help-10

[serene obsidian]

Not as slow as me

[robust sleet]

U can try guess and error to find a zero value then do synethic division

[serene obsidian]

Alrighty

I’ll figure it out

.close

[obtuse pebble]

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[obtuse pebble]

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[tulip falcon]

hey ! is it possible to isolate the P2 here ? if yes, could I screenshare and have a helper guide me through plz ? thank you

[timid silo]

Oh hi again goat

[sick grail]

Lex got u

[tulip falcon]

EYYY HAHAHHAA how are you ?

[timid silo]

Yeah hop on vc we can walk thru it again haha

[tulip falcon]

Bet bet I’ll get my earbuds lol

[timid silo]

Aye

[wild swallow]

[timid silo]

I miss my emojis..

I am having nitro withdrawals

[wild swallow]

[obtuse pebble]

@tulip falcon Has your question been resolved?

[timid silo]

$c(a-b) = ca - cb$

[warm shale]

♡Lex♡

[timid silo]

$ca-cb = c(a-b)$

[warm shale]

♡Lex♡

[timid silo]

$P_{2}a = b \to P_{2} = \f{b}{a}$

[warm shale]

♡Lex♡

[wild swallow]

lex talking to himself

[timid silo]

,w (4281.98-(1.0125^4 × 4075))/(-1.0125^4 + 1.004125^12)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ♡Lex♡#5050

[timid silo]

:xd:

[tulip falcon]

.close

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[royal basin]

have you made progress thus far?

[somber leaf]

Im in class can u give me answer now pls later ill go home and learn it back

Cause the time the tescher tells teach student i am sick

I am at home that time

So i need answer now pls

[royal basin]

no, we don't give answers here.

[obtuse pebble]

@somber leaf Has your question been resolved?

[obtuse pebble]

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[halcyon stag]

How do I solve this

[halcyon stag]

I guess we can take out the 1/sqrt(n) but I don’t know what to do after that

Guessing we need to get ur as a function of E(Xi)

[royal basin]

@hot dawn this channel is occupied. please open your own channel. read #❓how-to-get-help for instructions

@halcyon stag do you have a screenshot or picture of the original question

[royal basin]

right

well, yeah, expectation is linear

and E[X+c] = E[X]+c

so you can take this all the way to $\frac{1}{\sqrt{n}} \sum_{i=1}^n (2E[X_i] - 1)$

[warm shale]

Ann

[halcyon stag]

How does that evaluate to 0

Since E(Ci)=1/2

[royal basin]

yes

[halcyon stag]

Xi*

[royal basin]

X_i, not C_i

but yes

E[X_i] = 1/2

and what's 2*1/2 - 1

[halcyon stag]

Oh

[royal basin]

exactly

[halcyon stag]

Ok nice thanks

And the variance is the same but the 1/sqrt n becomes 1/n

And we don’t use the -1

[royal basin]

sort of.

[halcyon stag]

Ah yes I got 1

Thanks

.close

[obtuse pebble]

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[ivory trout]

Not really a question, but is there away to avoid doing long polynomial division with this type of integrals?

[ivory trout]

Integrals such as h(x)/f(x) where both h and f are polynomials and h grade is higher than f grade

[royal basin]

well for this problem in particular you may be able to make your own life a bit easier by substituting u := x+a

[ivory trout]

oh, a is a number

b as well

[tardy epoch]

No

[ivory trout]

cause i find it extremely inefficient, that's something a CAS would do

[royal basin]

x^3 + a^3 = (x+a)(x^2 - ax + a^2)

$u := x + a$ turns this integral into $\int \frac{u((u-a)^2 - a(u-a) + a^2)}{u^2 + b^2} \dd{u}$

or $\int \frac{u(u^2 - 2au + a^2 - au - a^2 + a^2)}{u^2 + b^2} \dd{u}$

[warm shale]

Ann

Ann

[royal basin]

[wild swallow]

should be all +a^2

[royal basin]

maybe i fucked up

yeah

[ivory trout]

[royal basin]

that sounds right ish

idt this will take us anywhere

but was worth trying anyway

[ivory trout]

i feel like polynomial division should be like your last resort

its a technique that involves no ability, you just gotta write a lot

[wild swallow]

,w integrate (x^3 + a^3)/((x+a)^2 + b^2)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 夢雪#2250

[wild swallow]

looks like its unavoidable

[zenith raft]

it is last resort

first resort is wolframalpha

second resort is polynomial division

and that's the last

[tardy epoch]

Then get better at it

[obtuse pebble]

@ivory trout Has your question been resolved?

[ivory trout]

well there's also something called

matching coefficients

you end up with a system

[zenith raft]

that's just polynomial division disguised as polynomial multiplication

[ivory trout]

i personally don't know the algorithm of long division, I did it once when i was 13-14 at school and totally forgot it

i much prefer matching coefficient cause rather than memorizing something, I get to solve the problem by thinking

[zenith raft]

it is generally faster than the method you are thinking

well

ig i can say i have it memorized but like

it makes sense?

long division i mean

[obtuse pebble]

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[ivory trout]

.reopen

[obtuse pebble]

✅

[ivory trout]

it doesn't lol

btw I think I found a particular example where matching coefficients doesn't even work

try to do this without long division

[obtuse pebble]

@ivory trout Has your question been resolved?

