Available help channel!
#help-10
obtuse pebbleBOT
Available help channel!
gritty depot
really simple question
say I have
obtuse pebbleBOT
really simple question
say I have
gritty depot
integral of a^u du
this sheet says this becomes 1/ln(a)a^u+c
shouldnt it just be ((a^u+1)/u+1)+c
median skiff
integrating exponential functions is not the same as polynomials
you cant just do that, same reason why differentiating a^x doesnt yield (x)a^(x-1)
median skiff
pretty much
frail rapids
obtuse pebbleBOT
frail rapids
14iii and 14iv
jolly ginkgo
What did you try?
exotic wharf
Consider AI being a single element
frail rapids
Consider AI being a single element
yes
360 combinations
times 2
because AI, IA
720 combionations
how about 14iv
jolly ginkgo
Yes you are right
royal basin
unrestricted count minus the number of arrangements in which C and H fail to be apart
obtuse pebbleBOT
@frail rapids Has your question been resolved?
obtuse pebbleBOT
wanton hull
as a python user, you cube it first
if it doesnt have a paranthesis then i believe you cube it first in maths too
exponents are right associative
so
it the question is
$2 \times 3^2$
warm shaleBOT
bettim
wanton hull
then its 2 * 9
18
im not exactly sure if it is the case in maths but im pretty sure thats how it is in programming
a^x
exponents
to any power
boreal haven
in the third line of work, why is it (4/3)(pi)(3r^2)? where did the 3 come from
tardy epoch
in the third line of work, why is it (4/3)(pi)(3r^2)? where did the 3 come from
Do you know the formula for volume of a sphere of radius r
boreal haven
like the general formula for volume of a sphere ?
tardy epoch
Yes
boreal haven
v = 4/3(pi)(r^2) right ?
boreal haven
hmmm
boreal haven
Do you know the formula for volume of a sphere of radius r
like the volume of the sphere where r is by itself ?
tardy epoch
They tell you in the hint
.
boreal haven
i’m sorry i don’t have a clue :(
tardy epoch
i’m sorry i don’t have a clue :(
What do you think the hint says
boreal haven
the volume of the sphere
tardy epoch
Do you know the formula for volume of a sphere of radius r
That's the same as this
tardy epoch
the volume of the sphere
Sphere of radius r
boreal haven
ohhh they took the derivative of the formula ?
tardy epoch
Yes
frigid dove
Is this right
obtuse pebbleBOT
Is this right
dreamy acorn
what do you mean?
frigid dove
what do you mean?
See the way I take way the 4n squared and the 2n squared at number 1 and 2
frigid dove
4n/2n=2
Oh I see what u mean
But don't you multiply by the button and divide by the top to get n
Or you just divide
obtuse pebbleBOT
@frigid dove Has your question been resolved?
frigid dove
2n^2+9n+1-3n+1
Oh now I understand
frigid dove
I was thinking it should be 2n^(squared) but I thought maybe it's wrong
frigid dove
Yeah because u said n = (1)
frigid dove
.reopen
obtuse pebbleBOT
✅
frigid dove
n/n=1
But even if you did 4(1)/2(1) = 2 it would still be the same as 4n/2n = 2
Since we are moving the N in this situation
frigid dove
I just like it
dreamy acorn
But even if you did **4(1)/2(1) = 2** it would still be the same as **4n/2n = 2*...
what is this
frigid dove
i think we can cancel out the n
Sorry this one
U said we have to cancel out the n
dreamy acorn
yes
frigid dove
Oh
dreamy acorn
n can be all real number
obtuse pebbleBOT
Available help channel!
lost summit
Does P series test work if the series is 1/(n+1)^2
obtuse pebbleBOT
Does P series test work if the series is 1/(n+1)^2
lost summit
If it doesnt, would u need to do a direct comparison test in order to use P - series?
obtuse pebbleBOT
@lost summit Has your question been resolved?
obtuse pebbleBOT
@lost summit Has your question been resolved?
lost summit
<@&286206848099549185>
obtuse pebbleBOT
@lost summit Has your question been resolved?
gray haven
When given the question of how to find the sum of n square numbers, how do I know to go down the path of finding a telescoping series and an arithmetic progression. e.g. (n-1)^3=n^3-3n^2+3n-1 and then n^2=1/3[n^3-(n-1)^3+3n-1] (sorry if its confusing)
obtuse pebbleBOT
When given the question of how to find the sum of n square numbers, how do I kno...
