#help-10
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how else do you define an integral along a curve
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how to prove OPSM is cyclic
Use Taylor's formula to find the linear and quadratic approximation of functions at origin
i. f(x, y) = x * e ^ y
ii. f(x, y) = sinxcosy
iii. f(x, y) = e ^ x * cos y
iv. f(x, y) = ysinx
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Im not convinced it is
MOP is acute and MSP is right
Cyclic quads should have opposute angles equal to 180
@deep bane Has your question been resolved?
MSO is right
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Hey, I was wondering if I could get some help on mathematics because I’m starting school next month and I wanna get most of my math down, and gets some notes and pointers, I’m going to the 11th grade and I’m scared the score that I’m going to two kids have committed suicide
india?
....
ask an actual math question you need help with
We can help you if you have any homework questions you’re stuck on, feel free to ask
Oh sorry
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The integer from 1 to 2023 are written on a blackboard. At each step,two randomly chosen numbers are erased and a new number equal to their difference is written on the board,making the total count of numbers on the board lesser by one.This process is repeated until there is only one number remaining.The question is remaining number is even or odd?
Any idea how to do it?
have you considered parity?
What is that?
Oh
Alr
So two even/odd numbers are selected then.....
There difference will be even
Oh my god this is funny
I chose this problem of the day in the math olympuad discord a while back
Ohhh
If I choose one odd and one even then the difference will be odd
That's all I can conclude
try an example
start with 1 to lets say 7
how many odds and evens are there after every step
Well after each step there is 4 odd and 3 even
well you are getting less numbers so it cant always stay that way
Nvm i lied
1,3,5,7 ( 4 odd) 2,4,6 ( 3 even)
But i do remember showing it to my friends
yes thats at the start
👍
now do a step
Wdym by step ?? Like jump to another number?
What happens if at least one even is involved?
take two random numbers and replace them by their difference
What happens when to the count of odds and evens when its (odd, even) or (even, even)?
let them experiment before going at it from a more abstract perspective
1 2 3 4 5 6 7
Say (1,2)
1 3 4 5 6 7
So here odd = 4 even = 2
If I take (4,6)
1 2 3 4 5 6 7
1 2 3 2 5 7
odd = 4 even = 2
So of the last number is odd, then only even number will change
So in the black board the number was upto 2023 so only number of even number will change
what happens if you take (1,5)
should be 2 3 4 4 6 7, so even=4 and odd=2

consider the parity of the sum of all the numbers before and after steps
If both number are even then number of odd doesn't change but if both numbers are odd then number of odd changes 🤔
Alr
1 2 3 4 5 6 7
Let's say (1,2) is choosen so 1 3 4 5 6 7
28-26=2

it will help to think about this in more detail. how much does the count of odd numbers on the board change if you use two odd numbers?
also what about using an even and an odd number?
1 2 3 4 5 6 7
Say (1,2) ( even, odd)
1 3 4 5 6 7
So here odd = 4 even = 2
If I take (4,6) (even, even)
1 2 3 4 5 6 7
1 2 3 2 5 7
odd = 4 even = 2
Take (3,5) (odd, odd)
1 2 3 4 5 6 7
1 2 4 2 6 7
Even = 4, odd=2
you are not executing it correctly when taking 3 and 5
Yes I forgot that
Sry
From obv, we can see that if taken (even,even) then even changes by -1, taken (odd,odd) even change by +1 and taken (odd,even) even changes by -1
you have managed to skillfully sidestep my question
and how does odd change in each case?
Well for EO and for EE it doesn't changes but for OO it changes by -2
0 => odd, E => even
incorrect
Now it's correct
ok good
so the count of odd numbers on the board can only ever change by -2.
this is significant. do you see how?
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cant i use natrual log on this question
Why would you, if the question is asking for base 10
i mean if it wasn't base 10?
You can use whatever logs you want whenever you want
yes, try it
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1+1=2
<@&268886789983436800>
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Hi
I need help with part B
I wrote
as axis of symmetry is 2 then it will take 2 more seconds to fall making it 4 seconds,
But i think they want working
Because it is 2 marks
(Btw this is a practice question)
Ok wait
well you could give the diifference of both the roots as your answer, i think?
