#help-10

1 messages · Page 258 of 1

tacit scarab
#

we expressed b and c in terms of a

spark wasp
#

ok

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so what does that even tell us

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c = -a b =-2a

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av1 -2av2 - av3 = 0 oooh

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but how do we now from this if its linearly dependent

tacit scarab
#

we found solution to av1+bv2+cv3=0

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so they are dependent

spark wasp
#

bruh what

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its dependent if a b and c

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are 0

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we dont know if it is

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so how can u tell that

tacit scarab
#

it's INdependent if a b c are 0

spark wasp
#

ok but we dont know the value of a

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so how can we say its dependent

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or independent

tacit scarab
#

..

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we're not solving for a

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we are proving the solution exist

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the solution doesn't matter that much

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for example let a = 1

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then you get one solution

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a = 2 is another solution

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etc

spark wasp
#

this is killing my braincells

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💀

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my prof is solving for c1 c2 c3

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to figure out if its depedent or not

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you see?

timid silo
#

scalar triple product != 0

tacit scarab
#

the general solution is -2t,0,t

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-2,0,1 is just one of the solution

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again what's important is that a solution exist

spark wasp
#

where she got that from

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like how can you tell if a solution exist

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if you dont know the number

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thats what i mean

tacit scarab
#

..

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let y=2x

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are there solutions?

spark wasp
#

yea

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but in our case its different

tacit scarab
#

you don't know the value of x and y though

tacit scarab
#

it's the same

spark wasp
#

we need to know if the values are all 0 or if 1 of them is not 0

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to determing if dependent

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or independent

tacit scarab
#

bro

spark wasp
#

correct?

tacit scarab
#

they are not mutually exclusive

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every system have the trivial solution

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of all 0

#

s

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we want to find if there are non trivial ones

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btw I gtg

spark wasp
obtuse pebbleBOT
#

@spark wasp Has your question been resolved?

obtuse pebbleBOT
#

@spark wasp Has your question been resolved?

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errant crane
#

How do I do this one?

obtuse pebbleBOT
obtuse pebbleBOT
#

@errant crane Has your question been resolved?

sterile trench
#

Hey @errant crane , the answer is A

#

You still there?

tawny birch
final locust
#

whats 2 + 2 ?

sterile trench
#

22

timid silo
#

4

sterile trench
#

The formula would be K.E= kq1q2/r, take r on one side and put the values

obtuse pebbleBOT
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obtuse pebbleBOT
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late chasm
#

is the first one a bijection? I am confused . since all of the negative integers would map to -2 which isnt in the codomain

latent walrus
#

even if you ignore the issue with the -2
it doesnt map to any positive even integers so its not surjective anyway

#

If it only maps to -2 for negative integers then its also not injective

timid silo
#

shouldnt here be a x<0 ?

latent walrus
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it says x>=0 so the -2 is basically reserved for (else do this)

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which would only be x<0

late chasm
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oh yeah thank you

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what about the third one

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From what i figured out it maps between 0 and 1 only

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@latent walrus I need your guidance

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is it also not a bijection?

latent walrus
#

it doesnt map to any negatives or even 0 so it cant be a bijection

late chasm
#

as

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nvm

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real numbers

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but somehow the question is asking

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which one of these is not a bijection

latent walrus
#

the first one isnt even a valid function so it may not count that

late chasm
#

makes sense

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thank you AZ empty set!

#

is there a way i could give you some sort of points?

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also how do i close thsi channel

latent walrus
#

theres no point system or anything here no, but thank you

#

just type '.close'

late chasm
#

.close

obtuse pebbleBOT
#
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spring elk
#

.reopen

half acorn
#

How do i calculate and get the 0.12% between this two prices ? 🤔 most easy way

tacit scarab
#

(changed_price-original_price)/original_price

half acorn
#

when i do * 100 giving me then 0.1126307320997586

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meaning it's exactly 0.112 % right ?

tacit scarab
#

Yes

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,w calculate 100(0.6215-0.6222)/0.6222

half acorn
#

Thx ❤️

obtuse pebbleBOT
#

@half acorn Has your question been resolved?

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timber pine
#

how would i do b?

obtuse pebbleBOT
timber pine
#

,rotate

warm shaleBOT
timber pine
#

i tried letting x=2sectheta

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dx=2sectheta*tantheta

echo knoll
#

i gotchu. lemme see what I can do for u.

timber pine
#

alright thanks!

echo knoll
#

i think what u need to do

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cos it's 2 squares

timber pine
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2 squares?

echo knoll
#

wait

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by trig

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gosh

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no u're right

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x=2secu

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$dx=4sec(u)tan(u) du$

warm shaleBOT
#

Krispeh

echo knoll
#

yea you're going right

#

so what's the issue?

timber pine
#

no idea how to continue

timber pine
obtuse pebbleBOT
#

@timber pine Has your question been resolved?

obtuse pebbleBOT
#

@timber pine Has your question been resolved?

obtuse pebbleBOT
#

@timber pine Has your question been resolved?

frank monolith
#

on 1 and the given integrand

obtuse pebbleBOT
#

@timber pine Has your question been resolved?

obtuse pebbleBOT
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covert forge
#

Hey guys can anyone help me please?