@gray haven Has your question been resolved?
obtuse pebbleBOT
@gray haven Has your question been resolved?
vivid creek
For c how is it anti clockwise by 90?
obtuse pebbleBOT
For c how is it anti clockwise by 90?
@vivid creek Has your question been resolved?
vivid creek
.close
proud halo
the statement AA^T = I_n
is only true for orthonormal matrices right? not for orthogonal?
obtuse pebbleBOT
the statement AA^T = I_n
is only true for orthonormal matrices right? not for or...
proud halo
the internet seems to use them interchangeably so its confusing
by orthonormal i mean orthogonal + each vector has magnitude 1
tardy epoch
by orthonormal i mean orthogonal + each vector has magnitude 1
Orthonormal matrices are not a thing
Orthonormal bases are a thing
Columns and rows of Orthogonal matrices do form an orthonormal basis wrt to Euclidean dot product
obtuse pebbleBOT
@proud halo Has your question been resolved?
median stone
Hello
median stone
How do you find the 5th and 95th percentile
Of this?
<@&286206848099549185>
.close
unborn sky
obtuse pebbleBOT
unborn sky
this is part of my homework and no one in my class has been able to do it (ping me if someone replys)
ive made it into a parallelogram which seems like a good start imo
obtuse pebbleBOT
@unborn sky Has your question been resolved?
unborn sky
.close
median stone
obtuse pebbleBOT
median stone
So 11x0.6=6.6
median stone
Ye still wrong boss
obtuse pebbleBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
median stone
Sorry
median stone
Well I’m way more stupid
median stone
If that makes u feel any better
Oh sure
That is incorrect still
Idk
Fuck that question
Why would any car need 132L of paint
That can flood a city
low frost
Idk
nocturne minnow
You should ask your teacher as that is correct
low frost
You should ask your teacher as that is correct
No
you have to take into account the actual size of the real car
bc 0.6 x 20 is 12**
nocturne minnow
It does, it's proportions
low frost
doesn’t make sense
median stone
Ye I think that question is mudded
12 surely it the right answer
I think the system is bugged
Thanks guys tho
Much appreciated for helping
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
mental cosmos
let $G=(V,E,W)$ be an undirected connected and positively weighted graph and let $T_1,T_2$ be two minimum spanning trees of $G$. prove that the sum of squares of the weights of $T_1$ is equal to that of $T_2$
obtuse pebbleBOT
let $G=(V,E,W)$ be an undirected connected and positively weighted graph and let...
warm shaleBOT
metnal
mental cosmos
doesnt that follow directly from the definition of a minimum spanning tree?
minimum spanning trees in a graph have the same weight which is the minimal one possible, square the weights and they'll stay equal...
is that it or am i missing something?
.close
spice storm
Can someone demonstrate if the relation ~ is reflexive? Define ~ on R by a~b iff a^2+b^2=10
obtuse pebbleBOT
Can someone demonstrate if the relation ~ is reflexive? Define ~ on R by a~b iff...
spice storm
I understand the definition of reflexive and how some problems ask you to almost put a in for b, but in this case I do not understand
tardy epoch
Can someone demonstrate if the relation ~ is reflexive? Define ~ on R by a~b iff...
if a^2 + b^2 = 10, what does b^2 + a^2 = ?
tardy epoch
I thought that was transitive
it isn't
use this definition or one from your book/notes
spice storm
Then wouldn't that be symmetry based on what you provided?
