help-10

[obtuse pebble]

@hot wing Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stuck herald]

was this correct approach?

[gilded drift]

I'm not great at this, but why did you immediately assume that 1+a^3*b is positive

couldn't both a^2 b^3 c and 1+a^3 b be negative

Oh wait

division

Well technically if it was negative signs would be reversed

[stuck herald]

no cos it won't be >0 then

[stuck herald]

?? what

[gilded drift]

Let me explain
if a^2 b^3 c and 1+a^3 b are both negative, then them multiplied would be positive

[gilded drift]

You divided it, but it could still be either positive or negative

[gilded drift]

also I don't get why you just removed a^2 and c

[fossil night]

This is where I get help?

[gilded drift]

No

You go to available help channels

[obtuse pebble]

@stuck herald Has your question been resolved?

[stuck herald]

so i didn't need to go further like that what i did

i could have deduced there itself u meant to say??

[gilded drift]

It's possible that
1+a^3 b < 0, a^2 b^3 c <0

[gilded drift]

It gives a different set of possible answers

well 1 + a^3 b < 0 cannot be true because rules but like it's there

[stuck herald]

why

it can be negative no?

[gilded drift]

Yes

but a<1 and b<1 therefor it cannot be <-1

so like ur solution was correct

although why did you cancel ur c

[stuck herald]

1 + a^3 b this will be positive no allways as all -1<a,b,c <1

they ratios

[stuck herald]

where

[gilded drift]

a^2 b^3 c > 0

c just disappeared

you can cancel the a^2 since we know that

but b^3 c > 0 can yield negative for b and c

since we know b^2 is positve

we can remove the b^2 in b^3 and get that bc>0

[obtuse pebble]

@stuck herald Has your question been resolved?

Channel closed

Closed by @stuck herald

Use .reopen if this was a mistake.

[stuck herald]

thanks

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[merry topaz]

Consider a polynomial P(x) = 8(2x^3 - 9x²+12x-5)+ a. Consider a function g(a) which is defined as number of real roots of equation P^a(x) = 0 in the interval (0,1) where p^a (x) = P(P(P.........P(x)))) (for example, P³ (x) = P(P(P(x)))). a times

Then find the value summation a 1 to 4 g(a)

[royal basin]

got a picture...?

[royal basin]

the fact that a is involved both in the polynomial it-

oh god the black bands.

[merry topaz]

G1 is 0

[royal basin]

ok so

... fuck how the hell are you even supposed to do this without being a human calculator

like

for g(4)

they expect you to... what, consider a fucking 81st degree polynomial?

[merry topaz]

Use brain 🧠 isuppose

[royal basin]

are you sure g(1) = 0 btw?

i don't know what you meant by G1.

but i assume you meant g(1) but typed it very badly.

[merry topaz]

g(1)

Yeah just put it

[royal basin]

are you SURE g(1) really is 0

when there is a root visible right there

[merry topaz]

Ok

Hmm

What is g2 g3 g4

Respectively

Hlo?

[royal basin]

sorry, did you just "Hello?" me for 30 seconds of absence?

[merry topaz]

It always works

[royal basin]

you realize it's very rude right

and entitled

for THIRTY GODDAMN SECONDS

[merry topaz]

Ok let it be

[royal basin]

idk take these screenshots and count them yourself

[royal basin]

i dont really want to let it be when people are rude to me

!volunteers

[obtuse pebble]

Helpers are just people volunteering their time to help you. Be polite and patient.

[royal basin]

it's disgusting how impatient you just behaved there

[obtuse pebble]

@merry topaz Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Ok so I am trying to find the ambient temperature of an oven(Ta)

I found the expression

But I could not figure out how to find Ta, given I have many unknown variables

The conditions given were:
initial temperature of liquid = 25c

After 1 minute of oven temperature increased by 25C

After 2 minutes in oven temperature of liquid is 73C

.close

[obtuse pebble]

Channel closed

Closed by @rich siren

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce lagoon]

Okay what about it

[worthy patio]

yo

[fierce lagoon]

For the most part yeah

This is undefined at 0

This is defined at 0

[worthy patio]

dang, am in 6 th grade we only learned plus and minus💀

[fierce lagoon]

But that's like the only difference

They're otherwise equivalent

[wooden cipher]

How old are you

[worthy patio]

sorry i can't say, am not allowed

guys what does x mean?

[wooden cipher]

Is it below 13?

[worthy patio]

i can't say

????

bro

i said i can't say

stop forcing me

what does x mean?

can u help me with my homework?

please

okay

what is a 90 dagree angle?

??

dang

90 degree angle

ok, is that u?

ur pfp?

is that u?

bye

pls stop saying am young

i said, stop saying what my age is

its not cool

i dont wanna say my age in discord

[royal basin]

!redir

[obtuse pebble]

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

[royal basin]

for legal reasons we need to know if you're over or under 13.

ah, rip them.

