#help-10

1 messages · Page 74 of 1

bold bane
#

Which problem are you working on?

tough hull
#

The second pic 3 first question

bold bane
#

Are you familiar with the Inscribed Angle Theorem?

tough hull
#

Yea I know circle theorems

bold bane
#

Ok, I'm going to name the vertices of the triangle for c) and d) as A, B, and C from left-to-right.

#

What would the measure of the arc be for arc AB?

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My pen died on me otherwise I would write it out on a graph.

tough hull
#

Im looking for a and b not c and d

bold bane
#

So you are looking for angle c.

#

If you know the arc measure of BC, you could find angle c.

#

To find the arc measure of BC, find the arc measure of AB.

#

Because AC is a diameter line, you can find arc BC that way.

tough hull
#

Ok but I'm talking about my equation and how far we get in theroems in the book

bold bane
tough hull
#

I did 90 - 42

#

= 48

bold bane
#

For a and b.

tough hull
#

Yeah

bold bane
#

So you've found b.

#

Have you found a?

spring trail
#

@tough hull

#

alpha = 50?

tough hull
#

Yes it's 50 but how do thy get there

bold bane
#

Find the measure of the corresponding arc for angle b.

spring trail
#

oh i didnt even zoom enough its just a

spring trail
tough hull
#

A is already given b is the one I found and c is the one I have to find idk how to measure arc @bold bane

bold bane
#

That will give you the angle from the center of the circle.

spring trail
#

yeah he probly doesnt

#

either way

#

its either through teh isosceles triangle i told u earlier about

#

and the answer in your book is sadly wrong

#

a=42

#

check out a video on isosoles triangle if u really dont get iit

tough hull
#

Nah its not wrong the answers are know to be accurate

#

a is 42 b is 48 and c is 50

bold bane
#

Do you know what arc measure is?

tough hull
#

Nope

#

Nvm I saw the answers and a and b are 42 and 48

#

The angle I was talking abt doesn't have a letter

bold bane
#

Arc measure is the angle of an arc from two points on the circumference of a circle with the apex at the origin.

tough hull
#

Ok

bold bane
#

The Inscribed Angle Theorem states that if you have a third point outside of that arc on the circumference of the same circle, the angle is equal to half of the measure of that arc.

#

Reload the link for the Geogebra file.

obtuse pebbleBOT
#

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quasi rapids
#

Hi, pretty easy question I just want to double check

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tawny pulsar
#

Question and my working so far not sure what to do from here

tawny pulsar
#

got x=2y and not sure how to show it has one stationary point

obtuse pebbleBOT
#

@tawny pulsar Has your question been resolved?

obtuse pebbleBOT
#

@tawny pulsar Has your question been resolved?

obtuse pebbleBOT
#

@tawny pulsar Has your question been resolved?

obtuse pebbleBOT
#

@tawny pulsar Has your question been resolved?

mint tendon
#

you have two systems of equations

#

two variables

raven spire
tawny pulsar
mint tendon
tawny pulsar
#

and how would that show there is only 1 stationary point? sorry im new to differentiation

mint tendon
#

a stationary point is defined as the point where the derivative is 0

#

in this case its a function of two variables

warm shaleBOT
tawny pulsar
mint tendon
#

the only real solution for y is 1

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so theres only one pair (x,y)

#

that works

tawny pulsar
#

ok tysm for the help sorry it’s such a basic question

#

.close

obtuse pebbleBOT
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restive pilot
#

How would I solve this?

obtuse pebbleBOT
restive pilot
#

finding both an upper and lower limit to x?

cedar lichen
#

What have you tried

restive pilot
#

well I mutiplied it out

cedar lichen
#

You don't have to do that

restive pilot
#

and factorised the x^3 out

cedar lichen
#

Let's just say x³ - 3 = t

#

So t² ≤ 4

#

So what range could t be in

restive pilot
#

I can just take the square root...

cedar lichen
#

Be careful when you do

restive pilot
#

yeah inequalitites are wild

#

would be my next question what do I have to watch our for?

cedar lichen
#

Well, what do you get when you solve t² ≤ 4?

restive pilot
#

t<2 and -t>2

#

both euqal and even

cedar lichen
#

You sure?

restive pilot
#

not really

cedar lichen
#

Explain your answer

restive pilot
#

well the first seems fine to me just taking the positive answer

#

and for the negative answer I would swap the sign, cause of the negative

cedar lichen
#

So -t > 2 --> t < -2?

