help-10

[obtuse pebble]

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[brisk matrix]

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[sleek breach]

1

[brisk matrix]

do you know what symmetric and anti symmetric relations are?

[sleek breach]

i actually have an answer, could u tell me if its right or wrong and if its wrong, kindly provide the right answer please

i think option A is correct

[brisk matrix]

can you justify it for me

[sleek breach]

If we have a set A defined as A = {1, 2, 3}, it means that A is a collection or grouping of distinct elements or objects, specifically the elements 1, 2, and 3.

In this case, A is a set containing three elements: 1, 2, and 3. The order of the elements within a set does not matter, and each element in a set is unique. So, the set A = {1, 2, 3} indicates that it contains the elements 1, 2, and 3, and no other elements.

[brisk matrix]

that looks like it came straight from chatgpt

[sleek breach]

kinda did

[brisk matrix]

id suggest you don’t rely on it for math

[sleek breach]

im not, frankly, i intend to rely on you maximo

[brisk matrix]

then do me a favor and give me explanations using your own words

because otherwise i can’t tailor my explanations to your understanding

[sleek breach]

well, is it acceptable to you if you just provide me the answer to the question?

[brisk matrix]

so let’s go from the top
was the answer you gave me yours or from chatgpt?

[brisk matrix]

no

!nosols

[obtuse pebble]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[sleek breach]

very well

[brisk matrix]

i’ll let someone else help you out, i think there is a disconnect between us

feel free to repost your question

[sleek breach]

aw man, let me be honest with you

i have this discrete math course, and im way behind, idk anything about relations but i have an ongoing test right now

[fathom flicker]

I too rely on maximo. Good strategy

[sleek breach]

i have done every other question except the ones with relations

[fathom flicker]

woah

we can't help with tests

[sleek breach]

cmon

[brisk matrix]

sad turn to an otherwise very simple question

just do your best to prepare more for the next exam

[sleek breach]

ditch that question

[brisk matrix]

we won’t help with any other questions

we cant help with tests and now every question you send will be suspect

[sleek breach]

now ik (Z,+) is a subgroup of (C,+) , (Q,+)

[sleek breach]

ok

very sad

[obtuse pebble]

@sleek breach Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[feral vigil]

how can i prove that the angle is 45 degrees?

[feral vigil]

i know that it’s 45 degrees but i need to show why with calculations

and idk how to do that

[rich plume]

you'll need a construction
(try drawing a perpendicular line to make this problem a piece of cake)

[feral vigil]

you mean splitting the shape into a square and a triangle?

i thought about that but idk what to do after that

5cm

yes

shit what does that mean

isoceles

ahh

its not even close to that in my language

but i know the translation now

then what?

i think i know this but forgot how to calculate it

yeah

right

now i understand

i remember now

thankyou

i have another one

i need to prove that the triangle is what it says there

this one looks really hard but maybe it isn’t

i keep forgetting it

isn’t it one side to the power of 2 plus the other side to the power of 2 and then you get the length of the 3rd side?

or am i lost?

wait

which side should i calculate?

the ”x” side?

ok and then how do i prove this?

no sorry

how do i prove what it says above?

but i am supposed to prove what it says above

3+2 to the power of 3 cm2

okay so i expand?

x•x + (x+2) (x+2) = (x+x) (x+x) ???

is that what you mean?

oh

well damn idfk

can you explain to me?

x to the power of 2 + 4x + 4?

and then?

yeah idk

its just 2x to the power of 2?

as said before?

what

[grizzled wave]

so (2X) (2X)

have like terms

2 and X

multiply them

[feral vigil]

2x?

[grizzled wave]

so take lets say

(2x3)(2x3)

wait

how would you do this

[feral vigil]

6x6

[grizzled wave]

yes

so 2x multiplied by 2x

[feral vigil]

but it isn’t 4x

it’s 2x(2)

[grizzled wave]

it would be 4x^2

[feral vigil]

what

how

wait nvm

i get it

it was just the same thing

holy f*ck im stupid

[grizzled wave]

nah it takes some time dw

[feral vigil]

but im still lost

i did all of this because?

[grizzled wave]

are you aware of the index principles

[feral vigil]

so x^2 + 4x + 4 = 4x^2?

[feral vigil]

idk what that is in my language

[grizzled wave]

wait ill send a picture

[feral vigil]

which one?

[grizzled wave]

my b

[feral vigil]

i dont get it

[grizzled wave]

would it not help?

[feral vigil]

can you write the equation for me?

[feral vigil]

this one

and now?

is the parenthesis necessary?

so x^2+x^2+4x+4-4x^2=0?

why did i choose math

i had math 1b which you have to do but i chose math 2b this year and it was really dumb because i suck at math

i used to be so good

but everyone gets better progressively as it gets harder

i didn’t change

but everyone else seems to understand

i relied too much on natural talent

i was good at almost everything as a kid so i didn’t find anything hard which means i didn’t learn shit. now im not used to actually making an effort which makes it so much harder

im kind of pissed the teachers didn’t challenge me more

[feral vigil]

sorry, how do i make this easier for myself?