@vocal marsh do you still have a question to ask?

[obtuse pebble]

@vocal marsh Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split dew]

Would f(0) here be equal to 2 here?

[split dew]

And f(x) would be 1?

[dark stirrup]

✅

[dark stirrup]

❌

[split dew]

Thanks

.close

[obtuse pebble]

Channel closed

Closed by @split dew

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still oxide]

does anyone know what this equation is about? I don't get how the partial of 2 terms on the left become 4 terms on the right

[pseudo swift]

you have some product rule going on

f_x x_s is a product of 2 functions

[still oxide]

yea but i dont get why
∂/∂t of f_x * x_s = f_xt * x_s + f_x * x_st

[pseudo swift]

$\pdv{}{t}\left( f_x x_s\right) = \left(\pdv{}{t}f_x\right)x_s + f_x\left(\pdv{}{t}x_s\right)$

[warm shale]

aPlatypus

[pseudo swift]

that's the product rule right?

@still oxide

[still oxide]

oh

wait i didnt learnt that

[pseudo swift]

I'm pretty sure you had calc 1 at some point

it's the same thing here

except with the partials

[still oxide]

yea ok

thanks

.close

[obtuse pebble]

Channel closed

Closed by @still oxide

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uneven night]

Determine all functions f (x, y) that solve the equation
for example with a variable change u = ax + y, v = x, for any suitable value of the number a

[austere hound]

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[uneven night]

4

@austere hound

<@&286206848099549185>

Is my work correct

[olive urchin]

Hi. Can anyone help me in choosing one of these four topics for my mathematics projects: 1)Mensuration: Applications and
illustrations from daily life situations, etc.
2)Applications of Arithmetic
Progression in daily life situations, etc.
3)E-commerce -Impact on World
economy -Discusswith-illustrationss, etc.

[uneven night]

But g(3x)=x

[olive urchin]

k

[uneven night]

I just ignore the the x on the RHS

Np

So my work aren’t correct

Homework

So I integrated on both sides I got v=g(u)

Then I changed u to 2x+y

And plugged in f(x,x)

So we got g(3x)=x

What happens next

What

I don’t understand

Plug what

I already plugged in f(x,x) which gave me 3x

But

How did you got 4a+b

What is a and what is b

5?

Wait where did c come from?

So you can’t help me?

Np

Thanks anyway

.close

[obtuse pebble]

Channel closed

Closed by @uneven night

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[timid silo]

3

And

1

[upper widget]

what did you do to get ur incorrect answer

[timid silo]

Added parallel lines then time by 2

[upper widget]

right

so

lets start from what we want

the height

we have

right

[timid silo]

4 and 6

[upper widget]

yes

so we end up with

[timid silo]

10

[upper widget]

right

well its 10/2

so its 5

[timid silo]

Yes

[upper widget]

whats A=?

[timid silo]

Area

[upper widget]

i mean the value

whats the value

[timid silo]

20cm2

[upper widget]

so this right

we want h on its own

how do u think we can get h on its own

[timid silo]

Divide by 5 on both sides?

[upper widget]

yup

so h =?

[timid silo]

4

[upper widget]

yeah

[timid silo]

Thank you!

.close

[obtuse pebble]

Channel closed

Closed by @slender ledge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[burnt light]

Why is the square root of 2 equal to the fourth root of four?

[tardy epoch]

2^2 = 4

,tex .exp rules

[warm shale]

riemann

[cunning breach]

$2^{\frac{1}{2}}=2^{\frac{2}{4}}$

[warm shale]

Good

[burnt light]

Makes sense, thanks.

.close

[obtuse pebble]

Channel closed

Closed by @burnt light

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[indigo cipher]

Is this derivative correct?

[brazen gorge]

,rccw

[obtuse pebble]

@indigo cipher Has your question been resolved?

[obtuse pebble]

@indigo cipher Has your question been resolved?

[obtuse pebble]

@indigo cipher Has your question been resolved?

[heavy thicket]

Looks good

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[short burrow]

my math teacher gave this problem as a practice and i think x = 1 but that is only using the short leg and hypotenuse. When i try to double check with base leg i get stuck

[austere hound]

30-60-90 triangles have this neat property that the hypotenuse is twice the length of the short leg

And the long leg is short_leg*sqrt(3)

[short burrow]

when i set the long leg equal to 3.5√3 it dosent work.

there is no 0

is the problem written wrong?

[austere hound]

no the math looks good to me

That might be the solution though

that for no value of x is that triangle a 30 60 90 triangle

[short burrow]

hmm makess sense

i think your right.

