help-10

[hallow quiver]

so since the derivative is positive on [0,10]

wasn't sure what t would be here

[limber quartz]

what are you trying to do?

[hallow quiver]

to show the function is increasing or decreasing

[limber quartz]

it is only asking if the graph is concave or convex on the interval, and if it is increasing or decreasing on the interval

ok, you are looking for a stationary point?

[hallow quiver]

yes

[limber quartz]

well, it happens far outside our interval. approx 89

what is the sign on LHS

||(should be +)||

[hallow quiver]

that doesn't seem right

i must be doing something wrong

[limber quartz]

I don't think so yeah maybe

$f'(t) = -400(1.02)^t \ln{(1.02)} + 46$

[warm shale]

Disorganized

[limber quartz]

$\frac{46}{400\ln{(1.02)}} = (1.02)^t$

[warm shale]

Disorganized

[limber quartz]

$\ln{\left(\frac{46}{400\ln{(1.02)}}\right)} = t\ln{(1.02)}$

[warm shale]

Disorganized

[limber quartz]

$t = \frac{\ln{\left(\frac{46}{400\ln{(1.02)}}\right)}}{\ln{(1.02)}}$

[warm shale]

Disorganized

[limber quartz]

was that top part the same as before?

[hallow quiver]

yes

so I just had to divide it by ln (1.02)

[limber quartz]

this is the same though

well this really doesn't matter at all though

it's true. the graph is increasing and convex down

it levels off at about t = 89

any point inside of t=[0,10] would have been sufficient as a test point

and it will be +

https://www.wolframalpha.com/input?i2d=true&i=plot+f\(40)t\(41)+%3D+-400Power[\(40)1.02\(41)%2Ct+]%2B+46t+on+t%3D\(91)0\(44)10\(93)

change the interval to something like 200 and we will see an arch (prediction)

[hallow quiver]

right ok

so the function f_rent - f_buy here would be concave

[limber quartz]

I think the convex label in this context is kind of strange

normally it's "concave-up" (holds water) or "concave-down" (dumps water out)

("convex" is it's own thing)

[hallow quiver]

ok I get it now

[limber quartz]

ok, just quickly let me summarize here

to make sure the graph was concave-up or concave-down, we used the second-derivative test

and in this case the graph is concave-down on the entire interval

we used the interval test (using first derivative) to figure out that any value of f'(t) in the interval [0,10] would summarize the entire interval as increasing or decreasing (since the stationary point was far to the right of our interval, which was extra easy)

and that's that I guess

[hallow quiver]

thank you so much for your help!

[hallow quiver]

.close

[obtuse pebble]

Channel closed

Closed by @hallow quiver

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mild flint]

Find area ABC, if AB=5, AC=10 and AK bisector=4

[static beacon]

Are you assuming any right angles

[mild flint]

nope, couldnt come up with anything

only thing I may do is that bisector cuts bk/kc=1/2

[mild flint]

<@&286206848099549185>

[obtuse pebble]

@mild flint Has your question been resolved?

[obtuse pebble]

@mild flint Has your question been resolved?

[obtuse pebble]

@mild flint Has your question been resolved?

[earnest elk]

Doesn’t look like enough info

[obtuse pebble]

@mild flint Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plucky lava]

hi

[obtuse pebble]

Please don't occupy multiple help channels.

[plucky lava]

hrllo

i need help with some pythagorean theorem and triangle exercises

[lost tree]

yeah

use pythagoras's theorem on triangle ABH

[plucky lava]

for what f

fam

[lost tree]

?

[plucky lava]

i have no sides or angles of abh

how can i

[lost tree]

it is given that AB = 4

[plucky lava]

use pythagorean theorem

yeah thats all i have

[lost tree]

and ABH is a right triangle

[plucky lava]

yeah

[lost tree]

just write pythagoras's theorem

with what u have

[plucky lava]

i only have 4

[lost tree]

it doesnt matter

[plucky lava]

dont i need at least 2

[lost tree]

use BH and AH

in place of the other numbers

[plucky lava]

I DONT KNOW THEM

okay

wait

what am i solving for

Ah?

or BH

Ah i think

[lost tree]

no now write the equation for triangle AFH

[plucky lava]

what equation fam

[lost tree]

pythagoras theorem

[plucky lava]

oh my days

I LITERALLY HAVE NOTHING

WAIT

[lost tree]

treat what u dont know as unknowns

[plucky lava]

first i need to find AH

[lost tree]

and then notice that triangles FBH and AFH are similar

and that FB = 4 - AF

[plucky lava]

no sorry

nvm

.close

[lost tree]

using all that u can find a system of equations ig

[obtuse pebble]

Channel closed

Closed by @plucky lava

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bronze rover]

for (f(x))^(g(x)) to be defined, f(x)>0, why?

[brisk matrix]

what

[knotty crow]

imagine (-2)^x for even/odd x's

[brisk matrix]

this depends on g(x) as well

[bronze rover]

isn't it still defined tho?

[brisk matrix]

do you have the whole question?

[bronze rover]

it's not a question, it's a theorum that I don't understand

[brisk matrix]

do you have the whole theorem?

what are f and g?

