#help-10

1 messages · Page 102 of 1

dapper wharf
#

Ok

kind hawk
#

otherwise it would be sec(t/2)

dapper wharf
#

Ok ok

#

That gets us (sec^2(t)-1)/4

#

Wouldn’t I be deriving in respect to t now

kind hawk
#

yes you have to get dt now

dapper wharf
#

Ugh tahts gonna be nasty

kind hawk
#

yeah it's really not nice

dapper wharf
#

How do u do it

kind hawk
#

well derivative of sec(t) should still be standard

dapper wharf
#

It’s just cos^-1

#

Derived

#

Uhh idk

#

I don’t remember

kind hawk
#

well then derive it again. chain rule

dapper wharf
#

So uhh tan(t)sec(t)

kind hawk
#

yes

dapper wharf
#

So I derive this basically right

kind hawk
#

yes

dapper wharf
#

Is it (tan(x)sec(x))/2

kind hawk
#

well the x's appeared out of nowhere but ok

#

so du = 1/2*tan(t)sec(t) dt

dapper wharf
#

Yh that

#

So I times that by the sqrt((sec(t)-1)/4

kind hawk
#

dont forget the square

#

sqrt((sec(t)^2-1)/4)

#

now what do we get from the mentioned trig identity from earlier?

dapper wharf
#

ye

kind hawk
#

and now taking the sqrt ?

dapper wharf
#

tan(t)/2

kind hawk
#

ok

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now lets do the bounds

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if u=sec(t)/2 and u=1/2, what is t

#

if u=sec(t)/2 and u=3/2, what is t

dapper wharf
#

put it in cal

#

im sorry but i gtg

#

thx

obtuse pebbleBOT
#

@dapper wharf Has your question been resolved?

obtuse pebbleBOT
#
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void gyro
#

how to do these

obtuse pebbleBOT
dapper wharf
sage geode
#

Express 1/125 as a power of 5 for part a

void gyro
dapper wharf
#

its used as fidning the power of smth

void gyro
void gyro
dapper wharf
#

just do log((base5)(1/125))=n

dapper wharf
void gyro
#

my calculator dont have the word base

#

is that a problem?

dapper wharf
#

lemme show u

void gyro
dapper wharf
#

It’s the small number on the bottom

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Put 5 in there

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The one outside the bracket

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That is called the base number

void gyro
dapper wharf
#

no

void gyro
#

?

#

Which button do i press?

dapper wharf
#

pick the one with a number outside the brakcet

#

its not there

void gyro
#

;-; what do i do

dapper wharf
#

do it on wolfram alpha

void gyro
#

?

dapper wharf
void gyro
#

What if these sort of question pop up on my exam, what do i do?

polar locust
#

can someone pls help me to understand how to solve long division of polynomials:')

void gyro
#

;-;

dapper wharf
#

its ez to just use logs

dapper wharf
#

@kind hawk

void gyro
dapper wharf
void gyro
dapper wharf
#

you learn it in yr 12 but its rllt simple to understand

#

so basically log is a functipn that gives u the power of smth

void gyro
dapper wharf
#

say you got 3^n=9

dapper wharf
#

express 1/125 as a power of 5

#

so we know 1/n=n^-1 right

dapper wharf
dapper wharf
#

125 is also 5^3

void gyro
#

what???

dapper wharf
#

that means 1/125 is 5^-3

void gyro
dapper wharf
#

ahh

void gyro
#

my school suck

dapper wharf
#

oof

void gyro
dapper wharf
dapper wharf
#

and 125 is 5^3

void gyro
dapper wharf
#

no

#

not quote

#

its 1/125

void gyro
#

?

dapper wharf
#

you can express that as 125^-1

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right

#

have u done that before

void gyro
#

no

#

my calculator it said...

dapper wharf
#

okay fine

polar locust
void gyro
dapper wharf
#

bro what

#

thsi is so werid

void gyro
#

I really dont know

#

It can do normal calculation like sohcahtoa and basic stuff

#

Though

dapper wharf
#

wiait i see

#

its put it as a decimal

#

times ur answer by 125 and you should get 1

#

use this calculator

void gyro
#

Yes

dapper wharf
void gyro
#

isnt all of this just have to find the value of N

dapper wharf
#

ye

#

rn its to show u that any number to the power of -1 is the 1/that number

#

so a^-1=1/a

void gyro
#

Whats tp

dapper wharf
dapper wharf
void gyro
#

And whats that?

dapper wharf
#

wdym

dapper wharf
#

so 125^-1=1/125

void gyro
#

Srry i need time to understand

#

Englisj not my 1st language

dapper wharf
#

oh

#

sorry

#

@kind hawk hello? you there?

void gyro
polar locust
dapper wharf
#

remember you have to match the r to the first term, so you gotta find smth that times r to get r^3