[obtuse pebble]

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[brave harbor]

Problem with vectors i've been stuck and don't know how to progress.
I will translate the question:
"Let 𝑢⃗ and 𝑣 be vectors such that ∥ 𝑢⃗ ∥= 3, ∥ 𝑣 ∥= 1, and (u ^ v )= 𝜋/ 3 . Determine the magnitude of the angle formed by the vectors 𝑢⃗ + 𝑣 and 𝑢⃗ − 𝑣 . Displays the result in degrees, rounded to the nearest integer."

[brave harbor]

I've done this so far i tried to progress but i can't seem to find the right way to do so

[obtuse pebble]

@brave harbor Has your question been resolved?

[brave harbor]

<@&286206848099549185>

[obtuse pebble]

@brave harbor Has your question been resolved?

[obtuse pebble]

@brave harbor Has your question been resolved?

[lost tree]

u can also like do (a+b)(c+d) = ac + ad + bc + bd

[obtuse pebble]

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[lost tree]

49 = 7^2

[atomic bobcat]

loga((b)= log b/log a

[lost tree]

log a^b = b*log a

[obtuse pebble]

@shrewd trench Has your question been resolved?

[obtuse pebble]

@shrewd trench Has your question been resolved?

[obtuse pebble]

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[hazy root]

How do they get to the = 2?
At AC: 2x -y = 2

[hazy root]

And / or the row below, how to get that 16?

Nevermind I got it.

/close

.close

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[light dagger]

hi can someone help me with this question? i cant find the second value of x. thanks

[loud tangle]

well you know the middle line of a trapezoid is the mean of the bases, therefore it can be written as 7x-6=1/2(36+x^2) so 14x-12 = 36+x^2 => x^2-14x+48=0.
now, solve as you wish: factor or quadratic formula

[light dagger]

thanks

so its (x-8) and (x-6)

so its just 8 and 6

[loud tangle]

yes

good job

[light dagger]

.close

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[little sandal]

I am supposed to find a mistake here but I cant. They dont add up to same but the formula seems alright

[rigid lintel]

$\sum_{k = 0}^n 2^k = 2^{n+1} - 1$

[dense imp]

that step doesn't make any sense, if you were to factor 2^2 out of that sum you would be left with: 2^2(1 + 2^1 + 2^2 + 2^3 + 2^4 + 2^5) not that mysterious subtraction that is written

[spiral knot]

n instead of k in the RHS

[rigid lintel]

time to retire

[warm shale]

Gijs

Mehdi_Moulati

[spiral knot]

so the answer will be correct if you replaced 7 with 6

[little sandal]

I havent undestood this concept yet

[little sandal]

Is it because we start from 2 and not 1 in exponent?

[spiral knot]

which line ?

[little sandal]

This

[warm shale]

Mehdi_Moulati

[spiral knot]

you need to start from k=0 to use this

[little sandal]

Does that apply to this too

That I would have to start from 0 to go with this

[spiral knot]

yes

[little sandal]

okay okay I am starting to understand something

[spiral knot]

depend on the interval of n i guess

[spiral knot]

you didn't understand it ?

[little sandal]

I understood why it is wrong but I am still trying to do it myself

https://cdn.discordapp.com/attachments/903430332324405288/1062395148681625700/394938706760302592.png

What is this formula?

Is it same as the one I had

But looks simpler?

https://cdn.discordapp.com/attachments/903430332324405288/1062399769273696367/image.png

it is not

[spiral knot]

it's

a_1 = 1
q = 2

but n>=1

[little sandal]

I had a misspelling in my calculation in my calculator so I got lost now I understand a lot more

It is the same I belive you now😂

[spiral knot]

the sum of element of a geometric sequence
$$S = u_p + u_{p+1} + ............ + u_n = \sum_{k=p}^n u_k$$
is :
$$S = u_p * \frac{1 - q^{n-p +1}}{1 - q}$$
where $q \ne 1$

[warm shale]

Mehdi_Moulati

[spiral knot]

so in your case

. u_k = 2^k
p = 2
q = 2
n= 7

[little sandal]

got it dude

Now I understand it

Thank you dude

[spiral knot]

anytime bro 😉

[obtuse pebble]

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[thorn badge]

How do I solve question f?

[unreal musk]

,rccw

[obtuse pebble]

@thorn badge Has your question been resolved?

[thorn badge]

.close

[obtuse pebble]

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[covert spoke]

@timid silo for 1, find the north/south and East/west displacement, then use Pythagorean theorem to find the line connecting the two points

Looks like she moved 5 south and 7 east, so you would do sqrt(5^2 + 7^2)

Yes find the length of that diagonal line using Pythagorean theorum

A will be the displacement east, b will be the displacement south, c is the diagonal line

A and b can be switched tho

Doesn’t matter the order

The equation is right but the diagram is wrong, where you wrote 7 should be c, and b should be the 7 units that she moved east

I’m guessing the distance around all bases

Gimme one minute cause I’m walking rn

I’ll help once I’m sitting

Side a and b will both be 85/2. Use Pythagorean theorum to find c and multiply c by 4

[verbal niche]

You know if you rotated it just a bit it would be a square right

@timid silo

[obtuse pebble]

@timid silo Has your question been resolved?