[austere hound]

Because the rules of geometry are pretty strict and sqrt(3)/2 * 1 + sqrt(75) != sqrt(3)*3.5

[short burrow]

yeah

[austere hound]

Your graphical solution work well as a proof too, showing there are no roots to the equation is proof

[short burrow]

thank you

.close

[obtuse pebble]

Channel closed

Closed by @short burrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tiny spire]

Is anyone able to help me with this linear algebra problem. Question 22 please : )

[austere hound]

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[tiny spire]

1

[obtuse pebble]

@tiny spire Has your question been resolved?

[obtuse pebble]

@tiny spire Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mellow pelican]

I do need some help with something

[teal turret]

pray tell

[obtuse pebble]

@mellow pelican Has your question been resolved?

[teal turret]

what have u tried

[mellow pelican]

I understand how to do the first part but I am confused on how to do the second part

[teal turret]

plug in the point (0,1) into ur value of dy/dx

then use point slope form to make a linear equation

[mellow pelican]

wait both values

[teal turret]

what dy/dx did u get

[mellow pelican]

I got

[teal turret]

ok now plug in ur values of x and y into that to find the slope at that point

[mellow pelican]

Ok

Ok I pluged in the values the slope to equal - 1 - e

[teal turret]

ok now

u know point slope form of linear eqns?

[mellow pelican]

Ok so then: y-1=(-1-e)

[teal turret]

what happened to the x part

[mellow pelican]

Oh wait

y - 1 = (- 1 - e)x

Ok thank you

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting wraith]

hint from google

well it means 10^4

9999 is divisible by 101

i don't get it though

oh okay

@fierce ocean

remember the rule for divisibility by 3, especially why it's like that

[obtuse pebble]

@fierce ocean Has your question been resolved?

Channel closed

Closed by @fierce ocean

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant cipher]

hello i need help with relative rate

[pliant cipher]

i simplified the equation for it to be like

6(dc/dt) = 320sin(theta)

.close

[obtuse pebble]

Channel closed

Closed by @pliant cipher

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sterile vale]

"determine the new equation after the following transformations."

8x^2 +y^2 =2
a horizontal expansion by a factor of 2, then a vertical compression by a factor of 1/3

[sterile vale]

here is what I'm doing

1/2(8x^2) + y^2 =2

then 4x^2 + 1/3(y^2) =2

and in the end I get 4x^2 + y^3 =6

but the answer is 2x^2 +9y^2 =2

where did I go wrong?

wont 8(x/2) result in the same thing?

How did you get the 4 in the denominator’s place?

Oh my goodness, I can be such a dunce sometimes

Maybe it’s a good idea to fully write out what I’m doing lol

Now I’m wondering just how in the world there is a 9 beside the y

Yeah, I now see how it could be y^2/9

That’s what makes this confusing lol

[obtuse pebble]

@sterile vale Has your question been resolved?

[obtuse pebble]

@sterile vale Has your question been resolved?

[obtuse pebble]

@sterile vale Has your question been resolved?

[obtuse pebble]

@sterile vale Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hard pike]

can 3x^2+11x−20 be simplified further?

[rich plume]

you mean can it be factored?

[hard pike]

yes

[rich plume]

yes it can be

[hard pike]

b

[rich plume]

you can try to break the middle term

or by the concept of perfect squares

[hard pike]

nothing ads to give 11 and multiplies to give 60

or is it -60

wait...

[rich plume]

It is -60

[hard pike]

its 15 and -4

,$ 3x^2+15x-4x−20

[rich plume]

yes

[hard pike]

$3x^2+15x-4x−20

[rich plume]

$3x^2+15x-4x−20$

[warm shale]

B-eard

[hard pike]

cool, i know where to go from here

[hard pike]

Thank you for your help

.close

[obtuse pebble]

Channel closed

Closed by @hard pike

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[valid temple]

Hey there! I'm doing some intercepts on the plane and I was wondering why in some cases you have to sqrt all the equation, meanwhile in others you don't. Here is the example:

The operations on the whiteboard is what I think i should do, but apparently nop.

Thanks in advance!

[valid temple]

My question is, why on the first screenshot you can sqrt all and have the result, meanwhile in the other operation, you cannot sqrt all

[sage geode]

sqrt(a^2 + b^2) is not a + b

[cunning breach]

$(-2)^2+y^2$ is not $(-2+y)^2$

[warm shale]

Good

[valid temple]

mmm

still don't understand

I mean, why i cannot just sqrt all the equation for eliminating those ^2?

[cunning breach]

The reason why you are allowed to cancel the squared in the first photo, is that the expression is one. In the third picture, you're trying to cancel out two expressions, which is not allowed.

