help-10

[tardy epoch]

https://www.wikihow.com/Do-Long-Division
Read part 3

[deft forge]

I'm dumb I know

Okkk

Thanka

Thanks!!

Do we do 113 divided by 355?

Would 113 be the dividend?

And 355 the divisor

But then that would be impossible to do long division with because ull be doing fractions

So it should be 355 ÷ 113?

And after that we do the reciprocal of it to find the lower bound

[dark stirrup]

yes

[deft forge]

Of 1/pi

[dark stirrup]

no

[deft forge]

Okay I think I got it

How is this?

And then I repeat for 106/333?

[dark stirrup]

Hi singh

[deft forge]

Or 333/106

[dark stirrup]

I suck

[deft forge]

Ohh

[dark stirrup]

You had it correct here. I'm very sorry for you mixing you up

[deft forge]

Ohhh yeha I was mad confused thanks!!

[dark stirrup]

I thought you were trying to find pi the whole time, not 1/pi

[dark stirrup]

I'm very sorry. I wasted your time and I feel bad

[deft forge]

It's okay!!

How's this?

Matches so far

[dark stirrup]

Beautiful

You're doing great

(Still feel bad I got you turned around but I guess it was good long division practice)

[deft forge]

Thank you!

Yeah I did most long division back in highachool

And grade school

Been a while

So which one is upper bound?

The larger decimal?

000.374647

Which is 133/355

And lower bound as 106/333 =000.318318

This tells us for c

The decimal expansion should be between those numbers?

0.318318<1/pi<0.374647

???

Someone check and correct me if possible

[dark stirrup]

Yeah I forgot it all too (as you can see)

[deft forge]

It's all good

Can I ask another question?

If possible

Thanks for anyone that helped

[dark stirrup]

sure

Getting sleepy so may not stay forever

[deft forge]

Yeah it's 2:49 am here

Hehe

Like I can convert root 2 to a decimal and the fractions to a decimal and see which one is bigger or smaller

But I think the professor would want use to do it a certain way

I assume we have to square the root 2

[dark stirrup]

yeah you're missing a detail here

[dark stirrup]

There's the detail

Use this

[deft forge]

I don't really know fi I expressed it correctly

If*

[dark stirrup]

looks good

full marks

[deft forge]

Thanks!!

That's my b

And I guess we follow the same thing for c

[dark stirrup]

,rcw

[dark stirrup]

Looks good

[deft forge]

Thanks again! Appreciate it!

[obtuse pebble]

@deft forge Has your question been resolved?

Channel closed

Closed by @deft forge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[opaque wren]

Hello, I'm trying to solve x^3-((4+i)x)^2+(5+4*i)x-5*i, but I can't find any solution

[opaque wren]

I need to factorize it by (z-iα) where α is a real

[mellow glacier]

,w y = x^3-((4+i)x)^2+(5+4* i)x-5 *i

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Shockshwat#6202

[opaque wren]

yeah but, it's not factorized by z-(i*alpha) right?

(z-iα)(az^2+bz+c)

[obtuse pebble]

@opaque wren Has your question been resolved?

[opaque wren]

<@&286206848099549185> do you have an idea?

[twilit ivy]

try comparing coefficients

[opaque wren]

(4+i) and (5+4i) ?

hmm

[twilit ivy]

(x-iα)(ax^2+bx+c) = x^3-((4+i)x)^2+(5+4* i)x-5 *i

find a b c and α

[opaque wren]

all right, I'm going to develop and find the results

I don't think it's what they want me to do, as the first question is "prove that P admit a solution in C pure imaginary i(alpha) that we'd determine"

then, I have to factorize by (z-i(alpha))

don't you think there is another solution, like an evident root?

[twilit ivy]

this doesnt show a purely imaginary solution tho

[twilit ivy]

perhaps you wrote it incorrectly

(sorry for no crop)

[obtuse pebble]

@opaque wren Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[opaque wren]

thank you

.close

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis spruce]

is -i= -e^(ipi/2)

[lapis spruce]

3^z=-i

using natural log i cant solve this eq right??

.close

[obtuse pebble]

Channel closed

Closed by @lapis spruce

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[atomic agate]

Can a biconditional statement(p<->q) be verified by testing if p->q and q->p is True

[worldly nacelle]

Yes

[atomic agate]

ok ty

.close

[obtuse pebble]

Channel closed

Closed by @atomic agate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[manic wolf]

number = a* b* c consider a,b,c are primes . How many build up factors does the number have. (the answer is 3) just wondering if there is a formula or smthing to this without actually picking 3 primes

[high lily]

wdym by
"build up factors"

[manic wolf]

so like for example 2 * 7 * 3

[ruby path]

Do you mean prime factors

[manic wolf]

u get 42

[manic wolf]

the other ones

[worldly nacelle]

You devidr by the lowest prime number

[ruby path]

All possible factors except prime?

