#help-10

1 messages · Page 181 of 1

obtuse pebbleBOT
royal basin
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vieta & careful manipulations to get that thing in terms of symmetric polys

wanton dagger
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So how do I use vietas formula in this question

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Formulas*

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So I expanded the brackets

astral ivy
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Unnecessary

wanton dagger
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Why?

royal basin
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this is fine as is though

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the numerator is (αβγ)^2 + αβγ(α+β+γ) + (αβ + βγ + γα) + 1

royal basin
wanton dagger
obtuse pebbleBOT
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@wanton dagger Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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wooden needle
#

Let the set T = { 2 ; 3 ; 4 ; 5; 6 ; 7 ; 8 ; 9 } . Let B be the set of 3-digit natural numbers formed from the digits of the set T . Randomly select a number from set B . Find the probability to choose a number from set B such that the preceding digit is always less than or equal to the next digit

hybrid gull
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• Show your work, and if possible, explain where you are stuck.

drifting wraith
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it's stars and bars

wooden needle
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I'm not sure how to find a 3-digit number in the set B such that the preceding digit is less than or equal to the next digit

drifting wraith
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you can also do cases, the number has two different digits (in one of two ways) or 3, or 1 (one case each)

wooden needle
#

thx, I found the answer from your suggestion

#

.close

obtuse pebbleBOT
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strong nebula
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im confused why on the first step he switch signs

tardy epoch
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Plot it

strong nebula
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ok

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and then rotating it around the x axis I use the formula pi*r^2

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I dont really get why we need to change the signs @tardy epoch

obtuse pebbleBOT
#

@strong nebula Has your question been resolved?

obtuse pebbleBOT
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verbal atlas
obtuse pebbleBOT
#

@verbal atlas Has your question been resolved?

fervent nexus
#

!help

obtuse pebbleBOT
obtuse pebbleBOT
#

@verbal atlas Has your question been resolved?

obtuse pebbleBOT
#

@verbal atlas Has your question been resolved?

obtuse pebbleBOT
#

@verbal atlas Has your question been resolved?

obtuse pebbleBOT
#

@verbal atlas Has your question been resolved?

forest sinew
obtuse pebbleBOT
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@verbal atlas Has your question been resolved?

scarlet pendant
#

Use parameteric equations

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Idk how to use calculator sites, but that could help

obtuse pebbleBOT
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feral siren
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If AB = 0 what can we conclude from this statement ?

feral siren
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If A,B both are matrix

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I asked one of my seniors but he said this doesn't mean that One of A B is a null matrix

haughty coyote
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It doesn't

feral siren
haughty coyote
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((1,0),(0,0)) x ((0,0),(0,1)) = 0

feral siren
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Oh. So we can conclude nothing from this statement?

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AB=0

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A ,B can be anything

kind hawk
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well depends on what kind of information you want to conclude

haughty coyote
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You can however say that im(B) is included in Ker(A)

kind hawk
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you can for example conclude something about the rank or nullity of these matrices

feral siren
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Ohh got it so one more question

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If A^2 = I
Why cant we say that A = I

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I is unit matrix

kind hawk
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even for numbers this wouldnt be true

haughty coyote
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A = ((-1,0), (0,-1)) is a counter example

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And there are much more complicated ones

feral siren
haughty coyote
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And many more

kind hawk
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but -I is the easiest other option

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you could also have ((-1, 0), (0, 1))

haughty coyote
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Like ((0,1),(1,0))

kind hawk
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and that's just for 2x2 and staying diagonal

feral siren
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Okay So in this statement A^2 = I
We can although conculde that detA is either 1 or -1

kind hawk
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yes

haughty coyote
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Yes

feral siren
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So that means all matrix whose det is 1 or -1

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Will satisfy

kind hawk
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no

haughty coyote
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Most certainly not

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Every rotation matrix for instance has determinant 1

feral siren
haughty coyote
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Ones that are less simple to check or obvious to come up with

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Ofc 2x2 can't get that complicated, but nxn can

feral siren
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Yessir got it , i am getting so much confused as this is related to algebra

haughty coyote
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Matrices aren't numbers. Nothing is true unless proved

feral siren
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Here is another one
If AB = AC we cant say B = C
Likee broo how does that even make sense

haughty coyote
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Not every matrix is invertible

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That's your problem

kind hawk
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again, not even true for numbers. if A=0 for example

haughty coyote
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As opposed to real numbers, where everything is either 0 or invertible

kind hawk
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(although granted for numbers thats the only counterexample)

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but the point is even for numbers stuff can go wrong. that's nothing new

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just that now for matrices stuff can be even worse

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AB=AC is equivalent to A(B-C)=0 which is again of the form "AB=0" which we had earlier

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from which you cannot include B-C=0, aka B=C

feral siren
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Oh true
I am new to this chapter so it will definitely take me some time to digest the concepts

kind hawk
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yes thats normal

feral siren
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Thank you both KEK

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.close

obtuse pebbleBOT
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kind hawk
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do lots of examples

feral siren
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Yeee will make sure

obtuse pebbleBOT
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timid silo
obtuse pebbleBOT
timid silo
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I wrote the derivative I got in red

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Can someone please explain why the answer in blue is -sec^2xsinx

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I used chain rule and multiplied the negative at the front, subtracted 1 from the power then multiplied by the derivative of the inside cosx-> -sinx

hollow river
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Ok

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So

timid silo
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Yeah

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@hollow river

fervent nexus
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Do you want solve it using integration or differentiation

timid silo
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Differentiation

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Is the solution wrong?

