#help-10

1 messages Β· Page 262 of 1

wheat vapor
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I wrote a script to check it real fast and got 1381.

daring cairn
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bro wrote a script?

wheat vapor
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>>> n = 1
>>> while n < 5000:
...     if n%2 == 0 and checkUnique(n):
...             count += 1
...     n += 1
... 
>>> count
1381
>>> ```
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Yeah.

daring cairn
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damn how could i be off by 8 though

wheat vapor
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I got it, sec.

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,w 2874+2875+484+585+44+55+4

obtuse pebbleBOT
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daring cairn
#

.reopen

obtuse pebbleBOT
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βœ…

daring cairn
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.close

obtuse pebbleBOT
#
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daring cairn
#

.reopen

obtuse pebbleBOT
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βœ…

daring cairn
#

u mind helping me with another?

wheat vapor
#

What's up?

daring cairn
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its a flag where you can use ten colours but none can be the same in adjacent squares

wheat vapor
#

Do you know the answer?

daring cairn
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no clue. done some with 2 cases only being distinct vs 2 boxes the same but this one has mulitple

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this test q was from like 2019 so idk teach only said a max of 2 cases for flag questions

wheat vapor
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I've got a best guess that might be right. I just figure pick one of the spots to have 10, then pick 9 or less based on how many possibilities it can be considering the ones next to it that are already picked.

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Like, A:10, B: 9, C:8 (since it's next to A and B), D: 9, F: 9, E: 8 (since next to D and F), G: 9, H: 8. Then multiply.

daring cairn
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that is one case however, since you can pick a colour twice, if d and f are the same coluor that adds a colour to choose from for c and e

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and so one and so forth for gh ab

wheat vapor
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Oh yeah, I was just listing number of possible choices given how many adjacent things are next to it that I've already picked a color for. My method accounts for A and D both being green.

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Otherwise it'd just be 10x9x8x7x6x5x4x3

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I may be off in my thinking. That's just how I'd try to do it.

daring cairn
#

.close

obtuse pebbleBOT
#
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patent marten
obtuse pebbleBOT
patent marten
#

Hi, I wanted to check if the domain for this would be (-infinity, infinity) and the range (2, infinity)?

empty cypress
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it really depends what you think is happening off this page

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do you care about inclusive/exclusive difference?

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because it is wrong if you do

patent marten
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In that case it would be (-infinity, -1)U(-1,1)U(1, infinity)?

empty cypress
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no

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i mean that range: (2, infinity) inplies y = 2 is not possible (which is clearly is)

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so it should be [2, infinity), notice the inclusive parens

patent marten
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I thought would be excluded because of the open circle also being present or having the chose of using ()/[].

empty cypress
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or g(1) in this case

patent marten
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2

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This is a different problem but it was what I was going by when dealing with the current one.

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So, if I understand correctly, if the function exists even if an open circle is present, that value is still inclusive?

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?

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.close

obtuse pebbleBOT
#
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wind sierra
obtuse pebbleBOT
wind sierra
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Can anyone even briefly give a hint

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(for the first one)

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Im trying to analyse the terms

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perhaps something that differentiaties to x sec^2(x)*tan(x)

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this is A level (17 year old maths) btw

weary delta
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Derivative of tanx is sec^2(x) maybe that can work somehow

wind sierra
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oh

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If i just take the bottom

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it cleanly differentiates

weary delta
wind sierra
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ikr

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thank you for your help!

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now I just got to do the next one XD

#

.close

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hearty snow
#

Simple math, but for the life of me I cant figure out how to show the answer

Pete bought a car for 3000€, how much does he need to sell the car for, when he’s giving a 20% sale, but wants 25% profit from the original price ( answer is given on the equation 4687,50€, but I deadass js cant figure out how to get to that point πŸ€¦πŸ»β€β™‚οΈπŸ˜­)

weary delta
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First figure out how much he needs to sell it for to make his desired profit

hearty snow
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Like without the 20% sale?

orchid wind
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Yes

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3000 times 25 percent profit

neon eagle
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How much just to make 25% profit basically

hearty snow
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3750 aint it

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Imma be feelin too dumb after this icl 😭

weary delta
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Hm, are you sure about the answer given?

hearty snow
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Like the answer given at the start?

weary delta
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Oh, oh, nvm. I misread, yeah it’s fine

hearty snow
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Alr

weary delta
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3750 is the price on sale then, yes?

hearty snow
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Yh answer is ”about 4687,50€”

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Thats the price needed to make 25% profit w/o the 20% sale

weary delta
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Let’s say X is the price before sale, so we have that x - 0.2x = 3750

hearty snow
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Wait

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dont send it e

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mightve js figured it out hold up πŸ˜‚

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wait no keep going

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😭

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@weary delta Able to help me finish this? Tryna go sleep

weary delta
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Or equivalently you can say that, 80% of the price before discount is 3750, either way, simple to solve

weary delta
hearty snow
#

OHHHHH

hearty snow
#

.close

obtuse pebbleBOT
#
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wise panther
obtuse pebbleBOT
wise panther
#

