help-10

[brisk matrix]

but we haven’t shown it

[uneven otter]

oh

[brisk matrix]

the idea is to start with
… -> n-1 -> n

this is our ordered list

and we assume n+1 loses to n

[uneven otter]

then its n-1 -> n -> n+1

[brisk matrix]

perfect

now let’s consider the other case

[uneven otter]

and if n+1 were to win against n

it would b n-1 -> n + 1 -> n

and then the next case

[brisk matrix]

if they lost to n-1

[uneven otter]

could be if they lost to n-1

then that is the final

order

and if they win against n-1 then it should be

n+1 -> n-1 -> n

[brisk matrix]

if they lost to n-2

make sure you’re clear about that

[uneven otter]

n-2 -> n+1 -> n-1 -> n

[brisk matrix]

in general

we have a section
a -> b -> c

[uneven otter]

and i add d and then consider each case

just like that i can keep adding

but they only asked for k+1 so i should j talk abt that

[brisk matrix]

ok as long as you understand the proof

it’s just cases until you reach the start of the line

[uneven otter]

Ok let me write this down and then could u proofread it

because idk how to say this in a proofy way

[brisk matrix]

maybe an easier way to phrase this is starting with n+1 beating 1

then we have

n+1 -> 1 -> … -> n

then we assume the contrary

and we get the sequence 1 -> n+1 -> 2 -> … -> n

now we know 1 -> n+1 is well positioned

since we are assuming n+1 lost to 1

so we just consider the rest

n+1 -> 2 -> … -> n

repeat

[uneven otter]

ohhhhhhhh

ok one second i think I get it properly now brb

[brisk matrix]

eventually n+1 fits, or they lose to n and end up at the end of the list

also make a note in your proof that we are assuming there is a sequence that works of the form
1 -> 2 -> … -> n
that’s the inductive hypothesis

the labels don’t really matter, i’m calling them 1 through n for simplicity’s sake

[uneven otter]

could you please lmk if its valid

[uneven otter]

oh true let me add that

[brisk matrix]

don’t use commas before the dots

just use an arrow like you were using before

[uneven otter]

done

[brisk matrix]

also say “the queue would be” instead of “the queue would be something like”

we know for certain it would be that

or better yet say “could be”

since there probably are multiple valid arrangements

[uneven otter]

bet

[brisk matrix]

looks fine otherwise

maybe explain the last bit in a few lines

like the k -> k+1 case

and why it works still

[uneven otter]

oh what do u mean

but wont it

oh so like

when it reaches k

[brisk matrix]

like just add a line about “if it loses against the k ninja then we can let the queue be: … -> k -> k+1”

so one more nitpick notation wise

do 2 -> 3 -> … -> k

so an arrow before the dots

[uneven otter]

bet added

[brisk matrix]

(also you didn’t move the k+1 element in the 4th queue you wrote)

and finally

probably worth adding a not somewhere that inserting this ninja won’t change the rest of the queue’s validity

[uneven otter]

i did wym

it lost to the second ninja

so its after the second ninja

[brisk matrix]

i mean

the fourth queue

you’re looking at the fifth

oh

that says win

never mind

[uneven otter]

yea lol

so my proof is god?

good*

[brisk matrix]

en

so

after you say you assume it loses against the first ninja

don’t write the queue

say first that you assume it loses to the second ninja

[uneven otter]

coz it remains the same as winning against the second ninja?

oh should i

talk about them at once

[brisk matrix]

well because we don’t know if it fits there yet

[uneven otter]

losing to 1 and winning to 2

[brisk matrix]

it could have lost against the second ninja

[uneven otter]

right

[brisk matrix]

yeah. other than that

maybe mention what i said above somewhere

how placing this ninja doesn’t change the rest of the queue being valid

like literally one sentence somewhere

[uneven otter]

is this better

[brisk matrix]

eh

so again i want to suggest you put an arrow after the 3

and before the dots

but also make note of the assumption that “k+1 ninja was to lose agains the first ninja and win against the second ninja”

then go over what happens if the k+1 ninja was to lose to the second ninja and win agains the third ninja

[uneven otter]

ah

I see

tysm

[unique grail]

is it possible to calculate the value of theta

[uneven otter]

oh lemme close my fault n u can take the channel

.close

[obtuse pebble]

Channel closed

Closed by @uneven otter

Use .reopen if this was a mistake.

[unique grail]

. reopen

.reopen

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unique grail]

is it possible to calculate the value of theta

if yes how?

[royal basin]

what's given?

[unique grail]

no value is given

I mean using geometry

[royal basin]

if nothing is given then nothing can be found

[unique grail]

I need to check they are perpendicular or not

<@&286206848099549185>

[timid silo]

Sorry we must close your ticket

[unique grail]

I calculated this. Is it correct?

[heavy frost]

can you tell the problem

ill help if i can

[obtuse pebble]

@unique grail Has your question been resolved?

Channel closed

Closed by @unique grail

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solemn pollen]

Hi there, I really have no idea how to start solving this question, should I use integration by parts or by substitution

[urban patrol]

i mean you can start by simplifying the log

[shell garnet]

i think u take x2+1 = t

and then sub it all in the integral

oh boy is it long

[obtuse pebble]

@solemn pollen Has your question been resolved?

