#help-10
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the rate of change of volume is constant
implying the height is changing at a constant rate as well
ohh so if i think logically about it the rate of the height stays the same as it decreases
since volume is proportional to height
so the same answer would apply if i was looking for the rate when the height is 4m for example
right
yes
np
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AX = XB + C
B = 2I
AX = X(2I) + C
not sure where to go from here?
Can I do this?
(A^-1)AX = (A^-1)X(2I) + C
or am I forgetting about C when I do that
Oh, I thought it could remove A from the LHS
so you're fucking up both planning and execution
this is as unhelpful as dividing both sides by 7 in the equation 7x = 2x + 9
OK
anyway what you want to notice here is that $X \cdot 2I = 2I \cdot X = 2X$
AnnGhost
so I'm on the right track here, but I'm stuck on next step..
AX = X(2I) + C
the identity matrix and all scalar multiples thereof commute with everything
in order for the addition on the RHS to make sense, we need X(2I) to be 2x2
and we also need AX on the LHS to be 2x2
so X must be 2x2
but do we know that X is 2x2? or just assuming
no, this doesn't have to do with the size.
so therefore we know that the number of rows of X is 2
similarly on the LHS we know that AX is 2x2
but you do know that X is 2×2 from the equation.
where A is 2x2
we do?
yes
basically you can't add matrices unless they're the same dimension
but we have like X(2I) + C
this helps
but X could either be
- a scalar
- 2x2 matrix
ok look it wants a matrix it just says that in the question
oh right
ty
AX = X(2I) + C
so the identity disappears?
AX = X2 + C
AX = 2X + C
all 3 of these equations are equal?
yeah
just based on this
huh.. interesting
and the identity goes away because it doesnt' change anything when multiplying same size matrix
so it's kinda irrelevant
sure
OK
so now we are cooking with fire
AX = 2X + C
AX - 2X = C
is that a good next step?
yes
then I can factor out the X on LHS?
yes
good catch
now I divide both sides by A-2
no division in matrices
because you're doing matrix subtraction
multiply by reciprocal instead
would it be "wrong" to remove the I in this case?
yes
damn
well
X = C/(A-2I)
oh right, same thing as reciprocal
the equivalent, yeah
Probably show that it exists first?
so it cancels out the (A - 2I)
yes
yeah
and now you just need to find what that actually is with like matrix multiplication and inversion and stuff
I can't do thisX = C/(A-2I) because it's not clear if (A-2I) is on left or right side
essentially yeah
but X = [(A-2I)^-1]C is very clear it's on left side of C
OK tyvm
now I just calculate
wait, could I not just write it like this as well?
[(A-B)^-1]C
since B = 2I
i got X =
5 6 4 2
My A|I ~ I|A^-1 method might be using a chainsaw to cut a matchstick in half, but it gets the job done
gawd dammit
where?
hmmm, I did my multiplication wrong
oh it's the signs
99% of the way there and trip right before the finish line
sadly, if I had this as my answer on exam. big fat 0 for everything
they only give marks for correct answer and showing work
so all that effort and time for nothing, just flushed down the toilet
i don't know if I necessarily agree with that. Does your university do the same thing?
5 6 -2 -2
that's what it should be, but all the work before the last 2 steps are correct
that's how it goes
all or nothing
well no
ok they care about the working
i'm saying, very common to get basically everything right but make a small arithmetic mistake
but yeah more forgiving usually in my experience
so i should probably still get some marks for showing the work at least
up until the very last fumble
sure
marking math must be so time consuming, and subjective to the grader
i'm sure the examiner sees all sorts of weird shit on exams
they gotta determine if any of the mess is worth anything, which takes time, and it cannot be automated, only humans can do the job
my guess is that math teachers really earn their pay, the good ones should be paid more imo, it feels like they are doing more work than other subjects. but i could also be very wrong.
no clue
i've had a lot of exams that are simply multiple choice and get marked with dots on a score card by a computer
math exams are never offered in this format unfortunately lol
tyvm for the help @fervent cradle
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I was thinking exponential because the common ratio thingy of the y's but the X's look kinda funky idk
I think like exponential or maybe neither
Idk
try plotting the points and seeing what it looks like
ITS EXPONENTIAL LOOKING
it doesn't have to be beautiful
Plz believe
sketch it
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i can't even read properly
No helpers want to help me
sad
,rotate
Couldn't find an attached image in the last 10 messages.