#

The union of t < 2 and t < -2 is just t < -2

#

(-3)² is not ≤ 4 though

#

You flip the sign when you multiply or divide by a negative

#

You don't flip the sign when a negative just appears

restive pilot
#

yeah would have been my idea xD

cedar lichen
#

You can also think of it like √t² = |t|

#

So t² ≤ 4 --> |t| ≤ 2 --> -2 ≤ t ≤ 2

restive pilot
#

I should think myself a little bit more. Thanks for the help chief love

cedar lichen
#

Now, t = x³ - 3

#

You can treat each inequality seperately

#

Or, if you know what you're doing, you can do them both at once

restive pilot
#

yeah now its easy

#

$$1 <= x <= (5)^{1/3} $$

warm shaleBOT
#

Eichhorst

restive pilot
#

.close

obtuse pebbleBOT
#
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supple epoch
#

Let $c > 0$ be chosen arbitrarily and $b_0 \in ]0,\frac{1}{c}[$ given. For $n \in \mathbb{N}$ we set $b_{n+1} := 2b_n - c(b_n)^2$. Find out whether it's convergent or not, and if so, find its limit.

warm shaleBOT
#

Levens

supple epoch
#

I dont understand the notation for $b_0$... isnt that an open interval?

warm shaleBOT
#

Levens

supple epoch
mint tendon
#

lmao it looks like a misatke

#

the universally accepted symbol for open interval is ()

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oh wait nvm

#

apparently it is open interval

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wtf

supple epoch
#

ya i think my professor is extra

mint tendon
#

thats horrible notation lol

supple epoch
#

lol

#

but hows that comprehendable for recursive sequences

warm shaleBOT
supple epoch
#

i mean like in context to the question

mint tendon
#

well i'll just give a little intuition to what this could converge to

warm shaleBOT
mint tendon
#

and decreasing everywhere else

warm shaleBOT
obtuse pebbleBOT
#

@supple epoch Has your question been resolved?

obtuse pebbleBOT
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drifting prairie
#

What does this mean

obtuse pebbleBOT
raven spire
#

means you put "y" in place of all the "x"s in the function...
You're given M(x, y) and you need to figure M(y, y)

drifting prairie
#

also what does this notation mean

#

and this

#

@raven spire

raven spire
#

partial derivatives with respect to the respective variable

drifting prairie
obtuse pebbleBOT
#

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stable rain
#

given H <= G, for any coset gH=C, where g in G, is it true that for any c in C, cH = C?

stable rain
#

ok thanks

#

hm?

gilded needle
#

you can characterize gH as "the coset of H that contains g"

#

so if c is any element in gH, then cH = gH

#

the last equality could simply be read as "the coset containing c is the same as the coset containing g", i.e. c and g are in the same coset

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#
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green field
obtuse pebbleBOT
gilded needle
#

where are you stuck?

stable rain
#

the left u can find some value

#

the right ull get some value in terms of y

#

equate n solve for y

green field
#

Got it, thanks a lot everyone
I was just overthinking this

#

.close

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frozen aurora
#

Could anyone please help me top solve this?

obtuse pebbleBOT
stable rain
#

try guessing some groupings

frozen aurora
#

I've tried to solve this using all the techniques I know, and I can't get it right.

stable rain
#

so weve

#

8x^2+10x+3=

#

(ax+b)(cx+d)

#

ac=8

#

bd=3

#

so over ints

#

bd can be (1,3)

#

ignoring order

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ac can b

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(1,8)
(2,4)

#

just guess around

frozen aurora
#

thank you

#

.stop

stable rain
#

np

#

.close

obtuse pebbleBOT
#
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stable rain
#

is the command

#

💕

frozen aurora
#

Oh

#

cool

#

sorry

#

'close

#

.close

stable rain
#

i closed it alr

frozen aurora
#

Imma slow

#

lol

#

ttyl

obtuse pebbleBOT
#
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weary quarry
#

how would you write this in predicate logic, if two numbers multiplied by 3 are equal then they are the same number?