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It’s the writing in blue

fervent nexus
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It is sec^2(x)sin(x)

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You took the derivative of cosx as just sinx whereas it is -sinx

timid silo
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I didn’t do that

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My writing is in red

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I’m asking if the blue writing is wrong?

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Or maybe I missed something idk

fervent nexus
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The blue part's differentiation is incorrect

timid silo
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Also for this

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This integration is incorrect?

fervent nexus
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What have they integrated

timid silo
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@fervent nexus

fervent nexus
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4xcosx^2?

timid silo
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Yeah

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These are solutions but it’s written weirdly

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It shouldn’t be negative right?

fervent nexus
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No it should not be negative, and also the term should be 2sin(x^2) + c not 2sin^2(x) +c

timid silo
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Thank you

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Could I ask you 1 more last thing if you don’t mind?

fervent nexus
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No issue

timid silo
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Could you please explain these steps, I’m a bit confused

fervent nexus
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What is the question

timid silo
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I don’t get what happens after the y’ part

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I’ll send it one sec

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4b

fervent nexus
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After you found the derivative as y' = 2x,
You are substituting y = x^2 -1 and y' = 2x.

timid silo
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I don’t get the third line

fervent nexus
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The third line is the differential equation given in the problem

timid silo
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OHHHHHHH

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I was sooo confused

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I didn’t even see that

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Thank you so much 😊

fervent nexus
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If you are done, you can close this channel

obtuse pebbleBOT
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@timid silo Has your question been resolved?

fervent nexus
#

.close

obtuse pebbleBOT
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tulip anvil
#

What method am I suppose to use for this question? I can't get my head around it

obtuse pebbleBOT
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@tulip anvil Has your question been resolved?

vast musk
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the question is essentially asking what is the length of the curve for x [0,1]

obtuse pebbleBOT
#

@tulip anvil Has your question been resolved?

obtuse pebbleBOT
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crimson orbit
obtuse pebbleBOT
crimson orbit
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i just started related rates

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can someone guide me through this q?

obtuse pebbleBOT
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@crimson orbit Has your question been resolved?

crimson orbit
#

<@&286206848099549185>

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can you guys check tis out

fiery olive
#

Hey, what have you tried?

crimson orbit
#

uhhh let me send

crimson orbit
fiery olive
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What do you mean by dr/dt? What is r?

crimson orbit
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dr/dt is the rate of change

south oracle
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The angle? The area?

crimson orbit
#

i got that from the q, angle from two equal sides decreasing at rate of 0.1pi rad/sec

crimson orbit
south oracle
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Then shouldn't it be d(theta)/dt = -0.1 pi rad/s
Edit: pi

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You already have seemed to have drawn the pic and marked your angle as theta

fiery olive
crimson orbit
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oh yeah

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ill change that

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but idk what to do next

south oracle
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Represent the area as a function of theta

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Then differentiate it with t

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I believe you know how chain rule works

crimson orbit
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Area = 1/2(10)(10)sin(theta)

south oracle
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The reason why we express the area with theta

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S because we have too much to think of when we represent it as t

south oracle
crimson orbit
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and then you differentiate it?

south oracle
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With t

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Not theta

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Note that

crimson orbit
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so its gonna be like

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dA/dt = 50cos(theta) * d/dt

south oracle
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Yes

crimson orbit
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like yk

south oracle
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Chain rule:

crimson orbit
#

shouldnt it be d"something"/dt

south oracle
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dA/dt = dA/d(theta) * d(theta)/dt

south oracle
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Nothing really special

crimson orbit
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what is d(theta) here?

south oracle
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Did you learn the leibnitz notation of the chain rule?

crimson orbit
south oracle
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Oh that makes sense now

crimson orbit
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whatever i did was like what i do for implicit diff

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diff then times d/dt

south oracle
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Okay so basically (f(g(x)))' is f'(g(x)) * g'(x)

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Is it

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If we just express a= f(b) and b=g(x)

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f'(g(x)) = f'(b)= da/db

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g'(x)= db/dx

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da/ dx= d/dx (f(b)) = d/dx {f(g(x))} = {f(g(x))}'

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So yeah basically

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da/dx = da/db * db/dx

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Please review the leibnitz notation afterwards you solve this problem