  1. How do I work out on a calculator? what is 2/3 thirds of [X meaning the total number].

  2. how do I work out what is X% of amount.

  3. how to I Calculate my currency to another at the BUY rate. and then how do I Calculate the buy / SELL. of the Foreign currency where I to SELL it. If you can give me an Example for each with the icons on a calculator. Thank you very much.

latent walrus
#

if you want 2/3 of x then do 2/3 multiplied by x
if you want x% then multiply by x/100
for 3 id assume its just the above two but youd have to see the exchange rates and calculate it

covert forge
latent walrus
#

i see

  1. 2/3 of x will be (2÷3)*x
covert forge
latent walrus
#

the *?

covert forge
latent walrus
#

thats multiplication, its the x above the -

covert forge
latent walrus
#

yeah

covert forge
latent walrus
#

it can always be used as a replacement for it yes

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/ generally means fraction, but you can consider it ÷

#

they do the same thing

latent walrus
obtuse pebbleBOT
#

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obtuse pebbleBOT
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eternal garden
#

Trying to write a sci-fi novel, and I'm having trouble with some math. Consider a galaxy 100,000 light-years in diameter. How fast would one need to go in order to traverse the entire length in one week? (This would likely be the max speed of the warp in my book)

tardy epoch
#

,w light year

tardy epoch
#

distance = 100,000 * 9.461 * 10 ^ 15 meters

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,w seconds in a week

tardy epoch
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time = 604800 seconds

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use speed = distance / time

obtuse pebbleBOT
#

@eternal garden Has your question been resolved?

eternal garden
#

0.16 lightyears per second, or 5,049,216 times the speed of light

#

thanks

obtuse pebbleBOT
#
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full crown
#

Yo can someone help rq

obtuse pebbleBOT
full crown
#

can someone explain this to em

#

me

obtuse pebbleBOT
# full crown
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
#

Show your work, and if possible, explain where you are stuck.

tight patio
#

@full crown

full crown
#

idk where to begin

tight patio
#

aight

#

which part do u need help in?

#

Im pretty sure u just estimate this stuff but idk if thr is a formula for these

full crown
#

how do i find out how many people are between 120-150

tight patio
#

240 ^^

full crown
#

no like

#

for part a

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how many had a systolic blood pressure reading 120 and 150, including 120 but not 15

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150

full crown
#

yea help pwease 🥺

#

what do i do

obtuse pebbleBOT
#

@full crown Has your question been resolved?

obtuse pebbleBOT
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boreal otter
#

can anyone see what i did wrong?

obtuse pebbleBOT
boreal otter
#

i am suppose to find if the limit exists

#

the answer is 2

obsidian estuary
#

The x will cancel top and bottom

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So you have 2

boreal otter
#

what

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second like as in when i waa cancelling the 2x?

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line*

#

here is the original question

obsidian estuary
#

Your variable should be canceled out on the third line

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So it should be 2/1

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On the second step of the third line

boreal otter
#

sorry i’m not sure what you mean by third line

#

that last bit?

latent walrus
#

yeah, you cancelled $\Delta x$ but then its still there and the 2 is missing

warm shaleBOT
#

AℤØ

latent walrus
#

should have just been lim(2)=2

boreal otter
#

ooooooooh

#

i just cancelled it wrong

#

thank you

#

i’m not sure where to start

#

delta x towards zero ***

tardy epoch
#

Multiply the top and bottom by the conjugate

obtuse pebbleBOT
#

@boreal otter Has your question been resolved?

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timid silo
#

What am I misunderstanding about Vectors? Ive watched about an hour if video and tried looking in my text book but I just cant seem to make any sense of what's the right way to do it

timid silo
#

The question just wants the magnitude and direction of the resultant

#

What are the bearings relative to?

#

I see it as go 5 units on a 100° bearing like a compass and then go 6 units on a 60° bearing from that point

#

Last picture is horrible, I realised how wrong it is, but the first two I just cant understand whether its right or not

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
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meager gale
#

ok

obtuse pebbleBOT
meager gale
#

ok

#

so

#

this is the hw

#

and

#

specificallty

#

i wanna understand how to do

#

9ab

#

i dont get it

#

because

ripe venture
#

Don’t dox urself homie

meager gale
#

idk

meager gale
#

IS MY NAME ON THAT?

ripe venture
#

no but might not be impossible to figure out a location

meager gale
#

oh thats fine

ripe venture
#

Which one?

meager gale
#

like half of mathcord knows where i live

#

(a) first ig

#

so

#

i was gonna

serene fossil
#

yeah the course name is kinda unique

#

identifying

meager gale
#

start with the summation definition of multiplication

meager gale
#

u wont track me

serene fossil
#

oh i see

#

its not even your class

meager gale
#

wdym

serene fossil
#

do you go to stanford?

meager gale
#

its like a program for highschoolers

#

for UG math

serene fossil
#

oh i see

meager gale
#

ye

serene fossil
#

lol then its even less doxxing

#

sorry off topic

meager gale
#

costed way too much for me to fail 😭

#

i think the midterm will have proofs so

#

i gotta get good at these

#

ima latex now.