[lost tree]

,rotate

[lost tree]

do u know pythagoras's theorem?

[obtuse pebble]

@timid silo Has your question been resolved?

[verbal niche]

It's the same as your first question

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[obtuse pebble]

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[umbral plume]

can someone do a quick min call with me to help me with imput and function grapis

[umbral plume]

its four problems

please

or i can show you

[tardy epoch]

f(0) is the y-intercept

[obtuse pebble]

@umbral plume Has your question been resolved?

[obtuse pebble]

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[pliant wolf]

hey

[pliant wolf]

i need help

question 13.

[knotty crow]

It doesn't reserve the existence of other roots

so think about conjugate pair

[pliant wolf]

wym

im a little shlow sorry

heres the answer key

im just confused

mind explaining ifykh

[knotty crow]

This is what I've said

We want to get rid of 'i' in the expanded form

[pliant wolf]

ye how

[knotty crow]

notice that it can occur when we would have (a+bi)(a-bi) = a^2 + b^2

this is why they took 2 - i

also

because it's conjugate of (2+i)

[obtuse pebble]

@pliant wolf Has your question been resolved?

[cyan kite]

what does conjugate mean

[pliant wolf]

ye idek

[obtuse pebble]

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[obtuse pebble]

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[timid silo]

hi! how is this solution wrong for

[timid silo]

the solution i did was

3+48/60 x 5

i got 7 miles

[static beacon]

Nearly

But read carefully

He’s travelling for 3 hours at 5 MPH

so that’s 15 miles already

Than add on the (48/69) * 5

[timid silo]

ah okay

tysm

.close

[obtuse pebble]

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[lost tree]

the third side can be expressed using the law of cosines

find an expression for it in terms of an angle, differentiate it

and find its maximum

[warped anvil]

Is there a way to find it with a congruence shortcut like SAS? I have to solve it with high school geometry level knowledge

Not sure if it can be solved with a congruence shortcut like that. Maybe it was a different one like SSS

[lost tree]

i dont know what u mean by a congruence shortcut...theres no other triangle that u can set this congruent to

[timid silo]

If you have a given angle yeah you can find the perimeter with SAS

[warped anvil]

There’s no angle so maybe it’s not supposed to be solved with a congruence shortcut

[warped anvil]

Do you know any other ways of solving it?

[timid silo]

Maybe you can upload a picture of the problem because it doesn't work with only 2 side measurements I think

[warped anvil]

That’s the problem

[timid silo]

Is there no instruction like "Assume all triangles are 30/60/90 or 45/45/90" ?

[warped anvil]

Sadly no

That’s what confused me too

[timid silo]

Oh I'm sorry then I wouldn't know how to proceed either

2 given side measurements might as well be none it doesn't really tell you much

[warped anvil]

It’s alr

Thanks tho

.close

[obtuse pebble]

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[obtuse oracle]

!help

[obtuse pebble]

Please don't occupy multiple help channels.

[obtuse oracle]

!help

[obtuse pebble]

Please read #❓how-to-get-help

[nocturne minnow]

Read #❓how-to-get-help

.close

[obtuse pebble]

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[obtuse oracle]

I need help please?

!help

[obtuse pebble]

Please read #❓how-to-get-help

[unreal musk]

with what

[nocturne minnow]

Then follow this

• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.

[obtuse oracle]

Can u find me a list of decimals and positives?

[unreal musk]

If you have a math question you should ask it in the original post

[nocturne minnow]

Google it

[obtuse oracle]

I’m to lazy.

[unreal musk]

sounds like a you problem then tbh

[obtuse oracle]

Thanks for the help.

https://tenor.com/view/sigh-of-relief-omg-hard-case-oh-my-god-sarcastic-smile-gif-23094385

[nocturne minnow]

But you're not lazy to open two help channels?

[robust sleet]

List of decimals and positives lol

[obtuse oracle]

OK CHILL OUT I

[nocturne minnow]

And have a 5 minute conversation?

[obtuse oracle]

JUST ASKING

[robust sleet]

U can think of many in one second

[daring rock]

You didn't really ask anything that anybody could help you with

[robust sleet]

Do u know what decimals are

[obtuse oracle]

Why is there so many people here.

[nocturne minnow]

Do you know what google is?

[obtuse oracle]

🖕

OH

[grizzled shore]

it's a spelling mistake

[nocturne minnow]

It's a free country

[obtuse oracle]

What?

Where did u get that from.

I was just asking a small question

[obtuse pebble]

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[pliant wolf]

hey

[pliant wolf]

can someone explain how they went from (x+4)(x^3-64) to the bottom part?

[robust sleet]

Factored further

,w (x^3-64) factor

[warm shale]

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[nocturne minnow]

Difference of cubes

[pliant wolf]

how do u factor that tho?

[nocturne minnow]

Difference of cubes

[obtuse pebble]

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[frozen jolt]

Why would the probably of > 0.49 and >= 49 be the same?

For A I got 0.51 and for B I got .52

However the answer key says B is .51

How?