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It will be used way more than the newton's notation as you learn further

crimson orbit
#

oh ok

crimson orbit
#

how would we apply that to my current prob

south oracle
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Substitute:
a= A
b= theta
x= t

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dA/dt= dA/d(theta) * d(theta)/dt

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Boom

crimson orbit
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ok

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but we cant just write it like that right

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dA has to be smth

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and d(theta) has to be smth

south oracle
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We can...??

crimson orbit
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then what do you do next?

south oracle
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What is A in terms of theta?

crimson orbit
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50sin(theta)

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but thats A not dA

south oracle
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now differentiate that with theta

crimson orbit
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is it 50cos(theta)?

south oracle
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dA/d(theta) is just A'(theta) when A is basically A(theta)

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dA/d(theta) is NOT a fraction

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We will later learn that it kinda is but

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Not now

crimson orbit
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oh alright

south oracle
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Oh have you learnt about differentials?

crimson orbit
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yeah

south oracle
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I see

crimson orbit
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but we just learn like

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A and then make it A' and then A''

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we dont use fraction much(dA/d(theta))

south oracle
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We define dA to be A'(theta)d(theta)

crimson orbit
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so its hard to understand

south oracle
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You can see delta x is just dx when delta x goes to 0

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If y= f(x), we can define dy =f'(x)dx

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The important part is

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the f' is in terms of x

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And y is here, a function of x

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That's why we state dy/dx

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To clarify what we differentiate with

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Now, if we apply that to our problem

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Since A= f(theta)= 50sin(theta),
dA= f'(theta)d(theta), is it?

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The Liebnitz notation of dA/d(theta) is just what you get when you divide dA with d(theta)

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Same goes with d(theta)

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You know here that theta is a function of t, right?

crimson orbit
#

yeah

south oracle
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so if we say theta= g(t)

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d(theta) = g'(t)dt

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Therefore dA= f'(theta)d(theta)=f'(theta)g'(t)dt

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dA/dt=f'(theta) *g(t)= dA/d(theta) * d(theta)/dt

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There

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This is what chain rule is, at least what I understood

crimson orbit
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then..

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i think

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50cos(theta) * d/dt is correct

south oracle
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Actaully, d/dt (50cos(theta))

crimson orbit
#

thats the same thing no?

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just rearrange

south oracle
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Kinda but

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It's generally preferred to be at the left

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Since dA is different from A

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d is kind of an operator, not a "number"

crimson orbit
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alright

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then what do we do next

south oracle
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find dA/d(theta)

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We know what d(theta)/dt is

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A= 50sin(theta)

crimson orbit
#

ok

south oracle
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So what is dA?

obtuse pebbleBOT
#

@crimson orbit Has your question been resolved?

obtuse pebbleBOT
#
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plain monolith
#

Anyone can help me with this?

obtuse pebbleBOT
plain monolith
#

Wait wait

#

Number 23

fervent nexus
#

,rotate

warm shaleBOT
plain monolith
#

I figured out thank you helping @fervent nexus 🙏

#

. Close

#

,close

#

.close

fervent nexus
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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steep trellis
#

Which one the right way

obtuse pebbleBOT
timid silo
#

x+1= cos(-π/3)

steep trellis
#

Thanks

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Why not the other one

#

?

timid silo
#

How can you even do that

steep trellis
#

Idk?

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Hahaha nvm im too dumb

timid silo
#

Also

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How can cos^-1 (x+1) =-π/3 ?

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Range of cosinverse is [0,π]

steep trellis
#

I also dont know about these questions lmao

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Teacher just wants to find x

timid silo
#

No solutions is the answer of that

steep trellis
#

Thats what im saying too

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Hahaha

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Thanks

#

.close

obtuse pebbleBOT
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tacit imp
obtuse pebbleBOT
tacit imp
#

quick question, why are +- sqrt5 excluded values as well

solemn plank
#

wdym by "excluded values"

tacit imp
#

excluded values of x

solemn plank
#

you means values of x as solutions?

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assuming its even defined at that value

timid silo
#

Isnt x not equal to +-5 , 2 , 0 ?

tacit imp
#

no i mean like x cant be +- 5 because then in the first fraction we would divide by 0 which is impossible

solemn plank
#

ah

tacit imp
#

yes but i put it in a calculator and it said that +- sqrt5 is also an excluded value

solemn plank
# tacit imp

the +- sqrt 5 is only concerning in the second fraction

tacit imp
#

yes i get it

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but x:(a/b)= x*(b/a)

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so why should x^2-5 be a part of the excluded values

solemn plank
#

hm

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you could try simplifying it to make sure the polynomial at the bottom doesnt equal 0 at +-sqrt5

solemn plank
tacit imp
#

alright thanks

solemn plank
#

dont mind the ^-1

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i wrote it wrong

tacit imp
#

its all good

#

.close

obtuse pebbleBOT
#
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floral dagger
#

Self explanatory, no clue how to solve :(

obtuse pebbleBOT
willow fjord
#

Hi I need help

obtuse pebbleBOT
#

@floral dagger Has your question been resolved?

obtuse pebbleBOT
#

@floral dagger Has your question been resolved?

