
#

gawd dammit

shadow lava
fervent cradle
#

two mistakes

#

minor

shadow lava
#

hmmm, I did my multiplication wrong

fervent cradle
#

no the multiplication is right

#

it's just, the subtraction

shadow lava
#

oh it's the signs

#

99% of the way there and trip right before the finish line

#

sadly, if I had this as my answer on exam. big fat 0 for everything

#

they only give marks for correct answer and showing work

#

so all that effort and time for nothing, just flushed down the toilet

shadow lava
#

5 6 -2 -2

#

that's what it should be, but all the work before the last 2 steps are correct

fervent cradle
#

that's how it goes

shadow lava
#

all or nothing

fervent cradle
#

well no

#

ok they care about the working

#

i'm saying, very common to get basically everything right but make a small arithmetic mistake

#

but yeah more forgiving usually in my experience

shadow lava
#

so i should probably still get some marks for showing the work at least

#

up until the very last fumble

fervent cradle
#

sure

shadow lava
#

marking math must be so time consuming, and subjective to the grader

#

i'm sure the examiner sees all sorts of weird shit on exams

#

they gotta determine if any of the mess is worth anything, which takes time, and it cannot be automated, only humans can do the job

#

my guess is that math teachers really earn their pay, the good ones should be paid more imo, it feels like they are doing more work than other subjects. but i could also be very wrong.

fervent cradle
#

no clue

shadow lava
#

i've had a lot of exams that are simply multiple choice and get marked with dots on a score card by a computer

#

math exams are never offered in this format unfortunately lol

#

tyvm for the help @fervent cradle

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @shadow lava

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

honest flicker
obtuse pebbleBOT
honest flicker
#

I was thinking exponential because the common ratio thingy of the y's but the X's look kinda funky idk

#

I think like exponential or maybe neither

#

Idk

fervent cradle
#

try plotting the points and seeing what it looks like

honest flicker
#

It looks exponential

#

So is that the asnwer fr

#

@fervent cradle

fervent cradle
#

does it look exponential

#

show your sketch

honest flicker
#

I already destroyed it

#

😭

fervent cradle
#

ok do it again lol

#

just rq

honest flicker
#

ITS EXPONENTIAL LOOKING

fervent cradle
#

it doesn't have to be beautiful

honest flicker
#

Plz believe

fervent cradle
#

ok well

#

it's not exponential

#

sketch better

honest flicker
#

.

#

What it is

#

Fr

fervent cradle
#

sketch it

honest flicker
#

@fervent cradle

fervent cradle
#

ok

#

wait that does look exponential wtf

#

ok i was wrong sorry

honest flicker
#

😭

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @honest flicker

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tawdry vortex
obtuse pebbleBOT
tawdry vortex
#

this third one confuse me sadly

#

like it cant be 1/2

alpine bison
#

i can't even read properly

tawdry vortex
#

oh

#

,flip

#

.flip

shrewd moon
#

No helpers want to help me

tawdry vortex
#

sad

uneven palm
#

,rotate

warm shaleBOT
#

Couldn't find an attached image in the last 10 messages.

tawdry vortex
uneven palm
warm shaleBOT
shrewd moon
#

Bro this is grade 10 work

#

That root 6 is 6^0.5

#

And 6 is 36^0.5

#

So u get 36^0.5x0.5

dusk ruin
#

ozioma do not directly give people answers, the point of this server to help people understand

spare prairie
#

this one is pre-calculus?

#

Very simple material

uneven palm
dusk ruin
#

and the level of the problem is irrelevant, so long as someone needs help with it

warm canopy
#

yeah stop commenting on how "simple" material is for you

shrewd moon
#

So x is equal to 0.25 or 1/4

daring sorrel
#

Also how do you not know he isnt in 10th? Absolutely useless comment

willow mauve
#

the point is not to give the answer

shrewd moon
#

Sorry

spare prairie
#

Lol

shrewd moon
#

My first time helping

spare prairie
#

SOmetime its good to be honest

daring sorrel
#

Im more worried about how he keeps asking for help with pretty much exact same questions

spare prairie
#

I never asked a question

#

Or you talk about ozioma

shrewd moon
#

Yah me

daring sorrel
#

Im talking about ac lol

obtuse pebbleBOT
# shrewd moon So x is equal to 0.25 or 1/4

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

spare prairie
#

Anyway the answer was very easy to get

tawdry vortex
#

Ok thnxs

shrewd moon
#

That's what I did there

#

Got myself to a base of 36

#

So the bases cancel out

#

And they can cancel like that only when they r in opposite side of the = sign

tawdry vortex
#

yea

#

I just realized this homework is so repetitve

#

I Just went through 10 questions same damn thing they jsut ask it different ways

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @tawdry vortex

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ember inlet
obtuse pebbleBOT
ember inlet
#

