help-10

[sage geode]

Yup

[hard minnow]

I’m sorry, but we got pi/3 by setting the expressions equal to one another?

[sage geode]

Yes

And by looking for the solutions inside the interval (0, pi)

[hard minnow]

Can you show me how you were able to solve it?

[sage geode]

cosx - 0.5 = 0

cosx = 0.5

And I just remembered that happens when x = pi/3

[obtuse pebble]

@hard minnow Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frail rapids]

the question is to find the values of k for which the following equations have two equal root

[sonic anchor]

c is -2k

[frail rapids]

kk

[sonic anchor]

so try and find the discriminant again

just ping me when you have and send another picture

[frail rapids]

i think this gives the answer

but how do i do this quadratic

[sonic anchor]

yes now you just use the quadratic formula to calculate what k would give you a discriminant 0

[frail rapids]

kk

[sonic anchor]

with a=9, b=8, c=0

[frail rapids]

got it

k = 0 or -8/9

thanks

.close

[obtuse pebble]

Channel closed

Closed by @frail rapids

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse burrow]

Your patient is at high risk for developing refractory cardiogenic shock and is extremely hypotensive. You receive an order for:

IV Levophed (norepinephrine), start infusion at 0.03 mcg/Kg/min STAT.

The patient weighs 198 Lbs.

The medication is available in a concentration of 4 mg per 0.25 Liters of D5W.

At what rate will you set the pump in mL/hr to start the infusion (with mL rounded to the nearest whole number)?

[tardy epoch]

i don't recommend using help channels for dispensing drugs to patients

[obtuse burrow]

its not real friend

its a problem working on dimensional analysis

I am a nursing student

First, convert the patient's weight to kilograms:

198 lbs / 2.205 = 89.8 kg

Next, use dimensional analysis to calculate the rate in mL/hr:

0.03 mcg/kg/min * 89.8 kg * 60 min/hr * 1 mg/1000 mcg * 4 mg/0.25 L = 86.6 mL/hr

Therefore, the rate at which the pump should be set is 87 mL/hr (rounded up to the nearest whole number).

[obtuse burrow]

If you recommendation is valuable, as you're shown to believe so in your entail statement, can you double check my work?

[tardy epoch]

i have an entail statement?

what's mcg?

[tardy epoch]

is this what you typed?

$0.03 \frac{mcg}{kg\cdot min} \times 89.8 kg \times 60 \frac{min}{hr} \times 1 \frac{mg}{1000 mcg} \times 4 \frac{mg}{0.25 L} = 86.6 \frac{mL}{hr}$

[warm shale]

riemann

[tardy epoch]

you have 2 mg in the numerator, so you should flip the 4mg / 0.25 L term

[obtuse burrow]

micro gram

im sorry i dont follow you my friend

[tardy epoch]

can you confirm the long equation i typed above is what you meant to type?

[tardy epoch]

.

[obtuse burrow]

ohh yeah

nice

[tardy epoch]

do you see that mg in the numerator appears twice?

and your volume unit (L) is in the denominator?

[obtuse burrow]

Awesome

[tardy epoch]

but you want mg to cancel and you want L in the numerator

[obtuse burrow]

Thank you

[tardy epoch]

good work

good luck on nclex

[obtuse burrow]

fuck

nex gen started this year

its a beast

[obtuse pebble]

@obtuse burrow Has your question been resolved?

Channel closed

Closed by @obtuse burrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine kraken]

Is this a linear or Logarithmic trend

I put a linear line down because it's apparently linear but it curves at the beginning

[cursive slate]

It is linear in a logarithmic axis. If you look at the x-axis it is 10^0, 10^1, 10^2, 10^3. If it is linear in a logarithmic axis, that means the function itself is logarithmic when plotted on a normal linear axis

[alpine kraken]

So should I draw a straight line or slight curve in the beginning

Because I have this one from earlier

[obtuse pebble]

@alpine kraken Has your question been resolved?

Channel closed

Closed by @alpine kraken

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frank flint]

hello

[frank flint]

Im trying to understand Big O Notation properly for my algorithm class
is it the case that:

[warm shale]

GoldTheseus
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[obtuse pebble]

@frank flint Has your question been resolved?

[obtuse pebble]

@frank flint Has your question been resolved?

Channel closed

Closed by @frank flint

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant tide]

How am I supposed to do this?

[pliant tide]

im thinking about substituting something to get rid of the e^x but idk

[neon ginkgo]

What I can see is take e^x as second function and then integrate it by parts..then later on substitute e^x as u, might help

[pliant tide]

can i let u = e^x right now

[neon ginkgo]

but then it will cause problem while solving $\int \sec ^3 (u^3) \ dx$

[warm shale]

Gamin8ing

[tardy epoch]

did you write the problem down wrong

[pliant tide]

What do you mean take e^x as a 2nd function?

[pliant tide]

no i took a screenshot of the problem

[tardy epoch]

can you show the whole page

including the instructions

[neon ginkgo]

i meant taking it as g`(x) like here

[tardy epoch]

i see

[pliant tide]

i dont think i would get anywhere tho...

[tardy epoch]

ask your teacher if they made a mistake typing (d)

,w int e^x sec^3(e^(3x))dx

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[tardy epoch]

,w int sec^3(y^3) dy

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[pliant tide]

damn my teacher tripping 💀

[neon ginkgo]

look, as we goo it would be, $\sec^3 (e^{3x}) \times e^x - \int (\sec^3 (e^{3x}))` e^x dx$

[warm shale]

Gamin8ing

[unreal musk]

By pattern of the rest, I'd assume they wanted it to be e^{3x} rather than e^{x} I would guess(?)