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
steep flax
steep flax
obtuse pebbleBOT
#

@floral dagger Has your question been resolved?

obtuse pebbleBOT
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worldly briar
#

Can sb pls help me with Linear Transformation?

worldly briar
#

I'm not getting forward with this questions:

tardy epoch
#

there are two questions

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where first do you get stuck

worldly briar
#

with the first one

tardy epoch
#

do you know the definition of linear operator

worldly briar
#

It is a mapping between vector spaces that respects the operations of vector addition and scalar multiplication, right?

tardy epoch
#

yes

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equations are more useful though

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a "vector" in this case is an n-by-n matrix

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and scalar is just a real number

worldly briar
#

ahh ok thank you, but how can we prove that?

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we have to show that it is additivit and homogeneity, right?

tardy epoch
#

just plug general "vectors" into them and see the definition is satisfied

worldly briar
#

i'm sorry i don't know what you mean😅

obtuse pebbleBOT
#

@worldly briar Has your question been resolved?

timid silo
#

Its ok youll get there!

obtuse pebbleBOT
#

@worldly briar Has your question been resolved?

stoic harbor
#

what is -1-8 and how do I solve it

obtuse pebbleBOT
#

@worldly briar Has your question been resolved?

tardy epoch
obtuse pebbleBOT
#
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desert hull
#

can someone explain to me how this was calculated i dont get it

pastel sphinx
#

could you give the question for some context?

desert hull
pastel sphinx
#

they differenciated A

#

to get A derivative

#

have you done calculus before?

obtuse pebbleBOT
#

@desert hull Has your question been resolved?

desert hull
pastel sphinx
#

what did you not understand

#

once they got the derivate

desert hull
#

im talkin bout da calculations here

pastel sphinx
#

they just dropped in the value of t

desert hull
#

like when i calculate it at this step i dont get the same answer

pastel sphinx
#

well A0 is a constant right

desert hull
#

ye

pastel sphinx
#

if there are still further discrepancies i would say either the Markscheme is wrong or there is some physics behind this that i dont know

desert hull
#

nvm i get it

#

i read the 1/20 as 1/25

#

thats why

pastel sphinx
#

what is the A0 constant

pastel sphinx
desert hull
#

it made me get the wrong answer

#

aight

#

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rustic violet
#

3x + x + 5y - y = , needs to be simplifyed where possible

pastel sphinx
#

ok so whats your current approach

#

what have you tried so far

obtuse pebbleBOT
#

@rustic violet Has your question been resolved?

rustic violet
#

not anything yet ;-;

#

just looked at it blankley

#

would you put it into brackets?

tardy epoch
#

$ab + ac = a(b+c)$

warm shaleBOT
#

riemann

rustic violet
#

ive got as my answer = (3x + x) + (5y + y)

#

= 4x + 6y

tardy epoch
rustic violet
#

is that the right way to approach it?

tardy epoch
#

yes

#

ah wait

tardy epoch
tardy epoch
#

which is it

rustic violet
#

the minus y is in the original question

#

but when symplified made it into a plus

tardy epoch
tardy epoch
#

according to you, 5y - y if y =3 would become 5(3) - (3) becomes 5(3) + 3 = 18

#

but 5(3) - (3) is 12

rustic violet
#

(3x + x ) + (5y-y) = 4x + 4y?

obtuse pebbleBOT
#

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dim copper
obtuse pebbleBOT
dim copper
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.close

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dusk ruin
#

you got your answer?

dim copper
#

uhm, I just figured I would read the chapter a bit more :p

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dusk pawn
#

If I have a random variable with uniform distribution: X~U[0,1]. What is the pdf of Y~U[0,X]

obtuse pebbleBOT
#

@dusk pawn Has your question been resolved?

obtuse pebbleBOT
#

@dusk pawn Has your question been resolved?

dusk pawn
#

<@&286206848099549185>

obtuse pebbleBOT
#

@dusk pawn Has your question been resolved?

timid silo
rustic violet
#

younh

timid silo
#

15?

#

16?

#

17?

#

18?

