wdym?
#help-10
carmine surge
cedar mantle
obtuse pebbleBOT
@carmine surge Has your question been resolved?
timid silo
Hello. Any help would be appreciated, especially for part 2, trying to assignment a friend
obtuse pebbleBOT
Hello. Any help would be appreciated, especially for part 2, trying to assignmen...
@timid silo Has your question been resolved?
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
@timid silo Has your question been resolved?
past kindle
May I pls get help on how to solve this, if possible with all the steps, It for a home work and the professor wont grade without all steps. tysm.
obtuse pebbleBOT
May I pls get help on how to solve this, if possible with all the steps, It for ...
royal basin
we won't solve things for you or give you finished work on a silver platter
are we to understand you're stuck not knowing how to begin on this?
past kindle
yes
tame forge
||isn't that the fundamental theorem of calc. pt. 1?||
timid silo
May I pls get help on how to solve this, if possible with all the steps, It for ...
You want to get it into the form where FTC is applicable
You have to split up the integral and use chain rule. That's your hint
obtuse pebbleBOT
timid silo
just as a btw, we won't solve it for you but that doesn't mean we won't help/guide you through the problem
past kindle
kk
obtuse pebbleBOT
Available help channel!
digital ivy
$$x^2+5x=-2$$
obtuse pebbleBOT
$$x^2+5x=-2$$
warm shaleBOT
_sami
digital ivy
i) Find what must be added to both sides of the equation to create a perfect square on the LHS
ii) Write each equation in the form $$(x + p)^2 = k$$
warm shaleBOT
_sami
digital ivy
i) I think 5/2
jaunty goblet
U know completing the square?
digital ivy
ii) i think the right side of the equation would be -2 x 5/2 which is -2 x -2.5 so 4 1/4
currently i have
x^2 + 5x + 5/2 = 4 1/4
nah ive done this shit wrong what
im so confused
ok from the start bruv
$$x^2 + 5x = -2$$
warm shaleBOT
_sami
jaunty goblet
U know completing the square?
.
digital ivy
idk my instructions say to half the coefficient and then square it
jaunty goblet
Ok complete the square of the LHS for me
jaunty goblet
it'd become 5/2^2 which is 25/4
Write out the whole equation
digital ivy
is 5/2^2 = 25/4
jaunty goblet
It will start making sense then
digital ivy
or 25/2
jaunty goblet
Ok wait
Do u know how when I complete the square for x^2+ 2
It becomes (X+1)^2 -1
Do u know how to get from what I wrote at the top to the bottom
digital ivy
yes
jaunty goblet
Do the same for our LHS
jaunty goblet
Hmm well I suggest u watch a video on completing the square that explains it much better than me
But (X+1)^2 expands out to x^2 +2x+1
However we only need x^2+2x
So we minus the thing at the end
And to get the thing at the end
U square the 1 in (X+1)^2
warm shaleBOT
_sami
digital ivy
halfed the coefficient = 5/2^2
jaunty goblet
Mhm
digital ivy
which is 25/2 right?
jaunty goblet
No it's (5/2)^2
jaunty goblet
Wait can u show me the video u watched if any
Cuz I don't think your doing it correct
jaunty goblet
Ok wait
Do u know how when I complete the square for x^2+ 2
It becomes (X+1)^2...
Let's go back to this
Do u understand how I did that
digital ivy
in my book itd say to half the coefficient so in x^2 + 2x = 5 itd become (x+1)^2 = 6
watching the vid
digital ivy
i halfed the coefficient
2 (2x) / 2 (x^2)
2/2 = 1 = 1^2
and u plus it on both sides
digital ivy
not really bc in his he had an thing but in mine i dont
ok wait lemme see
x^2 + 5x + (5/2)^2 = -2 + (5/2)^2
do i send it over to the other side?