[bronze rover]

oh nevermind I just understood it

0^0 will be undefined

Thanks for the help

.close

[obtuse pebble]

Channel closed

Closed by @bronze rover

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[latent jasper]

does x need to be defined for all x's to use for intermediate value theorem

[rigid lintel]

you need continuity for intermediate value theorem

so yes

[latent jasper]

but continuity doesn't mean that x is defined for all x's

for example 1/x is a continuous function right?

but x can't be zero

[rigid lintel]

1/x is continuous everywhere except 0 yes

[latent jasper]

and if I give you [-2, 3] you can't guarantee that 1/x=0 has a solution

[rigid lintel]

1/x is not continuous on [-2, 3]

[latent jasper]

just by knowing that f(x) is continuous

[latent jasper]

but we say that 1/x is continuous?

as a function don't we?

[rigid lintel]

.

[latent jasper]

so basically knowing a func is continuous is not enough?

We need to make sure it is defined for all x's

[rigid lintel]

1/x is not continuous on [-2,3]

[latent jasper]

I guess what I am trying to say is knowing a function is continuous is not enough? I need to make sure that it is continuous in the intervall as well? We say elementray functions are continuous but I still need to make sure it is continuous in the intervall right?

[rigid lintel]

you only need to make sure the function is continuous on the interval

1/x is not continuous on R

it is not

it is on $(-\infty, 0) \cup (0, \infty)$

[royal basin]

\cup

[warm shale]

heavy

[rigid lintel]

thjats better

ty

[obtuse pebble]

@latent jasper Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pure dune]

ive asked for help on writing this graph as a rational function multiple times here and no one has helped

[pure dune]

<@&286206848099549185>

[obtuse pebble]

@pure dune Has your question been resolved?

[pure dune]

.close\

.close

[obtuse pebble]

Channel closed

Closed by @pure dune

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold cedar]

Hello. I'm trying to find y' here, but the computer system I'm checking against says I'm incorrect, and idk why

[civic zealot]

the 1/3 isn't in the denominator

and $\sqrt[3]x = x^{1/3}$\ but $\frac{1}{\sqrt[3]x} = x^{-1/3}$

[bold cedar]

I'm lost. How is 1/3 not in the denominator?

That's where the cubed root is in y

[warm shale]

Zybikron

[civic zealot]

what's the derivative of x^(-1/3)?

[bold cedar]

(-1/3)x^(-4/3)

[civic zealot]

you see that that's not the same as what you have?
You applied power rule while the root was still in the denominator, which you can't do. You have to move it up to the numerator before you use power rule

[bold cedar]

Gotcha I think

Let me try again from the beginning and keep that in mind

Got it, ended up with 2e^x-(7/3x^(4/3)))

Thanks for the help

.close

[obtuse pebble]

Channel closed

Closed by @bold cedar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma flax]

how do i solve this?

[shy mango]

for exponential functions like that you will want to take the natural log of both sides

ie ln(e^2x) = ln(2/3)

natural log cancels with e, leaving you with 2x = ln(2/3)

x = 1/2 ln(2/3)

if you want an actual value ask your calculator from there

[prisma flax]

yes

it worked

thanks

[shy mango]

👍

.close

[obtuse pebble]

Channel closed

Closed by @shy mango

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold cedar]

Hello, I'm having issues thinking about this problem. I know it's asking to find the derivative of y with respect to the variable on the bottom of each problem, but how do I do it with respect to a specific variable?

[bold cedar]

Do I ignore the other's existence?

[sharp pecan]

the 'other' is just a number in that case, or a constant, or multiplier etc.

[bold cedar]

So just leave it be?

So dy/dx would be t2x+t^5x

[sharp pecan]

yh:\
$f(x)=2tx^2$\
$f`(x)=4tx$

[warm shale]

Jigglyproff

[sharp pecan]

yeah

but I guess you would rather write 2tx, actual numbers first, then list variables

but thats preference

[bold cedar]

Gotcha, thanks

.close

[obtuse pebble]

Channel closed

Closed by @bold cedar

Use .reopen if this was a mistake.

[sharp pecan]

ah wait

.reopen

[obtuse pebble]

✅

[sharp pecan]

why x at end

x^1 derives to 1

[bold cedar]

Oh yeah, that would be right

My bad

[sharp pecan]

alright

.close

[obtuse pebble]

Channel closed

Closed by @sharp pecan

Use .reopen if this was a mistake.

[bold cedar]

.reopen

[obtuse pebble]

✅

[bold cedar]

It seems I did not fully understand this

[sharp pecan]

uwu

what is the derivative of x^5

[bold cedar]

5x

[sharp pecan]

no

[bold cedar]

Wait

5x^4

I'm just being dumb

[sharp pecan]

the rule is\
$f(x)=ax^b$\
$f`(x)=b\cdot ax^{b-1}$

[warm shale]

Jigglyproff

[bold cedar]

I guess this is the point of review

[sharp pecan]

better

[bold cedar]

So for the first half of this

We have tx^2

So I put 1 in front, get rid of t, and have x^2 left

[echo lava]

bruh

[bold cedar]

They're helping, don't insult their vernacular

[sharp pecan]

its just a joke lol

[bold cedar]

So then for the second half we have t^5x

[echo lava]

ik they are helping

[bold cedar]

So we take 5 to the front, and have t^4, and multiply by x

[sharp pecan]

correct

[bold cedar]

Oh, got it correct this time

I skipped over one of the steps in my head ig, typing it out helped

Thanks for the help

.close

[obtuse pebble]

Channel closed

Closed by @bold cedar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bitter rock]

I am confused on what format the answer should be and dont quite know how to find the plane

[obtuse pebble]

@bitter rock Has your question been resolved?

