help-10

[naive sigil]

You could've searched it... Google is useful after all.

[lethal ice]

real

[naive sigil]

Just saying. xD

[lethal ice]

i come here normally when ive been doing hw for hours and am half functioning 😭

thanks

.close

[obtuse pebble]

Channel closed

Closed by @lethal ice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[austere rune]

hey guys I wanted to clear up a few things, for this problem it asks to find the limit of the function. One of my friends told me that you can find the limit of any point even if it exists, meaning that any linear line has a limit at any point. What mindset should i think of when I think about limits. If its based on any point then any graph should have a limit right? Or is it that every limit is based on a discountinity?

[royal shard]

limit doesnt always exists

existence of a limit implies that the left and right sided limits exist and are equal

what limit do you want to get here?

for example, at x=0 we have h(0)=0

however the limit from the left is not the limit from the right

thus the limit does not exist

with "limit" we usually mean the two sided limit

[austere rune]

yes techincally

it does

h(1) = 0

[royal shard]

$\lim_{x\to x_0}h(x) \ \lim_{x\uparrow x_0}h(x) \ \lim_{x\downarrow x_0}h(x)$

[warm shale]

Martin

[austere rune]

like if I put in h(0.99) = -0.01

and like

h(1.01) = 0.001

so from both sides its techincally approaching right?

[royal shard]

yes

that is not the best argument though, but the idea is good

[austere rune]

but does it not right tho

like if its approachiing from both sides

it should be a limit right?

[royal shard]

then the limit exists

[austere rune]

nah but something seems off

then at that point

any line

even a rational function

with vertical asymptote

can have a limit right?

[royal shard]

hmm

if we have a vertical asymptote, we will get + or - infinity at that point

at x=1, our function h i continuous, that is something very nice

[austere rune]

no

look at this graph for example

its taking 0 right

[royal shard]

which limit do we want here?

for which x

[austere rune]

lets say 0

im so

im so

[royal shard]

then we dont care about the asymptode, since we are not at that asymptote

[austere rune]

im pissed

look at how stupid I am

they GAVE ME A AND B

I WASTED ALL THIS TIME

thx for the help

.close

[obtuse pebble]

Channel closed

Closed by @austere rune

Use .reopen if this was a mistake.

[royal shard]

easy rule:
if a function is continuous at a point x, then the two sided limit at that point exists and equals f(x) at that point
the opposite is also true:
if the two siderd limit exists at a point x and f(x) equals that limit, then f is continuous in this x

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet yew]

Can I get put in a channel for pre calc help

[obtuse pebble]

Please don't occupy multiple help channels.

[violet yew]

I’m confused am I supposed to wait here

Until I get help

[gentle atlas]

do you know the Pythagorean theorem?

[violet yew]

I finished that prob

I’m confused on this 1 though

I got too b squared = 2304

Can you help please

I’m struggling and my homework due tn

[gentle atlas]

then you should square root 2304

[violet yew]

Okay thank you

[gentle atlas]

the distance between P and Q can be found out using the Distance formula

[violet yew]

What’s the distance formula

[gentle atlas]

distance between two points (x1,y1) and (x2,y2)

[violet yew]

I don’t think ill be able to do that I don’t have calculator besides on computer

[gentle atlas]

it should be a fairly simple calculation

[violet yew]

I don’t think so for myself I’m getting confused

[gentle atlas]

ok

so let me go step by step

[violet yew]

Thank you

[gentle atlas]

we have P = (-5, 4)

[violet yew]

Yep

[gentle atlas]

Q = (2,-2)

[violet yew]

Yep

[gentle atlas]

we will take P as point 1 and Q as point 2

[violet yew]

Okay

[gentle atlas]

x1 = -5

[violet yew]

How come we lost the 4

[gentle atlas]

-5 is the x-coordinate

[violet yew]

Ok

[gentle atlas]

4 = y-cooridnate

[violet yew]

Oh

Yea

[gentle atlas]

y1 = 4

[violet yew]

Yep

[gentle atlas]

the same way x2 = 2

y2 = -2

[violet yew]

ok

[gentle atlas]

did you understand till here?

[violet yew]

Yes

[gentle atlas]

now we substitute these values in the distance formula

[violet yew]

2-5

-3

[gentle atlas]

why 2-5?

[violet yew]

Becuz isn’t x1 5

[gentle atlas]

x1 = -5

x2 = 2

y1 = 4

y2 = -2

[violet yew]

Yeah so 2-5

Squared

?

[gentle atlas]

it will be 2 - (-5)

[violet yew]

7

[gentle atlas]

yes

[violet yew]

49

[gentle atlas]

yes

[violet yew]

49 and 2

[gentle atlas]

?

[violet yew]

4

Y=4

[gentle atlas]

y1 = 4

y2 = -2

y2 - y1 = -2 - 4

[violet yew]

-6

[gentle atlas]

yes

[violet yew]

49 36

[gentle atlas]

yes

add them

[violet yew]

85

[gentle atlas]

yes

[violet yew]

That’s the answe?

[gentle atlas]

no

square root of 85

it is taking square root of 85

[violet yew]

Like square root 85 is the answer or square root it

?

[gentle atlas]

square root of 85 is the answer

it is the distance between P and Q

[violet yew]

Is the midpoint

?