A book I have that is assisting me in the class gives another example where ~ is the relation on Z where a~b if a+b is even, then it continues to show a+a=2a which is even by def of evens
tardy epoch
Then wouldn't that be symmetry based on what you provided?
ah yes i misread what you wrote
tardy epoch
if a^2 + b^2 = 10, what does b^2 + a^2 = ?
so replace b with a 
spice storm
that's where I get lost tho. I have a^2+a^2=2a^2, but I don't know where to go from there
I think it has something to do with inequalities but that's where the disconnect is
spice storm
so ur saying to show reflexivity, I can just write that a^2+a^2=10
Oh wait
I see it now
thank you so much
.close
hard minnow
Can someone help me?+
obtuse pebbleBOT
Can someone help me?+
royal basin
!status
obtuse pebbleBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
This is all I have, not sure how to multiply these terms out
royal basin
bad handwriting
hard minnow
I'm sorry.
royal basin
you somehow manage to make your twos look like threes in some places. gonna get confusing for the reader and yourself.
anyway
hard minnow
😦
royal basin
the stuff you have inside the limit is $\frac{(n+1)^4 \cdot 3^{2n+2} \cdot 7^{n+2}}{7^{n+3} \cdot n^4 \cdot 3^{2n} }$
warm shaleBOT
Ann
royal basin
do you see how to proceed from here?
obtuse pebbleBOT
@hard minnow Has your question been resolved?
spare ibex
I've solved this by turning the equation into -Tan(2x) = 1 and going on to figuring out what x is. In the end, I got the correct answer which is x = 45. However, I was wondering if there are any other ways to find x other than my way of doing so?
obtuse pebbleBOT
I've solved this by turning the equation into -Tan(2x) = 1 and going on to figur...
median yacht
Maybe by expanding cos(2x) and sin(2x)
spare ibex
I tried that but it made it even more confusing. The professor I was watching turned Sin^2(2x) into "1-Cos^2(2x)" which I have never been taught before
median yacht
But there is no squares here
spare ibex
This is how he's done it
median yacht
$$\frac{\sin(2x)}{1-\cos(2x)} = 1$$
$$\sin(2x) = 1 - \cos(2x)$$
$$2\sin(x)\cos(x) = 1 - \cos^2(x) + \sin^2(x)$$
$$2\sin(x)\cos(x) = \sin^2(x) + \sin^2(x)$$
$$2\sin(x)\cos(x) = 2\sin^2(x)$$
$$\sin(x)\cos(x) =\ sin^2(x)$$
$$\sin(x)\cos(x) - \sin^2(x) = 0$$
$$\sin(x) (\cos(x) - \sin(x)) = 0$$
warm shaleBOT
Rub05
spare ibex
OHH I just remembered Sin^2x+Cos^2x=1
spare ibex
But maybe I commited a mistake
That's fine. I remember now where that 1-Cos^2x came from after seeing you do it
Anyhow, thanks for your help
.close
rose zinc
hello, can someone help me with something like 2,3 x 10^3
obtuse pebbleBOT
hello, can someone help me with something like 2,3 x 10^3
frank horizon
Do u want to know the number written out from scientific form
rose zinc
no it was an example, id like to have an explination for that
rose zinc
for how the scientific form is build and how i can calculate with it
btw sorry for my english im actually german
frank horizon
Np
So scientific form is useful for very small or big numbers
Or conversions
So if you were dealing with an electron charge
It’s a very very small number
And to express it, you would approximate it with (number).(number)*10^(degree of magnitude)
So for 1kOhm resistor
For example
Instead of writing it as 1000Ohms
You would do 1.0*10^3
rose zinc
ahh okay
alpine raven
frank horizon
And the number raised to 10 is how you should move ur decimal point
rose zinc
yeah
frank horizon
Negative you go to left, positive you go to the right by the number above the 10
rose zinc
ohh okay
frank horizon
And when converting to scientific you always want the decimal point after the first number
2.1
4.6282
rose zinc
really omg
nocturne minnow
Basically you want the number to be between 0 and 10 exclusively, so $0 \leq x < 10$
warm shaleBOT
dldh06
rose zinc
okay
frank horizon
It’s also very useful when multiplying numbers
You can just add the numbers above the 10
And multiply the two numbers
rose zinc
alright
rose zinc
but what when the exponent is a mathematical fraction
frank horizon
Uh for scientific form you usually don’t see that
But you would probably just take the root of the exponent of 10
rose zinc
ohoh
frank horizon
And the multiply it by the first number
But then it wouldn’t be useful to express it in scientific form
frank horizon
Np good luck
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
mental cosmos
let $G=(V,E,W)$ be an undirected connected and positively weighted graph, and given that the weights of the edges of $G$ differ from one another. prove that for every $G$ there is a single mst
obtuse pebbleBOT
let $G=(V,E,W)$ be an undirected connected and positively weighted graph, and gi...