Not sure about that
If u mean in the surd notation, then yes, otherwise I have no idea what u mean
Yes. Technically you could, but it's not universal so I'd recommend just finding the x intercept, picking the further one and taking the x coordinate of it
i got roots...
That works (sorry no it doesn't, unless it's an unsimplified then...)
but the x intercepts arent roots
I actually have no idea what the answer is lemme check lmao
Show the working
Well that sorts that out
U should get 0 for the - and the answer for the +
Yes
How can i factorise
Wait factorise?
U can do difference of squares
One sec lemme check smth
Omg...
(-2t+9)(2t+1) yes u can factorise
U can use factorization, difference of squares or formula
But formula is the most braindead so it's my go-to
There's a formula for it
Wait shit
Sorry not difference of squares
I forgot the proper terminology
Complete the squares sorry
That's uhm wrong
Anyway u got the right answer, congrats
Also the other intersection shouldnt be 0.5 I think
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I’m stuck on this question should I use integration by parts
There is no elementary antiderivative to this function first of all
So how should I proceed?
Well the indefinite integral here is -0.5 pi ln(2) apparently
Unsure. Doesn't sound possible without some advanced techniques
Oh
I mean it’s Highschool level math :((
Definitely misinterpreting something then?
maybe there is some smart u-sub coupled with trig properties which you gives you the same integral again?
Any other context to this question?
I’ll try doing the problem again from the beginning
Nope just that
Evaluate the integral
Oh I think I figured it out? @solemn pollen
Oke I solved it
You're on the right track with your attempt 
That’s great what should I do now
Oh wait my solution is missing smth
You could try u=pi/2 - x or u=2x
This is the answer
Wl
.close
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error here?
what error do you see ?
surely -1^2 should become +1 and make the denom 3x+14?
sigh ok. not sure when it's that way vs. the way i was thinking?
the other way would be (3x+13)(-1^2)? or (3x+13)(-1)^2?
that would be multiplication the way you wrote it
not addition
(3x + 13) + (-1)^2 if anything
wait it should be subtraction
there's no substraction here either
it's about the order of operations, you compute powers first, then multiplications/divisions, then additions/substractions
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I need help with this math question
why ping me
i was not
i probably do.
Can you help me?
i could if i wanted to.
Please?
i do not have the energy or patience.
?
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
saying this preemptively
alr i wont
Can you help?
i already said no.
Why not?
do you want me to say it seventeen more times so that you get it?
Why not?
u know integral calculus?
i need help with a ques
@vernal cobalt i don't have the energy or patience to help you. asking "why not" about that is idiotic.
Can you help me tomorrow then ?
BRUV ERSPOND TO ME PLEASE
you're not entitled to my help.
Why?
and neither are you.
!volunteers
Helpers are just people volunteering their time to help you. Be polite.
please don't advertise your questions in other channels
alr sorry sir
its impolite to repeatedly ask for something after clearly being told no
So when can I get help
be patient
if someone wants to help they will
but berating people for help doesn't make anyone want to help more
.close
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I have sin²x × cos x and I want to find x by which the expression will be maximum. How to find it?
Remember we haven't studied any derivative!
so analytically, what is the maximum of both sin and cos, separately? What is the maximum value for those functions alone?
yep exactly
so what that tells us is that when sin(x) = 1, cos(x) = 0 and vice versa
since we're multiplying sin^2(x)cos(x), then that means that at their individual maximum values, the function will equal 0
so we know the max won't be 1
(is the point)
yep! Now the question is "is that the maximum"?
I doubt it, 3/16 is fairly small 🙂
Actually I calculated by graphing x = 54 but don't know what to do it myself
wait where did you get x = 54?
With geogebra I graphed it
oh I see
yeah that's the correct answer, lol
is graphing allowed? Otherwise without deriviatives this will be somewhat difficutl
Absolutely not
spoiler: it's not 54 degrees exactly
Approximately
hmmm
I'm thinking but tbh I'm stuck on where to go from here without derivatives
one moment
do you know am-gm?
What? No
okay do you know about cubic polynomials?
Yeah
do you know that when they have a double root, then there is a turning point
i.e. a local maximum/minimum
Ok
use that fact, plus the pythagorean identity
Cos x = sqrt3 / 3 right?
well yes
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Did they get root(2)/2 and root(3)/2 using special triangles? If so, how?
unit circle?