How do I solve for the midpoint

Of the segment joining p and q

[gentle atlas]

take another point R on the line with coordinates (x, y)

actually I will let someone else do this one

I am extremely sorry

but I will have to leave

[violet yew]

Okay thank you does someone else just come in here

[gentle atlas]

yes they will come in here

[violet yew]

Okay thank you

[gentle atlas]

<@&286206848099549185> can you continue, I will have to leave, work irl

[violet yew]

<@&286206848099549185>

[nocturne minnow]

First it was already pinged by the previous person so you didn't need to do it again

Second use the midpoint formula

[topaz timber]

You can use midpoint formula for part b, and the pythagorean theorem or distance formula for part a

since d formula is derivation of pythagorean theorem

[violet yew]

Finished

Onto the next homework problem

[obtuse pebble]

@violet yew Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[manic vigil]

How do you solve this

Idk how it's wrong

[obtuse pebble]

@manic vigil Has your question been resolved?

[manic vigil]

. Close

.close

[obtuse pebble]

Channel closed

Closed by @manic vigil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen verge]

Hi, can someone help me with this? I have legit no idea where to start:

[obtuse pebble]

@keen verge Has your question been resolved?

[keen verge]

I've solved the hint, but I don't really see how that applies to the first part of the question. I'm only very new to this multivaraiable stuff and so I'm just having trouble "translating" what the question is asking me. noatiton and whatnot

[obtuse pebble]

@keen verge Has your question been resolved?

[obtuse pebble]

@keen verge Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Find dy/dx

[fathom flicker]

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[timid silo]

1

[drowsy cosmos]

do you know what dy/dx is?

[timid silo]

I know

[drowsy cosmos]

do you know any rules?

[timid silo]

Yes

[drowsy cosmos]

tell me some of them

[timid silo]

d/dx (c)=0

[drowsy cosmos]

others? tell every rule you know

[timid silo]

d/dx (x)=1

[drowsy cosmos]

if thats all the rules you know perhaps you should first learn more rules for derivatives

[timid silo]

No

Bot all

Not

Its jut hard for mr to tyoe rn

[drowsy cosmos]

you can also tell them by name

[slim solar]

Can you tell the derivative of d/dx(x^n)

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

nx^(n-1)

[slim solar]

Yes

Just do that here

Also remember that when there are multiple terms like this you can differenciate them seperately and add them

Should I show that? Or do you get it

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Oh ok

[timid silo]

.close

[obtuse pebble]

Channel closed

Closed by @silent basin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold cove]

how to solve √4x+3 using the derivatives of 4-step rule

[royal basin]

"4-step rule"?

also, you mean $\sqrt{4x+3}$, right?

[warm shale]

Ann

[bold cove]

yes

[royal basin]

anyway, what is this "4-step rule"?

[bold cove]

1st step:
substitute x to x + delta x
substitute y to x + delta y

2nd step: subtract the original function

3rd step: divide by delta x

then lastly,

4th step: Get lim delta x as it approaches 0

[royal basin]

[bold cove]

here is an example

TT

[sage geode]

Basically evaluate $\lim_{\Delta x \to 0}\frac{\sqrt{4(x + \Delta x) + 3} - \sqrt{4x + 3}}{\Delta x}$, right?

[warm shale]

A Lonely Bean

[sage geode]

Huh wait

Well yeah you end up doing the same thing

Anyway, try using the conjugate

I.e. multiply by $\frac{\sqrt{4(x + \Delta x) + 3} + \sqrt{4x + 3}}{\sqrt{4(x + \Delta x) + 3} + \sqrt{4x + 3}}$

[warm shale]

A Lonely Bean

[hybrid kestrel]

hmm

[bold cove]

$\frac{1}{\sqrt{2x + 3}}$

[warm shale]

Riwryyyy

[sage geode]

The final answer should be 2/sqrt(4x + 3) though, could you show your work?

[obtuse pebble]

@bold cove Has your question been resolved?

[bold cove]

our professor arrived with this answer using chain rule

i just didn't know how

TT

[bold cove]

anw i have to go, I'll try using this later

.close

[obtuse pebble]

Channel closed

Closed by @bold cove

Use .reopen if this was a mistake.

[bold cove]

ty

[raven crescent]

its 0/0 indeterminate form you can also solve it by using L'hopital rule

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stoic token]

Guys what to do after this step

??

I have to solve for |Z|

[tacit escarp]

if you know that sin𝛂 is -'ve then you can multiply it by -1 because of the absolute value

[obtuse pebble]

@stoic token Has your question been resolved?

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elfin pilot]

kinda new to limits so, sorry if this is way too simple to be here

[elfin pilot]

$$ \lim _{x\to 0}\left(\frac{f\left(x\right)}{x}\right)=1,:\lim _{x\to 0}\left(\frac{f\left(x\right)+2x}{x+sinx}\right) $$

[warm shale]

TubyconB

[elfin pilot]

I know the limit of f(x)/x = 1, I don't really see how I can isolate it in the other limit though

[sweet cobalt]

I am also new to limits, can you just say 2x and sin(x) both tend to 0 as x tends to 0?

[elfin pilot]

can I?