warm shaleBOT
metnal
mental cosmos
any hints?
obtuse pebbleBOT
Available help channel!
bright mauve
i just dont know what im supposed to do here
obtuse pebbleBOT
i just dont know what im supposed to do here
bright mauve
something like find the maximum length the side can be or something im not sure
this place is really neat the way ya gots it set up here :3
forest sinew
you gotta set up some equations
i can give you a start
the thing is rectangular right?
so let 2 of the side lengths be x
whats the area?
bright mauve
x squared
forest sinew
no i mean
bright mauve
sorry, am listening
bright mauve
ohh
bright mauve
okayy
so then. we dont have an area because we'd need a variable to represent the other sides right?
forest sinew
think of how you can find the areA
2 of the sides are x
what are the other 2 sides?
what information havent you used
bright mauve
kay, picture drawing commences
forest sinew
you know what all the sides should add up to right?
so draw a picture, label all the sides, and add them up
bright mauve
so two opposite sides are labeled as x, yes?
OH WAIT i got a spark in my brain then it went awayy ugh
somethin about if i subtract x from 280 i get what the two reamining sides add up to and then i split that in two but idk that doesnt sound like it makes sense..
oh yea and there's still the area thing to figure out..
forest sinew
you have a way to check your guesses
forest sinew
i mean it doesnt make sense
you have two sides of length x
the total is 280
so how much is left after the 2 sides of length x
bright mauve
280-2x?
closer? not so much?
im sorry im kinda dumb..
what i have in my head now is 280-2x = the two remaining sides lengths totaled
forest sinew
okay so you have that much left for the remaining 2 sides ...
how long is each side
bright mauve
i.. dont know lol
cuz is a rectangle, two sides will share a length, and the other two sides will share a length
lone dirge
Right, let's call the width x and the length y
forest sinew
you should stop guessing and badmouthing yourself IMO
bright mauve
i perfer length and height but am listening
forest sinew
you could solve this if you sat down and spent some time drawing and checking yourself
bright mauve
you could solve this if you sat down and spent some time drawing and checking yo...
i drew some stuff!! i just dont have any information idk
bright mauve
So what's the area?
xy
lone dirge
and 2x+2y =
bright mauve
the perimeter
lone dirge
was it 280?
lone dirge
So x+y?
bright mauve
half the perimeter?
lone dirge
140?
bright mauve
... so x+y = 140?
lone dirge
Now when is x*y is maximized subject to x+y=140
bright mauve
wait huh
bright mauve
okay
floral mirage
280-2x=y and Area=x*y can you not sub it in and isolate for x?
bright mauve
wait but isnt that a square then
lone dirge
A square is a type of rectangle isn't it
floral mirage
are you able to check the answers?
lone dirge
But go with Ayamew to prove that's the answer
bright mauve
are you able to check the answers?
