help-10

[silver plover]

ok so

[timid silo]

eg if x=2.5, then output is 0.5

[silver plover]

let x be 1/2

would the floor be 0

[timid silo]

yes

[silver plover]

so - 0.5

ok

i see

now what kinda graph will it look like

idk how id draw it but i understand the range part

[timid silo]

its spikey

[silver plover]

bruh

spikey

[timid silo]

,w plot x-floor(x)

[silver plover]

wats frac

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Toby#2275

[timid silo]

should be floor not frac mb

[silver plover]

bruh

yh idk how to get that

[timid silo]

try plot it for x in [0,1)

then plot it for [1,2)

then spot a pattern

[royal basin]

@silver plover i remember trying to walk you through why x-floor(x) is 1-periodic only to get swarmed by a bunch of trolls and one well meaning but clueless person who tried to insist on something too trigonometric

[silver plover]

yh i was lost after that point

[grand thunder]

what?

[silver plover]

😳

[exotic rock]

?

[timid silo]

????

[royal basin]

not again...

[grand thunder]

x - floor(x) isnt 1-periodic im pretty sure

lemme try to put together a proof

[timid silo]

huh wtf is happening

[royal basin]

@silver plover can i DM you this once

[silver plover]

sure

[timid silo]

hi sir, it looks fine part i).

[grand thunder]

@royal basin Hi can we work through a problem on vc?

[silver plover]

idk toby

confused as u r

[royal basin]

@timid silo

1. you're being way too formal for a discord server. nobody calls each other "sir" or "ma'am" here.
2. SA2017 was asking for help on part (ii), with the function f(x) = x - floor(x).
3. last time you tried to help, you wrote things in unclear ways, and the things you did write were wrong. there is no trigonometry involved and the period of the function is 1, not 2pi as you apparently tried to say.

[timid silo]

sorry i just use what i use in day to day speech, english not my first language and i losely translate to sir and ma'am, i like to help on discord to improve my english also

[exotic rock]

Do you study any extra maths independently by yourself or do you do it all through a university course

[timid silo]

yes i sorry i reply without reading all sorry.

yes with 3. as i say english not first language i here to help, if they udnerstand, ok, if not, i apologize and i try to learn better explanation in english

your right thoug yes i should first understand see if i can explain well

my one thousand apologies

[exotic rock]

le francais, c'est ta langue maternelle? je peux parler en francais si tu veux

[timid silo]

non monsieur, le français n'est pas ma langue maternelle. je l'ai appris à l'école mais je ne sais pas trop. désolé monsieur.

[exotic rock]

d'accord pas de soucis

[grand thunder]

Please stop coming at my friend like this.

he's trying his best

[timid silo]

sir very nice of you but i and you are not friends. compliances by best.

[grand thunder]

Nevermind Ann.... I agree with your points.

[obtuse pebble]

@silver plover Has your question been resolved?

[sage finch]

sir

[solar axle]

help-10 | sa2017

[silver plover]

I JUST WANT MATHS HELP

😭

😭

😭

[timid silo]

sir you're going to have to calm down

[covert forum]

I love monads.

[silver plover]

u calm down

ive had enough of all of u

[solar axle]

I love monads.

[solar axle]

https://tenor.com/view/lol-gif-20061184

[covert forum]

Sir please stop posting useless gifs in this channel.

[solar axle]

??????

[covert forum]

Please be respectful.

Or I will have to call a mod.

[solar axle]

find god

[dense matrix]

sir this is a math server

[sage finch]

sir

[covert forum]

I found mod!

[solar axle]

sir

[covert forum]

Aha!

[covert forum]

PerpendicularParking

[solar axle]

sir im going to have to ask you to leave.

this is a maths server.

[amber nimbus]

how to integrate. please help

[solar axle]

lower your voice.

no exclamation marks here

[sage finch]

gauss.

[covert forum]

Sir please be useful or I will kick you in the stomach.

[dense matrix]

are sigma pi and mu constants?

[covert forum]

This seems normal.

[solar axle]

step 1 kill yourself

[sage finch]

x is the only variable u tool

[amber nimbus]

step 1 no longer exists

[sage finch]

literally says function in x

?

[solar axle]

step 1

https://tenor.com/view/siuuu-siuu-gif-24345363

[timid silo]

there is a square

clown

[solar axle]

taylor swifties

[covert forum]

@royal basin Madam Ann please can you restore order to this channel; they are bullying SA2017.

[timid silo]

if you want to discuss maths, please make sure you are good at it.

[covert forum]

also how do you have 460,000 messages are you human

[dense matrix]

I've personally never seen any square clowns

[sage finch]

wtfuck

[timid silo]

please dont make fun of my english, i am international

[sage finch]

touch grass fr

[timid silo]

it is hard for me to understand math not in my language

[sage finch]

maths is the language of the universte

the university

[covert forum]

UNIVERSITY

UNIVERSE

OMG

[sage finch]

bath spa

[amber nimbus]

cristiano > messi

[covert forum]

Sir baths and spas are different.

[solar axle]

a la cristiano

idiot

get good

[sage finch]

wrong

[covert forum]

Which college? Harvard or MIT?