[viral blade]

Neither of those are parallel to the xy-plane

And they both intersect the sphere at it's center

[bitter rock]

how would i write an equation for a plane?

[viral blade]

The standard form is ax+by+cz = d

[bitter rock]

what is d represent in the equation?

[viral blade]

just a number

it doesn't have any particular geometric interpretation if that's what you're asking

[bitter rock]

how do i find its value for example in this problem?

[viral blade]

Two planes would be parallel if they have the same values for a,b,c

so you can use the a,b,c values from the xy-plane

[bitter rock]

ight

i figured it out

i was being dumb

.close

[obtuse pebble]

Channel closed

Closed by @bitter rock

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dry dawn]

is there a resource i can cite to show that 1 can be represented as a fraction?

[timid yacht]

yeah

me

1/1 = 1

[tropic leaf]

1 is a rational number

so it is a fraction ( a ratio)

[dry dawn]

but is there a proof for that though

[tropic leaf]

here is the proof

[dry dawn]

like an actual resource i can cite 💀

is it lierally just QED?

[tropic leaf]

QED means "Just like we wanted to prove"

in latin

[timid yacht]

wdym, u write it up as a fraction: like 25/25 and we know it equals to 1, so voila we wrote it up as a fraction

[dry dawn]

no i get that

[timid yacht]

i'd say its a solid enough proof, that we can write it up: we ACTUALLY wrote it up in a fraction form

[dry dawn]

like u take x^2 / x^2 its 1

and thats a "no shit"

but this assignment asks to prove all our steps via a resource

by MIV step 3

[tropic leaf]

'-'

is this a troll

[dry dawn]

no

its literally an assignment i ahve to hand in by midnight 💀

[tropic leaf]

show the actual question

[obtuse pebble]

@dry dawn Has your question been resolved?

Channel closed

Closed by @dry dawn

Use .reopen if this was a mistake.

[dry dawn]

.close

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mellow relic]

Can u help me find my error in this integral?

[mellow relic]

It should be -11/384 according the key answer

[tropic leaf]

faz u = sinx dai du = cos x

sobra um cos x ali se vc fizer cos^2 x = 1- sin^2 x

[obtuse pebble]

@mellow relic Has your question been resolved?

Channel closed

Closed by @mellow relic

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mellow relic]

@tropic leaf vlw

[mellow relic]

.close

[obtuse pebble]

Channel closed

Closed by @mellow relic

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thick gyro]

first step is to get the equation for the velocity of the ball

do you know how to do that given you have the equation for the distance of the ball

yh

acc no

jumping too far ahead lol

you dont need to the derivative

basically you have the point at t=2s and y=something. and what its asking you for is a simple gradient at another point where t=2.5 secs for i)@waxen fossil

like y1-y2/t1 - t2

yh

[warm shale]

Cringelord

[thick gyro]

yh perfect

@waxen fossil

[warm shale]

Cringelord

[thick gyro]

you probably rounded when you didnt need to

desmos gives me this for the answer

you know you can just

do f(t) = 42t - 16t^2

on desmos

then use f() for whatever

even f'()

well acc, f' doesnt work if you use t and not x

so best to just use x

on desmos

find the average between (2,3) and (3,4)

yh

[obtuse pebble]

@waxen fossil Has your question been resolved?

Channel closed

Closed by @waxen fossil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coarse beacon]

I'm doing some geometry homework rn and I don't know why I got a question wrong, I'll link the photos in a sec and what I used

[obtuse pebble]

@coarse beacon Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[random notch]

im stuck, on the 2:5 ratio part

[thick gyro]

whats the total angle in a quadrilateral @random notch

[random notch]

360?

[thick gyro]

so whats the angle left over for the other 2 angles

well this is just covering the basics

just incase you messed up here

[random notch]

35?

[thick gyro]

ok

so how do you split 35

in a ratio of 2 to 5

[random notch]

i dont know 😭

[thick gyro]

for these

instead of 2:5 write it as 2/7 : 5/7

since 2+5 = 7

[random notch]

oh so if it was 3:4 it would be 3/7 & 4/7?

[thick gyro]

yh

[random notch]

okok

[thick gyro]

2/7 is the fraction of the total it takes for itself

[random notch]

okok

.close

[obtuse pebble]

Channel closed

Closed by @random notch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[native idol]

I need to do this integral by parts

[native idol]

this is the solution

i can´t find my mistake/mistakes and i'm praticing this method so i'm not that familiar with this strategy, if someone could help i would appreciate

[small cobalt]

quick question, that's an x^4 right?

not an x^5?