[worldly nacelle]

Until that's not possible you go to the next

[manic wolf]

yea

[worldly nacelle]

Until you have only primes left

[ruby path]

Are you aware of nCr

Like the notation

[manic wolf]

Anyway factors of 42 are 1, 2, 3, 6, 7, 14, 21, 42 so you can see that 14, 21 , 6 are the ones im looking for

[ruby path]

or what it does

[manic wolf]

14, 21 and 6 non primes

So Im wondering if there is any formula to this or smthing

[ruby path]

well

[civic jasper]

isnt that just 3c2

oh you mentioned it sry

[manic wolf]

yea what is that

what is nCr

[ruby path]

n choose r?

$\frac{n!}{r!(n-r)!}$

[warm shale]

NEONPerseus

[ruby path]

But I don't think its needed for this

[civic jasper]

basic combinatorics concept, ncr basically means the number of ways to choose r objects from a set of n

[manic wolf]

yea me neither lol

[ruby path]

For a number $(x_1)^{n_1}(x_2)^{n_2}(x_3)^{n_3}... (x_r)^{n_r}$ where $x_i$ is a prime number and $n_i$ are whole numbers, the total number of factors is $(n_1 + 1)(n_2 + 1)(n_3 + 1)...(n_r + 1)$

[warm shale]

NEONPerseus

[manic wolf]

leme process this

[ruby path]

It works on principles of combinatorics

[manic wolf]

so how would this be used in 2 * 3 * 7 for example

[civic jasper]

2^1 * 3^1 * 7^1

number of factors = (1+1)(1+1)(1+1)

= 8

[civic jasper]

8 factors

[ruby path]

3 of those are primes

Which are 2, 3, 7

[manic wolf]

leme process

[civic jasper]

1 and the number are 2 more

so 3 left

[ruby path]

If you want only perfect factors, subtract 2 because this includes 1 and the number itself

[manic wolf]

why do u use the ^1

[civic jasper]

because the formula requires the powers of primes

[manic wolf]

So everytime its ^1

[timid silo]

You should explain the idea behind it, not just give them a strange formula which they have never seen

[manic wolf]

Thanks

[ruby path]

Yeah I should

[civic jasper]

not always

[ruby path]

Okay so take for example a number like 50

5^2 * 2^1

[manic wolf]

sure

[manic wolf]

yea

[ruby path]

Applying the formula would give us (2 + 1)(1 + 1) = 6 factors

In general, a factor of a number is always composed using its prime factors

The idea behind adding one to each power is the number of ways you can select each power to appear in a number

[manic wolf]

wait so u have to make a number into a number with a power ?

[ruby path]

fuck

💀

[civic jasper]

yes, write it as the product of the powers of its primes

[ruby path]

Natural selection has been graceful towards me

Anyways

[manic wolf]

Oh wait thats why its 42 = 3^1 * 2^1 * 7^1

[civic jasper]

yep

[ruby path]

If you think of these factors as items in a box

[manic wolf]

Ohhhhhh thanks

[ruby path]

And in how many ways you can pick various amounts of these items

[manic wolf]

yea

now that makes sense

[ruby path]

For example in 5^2:
You can pick 0 5s out in 1 way
You can pick 1 5 out in 1 way
You can pick 2 5s out in 1 way

So the total number of ways of picking out a 5 is 3

[manic wolf]

yeye

[civic jasper]

which is just 5's exponent plus 1

[ruby path]

Similarly for all prime factors

Then you multiply to get all possible cases

The intuition behind the +1 is because you can also choose to not pick a 5 at all

i.e. 5^0

[manic wolf]

yea

tysm guys

[civic jasper]

🤝 group mafs

[manic wolf]

wish u a good one

[ruby path]

have a good one yourself

[manic wolf]

.close

[obtuse pebble]

Channel closed

Closed by @manic wolf

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

are you familiar with the inscribed angle theorem?

[spiral ferry]

nope

[timid silo]

(assuming O is the center of the circle)

[spiral ferry]

how can i solve it

[timid silo]

in a diagram like this, do you know the relationship between the two angles?

[spiral ferry]

not really

what is it

[high lily]

consider looking up the inscribed angle theorems if you don't know then already

majority of circle geometry questions will involve that

[spiral ferry]

alright

can yiu help with this question tho

[high lily]

and point to specific parts you don't understand even after reading

[spiral ferry]

an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle
what does this mean

[high lily]

there should've been a nice diagram that goes with that

[spiral ferry]

this

[ancient jacinth]

the angle which touches the circumference is half the central angle

this is known as the central angle theorem @spiral ferry

[spiral ferry]

ohhhhhhhhhhhhh

that makes sense

[ancient jacinth]

ye it was pretty easy to explain @high lily

[ancient jacinth]

inshallah

[ancient jacinth]

can you solve this now?

[spiral ferry]

would we just divide by 2

[high lily]

yeh

[spiral ferry]

then itd be 36

i understand

ty

.close

[ancient jacinth]

yes

[obtuse pebble]

Channel closed

Closed by @spiral ferry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cursive mirage]

we are saying this is fault because lnx / lnc != ln(x/c) or something else?

[stuck pilot]

Yes

lnx/lnc = log(c, x)
But ln(x/c) is lnx - lnc

Just for reference:
log2 = log(10, 2)
ln2 = log(e, 2)

In case you didn't know what log(c, x) means

[cursive mirage]

I got it thank you

.close

[obtuse pebble]

Channel closed

Closed by @cursive mirage

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse pebble]

@ancient jacinth Has your question been resolved?