#

and then times that number for 3 and subtract the first 2 terms and repeat

polar locust
dapper wharf
#

ok

dapper wharf
polar locust
void gyro
#

...

dapper wharf
obtuse pebbleBOT
#

@void gyro Has your question been resolved?

obtuse pebbleBOT
#

@void gyro Has your question been resolved?

obtuse pebbleBOT
#

@void gyro Has your question been resolved?

obtuse pebbleBOT
#

@void gyro Has your question been resolved?

rustic harbor
#

Guys why are you talking about logs when it's a secondary school type of problem

#

@void gyro

#

You can see that you have a question with a power, so do you know your exponent rules ?

strange belfry
#

to be systematic and exact ig

obtuse pebbleBOT
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royal karma
obtuse pebbleBOT
royal karma
#

g(x) is by substitue
f(x) is by expand

why they are not equal to each other?

royal basin
#

don't these differ by a constant?

#

,w simplify x^8/8 + x^6/2 + 3x^4/4 + x^2/2 - (x^2+1)^4/8

royal basin
#

yeah, they do.

#

@royal karma do not forget the +C.

royal karma
#

oh yea!

#

correct

#

thank you!

#

.close

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crude veldt
obtuse pebbleBOT
crude veldt
#

is it f(2/5(0))

#

so then the point stays the same?

#

or does the new point become (0, 2/5)

rigid lintel
#

exactly

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no

rigid lintel
crude veldt
#

so it is unchanged because it is an invariant point

rigid lintel
#

i wouldnt bring any unnecessary terminology in here

timid silo
crude veldt
#

pre calc 12

timid silo
#

12th grade?

crude veldt
#

yeah

timid silo
#

damn i learned it before break

#

im in 9th

rigid lintel
#

no need to flex

robust sleet
#

I learnt it in pregarden

obtuse pebbleBOT
#

@crude veldt Has your question been resolved?

obtuse pebbleBOT
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jade wedge
#

Why do I keep getting banned from Discord servers?

cedar lichen
#

This isn't a math question

jade wedge
#

Yes it is

strange belfry
#

can see why

cedar lichen
#

This is why you get banned from servers

rigid lintel
#

well somebody kept sending explicit gifs

#

not saying that was you

#

but the timing is suspicious

tardy epoch
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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silver plover
obtuse pebbleBOT
silver plover
#

heres the MS

#

shouldnt the t's be s's no?

#

since U1 correlates to s?

robust sleet
#

(Nested piecewise first time seeing it)

silver plover
obtuse pebbleBOT
#

@silver plover Has your question been resolved?

unreal musk
silver plover
#

this is for u1

#

u1 is s

#

not t

unreal musk
#

Could rename the t's or s's to be whatever you like?

silver plover
#

makes sense to use s

silver plover
#

I thought they were respective

#

Ie

#

U1 is s

unreal musk
# silver plover

I mean, it would be neater, but you could e.g. write that as f(p)

silver plover
#

And u2 is t

unreal musk
#

Yeah imo that's bad form tbh, very naughty

#

To whoever wrote that monkey

silver plover
#

r

#

tragic

#

Btw just doing worksheet questions now

#

I’ve completed the theory for my prob stats course

#

Finished it in like a week

#

Not bad

unreal musk
#

Nice nice, good progress 💪

unreal musk
#

Where's the analysis and algebra at catlove

silver plover
#

Imma do one tmr

#

That chapter is vectors

#

Imma do more calculus revision tho tmr since that exam is on Wednesday

unreal musk
silver plover
#

Ye so vectors and calculus tmr

unreal musk
#

Nice nice, beautiful devilish

silver plover
#

Have u done cardinality proofs before?

#

I find them so hard

unreal musk
#

I have, but some time ago tbh

#

Stuff like prove the naturals and rationals have the same cardinality, prove the reals are uncountable, the power set has a greater cardinality than the set itself?

silver plover
#

U wanna see my mock paper

#

I can DM it to u

unreal musk
#

Ahh fair fair!

#

Ahh let's see how it looks like, it may or may not be nuts I guess catshrug

obtuse pebbleBOT
#

@silver plover Has your question been resolved?

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bronze ferry
#

just to be sure, with this matrix:
2 & 5 & 7
0 & 3 & 4
0 & 0 & 1
the rank of this matrix is 3 because in the pivot position i have all numbers that are not 0?

obtuse pebbleBOT
#

@bronze ferry Has your question been resolved?

bronze ferry
#

haha thx

#

.close

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spice chasm
#

what to do from here

obtuse pebbleBOT
spice chasm
#

i got this far

unreal musk
#

Ouch, where are you getting these questions from monkey

#

,w log(x+1)/log(3) - log(3x+1)/log(5) = log(x-1)/log(7)

spice chasm
#

is there so exact solution

#

no*

spice chasm
unreal musk
#

Not sure, but I don't think it'll be anything trivial to find

unreal musk
hollow kestrel
spice chasm
#

i mean the original question

unreal musk
hollow kestrel
#

ahh ok

spice chasm
#

is there an identity for logarithm sum for like log(a+b)

unreal musk
#

Not really that I know of, closest I know of is series expansion (and that comes with its own limitations)

spice chasm
#

oh ok

#

so like what type of questions of different bases can you solve

unreal musk
#

Let me see if I can spot one for you, let me do some digging through my post history