jaunty goblet
Why are u not doing (X+5/2)^2 first
U cannot be squaring that term if u havent made this statement
Cuz then the math won't add up
(X+5/2)^2 - (5/2)^2= -2
Tell me where u are confused
From the bottom equation
digital ivy
i could do that but how do i know that it'd turn into (x+5/2)^2
jaunty goblet
Well that's just completing the square
If u expand that out
Ud get that + (5/2)^2
Extra
And that's why we subtract (5/2)^2
That being x^2+5x
digital ivy
ok wait if i expand (x+5/2)^2
jaunty goblet
Yes
digital ivy
how tf do i expand that
idk how to do that multiplication w fractions
ok test run
stay w me
jaunty goblet
Ok
jaunty goblet
5/2x
jaunty goblet
How would u expand (X+2)(X+2)
digital ivy
so i take +5x out of the equation to complete the square
@jaunty goblet
in x^2 + 5x + (5/2)^2 = -2 + (5/2)^2
i take out +5x to the right side
so x^2 + (5/2)^2 = -2 + (5/2)^2 - 5x
jaunty goblet
I mean algebraically what Ur doing is correct but I doubt it will lead u to the answer
digital ivy
well i mean
i can turn left side into (x+5/2)^2 = -2 + (5/2)^2 - 5x
can u js show me how u would do it step by step and ill see if i get the pattern
ok my friend will explained it now thank u for ur help :)
.close
humble maple
How would I go about starting to solve ii?
obtuse pebbleBOT
How would I go about starting to solve ii?
royal basin
zero-product property
humble maple
So I would solve sin(x + 30) = 0 and cos(x + 30) = 0 separately
royal basin
yes, and then take the union of their solution sets
humble maple
By that do you mean the common shared answers?
timid silo
You're thinking of intersection, they were mentioning union
humble maple
So just all of the valid answers
timid silo
Union is just the collection of all elements shared by both sets
humble maple
I think I get you, thank you very much, both of you
timid silo
So just all of the valid answers
Sure yeah
humble maple
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
light zinc
if h approaches 0, why is e^h-1=h?
obtuse pebbleBOT
if h approaches 0, why is e^h-1=h?
sage geode
You mean why $\lim_{h\to{0}}e^h - 1 = \lim_{h\to{0}}h?$
warm shaleBOT
A Lonely Bean
obtuse pebbleBOT
@light zinc Has your question been resolved?
light zinc
**A Lonely Bean**
Yes
sage geode
Well the first limit is just e^0 - 1, which is just 0
And the second limit is also 0
Hence the limits are equal
stable rain
lol
obtuse pebbleBOT
@light zinc Has your question been resolved?
warm shaleBOT
bronny
obtuse pebbleBOT
@shell prairie Has your question been resolved?
obtuse pebbleBOT
@shell prairie Has your question been resolved?
elfin galleon
hi
elfin galleon
what is square roots
gentle pelican
The square root of a number is a value that, when multiplied by itself, equals the original number. For example, the square root of 4 is 2, because 2 x 2 = 4. The square root of 9 is 3, because 3 x 3 = 9.
timid silo
think of it as the reverse operation of squaring i guess
obtuse pebbleBOT
@elfin galleon Has your question been resolved?
topaz totem
its
2 x 2 = 4
3 x 3 = 9
4 x 4 = 16
5 x 5 = 25
6 x 6 = 36
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
the ^2 essentially implies how many times the number is being multiplied
so if it were like 5^3, then 5 x 5 x 5.
if it were 6^5, then 6 x 6 x 6 x 6 x 6, 6 multiplied 6 times
then square root is basically for numbers that are like 2^2, 3^2, essentially N^2
Since 2 x 2 = 4, the square root of 4 is 2, cause 2 is the only one multiplied by itself that makes 4
3x3 = 9, square root of 9 is 3, cause 3 the only one multiplied by itself to make 9
so square root of 25 would be 5, cause 5^2 = 25
square root of 36 = 6
square root of 49 = 7, square root of 81 = 9 and so on
obtuse pebbleBOT
@elfin galleon Has your question been resolved?