[timid silo]

i got an idea to apply cosine or sine rule

let me try this question

[mellow glacier]

lmoa ded

[timid silo]

because side and angle is there so cosine rule will be good enough to find to answer this question

tho area is provided so i doubt my approach

i am gonna try with cosine rule hope i get the answer lmao

[mellow glacier]

law of cosines will apply here

c = $\sqrt{a^2 + b^2 -2ab cos\theta}$

[warm shale]

Shockshwat

[mellow glacier]

by this u can find the 3rd side and then you could use herons formula to find the value of x then use values of sin and cos to get the value of angles

[mellow glacier]

sine rule is better to use in this condition tho

[ancient jacinth]

but when i plug in 3x and x+5 as a and b, the solution gets very big

[timid silo]

abbey bevkoof yeh nahi

[ancient jacinth]

is there not an elegant way to solve this?

[mellow glacier]

sine rule

[timid silo]

cosine law cosA = (b^2+c^2-a^2)/2bc

this is cosine law

not what u r telling

[ancient jacinth]

sin(a)/3x=sin(b)/(x+5)

then what should i do

[timid silo]

u r telling law of addition of vectors formula

@mellow glacier

hey @ancient jacinth

[ancient jacinth]

yes

[mellow glacier]

u r mistaken

[timid silo]

u can apply sine rule using this approach

[timid silo]

no

the one formula u r telling is of physics to find sum of vectors as far as i remember

[mellow glacier]

Bhai maine literally dono side ko root kar diya

[timid silo]

but wait a sec

ha

[mellow glacier]

💀

[timid silo]

sorry i didnt se

see

anyways

mujhe laga kuch aur hi likha hua hai

[mellow glacier]

vector addition got its derivation from cosine rule

[mellow glacier]

soka

[timid silo]

yea so this approach is better

.close

[obtuse pebble]

Channel closed

Closed by @onyx hinge

Use .reopen if this was a mistake.

[timid silo]

.reopen

[obtuse pebble]

✅

[ancient jacinth]

i still dont get it

[timid silo]

bruh

[ancient jacinth]

like i got this complicated expression

one second

[timid silo]

ok

use area formula

[ancient jacinth]

i solved for the height of this triangle

x+5/2

[timid silo]

1/2*sina into bc

[mellow glacier]

wait

u could also use

[timid silo]

like use something like this

[ancient jacinth]

ok

[mellow glacier]

$\frac{sinA}{a} = \frac{sinB}{b}$ ig

[warm shale]

Shockshwat

[mellow glacier]

2 sides and 1 angle is given

[ancient jacinth]

but the 1 angle's side is not given

[mellow glacier]

nah nevermind its in terms of x

[timid silo]

just use 1/2sina bc

= 7.25

u get quadratic equation

and u get x value

[ancient jacinth]

could you do it step by step

[timid silo]

sorry i m busy

[ancient jacinth]

ok i will try to work this out

[timid silo]

bro it is literally

[mellow glacier]

Tex me likh

[ancient jacinth]

what

[mellow glacier]

$like this$

[warm shale]

Shockshwat

[timid silo]

$((sin150)(3x)(x+5))/2 = 7.25$

[warm shale]

cauchyschwarzsded

[timid silo]

using this u get x value

area formula

[ancient jacinth]

i did

[timid silo]

for triangle

[mellow glacier]

$\frac{((sin150)(3x)(x+5))}{2} = 7.25$

[ancient jacinth]

i did solve for x

[warm shale]

Shockshwat

[ancient jacinth]

but the thing is, how do i use that huge radical in the equations to solve for that small angle

[mellow glacier]

by this equation you can get x

[ancient jacinth]

i did

-15+sqrt(573)/6

[mellow glacier]

then put the value of x here

[mellow glacier]

wait what

[ancient jacinth]

ya

[mellow glacier]

,w ((sin150)(3x)(x+5))/2 = 7.25

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Shockshwat#6202

[mellow glacier]

its coming 1.4

[ancient jacinth]

oh wait i can just approximate right

[mellow glacier]

[timid silo]

lmaoooooooooooooooooooooooooooooooo

[ancient jacinth]

ohhh ok

ill just take x=1.5

[mellow glacier]

yeaaaa

[timid silo]

shall i close

??

[ancient jacinth]

I CLOSE

.close

[obtuse pebble]

Channel closed

Closed by @ancient jacinth

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine raven]

,rotate

[alpine raven]

how can I get rid of the integral

Context : I need to find probability density of (X,Y)

[royal basin]

show original problem statement?

you can probably sidestep this grueling integral bashing

[alpine raven]

Ok give me one sec

You understand french right ?

X est une variable aléatoire qui suit une loi normale centrée réduite et Y une loi de Khi-deux.

[royal basin]

Khi-deux ?

pk pas khi-carré

[alpine raven]

Calculer la loi conjointe de X et Y

Ah c'est comme ca le prof l'appelle

[royal basin]

alors X ~ N(0,1) et Y ~ χ^2(k)...?