Im so confused and im lost O-o idk where to start even

obtuse pebbleBOT
#

@ember inlet Has your question been resolved?

obtuse pebbleBOT
#

@ember inlet Has your question been resolved?

ember inlet
#

<@&286206848099549185>

obtuse pebbleBOT
#

@ember inlet Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cosmic veldt
obtuse pebbleBOT
cosmic veldt
#

So I think the bounds are 0 to pi/2 by that last part but not sure what c(t) is?

#

This is the formula btw

worn yoke
#

what's the usual parametrization of the unit circle?

cosmic veldt
#

Basically the formula but different letters

cosmic veldt
worn yoke
#

other way round

cosmic veldt
#

Oh yeah cuz cosine is x and sine is y

#

Oh is that it?

#

(cos t, sin t)?

worn yoke
#

yes

cosmic veldt
#

Nice

obtuse pebbleBOT
#

@cosmic veldt Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lavish kayak
#

Can someone please give me an intuitive explaniation of what the mixed partial derivative means graphically?

lavish kayak
#

I know that the second order partial derivative fxx and fyy just determine the concavity of the function created at a fixed x (or y) variable

obtuse pebbleBOT
#

@lavish kayak Has your question been resolved?

obtuse pebbleBOT
#

@lavish kayak Has your question been resolved?

#
Channel closed

Closed by @lavish kayak

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

solid bear
#

I know the right answer is 3 but I. don't get why if someome could help me

brazen gorge
#

mind providing a translation?

solid bear
#

the answers 3 says a can be any number you want and b <0

brazen gorge
#

x-> -inf, so ae^x goes to 0

#

same with e^x

#

so you get be^-x/x^3

#

$\lim_{x \to -\infty} \frac{be^{-x}}{x^3}$

warm shaleBOT
#

artemetra

brazen gorge
#

e^-x goes to +inf, x^3 goes to -inf

#

therefore b must be negative to get -inf/-inf = +inf

#

it's.. basically what you have there written already

solid bear
#

i just got confused cuz I thought -inf/-inf was indeterminate

#

or is it only when is -inf/+inf

brazen gorge
solid bear
#

so is it wrong?

#

or is there another way to do it?

obtuse pebbleBOT
#

@solid bear Has your question been resolved?

#
Channel closed

Closed by @solid bear

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
#

Can anyone recommend me a good video or resource on directional derivatives, thanks

tardy epoch
timid silo
#

thnks

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

#
Channel closed

Closed by @late aspen

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

acoustic portal
#

Question one

obtuse pebbleBOT
acoustic portal
#

<@&286206848099549185> Rigorous proof alert ⏰

#

I dont really want to answer but i dont know what to do

#

I know it converges to 1/2(a + b) but i dont know how to prove it

#

perhaps i can use the definition of cauchy sequence or somethinig but idk how to proceed with that

obtuse pebbleBOT
#

@acoustic portal Has your question been resolved?

acoustic portal
#

<@&286206848099549185> !!

obtuse pebbleBOT
#

@acoustic portal Has your question been resolved?

acoustic portal
#

<@&286206848099549185> ☹️

tardy epoch
obtuse pebbleBOT
#

@acoustic portal Has your question been resolved?

acoustic portal
tardy epoch
#

Oh hmm

#

Try finding the first 5 terms and find a pattern

#

Then you can make some induction argument

acoustic portal
#

(1/2)^n * coefficient of a + coefficient of b where

#

The coefficients are jacobinan(?) numbers for

obtuse pebbleBOT
#

@acoustic portal Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

thick sun
#

I need help finding the measure of the angle of the two intersecting bike trails, and the length of the pathway to the bridge (I also need help with the full solution)

jagged falcon
#

Okay, can you draw a simpler diagram on paper?

obtuse pebbleBOT
#

@thick sun Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
#

trying to find [
\lim_{n \to \infty} \f1n \p{n!}^{\ff1n}
]

warm shaleBOT
timid silo
#

I did this to check to see if like I can find out if I can find an upper bound that diverges