[sweet cobalt]

No idea lol

[elfin pilot]

doesn't really seem right to me, to just ignore 2x and sinx

I should have something like $$\lim _{x\to 0}\left(\frac{f\left(x\right)}{x}+A\left(x\right)\right)$$

[warm shale]

TubyconB

[elfin pilot]

I guess

[rich plume]

divide both numerator and denominator by x

you will have something like ((f(x)/x)+2)/(1+(sinx/x))

[elfin pilot]

yeah I see

doing it right now

[rich plume]

use the given info

and are you aware of the limit x tends to zero sinx/x?

[elfin pilot]

is equal to 1

yeah

[rich plume]

yes

[elfin pilot]

alright thanks very helpful

.close

[obtuse pebble]

Channel closed

Closed by @elfin pilot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wild vigil]

wwith what kind of formula/way can this be calculated ?

[tacit escarp]

Basic trig

And similar triangles I think

I can’t read German though

So they might not be similar

[wild vigil]

want me to translate?

[tacit escarp]

Yes please

[wild vigil]

so theres a boy his shadow reaches 2,86m the trees shadow reaches 37,40m the boy is 1,93 now how tall is the tree?

[tacit escarp]

It might be to find the ratio between the sides you know and then multiplying that ratio with another side

This only works if there are similar triangles

[royal basin]

boy
1.93m tall

that's a whole grown man unless hes like had a MASSIVE growth spurt

[royal basin]

you don't need trig here btw

[tacit escarp]

Similar triangles?

[royal basin]

(man's height)/(man's shadow) = (tree height)/(tree shadow)

[royal basin]

yes

[tacit escarp]

Nice

[wild vigil]

ahh okey lemme try

yup got the right answer

but on the bottom it says i should use

this thing here to solve it which i just saw now

[wild vigil]

is that the same thing you did ?

[tacit escarp]

This is the similar triangle idea

[royal basin]

yes

[wild vigil]

so thats how it alwys goes height/lenght= height/lenght?

[royal basin]

not necessarily...

[wild vigil]

but still if the height of the tree was given but the lenght of its shadow wasnt the same formula would apply?

[royal basin]

sure

[wild vigil]

.close

[obtuse pebble]

Channel closed

Closed by @wild vigil

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe oracle]

you can use `` or $ $ to surround your electrostatic force equation to avoid discord formatting btw

[obtuse pebble]

@opaque pier Has your question been resolved?

[warm shale]

Berry

[timid silo]

when q is negatively charged on the right hand side of particle 2, the electrostatic force with particle 2 is bigger than the one with particle 1. So their net force cant be 0.

i mean one of the scenarios is impossible

[frank monolith]

as you move forward, it can be zero

try to graph this ig

show

im lazy to think

show the graph lol

,rotate

[frank monolith]

what graph is this?

draw a rough graph of force vs coords

[timid silo]

we can sure one thing that is, these three are in one line.

[frank monolith]

oh

yeah, hank's approach is correct, one of the conditions is false.

the distance between particle 2 and 3 is too smol if 3 is at right of 2

so force tends to infinity

too large for 1 to handle

which has a smaller charge

(but it can be zero as you move towards +ve x direction, but i think question wants you to answer the nearest coords)

and charge being positive or negative wont matter

idk, show your working

,w solve for x (1)/(x^2) = (3)/(x+10)^2

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by oldieidlog

[frank monolith]

[timid silo]

force is a vector

it has not only quantity but direction

$k\frac{q_1q_3}{r^2}+k\frac{q_2q_3}{(r-10)^2}=0$

[warm shale]

Hank

[timid silo]

comes from here

[frank monolith]

yeah why -10?

[timid silo]

for example, p3 is at (-10,0)

then their distance between p2 and p3 is -10-10=20

[frank monolith]

huh?

distance is not negative

[timid silo]

|-10-10|

[frank monolith]

but you dont put -10 in place of r

r is always positive

so it obv is r + 10

[timid silo]

$k\frac{q_1q_3}{x^2}+k\frac{q_2q_3}{(x-10)^2}=0$

[warm shale]

Hank

[timid silo]

do you mean how to solve this equation

it has one variable

only x

in this equation, we want to solve out x

and we know q1, q2

and k, q3 can be cancel out

[warm shale]

Berry

[timid silo]

$kq_3(\frac{1}{x^2}+\frac{-3}{(x-10)^2})=0$

[warm shale]

Hank

[timid silo]

k cant be 0

q3 isnt 0

almost

[warm shale]

Berry

[timid silo]

right

you can put the negative one to right side

the equation just means forces on p3 is equal in quantity

but their direction is the same, and the net force is twice as much as one of them

when their direction is opposite, then net force can be 0

[obtuse pebble]

Channel closed

Closed by @opaque pier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[graceful loom]

I made help and no one is helping me

[sage geode]

I could help if you post the questions

[graceful loom]

just these @opaque pier

I had

but I'm finding its

diffucult to understand

yes

I solved 2 questions

now I'm stuck with question 14

thanks for the help I did 2

now I'm trying to figure out question 14

its calculate

the length of D

and mid point (M)

of AB

@opaque pier

so like I subtitude x and y

So

I figuired

the answer is D

-6

[obtuse pebble]

@graceful loom Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[errant smelt]

I am stuck and dont know what to do next

[timid silo]

a^3=2b^3 means that a^3 is even. What does that mean for a?

[errant smelt]

a^3 is divisible by 2?

[timid silo]

That's not my question. Yes, a^3 is divisible by 2, a.k.a. even, but what can we conclude about a?

