#help-10

1 messages · Page 214 of 1

drifting badger
#

Weird it says 'defined as' pandaHmm I had to prove that relation in my Analysis exam glassescat

kind hawk
#

how else do you define an integral along a curve

obtuse pebbleBOT
#

@shy solar Has your question been resolved?

obtuse pebbleBOT
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deep bane
obtuse pebbleBOT
deep bane
#

how to prove OPSM is cyclic

restive sage
#

Use Taylor's formula to find the linear and quadratic approximation of functions at origin
i. f(x, y) = x * e ^ y
ii. f(x, y) = sinxcosy
iii. f(x, y) = e ^ x * cos y
iv. f(x, y) = ysinx

wooden cipher
#

MOP is acute and MSP is right

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Cyclic quads should have opposute angles equal to 180

obtuse pebbleBOT
#

@deep bane Has your question been resolved?

deep bane
deep bane
obtuse pebbleBOT
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sour flume
#

Hey, I was wondering if I could get some help on mathematics because I’m starting school next month and I wanna get most of my math down, and gets some notes and pointers, I’m going to the 11th grade and I’m scared the score that I’m going to two kids have committed suicide

timber island
#

india?

kind hawk
#

ask an actual math question you need help with

candid yarrow
sour flume
#

Oh sorry

obtuse pebbleBOT
#

@sour flume Has your question been resolved?

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sacred root
#
The integer from 1 to 2023 are written on a blackboard. At each step,two randomly chosen numbers are erased and a new number equal to their difference is written on the board,making the total count of numbers on the board lesser by one.This process is repeated until there is only one number remaining.The question is remaining number is even or odd?
sacred root
#

Any idea how to do it?

candid yarrow
#

have you considered parity?

sacred root
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What is that?

candid yarrow
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the cases when even numbers are erased

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or one odd and one even

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or two odd

sacred root
#

Oh

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Alr

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So two even/odd numbers are selected then.....

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There difference will be even

wooden cipher
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Oh my god this is funny

sacred root
#

?

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The question?

wooden cipher
#

I chose this problem of the day in the math olympuad discord a while back

sacred root
#

Ohhh

sacred root
#

That's all I can conclude

kind hawk
#

try an example

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start with 1 to lets say 7

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how many odds and evens are there after every step

sacred root
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Well after each step there is 4 odd and 3 even

kind hawk
#

well you are getting less numbers so it cant always stay that way

wooden cipher
#

Nvm i lied

sacred root
#

1,3,5,7 ( 4 odd) 2,4,6 ( 3 even)

wooden cipher
#

But i do remember showing it to my friends

kind hawk
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yes thats at the start

sacred root
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👍

kind hawk
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now do a step

sacred root
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Wdym by step ?? Like jump to another number?

wooden cipher
#

What happens if at least one even is involved?

kind hawk
#

take two random numbers and replace them by their difference

sacred root
#

Alr

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1 2 3 4 5 6 7
Say (1,2)
1 3 4 5 6 7

wooden cipher
#

What happens when to the count of odds and evens when its (odd, even) or (even, even)?

kind hawk
wooden cipher
#

Ok sorry

#

It was my approach tbf, but i understand where youre coming from

sacred root
#

1 2 3 4 5 6 7
Say (1,2)
1 3 4 5 6 7

So here odd = 4 even = 2

If I take (4,6)

1 2 3 4 5 6 7
1 2 3 2 5 7

odd = 4 even = 2

#

So of the last number is odd, then only even number will change

So in the black board the number was upto 2023 so only number of even number will change

kind hawk
#

what happens if you take (1,5)

sacred root
#

1 2 3 4 5 6 7

1 3 4 4 7
even = 2 odd = 3

Hmm hmmCat

#

So

kind hawk
#

should be 2 3 4 4 6 7, so even=4 and odd=2

sacred root
candid yarrow
#

consider the parity of the sum of all the numbers before and after steps

sacred root
#

If both number are even then number of odd doesn't change but if both numbers are odd then number of odd changes 🤔

#

Alr

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1 2 3 4 5 6 7

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Let's say (1,2) is choosen so 1 3 4 5 6 7

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28-26=2

royal basin
royal basin
#

also what about using an even and an odd number?

sacred root
#

1 2 3 4 5 6 7
Say (1,2) ( even, odd)
1 3 4 5 6 7

So here odd = 4 even = 2

If I take (4,6) (even, even)

1 2 3 4 5 6 7
1 2 3 2 5 7

odd = 4 even = 2

Take (3,5) (odd, odd)

1 2 3 4 5 6 7
1 2 4 2 6 7

Even = 4, odd=2

royal basin
#

you are not executing it correctly when taking 3 and 5

sacred root
#

Yes I forgot that

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Sry

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From obv, we can see that if taken (even,even) then even changes by -1, taken (odd,odd) even change by +1 and taken (odd,even) even changes by -1

royal basin
#

you have managed to skillfully sidestep my question

kind hawk
#

and how does odd change in each case?

sacred root
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Well for EO and for EE it doesn't changes but for OO it changes by -2

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0 => odd, E => even

royal basin
#

incorrect

sacred root
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Now it's correct

royal basin
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ok good

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so the count of odd numbers on the board can only ever change by -2.