#

[
\f1n \p{n!}^{\ff1n} = \p{\f1{n^n} n!}^{\ff1n} = \f1n\m\ln{\f1{n^n} n!} = \f1n\m\ln{\f1{n^n}\int_1^n x \dd x} =\f1n\m\ln{\f{n^2-1}{2n^n}}
]

warm shaleBOT
timid silo
#

but this probably converges thonk2

timid silo
# warm shale

I'm 99% sure this is some wicked limit of e I can't find

warm canopy
#

A divergent upper bound would not tell you anything

tardy epoch
#

Do you know Stirling's formula

timid silo
#

oh sorry I probably mixed stuff up

timid silo
#

Ah you mean that

#

would substituting n! for that make it work out

#

oh I guess n^n's cancel

#

so that's nice

warm canopy
#

n! = ∫_1^n x dx ?bhappy

timid silo
#

OHHH

timid silo
#

ok thanks for telling me about this Stirling formula thingy really helpful

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @brave kite

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

craggy tapir
#

I need help with basically everything shown in this image. I'm very clueless on what to do or how to read it.

obtuse pebbleBOT
#

@craggy tapir Has your question been resolved?

craggy tapir
#

<@&286206848099549185>

obtuse pebbleBOT
#

@craggy tapir Has your question been resolved?

craggy tapir
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @craggy tapir

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

weary bone
#

My calculus teacher insists that none of the options are correct, but i got D
Could this just be a difference in the interpretation of the question?

twin sapphire
#

show your working out

#

and also f(5) =/=1 no?

weary bone
#

It doesn’t equal, which is why I think she interpreted it differently

twin sapphire
#

i mean the question doesnt make sense then

weary bone
#

Yeah…

twin sapphire
#

like theres no such tangent line

#

as (5,1) isnt on the curve

weary bone
#

Could this be interpreted as (5,1) being a point on the tangent line, not on the graph?

#

I feel like that would be the only way

twin sapphire
#

oooh then this gets much harder

#

and there could be multiple answers

#

i think there would be 2 answers

#

you can do that

weary bone
#

Even with that interpretation, it would be y-1 = (10-2sqrt14)(x-5), which is not an option

twin sapphire
#

im not sure its that simple

#

for a tangent at point a

twin sapphire
#

right?

weary bone
#

that was my initial answer

twin sapphire
#

so in this case

#

y-(a²-10) = 10(x-a)

#

and you also want

#

that for some value (x,y) = (5,1)

#

it holds true

#

so you have

#

1-(a²-10) = 10(5-a)

#

so you have to solve this quadratic in a

#

and this will lead you to the points

#

a

#

where the two tangent lines are possible

weary bone
#

interesting

twin sapphire
#

so we can solve it

#

-a² +10a -40 = 0

#

i think

#

theres no answer

weary bone
#

Yeah

twin sapphire
#

we could plot it

#

,w plot x^2 -10

twin sapphire
#

its weird because visually it seems there should be such a tangent line

#

maybe i messed up somewhere

#

oh

#

the original is not with 10

#

y-(f(a)) = f'(a)(x-a)

#

1-(a²-10) = 2a(5-a)

#

a² -10a+10 = 0

#

,w solve x^2-10x+10=0

twin sapphire
#

and plug that back

#

two solutions

#

as i said

#

you got what i did?

weary bone
#

yes I understand

twin sapphire
#

ok

#

so $y - ((5 \pm \sqrt{15})^2 -10) = 2 (5 \pm \sqrt{15})(x-(5 \pm \sqrt{15}))$

warm shaleBOT
#

Benjamin

twin sapphire
#

its a bit convoluted

#

but its the only valid answer

#

its a tangent

#

and it goest through (5,1)

weary bone
#

I see…

twin sapphire
#

but the real answer

#

is that the question doesnt have an answer in what they wanted you to do

weary bone
#

Yeah the question was written poorly

obtuse pebbleBOT
#

@weary bone Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

silver plover
#

how do the two equations at the bottom have no solutions?

#

u can calc t for when it equals 0, no?

unreal musk
#

A solution for one won't be the solution for the other one catlove

silver plover
#

t has to be the same

#

for the vector to be (0,0)

#

makes sense, thanks

unreal musk
#

SCgoodjob2 np

silver plover
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @silver plover

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mint nebula
#

In the exterior of the square ABCD there are equilateral triangles ADF and BCE. If DE intersected with CF = G, prove that the triangle AGB is equilateral

mint nebula
obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

mint nebula
#

Dang.

#

Is it that hard as I thought? lol

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

fathom flicker
#

maybe try drawing some parallel lines

obtuse pebbleBOT
#

@mint nebula Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wild kayak
#

when using the a^2+b^2-= c^2 why cant i just square root the equasion to remove the ^2s?

wild kayak
#

like 9^2 +12^2 =c^2 equals 15

shut lagoon
#

Because sqrt(a^2 + b^2) is (almost) never equal to a+b.