trail musk
#

3x = 3y <=> x=y

twin sapphire
#

$\forall (x,y) \in \mathbb{R}^2 , 3x=3y \implies x=y$

warm shaleBOT
#

Benjamin

weary quarry
#

thanks

obtuse pebbleBOT
#

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broken jay
obtuse pebbleBOT
raven spire
# broken jay

y = 3x - 12; x + 6x - 24 = 7 => 7x = 31 => x = 12; y = 24

broken jay
#

im kinda confused

#

did we skip a few steps

ocean nexus
#

what does mod mean

broken jay
#

modular

#

eg 6 mod 3 would be 0

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7 mod 3 = 1

#

remainders essentially

zenith raft
#

and in the way it's used in the problem, a ≡ b mod n means a and b leave the same remainder when divided by n

broken jay
#

yeah this problems got me stumped tho

ocean nexus
#

i only know how to solve the system of equation lol

obtuse pebbleBOT
#

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cunning berry
obtuse pebbleBOT
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@cunning berry Has your question been resolved?

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zenith raft
#

<@&268886789983436800>

obtuse pebbleBOT
#
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fierce lagoon
zenith raft
#

just ignore it

obtuse pebbleBOT
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dim copper
obtuse pebbleBOT
dim copper
#

is A = 4/7

#

i.e. the total height divided by total length ?

solar hornet
#

hold on

dim copper
#

the only info I have to go on is the height (144) and the length (252) of the mountain

#

I figure it has something to do with that

solar hornet
#

yeah it's a function where y = 144 and x=252

#

they even drew the mountain on the graph, which is pretty funny

#

what you can do is put these numbers into the equation to solve for A

#

I tried doing that but the answer isn't as pretty as I expected

dim copper
#

oooh ic

#

ty

obtuse pebbleBOT
#

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gaunt iris
obtuse pebbleBOT
gaunt iris
#

A cone and a sphere have the same volume.
The radius of the cone,
r
, is
1/4
that of the sphere.
Find an expression for the height of the cone,
h
, in terms of
r
.

timid silo
#

has same volume??

gaunt iris
#

yup

timid silo
#

ok

#

h =256r

gaunt iris
#

thanks

timid silo
#

no

gaunt iris
#

yea its not

timid silo
#

now is true

#

h = 256r

#

hey is it true??

gaunt iris
#

not sure

timid silo
#

4/3 pi (4r)^3 = (h pi r^2)/3

#

then

#

h = 256r

#

i'm sure is true

gaunt iris
#

Alright thanks

timid silo
#

oh

gaunt iris
#

??

timid silo
#

the volume of cone is (pi * r^2)/3

gaunt iris
timid silo
#

h = 256 r

#

not 64

gaunt iris
#

thanks

solar hornet
#

find the volume of the sphere first

timid silo
#

guys help me

solar hornet
#

you know the height of that blue cylinder inside

#

@timid silo find your own channel this one is occupied

timid silo
#

ok

#

but how

solar hornet
#

look at math help available

#

on left

gaunt iris
#

i got 268

#

for the sphere

solar hornet
#

ok I think best approach is to turn the volume of the sphere, into a cylinder with diameter 12cm

#

find it's height

#

once you do, add it to the height of that blue cylinder

gaunt iris
#

its water and you have to work out how high up the water will reach after its submerged

solar hornet
#

i know

#

the volume will increase exactly by the volume of the sphere, so you can just fit the sphere into that cylinder

#

and check the overall height

#

another way to explain, if you find a cylinder of diameter/width 12 cm that has the same volume as that sphere

#

you can check it's height, add it to the height of the blue one, and that's the total height the water will reach

gaunt iris
#

alr thx

obtuse pebbleBOT
#

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solemn ravine
#

Any tips on how to solve this? Tau is the number of divisors of d

solemn ravine
#

(Solve, as in, find one natural number n)

royal basin
#

let n = prod p_i^a_i

how can this sum be expressed in terms of the a_i?

solemn ravine
#

do you mean d = prod p_i^a_i? because then we can use tau(d) = prod (a_i + 1)

#

which would give a sum in terms of a_i

royal basin
#

no, i mean n.