#

19?

timid silo
rustic violet
#

16

timid silo
#

'

rustic violet
#

whys that

timid silo
#

your doing that question at 16?

rustic violet
#

yea is that good or bad

gilded needle
#

in case you guys didn't notice, this channel belongs to someone else now

#

you're creating a lot of spam

rustic violet
#

sorry

rustic violet
timid silo
#

err

#

im just surprise since in my country we learn this when we r around 12-13

rustic violet
#

oh right

#

im not great accademicly anyways

dusk pawn
#

Get out of my channel

dusk pawn
obtuse pebbleBOT
#

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whole halo
#

Hi I need help with this question, I dont really know how to approach it

whole halo
#

<@&286206848099549185>

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.close

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junior nymph
#

Can someone please explain how to calculate the change of basis matrix if you are given two basis? I will send the question now

junior nymph
#

Basis 1

#

Basis 2

gleaming ridge
junior nymph
#

2->1

gleaming ridge
#

Then write the basis 2 in terms of basis 1

junior nymph
#

How would I do that? I also have calculated a coordinate vector with respect to basis 1

gleaming ridge
#

Take the first element call is c1 (from basis B`) and then write c1 as summation of elements of basis B

junior nymph
#

Okay let me try

#

Awesome! I got it! Would this still work other way around as well?

gleaming ridge
#

Yep

#

As long as they're a basis it would work

junior nymph
#

How would you calculate this?

obtuse pebbleBOT
#

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sharp sail
#

can anyone help with this question?

obtuse pebbleBOT
sharp sail
#

I’ve basically tried finding two equations for vector ON, by using two unknowns

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weak yew
obtuse pebbleBOT
weak yew
#

how do i find angle bop

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dawn sphinx
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dawn sphinx
#

Can somebody help

#

I’m stuck

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@dawn sphinx Has your question been resolved?

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timid silo
#

Im doing differential calculus with product rule im just struggling with the algebra

supple quest
timid silo
#

Im not sure where to go from here the fraction is messing me up

supple quest
#

I see

timid silo
#

sorry for not being specific its kinda the whole thing thats a bit confusing

supple quest
#

$x \frac{1}{2 \sqrt{x}}=\frac{\sqrt{x}}{2}$

warm shaleBOT
#

SirLance013

timid silo
#

whats with the x at the start?

#

i dont have that

#

ohh

supple quest
#

Im talking about one term

#

in the numerator

#

so numerator becomes $\frac{\sqrt{x}}{2}+1$

warm shaleBOT
#

SirLance013

timid silo
#

ahh ok ima go ahead and attempt the question now so do i have to close the channel or should i wait until i finished the question?

supple quest
#

If you're clear about da question you can close it.

timid silo
#

would this then be right?

#

oh sorry its flipped

twin sapphire
#

,rccw

warm shaleBOT
timid silo
#

would that be right so far?

#

<@&286206848099549185>

grave trout
#

maybe

timid silo
#

im going to try the question again thanks for the help

#

.close

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bold siren
#

basic math question

obtuse pebbleBOT
bold siren
#

im doing revision on differeantiation

#

and i encountered

#

is the 2 part of the function and what happens to it when i differentiate it

fervent nexus
#

Chain rule

obtuse pebbleBOT
#

@bold siren Has your question been resolved?

bold siren
fluid snow
bold siren
#

so if you were to differentiate it

fluid snow
#

[\frac{d}{dx}\Bigl[k \cdot f(x)\Bigr] = k \frac{d}{dx} \Bigl[f(x)\Bigr]]

bold siren
#

2cos(x^3)*(3x^2)

#

?

#

so what im reading here

#

k just dosnt really matter when differentiating

fluid snow
bold siren
fluid snow
#

Yes, you can simplify it though

#

It's just cos(x^3) * 6x^2

bold siren
#

wouldnt the (x^3) become (2x^3?)

fluid snow
bold siren
#

lol

fluid snow
bold siren
#

hang on what

#

wait

#

yea

#

you leave (x) that is attached to its function alone

fluid snow
bold siren
#

sorry?

fluid snow
#

If we had $f(x) = 2(x^2 + x)$ for example, then [\frac{d}{dx}(2(x^2 + x)) = 2\frac{d}{dx}(x^2 + x) = 2(2x+ 1) = 4x + 2]

bold siren
#

AH

#

ok that makes sense

#

ty

#

.close

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stone stone
#

I have to convert this from polar-coordinate form to rectangular-coordinate but our notes didn’t cover anything like this so I’m not sure how to approach it

stone stone
#

I’m stuck at this point but I’m not totally sure that my work is correct even here since ((1-y)/2)^2 gets kind of messy

thin pawn
#

I googled quickly and apparently you should use $x = r\cdot cos\theta$ and $y = r\cdot sin\theta$

warm shaleBOT
#

imTyp0

thin pawn
#

To build some kind of system of equation I believe

stone stone
#

Is there any way you could elaborate??

thin pawn
#

Thing is I haven‘t learned that yet. I know what polar and rectangular coprdinates are, i just don‘t know how to work with what you‘ve been given. I‘m trying to work it out at the same time as you :)

warm canopy
#

what you've done is fine, just keep going

cold rampart
cold rampart
warm canopy
#

althought you have a typo, r^2 is x^2 + y^2

stone stone
#

Oh oops

#

Okay, thank you guys!