#

Exponentiation and surds aren't distributive like multiplication and addition are.

wild kayak
#

but doesnt it remove the ^2>

#

ohh ok

#

thats confusing

shut lagoon
#

I mean

#

In your example you say 9^2 + 12^2 = 15^2

#

But clearly 9 + 12 = 21, not 15

#

So you can't just sqrt both sides and hope for the best

#

I mean you can, but then you have $c = \sqrt{a^2 + b^2}$

warm shaleBOT
#

Azyrashacorki

shut lagoon
#

And this can't be simplified further.

wild kayak
#

ok i havent learned that yet im just trying to learn the pythagorum therum

shut lagoon
#

Yeah just know that the square root and exponentiation distribute over multiplication/division, but not over addition/subtraction.

#

$\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}$

wild kayak
#

ok kind of like factoring

warm shaleBOT
#

Azyrashacorki

shut lagoon
#

This works

#

At the end of the day

wild kayak
#

yes ok i know thay

shut lagoon
#

It's the exponents law

wild kayak
#

ok

#

so you cant just ^2 away the root

#

like multiplying to remove division

shut lagoon
#

I wouldn't say it like that, but I guess so. You just can't distribute the square root. For the same reason that you can't distribute squares $(a+b)^2 \neq a^2 + b^2$.

warm shaleBOT
#

Azyrashacorki

pure kayak
#

Someone explain to me wth is parametric form of a eqn of a straight line

shut lagoon
#

!occupied

obtuse pebbleBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

wild kayak
#

ok that makes sense

shut lagoon
#

If you have some roots you want to get rid of, like say you have $v = \sqrt{a}$.

warm shaleBOT
#

Azyrashacorki

shut lagoon
#

Then you can square both sides to get $v^2 = a$.

warm shaleBOT
#

Azyrashacorki

shut lagoon
#

This you can do

wild kayak
#

or what about if it is a square root * a square troot

shut lagoon
#

Yes this distributes

wild kayak
#

then you could square to remove beacuse its multiplication right?

#

oohhhhok

shut lagoon
#

square roots are just exponents 1/2

wild kayak
#

they arent opposites?

shut lagoon
#

So $a^{1/2}\cdot a^{1/2} = a^{1/2 + 1/2} = a^1 = a$

warm shaleBOT
#

Azyrashacorki

wild kayak
#

and 1/2 is a square root

shut lagoon
wild kayak
#

ok interesting

#

what is the oppostie of a square root?

shut lagoon
#

The inverse would be squaring.

#

Similarly, you can think of division as a multiplication right? a/b = a * (1/b)

wild kayak
#

ok

shut lagoon
#

Well you can think of surds as exponents that are fractions.

wild kayak
#

yes

shut lagoon
#

Cube roots are 1/3

wild kayak
#

yes

#

ok interesting i understand now i just need to fully wrap my head around it

shut lagoon
#

Yeah it'll clock in with some practice

wild kayak
#

ok cool i appreciate your help

#

i think thats all i need im going to keep practacing

#

!close

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @wild kayak

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

spare phoenix
#

hello

obtuse pebbleBOT
spare phoenix
#

can someone help me with these questions and correct them for me
"List your 3 points you have identified. Write them to 2 decimal places.
(-1,2) (0,1) (1,3)

Write the equation you have found using this Step (write the three points on your parabola (labeling effectively) and use your knowledge of three variable, three equation systems to find a quadratic equation for your parabola. Need to find a, b, and c! (USE MODE, 5, 2)"

#

this is the points you might need it

obtuse pebbleBOT
#

@spare phoenix Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

royal basin
obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tired jackal
#

I have a question here that is kinda confusing me, its SCM, but its basic math, its just a word problem. I already calculated shrinkage which is 326 units per month to meet 7500 sets per month, so now I'm just having trouble with question #3.

tired jackal
#

How I thought of solving it was 7500 x 12 = 90,000 sets per year sold and 7826 x 12 = 93912 to account for shrinkage.
So you're profiting off 90,000 sets per year, so 275 x 90,000 = 24,750,000 and then 200 x 93912 = 18,782,400 to account for all costs.
Now its just revenue - costs so 24,750,000 - 18,782,400 = 5,967,600 profit.