I thought there would be no more disconitniues other than 6

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I put dne earlier but didnt work

haughty coyote
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-4 is the root, not 4

neon eagle
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rip

daring rock
wise panther
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burh

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thx

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idk why I overlooked that

daring rock
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it happens lol

wise panther
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but

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arentn the roots

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(x+4)(x-6)

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bruh

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I just proved my self wrong

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by being a geniuus

daring rock
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that is the factored form of the denominator

wise panther
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ik

daring rock
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x=-4 and x=6 are the roots

wise panther
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Ik i REALIZed as I typed it ol

daring rock
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lmao

wise panther
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why is -4 removable

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and 6 isnt

daring rock
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because the numerator also has a factor of x+4

wise panther
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bruh

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ye ur right

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thx

daring rock
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np πŸ‘

wise panther
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I swear whenever you dont understand smth in math and someone explains it its always

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"Oooohh"

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thats what I think everytime I hear an explenation lmao

daring rock
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i know what you mean lol

obtuse pebbleBOT
#

@wise panther Has your question been resolved?

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elfin sequoia
obtuse pebbleBOT
golden sand
#

!show

obtuse pebbleBOT
#

Show your work, and if possible, explain where you are stuck.

elfin sequoia
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I don't even know how to start

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<@&286206848099549185>

golden sand
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draw a diagram

elfin sequoia
#

there

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<@&286206848099549185>

golden sand
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you can find the angles and the radius

elfin sequoia
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radius = 6/Ο€

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@golden sand

golden sand
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and after you find the angles there is a formula relating two sides and angle between them to opposite side

elfin sequoia
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how to find angles

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@golden sand

golden sand
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you've got arcs

elfin sequoia
#

wdym

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@golden sand

golden sand
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the whole circle is 2pi rads

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or 360 deg

elfin sequoia
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ok

golden sand
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how much is 5/(3+4+5) of a circle

elfin sequoia
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5/12

golden sand
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what angle with the vertex at the circle center does the arc of length 5 subtend?

elfin sequoia
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does it have to do with sin/cos/tan?

golden sand
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yes

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You should know the formula involving two sides of a triangle and an angle between them

elfin sequoia
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let me look for it, i think i have it written down

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is it 1/2 ab sin C?

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wait the sides are radii

golden sand
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or yeah, you could use some properties of those triangles to just use sin

elfin sequoia
#

ok

golden sand
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not 1/2absinC though

elfin sequoia
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$(27+9sqrt(3))/pi^2$

warm shaleBOT
#

fokeww

golden sand
#

what is this

elfin sequoia
golden sand
#

that's the area?

elfin sequoia
#

yep

golden sand
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ok, and?

elfin sequoia
#

i am done

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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rotund vector
#

Can someone help me solve this differential equation?

visual gulch
obtuse pebbleBOT
#

@rotund vector Has your question been resolved?

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torn knoll
#

need discrete math folks to tell me if i made a mistake or this is valid

torn knoll
#

lost on precedence and most online calculators seem to be wrong

obtuse pebbleBOT
#

@torn knoll Has your question been resolved?

torn knoll
#

.CLOSE

#

.close

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fallow tusk
obtuse pebbleBOT
fallow tusk
#

Do I do the cross product between 4, 10, -13 and 3, -1, 1 here?

#

doesnt really sound right...

latent walrus
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(4,10,-13) is normal to the plane already

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so you can take that as your direction vector for the line

fallow tusk
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so do I subtract 3,-1,1 from 4,10,-13?

latent walrus
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so, do you know this form of equation for a line? (a)+t(d) where a is a point on the line and d is the direction vector and t is some scalar

fallow tusk
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yes

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so 3,-1,1 is your a?

latent walrus
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yeah

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(3,-1,1)+t(4,10,-13) can express any point on that line by changing t

fallow tusk
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so then x = 3+4t, y = -1+10t, z = 1-13t

latent walrus
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exactly

fallow tusk
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do I have to solve for t?

latent walrus
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no, theres nothing to solve it for

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youre just setting up equations

latent walrus
fallow tusk
#

ah, fair enough

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thanks πŸ‘

#

.close

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real gorge
#

for A3

I got x_1 = 1
x_2 = 1
x_3 = 0

the answer to the homogenous system defining the subspace was x_3 = 0

I see the method of getting it, but I don't understand why/how. Can someone explain what this means actually

real gorge
#

please use reply

obtuse pebbleBOT
#

@real gorge Has your question been resolved?

brave bramble
#

We have a system that can take an (x1, x2, x3) and returns "yes" or "no"

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For A3, the system returns "yes" if x3 = 0

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That means a few vectors like (1, 1, 0), (5, -4, 0) satisfy the system

real gorge
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ok let me try understanding 1 sec

brave bramble
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But that's exactly the same as the span definition they gave. That is, vectors that satisfy the system are in that span, and vice versa

real gorge
#

alright so im a bit bad with technical deifitinitons in linear algebra

so a homogenous system of linear equations means they = 0

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i got x_3 = 0

and x_1 = 1 and x_2 =1

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in the augmented matrix

real gorge
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not sure if you can simply this for me