[pliant tide]

ye prob

[neon ginkgo]

after differentiating, $e^x \ sec^3(e^{3x}) - \int 3sec^2(e^{3x}) \times 3e^{4x} dx$, then assume $e^{3x} = u$, then apply by parts, @pliant tide

[warm shale]

Gamin8ing

[pliant tide]

thanks for the help everyone but i think my prof just mistyped the question

.close

[obtuse pebble]

Channel closed

Closed by @pliant tide

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wide flame]

I got 0=0

[unreal musk]

Really? How so?

,w 4x + 2y = 6, 2x + y = 3

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by chartbit#3171

[unreal musk]

Oh yea you're right, fairs, scalar multiple of each other

Well, of course you have effectively one equation so you can e.g. get y in terms of x

[wide flame]

So does that mean I could input anything into x?

[novel trench]

i dont think its possible to find x and y in here

[unreal musk]

Yea for example x can be anything you want, and then you can determine y from there, you get a line of solutions

[novel trench]

send y to one side so you can find the linear function

if thats what is asked here

[warm plover]

For problems like these solutions are infinite

[novel trench]

yeah

[warm plover]

Cause both lines are parallel

Therefore, infinite number of coordinate pairs

[wide flame]

So it just one straight line keep going up

[novel trench]

yea

what is asked exactly in the question though

the graph or the f(x) equation

[wide flame]

Solve the following system of linear equation. Use the elimination or the substitution method.

[novel trench]

well is it asking to find x and y

cuz if yes its not possible

[warm plover]

Thinking of it as a graph has no harm

It's just representing it visually

[wide flame]

so for question it impossible to solve it by find point xand y of int between the equation because their the same thing

[obtuse pebble]

@wide flame Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

hello

[timid silo]

this too please

[timid silo]

<@&286206848099549185>

[solemn osprey]

1. is that the sides MUST be proportional. Proportionate means the sides must be the same ratios
2. is that the two triangles must be equiangular (have the same angles).
   Can you take it from here?

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[north anchor]

someone can help me

[sweet edge]

what have you tried so far

[north anchor]

I don't understand why the point Q is not included and the P is

[sweet edge]

That's just how they labeled it ig

[north anchor]

?

[sweet edge]

Poor labeling choices

That's what I'm betting on

[north anchor]

oka

[obtuse pebble]

@north anchor Has your question been resolved?

Channel closed

Closed by @north anchor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

hello i am very stuck

i keep trying "practice another" on webassign

i use the same exact formula for the practice as i do the original, but i keep getting the original wrong and the practice correct.

here is what i did for the practice:
sqrt(49+16) * sqrt(36+16)

this got me 58.137

here is the original

i tried decimal and no decimal.

here is what i did:

sqrt(25+4) * sqrt(25+9)

i got 31.4

tried 31, tried 31.4. both are wrong. really not sure what to do because i keep getting this right in the practice problem.

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

<@&286206848099549185>

[idle otter]

hey! i think it may be an error on webassign. using the formula W=F•d, I also got 31.

[timid silo]

i will email someone then

thank you for the confirmation. its very weird because i kept using the practice feature for the problem, kept getting it right, and this is wrong. wtf lol.

.close

[obtuse pebble]

Channel closed

Closed by @broken vapor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[terse stone]

Hello

[timid silo]

Greetings

[terse stone]

I'm in a college-level math stats class, and our instructor hasn't gone over Bayes' theorem in much detail, and I feel that that's exactly what I need to complete the problem below.

I'm going to be honest in that I've tried using chatgpt for answers, and all the answers it generated were marked as wrong. I'm wondering if isn't a problem with the answer key/website automatic grading thing.

[timid silo]

ChatGPT is an epic fail at anything math related.

[terse stone]

Yeah

[timid silo]

it cant do basic physics lol

[terse stone]

So I noticed

I gave it the same problem 5 times in a row...

and each time it gave a brand new answer.

[timid silo]

Maybe one day. but today is not that day.

math discord prevails

[terse stone]

Yeah.

[timid silo]

sorry i never took stats so i cant help lol, but i thought id add this much at least.

[terse stone]

Think you could help me through it?

🙃

[timid silo]

kekw

[terse stone]

Thanks.

[timid silo]

false hope

good luck soldier, and sorry for flooding ur chat

[terse stone]

No worries.

[terse stone]

To anyone able to help, this is my problem.

@timid silo Think you might be able to help?

[timid silo]

Hello

I know nothing about stats

[terse stone]

😢

Okay, thanks.

[timid silo]

but isn't the first problem just multiplication

[terse stone]

What would you think you need to multiply?

[timid silo]

Chance a user test positive for drug use = 0.93
Chance a positive test is a false-positive = 0.05

[terse stone]

I can try it, perhaps.

[timid silo]

Chance a user is a drug user = 0.93 * (1-0.05)

[terse stone]

Just tried it. didn't work.

[timid silo]

oh wait

i read tht wrong

or did i

missing a step maybe

[terse stone]

Maybe

[terse stone]

<@&286206848099549185> If you have any knowledge of stats and enough to help out, some help would be greatly appreciated!!