#

The actual answer to this question is 782,400, which makes no sense to me

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @tired jackal

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
#

hi
if u(x) = cos(x+1) and v(x) = x-1 then u(v(x)) is cos((x-1)+1) right
which is just cos(x)

shy vigil
#

yes

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bold brook
#

i subtitue its -25/0 .

obtuse pebbleBOT
bold brook
#

how to solve it?

sage dagger
#

L 🏥

bold brook
#

but if 2x - 6 / 1 = 4

sage dagger
#

wow annnn

#

u would

bold brook
#

using another way

sage dagger
royal basin
#

but even with l'hop: 2x-6 at x=1 gives -4, not 4

royal basin
sage dagger
#

I give myself a W

bold brook
#

i replace x as 5

#

which one is correct , -4 or 4 or -25/0

sage dagger
#

You can’t divide by 0

bold brook
#

yes

#

im confused

royal basin
#

ah fuck.

#

shit.

#

i misread the thing sorry

obtuse pebbleBOT
#

@bold brook Has your question been resolved?

pseudo swift
#

also -25/0, you can't do l'hopital on that, it's only for 0/0 or infty/infty cases

bold brook
#

so the answer is 4

#

right ?

pseudo swift
#

your problem seems broken tbf

#

as written in the question, the limit doesn't even exist

bold brook
#

yeah

#

that's make me confused

pseudo swift
#

well ask your prof or whatever

bold brook
#

she said the answer was there

pseudo swift
#

,w lim x->5 (x^2-6x-20)/(x-5)

pseudo swift
#

well it's not

#

big L for your prof

bold brook
#

what should i do? i need to chose between these option

#

😭

pseudo swift
#

you don't

#

attach a screenshot of wolfram alpha and voila

bold brook
#

ok

#

thanks

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @bold brook

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
obtuse pebbleBOT
timid silo
#

anyone please 🤦‍♂️

royal basin
#

!status

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
timid silo
#

4

royal basin
#

show work and answer

#

@timid silo ?

timid silo
#

my bad

royal basin
#

do you understand how nonsensical the answer is lol

timid silo
#

not at all 😭

royal basin
#

oh wait no hold on i misread

#

thought you had a six figure tax total

#

but also why do you add 5092 tho.

timid silo
#

was i supposed to minus

royal basin
#

no

#

you were supposed to see you are in the third bracket: 45,001-120,000

#

the tax equals 32.5% of everything in excess of 45k, plus 5092

#

that's what you add 5092 to

#

not the original gross income

timid silo
#

ohhh

royal basin
#

the amount taxable in this bracket specifically is 97000-45000

timid silo
#

still abit lost, whts the answer tho 😭

royal basin
#

oh my bad typo

#

92,000 - 45,000

#

this difference is taxed at 32.5%

#

so the tax for this bracket is 32.5% * (92k - 45k)

#

and you add to that the total tax from the prev brackets which is 5092

timid silo
#

20,367?

royal basin
#

,calc (92000-45000)*0.325 + 5092

warm shaleBOT
#

Result:

20367
royal basin
#

ok yeah

timid silo
#

cheers bro

royal basin
#

don't call me bro

#

please edit that out

obtuse pebbleBOT
#

@edgy hull Has your question been resolved?

trail musk
#

everyone's a bro

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ivory spoke
#

Are $\lnot (P \lor Q)$ and $(\lnot P \lor \lnot Q)$ the same?

warm shaleBOT
#

Shinutsi

ivory spoke
#

For instance in this example:

"Either John and Bill are both telling the truth, or neither of them is."

#

Does $(J \lor B) \lor \lnot(J \lor B)$ and $(J \lor B) \lor (\lnot J \lor \lnot B)$ both translate the statement correctly?

warm shaleBOT
#

Shinutsi

timid silo
ivory spoke
#

What's the difference?

timid silo
#

[
\neg(P \vee Q) \equiv \neg P \wedge \neg Q
]

warm shaleBOT
ivory spoke
#

What how

#

wait

#

let me process

timid silo
#

I will neither eat a burger or go out.