uhm no this is just an exam review lol
floral mirage
T_T feel you bro
bright mauve
okay checking now..
bright mauve
70 = 140, nope, doesnt line up
floral mirage
hm
bright mauve
2y = 280 -2x
oh wait
floral mirage
im pulling up the iconic ms paint to get the visual
bright mauve
49,000
no
4,900
jeebus
im cool with that answer i guess lol
idk how to show my work for it
lone dirge
That was only an intution
bright mauve
all my work was 💻on here and 🧠in this thing
lone dirge
You should go with Ayamew's advice, move to a single variable function for the area
Then find a maximum to this function
floral mirage
wait sorry the correct form for y is y=(280-2x)/2
lone dirge
Yes
bright mauve
im still here btw just kinda listening now
floral mirage
yeye
lone dirge
So x*y = (140-x)x = 140x -x^2
floral mirage
complete the square?
bright mauve
goodness youve lost me at this point but this is an entertaining discussion
math people amirite lol
floral mirage
thats how you find max area generally we use the vertex equation for this
y=c(x-a)^2+k kinda of thing
and k is the max area
lone dirge
Hmm
bright mauve
whenever y'all are ready i would like to close the room btw
got an answer and some work written down, thank you all 💙
lone dirge
But...
You don't know how to generally get there
You should be able to prove your answer is right
bright mauve
hold on i'll take a pic and show what i have
lone dirge
Wait, bare with me for a sec
bright mauve
am listening owo
bright mauve
uh,.. yea yea makes sense
lone dirge
Then, xy = x(140-x)
bright mauve
took me a sec lol
jade light
Hello.
bright mauve
hoiii welcome to math peeps talkin
floral mirage
ok so you know the formula ax^2+bx+c right?
jade light
Can somebody help me study my benchmark I have tomorrow
floral mirage
the quadratic equation
bright mauve
ye ye that form! i think that's standard
lone dirge
So, the area, xy = x(140-x) = 140x-x^2
floral mirage
ye ye so c=(b/2)^2
jade light
I’m so confused
floral mirage
use that formula for c to complete the euqation first
lone dirge
No you need to find a maximum to this parabola 140x-x^2
bright mauve
I’m so confused
sorry but you'll need to post your question in one of the available math help channels,,
should be above this category here
this one is occupied ehehe
bright mauve
y'all im sorry i really want to move to my next questionn
floral mirage
sorry real quick
once you find c
just follow the steps to vertex equation
complete the square and shit and the last number equals max area
you can find tutorial online of the vertex equation
lone dirge
Shantie, the trick that I walked you through is nice, but it's not the way you should solve it...
floral mirage
wahts his question?
lone dirge
You need to be able to justify your answer
lone dirge
FINE
fast silo
im not sure if this is a math problem but this is the only place i could think of to go lol
How would i figure out what parts are being compressed
obtuse pebbleBOT
im not sure if this is a math problem but this is the only place i could think o...
fast silo
and which ones have tension applied to them
grizzled shore
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
normal maple
obtuse pebbleBOT
trail musk
Well when you divide you get another polynomial
Can you divide again?
Keep going and going.
Forever.
normal maple
alr
obtuse pebbleBOT
@normal maple Has your question been resolved?
frail depot
obtuse pebbleBOT
frail depot
Is this not correct that I can determine A from the inverse of E1^-1 ... Ek^-1
Like I did on the picture with k=4
Determine for each i = 1, 2, 3, 4 the elementary matrix $E_i^{−1}$
and use these to determine A
warm shaleBOT
SimonWin
frail depot
that's the main question
frail depot
Then obviously, multiply, but I'll wait till i know it's at least right 😂
civic zealot
assuming E4E3E2E1A = I, then yes.
frail depot
assuming E4E3E2E1A = I, then yes.
What does the mean exactly haha?
frail depot
assuming E4E3E2E1A = I, then yes.
