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1 messages · Page 119 of 1

true granite
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thought you meant equal sides, and equal angle

wind patio
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nah

true granite
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there are a few simple ones

wind patio
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the only one i have found is AED and FEC

true granite
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if you cut two secant lines with two parallel lines, you’ll get two similar triangles, right?

wind patio
#

secant?

true granite
#

secant means they intersect

wind patio
#

and also we dont have any proof of them being parallel

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ok ty but ye we dont know if theyre parallel

true granite
#

oh I didn’t see, no right angle

wind patio
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and my geo teacher is kinda strict about using the information in there

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ye

true granite
#

tempted to use trig

wind patio
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idk trig tho

true granite
#

but I’m gonna stick to the ratios

wind patio
#

ima learn it soon, but havent yet

true granite
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yeye dw

wind patio
#

also nice pfp

true granite
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thanks!

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ok I’m gonna try to solve it with you, it looks fun

wind patio
#

k

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thats what i thought at first glance, and now it is making my head hurt

true granite
#

so we can get the two other angles

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AEB and BEC

wind patio
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those wouldnt cuz 40 and 20 wouldnt work together

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however the top angles

true granite
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yeye I’m talking about the angles

wind patio
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are 50 and 70

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ye those angles are these

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and DEA and FEC are 60 each

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and they are the same

true granite
#

50 and 70 add up to 120

wind patio
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ye then vertical to get 120 on other side

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then 360-240 gives 120

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and then vertical angles so just divide in half

true granite
#

so the opposite angles at E are 60

wind patio
#

ye

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if we had proof of the perpendicular, this thing would be done by now

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just use ~AA and boom

true granite
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yup

wind patio
#

wait i have an idea

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if we can find ADE

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with BED being 110

true granite
#

reposting so I don’t have to scroll, forgot the command

wind patio
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ok

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and if we find ade we can prove that DAB is 90

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and we could also get the 50 from 90-40 and that is angle F

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which is the same as AEB

true granite
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A+D+40+50+90=360

wind patio
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which would give us the AEB AFC similarity

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so EAD+ADE = 180

true granite
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wait

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no

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missed something

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that’s impossible

wind patio
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oh ye

true granite
#

missed a 60

wind patio
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oh we forgot the 60

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ye

true granite
#

A+D=120

wind patio
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so EAD + ADE = 120

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ye

true granite
#

if we can get another equation we can solve a system

wind patio
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but we need those exact variables

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ead and ade

true granite
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yup

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and in a different form

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Otherwise we’re just finding what we already know

wind patio
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i was about to do going to 180 w tst but realized that would just get us ead + ade = 120

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cuz the other one is 60

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WAIT

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ADE + EAD + 40 + 20 = 180

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shoot

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thats just the same

true granite
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yeah

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don’t think this goes anywhere tbh

wind patio
#

this is dificult

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ye

true granite
#

still tempted to use trig

wind patio
#

idk if i should email my teacher and ask her if they are perpendicular

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i mean if it works and you can explain it to me

true granite
#

wait we’ve already solved the problem

wind patio
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we have?

true granite
#

the question asks if there are any similar triangles

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answer:yes

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for example, those two you found

wind patio
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one of my friends solved it as well

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and got 3

true granite
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oh then we haven’t

wind patio
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ye

true granite
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trying to get the technicalities haha

wind patio
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idk if he made a mistake tho

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ye

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but

true granite
#

reposting again, don’t mind me

wind patio
#

has to be complete solution

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nah ur good

true granite
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wait

wind patio
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ye?

true granite
#

maybe we can use the fact that those two triangles are similar

wind patio
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OOOH

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ADE is congruent to FCE

true granite
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no

wind patio
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but then we run into the same problem of not being able to define it

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the angle is congruent

true granite
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we can find a relationship between AD and FC

wind patio
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how?

true granite
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and try to see if that holds for other sides of AFC and ADC

wind patio
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we can approcimate the length

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we know the proportion is 1 1/3

true granite
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ok got it

wind patio
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just remember to flip one

true granite
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so EF is proportional to which side?

wind patio
#

AE is proportional to FE

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and DE to EC

true granite
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okay

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5/2 = FC/AD right?

wind patio
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i believe so

true granite
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so FC=2.5AD

wind patio
#

ye ig

true granite
#

If ACD and ACF were similar, then DC/AF would be equal to AD/FC

wind patio
#

shoot where did i get 1 1/3 from

true granite
#

AD/FC is 2/5

wind patio
#

ye

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but thats just the rate

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cuz we got those numbers from elsewhere

true granite
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so we just have to check if DC/AF is also 2/5

wind patio
#

ok

true granite
#

,w (1.5+3.75)/7

warm shaleBOT
wind patio
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5.25/7 is 0.75

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wait waht is taht

true granite
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magic

wind patio
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damn my h is really behind

true granite
wind patio
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wait but how does it work

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,w3*5

true granite
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it’s just sending a query to a site called wolfram alpha

wind patio
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,w(3*5)

true granite
#

put a space

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,w 3*5

warm shaleBOT
wind patio
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oh thats cool

true granite
#

,w binomial(10,5)

warm shaleBOT
wind patio
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whats a binomial

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idr if ive learned it yet

true granite
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dw

wind patio
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wait what grade r u in

true granite
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it’s something used to count combinations and to expand polynomials

wind patio
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ok

true granite
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and some other stuff probably

wind patio
#

but what grade are u in, if ur still in school?