,rotate
Bro this is grade 10 work
That root 6 is 6^0.5
And 6 is 36^0.5
So u get 36^0.5x0.5
ozioma do not directly give people answers, the point of this server to help people understand
no need for that
and the level of the problem is irrelevant, so long as someone needs help with it
yeah stop commenting on how "simple" material is for you
So x is equal to 0.25 or 1/4
Also how do you not know he isnt in 10th? Absolutely useless comment
the point is not to give the answer
Sorry
Lol
My first time helping
SOmetime its good to be honest
Im more worried about how he keeps asking for help with pretty much exact same questions
Yah me
Im talking about ac lol
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
Anyway the answer was very easy to get
Ok thnxs
U know when u have same bases u can cancel them out right?
That's what I did there
Got myself to a base of 36
So the bases cancel out
And they can cancel like that only when they r in opposite side of the = sign
yea
I just realized this homework is so repetitve
I Just went through 10 questions same damn thing they jsut ask it different ways
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Im so confused and im lost O-o idk where to start even
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So I think the bounds are 0 to pi/2 by that last part but not sure what c(t) is?
This is the formula btw
what's the usual parametrization of the unit circle?
Basically the formula but different letters
(sint, cost) right?
other way round
yes
Nice
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Can someone please give me an intuitive explaniation of what the mixed partial derivative means graphically?
I know that the second order partial derivative fxx and fyy just determine the concavity of the function created at a fixed x (or y) variable
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I know the right answer is 3 but I. don't get why if someome could help me
mind providing a translation?
the answers 3 says a can be any number you want and b <0
x-> -inf, so ae^x goes to 0
same with e^x
so you get be^-x/x^3
$\lim_{x \to -\infty} \frac{be^{-x}}{x^3}$
artemetra
e^-x goes to +inf, x^3 goes to -inf
therefore b must be negative to get -inf/-inf = +inf
it's.. basically what you have there written already
i just got confused cuz I thought -inf/-inf was indeterminate
or is it only when is -inf/+inf
i also think that honestly
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Can anyone recommend me a good video or resource on directional derivatives, thanks
Why can't you just Google this
Alright, i got a video from khan academy
thnks
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Question one
<@&286206848099549185> Rigorous proof alert ⏰
I dont really want to answer but i dont know what to do
I know it converges to 1/2(a + b) but i dont know how to prove it
perhaps i can use the definition of cauchy sequence or somethinig but idk how to proceed with that
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<@&286206848099549185> !!
@acoustic portal Has your question been resolved?
<@&286206848099549185> ☹️
Usual way is to assume the limit exists and is a variable, say c, then take the limit of the entire sequence and solve for c
@acoustic portal Has your question been resolved?
But for a recursive sequence, isn’t it much different v
Oh hmm
Try finding the first 5 terms and find a pattern
Then you can make some induction argument
The terms are like
(1/2)^n * coefficient of a + coefficient of b where
The coefficients are jacobinan(?) numbers for
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I need help finding the measure of the angle of the two intersecting bike trails, and the length of the pathway to the bridge (I also need help with the full solution)
Okay, can you draw a simpler diagram on paper?