Or I know what it means its the identity matrix
But like
I don't think I've been told that
civic zealot
Like, what are these Ei's how are they related to to A.
You just posted a bunch of matrices and asked if they're equal to A? What's A?
frail depot
Ye so it's told
that the elementary equation operations ero1 ero2, ero3 and ero4 in that SPECIFIC order can transform to the identity matrix
And then I've created E_i corresponding to each ero_i
So since they say " in that SPECIFIC order can transform to the identity matrix"
It should be valid, yes?
It is stated that an unknown 3 x 3 matrix A, which includes a parameter a ≠ 0, can be transformed into the identity matrix by performing row operations ero1, ero2, ero3, and ero4 in that order.
civic zealot
Yes. That would mean they multiplied $A$ by $E_1, E_2, E_3, E_4$ to get the identity. So $E_4E_3E_2E_1A = I$. \
You can then rewrite that as your oringal post.
warm shaleBOT
Zybikron
frail depot
Find the elementary matrix E_i^-1 associated with each i = 1, 2, 3, 4 row operation and use them to determine A.
Thats the questions in english
frail depot
Yes. That would mean they multiplied $A$ by $E_1, E_2, E_3, E_4$ to get the iden...
Ye, okay so just mention that as well right?
Before doing the operation?
civic zealot
sure
hallow cradle
i can't understand this question if it uses factorials and idk
Every day at school, Jo climbs a flight of 6 stairs. Jo can climb using 1, 2
or 3 steps or a combination of any of them. How many ways can Jo climb
the flight of 6 stairs?
obtuse pebbleBOT
i can't understand this question if it uses factorials and idk
Every day at sch...
hybrid gull
I'd start by listing out the possibilities
twin sapphire
uuuh thats a lot of them no?
hallow cradle
i dont think so
twin sapphire
this is fibonacci esque
twin sapphire
lets consider the first step
and if we have n stairs
we can do 1 stair 2 stair or 3 stair,
hallow cradle
there are 6 stairs
twin sapphire
we'll replace n by 6
hallow cradle
ok
twin sapphire
its just for you to understand
hallow cradle
ok i will let you continue my bad
twin sapphire
so the total number of ways
is the number of ways if we chose to start with 1 stair + number of ways if we chose to start with 2 stairs + number of ways if we chose to start with 3 stairs
right?
hallow cradle
i think so
twin sapphire
lets call T(n) the number of ways for n stairs in total
so essentially
T(n) = T(n-1)+T(n-2)+T(n-3)
twin sapphire
is the number of ways if we chose to start with 1 stair + number of ways if we c...
from this
T(n-1) is the number of ways to climb the whole stairs if we start by 1
since there remains n-1 stairs to climb
same for starting with 2 or 3 stairs
is it ok?
twin sapphire
wdym?
hallow cradle
A. 13
B. 18
C. 20
D. 22
E. 24
hallow cradle
ok
hallow cradle
yes
twin sapphire
A. 13
B. 18
C. 20
D. 22
E. 24
because given this maybe i'm going too far
and maybe you should indeed list out everything
twin sapphire
dont be lol
hallow cradle
do u know combinatorics
twin sapphire
i know
hallow cradle
maybe that works
twin sapphire
what grade is this?
twin sapphire
yeah oik
hallow cradle
algebra
hallow cradle
yea
hallow cradle
ok
twin sapphire
and continue to expand the tree until you get to 0 stairs
and count the number of paths
that get to 0 stairs
hallow cradle
ok
twin sapphire
or you can build your way up
hallow cradle
ok
hallow cradle
1
hallow cradle
2
hallow cradle
6
twin sapphire
list them
hallow cradle
ok
twin sapphire
try
hallow cradle
ok
twin sapphire
6 isnt that much
hallow cradle
yea
hallow cradle
1 1 1 for 3 times one stair,
3 for one times 3 stairs
1 2 for 1 then 2 stairs
2 1 for 2 then 1
hallow cradle
oh
twin sapphire
thats why i asked
the answer wasnt just factorial
i wanted you to count them for the first 3 cases
then use the formula to find the other ones
so T(4) = ?