[valid temple]

okey so, in the first image it's correct because it just sqrt((x-2)^2) meanwhile what i tried to do it's incorrect because its sqrt((-2)^2+y^2)

and why it's not allowed?

[cunning breach]

$$(x-2)^2 = (x-2)(x-2) = y \cdot y$$ meanwhile $$(-2)^2 + y^2 \ne (-2+y)(-2+y)$$

[warm shale]

Good

[valid temple]

okay so, you in this cases you can just sqrt when you have those special identities?

[cunning breach]

$$\sqrt{x}=x^{\frac{1}{2}}$$ so $$\textcircled{1} (x-2)^2 => \sqrt{(x-2)^2} => x-2$$ but $$\textcircled{2} \sqrt{(-2)^2 + y^2}$$ you cannot do the same as $\textcircled{1}$.

[warm shale]

Good

[valid temple]

Okay, i think i got it

thank you so much!!

@valid temple

[cunning breach]

Welcome.

[valid temple]

.close

[obtuse pebble]

Channel closed

Closed by @valid temple

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[junior jay]

.repen

.reopen

[dense crater]

Do you know the SOH CAH TOA?

[craggy berry]

what is tan27

the value of tan27

[royal basin]

that isn't how the command is used

in fact, if you type anything beginning with a . in an available channel, it PREVENTS the channel from opening on your message

also yeah @junior jay do you know basic trigonometry

[craggy berry]

.reopen

oo

[alpine raven]

[craggy berry]

trignometry

i know the tan 30 value

1/root 3

[royal basin]

thats great but nobody asked

!redir

[obtuse pebble]

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

[craggy berry]

but how to find tan 27

[junior jay]

I think

[craggy berry]

anng host

[dense crater]

You have a given of adjacent and an angle

[craggy berry]

you can use tan value and find it

[dense crater]

You're trying to find the Opposite

[junior jay]

yep

[craggy berry]

tan = opposite/adjacent

[junior jay]

yes

[dense crater]

Use TOA

[craggy berry]

tan27=ac/bc

bc=13

[dense crater]

from the SOH CAH TOA

[junior jay]

so tan(27 = 0.50952

then what

[craggy berry]

0.50952 = ac / 13

then ac= 0.509*13

ac = 6.617

cm

Yea AC = 6.617cm

[junior jay]

yeah

so thats it?

[craggy berry]

yea

[junior jay]

I got another

[craggy berry]

I still study in like high school

[junior jay]

that's good

[craggy berry]

do you have any high school level math

doubts

[junior jay]

yep

[craggy berry]

oke

[junior jay]

wait

so this would be a

[craggy berry]

130 degress

130 degree

because when we add both angles a and b we need to get 180

soo 180-50

is 130

wait bro one sec

[junior jay]

where did you get 130?

I dont know how to do this

[craggy berry]

yess its 130

we had the same question

see

if we add both angles A and B

we are supposed to get 180 degree

because both form straight line

therefore

[junior jay]

the missing is 130

[craggy berry]

angle A=50

A+B=180

50+B=180

B=180-50

B=130

soo angle B is 130 degree

co interior angles

gott it

[junior jay]

alright let me get another question cause I need to practice to learn

[craggy berry]

do you have the answer key

for the bearing question

[junior jay]

wait I think you might be wrong

[craggy berry]

do u have google

on your device

[junior jay]

yeah I used the same one

[craggy berry]

lol

b is 130

its given'

[junior jay]

alr thanks Im gonna go now

[craggy berry]

add me brother

gtg too

byee

[junior jay]

ill ask if I need help

[craggy berry]

oke

[junior jay]

goodbye

[craggy berry]

bye

[obtuse pebble]

@junior jay Has your question been resolved?

Channel closed

Closed by @junior jay

Use .reopen if this was a mistake.

[junior jay]

.reopen

[obtuse pebble]

✅

[junior jay]

.reopen

<@&286206848099549185>

[obtuse pebble]

@junior jay Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plain nebula]

can someone lmk what i did wrong

[royal basin]

what's the deriv of 2x^3+x?

[plain nebula]

6x^2

is it not

[royal basin]

no

that's just for 2x^3

[plain nebula]

oh shit

i forgot the 1 lol

[royal basin]

yes you did

[plain nebula]

thanks so much lol

[royal basin]

also don't forget parentheses, also don't quite your sixes like b's.

[plain nebula]

what are those again

[royal basin]

those = who?

[plain nebula]

parenthases

[royal basin]

()

these fuckers

[plain nebula]

oh oh okay

[cloud shadow]

hi

[plain nebula]

did i do it wrong somewhere?\

[royal basin]

!redir

[plain nebula]

like the brackets

[cloud shadow]

!redir

what does that do

[royal basin]

formally no but you'll need them in the corrected version

[plain nebula]

oh u mean like () instead of writing multiply

[royal basin]

ok my bad it used to be a factoid but now it's not

anyway uh

[cloud shadow]

k

[royal basin]

if you have a question of your own then take your own channel, otherwise go to #discussion or #chill

[plain nebula]

ok im done tysm!