[drifting wraith]

you kinda draw it like a tree, and it makes sense, and you get it

someone said they don;t get it when it's a tree but they get it when it's a venn diagram

but i only get it when it's a tree

[terse stone]

I can't make it into either one...

I don't have enough info

[drifting wraith]

i'll do it

we know that 0.93x + 0.05(1−x) = 0.17, so we have enough info to get x

[terse stone]

Okay

I'd agree

But what formula is that?

[drifting wraith]

it would be something like P(A) = P(A & B) + P(A & ~B)

i don't know

[terse stone]

Hmmm

[timid silo]

Solution: Don't do drugs

[terse stone]

Yea

[drifting wraith]

@terse stone

[timid silo]

• Create a language model
• Give it a huge dataset of text to train on
• Make it learn to predict the continuation of a text
• It learns the intricate linguistics of English and human writing
• Modify it slightly to make it a chatbot
• People use it to aid with their math homework
• Screw it might as well let it kill us all

Anyways I won't bother any further, good luck with your math question

[timid silo]

Where did the last point even come from

[timid silo]

I made it up

Yeah but whats the relevance lol

[terse stone]

Interesting

[timid silo]

That's what I would do if I made a language model that learned to reproduce human writing and people used it for math homework even though it has basically no math knowledge whatsoever

[terse stone]

Let me try and solve the equation you came up with

[timid silo]

lmao

[terse stone]

Cool, it worked...

But like why?

[drifting wraith]

but like what do you mean when you ask why

[terse stone]

One second.

x = 0.13636363636363636363636363636364

roughly

[drifting wraith]

like in algebra you can get a problem like "a number increased by 7% is 9 more than the same numebr increased by 2%"

you write it as an equation and it works

and then there are problems where it's like "a 5% solution is mixed with this and that and you get that much 14% solution"

you write it as an equation and it works

[sweet edge]

I HATE DIFF EQ O GOD

[drifting wraith]

and then there are problems like probability

[sweet edge]

sorry, I got triggered

[drifting wraith]

and it's all just algebra, they are all the same problem

[hidden garnet]

lol you had chosen the worst possible option for a second there

I shouldn't exactly promote stuff which just gives you answer but StackExchange rocks

[terse stone]

Yeah

[hidden garnet]

relatable

Anyways I'm sorry, you guys carry on - or should I add something?

[terse stone]

Add 4+5

[hidden garnet]

lol

9

[terse stone]

Nah

[hidden garnet]

I mean it can be 1 also if mod 8

[terse stone]

He asked if he could add something, so I told him to add 4 and 5

[hidden garnet]

n1 💯

it's okay it happens sometimes

[terse stone]

Anyway...

can I ask to move the conversation not related to my homework problem to another channel lol

[hidden garnet]

Yeah sorry my bad

[terse stone]

👍

[hidden garnet]

About the bayes theorem - the difference between "something happening given another case" and "another case happening given something" is the key, otherwise it's simply conditional probability

Successfully Identifying a drug user = you used the drug test which returned positive, given the guy was actually using drugs

False positive= drug test says positive given the guy didn't use drugs

So make two events, and yry to think about the probabilities of complements

I think it should help

[drifting wraith]

i think it shouldn't help, it feels wrong that an algebra problem should take so much effort

[hidden garnet]

[terse stone]

🗿

[hidden garnet]

Wait, algebra?

[terse stone]

.76/.88

oops this isn't my calc

[hidden garnet]

P(T int D^c) = P(T|D^c)P(D^c)

I think you have all the values already for this one

Then use Inclusion-Exclusion to find

P(T uni D^c)

[terse stone]

ooh

intersection and union

[hidden garnet]

Yes

[terse stone]

I wasn't quite sure what int was

until I saw uni

[hidden garnet]

oh i'm sorry

[terse stone]

I'd just type it with n and u lol

[hidden garnet]

Should've used Tex

[terse stone]

🙃

[hidden garnet]

[terse stone]

Okay so this the tree diagram filled out.

[terse stone]

for the or one, you need to subtract out the and section, right?

[drifting wraith]

no, we didn't add things that intersect

we don't even have them

[terse stone]

what?

[drifting wraith]

like P(D) is the sum of the first two rows in your diagram

you mean like P(T’ or D’) = P(D’) + P(T’) − P(T’ and D’)

[terse stone]

ye

[drifting wraith]

but we haven't calculated P(D’)

we haven't calculated P(T’) either

[terse stone]

t` is .83

[drifting wraith]

we just have 3 parts that add up to whole

yeah tru

[terse stone]

because t is .17

[drifting wraith]

alright you got it

ping if more queschins

[terse stone]

coolio

Let me just make sure everything checks out

and...

cool, it checks out

[obtuse pebble]

@terse stone Has your question been resolved?

[terse stone]

Yes

[obtuse pebble]

Channel closed

Closed by @terse stone

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[narrow tinsel]

In a dollar bill serial number (8 digits) how many notes are composed of exactly 3 unique numbers

[grizzled shore]

Have you tried anything?

[obtuse pebble]

@narrow tinsel Has your question been resolved?

[narrow tinsel]

I tried to review permutation and computation but wasn’t catching on

[grizzled shore]

Can you show what you’ve tried?

[drifting wraith]

this is harder than basic

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic nebula]

I need help with this

[exotic nebula]

.close

[obtuse pebble]

Channel closed

Closed by @exotic nebula

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wise marlin]

can anyone help me understand the steps here, more specifically why the answer is still a quotient?