[frosty pendant]

Pull out x² from the root and bring the difference of ln together

I've noticed that the answers have 1 + 1/x² and not x² + 1

[shell garnet]

oh yeah

damn

nice obs

fk im dum

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[astral aurora]

Number of non trivial entries in matrix A=[a ij] n×n which commutes with
D=dig[a1,a2,....p1 times...p2 times.......ak....pktimes

[astral aurora]

I didn't understand it

This is the solution

.close

[obtuse pebble]

Channel closed

Closed by @astral aurora

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[toxic kraken]

|x|-2 / x(x-1) > 0
when we take x<0, will the numerator be -(x-2)?

[polar fossil]

numerator will be -x-2

[toxic kraken]

OH, i get it now, the mod sign is on x so the negative sign would also be on x only, thanks!

[polar fossil]

[toxic kraken]

.close

[obtuse pebble]

Channel closed

Closed by @toxic kraken

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[timid silo]

🤡

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

So the answer is 0 but I get infinity

Can someone show me where I went wrong

[boreal patio]

dx = du/2x

and then in the second step you also lose the x

[timid silo]

oof

the x was above

the 2 became half since there was no 2 on the numerator

[boreal patio]

yes

the x above dissapears

[timid silo]

so it goes to the denomenator??

[boreal patio]

so first you did the substitution

u = x^2 + 4

then when you derive you get,

du = 2x * dx

and then when you plug in dx with your substitution in the second step you get
x/u^(3/2) * du/2x

[timid silo]

OHH

so then

it becomes

du/2u^3/2

[boreal patio]

yes

[timid silo]

ayyy

Did I do this right? :D

Wait no

I still get infinity plus infinity

The negatives cancel out

[boreal patio]

you are not evaluating integral bounds after substitution correctly

what is b?

[timid silo]

infinity

[boreal patio]

when x -> - inf

u -> inf

[timid silo]

Oh it’s still infinity

[boreal patio]

yeah (its because f(x) is symmetric)

[timid silo]

I just used the second definition

[boreal patio]

this will apply to the 0

wait ill try to solve it

when i derive the indefinite integral i just get - 1/sqrt(x^2+4)

and if i apply the bounds both go to 0

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

Ye?

[boreal patio]

no

the first problem here is already division by 0

what are the bounds of the integral after substitution?

both are infinity, you agree?

you don't have to include 0 in the definite integral after substitution

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

omg true

how would i do this

[boreal patio]

when you do substitution

your bounds change

[timid silo]

but infinity makes it stay same

[boreal patio]

for u = x^2 + 4
when x goes to bound -inf, then u goes to +inf
and the same for x -> inf

[timid silo]

ooohh

[boreal patio]

you dont have -infinity anymore

[timid silo]

so it goes from infinity to infinity

[boreal patio]

exactly

[timid silo]

woahhh

but then what next

[boreal patio]

you can evaluate the definite integral... and because you have -1/sqrt(u) the u -> inf will be equal to 1/inf = 0

[timid silo]

Like this?

[boreal patio]

yeah like this

[timid silo]

:DDDDDDDDDDDDDDDDDDDDDDDD

OMG TY

[boreal patio]

also the summands just cancel out so you get 0 anyways

np

[timid silo]

what is summands?

[boreal patio]

-t^1/2 + t^1/2

[timid silo]

true

Alright last question

Oh waiittt

I substituted 0 instead of 2

Brb

[boreal patio]

i get pi/2 + 2

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner spear]

When trying to prove that 3 vectors lie in the same plane, we use a dot (bxc)=. I understand that bxc gives a vector perpendicular to a (Call this the normal n). a dot n equals zero means that a is perpendicular to n. However, how does this prove that they are on the same plane?

[inner spear]

for example, imagine a piece of paper with vectors b and c on it. bxc gives a normal, which is like a pen sticking out of the paper. even though vector a is perpendicular to the pen, it doesn't mean it's on the paper, right? it's parallel to the paper, but couldn't it be above the paper too?

[warm canopy]

If it wasnt on the paper, it wouldn't be perpendicular to the normal

[wooden cipher]

They are if you move the takls together

tails*

[royal basin]

vectors don't have a fixed start point

so it being parallel to the paper is good enough

[inner spear]

I don't understand this point. Isn't any plane parallel to the paper perpendicular to the normal?

[inner spear]

but if it is parallel to the paper, but not on the paper, then it's not on the plane?

I'm a bit confused

[wooden cipher]

The starting location of a vector can be changed

What cannot be changed is its magnitude and direction

[royal basin]

when we talk about three vectors lying in the same plane we imply a plane that goes through three manifestations of said vectors w/ the same start point

[inner spear]

manifestation?

[inner spear]

ya but if any plane parallel to the paper is perpendicular to the normal then they're not on the same plane

or am i wrong

[wooden cipher]

We specifically move the tails to the same point and then check coplanarity

[warm canopy]

Youre thinking of it in terms of physical lines in space instead of slightly more abstractly where a vector is the same vector if you only move it around

[inner spear]

the vector a is perpendicular to the normal but not on the plane

[inner spear]

hmm, I can see that a is parallel to the plane and can be moved to fit on the plane yes

[wooden cipher]

Does vector a's tail match the location of the tail of b and c?

[inner spear]

I don't really understand the question

you mean can a be shifted to the same plane as b and c and be on the same plane?