[sage finch]

Messi is the 🐐

[tall tusk]

sir toby was helping tho

[sage finch]

sir

[solar axle]

imagine only getting 8.2 marks on a 40 mark test

[amber nimbus]

first decent second bad

[tall tusk]

sir toby is capable of helping @silver plover

[covert forum]

Oh oxford isn't that from the land of tea?

🤮

[sage finch]

@silver plover sir

[red loom]

I am free.

[solar axle]

FREEEEEEEEE

[red loom]

Ok

[timid silo]

@silver plover did you solve the problem?

[covert forum]

Baked bean munchers

[amber nimbus]

@timid silo 8.2 wasnt a score this year

[dense matrix]

you're thinking of teesside

[silver plover]

no

[covert forum]

Purchased.

[tall tusk]

sir, this channel is taken

SIR

[solar axle]

https://tenor.com/view/sir-sir-sir-give-me-that-get-me-that-pervert-gif-20490657

[red loom]

https://tenor.com/view/flight-reacts-flightreacts-madden-nfl-gif-18707262

[tall tusk]

where is sir toby afterall

[sage finch]

https://tenor.com/view/imspeee-ed-speed-gif-23549021

[solar axle]

afterall what?

[amber nimbus]

https://tenor.com/view/ronaldo-cristiano-ronaldo-ronaldo-manchester-ronaldo-united-ronaldo-atalanta-gif-23663364

[solar axle]

you didnt finish the sentence

[tall tusk]

sir toby was helping

wasnt he

[solar axle]

bad save

[timid silo]

who is toby

[amber nimbus]

bottom bins stop chatting

[tall tusk]

ma'am, sir toby was the initial helper

[solar axle]

he couldve got to it

like bro

he dived too EARLY

[timid silo]

i am not ma'am to you

[solar axle]

how do you even do that

[covert forum]

sir who is the ma'am

[tall tusk]

[covert forum]

Shark is non-binary

[sage finch]

there is a maaam

[amber nimbus]

https://tenor.com/view/ronaldo-goal-what-ronaldo-bicycle-kick-cl-qf-gif-11553490

[covert forum]

Wait do sharks have genders

[solar axle]

ma'am, sir if ma'am sir but sir

[solar axle]

only one way to find out

[timid silo]

Yes but have you heard of richarlison

[covert forum]

Google right

Right?

[timid silo]

?????????/

[covert forum]

Fr

[solar axle]

richarlison gon swerve in the cross

use that head to take to dont act like you lost

[timid silo]

Also neel, he should try doing it from 40 metres

[amber nimbus]

messi should try doing it

[sage finch]

if theres a hole theres a goal

[solar axle]

https://tenor.com/view/guy-necklace-staring-gif-21466902

[covert forum]

Null pointer the type to aim for nothing

Gettit

Cus null pointer

[solar axle]

point to nothing

[covert forum]

So it's a pointer

[solar axle]

not aim

[timid silo]

what is sgn

[covert forum]

Yeah but then it sounds better if you say aim

this why nish got a 3 in English

Too literal

[amber nimbus]

he got 3 in ennglish?

[timid silo]

Sign function

[silver plover]

sign

[covert forum]

sorry I meant 2

[solar axle]

what do you think

[amber nimbus]

no

[covert forum]

What's the point of abbreviating a 4 letter word

To 3

[timid silo]

so just f(x) / | f(x) |

[solar axle]

sgn

[tall tusk]

can i try helping sir

[covert forum]

like at that point just dont

[solar axle]

sur

sir

[timid silo]

it's ma'am to you

[timid silo]

You mean x?

[silver plover]

its ok dw i will move on

[tall tusk]

ok sir if you insist

[timid silo]

what

[silver plover]

yessir

[timid silo]

sgn f(x)

It's 1 if x > 0

-1 if x < 0

[amber nimbus]

zed

thats sgn(x)

hes saying sgn(f(x))

[timid silo]

Oh right

Yh

[covert forum]

izet

[timid silo]

But it's undefined at x = 0

If you consider that definition

[sage finch]

sign(0) = 0

[timid silo]

Yeah

[sage finch]

not even a debate just a simple fact

[timid silo]

good point

[sage finch]

Like for france, comment for argentina

[timid silo]

Comment

what if we define 0/0 as 0

Fuckoff neel

then we dont have that problem

[timid silo]

Then 1 = 2 QED

[covert forum]

ok

[covert forum]

ok and

[silver plover]

no way

1 minute of piece and quiet

[covert forum]

piece

[royal basin]

ok if y'all just wanna chat you can go to #chill, #discussion, or off-server

[covert forum]

I have one question though

[amber nimbus]

@royal basin messi or ronaldo

there is only one right answer

[sage finch]

y'all

[royal basin]

literally who are those people?

otherwise this channel really is not the place for several cars' worth of clowns to clown in.

.close

[obtuse pebble]

Channel closed

Closed by @royal basin

Use .reopen if this was a mistake.

