help-10

[mossy minnow]

Example equation which does have them(Only 2):

[obtuse pebble]

@mossy minnow Has your question been resolved?

[mossy minnow]

<@&286206848099549185>

[obtuse pebble]

@mossy minnow Has your question been resolved?

[drowsy burrow]

Well, have you tried simplifying it?

[mossy minnow]

This is as simplified as it gets

[drowsy burrow]

Okay, then try writing it as an expression of x

But i guess you can look at it Like that

If e is integer

Then what condition needs to be satisfied?

[mossy minnow]

x and e are both integers

[drowsy burrow]

Thats already True

[latent jasper]

still need help?

[mossy minnow]

Yep

[latent jasper]

e is a random variable right?

it is not like the e=2.7...

[mossy minnow]

Ye

[latent jasper]

which one is it lol?

[mossy minnow]

An integer

Should of wrote y instead of e

[latent jasper]

Here is what I think you should do

cross multiply

Then solve for x

Then you will get an expression that looks something like

x = (ed - b)/(a - ec)

x is integer only if (ed - b) divisible by (a - ec) Ig

[mossy minnow]

Interesting

Plugging it into Wolfram gives me the integer ones

But how to show which e do that is unknown to me

[obtuse pebble]

@mossy minnow Has your question been resolved?

[latent jasper]

wdym?

[latent jasper]

do you know about modulo?

[mossy minnow]

Yes

[latent jasper]

well then use that

(ed - b) mod (a - ec) = 0

Btw I'm not really sure if this is the way to do it, I'm just guessing, but maybe try to continue on this

[obtuse pebble]

@mossy minnow Has your question been resolved?

[obtuse pebble]

@mossy minnow Has your question been resolved?

[obtuse pebble]

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[rocky locust]

How do you get to the answer 4/3 ?

[supple granite]

how many solutions does 3x^2-4x+c=0 have?

[rocky locust]

oh

LOL

ty

[fluid garnet]

Put y=0

[supple granite]

yeah you use determinant=0

[fluid garnet]

Thats it

[viral blade]

discriminant*

[sweet edge]

also the axis of symmetry

[supple granite]

oh lol I'm not used to english math terms

[viral blade]

I've done the same thing before too lol

[rocky locust]

wait

sry what do u mean by discriminant = 0 ?

[rocky locust]

cause this has 2 variables so i still dont know how to solve for c

[sweet edge]

the discriminant is the inside part of the sqrt(...) part of the quadratic formula

[supple granite]

consider c a constant

[sweet edge]

$\sqrt{b^2-4ac}$

[supple granite]

and x is the variable

[viral blade]

solve for x in terms of c

[warm shale]

Jukelyn

[viral blade]

it's just the b^2-4ac I believe

not including square root

[sweet edge]

sorry, yeah the inside

mb

[fluid garnet]

You can also factorize easily

[supple granite]

if you're confused, you can find the vertex, then (y coordinate of the vertex)=0

it's the same principle as discriminant=0

[rocky locust]

ahh

alr thx

[obtuse pebble]

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[rocky locust]

How do you get to that answer ?

[floral canopy]

Let sinx = t and solve for t

[rocky locust]

thx thats nice solution

and then u get sin x = 1/3

and then u do arcsin(1/3)

[obtuse pebble]

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[rocky locust]

How do you solve for 5/4 ?

[royal basin]

you don't "solve for 5/4", you solve for x

[rocky locust]

How do you solve for x

[royal basin]

well, one possible first step would be to square both sides immediately, although i am not sure whether that's the best way.

have you made any progress so far yourself?

[pine echo]

I need help with tree diagrams, ik its pretty basic but I forgot them...

[rocky locust]

yeah i think thats the solution

[crimson oyster]

move the square rooted terms to one side and 1 to the other

now square on both sides and solve

[royal basin]

@Monke_Muncher#6695 channel occupied, please move. read #❓how-to-get-help for instructions.

[obtuse pebble]

@rocky locust Has your question been resolved?

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[karmic crypt]

Difference of two squares for 65 squared and 63 squared

[karmic crypt]

Hell

Help

[warm canopy]

Your question is too vague, what are your instructions

[karmic crypt]

It’s erm

Using the difference of two squares

Evaluate the following

And then 65 squared and 63 squared

But idk how cause no number is squared to 65

You know

[warm canopy]

But you know what number squared gives you 65²

[karmic crypt]

What

Am I dumb

[timid silo]

do you mean to evaluate 65^2-63^2?

[karmic crypt]

Yep

Using the difference of two squares

[timid silo]

so are you familiar with the factorization of difference of squares?

[karmic crypt]

Yeah

I watched a video on it yesterday

Seems easy

But when you factorise squares it’s like a square number like 7^2 or something idk

So I’m confused

[warm canopy]

You have two square numbers

65² and 63²

[karmic crypt]

Yes

[warm canopy]

So you know what their square roots are

[karmic crypt]

So 65 square root

Is 65x65?

[warm canopy]

?