#

all of its divisors are then prod p_i^b_i with 0<=b_i<=a_i

#

i think this sum may have a nice expression

solemn ravine
#

gimme a sec to play around with this

solemn ravine
royal basin
#

i have a feeling that this sum of products is actually the product of triangular-number sums

obtuse pebbleBOT
#

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snow olive
#

Hello .. i was doing research on how to do math properly ... could you help with giving analogies to what the process is like? ... my closest guess is it is like passing axiom "objects" through logic circuits to explain theorems in the form of empirical mathematical observation ... somewhat like how a circuit is built in a computer ... What is your own personal experience with this?

obtuse pebbleBOT
#

@snow olive Has your question been resolved?

snow olive
#

<@&286206848099549185>

solar hornet
#

well math is fundamentally based on logic, yes

#

but this part.. "empirical mathematical observation", why call it empirical? it's like the opposite of what math is

#

sure, you can notice something and reverse-engineer it but that's not what math truly is, imo

#

and rarely this observation is empirical.. it's just observation and pattern recognition

snow olive
#

thanks!

#

.close

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sage dagger
#

if im trying to calculate <ABN what am i looking for i dont understand

royal basin
#

microsoft paint has straight line and text tools, for future reference.

sage dagger
#

🤦‍♂️

#

so what am i trying to find if it asks to calculate ABN?

royal basin
#

angle ABN?

sage dagger
#

yes the

#

<

royal basin
#

$\angle ABN$

warm shaleBOT
sage dagger
#

yes

royal basin
#

are you saying you don't know what "angle ABN" refers to?

sage dagger
#

i know what its talking about but what am i trying to find here

royal basin
#

you are trying to find this angle

#

the measure of this angle, if you want to go technical.

#

i've recreated your diagram, by the way.

sage dagger
#

nice

#

this ?

#

or

royal basin
#

yes.

sage dagger
royal basin
#

angle ABN means the angle whose vertex is B and whose sides are BA and BN

#

no, this angle would be called BAN.

sage dagger
#

oh okay

royal basin
#

the middle letter in the name of an angle is always its vertex.

sage dagger
#

i see

#

alright

sage dagger
royal basin
#

first off, if you just want to ping me, then you can ping me. don't reply to a message that has nothing to do with your question!

sage dagger
#

ok

royal basin
#

and second, you can succeed with either one.

#

like, they'll require different inputs to produce what you actually need

sage dagger
royal basin
#

but there is no prohibition against one or the other for this problem
or any problem

royal basin
sage dagger
#

so if im doing sin-1 i am doing sin-1(3.6/9)

royal basin
#

well, is sin(ABN) equal to 3.6/9?

sage dagger
#

i think so

royal basin
#

and you are right to think so.

sage dagger
#

alright thanks

obtuse pebbleBOT
#

@sage dagger Has your question been resolved?

sage dagger
#

@royal basin the question says; in the triangle ABC, find cosx in terms of a and b

#

how would i do this?

#

cosx = cos(b/a) ?

royal basin
#

no

#

"cos(b/a)" is something you should not be considering in all honesty

#

with VERY VERY RARE EXCEPTIONS, it does not make geometric sense to take the cosine (or any other trig function) of a ratio of side lengths

#

anyway, identify the sides whose ratio is cos(x).

#

one of them will be the hypotenuse.

#

find a way to express the hypotenuse in terms of a and b, and you will be done

sage dagger
#

i think the cosx is throwing me

royal basin
#

throwing you how?

#

if you remember your SOH-CAH-TOA you should have no trouble writing down which sides' ratio equals cos(x).

sage dagger
#

confusing me like am i still considering the adjacent/hypotenuse

royal basin
#

sure you are. you just haven't written that down yet...

sage dagger
#

wait so

#

cos(b/ac

royal basin
#

no, bad!!!

#

the stuff that goes inside the cos function is an ANGLE!

#

ANGLES are INPUTS to trig functions!

#

cos(x) = AB/AC.

sage dagger
#

ohh

#

yeah i forgot about the AB and only looked at the b part

#

im not sure what the 57 is referring to

#

the outside angle of the inside angle

#

or like the inside inside angle

#

i need to find the distance of OA

#

so when i add up 59 + 57

#

i get 116 so then

#

180-116 = 64

#

wait

#

no

#

the 59 degrees is the whole <S

#

@royal basin i require your assistance once again

royal basin
#

im not sure what the 57 is referring to
it's referring to angle ASO, whose arc-mark it is right next to.