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im in 8th

true granite
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us?

wind patio
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ye us

true granite
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hmm no idea tbh
not from the us

wind patio
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wait r u in college?

true granite
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nope

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but I love math

wind patio
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past or b4

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like r u done w college or not in yet

true granite
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before

wind patio
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ok

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wait how old are u

true granite
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16

wind patio
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dam ur 3 years older than me and know so much more

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im rn in 8th, but you would be in 10th most likely if you were in us

true granite
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makes sense

wind patio
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im rlly young for my grade

true granite
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I study math for fun

wind patio
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nice

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i used to until geometry

true granite
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it’s great when you’re not forced to do it

wind patio
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HONESTLY THO

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but now i mainly spend my time coding, reading, playing games, or playing percussion

true granite
# true granite ,w binomial(10,5)

if you wanna know more about this check out combinatorics
it’s a way of counting in how many ways you can arrange objects, or make combinations of them

wind patio
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ok

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ive heard of 5x+4y as a binomial in alg

true granite
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oh yeah it’s called binomial because it’s part of the binomial theorem

wind patio
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oh ok nice

true granite
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it’s a way to expand binomials

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(a+b)^2, …^3, and so on

wind patio
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ok

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do yk any good places i could go to learn more?

true granite
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if you like learning math you can use khan academy, they have some good math content

wind patio
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ok

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ok wait we should get back on track

true granite
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yeah

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HMMM

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let me just check if they’re actually perpendicular, then we’ll try to solve it normally

wind patio
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ok

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if its perpendicular its p much done

true granite
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oops forgot wolfram

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,w sqrt(1.5^2+2^2-221.5*cos(60deg))

warm shaleBOT
true granite
#

,w arcsin(sin(60deg)*1.5/1.8)

wind patio
#

wha-

warm shaleBOT
true granite
#

,w 0.806 radians in degrees

warm shaleBOT
wind patio
#

is this just figuring out the 90 degrees?

true granite
#

ok so they’re not perpendicular

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the left one is like 89.18 degrees

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with some rounding error

wind patio
#

just keep in mind that this is most likely not to scale

true granite
#

they could be perpendicular

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wait one sec

wind patio
#

they are most likely intended to b perpendicular

true granite
#

,w arcsin(sin(60deg)1.5/sqrt(1.5^2+2^2-221.5cos(60deg)))

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dw

warm shaleBOT
wind patio
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what tha hell

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bro im so confused

true granite
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DON’T WORRY

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,w 0.804634 radians in degrees

warm shaleBOT
true granite
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okay so it’s not perpendicular for sure

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sorry about that

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it’s like 86.1021 degrees

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something random

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just ignore all the wolfram queries

wind patio
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ok

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is it just the result + 40

true granite
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yeah

wind patio
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oh ye cuz of EAB

true granite
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I was finding EAD

wind patio
#

ye

true granite
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with like 2 different trig laws combined

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there’s probably a faster way to do it but oh well

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letting the computer do the hard work

wind patio
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lmao

true granite
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so knowing they aren’t perpendicular, there’s prob no way there are others tbh

wind patio
#

ok

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my dad suggested a theorem

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but idk what its called

true granite
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I used the sine law and cosine law

wind patio
#

but basically with a perpendicular line on it

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the segments its divided into are proportional

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and its prob true

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and then u can sas

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cuz u alr have 3.75 is proportional to (3.75 + 1.5)

true granite
#

so which segments would be proportional?

wind patio
#

so with the theorem AC would be proportional to BC

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and AB to AC

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making FAC EAB and DCA ECB possible

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it seems likely

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using reflexive we have the angles

true granite
#

this is a tough problem

wind patio
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ye

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and they give this to 8th graders

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well nr

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its meant for 10th and 9th

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but its in the geo course

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and we are in "advanced" since we skipped 2 grades of math

true granite
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I only found the 2 you found haha

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just noticed something

wind patio
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what?