[karmic crypt]

or

Bro idk

[warm canopy]

What's the square root of 65²?

[karmic crypt]

4225

[warm canopy]

How are you getting 4225

[karmic crypt]

Wait

If I get the square root

It will be a decimal right

[warm canopy]

Do you know what a square root is

[karmic crypt]

Yes

[warm canopy]

What is it

[karmic crypt]

Multiples itself

So

[warm canopy]

What?

[karmic crypt]

Bruh

Are you trolling me

@timid silo

[timid silo]

waht

no one is trolling you

[karmic crypt]

Then what is a square root

I’m asking you to help me

Cause this guy isn’t really

Not explaining

[warm canopy]

I am trying to understand what you know

[karmic crypt]

Yes and I’ve told you

And you just question me

What else is a square root ?

7^2

49?

[timid silo]

welp knowing what a square root is is quite important, but i mean we can kinda just ignore the square root part for now

[karmic crypt]

7x7

[karmic crypt]

I legit do

[warm canopy]

That's squaring a number

[karmic crypt]

Yes

[warm canopy]

Which is not a square root

[karmic crypt]

But I know how to define a square root when you put it on anything

Multiply itself to get that number

That’s legit what square root does

[warm canopy]

So you should know what the square root of 65² is

[karmic crypt]

Ok so

65 x itself?

Cause it’s square rooting

Which is how I got that number earlier

[timid silo]

so are you saying the square root of 65^2 is 65 or 65x65

[warm canopy]

65 times itself is 65², we want the square root of 65²

[karmic crypt]

65 x itself is 65^2

So then if I put 65^2

In a calculator

4225?

Can you explain

[warm canopy]

square root of x is asking "what number do I times by itself to get x?"

[karmic crypt]

You get x^2

[warm canopy]

No

That is not what the sentence says

That's you squaring x, not square rooting

Literally the opposite

[karmic crypt]

So then

If it was 49 for example 49^2

It would be 7?

Cause 7x2

I mean 7x7

[warm canopy]

7x7 is 7 squared

[karmic crypt]

Ok

Why are we using square root

Here

It’s 65^2

[timid silo]

square root can help you understand the question better, but just ignoring square roots for now, if you know that a^2-b^2 = (a+b)(a-b)

in 65^2-63^2

what is a and b

[karmic crypt]

That’s exactly my question

If you write

(A+b)^2

What is a and b

[warm canopy]

https://brilliant.org/wiki/applying-the-difference-of-two-squares-identity/

[karmic crypt]

Don’t worry

I give up

[obtuse pebble]

@karmic crypt Has your question been resolved?

[obtuse pebble]

@karmic crypt Has your question been resolved?

[obtuse pebble]

@karmic crypt Has your question been resolved?

[obtuse pebble]

@karmic crypt Has your question been resolved?

[obtuse pebble]

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[rustic musk]

help

[rustic musk]

how do i find a skew projection matrix?

i know how to find a projection matrix i just dont know what a skewed one is

[gleaming ridge]

I am not sure what a skew projection means but to find transformation matrices

See where does the transformation maps the basis vectors to

In this case, (1, 0) and (0, 1) as they form the basis for R2

[cosmic berry]

Can someone send me Dr. John chungs fourth edition book?

[inner field]

download it from libgen

just type libgen

and search in it

[rustic musk]

ok, so how would I do that? would I find the vector spanning the line x + 4y = 0, which is [-4; 1] right? Then what would I want to do?

[cosmic berry]

not available

[gleaming ridge]

Talking about piracy is against tos of this server please refrain. You might get banned

[inner field]

blunt library?

[gleaming ridge]

My main issue is that I don't understand what skew projection means

So, I won't be able to help further here

[cosmic berry]

not available

[inner field]

damn then last is pdf drive

i dont know any other site

[cosmic berry]

I need help

[inner field]

pdf drive

[cosmic berry]

Can you send me a pdf if you have it

[inner field]

i dont have access to broweser rn

they are under update

[cosmic berry]

what is the solution now

[civic zealot]

so, this whole conversation goes entirely against TOS of the server. It also has nothing to do with swim's question.

[rustic musk]

yea i just want help and people are trying to pirate a text book

[cosmic berry]

Anyone can send me John chung's book pdf

[rustic musk]

what do you think the answer is

[civic zealot]

bruh.... what don't you get here.
This isn't your channel. You're asking for an illegal copy of a book

kindly, stfu

[civic zealot]

do you have anything on what a skew projection is?

[cosmic berry]

Sorry for disturbing you

[rustic musk]

nope, only a projection matrix

[civic zealot]

https://math.stackexchange.com/questions/4347129/to-find-the-matrix-of-skew-projection-along-a-vector
This is what I could find. I've never heard of a skew projection before.

[obtuse pebble]

@rustic musk Has your question been resolved?