hoary moon
help please
obtuse pebbleBOT
help please
hoary moon
why answer incorrect im confused
high lily
show work
high lily
type y' as y'
hoary moon
dx/dy
high lily
how did you manipulate your equation that lead to what you entered
high lily
in case I'm not being clear enough
how are you getting from
5ax^4-2by*y'=0
(which is correct result after the initial differentiation)
to dy/dx = (5a(x)^(4)/(b^(1/2))
hoary moon
why b^1/2
high lily
i'm just re-typing out what you wrote
high lily
that's what you had in your initial equation after differentiating
which i'm saying is fine
you just fked up in the stuff you did after that
and why i'm trying to get to to show what you did
hoary moon
so the answer 5ax^4-2by*y'
hoary moon
can you tell me the answer
high lily
because based on your responses what i'm infering is
you differentiated to get
5ax^4-2by*y'=0
<do dark magic>
stuff you entered into the system
hoary moon
5ax^4-2by*dy/dx
high lily
what happened to the = 0
hoary moon
i deleted it
high lily
5ax^4-2by*dy/dx = 0
isolate/solve for dy/dx
you've already done the main calculus component
the remaining work is basic algebra
hoary moon
my algebra is terrible
high lily
if your algebra is rusty, its highly recommended that you work on that before continuinig with more calculus
but you're probably just massively overthinking there
the following steps are pretty much no different to what you'd do to solve
ab - cd = 0
for d
high lily
hence d = ?
hoary moon
maybe 0
hoary moon
we dont know the value
high lily
so?
hoary moon
ab/c
high lily
yes
hoary moon
i know this
hoary moon
but i dont understand what should i do in this question
high lily
no
you didn't say that d was c-ab did you?
recall what you did with
ab - cd = 0
ab = cd
d = ab/c
hoary moon
it is not 2by ?
high lily
to unambiguously represent the desired expression in plain text, () are needded
5ax^4/(2by)
scenic nova
cos(2tan^(-1)(4/3)
How do i find the exact value of this in fractions?
obtuse pebbleBOT
cos(2tan^(-1)(4/3)
How do i find the exact value of this in fractions?
unreal musk
||"Tangent half-angle substitution"||
obtuse pebbleBOT
@scenic nova Has your question been resolved?
scenic nova
||"Tangent half-angle substitution"||
oh thanks
little steeple
Hey can someone help me out with the trapezoid rule in python when we don’t know the upper limit but have the value for the integral?
obtuse pebbleBOT
Hey can someone help me out with the trapezoid rule in python when we don’t know...
little steeple
So something like this
How would I go about using the trapezoid rule to converge to a value of x?
trail cloak
Well what do you usually do when you find an integral with bounds and need to use trapezoidal rule?
Don't you find the Δx?
(b-a/n
And assume that n is big
Take a limit for n
So your Δt will be x/n
kind hawk
view the left side as a function of x. for simplicity just call it f(x). you can calculate f(x) for any arbitrary x just by the standard trapezoid rule. and then you want to find the x with f(x)=1. for that you can use your standard equation solve algorithm like eg newton
helps that due to FTC the derivative f'(x) is easy to calculate there
trail cloak
Ooo
kind hawk
but well you could also just solve this analytically
trail cloak
That's for the Python algorithm?
obtuse pebbleBOT
@little steeple Has your question been resolved?
merry vault
\begin{align*}
\sum_{n=0}^\infty \dfrac{5+(-1)^n}{3^n}
&= \sum_{n=0}^\infty \dfrac{5}{3n} + \dfrac{(-1)^n}{3^n}\
&= \sum_{n=0}^\infty \dfrac{5}{3n} + \left(-\dfrac{1}{3}\right)^n
\end{align*}
obtuse pebbleBOT
\begin{align*}
\sum_{n=0}^\infty \dfrac{5+(-1)^n}{3^n}
&...
warm shaleBOT
madmike
merry vault
The (-1/3)^n is a geometric series, but I am not sure what to do with the 5/3n
Any idea?
wild swallow
it should be 5/(3^n)
merry vault
oh 🤦♂️
warm shaleBOT
madmike
merry vault
alright but I am still not sure what to do with the 5/3^n 😄
final hornet
alright but I am still not sure what to do with the 5/3^n 😄
take 5 out of the sum
wild swallow
imagine
warm shaleBOT
warm shaleBOT
madmike
merry vault
alright I assume this is correct
final hornet
alright I assume this is correct
in order to distribute the infinite sum into two infinite sums, you must check that the two infinite sums converge I think
the property infinite_sum(a_n+b_n) = infinite_sum(a_n) + infinite_sum(b_n) needs an assumption
timid silo
I mean $|r| < 1$ so he is fine I think
warm shaleBOT
♡LexQa♡
merry vault
Oh okay
final hornet
I mean $|r| < 1$ so he is fine I think
yes but he should mention it
merry vault
The exercise says "find the limit of the following convergent series"
merry vault
I should mention that I guess?