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here just reposting

true granite
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angle ADE is equal to angle ECF right?

wind patio
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yes

true granite
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same thing with DAE and EFC

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wait

wind patio
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or, as my teacher would have us say, m<ADE = m<ECF

true granite
#

wrote them wrong

true granite
wind patio
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ye

true granite
#

maybe knowing that their sum is 120 can give us info on if m<DAC = m<ACF

wind patio
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wait how we know that

true granite
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let’s call x the entire interior angle at A, and y at B (I don’t know if this works btw)

wind patio
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ok

true granite
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x = 40 + m<DAE

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y = 20 + m<ECF

wind patio
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like this

true granite
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no

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oh, I said B

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with y I meant C

wind patio
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oh

true granite
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yeah

wind patio
true granite
#

x+y = 180!

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wait wait

wind patio
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no

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x + y = 120

true granite
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nono

wind patio
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same as the ADE and DAE from b4

true granite
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meant the two FULL angles

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including eab

wind patio
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oh

true granite
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and bce

wind patio
#

like with the 40 and 20

true granite
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yeah

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so you just add 60 and get that they add up to 180

wind patio
#

k

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ye

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but we alr know where the 40 and 20 go

true granite
#

which means they are parallel

wind patio
#

how

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the only parallel proving thing ik is with converse and transversal

true granite
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if you cut two parallel lines with one line, the angles on the same side add up to 180

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since you can just translate the other angle

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does it make any sense?

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or should I draw it

wind patio
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draw plz

true granite
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one sec

wind patio
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wait so the one line would be the transversal

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like this?

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x + y = 180?

true granite
#

like that

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if they are parallel, they add up to 180

wind patio
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yes

true granite
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and we just proved that in our case, they add up to 180

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so AD and FC are parallel

wind patio
#

oh so converse of same side alternate interior angle theorem

true granite
#

not perpendicular, but parallel

wind patio
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ok wait then with that we can solve the entire thing

true granite
#

we proved a sort of duality of that theorem

wind patio
#

ye

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WAIT

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USING THAT

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WE CAN PROVE DA IS PARALLEL TO EB

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wait can we

true granite
#

I prefer free dart monkey tbh

wind patio
#

lmao

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fair choice

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allows greed in the early game

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with farming early

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depends on hero as well

true granite
#

I’m not that good at btd6 though

wind patio
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i have knowledge, just not much experience, in game or with hotkeys

true granite
wind patio
#

so i odnt have paragons, or much good boss damage

true granite
#

I can unlock them, but I don’t have enough xp

wind patio
#

ye same

true granite
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yeah we can

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wait

wind patio
true granite
#

no, we’ve just proved it isn’t

wind patio
#

wait how

true granite
#

since it’s not perpendicular

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and if it were parallel, it would be perpendicular

wind patio
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no the thing we need perpendicular is DA to AC

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and FC to AC

true granite
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yeah, if da was parallel to eb, then da would be perpendicular to ac

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and we know it isn’t

wind patio
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it isnt?

true granite
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proved it with trig

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a few minutes earlier

wind patio
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but that requires it to be to scale right

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this isnt to scale

true granite
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let me make a scale diagram

wind patio
#

at least the measurements

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ok

true granite
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wait

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that’s much harder than I thought uhhhh

wind patio
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ye bro

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idk how my other friend got it easily

true granite
#

well I can use some construction tools on geogebra

wind patio
#

whats geogebra

true granite
#

an app

wind patio
#

is it similar to desmos?

true granite
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yeah

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ok I’m getting close

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give me 2 secs

wind patio
#

ok

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just can u explain it to me after ur done

true granite
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yeah, I just want to do it to understand how it actually looks

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ok I got it

wind patio
#

ok

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btw

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this is almost definetly not how we are supposed to solve it

true granite
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not solving it

wind patio
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lmao ye

true granite
#

just making it to scale to understand what it looks like

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then prove what you think is right lol

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shortcut!

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ok so FC is def parallel to ad

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and eb is not

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there’s a slight difference

wind patio
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k ima just ask my teacher tmrw

true granite
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so i’m pretty sure there’s just 1 pair of similar triangles

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and it’s the two top ones

wind patio
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ill ask my teacher and friends if theres more

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if there is, ill lyk

true granite
#

so we had actually solved the problem an hour ago

wind patio
#

ye

true granite
#

great

wind patio
#

sorry if you felt it was a waste of time

true granite
#

not really

wind patio
#

had fun working thru it w u tho

true granite
#

I had fun

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it’s 2 am here though

wind patio
#

oh dam

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you should prob gts

true granite
#

yup

wind patio
#

ima gts now too

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gn

true granite
#

gn!