[rustic musk]

apparently i have this formula, not sure how to use it

[rustic musk]

alright figured it out

[rustic musk]

this was right, thanks so much

.close

[obtuse pebble]

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[brisk needle]

i missed a day in class and never got any formulas to do this

[timid silo]

3a = 2a+a

[brisk needle]

what does that mean

[timid silo]

use the sin of sum of angles formula for sin(2a+a)

[brisk needle]

where did you get sin(2a+a)

[timid silo]

sin(3a)=sin(2a+a)

[brisk needle]

oh

sin 2a*cos a+cos 2a*sina?

[timid silo]

yeah

now use the double angle formula and try and figure out what cos(2a) is

[brisk needle]

2sin a*cos a?

wait no

cos is different

cos^2(a) - sin^2(a)

i got it thanks

.close

[obtuse pebble]

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[novel geyser]

10. The managing director of a private television has to assign five programmes (a,b,c,d,e, not necessarily in this order) to the five time bands of the day numbered from 1 to 5. He also
    has to assign each programme to each of the five compéres (Bruno, Nicola, Pietro, Raffaele e Walter, not necessarily in this order).
    Rafaele is asigned to time band 2
    Pietro presents programme D
    Programme E is televised in time band 4
    Nicola presents programme A in time band 3
    Progamme B is televised in time band 1
    According to these statements, programme C:
    A)will be televised in time band 1
    B)will be televised in time band 5
    C)will be presented by Bruno
    D)will be presented by Raffaele
    E)will be presedente by Nicola

[novel geyser]

so I eliminate a and b choices

but b c and d choices are not precise

[obtuse pebble]

@novel geyser Has your question been resolved?

[obtuse pebble]

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[novel geyser]

.reopen

[obtuse pebble]

✅

[novel geyser]

<@&286206848099549185>

[obtuse pebble]

@novel geyser Has your question been resolved?

[obtuse pebble]

@novel geyser Has your question been resolved?

[obtuse pebble]

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[timid silo]

I got these 2 wrong I need help

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

Nvm I got it

[obtuse pebble]

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[timid silo]

.close

[obtuse pebble]

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[proper coyote]

What did I do wrong? Because i followed all the mathematical rules and should get the same answer right…

[obtuse pebble]

@proper coyote Has your question been resolved?

[frosty spoke]

it seems like you didn't adjust your bounds after doing a substitution

but I guess that doesn't matter, since you did the inverse substitution without adjusting the bounds

also this equality doesn't seem correct

the first log should be negative

[obtuse pebble]

@proper coyote Has your question been resolved?

[obtuse pebble]

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[timid silo]

so im taking discrete math and im just confused how the quantifier stuff works.

[timid silo]

can i just say "assume a = 0, and c = 0"

then all ad and bc will equal 0

or do i somehow math it like

0 * d = 0 * c

0 = 0

so therefore its true

[ivory trout]

uh

[haughty coyote]

That's the idea yeah

[timid silo]

so i can just say assume a = 0 and b = 0?

and sub it in

[haughty coyote]

Not how you'd write it

[ivory trout]

I'm not sure if the way that problem is posed make sense in the first place

[haughty coyote]

Ideally you follow the order of the symbols and use the proper vocab, i.e. (imo but not only imo) "set" and "let"

[ivory trout]

a b c d are numbers, but from what sets?

[timid silo]

real numbers

sorry didnt post the full question

[haughty coyote]

Like set a = 0, let b in R (I guess), set c = 0, let d in R, then ad = bc

[wise talon]

i dont think we can assume a = 0 no?

exists a means a is given to us

[ivory trout]

cause usually an exercise like that would explicitly say eg, Q, N, R+, R - {0}

[unique kettle]

There exists an a means that we can find some a for it to work

[haughty coyote]

That's precisely the meaning of for all actually

[ivory trout]

and especially there where you gotta prove a product, probably using the 0 isn't the best idea

[unique kettle]

So we can assume here that a=0

[wise talon]

waht

there exists an a such that for all b, there exists a c such that for all d, ad=bc

our job is to find a and c im guessing

[haughty coyote]

Which he already did

[wise talon]

yeah I guess thats fine

[timid silo]

like as long as i define c and d its fine i guess

thanks

.close

[obtuse pebble]

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[burnt thunder]

how do i isolate Vf outsidd

[burnt thunder]

😭

[timid silo]

what have you tried?

[timid silo]

THERE THERE DONT CRY

[burnt thunder]

i started with moving Vf to the left

[burnt thunder]

i duno what to do after

my answer is nthn like like the actual answer

[upbeat lagoon]

... what are you trying to find in here ? what is delta(d) ?

[burnt thunder]

Vf

i need to isolate it

to find it

[upbeat lagoon]

$\frac{\Delta d}{\Delta t} = \frac{V_f + V_i}{2}$

[burnt thunder]

yea

[warm shale]

mino65

[upbeat lagoon]

okay ... just split the fraction

[burnt thunder]

wdym

[upbeat lagoon]

$\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}$

[burnt thunder]

what do i do next to isolate Vf

[upbeat lagoon]

tbh i really dunno what's the purpose here what benefit is in isolating Vf ?, if you're trying to derive the equation of distance you'll have to take the delta(t) to the other side and integrate, after that you'll find Vf after plugging the distance, the period t, the initial speed Vi

[burnt thunder]

bec i have all the variables

except vf

so i need to sub them in to find vf

but i need to isolate it out first

[upbeat lagoon]

you don't know derivatives and integrations right ?