I will not eat a burger and I will not go out

ivory spoke
#

OHHHHHHHHHHHHHHHHHHHHHHHH

#

damn

#

thank you

#

got it now

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @ivory spoke

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

patent fog
#

did i derive C'(x1,x2) correctly?
fyi: a_n is an activation function, and although some values are the same (ie. w_1^1) every value is unique.

patent fog
#

sorry its a bit complicated but to give some info, im deriving the gradient for weights in the first hidden layer

#

$c_n^m$ represents the "constants" that wont need to be derived, just need the value for chain rule

warm shaleBOT
#

jtangkilla

obtuse pebbleBOT
#

@patent fog Has your question been resolved?

obtuse pebbleBOT
#

@patent fog Has your question been resolved?

patent fog
#

bruh

#

damn ig no one wants to do chain rule 😭

mighty lava
obtuse pebbleBOT
#

@patent fog Has your question been resolved?

obtuse pebbleBOT
#

@patent fog Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sharp anchor
#

So my problem is " what are the maximum amount points you can fit in a sphere of a radius of 60. Each point has the dimensions of a 4x4x4 box and has to be 20 units away from every other box."

obtuse pebbleBOT
#

@sharp anchor Has your question been resolved?

sharp anchor
#

I tried a triple integral but idk.

#

Used spherical coords

obtuse pebbleBOT
#

@sharp anchor Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

warm shaleBOT
#

Abo Wisam

obtuse pebbleBOT
#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

alpine bison
#

induction?

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vestal geode
#

I have multiple questions

obtuse pebbleBOT
vestal geode
#

Ill send them

tardy epoch
#

just ask one at a time

vestal geode
vestal geode
#

I just wanna know the answers

tardy epoch
#

too bad that's against the rules

vestal geode
#

Bet

#

How do i close

tardy epoch
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @tardy epoch

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

undone sentinel
#

The length of a box(say x) is only half of its width, and its height is 7 units larger than its length. If the volume of this box were to be 100^3, what would the box's length = x be? Round to the nearest hundredths necessary

undone sentinel
#

<@&286206848099549185>

unborn coral
#

I suggest naming the width y, and the height z, and expressing y and z in terms of x

unborn coral
#

if you name the width y, and x is half of y, that would mean y is twice the size of x, so y=2x

#

if you do the same for z, you're left with the width, height and length in terms of x

#

if you then use the formula to calculate volume and just insert your x'es and the number given for volume you should get an answer

undone sentinel
#

Thanks

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @undone sentinel

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lean dust
#

help

obtuse pebbleBOT
lean dust
obtuse pebbleBOT
#

@lean dust Has your question been resolved?

desert verge
#

what should you say?

lean dust
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @lean dust

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

grave crypt
#

how would i sketch this?

obtuse pebbleBOT
#

@grave crypt Has your question been resolved?

grave crypt
#

Consider the function
a) Estimate the slope of the tangent line at
b) Using the slope and the point of tangency, find the equation
of the tangent line.
c) The tangent line intersects the original graph one more time.
Where? Graph both the original function and the tangent line
to illustrate this.

#

i found the iroc is about -1

#

so thats my slope

obtuse pebbleBOT
#

@grave crypt Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ember island
#

why does 4-4sin^2 turn in 4(1-sin^2)

obtuse pebbleBOT
ember island
#

he said both of the terms have a common factor of 4

#

and said lets remove that common factor

#

but ion get it

stoic vale
#

well both 4 and -4sin^2x can be divided by four

ember island
#

yes

stoic vale
#

so you factor it out

ember island
#

4/4=1

stoic vale
#

i imagine you split it into root 4 * root (1- sin^2x)

#

okay well think about it like this

ember island
#

i dont get the 4 outside

stoic vale
#

say you had

#

9x^2 + 6x + 3

#

would you agree that all of these are multiples of three

ember island
#

yes

stoic vale
#

that means that you can turn it into 3(3x^2 + 2x + 1)

ember island
#

ye

stoic vale
#

okay so

#

its the exact same even when you have sin^2x

#

4 - 4sin^2x

ember island
#

so its like if i were to distrubute the 4

#

it would go to be 4-4sin^2

stoic vale
#

ye

#

if u want u can think about it like this

ember island
#

oh ok maybe im just having a slow moment

stoic vale
#

i have those

ember island
#

i can do factoring and stuff

stoic vale
#

so i get it

#

i think ur just overthinking it

ember island
#

but having to do everything wit sin cos and all that

#

struggling hard rn

stoic vale
#

cuz if ur at the level to be using sin^2x and all that you definitely know how to do it

#

its just recognising it that can bet he problem

ember island
#

and then he mentions how 1-sin^2x is equivalent to the identity sin^2x+cos^2x=1 which i get how but like ig its just confusing me cuz its just stuff u should know but i havent rememeber all this yet

stoic vale
#

if u just remember sin^2x + cos^2x = 1

#

you can rearrange that

#

but ye these identities are stuff you eventually just remember

ember island
#

would cos+1=sin

stoic vale
#

no

ember island
#

cos-1

#

...