.close

[obtuse pebble]

Channel closed

Closed by @plain nebula

Use .reopen if this was a mistake.

[royal basin]

wait let me test this again...

!redir

[obtuse pebble]

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

[royal basin]

huh strange

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mellow remnant]

For number one. If a^2 - b^2 equals (a+b)(a-b) why is exercise number one doing something else? Could somebody explain please?

[austere hound]

,rccw

[austere hound]

Having kind of a hard time reading but are you referrring to the task

,, \Big( \sqrt{x} + \frac{1}{\sqrt{x}}\Big)^2 - \Big(\sqrt{x} - \frac{1}{\sqrt{x}}\Big)^2

[warm shale]

Joachim

[obtuse pebble]

@mellow remnant Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom schooner]

39a

[austere torrent]

How

Srr

[fathom schooner]

?

39 a please

[obtuse pebble]

@fathom schooner Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

<@&286206848099549185> tell me if this is correct or not.

[timid silo]

I'm using the quadratic formula to solve

[flat star]

yes it's correct

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pine yacht]

can someone plz explain this from the 2nd last step

[tacit scarab]

so we factored the quadratic

and for the last step you can either treat (m-4)(m-6) as a quadratic

or consider two cases: case 1 which m-4 is positive and m-6 is negative, and case two of m-4 being negative and m-6 positive

[pine yacht]

@tacit scarab didnt get it

[tacit scarab]

ok let's remember that a quadratic open upwards with positve coefficient

thus it's negative between the roots

[pine yacht]

i dont get it

can u explain it in a simpler way (english isnt my first lang srry )

im not getting things from this part

[tacit scarab]

a general quadratic can be written as ax^2+bx+c=0

[pine yacht]

yes

[tacit scarab]

and when a is positive, it open upwards

[pine yacht]

what does open upwards mean

[tacit scarab]

like it curves upwards

,w graph y=x^2-1

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by _wherewolf_

[pine yacht]

ok

[tacit scarab]

as you can see if the graph curves upwards, it is negative between the roots

[pine yacht]

negative between the roots ?

@tacit scarab is it ok if i revise my theory (as i dont remeber it) and then come back to u

[tacit scarab]

ok

[pine yacht]

thanks

mb for coming half prepared

[tacit scarab]

let a<b and they are the roots, then the quadratic is negative for a<x<b

[obtuse pebble]

@pine yacht Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid yew]

what's the procedure to do this exercise

[obtuse pebble]

@vivid yew Has your question been resolved?

[vivid yew]

help

[timid silo]

Yeah thanks

[vivid yew]

fine

[pulsar oriole]

Okay, this question is not very well posed. But the lines in each family all pass through a single point.

I would locate that point in each case and then draw five lines through it.

[vivid yew]

i know that , i mean what's the correct sentence and procedures to used.
i will do an exam next week linked to this, so i want to see someone do an example.

if it's too long for you, give up, some else will try

.close

[obtuse pebble]

Channel closed

Closed by @vivid yew

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

I want to understand the geometrical proof of d(sin(θ))/dθ = cos(θ).

I was watching Grant's video on derivatives and he used a unit circle to prove that d(sin(θ))/dθ = cos(θ). The image attached below shows how he did it.

My question is, how is the smaller triangle similar to the bigger one, so that the angle between d(sin(θ)) and dθ is equal to θ?

[civic briar]

AAA similarity

You see that that angle is theta with alternate angles

[timid silo]

Ah I see it now, thanks.

.close

[obtuse pebble]

Channel closed

Closed by @wide geyser

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nova cave]

how can I solve for the x's?

[nova cave]

basically x^2(9-x)=44, x=?

[civic briar]

its guess and check time

[nova cave]

😭

alr thx

[civic briar]

x = -2 is an obvious solution

you can use that to factorize the cubic into a linear and quadratic

[nova cave]

damn ur right

[civic briar]

The quadratic is easily solvable

(hopefully)

[nova cave]

how do u do this?

i can do quadratics

[civic briar]

Polynomial long division

Or if you're smart (about it) you can do it in your head

[nova cave]

okie thanks!

[obtuse pebble]

@nova cave Has your question been resolved?

Channel closed

Closed by @nova cave

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful blade]

Im confused by this question. I have no idea how to start, the only thing i know about is the formula for the volyme but other than that i dont understand the question very well.

[obtuse pebble]

@woeful blade Has your question been resolved?