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trying to find [
\lim_{n \to \infty} \f1n \p{n!}^{\ff1n}
]
I did this to check to see if like I can find out if I can find an upper bound that diverges
[
\f1n \p{n!}^{\ff1n} = \p{\f1{n^n} n!}^{\ff1n} = \f1n\m\ln{\f1{n^n} n!} = \f1n\m\ln{\f1{n^n}\int_1^n x \dd x} =\f1n\m\ln{\f{n^2-1}{2n^n}}
]
but this probably converges 
I'm 99% sure this is some wicked limit of e I can't find
A divergent upper bound would not tell you anything
Do you know Stirling's formula
oh sorry I probably mixed stuff up
No probably not
Ah you mean that
would substituting n! for that make it work out
oh I guess n^n's cancel
so that's nice
n! = ∫_1^n x dx ?
OHHH
.> but I was lazy sorry 
ok thanks for telling me about this Stirling formula thingy really helpful
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I need help with basically everything shown in this image. I'm very clueless on what to do or how to read it.
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My calculus teacher insists that none of the options are correct, but i got D
Could this just be a difference in the interpretation of the question?
It doesn’t equal, which is why I think she interpreted it differently
i mean the question doesnt make sense then
Yeah…
Could this be interpreted as (5,1) being a point on the tangent line, not on the graph?
I feel like that would be the only way
oooh then this gets much harder
and there could be multiple answers
i think there would be 2 answers
you can do that
Even with that interpretation, it would be y-1 = (10-2sqrt14)(x-5), which is not an option
you have y-(f(a)) = 10(x-a)
right?
that was my initial answer
so in this case
y-(a²-10) = 10(x-a)
and you also want
that for some value (x,y) = (5,1)
it holds true
so you have
1-(a²-10) = 10(5-a)
so you have to solve this quadratic in a
and this will lead you to the points
a
where the two tangent lines are possible
interesting
This equation doesn’t seem to have any solutions though
Yeah
its weird because visually it seems there should be such a tangent line
maybe i messed up somewhere
oh
the original is not with 10
y-(f(a)) = f'(a)(x-a)
1-(a²-10) = 2a(5-a)
a² -10a+10 = 0
,w solve x^2-10x+10=0
yes I understand
Benjamin
its a bit convoluted
but its the only valid answer
its a tangent
and it goest through (5,1)
I see…
but the real answer
is that the question doesnt have an answer in what they wanted you to do
Yeah the question was written poorly
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how do the two equations at the bottom have no solutions?
u can calc t for when it equals 0, no?
A solution for one won't be the solution for the other one 
oh yhhh
t has to be the same
for the vector to be (0,0)
makes sense, thanks
np
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In the exterior of the square ABCD there are equilateral triangles ADF and BCE. If DE intersected with CF = G, prove that the triangle AGB is equilateral
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@mint nebula Has your question been resolved?
maybe try drawing some parallel lines
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when using the a^2+b^2-= c^2 why cant i just square root the equasion to remove the ^2s?
like 9^2 +12^2 =c^2 equals 15
Because sqrt(a^2 + b^2) is (almost) never equal to a+b.
Exponentiation and surds aren't distributive like multiplication and addition are.
I mean
In your example you say 9^2 + 12^2 = 15^2
But clearly 9 + 12 = 21, not 15
So you can't just sqrt both sides and hope for the best
I mean you can, but then you have $c = \sqrt{a^2 + b^2}$
Azyrashacorki
And this can't be simplified further.
ok i havent learned that yet im just trying to learn the pythagorum therum
Yeah just know that the square root and exponentiation distribute over multiplication/division, but not over addition/subtraction.
$\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}$
ok kind of like factoring
Azyrashacorki
yes ok i know thay
It's the exponents law
I wouldn't say it like that, but I guess so. You just can't distribute the square root. For the same reason that you can't distribute squares $(a+b)^2 \neq a^2 + b^2$.
Azyrashacorki
Someone explain to me wth is parametric form of a eqn of a straight line
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ok that makes sense
Ok
If you have some roots you want to get rid of, like say you have $v = \sqrt{a}$.