[alpine raven]

Yep

[royal basin]

sont-elles indépendantes ?

[alpine raven]

Oui oui

[royal basin]

donc prends leurs densités individuelles et multiplie-les

[alpine raven]

Je l'ai fait et je suis arrivé à ça

[royal basin]

bah quoi ?

oh tu veux la LOI conjointe ?

[alpine raven]

Yep

[royal basin]

ça veut dire CDF en rostbif ?

[alpine raven]

Huh ?

[royal basin]

en anglais

[alpine raven]

J'en sais rien mdr

[royal basin]

CDF

cumulative distribution function

$P( X \leq x, Y \leq y )$

[warm shale]

Ann

[royal basin]

celle-ci

[alpine raven]

Ah okk

Ouais c'est ce que je recherche

[royal basin]

c'est qd mm le produit des lois individuelles non ?

directement de la définition des variables indp

[alpine raven]

J'ai utilisé une définition du cours qui dit que ça revient à determiner la fonction de repartition de (X,Y)

[royal basin]

y a pas de bonne forme non intégrale pour la loi de X sans utiliser la fonction erreur ou comment ça s'appelle

exp(-x^2) n'est pas intégrable en fonctions élémentaires

[alpine raven]

Oui j'ai pensé à la fonction erreur mais je sais pas si c'est possible de le faire sans fonction spéciale

[alpine raven]

Yep

[royal basin]

je n'en pense pas

[alpine raven]

J'ai oublié de dire, ce que j'ai trouvé là c'est la fonction de repartition

<@&286206848099549185>

[obtuse pebble]

@alpine raven Has your question been resolved?

[alpine raven]

.close

[obtuse pebble]

Channel closed

Closed by @alpine raven

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[real ginkgo]

How would I proceed after this?

[obtuse pebble]

@real ginkgo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[humble wolf]

My girlfriend got gifted this boomer-humor calendar, and today there is a math one, however, neither of us understand what the humor is intended to be. Any ideas?

[humble wolf]

I don't get it

[tardy epoch]

too grainy photo

[teal turret]

The guy is working on a solution on the whiteboard and his fellows have found the solution and have pinned the tail on the donkey

[drifting wraith]

i don't think you;re supposed to read it lol

the joke is that they put a sticker but it's in math

[royal basin]

it's mathy-looking gibberish

[humble wolf]

It does look like mathy-looking gibberish

[drifting wraith]

there's no reason to even think it's the solution

it's anything, but it's in math

[humble wolf]

a 'kick me' joke that makes no sense

funny haha math people put math sticker on math man's back

[drifting wraith]

yes that's it

[humble wolf]

💀

[tardy epoch]

.close if you're done

[obtuse pebble]

@humble wolf Has your question been resolved?

Channel closed

Closed by @humble wolf

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[agile parcel]

Hi

[agile parcel]

Anyone able to help

[civic zealot]

depends on the question

[wooden cipher]

[agile parcel]

Anyone know how to do this?

[obtuse pebble]

@agile parcel Has your question been resolved?

[obtuse pebble]

@agile parcel Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spark sail]

This is my first time doing a proof. Can anyone check this and give me pointers

z is a set of all positive and negative integers

[obtuse pebble]

@spark sail Has your question been resolved?

[obtuse pebble]

@spark sail Has your question been resolved?

[spark sail]

fine ig

[obtuse pebble]

Channel closed

Closed by @spark sail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce lagoon]

Discriminant

[rotund vector]

this is the value I got for the discriminant: k^2 + 2k -143

[fierce lagoon]

Do you understand the significance of the discriminant

,w expand (k+1)^2 - 4(9)(4)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Umbraleviathan#3607

[rotund vector]

don't I have to factorise the discriminant?

[timber fox]

u can factor that

[rotund vector]

how?

[timber fox]

im not gonna tell you

its two numbers > 10 ,

[rotund vector]

so I have to find two numbers that add to 2 and multiply to -143

[timber fox]

split the 2k into a sum of k's that when the coefficents multiply give 143

[rotund vector]

ok so first I start with (k ) (k )

[timber fox]

I mean ok

we can do

[rotund vector]

I don't even know where to start

literally have no idea

[timber fox]

do you know your 10 through 15 or even 20 times tables ?

13 * 10 = 130

if that helps

[rotund vector]

not 15 or 20

are we even meant to learn the 15 and 20 times table?

[timber fox]

I mean just move than up to 10 is useful for saving time and avoiding having to use tricks

[fierce lagoon]

,w factors of 143

[warm shale]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by Umbraleviathan#3607

[fierce lagoon]

:((((

[timber fox]

,calc 143 / 13

[warm shale]

Result:

11

[fierce lagoon]

Gamer

[timber fox]

took 2 seconds to spot 13-11 = 2 and 13 * 10 = 130 , so 13 * 11 = 143

[stark valley]

Can u come to my channel i need help

[tardy epoch]

clarkie's memorized the multiplication table 1-100

[warm canopy]

the 1 by 100 multiplication table

[rotund vector]

okay so I got (k-11)(k+13)

[timber fox]

👍

do you understand what umbral was saying earlier? the significance of this?