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this is significant. do you see how?

sacred root
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No

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OK wait I'll try myself

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I'll think for a bit

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Thanks

#

.close

obtuse pebbleBOT
#
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regal jewel
obtuse pebbleBOT
regal jewel
#

cant i use natrual log on this question

warm canopy
#

Why would you, if the question is asking for base 10

regal jewel
#

i mean if it wasn't base 10?

warm canopy
#

You can use whatever logs you want whenever you want

candid yarrow
obtuse pebbleBOT
#

@regal jewel Has your question been resolved?

obtuse pebbleBOT
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pale raft
#

1+1=2

obtuse pebbleBOT
#

Show your work, and if possible, explain where you are stuck.

civic socket
hot hazel
#

yeah pls dont abuse help channels

#

.close

obtuse pebbleBOT
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edgy needle
#

Hi

obtuse pebbleBOT
edgy needle
#

I need help with part B

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I wrote

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as axis of symmetry is 2 then it will take 2 more seconds to fall making it 4 seconds,

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But i think they want working

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Because it is 2 marks

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(Btw this is a practice question)

violet vine
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Find the x intercepts

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Then choose the positive one

edgy needle
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Ok wait

leaden ginkgo
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well you could give the diifference of both the roots as your answer, i think?

leaden ginkgo
#

hmmm

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because like

violet vine
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If u mean in the surd notation, then yes, otherwise I have no idea what u mean

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Yes. Technically you could, but it's not universal so I'd recommend just finding the x intercept, picking the further one and taking the x coordinate of it

edgy needle
#

i got roots...

violet vine
edgy needle
#

but the x intercepts arent roots

violet vine
#

I actually have no idea what the answer is lemme check lmao

violet vine
edgy needle
#

The scribbles are 256

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Omg nvm

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I see my mistake

violet vine
#

Well that sorts that out

edgy needle
#

Wait

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Is the only way i can figure this out

violet vine
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U should get 0 for the - and the answer for the +

edgy needle
#

Is by using quadratic formula

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Or can i factorise

violet vine
edgy needle
#

How can i factorise

violet vine
#

Wait factorise?

edgy needle
#

I tried non monic didnt work

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Yes

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And then use the null factor law

violet vine
#

U can do difference of squares

edgy needle
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I only know how to do that when its 2

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Not a trinomial

violet vine
#

One sec lemme check smth

edgy needle
#

Omg...

violet vine
#

(-2t+9)(2t+1) yes u can factorise

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U can use factorization, difference of squares or formula

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But formula is the most braindead so it's my go-to

edgy needle
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How do u do difference of squares

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In a trinomial?

violet vine
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There's a formula for it

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Wait shit

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Sorry not difference of squares

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I forgot the proper terminology

edgy needle
#

I can also do this way

violet vine
#

Complete the squares sorry

violet vine
edgy needle
#

How

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I got the right answer though

violet vine
#

-4t * -4t isn't -4t^2

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It's 16t^2

edgy needle
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Oh this isa different way

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Wait let me show u

violet vine
#

Interesting, never learned it

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But yes there are a ton of methods and u only need 1

edgy needle
#

Yeah lol a lot of people have said dat

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Yeah only my teacher uses it

violet vine
#

Anyway u got the right answer, congrats

edgy needle
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But then we divide both sides by -4t

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Nvm

violet vine
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Also the other intersection shouldnt be 0.5 I think

edgy needle
#

Oh i forgot the negative

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It's -0.5

violet vine
#

Yep

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Anyway if ur done u can do .close

edgy needle
#

Ok thanks

#

.close

obtuse pebbleBOT
#
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solemn pollen
#

I’m stuck on this question should I use integration by parts

timid silo
solemn pollen
sage geode
timid silo
#

Unsure. Doesn't sound possible without some advanced techniques

solemn pollen
#

Oh

solemn pollen
timid silo
#

Definitely misinterpreting something then?

kind hawk
#

maybe there is some smart u-sub coupled with trig properties which you gives you the same integral again?

timid silo
#

Any other context to this question?

solemn pollen
#

I’ll try doing the problem again from the beginning

solemn pollen
#

Evaluate the integral

timid silo
#

Oh I think I figured it out? @solemn pollen

sage geode
#

Oke I solved it

timid silo
#

You're on the right track with your attempt thonk

sage geode
#

Oh they definitely are

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I got smth similar

solemn pollen
#

That’s great what should I do now

sage geode
#

Oh wait my solution is missing smth

solar trellis
#

You could try u=pi/2 - x or u=2x

solemn pollen
#

This is the answer

solar trellis
#

Yea so the integral you're left with should be I

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After integrating the constant

solemn pollen
#

Oh yeaaa

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I think I’m getting it

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Yes

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Ur right

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Got it

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Thanks @solar trellis

solar trellis
#

Wl

solemn pollen
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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timid silo
obtuse pebbleBOT
timid silo
#

error here?

pseudo swift
#

what error do you see ?

timid silo
#

surely -1^2 should become +1 and make the denom 3x+14?

pseudo swift
#

nope

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(3x+13) - (1^2)

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that's how it should be read

timid silo
#

sigh ok. not sure when it's that way vs. the way i was thinking?

