#help-10
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otherwise it would be sec(t/2)
yes you have to get dt now
Ugh tahts gonna be nasty
yeah it's really not nice
How do u do it
well derivative of sec(t) should still be standard
well then derive it again. chain rule
So uhh tan(t)sec(t)
yes
So I derive this basically right
yes
Is it (tan(x)sec(x))/2
dont forget the square
sqrt((sec(t)^2-1)/4)
now what do we get from the mentioned trig identity from earlier?
ye
its tan^2
and now taking the sqrt ?
tan(t)/2
ok
now lets do the bounds
if u=sec(t)/2 and u=1/2, what is t
if u=sec(t)/2 and u=3/2, what is t
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how to do these
use log
Express 1/125 as a power of 5 for part a
what is that
its used as fidning the power of smth
i dont understand what you saying
i think my school never teach me that
just do log((base5)(1/125))=n
its rlly simple
ok thank you
It’s the small number on the bottom
Put 5 in there
The one outside the bracket
That is called the base number
no
;-; what do i do
do it on wolfram alpha
?
What if these sort of question pop up on my exam, what do i do?
can someone pls help me to understand how to solve long division of polynomials:')
sorry what is that
In 10 min
;-;
lets see ur question
what year r u in
its ez to just use logs
year 10
same
im braindead in math
you learn it in yr 12 but its rllt simple to understand
so basically log is a functipn that gives u the power of smth
i got igcse test in the next 2 days
r there other way?
say you got 3^n=9
yes
express 1/125 as a power of 5
so we know 1/n=n^-1 right
thats supoosed to be in yr11
what???
that means 1/125 is 5^-3
i got early
ahh
my school suck
oof
1/125 is 5^n
what u confused on
n is 3?
?
okay fine
(r^3+4r^2+r-10)÷(r+3) and (2v^-3v^2+4v+5)÷(18+2v^2+7v)
I really dont know
It can do normal calculation like sohcahtoa and basic stuff
Though
wiait i see
its put it as a decimal
times ur answer by 125 and you should get 1
use this calculator
Yes
match the r in the r+3 to every term. so itll be smth liek this
isnt all of this just have to find the value of N
ye
rn its to show u that any number to the power of -1 is the 1/that number
so a^-1=1/a
Whats tp
u sure u typed it right
to sorry typo
And whats that?
wdym
This example means any number, if we put ^-1 on it. Means that the result will be the same as 1/original number?
that should be -3v^2 ;-;
yes
what about the r bit
remember you have to match the r to the first term, so you gotta find smth that times r to get r^3
and then times that number for 3 and subtract the first 2 terms and repeat
yes i typed it right
ok
sorry but igtg rn
thats fine, take care
...
thx
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@void gyro Has your question been resolved?
@void gyro Has your question been resolved?
Guys why are you talking about logs when it's a secondary school type of problem

@void gyro
You can see that you have a question with a power, so do you know your exponent rules ?
to be systematic and exact ig
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don't these differ by a constant?
,w simplify x^8/8 + x^6/2 + 3x^4/4 + x^2/2 - (x^2+1)^4/8
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is it f(2/5(0))
so then the point stays the same?
or does the new point become (0, 2/5)
you had it right here
so it is unchanged because it is an invariant point
i wouldnt bring any unnecessary terminology in here
what grade it is?
pre calc 12
12th grade?
yeah
no need to flex
I learnt it in pregarden
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Why do I keep getting banned from Discord servers?
This isn't a math question
Yes it is
can see why
This is why you get banned from servers
well somebody kept sending explicit gifs
not saying that was you
but the timing is suspicious
.close
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(Nested piecewise first time seeing it)
?
@silver plover Has your question been resolved?