wild swallow
final hornet
I should mention that I guess?
yes you should, but probably your teacher won't double down on it
final hornet
The exercise says "find the limit of the following convergent series"
even better : your sum is equivalent to the sum of 5/3^n when n goes to infinity, since they're both positive, and 5/3^n converges, your sum also converges and has the same limit
no need to play with sums at all
I assume here that you studied equivalence
final hornet
but what about (-1)^n
it's a negligible term when n goes to infinity, but sounds like you didn't study equivalence
merry vault
probably not
glossy ridge
i need some help
merry vault
we learned that (-1)^n diverges or something because it changes sign forever
final hornet
we learned that (-1)^n diverges or something because it changes sign forever
yes that's true.
but I was talking about someth else
never mind
your solution above is true
merry vault
oh you mean because it doesn't grow and is either 1 or -1 so you kinda ignore it?
idk not sure if we can do that yet
final hornet
oh you mean because it doesn't grow and is either 1 or -1 so you kinda ignore it...
yeah pretty much
if you didn't study it in class forget it for now
it"ll come anyways
merry vault
okay thank you
final hornet
Yw !
final hornet
apparently this diverges
this is very counter intuitive
actually the sum behaves like the logarithm function log(n), but this is equivalence again lol
final hornet
indeed
warm shaleBOT
madmike
warm shaleBOT
madmike
worthy moth
obtuse pebbleBOT
nocturne sun
so let's say x(t) gives the height of the rocket at the time t
then x''(t) = c is your acceleration
x'(t) = ct + v_0 is the velocity if you integrate it once
rocket starts at rest so initial velocity v_0 should be 0
x(t) = (c/2)t^2 + x_0 is the height function, we start at ground level so the initial position x_0 is also 0
so you really have x(t) = (c/2)t^2 where c is your acceleration
from there you can solve for x(10) = 100 since you want the rocket to be at 100 m after 10 seconds
worthy moth
I've got these equations
V = u + at
S = 1/2(u + v) * t
S = ut + 1/2at^2
S = ((u + at) / 2) * t
Which one would I use?
nocturne sun
I've got these equations
what's S and u in these?
I assume a -> acceleration, V -> velocity and t -> time
obtuse pebbleBOT
@worthy moth Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
urban anchor
can someone help me interpret a two tail t test pls
obtuse pebbleBOT
can someone help me interpret a two tail t test pls
urban anchor
this is my findings
do we take the absolute value of the t stat?
and how do we interpret the t stat and the two tailed p valye
obtuse pebbleBOT
@urban anchor Has your question been resolved?
obtuse pebbleBOT
@urban anchor Has your question been resolved?
obtuse pebbleBOT
@urban anchor Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
timid silo
how do you find the antiderivative of sec^2(x) here to be tan?
obtuse pebbleBOT
how do you find the antiderivative of sec^2(x) here to be tan?
timid silo
i am unfamiliar with trig antiderivatives
I mean you are meant to know your derivatives by this point if you are taking integrals
tardy epoch
differentiate sin(x)/cos(x)
warm shaleBOT
riemann
fierce lagoon
$\int\sec^2(x)dx = \tan(x) + C$
warm shaleBOT
Umbraleviathan
fierce lagoon
that is tan(x)
Also no
fierce lagoon
**riemann**
This doesn't equal to tan(x)
timid silo
how are u guys writing in latex so fast 
tardy epoch
that is tan(x)
did you answer my question?
fierce lagoon
how are u guys writing in latex so fast <:glassescat:1037770587235434567>
We skilled
I go crazy on mobile
You can also just go to desmos, type it out, copy paste
But I don't have that luxury when I'm on mobile
tardy epoch
$\frac{d}{dx} (\tan(x)) = \frac{d}{dx} \left(\frac{\sin(x)}{\cos(x)}\right) = ?$
fierce lagoon
Like 90% of the time I'm here
warm shaleBOT
riemann
obtuse pebbleBOT
@timid silo Has your question been resolved?
timid silo
ok i feel like my knowledge of trig functions is literally 0 after seeing all these stuff
.close
rare oak
can someone please check if this is right? Thanks a lot!
obtuse pebbleBOT
can someone please check if this is right? Thanks a lot!
dark stirrup
It is not
dark stirrup
Did they say why?
rare oak
no
dark stirrup
Well, real quick, how did you get isosceles and right?
rare oak
I got isosceles as when I used distance formula for 3 sides I found that 2 are equal so I though isosceles and right because I assumed it was right by the image.
dark stirrup
Well if it were a right triangle, how could you prove it?