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also

wind patio
#

and lmk if u wanna play btd6 together sometime

true granite
#

I’m happy you haven’t noticed that english is not actually my first language

true granite
wind patio
#

really? you spoke it incredibly well

true granite
#

yeah, I’m from south america

wind patio
#

i honestly thought you were from the US or England

true granite
#

español

wind patio
#

ah nice

true granite
#

I can type the ññññññ

wind patio
#

rn im taking a spanish 2 class lmao

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puedo hablar mas o menos espa~nol

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pero no estoy muy bueno

true granite
#

soy

wind patio
#

oh ok

true granite
#

yeah ser/estar is prob confusing

wind patio
#

i did estoy cuz im tryna get better

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so its not permanent

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i heard ser is permanent, and estar is not permanent

true granite
#

ser is like something that you are, something that describes you

wind patio
#

ok

true granite
#

I am nice, I am a man

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etc etc

wind patio
#

ah

true granite
#

and estar is something that you are doing or somewhere you are

wind patio
#

soy simpatico

true granite
#

you are at the supermarket

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estoy en el supermercado

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but you aren’t the supermarket

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you are at the supermarket

wind patio
#

ight well i gtg now

true granite
#

that’s basically the difference

wind patio
#

gn

#

ye ty

#

ttyl

true granite
#

cya!

wind patio
#

.close

obtuse pebbleBOT
#
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ionic summit
#

Hello! So I am doing some practice integrals and this one (the first one lol) threw me off, I got -15/2 instead of the correct answer of 15/2

ionic summit
#

I ended up with 1/2x^2 -3x

viscid crag
#

x²-6x+9 can be factorised to (x-3)²

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Then you can remove square root and take absolute value of |x-3|

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Take out a minus and you get the integration of -1,2 of |x-3| dx

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So now its -x+3

ionic summit
#

/why?

viscid crag
#

Its absolute value. To remove it, you have to take out a minus

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That removes the absolute value

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For example

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In the case of |x-3|, it becomes -(x-3) and so its -x+3

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Alternatively, you can replace x with -x which also removes the absolute value

ionic summit
#

Thats for every case? No matter what kind of function is in the absolute values and limits of integration?

viscid crag
#

Pretty much

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You just have to replace x with -x to remove abs

ionic summit
#

what is it was like |sinx|

viscid crag
#

Replacing x with -x here gives sin(-x). Fron trig rules, this is equal to -sin(x). If it was cos(x), from trig rules, cos(-x) = Cos(x)

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Are you aware of the unit circle?

ionic summit
#

wow okay I see

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thats kinda interesting

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right cus like cos is an even function and sin is odd

viscid crag
#

😀

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Hmm

ionic summit
#

uhh

viscid crag
#

Yes

ionic summit
#

ok but the "pretty much" answer concerns me

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is it like the only case its not

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outside of the scope of this

#

im in calc 2 for reference

viscid crag
#

Lmao i say that sometimes. Although yes, it can be a bit janky when it comes to "e"

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Like e^|x| - |x³| for example

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You have to separate it into 2 integrals

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By finding where it equals to 0

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Its hectic

ionic summit
#

okay ima just hope that never happens

#

idk prof never went over that case and just touched on the abs value thing for integrals

viscid crag
#

Lets hope

ionic summit
#

and trig sub

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but thank you so all I gotta do

viscid crag
#

Trig sub is a hard concept at first

ionic summit
#

is pull a negative out

viscid crag
viscid crag
ionic summit
#

okay sorry another example is needed

viscid crag
#

Lmao

ionic summit
#

|x^3 - x^2 +7|

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is it just

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-x^3 + x^2 + 7

viscid crag
#

Yea so replace x with -x

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Yea

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Done

ionic summit
#

wait seriously

viscid crag
#

Yep

ionic summit
#

i dont understand abs value

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I thought it made things positive

viscid crag
#

Its a bit funky

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This method works for most functions

ionic summit
#

oh goodness there it is again

#

most

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the excepting being e?

viscid crag
#

Wait youre making me confused now

ionic summit
#

hahahah

viscid crag
#

💀

#

There might be more. Im pretty good at this but then again, it won't work for all

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Just be careful

ionic summit
#

mann

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ok wait what the heck

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i threw something random into symbolab

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and this appears not to follow that urle

viscid crag
#

One sec

#

Watch that

#

I was slightly mistaken forgive me. Apparently my method only works with linear functions

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💀

ionic summit
#

mmmmmmmmmm

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wait

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but the thing i posted above on symolab

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is linear

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but that did not work

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WAIT

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wait no it does I just got confused when it split the integral up

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i accidently made an improper integral

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sorry one last test @viscid crag

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|x- 7|

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U said to just make -x

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so its -x - 7?