[kindred yarrow]

Can someone help me with question 6 solving in degrees. I know how to solve it by box method, but I wanted to see if I could use the tan(alpha-beta) formula, but it didn’t seem to work. Can someone tell me what I’m doing wrong

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[feral sentinel]

hello could someone help me with this?

for me its way too vague to come up with anything

<@&286206848099549185>

[serene fossil]

ok ill give you the first

the idea is to assume that the statment is true and derive a contradiction

so assume that f(x)+g(y)=xy for all x and y

then try some x and y, say x=1 and y=0, and y=1 and x=0

this gives you f(1)+g(0)=0=f(0)+g(1)

[ruby topaz]

In fact, f(0)+g(y) = 0 for all y and f(x) + g(0) = 0 for all x

[serene fossil]

but then this means that -g(0)=f(1) and -f(0)=g(1), so now try g(1)+f(1) for example. You know it should equal 1 by assumption, but you then have g(1)+f(1)=-f(0)-g(0)=-(f(0)+g(0)) which clearly should be zero

and since 0 doesnt equal -1 you get a contradiction

does this logic make sense to you @feral sentinel

and like pramma said it doesnt have to be 1 you coulda really used any numbers

[ruby topaz]

also it shows that f(x) and g(y) are constant functions, which makes a contradiction pretty easy to derive

[feral sentinel]

Oh sorry i have notifs on

didnt have*

[feral sentinel]

hmm lemme try with this

im trying not to see the solution first

[serene fossil]

ok

[feral sentinel]

got it

thanks

[obtuse pebble]

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[queen mica]

how do i find +c correctly

[queen mica]

I keep getting wrong answers, once i got 4, but i need five

i got y=2x^2-2x^3 + c so far

[plain stag]

now use the fact that the curve passes through (-1,9)

[obtuse pebble]

@queen mica Has your question been resolved?

[timid silo]

plug in values of x = -1 and y = 9 in the equation that you got above
Then solve for C

c will be 5

[queen mica]

OHHH

THanks!

.close

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[meager mantle]

h

[meager mantle]

where the hell does the 27 in the hint come from

[royal basin]

x and y are integers representing the number of coins per string in each case

if you take x coins per string you can make 77 strings with some coins left over, but if you try x+1 coins per string you fall 50 short

i.e. the number of coins is 77(x+1) - 50

it's a little odd that they word it like this though

[meager mantle]

ohhhhhhhhhhhhhhhhhhh

yeah i didnt understand the wording

[royal basin]

i would've gone for 77x - 50 = 78y myself tbh

[meager mantle]

yea i did that too

and the hint is like 77x + 27

i was confused

[timid silo]

Can anyone solve this

[royal basin]

@timid silo channel occupied please move

see #❓how-to-get-help for instructions

[obtuse pebble]

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[steel pasture]

[-0.1, -0.01, -0.001, 0, 0.001, 0.01, 0.1]

[steel pasture]

what's the difference between each number here?

i know the decimal place is moving one place to the right for the first three

so, tens, hundreds, thousands

but what is this decimal representation?

[royal basin]

are you asking this question of your own accord or is this something a problem asks you to answer?

[steel pasture]

I'm making a table:

[dark stirrup]

Ah that gives much more context

[steel pasture]

my x values seem incorrect though

[royal basin]

for what reason do they seem incorrect to you?

and are you asked explicitly to make a table of values like this?

or are you asked to find this limit by any means possible

[steel pasture]

well, here is the question itself:

[steel pasture]

the f(x) value spacing seems off

[royal basin]

off in what way?

brb

[steel pasture]

-12481, -12498, -12450, -12455

the order is incorrect

it should be -12500 or so and then increase

[royal basin]

maybe doublecheck your arithmetic...?

let me desmos this myself

[steel pasture]

it's ok, I couldn't wait and just checked the answer

my initial answer was correct, I shouldn't have changed it

I didn't think the f(x) values could be the same

but they can

kind of "trick" question since I hadn't seen this before

good to know, I guess

ty

.close

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[royal basin]

.reopen

[obtuse pebble]

✅

[royal basin]

@steel pasture here

[steel pasture]

oh wow!

Is that what the problem meant by use a graphing utility to verify your results?

[royal basin]

guess so...? except i only showed the table of values here

[steel pasture]

ok

hmm, I guess that's good to know.

ty for sharing!

can you share the link for that, please?

[royal basin]

http://desmos.com

i did it on the mobile app so no link to the graph itself

but its easy to reproduce

this is the graph

kind of underwhelming but thats what it is

[steel pasture]

ty

.close

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[spiral halo]

Can someone help with this question please I don't even know where to start: Let ∼ and ≡ be two equivalence relations on a set M with m · k elements, where there are exactly m equivalence classes for each of the two relations ∼ and ≡, and each equivalence class always has exactly k elements. Show that there are elements r_1, . . . , r_m ∈ M, which both ∼ and ≡ form a representative system. Note: Hall's marriage theorem may be useful.

[obtuse pebble]

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[tiny rune]

this question is claiming to be a separable differential equations question but im not seeing how to separate it :')

[obtuse pebble]

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[tiny rune]

nvm

.close

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[shy flax]

Hi
Can anyone help me to find x and y in this question ,please?