twin sapphire
T(n) = T(n-1)+T(n-2)+T(n-3)
using this
twin sapphire
T(3) was 4 not 6
hallow cradle
oh right
twin sapphire
so?
hallow cradle
t4 is 6
twin sapphire
break it down pls
hallow cradle
t1 is 1, t2 is 2, t3 is 4. T(4) = T(3) + T(2) + T(1). 7 = 4 + 2 + 1
its 7 actually
hallow cradle
24
twin sapphire
yay
hallow cradle
ur a genius
twin sapphire
no, i already did this exercise
hallow cradle
oh wow when
twin sapphire
when i said its Fibonacci eesque
its because F(n) = F(n-1)+F(n-2)
its the definition of the fibonnaci sequence
twin sapphire
and the sequence we were using is called the Tri-bonacci sequence
since we add the three last terms
to get the next one
hallow cradle
how did you know that you were supposed to use this sequence and not like any other method
twin sapphire
when you have possibilities like this
try to reduce the problem to a smaller version
like i did
I considered the first choice joe has
either 1 2 or 3 stairs
then once this choice is made we can link the total number of possibilities to the number of possibilities in each case
which are smaller
since with the first choice joe climbed some stairs
and i write mathematically
T(n) = T(n-1)+T(n-2)+T(n-3)
once you have this we can compute what happens for the first number of stairs like we did by hand
and for a more advanced version
hallow cradle
yea
twin sapphire
using more maths you can deduce a general formula
but its more end of highschool college maths
hallow cradle
nice
twin sapphire
thats what you would use if the exercise said
jo has to climb 537 stairs
for example
you couldnt do what we did by hand on an on
it would take too long
hallow cradle
thats true
anyways, it was great having you to talk about this math problem
Thanks for helping me
May i close the channel now if you'd like?
.close
zealous gyro
obtuse pebbleBOT
royal basin
first step's to multiply num and denom by sqrt(3) for sure
valid comet
h = -16t^2 + 128t when will it hit the ground
obtuse pebbleBOT
h = -16t^2 + 128t when will it hit the ground
valid comet
im so confused
brave bramble
When h = 0. In other words, when:
0 = -16t² + 128t
That can be solved by factoring. Remember to check for common factors!
dense pasture
next step the easiest part!
if x * y = 0
this means either x or y has to be 0 right (x = 0 or y = 0)? cause otherwise how u gonna get 0 as the answer?
now going back to -16t(t - 8) = 0
if -16t(t - 8) = 0 then either -16t = 0 or (t - 8) = 0
from there u can solve for t
valid comet
So with the (t - 8) do I do the thing where make it 8
and is the -16t the 0 because its not in parentheses
dense pasture
yeah that is the answer, t = 8
For something like this you would want to re-arrange to make t on it's own
(move everything to the right side of the equal sign except for t)
so for
-16t = 0
you divide both sides by -16
which makes t = 0
t - 8 = 0
to make t on its own you add both sides by 8
t - 8 = 0
t - 8 + 8 = 0 + 8
t - 0 = 8
t = 8
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
sick dragon
Hi there! I have this question "What are all possible results of the expression (n % m), where n and m are
integer?"
obtuse pebbleBOT
Hi there! I have this question "What are all possible results of the expression ...
violet sentinel
% is the modulo operator?
sick dragon
yes!
wanton hull
all possible values?
sick dragon
yes!
wanton hull
$n \text{ mod } m = x \implies x \in [0,m-1)$?
violet sentinel
it's the number of moms
warm shaleBOT
bettim
wanton hull
it's the number of moms
lmao
violet sentinel
$ n \mod m $ I think
warm shaleBOT
bettim
sick dragon
hahahaha
violet sentinel
$\mod{n}{m}$
warm shaleBOT
MellowDramaLlama
wanton hull
lmao
wanton hull
$n \mod m$
warm shaleBOT
bettim
violet sentinel
Basically if you had something like n (mod 5), the only possible answers are 0, 1, 2, 3, 4
sick dragon
It makes some sense but I need more information i guess
sick dragon
okay okay
wanton hull
$x \in (-(m-1),m-1)$?
warm shaleBOT
bettim
wanton hull
u told integers
wanton hull
Hi there! I have this question "What are all possible results of the expression ...