#

Ah here's one, if you haven't seen it before

#

There was another one but I can't seem to find it sad

#

It was a "solving" one where there were like many steps to it, but I can't seem to get it

obtuse pebbleBOT
#

@spice chasm Has your question been resolved?

spice chasm
#

ty

#

.close

obtuse pebbleBOT
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thorn elbow
#

for a) do i just have to add (x1+x2+x3 , y1+y2+y3) or is there something different i need to do?

dark stirrup
#

yes add them

thorn elbow
#

wouldnt it be just like the resultant but reversed

fierce lagoon
#

Just multiply the resultant by a scalar multiple of -1

thorn elbow
#

yeah i got it thank you

#

.close

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#
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tall tusk
obtuse pebbleBOT
tall tusk
#

can anyone explain the last 3

nocturne minnow
fierce lagoon
#

Parametric I get

true granite
# tall tusk

ok so I get the parametric form, it's the same concept as the standard equation (y=mx+c) but you can change the rate at which the value of x changes as t increases

fierce lagoon
#

If b/a is a vector on the line

#

And parametrics kinda go crazy

true granite
#

the first three are the ones you'll use 99% of the time tbh

fierce lagoon
#

If $\vecb{b, a}$ is a vector on the line, and you have a point, $(x_0, y_0)$, then the line can be parameterized as:

$${x(t), y(t)} = {x_0, y_0} + t{b, a}, t\in\bR$$

warm shaleBOT
#

Umbraleviathan

fierce lagoon
#

If you were to separate the sets and all that funny shit you get what the image has

timid silo
#

for the parametric form, what you are doing is that you are representing a line parallel to some vector v, which will be a scalar multiple of that vector

#

like

#

[
\bold{r} = \bold{r_0} + s\bold{v}
]

warm shaleBOT
#

♡Lex♡

timid silo
#

sorry there ya go

#

but like imagine this

#

bruh'

timid silo
# timid silo

Suppose that $L$ is a line in space passing through a point $P_0(x_0 , y_0 , z_0)$ parallel to vector $\bold{v} = v_1 \bold{i} + v_2 \bold{j} + v_3 \bold_{k}$ then $L$ is the set of all points $P(x,y,z)$ for which $\bold{P_0 P}$ is parallel to $\bold{v}$

warm shaleBOT
#

♡Lex♡
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

timid silo
#

so from that, you can say $\bold{P_0 P} = t\bold{v}$ for some scalar parameter t

warm shaleBOT
#

♡Lex♡

nocturne minnow
true granite
#

I was gonna mention linear algebra

#

but unless you're working with that, you prob won't use it

#

but it's useful to know nonetheless

timid silo
warm shaleBOT
#

♡Lex♡

timid silo
# warm shale **♡Lex♡**

anyways the expanded form of $\bold{P_0 P} = t\bold{v}$ is this:
[
(x- x_0)\bold{i} + (y-y_0)\bold{j} + (z-z_0) \bold{k} = t(v_{1}\bold{i} + v_{2} \bold{j} + v_{3}\bold{k})
]
which you then can rewrite as
[
x\bold{i} + y\bold{j} + z\bold{k} = x_{0} \bold{i} + y_{0}\bold{j} + z_0\bold{k} +t(v_{1}\bold{i} + v_{2}\bold{j} + v_3 \bold{k})
]

warm shaleBOT
#

♡Lex♡

timid silo
#

there ya go i somehow inserted an underscore in there lol

#

basically we need to take r and theta as components, and break them

#

into x and y comp

#

thats it

timid silo
# warm shale **♡Lex♡**

oh and from this you can just say
[
\bold{r(t)} = \bold{r_{0}} + t\bold{v} = \begin{cases} & x_0 + v_{1}t \ & y_0 + v_{2}t \ & z_0 + v_{3}t \end{cases}
]

warm shaleBOT
#

♡Lex♡

timid silo
#

uhhhh

#

its rather graphical.

#

i mean

#

it is meant to be

#

$\arrow{P_0 P}$

warm shaleBOT
#

♡Lex♡

timid silo
#

I just like bolding vectors instead xd

obtuse pebbleBOT
#

@tall tusk Has your question been resolved?

tardy epoch
#

Oh you're boki?

#

Why do you have two discord accounts?

timid silo
#

whats AMC

wise talon
#

american math competition?