stoic vale
#

no

ember island
#

damn

stoic vale
#

you can figure that out using sin^2x + cos^2x = 1

#

if you think about it

#

sin^2x = 1 - cos^2x

#

sqr root both sides

#

sin = root(1 - cos^2x)

ember island
#

so since 1-sin^2x is equivalent to cos

#

u can simplify that to

#

cos^2

#

so iits 1/sqrt4cos^2x?

stoic vale
#

cos does not equal 1 - sin^2x

#

cos^2x = 1 - sin^2x

ember island
#

oh

stoic vale
#

its a rearrangement of sin^2x + cos^2x = 1

#

depending on ur country/exam board you may not need to memorise these

#

but generally you should just know them after using them enough

ember island
#

for my exam i get a list of the trig identities

#

its just using them correctly🥲

stoic vale
#

ahaha good luck

ember island
#

like the way this was explained i just understood that 1-sin^2x=cos^2x because sin^2x+cos^2x=1 and if you subtract sin^2x from the left and right then it looks like what he said

stoic vale
#

thats right

ember island
#

is there a time where it would be 1-cos^2x

stoic vale
#

what do you mean?

ember island
#

like does sin^2x=1-cos^2x make sense

stoic vale
#

yup

#

again you just need to remember sin^2x + cos^2x = 1

#

and rearrange it

ember island
#

okay

#

and then he sqrts it

#

so cos^2x is just cos(x)

stoic vale
#

yep

ember island
#

and ik sqrt4 is 2

#

1/2cos(x)

stoic vale
#

because cos^2x is actually just (cosx)^2

#

ye thats right

ember island
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @ember island

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lethal garnet
#

Hi, if I attempt and have 50% chance of getting 1 point, and if I get it I have a 50% chance of it becoming 2 points, and if I get that I have a 50% chance of it becoming 3 points, what is the average points I get per attempt?

obtuse pebbleBOT
#

@lethal garnet Has your question been resolved?

obtuse pebbleBOT
#

@lethal garnet Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

slim glen
#

Hello. I am in pre algebra, and i have just a quick question. I am conevrting repeating decimals to rational numbers, and i multiply it by 100x etc. then i would subtract 10x. Why tf 10? And how does subtracting 10 make an irrational number rational 😭

slim glen
plain stag
#

You aren't subtracting 10x here

slim glen
#

Ik

slim glen
#

Sometimes its 10, 100 etc

#

And why would it get rid of the decimal?

#

And how do you know which number to use?

slim glen
plain stag
#

Well you multiply by 10, 100 etc so that you have one iteration of the repetition on the left side of the decimal

slim glen
#

Yes

#

I understand that

#

But not the subtraction part

plain stag
#

So for 0.45 repeating, you need to move the decimal 2 digits to the right, which is multiplying by 100

slim glen
#

Yes

plain stag
#

Well you subtract the original number to remove the decimal point entirely

slim glen
#

Original number?

plain stag
#

These two numbers have the same decimal part (since the decimal is infinite), so subtracting them gives 0

slim glen
#

How would i know when to subtract 10, 1, 100 etc

#

?

plain stag
#

Can you show a problem where you've subtracted anything other than 1?

slim glen
#

I was absent, i was looking over the slideshow and was confused, but i will provide what the slideshow gave me

plain stag
#

Seems to me it's a matter of convenience

#

You could do 1000x - x = 136, giving you x = 136/999 which is somewhat harder to reduce

#

Oh wait no, oops

#

You need to make the decimal parts match

#

So you have an extra 1 before the repeating part, so you need to multiply by 10 to move that to the left side of the decimal

slim glen
#

Ok, thanks so much.

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @slim glen

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

harsh remnant
#

Hello

obtuse pebbleBOT
harsh remnant
#

Can anyone explain what this means?

#

I understand that the probability vector above

#

But for the bottom, I am not sure why identity matrix is introduced

brave bramble
#

To get the result (P - I)s = 0

#

Do you understand how that result was obtained?

harsh remnant
brave bramble
#

They factored s

harsh remnant
#

I mean like

#

I understand Ps - s = 0

#

But why is this equation

#

The equivalent to

brave bramble
#

s = Is

harsh remnant
#

Ps - Is = 0

#

How though

brave bramble
#

Take any vector. Multiply it by the identity matrix. You get that vector back.

harsh remnant
#

I is a stochastic matrix

brave bramble
#

Ia = a

#

Ix = x

harsh remnant
#

Ohh

harsh remnant
brave bramble
#

Okay so we're at (P - I)s = 0

#

This actually gives a method for determining s, given P.