[obtuse pebble]

@feral vigil Has your question been resolved?

[obtuse pebble]

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[feral vigil]

sorry i had to go

[feral vigil]

thankyou for everything though

it was nice of you

i have a test in like 10 mins

wish me luck

.close

[obtuse pebble]

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[potent cairn]

Can someone please help me

[gleaming ridge]

[timid silo]

https://dontasktoask.com

[obtuse pebble]

@potent cairn Has your question been resolved?

[obtuse pebble]

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[hearty island]

i need some help with proving trig identities

[hearty island]

i cant see the next step

but ive been told im super close

[timid silo]

from this step, factor the denominator

[hearty island]

oh

because it's a difference of two squares

[timid silo]

yup

[hearty island]

that's brilliant thank you

I have another problem that im stumped on

im thinking of this identity

[timid silo]

its probably easier to start from the rhs for this one

[hearty island]

okay let me try that

oh

the numerator is one

and the denominator is cos 2x

omg!!

[timid silo]

yup, thats correct :D

[hearty island]

omg omg omg

thank you

[timid silo]

np!

[hearty island]

okay this made my night thanks!

.close

[obtuse pebble]

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[terse rapids]

need to find DH/HC, been trying to do it forever

[knotty gulch]

original q?

[terse rapids]

cos DCE = 2/7

ALE and DEC are isosceles triangles

that's all

oh and CL is the bisector of DCE

i was trying to work with angles to find right triangles

[obtuse pebble]

@terse rapids Has your question been resolved?

[obtuse pebble]

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[heady galleon]

somone help solve this hard math

[timid silo]

[heady galleon]

180- x-180-3x=180-x-180-3x=4x

[royal basin]

180-x-180-3x=4x ?

this is a linear equation.

do you know how to solve linear equations?

[heady galleon]

yes

but my brain cells is to slow

[royal basin]

then what is troubling you with this one?

[heady galleon]

wait

oh thanks my man i know how now

thank you

[royal basin]

not a man, but you're welcome.

[heady galleon]

thanks

[obtuse pebble]

@heady galleon Has your question been resolved?

[obtuse pebble]

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[fallen wadi]

how is 6/x^2 = 6x^-2

[native inlet]

$x^{-1}=\frac{1}{x^1}$

[warm shale]

XxMrFancyu2xX

[fallen wadi]

ok I think I get it. thanks

.close

[obtuse pebble]

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[native inlet]

yw!

[obtuse pebble]

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[opaque galleon]

For every point P(a, b, c), there corrresponds a vector whose position representation has
terminal point at P; that is, the vector ⟨a, b, c⟩. Thus, there is a one-to-one correspondence
between the set of vectors and the set of points in R3

Can someone explain to me what this is saying, I can't understand it

[opaque galleon]

🙏

[royal basin]

do you understand what a point is and what a vector is

[opaque galleon]

yeah

[royal basin]

the paragraph says there is a one to one correspondence between those

do you understand what that means

[opaque galleon]

is it like

$P(1,2,3)
\ \vec{v} = \left\langle 1,2,3 \right\rangle$

[royal basin]

notation is a bit bad

but yes sure

\langle and \rangle, or \left< and \right>

[warm shale]

steamhahasteamhaha

[opaque galleon]

there

but what is a terminal point?

I don't understand

what is that

is it like endpoint

[royal basin]

strange how you ask only about "terminal point" and not about "initial point" as well

starting point and ending point

you know the visualization of vectors as arrows right

[opaque galleon]

yeah

from physics

[opaque galleon]

does it also mean terminal point is unique and but initial point is not

[royal basin]

no

it does not say anything of this sort

[opaque galleon]

oh okay

nvm

[opaque galleon]

If one component of a vector is zero, the vector lies on a coordinate plane. In particular, if
the third component is zero, the vector is on the xy-plane and we simply write ⟨a, b⟩.

what if 1st component is zero or 2nd component is 0

[royal basin]

nothing

but also this is kind of an abuse of notation you're getting taught here

viewing R^2 as being a subset of R^3

it's kind of questionable

[opaque galleon]

😦

[royal basin]

also just fyi there exist ways to format your text to make it actually look like a quote

compare:

This text is quoted from a textbook, or notes, or something of this nature.
vs:

This text is quoted from a textbook, or notes, or something of this nature. But it
looks like I'm just saying it myself, with some weird line spacing.

how what

[opaque galleon]

nvm

[opaque galleon]

what does the double bars mean

[royal basin]

magnitude, or length, or norm

(three different names for the same thing)

[opaque galleon]

oh then what is single bar

$|\vector{A}|$

[royal basin]

absolute value, specifically for real (or complex) numbers

[warm shale]

steamhahasteamhaha
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[opaque galleon]

ohhh yeah

bruh

in physics they use single bar

[obtuse pebble]

@opaque galleon Has your question been resolved?