[errant smelt]

a is even

[timid silo]

Correct

If a is even then there exists an integer k such that a=2k

So you can substitute in a=2k to see what properties you can get out of this

[errant smelt]

ahhh, i get it now

b is also even then

which contradicts that a/b is already simplified

thank you

[timid silo]

Don't forget to .close

[errant smelt]

.close

[obtuse pebble]

Channel closed

Closed by @errant smelt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[long hedge]

this doesnt seem right

[long hedge]

if i keep adding zeros it stays 5

[wooden cipher]

That is true

e^(-inf)=0

So left side limit would be 5/(1-0)=5

[long hedge]

i dont understand

[wooden cipher]

I think it converges too quickly that the precision on desmos just rounds it to 5

[wooden cipher]

since youre plugging in a negative number, the exponent is negative

as x -> 0-, 1/x -> -inf

[obtuse pebble]

@long hedge Has your question been resolved?

Channel closed

Closed by @long hedge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich steeple]

Hi, i need help with a geometry problem

ADBE is a rhombus
G lies on DE
GF is parallel to AD
GI is parallel to DB

I need to prove that FDIE is a kite

So far i figured out a few angles are equal, but i haven't made that much progress

[obtuse pebble]

@rich steeple Has your question been resolved?

[rich steeple]

<@&286206848099549185>

[turbid folio]

a kite

[rich steeple]

yes

i assume that like most of the times i face a geometry problem, there's something i hadn't checked that makes the whole answer reveal itself

[turbid folio]

a rhombus is always a kite

[rich steeple]

it is

but i do not know that FDIE is a rhombus

i know that ADBE is one

[turbid folio]

I thought you said you need to prove FDIE is a kite?

[rich steeple]

i did

[turbid folio]

oh ok

[rich steeple]

<@&286206848099549185>

[rich steeple]

45 minutes and no help, i guess i'll have to try another day

.close

[obtuse pebble]

Channel closed

Closed by @rich steeple

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hard minnow]

This is a structures homework but I'm just not understanding how to derive my answer based off of my truth table:

[hard minnow]

This is my attempt:

[royal basin]

that looks like only a problem statement

did you forget to post your work there

[hard minnow]

Sorry this

So I have 8 combinations here for what color the hats of Harry, Ron, and Hermoine can be each time.

I immediately rull out the positivity of WWW

because the problem specifically says not all 3 are white at the same time.

But I'm loss on trying to understand the rest of the problem

[royal basin]

uh huh

well think about harry's perpsective

[hard minnow]

Or more appropriately, moving from here.

[royal basin]

he knows that not all 3 hats are white

under what circumstances could he tell the color of his own hat?

[hard minnow]

Would it be if both Ron and Hermoines hat colors were white?

Because that would imply his own hat color is black, because not all 3 hats can be white at once.

[royal basin]

yes, exactly.

[hard minnow]

Okay, so that immediately implies the color of Ron and Hermoine's hats are either black and black, or white and black, right?

[royal basin]

yes

in fact

[hard minnow]

Oh snap. So therefore Hermoines hat is black

[royal basin]

this next step's a little trickier, though

[hard minnow]

wait disregard this

my deductive reasoning wouldnt make sense

[royal basin]

and of course the reason Ron knows about that scenario being out is that he heard Harry say no.

cause Harry wouldn't have said no in that scenario -- he would have claimed his color

[obtuse pebble]

@hard minnow Has your question been resolved?

[hard minnow]

I'm sorry, I was out. Let me reread this.

[hard minnow]

What about Hermione?

[royal basin]

well Hermione's blindfold does not stop her mapping out all this same reasoning in her head

eventually arriving at the pic that i sent

knowing now that in all the non-ruled-out scenarios, her hat is black!

[hard minnow]

Can we go over this part again

Sorry if I'm being slow. So Ron also says no because similar to Harry, the options available are either: black and white or black and black?

[royal basin]

no

Ron saying no is based on more complex reasoning

like, ok, let's list their hats in Harry-Ron-Hermione order for consistency

we already know WWW is ruled out right off the bat

we know BWW is out since Harry would have said yes. Ron also knows BWW is out.

agree or disagree?

[hard minnow]

Wait I'm sorry why is that ruled out? It's because in the beginning, Harry was unable to determine his hat color because Ron's and Hermione's hat colors very well could have been black and black or white and black?

Yes, I agree

[royal basin]

ok picture this

if harry were to see two white hats he would know the scenario is _WW

and since it isn't WWW it would have had to be BWW

[hard minnow]

right, I understand

[royal basin]

right

similar logic

[hard minnow]

we can cross it out

[royal basin]

Ron knows BWW is out, because Harry said no.

so if he saw B_W he would know his own color as well

ie if he saw harry in black and hermione in white

[hard minnow]

Right, so both Harry and Ron know BWW is out because they'd know their color because any other option would violate the "not all 3 can be white" rule

[royal basin]

yes sure

[hard minnow]

Omg, I think I got it! Tell me if this makes sense: Harry says "no" , the only way he'd be able to say "yes" is if the other two fellas were both white, implying he'd be able to choose black. But they aren't-they're either black and white or black and black. Ron says "no", because the game stipulates that not all three can be white, implying Harry is not white at all and is in fact black because if he was white, Ron would be able to tell his own color because Harry being white and Hermione being white implies he must be black. Harry is thus black. Now we are left with the knowledge that Harry is black, and Ron and Hermione are still either black/white or black/black...