You found the length of the 3 sides, so what could you do?
rare oak
right triangle therom or if there is a right triangle sign
dark stirrup
you mean Pythagorean theorem?
rare oak
yea
dark stirrup
yeah that'll work
dark stirrup
bro it's been 2 minutes
rare oak
oh lol sorry
dark stirrup
Anyway, I was saying, you should prove whether it is right or not
rare oak
and I cant at the moment
rare oak
cause it doesnt prove
dark stirrup
How does it not prove?
rare oak
ik its for sure isoceles but I dont think its right
dark stirrup
Well... If you checked with PYTHAGOREAN THEOREM, you could figure out if it was a right triangle.
rare oak
then why did someone say its wrong bruh most be whack
dark stirrup
Yeah no idea why they said you were wrong.
rare oak
werid
dark stirrup
But at least now you did better than guessing and proved it was a right triangle.
rare oak
yea
dark stirrup
Shouldn't just guess.
rare oak
thanks
dark stirrup
My teacher used to call that the "looks-like theorem"
rare oak
cool
rare oak
But at least now you did better than guessing and _proved_ it was a right triang...
thanks again man!!
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
timid silo
obtuse pebbleBOT
timid silo
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
rigid ginkgo
Give a 95% upper confidence interval for a new parameter defined as e^µ
obtuse pebbleBOT
Give a 95% upper confidence interval for a new parameter defined as e^µ
rigid ginkgo
What are some approaches for this? My currently thought is to look for a pivotal quantity, but I can't find one
obtuse pebbleBOT
@rigid ginkgo Has your question been resolved?
timid silo
No yz plane @wary vigil
obtuse pebbleBOT
No yz plane <@160921656313905152>
timid silo
Change the following into spherical coordinates
Limits are in dz dy dx order
For z: 2-sqrt(4-x^2 -y^2) to 2+sqrt(4-x^2 -y^2)
For y: - sqrt (4-x^2) to sqrt(4-x^2)
And for x: -2 to 2
Can someone please tell me how to figure out range of phi
And theta is on xy plane
Wait
Coordinates are: (p, phi, theta)
<@&286206848099549185>
obtuse pebbleBOT
@timid silo Has your question been resolved?
real reef
how did they get that
obtuse pebbleBOT
how did they get that
real reef
I keep doing Second fuction SHIFT E^-6
then it gives me like
2.478752177x10-3
nvm
moved decimal 3 places and rounded
obtuse pebbleBOT
Available help channel!
timid silo
obtuse pebbleBOT
timid silo
how do people find -4y^2+4y+3 = -(4y^2-4y+1-1)+3 ?
When this is what happens when I try to complete the square
solar hornet
this doesn't make sense to me
timid silo
this doesn't make sense to me
What part?
solar hornet
what do you want to achieve here?
warped agate
first divide by coefficient of y^2 term
timid silo
first divide by coefficient of y^2 term
Or are you reffering to something else?
timid silo
Yes
warped agate
timid silo
Tve?
solar hornet
how do people find -4y^2+4y+3 = -(4y^2-4y+1-1)+3 ?
okay, I'm not entirely sure what this has to do with completing the square, but the only thing they did there was pull out -1 and add "+1 -1"
timid silo
Ok
Does not seem to be right
It's supposed to complete into -(2y - 1)^2 + 4
@warped agate
Thats what I got
Seems to be what you did
I think I got it
thanks
.close
still lily
obtuse pebbleBOT
still lily
Would someone mind helping me with this
slender badge
look at triangle ABD
alternatively, in a parallelogram, opposite angles are equivalent
so DAB and DCB are the same angle
obtuse pebbleBOT
@still lily Has your question been resolved?
winged otter
I just need someone to vc with I can screenshare and show you the stuff if you can help me with it (Algebra 2)
obtuse pebbleBOT
I just need someone to vc with I can screenshare and show you the stuff if you c...