[obtuse pebble]

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[shadow lava]

Technically are these both exactly the same? Brackets are necessary or not necessary?

[solid oxide]

In this case brackets aren't necessary

[royal basin]

matrix multiplication is associative

so no those brackets are redundant

[shadow lava]

But also not wrong if you include brackets?

[solid oxide]

Yeah

[shadow lava]

OK ty

[royal basin]

you can include brackets, and sometimes terms (or factors) are bracketed a certain way to illustrate a point

[solid oxide]

np

[shadow lava]

.close

[obtuse pebble]

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[sacred walrus]

Hello. I have a geometry question. I need to calculate the radius of a thick circle like that and also implement some things in Computer Graphics.

Which line shows the right radius? and if you know any references i could use in my report. Thank you.

[royal basin]

a thick circle...? so an annulus?

why do you need only one number to serve as its radius

[sacred walrus]

My task is to create a circle and be able to change its line "thickness". I need to keep the radius as it was at start. So when i just increase the linesize i believe the blue line shows the correct Radius. But if pink line is true i am mistaken

[tardy epoch]

You're overloading the word radius. What you've drawn in black is what Ann said, an annulus that has two radii.

If you want to keep the same average value for the two radii then the blue is correct. If you want to keep the same inner radii, then pink is correct

[sacred walrus]

I see, so there is no mistake in taking pink or blue as far as i mention what you said about average or inner right?

[tardy epoch]

I don't know what you mean by mistake

You haven't told us the exact question

[sacred walrus]

The whole thing is just an opengl project:
Write a computer program in C++/OpenGL programming language that implements the circle process. The user will be able to interactively and in real time change the coordinates of the center (xc, yc), the radius (r) and the thickness of the drawing line (size). At each change of these values the circle must be redrawn. The calculations must be done in a mathematical way.

My professor said beware the radius when changing the line thickness so... That's why I am asking

[tardy epoch]

Then you have to define for us what a radius of an annulus is

It could be the average of the two radii, inner radius, or outer radius, or something else

Or define the thickness of a "circle"

[sacred walrus]

So there is not something standard for this cause an annulus wont have 1 radius like circle does right? and a thick circle would be an annulus?

[tardy epoch]

A circle does not have any thickness

[sacred walrus]

Is there a way to find a mathematical proof for this? To include the fact in my report as a fact? Cause i don't seem to find anything except the 2 radii of an annulus

[tardy epoch]

These are just definitions or conventions

Graphics or design resources will be more useful

[obtuse pebble]

@sacred walrus Has your question been resolved?

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[sacred walrus]

Thanks a lot you reallly helped.

[obtuse pebble]

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[tulip barn]

What happens if my amortization schedule does not hit 0?

[tulip barn]

Like what can I conclude with that

[brisk matrix]

this sounds like an accounting question

[oak bolt]

Doesn't it just mean that the last payment will be smaller than the regular payments?

[obtuse pebble]

@tulip barn Has your question been resolved?

[obtuse pebble]

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[tulip barn]

.reopen

[obtuse pebble]

✅

[obtuse pebble]

@tulip barn Has your question been resolved?

[oak bolt]

If you go one more step does it go negative?

It would be nice to know what the columns represent

[tulip barn]

Left represents the reduction of the loan balance, right column represents the loan balance itself

It's like the amortization schedule in western countries

But for some reason, ours is different

Here are the columns

[brisk matrix]

@tulip barn is this an accounting question

[obtuse pebble]

@tulip barn Has your question been resolved?

[obtuse pebble]

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[left cargo]

can someone explain this please

[shut marlin]

So factorial is a recursive function, that means if you minus what goes in by 1, the result is the same as the previous one

[left cargo]

ok

[shut marlin]

So (r-1)! times r will be r!

[left cargo]

r! = r x (r-1)!

[shut marlin]

Exactly

[left cargo]

yh

i got that

[shut marlin]

And so we have the first fraction being r on r!

[left cargo]

how

how does 1/(r-1)! go to r/r!

[shut marlin]

You can turn a fraction into another fraction by multiplying both the numerator and the denominator by the same number

Which is equivalent but sometimes easy to work with

So in this case if we have the denominator to both be r! it is easier to carry on

[left cargo]

yea

[shut marlin]

So we multiply both number by r and 1/(r-1)! becomes r/r!

These two are equivalent

Because 1*r=r

And (r-1)!*r=r!

[left cargo]

mhm

[shut marlin]

And once we have the same denominator, we can perform the subtraction

That is, (r-1)/r!

