help-10

[kind hawk]

if you had 9816507015124=39659128*some integer + (some number in [0, 39659128) )

why should that have only one solution

[timid silo]

because it's a linear equation? lol i'm probably trolling

but why should it have more than one solution?

9816507015124=39659128* some integer + 39659127

[kind hawk]

why shouldnt it have more

and why should it have even one

[timid silo]

Idk, is it because the "some integer" has to be integer which makes it so that it oculd have more than one solution

don't linear solutions have liek one solution? I guess this is more diophantine and it can have more than one solution

sry idk number theory

[kind hawk]

or the solution could be a fraction

who knows

but ok

lets move on

[timid silo]

yeah

so basically n = 7q + 4 and n = 3k + 4

[timid silo]

also tbh i don't get this but i might just be bugging. If this was basic algebra then it would be guaranteed one solution, no?
9816507015124=39659128* x + 39659127

I assume the condition that "x" has to be integer is what gives rise to more solutions, right?

[kind hawk]

well if you try to solve that equation there you probably get a fraction

cause you filled in the remainder

[timid silo]

yeah

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by !Kiz__#0012

[timid silo]

so is it something totally different when solving for x where x has to be integers?

Is it why x could typically have more than 1 solution or none at all?

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by !Kiz__#0012

[kind hawk]

you have two variables

q and r

you want to solve for both being integers and r has to satisfy this condition

[timid silo]

Oh lmao

Okay that makes sense

so you need both q and r to be integer and that's unique is what you meant?

[kind hawk]

and r to be in that range

yes

[timid silo]

okay nice nice i get it

now for the chinese remainder theorem thingy

n = 7q + 4 and n = 3k + 4

[drifting wraith]

may i show?

[timid silo]

the 7 and 3 are coprime, yes

what now?

[timid silo]

?

[drifting wraith]

like the method is stupid easy

[timid silo]

U mean chinese remainder theorem?

[kind hawk]

which one? euclidean algorithm or CRT?

[timid silo]

Or diophantine

[timid silo]

my original question, you mentioned crt so i guess crt?

[drifting wraith]

well you already found 1 pair or even more

[timid silo]

aren't we done with euclidean

[drifting wraith]

so that's most of it

[timid silo]

you mean finding numbers that satisfy both these conditions n = 7q + 4 and n = 3k + 4 provided q and k is an int?

yeah i think i found 2

[kind hawk]

if you found one solution n, then n+21 will be another one

[timid silo]

O

what about the third one?

okay so basically

[kind hawk]

n+21+21

[drifting wraith]

or minus

[timid silo]

dang

[kind hawk]

n+21m

[timid silo]

m?

[kind hawk]

some integer

[timid silo]

ahh okay that's nice so basically find one solution

then that solution + (7)(3) m

[drifting wraith]

lowest common multiple

it's not always product

[timid silo]

ah so solution + lcm(7,3) m

are these guaranteed solutions?

[kind hawk]

well the numbers are assumed to be coprime

so it actually is the product

[drifting wraith]

i guess if there's just 2 "equations" it is?

but if there's 3 it may not be right?

[timid silo]

?

so i should take lcm to be careful or what?

if there are more than 2 equations

[drifting wraith]

maybe not

yeah it's always product

no catch

[kind hawk]

so in general, if you have some divisors a1,a2,a3,a4,... and remainders r1,r2,r3,r4,... and then want to find a solution n=r1 mod a1, n=r2 mod a2, ...

then

if gcd(a1,a2,a3,...)=1, there is a solution

and if k is a solution, so is k+lcm(a1, a2,a3,...)

in that case lcm(...)=prod(...)

if gcd(a1,a2,a3,...) is not 1, then there might not be a solution (depends on r1,r2,...)

but if k is a solution, then k+lcm(a1,a2,a3,...) is also a solution

and in that case lcm(...) is not the same as prod(...)

[drifting wraith]

thanks got it

[timid silo]

lil iffy to understand lol

[drifting wraith]

i'll give an example

[timid silo]

divisors a1,a2,a3,a4,... and remainders r1,r2,r3,r4 by this you mean multiple equations i guess?

[kind hawk]

yes

[timid silo]

n=r1 mod a1, n=r2 mod a2, ...

why are you doing this?

[kind hawk]

do you know mod?

[timid silo]

i know it from programming i guess

5%2 = 1?

[kind hawk]

n = r1 mod a1 means that n = a1*q + r1 with some integer q in the way we discussed before

[timid silo]

ah okay that's a shorthand way of writing it

okay cool

so the point of finding if a_1,a_2, and so on is coprime is to check if gcd(a_1,a_2,...) = 1 right?