[woeful blade]

.close

[obtuse pebble]

Channel closed

Closed by @woeful blade

Use .reopen if this was a mistake.

[timber fox]

open a new channel

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bronze pumice]

Can some one help me solve this problem?

[bronze pumice]

Oops wrong one

This one

Is this channel open?

[brazen gorge]

yes

[brazen gorge]

what's your progress?

[bronze pumice]

I know that height is changing at -1.4 in/sec and I know that the formula is V =1/3pi(r^2)h

Bc I am differentiating with respect to h, I could treat everything else as a constant

I feel like I already messed up somewhere

I have a feeling I might need similar triangles

Can I compare my radius to my hypotenuse

I just realized there are 2 variables here R and H

I ignored r before and treated it as a constant but bc it is a cone, the further away you get from the base the smaller the radius becomes

So I think my next step is to differentiate the volume formula with respects to time

So am I on the right path

?

[obtuse pebble]

@bronze pumice Has your question been resolved?

[bronze pumice]

No

.close

[obtuse pebble]

Channel closed

Closed by @bronze pumice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe forum]

If the number 1,1010101… that has 1 as a whole and a random decimal place which we will call k, that for each whole positive k is: 0 if k is even and 1 if its uneven, is it irrational or rational?

[severe forum]

I did my best to translate

I also have to justify my answer

[obtuse pebble]

@severe forum Has your question been resolved?

[drifting wraith]

what do you think

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tawdry arrow]

Is this enough as proof (Is it even correct?), or am I missing something?
I is an index set, C is a set, (Ai)i ∈ I is a family of sets with Ai ⊂ C for all i ∈ I.

[tawdry arrow]

I hope the terms are correct cause I'm just translating as best as I can from german.

Wait, it formatted the first part wrong. Here's a better picture.

[obtuse pebble]

@tawdry arrow Has your question been resolved?

[sage geode]

On the second line shoudln't it be "x not in A_i"?

Ah wait I just noticed the bar

Yeah it's all correct @tawdry arrow

[tawdry arrow]

Thank you, much appreciated!

.close

[obtuse pebble]

Channel closed

Closed by @tawdry arrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thick crystal]

how did they come from left side to the right side? lets pretend we dont know how the right side look and we want to go turn the left side to right side, how do i do it?

[empty cypress]

I suppose you could try to convert it to factorials and see if something nice comes out

I just know it as an identity

[sage geode]

Yeah if you defined binomial coefficients with factorials straight away then you just need to directly show that the equation is true

[thick crystal]

its combination

[empty cypress]

yes

I know that that equation is true by memory

[thick crystal]

k let me send the whole problem: so i have to proof this summation using mathemathical induction. I got kinda stuck and i looked up the answer and couldnt understand how they rewrite that red underlined thing

[sage geode]

Yeah well how have you defined the binomial coefficient?

[thick crystal]

sorry i dont understand the question

[sage geode]

How were you introduced to the binomial coefficient? Just using this formula?
[ \binom{n}{k} = \frac{n!}{k!(n-k)!} ]

[warm shale]

A Lonely Bean

[thick crystal]

yes

[sage geode]

Right, then you would first need to show that this is true

Just apply the formula and the fact that (n+1)! = (n+1) * n!

The rest is simplification

[thick crystal]

nope i tried that, it wont work

if you look at the answer i send, they write it as this, so first number + whatever in the middle + the last number

but i dont understand how they got this

to this

[thick crystal]

yes but its the opposite thing of what im asking

you showing me how to get this

to this

[sage geode]

Just write it the reverse way then

[thick crystal]

.close

[obtuse pebble]

Channel closed

Closed by @thick crystal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce matrix]

can anyone help me with this?

[fierce matrix]

its an infinite seuence i think

sequence

[regal tundra]

Yes

Do you know the formula for infinite sum of geometric series

A/1-r?

[fierce matrix]

Yeah

idk how to type it in a keyboard tho

[regal tundra]

A/1-r?

[fierce matrix]

is that it?

[regal tundra]

Yes

[fierce matrix]

infinite geometric series

yh i think thats it

[regal tundra]

Ok

So you threw the ball once

[fierce matrix]

this

[regal tundra]

Yes

[fierce matrix]

alr

[regal tundra]

How much did it travel in going up and coming down once

[fierce matrix]

two thirds?

[regal tundra]

It went up 6m feet and came down 6 feet

[fierce matrix]

ohh

[regal tundra]

How much did it travel

[fierce matrix]

two thirds?