[left cargo]

oh because r!/r! is 1 so we dont change the actual fraction

ok

cheers mate for that, i just have never manipulated factorials before so it can be a little confusing

but you are a great teacher thank you ❤️

[shut marlin]

Remember to type .close

[left cargo]

.close

[obtuse pebble]

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[tired nacelle]

Intergal of (x⁴(lnx)²)

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[limber quartz]

did you have a question

[tired nacelle]

I should use DI method

But don't know how to start

[limber quartz]

ok

so DI method is a faster way of doing Integration by Parts multiple times

the process ends either when the derivative ("D") part goes to zero

[tired nacelle]

@limber quartz

[limber quartz]

or when you get what you started with for int. v du

[limber quartz]

we know that derivatives of polynomial-types eventually go to zero

...but integral of (lnx)^2 makes me a little nervous

in situations of uncertainty, I check a table of integrals. Or rather, I would, in the days before wolfram alpha 😉

meh

you know

I think you should differentiate (lnx)^2

and integrate x^4

since integrals of polynomials are easy

and the integral of (lnx)^2 is nuts

[tired nacelle]

Yeah , just i wanna try to get integral of (lnx)² 😅

[limber quartz]

I don't know how to do that or if you should even try doing that to solve this

instead, I would set it up like this

D       |   I
--------|-------
(lnx)^2 |  x^4 dx

do those columns

[tired nacelle]

Yeah

But if i try to go to zero (for x⁴)

🤔

And integral ln(x)²

[limber quartz]

I'm struggling too but gimme a sec

[tired nacelle]

Oh it's hard 😂

[sage geode]

How about first substitute for lnx and then do integration by parts?

[limber quartz]

u            |   dv
-------------|-------
(lnx)^2      |  x^4 dx
2lnx/2       | (1/5)x^5
2(1-lnx)/x^2 | (1/30)x^6
(4lnx-6)/x^3 | (1/210)x^7

[tired nacelle]

So where i should stop?

[limber quartz]

I'm sure any other idea is a better idea than what I'm doing

because I'm just hoping we circle back at some point and it's a long shot not happening

[tired nacelle]

How

[sage geode]

t = lnx
dt = dx/x
dx = xdt = e^t dt

So you are basically integrating e^4t * t^2 * e^t dt or e^5t * t^2 dt

Can you do that?

[tired nacelle]

Wait, i will try rn

[tired nacelle]

Well , but why dt= dx/x and not (d(1)/x) 😅 bc (lnx)' = 1/x

[sage geode]

Huh? So dt = 1/x * dx

Which is the same as dx/x

[tired nacelle]

Oh 😅

[limber quartz]

There's my only contribution here--verifying Bean

[tired nacelle]

We don't wrote dx here 🥲 so it's something new for me

[limber quartz]

You should write it if it's there

[tired nacelle]

Yeah

[tired nacelle]

Get it 😁

[limber quartz]

DI is really easy now though

[tired nacelle]

So i should now just integral by T then i replace the results with x

[tired nacelle]

Yeah true

[limber quartz]

Yeah, when you're all done

[tired nacelle]

Alright, tysm

.close

[obtuse pebble]

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[vague otter]

A man has 1,000,000 dollars and buys baseball cards for 325 dollars, every 10 same cards he gets will max out his card and the rest he will receive are extra, how many extra cards will he receive?
V player has a 5.33% chance of being found
X player has a 4.67% chance of being found
Y player has a 10.25% chance of being found
Z player has a 79.75% chance of being found
help?

[obtuse pebble]

@vague otter Has your question been resolved?

[obtuse pebble]

@vague otter Has your question been resolved?

[vague otter]

yuo

[obtuse pebble]

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[obtuse pebble]

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[fiery rivet]

i need help again

i didnt find the answer

[obtuse pebble]

@fiery rivet Has your question been resolved?

[fiery rivet]

<@&286206848099549185>

[solar slate]

You have the midpoint right

I think if u set up an equation using pythag

I think the midpoint was (-2,2)

In this case it would be sqrt(-2-x)^2 +(2-y)^2 =3/2sqrt10

I halved the 3sqrt10 bc its the midpoint

[obtuse pebble]

@fiery rivet Has your question been resolved?

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[frail depot]

What does it actually infer to transpose the null space ahaha?

[frail depot]

Because here I obviously just solve null A

But not null A^T

So would I need to transpose the reduced echelon form?

[trail musk]

Can you translate

[frail depot]

It's just finding the null space transposed

So I set Ax=0

and solved

And I have just written what I did but not important xD

[trail musk]

Why are you talking about the transpose at all

Nul(A^T) gives you the orthogonal space to the column vectors of A.