slender badge
i can't do vc but if you write out your question i can answer it
timid silo
What are 2 numbers that add to get 6 and multiply to get 8
winged otter
4, 2
timid silo
So what does x^2+6x+8 look like factored
winged otter
I really need someont o vc though it's hard for me to focus when typing
livid phoenix
obtuse pebbleBOT
livid phoenix
can anyone help me solve this?
cursive coyote
livid phoenix
.close
opal cobalt
Hello I think I am doing something dumb. I'm trying to find all the 0s and I can figure out how to factor 4x^3 + 12x^2-x-3
obtuse pebbleBOT
Hello I think I am doing something dumb. I'm trying to find all the 0s and I can...
opal cobalt
Can't figure out*
narrow vault
rational root theorem gives you a root reasonably quick i think?
by eye with how large the first 2 terms are you roughly have an idea :p
narrow vault
2 is a root in your original polynomial
opal cobalt
I got the root I just cant break up the quotient
narrow vault
now that you've reduced it to a cubic you can do rational root theorem on the cubic
narrow vault
yes
obtuse pebbleBOT
can someone tell me how you get from line 2 to 3?
obtuse pebbleBOT
@austere crater Has your question been resolved?
neon eagle
can someone tell me how you get from line 2 to 3?
is where it says LHS line 1?
neon eagle
ok ok
tardy epoch
They split each term in parentheses on line 2 into two sums on line 3
$k^2 + 2k + 2 = (k^2 + 1)+(2k+1)$
warm shaleBOT
riemann
austere crater
They split each term in parentheses on line 2 into two sums on line 3
it works for that one but the rest tho...
neon eagle
yeha thats what im saying
warm shaleBOT
riemann
neon eagle
you sure?
austere crater
ik from line 3 to 4 (k^2+1)+(k^2+2)+(k^2+3)+...=k^3+(k+1)^3
tardy epoch
Because the last one on that line is 2k+1
austere crater
alright
neon eagle
oh wait you're right
austere crater
but then would it make sense from like 3 to 4?
wait it is 2n+1
@tardy epoch hey do you know how you get from line 3 to 4?
tardy epoch
<@261933205387477002> hey do you know how you get from line 3 to 4?
That's the inductive hypothesis
If you mean 3rd equal sign to 4th
neon eagle
and if u sum all 2n+1 k times would that equal (2n+1)^2?
if k=2n+1 then yeah
austere crater
if k=2n+1 then yeah
yeah alright ty
obtuse pebbleBOT
Available help channel!
jade hedge
How to solve this plz help
obtuse pebbleBOT
How to solve this plz help
gilded needle
use a calculator?
jade hedge
Calci not showing proper ans
narrow vault
that's disgusting, plug it straight into a calculator
royal basin
define "proper answer"?
jade hedge
Try it in calci if u got 52.29 let me know how
narrow vault
,w 0.36 * (159043.1282/107521.0086 - 1) * 25/415
warm shaleBOT
narrow vault
every term is smaller than 1, you're not gonna get 52.29
jade hedge
I will send u full que then let me know how that ans came
Plz check this I think now u will understand the equation
jade hedge
That's y I need ur direction
narrow vault
rearrange the inequality to have nothing but pitch on one side
narrow vault
plug what's on the other side into the calculator
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
quaint finch
obtuse pebbleBOT
lost tree
Well just try putting in some values ig
What happens when n=1, n=10, n=539201
What happens when n=-5, n=-610.6482
copper spade
9 is like
If n is not 0
Then n either is positive or negative
Let the no. Be x
If n= positive x
Then |x|/x
=x/x
=1
And if n=-x (negative no)
Then
|-x|/-x = x/-x = -1
So either 1 or -1
hollow vessel
What happens when n=-5, n=-610.6482
copper spade
Like that ig
hollow vessel
It's either 1 or -1 in 9
copper spade
Guess I was speaking urdu Or something the whole time.
@hollow vessel and refrain giving direct answers
Explain bro
hollow vessel
Okay..
copper spade
In no.10
Ya don't want to get 0 in the denominator, or it will become undefined, so x≠2
Now ya know
hollow vessel
n > 0 => Both are positive => n/n = 1
n<0 => lower is negative => positive divided by negative gives negative => n/-n = -1
copper spade
Now ya know
X cannot be 2, so x is more or less than 2
Let's take neighbors of 2
1 and 3
Wait we just need to tell which value of x is not possible in 10.