[misty gate]

yo

did you try it?

hello?

[wise marlin]

yes but my answer looks more just like a product rather than a quotient

[timid silo]

they probably rewrote b^-3 as 1/b^3

[misty gate]

send what did you try

[timid silo]

can you show provided solution and your attempt

[wise marlin]

okay one second

[misty gate]

ok

yo

[wise marlin]

yo sorry i was working on the problem

[misty gate]

the same problem?

[wise marlin]

Yeah

[misty gate]

what did you try

[wise marlin]

Am I on the right track?

[timid silo]

not really

[misty gate]

yeah

[timid silo]

like its correct but ur overcomplicating it

[misty gate]

1 st just cut the constants

[misty gate]

simplify constants

what do you get?

[wise marlin]

like a^-2 & a^-7?

[timid silo]

$\frac{48a^{-2}b^{2}}{8a^{-7}b^{5}}$

[warm shale]

hibyehibye

[supple granite]

Simplify 48 and 8 first

[misty gate]

8*6= 48

so

6 in numerator

[timid silo]

$\frac{48a^{-2}b^{2}}{8a^{-7}b^{5}} = \frac{6a^{-2}b^{2}}{a^{-7}b^{5}}$

[warm shale]

hibyehibye

[misty gate]

did you get it

?

@wise marlin

[wise marlin]

I believe i get it now but arent we supposed to work on exponents first since PEMDAS or is it not necessary?

[misty gate]

nope

not here

[wise marlin]

ahh okay gotcha.. after we subtract the 2 exponents correct?

-2-(-7)

[supple granite]

Yeah

[misty gate]

a^5 b^-3

[supple granite]

Look at a^(-2)/a^(-7) and b^2/b^5 seperately

Yeah, and don't forget the 6

[misty gate]

yeah do you get this?

[misty gate]

yes

[wise marlin]

understand for the exponents but a bit confused about the 6

[misty gate]

48/8

?

[wise marlin]

is there any way you canwrite in texit? that looks very easy to understnad

ill try to give you where im at now in the problem

[supple granite]

Maybe you can send a picture of ur work

[misty gate]

hm

if just follow what we said you could get it

first simplify the constants

48/8

then do variables

read the rules of how powers are subtracted and added to same bases

[misty gate]

ig it must be given in your book

nvm just the pic

[misty gate]

yeah

you are right

[wise marlin]

But these are my choices

[misty gate]

b

[wise marlin]

And this is what comes out in Mathway

See my problem is why is mine a product and not a quotient

[misty gate]

because when power is negative it is done positive by

?

tell

[wise marlin]

Are you saying there should be one more step on this? If so how can I get there

[misty gate]

b^-3 =1/b^3

[wise marlin]

Oh I get it now

That’s why the answer choice is a positive exponent

[misty gate]

hmm

[wise marlin]

Okay thank you, I’m gonna try the next problem and see if I can do it myself

[misty gate]

try

do as fast as you can

[wise marlin]

gotcha

[misty gate]

done?

[wise marlin]

Should I ele mínate the constants again or subtract the exponent first

[misty gate]

the constants canot be simplified more

do you agree?

@wise marlin

[wise marlin]

So simplify 13(r^5)?

[misty gate]

yeah parantheses now()

[wise marlin]

Gotcha

[misty gate]

just keep 3/13 aside for a while

deal with r

[wise marlin]

Yea?

[misty gate]

yeah

do same with denominator

[supple granite]

You should distribute the exponents of the denominator first

Also the numerator

[misty gate]

yeah now exponents

[wise marlin]

I assume I need to add the exponent on numerators now correct

[misty gate]

yeah

[wise marlin]

It should be 3r isn’t it

[misty gate]

4?

[misty gate]

yeah

now make exponents +

i mean positive

[wise marlin]

I’m not sure how to write it from hear I know I have to subtract the negative but what about the coefficient

[misty gate]

do the r^-20 positive

[wise marlin]

Did you mean like this?

[misty gate]

yeah

now take it to the numerator

[wise marlin]

Correct?

[misty gate]

yeah

bro

you got the ans

option d

right?

[wise marlin]

Yeah forgot I sent the question last time..

[misty gate]

lol

[wise marlin]

So when I subtract the exponent the variable canceled out?

& just left the 13?

[misty gate]

13 is just multiplied with variable r

[wise marlin]

Oh true

Thanks allot vaibhav this was actually the first time I tried using discord to get help for a math problem

[misty gate]

i am not a helper i was just getting bored so i hoped in this channel

[misty gate]

welcome

[wise marlin]

Your a good helper

Do you know If & Jodi leave the help section when I’m finished

How*

[misty gate]

.close

are you asking how to close this channel?

[wise marlin]

Yeah

.close

[obtuse pebble]

Channel closed

Closed by @wise marlin

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heavy summit]

quick question, is B correct?

[ruby path]

Quadratic formula

[sage geode]

Not really that necessary

You can collect the similar terms and solve for r yourself

You should get r^2 = q/(9 + 16s^2)

Meaning B is the correct choice, yeah

[heavy summit]

thanks, just wanted to verify :)

.close

[obtuse pebble]

Channel closed

Closed by @heavy summit

Use .reopen if this was a mistake.