Variable names, doesn't matter(?)
ik but
this is for u1
u1 is s
not t
Could rename the t's or s's to be whatever you like?
makes sense to use s
oh i see
I thought they were respective
Ie
U1 is s
I mean, it would be neater, but you could e.g. write that as f(p)
And u2 is t
True
my uni LNs
r
tragic
Btw just doing worksheet questions now
I’ve completed the theory for my prob stats course
Finished it in like a week
Not bad
Nice nice, good progress 💪
Algebra two chapters left
Imma do one tmr
That chapter is vectors
Imma do more calculus revision tho tmr since that exam is on Wednesday
I'll be preeing tomorrow then 
Calculus 
Ye so vectors and calculus tmr
Nice nice, beautiful 
I have, but some time ago tbh
Stuff like prove the naturals and rationals have the same cardinality, prove the reals are uncountable, the power set has a greater cardinality than the set itself?
ye that
U wanna see my mock paper
I can DM it to u
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just to be sure, with this matrix:
2 & 5 & 7
0 & 3 & 4
0 & 0 & 1
the rank of this matrix is 3 because in the pivot position i have all numbers that are not 0?
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Yes
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what to do from here
i got this far
Ouch, where are you getting these questions from 
,w log(x+1)/log(3) - log(3x+1)/log(5) = log(x-1)/log(7)
i just made it up cuz idk how to solve logs with different bases
Not sure, but I don't think it'll be anything trivial to find
Ahhh I get you, fair dos then, well that one is pretty tough imo
those all have the same base
i mean the original question
ahh ok
is there an identity for logarithm sum for like log(a+b)
Not really that I know of, closest I know of is series expansion (and that comes with its own limitations)
Let me see if I can spot one for you, let me do some digging through my post history
Ah here's one, if you haven't seen it before
There was another one but I can't seem to find it 
It was a "solving" one where there were like many steps to it, but I can't seem to get it
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for a) do i just have to add (x1+x2+x3 , y1+y2+y3) or is there something different i need to do?
yes add them
whats the equilibrant??
wouldnt it be just like the resultant but reversed
Just multiply the resultant by a scalar multiple of -1
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With the power of google
Parametric I get
ok so I get the parametric form, it's the same concept as the standard equation (y=mx+c) but you can change the rate at which the value of x changes as t increases
the first three are the ones you'll use 99% of the time tbh
If $\vecb{b, a}$ is a vector on the line, and you have a point, $(x_0, y_0)$, then the line can be parameterized as:
$${x(t), y(t)} = {x_0, y_0} + t{b, a}, t\in\bR$$
Umbraleviathan
If you were to separate the sets and all that funny shit you get what the image has
for the parametric form, what you are doing is that you are representing a line parallel to some vector v, which will be a scalar multiple of that vector
like
[
\bold{r} = \bold{r_0} + s\bold{v}
]
♡Lex♡
Suppose that $L$ is a line in space passing through a point $P_0(x_0 , y_0 , z_0)$ parallel to vector $\bold{v} = v_1 \bold{i} + v_2 \bold{j} + v_3 \bold_{k}$ then $L$ is the set of all points $P(x,y,z)$ for which $\bold{P_0 P}$ is parallel to $\bold{v}$
♡Lex♡
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reaction for more information.
(You may edit your message to recompile.)
so from that, you can say $\bold{P_0 P} = t\bold{v}$ for some scalar parameter t
♡Lex♡
Parametric form like 50% of the time in linear algebra
I was gonna mention linear algebra
but unless you're working with that, you prob won't use it
but it's useful to know nonetheless
the value of t depends on the location of the point, but usually $t \in (-\infty, \infty)$
♡Lex♡
anyways the expanded form of $\bold{P_0 P} = t\bold{v}$ is this:
[
(x- x_0)\bold{i} + (y-y_0)\bold{j} + (z-z_0) \bold{k} = t(v_{1}\bold{i} + v_{2} \bold{j} + v_{3}\bold{k})
]
which you then can rewrite as
[
x\bold{i} + y\bold{j} + z\bold{k} = x_{0} \bold{i} + y_{0}\bold{j} + z_0\bold{k} +t(v_{1}\bold{i} + v_{2}\bold{j} + v_3 \bold{k})
]

♡Lex♡
there ya go i somehow inserted an underscore in there lol
basically we need to take r and theta as components, and break them
into x and y comp
thats it
oh and from this you can just say
[
\bold{r(t)} = \bold{r_{0}} + t\bold{v} = \begin{cases} & x_0 + v_{1}t \ & y_0 + v_{2}t \ & z_0 + v_{3}t \end{cases}
]
♡Lex♡
♡Lex♡
I just like bolding vectors instead 
@tall tusk Has your question been resolved?