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wait nvm I think u were refering to just the trig

#

u take out a minus for linear functions

#

sorry for spam ty

#

.close

obtuse pebbleBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
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grand hawk
obtuse pebbleBOT
grand hawk
#

how would i go about solving this?

obtuse pebbleBOT
#

@grand hawk Has your question been resolved?

daring rock
#

@grand hawk Are you familiar with the remainder theorem?

daring rock
#

It says, if you have a polynomial p(x) and you divide it by (x-t), the remainder is p(t)

daring rock
#

Well, for your first polynomial

#

You're told that if you divide $x^4+5x^3-ax+b$ by $(x+1)$, the remainder is 7

warm shaleBOT
#

tatpoj

daring rock
#

So the remainder theorem tells you that if you evaluate that polynomial at x=-1, you get 7

grand hawk
#

so

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p(-1) is 7

#

oh wait lol i got it\

#

ty for the pointers @daring rock

#

.close

obtuse pebbleBOT
#
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Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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next reef
#

The sample space consists of all the numbers from 000 to 999, both inclusive

obtuse pebbleBOT
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viscid crag
obtuse pebbleBOT
viscid crag
#

what is meant by A

pastel meadow
#

A denotes that matrix here

viscid crag
#

oh ok

#

thanks

#

.close

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somber zealot
#

how would i integrate this?? i thought the derivative and integral would cancel each other but there is an upper and lower bound?

timid silo
#

um

#

seemingly you don't have to integrate anything

#

since they are asking you to take the derivative

#

Apply the Fundamental Theorem of Calculus of
[
\dv{x} \int_a^x f(x) \dd{x} = f(x)
]

warm shaleBOT
somber zealot
#

idk why i keep forgetting fundamental theorem of calc

#

thanks!

#

.close

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vivid edge
#

just want to make sure

#

x=2.4 or x=-1

timber fox
#

plug the values you get back into the original equation and check if you get 0=0

vivid edge
#

wdym?

timber fox
#

if u got x = (-1)

#

check if 5(-1)^2 + 17(-1) - 12 = 0

vivid edge
#

i got -24 so im guessing its wrong

#

how can i fix it?

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vivid edge
#

.close

sour lantern
obtuse pebbleBOT
sour lantern
#

I want to calculate inverse laplace and this is what I got

#

this is what the internet says should be the answer

#

is my answer also right or did I mess something up?

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whole dock
obtuse pebbleBOT
whole dock
#

Why does the electric field does not add to the force on the charge due to gravity aren't they both opposing the repulsive force due to the negative charge?

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timid silo
#

Anyone able to explain how this equals a circle???

timid silo
lone jetty
#

|z - z1| = r

is a circle radius r centered at z1

#

| (x + iy) - (x1 + iy1) | = r

((x + iy) - (x1 + iy1))^2 = r^2

#

you can have the fun of expanding it out and proving it to yourself @timid silo

#

it works out exactly the same as the cartesian equation of a circle

timid silo
#

Thank you very much

#

Now I understand it

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elfin abyss
#

if something is not a divisor of 0 in a ring, is it not necessarily invertible?

elfin abyss
#

Can you give me an example

royal basin
#

oh, nevermind, i misread.

#

no, a non-zerodivisor is not necessarily invertible. and even Z has examples aplenty

#

such as the number 2

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#

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harsh crow
#

I understand this but how u even get the number of 50 cent coins idk

harsh crow
obtuse pebbleBOT
#

@harsh crow Has your question been resolved?

harsh crow
#

No

lost tree
#

what have u tried

harsh crow
#

The obivous parts

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hard whale
#

I have a further question about the scalar product

hard whale
#

Isn't n . p =0 since p the position vector on the plane is also perpendicular to the plane

#

So shouldn't n .p =0

#

Instead of d

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#

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edgy whale
obtuse pebbleBOT
edgy whale
#

but i dont know how to find y-intercept of equation. (high possibility chance of miss counted question)

high lily
#

after isolating y, the equation will pretty much be in slope intercept form from which the slope and y-intercept (as the name suggests) can be easily identifiable

edgy whale
high lily
#

you said you did that

edgy whale
#

oh ok i see

high lily
#

i know how to make y subject of l2

edgy whale
#

so not using the y subject

high lily
#

making y the subject, isolating y, solving for y

#

are different ways of saying the same thing

edgy whale
#

ok ill try that and see how it goes

high lily
#

with the goal of getting an equation in the form
y = stuff without y

#

supposedly you have that already

edgy whale
#

great explanation Thank you!

uncut vault
#

HElp

#

Rewrite x1/2 in radical form.

c)√x

#

not getting it

high lily
#

channel is occupied. please read #❓how-to-get-help and claim your own under the available section @uncut vault

uncut vault
#

ok

edgy whale
uncut vault
#

but i dont have permision to it

high lily
#

if you're done type .close

edgy whale
high lily
#

if you can send stuff here, you definitely have the perms to send stuff in an available one

edgy whale
#

.close

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proper ivy
obtuse pebbleBOT
proper ivy
#

why cant we write this as: 1/3 + (2/3 * 1/3) + (1/3 * 1/3)