[ruby path]

Yeah I misread the question

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wooden warren]

my prof said when integrating to solve a differential equation we should add a constant, and not simply integrate between x0 and x. so$\int xdx=x^2/2+cte$ != than $\int_{x_0}^{x} xdx$

[wooden warren]

is that true?

maybe not in the x case, but is it true for f(x) in general... he said sometimes through the integral we can't reach all possible constants

Can someone give me an example, and explain if it's true that we should always just integrate with a constant especially when solving differential equations

[warm shale]

Dazzlefishe

[trim portal]

The integral without bounds stays for antiderivate. If you do antiderivaitive of x^2, you get x^3/3, because derivative of x^3/3 is x^2. But you could also get x^3/3+6, because it's derivative would still be x^2, or x^3/3-67 or anything, so it's x^3/3+constant

[wooden warren]

yeah i know that

I am saying is it equivalent to adding a lower bound. Can i say that for any constant C, there's a lower bound corresponding to it

i think not

i am talking especially in the context of differential equations so it's not really an integration question.. just in differential equations should we add a constant or add a lower bound

[trim portal]

If you had differential equation f'(x)=0, the lower bound would not affect anything at all

So while the correct result would be f(x)=C, the lower-bound method would give you f(x)=0

[obtuse pebble]

@wooden warren Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[kind hawk]

Well the lower bound is often given by your initial condition

So you can't choose it freely

So you have to put the constant C

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen karma]

Another ez question 4 u guys

[keen karma]

So if my function is like :

I know it can not be g(-1)

But

I want to write it in a beautiful way

(Perfect way)

Do i need to do a existence calculation?

Like x+1 ≠ 0
<=> x ≠ 1

Do i need to do that?

Or can i just say it does not work with g(-1)

[echo basalt]

I think you can just write x ≠ -1

[keen karma]

How do I call this in english

Like this prove thing

[frank hamlet]

find critical points

here it will only be -1

[keen karma]

And there is an exercise with multiple g(x) what i need to fill into the function

[magic dirge]

∴

[keen karma]

So i just need to say that the last one does not work

[echo basalt]

you can say that g(-1) is undefined

[versed turret]

Could write "undefined."

[keen karma]

Or do i need to write the critical points once and then imply

[keen karma]

Do i need to write a prove?

I am sorry guys, i am just used to do the bigger functions and i am starting from the roots again

[west sierra]

If you want to

[versed turret]

"g(-1) = 1/0 which is undefined"

[west sierra]

Just say put x=-1 and when it becomes 1/0 , say that g(-1) is undefined so x not equal to -1

[keen karma]

Okay thx this looks good

Thank u guys

.close

[obtuse pebble]

Channel closed

Closed by @keen karma

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[faint sphinx]

Can someone help me find the limit of this series

[obtuse pebble]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[faint sphinx]

i tried things

tried to use derivatives and integrals by taking 3=x and like trying to bring down the power to the numerator / denominator to cancel out things

[median dome]

what do you have to do exactly?

simplify it?

[faint sphinx]

find the limit

[median dome]

oh mb i didnt read the text

[faint sphinx]

i also did (4k-1)= 4k+8 - 9 and it helped cancel the k+2

[normal lodge]

i have seen it somewhere but cant actually remember where

[faint sphinx]

i feel like this the way 2 go

[median dome]

would this not diverge?

because of the 3^(k-1)

[faint sphinx]

ye you're right

i have to show it using partial fractions

[median dome]

what did you get after this

[faint sphinx]

4*sum of (3^k-1 / k ) - sum (3^k+1 / k(k+2))

bruh this is the furthest wolfram alpha goes in the decomposition as well

[trim portal]

Seems like it diverges

Try to take the limit of a single term as k approaches infinity

it's enough to show that this diverges

[faint sphinx]

have to use partial fractions

[obtuse pebble]

@faint sphinx Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[next cypress]

Can someone help me with this

I don't even know where to begin with this question

What does No mean

Is it related to sets

Or functions

[mental cipher]

I think if I'm reading this correctly (No) is the number of fish added into the lake and (N) is the number of these fish that are left after a certain time has passed

So basically N=No(1/2) after 34 weeks if you get me

for (i)

[next cypress]

Yes

[next cypress]

Yes

[mental cipher]

so the equation would be something like N = (1/2)No e^-k(34)

[next cypress]

Yes

I wrote that

But how do you derive k from that

We have N0 and N unknown

I have the answers

But I do not know the process

[mental cipher]

Are the answers actual values ?

[next cypress]

Yes

[mental cipher]

May I see them ?

[next cypress]

Yes sure

Wait

My friend wrote down 0.5=e^-34k

And he found the value

From thta

But where did N0 go?

[loud crag]

so in this you would write N as No\2

and when you calculate u r left off w what ur friend has going on

[next cypress]

Ohh

I see

Thanks

How do I close

[loud crag]

nw

.close?

idk 💀

[next cypress]

.close

[obtuse pebble]

Channel closed

Closed by @next cypress

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solemn ravine]

what kind of a multiplication can you put on a sequence space, say $\ell^2,$ in order to make it an algebra? What would a multiplicative inverse of an arbitrary sequence look like?

[warm shale]

Joy!

[solemn ravine]

.close

[obtuse pebble]

Channel closed

Closed by @solemn ravine

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable vector]

does any one know what this forme of integration called or link to wikipedia to how it work

[obtuse pebble]

@stable vector Has your question been resolved?