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but what does the question even mean

brave bramble
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Forget matricies for a sec. You're concerned with Span{(1,0,0) , (0,1,0)}

real gorge
#

yes

brave bramble
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That is, this is the set of vectors you can make by freely adding and scalar multiplying, but only using the vectors (1,0,0) and (0,1,0)

real gorge
#

yes

brave bramble
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It should be clear that, no matter what you do, the third component will always be 0

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That's another way to define this set

real gorge
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yeah i get that

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oh

brave bramble
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That's it. If you get that, then you get everything.

real gorge
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well yeah i guess it wasnt that difficult

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but then for A4

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how would you do that

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i mean i can just equate each to a value of x_n

brave bramble
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So note the first component will always be double the second component

real gorge
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yep

brave bramble
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x1 = 2x2

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And the third component will always be 0.
x3 = 0

real gorge
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yeah 100% i see

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oh

brave bramble
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Arrange those into the form you want, you're done

real gorge
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so i'd like to ask something

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i dont always have to

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row reduce

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and get something like this

brave bramble
#

You could row reduce
[1| x1]
[2| x2]
[0| x3]
And you'd get the same answer

real gorge
#

yeah so i did that

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well there isnt really row reducing

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but isnt it 3 separate answers

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unless i make the first one 2 = 2x_1

brave bramble
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Check your reduction

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x1 is not always 1

real gorge
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amazing

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one last thing

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i did a problem

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row reduced twice

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got 2 different sets of answers

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like the first time was answers A and B

second time was answers C and D

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and the textbook onoly had answers A & C

brave bramble
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But it's a good idea do to some of this stuff without the matrix tech.

real gorge
#

all correct?

brave bramble
#

Depends on the question haha

real gorge
#

I mean i re did it and row reduced again

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hmm

brave bramble
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No an rref is unique

real gorge
#

because that's as far as the textbook went

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i guess i should recheck problems with the RREF?

brave bramble
#

Without seeing the problem, I can't be sure haha

real gorge
#

no worries ive taken too much time

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thanks so much, hope you have a wonderful day!

brave bramble
#

Okay! Feel free to ask if you have anything else.

real gorge
#

sure thing

#

.close

obtuse pebbleBOT
#
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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
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latent walrus
#

who has this half chicken

wooden cipher
#

I would argue half a chicken doesnt count but yes, 1.5

#

What do you think the answer is?

tepid sedge
#

its 1.5

surreal jetty
#

yeah 1.5

wooden cipher
#

The amount of eggs laid is proportional to the amount of chickens or amount of days

tawdry arrow
#

1.5

tepid sedge
#

the more days, the more eggs

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so you don't need more chickens

wooden cipher
#

Since both days and eggs are multiplied by 4, chickens stays constant

tawdry arrow
#

Eggs = 2/3 (Chickens x Days)

wooden cipher
#

The fact is you have like 5 people telling you 1.5 is correct

daring rock
#

You give the chickens 4 times more time, they'll give you 4 times more eggs. Why wouldn't you multiply by 4?

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with the same number of chickens

latent walrus
wooden cipher
#

Tell us whats right then please

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Explain

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The burden of proof is on you to prove it now

tawdry arrow
#

Chickens and Days are independent of eachother. Eggs are dependent on both Chickens and Days. So, if the value of Days changes, Chickens' value doesn't, but Eggs' does.

wooden cipher
#

The answer is 1.5, we have shown you the solution

#

The solution you forgot?

daring rock
#

your teacher is mistaken, or you are mistaken. The answer is 1.5

autumn adder
#

...

daring rock
#

then you have misrepresented the question

tawdry arrow
#

heres the way

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see how the chickens dont change but the eggs do if i change days

daring rock
#

it's not a matter of opinion dude lol

tawdry arrow
autumn adder
#

What's up here.

surreal jetty
#

1.5 chickens = 1.5 eggs/1.5 days
6/1.5 = 4
1.5 x 4 = 6 eggs/6 days

latent walrus
#

if we're wrong then point out a flaw in anyones argument

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and back it up

tawdry arrow
#

this conversation is a mobius loop man

autumn adder
#

Check if you wrote your question correctly @timid silo

tepid sedge
#

its 1.5 chickens bro

tawdry arrow
#

tony over here with the facts

daring rock
#

Genuinely cannot wait

latent walrus
#

what time shall this event be

autumn adder
#

That's wrong

#

Wait a min

tawdry arrow
#

its been a min@autumn adder

autumn adder
#

Figure of speech.

tawdry arrow
#

i know

autumn adder
#

Do you understand your question first

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I don't want your friend or professor to influence you.

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What do YOU say

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minus your friend and professor.

#

Look.

#

There's 1.5 chickens

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(I dont know how but its akin to carrying 600 watermelons in elementary school)

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So there's 1.5 chickens

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They lay 1.5 eggs in 1.5 days

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Can you listen?

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Have a plate for listening (thats what we say in our language).

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There's no need to overthink

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Use common sense

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If you let the 1.5 chickens sit for more 1.5 days

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They gonna give more 1.5 eggs

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Can you stop overthinking?