[rotund vector]

yes

[fierce lagoon]

No

[stark valley]

k

[rotund vector]

Just a quick question off topic: which concepts are the most important to cover and master before starting calculus - differentiation and integration?

I am trying to prep for calculus this year, but I missed most of the stuff from previous years, so I'm trying to catch up. It would be great if anyone could help me with which stuff to complete before moving on to calculus.

[timber fox]

all things functions and trig? linear algebra, idk

so much

trig identities are painful

[rotund vector]

so out of these which are the most important to cover?

I can open each individual section if you need specifics, but this would really help me out if I could get your opinion.

I've also completed a decent amount from the various sections

[timber fox]

in terms of 'most important' in my experience having knowledge of the general behaviour of functions has proven useful, same can be said for trig identities, hyperbolic functions, all that stuff. but most of my calc 2 , 3 stuff is self taught as we haven't gone over it in the curriculum yet, so I dont know if i'm learning it 'properly' and can't speak for it.

[tardy epoch]

@timber fox what's 1 * 69

[timber fox]

https://tenor.com/view/nice-click-nice-man-guy-gif-21933845

[rotund vector]

.close

[obtuse pebble]

Channel closed

Closed by @rotund vector

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rotund vector]

is my first step to find the discriminant?

[rigid lintel]

yup

[timber fox]

complete square :))))

should get something ^2 > negative

[rotund vector]

okay I got -47

for the discriminant

[timber fox]

interoperate that graphically

if b^2-4ac < 0

[rotund vector]

I don't understand

[timber fox]

what does it mean,

the -47

[rotund vector]

it is the discriminant

[timber fox]

if your discrim is less than 0

[rotund vector]

it means there are no solutions

[versed cave]

Oh that's a nice approach

[timber fox]

no real roots

[rotund vector]

yes

no real roots

[timber fox]

so its gonna be above the x axis..

which is

all

positive

if it touched the x axis or dropped below we would have =0 , >0

[fierce lagoon]

Find the vertex and discriminant

And boom

Or

Actually just find the vertex

[timber fox]

you dont even need to

try completing the square as well, its a fun alternative to finding discrim

[fierce lagoon]

,w 3(-1/6)^2 + (-1/6) + 4

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Umbraleviathan#3607

[fierce lagoon]

Since the vertex's y value is > 0 and the leading coeffient is > 0 boom

[timber fox]

oh true that is also quick

[fierce lagoon]

Funny

[timber fox]

damn

[rotund vector]

yes

[timber fox]

thats 3 ways to solve it in 2 minutes

[fierce lagoon]

-b/2a

[timber fox]

poggers

[rotund vector]

so then how would I answer the question

do I just write a sentence that since the discriminant is negative that must mean there are no real roots

hence it must be above the x-axis

[timber fox]

either with what umbral said with his reasoning, what heavy said with his reasoning, or my proof

[timber fox]

yes this is completely fine

[fierce lagoon]

This is pretty quick though

[timber fox]

so is finding the vertex for y>0 for positive x^2

[fierce lagoon]

Pretty much 2 very quick calculations

If you wanna get fancy

Uhh

[timber fox]

completing square is cool

cus you get a^2 > (-1)b

[rotund vector]

how would I complete the square?

in this case

[timber fox]

uhh here it would beee

,w complete square 3x^2+x+4

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Clarkie#5208

[timber fox]

so you would have

[rotund vector]

damn that looks complex

[timber fox]

(x+1/6)^2 > -47/36

which is obviously true for all x

[fierce lagoon]

Let $f(x) = 3x^2 + x + 4$

$$3 > 0$$
$$\min_{x\in R}f(x) = \frac{47}{12}$$

$$\therefore \forall x \in \bR, f(x) > 0$$

[warm shale]

$e^{\text{Umbraleviathan}}$

[fierce lagoon]

The funny way

The

Funny

Shitpost way

[fierce lagoon]

There are complex numbers for roots lol

[rotund vector]

no I didn't mean that...

[fierce lagoon]

:)))

Ngl just analysis is enough

[fierce lagoon]

Like this

[rotund vector]

what about this?

discriminant: 2^2-4 * p * 4p

is this correct?

[fierce lagoon]

There's a caveat

p < 0

The leading coefficient determines whether the function is concave down or concave up

[rotund vector]

so no real roots?

[fierce lagoon]

Well there cannot be any real roots

But you also need to find what makes the discriminant less than 0

[rotund vector]

but is this working correct?

[fierce lagoon]

p < 0
4 - 16p^2 < 0

Yes

It just also has to satisfy the caveat

[rotund vector]

well should I factorise

cause I know I'll be putting some values on a number line

[fierce lagoon]

Up to you

[rotund vector]

or could I do this 4-16p^2 = 0

add 16p^2 to both sides

then take the square root?

would that work?

@fierce lagoon

[warm shale]

Lex1729

[rotund vector]

<@&286206848099549185>

[obtuse pebble]

@rotund vector Has your question been resolved?