#

$AB = BA$ \
$A^n = 0$\
$B^n = 0$\
For some $n \in \mathbb N$

warm shaleBOT
#

amukh1 | JS,Axler Fanboy

meager gale
#

right

#

tbh ill keep the power the same

serene fossil
#

well

#

to start

meager gale
#

instead of A^n B^k

#

ykwim

serene fossil
#

thats slightly incorrect

meager gale
#

as a first pass

meager gale
serene fossil
#

because of exacltly that

#

the powers are not the same

meager gale
#

yea ik

serene fossil
#

and you shouldnt assuem theya re

meager gale
#

im doing a first pass

#

ill do the more general one later

serene fossil
#

yeah but why bother tbh

meager gale
#

cuz it may be simpler?

serene fossil
#

i mean it might be

#

up to you

meager gale
#

right then

#

$$AB_{i,j} = \sum_{k=1}^r A_{i,k} B_{k,j}$$

#

af fuck

#

ok there

warm shaleBOT
#

amukh1 | JS,Axler Fanboy

meager gale
#

r is the

#

number of columns of A and rows of B

#

right

serene fossil
#

mm this is too complicated tbh

#

start with thinking about you need to prove

meager gale
#

😭

serene fossil
#

so you assume A^n=0 and B^n=0 and AB=BA

meager gale
#

yup

serene fossil
#

great those are your premises

#

now what do you need to prove?

meager gale
#

and i needa prove that..

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(AB)^n = 0?

#

for the same n?

#

ig

serene fossil
#

sure

meager gale
#

most likely

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B^nA^n

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iirc

#

no

#

no

#

ok

#

there

#

right?

serene fossil
#

what do you mean?

meager gale
#

is (AB)^n not B^nA^n

serene fossil
#

not in general

meager gale
#

then what is it

serene fossil
#

its actually just $ABABABAB\cdot AB$ n times

warm shaleBOT
#

llspacebarll

meager gale
#

right..

serene fossil
#

and thats the best you can do unless its commutative

#

but guess what

meager gale
#

aw

serene fossil
#

we have commutativity

meager gale
#

ohhh

#

perfect

#

so A^nB^n?

serene fossil
#

yes

meager gale
#

which is 0 . 0

serene fossil
#

yeah

meager gale
#

= 0

serene fossil
#

so QED

meager gale
#

thanks

#

idk why i didnt catch that

serene fossil
#

now generalize tho

meager gale
#

um

#

oh yeah thats fine

#

A^n is 0

#

0 * B^k

#

is gonna be 0

#

and same the other way

#

A^n * 0

#

= 0

#

right

serene fossil
#

well yeah but you should write a formal proof i guess

meager gale
#

yeah i will later

#

thats fine

#

is (b) false then?

serene fossil
#

i also think its worth noting that (AB)^n=A^nB^n

#

might not be taken for granted

#

meaning you could try to prove it as well

#

using induction is best

meager gale
#

ok

#

will try later

serene fossil
#

and for b) i think you shoul seek a counter example yeah

#

i doubt its true

meager gale
#

ok

#

kewl

#

thanks!

#

.close

obtuse pebbleBOT
#
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fleet quartz
#

I need to prove whether the set of all fractions p(x)/q(x), where p(x) and q(x) are polynomials with coefficients of complex numbers. (and q(x) is not the zero-polynomial q(x)=0 for all x). Is or isn't a field. I'm stuck deciphering the language of the question and I don't quite understand how to begin writing all the axioms. So far, I have been able to determine that q(x) cannot have a degree equal to 1.

polar fossil
#

why not?

fleet quartz
#

Because then q(x) is guarenteed to have an x value that causes it to be equal to 0.

warped scroll
#

so you need to prove the field axioms?

fleet quartz
#

Yes, I do.

polar fossil
warped scroll
#

do you know the field axioms

polar fossil
#

what q can't be is identically zero

warped scroll
fleet quartz
#

Right! Oh my goodness, I forgot the fundamental theorem of algebra. I forgot that complex x values exist and can make q 0.

warped scroll
#

wow

fleet quartz
#

I feel like that I might have an idea on how to start.

warped scroll
#

give it a try

fleet quartz
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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fathom flicker
obtuse pebbleBOT
fathom flicker
#