#

University has asked 1+1

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Doesnt mean you need to do a whole riemann zeta on it.

daring rock
#

Using a more complicated method isn't going to magically change the answer

autumn adder
#

You're unnecessarily complicating an easy question

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You want a complicated method?

#

I'll tell you what

autumn adder
#

1.5 chickens lay 1.5 eggs in 1.5 days

autumn adder
tawdry arrow
#

respect that

autumn adder
#

Leave that question

#

Come to a real question

#

1 CHICKEN lays 1 EGG in 1 DAY

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This is nonsense to me.

tawdry arrow
#

thats literally the thing i sent earlier

autumn adder
#

And trust me I do more math than you everyday

tawdry arrow
autumn adder
#

If you had to assume a calendar with leap years in the simplest form, you could just use 365.25 which was as simple.

#

That's a kids topic.

#

Sorry but that isn't some hyped uni topic

#

We solve better questions than this in high school

#

I remember solving <<insert dramatic music>> inverse proportionality questions

#

It was the worker problems if you know

#

You aren't required to overthink stuff, go by logic wherever you can.

#

I bet if the professor says the answer is four, you have written your question wrong

#

I bet, I bet you're either gonna change your question or do whatever nonsense you can to keep yourself right

tawdry arrow
#

astaghfirullah

#

literally talking to a wall

autumn adder
#

Did you just mistake his "1" for a "4"

daring rock
#

Either you are misremembering what she said, or you misunderstood her, or you did not write the question down correctly

autumn adder
#

I wonder.

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Also wait didnt you say 4.5

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How'd it lose a .5

#

.

tawdry arrow
#

you changed it to four

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by accident

autumn adder
tawdry arrow
tawdry arrow
#

man im going crazy

autumn adder
#

I think his neural network mistook the 1 for 4

#

If ykyk

tawdry arrow
#

some profs really got the worst handwriting

autumn adder
#

I hate the fact how people put their professors as the absolute truth

#

I respected my teachers, gave their solutions the first preference but always voiced my concerns if I found something wasn't right

tawdry arrow
#

theyre glorified a lot

autumn adder
#

I didn't agree to the fact that if a professor proved a flawed logic it should be right

#

They're like you, glory to the professor kids

tawdry arrow
#

now im thinking if she was explaining a wrong example of something

autumn adder
#

Or just didn't wanna work their brain a little

tawdry arrow
#

and he thought it was right

autumn adder
#

Then Ibet the question was incorrect.

#

(the one you told us)

tawdry arrow
#

i think it was an example of what not to do

#

😱

autumn adder
#

...

#

If you can't take logic and arguments you're the one who should shush. But anyway, I won't be remotely interested in knowing

#

I have better things to do in Desmos, and life.

tawdry arrow
#

desmos is life

autumn adder
#

Rather than run after a person who has a wall instead of an ear

#

There's never two answers to a linear question unless it's quadratic.

#

No, I don't take wrong things.

#

I'll leave you be, though

thin star
#

can someone give a tldr of this thread lmao

tawdry arrow
#

1.5 chickens

autumn adder
daring rock
#

Dude you're the one who can't accept that you could have possibly misunderstood the question or your teacher's answer, and you're telling someone else that their ego is too big?

autumn adder
#

Yea cool.

#

I disallow you from pinging me on this again.

fierce lagoon
#

Okay what's the original question

#

How the fuck do you have half a chicken

#

6 eggs in 6 days is equivalent to 1.5 eggs in 1.5 days

#

Since they're all 1 egg : 1 day in proportionality

#

So you'd still need 1.5 chickens

#

If you want it in fractions:

$$\frac{1.5}{\parens{\frac{1.5}{1.5}}} = \frac{x}{\parens{\frac{6}{6}}}$$

warm shaleBOT
#

Umbraleviathan

fierce lagoon
#

It's quite obvious what x is

#

Now why the answer is meant to be 1.5 chickens, no idea because you cannot have half a chicken and have it function

autumn adder
fierce lagoon
#

The damage is done

obtuse pebbleBOT
#

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sage dagger
#

A cylindrical tank standing upright (with one circular base on the ground) has radius 1 meter. How fast does the water level in the tank drop when the water is being drained at 3 liters per second?

So I know dV/dt is -0.003 and dV/dt = dH/dt? I don’t know I’m a little confused

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tardy epoch
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outer socket
#

can anyone help me making integrating factor from this equation?

obtuse pebbleBOT
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thin star
#

is I a constant?