#

i get it its easier with finding the opposite first, but why does my method give a wrong answer

drifting wraith
#

1/3 + (2/3 * 1/3) + (2/3 * 2/3 * 1/3)

proper ivy
#

thanks a lot man

#

sorry if i came off as a little bit racist

#

.close

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rancid leaf
#

I'm trying to solve the exercise a) I have to determinate if the set V is a subspace of R^2, I’m trying to use the gen but I'm not sure how it can say that is a subspace or not

obtuse pebbleBOT
#

@rancid leaf Has your question been resolved?

obtuse pebbleBOT
#

@rancid leaf Has your question been resolved?

unreal musk
#

One way that might help and be a bit more intuitive is to show it is a subspace directly: if you have $(x_{1}, y_{1}), (x_{2}, y_{2}) \in V$ (so $x_{1} = \frac{4}{3} y_{1}$ and $x_{2} = \frac{4}{3} y_{2}$), then show their sum also "looks the same", and that if you have a scalar $\alpha$, that $\alpha (x_{1}, y_{1})$ "looks the same" too

warm shaleBOT
#

chartbit

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blissful bane
#

Given 13% of people are left-handed. What is the probability the first left-handed person will be the sixth person polled?

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
blissful bane
#

I'm trying to figure out which distribution does this belong to

trim portal
#

Probability questions usually just need to be rephrased

blissful bane
#

so a geometric distribution, with 5 failures and 1 success?

trim portal
#

But according to probability formula for geometric distribution, you are right

blissful bane
#

the required probability by multiplication theorem is (0.87)^5(0.13) right ?

#

thanks a lot.

#

I wasn't able to comprehend that sixth person is the only success

#

i thought there was a chance of combination

#

have a great day.

trim portal
#

u2, bye

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#

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timid silo
#

Let $X$ be a normal space and $Y \subset X$ a linear subspace. For $x_0 \in X \setminus Y$ we define
[
f: \cmap{\spn}{Y,x_0} \longrightarrow \K, \map f{y+\lambda x_0} = \lambda, \quad \forall y \in Y, \forall \lambda \in \K
]
a) Prove that $f$ is well defined and linear

\vs{3 mm}
b) Prove that $f$ is continuous if and only if $x \notin \overline{Y}$

\vs{3 mm}
c) Prove that $\overline{Y} = \bigcap\set{\ker x^{\ast} \where x^{\ast} \in X^{\ast}, Y \subset \ker x^{\ast}}$

\vs{5 mm}
\textbf{My attempt:}

\vs{3 mm}
a) We start by noticing that
[
\cmap{\spn}{Y, x_0} = \set{y + \lambda x_0 \where y \in Y, \lambda \in \K}
]
To show that $f$ is well defined, we can show that
[
(y+\lambda x_0 = y' + \lambda ' x_0) \implies (y = y' , \lambda = \lambda ')
]
And assuming that $\lambda \neq \lambda '$. Then;
[
x_0 = \f{y-y'}{\lambda - \lambda '} \in Y
]
So since $y, y' \in Y$ and $Y$ is a linear subspace; this results in a contradiction. Thus,
[
(\lambda = \lambda ' ) \implies (y = y ' )
]

\vs{3 mm}
b) We can start off by supposing that $f$ is continuous. We will then prove that $x_0 \notin \overline{Y}$. Assume, for the sake of contradiction, that $x_0 \in \overline{Y}$.

\vs{2 mm}
Then there is a sequence $y_n \subset Y$ such that $y_n \to x_0$. Since $y_n , x_n \in Y, y_n \to x_0$ and $f$ is continuous, then $\map f{y_n} \to \map f{x_0}$.

\vs{2 mm}
By the definition of $f, \map{f}{y_n} = 0, \quad \forall n \in \N$. It follows that $\map f{x_0} = 0$ which is false, since by the definition of $f$, we have $\map f{x_0} = 1$

\vs{2 mm}
Suppose now that $x_0 \notin \overline{Y}$, for example, $x_0 \in \comp{(\overline{Y})}$, which would be open. Then
[
\exists \epsilon > 0 : \map B{x_0; \epsilon} \subset \comp{(\overline{Y})}
]
This inclusion would then be equivalent to $\overline{Y} \cap \map B{x_0; \epsilon} = \emptyset$. Let $x = y + \lambda x_0 \in \cmap{\spn}{Y, x_0}.$ If $\lambda = 0$, then
\begin{equation}
\abs{\map f x} = 0 \leq \f{\norm{x}}{\epsilon}
\end{equation}
if $\lambda \neq 0$ then $\f{y}{-\lambda} \in Y$ so $\f{y}{-\lambda} \notin \map B{x_0; \epsilon},$ for example, $\norm{-\f{y}{\lambda} - x_0} \geq \epsilon .$ Therefore,
\begin{equation}
\norm{x} = \abs{\lambda} \norm{-\f{y}{\lambda} -x_0} \geq \epsilon \abs{\lambda} = \epsilon \abs{\map f x}
\end{equation}
Then, both cases of (1) and (2) should show that $f$ is continuous

timid silo
#

Hey guys are the way a and b were done correct? I mainly followed the lecturer's method but I want to double check

warm shaleBOT
timid silo
#

i dont think (2) is true anymore

#

i am really suspicious of the last quarter of that to be honest

heavy siren
#

Can you solve this kenken

#

And this

timid silo
#

sigh

#

.close

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#

@timid silo Has your question been resolved?