[kind hawk]

coprime is defined as meaning gcd(...)=1

its really the same thing

[timid silo]

okay yeah that's true

i understand it now

[drifting wraith]

this is what gurantees that there is asolution, but it's not a necessary condition

[timid silo]

also, are these surely solutions?

or we have to test? since you said "maybe" a long while back so not really sure

[drifting wraith]

if n divided by 2 gives 1 as remainder, and n divided by 4 gives 3, there are solutions, 3,7,11,15...
we add lcm(2,4) which is not their product

if n divided by 2 gives 1, and n divided by 4 gives 2, there are no solutions

if gcd is 1 there will be solutions

[timid silo]

right right cuz 2 and 4 aren't coprimes

[timid silo]

ooo then what's the point of considering alternate cases?

when gcd(a_1,a_2, ...) \neq 1

when it doesn't yield solutions?

[kind hawk]

well sometimes it still yields solutions

n = 1 mod 2 and n= 3 mod 4

like frowny said

gives 3,7,11,15 etc as solutions

[timid silo]

but when gcd(all divisors) = 1 then what you mentioned above are surely solutions?

[kind hawk]

if gcd(...)=1, then you are guaranteed to have at least one solution

(and with one solution you get infinitely many cause you can always add the lcm)

have you solved linear systems of equations before? with matrices?

[timid silo]

i mean other_solution = solution + (7)(3) m

do these work for all m in Z?

[kind hawk]

yes

[timid silo]

Ah okay so it's a compact form of all the solutions then

Okay nice

[timid silo]

Yes

[kind hawk]

so in the form Ax=b with A some matrix and b some vector?

[timid silo]

Yes

[kind hawk]

ok then you know that for some matrices A there will always be a unique solution (rank(A) is full)

and for some A there might be no solutions or infinitely many, depending on the vector b

(rank(A) not full)

[timid silo]

haven't reached 😭 rank for matrices yet

only the first few lectures into lin alg

[kind hawk]

ok then nvm, you will encounter it later

[timid silo]

Okay, thank you!

I think that should clarify most of the queries

.close

[obtuse pebble]

Channel closed

Closed by @maiden quarry

Use .reopen if this was a mistake.

[timid silo]

.reopen

[obtuse pebble]

✅

[timid silo]

just as confirmation lol, would this have something to do with the columns of matrix A being linearly independent or not?

We've reached there but not talked about rank just yet

[kind hawk]

yes

the rank is the maximal number of linearly independent columns you can pick

[timid silo]

which in turn kinda gives us insight on what possible vectors of b can be obtained from linear combinations of columns (?)

[timid silo]

ah okay okay

[kind hawk]

full rank means all columns are linearly independent

[timid silo]

right, that makes sense

[kind hawk]

(and I didnt mention that I want the matrix to be square)

or at least more columns than rows

[kind hawk]

yes

[timid silo]

Okay nice, i'll try to come back and reread what we discussed about if i'm confused

I inferred it'd have to be square

just didn't think of how more columns than row would work though

[kind hawk]

(with more columns, full rank would mean "row many columns are linearly independent")

but not important right now

just the general idea, sometimes there is one solution, sometimes there might be one or not

[timid silo]

okay nice

thank you once again!

[kind hawk]

for matrices it depends on rank, for these equations here on the gcd

[timid silo]

.close

[obtuse pebble]

Channel closed

Closed by @maiden quarry

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton isle]

Have you ever tried squaring the equation?

[untold sparrow]

I tried to make it a quadratic

got the roots to be

[median dome]

you don't need to do any of that

just square it twice

[wanton isle]

There’s a trick for this type of equation

it’s by squaring

[untold sparrow]

Could you provide more insight

[wanton isle]

(x+1/x)^2=3^2

distribute it out

[untold sparrow]

wait a second doing it

[wanton isle]

You’ll see it soon

[rich plume]

notice if you square both sides the ab is just 1 leaving value of 2ab to be 2

[untold sparrow]

yeah saw that rn

[rich plume]

so you can easily calculate x^2+1/x^2

square it again

[wanton isle]

Now you know what to do if you were to encounter this type of equation again 👍

[untold sparrow]

wait im not done yet i think

im still doing it

oh wait

[wanton isle]

It’s just repetitive squaring lel

[untold sparrow]

yeah i got it

thanks mate

i was being dumb

.close

[obtuse pebble]

Channel closed

Closed by @untold sparrow

Use .reopen if this was a mistake.

[wanton isle]

Goodluck

[untold sparrow]

thanks

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wooden cipher]

.close

[obtuse pebble]

Channel closed

Closed by @wooden cipher

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gritty harness]

Guys

If I knew the dimensions of the net itself

Could I find out, if I were to roll it, the radius of what the circle would be ?

[forest sinew]

badminton

it depends how tight you roll it, right

[drifting wraith]

you can't

[forest sinew]

yea theres no clear answer

[drifting wraith]

using the fact that it has the same volume you get an approximation

but it's a net it compresses really well there's like literal holes

hm

but you can calculate volume with the holes in mind

...but it has that thing on the perimeter where's it not a net

[forest sinew]

heres what you do

fold it a few times

[drifting wraith]

so you could ignore the net in fact, you need to know the thickness of the white thing on the perimeter

[forest sinew]

get a volume of a roughly rectangular thing

then find the cylinder with the same volume

since itll share a dimension

[obtuse pebble]

@gritty harness Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma mountain]

when applying laplace to the first term on the Right hand side is it the same as applying it to the second term on the left hand side with the difference being it is Y(S) instead of X(S)

[obtuse pebble]

@prisma mountain Has your question been resolved?