[icy prism]

hmmm...

generally im not at this level at math but ill try to help you,

[strong sandal]

whats that dot before (u^2

[high lily]

its a multiplication dot

is this the original question?

[strong sandal]

oh thought its something else

[obtuse pebble]

@shy flax Has your question been resolved?

[shy flax]

yes

[woven flame]

try substituting x + y = a and put x^2 + y^2 = (x+y)^2 - 2xy

[obtuse pebble]

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[timber grotto]

what's the formula of distributing vectorial cross product over a cross product a*(b*c)

[obtuse pebble]

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[timber grotto]

am i supposed to close then ?

[versed turret]

I don't think there is one.

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[silver plover]

why is it that in expo hypothesis tests, u flip the equality sign of H1 when calculating the probability?

ie here in H1 its less than

so we calc the prob using greater than

whenever i do hyopthesis tests for anything, i normally use the same equality sign as H1 to calc the prob.

[obtuse pebble]

@silver plover Has your question been resolved?

[silver plover]

charbit

any ideas?

[spiral knot]

come on @unreal musk , ||the world depend on you||

[unreal musk]

Nope, me no goo at hypothesis testing

[spiral knot]

i hate probability

[unreal musk]

With very basic small brain reading of mine

Maybe that?

As to why, I couldn’t even answer that

https://tenor.com/view/empty-brain-loading-gif-20731521

[silver plover]

hmmm

[obtuse pebble]

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[lime wolf]

My teacher today explained that an integral doesn't need a range and it really confused me, could someone clarify it please??

[lime wolf]

How would it work without a range

Like I understand it's an undefinite integral but I don't understand what that is

[dark stirrup]

I'm surprised you didn't learn indefinite first

It's just the solution to an anti derivative

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[livid helm]

Help

[static beacon]

Well that is not the vertex

[obtuse pebble]

@livid helm Has your question been resolved?

[livid helm]

I’m talking about the graph

[static beacon]

Oh

U want help with q10?

[livid helm]

yes pls!!

I’m not sure what I did wrong I believe I solved it properly but I was told I was wrong

This is what I got when I solved it but I was told I was wrong

[static beacon]

Y intercept is 7

YK it has no real roots

[livid helm]

No 😭

[static beacon]

WYM no?

[gusty tartan]

That’s the closest I got 😭

[static beacon]

Found it

Had to brute force it tho

[livid helm]

TYSM

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[tall cedar]

How would a catapult demonstrate Newton’s third law

[obtuse pebble]

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[timid silo]

Sort of struggling with this question that says

"We have distributed two hundred balls into one hundred boxes with the restrictions that no box got more than one hundred balls, and each box got at least one. Prove that it is possible to find some boxes that together contain exactly one hundred balls."

[timid silo]

I thought about it kind of recursively that you would pick the box with the closest number to 100, and then try to find boxes that add to the rest

but I don't know how to formally show that what I described above will terminate

and also I'm not sure if its the right approach to take

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[hazy raft]

please help me answer this

[tardy epoch]

Quotient rule

[bleak eagle]

You know the quotient rule?

[hazy raft]

yes

[bleak eagle]

Okay, try using that formula here and see what you get

[fierce lagoon]

#❓how-to-get-help

[hazy raft]

wat

whats that

[tardy epoch]

Channels occupied. Delete and read #❓how-to-get-help

[fierce lagoon]

Naw dw

Someone just kinda

Plopped their shit here

Just do your quotient rule

[hazy raft]

(d/dx)(y) = (d/dx)((sin(x))/(1-2cos(x))) = (cos(x)(-2sin(x)) - (-2sin(x))(sin(x)))/(1-2cos(x))^2

-2sin^2(x) - 2cos(x)sin(x) / (1-2cos(x))^2

IS IT??

pls

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[noble kindle]

im having trouble understanding what "A contains two entries equal to 1 so that one of them is strictly above and strictly on the right of the other" means

[mental solstice]

i think you should be asking whoever gave you that question

[noble kindle]

like for the n = 3 example that I have there, would "strictly above" refer to the 2,2 entry and "strictly on the right of the other" refer to the 3,3 entry?

[mental solstice]

i don't understand it either, because the usual interpretation doesn't seem to make much sense with the question

[mental solstice]

it might be, but you need to clarify with whoever gave you the question

[noble kindle]

alright

thanks

.close

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[noble kindle]

oh yes, it is

[obtuse pebble]

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[north dove]

how do I get atan2 on the calculator

[loud tangle]

you mean arctan²?

[north dove]

no in C programming language you have atan and atan2 which give different results

https://www.programiz.com/c-programming/library-function/math.h/atan2

I want to be able to do this one on the calculator

[loud tangle]

oh

[north dove]

https://www.programiz.com/c-programming/library-function/math.h/atan

Thats the other one

in R its also atan2

[next reef]

Try in #computing-software

[north dove]

I found this online but uh how do I put it into the calculator?

I have to sum 2 sinusoids

which gives
new A = sqrt((A1 * cos(PHI) + A2 * cos(PHI2))^2 +(A1 *sin(PHI) + A2 * sin(PHI2))^2)
new PHI = atan2((A1 *sin(PHI) + A2 * sin(PHI2) / (A1 * cos(PHI) + A2 * cos(PHI2))

Is there another way to get the new PHI?