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@timid silo Has your question been resolved?

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@timid silo Has your question been resolved?

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@timid silo Has your question been resolved?

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@timid silo Has your question been resolved?

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magic tinsel
#

We have 16 buckets b_1, ... ,b_16. They contain w_1,...,w_16 balls respectively.
How many ways can I make groups of 10 balls such that no more than 3 balls are from the same bucket?

drifting wraith
#

there's no trick for this, sounds like a programming question

magic tinsel
#

it kind of is, it's related to a project im doing in python i just wanted to count to see if it'll be faster than the previous method

#

the hope is that if all w_n are equal to about 20 than the result would be less than 86 choose 10

drifting wraith
#

do the balls have identity or not?

magic tinsel
#

um hm not sure i get what you mean

drifting wraith
#

like if you have 2 buckets of 20 and the rest have no balls what's the answer

#

uh

#

and you can have any number not just 3

magic tinsel
#

right it can't be done for less than 4 buckets

#

since we'll need at least 10 balls

drifting wraith
#

but if you can have all 10 from the same one

#

like it's either (40 choose 10) or it's just 11

magic tinsel
#

right i think that would be 40 choose 10

drifting wraith
#

all right

#

@magic tinsel

from math import comb
from functools import *



@lru_cache(999)
def count(a,w):
   if not a: return 1
   if not w: return 0

   r = 0
   for i in (0,1,2,3):
     r += comb(w[0],i) * count(a-i, w[1:])
   return r


w = 23,23,21,23,19,23,18,20,21,22,18,23,21,18,18,18

print(count(10, w))
magic tinsel
#

oh thank you um

drifting wraith
#

the result is more than 86 choose 10 apparently

#

i don't know what's 86 choose 10

magic tinsel
#

function is a bit confusing

#

what does comb do

drifting wraith
#

choose

magic tinsel
#

like about 3.5 trillion iirc

drifting wraith
#

i meant why 86

magic tinsel
#

oh it's the number of magic series of order 4

#

just some stuff im working on, not really relevant

#

what about exactly 3 or 1

#

from each

#

do i just set i in (1,3)?

drifting wraith
#

yeah

magic tinsel
#

aight thank you so much for the help

#

deeply appreciated

#

have a nice rest of your day frownyfrog

#

!close

#

.close

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analog harbor
obtuse pebbleBOT
analog harbor
#

whats the 0 thing means

native cove
#

It's called theta, means angle

#

Just think of it as X, there's no difference if you call it a or x

analog harbor
#

ok got it

#

.close

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feral siren
#

How do i find the minimum value of
CosA + CosB + CosC
Given that A + B + C is 2π

feral siren
#

i think that the question itself is incomplete ?

lost tree
#

can u try using cosA + cosB = 2cos(A+B/2)cos(A-B/2) ?

#

and replace A+B with 2pi-C

feral siren
ruby path
#

Is there perhaps a geometric answer?

feral siren
#

yea original question is of geometry

ruby path
#

Have you tried drawing a unit circle perhaps

feral siren
#

ye=\

ruby path
#

,w cos (2pi/3)

warm shaleBOT
ruby path
#

Is the answer -1.5

feral siren
#

ye

ruby path
#

Hmm

#

So at the point where A = B = C

#

Our math teacher did tell us about these "equilibrium points" but I don't remember the context of the relation to minimas and stuff sorry

feral siren
#

.close

obtuse pebbleBOT
#
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buoyant void
#

The question says to approximate the answer

obtuse pebbleBOT
buoyant void
#

<@&286206848099549185>

obtuse pebbleBOT
#

@buoyant void Has your question been resolved?