[trail musk]

Yes

[frail depot]

Because I am solving for the orthogonal complement

So I need null A^T

[trail musk]

Mind just translating the exact wording of what the question is

[frail depot]

Bestem en basis for U komplement (det ortogonale komplement til U).
Determine a basis for U complement (the orthogonal complement for U)

[trail musk]

Ok now I understand. That didn't seem to have anything to do with your image here, somewhat confusing

Yes, to find the orthogonal complement take Nul A^T

[frail depot]

Well, I wrote it as the column space matrix

And then put it in echelon form?

And now my question is as ..

[frail depot]

What to do now?

[trail musk]

Doesn't seem like you've actually posted the question you're working on

Where is U defined?

[frail depot]

What is the problem?

I need to find null A^T

[trail musk]

So that is your matrix U?

[frail depot]

Yes

Written as a column space matrix

[trail musk]

Great

[frail depot]

So, I put it in echelon form

reduced echelon form

[trail musk]

Yep

[trail musk]

Take the transpose first

[frail depot]

Then we're here

[trail musk]

Alright

[frail depot]

The transpose?

WHat?

[trail musk]

So what's the problem?

[frail depot]

Well I only get one of the right answers

I am missing one

there's supposted to be two

And what do you mean transpose it?

Do I pick it as the column space matrix, and transpose it? lmao? 😂

Then it's the same as the row space matrix?

[trail musk]

Well thats because you didn't take the transpose of the matrix

Let me show you

You should have

[frail depot]

Do I pick it as the column space matrix, and transpose it? lmao? 😂 Then it's the same as the row space matrix right?

[trail musk]

-3 0
2 2
6 - 3

Row reduce this

[frail depot]

He said I could pick depending on which I want to solve

It's literally also what he does in the result list

[trail musk]

Yep

Theres multiple ways to do this

[frail depot]

Yes, so I write it as a column space matrix, but you're saying to transpose that, but then it comes the row A (row space matrix)

[trail musk]

Also what do you mean by missing one?

[frail depot]

Oh, I thought we wrote "or" but I can see now we just multipled the second one with 2

[trail musk]

This is right. You just have to account for the fact that there is a constant multiple attached.

2×(3,3/2,1) = (6,3,2)

[frail depot]

So the basis is just right?

[trail musk]

Yes

[frail depot]

But so all the things you said with transpose I can forget right? Like you can write it as the column space matrix and solve for that, or the row space matrix

Either way doesn't matter, but I feel like if I then tranpose them it doesn't make sense to pick because then you transpose and pick the other one

like you know what I mean 😂

I pick row A transpose it in this case and get col A anyway

SO like what's the point

Whereas if I solve for col A

I get null A and I have to transpose the vectors in there to get null A^T

and then we end up having 3 3/2 1

[trail musk]

Just refer to this

I don't have the context and I don't want to confuse you

[frail depot]

Nono true

But I also want to understand it

But so

say I pick this, right?

I write is a the column space matrix

And then reduced echelon form

And then that's the transpose part?

[trail musk]

Why don't you try putting what you circled in an English sentence

[frail depot]

Or no

[trail musk]

I don't think you understand the statement

[frail depot]

The col A complement is equal to the null space transposed

?

[trail musk]

The orthogonal complement of the column space of A is equal to the null of A^T.

[frail depot]

which i guess is calculating the subspace that is 90 deg to our column subspace

[trail musk]

the column space of A is just the span of the column vectors of the matrix A

there's no "calculating" the column space, it's given

[frail depot]

yues, but the basis

we get

Is the basis for the subspace that is 90 deg orthogornal

Isn't it?

[trail musk]

what was your original matrix A?

[frail depot]

A subspace U

Of 2 vectors, u_1, u_2

[trail musk]

take a screenshot of the original matrix

[trail musk]

ok finally that makes more sense

try to actually post the original question next time haha

saves us a lot of time and confusion

[frail depot]

sorry haha

fair sorry

But I feel like what I've done is correct so far

I guess i just don't see where the transpose part comes in

Like I never actually tranpose the null space

[trail musk]

yes. so we have:
A =
-3 0
2 2
6 - 3

[frail depot]

I write is as the column space matrix .. reduce echelon form ... free variables and vectors ... and the result

[trail musk]

A^T =
-3 2 6
0 2 -3

does that make more sense now?

we DID take the transpose

when we turn it from a 3x2 matrix into a 2x3 matrix

[frail depot]

Aah, because col

col is A=(u1, u2)

right

ANd then A^T

A

U1
U2
Instead

as rows instead of columns

[trail musk]

yes exactly

[frail depot]

I see

sooo

Just to make sure

So, if we'd picked the row A

It would've literally just been
A

U1
U2

from start

No need to transpose

And I think that was what Deterix was trying to tell me

in the other channel, which I thought I understood (kind of also did) but now I think it makes a lot more sense

[trail musk]

yes. if you want the orthogonal complement of the ROW SPACE, just take the nul of the ORIGINAL matrix

[frail depot]

yep yep!