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the other way would be (3x+13)(-1^2)? or (3x+13)(-1)^2?

pseudo swift
#

not addition

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(3x + 13) + (-1)^2 if anything

timid silo
#

wait it should be subtraction

pseudo swift
timid silo
#

right right

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ok i think i see the confusion

#

thanks

pseudo swift
timid silo
#

!close

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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vernal cobalt
#

I need help with this math question

obtuse pebbleBOT
vernal cobalt
#

Wait

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I need to find it

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Ok

#

I got it

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@royal basin I got it finnaly

royal basin
#

why ping me

vernal cobalt
#

I

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Thought you were waiting for me?

royal basin
#

i was not

vernal cobalt
#

Oh

#

Do you know how to solve this?

royal basin
#

i probably do.

vernal cobalt
#

Can you help me?

royal basin
#

i could if i wanted to.

vernal cobalt
#

Please?

royal basin
#

i do not have the energy or patience.

vernal cobalt
#

Why not?

#

?

buoyant hatch
#

alr

#

what is the question

vernal cobalt
#

?

buoyant hatch
#

lemme try ig

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oh wtf

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lemme get pen and paper

royal basin
#

!nosols

obtuse pebbleBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

royal basin
#

saying this preemptively

buoyant hatch
#

alr i wont

buoyant hatch
#

u know how to integral calculus?

vernal cobalt
royal basin
#

i already said no.

vernal cobalt
#

Why not?

royal basin
#

do you want me to say it seventeen more times so that you get it?

vernal cobalt
#

Why not?

buoyant hatch
#

i need help with a ques

royal basin
#

@vernal cobalt i don't have the energy or patience to help you. asking "why not" about that is idiotic.

vernal cobalt
royal basin
#

you're not entitled to my help.

vernal cobalt
royal basin
royal basin
obtuse pebbleBOT
buoyant hatch
#

alr

#

dont mind

vernal cobalt
#

||that is polite||

brisk matrix
buoyant hatch
#

alr sorry sir

brisk matrix
vernal cobalt
#

So when can I get help

brisk matrix
#

be patient

#

if someone wants to help they will

#

but berating people for help doesn't make anyone want to help more

vernal cobalt
#

.close

obtuse pebbleBOT
#
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supple trail
#

I have sin²x × cos x and I want to find x by which the expression will be maximum. How to find it?
Remember we haven't studied any derivative!

violet sentinel
#

so analytically, what is the maximum of both sin and cos, separately? What is the maximum value for those functions alone?

supple trail
#

So if we have sin x , x should be 90

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And for cos x should be 0

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And max is 1

violet sentinel
#

yep exactly

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so what that tells us is that when sin(x) = 1, cos(x) = 0 and vice versa

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since we're multiplying sin^2(x)cos(x), then that means that at their individual maximum values, the function will equal 0

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so we know the max won't be 1

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(is the point)

supple trail
#

So put 30 = x
It equals to ¼ × ¾

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It isn't 0

violet sentinel
#

yep! Now the question is "is that the maximum"?

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I doubt it, 3/16 is fairly small 🙂

supple trail
#

Actually I calculated by graphing x = 54 but don't know what to do it myself

violet sentinel
#

wait where did you get x = 54?

supple trail
#

With geogebra I graphed it

violet sentinel
#

oh I see

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yeah that's the correct answer, lol

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is graphing allowed? Otherwise without deriviatives this will be somewhat difficutl

wild swallow
#

spoiler: it's not 54 degrees exactly

supple trail
violet sentinel
#

hmmm

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I'm thinking but tbh I'm stuck on where to go from here without derivatives

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one moment

wild swallow
#

do you know am-gm?

supple trail
#

What? No

wild swallow
#

okay do you know about cubic polynomials?

supple trail
#

Yeah

wild swallow
#

do you know that when they have a double root, then there is a turning point

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i.e. a local maximum/minimum

supple trail
#

Ok

wild swallow
#

use that fact, plus the pythagorean identity

supple trail
#

Cos x = sqrt3 / 3 right?

wild swallow
#

well yes

supple trail
#

Tnx 👍

#

.close

obtuse pebbleBOT
#
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placid smelt
#

Did they get root(2)/2 and root(3)/2 using special triangles? If so, how?

civic zealot
#

unit circle?

placid smelt
#

Is there a way to know without the unit circle?

civic zealot
#

the graph of cos(x) and some special points (the ones on the unit circle)
or using triangles i guess is also possible.

placid smelt
#

How would it done done using triangles?

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Because no special triangle has 2

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like root(2)/2 can't be seen from a special traingle as far as I know

civic zealot
#

pi/6 is 30 degrees
pi/4 is 45 degrees

placid smelt
#

ok but how do we know that a is 2 in this case

civic zealot
#

cos(x) = adj/hyp

placid smelt
#

ik that lol

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but how do we know a is 2

civic zealot
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a isn't 2

placid smelt
#

hmm

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if we look for cos(pi/6)

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we have Aroot(3)/2A

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which is root(3)/2

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which is right

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but

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for cos(pi/4)

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we have a/aroot(2)

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which isn't root(2)/2

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...?

civic zealot
#

now cancel the a and rationalize the denominator

placid smelt
#

well we have 1/sqrt(2)

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To rationalize I multiply by sqrt(2)/sqrt(2)?

civic zealot
#

yep

placid smelt
#

ahhh

#

tysm!