Is there a way to know without the unit circle?
the graph of cos(x) and some special points (the ones on the unit circle)
or using triangles i guess is also possible.
How would it done done using triangles?
Because no special triangle has 2
like root(2)/2 can't be seen from a special traingle as far as I know
ok but how do we know that a is 2 in this case
cos(x) = adj/hyp
a isn't 2
hmm
if we look for cos(pi/6)
we have Aroot(3)/2A
which is root(3)/2
which is right
but
for cos(pi/4)
we have a/aroot(2)
which isn't root(2)/2
...?
now cancel the a and rationalize the denominator
yep
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How do i simplify the first part of the intergral without a calculator?
u-sub
sorry i meant when i finish everything i get 68^(3/2)/18 - (4/9)
is that the most i can simplify w/o a calculator
you could combine the fractions but not much more
you could just check with wolframalpha
for 68^3/2 its giving me 17sqrt(17)
im kinda conflicted with the no calculator rule
\begin{align*}
\int_0^4 x^2\sqrt{4+x^3}\dd{x} &= \int \frac{\sqrt u}{3}\dd{u} \
&= \frac13\cdot \frac23 u^{\frac32} \
&= \left.\frac29(4+x^3)^{\frac32}\right|_0^4 \
&= \frac29(4+64) - \frac89 \
\end{align*}
Hayley
!nosols etc
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
i was mostly just checking because it looks like you might have moved the 2 somewhere it shouldn't be
you'll still end up with a sqrt17 in there somewhere though which is fine
how would i get to sqrt17 from
sqrt(68) = sqrt(4*17) = 2 sqrt(17)
thank you sm
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Hi i need help, ive to maximize a function subject to another function. Can someone help me? if they know economy might be better. But all help is well received
the axis x has q_1 and the axis y has q_2
this is how i reached to that anwser:
but thats not the way i should reach it
CPO means FOC
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@mental gulch Has your question been resolved?
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@mental gulch Has your question been resolved?
@mental gulch Has your question been resolved?
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can this be differenciated with product rule?
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how do you find the related rate
@silver flint Has your question been resolved?
hey i figured it out stephen thanks btw
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need help
What do you need help with?
What is the distance formula?
Have you heard of the Pythagoras theorem
yes
Could you apply it here?
this is grade 10 math
Yeah
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We call it Euclidean distance
can you help me frost
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can someone help identify what's the answer when 3(1-5x^3)^2(-15x^2) is differentiated
the answer I'm getting is -450x^7-45x^4+90x I don't think it's right
ideally you'd leave the result in factored form
this is the answer in the answer sheet
I just want to know if the answer sheet is right or not
,w differentiate 3(1-5x^3)^2(-15x^2)
yes it is
,w calculate 90*25
yup
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notation crimes
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what's a notation crime
extremely bad notation
wym
your use of =
wait is that it
tell us what tan^(-2) (x) mean
anything else
it's supposed to mean that it's equal to whatever is above
yet it isn't entirely clear when your taking derivatives etc
oh yeah I'm aware of that
but I didn't plan to show it to anyone so that's why I did it that way
not recommended
yeah I'll write the full thing if it's an exam
the work you do should reflect what you'd write in the test
ok
don't get into bad habits
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looking to quickly hop into a vc for a problem if that's cool
it's complex analysis
how about just here
@timid silo Has your question been resolved?
.close
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Apologize for the glare
Can someone tell me what I’m missing on this?
The right limit is -5, how is this whole limit exist as 3
Better picture if needed
Better pic if needed
not quite. Remember it's only -5 at a single point: where x = 1. Remember the limit represents what is approaching.