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fringe trellis
#

Hi are these correct?

obtuse pebbleBOT
fathom flicker
fringe trellis
#

The procedure

#

The answers match up tho

#

But I want to make sure that I'm doing it correctly

obtuse pebbleBOT
#

@fringe trellis Has your question been resolved?

fringe trellis
fringe trellis
flat sparrow
#

b answers is 0 but your procedure is wrong

#

5^-x not equal to 5/x

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lunar rover
#

Hey, bit unsure how to do this, the question states to write the following as one fraction.

lunar rover
#

$$\lg(\sqrt[x]{10y})$$

warm shaleBOT
#

Totalani

errant lark
#

What have you tried?

lunar rover
#

Im trying to remember what happaned to the \sqrt[x] when you move it down

#

other than that nothing

#

I tried $$\frac{\lg(10y)}{x}$$

warm shaleBOT
#

Totalani

errant lark
#

That is correct. However, that's not sqrt{x}. It's a power of (1/x).

royal basin
#

\sqrt[x] is the tex code for it

#

square brackets

royal basin
lunar rover
#

yea its telling me wrong answer

royal basin
#

can you show the entire problem

#

yes even if it is in one of swedish, danish and norwegian

lunar rover
#

so write that as one fraction

#

any idea where im doing wrong

royal basin
#

oh because it's $\sqrt[x]{10^y}$ and not $\sqrt[x]{10y}$

warm shaleBOT
lunar rover
#

aaah

royal basin
#

you are misreading the problem

lunar rover
#

it was hard to see πŸ˜„

#

wait so my inital thing was correct, just change the y?

#

still says wrong

royal basin
#

i mean you can simplify it more

#

what is lg(10^y)?

lunar rover
#

y

royal basin
#

yeah so

lunar rover
#

oh ok

royal basin
#

you should be getting y/x

lunar rover
#

y/x

#

yea

#

so when you have \sqrt[x] you can move it to fraction and whatever x is becomes the numerator?

royal basin
#

bad

#

don't memorize like that

lunar rover
#

right

#

I got the answer i wanted, thanks ofr the help.

#

.close

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frail depot
#

$f(x)=x^3-2x^2+31x+7$
Extremal and critical points?

warm shaleBOT
#

SimonWin

frail depot
#

Is the answer just that there is none, since after calculating the discriminant to $d=-356$ there are no solution for $f'(x)=0$

warm shaleBOT
#

SimonWin

frail depot
#

So, there are zero critical points and extremal?

lone echo
#

what are you calling critical points? derivative 0?

#

if so, correct, since derivative cant be 0 as you explained

frail depot
#

But ye, I guess since it's a polynomial it's defined $\forall x \in \mathbb{R}$

warm shaleBOT
#

SimonWin

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opaque galleon
#

A six-sided die is loaded in a way that each even face is twice as likely as each odd face. Construct
a probabilistic model for a single roll of this die, and find the probability that a 1, 2, or 3 will come
up.

My solution: P(E) = 2 P(O)
P(E) + P(O) = 1
2P(O) + P(O) = 1

P(O) = 1/3
so P(E) = 2/3

but my answer is wrong and the correct answers are P(E) = 2/9, P(O) = 1/9

opaque galleon
#

what did I do wrong?

obtuse pebbleBOT
#

@opaque galleon Has your question been resolved?

opaque galleon
#

nope

abstract beacon
opaque galleon
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silver ore
#

Assume the exponent of a number is βˆ’127 and the sign bit is 0. Find the decimal number represented by a mantissa of: 00000000000000000000000 and find the decimal number represented by the mantissa 00000000000000000000001 Finally, find the difference between these two numbers, giving the resolution of decimal representation for small numbers (since we incremented the mantissa by 1, the smallest resolution in binary representation).

can i have help?

obtuse pebbleBOT
#

@silver ore Has your question been resolved?

silver ore
#

<@&286206848099549185> would the decimal number for the mantissa 00000000000000000000000 be 0?

#

.close

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swift moat
#

The number 11 is a prime number. Are there any more prime numbers among palindromes of the form 111...111?

swift moat
#

Are there?

kind hawk
#

yes

#

eg with 19 ones

swift moat
#

1111..1111 with 19 ones???

kind hawk
#

yes

swift moat
# kind hawk yes

okay thanks that was for an tornament if that is true i won an book

#

.close

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kind hawk
#

can't even cheat yourself with the internet?

reef cobalt
#

Yes

obtuse pebbleBOT
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thin oxide
#

Can anyone provide me with resources in Statistics?
(Could be cool if it contains the last three)

obtuse pebbleBOT
#

@thin oxide Has your question been resolved?

empty cypress
#

not English + not math question, should probably ask elsewhere

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tender meteor
obtuse pebbleBOT
tender meteor
#

can anyone do 3 c and d

#

this is example 23

#

<@&286206848099549185>

#

@regal jewel surely still help πŸ™πŸ™

obtuse pebbleBOT
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tender meteor
#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
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timid silo
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lusty shore
#

Open

obtuse pebbleBOT
lusty shore
obtuse pebbleBOT
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lusty shore
#

Part b haven’t been specifically taught but I’m just curious how to do it

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jovial lynx
obtuse pebbleBOT
jovial lynx
#

<@&286206848099549185>

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
jovial lynx
#

1

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

jovial lynx
#

?

fathom flicker
#

if your question has not been answered for 15 mins..

fathom flicker
#

Anyways you’re much more likely to get help if you put any effort into describing why you’re confused and what you need help with

jovial lynx
#

I need to find the subspace

#

the notation is a bit confusing, but we need to do direct sum

#

<@&286206848099549185>

obtuse pebbleBOT
#

@jovial lynx Has your question been resolved?