[warm canopy]

Vector a can be picked up and moved wherever you want and it still be the same vector as long and you don't change direction or magnitude

[inner spear]

oh

[inner spear]

so even though a is not on the plane, it is on the plane because it can be moved to be on the plane?

[warm canopy]

Yes

You can and sometimes should view all vectors as starting at the same point (might aswell be 0) and then a is immediately on the plane in the usual way you would want it to be

[inner spear]

gotcha, that makes a lot of sense

thank you

.close

[obtuse pebble]

Channel closed

Closed by @inner spear

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wise hedge]

Where have I gone wrong: https://i.imgur.com/oPXsfoU.png

[timid silo]

The stuff inside the cosine looks wrong

t is in years, 206 is in days

And yes I see the /365 at the front but then you get t/365-206/365

206/365 is in years, t/365 is meaningless

[wise hedge]

There is no t/365 that I put in anything.

[timid silo]

If you expand out the /365 into the parentheses you get t/365

Unless there is another mistake I am missing it is probably 2pi(t-206/365)

,calc 63.5-14.5

[warm shale]

Result:

49

[timid silo]

,calc 63.5+14.5

[warm shale]

Result:

78

[wise hedge]

I think you are mistaken, it's always regular period over new period

2pi/365

[timid silo]

Yeah okay but then the stuff inside the parentheses is wrong somehow

Since your new period is in days I'm guessing the stuff inside the parentheses should be too

[wise hedge]

No, it can't be. I've done that way a thousand times.

[timid silo]

So you need to convert t to days

[timid silo]

Look, you're subtracting days from years

[wise hedge]

It is in days, the 206th day of the year.

[timid silo]

t is in years

[wise hedge]

I just assumed they worded the question wrong. What sense does it make to talk about the function in years since everyone will look the same?

t is probably in days.

[timid silo]

I mean

I can't tell you whether they got the question wrong or whether it is actually in years

I can only tell you what I read

[wise hedge]

Trigonometric functions repeat, and they repeat exactly

[timid silo]

Yeah sure

[wise hedge]

So, what does the year matter?

[timid silo]

But then I don't know how to help

Oh wait I see the confusion

I was confused too at first

It's not just the year

It's uh

It's not necessarily an integer

[wise hedge]

Dont blow it

[timid silo]

...?

[wise hedge]

Just guide me if you see my error.

[timid silo]

Yeah okay

Well t is in years that's what I see

And it seems you don't understand t can be like 3.5

Not just 1, 2, 3, 4... It encodes the exact day

Does that make sense?

[wise hedge]

I'm trying to take it in and process what you are saying.

[timid silo]

"Why does the year matter"
t is not the year

It's not like the year 2022 or any of that

No, it's the exact time that has passed since January 1st 2015 in years

The exact time

If half a year has passed it's not gonna be 0 because we're still in 2015, it'll be 0.5

[wise hedge]

Right but it says you start at January 1st on the graph so...

[timid silo]

Yeah

So the problem here as I have stated many times is that your period is in days but t is in years

[wise hedge]

So convert the 206/365 to a simple decimal?

It's still a ratio

[timid silo]

Uh...?

How would that look like?

[wise hedge]

.56

[timid silo]

Not sure why you'd want to do that

[wise hedge]

I wouldn't because it doesn't help but that's in years, .56ths of a year

[timid silo]

Oh I see

I thought you were gonna convert everything in days instead of converting everything in years

Both work

So if you want to use years as your unit, yes, you'll have to use 206/365 instead of 206

[wise hedge]

206/365 is in years. it's .56ths of a year

[timid silo]

And you'll have to use a period of 1

For 1 year

[wise hedge]

It's just stating in days

365 means the units are in years

So 206/365 is in years

[timid silo]

Yes

@wise hedge So what do you think the formula would look like...?

[wise hedge]

I don't have a clue, I typed what I think it is. I'm lost on what's wrong other than changing the 365 to just a 1 to represent the period as a year.

The period is 365 days, that represents a year

[timid silo]

Yes

So have you changed the formula to something else now?

If so, can you screenshot it?

[wise hedge]

No, I haven't changed it. It's the same as I showed you.

[timid silo]

Do you want to use years or days as your unit?

[wise hedge]

365 days = 1 year, it's semantics to me.

[timid silo]

Well it's really not

Like say you're calculating the speed of something

And it moved 10 meters in a minute

That's 10/1=10 meters per minute

Now if you want to calculate it in seconds, you'd do 10/60=0.1666... meters per second

60 seconds is a minute yeah sure

But still, you're using seconds as the unit

@wise hedge Does that analogy make sense?

[wise hedge]

Yes, what you said just makes sense.

So, I guess I'm just confusing my units, using them 2 different ways I guess.

[timid silo]

Yeah, so now you gotta either convert everything to years or everything to days

Also I was myself confused as to how changing the unit gave the same formula, but then I realised we're dividing how much time has passed by the period which are in the same unit

And simple dimensional analysis shows that this gives a dimensionless (unitless) result

Ooooh right yes because we are therefore expressing the time in terms of a single period (which in this case is a year) no matter which units we use to do that calculation

@wise hedge Have you now changed the formula? If so, did it count it as right?

[wise hedge]

I haven't changed it yet but I understand what you're saying now. Thank You for helping me understand it. I'll have to go back and examine and see where I mixing the units together wrong.