#

the indian jee just feels like memorizing equations to me tbh

timid silo
#

would definitely take a lot of prep

#

poor you xd

zenith raft
#

that’s a lot of hours 😭

timid silo
#

LMAO what a gamer you are

#

respect for still playing that tho, thought it died

#

ayo add me on steam 😋

#

good

#

😔

#

honestly yeah games suck the life out of you, i only ever play nowadays if it was with some friends

#

wait i forgot why is this channel open again

#

whats ur question

#

i guess this is fine in 2D?

#

feels odd doe

#

i would suggest doing what i did with the parameterisation of a line since it is more general for 3D as well

obtuse pebbleBOT
#
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timid silo
#

oop

tardy epoch
#

Way to jynx it

timid silo
#

fair enough

obtuse pebbleBOT
#
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timid silo
#

man a lot of chinese speakers here, it makes me jelly

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

timid silo
#

lmfao okay

#

.close

obtuse pebbleBOT
#
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crude veldt
obtuse pebbleBOT
crude veldt
#

im pretty sure a = 1/5, b = 1/4

#

but i just want to confirm a is not 5

wise talon
#

1/5 is an expansion no?

#

,w plot y=x^2 and y=(1/5)x^2

crude veldt
#

its an expansion

#

actually wait

#

idk

wise talon
#

if a is 1/5 then it gets expanded

#

now if a is 5

crude veldt
#

so it should be 5

wise talon
#

,w plot y=x^2 and y=5x^2

crude veldt
#

because its being compressed

wise talon
#

yep

#

poor phrasing by the question ig

crude veldt
#

then horizontal expansion

wise talon
#

it should just say "scale factor 1/5"

crude veldt
#

is 1/4

#

its tryning to trick u up on purpose i think

wise talon
#

thats just poor phrasing tho....

#

well I'll leave that as an exercise for you to figure out

crude veldt
#

¯_(ツ)_/¯

#

thanks

#

also wait

#

theres an even worse phrasing

#

like

#

the last possible answer

#

is correct in its term

#

but has nothing to do with horizontal reflection

wise talon
#

yeah these phrasings are terrible

crude veldt
#

oh rip

#

it was the original answer

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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modern linden
#

Why is derivative of x^2 equal to 2x? Because (x+1)^2 - x^2 equals 2x + 1 and difference in y between x 3 and 4 equals not 6, but 7

fierce lagoon
#

The limit definition

strange belfry
#

because derivative isn't the slope that's defined by the secant line going from f(x+1) and f(x)

fierce lagoon
#

It's the slope of the tangent line for some x

#

So you're gonna have to calculate this limit:

$$\lim_{h\to 0}\frac{(x+h)^2 - x^2}{h}$$

warm shaleBOT
#

Umbraleviathan

fierce lagoon
strange belfry
#

basically like calculating the slope of a "linear line" but the difference between the considered x values tends to 0 where as it would be a constant that is bigger than zero otherwise

modern linden
modern linden
fierce lagoon
#

You can't say it's 0/0

strange belfry
#

kinda

fierce lagoon
#

You need to do some manipulation

strange belfry
#

but it is actually defined

#

rather it tends to 0/0

#

at a first glance

modern linden
#

So I need to know limits first?

fierce lagoon
#

Start with expanding (x+h)^2

#

Oh yeah ofc

wise talon
#

h is not actually 0 btw

fierce lagoon
#

Learn limits first lol

wise talon
#

if you use the eps-delta definition

fierce lagoon
#

$$\begin{align*}
\lim_{h\to 0}\frac{(x+h)^2 - x^2}{h} &= \lim_{h\to 0}\frac{\parens{x^2 + 2hx + h^2} - x^2}{h} \
&= \lim_{h\to 0}\frac{2xh + h^2}{h} \
&= \lim_{h\to 0}\parens{2x + h} \
&= 2x
\end{align*}$$

warm shaleBOT
#

Umbraleviathan
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

modern linden
#

but h isn't 0

wise talon
#

yup

#

but its the limit

fierce lagoon
#

Eh yeah, h just approaches 0

#

If you use the stupid epsilon delta thing (that I totally remember how to do trol) you'll find it ain't actually 0

wise talon
#

for all eps > 0 there exists a delta > 0 such that when

fierce lagoon
#

That I know because I tried fighting my teacher about this for Calc BC and he whips out the good old eps delta shit

wise talon
#

0 < |x-h| < delta

#

|f(x)-L|< eps

#

where L is the limit

fierce lagoon
#

Then h can't be 0

wise talon
#

yup

modern linden
fierce lagoon
#

But it approaches 0

#

Because of funky limit

wise talon
#

rather you can pick any x within

#

(h-delta, h+delta)

#

for any eps > 0

modern linden
#

So you wanna say derivative simply ignores the h because it's too small on small scale?

wise talon
#

well

#

not really

#

but you can somewhat think of it like that

modern linden
#

Then it doesn't ignore it?