#

.close

obtuse pebbleBOT
#
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queen parcel
#

How do i simplify the first part of the intergral without a calculator?

kind hawk
#

u-sub

queen parcel
#

sorry i meant when i finish everything i get 68^(3/2)/18 - (4/9)

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is that the most i can simplify w/o a calculator

kind hawk
#

you could combine the fractions but not much more

queen parcel
#

also would that be right?

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im checking all my work again

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but im not so sure

kind hawk
#

you could just check with wolframalpha

queen parcel
#

for 68^3/2 its giving me 17sqrt(17)

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im kinda conflicted with the no calculator rule

polar fossil
#

\begin{align*}
\int_0^4 x^2\sqrt{4+x^3}\dd{x} &= \int \frac{\sqrt u}{3}\dd{u} \
&= \frac13\cdot \frac23 u^{\frac32} \
&= \left.\frac29(4+x^3)^{\frac32}\right|_0^4 \
&= \frac29(4+64) - \frac89 \
\end{align*}

warm shaleBOT
#

Hayley

kind hawk
#

!nosols etc

obtuse pebbleBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

polar fossil
#

i was mostly just checking because it looks like you might have moved the 2 somewhere it shouldn't be

#

you'll still end up with a sqrt17 in there somewhere though which is fine

queen parcel
#

how would i get to sqrt17 from

kind hawk
#

sqrt(68) = sqrt(4*17) = 2 sqrt(17)

queen parcel
#

thank you sm

obtuse pebbleBOT
#

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mental gulch
#

Hi i need help, ive to maximize a function subject to another function. Can someone help me? if they know economy might be better. But all help is well received

mental gulch
#

the axis x has q_1 and the axis y has q_2

#

this is how i reached to that anwser:

#

but thats not the way i should reach it

#

CPO means FOC

#

<@&286206848099549185>

obtuse pebbleBOT
#

@mental gulch Has your question been resolved?

mental gulch
#

<@&286206848099549185>

obtuse pebbleBOT
#

@mental gulch Has your question been resolved?

mental gulch
#

NO

#

😭

#

<@&286206848099549185> ?

obtuse pebbleBOT
#

@mental gulch Has your question been resolved?

mental gulch
#

/close

#

.close

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vagrant arch
#

can this be differenciated with product rule?

obtuse pebbleBOT
vagrant arch
#

if no, why?

#

OH SHIT MB

#

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silver flint
#

how do you find the related rate

obtuse pebbleBOT
silver flint
#

i know that da/dt = 6

#

and we need to find dr/dt when A = 9

teal turret
#

Yep

#

What’s formula do we use for area of circle

silver flint
#

so sorry could you give me like 5 mins

#

i think im onto something

#

thx

obtuse pebbleBOT
#

@silver flint Has your question been resolved?

silver flint
#

hey i figured it out stephen thanks btw

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ripe fiber
#

need help

obtuse pebbleBOT
ripe fiber
grizzled shore
#

What do you need help with?

ripe fiber
#

3,2 is A

grizzled shore
#

What is the distance formula?

ripe fiber
#

i dont know

#

thats why im asking

grizzled shore
#

Have you heard of the Pythagoras theorem

ripe fiber
#

yes

grizzled shore
#

Could you apply it here?

ripe fiber
#

yes

#

so its asking for hypotenus?

grizzled shore
#

Pretty much

#

That’s what distance is

#

Well, at this level at least

ripe fiber
#

this is grade 10 math

grizzled shore
#

Yeah

ripe fiber
#

ok thank you

#

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obtuse pebbleBOT
#
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grizzled shore
#

We call it Euclidean distance

obsidian wren
#

can you help me frost

obtuse pebbleBOT
#
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vagrant arch
#

can someone help identify what's the answer when 3(1-5x^3)^2(-15x^2) is differentiated

vagrant arch
#

the answer I'm getting is -450x^7-45x^4+90x I don't think it's right

brisk grove
#

what have you tried

#

show your work

high lily
#

ideally you'd leave the result in factored form

vagrant arch
#

this is the answer in the answer sheet

#

I just want to know if the answer sheet is right or not

urban patrol
#

,w differentiate 3(1-5x^3)^2(-15x^2)

vagrant arch
#

yes it is

urban patrol
#

,w calculate 90*25

urban patrol
#

yup

vagrant arch
#

hold on imma send a pic

#

holy shit I finally got it

#

.close

obtuse pebbleBOT
#
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high lily
#

notation crimes

obtuse pebbleBOT
#
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vagrant arch
#

what's a notation crime

obtuse pebbleBOT
high lily
#

extremely bad notation

vagrant arch
#

wym

high lily
#

your use of =

vagrant arch
#

wait is that it

plucky rivet
#

tell us what tan^(-2) (x) mean

vagrant arch
#

anything else

high lily
#

it's supposed to mean that it's equal to whatever is above
yet it isn't entirely clear when your taking derivatives etc

vagrant arch
#

oh yeah I'm aware of that

#

but I didn't plan to show it to anyone so that's why I did it that way

high lily
#

not recommended

vagrant arch
#

yeah I'll write the full thing if it's an exam

high lily
#

the work you do should reflect what you'd write in the test

vagrant arch
#

ok

high lily
#

don't get into bad habits

vagrant arch
#

yessir

#

dab me up

#

.close

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#
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timid silo
#

looking to quickly hop into a vc for a problem if that's cool

timid silo
#

it's complex analysis

candid yarrow
#

how about just here

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

.close

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orchid pine
obtuse pebbleBOT
orchid pine
#

Apologize for the glare

#

Can someone tell me what I’m missing on this?