I got the right answer but it was in a tweaking fashion. But you did help me to understand it. Thanks again.

[timid silo]

Don't forget to .close

[wise hedge]

.close

[obtuse pebble]

Channel closed

Closed by @wise hedge

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo gazelle]

did i do that right

[obtuse pebble]

@echo gazelle Has your question been resolved?

[echo gazelle]

<@&286206848099549185>

[tardy epoch]

yea g'(4)= -6 is right if you're given f(4) = 1 and f'(4) = -2

[echo gazelle]

okay thanks

i also have h(x) = sqrt(x) * e^(f(x)) find h'(4) and im confused ab it

[tardy epoch]

product rule and chain rule

[echo gazelle]

do i use the product rule or the chain rule? or both? the e^f(x) is confusing me

o

okay

[tardy epoch]

there are 3 functions

sqrt(x), exp(x), and f(x)

[echo gazelle]

yeah so do i do the chain of e^f(x) and hten the product rule of that answer * sqrt (x)

im rlly confused trying to do the chin rule for e^(f(x))

is it f(x)(e)^(f(x)-1) * e^x

@tardy epoch

[tardy epoch]

It's not power rule

Power rule is for constants

Like x^n

[echo gazelle]

oh what do i do then?

e^f(x) * ln(e)?

but then its just e^f(x) * e^x again wait what

[tardy epoch]

no

$e^{f(x)} = a(f(x)), \ a(x) = e^x$

[warm shale]

rie.mann

[tardy epoch]

now try using chain rule

[echo gazelle]

e^f(x) * e^x ?

[tardy epoch]

look up the chain rule and type it exactly here

[echo gazelle]

g'(f(x)) * f'(x)

g is outside f is inside

[tardy epoch]

apply that to a(f(x)) here

[echo gazelle]

im confused is it just e^x then

[tardy epoch]

what's the outer function here?

[echo gazelle]

a

[tardy epoch]

yes

[tardy epoch]

so what's this equal to for g(x) = e^x

[echo gazelle]

e^(f(x))*f'(x)

[tardy epoch]

correct

$\frac{d}{dx} e^{f(x)} = e^{f(x)} f'(x)$

[warm shale]

rie.mann

[echo gazelle]

does f'(x) equate to e^x?

[tardy epoch]

what

ask in complete sentences

[echo gazelle]

wait nvm

do i just leave f'(x) as f'(x)?

[tardy epoch]

yes. you don't know what f'(x) is so that can't be simplified anymore

[echo gazelle]

so now i have h' = sqrt(x) * e^x * f'(x)

[tardy epoch]

nah

[tardy epoch]

you didn't use this

and you didn't use product rule

[echo gazelle]

wait what

[tardy epoch]

read this as many times as it takes for you to understand what it's saying

[tardy epoch]

you came up with it yourself

i just wrote it in latex for you

[echo gazelle]

okay i understand the derivative of e^(f(x) now

so do i now do the derivative of sqrt x = x^1/2 so it = 1/2x^(-1/2) or also 1/(2sqrtx) and do the product rule to multiply that with the derivative of e^(f(x)?

[tardy epoch]

write down the product rule exactly

[echo gazelle]

(f * g)' = f' * g + f * g'

[tardy epoch]

use different letters before you confuse yourself

$(u v)' = u' v + u v'$

[warm shale]

rie.mann

[echo gazelle]

okay

[tardy epoch]

identify what u and v are

[echo gazelle]

so

u is sqrt(x)
v is e^f(x)

u' is 1/(2sqrt(x))
v' is e^f(x) f'(x)

[ (1/(2sqrt(x))) * e^(f(x)) ] + [ sqrt(x) * e^f(x) * f'(x) ]

[tardy epoch]

looks good

[echo gazelle]

so now do i substitute 4 in for x?

wait nvm thats confusing bc of f(x)

[tardy epoch]

yes

[echo gazelle]

o

[tardy epoch]

you're given f(4) and f'(4) presumably

[echo gazelle]

what do i do about e^f(x) oh wait that'd be e^1 bc of the point (4,1)

so the final answer is
h'(4) = (1/4)e - 4e

or (-15/4)e

@tardy epoch i did

(1/4 * e^1) + (2 * e^1 * -2) to get that answer did i do it correctly?

[tardy epoch]

where's f'(-4) given

[tardy epoch]

is it the same f(x) ?

[echo gazelle]

i did f'(4) in part a of the problem its -2

wait f'(-4)?

[echo gazelle]

yes

[tardy epoch]

looks right

[echo gazelle]

thank you for your help

.close

[obtuse pebble]

Channel closed

Closed by @echo gazelle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[modest pine]

i divided the 4th degree (original) by x-1

then found -4 was a zero of the 3rd degree (result of division)

so divided 3rd degree by x+4

then i got this

how am i supposed to factorize that

[nocturne minnow]

Because you entered it wrong

What was the result when you did x^4 divided by x - 1?

[modest pine]

x^3

no way i got this wrong bor

[nocturne minnow]

The full result

[modest pine]

let me put it in a calculator

x^3-4x^2+5x+20

[nocturne minnow]

Yeah that's wrong

[modest pine]

i officially cant do divisions

??