wise talon
#

I'm afraid I might be confusing you

modern linden
#

I'd like to have the correct comprehension actually

wise talon
#

You're going to need real analysis

modern linden
#

But you throw some latin letters at me

wise talon
#

firstly, it's greek

#

and secondly that's the definition

modern linden
#

Even worse

wise talon
#

the idea of a limit is basically

#

let's say lim (x->c) f(x) = L

strange belfry
#

I don't think consepts like epsilon-delta definition or real analysis is needed for first getting the idea of a limit

wise talon
#

the closer you get to L you can always pick some x to plug into f(x)

modern linden
#

So the definition of derivative is bound to limits? Basically built on them?

wise talon
#

yeah

strange belfry
#

understanding the consept of approaching would help better if you're new

wise talon
#

or rather not pick some x

modern linden
#

Thank you

#

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#
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near jacinth
#

Can anyone cross check these answers for me? I have no help and I don’t have a solution manual to check the answers, any help would be appreciated. Thanks in advance

wise talon
#

15 is slightly wrong

#

specifically for x->0+ f(x) =2

unreal musk
#

16 should have a hollow hole in it at (0, 1), and also what happened with the “middle discontinuity”? While you can have it don’t see why you chose to, but if you do, make sure you put hollow holes at the end of the “pieces”

#

(Otherwise you could be seen to be implying your function is such that f(0)=1 and f(0)= -1)

#

Similar with 17 and (-2,2) being hollow

#

18 is cool with me, at least the idea

obtuse pebbleBOT
#

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#

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meager aspen
#

Can someone help with this integral

obtuse pebbleBOT
timid silo
#

alright

#

what did u try

#

@meager aspen

meager aspen
#

I tried integtating it by thinking x^2 as a constant, integrated and got -e^(x^2/y)/x^2 but when i differentiated it again i didn't get the same thing

timid silo
#

that wont have an elementary antiderivative i believe

#

can you approximate it? maybe with gamma functions

meager aspen
#

Maybe i wrote the question wrong from the board

timid silo
#

i don't see how it will even converge in the state it is in too

meager aspen
timid silo
#

,w int_0^inf int_x^inf e^(x^2/y)dydx

timid silo
#

,w does int_0^inf int_x^inf e^(x^2/y)dydx converge

meager aspen
#

, w integrate e^(x^2/y)dy

warm shaleBOT
timid silo
#

,w convergence int_0^inf int_x^inf e^(x^2/y)dydx

warm shaleBOT
trail cloak
#

,w evaluate integral from 0 to infinity (integral from x to infinity of e^{{x^2}/y} dy)dx

timid silo
#

okay whatever, no matter what u will get you definitely are not figuring it out with elementary functions

meager aspen
#

Yeah

meager aspen
#

Thanks for the help you two, really appreciate it

timid silo
#

yeah like i thought

timid silo
#

anytime!

trail cloak
obtuse pebbleBOT
#

@meager aspen Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
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radiant briar
#

I have to justify these interphases with a drop-down choice. The intention is to lead the formula for integration by parts.

I can't get it correct, need a little help here...

The options are (roughly translated to english)

  • Product rule formula
  • integrate both sides
  • subtract the same term from both sides
  • quotient rule
  • product integration rule
  • int (h(x))dx = h(x) + C
  • D(int(h(x)dx))=h(x)

As it stands, I have no use for the quotient rule, the formula where the + C is used as it's useless here, subtraction of the same term from both sides as it doesn't seem to happen here, product integration rule as such a thing does not exist. Am I correct? I have no idea if the same answer can be used twice. But I've played around with different answers and none of them are correct. IMO the correct answer is
product rule formula,
product rule formula,
integrate both sides,
integrate both sides.

radiant briar
obtuse pebbleBOT
#

@radiant briar Has your question been resolved?

obtuse pebbleBOT
#

@radiant briar Has your question been resolved?

timid silo
radiant briar
#

yes

obtuse pebbleBOT
#

@radiant briar Has your question been resolved?

strange belfry
# radiant briar

I think integration by parts is what you're looking for, seems like you had almost derived the formula

radiant briar
#

nope

#

I have to justify integration by parts by leading the formula with dropdown choices from the menu above

junior needle
#

WHAT IS 1+1

obtuse pebbleBOT
#

@radiant briar Has your question been resolved?

turbid wing
#

oh okay you have stated the problem above sorry. lemme see

turbid wing
# radiant briar

Product rule formula
subtract the same term from both sides
integrate both sides

obtuse pebbleBOT
#

@radiant briar Has your question been resolved?

radiant briar
obtuse pebbleBOT
#

@radiant briar Has your question been resolved?

tight oasis
tight oasis
radiant briar
#

4 boxes to select, what is the correct order of answers, imo it is [mentioned above], but it's not. 🤷

tight oasis
#

OH I'm blind af sorry

radiant briar
#

I hid them as theyre not in english haha

tight oasis
#

What is your langage?

radiant briar
#

Finnish

tight oasis
tight oasis
# radiant briar I have to justify these interphases with a drop-down choice. The intention is to...