#

"angle S" is ambiguous in this picture. so you should not be saying that at all.

sage dagger
#

what does the double angle mean though

sage dagger
high lily
#

wdym by double angle

sage dagger
#

theres two of them

royal basin
#

no, there are simply two arc-marks,

sage dagger
#

im strictly looking at the bottom

royal basin
#

one of which refers to angle BSO and the other to angle ASO

sage dagger
#

ohhh

#

i get it now

obtuse pebbleBOT
#

@sage dagger Has your question been resolved?

obtuse pebbleBOT
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distant musk
#

what is linear combination in matrix or determinant? can anyone pls explain?

alpine raven
#

I wrote x as the linear combination of two vectors u and v

#

now for matrix, its basically the same thing, I can write a matrix as a linear combination of any vectors (if those vectors respect some property)

#

determinant is more of a multilinear map

obtuse pebbleBOT
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merry stratus
#

Is there any difference in solving a differential equation in f: I -> R or in f: I -> C?

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

#

@merry stratus Has your question been resolved?

wraith remnant
#

i need help for divisions

narrow vault
wraith remnant
#

@proven zephyr

merry stratus
#

.close

obtuse pebbleBOT
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timid silo
#

The winning numbers for the Lotto 6/49 are drawn from a clear plastic drum that contains 49 ping-pong balls numbered from 1 to 49. The order of selection does not matter. Once a ball is drawn from the drum, it is put on display. The process is repeated a total of six times. Leave your answers as fractions.

a. What is the probability of you winning the jackpot (matching all six numbers)?

b. What is the probability of matching only 3 numbers?

c. What is the probability of matching at least one number?

brisk oracle
#

ok.. how do you start

timid silo
brisk oracle
#

what aren't you sure about

timid silo
#

is the probability 2% * six times

brisk oracle
#

no, but where did 2% come from?

timid silo
#

1/49

brisk oracle
#

ah yea. no what you're saying is wrong. it would be correct if order mattered, and if a number could come up more than once

#

here order doesn't matter, and a number is only picked up once

timid silo
#

okay but how do I get the probability?

brisk oracle
#

you have to find out the total number of combinations of 6 elements from a set that has 49 elements

timid silo
#

do I need to use logic or is there a mathematical way of getting it

brisk oracle
#

both. but more importantly this should be in your book

#

there's a formula that tells us in how many ways we can choose k objects from a set that has n elements

timid silo
#

Okay I assume you're referring to combinations

brisk oracle
#

yep

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

#
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latent mesa
obtuse pebbleBOT
latent mesa
#

How did they get 1/3

#

the rest i understand but where did they get that number from

timid silo
#

1/3 πr^2h

obtuse pebbleBOT
#

@latent mesa Has your question been resolved?

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timid silo
#

what is the general solution for this equation?

#

is "1,54" the "b" constant??

#

is T the b/a constant ??

sage geode
#

Depends on what you mean by those

#

Nonetheless this is a separable differential equation

#

Divide both sides by what you have on the right hand side and integrate

timid silo
#

is this not newtons cooling law?

sage geode
#

Yes, and you're solving for T, right?

timid silo
#

ye, but i just cant see how that can turn into " y = b/a + e^(-ax)"

#

it dosent look like the "y' = b - ay " type diff equation

sage geode
#

$\frac{1.54 - 0.259(T - 22)}dT = dx$, integrate

wild swallow
#

rip bot lol

sage geode
timid silo
#

ah i see

#

i always have to expand the brackets?

sage geode
#

Not always

timid silo
#

Aight ty

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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timid silo
#

could someone explain why we have 2 base cases here

alpine raven
#

there is only 1

dark stirrup
#

What do you mean

alpine raven
#

hes talking about induction

timid silo
#

the solution gives 2 base cases where n = 1 and n = 2

alpine raven
#

well they just answered your question

timid silo
#

yea i dont really get it

alpine raven
#

n=1 is obvious so it shows nothing

timid silo
alpine raven
#

n=1 isnt enough tho

timid silo
alpine raven
#

I was wrong

timid silo
#

o ok

dark stirrup
#

Not to derail, but I find the solution approach kind of inelegant because you don't really need to prove n=2 as a base case. You could just go straight to n=k>1 induction case.