MINUS 20

damn

😎

finally

is this what im supposed to do

[nocturne minnow]

I think it wants you to expand it out too

[modest pine]

i got a weird equation as result

so i did (x-1/2)(x-1/2)

same with x+5

and multiplied the result of each of them by each other

nvm

[obtuse pebble]

@modest pine Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grizzled lagoon]

i have a question

[grizzled lagoon]

.open

for this question how to make sure the the sign in front of 128/(x+4)

okay that is a stupied question

i got answer

[obtuse pebble]

@grizzled lagoon Has your question been resolved?

[grizzled lagoon]

.closed

[obtuse pebble]

Channel closed

Closed by @grizzled lagoon

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse pebble]

@worthy bramble Has your question been resolved?

[sage geode]

I would rewrite the given logarithm as $\frac{\ln{\cos{x}}}{\ln{\cos\frac{x}2}}$ and then just substitute for $\cos\frac{x}2$

[warm shale]

alonelybean

[sage geode]

And perhaps l'hop then

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallow cove]

Help guys idk how to do

[fallow cove]

Idk where to start, more specifically

[grizzled shore]

Do you understand the question?

Like do you know what it’s asking

[tropic pier]

Isnt there like, an specific equation for that?

The equation of motion?

[grizzled shore]

Don’t blindly use formulae

[tropic pier]

Meh, sometimes is useful when the demonstration is very extensive

[fallow cove]

Info I know:
v'(t)=-g
v(0)=25
calculate t?

[tropic pier]

But true

[grizzled shore]

That’s not really what the equation is asking

[fallow cove]

cuz counting t dosen't seems like it

oh

[grizzled shore]

Read the question and try to rephrase it (without the numbers)

[fallow cove]

Calculate the difference of time that the ball is thrown on Earth and in Mars?

[grizzled shore]

Try understand what is happening in the question first

What is “difference of time that the ball is thrown”

[fallow cove]

Like in how long will the ball last in the air

[grizzled shore]

Right

So we need to find 2 things

And subtract 1 from the other

[tropic pier]

The question doesnt ask the difference, just how long the ball last in the air on Mars

[grizzled shore]

Yes?

[grizzled shore]

It does

Read the last sentence

[tropic pier]

Is doing a comparison

Hmm

[fallow cove]

so we subtract v(t) in Earth from v(t) in Mars?

[grizzled shore]

Don’t worry about v(t)

We want to find time in air mars - time in air earth

Because obviously it will be longer in the air for mars than earth

[fallow cove]

yes

[grizzled shore]

That should be obvious

Ok so we need to find time in air then

If I shoot a ball upwards on earth at some velocity v

How long does it last in the air?

(What we want to find is a function of this form: f(gravity, initial velocity) = time in air)

[fallow cove]

so we need v(t)?

[grizzled shore]

What does v(t) tell you about the time in air?

[tropic pier]

It finally clicked, yes

[fallow cove]

it's initial velocity is 25m/s

thus meaning that when v(0)=25

[grizzled shore]

Or v(0) = 25

[fallow cove]

yeah

[grizzled shore]

Ok what’s next

[tropic pier]

Remember that the ball is affected by two other things

What are those things?

[grizzled shore]

It’s affected by only 1 thing

[fallow cove]

and it's only affected by gravity

[grizzled shore]

Yes

[tropic pier]

Indeed

[grizzled shore]

How would we model that?

[fallow cove]

v'(t)=g

[grizzled shore]

Sure

And then?

[fallow cove]

g is -3.711 here

so sub it in and integrate

[grizzled shore]

Don’t worry about that

[fallow cove]

ok

[grizzled shore]

If the ball experiences some acceleration

How does its current velocity change in time

[fallow cove]

a(t) is v'(t), since the acceleration is the derivative of velocity

[grizzled shore]

v(t) = something dependent on initial velocity and acceleration

[grizzled shore]

It’s got to do with this

[grizzled shore]

And I mean don’t worry about the exact value of g here

[fallow cove]

oh ok

[grizzled shore]

(Because we want to end up with a function that depends on g as well)

That way we can just sub it for earth and mars

[fallow cove]

so do we need the position of the ball here?

[grizzled shore]

We could

[fallow cove]

h'(t)=v(t) then

[grizzled shore]

You could also use the fact that the velocity at which the ball hits the ground with

Is negative it’s started velocity

Because of conservation of energy

[fallow cove]

yeah

v'(t)=-g when falling

now?

[grizzled shore]

That’s true falling or rising

[fallow cove]

wdym falling or rising?

[grizzled shore]

Whether or falling or rising the gravity is the same

[fallow cove]

oh ok

[grizzled shore]

Here they’ve defined down (towards the centre of planet) to be negative

And away from the centre of planet to be positive

[fallow cove]

yeah

[grizzled shore]

I’m saying if you start with some velocity v upwards

You will hit the ground with velocity -v

You can use this to find the time spent in air

[fallow cove]

oh ok

[grizzled shore]

(Also funny side note, mars doesn’t even have air so it wouldn’t be “in the air”)

[fallow cove]

lol

[grizzled shore]

Anyway from this

v’(t) = g

Can you find an equation for v(t)

[fallow cove]

now we sub g in? as -3.711?

[grizzled shore]

No g’s

g is a constant

[fallow cove]

v(t)=gt+c?

[grizzled shore]

Fuck

I did it wrong

[grizzled shore]

This is wrong

v’(t) = x(t)

Wait

[fallow cove]

what's x here?