[prisma mountain]

<@&286206848099549185>

[prisma mountain]

Anybody down to help?

or?

[limber quartz]

I'm looking at it but I am not good at this

do you have a similar example that you can share?

trying to remember if we need to deal with characteristic equation stuff before moving on to Laplace Transform stuff

[prisma mountain]

one sec

[limber quartz]

ok gimmie a few min

[prisma mountain]

https://youtu.be/CoYNcY0Tp_4

[prisma mountain]

Appreciated bro

@limber quartz

Here you go bro

could you just let me know which one is right?

[limber quartz]

hang on I'm wrapping up my work. It looks similar to what you have done on the RHS

except mine is inverted

y(s)/x(s)

I don't think it matters

[prisma mountain]

Appreciated lad

Thank you

.close

[obtuse pebble]

Channel closed

Closed by @prisma mountain

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone ermine]

I know how to do this if I had the slope as well

But here I don't, and strangely my class notes don't say what to do in this scenario

Would it be

$y+1=m(x-4)$

[warm canopy]

undefined slope means "infinite slope", i.e. a vertical line

[warm shale]

EDU

[obtuse pebble]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[stone ermine]

ok

.

So how would I insert this infinite slope into the equation?

[forest sinew]

recognize this means its a vertical line

and find the equation of a vertical line passing through the point

[stone ermine]

hmm

would it be just 4 then?

[teal turret]

What is just 4?

What’s the eqn

U get

[stone ermine]

if the slope is just 4, then I would insert it for m

correct?

[short spruce]

the slope is not 4

the slope is undefined

what is the equation for a vertical line?

[obtuse pebble]

@stone ermine Has your question been resolved?

[stone ermine]

x=

x=4

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[idle thunder]

what is the variable for arc length

idk

[obtuse pebble]

Channel closed

Closed by @grim trout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone ermine]

solve

[latent lynx]

…

[stone ermine]

?

Did I screw up that badly?

I just need this rational equation solved

Algebra is such a pain

[obtuse pebble]

@stone ermine Has your question been resolved?

[stone ermine]

.close

[obtuse pebble]

Channel closed

Closed by @stone ermine

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble iris]

is this easiest solved with comparison test?

[nimble iris]

can anyone walk me through it?

convergence or divergence btw

no need to find what it converges tio

[forest sinew]

compare to a p series

[brave bramble]

Worth guessing before anything else - do you think this converges or diverges?

[nimble iris]

converges

i must show my work though

with a comparison test

[brave bramble]

Good pick. Because it "looks like" 1/n² right?

[nimble iris]

yes yes

[brave bramble]

That's the comparison. Try 9/n²

[gilded needle]

and the comparison should be pretty easy in this case

[fierce lagoon]

Yippeeeee

[nimble iris]

i think im just misunderstanding comparison

[fierce lagoon]

Well you legit just compare it to another 'function'

[nimble iris]

im supposed to compare to something similar but bigger?

[fierce lagoon]

Yeah

Well

[gilded needle]

for convergence yes

[fierce lagoon]

To see if it converges

[gilded needle]

compare it to a bigger convergent series

[fierce lagoon]

Less if you wanna show it divergences

[nimble iris]

ohh thats why you guess first ?

[fierce lagoon]

Well

Yeah

[nimble iris]

uhhhhh

[fierce lagoon]

Pick a side see where it goes

[nimble iris]

okay, ill try with the 9/n^2

[gilded needle]

your intuitive thinking here should be "n^2 is gonna dominate in the denom when n is large"

[nimble iris]

ok!

[jolly ginkgo]

That's very nice bungo

I love it

[nimble iris]

wait so

it says in my profs notes ur supposed to find the ratio of an/bn

[fierce lagoon]

That's limit comparison

[frigid prism]

yeah so what they were telling you is a bit different

[nimble iris]

OH

[frigid prism]

theyre talking about direct comparison

[nimble iris]

frick man

[frigid prism]

here you would want to use lct

not dct

[nimble iris]

true

yeah, thats what the chapters on so im p sure i do

[fierce lagoon]

$\frac{9}{n^2} \geq \frac{9}{n^2 + 2n + 9} > 0$ for all $x \geq 1$

So you can just use DCT

Shit

Mfw I'm a genius

[frigid prism]

wait you could use it nvm

[nimble iris]

wtf

[frigid prism]

i always get them confused

[nimble iris]

im so dumb lol

[frigid prism]

youre not

[nimble iris]

gimme a sec i need to understand that

[warm shale]

Umbraleviathan

[fierce lagoon]

😶‍🌫️

[frigid prism]

wtf what is that emote

[nimble iris]

LOL

[fierce lagoon]

Me when I smoke 20 fucking packs a day

[frigid prism]

anyways just use lct here

[nimble iris]

yeah

[frigid prism]

dct could be used but the textbok says lct

[nimble iris]

ye^

an is still 9/n^2 tho right?

wait uhh

could someone explain this to me for my question at hand

[unreal musk]

Did you find $\lim_{n\to\infty} \frac{a_{n}}{b_{n}}$?