Azyrashacorki
Then you can square both sides to get $v^2 = a$.
Azyrashacorki
This you can do
or what about if it is a square root * a square troot
Yes this distributes
square roots are just exponents 1/2
they arent opposites?
So $a^{1/2}\cdot a^{1/2} = a^{1/2 + 1/2} = a^1 = a$
Azyrashacorki
and 1/2 is a square root
Yes.
The inverse would be squaring.
Similarly, you can think of division as a multiplication right? a/b = a * (1/b)
ok
Well you can think of surds as exponents that are fractions.
yes
Cube roots are 1/3
Yeah it'll clock in with some practice
ok cool i appreciate your help
i think thats all i need im going to keep practacing
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hello
can someone help me with these questions and correct them for me
"List your 3 points you have identified. Write them to 2 decimal places.
(-1,2) (0,1) (1,3)
Write the equation you have found using this Step (write the three points on your parabola (labeling effectively) and use your knowledge of three variable, three equation systems to find a quadratic equation for your parabola. Need to find a, b, and c! (USE MODE, 5, 2)"
this is the points you might need it
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I have a question here that is kinda confusing me, its SCM, but its basic math, its just a word problem. I already calculated shrinkage which is 326 units per month to meet 7500 sets per month, so now I'm just having trouble with question #3.
How I thought of solving it was 7500 x 12 = 90,000 sets per year sold and 7826 x 12 = 93912 to account for shrinkage.
So you're profiting off 90,000 sets per year, so 275 x 90,000 = 24,750,000 and then 200 x 93912 = 18,782,400 to account for all costs.
Now its just revenue - costs so 24,750,000 - 18,782,400 = 5,967,600 profit.
The actual answer to this question is 782,400, which makes no sense to me
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hi
if u(x) = cos(x+1) and v(x) = x-1 then u(v(x)) is cos((x-1)+1) right
which is just cos(x)
yes
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i subtitue its -25/0 .
how to solve it?
L 🏥
but if 2x - 6 / 1 = 4
using another way

but even with l'hop: 2x-6 at x=1 gives -4, not 4
you're taking an L from me
I give myself a W
You can’t divide by 0
@bold brook Has your question been resolved?
also -25/0, you can't do l'hopital on that, it's only for 0/0 or infty/infty cases
your problem seems broken tbf
as written in the question, the limit doesn't even exist
well ask your prof or whatever
she said the answer was there
,w lim x->5 (x^2-6x-20)/(x-5)
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anyone please 🤦♂️
!status
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4
do you understand how nonsensical the answer is lol
not at all 😭
oh wait no hold on i misread
thought you had a six figure tax total
but also why do you add 5092 tho.
was i supposed to minus
no
you were supposed to see you are in the third bracket: 45,001-120,000
the tax equals 32.5% of everything in excess of 45k, plus 5092
that's what you add 5092 to
not the original gross income
ohhh
the amount taxable in this bracket specifically is 97000-45000
still abit lost, whts the answer tho 😭
oh my bad typo
92,000 - 45,000
this difference is taxed at 32.5%
so the tax for this bracket is 32.5% * (92k - 45k)
and you add to that the total tax from the prev brackets which is 5092
20,367?
,calc (92000-45000)*0.325 + 5092
Result:
20367
ok yeah
cheers bro
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everyone's a bro
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Are $\lnot (P \lor Q)$ and $(\lnot P \lor \lnot Q)$ the same?
Shinutsi
For instance in this example:
"Either John and Bill are both telling the truth, or neither of them is."
Does $(J \lor B) \lor \lnot(J \lor B)$ and $(J \lor B) \lor (\lnot J \lor \lnot B)$ both translate the statement correctly?
Shinutsi
no
What's the difference?
[
\neg(P \vee Q) \equiv \neg P \wedge \neg Q
]
I will neither eat a burger or go out.