[burnt thunder]

nope

this is the answer

but like

[upbeat lagoon]

good

[burnt thunder]

i duno how

they got jt

it

💀💀

[upbeat lagoon]

okay okay

here

$\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}$

[warm shale]

mino65

[upbeat lagoon]

use this formula on the Vf Vi side

[burnt thunder]

so both would be over 2

[upbeat lagoon]

or ya know

forget about that

just look that :$\frac{\Delta d}{\Delta t} = \frac{V_f + V_i}{2}$

[warm shale]

mino65

[upbeat lagoon]

right ?

[burnt thunder]

ya

[upbeat lagoon]

we just divided both sides by delta t

[burnt thunder]

yes

[upbeat lagoon]

and there multiply both sides by 2

[burnt thunder]

okok

-vi

[upbeat lagoon]

?

[burnt thunder]

like this

[upbeat lagoon]

👍

[burnt thunder]

if i flip both sides the signs dont change

[upbeat lagoon]

aahhh ... dunno what does that mean but anyway you found the answer and that's all that matters

[burnt thunder]

like switch the sides so Vf is on the left

[upbeat lagoon]

if you switch the sides the signs will change

[burnt thunder]

like this

[upbeat lagoon]

don't think of it as switching but more like you just subtracted Vf in both sides so one side got out with 0 and the other side left with -Vf

aaaaaaaaaaaaaaaaaaaaaaaah yes

it's right

[burnt thunder]

iokok

[upbeat lagoon]

if you're donne close the channel

[burnt thunder]

okok tyy

.close

[obtuse pebble]

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[ebon finch]

I have to solve (|2x+3|)/(x-1) < 3 and I thought of approaching it by squaring both sides as to get rid of the absolute value but it seems like incorrect. Why?

[obtuse pebble]

@ebon finch Has your question been resolved?

[ebon finch]

<@&286206848099549185>

[ebon finch]

.close

[obtuse pebble]

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[crisp quail]

how do i intergrate this?

<@&286206848099549185>

[hidden rose]

you coud use the identity: cos(A + B) = cos(A)cos(B) - sin(A)sin(B)

in this case what will A and B be?

[crisp quail]

just some variable

constant

[hidden rose]

I mean in your case

[crisp quail]

they dont specify

[hidden rose]

I know you choose id doesn't matter

[crisp quail]

just treat it like a cnstant

[hidden rose]

this is an identity that works for any A and B so use it in your advantage to seperate your variable (theta) from the other constants

this will help simplify the integral and make it easy

do you get my point? @crisp quail

[crisp quail]

yes

i am doing it

[hidden rose]

ok

don't forget to close when you finish

[crisp quail]

hi

i did it

[hidden rose]

good job

[crisp quail]

i am getting A/2pisin(2pif*t)

is that right?

it is suppose to be 0

[hidden rose]

can you show me how you reached this

[crisp quail]

when I intergrate it i get A/2pi (sin(theta)cos(2pift)+sin(2pift)cos(theta))

i subsitute my bound

hold on

i think i notied y istake

[hidden rose]

you only substituted once right?

[crisp quail]

yea

[hidden rose]

it happens sometimes np

[crisp quail]

ok thx

[hidden rose]

welcome

[crisp quail]

how should I close it?

[hidden rose]

.close

[obtuse pebble]

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[real dove]

need to find this derivative. Im using quotient and chain rule, but the incorrect answer persists

[wooden cipher]

check your quotient rule

[real dove]

would this be wrong?

[wooden cipher]

no thats correct

where are your parentheses in the answer you gave?

[unique kettle]

The top is wrong on your answer

[wooden cipher]

indeed

[real dove]

it automatically removes them for some reason

[wooden cipher]

oh lmao

[real dove]

where did i mess up on the top?

[unique kettle]

We’ll look at your -1(x+1)

[wooden cipher]

distribute

[unique kettle]

You subtracted the 1 but added your x

[real dove]

wow

rookie mistake

thanks so much guys

[unique kettle]

👍

It’s always something small with calculus lol

[obtuse pebble]

@real dove Has your question been resolved?

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[obtuse pebble]

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[rare mirage]

i have 2 more after this but i can only send them once i get this right casue its in order

[obtuse pebble]

@rare mirage Has your question been resolved?

[mellow panther]

something like this might be what you are looking for

[rare mirage]

yea that was the correct one, i just guessed and got it wrong

by chance could u help me wiht 2 questions more?