[warm shale]

@unreal musk

[nimble iris]

I will do that run

Rn

so does it matter whether an is bigger than bn ?

[fierce lagoon]

I hate limit

Bro you can use DCT kefir what are you on

[nimble iris]

its cuz i have to use limit for my homework

sori

[unreal musk]

Not particularly in terms of "size", as long as the limit falls within one of the ranges

You only really care is the limit is nonzero and finite, zero, or infinite

[nimble iris]

i got 1

[nimble iris]

alright

[unreal musk]

Which is nonzero and finite(!)

[nimble iris]

oo

[unreal musk]

Does the series of this converge or not?

[nimble iris]

convergess

[unreal musk]

(the answer to that will be the same to the answer of whether the other one converges or not)

[nimble iris]

yippee, tysm

just to clarify, as long as the limit is finite and nonzero, if bn converges then an converges and vice versa right

[nimble iris]

im assuming thats what the 0<L<inf part means

[unreal musk]

Yea, that's exactly what they mean

[nimble iris]

thank youu!

.close

[obtuse pebble]

Channel closed

Closed by @nimble iris

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble iris]

i must use limit comparison test, what should my bn be ?

[unreal musk]

Do you have any ideas for what it should be?

[brave bramble]

You basically want to make the numerator and denominator the same degree

[mint tendon]

id suggest breaking the sum up first

[brave bramble]

You're gonna compare with 1/n

[mint tendon]

[obtuse pebble]

@nimble iris Has your question been resolved?

Channel closed

Closed by @nimble iris

Use .reopen if this was a mistake.

[nimble iris]

Thank you!

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal wagon]

Where is this coming from? I tried to get to the result by multiplying both the numerator and denominator by the product of the conjugates which I assumed to be (x^(1/3)+1)(x+1) but apparently I got something wrong

[violet sentinel]

diff of cubes

[native inlet]

$a^3-b^2=(a-b)(a^2+ab+b^2)$

[warm shale]

XxMrFancyu2xX

[vocal wagon]

oh ok, forgot about that

thank you

.solved

[violet sentinel]

.close is the command 🙂

[vocal wagon]

ty

.close

[obtuse pebble]

Channel closed

Closed by @vocal wagon

Use .reopen if this was a mistake.

[fierce lagoon]

No it's .coose

Get it right fool

[violet sentinel]

.goose

crap

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obsidian cloud]

Hello

[wooden cipher]

Hello! What question(s) do you have?

[obsidian cloud]

I was hoping to voice chat with someone is that possible?

[gilded needle]

it used to be, but the voice channels got closed

because of issues moderating them

[obsidian cloud]

😦 that seems so much better but I will still post

just need a min to type it

[violet sentinel]

it's also pretty easy to copy and paste a photo in discord as well if that's easier. Just make sure that the pic is clear and visible

preferably a screenshot on a screen but photos are fine too

[obsidian cloud]

A hallway of width "f" is at right angles to a second hallway of width "g". What is the longest stick that can fit around the corner (along the floor)?

I have watched some videos but all they were given numbers intead of variables f and g which I think prevents me from using the same method with trig.

min/max problem

someone call me if you wanna discuss it 😄

here is fine too of course

[obtuse pebble]

@obsidian cloud Has your question been resolved?

[obsidian cloud]

yea

flat along the ground

sure

maximize for L based on the width of g and f

[obsidian cloud]

<@&286206848099549185>

[quaint wigeon]

Yes

[obsidian cloud]

?

nobody wants to chat? 😦

[old isle]

if the hallway's infinite what's stopping you from having an infinite stick

[obtuse pebble]

@obsidian cloud Has your question been resolved?

[warm plover]

Can L start and end at any position?

Or does it have to be a 45° angle form your view

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stiff crown]

I need help with this

[royal basin]

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[stiff crown]

1

[night plaza]

what is the sum of angles 1 and 2 according to the diagram?

[stiff crown]

Let me see I’m doing the work now

Yea I can’t find it I’m stuck

[night plaza]

okay

that square denotes a right angle, meaning that angles 1 and 2 sum to 90 degrees

[stiff crown]

Ohh

[night plaza]

you're given algebraic expressions for angles 1 and 2

so you can say 11x+(20x-3)=90

[stiff crown]

Oh ok that makes since

So that mean

For every box it’s 90 degrees

Well that corner thing

[night plaza]

yes

[stiff crown]

So that mean the entire thing is 360

[night plaza]

yes

[stiff crown]

Uhh is x= 3?

[night plaza]

yes

[stiff crown]

So I’ll have to find the angle for 3, 4 and 5

You know where I can start to find the angles for those?