Okay thank you so much!
Made it a lot more clear now! 😂

So ye thanks for taking the time to explain it and not getting to frustrated with me 😂 ❤️

[trail musk]

next time just post the original question

it's a lot simpler to help without all these unrelated things

but all good

👍

[frail depot]

Yes, I promise I will do!
I don't know why I just thought it wasn't important for this type of question since I thought the "sub" question was sort of encapsulated in its own but I see now it isn't so will do!

Anyway, thanks again! ❤️

.close

[obtuse pebble]

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[pale mortar]

there is something wrong with what i did or its fine?

[brisk grove]

Do you know what's A * A^-1?

[pale mortar]

yes

and

[brisk grove]

In your second like, you suddenly ignored it.

It isn't O, it's the identity matrix

[pale mortar]

oh right

[pale mortar]

there is something more that i have wrong?

[brisk grove]

let me see

from the second to third line,

why did you switch the places of A and B^-1

[pale mortar]

mistake

that was the thing

[pale mortar]

and how do i do this one?

asking for (A^-1 X A)^-1

[brisk grove]

you did it correct when it was 2 matrices

switch the order and take the inverse

(ABC)^-1 = C^-1 * B^-1 * A^-1

[pale mortar]

okey thanks!

.close

[obtuse pebble]

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[brisk grove]

👍

[obtuse pebble]

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[obtuse pebble]

Please don't occupy multiple help channels.

[open wharf]

I need help please

idk if I did this right

work for it:

[brave bramble]

I see you divided by h + 232 in one step.

Is that always a legal move?

[open wharf]

im pretty sure

you can divide a row by a scalar

[brave bramble]

You can, as long as you aren't dividing by 0.

[open wharf]

true

so im not sure if its -24 or -232

or.....

[brave bramble]

So yeah, that step becomes illegal if h = -232

[open wharf]

cuz I had this other problem with the following work and this was the right answer

[brave bramble]

And the matrix can't be reduced

[open wharf]

and the answer was 6

so following the same login it gotta be -232 or -24

so you are saying its -24?

[brave bramble]

I don't follow where -24 is coming from

[open wharf]

so basically

[open wharf]

mb mb

[brave bramble]

But I am saying the matrix won't reduce if h = -232

[open wharf]

oh ok

so basically this was the work for this question:

and the answer was 6 when we got the h-6

so here:

our work was

so im feeling since we get an h-24, it should be 24

wadya think @brave bramble

<@&286206848099549185> pls help

[brave bramble]

The division is what's important

You're dividing by h + 232, which is legal, unless h is -232.

You'll notice in the other question you've divided by h - 6, so the matrix can't be reduced if h = 6.

[open wharf]

oh

so it is -232?

if I understand correctly

[brave bramble]

Ye

[open wharf]

ok thanks

[obtuse pebble]

@open wharf Has your question been resolved?

[obtuse pebble]

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• Show your work, and if possible, explain where you are stuck.
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[spark jungle]

Bruh

[timid silo]

what

[spark jungle]

i already claimed this

[obtuse pebble]

Please read #❓how-to-get-help

[timid silo]

oh shi

i posted that at the same time as you lol

[spark jungle]

lol

oops

[timid silo]

mb

[spark jungle]

its all good

[spark jungle]

im confused on the second question

the U

what does that mean

[native inlet]

A union B

[spark jungle]

union?

[native inlet]

what points in the data set are contained within A and B

the intersection

[spark jungle]

34?

its both

[native inlet]

oh wait

[spark jungle]

but thats the same as the first questino

[native inlet]

wrong symbol smh

[spark jungle]

?

[native inlet]

that's the intersection symbol

[spark jungle]

The U is?

[native inlet]

$\cap$

[warm shale]

XxMrFancyu2xX (anti glomed)

[native inlet]

this is the intersection symbol

[spark jungle]

No the second question

[native inlet]

ah ok

[spark jungle]

the first is right

[native inlet]

the U is the union symbol

[spark jungle]

$\uncap$

[warm shale]