[mellow panther]

sure

[mellow panther]

I can kinda work you through how I did it too

[rare mirage]

ik i look at the zeros

for the things in ()

[mellow panther]

yeah

[rare mirage]

but i always get confused on what to do with the y intercept

[mellow panther]

so theres one at 1 and one at 5

so you start with this

and you want it to intercept at -25

but right now, (0 - 1)^2(0 - 5)^2 = 1 * 25 = 25

so in this case you can multiply the whole thing by -1

[rare mirage]

so i set it equal to the equation and then set x as 0

and solve

[mellow panther]

kinda

so if you plug in 0

that gets you the current y intercept

which is probably wrong

and then you can multiply the whole thing from there

and since the zeroes have a value of 0

they won't move at all

since 0 times anything is still zero

so like if (x-1)^2(x-5)^2 is zero for some value of x, then clearly if you have a * (x-1)^2(x-5)^2 it will still be zero at that same value of x since it will just be a * 0 = 0.

[rare mirage]

i kinda ge tit

so

would this be correct

[mellow panther]

lets see

so theres a 0 at 2 and two zeroes at -6

so that seems riht

and evaluating that at 0, (0 - 2) * (0 + 6)^2 = -2 * 36 = -72

120/-72 = -5/3

so you would need to multiply the whole thing by -5/3

not 5/3

[rare mirage]

oo i prob forgot to add the negative on the72

tysm

appreciate it alot

[mellow panther]

np 👍

[rare mirage]

.close

[obtuse pebble]

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[lavish nymph]

can someone help

[lavish nymph]

I need the answers

[plain stag]

what's giving you issue?

[lavish nymph]

im not sure how to put it into a triangle

[plain stag]

try sketching the given info first

[lavish nymph]

where would I put 500

as a,c or b

[plain stag]

those letters mean nothing in isolation

[lavish nymph]

ok ty

let me try to use it

I got this

so is row 1 true cause 288.7 is the first value

@plain stag

[lavish nymph]

yea

[plain stag]

keeping it as a radical instead of a decimal will probably make answering the questions easier

[timid silo]

^

[plain stag]

but yes

[lavish nymph]

so 1 is true?

is this correct?

[plain stag]

the second is obviously false. Before verifying 3, I'm curious what your rationale is

[lavish nymph]

for which one

[plain stag]

for 3

[lavish nymph]

because the ramp built from the point to the top is 577.4 and the point is 500

so if point doubled 1000 than ramp would be 1154.7 not quadruple

[plain stag]

so 2 things. 1, the height of the building isn't doubling, it's the point on the ground moving further away

[lavish nymph]

oh

[plain stag]

and 2, I'm not sure about the math on your second part

[lavish nymph]

so it would be true

[plain stag]

,calc (1000^2 + 288.7^2)^0.5

[warm shale]

Result:

1040.8398964298

[plain stag]

i'm not saying it's true, i'm saying there's an issue with your reasoning, so see if you can correct that first

[lavish nymph]

wait so is it false?

[lavish nymph]

I wasnt doing the distance between them

[plain stag]

that's one issue

[plain stag]

the other is that this is incorrect, and thus your intuition is incorrect. Hence why I'm asking you to try again

[lavish nymph]

idk how

[plain stag]

adjust the correct side, then redo the calculation

[lavish nymph]

im not sure how to

[plain stag]

what part of that is unclear?

[lavish nymph]

what is the correct side

577.4?

[plain stag]

it says the distance between the point on the ground and the base of the tower

which side of the triangle is that?

[lavish nymph]

211.3?

500-288.7?

[plain stag]

no

[lavish nymph]

then what

[plain stag]

look again

the exact distance between the point on the ground and the base of the tower is explicitly mentioned, by that exact wording, earlier

[lavish nymph]

which is the base of the tower 500?

[plain stag]

500 is the height of the tower

[lavish nymph]

577.4?

[plain stag]

that's the distance from the point on the ground to the top of the tower

[lavish nymph]

im not sure what the base

[plain stag]

the base is the bottom

[lavish nymph]

288.7

?

[plain stag]

that's the only other side so yes

that side has its length doubled

[lavish nymph]

so to 577.4

the length of ramp would not quadrouple

so its false

[plain stag]

it is false yes

[lavish nymph]

so this is all good

[plain stag]

yes

[lavish nymph]

ok ty

.close

[obtuse pebble]

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[neon ginkgo]

Do you know the properties of diagonals of a parallelogram? (assuming it's given that is a parallelogram)

Yup that's it

Correct, no problem, you will two equations with two variables, solve them to get x and y

I don't get what you mean..

Yeah, correct for one diagonal, but a slight mistake, it should be, 4x - 2 = 3y - 1

Yup, now write it for other diagonal

Yup

Equate them both to find x

Ohh, sry, not y, like x=x, we know from above x=3y/4 + 1/4, and from second, x=y-1, so y-1=3y/4 + 1/4

Now you can solve them to find y

Lemme check...

Nope, try again

See, take common y terms same side, $y-\frac{3y}{4}=\frac 1 4 + 1$, right? Now solve it

[warm shale]

Gamin8ing

[neon ginkgo]

Yup, now it's correct

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

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[alpine heron]

how would i do this?