[night plaza]

well like you said

you can think of the 360 degrees being divided into four corners

5 is one of those corners

[stiff crown]

So that mean it’s over 360?

[night plaza]

no

i'm saying 5 is also a right angle

90 degrees

[stiff crown]

Ohh

[night plaza]

so what's 3+4

[stiff crown]

7

[night plaza]

sorry i meant in terms of degrees

angles 3 and 4

[stiff crown]

Wait so corner 5 is 90

So that mean

3 and 4 is over 90

Correct?

[night plaza]

yes

but you can get an exact number

the sides of angles 4 and 1 are made by the same line yes?

[stiff crown]

Yes

[night plaza]

so they're equivalent angles

[stiff crown]

So that means 4 is 45 degrees

[night plaza]

no

angle 3 + 4= 180

if all the angles sum to 360

360-angle 5-(angle 1+ angle 2)
= 360 - 90 - 90

= 180

[stiff crown]

So angle 3 is somewhere over half of 90 I assume?

Probably over 90

[night plaza]

well what's angle 4

what did you get for angle 1

because remember angle 4 and angle 1 are the same

[stiff crown]

33

O

angle 4 is 33

I hope

So that means

I do 180 minus 33

[night plaza]

yes

yes

[stiff crown]

And I’ll get 147

So angle 3= 147

[night plaza]

yes

.close

[obtuse pebble]

Channel closed

Closed by @night plaza

Use .reopen if this was a mistake.

[stiff crown]

Ty

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

wth

[obtuse pebble]

Channel closed

Closed due to the original message being deleted

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Please don't occupy multiple help channels.

Channel closed

Closed due to the original message being deleted

[echo lantern]

.close

<@&286206848099549185>

Is it A or B or None of the above

[cosmic sedge]

NOA

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

how do i complete this proof

[glossy basalt]

what have you tried?

[tardy epoch]

well it tells you to use the definition

[timid silo]

Well ye i mean idk how to prove it with that method

[tardy epoch]

where do you get stuck

[timid silo]

Where to go from 1/e^8x=o

First ljne of proof

[tardy epoch]

you should read the definition of eps-M convergence

[obtuse pebble]

@timid silo Has your question been resolved?

Channel closed

Closed by @wanton pasture

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble iris]

how is this divergent? is 8/sqrt(n) not convergent to 0?

[trim portal]

8/sqrt(n) converges to 0 as n approaches infinity, but that doesnt imply that the sum converges too

[nimble iris]

aw mann

[royal basin]

@nimble iris you're confusing convergence of a series vs. convergence of its terms

[nimble iris]

how come the sum diverges?

[trim portal]

compare it with sum of 1/n

[trim portal]

do you know that this sum diverges?

[nimble iris]

ohh

yes

so its because 1/radn is greater than that?

[trim portal]

basically yeah

[nimble iris]

alright, thank you

hmm

which method should i use to solve this ?

[trim portal]

wdym by solve?

Show it diverges?

[nimble iris]

yes

[trim portal]

I would first show that it diverges iff sum of 1/sqrt(n) diverges

[nimble iris]

direct comparison wouldnt work right, because 1/sqrt(n) diverges

[timid silo]

hi

[nimble iris]

hi

[timid silo]

I need help with the equations of 2nd grade really

[nimble iris]

#❓how-to-get-help

[trim portal]

Why wouldnt it work?

[nimble iris]

since 1/sqrt(n) is greater than 1/sqrt(n)+7, and 1/sqrt(n) diverges

[trim portal]

Oh you mean that

[worn yoke]

limit comparison should work fine

[nimble iris]

okok

1/sqrt(n) ?

for bn

[trim portal]

yeah, you can just compare it with something like 8/(n+7)

[worn yoke]

limit comparison always works as long as top and bottom are both polynomials & roots

[trim portal]

and then show that this diverges by changing the summation bounds

[nimble iris]

oh okay!

[trim portal]

to get to the 1/n sum

[worn yoke]

yes

[nimble iris]

is this for direct comparison ?

[worn yoke]

you would compare with the highest power of n on top and bottom

[trim portal]

yep but limit comparison might actually be easier

[nimble iris]

okk

im gonna try it rn

ok yes, since the limit converges to 8 which is 0<L=8<inf, and 1/sqrt(n) diverges, the series diverges

thanks guys!

.close

[obtuse pebble]

Channel closed

Closed by @nimble iris

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble iris]

am i allowed to say that sin(6/x) is less than sin(x) ?

[trim portal]

Consider x=5

[nimble iris]

wait nvm im dumb cuz either way that would not prove convergence

crappp

[royal basin]

http://xyproblem.info/

show your series

[royal basin]

are you instructed to use a particular test or are you allowed any you know?

[nimble iris]

any

whatever is most fit

[royal basin]

limit comparison with 6/n is easiest.

[nimble iris]

woah, i did not know you can do that

i will try

[royal basin]

do what

[nimble iris]

limit comparison with 6/n

why specifically 6/n?