I was hoping someone could check my work for this

#

Since $2|xy|\leq (x^2+y^2)$ for all $x,y$ then we should have that

warm shaleBOT
#

Austin

fathom flicker
#

$$\frac{x^2y}{x^2+y^2}\leq \frac{x^2y}{2|xy|}=\frac{|x|^{2}y}{2|x||y|}=\frac{|x|y}{2|y|}$$

warm shaleBOT
#

Austin

fathom flicker
#

if $y<0$ then $y=-|y|$ and $y\geq 0$ then $y=|y|$ so either way we have that

warm shaleBOT
#

Austin

fathom flicker
#

$$\frac{x^2y}{x^2+y^2}\leq \frac{|x|}{2}$$ or $$\frac{x^2y}{x^2+y^2}\leq \frac{-|x|}{2}$$

warm shaleBOT
#

Austin

fathom flicker
#

which when we then take the limit as (x,y)->(0,0) then these go to 0 so so does our original function

#

so lim (x,y)->(0,0) f(x,y) =f(0,0) so it is cont at (0,0)

gilded needle
#

my only issue with this is that when you put |xy| in the denominator, you have issues if x=0 or y=0

#

what if instead of applying the hint to the denominator, you applied it to the numerator?

fathom flicker
#

if we write |xy|x=x^2*y this is false

gilded needle
#

$|x^2y| = |xy||x|$

warm shaleBOT
fathom flicker
#

not true

#

oh

#

abs value of left

#

yeah

fathom flicker
#

taking limit gives us it goes to 0

gilded needle
#

yep

fathom flicker
#

of course my first method is the most complicated way

#

fml

gilded needle
#

your way works too but you'd have to have special cases if x=0 or y=0

fathom flicker
gilded needle
#

what the

obtuse pebbleBOT
#

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astral aurora
obtuse pebbleBOT
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Please don't occupy multiple help channels.

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low path
obtuse pebbleBOT
warped scroll
#

isn't it speeding up when the acceleration is positive

tacit scarab
#

yes s is displacement, v is velocity and a is acceleration

obtuse pebbleBOT
#

@low path Has your question been resolved?

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sage dagger
#

how do I evaluate this?

obtuse pebbleBOT
tacit scarab
#

what's e^(-infinity)?

sage dagger
#

0?

tacit scarab
#

that's it

#

so e^(-0.5t) = 0

sage dagger
#

ooh

#

okay thanks

#

.close

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formal inlet
#

confused on how this doesnt count as orthogonal

formal inlet
#

any vector times an orthogonal vector of the original vector is 0

#

so taking one of the parallel vectors and finding values that would make the dot product 0 should work

civic zealot
#

that's not totally true.

#

you're vector isn't orthogonal to the other parallel line, for example

formal inlet
#

ok

#

with the info I currently have aka 2 points and 2 parallel vectors of a plan, how would I find an orthogonal vector

#

.close

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timid silo
#

Ihello, I am learning the limits
To solve this I have to apply Identity lt x-> 0 Sinx/x = 1
I want to make x-> 0 as ax -> 0. can I equate x -> 0 as we do in equations
x-> 0
ax -> a*0
ax -> 0
So i can apply the identity
And what it is called I want to learn more about it

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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weary heart
#

Solve the equation for :
x^n=n!

obtuse pebbleBOT
royal basin
#

!status

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
royal basin
#

also did you mean x^n = n! with a lowercase x?

weary heart
weary heart
high lily
#

math is case sensitive

#

there is no (lowercase) x in
X^n = n!

old isle
#

the more i learn about math the more complicated it gets

royal basin
old isle
#

ann, how many languages do you know

royal basin
#

kinda out of the blue but 4 i guess

#

why do you ask

old isle
#

just curious cuz i feel like i remember you knowing polish and i saw someone mention you knew hindi

royal basin
#

perhaps we should move to #discussion if you want to talk about this further?

old isle
#

sure

weary heart
royal basin
#

X is a capital letter, x is a lowercase letter

weary heart
#

How will it make difference in solving this equation

royal basin
#

solving X^n = n! (with big X) for x (small x) makes no sense

high lily
#

if the question was genuinely solve:
$$X^n = n!$$
for $x$,
its nonsense because there is no $x$ to solve for

warm shaleBOT
#

ℝam()n()v

weary heart
#

Solve the equation for x :
x^n=n!

old isle
#

yall are missing the invisible x

royal basin
#

so then

weary heart
#

Sorry I didn't notice

old isle
#

$x*0 + X^n = n!$, duh

royal basin
#

how'd you get x=1

warm shaleBOT
#

accialto

weary heart
#

I'm stupid

royal basin
#

note: "how did you get ___" does NOT mean " ___ is wrong, redo your work without showing it to us"

weary heart
#

I didn't do anything I thought of a stupid thing

#

Never mind that

#

How to even solve this?

#

@royal basin

royal basin
#

i mean raising both sides to the power of 1/n should do the trick, no?

weary heart
#

Lemme try

#

That's just $x=(n!)^(1/n)$

warm shaleBOT
#

Hamdy Hisham

royal basin
#

$x = (n!)^{1/n}$

warm shaleBOT
royal basin
#

yeah so

#

what's wrong w/ that

weary heart
#

What's next

royal basin
#

nothing?