[native idol]

its 4

[small cobalt]

hm ok

ill try it out

[proud moon]

https://www.integral-calculator.com

[small cobalt]

tbh im still a freshman high schooler but ill try

[proud moon]

Put your integral in here and it’ll show you the steps

@native idol

https://www.integral-calculator.com

[small cobalt]

i have a feeling that you missed a step on the first step

[fierce lagoon]

Or use wolfram

You can legit do it right here

In discord

[small cobalt]

wolfram doesnt have steps tho?

or does it

[cold thistle]

It does with pro

[small cobalt]

oh huh

[civic zealot]

yeah, your fraction decomp doesn't make sense

[small cobalt]

i think they missed a term

[cold thistle]

I'll throw it in my wolfram

[small cobalt]

done

[native idol]

Omg

[small cobalt]

yeah they missed the 8x/x^3-7

you might need to integrate that too

do another partial fraction

[native idol]

i failed in the beginning when i was making the polynomial division

[small cobalt]

yeah, though i think you just missed a term

just integrate that 8x/x^3-7

and just add that to the end of your answer

[small cobalt]

yep that probably needs revising

[native idol]

its 2x not 0 the x should be +x not -x

@proud moon thanks for the site

i found the 2x+1 different

[small cobalt]

nice!

if you're done you can run .close

[proud moon]

Np it helped me a lot before as well

[native idol]

thanks you to @small cobalt

[small cobalt]

for integrals just use that site or wolfram

[native idol]

yes you can close this one thanks

[small cobalt]

lol

oop alr

.close

[obtuse pebble]

Channel closed

Closed by @small cobalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ember granite]

How do I do this problem?

[hollow willow]

A or b

[ember granite]

A

[hollow willow]

How many different numbers can you have that all don’t differ 10 from eachother

[ember granite]

9?

[hollow willow]

Well 10

A number that ends in 0, 1 , 2 , 3 etc .. 9

[ember granite]

Ok

[hollow willow]

Wait hold up

No that’s not true

Honestly I don’t know how to do this one let me think

[civic zealot]

it's not 'at least 10' it just 10.

i think

[ember granite]

Ah ok

[hollow willow]

So from 0-90 there are 2 numbers that are 10 more or less

One that is 10 more and one that is 10 less

[ember granite]

apparently i have to use the pigeonhole principle with the division algorithm

thats the hint i was given for this problem

[hollow willow]

So you’d take all the numbers from 91-100 which means you can’t take 81-90

[civic zealot]

yeah, so set up pairs of numbers that are 10 apart as your 'holes'
and show that if you pick 55 numbers, at least one of those sets has both number chosen with PH

[ember granite]

ah ok thanks

[civic zealot]

maybe.... that's my guess anyway

[ember granite]

its alright thanks for the help anyways

[hollow willow]

I’m thinking you have to take 91-100 since those are the most effective since they don’t have a +10, which means you can’t take 81-90, which means 71-80 are gonna be the most effective since they wouldn’t overlap with a +10 and you’d get an infinite loop until zero

And then you know the amount of numbers you can have without having two numbers be 10 apart

[civic zealot]

or maybe it has to do with multiples of 5 and 2....

[lost tree]

u can pick the 50 numbers 1 - 10, 21 - 30, 41 - 50, 61 - 70, 81 - 90,

with no two numbers 10 apart

but u cant find 5 more

[ember granite]

Ok

[lost tree]

so like consider splitting up ur numbers into like bins
first bin has the numbers 1, 1 + 10, 1 + 20, ..., 1 + 90
second bin has the numbers 2, 2 + 10, ..., 2 + 90
...
and the tenth bin has the numbers 10, 10 + 10, 10 + 20, ..., 10 + 90

u must pick 55 numbers out of these bins

[ember granite]

Alright

That makes sense

thanks for the help

.close

[obtuse pebble]

Channel closed

Closed by @ember granite

Use .reopen if this was a mistake.

[lost tree]

show that ull have to pick 6 numbers from one bin

[ember granite]

ok

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland spoke]

Hi

[inland spoke]

this is not graded btw (says practice problems at the top and submissions are not permanently recorded)

from this wee are given that V0 (initial velocity)=0m/s, acceleration is = -10 m/s^2 due to gravity, and displacement (x-x0)=40 m

[fickle surge]

is this for physics

[inland spoke]

no it's for calc

but it definitely feels like physics

[obtuse pebble]

@inland spoke Has your question been resolved?

[thick gyro]

start of with a = -10

you can integrate to get velocity

and then integrate velocity to get distance

[inland spoke]

srry I actually just figured it out

I didn't put displacement negative

thanks

.close

[obtuse pebble]

Channel closed

Closed by @inland spoke

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorn badge]

I got 537.28, however the answer key said it was 503.01 for the answer

[thorn badge]

I did A = 500(1 + 0.002)^36

[short spruce]

not quite the correct formula

A=P(1+rt) where r is rate and t is time in years and P is initial investment

[thorn badge]

.close

[obtuse pebble]

Channel closed

Closed by @thorn badge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed by @near zephyr

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[trail cloak]

[trail cloak]

Please open a new channel

[unique cliff]

Ok

[trail cloak]

This one will close

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uneven palm]

how the hell does it simplify to that?

[brisk matrix]

join the fractions, then factor a (x^3 + 1)^4/3

[uneven palm]

right

my brain was not braining

ty lol

.close

[obtuse pebble]

Channel closed

Closed by @uneven palm

Use .reopen if this was a mistake.