[royal basin]

$\sin(x) \approx x$ for small $x$.

[warm shale]

Ann

[royal basin]

but it doesn't make much of a difference if you instead decide to apply limit comparison with 1/n instead.

[haughty coyote]

It doesn't quite work though by mere comparison

[nimble iris]

ohh i see

[royal basin]

i said limit comparison.

direct comparison needs you to jump through another hoop.

[haughty coyote]

Nvm

[nimble iris]

could you explain to me how the limit of xsin(6/x) is 6?

much appreciated

since the limit of sin(6/n)n)/6 is 1 on desmos but i cant comprehend it

[royal basin]

limit of x sin(6/x) as x approaches infinity, surely

[nimble iris]

yes

[royal basin]

$\lim_{t \to 0} \frac{\sin(t)}{t} = 1$

[warm shale]

Ann

[nimble iris]

oh

but in this case, t is not the same

[trim portal]

$\frac{\sin\left(\frac{6}{x}\right)}{\frac{6}{x}}$ you started with this, right?

[warm shale]

MathIsAlwaysRight

[trim portal]

Try substituting u=6/x

[nimble iris]

yes

OHH

thank you guys, so since the limit is 0<L=1<inf and 6/n is divergent (harmonic series), the series diverges

.close

[obtuse pebble]

Channel closed

Closed by @nimble iris

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[night echo]

for part b)

how can I show the line L is not parallel to the plane $\prod$?

[warm shale]

play

[night echo]

i know the line L does not intersectg the plane $\prod$ because of the last row of the GaussianElimination matrix in part b)

[warm shale]

play

[obtuse pebble]

@night echo Has your question been resolved?

[obtuse pebble]

@night echo Has your question been resolved?

[obtuse pebble]

@night echo Has your question been resolved?

[night echo]

.close

[obtuse pebble]

Channel closed

Closed by @night echo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[true narwhal]

Hey, I am unsure how to calculate this:
The bakery has calculated that the variable costs of one loaf of bread are €1.30/piece and the selling price of the bread is €2.90 (incl. VAT 14%). The bakery's fixed costs are €23,000 per month.

The bakery's bread sales are 40% of the entire production. If it is assumed that the same share of the fixed costs should be covered by the sale of bread, how much bread should be sold in that case so that the result from the sale of bread would be €6,000/month.

[true narwhal]

I tried like this, but it just doesn't seem right

[obtuse pebble]

@true narwhal Has your question been resolved?

[true narwhal]

<@&286206848099549185>

[true narwhal]

.close

[obtuse pebble]

Channel closed

Closed by @true narwhal

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stuck herald]

Please help

[royal basin]

!status

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

@stuck herald Has your question been resolved?

[stuck herald]

2

[stuck herald]

pls can you send the solution iam getting 20 percent ans

[stuck herald]

chose numbers as AT = 100, FOOD = 12 AND THEREFORE ABT= 120 AND GOT 20% BCOS OF INCREASE IN 100 TO 120

[royal basin]

WHY ARE YOU SHOUTING?

also this is status 4 (I got an answer and would like my work checked), not 2 (I have begun but got stuck midway)

[stuck herald]

my caps was on lol

[stuck herald]

sorry

[royal basin]

anyway your work and answer are correct

[stuck herald]

but the ans shown is 17 percent

thats wrong then? because there are some mistakes in key i wanted to confirm my answer

[royal basin]

ah, wait. hold on.

i got confused.

you kind of played a part in it too. your status was in fact neither #2 nor #4 but #3 (I got an answer and I am told it's wrong)

and you should say this kind of detail upfront

okay hold up

[stuck herald]

ohh iam new and learning these rules here

pls 'don't mind

[royal basin]

post-tax income is 100, food expenses are 12, pre-tax income is 120, tax is 20

so tax is 20 out of 120

which is 1/6, or about 17%

it's not 20 out of 100

[stuck herald]

so the 20 is not a percent value right

its a integer term

[royal basin]

20 is a value in some currency unit such that the post-tax income of our family is 100 units

[stuck herald]

but 120 is greater than 20 percent of 100 this concept doesnt work here?

[royal basin]

what concept?

[stuck herald]

percent greater

[royal basin]

???

i am not talking about any percentages.

i'm simply considering the family's incomes and expenses in terms of a unit of currency that doesn't have a name

[stuck herald]

what i did was

[royal basin]

but is defined in such a way that the post-tax income is 100 units

what YOU did was the same thing. you took their post-tax income to be 100 units.

you are just overthinking/confusing yourself now.

[stuck herald]

100(1.20) = 120 so i considered this as 20 percent

[stuck herald]

ya totatally i guess

thanks

.close

[obtuse pebble]

Channel closed

Closed by @stuck herald

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dawn nest]

why is the related acute angle of sin(350) is sin(190). shouldn't we just subtract 360 from 350 since 350 degrees is in the 4th quadrant? So sin(10) has to be correct?