#

The right limit is -5, how is this whole limit exist as 3

#

Better picture if needed

#

Better pic if needed

violet sentinel
#

not quite. Remember it's only -5 at a single point: where x = 1. Remember the limit represents what is approaching.

#

aka, the limit from the right side is not -5

orchid pine
#

But if x on the right side is equal to 1

runic void
#

that’s just a removable discontinuity you have

orchid pine
#

I haven’t gotten up to that yet 😦

violet sentinel
#

this is what your function looks like

#

if you notice, if you approach from the left or right side, the continuous function "approaches" the value of 3

#

even though at x = 1, it's equal to -5

orchid pine
#

Should I know this without plugging this into anywhere? Possibly stupid question

#

Like looking at what it looks like

#

Before answering

runic void
#

Limits are not what happens at the point x=a, it’s more of where the neighbourhood of x=a approaches

orchid pine
#

Yeah, I get that part

#

Maybe I’m just being too robotic by trying to just solve them and move through the test

runic void
#

Only way to get a sense of the limit value is to plug values closer to 1

orchid pine
#

Through a table right

runic void
#

0.99999 ish

orchid pine
#

Yeah yeah

runic void
#

or 1.000001

orchid pine
#

Ngl I was trying to avoid that

#

But I guess that really is the surefire way to see for real huh

#

I’m still a little confused on it though, as for what I should think when I see something like this next time

#

To me it looks like the whole right side is -5 and it doesn’t exist because the left is 3

runic void
#

any point in the right and left side of x=1 is determined by -x^2-2x+6

orchid pine
#

Why does this apply to the right

#

It doesn’t list it as applying to the right in f(x)

runic void
#

x not equal imply both directions

orchid pine
#

What

runic void
#

Think about it as a number line

runic void
#

notice the green dot below

orchid pine
#

Yeah

#

I just don’t fully understand why just because the left side isn’t when x=1 it’s implied it’s to both

#

That’s what’s in the answer description too I just don’t can’t find the reasoning for it

violet sentinel
#

This is how I imagine it

#

follow the function on both sides. Do they end up at the same destination (even if it doesn't exist)? Then the limit exists at that point

orchid pine
#

I feel so dumb

#

They would either cross?

#

I’m doing this without using any form of calculator

#

Is that bad

violet sentinel
#

so none of them cross

#

it's just where they meet. If they meet in the same spot (aka at f(1) = 3 in your example), then the general limit exists

#

here let me see if I can make some general explanations

orchid pine
orchid pine
#

I just don’t understand why the right side doesn’t equal -5

#

If that’s the only thing in the right limit

violet sentinel
#

consider this example:
The left hand limit at x = 4 is y = 5.
The right hand limit at x = 4 is y = -14.

So the left hand limit exists and the right hand limit exists. But the limit at x = 4 does not exist because the LH limit does not equal the RH limit

#

In this example:
The left hand limit at x = 4 is -14
The right hand limit at x = 4 is -14.

Since LH limit = RH limit, then the general limit exists because they both approach the same point

#

now here's the tricky question

orchid pine
#

Hit me

violet sentinel
#

This is similar to your problem. this is function where there's a discontinuity at x = 4. So the function is continuous except at x = 4

#

But since the LH limit approaches the open point and the RH limit approaches the open point (aka where x doesn't exist in the function), then the limit at x = 4 exists and is 11

orchid pine
#

So all it is is that one point?

#

OHHH

#

I think I understand

violet sentinel
#

great! 😄

orchid pine
#

So because only one side can logically exist there “it takes over” ?

#

Is that it? Or a bad way to think about it

#

Otherwise no limit would exist in where x would approach?

violet sentinel
#

not sure what you mean by that lol

#

okay let me try this

orchid pine
#

Which part

#

So basically

#

If there’s an area where the limit doesn’t exist on one side, but does on the other, the side where it does not exist is covered by the side that does?

#

Like where doc said it’s implied?

orchid pine
violet sentinel
#

I don't think that's quite correct.

#

hmmmm

#

okay let's consider this analogy

orchid pine
#

I appreciate you helping me with this

violet sentinel
#

imagine that there was a crazy rollercoaster where a cart from both sides can go on the same track at the same time.

orchid pine
#

Okay

violet sentinel
#

meaning that the rollercoaster as two ends, both ends contain a cart, the both launch at the same time, and they meet in the middle

orchid pine
#

Yup

violet sentinel
#

now imagine there's a gap/hole right where they would meet

orchid pine
#

Yep yep

violet sentinel
#

at the same time, they approach the hole.