jovial lynx
#

<@&286206848099549185>

jovial lynx
#

<@&286206848099549185>

#

the orthogonal complement consists of all vectors x in R4 such that x * <1,1,1,1> = 0, since T^βŠ₯
from there we get x1 + x2 + x3 + x4 = 0
the vector <1, a, 1, 1 ,1> is in T^βŠ₯ if 1 + a + 1 + 1 = 0, no? => a = -3

jovial lynx
#

||<@&286206848099549185> ||

jovial lynx
#

||<@&286206848099549185> ||

jovial lynx
#

|| <@&286206848099549185> ||

jovial lynx
#

|| <@&286206848099549185> ||

dreamy ridge
#

you know its a subset of $\mathbb{R}^4$ so its basis vectors will be of the form $(x_1,x_2,x_3,x_4)$

warm shaleBOT
#

kitty queen

dreamy ridge
#

from what you worked out, $x_4=-x_1-x_2-x_3$
letting $x_1=1$ and $x_2=x_3=0$ we get $(1,0,0,-1)$

#

similarly, we can obtain $(0,1,0,-1)$ and $(0,0,1,-1)$

warm shaleBOT
#

kitty queen

#

kitty queen

jovial lynx
#

yes but x3 is free, x3 = c , c ∈ R

#

if we see H

#

x3 is not present

#

I assume x3 is free unrestricted , while x ∈ R

dreamy ridge
#

now i should be able to find a vector in that subspace of the form $(1,a,1,1)$

warm shaleBOT
#

kitty queen

dreamy ridge
#

set $(1,a,1,1)=x(1,0,0,-1)+y(0,1,0,-1)+z(0,0,1,-1)$

warm shaleBOT
#

kitty queen

dreamy ridge
#

you obtain a system with 4 equations and 4 unknowns

#

but its really easy

#

$x=1, y=-3, z=1, a=-3$

warm shaleBOT
#

kitty queen

dreamy ridge
#

next i would calculate H

#

we see that the vectors are of the form $(2x_2+x_4,x_2,x_3,x_4)$

warm shaleBOT
#

kitty queen

dreamy ridge
#

actually you just need two linearly independent vectors that are both in T orthogonal and H

#

one of them could be (1,0,-2,1), because $(1,0,-2,1)\cdot (1,1,1,1)=0$ and it is obtained by letting $x_2=0,x_3=-2$ and $x_4=1$

warm shaleBOT
#

kitty queen

dreamy ridge
#

same argument applies to (2,1,-3,0)

#

so we can let $S=\langle (1,0,-2,1),(2,1,-3,0)\rangle$

warm shaleBOT
#

kitty queen

dreamy ridge
#

@jovial lynx

obtuse pebbleBOT
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@jovial lynx Has your question been resolved?

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silver cove
#

Helpp is this correct

obtuse pebbleBOT
minor vortex
#

express this in scientific notation

0.0025=

silver cove
#

<@&286206848099549185>

keen garnet
warm shaleBOT
silver cove
#

Yes

silver cove
#

Ehh

#

Find the four arithmetic means

#

But firs i have to find common difference which is d

#

Omg nvm

#

I realized i was wring

#

.close

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timid silo
#

bro

obtuse pebbleBOT
timid silo
#

I keep making mistakes NoOoOo

#

How do i determine what's the remainder and what's the quotient when doing synthetic division

#

Is the remainder any values that aren't under the bottom line after the last multiplication is done?

#

so this

hasty viper
#

huh

#

whats the question

timid silo
#

How do i determine what's the remainder and what's the quotient when doing synthetic division

#

$$\frac{x^3}{x^2 + 0x+8}$$

warm shaleBOT
#

What should I do

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#

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wet storm
#

could someone explain what this notation means?

obtuse pebbleBOT
gilded needle
#

do you know what sup A and sup B mean?

wet storm
#

yeah

#

I don't understand the comma

gilded needle
#

so those are two numbers

#

sup(sup A, sup B) is just the bigger of those two numbers

#

could equally well have written
max(sup A, sup B)

wet storm
#

ok gotcha, thanks

#

.close

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#

@ashen matrix Has your question been resolved?

brisk grove
#

That's correct

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tame relic
obtuse pebbleBOT
tame relic
#

Where is this second fraction of a-1/ a+2 coming from

high lily
#

- g(a)

tame relic
#

whats the divided by t doing

#

why am I only worrying about the top part?

#

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sharp pecan
#

does anyone know how to differentiate this?

obtuse pebbleBOT
gilded needle
#

doesn't the usual quotient rule work?

sharp pecan
#

its too complicated and i need to find the horizontal points

gilded needle
#

what leads you to suspect that there's a simpler method?