[amber nimbus]

noo

[amber nimbus]

we were discussing a definition of the sign function

a non piecewise one

[sage finch]

💀

[obtuse pebble]

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• Show your work, and if possible, explain where you are stuck.
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[amber nimbus]

better definition of sign function

[sage finch]

question mark

explain

[amber nimbus]

its basically tanh

[sage finch]

than

[amber nimbus]

than

[sage finch]

ok bye

[stone flint]

<@&268886789983436800>

[obtuse pebble]

@amber nimbus Has your question been resolved?

[covert forum]

YOOOOOO

LINES

LIKE IN GEOGRAPHY

*GEOMETRY

OMG

GEOMETRY WITH GRAPHS IS GEOGRAPHY

OMGOMGOMGOMG

[obtuse pebble]

@amber nimbus Has your question been resolved?

[obtuse pebble]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[distant rampart]

What’s hidden in the “?”

[teal turret]

Is this just trivia for the server or are u actually trying to figure it out

I have a fitting solution, but I don’t know if it’s the right one

[stone flint]

I wanna know it

[teal turret]

@distant rampart

[obtuse pebble]

@distant rampart Has your question been resolved?

[frank hamlet]

tell it

[distant rampart]

What's the solution

The other 2 pictures are clues

[stone flint]

||SHER||LOCKED

[distant rampart]

is the answer 7?

[teal turret]

What’s ur thought process?

I’ll give u a hint

Addition and division

The colors may or may not have anything to do with the problem.

[distant rampart]

g: 4, r: 8, b: 1 = ?
g: 2, r: 3, b: 5 = 8
g: 1, r: 6, b: 1 = 10

g=green, r=reed, b=black

the numbers are the difference between the two numbers of each colors for respective image

except for red, which is just itself

that's the pattern i was trying to see

[teal turret]

I see

[distant rampart]

for example, to get 10, we do addition

1 + 5 equals six

and then we go down to 1 (b), which is also minus 5 from 6

and so 5+5 equals 10

[teal turret]

Man ur starting to make me think my solution is trivial lol

I don’t rlly like to give out answers, but for this, I’ll just give u the process I used

Added up all the outside numbers and then divided it by the number of colors on each flake (which is 3 for every snowflake) the result would yield the center value

Simple but works, idk if that’s the type of solution u were looking for

[distant rampart]

Yeah that makes sense…

[teal turret]

Lol

[distant rampart]

So 11?

[teal turret]

Yea that’s what I would put

Is this an assignment from school?

Or just a fun thing on ur own

[distant rampart]

No just a challenge on facebook

[teal turret]

Ah ok gotcha

[distant rampart]

Thanks for your input

[teal turret]

Np

Maybe the colors were just supposed to be a source of confusion

And it was just sum then /3

[distant rampart]

Why?

Or how would you get /3 from?

If colors were irrelevant

[obtuse pebble]

@distant rampart Has your question been resolved?

[obtuse pebble]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[sage dagger]

Could someone explain this to me?

[sage dagger]

I don’t quite understand what the equation means

[slender badge]

basically they're all of the form [some number]*x^[some number]

4x^3+2x^2+x+5

[vast wren]

the only thing you gotta keep in mind about polynomials is that the powers of x are always whole numbers

[sage dagger]

Hm

[vast wren]

btw, whole numbers = {0, 1, 2, 3, …}

for example

is (x^1000 + 1) a polynomial?

[sage dagger]

yeah because it’s a whole number

[vast wren]

looking at the powers of the two terms

1000 is a whole number

and remember: 1 is actually 1 times x^0

and 0 is also a whole number

[sage dagger]

o

I didn’t know that

[vast wren]

yeah, that’s also important

let’s look at another function

[sage dagger]

Alright

[vast wren]

x + 1/x

is this a polynomial?

[sage dagger]

I don’t think so

[vast wren]

why?

[sage dagger]

oh wait

[vast wren]

what are the exponents of the two terms?

[sage dagger]

x^0

[vast wren]

if you write them as x to the power of sth

[vast wren]

here it says

x plus 1 over x

[vast wren]

that’s just 1

[sage dagger]

(1/x)^0? Because it doesn’t have a power or

[vast wren]

well, it actually does

there is an x there

[sage dagger]

Oh I thought x was just a variable in that fraction

[vast wren]

it is a variable though

well, here’s a hint

if 1/2 = 2^n, what’s n?

[sage dagger]

one?

[vast wren]

n=-1

[sage dagger]

ohh

right

[vast wren]

so

1/x = x^n

n=?

[sage dagger]

-1

[vast wren]

yeah

rewriting the original expression, we get:

x + x^(-1)

[sage dagger]

ohhh

[vast wren]

first term’s exponent is 1

which is a whole number

but -1?

it sadly isn’t

so the expression isn’t a polynomial

think of polynomials as a special kind of function/expression

they have to satisfy the condition of having whole number powers

[sage dagger]

That makes sense

So basically we are taking the reciprocal of an integer in an expression

But what does this mean?

[vast wren]

https://en.m.wikipedia.org/wiki/Subscript_and_superscript

they’re used in formulas

in order to define general terms

or show how something works

I know that sounds vague

but the more you see it, the more you’ll get used to it

[sage dagger]

Do we have to do anything with it in the equation here

[vast wren]

not really, it’s just a fancy definition

[sage dagger]

alright

[vast wren]

this is the part you need to focus on

oh btw

one last example

is square root of x a polynomial

(hint: sqrt(x) = x^n, n = ?)