#

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cold gulch
#

A marathon swimmer starts at Island A, swims 9.2 km to Island B, then 8.6 km to Island C. The angle formed by a line from Island B to Island A and a line from Island C to Island A is 52°. How far does the swimmer have to swim to return directly to Island A?

cold gulch
#

How do I solve

#

Can u show me

#

??

#

<@&286206848099549185>

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golden hamlet
#

determine the number of zeros of the polynomial function.

f(x) = x^3 + 2x^2 + 1

spice citrus
#

Try taking the derivative and looking at it's sign

golden hamlet
#

sorry, let me add smth more. i should solve this via Rational zero test, but at the moment i dont see a solution with it.

#

it should be 1 or -1, but both doesn't fit

spice citrus
#

Does the question ask for the number of rational zeros?

golden hamlet
#

yes it does

spice citrus
trim portal
#

it has just one real, irrational root

golden hamlet
#

ow.

dark stirrup
#

Ow indeed

trim portal
golden hamlet
#

Ok, Thanks! atm i only learnt Rational zero test so got confused.

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hearty pendant
#

imean are these values hand calculated by some formula cuz i havnt started inverse yet?

trim portal
#

usually inverse cos and sin are calculated using calculators

hearty pendant
#

ohh ohk

grim mortar
#

doritos

hearty pendant
#

ty thats all

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elfin blaze
#

anyone need math help? i help class 8,9,10 students

dapper thicket
#

<@&268886789983436800>

ruby path
elfin blaze
#

ok ok

ruby path
#

.close

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obtuse musk
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subtle whale
#

Can someone show me how to find the uncertainty on B using partial derivatives?

subtle whale
#

You can assume random values like

u0 = constant = 4.0 * PI * 10^-7
2PI = constant

B = 5.0, error 0.001
I = 10.0 error 0.002
R = 15.0 error 0.003

autumn adder
#

Oh man what did you say mu_0 was

subtle whale
#

Real value is 4PI*10-7 but I just pick random values for the sake of simplicity

obtuse pebbleBOT
#

@subtle whale Has your question been resolved?

fading quest
# subtle whale Using this method

You are finding $\sigma_B$. $I$ and $R$ are the variables containing uncertainty hence you replace $\pdv{V}{d}$ and $\pdv{V}{t}$ with $\pdv{B}{I}$ and $\pdv{B}{R}$ respectively. Analogous for $\sigma_d$ and $\sigma_t$

warm shaleBOT
#

Duh Hello

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clever plaza
#

Just started as an undergraduate and haven't studied math in a very long time - I understand how to evaluate the other f(x) problems but I am having an issue understanding how to input f(x+1)=6x-4

fierce vale
#

then simplify

warm shaleBOT
#

adamchebil33

clever plaza
#

That's where I am getting stuck sorry - where would I start the simplification?

tardy epoch
#

a(b+c) = ab + bc

clever plaza
#

so 6(x+1) = 6(1x)?

warm shaleBOT
#

AVALON??
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clever plaza
#

.close

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haughty scroll
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@haughty scroll Has your question been resolved?

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spark shore
obtuse pebbleBOT
#

Please don't occupy multiple help channels.

spark shore
#

Can somebody please shed some light on how we went from the first line to the second?

tardy epoch
#

.close

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sage dagger
#

Is there some sort of property I should start with

sage dagger
#

I mean identity

nocturne minnow
#

Probably a pythagorean related one

sage dagger
#

tan^2(x)+1=sec^2(x)

clear condor
#

ok

static beacon
#

you could prove both left and right is 1?

thin pawn
#

Usually you don‘t touch RHS

sage dagger
#

Hm

#

What can I do to the lhs

nocturne minnow
#

Turn those into terms of sin and cos

sage dagger
#

sec^2(x) is just 1/cos^2(x) right

lean dew
#

Ye

sage dagger
#

I have (1-sin^2(x))/cos^2(x) now

sage dagger
lean dew
#

Correct

sage dagger
#

Ah okay

#

I’m not sure what to do now, change the numerator?

lean dew
#

Haha uhh give me a sec i dont have access to paper at the moment

sage dagger
#

Sure

clear condor
#

i mean idk just a thing i found

sage dagger
#

Huh

#

Did I do something wrong

lean dew
#

What can you turn 1-sin^2(x) into?

sage dagger
#

cos^2(x)

lean dew
#

mhmm

sage dagger
#

So that just makes the fraction 1 but

#

That doesn’t get me anywhere

lean dew
#

Well I'm not sure if there's a simpler way

#

there probably is

#

but try doing the RHS

#

and get them equal and then you can like

#

go backwards

#

im currently trying to find another way but know you're heading in the right direction

sage dagger
#

Ah okay

#

Yeah I’m not too sure

lean dew
#

oh shit theres an easy way

#

LMFAO

#

do you have this sheet?