[hard minnow]

Ann, I think I got it, can I run it through you one last time?

The question is specifically asking about the color of Hermoins hat, not Ron or Harry, right? So my answer doesn't have to include their hat color?

[obtuse pebble]

@hard minnow Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet fjord]

(4,8)(6,10)(8,8)(4,1)(0.8)(2,10)

[scarlet fjord]

Give me the area of this

It is shaped like a heart and it is a polygon

[warm canopy]

draw it, split it into simpler shapes

[scarlet fjord]

Alr whats the area?

[warm canopy]

no one here is going to do it for you

[scarlet fjord]

I need help on doing it

[warm canopy]

i gave you a starting point

[scarlet fjord]

Yeah i already did that

[warm canopy]

split it up into smaller shapes that are easy to calculate the area of

[scarlet fjord]

Yea but i got wrong answer

I got 64 for everything and divided 2

[warm canopy]

then show your work

[scarlet fjord]

Yeah i did

[warm canopy]

what

[scarlet fjord]

Nvm i got it

[warm canopy]

show it here so people can see what you did

[scarlet fjord]

.close

[obtuse pebble]

Channel closed

Closed by @scarlet fjord

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[finite drum]

hi

[fossil crag]

Wassup, you need math help?

[obtuse pebble]

@finite drum Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dawn thunder]

Im being told to create an equation to find the volume. Let R be the region between the graph of f and the y axis on the interval [0, 1] (on the y axis). Set up an integral to find the volume V of the solid region obtained by revolving R about the y axis and then find the volume. Because it was about the y-axis i used the shell method and it was wrong. But i used the washer method and it was correct? I wanted to know why this is because I thought that disk was only used if the axis of rotation was along the x axis.

[dawn thunder]

My work

[obtuse pebble]

@dawn thunder Has your question been resolved?

[obtuse pebble]

@dawn thunder Has your question been resolved?

Channel closed

Closed by @dawn thunder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy solstice]

What does dx in this equation mean? Can I just substitute 0 for x?

[worthy solstice]

i hate this server

[timid silo]

i hate your question

[obtuse pebble]

@worthy solstice Has your question been resolved?

Channel closed

Closed by @worthy solstice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[swift wedge]

i was wondering why this worked out to -2x+4

i originally got 2x-4 instead and im a bit confused

[nocturne minnow]

It looks like you subtracted 4 on both sides, correct?

[swift wedge]

moved my 2x over to isolate y

[nocturne minnow]

If you moved 2x over, then how did you get 2x - 4?

[swift wedge]

i think i counted y as a negative while dividing

i did that on my last question and it turned out correct i believe

[nocturne minnow]

In that problem, y isn't negative

[swift wedge]

what is the way to tell?

last one was also just y not like 2y

[nocturne minnow]

Because of the sign in front

If it was negative y, it would have been - y

[swift wedge]

oh okay im just confused since it worked out in my last problem

[nocturne minnow]

Show the last problem

[swift wedge]

5x+y=2 one

[nocturne minnow]

It shouldn't have worked

You just got lucky

There is no negative in front of the y so you don't divide by -y

[swift wedge]

oh okay

if i did it by postive y wouldnt i have gotten -5x?

[nocturne minnow]

Yes

[swift wedge]

-5x+2 also works out as an answer?

[nocturne minnow]

What do you mean by works as an answer? If you were setting 5x + y = 2 equal to positive y, the only possible answer is y = -5x + 2

[swift wedge]

oh like its basically the same thing as 5x-2 if reversed?

[nocturne minnow]

What?

[swift wedge]

nevermind so -5x+2 would be the correct answer

[nocturne minnow]

If you were setting 5x + y = 2 equal to positive y, the only possible answer is y = -5x + 2

[swift wedge]

oh okay thanks i thought u meant i got lucky as like got it correct

thx for the help i appreciate it

.close

[obtuse pebble]

Channel closed

Closed by @swift wedge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glossy lily]

looking for help in trying to solve piecewise functions

[glossy lily]

an explanation would be greatly appreciated

[viscid gull]

cmon bruv u haven't even tried yet

U should at least try 1st

did u not go to class when they taught u how to do this or something? If so u can just Google for a lesson on it. Did it this time for u but next time u can do it urself https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:absolute-value-piecewise-functions/x2f8bb11595b61c86:piecewise-functions/v/graphing-piecewise-function

[obtuse pebble]

@glossy lily Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deft hazel]

I just wanna ask on my scientific calculator brand: Casio, model: fx-CG50 AU if that matters what formula or wtv does the InvN function do in the statistics option use

[deft hazel]

Speaking about the Gaussian Distribution

Is the InvN option related to Wald Distribution or smth

[nocturne minnow]

Google the manual

[deft hazel]

Tbh i js wanna know what it calculates and the formula

Do the manuals show what’s used?

It’s for question like this really

[obtuse pebble]

@deft hazel Has your question been resolved?

[obtuse pebble]

@deft hazel Has your question been resolved?

[glossy lily]

so i did work around the problem a bit more and came to my find my graph looking like this

i understand how piecewise functions work but graphing is my struggle atm

[viscid gull]

Hmm

I have no idea how the web assign graphic tool works tbh

Does it allow you to switch between black filled dots and unfilled dots?