[sage dagger]

Hm

I don’t think so

Because it wouldn’t be a whole number ?

[vast wren]

exactly

you can write square root of x like this

x^(1/2)

and 1/2 is definitely not a whole number lol

[sage dagger]

right

alright Tysm for the help

Appreciate it 👍

.close

[obtuse pebble]

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[little flicker]

help

[obtuse pebble]

@little flicker Has your question been resolved?

[solar hornet]

@little flicker

more specifically about rotating around a point

an example, hope you can infer what you need if not then ask

[proper thistle]

To solve for the values of a, b, and c in the given equation, you can use algebraic methods to isolate and solve for each variable separately.

First, we can begin by re-arranging the terms in the equation to bring all of the a terms to one side, all of the b terms to another side, and all of the c terms to a third side. This gives us the following equation:

8a + 2b - 4c = 4

Next, we can divide both sides of the equation by 2 to eliminate the coefficient on the b term, giving us:

4a + b - 2c = 2

[solar hornet]

I think wrong channel bro

[proper thistle]

Then, we can divide both sides of the equation by 4 to eliminate the coefficient on the a term, giving us:

[proper thistle]

Why?

[solar hornet]

looks like this has nothing to do with rotating points

only saying because maybe you wanted to post this elsewhere

[obtuse pebble]

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[strange fiber]

Ehm it says

One point

Do you see the point?

Well it has x and y

Both are included in the sentence

Yes, I believe

Points are usually written in square brackets []

Or if you write them in parenthesis well thats up to you

Ure welcome 😁

[obtuse pebble]

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✅

[timber fox]

what were the reasons you chose those values??

[obtuse pebble]

@frail shell Has your question been resolved?

[obtuse pebble]

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[static pasture]

How do I do this?

[static pasture]

Huh

[hexed agate]

Better to send picture

[static pasture]

A sec

https://media.discordapp.net/attachments/486844829209198613/1053082508205494322/rn_image_picker_lib_temp_bd6e354d-ff0a-4983-ab26-5a2e220399ea.jpg

@hexed agate

Question 2

[dark stirrup]

Have you tried drawing it out?

[static pasture]

Yes

[trail cliff]

drawing it out is always a great first step

send your drawing!

[static pasture]

K

Pardon for the mess
Did it in rough

I tried to assume angle b 90 but that clearly didn't help

[dark stirrup]

,rccw

[nocturne minnow]

Here's a hint, that formula is useful

[static pasture]

I don't have the side required

[nocturne minnow]

You have all the info needed to use that formula

[static pasture]

Ellaborate

[nocturne minnow]

Use the formula with your values

[static pasture]

Ah wait

The formula says ab

Not AB

[static pasture]

ty

[nocturne minnow]

It's just notation

[static pasture]

So the answer to my question is 28 ?

Oh wait

Sorry nvm

Got it

It's 14 right?

Ty @nocturne minnow

.close

[obtuse pebble]

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[timid silo]

Yes, I know it says the answer. But can someone explain how they got this answer?

[nocturne minnow]

Proportions

[timid silo]

But that doesnt solve it

<@&286206848099549185>

[wraith rampart]

One easy way to think about similarity is that if ABC is similar to FGH then if o(A) denotes the side opposite the point A we have o(A)/o(F) = o(B)/o(G) = o(C)/o(H)

Can you finish the problem from here?

[timid silo]

yes, thanks!!!

.close

[obtuse pebble]

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[strange fiber]

The question is asking for the number of permutations on the set {1,…,2n} such that no even number appears on its own. In other words, every even number must appear next to an odd number.

[strange fiber]

The number of permutations on the set {1, ..., 2n} is (2n)!. To calculate the number of such permutations where no even number is displayed on its own, we can use the counting formula for choosing without repetition. We have a set of even numbers of size n and a set of odd numbers of size n. For each even number we have n options for where to place it, and similarly for each odd number we have n options for where to place it. In total, we have n^n options for placing even numbers and n^n options for placing odd numbers. The number of permutations where no even number is displayed on its own is therefore n^n * n^n = n^(2n).

Overall, the number of permutations on the set {1, ..., 2n} where no even number is displayed on its own is (2n)! / n^(2n).

Is this correct?

[haughty coyote]

By not on its own, do you mean that if you write out s(1), s(2), ..., s(2n), no even number is surrounded by odd numbers ?

[civic zealot]

Wouldn’t “no even number appears on its own” mean every even number is next to at least one other even number?

[haughty coyote]

Because then I don't think your representation of n options per parity is correct

[strange fiber]

Yes, that is correct. When we say that no even number is displayed on its own, we mean that if we write out the permutation $s(1), s(2), ..., s(2n)$, no even number is surrounded by odd numbers. This means that every even number is either at the beginning or end of the permutation, or it is immediately followed by another even number.