[grizzled shore]

No that’s wrong

Oh wait I got confused sorry

That’s right

[grizzled shore]

Ok what’s c

[fallow cove]

25 by using initial velocity

[grizzled shore]

Ok

So we have v(g, t) = 25 + gt

[fallow cove]

is it v(t) or v(g,t)?

cuz I remember that the t is the only variable here

[grizzled shore]

We want to find how long it takes to go from v to -v (how long it’s in the air)

[grizzled shore]

Yeah but g can change, being in a different planet will change g

[fallow cove]

oh ok

[grizzled shore]

And we will sub in different values for g

So it acts like a variable

So we want to find how long it takes to go from v to -v

[fallow cove]

ok

[grizzled shore]

Which means v(g, t₀) = -v(g, t₁)

Yeah?

[fallow cove]

one sec

lemme comprehend

oh ok

so g(t_0)+25=-g(t_1)-25?

[grizzled shore]

Yes

[grizzled shore]

Now when are we starting the “timer” (t₀)

We want to find t₁ - t₀ since that’s how long it takes to go from v to -v velocity

[fallow cove]

ooh

[grizzled shore]

(They are all functions of g but that’s fine)

[fallow cove]

t₁ - t₀=50/g

[grizzled shore]

What’s t₀

[fallow cove]

t₀=(50/g)-t₁

[grizzled shore]

Nah

[fallow cove]

wait

[grizzled shore]

You’re overthinking it

Remember v(g, t₀) is velocity when we start

v(g, t₁) is velocity when we end

ie we launch, and it hits the floor

What’s the time when we launch

[fallow cove]

when t=0

[grizzled shore]

So we start measuring at t₀ = 0

[grizzled shore]

Like this is what we want

[fallow cove]

so we use that info to find t_1?

[grizzled shore]

But we don’t need t₀ because it’s equal to 0

Yeah

[fallow cove]

oh ok

so then t_1=50/g

wait wtf

ok

better

[grizzled shore]

Ok

So that’s how long the ball is in the air

For some gravity value

[fallow cove]

on Mars

[grizzled shore]

Nope

[fallow cove]

oh

[grizzled shore]

For some gravity value g

[fallow cove]

oh

[grizzled shore]

We haven’t specified it yet

[fallow cove]

oh wait

I think I know it

[grizzled shore]

Ok now we want t₁(g=-3.771) - t₁(g=-9.81)

[fallow cove]

so then the difference is (50/9.8)-(50/-3.711)?

[timber island]

our teachers would ask to use equations of motions to find time of flight for both ball separately and subtract

[grizzled shore]

Wrong way

[timber island]

specifically the second one

[grizzled shore]

Bigger number goes first

[fallow cove]

oh ok

[grizzled shore]

Remember that we can obviously know by inspection that t(-3.771) is the longer one

Cos it’s on mars and it’ll take longer to fall

[fallow cove]

ok

wait

wouldn't the value be negative?

[grizzled shore]

Try rearrange this again

You lost a - sign at the front

[fallow cove]

oh

sry

one sec

Got it

8.371

thx

.close

[obtuse pebble]

Channel closed

Closed by @fallow cove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[willow tulip]

Hi

[willow tulip]

Do you know any website that is like little alchemy but math version

I have spent at least 20 minutes trying to find one

[rich plume]

Like what would you expect from that game

[willow tulip]

Idk

Search up little alchemy

Or do you know it already

[sacred root]

You wana mix things and learn math??

Sounds ridiculous...

[wise hedge]

I think what he is trying to do is learn math via fun games. To make the monotomy of learning seem less tedious.

A lot of websites take that approach. I remember a game that taught you about angles by shooting your projectiles from virtual cannons to try and hit targets. Things like that.

[sacred root]

I mean alr

[willow tulip]

I’m already learning math the hard way, but after watching that animation vs math gave me the urge to find out if there is a math game similar to that

[sacred root]

There is "brilliant", put you gotta pay

[willow tulip]

What

[sacred root]

brilliant.org

It's website

Where you can learn math visually

[willow tulip]

Oh

That’s good enough for me lol

Ty

[sacred root]

I mean you gotta pay tho

[obtuse pebble]

@willow tulip Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[astral aurora]

It will be minimum??

At x=0

For maximum the function is symmetric around y axis so -3/8

[obtuse pebble]

@astral aurora Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[astral aurora]

. reopen

.reopen

[obtuse pebble]

✅

[obtuse pebble]

@astral aurora Has your question been resolved?

[obtuse pebble]

@astral aurora Has your question been resolved?

[astral aurora]

.close

[obtuse pebble]

Channel closed

Closed by @astral aurora

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Hey

[timid silo]

I need help in databases

What’s the point of the attribute called start date between the relationship of the two entities ?

[next reef]

Start Date is a descriptive attribute since it is an attribute for the relationship set Manages

It could store the information on the date from which an employee started managing a particular department

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[empty salmon]

How do I find the minimum value of y(x)= sin^2(x) + cos^2(x) + x^2?

[empty salmon]

So far I've only found the derivative of y(x) which is 2sin(x) +2cos(x) + 2x

[warm canopy]

Can you think of a way to simplify the function

[empty salmon]

ah yeah 1 + x^2

sin^2(x) + cos^2(x)=1

So the stationary point would be 0 yes?