[high lily]

wording's the other way around
subtract 350 from 360,
→ 360° - 350° = 10°
will be the related acute angle

[dawn nest]

oh yh my bad that's what I meant, but is it -sin(10) or sin(10)?

[high lily]

= 10°
will be the related acute angle

apply the sign of sine in the 4th quadrant to get the value equivalent to sin(350°)

is sine positive or negative in Q4?

[dawn nest]

negative

[high lily]

yes

[dawn nest]

I understand it now, thank you

.close

[obtuse pebble]

Channel closed

Closed by @dawn nest

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[trail zealot]

I got 245 for the non inverse but i do not know how to get the inverse

[sage geode]

Think about when would g(x) be equal to -7

By walking through all of the cases

[trail zealot]

it would be the second case

[sage geode]

5x^2 = -7 can't be possible for real numbers, so we skip that

[sage geode]

Not really

Because there -3 < x <= 10

[trail zealot]

i meant first

[sage geode]

18 < 21 + x <= 31

[sage geode]

In the first case g(x) can't be negative

Thus it must be the third case

[trail zealot]

so it is 2-sqrt-7?

[rocky goblet]

we're not trying to find g(-7)

we're trying to find the input to g so that -7 is the result

[sage geode]

No, you gotta find x such that 2 - sqrt(x) = -7

[trail zealot]

oh

ive been doing. itwrong

I have another question

that I do not understand at all

[sudden wadi]

A/B is the same as when x=0

[sage geode]

Look at how the function is undefined at x = 1

Meaning the denominator must be x - 1

Thus B = -1

Then consider what oLouis said, because f(0) = A/B = -A = -2 (according to the graph)

[sudden wadi]

its -2 on the graph isnt it?

[trail zealot]

-1 is incorrect

[sudden wadi]

when x = 0 the graph is at -2 so A/B is -2

[trail zealot]

Oh I understand now thanks

last question

[sage geode]

Oh I forgot we were solving for A/B nvm

[trail zealot]

I tried plugging in numbers

like a guess and check

but I got stuck

[sage geode]

Note that C^3(n) = 16 means that C(n) = cbrt(16)

But it can't be possible because C(n) is always an integer, it can't be an irrational number

[trail zealot]

true

[high lily]

think here it means composition

[sage geode]

That makes more sense yeah

[high lily]

C(C(C(n))) = 16

[trail zealot]

oh i didnt think it like that

[sage geode]

I guess you then consider cases

[trail zealot]

?Im guessing one of the answers are 8

Am i correct?

[high lily]

how are you getting 8

[trail zealot]

well C(C(C(n)))=16

so since its even

we do

oh wait

ye i messed up

so how would I get the answer then?

[high lily]

i recommend using something like a tree

consider the value(s) of n where C(n) = 16

and branch out

[trail zealot]

so can n be 32?

[high lily]

C(32) is 16
and keep going

[trail zealot]

hmm

[high lily]

2 more times

there's another value of n where C(n) = 16

[trail zealot]

5 works

5x3+1

[high lily]

and same idea for the 16 and 5

whoosp

[trail zealot]

so would the answers by 32,5?

[high lily]

no

that's just if it was asking for C(n) = 16

repeat this process two more times

C of these values gets you 16,
so now you want the C of the values that give you 32, 5

[trail zealot]

oh so next it would be C(n)=32

[high lily]

and the C of the values that give the above values

[trail zealot]

I still am not understanding

[high lily]

oh so next it would be C(n)=32
start with that

what would be the values there

[trail zealot]

64

[high lily]

and then same idea for the 64

[trail zealot]

128

[high lily]

anything else?

[trail zealot]

hm

63

[high lily]

no

3 * 64 + 1 isn't 64

[trail zealot]

21

[high lily]

yes

[trail zealot]

so 128,21

[trail zealot]

42 and 256

[high lily]

why are you going further

[trail zealot]

so 32,64,21,128

is that correct?

[high lily]

no

[trail zealot]

then?

[high lily]

you're only interested at the value at the end of the tree

C(C(C(21)))
=C(C(64))
=C(32)
=16

[trail zealot]

im still lost

[high lily]

you do understand function notation right?

[trail zealot]

sorta

[high lily]

C(C(C(n)))=16
the notation asks for this

[trail zealot]

ye

C(n)=16

n=32

C(n)=32

[high lily]

that when the function is applied to a certain value 3 times gives 16

and such values can be obtained working backwards

32 is a value that when C is applied once gives 16

64 is a value that when C is applied gives 32,
thus when C is applied twice gives 16
i.e C(C(64)) = C(32) also gives 16

21 is a value that when C is applied gives 64,

[trail zealot]

yes

[high lily]

so applying C to 21 three times
C(C(C(21)) = C(C(64)) = C(32) = 16

n=21 is a value where C^3(n) = 16

[trail zealot]

i have to fin all the values of n

[high lily]

yes

and this is a broken down explanation of why 21, the value at the end of the tree is one of those values and NOT the 32, 64 in the middle of the tree