For example, in the permutation $s(1) = 3, s(2) = 1, s(3) = 4, s(4) = 2$, the even numbers 4 and 2 are not displayed on their own, because they are surrounded by odd numbers (1 and 3, respectively). However, in the permutation $s(1) = 4, s(2) = 3, s(3) = 1, s(4) = 2$, the even number 4 is not displayed on its own, because it is followed by another even number (2).

[warm shale]

Fate

[strange fiber]

$$\frac{(2n)!}{n^{2n}} = \sum_{k = 0}^n \binom{2n}{n - k} \frac{(n + k)!}{k!}$$

[warm shale]

Fate

[strange fiber]

$$\frac{(2n)!}{n^{2n}} = \sum_{k = 0}^n \binom{2n}{n - k} \frac{(n + k)!}{k!}$$

[warm shale]

Fate

[haughty coyote]

It definitely isn't as simple as n and n though

The way I see it:
Group the evens into p groups of at least 2 numbers
Group the odds into q groups
Set up stars and bars to see how to place them
See how to make the edges work nicely

[obtuse pebble]

@strange fiber Has your question been resolved?

[strange fiber]

wait

[grim eagle]

No, this calculation is not correct. The number of permutations on the set {1, ..., 2n} is indeed (2n)! as you stated. However, to count the number of permutations where no even number is displayed on its own, you need to use a different approach.

One way to do this is to use the principle of inclusion-exclusion. Let's call the set of even numbers E and the set of odd numbers O. We want to count the number of permutations where no element from E is displayed on its own. This is equivalent to counting the number of permutations where every element from E is paired with an element from O.

There are n! ways to arrange the elements of E and n! ways to arrange the elements of O, so there are a total of (n!)^2 ways to arrange the elements of E and O independently. However, this counts each valid pairing of E and O twice, since the order of the elements in E and the order of the elements in O are interchangeable. To correct for this overcounting, we need to divide by 2 to get the total number of valid pairings of E and O.

Therefore, the total number of permutations where no even number is displayed on its own is:
(n!)^2 / 2
= [(2n)! / (n!)^2] / 2
= (2n)! / (2 * (n!)^2)

This is the final result.

[strange fiber]

@haughty coyoteis he correct?

[grim eagle]

To prove that the result (2n)! / (2 * (n!)^2) is correct for counting the number of permutations where no even number is displayed on its own, we can use the principle of inclusion-exclusion as follows:

Let E be the set of even numbers {2, 4, ..., 2n} and let O be the set of odd numbers {1, 3, ..., 2n-1}. We want to count the number of permutations of the set {1, 2, ..., 2n} where no element from E is displayed on its own. This is equivalent to counting the number of permutations of the set {1, 2, ..., 2n} where every element from E is paired with an element from O.

We can use the principle of inclusion-exclusion to count the number of such permutations as follows:

|E ∪ O| = |E| + |O| - |E ∩ O|
= n + n - 0
= 2n

Since there are 2n elements in the set E ∪ O, there are (2n)! permutations of the set {1, 2, ..., 2n}.

However, this counts each valid pairing of E and O twice, since the order of the elements in E and the order of the elements in O are interchangeable. To correct for this overcounting, we need to divide by 2 to get the total number of valid pairings of E and O.

Therefore, the total number of permutations where no even number is displayed on its own is:
(2n)! / 2
= (2n)! / (2 * (n!)^2)

This is the final result.

I hope this helps! Please let me know if you have any further questions.

[strange fiber]

wtf

@haughty coyotelook at it

[wild swallow]

wtf lol

chatgpt much

[strange fiber]

is he right?

[obtuse pebble]

@strange fiber Has your question been resolved?

[obtuse pebble]

@strange fiber Has your question been resolved?

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[strange fiber]

.reopen

[obtuse pebble]

✅

[zenith raft]

looks very chatgpt :c

[obtuse pebble]

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[small crag]

Are both these ways correct?

[small crag]

<@&286206848099549185>

[obtuse pebble]

@small crag Has your question been resolved?

[obtuse pebble]

@small crag Has your question been resolved?

[obtuse pebble]

@small crag Has your question been resolved?

[obtuse pebble]

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[abstract karma]

whats the nth term of 12,8,4,0?

[amber meteor]

Is it an arithmetic or geometric sequence

[obtuse pebble]

@abstract karma Has your question been resolved?

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[eager arch]

I just need to prove the RHS=LHS... I'm right?

.close

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[limber talon]

.close

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[limber talon]

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[limber talon]

hi i just need help on this bc i don’t know how to approach it.

how do i find the max?

[unique spear]

Is this physics?

[timber fox]

do you know the relationship between displacement and velocity?

[limber talon]

No it’s precalc

[timber fox]

ok

doesn't change anything too much

[limber talon]

Oh

[timber fox]

you can solve this equation for y=0, to get the times at which the ball is on the ground.

[limber talon]

but then i would find the time

right?

[timber fox]

you would in fact find the time

think about what your actually solving for though,

[limber talon]

it asks for the maximum height

[timber fox]

its a quadratic related to motion, and its going to have a line of symmetry (in this case) around the maximum.

what are the times of the equation?

if y = 0

not their numerical value

but what actually ARE they

[limber talon]

2 and 0

oh

max is at 2 seconds

?

right?