whats AMC
american math competition?
the indian jee just feels like memorizing equations to me tbh
that’s a lot of hours 😭
LMAO what a gamer you are
respect for still playing that tho, thought it died
ayo add me on steam 😋
good
😔
honestly yeah games suck the life out of you, i only ever play nowadays if it was with some friends
wait i forgot why is this channel open again
whats ur question
i guess this is fine in 2D?
feels odd doe
i would suggest doing what i did with the parameterisation of a line since it is more general for 3D as well
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oop
Way to jynx it
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man a lot of chinese speakers here, it makes me jelly
Please don't occupy multiple help channels.
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so it should be 5
,w plot y=x^2 and y=5x^2
because its being compressed
then horizontal expansion
it should just say "scale factor 1/5"
thats just poor phrasing tho....
well I'll leave that as an exercise for you to figure out
¯_(ツ)_/¯
thanks
also wait
theres an even worse phrasing
like
the last possible answer
is correct in its term
but has nothing to do with horizontal reflection
yeah these phrasings are terrible
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Why is derivative of x^2 equal to 2x? Because (x+1)^2 - x^2 equals 2x + 1 and difference in y between x 3 and 4 equals not 6, but 7
The limit definition
because derivative isn't the slope that's defined by the secant line going from f(x+1) and f(x)
It's the slope of the tangent line for some x
So you're gonna have to calculate this limit:
$$\lim_{h\to 0}\frac{(x+h)^2 - x^2}{h}$$
Umbraleviathan
@modern linden
basically like calculating the slope of a "linear line" but the difference between the considered x values tends to 0 where as it would be a constant that is bigger than zero otherwise
Am thinking
something like 0/0?
You can't say it's 0/0
kinda
You need to do some manipulation
So I need to know limits first?
h is not actually 0 btw
Learn limits first lol
if you use the eps-delta definition
$$\begin{align*}
\lim_{h\to 0}\frac{(x+h)^2 - x^2}{h} &= \lim_{h\to 0}\frac{\parens{x^2 + 2hx + h^2} - x^2}{h} \
&= \lim_{h\to 0}\frac{2xh + h^2}{h} \
&= \lim_{h\to 0}\parens{2x + h} \
&= 2x
\end{align*}$$
Umbraleviathan
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but h isn't 0
Eh yeah, h just approaches 0
If you use the stupid epsilon delta thing (that I totally remember how to do
) you'll find it ain't actually 0
for all eps > 0 there exists a delta > 0 such that when
That I know because I tried fighting my teacher about this for Calc BC and he whips out the good old eps delta shit
Then h can't be 0
yup

So you wanna say derivative simply ignores the h because it's too small on small scale?
Then it doesn't ignore it?
I'm afraid I might be confusing you
I'd like to have the correct comprehension actually
You're going to need real analysis
But you throw some latin letters at me
Even worse
I don't think consepts like epsilon-delta definition or real analysis is needed for first getting the idea of a limit
the closer you get to L you can always pick some x to plug into f(x)
So the definition of derivative is bound to limits? Basically built on them?
yeah
understanding the consept of approaching would help better if you're new
or rather not pick some x
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Can anyone cross check these answers for me? I have no help and I don’t have a solution manual to check the answers, any help would be appreciated. Thanks in advance
16 should have a hollow hole in it at (0, 1), and also what happened with the “middle discontinuity”? While you can have it don’t see why you chose to, but if you do, make sure you put hollow holes at the end of the “pieces”
(Otherwise you could be seen to be implying your function is such that f(0)=1 and f(0)= -1)
Similar with 17 and (-2,2) being hollow
18 is cool with me, at least the idea
@near jacinth Has your question been resolved?