#

ehhh nvm that's a bad analogy lol

#

I"m losing it

orchid pine
#

Nah I got it

#

Does the -5 fall in the hole while the 3 keeps going the same direction into the way where -5 was going

violet sentinel
#

I think I gotta head to bed, I'm tired lol

#

this video I think can help fill in any final gaps

orchid pine
#

Does it though???

violet sentinel
#

This calculus video tutorial explains how to identify points of discontinuity or to prove a function is continuous / discontinuous at a point by using the 3 step continuity test. This involves evaluating piecewise functions using one sided limits. The first step is to determine if the function is defined at the given point. The second step is...

▶ Play video
orchid pine
#

If the hole is the limit does the 3 keep going into the -5 lane that came from there or

#

Metaphorically speaking

violet sentinel
# violet sentinel https://tenor.com/view/cute-fingers-gif-20081440

what I mean is this. Basically a way to look at it is look at your limit point in question: take your left pointer finger, put it on the left side of the graph. Do the same with your right pointer finger on the right side of the graph. Start moving them to the point in question. Do they meet at the same place (even though this point may not actually exits in the function)? If so, then the limit exists. This is where the RH limit = LH limit

orchid pine
#

Awesome okay gotcha

#

Thank you so much mellow drama llama

#

Have a fantastic night and thank you again 🙏🏻

violet sentinel
#

yeah no worries. Hopefully this was helpful! Take care

orchid pine
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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silver nova
#

hi,
the blue line is f(x) = sqrt(x) +2,
the green line is g(x) = - sqrt (x) +2
the red line is y=x^2-4x+4
and the area within these graphs is 9

silver nova
#

i was having trouble with this quetion, this was the answer

#

but i dont understand what they did

#

this was the question

obtuse pebbleBOT
#

@silver nova Has your question been resolved?

obtuse pebbleBOT
#

@silver nova Has your question been resolved?

viral blade
# silver nova

They calculated the area above the line in terms of d and set it equal to half the total area

obtuse pebbleBOT
#

@silver nova Has your question been resolved?

silver nova
viral blade
#

both of them start at the point the horizontal line intersects the graph and end at 4

silver nova
#

ohh i see thank you very much

#

.close

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#
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forest tide
#

Can anyone help me with 22 pls

obtuse pebbleBOT
#

@forest tide Has your question been resolved?

runic void
#

what are i,j,k in 3 space?

#

@forest tide

obtuse pebbleBOT
#
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deft sun
#

G is a planar graph with 5 nodes G = (V,E)
H is a non planar graph with 6 nodes that is made by adding 1 node to G with a degree of 2
prove that H is Eulerian

deft sun
#

I know that H contains K5

#

and G has no more than 9 edges

royal basin
#

hold on

forest tide
royal basin
#

how do you know H contains K5 and not K3,3

royal basin
# forest tide Hii

you were gone for too long and your channel timed out. you will have to open a new one, sorry.

forest tide
#

Ohkk

royal basin
#

no, you cannot reopen a channel opened by somebody else.

forest tide
#

Ok sry

royal basin
deft sun
#

I think so

#

sorry for the bad translation

deft sun
#

which rules k3,3 out

royal basin
#

ah wait ok youre right

#

alright

#

so then hm

#

doesnt this mean H can only look like this

#

oh wait no not necessarily

deft sun
#

but this is impossible

#

becuase k5 is not planar

royal basin
#

yeah but H is also nonplanar?

#

ok wait hold up

#

we could have this

deft sun
#

But G is

royal basin
#

with 6 being the new vertex

#

if we excise vertex 6 from that is the rest planar

#

ok yeah it is

deft sun
#

oh I see

#

we still need to prove that H is Eulerian

deft sun
royal basin
#

i have a feeling that theres only one thing G can be

#

like how else are you gonna have a 6-vertex H with a K5 minor

#

i dont think there any options for that other than the two i showed

deft sun
#

yeah right

royal basin
#

is that a "ok yeah i got you" or "no way that's true"

deft sun
#

haha

#

I get it but I would still like to prove it becuase its good practice for me WanWan

#

but I could do that later

#

of its a problem

royal basin
#

i mean "G is determined uniquely up to iso" is proof enough imo

#

or H

#

H has to contain a K5 minor, and since H has 6 nodes total, this means either it has a genunie K5 subgraph or it's this

#

we could "insert" vertex 6 into any of those edges but it doesnt matter bc iso

deft sun
#

it is a good proof
I think lets try to continue and I might try to find a different (equaly correct) proof later

#

wait we can just count

#

and see that all nodes have an even degree

#

which proves it

royal basin
#

or you could do this

#

which proves it in an even more undisputable way

deft sun
#

oh nice

#

you see like this proof is perfect but I feel like my teacher wanted us to solve it in a different way akabeko

#

but either way thanks for helping me catbread

#

if we have 10 or more and 11 or less edges that means we have 20 or 22 sum of degrees

we have 5x4 and that means the last one is 2 which means they are all even

#

is this any good?

royal basin
#

nyeh?