aka, the limit from the right side is not -5
But if x on the right side is equal to 1
that’s just a removable discontinuity you have
I haven’t gotten up to that yet 😦
no it only equals -5 at one single point
this is what your function looks like
if you notice, if you approach from the left or right side, the continuous function "approaches" the value of 3
even though at x = 1, it's equal to -5
Should I know this without plugging this into anywhere? Possibly stupid question
Like looking at what it looks like
Before answering
Limits are not what happens at the point x=a, it’s more of where the neighbourhood of x=a approaches
Yeah, I get that part
Maybe I’m just being too robotic by trying to just solve them and move through the test
Only way to get a sense of the limit value is to plug values closer to 1
Through a table right
0.99999 ish
Yeah yeah
or 1.000001
Ngl I was trying to avoid that
But I guess that really is the surefire way to see for real huh
I’m still a little confused on it though, as for what I should think when I see something like this next time
To me it looks like the whole right side is -5 and it doesn’t exist because the left is 3
any point in the right and left side of x=1 is determined by -x^2-2x+6
Why does this apply to the right
It doesn’t list it as applying to the right in f(x)
x not equal imply both directions
What
Think about it as a number line
Yeah
I just don’t fully understand why just because the left side isn’t when x=1 it’s implied it’s to both
That’s what’s in the answer description too I just don’t can’t find the reasoning for it
This is how I imagine it
follow the function on both sides. Do they end up at the same destination (even if it doesn't exist)? Then the limit exists at that point
I feel so dumb
They would either cross?
I’m doing this without using any form of calculator
Is that bad
so none of them cross
it's just where they meet. If they meet in the same spot (aka at f(1) = 3 in your example), then the general limit exists
here let me see if I can make some general explanations
I worded that poorly 😖
Okay yeah that part I get
I just don’t understand why the right side doesn’t equal -5
If that’s the only thing in the right limit
consider this example:
The left hand limit at x = 4 is y = 5.
The right hand limit at x = 4 is y = -14.
So the left hand limit exists and the right hand limit exists. But the limit at x = 4 does not exist because the LH limit does not equal the RH limit
In this example:
The left hand limit at x = 4 is -14
The right hand limit at x = 4 is -14.
Since LH limit = RH limit, then the general limit exists because they both approach the same point
now here's the tricky question
Hit me
This is similar to your problem. this is function where there's a discontinuity at x = 4. So the function is continuous except at x = 4
But since the LH limit approaches the open point and the RH limit approaches the open point (aka where x doesn't exist in the function), then the limit at x = 4 exists and is 11
great! 😄
So because only one side can logically exist there “it takes over” ?
Is that it? Or a bad way to think about it
Otherwise no limit would exist in where x would approach?
Which part
So basically
If there’s an area where the limit doesn’t exist on one side, but does on the other, the side where it does not exist is covered by the side that does?
Like where doc said it’s implied?
^ ?
I appreciate you helping me with this
imagine that there was a crazy rollercoaster where a cart from both sides can go on the same track at the same time.
Okay
meaning that the rollercoaster as two ends, both ends contain a cart, the both launch at the same time, and they meet in the middle
Yup
now imagine there's a gap/hole right where they would meet
Yep yep
at the same time, they approach the hole.
ehhh nvm that's a bad analogy lol
I"m losing it
Nah I got it
Does the -5 fall in the hole while the 3 keeps going the same direction into the way where -5 was going
I think I gotta head to bed, I'm tired lol
this video I think can help fill in any final gaps
Does it though???
This calculus video tutorial explains how to identify points of discontinuity or to prove a function is continuous / discontinuous at a point by using the 3 step continuity test. This involves evaluating piecewise functions using one sided limits. The first step is to determine if the function is defined at the given point. The second step is...
If the hole is the limit does the 3 keep going into the -5 lane that came from there or
Metaphorically speaking
what I mean is this. Basically a way to look at it is look at your limit point in question: take your left pointer finger, put it on the left side of the graph. Do the same with your right pointer finger on the right side of the graph. Start moving them to the point in question. Do they meet at the same place (even though this point may not actually exits in the function)? If so, then the limit exists. This is where the RH limit = LH limit
Awesome okay gotcha
Thank you so much mellow drama llama
Have a fantastic night and thank you again 🙏🏻
yeah no worries. Hopefully this was helpful! Take care
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hi,
the blue line is f(x) = sqrt(x) +2,
the green line is g(x) = - sqrt (x) +2
the red line is y=x^2-4x+4
and the area within these graphs is 9
i was having trouble with this quetion, this was the answer
but i dont understand what they did
this was the question
@silver nova Has your question been resolved?
@silver nova Has your question been resolved?