[uneven palm]

guys this is what happens when you do 40 integrals in one day

(there was 4 days to do it )

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime oracle]

By how many zeros the number
$460^{1500}−216000^{500}$,
written in the decimal system, end ?

[warm shale]

Pierre de Fermat

[strange belfry]

factor out powers of 10

[prime oracle]

3994 ?

Decimal are 10^3994

[strange belfry]

how did you come to that

[prime oracle]

By Wolfram alpha

[strange belfry]

that's just decimal approximation in scientific notation

the number itself has 3995 digits so I doubt I'd have 3994 zeroes

I meant factoring out powers of 10 algebreicly

[prime oracle]

How to do that ?

[strange belfry]

well

can you write 460 as an integer multiplied by a power of 10

and do that for 216000 as well

[prime oracle]

$460^{1500}-60^{1500}$

[warm shale]

Pierre de Fermat

[prime oracle]

I found it

[strange belfry]

should be $460^{1500}-216^{500}\cdot10^{1500}$

[prime oracle]

Oh okay

[warm shale]

biggboy

[prime oracle]

So it's 1500 ?

[strange belfry]

yeah but you don't come to that conclusion until you seperate 460^{1500} into something times 10^{1500} and then factoring the common 10^{1500} term

[prime oracle]

$460^{1500}=46\cdot 10^{1500}$

[warm shale]

Pierre de Fermat

[prime oracle]

So $10^{1500}( 46-216^{500})$

[warm shale]

Pierre de Fermat

[prime oracle]

???

[strange belfry]

yes

no

almost

$(ab)^c = a^cb^c$

[warm shale]

biggboy

[strange belfry]

it distributes

so $46^{1500} \times 10^{1500}$

[warm shale]

biggboy

[obtuse pebble]

@prime oracle Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal edge]

I’m terrible at geometry

[daring rock]

You can prove that the triangles are similar

And that means their sides are proportional

[vocal edge]

How do I do that

Like I understand some of it

Well, only one angle pair

Bc they are vertical

[daring rock]

in problem 10 you mean, right?

[vocal edge]

Indeed

[daring rock]

You also have parallel lines

Which can give you things like alternate interior angles

[vocal edge]

So q is congruent to s due to

Uh

[daring rock]

Are they alternate interior angles?

like this

[vocal edge]

Yes

[daring rock]

Yep, that proves they're congruent

the angles I mean

[vocal edge]

Is w and t congruent for the same reason?

[daring rock]

Yes

But you actually only need two pairs of angles

to prove that the triangles are similar

The third one is free, because they have to add up to 180, so you know it automatically

[vocal edge]

Oh true

I forgot ab that

Ty it’s 1 am I’m rlly tired Yk

[vocal edge]

What ab 11

[daring rock]

Same thing basically

[vocal edge]

Wha

They aren’t parallel

That means perpendicular

[daring rock]

You can still find two pairs of congruent angles

[vocal edge]

But that’s lines

Not angles

[daring rock]

Perpendicular tells you about the angles

Right angles are congruent to each other

And you do have parallel lines, since AP and CQ are both perpendicular to PQ

[vocal edge]

Oh I see

Ty

So how do I get to figure out

What the lines equal

[daring rock]

You can't find their actual values

but if they're similar, their sides are proportional

like this

[vocal edge]

I’m lost dory

Sorry*

[daring rock]

In number 11, do you see how AP in one triangle corresponds to PC in the other?

[vocal edge]

Angle p equals angle C?

[daring rock]

I mean the sides

AP and PC

They're both the hypotenuse of their triangle

[vocal edge]

Ohh

I see that yea

[daring rock]

Then in the small triangle, PB

corresponds to which side in the large triangle?

[vocal edge]

CQ

[daring rock]

Yeah

So the corresponding sides are proportional

meaning

[vocal edge]

This makes so much more sense now

Holy

[daring rock]

AP/PC = PB/QC

[vocal edge]

Yeah

[daring rock]

Awesome 🎉

[daring rock]

Btw, you should name your angles with three letters

I knew what you meant but your teacher will want you to be specific

[vocal edge]

Yeah I see ty

Holy you helped me out so much

Idk my teacher is terrible at explaining things

Algebraic math I’m rlly good at

Same w other classes

Geometry I just get mental dog

Dog

Fog

.closd

.close

[obtuse pebble]

Channel closed

Closed by @vocal edge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mild nimbus]

I don’t understand this algebra question very much. Does anyone know if I did this right?

[novel knoll]

Looks good

[mild nimbus]

ok 😅

[keen plover]

It's right but don't forget simplify it

[mild nimbus]

7/5?

[keen plover]

right

[mild nimbus]

Ok ty

😊

.close

[obtuse pebble]

Channel closed

Closed by @mild nimbus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rigid yacht]

me

[finite wind]

is the sequence defined by term
a_n = 1 + 1/2 + 1/3 + ... + 1/n convergent?

[rigid yacht]

why is ln b = 3?

seems like they obtained that by subbing x = 0 in an equation

but which equation did they even use???

[rigid yacht]

Q5ii btw

[obtuse pebble]

@rigid yacht Has your question been resolved?