Aaah right its positive
Right! thankyou so much for that!
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Please don't occupy multiple help channels.
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Can someone help with this integral
I tried integtating it by thinking x^2 as a constant, integrated and got -e^(x^2/y)/x^2 but when i differentiated it again i didn't get the same thing
that wont have an elementary antiderivative i believe
can you approximate it? maybe with gamma functions
i don't see how it will even converge in the state it is in too
Yeah, iirc the professor said that the answer will be something like a 0 or 1, can be integrated in elementary functions
,w int_0^inf int_x^inf e^(x^2/y)dydx
,w does int_0^inf int_x^inf e^(x^2/y)dydx converge
, w integrate e^(x^2/y)dy
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Perhaps try rephrasing your question?
Click here to refine your query online
,w convergence int_0^inf int_x^inf e^(x^2/y)dydx
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,w evaluate integral from 0 to infinity (integral from x to infinity of e^{{x^2}/y} dy)dx
okay whatever, no matter what u will get you definitely are not figuring it out with elementary functions
Yeah
Thanks for the help you two, really appreciate it
yeah like i thought
anytime!

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I have to justify these interphases with a drop-down choice. The intention is to lead the formula for integration by parts.
I can't get it correct, need a little help here...
The options are (roughly translated to english)
- Product rule formula
- integrate both sides
- subtract the same term from both sides
- quotient rule
- product integration rule
- int (h(x))dx = h(x) + C
- D(int(h(x)dx))=h(x)
As it stands, I have no use for the quotient rule, the formula where the + C is used as it's useless here, subtraction of the same term from both sides as it doesn't seem to happen here, product integration rule as such a thing does not exist. Am I correct? I have no idea if the same answer can be used twice. But I've played around with different answers and none of them are correct. IMO the correct answer is
product rule formula,
product rule formula,
integrate both sides,
integrate both sides.
@radiant briar Has your question been resolved?
@radiant briar Has your question been resolved?
Wtf are you learning
yes
@radiant briar Has your question been resolved?
I think integration by parts is what you're looking for, seems like you had almost derived the formula
nope
I have to justify integration by parts by leading the formula with dropdown choices from the menu above
WHAT IS 1+1
@radiant briar Has your question been resolved?
whats the problem?
oh okay you have stated the problem above sorry. lemme see
Product rule formula
subtract the same term from both sides
integrate both sides
@radiant briar Has your question been resolved?
theres 4 boxes to click, not 3. but i suspected you meant 2x product and those 2 for the final ones. nope didnt work haha....
@radiant briar Has your question been resolved?
You're not asking a question, nobody will help you if you're not more precise
This is the "integration by parts" formula
4 boxes to select, what is the correct order of answers, imo it is [mentioned above], but it's not. 🤷
Where are the 4 boxes and what even is the question?
OH I'm blind af sorry
I hid them as theyre not in english haha
What is your langage?
Finnish
Ok nvm lol
So your first guess is right: we use the product rule formula i.e. that D(fg)=Df.g+f.Dg
Your second guess is wrong, try to with about what happened between the first and the second line, how is the equivalence derived?
Your third guess is also correct: we simply integrate both sides resulting in the integral symbol appearing (and appearing twice on the right hand side by linearity)
Your last guess is also wrong, we are not integrating both sides in the last step. We are using another identity between the third and fourth line
Thanks, got it correct now!