[obtuse pebble]

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[obtuse pebble]

@north dove Has your question been resolved?

[trail musk]

What calculator

[obtuse pebble]

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[tame raven]

is drawing the black line the same as drawing line from QD?

so assuming QD and black line both aren't drawn, and I draw black line would i still get same points in contrast to if i draw QD

[thick oracle]

Wdym get the same points

[tame raven]

i did a math comp where i drew the black line

but the markscheme drew QD instead

and i cant figure out if thats the same thing

[thick oracle]

It depends on the nature of the triangle

And what you want to find

Maybe it would help to send the entire problem

[tame raven]

ED and DJ are equal

[thick oracle]

Ok

As i said, the height you draw depends on what the questions wants you to solve

[tame raven]

i wanted to prove ED = EJ

so i drew the black line and said since the height and base are equal, the hypotenuse eqj is equal to edj

[thick oracle]

The height and the base can't be equal

The height it always bigger

I think

Except for right triangles

[tame raven]

i split edj triange into two right triangles : EQJ & EDJ. Then I said, EQJ and EDJ share the same height, and their base is also the same, hence using pythagorean theorem, line EQJ must be = EDJ

[thick oracle]

Triangle EQJ?

Those aren't triangles

[tame raven]

yeah my bad i meant triangles EJ half of JD and ED half of JD

[thick oracle]

Just say the height it ex

Is*

[tame raven]

ilet me draw it out wait a sec

[thick oracle]

Draw only the triangle

If you dont need to other parts of the drawing

[tame raven]

that was my line of argument, but im not sure if its correct

[thick oracle]

Do we need the other parts of the drawing or not

[tame raven]

nah

[thick oracle]

Ok

Nkw

You know

ED=EJ

That's all?

[tame raven]

i wrote it wrong again bruh wait a sec

[thick oracle]

Send the whole exercidr if you can

[thick oracle]

How do you know that X=Y

[obtuse pebble]

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[cosmic gulch]

May I get A Chanel?

[thick oracle]

Yeah

[warped fulcrum]

This is now temporarily your channel. Ask your questions

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[unique spear]

Can anyone give me a simple idea of why radians are better than degrees? I don’t quite understand it.

[polar aspen]

Define radian you might get hint to it

[unique spear]

An angle that is subtended to the centre of the circle where the arc length = radius?

so what’s the use of it? other than just describing this?

[polar aspen]

It has same use that every unit of angle has

Just this definition is universal

And not some arbitary number 360

And degrees is a scale it asumes something, but it does not assume something

[royal basin]

it is more convenient to measure angles in radians for calculus purposes for example

the derivative of sin(x) is cos(x) if you're measuring angles in radians, but in degrees it'd be pi/180 * cos(x) instead

[obtuse pebble]

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[unique spear]

.close

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[unique spear]

thanks

[obtuse pebble]

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[timid silo]

Just a question, do we need to apply PEMDAS on radicals???

[timid silo]

If "PEMDAS" is that rule regarding the oder of arithmetic operations, radicals are treated just like exponents.

[high lily]

the radical operator itself would come under E
stuff under the radical would come under P

[timid silo]

ohh

[high lily]

$\sqrt{a+b}$ can be viewed as $(a+b)^{\frac12}$

[warm shale]

ℝamonov

[timid silo]

So I made an example and I try solving it using Photomath and the answer is 19 but when I answered it the answer was 15

[high lily]

how are you getting 15

also don't be oblivious to the cbrt(2)

handwriting is a bit dodgy, but the work seems ok
16 + 15 - 12 is 19

simplifying properly would get you 19cbrt(2)

[timid silo]

oh I see it lol

sorry XD

Thanks for the help!!!

.close

[obtuse pebble]

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[timid silo]

.reopen

[obtuse pebble]

✅

[timid silo]

oh wait

ok nvm

my brain just need to rest

.close

[obtuse pebble]

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[obtuse pebble]

@wild orbit Has your question been resolved?

[obtuse pebble]

@wild orbit Has your question been resolved?

[rigid pine]

You will not get any help if you just post your question and do nothing else.

[obtuse pebble]

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[civic ocean]

how do i draw a graph based on this information?

[civic ocean]

I am aware that there are three vertices.

i'm stuck on how the edges are defined

[royal basin]

no wonder

what even is that notation? it's horrendous.

you're best off asking your teacher wtf they meant lol

[civic ocean]

Should i write it in english instead

then we can attempt

[royal basin]

write what in english?

[royal basin]

are you saying this isn't the problem statement as originally given to you?

[civic ocean]

it isn't. i don't want to cheat on my assignment

the question asks a different question. i'm trying to draw it out as it gives me a better idea of how i'm working

[royal basin]

what kind of assignment is it?

are you explicitly banned from disclosing the details of your assignment to third parties?

[civic ocean]

No.

[royal basin]

ok then please share the original problem statement.

it sounds like you may have miswritten some notations here, and that's where our confusion is coming from.