C(32) is 16
C(C(C(32))) is not 16

C(64) is 32
C(C(C(64))) is not 16

similarly 128 would also be one of the values you want

[trail zealot]

so for n i have 128,21

[high lily]

currently yes,

apply the same idea with the branch with 5

[trail zealot]

thats the problem

[high lily]

consider the value(s) that get you 5

[trail zealot]

idk how to do 5

[high lily]

the same way you obtained 32, 64, 21, 128

[trail zealot]

o

10

works

then 3 works

and 20

[high lily]

is there an even number that when divided by 2 gives 5
is there an odd number that when multiplied by 3 and 1 is added to the result gives 5

[trail zealot]

yes for even

but no for odd

the even is 10

[high lily]

yeh

so 3,21,20,128 are the values you want

[trail zealot]

i have a problem that is liek this but different in a way

[high lily]

different how

[trail zealot]

instead of C^3

can you help explain in 10 mins

because I have to go

[high lily]

chuck the value in and repeat

see how many times it takes to get to 1

they're explicitly asking for the smallest as the conjecture states that this will converge to 4,2,1 and repeat

what's C(9)?

[trail zealot]

1?

[high lily]

no

look at the function

is 9 odd or even

[trail zealot]

28?

[high lily]

C(9) is 28, yes

and repeat

what's the C of that, C(28) = ?

[trail zealot]

14

[high lily]

and repeat until you get to 1

then count how many times you applied C

(so far its two times)

[trail zealot]

7

22

11

23

[high lily]

not 23

[trail zealot]

34

right?

[high lily]

C(11) is 34

yes

[trail zealot]

17

51

[high lily]

no

[trail zealot]

i meant 52

26

13

40

20

10

5

16

8

4

2

1

19 times right?

[high lily]

yeh

[trail zealot]

or 17?

oh wawi t19

yes

thank you so much for your help

have a good day

.close

[obtuse pebble]

Channel closed

Closed by @trail zealot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lunar tapir]

hello, is there any french helper here ?

[lunar tapir]

In English, the problem is "let E,F and G be 3 sub-vector space, let f:E->F and g:F->G be 2 linear maps."

I don't know if the notations for (1) and (2) are international (let me know if not)

I'm stuck because I have trouble picturing the sets

[obtuse pebble]

@lunar tapir Has your question been resolved?

[lunar tapir]

.close

[obtuse pebble]

Channel closed

Closed by @lunar tapir

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

integral tan^3xsec^4x dx

[timid silo]

here’s my work

why is my work incorrect?

wolfram alpha says :

[wooden cipher]

Its not wrong

You can make your answer match the one WA has

[timid silo]

why does wolfram say this?

[wooden cipher]

Because its a very weird expression

[timid silo]

hm okay

well thank u its good to know i was right anyway

.close

[obtuse pebble]

Channel closed

Closed by @quasi salmon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bronze elk]

Help with 1 a and 1b

[rich plume]

Use absinx/2

[bronze elk]

whats that

[rich plume]

Area of a triangle

[bronze elk]

Shoot

So what if it is an obtuse

[bronze elk]

does it still apply

hello

How do we do an obtuse triangle

pls help

<@&286206848099549185>

its been fifteen minutes

;-;

[foggy idol]

Uh

Yeah it applies to any type of triangle

[bronze elk]

really

So for this one

How would it work

10sin(30)

[rich plume]

It still applies

[rich plume]

Sin 30 deg

[obtuse pebble]

@bronze elk Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[terse warren]

I think you have to subtract 2 integrals here, I just don't know how to set those integrals up, can anybody help please

[terse warren]

using the 1/2 * integral from alpha to beta of r^2 dt

i dont know how to find the bounds

[obtuse pebble]

@terse warren Has your question been resolved?

[obtuse pebble]

@terse warren Has your question been resolved?

[obtuse pebble]

@terse warren Has your question been resolved?

[terse warren]

<@&286206848099549185>

[terse warren]

.close

[obtuse pebble]

Channel closed

Closed by @terse warren

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proven spindle]

regarding minimum modulus of a..complex function

[proven spindle]

using the inequality formula

suppose f(z) = a(z) + b(z) + c(z) + d(z) + e(z) + y, where y is some constant

using the modulus inequality formula

|f(z)| >= | |u(z)| - |v(z)| |, how do i extend it to more than 2 terms, as there are...say....6 terms above.
or how should i arrange them if i m supposed to split them up

[obtuse pebble]

@proven spindle Has your question been resolved?

[proven spindle]

this is for lower bound

[obtuse pebble]

@proven spindle Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proven flame]

I forgot how do

[native inlet]

if you have an initial amount of money, then deposit more what are doing to the money in your bank account?

[proven flame]

how to make expression?

[native inlet]

first what operation is being done?

[proven flame]

=

*+

[native inlet]

?

[native inlet]

yes, addition

so we 40 dollars then deposit 10

we have 40 _ 10 into our bank account

[proven flame]

I got

[cinder lynx]

What symbol should we replace the _ with @proven flame

[proven flame]

40 + 10 correct I finish question