[alpine heron]

or all of them

[glass garden]

use exponent rules

[alpine heron]

what are the exponent rules?

[glass garden]

https://www.mathsisfun.com/algebra/exponent-laws.html

[alpine heron]

sorry that confuses me more

how would i use that here?

can i get like an example

[glass garden]

well a square root is the same thing as an exponent of 1/2

that should help

so just write sqrt(x) as x^(1/2)

[alpine heron]

the fraction 1/2 equals the same amount as ^2?

[glass garden]

no

basically exponents can be fractions too

[alpine heron]

wdym then?

[glass garden]

square root is just saying the exponent is 1/2

[alpine heron]

oh so like x^1/2?

[glass garden]

yes

watch this vid maybe it will help
https://www.youtube.com/watch?v=Llrngdh3Rrg&ab_channel=TheOrganicChemistryTutor

[alpine heron]

so what’s does writing x^2 as x^1/2 do?

[glass garden]

you aren't writing x^2 as x^1/2
you are converting the square root to ^1/2
maybe the vid will explain better than me haha

[alpine heron]

ok yeah sorry i’m just trying to figure it out

it’s confusing lol

[glass garden]

yeah np, stuff is hard when you first learn it

but it gets easier, don't worry

[alpine heron]

sorry 1 question i watching the video and he's simplifying with square root of 2, but my question dosent have a square root so then what do i simplify with?

[glass garden]

what do you mean

[glass garden]

do you see the square roots here

[alpine heron]

no

in the first problem is it 2 and 10?

[glass garden]

what is that big symbol on top of everything

[alpine heron]

a square root?

or honestly i don’t know what it’s called

am i on the right tracks

?

[glass garden]

kinda

[glass garden]

yeah it's called a square root

[alpine heron]

did i do anything wrong?

or do you see anything wrong?

[glass garden]

you still have to do the simplifying part

[alpine heron]

oh yeah i know

the step after is the simplifying part right?

[glass garden]

yeah I guess

[alpine heron]

i got the answer

i got 2xy^5

but i know that’s wrong

so what did i do wrong cause the answer is 4xy^5

[glass garden]

you're close
it's 4xy^5

[alpine heron]

what was my miss step?

[glass garden]

tbh you don't have to write 16 as 2^4
you should know the square root of 16 is 4 automatically

then you won't run into any problems

because writing small numbers as exponents gets confusing

[alpine heron]

ohhhh i write down the square root?

and the square root of 2^4 is 4?

[glass garden]

the square root of 16 is 4

yeah

[alpine heron]

ohhhh shut

thanks so much i get it now

[glass garden]

ok nice

np

[alpine heron]

thanks for your help

[alpine heron]

sorry but how would i do wquestion number 2?

its confusing me

[glass garden]

why

[alpine heron]

or question E sorry

its a^21 and a^7

ill show you my work so far

[glass garden]

your answer is 20/6?

[alpine heron]

no thats just what i ended at

but im sure i did it completely wrong

[glass garden]

you can't get rid of the a like that

[alpine heron]

okay

how would i do it

[glass garden]

well do it like how you did the previous ones

[alpine heron]

how do i simplify a^21?

thats what confuses me?

do i just put a^3?

[glass garden]

remember what the square root means

[alpine heron]

what does it mean exactly?

[glass garden]

it means ^1/2

[alpine heron]

so i would do half of 21?

[glass garden]

yeah

[alpine heron]

but thats 10.5

[glass garden]

or you can do it like this I guess

so a^21 is a^20 times a

[glass garden]

basically like how you did this

I mean your first step

and then a^20 becomes a^10 if you simplify the square root

[alpine heron]

ohhh okay

so i did do it right?

like the first part at least

now i have

a^10 over a^3

would i do a^2 times 2?

[glass garden]

yeah this is good

don't forget the extra square root of a

[alpine heron]

yeah

so a^2 times a?

[glass garden]

wdym

[alpine heron]

sorry wdym by this?

can you write it out?

[alpine heron]

why would we do that if we end up with the same thing?

[glass garden]

yeah tbh you don't have to do as many steps as I did

I just showed that you still have to cancel out the square root of a

[glass garden]

what do you mean about this though

if you wanna simplify a^10/a^3 it's just a^7

[alpine heron]

i meant to get rid of the a^3

[glass garden]

you just subtract the exponents

[alpine heron]

cause its an uneven number?

[glass garden]

no it has nothing to do with even/odd

basically, dividing exponents is like subtraction

[alpine heron]

so basically the answer is a^7?

[glass garden]

yeah

[alpine heron]

okay thanks

[obtuse pebble]

@alpine heron Has your question been resolved?

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[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

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[shut rapids]

Hi

[shut rapids]

By any chance does someone know science here?

Cause I've a very important question.

Physics.

[ruby path]

Just ask

[shut rapids]

Ok.

[boreal condor]

i mean as long as someone knows how to do it....

[shut rapids]

<@&286206848099549185>

I'm desperate.