#

and what do you mean by horizontal points?

obtuse pebbleBOT
#

@sharp pecan Has your question been resolved?

static furnace
#

you could make turn sqrt(x) into x^(1/2) and then separate the fractions into two parts

#

then simplify the exponents of x in each fraction

#

and then differentiate

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pure sun
#

anyone know of a site i can use to graph ordered pairs?

pure sun
#

stuff like this:
5.37,0.2
6.3,0.28
7.33,0.32
7.93,0.34
7.42,0.32

#

nvm turns out desmos works very nicely for this

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hexed cape
obtuse pebbleBOT
hexed cape
#

how

#

help

#

what does this even mean

obtuse pebbleBOT
#

@hexed cape Has your question been resolved?

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@hexed cape Has your question been resolved?

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indigo cypress
#

Hello guys, I am having trouble solving this matrix

indigo cypress
#

what should my next step be?

#

I would be really thankful for your help

#

I must use the Gaus method

#

Is subtracting line 2 from line 3 the right choice?

obtuse pebbleBOT
#

@indigo cypress Has your question been resolved?

obtuse pebbleBOT
#

@indigo cypress Has your question been resolved?

indigo cypress
#

alooone

#

at the edge of the universe

obtuse pebbleBOT
#

@indigo cypress Has your question been resolved?

drowsy burrow
#

You know you can immediately multiply a row with a scalar and add it to a different

#

And do the calculating in your head

#

Actually i dont get what youre trying to do, you subtracted 4th from 3rd and then you just undid it?

obtuse pebbleBOT
#

@indigo cypress Has your question been resolved?

jagged wyvern
burnt urchin
#

what is patellorgorms theorm i forgot

indigo cypress
#

.close

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deep cairn
#

What happened between the highlighted parts?

obtuse pebbleBOT
deep cairn
#

How did a n magically pop in with an inequality?

glacial obsidian
#

So n+3 >= n+3n

deep cairn
#

say n = 2
5 >= 8 doesnt make much sense

#

so n + 3 <= n+3n

#

?

glacial obsidian
#

Yes, I wrote the inequality in the wrong way

deep cairn
#

also in the solved example, it says <= 1/2 [ ... ]
less than equal to what?

#

1/n ?

#

also why magically n+3 suddenly n+3n, no change to the rest of the quantities?

#

I think the book is either flawed or they skipped a lot of steps

glacial obsidian
glacial obsidian
deep cairn
#

πŸ˜‚

golden sand
#

3 < 3n if n>1

deep cairn
#

yep

golden sand
#

all good there

glacial obsidian
#

If 1 <= n then 3 <= 3n, then n+3 <= n+3n, then |n+3| <= |n+3n| (because both are positive numbers), then k|n+3| = k|n+3n| for all positive k. Then let k = 1/2 times 1/|2n^2+5n+7|

deep cairn
#

I think my understanding of inequalities is not proper

golden sand
#

n>1 in the text though

deep cairn
#

More practise will probably lead to better understanding

golden sand
#
  • n>=1
deep cairn
#

ya

#

Lemme see how to mark this channel as solved

golden sand
#

.close

deep cairn
#

.close

obtuse pebbleBOT
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deep cairn
#

@golden sand @glacial obsidian Thank you both, esp. D for spoon feeding me the inference

obtuse pebbleBOT
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sharp isle
#

Hi, I'm new haha. So I don't really know how this works. Can someone help with this? I tried using QR

sharp isle
#

Q needs to be orthogonal, but as QM is full rank, m22 can't be nonzero for a upper triangular M. I don't know how this can be decomposed easily

#

*can't be zero

#

:((

#

<@&286206848099549185>

obtuse pebbleBOT
#

@sharp isle Has your question been resolved?

sharp isle
#

no

royal basin
#

hold on

#

,w rank {{3,4,2},{0,2,-2},{-3,4,1}}

royal basin
#

and $M = \bmqty{&0&0 \ &0& \ &&}$

warm shaleBOT
royal basin
#

right?

#

which means that M is lower triangular up to a column permutation @sharp isle

sharp isle
#

Hi, ok, so up to a column permutation is bc U can switch column 2 and 3 and get a lower triangular matrix right?

#

But how go about it? Haha

#

*to

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.close

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frail depot
obtuse pebbleBOT
frail depot
#

We have found the x-axis for the critical point $x=e^{-1/e^n}$

warm shaleBOT
#

SimonWin

frail depot
#

And we just want to show whether it's a minimum or maximum by calculating f(x+ 0.1) and f(x - 0.1)

#

But that is pretty hard given the function KEKW

kind hawk
#

this isn't how you determine whether something is a max or min anyway. instead you can for example consider the second derivative

frail depot
frail depot
#

i guess it makes sense if we can show it's concave up then it must be a minimum right?