#

(Once you show true for n=1 still)

timid silo
#

i guess they showed n = 2 cuz they used it as their basis for the inductive step ig

alpine raven
timid silo
#

yea i meant about what swr said

timid silo
dark stirrup
#

You should. But I haven't written anything down yet so unsure if I'm missing anything subtle

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

.close

obtuse pebbleBOT
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timid silo
#

am i dumb or

obtuse pebbleBOT
timid silo
#

is the powerset of P(a x b) gonna be super huge if a = {1, 2} and b = {1,3}

sage geode
#

Its cardinality will be 4

#

Oh wait

teal prawn
#

2^4

sage geode
#

Power set of a powerset?

teal prawn
#

power set of a cartesian product

sage geode
#

They said "Powerset of P(a x b)"

teal prawn
#

ah

sage geode
#

Should be 2^16 then

teal prawn
#

yea it'll be big

sage geode
#

Well, if they didn't make typos

solar trellis
#

They most likely mean just P(A×B)

timid silo
#

like this is the question

timid silo
civic zealot
#

That's just the powerset of AxB

timid silo
#

yeah which is like

#

powerset of {(1, 1), (1, 3), (2, 1), (2, 3)}

civic zealot
#

yes

timid silo
#

is that not really big tho

civic zealot
#

its 16 elements. so not really big, probably tedious to write out

timid silo
#

uh im not sure if im doing it right

#

{empty set, {(1, 1)}, {(1, 3)}, {(2, 1)}, {(2, 3)}}

#

{empty set, {(1, 1)}, {(1, 3)}, {(2, 1)}, {(2, 3)}, {(1, 1),(1, 3)}, {(1, 1), (2, 1)}, {(1, 1), (2, 3)}, {(1, 3), (2, 1) }, {(1, 3), (2, 3)} , {(2, 1), (2, 3)}}

civic zealot
#

looks good so far

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

#
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remote vine
#

Can someone help me with a task i dont come further

ruby tapir
remote vine
#

Translation: 15 The graphs of f, with f,(x) - a -sin (x) and 8. with 8. (x) - - 1. sin (x) limit an area for x€ [0; mi). For which values of a is this area minimum? Specify the minimum content.

#

I understand what i should do, but the calculation is bullshit

#

Sorry for my bad writing

#

I write like shit

#

I have the solution but it doesn’t help me as i have some parts which i don’t understand and its not explained

#

@ruby tapir

obtuse pebbleBOT
#

@remote vine Has your question been resolved?

remote vine
#

Dumb question

#

Didnt even get a answer

obtuse pebbleBOT
#

@remote vine Has your question been resolved?

obtuse pebbleBOT
#
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uncut robin
#

how can I show that f(x)=f(x+kT) if f is a periodic function of period T. I just know that f(x)=f(x+T)

uncut robin
#

I think my professor said to use induction but have no idea how to

drifting badger
#

Hmm, I've never tried to use Induction on Integers before (I assume k is an integer). I guess the Induction Principle easily could be extended for this purpose.

Under induction for all natural numbers, you want to show for some predicate p(n) that p(1) is true and that if p(n) is true then p(n + 1) is true.

Extending this to integers for a predicate p(k), we could instead show that p(0) is true and from p(k) we can show that both p(k + 1) and p(k - 1) is true.

uncut robin
#

so for my case I would need to check if p(0) is true so f(x)=f(x+(0)T) which is obviously true

#

and then for k+1 so f(x)=f(x+T+kT) and for k-1 f(x)=f(x-T+kT)

#

but I have to prove those two equations to be true

#

right @drifting badger?

drifting badger
#

I think so

#

To show p(k) => p(k + 1), first we can assume f(x) = f(x + kT). From this we want to show that f(x) = f(x + (k + 1)T) will also hold

uncut robin
#

yup

drifting badger
#

We know from f(x) = f(x + T) that

f(x + kT) = f(x + kT + T).

From distributive axiom we then have that

f(x + kT) = f(x + kT + T) = f(x + (k + 1)T).