I will not eat a burger and I will not go out
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did i derive C'(x1,x2) correctly?
fyi: a_n is an activation function, and although some values are the same (ie. w_1^1) every value is unique.
sorry its a bit complicated but to give some info, im deriving the gradient for weights in the first hidden layer
$c_n^m$ represents the "constants" that wont need to be derived, just need the value for chain rule
jtangkilla
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True
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So my problem is " what are the maximum amount points you can fit in a sphere of a radius of 60. Each point has the dimensions of a 4x4x4 box and has to be 20 units away from every other box."
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Abo Wisam
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induction?
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I have multiple questions
Ill send them
just ask one at a time
Im gonna be real with you
I just wanna know the answers
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The length of a box(say x) is only half of its width, and its height is 7 units larger than its length. If the volume of this box were to be 100^3, what would the box's length = x be? Round to the nearest hundredths necessary
<@&286206848099549185>
I suggest naming the width y, and the height z, and expressing y and z in terms of x
Can you show me how
if you name the width y, and x is half of y, that would mean y is twice the size of x, so y=2x
if you do the same for z, you're left with the width, height and length in terms of x
if you then use the formula to calculate volume and just insert your x'es and the number given for volume you should get an answer
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help
@lean dust Has your question been resolved?
what should you say?
.close
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how would i sketch this?
@grave crypt Has your question been resolved?
Consider the function
a) Estimate the slope of the tangent line at
b) Using the slope and the point of tangency, find the equation
of the tangent line.
c) The tangent line intersects the original graph one more time.
Where? Graph both the original function and the tangent line
to illustrate this.
i found the iroc is about -1
so thats my slope
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why does 4-4sin^2 turn in 4(1-sin^2)
he said both of the terms have a common factor of 4
and said lets remove that common factor
but ion get it
well both 4 and -4sin^2x can be divided by four
yes
so you factor it out
4/4=1
i imagine you split it into root 4 * root (1- sin^2x)
okay well think about it like this
i dont get the 4 outside
yes
that means that you can turn it into 3(3x^2 + 2x + 1)
ye
oh ok maybe im just having a slow moment
i have those
i can do factoring and stuff
cuz if ur at the level to be using sin^2x and all that you definitely know how to do it
its just recognising it that can bet he problem
and then he mentions how 1-sin^2x is equivalent to the identity sin^2x+cos^2x=1 which i get how but like ig its just confusing me cuz its just stuff u should know but i havent rememeber all this yet
if u just remember sin^2x + cos^2x = 1
you can rearrange that
but ye these identities are stuff you eventually just remember
would cos+1=sin
no
no
damn
you can figure that out using sin^2x + cos^2x = 1
if you think about it
sin^2x = 1 - cos^2x
sqr root both sides
sin = root(1 - cos^2x)
so since 1-sin^2x is equivalent to cos
u can simplify that to
cos^2
so iits 1/sqrt4cos^2x?
oh
its a rearrangement of sin^2x + cos^2x = 1
depending on ur country/exam board you may not need to memorise these
but generally you should just know them after using them enough
ahaha good luck
like the way this was explained i just understood that 1-sin^2x=cos^2x because sin^2x+cos^2x=1 and if you subtract sin^2x from the left and right then it looks like what he said
thats right
is there a time where it would be 1-cos^2x
what do you mean?
like does sin^2x=1-cos^2x make sense
yep
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Hi, if I attempt and have 50% chance of getting 1 point, and if I get it I have a 50% chance of it becoming 2 points, and if I get that I have a 50% chance of it becoming 3 points, what is the average points I get per attempt?
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Hello. I am in pre algebra, and i have just a quick question. I am conevrting repeating decimals to rational numbers, and i multiply it by 100x etc. then i would subtract 10x. Why tf 10? And how does subtracting 10 make an irrational number rational 😭
You aren't subtracting 10x here
Ik
But ik saying
Sometimes its 10, 100 etc
And why would it get rid of the decimal?
And how do you know which number to use?