So your first guess is right: we use the product rule formula i.e. that D(fg)=Df.g+f.Dg
Your second guess is wrong, try to with about what happened between the first and the second line, how is the equivalence derived?
Your third guess is also correct: we simply integrate both sides resulting in the integral symbol appearing (and appearing twice on the right hand side by linearity)
Your last guess is also wrong, we are not integrating both sides in the last step. We are using another identity between the third and fourth line

radiant briar
#

Thanks, got it correct now!

tight oasis
#

perfect, you can .close

#

@mild rune If you're done, just type .close

radiant briar
#

.close

obtuse pebbleBOT
#
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autumn charm
#

it's a geometry question, I'd love if someone who speaks French could help me because the my notes are in French, my question is: what's the difference between 'vecteur colineaire/non colineaire/coplanaire, the lesson name is 'Droites et Plans de l'espace'

royal basin
#

.close

obtuse pebbleBOT
#
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royal basin
#

oh

#

.reopen

obtuse pebbleBOT
#

autumn charm
#

lol

royal basin
#

(was gonna close this channel bc i saw you typing in the other one)

#

anyway

#

on ne dit jamais d'un SEUL "vecteur (non) colinéaire" ou d'un SEUL "vecteur coplanaire"

#

la colinéarité et la coplanarité sont des propriétés qui peuvent être possédées par les ENSEMBLES d'au moins 2 (pour la colinéarité) ou 3 (pour la coplanarité) vecteurs

#

on dit qu'une couple de vecteurs {v, w} est colinéaire, ou alors que v et w sont colinéaires, s'il existe une constante réelle α non nulle telle que v = αw

autumn charm
#

sorry interrupt, but I also got another question, I don't really understand the concept of 'vecteur directeur/normale'

royal basin
#

tu sais imaginer les vecteurs comme des petites flèches avec une longueur et une direction fixes mais sans position fixe, oui ?

royal basin
#

au sens géométrique une couple de vecteurs est colinéaire si leurs directions sont les mêmes ou directement opposées

#

(si le scalaire est négatif)

autumn charm
#

okay makes sense

#

mais pour la colineairite, sur ce cours en ligne le prof a donné ca

#

é

#

mais au classe

royal basin
#

ah, c'est en termes de coordonnées hein

autumn charm
#

le prof a donné une autre proprietee

#

a/a' = b/b' = c/c'

royal basin
#

moi, j'essaie de donner une perspective plus visuelle

autumn charm
#

ah okay

royal basin
autumn charm
#

sorry if im being a pain, im not really good at maths and am trying to become better

royal basin
#

pour la coplanarité c'est un peu plus compliqué à mettre en symboles et de comprendre la relation entre ces derniers et la géométrie, mais:

on dit qu'un trio de vecteurs {u, v, w} est coplanaire, ou alors que u, v et w sont coplanaires, s'il existe un trio de scalaires (α, β, γ) ≠ (0, 0, 0) tel que αu + βv + γw = 0

#

au sens géométrique ça signifie qu'il existe un plan qui est parallèle à la fois à tous les trois

royal basin
#

et un vectur normale pour un plan, c'est un vecteur qui est à un angle de 90° avec tout vecteur dans le plan

autumn charm
#

thank you so much Ann

#

have a good day/night

royal basin
#

yw

tardy epoch
#

TIL Ann speaks french

royal basin
autumn charm
tardy epoch
#

don't think so, probably because we're in such different time zones. not many french questions. the usual helpers i've seen speak french are herels and mateo

autumn charm
#

sorry Rie, I gotta close this one, have a nice day mate

#

.close

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#
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jovial karma
#

might be simple question, but in (r,theta) how did we get r here after finding the theta?

jovial karma
#

a little confused because I'm doing multivar calc but my calc 1 and 2 didnt cover polar

tardy epoch
#

polar coordinates is a high school trig / pre-calc topic

jovial karma
#

I didn't take pre-calc or highschool trig 😦

tardy epoch
#

good time to learn

#

pre-calc probably is a pre-requisite for calculus

jovial karma
#

oh I get it now LOL

#

thank you!

#

that textbook is much nicer

#

@tardy epoch catlove

#

.close

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wooden sedge
obtuse pebbleBOT
sage geode
#

Clearly B, no?

thick oracle
#

You know when a line intersects a plane when the dotted line turns into a straight line

wooden sedge
#

sorry, why B and not C for example?

#

oh. thank you both

#

.close

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#
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thick oracle
#

Np

obtuse pebbleBOT
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uneven night
obtuse pebbleBOT
uneven night
#

i have to use maclauren but i dont know how to complete it

spiral knot
#

use the first two terms

uneven night
spiral knot
warm shaleBOT
#

Mehdi_Moulati

obtuse pebbleBOT
#

@uneven night Has your question been resolved?