[timber fox]

yes

because of midpoint between 0,4

and line of sym around t=2

[limber talon]

so i just plug in 2?

[timber fox]

sure can

[limber talon]

woah

wow thanks

[timber fox]

,w plot 64t-16t^2

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Clarkie#5208

[timber fox]

the time you work out at y=0 are the roots

[limber talon]

Oh, ok thanks

that really helped wow

i have one more math q so can i ask or do i have to open another thing?

im kinda new here mb

[timber fox]

you can ask here

[limber talon]

omg wow

kk gimme a sec lemme upload it lol

also thanks for hwlping me btw

helping*

Ok so abt this one ik 60,000 would be the y value

like the total

but idk how to express

the price decrease

ifykwm

[timber fox]

ok so

its asking for the revenue , and we can say that revenue = people in stadium * ticket price

to start with as an observation

[limber talon]

Yes

[timber fox]

we can see that it says

if ticket price P

goes down by 1

then people in stadium N + 2000

[limber talon]

yes

28,000(7-n)

?

n wouldl equal every dollar lowered

right?

[timber fox]

we know N_t is 60000 total

[limber talon]

ya

so 60,000 = 28,000 + 2000(7-x)

[lost tree]

no right

[limber talon]

oh

[lost tree]

28000 + 2000*(7-n)

[limber talon]

OHhhhh

[lost tree]

is the attendance

in terms of ticket price n

[limber talon]

ya ur right

[limber talon]

^?

[lost tree]

solving for x here gives u the ticket price which gets u max attendance

they ask u for a function that models the revenue in terms of ticket price

[limber talon]

but we dont know how many times the price has been lowered?

[lost tree]

yeah thats why u want a function

u cn tell the function how many times u HAVE lowered the price, then it tells u how much ur revenue will be

[limber talon]

ok so x = -9

how would that be the max price though?

[lost tree]

ok do u know what a function is

[limber talon]

ya

each input has an exactly one output

[lost tree]

yeah

so they are asking u for a function

u must be able to input the ticket price into it

and it must output how much ur revenue will be

so theyre asking for something like an expression

[limber talon]

Could you explain how to get that function from 60,000= 28,000 + 2000(7-x)

[lost tree]

u dont need the 60,000 = 28000 + 2000(7-x)

[limber talon]

do i just solve in terms of x?

[lost tree]

no need to solve for x

for example, if i write g(x) = 2000 * (7-x)

then g is a function that outputs the extra number of ppl who will attend the game

when u input the price of the ticket

[limber talon]

so i would write y = 2000(7-x)

[lost tree]

so if i wanna know how many more ppl will come if i make my ticket price 5

i can just find out g(5)

[limber talon]

y as in f(x)

[lost tree]

g(5) = 28000 + 2000(7-5) = 32000

[lost tree]

yeah

so u want to write something like that

which tells u the total revenue

[limber talon]

so it would be f(x)=2000*(7-x)

[lost tree]

this tells u how many MORE ppl will come to the stadium if ur ticket price was x

[limber talon]

oHh

[lost tree]

can u write a different function which gives how many TOTAL ppl will come?

[limber talon]

so f(x) = 28000 + 2000(7-x)

[lost tree]

write so this is the total number of ppl

how much is one ticket?

[lost tree]

what will be the total revenue u will get if this many ppl come

[limber talon]

7 dollars

[lost tree]

no

so the price has reduced right

its no longer 7

[limber talon]

i would put x as 0?

42000?

[lost tree]

what no

[lost tree]

do u get it upto here

[limber talon]

could you explain pls

[limber talon]

yes

[lost tree]

that thing u wrote is a function which outputs the TOTAL no. of ppl who will attend the stadium IF your ticket price were x right?

[limber talon]

this is the total revenue

[lost tree]

no it is the total NUMBER of ppl

[limber talon]

yes

[lost tree]

not the revenue

[limber talon]

oH kk i get it now

and max is 60,000

[lost tree]

if that many ppl come and each person pays x per ticket

write a different function which gives the revenue

[lost tree]

yeah

[lost tree]

can u do that

[limber talon]

32000=2000(7-x)

?

[lost tree]

no these are not functions u r writing equations

[limber talon]

how would i inlucde functions with the max?

[lost tree]

forget abt the max now

just write the function

worry abt the max later

[limber talon]

f(x)=28000+2000(7-x)

[lost tree]

this is a function which outputs the TOTAL no. of ppl who will attend the stadium IF your ticket price were x right?

[limber talon]

yes

[lost tree]

now each one of these ppl is paying x

per ticket

then how much do u get in total

[limber talon]

the total amount of people

right?

[lost tree]

so if this many ppl come in total

and each one pays $2 per ticket

how many dollars wud u have

[limber talon]

14000

[lost tree]

how

[limber talon]

wait

no

lmao

[lost tree]

lol

[limber talon]

320000

32000

[lost tree]

no

[limber talon]

?

the price would of decreased by 4 which is 2 $

[lost tree]

u have 28,000 + 2000*(7-x) ppl

[lost tree]

and u have this many ppl WHEN ur ticket price is $x right?

[limber talon]

yes

[lost tree]

so this means 28,000 + 2000*(7-x) ppl are coming, and each one is paying u $x

right?