Nvm
Its x≠2 coz if ya put x=2 in no. 10,the denominator becomes 0 and hence its undefined
copper spade
So maybe u also do want to talk abt the neighbors
HELLO NEIGHBORS
Me go for now
Got exams tmr
Y'all take over for no. 10
lost tree
Well 10 is just the same thing as 9
obtuse pebbleBOT
@quaint finch Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
elfin galleon
hi
elfin galleon
i need a help with my simplifiaction
how do i simplify the term 6 as numerator and 10 as denominatoor
it seems impossible
no table can do it
lost tree
how about the 2 times table
inland ingot
how do i simplify the term 6 as numerator and 10 as denominatoor
both have common factors
lost tree
try writing the first few numbers in the 2 times table
inland ingot
how 10 will come in 2?
I dunno if you're trolling but try dividing 10/2
lost tree
🙄
elfin cipher
how do i simplify the term 6 as numerator and 10 as denominatoor
bro go get a lyf
obtuse pebbleBOT
@elfin galleon Has your question been resolved?
elfin galleon
.close
timid silo
obtuse pebbleBOT
timid silo
you finna help me or not dawg
warped agate
i thought this server was smart
bud u dont wanna go down that route
tacit gate
"this server" is not a person
timid silo
helps at the a sectionth
pleath at the most prithee
i shall pleath shut the f up you uhelping me or not
tacit gate
xD
kids these days
won't read their book and ask for a free solution
go sit your ass down like everyone else learn what a median means and figure it urself
timid silo
dang you dum asf
tacit gate
yeah you are the dum asking for help tho
fiery olive
dang you dum asf
You're smarter than me, can you help me answering my question 😦
tacit gate
like imagine being asked to find the median when given a simple graph
and still you need help
to read what the question says
take the L
learn this and this time don't sleep on it like you did in class
timid silo
learn this and this time don't sleep on it like you did in class
I know they are being immature and they did start it, but there is no need for the personal insults. Take the high road dude and just give the help you wanted to give
tacit gate
I know they are being immature and they did start it, but there is no need for t...
that's not just immature but anyway it is what it is
obtuse pebbleBOT
@brittle swift Has your question been resolved?
pearl steeple
obtuse pebbleBOT
pearl steeple
Why -2/3
warm shaleBOT
rotund rune
yep
pearl steeple
yup 1+1/3
rotund rune
should be 4/3
pearl steeple
why ?
rotund rune
ibp then u substitution
rotund rune
$\int xe^{2x}\mathop{dx} = \frac{xe^{2x}}{2}-\int \frac{e^{2x}}{2}\mathop{dx}$
warm shaleBOT
nichoals
pearl steeple
1/2
rotund rune
then on the rhs, let u = 2x => du = 2dx ==> dx = du/2
then just plug in the upper and lower bounds and subtract them
pearl steeple
but here it become e^2x/4
rotund rune
should be (e^2+1)/4 though
$\frac{xe^{2x}}{2}-\frac{e^{2x}}{4}=\frac{(2x-1)e^{2x}}{4}$
warm shaleBOT
nichoals
pearl steeple
why e^2x/4
rotund rune
then on the rhs, let u = 2x => du = 2dx ==> dx = du/2
rotund rune
$\int f\mathop{dg}=fg-\int g\mathop{df}$, remember?
warm shaleBOT
nichoals
rotund rune
since f = x, df = 1. dg = e^2x, g = e^2x/2
so, fg = xe^2x/2
$\int xe^{2x}\mathop{dx} = \frac{xe^{2x}}{2}-\int \frac{e^{2x}}{2}\mathop{dx}$
warm shaleBOT
nichoals
rotund rune
then g df is e^2x/2
then use u-substitution with u = 2x
du = 2 dx => dx = du/2
$\int \frac{e^{2x}}{2}\mathop{dx}=\int \frac{e^u}{2}\frac{\mathop{du}}{2}=\frac{1}{4}\int e^u\mathop{du}.$
warm shaleBOT
nichoals
pearl steeple
rotund rune
no no
rotund rune
**nichoals**
integral of xe^2x is this
didnt you see what i've typed so far?
since f = x, df = 1. dg = e^2x, g = e^2x/2
so, fg = xe^2x/2
then g df is e^2x/2
then use u-substitution with u = 2x
du = 2 dx => dx = du/2
$\int f\mathop{dg}=fg-\int g\mathop{df}$, remember?
warm shaleBOT
nichoals
fathom belfry
obtuse pebbleBOT
fathom belfry
Can someone help me understand the question?