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timid silo
#

please help me derivate that

obtuse pebbleBOT
timid silo
#

in order to get the f'

tardy epoch
#

do you know quotient and chain rule

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

i think i'll use (u/v)' and (√u)'

tardy epoch
#

sounds good

obtuse pebbleBOT
#

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@timid silo Has your question been resolved?

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turbid kettle
#

Is there a way to stop a ti-84 from referencing previous solutions? I tried resetting the ram and data.

turbid kettle
#

Should I just manually delete the Ans everytime

#

It only recently started doing this

vestal thorn
#

like if you do 2+2

#

then you start your next one with +3

#

it will display ans+3

vestal thorn
#

the negative is under the 3

turbid kettle
#

Oops

#

That was the problem yeah

#

Thank you

vestal thorn
#

🙏

turbid kettle
#

😅

#

.close

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#
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silver plover
#

hello

obtuse pebbleBOT
silver plover
#

how do u know what brackets the A B and C multiply with?

tardy epoch
spiral knot
#

to remove the fraction

spiral knot
#

$\frac{x}{(x-1)(x-2)(x-3)} * (x-1)(x-2)(x-3) = \qty(\frac{A}{x-1} + \frac{B}{x-2} + \frac{C}{x - 3} ) * (x-1)(x-2)(x-3)$

warm shaleBOT
#

Mehdi_Moulati

silver plover
#

i see

#

so basically

#

whatever the denomintaor is

#

multiply A B and C by all the other brackets

#

disregarding that denomintor

#

if that makes sense?

#

so denominator of A is x-1

#

so itll be A(x-2)(x-3)?

spiral knot
silver plover
#

since theyre the other brackets

#

ok

#

thx

spiral knot
silver plover
#

.close

obtuse pebbleBOT
#
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spiral knot
silver plover
#

sigh

spiral knot
#

you have an exam Wednesday , Right ?

obtuse pebbleBOT
#
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silver plover
obtuse pebbleBOT
silver plover
spiral knot
silver plover
spiral knot
silver plover
#

how did they get

#

from top

#

to bottom

spiral knot
#

sec²(x/2) = 1 + tan(x/2)²

#

i believe

silver plover
#

yh

#

wait

vestal thorn
#

looks like they defined tan(x/2) to be t

silver plover
#

no

#

sry

#

sry

#

this part i dont get

#

how they get from top to bottom

#

here

spiral knot
#

sin(x/2) = tan(x/2)cos(x/2)

silver plover
#

mhm

vestal thorn
#

!help

obtuse pebbleBOT
vestal thorn
#

bruh

silver plover
#

i see

warm shaleBOT
#

Mehdi_Moulati

silver plover
#

makes sense

#

cheers mehdi

spiral knot
obtuse pebbleBOT
#

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#
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astral magnet
obtuse pebbleBOT
astral magnet
#

I have to solve for half life

#

I'm completely clueless

brave bramble
#

When t = 98, what is A(t)?

#

(I suggest using the half life equation for half-life questions)

astral magnet
#

I have no clue

#

i have a(t)=ao(1/2)^98/h

#

i believe i have to solve for h since half life

brave bramble
#

A(t) represents the amount present at time t

astral magnet
#

yes

brave bramble
#

When t = 98, A(t) = 0.75A0

#

A(98) = 0.75A0, in other words

astral magnet
#

im kinda confused cuz the question doesnt provide an Ao

#

😳

brave bramble
#

That's okay. It will divide out

astral magnet
#

and also if the exponent is t/h

#

im not sure man the resource says half life solving requires finding h

brave bramble
#

It does. You'll need to grab h.

#

In order to do that, you'll need to correctly use the information present in the question, such as when t = 98, A(t) = 0.75A0

astral magnet
#

oh holy shit

#

wait

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when it says decay to 25% of its original amount

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does that mean the remaining is 25 percent of the orinal amount

#

or is it a 25 percent decrease

#

nvm

#

idk im so puzzled

#

im told to assume 100mg sample

obtuse pebbleBOT
#

@astral magnet Has your question been resolved?

brave bramble
#

25% of the original amount disappears

#

Good start! You'll need logs to continue

#

@astral magnet

obtuse pebbleBOT
#

@astral magnet Has your question been resolved?

obtuse pebbleBOT
#
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timid silo
#

i gotta find the equation of a cos funtion with the points (4,72) and (24,56)

timid silo
#

i think i did it right

#

but when i put it into

#

desmos

#

it doesnt make sense

vestal thorn
#

Show your work, and if possible, explain where you are stuck.