[obtuse pebble]

@rigid yacht Has your question been resolved?

[obtuse pebble]

@rigid yacht Has your question been resolved?

[trail cloak]

!help

[obtuse pebble]

Please read #❓how-to-get-help

[unreal musk]

Remember from part (i) you have this

So ln(P/k -1) = ln(be^{-rt}) = … = ln(b) - rt

“y” intercept (or ln(P/k-1) intercept rather) is 3 so when t=0 you get ln(P/k-1)=3 and as per above

[finite wind]

I know I just pressed sent before he messaged "me" to take the channel

[trail cloak]

Oh well did you get help in another channel then?

[rigid yacht]

ohhh

right

[rigid yacht]

what about for R?

how’d they know that r has something to do with the gradient?

and why -r specifically and not just r?

[rigid yacht]

https://tenor.com/view/among-us-twerk-twerk-butt-dance-among-us-gif-19275026

[unreal musk]

Similarly notice that you basically have a line equation ln(P/k-1)=ln(b)-rt

You basically have ln(b) as the “y” intercept and -r as the gradient

So -r is the gradient between those points (0,3) and (1.5,0)

[finite wind]

🤓

[rigid yacht]

ohh

alrighty

danke

another question

could you shade the area that im supposed to find in the 2nd part of Q2?

im having trouble visualising it

[wise talon]

the area where they intersect

let f be the thing going up. let g be the thing going down

then the area you want is bounded by f=g

[obtuse pebble]

@rigid yacht Has your question been resolved?

[rigid yacht]

alrighty

thanks y’all

https://tenor.com/view/spongebob-twerking-ratchet-dancing-throwing-ass-gif-13893121

with fate shalt we meet each other again

vanish

.close

[obtuse pebble]

Channel closed

Closed by @rigid yacht

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silver ore]

where would I begin?

idk if what I did is right but so far I did

$\frac{\partial u}{\partial t}+\rho \nabla \cdot \overrightarrow{u}+\overrightarrow{u}\cdot \rho \nabla =0$

[warm shale]

arrow891

[silver ore]

I have no idea if this is the right approach or not

[obtuse pebble]

@silver ore Has your question been resolved?

[silver ore]

.close

[obtuse pebble]

Channel closed

Closed by @silver ore

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[next bison]

Can anyone help me with this exercise? I'd be really thankful.

[obtuse pebble]

Please don't occupy multiple help channels.

[next bison]

Sorry I'm new to discord

[ancient jacinth]

could you translate this

[trim portal]

I think he is looking for imaginary part of this expression. Am I right @next bison?

[high lily]

i^5 not 5i

[trim portal]

Right, sorry

[high lily]

that sounds like the gist of it

assuming x and y are real

[trim portal]

Yo, are you still online?

[timid silo]

yes

[next bison]

I'm trying to do it, thank you

[next bison]

Yes

[high lily]

show us what progress you've made and where/if you're getting stuck

[timid silo]

interesting question

[ancient jacinth]

$frac[x^3-3xy^2+3x^2iy-iy^3][i^5]$

$fra/[x^3-3xy^2+3x^2iy-iy^3][i^5]$

[high lily]

$\frac{numerator}{denominator}$

braces not (square) brackets

[ancient jacinth]

$frac/[x^3-3xy^2+3x^2iy-iy^3][i^5]$

$\frac{x^3-3xy^2+3x^2iy-iy^3}{i^5}$

[warm shale]

Blighter

[high lily]

try not to just give stuff away

[ancient jacinth]

what do they want us to do again

[trim portal]

He should also memorise this identity?

[timid silo]

z=x+iy is given and i have to find the imaginary part of w=z^3/i^5

[next bison]

Yes

[ancient jacinth]

so in the case of a+bi, the imaginary part is b?

like that?

[trim portal]

yeah

[ancient jacinth]

ok

[trim portal]

but do NOT just give-away the answers

[ancient jacinth]

@next bison what is your mother tongue

[next bison]

I speak Bulgarian and Italian

And I'm learning English since I need it for my master degree, but I'm not really good ahahaha

[trim portal]

So in order to solve your task, it's good to expand this expression

[ancient jacinth]

une secondo

mamma mia lascia fare!
Come già sapete, (a+b)^3 è uguale ad a^3+3a^2b+3ab^2+b^3. In questo caso, a è x e b è iy, quindi c'è una leggera differenza quando vediamo b o iy. a^3 sarà ovviamente x^3 e 3a^2b sarà 3x^2iy. MA, 3ab^2 è diverso, b^2 in questo caso è (iy)^2 e sappiamo che i^2=-1, quindi (iy)^2=-y^2, quindi 3ab^2=-3xy^2. Inoltre, b^3 è (iy)^3 e si deve sapere che i^3=-i, quindi (iy)^3=-iy^3.
Quindi, in definitiva, l'intera espressione (x+iy)^3 = x^3-3xy^2+3x^2iy-iy^3

Tradotto con blighter

i cooka da pizza

capito?