[obtuse pebble]

@stable vector Has your question been resolved?

[glossy basalt]

I thought it's just u sub?

u=a+bx^n

((u-a)/b)^(m/n)=x^m

[stable vector]

.close

[obtuse pebble]

Channel closed

Closed by @stable vector

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[true lily]

hello, I need help with solving this problem

[true lily]

this is my work so far

I'm stuck at writing the inequality

[sonic anchor]

what is the probability that you dont pick honey bunny once

@true lily ?

[obtuse pebble]

@true lily Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

how do i do part d?

should i just use the half angle formula or am i supposed to use something from another step?

[rigid lintel]

15 = 45 - 30

[timid silo]

the answer key makes no sense

[timid silo]

yeah or compound angle

but the answer key makes no sense

[rigid lintel]

we dont have to worry about the answer key

[sage geode]

I would guess that we need to use half angle identities but there should be a reason why finding those is right after parts with complex numbers

[timid silo]

idk how it uses the previous step

[timid silo]

exactly

it has to be related to the previous parts

i did half angle

[rigid lintel]

dont worry about it just use

[ruby path]

Perhaps turns out to be the argument or something

[rigid lintel]

use this

[timid silo]

nah, marks would be docked

[sage geode]

Yeah it was even simpler than I thought

[timid silo]

explain lonely bean

[sage geode]

(sqrt3 + 1) + (sqrt3 - 1)i = 2sqrt2cos(15) + i * 2sqrt2sin(15), right?

[timid silo]

why do we need the sum

[sage geode]

That is what the results from part b and c imply

[timid silo]

parts b and c do the product

[sage geode]

Yeah but part b got us that zw = (sqrt3 + 1) + (sqrt3 - 1)i

[timid silo]

oh yeah

[sage geode]

And part c got us zw = 2sqrt2sin(15) + i * 2sqrt2sin(15)

[timid silo]

yep

[sage geode]

So, according to the tranquillity of equality, (sqrt3 + 1) + (sqrt3 - 1)i = 2sqrt2cos(15) + i * 2sqrt2sin(15)

[timid silo]

u mean 2sqrt2cos(15) + i * 2sqrt2sin(15)

[sage geode]

Hm? That is what I wrote

[timid silo]

yep

[sage geode]

Generally two complex numbers are equal to each other if and only if their real and imaginary parts are equal

[timid silo]

u said sin(15) for the real part

it's cos(15)

[timid silo]

anyways, i get it now, thanks to this step

[sage geode]

So sqrt3 + 1 = 2sqrt2cos(15) and sqrt3 - 1 = 2sqrt2sin(15)

[timid silo]

but how do i come up with this during an exam

[sage geode]

Taking real and imaginary parts of LHS and RHS of an equation is a common thing to do when you are solving in complex numbers

[timid silo]

no, just this step: (sqrt3 + 1) + (sqrt3 - 1)i = 2sqrt2cos(15) + i * 2sqrt2sin(15)

setting the cartesian on one side and the polar on the other side

[sage geode]

I don't think you will be asked to do such a trick on an exam , but now you know how to do something similar

So keep this in mind I guess

[timid silo]

alright, thanks

.close

[obtuse pebble]

Channel closed

Closed by @zenith vigil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jovial karma]

I have a question, how do we find the normal vector here?

[jovial karma]

we know this is the formula

the curl was simple, but I don't understand the intuition with getting the normal

[royal basin]

is this curve even connected...?

what surface does it delimit

[jovial karma]

when I graphed it, it looked connected I think

I don't know how to figure that out

I just assumed like an idiot

this is off-topic but I never thought I'd see another trans girl who likes math, thats awesome!!

@royal basin

[royal basin]

hm.

well, maybe trying to parameterize the curve would yield something nice

or like

even figuring out its equation in any form

https://www.geogebra.org/3d?lang=en

OH BUT THATS RIGHT.

of course.

the curve projects onto a circle in the xy plane

[jovial karma]

it says its a hyperbolic paraboloid, and its within the cylinder with the parabaloid maximums in there touching z = 25 right

the circle from xy projection we have radius 5

[royal basin]

the circle of radius 5 centered at the origin

yeah so

the surface you integrate over is the piece of the surface z=x^2-y^2 that lies over this circle

er, y^2-x^2

almost same difference

x = r cos(t), y = r sin(t), z = y^2 - x^2, r ∈ [0, 5], t ∈ [0, 2π] and theres your parameterization for the surface

the surface itself is the bit inside

[jovial karma]

with the parameterization do I like sub it in

[royal basin]

well yeah

as you normally would for a surface integral

[jovial karma]

damn it

I got this wrong then

[royal basin]

so like, you have your function S(r,t) that parameterizes your surface
and then the normal is ∂S/∂r × ∂S/∂t

[jovial karma]

okay I understand

I messed this up

this is what I did

@royal basin can I add you :3

[royal basin]

uh yeah sure

[jovial karma]

okay thanks for your help!!

.close

[obtuse pebble]

Channel closed

Closed by @jovial karma

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elfin belfry]

Hello. Can I have a hint on how to solve this differential equation?
$g(x)g''(x) = (g'(x))^2 + g(x)g'(x)$, $g(0) = g'(0) = 1$

[warm shale]

King Dedede

[half silo]

yes, use characteristic equation of a differntial equation since the equation is in terms of y and higher order derivatives of y

i think that works

https://en.wikipedia.org/wiki/Characteristic_equation_(calculus)

[obtuse pebble]

@elfin belfry Has your question been resolved?