Fast.

<@&286206848099549185>

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[shut rapids]

ok

nvm. i'll ask somewhere else.

.close

[obtuse pebble]

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[fathom flicker]

I need help setting up the model equation for part a. I think it could be y'=Ce^kt ?

Could anyone point me in the right direction please?

https://tenor.com/view/ponder-pondering-hmm-tapping-wondering-gif-5036980

<@&286206848099549185>

[brisk matrix]

it may help to think of what the actual population looks like at year t

consider that y(t) = Ce^t, where C is the initial population at t=0

what should be the differential equation then?

[fathom flicker]

y'=Ce^t

right?

[brisk matrix]

y’ - y = 0 is “nicer” id say

[fathom flicker]

true

hmm

[brisk matrix]

although i’m not sure what they mean by the growth rate

[fathom flicker]

k

yeah well that is why I thought it was Ce^(kt)

because I feel like I had seen something of that form too beforehand

but I've never done a problem of this type

[brisk matrix]

yeah the thing is that they confirmed the population grows by a factor of e

i guess you could model this by y’ - ky = 0

and our model is a special case where k = 1

[fathom flicker]

^ that's what I was just thinking

perhaps k-1

k=1 *

[brisk matrix]

that’s probably what they want if i had to guess

[fathom flicker]

Alright

so for part b

[brisk matrix]

no idea what a logistic eqn is

[fathom flicker]

1000=Ce^t then since k=1

neither do I

this isn't going well

This is the solution, maybe it would help you explain? Because I can't follow it

[brisk matrix]

aye we got part a

that’s pretty cool

[fathom flicker]

yessir

[brisk matrix]

i think part b is just something you learn

it looks awfully similar to the limit definition of e so that might have something to do with it

i’m sure it’s meant to model how the population varies around 1000 rats

[fathom flicker]

Hold on, I will send an image

I see something that might be similar in my notes from lecture

neither of these are population models though

but it gives the form of k times a binomial

doesn't really help me out though it seems? unless you see something useful

[brisk matrix]

they all look kind of similar and i’m sure one of these will fit the bill

i’ve never done modeling though so i can’t comment

[fathom flicker]

yes the diffusion and conduction models are meant to be the same exact form

I wasn't sure if they related to population

this looks useful (from google)

lol

okay that solves part b for me

, rotate

[fathom flicker]

^ I feel like this is proper for step c, and it follows along with their answer all the way until the final step

they write 3/16 R = a

which is 3/16 * 1000= a

which is 187.5, like I got

but they say it equals 375

do you know why @brisk matrix

[brisk matrix]

no clue

maybe just a typo?

[fathom flicker]

I feel like it must be... otherwise I am missing something

thanks for your help!

.close

[obtuse pebble]

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[obtuse pebble]

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[karmic hedge]

https://i.gyazo.com/54b3b5014a5bcff289ffee5b090bc635.png

[karmic hedge]

for e)

[twin helm]

what do you think your predicates will be?

[karmic hedge]

Do you think I would lose marks for saying ∀x∀y(Pizza(x) -> likes(x,y))

Since its technically saying something different (Everyone likes pizza) but it means the same thing

[twin helm]

what is pizza and what is likes?

[karmic hedge]

∀x∀y(Pizza(y) -> likes(x,y))

**

Sry mistake

[twin helm]

no like, what is the predicate pizza and likes

like how are you defining it

[karmic hedge]

What do you mean sry

[twin helm]

what is pizza(y)

and what is likes(x,y)

like they need to have a definition

how are you defining them

[karmic hedge]

All y is pizza, and all x likes y

so everyone likes pizza

is that what you mean?

[twin helm]

I don't think this makes any sense

like translate your sentence into english

what do you get

what does all y is pizza even mean?

I think you can simplfy your predicates

[karmic hedge]

all y is pizza so if something is y (a pizza) then all x likes it

[twin helm]

so your sentence is trying to say
for all people x and for all pizza y, if y is a pizza then all people x like pizza y?

how does that equate to the sentence you are trying to translate?

[karmic hedge]

Thats what I was asking

like I think it means the same thing in predicate logic, but not in english, so would I lose marks for writing it like that?

[twin helm]

I still don't understand why you are defining pizza(y), it seems redundant personally. but it does mean the same thing

[karmic hedge]

How would you write it?

[twin helm]

Wouldn't $\not\exists x(!p(x))$ work? p(x) = x likes pizza

[warm shale]

xpoes

[karmic hedge]

Ah ok

So that symbol at the start means ¬∃x?

[twin helm]

yea

[karmic hedge]

Okok

[twin helm]

the translation would be
There does not exist a person x such that person x does not like pizza

[karmic hedge]

Ok I think I get it

Thanks!

❤️

.close

[obtuse pebble]

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[elfin burrow]

might be a long shot, but is anyone familiar with algebraic geometry?