.close
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it's a geometry question, I'd love if someone who speaks French could help me because the my notes are in French, my question is: what's the difference between 'vecteur colineaire/non colineaire/coplanaire, the lesson name is 'Droites et Plans de l'espace'
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✅
lol
(was gonna close this channel bc i saw you typing in the other one)
anyway
on ne dit jamais d'un SEUL "vecteur (non) colinéaire" ou d'un SEUL "vecteur coplanaire"
la colinéarité et la coplanarité sont des propriétés qui peuvent être possédées par les ENSEMBLES d'au moins 2 (pour la colinéarité) ou 3 (pour la coplanarité) vecteurs
on dit qu'une couple de vecteurs {v, w} est colinéaire, ou alors que v et w sont colinéaires, s'il existe une constante réelle α non nulle telle que v = αw
sorry interrupt, but I also got another question, I don't really understand the concept of 'vecteur directeur/normale'
tu sais imaginer les vecteurs comme des petites flèches avec une longueur et une direction fixes mais sans position fixe, oui ?
oui
au sens géométrique une couple de vecteurs est colinéaire si leurs directions sont les mêmes ou directement opposées
(si le scalaire est négatif)
okay makes sense
mais pour la colineairite, sur ce cours en ligne le prof a donné ca
é
mais au classe
ah, c'est en termes de coordonnées hein
moi, j'essaie de donner une perspective plus visuelle
ah okay
fais attention c'est un mauvais choix de notation
sorry if im being a pain, im not really good at maths and am trying to become better
pour la coplanarité c'est un peu plus compliqué à mettre en symboles et de comprendre la relation entre ces derniers et la géométrie, mais:
on dit qu'un trio de vecteurs {u, v, w} est coplanaire, ou alors que u, v et w sont coplanaires, s'il existe un trio de scalaires (α, β, γ) ≠ (0, 0, 0) tel que αu + βv + γw = 0
au sens géométrique ça signifie qu'il existe un plan qui est parallèle à la fois à tous les trois
un vecteur directeur pour une ligne droite est simplement un vecteur quelconque parallèle à la droite en question
et un vectur normale pour un plan, c'est un vecteur qui est à un angle de 90° avec tout vecteur dans le plan
yw
TIL Ann speaks french
what, you didn't see me speak it before?
LEGIT GOT ME SCREAMING
don't think so, probably because we're in such different time zones. not many french questions. the usual helpers i've seen speak french are herels and mateo
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might be simple question, but in (r,theta) how did we get r here after finding the theta?
a little confused because I'm doing multivar calc but my calc 1 and 2 didnt cover polar
polar coordinates is a high school trig / pre-calc topic
I didn't take pre-calc or highschool trig 😦
good time to learn
pre-calc probably is a pre-requisite for calculus
oh I get it now LOL
thank you!
that textbook is much nicer
@tardy epoch 
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Clearly B, no?
You know when a line intersects a plane when the dotted line turns into a straight line
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Np
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i have to use maclauren but i dont know how to complete it
thank you brother
anytime bro
Mehdi_Moulati
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please help me derivate that
in order to get the f'
do you know quotient and chain rule
@timid silo Has your question been resolved?
sounds good
@timid silo Has your question been resolved?
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Is there a way to stop a ti-84 from referencing previous solutions? I tried resetting the ram and data.
Should I just manually delete the Ans everytime
It only recently started doing this
if you do an operation, it will automatically put an ans there
like if you do 2+2
then you start your next one with +3
it will display ans+3
here though, it looks like you're using a subtraction symbol instead of a negative sign
the negative is under the 3
🙏
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hello
This precalculus video tutorial provides a basic introduction into partial fraction decomposition. The full version of this video contains plenty of examples and practice problems with repeated linear factors and repeated quadratic factors. Partial fraction decomposition is the process of taking a complex fraction and breaking it into multiple...
multiply all the equation with the denominator of the LHS
to remove the fraction
wdym
$\frac{x}{(x-1)(x-2)(x-3)} * (x-1)(x-2)(x-3) = \qty(\frac{A}{x-1} + \frac{B}{x-2} + \frac{C}{x - 3} ) * (x-1)(x-2)(x-3)$
Mehdi_Moulati
i see
so basically
whatever the denomintaor is
multiply A B and C by all the other brackets
disregarding that denomintor
if that makes sense?
so denominator of A is x-1
so itll be A(x-2)(x-3)?
yes
anytime brother
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you have an exam Wednesday , Right ?