They calculated the area above the line in terms of d and set it equal to half the total area
@silver nova Has your question been resolved?
thank you, but why is it the second expression being taken away and what does it represent, in terms of area in the graph?
the left expression is the area under the red curve and the right expression is the area under the blue curve
both of them start at the point the horizontal line intersects the graph and end at 4
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Can anyone help me with 22 pls
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G is a planar graph with 5 nodes G = (V,E)
H is a non planar graph with 6 nodes that is made by adding 1 node to G with a degree of 2
prove that H is Eulerian
hold on
Hii
how do you know H contains K5 and not K3,3
you were gone for too long and your channel timed out. you will have to open a new one, sorry.
no, you cannot reopen a channel opened by somebody else.
Ok sry
does "adding 1 node with degree 2 to G" mean we place a new node and connect it with 2 edges to two of the existing nodes?
its becuase it has only 6 nodes and one of them has a degree of 2
which rules k3,3 out
ah wait ok youre right
alright
so then hm
doesnt this mean H can only look like this
oh wait no not necessarily
But G is
with 6 being the new vertex
if we excise vertex 6 from that is the rest planar
ok yeah it is
this should help
i have a feeling that theres only one thing G can be
like how else are you gonna have a 6-vertex H with a K5 minor
i dont think there any options for that other than the two i showed
yeah right
is that a "ok yeah i got you" or "no way that's true"
haha
I get it but I would still like to prove it becuase its good practice for me 
but I could do that later
of its a problem
i mean "G is determined uniquely up to iso" is proof enough imo
or H
H has to contain a K5 minor, and since H has 6 nodes total, this means either it has a genunie K5 subgraph or it's this
we could "insert" vertex 6 into any of those edges but it doesnt matter bc iso
it is a good proof
I think lets try to continue and I might try to find a different (equaly correct) proof later
wait we can just count
and see that all nodes have an even degree
which proves it
oh nice
you see like this proof is perfect but I feel like my teacher wanted us to solve it in a different way 
but either way thanks for helping me 
if we have 10 or more and 11 or less edges that means we have 20 or 22 sum of degrees
we have 5x4 and that means the last one is 2 which means they are all even
is this any good?
eh and I also need to prove its Hamiltonian
ye this kinda suck
true but they take a bit of creativity and are not always possible
and I could easly use it incorrectly
thats why the long boring proofs are better for me
I tried to redo my proof I hope it came out ok
how could you possibly fuck up proving that a graph is hami by DRAWING a hami path on it
hahahazha
I dunno drawing is kinda difficult
becuase H contains k5 or a (i dunno how its called in english)
it must have 5 nodes with a degree of 4 and we know the node we added isnt one of these becuase it has the degree of 2
so the degrees are 4,4,4,4,2 which proves it
I feel like this is better
I will try to do hami now 
Ore's theorem works here right?
ok ok I have one last thing I need to find
the number of Faces
yay
thanks for you help Ann
sorry for being annoying 
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How do I solve this?
When solving I got
(x-3/(x+2)
And the questuon asked which is NOT a vertical asymptote
,rotate
can you show your work
you didn't factorise x^2 +2x - 3 correctly
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how is root 2 / 2 equals to 1/ root 2
sqrt(2)/2 = sqrt(2)/(sqrt(2)*sqrt(2)) = 1/sqrt(2)
$\frac{\sqrt {2}}{2}=\frac{\sqrt {2}}{\sqrt {2}\sqrt {2}}$
$\frac{\sqrt{2}}{2} = \frac{\sqrt{2}}{\sqrt{2} \cdot \sqrt{2}} = \frac{1}{\sqrt{2}}$
Ann
ohh makes sense!
pro_hecker_pj
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can some1 help me factorise this?
15x + y - xy - 15
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
consider factorisation by grouping
yh when i group there r no common factors
what are you grouping with what?
15x + y - xy - 15
show what exactly uve tried so we can help better
you've just reposted the question
i tried doing this (15x + y) - (xy - 15) and bringing out the common factors
im not supposedto?
not by itself when being asked to show work
o
as that's no indication of having done anything
right so as you say, that doesn't help. Try another grouping.
ok
also you didn't actually factor out the - properly
Not working
how do i do that?
well if u dont show us what isnt working
$-p-q \redneq -(p-q)$
no one can help
ℝamonov
i tried (15x - xy) - (15 + y)
grouping like that, the (15x+xy) can be factorised
yh but wat abt the second 1
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!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
Try having only a base of 3.
! What the hell am I doing here?
I got this
oh I forgot the 1/
Yes.