[trim portal]

,rotate

[ancient jacinth]

che cosa sto guardando

no

(x+iy)^3 = x^3-3xy^2+3x^2iy-iy^3

[next bison]

Expansion

[ancient jacinth]

fai diventare grandi le cose piccole

[next bison]

So the answer is C

[next bison]

Ok capito questo

[ancient jacinth]

mmm mm

[ancient jacinth]

dobbiamo dividere per i^5

[next bison]

Questo no bene ahahhaa però Grazie 🙏

[ancient jacinth]

uh

di nuovo

(a+b)^3=a^3+3ab^2+3a^2b+b^3

(x+iy)^3= x^3 + 3 * x * (iy)^2 + 3 * x^2 * iy + (iy)^3

(iy)^2=-y^2

3 * x * (iy)^2 = -3xy^2

3 * x^2 * iy = 3x^2iy

(iy)^3 = -iy^3

perché : (iy)^3 = i^3 * y^3

i^3 = i^2 * i = -1 * i = -i

= i^3 * y^3 = -y^3

(x+iy)^3= x^3 -3xy^2 + 3x^2iy -iy^3

capito

🤌

per favore, sono in ginocchio per cercare di farti capire

[next bison]

Ahahhaha

[next bison]

So

[ancient jacinth]

capito?

[ancient jacinth]

si

ora dobbiamo dividere per i^5

[ancient jacinth]

1/i = -i
1/i^2= -1
1/i^3=i
1/i^4=1

1/i^5= 1/i^4 * 1/i = 1 * 1/i = 1/i = -i

quindi...

$\frac{x^3-3xy^2+i(3x^2y-y^3)}{i^5} = -i(x^3-3xy^2+i(3x^2y-y^3))$

[warm shale]

Blighter

[ancient jacinth]

capito

[next bison]

Yes

So the imaginary part is -x^3+3xy^2

[next bison]

Answer C

[ancient jacinth]

si

[next bison]

Thank you very much for your really hard work and trying to translate everything to me you are very kind person 🙏

[ancient jacinth]

Non sono interessato

Nessun problema!

@next bison ehi amico devi chiudere questo canale

[next bison]

.close

[obtuse pebble]

Channel closed

Closed by @next bison

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bright scaffold]

Hi, just a numerical analysis question

[bright scaffold]

Nobody knows from the teachers lecture notes what this is

we assume its some sort of equation system

I know how we get there

but how to get the

a + b + c = 0 part just doesnt make any that much sense lol

aswell as a - c = 0
a/2 + c/2 = 1

The color thing makes sense

but after that i assume its just a 3x3 matrix

[hallow mesa]

Idk if I can help a lot but it seems that the picture is cut of at the end. Is there anything important there?

@bright scaffold

[bright scaffold]

Oh i can try to capture it better

no worries, just a sec!

[hallow mesa]

Thanks

[bright scaffold]

Must say that its quiet ironic that it ends up in a matlab script in order to solve it i assume

or its just a matrix solver

man's to lazy to do it by hand?

[hallow mesa]

So what exactly is your doubt

[bright scaffold]

This

Or, i don't understand how we get that

[hallow mesa]

Oh

[bright scaffold]

[hallow mesa]

Then I’m useless

[dense imp]

a + b + c just refers to doing matrix multiplication (first row of 3x3 matrix) multiplied with the a b c vector and getting the first element of the vector on the right, which is 0

[bright scaffold]

Aaah no problem

[dense imp]

1(a) + 1(b) + 1(c) = 0

[hallow mesa]

Sorry

I think his doubt is

More about how the function turns into the system of equations

[bright scaffold]

Aaah no i do understand that

Sooshon just explained what i was asking for lol

[hallow mesa]

Oh I’m dumb

Sorry

[dense imp]

well then i lucked out

lol

[bright scaffold]

But uuh

[bright scaffold]

💀

I do understand what you mean

yet not

[hallow mesa]

How does that function just disappear in the matrix though

[bright scaffold]

lol

[dense imp]

that system of equations and the matrix multiplication are exactly equivalent

pretty much you can think of it as a different way to write it

[hallow mesa]

Not that

[bright scaffold]

OOOH

wait

now i get it

[thick fog]

You need to show what you are even trying to do in the first place. It looks like you are deriving some finite difference method but there is zero context.

[bright scaffold]

Its okay

Sooshon made me realise it

.close

[obtuse pebble]

Channel closed

Closed by @bright scaffold

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grim skiff]

In this question;
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion s = 8/t^2, where t is measured in seconds. Find the velocity (in m/s) of the particle at times t = a, t = 1, t = 2, and t = 3.

How do I find the common denominator? I'm having a very hard time incorporating the 8 and knowing what to do with it

[dense imp]

do you know how to take the derivative of a power function? think of it as $8t^{-2}$

[warm shale]

Sooshon

[dense imp]

you would just find the derivative, which would be v(t), the velocity function and then you can just plug in those numbers for t

[grim skiff]

Finding the derivative in the first place is what I'm having trouble with

[dense imp]

well so youre not familiar with calculus at all?

[grim skiff]

I know how to find a derivative when it doesn't involve fractions

[dense imp]

the rule for power functions is the same, even with a negative exponent, thats why i suggested thinking of s(t) as:

$s(t) = 8t^{-2}$

[warm shale]

Sooshon

[dense imp]

you still just multiply the coefficient by the exponent (-2) and lower the exponent by one:

$v(t) = -16t^{-3}$

[warm shale]

Sooshon

[grim skiff]

So do 8t^-2(a+h)-8t^-2(a)/h for the formula instead?