#

you're done, are you not?

weary heart
royal basin
#

not significantly no

weary heart
#

The original one was $(x)^{2021-n}=(2021-n)!$

warm shaleBOT
#

Hamdy Hisham

weary heart
#

@royal basin

royal basin
#

can you show the original problem in FULL, please?

#

because i am suspicious still.

old isle
#

feels like some kind of 2021 olympiad problem

royal basin
#

like it was not just an equation

#

there had to have been something else written along with it

weary heart
#

Ahhh the original one is in arabic

#

Wait

#

This @royal basin

royal basin
#

???

weary heart
#

Wait I'll give you what I've done

royal basin
#

i do not understand this, i'm afraid.

#

don't give me what you've done

#

give me a clear and understandable problem statement first

weary heart
#

Ah I wrote it wrong

#

It's $y=x^{2021}$ then ...... =2021!

a.$y^{(2019)}$
b.$y^{(2020)}$
c.$y^{(2021)}$
d.$y^{(2022)}$

warm shaleBOT
#

Hamdy Hisham

weary heart
#

@royal basin

royal basin
#

this is literally the same as before

#

oh wait

#

those things are derivatives are they

weary heart
#

Yup

royal basin
#

so you're asked which order derivative of x^2021 results in 2021!

weary heart
#

Yup

royal basin
#

this doesn't need any of that equation-solving bullshit

#

how many times do you need to differentiate x^n to make a constant

weary heart
#

n?

#

@royal basin

royal basin
#

yes

weary heart
#

I think I'm stupid

royal basin
#

and what's the n'th derivative of x^n?

weary heart
#

nPn?

weary heart
royal basin
#

well maybe you could tell me what nPk is or admit you don't know

weary heart
#

I DON'T KNOW

#

I know it's like you do n(n-1)(n-2) but the number of terms is k

royal basin
#

ok and what happens if you have n of those terms

#

how far down does the product go

weary heart
#

I don't know

royal basin
#

if you start writing numbers from n and go down by 1 every time,

#

and you write out n numbers

#

what'll be the last number you write down?

obtuse pebbleBOT
#

@weary heart Has your question been resolved?

weary heart
royal basin
#

no, the last number won't be n!.

weary heart
royal basin
#

yes

weary heart
#

Aha thanks

#

@royal basin do you know any free to use CAS?

royal basin
#

geogebra?

weary heart
royal basin
#

dunno

obtuse pebbleBOT
#
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soft pond
#

Hey guys
I need help to calculate and understand this

tacit scarab
#

find the endpoints and equations of the two lines

soft pond
#

yea, i know, but how do I find it?

tacit scarab
#

let's start with end points

#

what's the end points of the first line?

cyan lark
#

Help each time this type of q come up I don't understand it

cyan lark
#

Oh did not saw that thanks

soft pond
tacit scarab
#

that's the right end point

#

does it contain 1?

#

I mean does the line contain that end point?

soft pond
#

yes?

obtuse pebbleBOT
#

@soft pond Has your question been resolved?

soft pond
#

<@&286206848099549185>

heavy zephyr
#

is there any x you can't plug in here?

soft pond
#

i dont know

heavy zephyr
#

well, do you kind of know how the function looks like?

soft pond
#

no i do not

heavy zephyr
#

for these kind of questions you only have to think about whether or not there is a mathematical rule you're going against when plugging in certain values

#

rules like "can't divide by zero"

neat blaze
#

(a+b)^3

soft pond
heavy zephyr
#

Is there a value for x you can't plug in here? Meaning: If you plug in 5 you will get an answer with h(5)=(5-3)^2=4. Is there an x so when you plug it in, you won't get an h(x) value

soft pond
#

I still don't know how to find the answer

heavy zephyr
#

Hmm okay. The answer is, the domain of the function is every x in the real numbers.

#

There is no number we can't plug in here so that h(x) is not defined. Why is this even important?
There are functions where we have fractions and x is in the denominator. So there x couldn't be 0 and therefore the domain would be all x in the reals but without x being 0

soft pond
#

Thanks
.close

obtuse pebbleBOT
#
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devout shell
#

HELLO

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

sage geode
#

You already have opened a channel, I will answer you there

#

.close

obtuse pebbleBOT
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inland thicket
#

⚔️ Guys

obtuse pebbleBOT
inland thicket
#

I try to figure out if this derivation

#

used this rule

#

anyone understand?

sage geode
#

Yes to both questions

inland thicket
#

woah

#

yo im confuse @sage geode just 1 more question

#

i know u not economic profesional but i also wonder why p*f(L,K) is also not that rule

sage geode
#

Is p a constant?

inland thicket
#

it could be because p is just number?

#

woah

#

woah

sage geode
#

Yes

inland thicket
#

🇺🇸US attack airstrike 500

#

Obama is dead.

sage geode
#

Even if you were to apply the product rule to p * f(L, K)

#

You would end up with the same thing

inland thicket
#

you expert

#

yo

#

yo wait can you just help with 1 more question

#

with your iq5000

sage geode
#

Sure

inland thicket
#

1min

#

this is perfect competition and diference is

#

there is no complex derivation there

#

but your probably cant use iq5000 for this

#

but i try wrap my head around this

#

first example i gave

#

second picture was first example

#

THIS FUNCTION IS MONPSONY (SECOND PICTURE)

#

first picture is without complex derivation

#

shiiii

#

so market supply in second picture ( Monopsony) is rising because it increases with wage and labour increases (each another worker hired, monopsony has to pay him more, but also pays every other worker more

#

that why w(L)??