[civic ocean]

all the info i'm given

One second i'll send

[civic ocean]

Apologies i misread, it's a screenshot of the original statement

[royal basin]

okay, so then it's not you who's to blame

it's your teacher

$E = { a \in V; b \in V \mid a \neq b \bullet {a, b}}$ is a string of symbols that looks vaguely related to the problem if you squint, but is impossible to actually understand.

[warm shale]

Ann

[royal basin]

there's not really much point in trying to guess at what was meant.

[civic ocean]

ah you haven't been given context as to what the symbols mean?

I asked to draw a graph based on me thinking it would help me draw a graph, although the original question asks the min. and max. degree of the graph

oh god that makes no sense whatsoever

[royal basin]

well ok let me try to ask one thing at a time

what does \bullet mean

[civic ocean]

Still, the bullet point isn't given a meaning

[royal basin]

well, no, it is given meaning as part of this... unorthodox notation for set comprehensions

i have not seen it written that way before

now there's the conflict of notation between the letters a and b as used in this set comprehension and the letters a and b as used for the names of two specific elements of V = {a, b, c}

it is unclear whether the intended meaning is "every pair of distinct vertices is connected" or "only the specific vertices named a and b are connected"

i.e. whether we have a triangle or a lone edge ab and an isolated vertex c

[civic ocean]

So we're on the same page - would it make sense to try and use extension in this case?

[royal basin]

"use extension"?

[royal basin]

eughhhh

[civic ocean]

just an example

[royal basin]

what is this, a "mathematical bureaucracy 101" class?

it sounds like your teacher doesn't want you to do anything graph-theoretic, but instead to wade and struggle through formal notation

[civic ocean]

Not helpful from him

Thanks for your help i'll speak to him

[royal basin]

np

my personal opinion is that notation and formalism are beneficial precisely to the extent that they help make clear the intended message, and no further.

[civic ocean]

it's no bother, it's for the application of computer science so we simply need to understand logical thinking. although it's odd that we both couldn't understand what he's on about

[upbeat plinth]

set this notation ablaze

[civic ocean]

i'll set my lecturer's email on fire

[royal basin]

do that

[civic ocean]

Although is it possible to find the min and max degree from that info?

min. is 0

[royal basin]

that's assuming the intended meaning is "lone edge ab and isolated c"

in which case yeah the minimum degree is 0, which is deg(c)

the values of deg(a) and deg(b) should be obvious

[obtuse pebble]

@civic ocean Has your question been resolved?

[obtuse pebble]

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[verbal finch]

x + 1/x = 3 prove x^2 + 1/x^2 = 7x

QUICK

[fickle turret]

What did you try?

[verbal finch]

nothing, I suck at math

Im in 8th grade and freaking out every day because i dont know shit

ive written it it word to be more concise

[fickle turret]

Is this a test question?

[verbal finch]

yeah, but im not on a test right now

its homework

obv, i dont have a computer in class

[tropic leaf]

Your second equation has x². You could try squaring something to get x²

[fickle turret]

I'd rather multiply the first equation by x and solve the quadratic

[tropic leaf]

I mean, x and 1/x would cancel

so i think squaring is bttere

[obtuse pebble]

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[undone niche]

please could someone check over my working?

im not sure i converted the plane equation from vector to cartesian correctly.

i made the assumption that r is a point in the plane and n is the vector normal to the plane.

<@&286206848099549185>

[dense tinsel]

what the fuck

am i looking at

this is painful to look at

my eyes are burning

and im in 9th grade 💀

[undone niche]

did i do something wrong? lol

[dense tinsel]

idk bro

gpa 3.74

what a disgrace to my family i am

[undone niche]

?

.close

[obtuse pebble]

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[timid silo]

.reopen

rt

[timid silo]

Algebra - Brackets and Equations

need help

[fervent nacelle]

Is this abstract algebra or highschool algebra?

[timid silo]

highschool

[fervent nacelle]

Then ask mate

[tardy epoch]

can you just ask your quesiton

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

No

[obtuse pebble]

@timid silo Has your question been resolved?

[tardy epoch]

come back when you have a question someone can help with. usually a homework problem

.close

[obtuse pebble]

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[obtuse pebble]

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[round ether]

https://pichost.pics/image.php?id=3GSVPH.png

this is my math

[tardy epoch]

delete your message. go troll elsewhere

[robust sleet]

Lol

[tardy epoch]

just screenshot and upload

[robust sleet]

Ain't gonna open it

[tardy epoch]

dafuq

[robust sleet]

Lol

[tardy epoch]

https://www.selecthub.com/resources/how-to-take-a-screenshot/

[robust sleet]

Ain't gonna open that link too

[tardy epoch]

.

[loud tangle]

holy hell

[timid silo]

what is the point of that math

whoever invented advanced maths is a maniac

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[fierce lagoon]

What relationship do CD and BD have with x

[oak night]

Angle?

i didn’t really pay attention to this lesson so i’m lost

[high lily]

look up sohcahtoa

[oak night]

clutch

thanks bro

[obtuse pebble]

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[weak oriole]

For the third problem how would I show my work or is this problem just know it or not from the power of 2

[tardy epoch]

Yes (x-1)^2 is positive for all x not equal to 1

You can say the top stays finite while the bottom goes to 0 from above

[weak oriole]

That makes more sense now ty

.close

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[timid silo]

Is it correct that if two zeros of a quadratic are conjugate does that they always have the form a+/-bi

[civic zealot]

complex conjugate, yes

[timid silo]

ok ty

Followup where can I read about the conjugate imginary numbers properties and uses in algebra?