[elfin burrow]

the proof it's referring to

the bar denotes the projective closure, the subscript a denotes that we're working in affine space, and h denotes the homogenized ideal

[twin helm]

I can't, but I think you would have better luck asking in the advanced math categories

[timid silo]

@elfin burrow #algebraic-geometry

[elfin burrow]

thanks

asked there four hours ago

#algebraic-geometry message

[elfin burrow]

apparently it suffices to show the equality for homogeneous polynomials, but i'm not sure why

[obtuse pebble]

@elfin burrow Has your question been resolved?

[bold panther]

dwadmaw+-32-0-=42-=/2/2--5--201045-5=-wpda=aw=d-2=232-31=---=-zx-x==t-y--y-xyxyz-xc-35-===4/2-04i5820-1-3 which gives us 69 and also gives us =455950043--==023761202=12/.,[,-50?><<::{P401541=59087478592145903554

solve this

[elfin burrow]

I think I was able to prove it?

[obtuse pebble]

@elfin burrow Has your question been resolved?

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[frosty valve]

ans:7.07

what's my mistake lol

[trim locust]

How did you calculate distance?

Between those points?

[frosty valve]

i think i haven't calculated yet

but are my workings right so far?

[trim locust]

Oh I see, yeh those pairs of x and y are A and B, they are correct

But it says length so

[frosty valve]

this?

[lost tree]

Yes

[frosty valve]

ok i got it ty:)

.close

[obtuse pebble]

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[shrewd stone]

How can I complete this question?

So far, I let 2sec^2(x) = 5|tan(x)|

Then, when x is an element of (-pi/2, 0) => tan(x) < 0, hence:

2sec^2(x) = -5tan(x)

And when x is an element of [0, pi/2) => tan(x) >= 0, hence:

2sec^2(x) = 5tan(x)

But I am really not sure after this

I tried to multiply each side by cos(x), so that 2/cos(x) = +/-5sin(x)

And therefore 2sin(x)cos(x) = +/- 2/5

Hence, sin(2x) = +/- 2/5 and solve

But yeah, I'm not sure what to do because when i solve this, my answer doesn't match with any of the provided options

[obtuse pebble]

@shrewd stone Has your question been resolved?

[shrewd stone]

<@&286206848099549185>

[wintry swift]

maybe this helps.

[shrewd stone]

ok

ill try it, thanks

.close

[obtuse pebble]

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[bright geyser]

we did this in a lecture, proving that f: Z --> Z, f(x) = 2x + 1
is injective
the lecturer went through a bit of a strange method
would saying
take f(x1), f(x2) in Z
such that f(x1) = f(x2)
then 2(x_1) + 1 = 2(x_2) +1
2(x_1) = 2(x_2)
x_1 = x_2
therefore f(x_1) = f(x_2) implies that x_1 = x_2
is that a proof of injectivity aswell>?
and is that too informal / not layed out very well

[royal basin]

take f(x1), f(x2) in Z
you mean take x1, x2 in Z

otherwise it's fine

[kind hawk]

That is the standard way of showing injectivity

You directly show the definition

[obtuse pebble]

@bright geyser Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[quasi pelican]

What this mean if use word

Like enlgish word

Like write it in english waht it be

[timid silo]

square root?

[quasi pelican]

If root 12 + root 112

The full sentence sir what it call

[timid silo]

probably isnt a very clean way to say it

either "sqrt bracket open 12 plus sqrt 112 bracket close"

[quasi pelican]

If the square root of 12 + the square root of 112 in squasre root of 12

[timid silo]

or "12 + sqrt 112, everything under another squareroot"

[quasi pelican]

Wait lemme ask elon

He aint haplping

[ruby path]

The square root of 12 + root 112?

[mighty geyser]

alternatively "polish square root plus twelve square root one hundred and twelve"

[ruby path]

Polish square root?

[mighty geyser]

polish notation

[ruby path]

Then the winged hussars arrived

[quasi pelican]

Oh my god

Im boutta die

Polish square root plus twelve square root one hundred and twelve

[timid silo]

i need help with these

i know these topics so well but it just doesnt turn out right..am i doing somehtign wrong? am i not accurate enough?

[quasi pelican]

Not my land ( I still need help )

[mighty geyser]

i think this is an efficient way to describe it since polish notation avoids brackets

[obtuse pebble]

@quasi pelican Has your question been resolved?

[timid silo]

?

[obtuse pebble]

@quasi pelican Has your question been resolved?

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[timid silo]

"A gastric dressing contains sodium bicarbonate as an active substance, in a concentration of 25%. Knowing that to reduce the hyperacidity of 200 grams of gastric juice, by decreasing the concentration of hydrochloric acid, from 0.5% to 0.3%, the patient consumes two doses, then one dose weighs:”

[timid silo]

<@&286206848099549185>

[trail cloak]

Hmm

What did you try out in the problem?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

Bestie I have no clue on how to solve it

[trail cloak]

Hmm

Okay first react to the bot's message

[timid silo]

I did

[obtuse pebble]

@timid silo Has your question been resolved?

[trail cloak]

Okay

Hmm