#

but in first picture w is constant cos its perfect competition (firm cant affect wage)

#

so thats why no complex derivation in perfect competition

#

am i right?! 😮

sage geode
#

I don't know econ catThimc

inland thicket
#

yo but

#

like does it make sense

#

from iq5000 perspective

#

its just lines and graph and math like

#

i gave like econ premise

#

but in math like does it connect

#

i make econ bold

#

just 2 rules

sage geode
#

I suppose it connects

inland thicket
#

woah

#

im enlightedn now

#

i used to look at those function and think damn

#

and thought i gotta memorise

#

in my brains

#

but now i knwo the truth

#

.close

obtuse pebbleBOT
#
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frail depot
#

Try and use Newton-Raphson Method to compute all the zeros of f1(x) = 0.

frail depot
#

What would the steps be to compute all the zeros?

atomic hornet
#

have you studied the newton-raphson method yet?

royal basin
#

what is f_1

atomic hornet
#

also that yea

frail depot
#

I have also implemented it in python

atomic hornet
#

but what is f1(x)

frail depot
#

So, I think it only has one zero

royal basin
#

i mean yeah, it does

polar fossil
#

I'd agree with that

atomic hornet
#

definetly has one

royal basin
#

you can even solve the eq explicitly without the use of any special methods

frail depot
#

I did

royal basin
#

which ig means you have a way to doublecheck yourself

frail depot
#

I got x=0

#

But, exercise is to use the method

#

So

#

But so would the idea be to find two values one negative and one positive

#

f(x)

#

and then you know by IVT that inbetween this there must be a value for f(x)=0

atomic hornet
#

thats not newton raphson is it?

#

or are you told to just approximate a solition

frail depot
#

No, but to find a qualified guess

#

for x_1

atomic hornet
#

oh sure then

frail depot
#

You find a negative f(x) and a positive f(x) and then you know by the intermediate value theorem that inbetween these two there must exists x such that f(x)=0

#

Because the assignments says "compute all the zeros of"

atomic hornet
#

but as you said,theres only one

frail depot
#

Yes, but how would I know that using the newtons raphson?

#

Or is that just not possible

#

Or not using that

#

but like without solving the equation

atomic hornet
#

not possible really

frail depot
#

f(x)=0

atomic hornet
#

its just a lot easier to do algebraicaly

frail depot
#

Ye, I did solve f(x)=0

#

i just don't feel like thats what the assignment is telling me to do

atomic hornet
#

thats true

frail depot
#

Try and use Newton-Raphson solver to compute all the zeros

atomic hornet
#

is that a given solution?

frail depot
#

But that does not furfill that tho

#

It's the question

#

2) Try and use Newton-Raphson solver to compute all the zeros of f(x)=0

#

Anyway, perhaps it's fine what i've done

#

thanks for the help

#

.close

obtuse pebbleBOT
#
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graceful marten
#

Howdy

obtuse pebbleBOT
graceful marten
#

L1= y=2x +4

#

L2= y=2x -3

amber nest
#

!show

obtuse pebbleBOT
#

Show your work, and if possible, explain where you are stuck.

graceful marten
#

I dont know where to start

#

I know they are parallel lines.

#

I know the formula (x-x)^2 + (y-y)^2 Root all this stuff

#

Is the shortest distance between two points

#

Its also not the Green Line (Difference in Y axis)

polar fossil
#

yeah you need the perpendicular line

proper verge
#

the shortest distance would be the perpendicular

#

there is also a formula for it

#

which always works

graceful marten
#

Alright?

#

I dont think ive done that formula before

#

and chat gpt isnt helping, usless as always 0/10 i rate out of the 5 times i used it

proper verge
#

try |C1–C2|/√(A^2 + B^2 )

graceful marten
#

what would A and B be?

proper verge
#

both equations can be written as ax + by + c = 0 and ax + by + c1 = 0

graceful marten
#

ah

#

will do

proper verge
graceful marten
#

xD

#

Sounds about accurate

#

.close

obtuse pebbleBOT
#
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edgy cedar
#

hello

obtuse pebbleBOT
edgy cedar
#

im kinda confused with this one

#

cna someone help me rq

frank monolith
#

what's confusing you?