[limber talon]

i am confused about the (7-x)

[lost tree]

why

so the original ticket price is 7

if now ur price is x

[limber talon]

that would mean x = 4 right

since it lowered by 4

[lost tree]

no this $2 was just an example forget abt it

[limber talon]

kk

but the amnt people would pay is (7-x) right

so (7-x) = price per person

[lost tree]

no 7-x is the amt by which the price was lowered

the price is x now

[limber talon]

so for example if the price is 2$

we would do 7-2?

[lost tree]

yeah 7-2=5, so that means u have lowered the price by 5$

[limber talon]

ohhh

kk

i get it now

we are trying to find out the price lowered

[lost tree]

so the problem tells u that for each dollar u lower the price by

2000 more ppl will come

[limber talon]

yes

[lost tree]

so this is the total number of ppl who will come right

[limber talon]

yes

[lost tree]

and how much is each one of them paying?

[limber talon]

?

we dont know

[lost tree]

@winter cargo help me out

[winter cargo]

wait

[limber talon]

it doesnt say how much its lowered?

[winter cargo]

Say the amount reduced in dollars is n
then people increased = 2000n
so now, total people = 28000 + 2000n

u understand this?

[limber talon]

yes

[winter cargo]

so now what is the new price?

7 - n

[limber talon]

yes

[lost tree]

lol

[winter cargo]

lets say new price is t

t = 7 - n

[limber talon]

ok

so

[winter cargo]

t + n = 7
n = 7 - t

[limber talon]

60,000>=28,000+2000(t)

[winter cargo]

u dont need that part

for now

[limber talon]

oh ok

[limber talon]

what is this for?

[winter cargo]

youll know

1 min

[limber talon]

okk

[winter cargo]

now we know n = 7-t
now, total people = 28000 + 2000n
= 28000 + 2000(7-t)
= 28000 + 14000 - 2000t
= 42000 - 2000t

now the amount is in terms of the new price

[limber talon]

kk

[winter cargo]

now revenue = amount of people * new price

[limber talon]

but isnt the max 60000

?

[lost tree]

lol

ull get there

wait

[limber talon]

kk

ok lol

[winter cargo]

= (42000 - 2000t)*t
= 42000t - 2000t^2

If the new price is t, the revenue is 42000t - 2000t^2

[limber talon]

so we didnt need 60,000

?

[winter cargo]

no

[limber talon]

wow

that makes much more sense

thanks guys

[winter cargo]

we are dealing with revenue (that is, money)

so people are not needed in final result

[limber talon]

👍

thank you

[limber talon]

thank u too lmao

[winter cargo]

you can bound the equation with that though

like the maximum amt of ppl
42000 - 2000t <= 60000

[limber talon]

ya lol

it makes much more sense now

thanks

thats all the q's i had for today

.close

[obtuse pebble]

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[slate charm]

Product A is twice the price of Product B. Their sum is $46. Represent the problem in an
equation.
x+2x=46
Is my answer correct?

[tidal hawk]

ya

can simplify

[slate charm]

ok thx

.close

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[bleak totem]

how do you find the range of this?

[sage geode]

I like to think of it this way: For what values of y will x not have a solution in the equation?

[bleak totem]

I'm sorry I don't understand what you mean

[sage geode]

Try solving for x

[bleak totem]

isn't x all real numbers except x=3 which wouldn't work?

[sage geode]

I mean solve for x in the equation y = (4 - 2x)/(x - 3)

[bleak totem]

oh I figured it out now

thank you

.close

[obtuse pebble]

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[weary breach]

I need to calculate this, using D as the amount of all points in the first quadrant that satisfy the inequality x+y <=1

[weary breach]

,rotate

[weary breach]

It's a triangle, I get the limits $0\leq x\leq 1$ and $ 0 \leq y \leq 1-x$ and it leads me to $\frac{1}{24}$
But that's apparently wrong

[warm shale]

Kienai

[weary breach]

What am I missing here? Wolfram tells me the inequality extends to 1.5 but that seems weird to me.. I tried it that way too but that was also wrong

[obtuse pebble]

@weary breach Has your question been resolved?

[weary breach]

<@&286206848099549185>

[obtuse pebble]

@weary breach Has your question been resolved?

[weary breach]

.close

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[vocal matrix]

apparently this is not how you solve this

[high lily]

apart from the last line and the vanishing = 0 ,
the work is valid but inefficient

[vocal matrix]

forgot =0

[high lily]

note that the denominators already have a common factor of (x+4)

you can do something like multiply
(x+2)/(x+4) by x/x
and then equate the numerators

[vocal matrix]

ok thats what I thought

but the problem is to find

all solutions

[high lily]

that'll give you all solutions

[vocal matrix]

yes but in khan its saying its incorrect

when I put it in wolfram

[high lily]

oh, you have to also consider the domains of the original expressions

[vocal matrix]

ok thanks

[high lily]

actually that isn't actually really an issue here (though you should generally do a quick check)

you can do something like multiply
(x+2)/(x+4) by x/x
and then equate the numerators
if you did that properly, you should reach the correct answer