[regal tundra]

Bro 6 +6 = 12

It travelled 6feet up and then 6 feet down

[fierce matrix]

oh

[regal tundra]

12 feet

[fierce matrix]

mb

[regal tundra]

So it went 12 feet the first time

[fierce matrix]

yh

[regal tundra]

Now

Second time

It went up two thirds of six feet

What is two thirds of 6

[fierce matrix]

8

wait

uh

3?

wait no

tha half

4

has to be 4

[regal tundra]

Yes

2*6/3 = 4

[fierce matrix]

howd u come up with that

[regal tundra]

Ok

[regal tundra]

Let's ignore this

[fierce matrix]

ok

[regal tundra]

Let's not even calculate two thirds of six

[fierce matrix]

ait ait

[regal tundra]

It went 2/3 ×6 up and 2/3 × 6 down

So how much did it move

2/3 ×(6+6) = 2/3 ×12

[fierce matrix]

wtf

[regal tundra]

Ok

Till what point did you get it?

[regal tundra]

Did you get this one?

[fierce matrix]

from here

[fierce matrix]

.

[fierce matrix]

nope

dont we have to lay out the given?

like a sub 1 is 6

[regal tundra]

Two thirds of something is 2/3 × the thing?

[fierce matrix]

idek tbh

i am so dead tmrw

[regal tundra]

Fraction bro?

[fierce matrix]

i have math exams tmrw

[fierce matrix]

nah

hold on lemme send u a vid

[regal tundra]

Bro you know fractions?

[fierce matrix]

https://youtu.be/chTlVcS60w0?si=EUdSqVUnoOBt4Ybj

[fierce matrix]

no xD

[regal tundra]

What grade are you in?

[fierce matrix]

10

[regal tundra]

They teach fractions in like 3rd grade or sum

[fierce matrix]

yh ik

[regal tundra]

Like did you ever learn 1/7 or 2/3, 4/9 stuff like that?

[fierce matrix]

yep

i j forgot abt how to divid or multiply them

also integers

and idk how to divide

[regal tundra]

Ok show me you syllabus for tmr

[fierce matrix]

i have exams tmrw

math

[regal tundra]

What's coming in the exam

[fierce matrix]

i need it rn lol

[fierce matrix]

lemme send u the pointers

MATH

• Generating Patterns
• Arithmetic Sequence
• Arithmetic Series
• Arithmetic Mean
• Geometric Sequence
• Geometric Series
• Infinite Geometric Series

here

[regal tundra]

You know arithmetic sequences?

[fierce matrix]

yep

a sub n = a sub 1 ( 1 - r)d

[regal tundra]

Yes

Their sum?

[fierce matrix]

wdym

[regal tundra]

Sum of arithmetic sequences

[fierce matrix]

n?

[regal tundra]

S=n/2(2a + (n-1)d)?

[fierce matrix]

wtf is that

[fierce matrix]

ahh

[regal tundra]

Ok i see

So

[fierce matrix]

its geometric sequence?

[regal tundra]

Can you give me an example of any arithmetic sequence

[fierce matrix]

mk

this was 1 of our activities abt arithmetic sequence

[regal tundra]

Stop looking at questions

First understand

[fierce matrix]

all ik is we have to lay out the thingies

[regal tundra]

1,4,7,10,13,16.... Is an arithmetic sequence

[fierce matrix]

can i explain to u how i answered it?

[regal tundra]

Basically you add something to get the next term

[fierce matrix]

yeah

[regal tundra]

You start with a number

Add something to it

Get the next number

You keep adding you keep getting numbers

[fierce matrix]

yh but it has a difference

like u gotta add them by 3

[fierce matrix]

this

[regal tundra]

Yes

So the number I keep adding is 3

And I started with 1

[fierce matrix]

yh and u gotta find the 47th term

[fierce matrix]

u gotta start with 4 i think

cuz its the first one

[regal tundra]

I said stop looking at the questions

[fierce matrix]

dam ok

[regal tundra]

Not talking about the ques

The number you begin with is "a"

It's the first term

[fierce matrix]

yhyh

[regal tundra]

So like in series 2,6,10,14,18... The first term is 2 and common difference is 4

You get this right?

@fierce matrix ?

[fierce matrix]

yhyh

[regal tundra]

You got that or no?

Be honest

So basically "a" and "d" can be any numbers

Like negative too

So 9,6,3,0,-3,-6 and so on

Here d is -3

Cuz you keep adding -3

@fierce matrix bruv you wanna do this or no?

[fierce matrix]

yh i get it

lol

[regal tundra]

Bruh you have test tmr you gotta focus up

[fierce matrix]

i am focusingg

im j watching a vid abt infinite geometric sequence

cuz the vid i sent u was the one my sir sent

aka the guy who made the vid

[regal tundra]

Hm

Ok

First do arithmetic series and related stuff tho

Thenn geometric

That'd be easier

If you have video

Then do it from video

That's easier

[fierce matrix]

i have all the vids

its from my sir's yt channel

[regal tundra]

Do it from there

And learn how to divide

And multiply

[fierce matrix]

alr

ty fr

[regal tundra]

Bruh I didn't even help

Good luck for your exam

[heady walrus]

Not sure if you still need help but the first question is simply adding by 3, repeat this process 47 times by multiplying to get your answer.