#

not sure

deft sun
#

eh and I also need to prove its Hamiltonian

royal basin
deft sun
#

ye

royal basin
#

honestly i love picture proofs like this

#

which cannot be argued against

deft sun
#

true but they take a bit of creativity and are not always possible

#

and I could easly use it incorrectly

#

thats why the long boring proofs are better for me

#

I tried to redo my proof I hope it came out ok

royal basin
#

how could you possibly fuck up proving that a graph is hami by DRAWING a hami path on it

deft sun
#

hahahazha

#

I dunno drawing is kinda difficult

#

becuase H contains k5 or a (i dunno how its called in english)
it must have 5 nodes with a degree of 4 and we know the node we added isnt one of these becuase it has the degree of 2
so the degrees are 4,4,4,4,2 which proves it

#

I feel like this is better

#

I will try to do hami now whatcanisay

#

Ore's theorem works here right?

royal basin
#

dunno

#

i don't have much patience for fancy theorems when constructive proof go brrr

deft sun
#

ok ok I have one last thing I need to find

#

the number of Faces

#

thanks for you help Ann
sorry for being annoying fishthonk

#

.close

obtuse pebbleBOT
#
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hallow olive
obtuse pebbleBOT
hallow olive
#

How do I solve this?

#

When solving I got

(x-3/(x+2)

#

And the questuon asked which is NOT a vertical asymptote

high lily
#

,rotate

warm shaleBOT
high lily
#

can you show your work

hallow olive
#

That's how I solved it

high lily
#

you didn't factorise x^2 +2x - 3 correctly

hallow olive
#

My bad

#

Thanks

#

.close

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#
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umbral nest
#

how is root 2 / 2 equals to 1/ root 2

obtuse pebbleBOT
gaunt tiger
#

sqrt(2)/2 = sqrt(2)/(sqrt(2)*sqrt(2)) = 1/sqrt(2)

prisma hatch
#

$\frac{\sqrt {2}}{2}=\frac{\sqrt {2}}{\sqrt {2}\sqrt {2}}$

royal basin
#

$\frac{\sqrt{2}}{2} = \frac{\sqrt{2}}{\sqrt{2} \cdot \sqrt{2}} = \frac{1}{\sqrt{2}}$

warm shaleBOT
umbral nest
#

ohh makes sense!

warm shaleBOT
#

pro_hecker_pj

umbral nest
#

thank youu

#

amazing ppl

#

.close

obtuse pebbleBOT
#
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steady parcel
#

can some1 help me factorise this?

obtuse pebbleBOT
steady parcel
#

15x + y - xy - 15

balmy mortar
#

!status

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
high lily
#

consider factorisation by grouping

steady parcel
#

yh when i group there r no common factors

royal basin
#

what are you grouping with what?

steady parcel
#

15x + y - xy - 15

balmy mortar
steady parcel
#

factorization

#

ooo

high lily
#

you've just reposted the question

steady parcel
#

i tried doing this (15x + y) - (xy - 15) and bringing out the common factors

steady parcel
high lily
#

not by itself when being asked to show work

steady parcel
#

o

high lily
#

as that's no indication of having done anything

balmy mortar
steady parcel
#

ok

high lily
#

also you didn't actually factor out the - properly

steady parcel
balmy mortar
high lily
#

$-p-q \redneq -(p-q)$

balmy mortar
#

no one can help

warm shaleBOT
#

ℝamonov

balmy mortar
#

yeah lets first resolve this issue

#

you need to be able to factor properly

steady parcel
#

i tried (15x - xy) - (15 + y)

high lily
#

grouping like that, the (15x+xy) can be factorised

steady parcel
#

yh but wat abt the second 1

high lily
#

well you can leave that as is for now

#

what do you have after factoring the (15x+xy)

steady parcel
#

u get x(15 + y)

#

ooooo

#

bruh its (15x - xy)

#

.close

obtuse pebbleBOT
#
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autumn kiln
obtuse pebbleBOT
pine sail
#

!status

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
autumn kiln
pine sail
#

Try having only a base of 3.

warm shaleBOT
#

! What the hell am I doing here?

autumn kiln
pine sail
#

It's wrong.

#

Somewhat.

autumn kiln
#

oh I forgot the 1/

pine sail
#

Yes.

autumn kiln
#

The fraction part for the second bit

pine sail
#

Yes, now for the 1/that term

#

You can multiply both sides by that term.

autumn kiln
novel grotto
#

ah but

#

one of these solutions needs to be rejected

#

whcih one and why

autumn kiln
autumn kiln
# autumn kiln

Actually it doesn’t work in this equation either bc the rhs will be log(-2)

#

thanks guys👍

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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zealous hornet
obtuse pebbleBOT
zealous hornet
#

where do i begin with this question

jagged falcon
#

What's the surface area of a cylinder?

zealous hornet
#

2pirh +2pir^2

timid silo
#

h = 2r

jagged falcon
#

And do you know the relation between h at r here?

royal basin
#

@timid silo was better to let op discover that himself

#

now youve robbed him of that opportunity

timid silo
#

alr

zealous hornet
#

i already knew h =2r but idk where i go from there after subtituting values

timid silo
fiery cairn
#

.reopen

jagged falcon
#

Yeah, so you get 6pir^2=314whatever. Can you solve for r?