[vocal matrix]

ill try it

[high lily]

yes but in khan its saying its incorrect
are they explicitly saying its incorrect?

or are they just providing an alternate method

[vocal matrix]

no its just saying

we dont understand your answer

or something

its making me type the right answer

[high lily]

what exactly were you putting in

[vocal matrix]

-5, -4, 3

when its just -5, 3

[high lily]

so yeh, like i said

equating numerators gets you the only two solutions -5,3

[vocal matrix]

what was I doing

I cross multiplied instead

[high lily]

your cubic equation had a different domain

[vocal matrix]

=0

.close

[obtuse pebble]

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[vocal matrix]

wait

thats wrong

• 2x

[obtuse pebble]

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[timid silo]

($\textbf{Probabilistic classical algorithm}$) Suppose that the problem is not to distinguish between the constant and balanced functions with $\textit{certainty}$, but rather, with some probability of error $\epsilon < \frac{1}{2}$. What is the performance of the best classical algorithm for this problem?

[warm shale]

verymischievousperson

[timid silo]

so

[warm shale]

verymischievousperson

verymischievousperson

verymischievousperson

verymischievousperson

verymischievousperson

verymischievousperson

[timid silo]

so query means doubt right?

as a noun

while query as a verb means like to ask a question am i right?

all i know is that if the error is less than half, then it would be less balanced

so what is the relationship between error and probability?

btw, if you want to reply to me here, please consider pinging

[warm shale]

verymischievousperson

[timid silo]

the book says like 2^n/2 + 1

so yeah

i made a small mistakes here

i would say like

[warm shale]

verymischievousperson

[timid silo]

i'm not sure

[timid silo]

^

but anyway...

so i would say it would be less balanced

¯_(ツ)_/¯

or

uhh

maybe i got the idea

$\frac{1}{2} > 1 - \frac{1}{2^{x-1}}$, for $0 \leq x \leq 2^{n-1}$

[warm shale]

verymischievousperson

[timid silo]

¯_(ツ)_/¯

[trail cloak]

Wouldn't this inequality hold true only for 0<x<2?

@timid silo

[timid silo]

uhh

why?

[trail cloak]

Because then when x = 2, 1/(2^{2-1}) = 1/2

[timid silo]

ok

[trail cloak]

And 1-1/2 = 1/2

Which then breaks the inequality

[timid silo]

can probability be negative?

i don't think so

theoretically

[trail cloak]

So it goes 1<=x<2

[timid silo]

and x belongs in natural number?

[warm shale]

verymischievousperson

[timid silo]

???

[trail cloak]

Did the question specify?

[timid silo]

uhhh

it asked me for the performance

idrts

but i have read the book

in case of using classical algorithm

instead of using deutsch-josza algorithm

aka general quantum algorithm

[trail cloak]

Hmm

Ok since x belongs to the natural numbers, then only 2 queries are allowed to give an error of at most 1/2

If more are made, then the function would be less balanced

I think

[timid silo]

i think so too

it might as well belong to the set of positive real numbers

that would be less balanced

i think i got it

thank you so much

[trail cloak]

I haven't done much lol

You did the bulk

[timid silo]

ty

u2

i think you did great in helping

[trail cloak]

Glad you think so :)

[timid silo]

:)

[trail cloak]

Good luck

[timid silo]

ty

u2

with your life

.close

[obtuse pebble]

Channel closed

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Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

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[vernal shoal]

.close

[obtuse pebble]

Channel closed

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Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell prairie]

pain

[obtuse pebble]

@shell prairie Has your question been resolved?

[raven spire]

so basically, we have: \ $\sum_{n = 0}^9 \abs{2 + (p + q)n} \ = \sum_{n = 0}^9 \left[ \abs{12+pn} - \abs{-10 + qn} \right] \ = 41$

[warm shale]

Arya

[shell prairie]

yeah

[raven spire]

so, p, q are integers right? or what?

[shell prairie]

yes

is there an efficient way on doing this

[raven spire]

ofc there is

for starters, notice that:
|2| + |3| + |4| + |5| + |6| + |7| + |8| + |9| + |10| = 55 > 41

[shell prairie]

i think im able to get p+q

but the hard part for me is to get them individually

i feel like im gonna mess up

[raven spire]

wait, what's p + q?

[shell prairie]

idk i havent tried yet but im pretty sure it can be obtained by the first info

wait

is it 41?

oh man

its supposed to be 31

typo

[raven spire]

oof 🤦‍♂️

yeah, I was wondering there's no solution

integer at least

[shell prairie]

its prob -1

[raven spire]

Yeah so, from first info you have (p + q) must be -1

[shell prairie]

yeah

[raven spire]

from second info you can say:
|A| - |B| ≤ |A - B|

so 41 ≤ |22 + (p - q)n| hmmm

[shell prairie]

Also

|a3|=|b3|

[raven spire]

that's given?

[shell prairie]

no

i just got it

sinc p+q=-1

[raven spire]

how does (p + q) = -1 give you |a3| = |b3|

[shell prairie]

just change q as -1-p

you will see

but i dont think its useful

this is ass

i hate sequences

labor

i dont see any patterns

ok i did find the answer