[obtuse pebble]

@fierce matrix Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast sun]

hi, i've been asked to mathematically prove that there this functions graph is symmetrical to a point

[vast sun]

and find that point

i've read about some thing like this

if:

then:

where omega is the point of symmetry

but i'm skeptical

[vast sun]

btw these are the same thats how i read about that

[neon vector]

Why are you skeptical

[vast sun]

idk i just like something with proof

[obtuse pebble]

@vast sun Has your question been resolved?

[vast sun]

<@&286206848099549185>

[obtuse pebble]

@vast sun Has your question been resolved?

Channel closed

Closed by @vast sun

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom flicker]

Could anyone double check my proof here?

[obtuse pebble]

@fathom flicker Has your question been resolved?

[kind hawk]

from where are you pulling the primes

[dark stirrup]

$9000=2^3 3^2 5^3$

[warm shale]

SWR

[kind hawk]

the first paragraph is clear, you are using that argument already to show that a,b,c,d need to be of that form with the exponents being less than 3,2,3

(well yes I know but its not clear in the proof)

[dark stirrup]

I have no idea how to read || * *| * *

[kind hawk]

same

[fathom flicker]

I gave the example for that reason

That means | 1 power

And every star after it

Gets it

[kind hawk]

even with the example its not clear

[fathom flicker]

||*

Means a being the first star

Gets 2 powers

And placing the stars in order like that garuntees the non decreasing

[fathom flicker]

What isn’t clear in the first paragraph?

[kind hawk]

you are pulling the 2,3,5 out of nothing

instead of stating that

[fathom flicker]

Oh well yeah I can just state the prime factorization of 9000

I should do that

I forgot when I was writing it up

[kind hawk]

and when you then argue that a,b,c,d have to be of that form then you basically already give the argument for why the exponents have to be nondecreasing

[fathom flicker]

I elaborated incase it wasn’t clear

But It should be immediate yet

Yes*

[kind hawk]

are there really 35 nondecreasing sequences with 0-3? that seems super high. I am not convinced by your stars and bar argument somehow

I suppose there are quite a bit more total

ehh probably works out

[fathom flicker]

Yeah because like for example if d=2^3 there can also have c=b=a=2^3

And so like it kind of cascades since they can still be equal to the preceding variable

2^3 2^3 2^3 2^3 , 2^3, 2^3 2^3 2^2, 2^3 2^3 2^2 2^2, 2^3 2^2 2^2 2^2

like that is just 16 i think real easily

so 35 is fari

fair*

[kind hawk]

how about you just write the exponents instead of this mess

but yeah I think it works out

[fathom flicker]

3 3 3 3, 3 3 3 2, 3 3 2 2, 3 2 2 2, 2 2 2 2, 2 2 2 1, 2 2 1 1, 2 1 1 1

yea

[kind hawk]

but your argument needs to be rewritten. not clear currently whats happening

[fathom flicker]

which part of it unclear besides the prime factorization

[kind hawk]

how to read the stars bars thing

[fathom flicker]

Okay

I'll work on that

ty

[fathom flicker]

SWR appearance

how r u

long time no see kinda

[dark stirrup]

been busy

[fathom flicker]

understandable

well anyways ttyl

ty denascite

.close

[obtuse pebble]

Channel closed

Closed by @fathom flicker

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tawdry arrow]

Does this make sense (if it does, is it complete?), or did I misunderstand certain rules of sets?

[tawdry arrow]

I'm going batshit insane.

Let's fucking go, thank you for checking.

.close

[obtuse pebble]

Channel closed

Closed by @tawdry arrow

Use .reopen if this was a mistake.

[tawdry arrow]

forgot to close 💀

[dark stirrup]

.reopen

[obtuse pebble]

✅

[dark stirrup]

@tawdry arrow that user was banned for giving random, not necessarily true advice.

[tawdry arrow]

Oh.

[dark stirrup]

I would expand your reasoning between these two steps

Specifically, have you shown in the past that $(A\times B)\setminus(C\times D)=(A\setminus C)\times (B\setminus D)$?

[warm shale]

SWR

[tawdry arrow]

No, I haven't. For some reason I thought they would just be equal without showing it.

Let me try.

[dark stirrup]

(hint: they will not be equal)

[tawdry arrow]

So, the entire thing is just bullshit.

[dark stirrup]

Not entirely. You just made a bad assumption here.

You at least have a decent understanding otherwise.

But, I do recommend starting over, just to be safe.

You're fine up to here