The fraction part for the second bit
Oh the -3 because then in the original equation it’ll be log base -2 which isn’t possible
Actually it doesn’t work in this equation either bc the rhs will be log(-2)
thanks guys👍
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where do i begin with this question
What's the surface area of a cylinder?
2pirh +2pir^2
h = 2r
And do you know the relation between h at r here?
@timid silo was better to let op discover that himself
now youve robbed him of that opportunity
alr
i already knew h =2r but idk where i go from there after subtituting values
how about u show the last step where u got stuck at.
.reopen
Yeah, so you get 6pir^2=314whatever. Can you solve for r?
What? They said they don't know where to go AFTER substituting values, so they already have this equation
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Can't I use this to solve the above problem
Because I tried doing it and got the wrong answer
show your work if possible
Wait
As i was rewriting it to take a picture
I found a mistake
That's prolly what I messed up
@knotty crow
It's right thus far no?
First time I'm ever using that formula so just making sure ig
Yeh multiplied it by the conjugate and it gave me the right thing
Noice
Thanks
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Hi! I've been trying to do this question for a quiz on trigometric derivatives, and I'm not exactly sure where to start. It wants me to find an "equivalent expression" though I'm not sure how. I don't know if there is some way to factor this or if there is some rule I missed- I tried deriving it but the denominator remains as pi-pi=0. Thanks! https://i.imgur.com/xBFgp4i.png
Do you mean you have used l'Hospital?
looks oddly like a derivative
Haven't got there yet
,tex .sum diff trig
Definition
Like I said when I try to derive it the denominator stays as pi-pi and I don't really see a way to remove that discontinuity
Hayley
do you know these?
A quiz?
Nope
oh those won't help you nvm
Yep
We don't provide help with quizzes or tests
:(
first definition is only true if f is defined on an interval
(or all of R)
all of R is an interval
Can you see what happens if I replace x by pi+h, and h tends to 0?
Ah I think I see where this is going now- I'll try that rq, thanks :D
OH okay I had to use a bit of my big boy brain- I was tryna think forward when I had to think in reverse that the equation literally just represents the derivative of sin(pi) which is just cos(pi)- I knew it was simple and I was just overthinking it lmao. Thanks everyone for your help!
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This is the PMF of Poisson Binomial distribution. anyone here know a way to calculate CDF of Poisson Binomial distribution without needing to calculate all the probability one by one? because this is compute expensive
This is the CDF
I can find the mean, the STDEV, and the Variance
uh... are my question clear?
I just want a more efficient way to calculate the CDF, maybe anyone know another way to calculate the CDF?
there is also another formula in that Poisson Binomial Wiki, it use Fourier Transform so it's should be more efficient, but I don't even know if this is CDF or PMF, there is also many symbol that I don't understand there
since it's P(K = k) that's PMF
ah... I see....
Hayley do you understand this? Like do you know which part of this is the CDF?
anyone? 
<@&286206848099549185> help please 
bro what is that lmao
not in any meaningful way 
yeah I'm going crazi, been searching a way to understand this for month 
I see... thanks at least you tried
what class is this
i see its more or less a stats topic
since its a type of probability distribution
lmao i feel so dumb
it's not on any class I do this myself
I need this, not because of studying...
which is why I'm still searching away even after month 
I don't know I found this on random place on internet, I don't even remember where
okay 
@final lily Has your question been resolved?
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is the norm of this partition -1.1 or +1.1?
not sure what the norm of a partition is, but usually norms are non-negative (just from the word alone)
I guess largest length of subinterval?
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how did ln 2 get on top
You mean... in the last line ?
yes
They have just divided both the sides with 12*ln(1+0.5/12).
so that they could separate variable t to the one side.
It's a fairly simple thing. You separate out the variable you need the value for on one side.
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use points
thats the easiest way
or you can get the maxima and minima of the function and graph it like that
So like when x =3 then I put three into the equation to get y
yes
But it isn’t labelled
Complete the square to get points of rotation?
no, thats only in second degree functions
you can use the cubic formula, but its super long and messy
as i said, just use points
it saves you the hassle
y=1
So it will intersect y axis at 1
Can’t I complete the square and get rotation points?
what dpo you mean by points of rotation?
you mean like critical points?
Where it rotates bro
those are called critical points, you gotta differentiate the function
I had to prove that relation in my Analysis exam 