..
jolly ginkgo
u told integers
Why are you writing set in that way tho?
wanton hull
mb
jolly ginkgo
I'm attracted
wanton hull
$x \in {-(m-1) ............ m-1}$?
warm shaleBOT
bettim
wanton hull
I'm attracted
||to children||
jolly ginkgo
||to children||
Are you a child?
wanton hull
Are you a child?
yess
violet sentinel
||to children||
whoaaaaah
jolly ginkgo
9teen
wanton hull
7
wanton hull
discord is 13+ im fine
jolly ginkgo
They just change the rules today and now it's 18+
wanton hull
tardy heart
I kind of get the unit circle, but I am stuck on this problem
obtuse pebbleBOT
I kind of get the unit circle, but I am stuck on this problem
wanton hull
draw a triangle
and mark the sides
you'll get the other side using pytho's
use the quadrant info to determine the sign of sin theta
tardy heart
and mark the sides
How do I know where the adjacent is?
undone rover
quadrant implies a cartesian plane
tardy heart
What is that?
undone rover
literally just a graph
tardy heart
Oh
So I know the hypotenuse is 13
But I still dont understand which side the adjacent is on
wanton hull
tardy heart
and how the triangle is drawn
Sure
tardy heart
Thanks
wanton hull
find x
wanton hull
wanton hull
Where to place the 12
bcz cos theta = adj/hypo
wanton hull
from here what is sin theta?
tardy heart
5/13
wanton hull
yes
tardy heart
Sorry I am just confused on where you place the theta
tardy heart
-?
wanton hull
Sorry I am just confused on where you place the theta
you can do it anywhere just make sure you do the sides right
warm shaleBOT
bettim
tardy heart
Ohhh
Ok sweet
Thanks for the help
I will probably have a question on another problem in a couple of minutes
But until then thanks again 😉
.close
lavish nymph
obtuse pebbleBOT
lavish nymph
Can someone help me do this
royal basin
have you made a diagram yet?
lavish nymph
no
royal basin
make a diagram
lavish nymph
how
royal basin
read the problem and map out her walking path
royal basin
suppose there's no way to avoid that... give me a moment
lavish nymph
ok
lavish nymph
so what am I solving for
royal basin
do you understand why this diagram represents the problem?
lavish nymph
yea
royal basin
do you see where i've put a question mark on the diagram?
lavish nymph
yes
royal basin
do you understand what the question mark refers to?
royal basin
no, i did not mark any side with the lowercase letter c.
royal basin
cannot say for sure without seeing your work.
lavish nymph
I just used the law of cosines formula and plugged in 1.2 ,0.5 and 70deg
royal basin
the angle in your triangle isn't 70°.
it is this angle in red that you want to use in the law of cosines formula, NOT 70°.
lavish nymph
uh
royal basin
do you want to ask something?
royal basin
no
lavish nymph
whats wrong
royal basin
why'd you put zero as your angle now?
royal basin
yes, that is theta.
royal basin
also i deliberately didn't write its value on my diagram.
you were supposed to actually think about what's written on the diagram,
not throw it into mathway
lavish nymph
idk how to
royal basin
you don't know how to what
royal basin
what's wrong is your attitude of "oh i will just throw this into mathway and it will give me a magic number and i will hope for the best and ask if it's right"
lavish nymph
ok
royal basin
no mathway allowed, and really no mathway necessary either.