[rotund vector]

.close

[obtuse pebble]

Channel closed

Closed by @rotund vector

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[red spoke]

I am going to need help with the math problem

[dark stirrup]

Do you know your quadratic equation?

[red spoke]

yes I do know the formula

[stable rain]

ok so what do u get after u use it

[red spoke]

x =12 +- square(12^2-4(6)(7) over 2a

[obtuse pebble]

@red spoke Has your question been resolved?

[red spoke]

.close

[obtuse pebble]

Channel closed

Closed by @red spoke

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shut field]

Hi I dont really understand what this symbol means

[icy rose]

2 dimensional space

essentially

[shut field]

Thankss

.close

[obtuse pebble]

Channel closed

Closed by @shut field

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

help

[deft gust]

with what

[timid silo]

I need help tomorrow I have an exam and I need an answer to this question I am confused. Question: "Arwa has $50 in her bank account and saves $25 per week. Her sister has $15 in her account and saves $55 per week. After how many weeks will they both have the same amount of money in their account? How much money will each have? Write a system of equations and solve using substitution."

with this

please

[deft gust]

What have you trid

[timid silo]

I already got the equation

[deft gust]

Okay what is it

[timid silo]

50x+25y=15x+55y

equals

35/30

7/6

for simplify

[deft gust]

The equations should be (m is money and w is weeks)
m = 50 + 25w
m = 15 + 55w

[timid silo]

Yes

I know

but How do I get the amount in their

bank account

[deft gust]

Those equations differ from what you wrote

[timid silo]

I got the weeks

[timid silo]

7/6

[deft gust]

How did you use that equation to get the weeks?

[timid silo]

I basically

50-15

and

55-25

7/6

same as

1.16

or round up

1.2

you wanna see what my teacher got?

[deft gust]

uh

[timid silo]

as the answer

[deft gust]

I know how to get the answer.

[timid silo]

ok

[deft gust]

So the equation 50x+25y = 15x+55y isn't the right equation

First can you tell me what x represnets

[timid silo]

x= whats already in the bank acc

y= Saves every week

[deft gust]

So what did you get for x

[timid silo]

1.2

[deft gust]

Also there hsoulbe a second eqution

because you can't solve for x and y without a second equaiton

[timid silo]

so

[deft gust]

Why are we multiplying 50 and x

[timid silo]

I am not

multiplying

[deft gust]

You wrote 50x

thata means 50 times x

[timid silo]

I mean that x represented 50😭

[deft gust]

That is not how you write an equation

[timid silo]

I am sorry if that confused u

[deft gust]

So you should be writing 50 + 25y = 15 + 55y

?

[timid silo]

oh ok

[deft gust]

Does that make sense

[timid silo]

Yes

Since 50 is not multiplying

We should not add X

[deft gust]

Alright perfect

Do you understand how to get y = 7/6

[timid silo]

Yes

Subtraction

[deft gust]

Just saying "do 50 - 15, and 55 - 25 and then do 35/30" is I would say uncareful logic

Can you explain it in terms of what you do to both sides

It is correct though

[timid silo]

I just subract the amounts saved together

and the amount earned per week together

After that I divide if possible

[deft gust]

It's like you memorized that if a+bx = c+dx, then x = (a - c)/(d - b)

Do you understand what I mean doing things to both sides

I just want to make sure you understand this for the future

[timid silo]

Ye

Yes

I do

[deft gust]

Alright then, we'll continue

So the question is how much moeny they've saved too

Do you know how to calculate that

[timid silo]

Money they saved

No

I dont think so

[deft gust]

The money one of them has got is 15 + 55w

we know w = 7/6

so you just substitute it in

15 + 55(7/6)

Does that make sense

When you solve that, if you were to simplify 50 + 25(7/6) you would get the same thing

[timid silo]

OH

Wait

my teacher got 80 for the money

Like when they got the same amount

@deft gust

[deft gust]

Okay can you show me what your teacher did

[timid silo]

Hmmm

[deft gust]

wait no that's right

[timid silo]

He just posted the answer

[deft gust]

that's about 80

[timid silo]

so ROUNDING UP?

sorry caps

[deft gust]

Yes, looks like it.

[timid silo]

wouldn't that end up as 79

[deft gust]

It is 80 because your teache rounded 7/6 to 1.2, and 50 + 25(1.2) = 80

[timid silo]

oh ok

thx

man

How do I give rating

[deft gust]

.close

!close

,close

type one of those

[obtuse pebble]

@timid silo Has your question been resolved?

Channel closed

Closed by @timid juniper

Use .reopen if this was a mistake.

[timid silo]

.close

!close

.reopen

[obtuse pebble]

✅

[timid silo]

.close

[obtuse pebble]

Channel closed

Closed by @timid juniper

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse pebble]

@fathom kindle Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe violet]

I am once again requesting help

[ripe violet]

so this is the problem

I don't know where they got that 9 from plus I don't know how the site got the numbers that are used to factor

[nocturne minnow]

https://www.youtube.com/watch?v=f6yhfmW41wI&ab_channel=TheOrganicChemistryTutor

That might be useful

[ripe violet]

thank u ama watch it

[ripe violet]

I know now how to do the problem the only thing is that in my screenshot the first question says find n and the video does not explain how to do that

[nocturne minnow]

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:completing-square-quadratics/v/solving-quadratic-equations-by-completing-the-square
This concept too

It was a mix of both videos

[ripe violet]

alr going

[ripe violet]

I got it thank you, you know very useful videos

.close

[obtuse pebble]

Channel closed

Closed by @ripe violet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Anyone know why b and c is wrong?