tight patio
#

!status

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
edgy cedar
#

that

#

from 1/2 divide 1/2 it went to multiply

#

and second one went 2/1

tight patio
#

Because I’m division when u divide anything by a fraction

#

U make the think ur dividing by its own reciprocal

#

And the signs becomes multiplication

edgy cedar
#

uhm

thin star
edgy cedar
#

can u explain simpler pls

#

if i divide fraction the second fraction go upside down and it become multiply

#

cooks told me that before

#

i remember now

thin star
#

$\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} * \frac{d}{c}$

warm shaleBOT
#

TooManyCooks

graceful marten
edgy cedar
#

ooooh tysm

#

it was realy basic

#

sorry to bother wit hsuch smal problm

#

ty again

obtuse pebbleBOT
#

@edgy cedar Has your question been resolved?

gilded ferry
#

Hi

obtuse pebbleBOT
#
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royal basin
obtuse pebbleBOT
#
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edgy cargo
#

for this I got 8y+6 for the width but im not sure what to do next to find the area

edgy cargo
#

do i just do (8y+6)*2y

wide rose
#

but

#

this is not a rectangle

obtuse pebbleBOT
#

@edgy cargo Has your question been resolved?

edgy cargo
#

ty

obtuse pebbleBOT
#
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runic void
#

For any integer n>2, Show that there are at least two elements in U(n) that satisfy x^2=1.

runic void
#

U(n) is the set of all least residues modulo n which are relatively prime to n

#

1 is element of U as 1 is always relatively prime to n

wide rose
#

and -1?

runic void
#

-1 isn’t an element in U

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maybe -1 congruent to (n-1) modulo n

wide rose
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hasn't the degree 2 polynomial only 2(max 2) solutions?

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like 1 and -1 here

runic void
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Different context

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that’s one of my confusion too, if think they are taking solutions modulo m i guess

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definitely -1 not in U(n), -1 cannot be a least residue aka remainder when divided by m.

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<@&286206848099549185>

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Question 20.

obtuse pebbleBOT
#

@runic void Has your question been resolved?

royal basin
#

also what's m

obtuse pebbleBOT
#
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thin oxide
#

Alpha is contained in irrational n.group. just how?

royal basin
#

it doesn't matter that alpha is irrational

thin oxide
#

Some context.

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The language is French.

royal basin
#

ça matière pas qu'il est irrationnel

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pour le premier pas au moins

thin oxide
#

Can you speak English?

royal basin
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sure i can

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thought it'd be easier if we spoke french

thin oxide
#

What I don't get is how `Alpha^(n+1)+Alpha^n = Alp^(n) * (Alp+1)

alpine raven
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alpha +1 = alpha²

royal basin
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$\alpha^{n+1} + \alpha^n = \alpha^n \cdot \alpha + \alpha^n \cdot 1$

warm shaleBOT
royal basin
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do you agree or disagree with this?

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@thin oxide

alpine raven
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si tu te souviens du polynome qui donne le nombre d'or

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x²-x-1

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x² = x+1
vrai pour alpha

thin oxide
royal basin
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yeah so

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$\alpha^n \cdot \alpha + \alpha^n \cdot 1 = \alpha^n(\alpha + 1)$

warm shaleBOT
royal basin
#

agree or disagree?

thin oxide
#

agree.

royal basin
#

so...

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wait, what exactly confused you about this?

thin oxide
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Alp + 1 = Alp^2???

royal basin
#

yes!

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you are told they are roots of the equation x^2 = x + 1.

thin oxide
royal basin
#

i mean...

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sure?

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like alpha was INTRODUCED as one of the roots of that equation

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so it's a strange question to ask

thin oxide
#

Well, this will take me to another topic rather math that if you want to know.

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which is I'm going to learn math using French in Uni while I'm not that cool with the language.

#

Anyway, thank you.

#

.close

obtuse pebbleBOT
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copper citrus
#

hello guys! I think that the correct answer from the book to the challenge question 20 was totally unclear for me (didn't even visualize or get the first requirement that scalars should be positive)

obtuse pebbleBOT
#

@copper citrus Has your question been resolved?

copper citrus
#

<@&286206848099549185>

obtuse pebbleBOT
#

@copper citrus Has your question been resolved?

copper citrus
#

<@&286206848099549185>

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.close

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tacit sorrel
#

anyone can explain me the sum of sequences formula ? the 1-q^n+1 / 1-q ?

tacit sorrel
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on geometrical sequences

sage geode
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There is a really quick proof for that

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Say $S = 1 + q + q^2 + \dots + q^n$

warm shaleBOT
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A Lonely Bean

sage geode
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Then $qS = q + q^2 + q^3 + \dots + q^{n+1}$, right?

warm shaleBOT
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A Lonely Bean

sage geode
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@fickle flame If you have any questions about what I am writing/saying, just ask

fickle flame
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yes, until now i didn't study that, so i'm a bit confiosing

sage geode
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You will understand the proof once I am finished, I hope, but for now I shall wait for the helpee's response

tacit sorrel
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for what u said yes

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but then saying that my sequence start at u1 = 1

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does it change something to the formula

sage geode
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Once you know the formula for 1 + q + q^2 + ... + q^n, you can just multiple it by u1 and you will get the formula for any geometric sequence

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But let's first be done with simplifying S

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Alright, so, you may notice that these two sums (S and qS) share a lot of terms in common

tacit sorrel
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yes

sage geode
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In fact, every term is shared except for 1 and q^{n+1}

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What would happen if we were to subtract S from qS?

tacit sorrel
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just q ?

sage geode
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What just q?