[wooden cipher]

Mhm

[empty salmon]

Aight

And thus the minimum value of y(x) would be 1 innit

since 1 + (0)^2 = 1

[wooden cipher]

Yup

[empty salmon]

aight thanks

.close

[obtuse pebble]

Channel closed

Closed by @empty salmon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[novel onyx]

yo just needed help with this question

[novel onyx]

you need to find the value of angle theta, and the length of x

[civic socket]

yes

do you know how to find them?

[lone dirge]

@novel onyx please label the vertices, and describe in detail what did you try

[obtuse pebble]

@novel onyx Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo gazelle]

is the derivative of e/x = -e/x^2?

[obtuse pebble]

Please don't occupy multiple help channels.

[wooden cipher]

Yes

[echo gazelle]

bc power rule

[wooden cipher]

Also close one of the two channels you are currently occupying please

[wooden cipher]

Yes, in this case, e is like any other constant

[echo gazelle]

i closed the other sorry i forgot to

alr thank u

[wooden cipher]

All good

[echo gazelle]

.close

[obtuse pebble]

Channel closed

Closed by @echo gazelle

Use .reopen if this was a mistake.

[teal turret]

It’s ok I forgive u man

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[verbal coral]

Hello, I'm trying to make a python script that will calculate all possible variations for a given Title. Here are some requirements: The title must be between 8-64 chars. And you can only add or remove "extra" spaces to make it unique. Another thing is that 2 titles that are generated one after the other cannot have the same character length.

Now here are some example:
Original Title: Used 2011 Honda Civic

Possible new titles (you can only add or remove "extra spaces")

1. Used 2011 Honda Civic
2. Used 2011 Honda Civic
3. Used 2011 Honda Civic
4. Used 2011 Honda Civic
5. Used 2011 Honda Civic
6. Used 2011 Honda Civic
7. Used 2011 Honda Civic

Reminder
a) total title length must be between 8-64 characters
b) two consecutive titles should note have the same character length

my questions:
How many possibilities for a given title depending on
a) Original titles character count
b) Original titles word count

does the chances of duplicate ad increase or decrease as the number of words increase?
does the chances of duplicate ad increase or decrease as the number of characters increase?

[verbal coral]

maybe someone can help me with the math / logic part of this question (help to understand the possiblity / probability )

[obtuse pebble]

@verbal coral Has your question been resolved?

[obtuse pebble]

@verbal coral Has your question been resolved?

[obtuse pebble]

@verbal coral Has your question been resolved?

[drifting wraith]

why do you care

the 2 questions seem pointless

[drifting wraith]

well 4

[brisk matrix]

this is just putting balls into boxes

the number of words is the number of boxes, the number of balls is 64 - number of characters already in the string

putting spaces between words is the same thing as putting balls in boxes between them, plus 1 added box which represents not including those spaces

the question then becomes
how many nonnegative integer solutions are there to
x_1 + x_2 + x_3 + ... + x_n = 64 - k
where n is the number of words and k is the number of characters in the string

for example if you have a 60 character string with 2 words A and B
then we want the number of nonnegative integer solutions to
x + y = 4
which is exactly 5: (0,4) (1,3) (2,2) (3,1) (4,0)
and you'll noice there's 5 strings:
A B
A B
A B
A B
A B

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[remote timber]

Hey can somebody just check my thinking here?..

[remote timber]

so f(x) is y=x correct?.. Because it's on top, it'll be (x^2 - (x^2)^2)

so because the inner value is the closer function, you'd set up the integral as pi 0 to 1 then f(x) minus g(x) squared

[polar fossil]

it's around x= 0 (a vertical axis) not y = 0

[remote timber]

ohh shoot

I didn't even.. wow

okay so

the y-axis basically, right? so it'll still be 0 to 1, except both will be in terms of y?..

so now the inner is still y=x

right?..

inner is y=x , outer is x^2

or would you add a -1 or whatever

I think you'd do that though since the function is right up against the axis of rotation

dont think*****

@polar fossil please I need you just one more time! :(

like how would you set up the integral for that?.. I think I'm right

[polar fossil]

if you want to revolve around x = 0 with the washer method you need to write x = f(y)

note though that the region you care about here is R1

[remote timber]

yeah definitely, so both functions will be in terms of x, right?

[polar fossil]

correct

[remote timber]

oh ashit wait

that's completely the wrong problem oml

okay imagine we're revolving

hold on

revolving around y=0, r2

R2*

man okay nvm here

just explain this one I tihnk im right

so the integral will be 7 squared mins sqrt(4-x) squared

right?! cause f(x) is 7

it's the one on top

g(x) is the root function, since it's on the bottom

[remote timber]

so you'd use washer method instead?

honestly I think that'd be easier in this instance

because R is 7, r is the root function

instead of trying to figure out the weird binomial disk method would create

[polar fossil]

well i mean

washer method is just disk method twice

[remote timber]

wait wym

[polar fossil]

$\int (R^2 - r^2) = \int R^2 - \int r^2$

[warm shale]

Hayley

[remote timber]

but couldn't you just say that IN DISK METHOD R(x) is (7-sqrt(4-x))

I guess yeah, you could just split it up anyways

because of integral rules

huh... wow

which will almost always make it easier

okay so lemme get this straight. the FINAL INTEGRAL WOULD BE pi ZERO to FOUR, 7^2 MINUS sqrt(4-x)^2

then evaluated at 4

then boom!