#

What? They said they don't know where to go AFTER substituting values, so they already have this equation

obtuse pebbleBOT
#

@zealous hornet Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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shell moth
obtuse pebbleBOT
shell moth
#

Can't I use this to solve the above problem

#

Because I tried doing it and got the wrong answer

knotty crow
#

show your work if possible

shell moth
#

Wait

#

As i was rewriting it to take a picture

#

I found a mistake

#

That's prolly what I messed up

#

@knotty crow

#

It's right thus far no?

#

First time I'm ever using that formula so just making sure ig

knotty crow
#

seems good

#

now just solve for the limit of the exponent

shell moth
#

Yeh multiplied it by the conjugate and it gave me the right thing

#

Noice

#

Thanks

#

.close

obtuse pebbleBOT
#
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timid silo
#

Hi! I've been trying to do this question for a quiz on trigometric derivatives, and I'm not exactly sure where to start. It wants me to find an "equivalent expression" though I'm not sure how. I don't know if there is some way to factor this or if there is some rule I missed- I tried deriving it but the denominator remains as pi-pi=0. Thanks! https://i.imgur.com/xBFgp4i.png

pseudo swift
#

trigometric derivatives

#

you said it yourself

knotty crow
#

Do you mean you have used l'Hospital?

pseudo swift
#

looks oddly like a derivative

timid silo
polar fossil
#

,tex .sum diff trig

knotty crow
#

Definition

timid silo
warm shaleBOT
#

Hayley

polar fossil
#

do you know these?

timid silo
polar fossil
#

oh those won't help you nvm

timid silo
fierce lagoon
#

We don't provide help with quizzes or tests

timid silo
#

:(

wise talon
#

first definition is only true if f is defined on an interval sotrue (or all of R)

polar fossil
#

all of R is an interval

jagged falcon
timid silo
#

OH okay I had to use a bit of my big boy brain- I was tryna think forward when I had to think in reverse that the equation literally just represents the derivative of sin(pi) which is just cos(pi)- I knew it was simple and I was just overthinking it lmao. Thanks everyone for your help!

#

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obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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final lily
#

This is the PMF of Poisson Binomial distribution. anyone here know a way to calculate CDF of Poisson Binomial distribution without needing to calculate all the probability one by one? because this is compute expensive

final lily
#

This is the CDF

#

I can find the mean, the STDEV, and the Variance

#

uh... are my question clear?

#

I just want a more efficient way to calculate the CDF, maybe anyone know another way to calculate the CDF?

#

there is also another formula in that Poisson Binomial Wiki, it use Fourier Transform so it's should be more efficient, but I don't even know if this is CDF or PMF, there is also many symbol that I don't understand there

polar fossil
final lily
#

ah... I see....

final lily
#

anyone? OhNo_cat

#

<@&286206848099549185> help please pandaWow

bold carbon
#

bro what is that lmao

final lily
#

it's Poisson Binomial distribution

#

should I post the wiki link here?

bold carbon
#

i see

#

im not sure i can help u lmao

#

that looks really tough

polar fossil
final lily
bold carbon
#

i see

#

gl

final lily
bold carbon
#

what class is this

#

i see its more or less a stats topic

#

since its a type of probability distribution

#

lmao i feel so dumb

final lily
#

I need this, not because of studying...

#

which is why I'm still searching away even after month sadcat

bold carbon
#

i see

final lily
#

I don't know I found this on random place on internet, I don't even remember where

bold carbon
#

i see

#

alr bye

final lily
#

okay sad

obtuse pebbleBOT
#

@final lily Has your question been resolved?

obtuse pebbleBOT
#

@final lily Has your question been resolved?

obtuse pebbleBOT
#
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timid silo
#

is the norm of this partition -1.1 or +1.1?

obtuse pebbleBOT
kind hawk
#

not sure what the norm of a partition is, but usually norms are non-negative (just from the word alone)

#

I guess largest length of subinterval?

timid silo
#

yes

#

I wasn't sure how it is noted

kind hawk
#

then +1.1

#

lengths are also non-negative

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
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long hedge
#

how did ln 2 get on top

obtuse pebbleBOT
errant lark
long hedge
#

yes

errant lark
#

They have just divided both the sides with 12*ln(1+0.5/12).

errant lark
#

so that they could separate variable t to the one side.

errant lark
obtuse pebbleBOT
#

@long hedge Has your question been resolved?

obtuse pebbleBOT
#
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woeful folio
obtuse pebbleBOT
silent thorn
#

thats the easiest way

#

or you can get the maxima and minima of the function and graph it like that

woeful folio
#

So like when x =3 then I put three into the equation to get y

silent thorn
#

yes

woeful folio
#

But it isn’t labelled

silent thorn
#

thats fine, it doesnt have to be perfect

#

just draw a rough picture

woeful folio
#

Complete the square to get points of rotation?

silent thorn
#

you can use the cubic formula, but its super long and messy

#

as i said, just use points

#

it saves you the hassle

woeful folio
#

Wait bro I got a solution

#

Let me find y

#

So let x=0

silent thorn
#

y=1

woeful folio
#

So it will intersect y axis at 1

#

Can’t I complete the square and get rotation points?

silent thorn
#

you mean like critical points?

woeful folio
#

Where it rotates bro

silent thorn
#

those are called critical points, you gotta differentiate the function