Filled dots represent that an endpoint of a graph is part of the function

Unfilled dots represent that it's not part of the function

So if you see a less than sign without the equals

You'd want an unfilled dot

E. G.

(the dash doesn't need to be part of the graph I just drew it to help you realize that the dots have the same x value)

That would be the graph of a piece wise function where for - 1 <= x the graph is one line and for - 1 < x the graph is another line

another example

[obtuse pebble]

@deft hazel Has your question been resolved?

[royal basin]

the question asks how hermione knows her own hat color. and your thing doesn't sound quite right to me. but we should continue in #proofs-and-logic

[obtuse pebble]

@deft hazel Has your question been resolved?

[obtuse pebble]

@deft hazel Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[versed stratus]

How do I determine if the limit of $a_n$ exists here?

[warm shale]

physicsrocks

[sage geode]

Have you found the explicit formula for a_n yet?

[versed stratus]

Not really, just $2\int_0^n f(x+1) dx = \int_0^n f(x) dx$

[warm shale]

physicsrocks

[sage geode]

The fact that $f(x + k) = \frac1{2^k}f(x)$ should be trivial, so consider the following [ \int_0^n f(x) \dd{x} = \int_0^1f(x)\dd{x} + \int_1^2f(x)\dd{x} + \dots + \int_{n-1}^nf(x)\dd{x} ]

[warm shale]

A Lonely Bean

[sage geode]

(Hint: ||Substitute for x-1 in the second integral, x-2 for the third integral, and so on||)

[versed stratus]

I'm sorry, how's $f(x + k) = \frac1{2^k}f(x)$ s trivial?

[warm shale]

physicsrocks

[sage geode]

Thought you would immediately see why it's true

It's just a quick proof by induction

Holds for k = 1 by definition and f(x + k + 1) = 1/2 * f(x + k) = 1/2 * 1/2^k * f(x) = 1/2^(k + 1) * f(x)

[versed stratus]

ah, got it. Thanks!

.close

[obtuse pebble]

Channel closed

Closed by @versed stratus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[clever ginkgo]

HELP

?

[tacit scarab]

translate plz

[clever ginkgo]

oh sorry 😦 uh

yeah just a sec

[viral blade]

@brisk grove

[clever ginkgo]

determine if the 5=x is a solution of the equation

[river trout]

כמה ישראלים יש פה?

[tacit scarab]

just substitute x = 5 in

then check if left hand side = right hand side

[clever ginkgo]

ok

[brisk grove]

lol

i was too late

[obtuse pebble]

@clever ginkgo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tight vigil]

can someone tell me the difference between these two?

[tacit scarab]

I think proper and improper subsets

[timid silo]

the first states "B is a subset of A" the second states "B is a proper subset of A"

[tacit scarab]

where a proper subset couldn't be A

[timid silo]

it is common notation to have $\subsetne$ instead of $\subset$

[royal basin]

badtex

[royal basin]

(1) includes the possibility that B is equal to A while (2) does not

[tight vigil]

ahh okay that makes sense. But in that case, what does \subset mean then?

[royal basin]

$\subset$?

[warm shale]

Ann

[tight vigil]

yeah

[royal basin]

some authors (and especially older texts) use that to mean $\subseteq$

[warm shale]

Ann

[royal basin]

but some use it for $\subsetneq$

[warm shale]

Ann

[royal basin]

you have to look at the beginning of your text to see which it is

[tight vigil]

okay thanks for the help

[obtuse pebble]

@tight vigil Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rancid leaf]

why 1/n <= e is the same that n <= 1/e? I don't understand it

[tacit scarab]

for positive numbers a and b, a>b is equivalent to 1/a<1/b

[rancid leaf]

aaah

a = 1/n and b = e

thank you so much :3

.close

[obtuse pebble]

Channel closed

Closed by @rancid leaf

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty kiln]

Could I get a sense of direction for 3? Just a few words to get the brain moving

[tacit scarab]

what's the definition of dot product?

[misty kiln]

Shows whether or not vectors are orthogonal

[tacit scarab]

that's a property of dot product

not the definiton

[misty kiln]

Do you mean like

a_1b_1 +a_2b_2 + …

[tacit scarab]

yes

[misty kiln]

I’m thinking it has to be true because how else would you get the same number?

[tacit scarab]

hmm

it should be easier with the other definition

[misty kiln]

||a||cos(theta) ?

I don’t really know this one well

Norm(a)cos(theta)

[misty kiln]

Idk if I’m even right on this other one

[tacit scarab]

yes |a||b|costheta

[misty kiln]

That computes the dot product of a & b ?

[misty kiln]

Is this equal to something

[tacit scarab]

it equals the dot product

[misty kiln]

Right

[tacit scarab]

we have |a||b|costheta

=

|a||c|cosphi

[misty kiln]

What’s phi

[tacit scarab]

another greek alphabet to denote angle

[misty kiln]

Ok

[tacit scarab]

$\phi$

[warm shale]

WhereWolf

[tacit scarab]

so we have $|b|cos\theta_b=|c|cos\theta_c$

[misty kiln]

You divided the a cause both sides have?

[tacit scarab]

yes

notice that a vector can be any length and any angle

[misty kiln]

So theta doesn’t necessarily equal phi right?