Because if that works that's a lot easier than the abomination I have written right now

[dense imp]

ah youre supposed to do it using definition of derivative?

yeah you usually get tortured with that for a day or two before you learn the easy shortcuts, i don't know what class youre doing \ what stage of learning derivatives you are at

[grim skiff]

It's Calculus I first semester

[dense imp]

basically the definition with limits that sounds like maybe you're supposed to be using is how you eventually derive the easier shortcuts but that might be tomorrow's lesson for you

if you're using the definition it's just pure algebra to simplify it all, but it should come out to what i showed you, at least you can use that to double check your work

$v(t) = -16t^{-3} = \frac{-16}{t^3}$

[warm shale]

Sooshon

[grim skiff]

Alright, I think I get what you're saying now

I just don't quite understand the shortcuts because we haven't gone over those

Just the long algebraic equations in which I still suck at implementing fractions into

Thank you though, that clears a lot of clutter up

.close

[obtuse pebble]

Channel closed

Closed by @grim skiff

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vital kindle]

I need help with item no. 5

[warm shale]

SilverSoldier

[vital kindle]

yes

[lost tree]

okay and do u know what csc x is?

[vital kindle]

1/cos x?

[lost tree]

no

[vital kindle]

oh

1-sinx

please come back hahahha

[lost tree]

not 1 - sinx

[vital kindle]

ohhh. I don't knowww

1/sinx?

[vestal thorn]

yes

[lost tree]

now u can do it

[vital kindle]

omg how do I do it?

I'm super new to this topic im sorryyy

[lost tree]

replace the cscx with 1/sinx

and rewrite the limit

[vital kindle]

what about the other x?

[lost tree]

well leave it

[lost tree]

see if what u get looks similar to this

[vital kindle]

I srsly do not know what to do

help please 🥲

nvm I got it

.close

[obtuse pebble]

Channel closed

Closed by @vital kindle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unborn pewter]

Hello guys

Options
50
65
75
80

[unborn pewter]

Umm....
I found the answer
Late realization

.close

[obtuse pebble]

Channel closed

Closed by @unborn pewter

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith kelp]

(Undergrad Analysis) Could someone help explain to me what the L and R terms represent

[kind hawk]

the L is the derivative

and the r is the remainder which has to go to 0 sufficiently quickly

[obtuse pebble]

@wraith kelp Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tired sandal]

Hey, i need help i try but i not understand

[thick gyro]

translate it?

[tired sandal]

Yes

1. using the length gives the coordinates of the 4 points
   A,B,C,D
2. calculate the lengths AB, AC and BC
3. deduce the nature of triangle ABC, demonstrate your result.
4. Prove that ABCA' is a rectangle whose area you are calculating

( i understand the first)

[thick gyro]

for number 2, do you know how to find the length of a vector

[tired sandal]

No

[thick gyro]

the length of a vector is just the pythagorean theorem

as in

if you have (a,b)

the length of that vector

is sqrt(a^2 + b^2)

the length of AB is the length of the vector AB

[tired sandal]

I dont have measure

[thick gyro]

its the length of the vector

you can find the vector

using your coordinates

that you do from question 1

[thick gyro]

then do this^

[tired sandal]

What' "^"?

[thick gyro]

ok have you dont the first question @tired sandal

to find the coorindates of A B and C

[tired sandal]

If

A (-4;-4)
B (4;-2)
C (3;2)
A' (-5;0)

[thick gyro]

what would the vector AB be

[tired sandal]

I just started this chapter and I don't know how

[thick gyro]

well basically

the vector AB would be going from A to origin (which is -A) then going from origin to B

so AB = -A + B

= (4,-2) - (-4,-4) = (8,2)

what would the length of this vector be

[tired sandal]

Oh no it's good i have understand

[thick gyro]

the coodinate A is actually OA which means go from origin to (-4,-4)

[tired sandal]

I have understand

Thx for the help

[obtuse pebble]

@tired sandal Has your question been resolved?

Channel closed

Closed by @tired sandal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[urban quartz]

help

[vestal ridge]

yes

[urban quartz]

alr

so

ABC is a isosceles triangle

[vestal ridge]

yes and

[urban quartz]

AB = 6/5 of BC

and BC=AC

AK=CH+4

i need to find out the measures of AB, CB, AC

@vestal ridge are u there?

ismael despawned

<@&286206848099549185>

<@&286206848099549185>

[obtuse pebble]

@urban quartz Has your question been resolved?

[urban quartz]

<@&286206848099549185>

[keen plover]

Are AK and CH perpendicular to CB and AB

This question is ask for the circumference of a triangle, right

@urban quartz

[urban quartz]

yo hi

yes

yes they are

[keen plover]

OK

so AK * CB/2=the area of the the tri=CH * AB/2

[urban quartz]

yeah it's right

[keen plover]

which means

AK * CB=CH * AB

[urban quartz]

yeah ok

but idk their numbers

[keen plover]

and AB=1.2BC

AK=CH+4

therefore

(CH+4)CB=CH*1.2 CB

1.2CH=CH+4