timid silo
#

so first i did

#

to find the middle

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/ the

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c value

#

sorry 72+56/2

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which i got 64

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so thats my c value

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then i did

#

72-56/2

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to find the amp

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which is also the a value

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which i got

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8

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then i did 44-4

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to find

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the period

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which is 40

#

then did

#

360/40

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and i got 9

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as my

#

k value

#

so i chose a cos funtuon

#

cause

#

im starting at the top

#

so my final thing was

#

f(x)=8cos(9(x-4))+64

#

what did i do wrong

bold bane
#

Were there other givens? There are four unknown values so you would need at least four data points to determine their exact values.

timid silo
#

no you only get 2 points

#

the max

#

and the min

bold bane
#

No amplitude or center line?

timid silo
#

well u can just find that ur self

#

by doing

#

the max

bold bane
#

No, you can't.

timid silo
#

the min

#

/2

#

to find

bold bane
#

Oh, those points are max and mins?

timid silo
#

(4,72) is the max

#

and

#

(24,56)

#

is the min

bold bane
#

You should be able to figure out P and H from this.

timid silo
#

p is 9

#

adn

#

h is 4

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f(x)=8cos(9(x-4))+64

#

thats what i got

#

x-4

#

cause

#

the first point

#

is

#

(4,72)

#

so it woukd be -4

#

cause like it dont start at 0

#

thw p val

#

is like

#

360/ the period

#

the period

#

is 40

#

so the p val

#

is 9

#

@bold bane

bold bane
#

Sorry, was solving the problem.

#

So the period and horizontal values you found are incorrect.

timid silo
#

why tho

bold bane
#

One moment. Let me go through what your wrote.

#

Oops, I wrote something down wrong and got an incorrect answer.

#

Give me a moment to fix it.

#

Ok, fixed.

bold bane
timid silo
#

how

bold bane
#

This is what I did to make an equation for P.

timid silo
#

is the period

#

not just

#

one full cycle

#

like

#

max to max

bold bane
#

Yes.

timid silo
#

ill show u

#

a graph

#

i made

bold bane
#

I see what you are talking about.

timid silo
bold bane
#

So you have half of the period which was 20 which means the total period is B=40 which means that P=2pi/40, or pi/20.

timid silo
#

why pi tho

#

i was taught that

#

k=360/period

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or ih

#

ig

#

op

#

p

#

in this case

#

so

#

p=360/period

bold bane
#

360 is 2pi.

timid silo
#

oh shit

#

okay

#

yeah so i got 9

bold bane
#

$P = \frac{2\pi}{40} = \frac{\pi}{20}$

warm shaleBOT
#

Kookiemon

timid silo
#

its 9 tho

bold bane
timid silo
#

whats the

#

equation

#

u put in

bold bane
#

You have the period now. You can enter the equation yourself now. It appears everything else you have is correct.

timid silo
#

so its

#

f(x)=8cos(9(x-4))+64

bold bane
#

The period is not 9.

timid silo
#

360/40

bold bane
#

You cannot use degrees.

#

$\frac{360^\circ}{40} \ne \frac{2\pi}{40}$

warm shaleBOT
#

Kookiemon

timid silo
#

but u said

bold bane
#

Degrees are a measure of rotation while radians are a measure of length.

timid silo
#

#

is 360

bold bane
#

My apologies for confusing you.

timid silo
bold bane
#

But you do not use degrees when solving this type of equation, you should always use radians.

timid silo
#

so 2π/40

bold bane
#

Yes.

timid silo
#

okay got it

#

so

#

#

is the same

#

as 360

#

but

#

u have to use

#

bold bane
#

Yes.

timid silo
#

in the equation

bold bane
#

Correct.

timid silo
#

and π

#

is just

#

180

bold bane
#

Pi is equivalent to 180 degrees, but it has an actual value on the Unit Circle of 3.1415...

timid silo
#

yeah

#

okay thank u

bold bane
#

yw

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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serene obsidian
#

Regarding expanding logs

obtuse pebbleBOT
sage geode
#

And what's the question?

serene obsidian
#

One sec let me get the pic

#

This is from the answer key and I’m confused here

sage geode
#

What's confusing you?

serene obsidian
#

log_3(x+2) I am a bit rusty in my algebra so I don’t know what step I’m missing here

sage geode
#

Probably a typo, it's supposed to be x + 12

serene obsidian
#

See that’s what I thought

#

I do have another one that I am also stuck on

unreal musk
#

[if you're still stuck of course]

serene obsidian
#

oh this is an answer key

serene obsidian
robust sleet
#

They factorization it

#

Factoriwed

#

Factorized

serene obsidian
#

Yea I get the factorization but where did 2u come from?

unreal musk
serene obsidian
#

That’s the part where I’m confused on

unreal musk
#

This 2u?

serene obsidian
#

Ye

unreal musk
#

,w expand (u-2)(u^2 + 2u + 4)

unreal musk
#

Also I'm surprised they stopped there tbh

#

,w expand (u+2)^2

robust sleet
#

Lol

unreal musk
#

Oh that's why, I'm being slow KEK

#

Big brain time over broke