[misty kiln]

Yes

[tacit scarab]

yep

[warm shale]

WhereWolf

[misty kiln]

Well if they can be any length or angle then b won’t have to equal c?

[tacit scarab]

yes

[misty kiln]

I see

Thank you

[obtuse pebble]

@misty kiln Has your question been resolved?

Channel closed

Closed by @misty kiln

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[idle patio]

So I did number 1 it’s just I can’t figure out number 2 and jus rlly don’t know where to start

[wanton hull]

$\frac{3 \times x}{4} -12$

[warm shale]

Bettim

[wanton hull]

sub in x=8

[idle patio]

Wait so I just multiply 3 by -5 then subtract it from 12?

[wanton hull]

not by 5

by 8

[idle patio]

Oh ok then once I do that it should be something like this

[slender nest]

yep

and you just do the math

[idle patio]

Aight thank you

.close

[obtuse pebble]

Channel closed

Closed by @idle patio

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vague mural]

Hey Im curious how to rotate a line by some amount of degrees
For example let's say I have the line y=x and I want to rotate it counterclockwise by 5 degrees, how would I do that?

[brisk grove]

Calculate the angle the line makes with the positive x axis, and use the tangent function to find the new slope

Also it depends where you're rotating from (which point stays fixed).
Use that point along with the new slope to find the line.

[vague mural]

I don't understand this, how would we use the tangent function to find the new slope

[brisk grove]

Do you know the definition of tan?

[vague mural]

sin/cos

so y/x

[brisk grove]

Yes

Which is exactly the slope.

[vague mural]

how would we find the new slope with it?

[brisk grove]

tan(angle)

[vague mural]

i dont understand

[brisk grove]

If the angle here is theta

then m = tan(theta)

[vague mural]

and thats our current slope right

[brisk grove]

Yes

But you can find the new angle

[vague mural]

so would we do tan(theta+5degree)

[brisk grove]

By taking the current slope, doing arctan(m) to find the current angle, adding 5 degrees, then taking tan() again

Yes

If you already know the current angle just add 5 degrees to it

[vague mural]

gotcha

alright ty

ill try that

[brisk grove]

No problem!

[vague mural]

.close

[obtuse pebble]

Channel closed

Closed by @vague mural

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis gate]

I need help understanding fractions. Specifically ones with unlike denominators.

[tacit scarab]

$\frac{1}{a}+\frac{1}{b}=\frac{b}{ab}+\frac{a}{ab}=\frac{b+a}{ab}$

[warm shale]

WhereWolf

[lapis gate]

I'm still confused

I don't want the specific answer but if I send the question I'm stuck on could I maybe get points on how to visualize it in my head or something?

straight up first grade style

[tacit scarab]

ok let's do $\frac{1}{2}+\frac{2}{3}$

[warm shale]

WhereWolf

[tacit scarab]

find the lowest common multiple of 2 and 3

[lapis gate]

NEVERMIND nevermind my sister helped me

thank you stay hydrated

[obtuse pebble]

@lapis gate Has your question been resolved?

[tardy epoch]

<@&268886789983436800> multiple channel troll

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[granite remnant]

The answer I got is on the top so my question is how do I graph it when the number doesn't fit the number line

[tacit scarab]

,rotate

[tacit scarab]

umm

draw a larger one

[granite remnant]

Can't it's from one of the questions from my assignment

.close

[obtuse pebble]

Channel closed

Closed by @granite remnant

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[balmy meteor]

How do I solve this problem?

[balmy meteor]

I have tried expanding it and u sub and I can’t figure it out

[hidden compass]

I would add and subtract 1 to the numerator firstly

[compact shadow]

Rational function it is, decompose it

[hidden compass]

So that you get x⁴ - 1 which has a factor (x² - 1) that make the denominator cancel

Sign apart

[compact shadow]

||-x^2-1+1/2(1+x)-1/2(x-1)||

[balmy meteor]

Alrighty let me try that really quick

Ok wait so how can you subtract 1 from the numerator without doing something to the denominator?

[hidden compass]

Add and subtract, not only subtract

Which is the same as adding 0, which of course doesn't affect the function

[balmy meteor]

Ooooh ok so that makes sense

Ok wait that is so cool, that makes it so much easier

[obtuse pebble]

@balmy meteor Has your question been resolved?

Channel closed

Closed by @balmy meteor

Use .reopen if this was a mistake.

[balmy meteor]

.reopen

[obtuse pebble]

✅

[balmy meteor]

Ok so I added and subtracted a 1 to the top and I crossed out the (x^2 - 1) which led me to the integral of -(x^2 + 2) dx

Which is the wrong answer I think

[hot spire]

i need help

!help

[obtuse pebble]

Please read #❓how-to-get-help

[balmy meteor]

I don’t understand how to simplify this

The integral of 1/(x^2 - 1)

I thought it would be arctangent

But it’s a negative number on the bottom so it can’t be arctan

<@&286206848099549185>

[timid silo]

WHY AM I A HELPER

BRO

okay

bruh

:hacker:

i mean

hey vsauce micheal here

my braincells are off

sorry

@balmy meteor

[balmy meteor]

Where are your fingers?

[obtuse pebble]

@balmy meteor Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusky bobcat]

Dumb question, possible quick answer

You drive 4 miles at 30mi/h and then another 4 miles at 5mi/h. What is the average speed?