*im
Well you multiply by 10, 100 etc so that you have one iteration of the repetition on the left side of the decimal
So for 0.45 repeating, you need to move the decimal 2 digits to the right, which is multiplying by 100
Yes
Well you subtract the original number to remove the decimal point entirely
Original number?
These two numbers have the same decimal part (since the decimal is infinite), so subtracting them gives 0
Can you show a problem where you've subtracted anything other than 1?
I was absent, i was looking over the slideshow and was confused, but i will provide what the slideshow gave me
Seems to me it's a matter of convenience
You could do 1000x - x = 136, giving you x = 136/999 which is somewhat harder to reduce
Oh wait no, oops
You need to make the decimal parts match
So you have an extra 1 before the repeating part, so you need to multiply by 10 to move that to the left side of the decimal
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Hello
Can anyone explain what this means?
I understand that the probability vector above
But for the bottom, I am not sure why identity matrix is introduced
Not really..
They factored s
I mean like
I understand Ps - s = 0
But why is this equation
The equivalent to
s = Is
Take any vector. Multiply it by the identity matrix. You get that vector back.
I is a stochastic matrix
Ohh
Can you also explain this part please?
Okay so we're at (P - I)s = 0
This actually gives a method for determining s, given P.
Compute P - I, then find the nullspace
Why does s = [t/2, t]?
To get the nullspace of a matrix, we row reduce it, then look at the rows, as if they were equations
That top row says:
x - y/2 = 0
That's one equation, but two variables. So, one of the variables is free. To show this, we set that free variable to t
And that's the result
We are finding the nullspace, so we care about the case where these rows are equal to 0
Looks like the components have to sum to 1
A probability thing
So t + t/2 = 1
t = 2/3
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can anyone actually help me with whats wrong..
Have you constructed your tangent line?
@manic plover
wym
I mean precisely what I said
The question asks you to use a tangent line near a "nice" point; have you figured out such a line?
Now evaluate that at x = 1.002
,calc -1*(1.002-1)+1
Result:
0.998
You sure?
Knowing the shape of f(x) = 1/x, if x > 1, should f(x) > 1?
x is not 1/1.002. x = 1.002
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If you click on the curve in 1950, 32.44 babies died in the first year of their lives. In 2020 there were 5.5 babies per 1000 live births. Using this to create points (1950, 32.44) and (2020, 5.5). Find the slope. What does this mean in the context of the problem
the slope is -0.39
but idk what that means
that the mortality rate decreased by 0.39 per year?
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is there a limit? if there is what is solution? I calculated it as 1 but not sure
can you show how you calculated it as 1?
i wrote also x as square root
which is sqrt(x^2)
then divide both of them by sqrt(x^2 ) in square root
that made it sqrt(1/(1-0))
and then sqrt(1)=1
like this
ok yeah that tracks
is this correct
yes, that's what i said.
Also can you really check if limit exists in limits goes to infinity?
When it is something like 3,4 i learned that you could check it from left and right side and see if they are equal which causes problems in piecewise functions i guess.
but can you do that really for infinities too?
Infinite limits are one-sided limits
yeah so would that make them naturally doesn't exist or something?
that really confused me
So no, you can't check from the left and right, like you would with a two-sided limit
None of this naturally exists. We made it all up!
thats right
But infinite limits are "as legit" as other limits
oh okay thanks
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why is one infinity on the x part of the point while the other is on the y? ik one is negative and one isnt but i dont understand why one is on "x" and one is on "y"
That are the intervals, not the points.
oh
Calculate the angles of trapezium ABCD. Justify the answer!
Point is something defined in the coordinate system, and intervals restricts x-values.
ah i just remembered ty though
been tryna figure this out for 5 days now and im 1 day late for my test
there are unoccupied channels btw
i could just send it in how it is but i wanna get a good grade
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oh my bad
ur fine
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You post your question in one of the available channels.
.close
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Yes