#

I guess that's the though process?

kind hawk
#

yes

frail depot
#

Okay.. WOw

#

That's crazy πŸ˜‚

#

Thanks a lot ❀️

#

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lean tendon
#

Given the 16-element set consisting of the ten digits ${0,1,2,...,9}$ and the six capital letters ${A,B,C,D,E,F}$.

warm shaleBOT
lean tendon
#

How many strings of length 9 can be formed using exactly two 6's, three B's and four D's if the four D's are required to occur consecutively in the string?

obtuse pebbleBOT
#
What step are you on?
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2. I have begun but got stuck midway
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4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
lean tendon
#

I want help undrestanding the solution

#

i think i understand now actually

#

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coarse path
#

x^2 +7x-8
Factor the expression

obtuse pebbleBOT
timid silo
wide rose
jovial moss
coarse path
#

? + ? = 7
? * ? = -8

wide rose
coarse path
#

I can’t don’t have one

coarse path
wide rose
#

$(x-x_1)(x-x_2) = x^2-(x_1+x_2)x+x_1 x_2$

warm shaleBOT
timid silo
#

Right, I was gonna ask if you had that in mind

wide rose
#

it's minus

coarse path
#

That’s not how you do it

wide rose
timid silo
#

It's another way of doing it

wide rose
#

what is $(x-1)^2$?

warm shaleBOT
coarse path
#

Let me give you a example

wide rose
#

you know Viet?

coarse path
#

x^2 +10 + 24
4+6= 10
4*6= 24
(X+4)(X+6)

#

This is how you do it

timid silo
#

It's another way to do it

#

It's just the way your school taught you

#

Which is totally fair because this works just fine

wide rose
coarse path
wide rose
coarse path
#

4x6 = 24

wide rose
coarse path
wide rose
warm shaleBOT
wide rose
#

where expression is 0

#

whatever

#

your method is also fine

#

for $(x+x_1)(x+x_2)$

warm shaleBOT
coarse path
wide rose
coarse path
#

What are the 2 numbers that ?+? = 7 and ?*?= -8

wide rose
coarse path
#

Dam you are smart

jovial moss
#

isnt it 8 and -1

wide rose
coarse path
#

Oh yeah

wide rose
#

I've mistaken

wide rose
coarse path
#

.close

obtuse pebbleBOT
#
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coarse path
#

Thanks btw

timid silo
# coarse path Dam you are smart

It's just a matter of considering every factor of 8, then from that finding all the ways to multiply up to 8:
\1*8
2*4
Then 4*2 and 8*1 are just these 2 backwards
Then if you look at the list for answers you find 8-1=7 which solves your problem

obtuse pebbleBOT
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pallid berry
#

is there a clever way to do this or is it just bashy

wide rose
#

start from the cheapest?

pallid berry
#

yeah, initially thought 8 + 5 + 2 was best but given enough time realised that 8 + 3 + 3 + 1 was best

#

ill try that thanks

#

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timid silo
obtuse pebbleBOT
timid silo
#

so i know how i solved it using the top method but im unsure how the bottom method works

jovial moss
#

law of indices

#

they simplified 2/4 to 1/2

timid silo
#

where did i get "16^1/2 x 16^1/4" from

timid silo
timid silo
jovial moss
#

3/4 = 1/4 + 2/4

timid silo
#

ok ok starting to make sense for me

#

so 3/4 is simplified to 1/4 + 2/4 to make it easier for me?

jovial moss
#

is not to make it easier

#

is to find a way to solve it

#

unless u have learnt the last indices law

timid silo
#

i have that law noted down

jovial moss
#

ya u can use it too

#

many methods

timid silo
#

so why can i not just do

timid silo
jovial moss
timid silo
#

mb

#

so the 3/4 is broken down into 1/2 x 1/4 got it

jovial moss
#

what

#

no

#

not x

#

its +

timid silo
#
  • i mean
jovial moss
#

yes

timid silo
#

then u use both them as a power

jovial moss
#

u seperate it

#

using the 1st law of indices

timid silo
#

ok ok

#

got it thanks

#

.close

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#
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bright sleet
#

Can someone explain what the symbol on the right is? The image has to do with set theory

warm canopy
#

Usually denotes a partial order

bright sleet
#

Thank u

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raven bluff
#

Please help with this i understand most of it just have a quick question

wide rose
#

sum of vectors?

raven bluff
#

Yes

#

Which triangle do I use

wide rose
#

draw the plane's vector

raven bluff
#

The 250km/hr?

wide rose
#

right

raven bluff
#

Sorry it’s kinda flipped

#

,rotate

warm shaleBOT
wide rose
#

can you add 2 vectors?

raven bluff
#

,rotate

warm shaleBOT
raven bluff
#

Like this?

wide rose
#

right

#

but both

raven bluff
#

By the way do I always add it to both when I have 2 triangles with a 45 angle

wide rose
#

just add the planes speed at the end of the first vector

#

then the vector start -> final is your planes final speed

raven bluff
#

Do I put that value on both triangles

wide rose
#

like this

wide rose
wide rose
#

but, this is not the answer

raven bluff
wide rose
#

draw 2 vectors as i showed here

#

but in questions case

raven bluff
#

Like the triangle you drew?

wide rose
#

yup

raven bluff
#

This is my teachers work

#

Your triangle kinda looks like his

raven bluff
wide rose
#

can't you solve it geometrically?

#

I'm not familiar with this notation

obtuse pebbleBOT
#

@raven bluff Has your question been resolved?

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long plaza
#

help plz

obtuse pebbleBOT
vast willow
#

you have to look into all choices check which one is correct

#

so lets start by the first one