I know it cant be equal to 40mi/hr even though 8 total was traveled because of the time difference of the 2 speeds, so I started to calculate it

t1 => d=s/t => 4mi= (30mi/hr)/t

t2 => d=s/t => 4mi= (50mi/hr)/t

for t1, the t needs to be 7.5
for t2, the t needs to be 12.5

[dusky bobcat]

So I did (total distance)/(total time), but my total time is in small denominations like 7.5 and 12.5

so it was just basically 8/19.5, which doesnt calculate to an mph

[brave bramble]

velocity = distance / time

[dusky bobcat]

yeah, avg velocity= total distance/total time

im thinking i messed up with calculating for time spent to do the 4mi for each, but i dont know how

4=30/x, x=30/4, x=7.5

[brave bramble]

You've scrambled them up

30 = 4/x

[dusky bobcat]

so, i started wrong at the beginning, ah

That was the only problem in my logic?

[brave bramble]

Ye otherwise your strategy will get you the right answer

[dusky bobcat]

so let me ask a quick few questions

in this I was trying to solve for time, but not TIME time

for velocity at that current section of time

All I needed was the time for it, so it would just be 4/30?

so in the future, to better help myself, just write it opposite of the box?

solution worked, thanks

.close

[obtuse pebble]

Channel closed

Closed by @dusky bobcat

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy musk]

how am I do this?

[polar fossil]

,tex .plane geom

[warm shale]

hayley!

[polar fossil]

use the formula for area of a rectangle

[worthy musk]

I have

I got x(1+sqrt(3)) = sqrt(12)

or x + x*sqrt(3) = 2*sqrt(3)

[polar fossil]

solve for x

[worthy musk]

how

[polar fossil]

same as usual

you've got $x(1+\sqrt3) = \sqrt{12}$

[warm shale]

hayley!

[polar fossil]

so divide

[worthy musk]

$1+\sqrt3 = \sqrt{12}/x$?

[warm shale]

panica5193

[polar fossil]

i mean that is true but

[worthy musk]

im not sure where to go from here

[polar fossil]

if you had $x\rsq = \bsq$

[warm shale]

hayley!

[polar fossil]

or like

$3x = 17$

[warm shale]

hayley!

[worthy musk]

oh

I divide both sides by (1+ sqrt(3))

[polar fossil]

yeah

[worthy musk]

it was a surd so that threw me off lmao

[polar fossil]

then rationalize the denominator

yeah surds are just numbers, got to remember that

[worthy musk]

yeah

always forget that

I thought I had to do some weird stuff with the surd

with expanding the bracket

wait, if I multiply with a surd like

$x\sqrt(y)$

thhen I just multiply either the x or the y term but not both

[warm shale]

panica5193

[worthy musk]

but if I were to square it, I'd square both terms

[polar fossil]

if you had like

[worthy musk]

so they count as seperate numbers

[polar fossil]

$(x\sqrt y) \cdot 3$ then yes it would be $3x\sqrt y$

[warm shale]

hayley!

[worthy musk]

and if I were to square it, I'd square both terms

[polar fossil]

yeah

[worthy musk]

weird

[polar fossil]

well i mean

[worthy musk]

they count as 2 numbers

[polar fossil]

it's just the same as any other product

like

,tex .exp rules

[warm shale]

hayley!

[polar fossil]

distributivityu

[worthy musk]

yeah

I just am noticing that they are seperate numbers not seperate ones

hm

wait what other rules commands does this have?

[polar fossil]

none built in, i added all of these myself

but yeah like $2\sqrt5 = 2\cdot \sqrt5$

[warm shale]

hayley!

[polar fossil]

that's all it means

[worthy musk]

oh okay

can you show me the other ones you've added?

im curious

[polar fossil]

hmm

,tex .log rules

[warm shale]

hayley!

[polar fossil]

,tex .plane geom

[warm shale]

hayley!

[polar fossil]

,tex .freshman

[warm shale]

hayley!

[worthy musk]

LMAO that one is funny

[polar fossil]

working on a 3d geometry equiivalent

for like volumes and surface areas

[worthy musk]

oooh

that's really nice

[polar fossil]

,tex .quadratic formula

[worthy musk]

these are all really cool

[warm shale]

hayley!

[polar fossil]

i didn't write all of these to be clear

i did write the geometry one

[worthy musk]

who did?

[polar fossil]

mostly someone named riemann i think

you'll see him around here sometimes, he's got a yellow name so he stands out

[worthy musk]

oh ok

[worthy musk]

is there a way I can stay updated when you do add more?

[polar fossil]

these are mostly for us to use when we're teaching / helping people

you can find all this elsewhere presented nicely as well

so like... there's nothing groundbreaking here :P

but if you want to follow the canonical source: https://github.com/riemann-discord/math-discord/blob/main/preamble.tex

oh i forgot i had this one too

,tex .cts

[warm shale]

hayley!

[polar fossil]

,tex .unit circle

[warm shale]

hayley!

[worthy musk]

ooh helpful

[worthy musk]

uhm I don't actually have anything for rendering tex

[polar fossil]

if you go to the repository root

it actually tells you how to set it up yourself

so that you can use these too

[worthy musk]

oh thanks

is that a list of all of them then?

[polar fossil]

you can add whatever you want to your own

like i had 2d geom for a couple weeks before everyone else had it

while i was testing it to see if it was useful (it was, very)