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@buoyant void Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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weak mauve
#

hi im pretty weak on vectors could someone help me with these two questions

obtuse pebbleBOT
#

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uneven ravine
#

@bronze sky

obtuse pebbleBOT
uneven ravine
#

LAMo

#

why u here

sharp pecan
gloomy canyon
#

dont use the channels like this please

uneven ravine
#

mbmb

gloomy canyon
uneven ravine
#

he is my boyfriend

#

mb

sharp pecan
#

.close

gloomy canyon
#

ye ye

obtuse pebbleBOT
#
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gloomy canyon
#

no prob

uneven ravine
#

anyone knows why dividing by 0 is undefined

#

give me a detailed explaination

sharp pecan
#

.reopen

obtuse pebbleBOT
#

sharp pecan
#

seems like a google search, the answer depends on your knowledge

zenith vale
#

cavendish your pfp looks cute

tawny fog
warm shaleBOT
tawny fog
#

The limit $\lim_{x\to c}f(x)$ dosen't to be more specific

warm shaleBOT
tawny fog
#

So in the graph

#

,w plot y= 1/x

warm shaleBOT
gloomy canyon
#

approaches both negative and positive infinities

tawny fog
tawny fog
#

Ufff

#

$\lim_{x\to 0^+}\frac{1}{x}=\infty$

warm shaleBOT
tawny fog
#

And when c is c^-

#

$\lim_{x\to 0^-}\frac{1}{x}=-\infty$

warm shaleBOT
gloomy canyon
#

what arnab said is basically correct

tawny fog
gloomy canyon
#

though another way to look at is that
for 1/0 =x
x is valid for every value

#

i forget exactly what the proof if is, but basically if 1/0=1, then 1/0=2, and also -2, or 10^100

#

thats another reason why its undefined

sharp pecan
# tawny fog 🥲🫂

I believe that cavendish207 is not actually interested in this and just said that to make it seem like they had a question

obtuse pebbleBOT
#

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silver plover
obtuse pebbleBOT
silver plover
#

need some help with this please

#

im new to this Kernel terminology

#

CHARTBIT

#

LONG TIME NO SEE

#

as u can see

#

im back

unreal musk
silver plover
#

semester 2 has commenced

unreal musk
#

Welcome back! catlove

silver plover
#

and im back to learning again

unreal musk
#

Assuming by the kernel of that matrix $A$, they mean the kernel of the linear map $f : \mathbb{R}^{2} \to \mathbb{R}^{2}, f(x) = Ax$?

silver plover
#

lemme send u my definintion

warm shaleBOT
#

chartbit

silver plover
unreal musk
#

Ah yea same thing haha

#

Might help to find the determinant of that matrix (why?)

silver plover
unreal musk
#

Well that is what we want to do of course, ideally

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But here it's a nice square matrix that we have

silver plover
#

then maybe solving for x and y?

#

wont x and y just be 0 lol

#

hence is the kernel just the trivial solution?

unreal musk
#

Also, are you familiar with the fact that a linear map is injective (one-to-one) if and only if its kernel is trivial?

#

(similar with group homomorphisms too catGiggle)

unreal musk
#

Oh, well then, exercise for the reader to do both devilish

silver plover
#

lmao

silver plover
#

the determinant is -16

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hence that shows that A is invertible

#

so for invertible matrices, will the kernel ALWAYS be the trivial solution?

#

interesting

unreal musk
#

[left multiply by the inverse matrix]

silver plover
#

ofc

#

ye this makes sense now

#

thanks chartbit

silver plover
#

DERPZ

wise talon
#

hey

silver plover
#

havent seen u in ages as well

#

im in semester 2 now

wise talon
#

nice

silver plover
#

back learning again

wise talon
#

so that kernel definition is shockingly close

#

in fact its not just close

#

its the exact one as in group homomorphisms

silver plover
#

lmao

wise talon
#

so let f be a homomorphism from G to H

#

the Ker f = {g in G | f(g) = e_H}

#

so here you think of e_H as the 0

silver plover
#

i see

#

btw i havent done homhphpophposiissm groups before

wise talon
#

ah okay

#

its fine

#

its a nice way to think about it tho

silver plover
#

i just started 2 days ago

#

😭

unreal musk
#

You'll get to them soon enough devilish

silver plover
unreal musk
#

Nice nice happyCat

wise talon
#

vector spaces are just abelian groups under + sotrue

silver plover
#

for this module

#

my lecturer has a 'flipped classroom strategy'

#

so i have to learn the content

unreal musk
#

Modules are like generalisations of vector spaces over arbitrary rings devilish

silver plover
#

before the lecture

#

we only have 1 lecture a week for this

#

...

unreal musk
#

Oh, damn, I see 🤯

silver plover
#

thats why im learning this all now

#

since my first lecture for this module

#

is

#

tmr

#

...

#

😂

unreal musk
#

Oh damn, fair enough! Best of luck for it happyCat

silver plover
#

learning is so much better than revision

#

too much pressure when revising

wise talon
#

take group theory

#

real fun

unreal musk
#

Awww I see, for me it's the other way around

silver plover
wise talon
#

noiceee

#

NOICE

#

idk why no fields but its probably included

unreal musk
#

Well, actually, can't lie, I'm just a nerd

silver plover
wise talon
wise talon
#

NO

#

no

#

no

silver plover
#

mate i aint doing that shite

wise talon
#

do both

wise talon
#

not allowed

#

if you do not take analysis 2 you will be forced to wait

#

69mins for help