I know its chain rule
But I do not understand the question
cedar lichen
What have you tried
patent jetty
Did u take derivative
warped agate
take derivative using chain rule
fathom belfry
of the small f?
cedar lichen
If F(x) = f(³√x + 7), what's F'(x)?
fathom belfry
f'(³√x + 7)* the derivative of ³√x + 7
unreal musk
f'(³√x + 7)* the derivative of ³√x + 7
The latter being?
fathom belfry
1/3x^(-2/3)
unreal musk
Cool, now piece it all together...
unreal musk
but we dont have f'(8) tho?
When $x=8$, $\sqrt[3]{x} + 7$ is what?
warm shaleBOT
chartbit
fathom belfry
9
unreal musk
...
unreal musk
but we dont have f'(8) tho?
Why did you say f'(8)?
fathom belfry
because the question is asking for F'(8)
unreal musk
...Earlier, you told us, basically, that $F'(x) = f'(\sqrt[3]{x} + 7) \cdot \frac{1}{3} x^{-2/3}$, did you not...
warm shaleBOT
chartbit
unreal musk
Then show me how you'd work out $F'(8)$, knowing that?
warm shaleBOT
chartbit
fathom belfry
the derivative of the outside function * the derivative of of the inside function?
unreal musk
**chartbit**
Use what you just worked out here
unreal musk
Then show me how you'd work out $F'(8)$, knowing that?
Relate it to this
fathom belfry
Let me review chain rule rq
cedar lichen
Let me review chain rule rq
F'(8) means you plug 8 in for x into F'(x)
And you know what F'(x) is
fathom belfry
And you know what F'(x) is
is it a composite function?
acoustic rune
Hi Can someone help me ?? But its in polish
cedar lichen
F'(8) = ?
fathom belfry
oh
oh so like
the derivative of the outside function * the derivative of the inside function
Got it
.close
karmic vine
I'm stuck on this problem where all you're given is the triangles PSR perimeter is 24cm and you have to find SM. The sides of the triangle are even because of the colliding points of the circle from the same point. (colliding with the outskirt.) And then there is also K which also collides with the outside of the circle.
obtuse pebbleBOT
I'm stuck on this problem where all you're given is the triangles PSR perimeter ...
timid silo
karmic vine
it's for triangle?
oh wait those
that means they are even
because they go from the same point those SR and SP are even in lenght
mighty geyser
seems to be a somewhat confusing way to say "the same"
karmic vine
yea
mighty geyser
nonnative i suppose?
mighty geyser
why do SR and SP have the same length?
karmic vine
It's a rule about the touching lines of the circle
if it's from the same point they are even
mighty geyser
is SP tangent to the circle?
well the line is, but the line segment SP doesn't touch the circle
karmic vine
is SP tangent to the circle?
Without using word tangent?
mighty geyser
the English word is tangent
karmic vine
oh wait I think it is yes
mighty geyser
does the line segment SP touch the circle?
karmic vine
SP itself does not but it is a part of SM that does
mighty geyser
so the segments which have the same length are...?
karmic vine
SP and SR because SM and SN are tangent from the same point
mighty geyser
can you apply this idea 2 more times?
karmic vine
I now have this
But all I have for numbers is the perimeter of PSR so I don't think that really helps
karmic vine
can you apply this idea 2 more times?
wha huh
mighty geyser
you applied it to SM and SN
can you apply it 2 more times? where else can you find other lines touching the circle?
karmic vine
mp and kp are the same
rk and rn are the same
but I don't know how that helps me ._.
mighty geyser
maybe try writing down what you have and see if you can make any progress algebraically
obtuse pebbleBOT
@karmic vine Has your question been resolved?
mighty geyser
actually you have enough information from what you shown in the diagram
the problem is using it
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
simple thorn
obtuse pebbleBOT
unreal musk
Expand out (x-1)^2
unreal musk
,w expand (x-1)^2
warm shaleBOT
simple thorn
did the 1 just spawn there?
either way if my calculator will give me that result then im fine ig
thanks
.close
obtuse pebbleBOT