carterr

$\uncap$
```Compilation error:```! Undefined control sequence.
<recently read> \uncap 
                       
l.57 $\uncap
            $
The control sequence at the end of the top line
of your error message was never \def'ed. If you have
misspelled it (e.g., `\hobx'), type `I' and the correct
spelling (e.g., `I\hbox'). Otherwise just continue,
and I'll forget about whatever was undefined.```

[native inlet]

$\cup$

[warm shale]

XxMrFancyu2xX (anti glomed)

[native inlet]

This is the union symbol

[spark jungle]

What does it mean?

[native inlet]

it means combine the sets

so $A\cup B$

[warm shale]

XxMrFancyu2xX (anti glomed)

[native inlet]

are the things in set A combined with set B

[spark jungle]

do i change the denominator

its wrong

[native inlet]

;-;

[spark jungle]

i added them

i think the denominator is wrong

oops

[native inlet]

are A and B mutually exclusive?

[spark jungle]

What does that mean

idk what to do

[native inlet]

no they aren't yes ok hang on—I have completely forgotten how to do this but

[spark jungle]

lol

[native inlet]

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

[warm shale]

XxMrFancyu2xX

[native inlet]

idk where this formula comes from

but

[spark jungle]

lol

[native inlet]

big font size

anyways

what is the new answer you get?

[spark jungle]

wait

0?

i add and subtract

[native inlet]

uhh you shouldn't have gotten 0...

[spark jungle]

109 + 38 - 109 + 38?

[native inlet]

What is $P(A\cap B)$ again? (recall your previous answer)

[spark jungle]

147/280
\

147/280

[native inlet]

https://media.discordapp.net/attachments/903430332324405288/1112904117631860838/image.png?width=1440&height=1153

take a look at the top question

[warm shale]

XxMrFancyu2xX

[spark jungle]

34/280

34/280 - 147/280

[native inlet]

slow down a little 😅

[spark jungle]

ok

[native inlet]

ok so we have $P(A\cap B)$, now we need $P(A)$ and $P(B)$ what are those?

[warm shale]

XxMrFancyu2xX

[spark jungle]

109 and 38

[native inlet]

not quite those are the values

but what's the probability of each?

[spark jungle]

109/280

38/280

[native inlet]

yes!

now we use $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

[warm shale]

XxMrFancyu2xX

[native inlet]

and we get the probability of A union B

[spark jungle]

so

147/280

34/280

113/280

?

[native inlet]

and now we hope that's right or otherwise I've just embarrassed myself 😂

[spark jungle]

it doesnt work

[native inlet]

ah great

[spark jungle]

lmao

itsd ok

dont be embarrassed

what should i do

[native inlet]

idk what went wrong tbh

omg

P(A) and P(B) are not 109/280 and 38/280

P(A)=(109+34)/280

[spark jungle]

lol

[native inlet]

P(B)=(38+34)/280

omg

simple mistake bruh

[spark jungle]

wait what

109+38/280

= 139/280

-34/280

105/280

doedsnt work

[native inlet]

ok so P(A)=143/280

right?

P(B)=72/280

right?

[spark jungle]

ye

no?

109 and 38

[native inlet]

A is the entire circle

109+34

[spark jungle]

oh

whats b than

[native inlet]

the other circle!

[spark jungle]

72

[native inlet]

yes!

so then P(A)=143/280 and P(B)=72/280

[spark jungle]

109+34+72-34

=181/280

works

thanks

[native inlet]

yw man have a good day!

:))

[spark jungle]

@native inlet r u here

[native inlet]

yep

[spark jungle]

ok so

F is

female is

109/280

left hand is 38/280

how do i find right hand

[native inlet]

https://media.discordapp.net/attachments/903430332324405288/1112904117631860838/image.png?width=1440&height=1153

[native inlet]

how is set B defined?

[spark jungle]

the number of left-handed students in the same year group (set B)

[native inlet]

so then what would be people who are right handed?

[spark jungle]

what does 99 represent

[native inlet]

students who were neither left-handed nor female

they're in neither set

[spark jungle]

so

right is in there

but also male is

so

I don't know how I am supposed to find the number of right handed people from that graph.

[native inlet]

ok think about this

do you agree that people are either left or right handed?

[spark jungle]

yes

[native inlet]

so if all the people that are left-handed are the number in set b

[spark jungle]

38

[native inlet]

what is true about all the other people outside of set b

[spark jungle]

they arent left handed

[native inlet]

hence

they must be....

[spark jungle]

but they can also be male

or femla

[native inlet]

exactly

[spark jungle]

female

[native inlet]

but their right-handed

[spark jungle]

yes

wait

wat

oops

🤦‍♂️

[native inlet]

lmao

[spark jungle]

i got confused

242/280
?

its incorrect

wait

hmm

280-38 left handed

[native inlet]

no

[spark jungle]

What is the probability that the student is right-handed given that they are female?

so they have to be female

109 females

242 right handed

so

i need to subtract males

[native inlet]

there are NOT 242 right-handed ‼️

[spark jungle]

280-38

subtract left handed

[native inlet]

there are not 38 left-handed ‼️

[spark jungle]

and the number of left-handed students in the same year group (set B)

38+34?

what 😭

[native inlet]

so there are 72 left-handed persons‼️

[spark jungle]

and 143 females?

[native inlet]

yep!

[spark jungle]

71/280?

females-left hand person

but the 62 left handed people

can be male

also

so

left handed females: 34

143 females

143-34 = 109