[daring rock]

Looks like you approximated

Unless it tells you to round, you probably should use exact answers

[static beacon]

C should be from 35 to 30 no?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

yea you're right

thx

.close

[obtuse pebble]

Channel closed

Closed by @quiet folio

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone marlin]

Hi
Is the polynomial $y-x^2$ irreducible over any algebraically closed field?

[warm shale]

Eduardo291299

[timid silo]

Use abstract algebra channel

[obtuse pebble]

@stone marlin Has your question been resolved?

[obtuse pebble]

@stone marlin Has your question been resolved?

[stone marlin]

How?

[timid silo]

Get advanced access

@stone marlin

[obtuse pebble]

@stone marlin Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

does the fact the one on the right has parenthesis change anything ?

[trail musk]

What would it change

[candid moth]

I'd guess it's basically just there to frame the problem as "adding a negative"

Which is of course the same as subtracting a positive, but I'd guess they want to get that point across

$$-\frac{8}{25} + \left(-\frac{17}{20}\right) = -\frac{8}{25} -\frac{17}{20}$$

[warm shale]

Gamma is an Algebraic Number

[timid silo]

ok

[timid silo]

can i add 5 to the denominator and numerator on the left to make them equal ?

or add -5

i mean

.close

[obtuse pebble]

Channel closed

Closed by @barren linden

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

a = .12 * 5000

no

5000 * 12 * 4

divided by 100

so

[royal basin]

12, not 0.12

the division by 100 is to account for the rate being given in percents

[timid silo]

2400

[royal basin]

@cobalt totem this is once again a plug and chug problem

you know that when we put two letters next to each other in algebra it means multiplication, right?

[timid silo]

no to find 12% of 5000 we times 5000 by .12

so 5000 * .12 = 600 * 4 = 2400

[cobalt totem]

i see okay

[royal basin]

bad notation also you're likely just confusing OP here

[cobalt totem]

yesh i am

idk what @timid silo is doing

[timid silo]

but im right

[royal basin]

ok then let's set that side for a moment

@cobalt totem

you know that when we put two letters next to each other in algebra it means multiplication, right?

[cobalt totem]

yes

i do

[royal basin]

right

so then you have your formula

I = P * R * T / 100

can you do part a by plugging in P, R and T with their given values?

[cobalt totem]

5000x12x4 /100

[timid silo]

[royal basin]

5000 * 12 * 4 /100

yes

[cobalt totem]

$2400

right

[timid silo]

[timid silo]

yes

you can also do it my way which is zased

[cobalt totem]

thanks

bye

.close

[obtuse pebble]

Channel closed

Closed by @cobalt totem

Use .reopen if this was a mistake.

[timid silo]

rude

[cobalt totem]

soz

because i need to finish this quickly

[timid silo]

to find 12% of 5000 we times 5000 by .12
so 5000 * .12 = 600 * 4 = 2400

5000 * .12 = 600
(interest paid for one year)
but 4yrs of interest is paid so
600 * 4
=2400

[timid silo]

My brother in christ I gave you the answer before the other person did

[royal basin]

.reopen

[obtuse pebble]

✅

[royal basin]

if y'all wanna keep discussing this

[cobalt totem]

no reopen

.close

[obtuse pebble]

Channel closed

Closed by @cobalt totem

Use .reopen if this was a mistake.

[timid silo]

.

[tardy epoch]

Don't take it personal. Giving the answer doesn't mean they understand it

[cobalt totem]

ann helped me

[timid silo]

i did explain it as well doe

in my first message

[tardy epoch]

The way you understand something is not how everyone else learns. Ann helped Angie before so she had experience

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[snow gull]

How to find the absolute minimum and absolute maximum values of y=x^3-12x on the interval [0,3]?

[snow gull]

I have the answers but Im not sure how to solve it

i know i set it to equal 0 first

and i also know how to find the critical values

which are -2 and 2

nt sure how to solve that in the interval though

[hearty terrace]

i mean the maximum is 0

because from 0 to 3 the equation is always negative or zero

idk if you can use calculus but if you can, then just find the places where the derivative is 0 in the interval

[snow gull]

so i plug in 0 and 3 in the derivative of the equation?

0 --> 0

[hearty terrace]

what is the derivative of the euqation

can you tell me

[snow gull]

3x^2-12

[snow gull]

^ my equation

[long dove]

Sub y'=0 and find value of x

[snow gull]

so like f(0)=insert equation

which would equal 0?