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Ah

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You mean we would get just q?

tacit sorrel
#

yes

sage geode
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No no q gets cancelled out as well

sage geode
sage geode
sage geode
sage geode
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So q, q^2, q^3 and so on up until q^n disappears when we take qS - S

sage geode
# tacit sorrel how tho i m interested

\begin{align*}
S &= 1 + q + q^2 + q^3 + \dots + q^n \
qS &= \phantom{1 + } q + q^2 + q^3 + \dots + q^n + q^{n+1} \
S - qS &= 1 + \cancel q - \cancel q + \cancel{q^2} - \cancel{q^2} + \cancel{q^3} - \cancel{q^3} + \dots + \cancel {q^n} - \cancel {q^n} - q^{n+1}
\end{align*}

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Ugh wait

warm shaleBOT
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A Lonely Bean

tacit sorrel
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okay i see and how does it give the 1-q^n+1/1-q formula tho

sage geode
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So the last equation is just the same as S(1 - q) = 1 - q^{n+1}

#

And you just divide both sides by (1 - q)

tacit sorrel
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i m so confused wait

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in this

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number 4

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how does it give 2^64 -1

sage geode
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1 - 2 is -1

tacit sorrel
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knowing first term is =1

sage geode
#

So 1 - 2^64, when divided by -1, becomes 1/(-1) - 2^64/(-1)

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Which is -1 + 2^64

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Or just 2^64 - 1

tacit sorrel
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why divide by -1

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can you explain more in debt please if it doesn t bother u

sage geode
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Because the formula gives us $\frac{1-2^{64}}{1-2}$, everything up until this makes sense, right?

warm shaleBOT
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A Lonely Bean

tacit sorrel
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the why we do this no but ig it s just applying formula

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like i could get there too by just following the formula

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but then the after for results i don t get it

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do u think i should understand the formula?

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like the why

sage geode
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thonk Well I have shown you the proof of the formula already

tacit sorrel
sage geode
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That's just how I defined S to be

tacit sorrel
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so wait instead of putting the 1 at the beginning u just put it in qS ?

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to explain it s q^next one always?

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i m sorry i lack a lot in some stuffs in maths i m trying to figure out

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so i can understand the exercice better

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and why it gives 2^64 -1

sage geode
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No I defined S to be 1 + q + q^2 + ... + q^n because any geometric sum can be evaluated by knowing the formula for 1 + q + q^2 + ... + q^n

tacit sorrel
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why the 1 at the beginning tho

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i see why the continue of it

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but the 1 no

sage geode
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Let's say we have some geometric sequence with the first term and the common ratio given as $u_1$ and $q$ respectively

warm shaleBOT
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A Lonely Bean

sage geode
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The $k$th term of the sequence can be calculated using $u_k = u_1q^{k-1}$, right?

warm shaleBOT
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A Lonely Bean

tacit sorrel
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why ^k-1

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i usually know Un= u0 * q^n

sage geode
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Ah, so you start with 0

tacit sorrel
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it s another system that might be the reason as well

sage geode
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Alright one moment I'll fix that

tacit sorrel
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in my today exercice it starts from u1

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but i would like to understand the difference

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of what it does to the formula

sage geode
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So do you want to start with u0 or u1?

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Ah

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There's no difference

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Just preference

tacit sorrel
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oh

sage geode
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The end result is the same no matter what you call your variables

tacit sorrel
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and no matter from when does it start?

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the sequence

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no matter like first term is ?

sage geode
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Yeah, as long as you have done everything else correctly, there should be no problem

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So u0 or u1, which one shall we start with?

tacit sorrel
sage geode
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Let's say we are given some geometric sequence starting with $u_0$ and the common ratio as $q$. The $k$th term of the sequence can be aclculated using $u_k = u_0q^k$, right?

warm shaleBOT
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A Lonely Bean

tacit sorrel
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yes

sage geode
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So if we were to add up some amount of first terms in the sequence, we would have [ u_0 + u_1 + u_2 + u_3 + \dots + u_n ] For some natural number $n$. According to the formula for the $k$th term, we are able to rewrite that as [ u_0 + u_0q + u_0q^2 + u_0q^3 + \dots + u_0q^n ] Can you see anything that can be factored out?

warm shaleBOT
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A Lonely Bean

tacit sorrel
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u0?

sage geode
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Yes, when we factor it out, we get $u_0(1 + q + q^2 + q^3 + \dots + q^n)$

warm shaleBOT
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A Lonely Bean

tacit sorrel
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ohhhh

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that s where the 1 comes from

sage geode
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And that sum in the parenthesis is some geometric sequence starting with 1 as its first term

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This is why you can calculate any geometric sum by knowing how to calculate geometric sums whose first term is 1

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Hence I defined S to be 1 + q + ... + q^n

tacit sorrel
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oh my god