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ye
you need to give yourself some rest
just doing light revision
correct
looks like they defined tan(x/2) to be t
sin(x/2) = tan(x/2)cos(x/2)
mhm
!help
bruh
i see
Mehdi_Moulati
anytime bro
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When t = 98, what is A(t)?
(I suggest using the half life equation for half-life questions)
I have no clue
i have a(t)=ao(1/2)^98/h
i believe i have to solve for h since half life
A(t) represents the amount present at time t
yes
That's okay. It will divide out
and also if the exponent is t/h
im not sure man the resource says half life solving requires finding h
It does. You'll need to grab h.
In order to do that, you'll need to correctly use the information present in the question, such as when t = 98, A(t) = 0.75A0
oh holy shit
wait
when it says decay to 25% of its original amount
does that mean the remaining is 25 percent of the orinal amount
or is it a 25 percent decrease
nvm
idk im so puzzled
im told to assume 100mg sample
@astral magnet Has your question been resolved?
25% of the original amount disappears
Good start! You'll need logs to continue
@astral magnet
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i gotta find the equation of a cos funtion with the points (4,72) and (24,56)
Show your work, and if possible, explain where you are stuck.
so first i did
to find the middle
/ the
c value
sorry 72+56/2
which i got 64
so thats my c value
then i did
72-56/2
to find the amp
which is also the a value
which i got
8
then i did 44-4
to find
the period
which is 40
then did
360/40
and i got 9
as my
k value
so i chose a cos funtuon
cause
im starting at the top
so my final thing was
f(x)=8cos(9(x-4))+64
what did i do wrong
Were there other givens? There are four unknown values so you would need at least four data points to determine their exact values.
No amplitude or center line?
No, you can't.
Oh, those points are max and mins?
yeah
(4,72) is the max
and
(24,56)
is the min
You should be able to figure out P and H from this.
p is 9
adn
h is 4
f(x)=8cos(9(x-4))+64
thats what i got
x-4
cause
the first point
is
(4,72)
so it woukd be -4
cause like it dont start at 0
thw p val
is like
360/ the period
the period
is 40
so the p val
is 9
@bold bane
Sorry, was solving the problem.
So the period and horizontal values you found are incorrect.
why tho
One moment. Let me go through what your wrote.
Oops, I wrote something down wrong and got an incorrect answer.
Give me a moment to fix it.
Ok, fixed.
So you calculated the period incorrectly.
how
Yes.
I see what you are talking about.
So you have half of the period which was 20 which means the total period is B=40 which means that P=2pi/40, or pi/20.
why pi tho
i was taught that
k=360/period
or ih
ig
op
p
in this case
so
p=360/period
360 is 2pi.
$P = \frac{2\pi}{40} = \frac{\pi}{20}$
Kookiemon
its 9 tho
You have the period now. You can enter the equation yourself now. It appears everything else you have is correct.
The period is not 9.
360/40
Kookiemon
but u said
Degrees are a measure of rotation while radians are a measure of length.
My apologies for confusing you.
this
But you do not use degrees when solving this type of equation, you should always use radians.
so 2π/40
Yes.
Yes.
in the equation
Correct.
Pi is equivalent to 180 degrees, but it has an actual value on the Unit Circle of 3.1415...
yw
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Regarding expanding logs
And what's the question?
What's confusing you?
log_3(x+2) I am a bit rusty in my algebra so I don’t know what step I’m missing here
Probably a typo, it's supposed to be x + 12
What part are you stuck on? Do you want to simplify it more?
[if you're still stuck of course]
oh this is an answer key
I am stuck on the first part lol
Yea I get the factorization but where did 2u come from?
Third time lucky 
That’s the part where I’m confused on
This 2u?
Ye
,w expand (u-2)(u^2 + 2u + 4)
Lol