[elfin belfry]

Oh okay, thank you

I'll keep this channel open for now if I have more questions

[elfin belfry]

Wait, but the coefficients aren't constants are they?

I don't think we can use that here then

[half silo]

yeah i cant work around it

sorry

i thought it would work

[elfin belfry]

That's fine, thanks for helping

<@&286206848099549185>

[elfin belfry]

<@&286206848099549185>

[elfin belfry]

<@&286206848099549185>

[obtuse pebble]

@elfin belfry Has your question been resolved?

[elfin belfry]

<@&286206848099549185>

[elfin belfry]

<@&286206848099549185>

[obtuse pebble]

@elfin belfry Has your question been resolved?

[wispy wyvern]

u still need help?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse pebble]

Please don't occupy multiple help channels.

[half pecan]

confused as to how P(2<X<4 and X<5) ends up as just P(2<X<4)

[kind hawk]

show context

what is X

but well either way, if X is already smaller than 4, then it is surely smaller than 5

[half pecan]

here

so my question refers to part d

why don't we do P(2<X<4) and P(X<5)

since that's the conditional probability formula

[kind hawk]

its not

$P(A | B) = \frac{P(A \cap B)}{P(B)} = \frac{P(A \text{ and } B)}{P(B)}$

[warm shale]

Denascite

[half pecan]

right

so P(A and B)

P(2<X<4 and X<5)

since it's also X<5

why do we just disregard that

[kind hawk]

well if X is already between 2 and 4 then it is smaller than 5

[half pecan]

ohhhh

so if it was the other way

P(X<5 | 2<X<4)

would it be the same

it would just equal P(X<5)?

[kind hawk]

well the denominator would change

no

[half pecan]

or i mean

the top part

P(X<5 and 2<X<4)

oh wait

it would still equal P(2<X<4)

[kind hawk]

yes

[half pecan]

i see

for some reason i keep thinking

that they are different

cause the probability of P(X<5)

and P(2<X<4)

are different values

so that's why i get confused when P(2<X<4 and X<5) is just P(2<X<4)

[obtuse pebble]

@half pecan Has your question been resolved?

Channel closed

Closed by @half pecan

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorny adder]

Given y(0)=1 and y(0.01) = 0.999983
Have your code print out the value of y(1).

[thorny adder]

can someone give answer but pls do not show work to this differential problem?

i have some answers but not sure if correct and unsure how to check

0.9047921471137096

y(1) = 3.669296670990947e-45

[gilded needle]

is there some assumption aboutwhat kind of function y is?

without any additional constraints, y(1) could be anything

[viral blade]

[thorny adder]

sorry english is second language, when you ask what type of function y is i am confused.

for reference, i am using Euler method from ordinary diff eq

[thorny adder]

pls dont judge me

[viral blade]

all right well if you're checking ig its fine

[thorny adder]

maybe this is not useful

[viral blade]

Do you know anything else about y

[thorny adder]

def functionCalc(t, yt):
    return -yt/10 


tNot = 0
yNot = 1
h = .01

y_1 = yNot + h*functionCalc(tNot, yNot)

for i in range(1, 100):
    ti = tNot + i*h
    yi = y_1 + h*functionCalc(ti, y_1)
    y_1 = yi

print(y_1)

here is my code

[thorny adder]

this is only instruction im given lol

[gilded needle]

"solve the differential equation" - what differential equation?

surely there must be more context

[viral blade]

yeah I doubt I can help

this doesn't really look like a question at all

y(1) can be anything

[thorny adder]

im thinking

but i feel inadequate

[gilded needle]

feelings aren't involved here, please show the full problem statement

no one can read your mind

[thorny adder]

that is all i am given o-o

[balmy mortar]

makes no sense

[thorny adder]

i only think can use linear interpolation

[balmy mortar]

y(1) = -200

[gilded needle]

1 is not between 0 and 0.01, so no, you can't use linear interpolation

maybe linear extrapolation

but that still has nothing to do with the undisclosed differential equation referred to in the question

[balmy mortar]

this problem looks like complete nonsense to me.

I would suspect its missing here https://i.imgur.com/07SZRp4.png

[gilded needle]

or, the equation was mentioned previously

is there any text above this question?

[thorny adder]

this is literally an interview question

lol

the only one

i would feel like idiot if i reached out and asked if there was a mistake in formatting lol

[balmy mortar]

but there is

ask them where the differential equation is

[gilded needle]

doesn't sound like a company you would want to work at, if their assignments are this incomplete

[balmy mortar]

there is none

do you see any?

either we're all idiots or its been missed out

[gilded needle]

aside from the issue with the incomplete problem statement, is it really ethical to ask for help on discord to pass an interview?