#

Compute P - I, then find the nullspace

harsh remnant
#

Why does s = [t/2, t]?

brave bramble
#

To get the nullspace of a matrix, we row reduce it, then look at the rows, as if they were equations

#

That top row says:
x - y/2 = 0

harsh remnant
#

But the matrix is not augmented

#

?

brave bramble
#

That's one equation, but two variables. So, one of the variables is free. To show this, we set that free variable to t

harsh remnant
#

So wait

#

x2 = t

#

So x1 = t/2?

brave bramble
#

And that's the result

harsh remnant
#

Ohhhh

#

Okay

#

Oh

#

nvm

#

Now

#

How do I go to the next step?

brave bramble
harsh remnant
#

How does t/2 and t become 1/3 and 2/3 respectively?

#

Ohhh ic

brave bramble
#

Looks like the components have to sum to 1

#

A probability thing

#

So t + t/2 = 1
t = 2/3

harsh remnant
#

By the way

#

Why is transpose also introduced?

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @harsh remnant

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

manic plover
#

can anyone actually help me with whats wrong..

plain stag
#

Have you constructed your tangent line?

tardy epoch
manic plover
#

wym

plain stag
#

I mean precisely what I said

tardy epoch
plain stag
#

The question asks you to use a tangent line near a "nice" point; have you figured out such a line?

manic plover
#

-1(x-1)+1

#

no?

plain stag
#

Now evaluate that at x = 1.002

manic plover
#

ok

#

1.001996

plain stag
#

,calc -1*(1.002-1)+1

warm shaleBOT
#

Result:

0.998
plain stag
#

You sure?

manic plover
#

what

#

you did 1.002

#

not 1/1.002

plain stag
#

Knowing the shape of f(x) = 1/x, if x > 1, should f(x) > 1?

tardy epoch
manic plover
#

bro what

#

why is 1/1.002 in the problem then

obtuse pebbleBOT
#

@manic plover Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

undone sentinel
#

If you click on the curve in 1950, 32.44 babies died in the first year of their lives. In 2020 there were 5.5 babies per 1000 live births. Using this to create points (1950, 32.44) and (2020, 5.5). Find the slope. What does this mean in the context of the problem

undone sentinel
#

the slope is -0.39

#

but idk what that means

#

that the mortality rate decreased by 0.39 per year?

obtuse pebbleBOT
#

@undone sentinel Has your question been resolved?

#
Channel closed

Closed by @undone sentinel

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
#

is there a limit? if there is what is solution? I calculated it as 1 but not sure

royal basin
#

can you show how you calculated it as 1?

timid silo
#

which is sqrt(x^2)

#

then divide both of them by sqrt(x^2 ) in square root

#

that made it sqrt(1/(1-0))

#

and then sqrt(1)=1

#

like this

royal basin
#

ok yeah that tracks

timid silo
royal basin
#

yes, that's what i said.

timid silo
#

When it is something like 3,4 i learned that you could check it from left and right side and see if they are equal which causes problems in piecewise functions i guess.

#

but can you do that really for infinities too?

brave bramble
#

Infinite limits are one-sided limits

timid silo
#

that really confused me

brave bramble
#

So no, you can't check from the left and right, like you would with a two-sided limit

#

None of this naturally exists. We made it all up!

timid silo
#

thats right

brave bramble
#

But infinite limits are "as legit" as other limits

timid silo
#

oh okay thanks

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

#
Channel closed

Closed by @spark egret

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

kindred marten
#

why is one infinity on the x part of the point while the other is on the y? ik one is negative and one isnt but i dont understand why one is on "x" and one is on "y"

cunning breach
#

That are the intervals, not the points.

kindred marten
#

oh

humble solstice
#

Calculate the angles of trapezium ABCD. Justify the answer!

kindred marten
#

what's the difference between the 2

#

..

cunning breach
#

Point is something defined in the coordinate system, and intervals restricts x-values.

kindred marten
#

ah i just remembered ty though

humble solstice
kindred marten
humble solstice
#

i could just send it in how it is but i wanna get a good grade

kindred marten
#

ur supposed to

#

use those

#

in the future

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @kindred marten

Use .reopen if this was a mistake.

humble solstice
#

how can i use one

kindred marten
#

see how there are ones under "occupied" and ones that arent

#

the channels

humble solstice
#

oh my bad

kindred marten
#

ur fine

humble solstice
#

what do i do now tho

#

do i occupy it or?

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cunning breach
cunning breach
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @cunning breach

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

brave bramble
#

Yes