[long dove]

My bad

The derivative of function

[snow gull]

ohh okay thank you

but if i plug in 0 i get 0 and when i plug in 3 i get -9

[hearty terrace]

solve for 3x^2-12=0

that's what we're trying to say

solve for when the derivative is equal to 0

[snow gull]

so idk how the answer is (2, -16)

i understand x value not y

[hearty terrace]

^

[hearty terrace]

when you plug in 2 for your original euqation x^3-12x you get -16 lol

[knotty falcon]

maybe be carefull in other exercices that this will give you max and min value. not only min ^^ (just in case)

[hearty terrace]

do you understand why the minimum/maximum has a derivative of 0 btw

[long dove]

But you need reason why you chose x=2 from infinite option between [0, 3]

[hearty terrace]

yeah it gives you the extrema

it gives possibilities of max/min

[snow gull]

tbh not rly bc ive been lost in every test 😓

[hearty terrace]

because to get from a low point to the maximum and descend again you need to level out

[snow gull]

ik how to solve critical values

ohh okay

[hearty terrace]

the top of every hill is flat (excluding jagged edges)

[snow gull]

to equal the original number?

[hearty terrace]

ok so we want to solve 3x^2-12=0 to find where the derivative is 0

x=2 in this case, and then you want to plug x=2 into your original function to find the mininmum here

[snow gull]

ohhhh

[hearty terrace]

the maximum between [0,3] is just 0 because all other values are negative, so this critical point has to be the minimum (or it could be just a flat part of the graph i suppose but then there'd be another place with derivative 0)

[snow gull]

any tips on understanding ap calc ab? i asked my counelor if i could drop out of this class but she said no unless i fail...

[hearty terrace]

lol im taking it now

so ill leave it to someone more experienced haha

[snow gull]

ahh okauy

also could i get help on one more problem?

[hearty terrace]

send it

[snow gull]

finding the mvt of x=1/3x^3-x on the interval [-3,0]

would i find the derivative first

[hearty terrace]

mvt?

[snow gull]

oh sry

mean value theorem

[hearty terrace]

ah

first calculate the point at x=-3

[snow gull]

so plug in -3 into equation

[hearty terrace]

yeah

then use slope formula between that point and the origin
that's your slope that you wanna find for the MVT
then just take the derivative and then solve for that value

[snow gull]

i got 12

[snow gull]

can u go step by step pls

[knotty falcon]

what do you understand of the "mvt" first ?

[hearty terrace]

it's -6

1/3(-3)^3-(-3)

[snow gull]

oh ya i accidenly wrote a negative wrong

got -6 now

[hearty terrace]

^

[snow gull]

ik the formula 😭 and that i hv to dettermine a point in the interval where the slopes and tan lines are equal

i think theres another line its also equal to i dont remember

[knotty falcon]

whell, I think that's pretty much all you need to know

[snow gull]

i was absent when my teacher taught it so im a bit confused

do i find derivative then plug in values from derivate 'b' and 'a'

or original

[hearty terrace]

find the slope from (0,0) to (-3,-6), and your goal is to find a tangent line on the graph that also has this slope (aka set the derivative to the slope between 0,0 and -3,-6)

[knotty falcon]

basicly, you look for the slope between a and b (so this is the regular slope equation Dy/Dx ) here (y_2 - y_1) / (x_2 - x_1) with 2 being the b point and 1 the a

and then you look for a point in the function that has the same derivative value ^^

(sorry if I miss spell something, I don't have class in english)

[snow gull]

its okay! so kinda like slope formula but you subtract

[knotty falcon]

it is exactly slope formula tho

[hearty terrace]

you subtract in the slope formula as well lol

you don't add

[snow gull]

wait then whats the differnce

[hearty terrace]

wdym? you're trying to find the slope here

[snow gull]

oh

[hearty terrace]

so use the slope formula

[knotty falcon]

here to have the slope you do $$\frac{\Delta y}{\Delta x}$$

[warm shale]

Tonitch

[knotty falcon]

well in the mvt it's the same

[knotty falcon]

and you will basicly have the slope of the bottom line

[snow gull]

oh and in the beginning i plug in the interval values correct?

[knotty falcon]

yes

[snow gull]

okay so for 0 i got 0

and -3 i got -6

[hearty terrace]

oh yeah

sorry

now find that slope

[snow gull]

its okay

[hearty terrace]

i thought you were finding the slope at 0,0 being 0 lol

[snow gull]

and then i use the formula again? so

0-(-6)/0-(-3)?

[knotty falcon]

now that you have the "mean" slope, you have to find a point that have a tan with the same slope

(by definition, the derivative)

[hearty terrace]

=2

[snow gull]

d/dx of original equation is = to 0-(-6)/0-(-3)?

[hearty terrace]

yea

you wanna find the point where the derivative is equal to 2

[knotty falcon]

so you keep 2 for now, you do the derivative of the function you are looking for and then you look for all the value of that derivative that equals your "mean" value (2)

[hearty terrace]

the mean slope is 2

[knotty falcon]

ho sorry

I didn't check

so now you just have to find $$ \partial f(x) = 2$$ you solve the derivative and you have a simple equation to solve basicly

[warm shale]

Tonitch

[hearty terrace]

^

[knotty falcon]

yep basicly that ^^ sorry

[hearty terrace]

no problem, all good

[snow gull]

ohhh