[thorny adder]

i didnt ask for help on how to solve

[balmy mortar]

depends what interview this is

[thorny adder]

https://docs.google.com/document/d/1WFwv0T0XMHkucTydT__ADgRGdgpRVljQ0wSe7rWU7DQ/edit?usp=sharing

it is referring to this, but maybe i am not putting pieces together

[balmy mortar]

so this really is ODEs as we know it

the question is incomplete

[thorny adder]

also the answer is not super important as i am being quizzed on my ability to code a function to solve but i do not see any lol

[thorny adder]

i can see where you are coming from, just wondered if i was being dumb

[gilded needle]

if i were in your situation, i would ask them to clarify the problem as there's no differential equation in sight

and without that, the answer could be anything

[thorny adder]

im wondering if they re-use the question pdf and whited over the equation so they dont reuse the same diffeq

[thorny adder]

i think i will do this, i will recieve clarity anyways

thanks guys

.close

[obtuse pebble]

Channel closed

Closed by @thorny adder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rancid leaf]

Hi, I'm trying to solve this limit(x,y) but I'm running in circles I don’t know how to solve it, what more paths use and I try to use the squeeze theorem but doesn’t helps me :(

[obtuse pebble]

@rancid leaf Has your question been resolved?

[unreal musk]

Maybe polar coordinates?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strange yoke]

Can someone help me with what my next step should be

To try to integrate this

Sec should actually be csc i think

[high lily]

yeh, though instead of doing it like that, consider
cos(t)/sin(t) * 1/sin(t)

[strange yoke]

What can I do with that?

[high lily]

cos(t)/sin(t) = ?

[strange yoke]

Oh

Thats cotangent

Thanks

.close

[obtuse pebble]

Channel closed

Closed by @strange yoke

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[normal spindle]

i have no clue where to start with this

[unreal musk]

addition formulas

[normal spindle]

yeah

would i do it for each sin/cos?

and then put that value in place of them in the above ss

and then solve?

thats what i thought at first but i thought i was overthinking it

[autumn gale]

sin (A+B) = sin A cos B + cos A sin B

this is a standard formula

[normal spindle]

no i know those

im asking do i have to convert each expression into their formulas, evaluate and then plug that value back in?

is that what u guys are saying i should do?

[unreal musk]

Well I'm not quite sure I get what you mean, but we're saying that you have the initial being the right hand side of this

so identify what A and B are and use that, you get something easier to evaluate if you do that

[normal spindle]

right but what values would add up to π/18 anyway

i tried finding and was unsuccessful

[autumn gale]

i think you might be misunderstanding the formula, you should be getting sin (π/18 + 5π/18)

[normal spindle]

well

dont tell me thats the answer

istg

if it was that easy

OH

[autumn gale]

which becomes sin (6π/18) and u can simplify from there

[normal spindle]

im

ugh

ok so like 1

[autumn gale]

um no

what's the sin(x) you're getting after simplying the equation

[flint osprey]

Need help

[autumn gale]

#❓how-to-get-help

[normal spindle]

uhh

OH

sin (π/3)

[autumn gale]

yes

[normal spindle]

which is √3/2

[autumn gale]

yes

👍

[normal spindle]

thats the only solution right

[autumn gale]

yep

[normal spindle]

tysm

also

in this eqs im just gonna be plugging values in right

and then using the correct equation for the sin difference

[autumn gale]

what equation will you plug the values into?

[normal spindle]

sin (a-b)?

maybe after finding the sin of a?

[autumn gale]

you need to plug it into the formula for sin (a-b) , u can't plug it in directly

[timid silo]

omg its vedant

[normal spindle]

yeah

so thats what i meant

[timid silo]

hi vedant

[normal spindle]

hi shaivi

[timid silo]

i acc know how to do this problem

[normal spindle]

gj

smart fr

[timid silo]

omg tyy

bro help 7 says "negative rizz"

[normal spindle]

i plug it into the difference eq right

[timid silo]

must be a sin🤣🤣🤣

GET IT CUZ LIKE SIGN AND SIN

[normal spindle]

sin a cosb - cos a sin b

[autumn gale]

Sin (A-B) = sin A cos B - cos A sin B

[normal spindle]

yesss i was close

[autumn gale]

similar to the sin A+ B formula

and plug in the values into that

[normal spindle]

ok ok

got it

will the answer for this be on the unit circle?

or just any value will work

not sure

i got 2√5/25

found the sin and cos of the opposite ones (2√5/5 and -3/5 respectively) and then plugged them into the eq

idk i feel like i did smt wrong

[autumn gale]

yea that sounds correct, haven't checked the values

[normal spindle]

can 6√5/25 - 4√5/25 subtract to 2/25?

idk the answer box doesnt have a root symbol option that generally means there isnt a root in the answer

[autumn gale]

2√5 /25

[normal spindle]

wait wdym

[autumn gale]

6√5 -4 √5 is 2√5

[normal spindle]

√5?

or √25

ohhh you mean the top

its wrong

[autumn gale]

yea i was just talking about the numerator

[normal spindle]

my answer is wrong

[autumn gale]

so when the number under the root is the same (called the radical btw), you can add or subtract them and treat the √5 basically as x

[normal spindle]

i see

got it

[autumn gale]

for example 3 √5 + 6√5 would be 9 √5

[autumn gale]

idk ask someone else, ur process looked correct, might just be calculation error

[normal spindle]

lemme double check

[normal spindle]

question

will the cos of b be -3/5 or 3/5

b as in beta

[autumn gale]

i assume ur talking about cos B

[normal spindle]

sorry i mean cos

yeah

[autumn gale]

it will be -3/5

[normal spindle]

bc the 5 is neg

?

[autumn gale]

well, you just put in whatever value of cos B you get

from the calculation

-3/5 and 3/-5 is the exact same if that's what you're asking

[normal spindle]

i see

okay

so i got

10√5/25

after doing the negatives right

can that be reduced to