I have a question thats asking to pick all the correct properties/uses but I don't even remembering learning about them or which class it would be under

[civic zealot]

https://openstax.org/books/college-algebra-2e/pages/2-4-complex-numbers
probably as good a place to start as any

[timid silo]

tysm

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[grim quest]

I’m just revising derivatives and I think I can understand how to use the formulae but I don’t understand why specifically moving the exponent multiplying and subtracting one. Easy enough but can’t seem to connect the dots and find the reason behind this

[grim quest]

I presume dx/dt is the specific point / derivative on the graph

[shut trellis]

are you talking about the power rule?

(x^n)' = (nx^(n-1))

[grim quest]

Yeah I think it’s the same as a f prime

[shut trellis]

https://tutorial.math.lamar.edu/classes/calci/DerivativeProofs.aspx

this has a decent explanation of why it works

[civic zealot]

all the derivative rules come out of the limit definition, some brute force, and sometimes clever substitutions

[grim quest]

Hmm

If I had a integral from 5-10 that’s also a type of limit?

[shut trellis]

integrals can also be written as limits

they are more sums than limits but sorta

[grim quest]

Hmm okay I got more to figure out lol

Thanks

@shut trellis @civic zealot

[shut trellis]

np

[obtuse pebble]

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[lethal gulch]

Question: How do I arrange mixed numbers (Least to greatest) if the 3 whole numbers are the same? I can only solve if only they were 2 same whole numbers and the other isn't.

[obtuse pebble]

@lethal gulch Has your question been resolved?

[lethal gulch]

<@&286206848099549185>

[supple granite]

the first step would be to find the common denominator

have you found that?

[lethal gulch]

I learned the other way, multiplying the two same mixed numbers which they have the same whole number to know which of them are the small and big number. In this case, should I solve it by getting the LCD because they are three same whole numbers?

I learned the other way, multiplying the two same mixed numbers which they have the same whole number to know which of them are the small and big number.
Reference:
https://www.youtube.com/watch?v=9TPnoluWPgE

[obtuse pebble]

@lethal gulch Has your question been resolved?

[royal basin]

@lethal gulch i'm not sure there needs to be a Separate Method™️ that's like, Specifically for Sorting Mixed Numbers™️ and made into a Thing™️ of its own

however, if they're already in 'canonical' form (i.e. the fractional part is less than 1),

then surely you understand that comparing 2 + 3/4, 2 + 5/6 and 2 + 7/9 is the same as comparing 3/4, 5/6 and 7/9 alone?

[lethal gulch]

I guess I'll just use LCD if there's three of them that has the same whole number, thank you for your help!

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[near pier]

Of the 81 members of the local sports club, 45 play football, 21 volley and 15 hockey. At the annual club
meeting, a new managing committee is to be elected. If the 5 members were chosen completely at random, what would be the probability for at least one of each sport. Even my math teacher couldn‘t solve it, so I don‘t have any work to show.

[winter cargo]

whoa :0

hmm

1 min

lemme try

[obtuse pebble]

@near pier Has your question been resolved?

[brave bramble]

I think you can just count:

• The number of committees with no football players
• The number with no volley players
• The number with no hockey players

And that should give the number of committees that don't contain one of each sport, no?

[winter cargo]

unfortunately, i dont think so

then you would include the number of committees without football players AND hockey players twice

[near pier]

yea that was the main problem when trying to solve it, that that doesn't work

[brave bramble]

Ah we are double counting at least the committees with all hockey players

But we're counting those exactly twice, no? So subtract that number out

[winter cargo]

oh wait

1 min

lemme just draw the diag

[brave bramble]

Unless I'm also double counting something else

Which is very possible with these questions lol

[distant moth]

Making a table while considering cases doesnt work?

The denominator is definetly c(81,5) right?

[near pier]

ye

[distant moth]

And wouldnt there be 6 cases to consider?

For numerator

[near pier]

that could work

[distant moth]

Do you have the solution

As in the final answer

[near pier]

Nope

[distant moth]

Would we have to use union?

[brave bramble]

,w C(66,5) + C(60,5) + C(36,5) - C(45,5) - C(21,5) - C(15,5)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
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Requested by Kaynex#7520

[winter cargo]

Say committees without football, volley, and hockey be F, V, and H respectively.
Then total committees without any one = $F ∪ V ∪ H\$
$= F + V + H - (F ∩ V) - (V ∩ H) - (H ∩ F) + (F ∩ V ∩ H)\$
$= \prescript{66}{}C_{5}+\prescript{36}{}C_{5}+\prescript{60}{}C_{5}-\prescript{45}{}C_{5}-\prescript{21}{}C_{5}-\prescript{15}{}C_{5}+0\$
$= 13530321$
So, P(group with at least one player of each sport) = $1-\frac{13530321}{\prescript{81}{}C_{5}}\$
$= \frac{12091275}{25621596}$

[warm shale]

GameSwitch