#

well now u do

#

what can you write sec^2(x) as?

sage dagger
#

1+tan^2(x)

lean dew
#

mhm

#

lhs becomesss

sage dagger
#

1+tan^2(x) - sin^2(x)/cos^2(x)

sage dagger
lean dew
#

and what is sin^2(x)/cos^2(x)

lean dew
sage dagger
lean dew
#

right right but now lhs just becomes 1 again

sage dagger
#

Oh yeah

lean dew
#

i just wanted to lyk theres another way cuz i didnt realize lol

#

well if u look at the sheet again

#

what is 1 equal to

#

hint hint

sage dagger
#

sec^2(x)-tan^2(x)

#

Equals to 1

lean dew
#

hint hint

#

do u notice something

#

lmao its right there

#

altho im not sure

sage dagger
#

what that

lean dew
#

would your teacher take that as an answer?

#

just directly converting it to 1

#

considering u aint never seen this sheet before

#

if so u might have to do some more steps

sage dagger
#

Wait

lean dew
#

hm

sage dagger
#

So from this

#

1+tan^2(x) - sin^2(x)/cos^2(x)

#

What am I supposed to concert

#

Convert

lean dew
#

remember sin^2(x)/cos^2(x) is tan^2(x)

#

so tan^2(x) - tan^2(x) is 0

#

you are left with 1

#

then you have to prove 1 = RHS

#

so you convert 1 to something that is equal to RHS

sage dagger
#

Ah alright

#

I gotta head to class rn

#

I’ll read everything later

#

Ty for the help

lean dew
#

take this too

#

this was the other way you were doing

lean dew
obtuse pebbleBOT
#

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obtuse pebbleBOT
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civic magnet
#

Are there any cheat sheets or tips to determine what test I should use on a series quickly? Like -1^n means i should use alternating series test, or a sin/cos in a series means to use the comparison test?

civic magnet
#

also how would I determine if 1/n diverges or conditionally converges?

lean dew
#

Courtesy of my math teacher

lean dew
#

You can google proofs that it diverges

civic magnet
lean dew
#

my teacher also uses the acronym "NO PARKING" which stands for nth term, o, p series, arithmetic/alternating, ratio, komparison, integral, nth term (again i think?), geometric

#

if thats what u were looking for

civic magnet
#

looking up harmonic rn, but can you explain rq why -1^(n+1) just turns into 1? I get the - sign but why the n+1?

civic magnet
lean dew
lean dew
#

since it's the only test for divergence

civic magnet
#

been struggling to remember

#

if you had any tips regarding what to review

lean dew
#

like

civic magnet
lean dew
#

practice wksheets or?

civic magnet
#

well notes or something to keep a look at for the most part

lean dew
#

hm

#

i can look thru my folder

civic magnet
#

thank you!

obtuse pebbleBOT
#

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civic magnet
#

.close

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glossy grove
#

(a) f(x) = 2x^3 + 3x^2 + 2x + 8
= (x+2)(2x^2 -x + 4)
From this, one real solution is x = -2
(b) Using answer to part (a) ,hence solve x^3 + 3x^2 +4x + 32 = 0

real hound
#

or like

#

Notice that the part after (x+2) is "quadratic form"?

obtuse pebbleBOT
#

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inner stratus
inner stratus
#

Is my reasoning correct?

obtuse pebbleBOT
#

@inner stratus Has your question been resolved?

inner stratus
#

.close

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rich silo
#

lol, the moment I took a look, you closed it xD

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grand schooner
obtuse pebbleBOT
grand schooner
#

Hi I need the intersection of C

#

But i dont have much info

opaque lily
#

im pretty sure it is impossible to find C without knowing B

grand schooner
#

F

#

thanks anyways

rich silo
#

B is 2A

opaque lily
#

ohhh

#

it is possible in that case

rich silo
#

Yes

grand schooner
#

you take like cos

opaque lily
#

there might be some way of using cos, but you could also find the equation for both lines then find their point of intersection with y1 = y2

jolly ginkgo
#

doesn't A look bigger than B?

rich silo
#

Well, without knowing B, it is impossible to find the intersection and thus solve the problem

#

They must have forgotten to put it

jolly ginkgo
rich silo
#

But, the drawing looks accurate, not roughly

#

We can say B=2A

jolly ginkgo
rich silo
#

whaaaat 😛

jolly ginkgo
#

A looks greater than B

#

maybe it is A=2B

rich silo
#

Are you kidding me?