[polar fossil]

no because r isn't sqrt(4-x)

[remote timber]

it's 7 minus the function then huh

[polar fossil]

eg at x=4, r should be 7

very much encourage you to draw these sketches btw

and label r and R

[remote timber]

yess okay

yeah I have my own

okay wait Im getting is

so R is 7 itself, r is 7 MINUS sqrt(4-x)

[polar fossil]

yes

[remote timber]

YESS okay I understand, that applies for every axis of rotation that ISNT the y / x axis

okay so...

BAck to this stupid thing. IGNORE THE QUESTION AT THE TOP. What if you rotated R2 over y=0

INNER would be just x^2

outer would be y=x

there wouldn't be any number added because the function is right against the axis?..

or would be each of those functions minus 1

because it's making a giant circle (the sketch I made)

definitely. outer would be x - 1. Inner would be x^2 - 1?

[polar fossil]

it applies for the y/x axis as well

$\int (0-f(x))^2\dd{x} = \int (f(x))^2\dd{x}$

[warm shale]

Hayley

[remote timber]

for what

wait so around y = 0 the nunber is just 0?..

[polar fossil]

look at what i wrote

in this case it would be like

if you're revolving around y=0

[remote timber]

yeah R2

AROUUN Y=0

[polar fossil]

$\int (0 - x)^2 - (0-x^2)^2$

[warm shale]

Hayley

[polar fossil]

dx

[remote timber]

yess okay I see

that makes sense, so it's 0 because ther's no number between

like the function covers it

between the axi

axis

[polar fossil]

like you don't have to include the 0 because it works out the same way as if you just had the functions themselves
but since you're squaring things it doesn't hurt to include it

[remote timber]

wait so one last quick question; if the line is UNDER the function, would the line function still be first

like if you have the function X, rotated around y= -2

would it just be (x - 2)

instead of (-2 minus x)

like I guess why are they negative? like the x and x^2

[polar fossil]

draw graph -> label radii

[remote timber]

ugh why am I dumb broo

so finally @polar fossil it's x^2 - x^4

final integral

[polar fossil]

you could write it equivalently as $\int (x-0)^2 - (x^2-0)^2$

[warm shale]

Hayley

[polar fossil]

they're the same since we're about to square it

[remote timber]

it but that isn't right

it endsu p being

see

fuck this is timed how am I wrong

LIKE WHAT @polar fossil

SHOOT I NEED TO GET THIS RIGHT

[polar fossil]

why would a homework be timed...

[remote timber]

It’s because I submitted it wrong on accident so now he made it timed

Like wtf is wrong here everything is right

[polar fossil]

where are you getting x and x^2 from

x^2 isn't even in that picture

[remote timber]

ommg it's x^5

lord

ITS SO SMALL

[polar fossil]

📖

[remote timber]

so i just ended up getting this one wrong : I got 188pi like ??

204pi was my first answer but

I put 188 pi and was wrong somehow this was is so easy

nvm I see im dumbokay thanks hayley ily

.close

[obtuse pebble]

Channel closed

Closed by @remote timber

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[merry cave]

@frail junco

[merry cave]

i didnt close the channel it got closed

[frail junco]

oh

i need the pic again or else i'll get lost

[frail junco]

alr so the measure of YZL i'm pretty sure is half the measure of YXL arc

oh wait this isn't that hard

[merry cave]

the sum of all arcs equals 360

[frail junco]

yeah so find the measure of YXL and it should be half of that

yeah if it has the lines that connect on the circle the angle measure should be half the arc

[merry cave]

but how would i find YXL would it jus be half of 87?

[frail junco]

no because look at the lines

87 degrees corresponds to ZYX arc

so you see how the other 2 are already put in

[little cedar]

shouldnt angle z be half of angle x

[frail junco]

idk man i haven't done this in a bit but i'm going off what i think is right

[heavy frost]

hi

[frail junco]

yeah so just subtract the others from 360 and halve it i'm pretty sure

[merry cave]

[heavy frost]

arc YXL is arc YXZ + arc ZXL = 112+118 = 230

and half of that is 115

YXL = 115

so YZL = 65

[frail junco]

112+118 =230

360-230=130

[heavy frost]

bruhh

[frail junco]

half of 130 = 65

[heavy frost]

yeah

[frail junco]

65 degrees should be it right

[heavy frost]

yes

[merry cave]

ok thanks i got another one shouldnt it be a 2 step

[heavy frost]

i think you should be able to do this now

[frail junco]

i have to like inspect it just to figure out how to get it😭

ok i know

angle W is 97 degrees so XPV should be 194

then find the other major arc and halve it

at least that's what i'd do

[heavy frost]

no

[frail junco]

oh i meant arc XPV sory

[merry cave]

8x+12=72

?

[heavy frost]

no

how would you find PXW

[frail junco]

72 * 2

[heavy frost]

if you find PXW than you can easily solve for x, so first find that

dont give random numbers, use formulas

[frail junco]

oh i found the wrong thing

[merry cave]

okok

[frail junco]

idk i just joined this server a couple minutes ago

[heavy frost]

doesnt matter, its okay

[frail junco]

oh wait yeah i was on the right track at least

bc i found the missing angle so we can solve fter

[heavy frost]

i can give a hint, PXW + PVW = 180

[frail junco]

oh wow i should've known tht