109/280 is wrong

makes no sense

[obtuse pebble]

@spark jungle Has your question been resolved?

[spark jungle]

anyone help

[obtuse pebble]

@spark jungle Has your question been resolved?

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[vocal cove]

help

[rich plume]

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[rich plume]

What do you want to do? Simplify?

[vocal cove]

i want to know which one i do first

like the square root

[rich plume]

What do you want to achieve through this equation??

[vocal cove]

do i solve the questions in it and then square root final answer?

or all

im trying to help someone despite knowing nothing

[ruby path]

What's the original question

[rich plume]

Ask them the complete question

[vocal cove]

?

[rich plume]

You have an equation without any context

[vocal cove]

k

[obtuse pebble]

@vocal cove Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

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• Show your work, and if possible, explain where you are stuck.
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• Be polite and have a nice day!

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[crimson torrent]

hlo can someone help me understand this question please,
let A (3,-4) , B(1,2). Let P (2k-1 , 2k+1) be a variable point such that PA + PB is the minimum. Then k is

[crimson torrent]

i didn't get what it means by PA + PB is the minimum ?

[brave bramble]

I also don't know. The minimum of what?

[crimson torrent]

idk its just written as PA + PB is the minimum

[brave bramble]

Doesn't help that you can't order vectors

[crimson torrent]

Its coordinate geometry if that gives any idea ?

[brave bramble]

No lengths in there, or anything?

[crimson torrent]

i have the answer to that question and it says

the points are cooliner

one sec

[brave bramble]

That is very broken

[crimson torrent]

im legit confused lmao

it says by triangle inequality

[brave bramble]

I'm thinking they mean "when is |PA| + |PB| minimized?"

That is, the length of both vectors individually, then summed. You can only minimize it by making the three points collinear

[crimson torrent]

oeh

[brave bramble]

What they've actually asked is not English

[crimson torrent]

hmm i see

ig i will skip on this instead of wasting time

thank u for trynna help

.close

[obtuse pebble]

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[subtle jasper]

Trying to find the derivative of ln(arccosh(4x)) but the answer i get is different to the answer sheet

[native inlet]

why not just $\frac{\mathrm{d}}{\mathrm{d}u}[\ln(u)]\cdot\frac{\mathrm{d}}{\mathrm{d}x}[\text{arccosh}(4x)]$?

[warm shale]

XxMrFancyu2xX

[subtle jasper]

Wanted to try implicit differentiation

[native inlet]

I see well when your undoing ur y

you only have arccosh(4x)

you missed your ln

[subtle jasper]

Ohhh

Thanks 🙏

[native inlet]

yw! :))

[subtle jasper]

.close

[obtuse pebble]

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[winter spruce]

hi has someone here had pure maths in highschool? i just wanted to talk about it a little because im taking it next year and im a little nervous and unsure

[brisk matrix]

that's a very vague class name

do you know what the topics covered will be?

[timid silo]

Any particular curriculum

[winter spruce]

no idk what topics will be covered, im a homeschooling student at impaq

[brisk matrix]

well it's tough to discuss the course without knowing what it'll talk about

if you can find out then maybe someone can discuss it with you, and if so would you mind moving it to #math-discussion

[winter spruce]

ok i will do so, thank you

[obtuse pebble]

@winter spruce Has your question been resolved?

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[obtuse pebble]

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[timid silo]

need help finding the integral

[timid silo]

I know my antiderivative is wrong but i can't think of another way to do it

[runic void]

@timid silo

[timid silo]

?

[runic void]

do a trig sub

[timid silo]

what's a trig sub

[scarlet mason]

you dont need to use a trig sub

[runic void]

Can you recognise the function as something familiar?

like say some shape?

[scarlet mason]

read what the problem originally said: "evaluate the integral by interpreting in terms of areas"

[timid silo]

not really

[runic void]

^

What’s the equation of circle with radius 6?

[timid silo]

(x-h)^2 ?

[runic void]

Equation of circle entered at origin with radius 6?

[timid silo]

area of a circle ?

pi r^2 ?

[runic void]

No, just the equation of ciricle

[timid silo]

idk

[runic void]

if you are unaware it’s fine, we can work through it

draw a circle

and mark one radius

[timid silo]

ok

[runic void]

construct a right triangle with the radius as hypotenuse

The drawing must be in a cartesian XY plane

our goal is to find the set of all coordinates which lies in the ciricle

This is like a specific example

[timid silo]

what is cartesian ?

[runic void]

The XY plane you draw graphs

[timid silo]

ok

[runic void]

Do you see 3 is the x coordinate and 4 is the y coordinate?

[timid silo]

yes

[runic void]

What theorem can we use to get to radius from x and y?

[timid silo]

X^2+y^2 ?

[runic void]

what theorem?

You should know it

[timid silo]

idk

[runic void]

What grade are u in ?

[timid silo]

calc 1