#

B is after A

grand schooner
#

distance calculo works?

rich silo
#

B is after A, B is to the right of A

jolly ginkgo
rich silo
#

of course its x-coordinate is greater than A's

jolly ginkgo
#

oh you mean angle with X axis?

rich silo
#

B's x-coordinate is twice A's x-coordinate

jolly ginkgo
rich silo
#

Ohhhh, there was a misunderstanding then!

jolly ginkgo
#

a proper photo

jolly ginkgo
rich silo
#

I meant since they most likely forgot to put the x-coordinate of B

#

And the drawing is accurate

grand schooner
#

it's in spanish

#

I'll translate for you

elfin burrow
#

oh they are perpendicular

nocturne minnow
#

That's useful info

jolly ginkgo
nocturne minnow
grand schooner
#

a) find the coordinates of point C, knowing that L1 is perpendicular to L2
c) calculate de area of the triangule rectangule ABC

nocturne minnow
#

Find the equation of L1

#

Use that to find the equation of L2 because you know L1 and L2 are perpendicular

grand schooner
nocturne minnow
#

You have two points

#

You should know how to find the equation of a line given two points

grand schooner
#

oh...

#

thanks

obtuse pebbleBOT
#

@grand schooner Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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shut field
#

hi for this parametric equation i get x = 1-3k and 3+2k but the solution says this

shut field
#

it goes through the points (1,3) and (-2,5)

obtuse pebbleBOT
#

@shut field Has your question been resolved?

knotty gulch
#

does ur solution work

shut field
wispy wadi
#

your solution works too anno, take -k instead of your k

#

you get the solution you took a screenshot of

shut field
#

!close

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.close

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knotty gulch
#

cos² theta - sin² theta = 1-2sin² theta

obtuse pebbleBOT
#

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whole cipher
obtuse pebbleBOT
whole cipher
#

I plug in the number in my calc but something is wrong 😭

#

!close

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.close

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obtuse pebbleBOT
ruby path
#

When is tan x undefined

#

Yes

#

I think

#

You should stop thinking about trig in terms of triangles when you reach graphs

unique nebula
#

Strictly speaking

#

The function is continuous

ruby path
#

Do you understand the concept of radians?

ruby path
#

,w plot y = tanx cosx

unique nebula
warm shaleBOT
unique nebula
#

Don't plot it anywhere

ruby path
#

Generally speaking you do not modify a function even if it can be simplified

unique nebula
#

Functions ignore undefined parts

ruby path
#

You get a hollow circle there

unique nebula
#

The function tan(x) cos(x) has portions of the real line which are not in its domain at all

ruby path
#

tanxcosx and sinx are not the same function

unique nebula
#

Both tan(x)cos(x) and sin(x) are continuous functions

ruby path
#

,w tanxcosx at x = pi/2

warm shaleBOT
ruby path
unique nebula
#

@ruby path
The function tan(x) cos(x) has portions of the real line which are not in its domain at all

#

Not in its domain at all

#

Read carefully

#

Do not mislead

obtuse pebbleBOT
#
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obtuse pebbleBOT
#

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exotic creek
obtuse pebbleBOT
exotic creek
#

what did i do wrong here?

#

this is the answer

obtuse pebbleBOT
#

@exotic creek Has your question been resolved?

exotic creek
#

<@&286206848099549185>

tame narwhal
#

it shows you how to properly calculate the quartiles

#

so that 3/12 values are below Q1 and 3/12 are above Q3

#

same principle you used when calculating the median

#

so that 6/12 values are below and above the median

exotic creek
#

shouldn't it be the same for n/4 and 3n/4 tho?

#

why doesn't it work?

tame narwhal
#

because Q1 is the same as the median of the lower half

#

if you were given just the first 6 numbers, how would you get the median?

exotic creek
#

(n+1)/2?

tame narwhal
#

yes, which is exactly what was done in the solutions picture you show

exotic creek
#

but ur finding the median of 6 numbers not including the other 6

#

so you're saying 3n/4 is wrong for finding the lower quartile of a set of numbers?

#

i should be using the median of half of the set of numbers?

#

isn't that the same as n/4?

tame narwhal
#

it is not, you have the visualization of that in the answer

#

n/4 is the 3rd value, which is 172. but the median of the first 6 values is (172 + 175) / 2 = 173.5

exotic creek
#

isn't n/4 is how you find the lower quartile?

tame narwhal
#

no. according to wikipedia there is no universal agreement for selecting quartile values

#

but see Method 1, which is what your answer shows: https://en.wikipedia.org/wiki/Quartile#Method_1

In statistics, a quartile is a type of quantile which divides the number of data points into four parts, or quarters, of more-or-less equal size. The data must be ordered from smallest to largest to compute quartiles; as such, quartiles are a form of order statistic. The three main quartiles are as follows:

The first quartile (Q1) is defined as...

#

you have an even number of values, so you split the data into lower and upper halves. then the quartiles will be the medians of those halves

exotic creek
#

so n/4 is only for odd number of values?

#

and 3n/4

tame narwhal
#

if n is odd then n/4 and 3n/4 will not be integers

#

on the wikipedia page, there are 2 examples. you can see that the different methods for getting quartiles give different answers

#

so you can ask your teacher if they have a preference

exotic creek
#

alr

#

.close

obtuse pebbleBOT
#
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dim nacelle
#

Stuck in this. I think I’m struggling with the distributive law and am confused how to get this down to Xsmall1 = Xsmall2