From our assumption p(k) is true, it holds f(x) = f(x + kT) and therefore from the equality above that

f(x) = f(x + (k + 1)T)

Therefore p(k + 1) holds to be true from p(k)

uncut robin
#

ohh we say k+1=n then p(n) holds because it's in the form of p(k)?

drifting badger
#

What do you mean k + 1 = n?

uncut robin
#

so like p(k) is true so f(x)=f(x+kT)
now to show that it holds for p(k+1) we do f(x)=f(x+(k+1)T)

#

but how do I show it holds

#

I have T multiplied by k+1 not just k

drifting badger
#

You stated in the beginning that we know f(x) = f(x + T). This means if we put x + kT into f we get f(x + kT) = f(x + kT + T)

uncut robin
#

that's what I was missing

#

thank you

#

a lot actually

#

.close

obtuse pebbleBOT
#
Channel closed

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drifting badger
#

Just a side note, you also need to show that p(k - 1) holds from p(k)

obtuse pebbleBOT
#
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inner terrace
obtuse pebbleBOT
inner terrace
#

how to do this?

timid silo
#

use the definition of linear independence

inner terrace
#

I did that

#

but how do I derive an expliciti equation which expresses and arbritary point

#

@timid silo

timid silo
#

a point (x,y) is in the span if there are real numbers a and b such that av_1+bv_2=(x,y)

#

we can solve the vector equation given explicit (x,y) since we have two equations and two unknowns (a and b)

inner terrace
#

but the unknowns are both 0's right?

timid silo
#

to check for linear independence, yes

#

but you are asking about an arbitrary point now

inner terrace
#

ah I see

#

so given any point x and y

#

so how do i do that

timid silo
#

solve the two equations for a,b in terms of x,y

inner terrace
#

so av1 + bv2 = (x,y)

timid silo
#

yeah

#

substitute in v1 and v2, then solve the pair of linear equations

inner terrace
#

wait what

timid silo
#

$a\begin{pmatrix}4\1\end{pmatrix}+b\begin{pmatrix}8\3\end{pmatrix}=\begin{pmatrix}x\y\end{pmatrix}$

warm shaleBOT
inner terrace
#

i have no clue how to solve for this

timid silo
#

if we had x=4 and y=1, would you know how to do it?

inner terrace
#

yes

timid silo
#

(oops bad example its v1 lmao)

timid silo
inner terrace
#

write it in augmented form?

timid silo
#

yeah

inner terrace
#

so like this

timid silo
#

$\begin{pmatrix}4&8&x\1&3&y\end{pmatrix}$

inner terrace
#

yeah

#

wait what

timid silo
inner terrace
#

😭

warm shaleBOT
timid silo
inner terrace
#

does this work @timid silo

timid silo
#

,w invert [[4,8],[1,3]]

timid silo
inner terrace
#

what does the inversion do

timid silo
#

now you can read off a,b in terms of x,y

inner terrace
#

ah so a = 3/4x-2y and b = y-1/4x

#

but thats not a function is it

timid silo
timid silo
inner terrace
#

the excercise asks for an expliciti equtaion

timid silo
#

its a function that takes two real numbers

inner terrace
#

ah I see

timid silo
#

given vector (x,y), we can find a and b using those two equations

#

eg we could substitute (4,1) and get a=1, b=0 without doing the augmented matrix thing

inner terrace
#

ahh

#

@timid silo any idea how to do this

timid silo
#

use the definition of a linear map

#

might help to write the function in vector form first

inner terrace
#

could you help me

#

with the steps

timid silo
#

you need to check that F(x,y,z)+tF(a,b,c)=F(x+ta,y+tb,z+tc)

inner terrace
#

which is preservation of multiplication right?

timid silo
#

its both additivity and scalar multiplication at the same time

#

you can do them separately if you've defined them seperately

#

so F(x,y,z)+F(a,b,c)=F(x+a,y+b,z+c) and tF(x,y,z)=F(tx,ty,tz)

inner terrace
#

sorry but i dont understand

timid silo
#

what definition of a linear map are you given?

inner terrace
timid silo
#

lets do addition first

#

v=(x,y,z) and v'=(a,b,c)

#

substitute everything into F(v+v') and show that its the same as F(v)+F(v')

inner terrace
#

so

#

for F(x,y,z)

#

what do we add?

#

for the exercise

timid silo
#

F((x,y,z)+(a,b,c)) = F(x+a,y+b,z+c)

#

then substitute the rhs into the definition of F in the question

inner terrace
#

rhs?

#

what are rhs

#

right hand side

#

my bad

timid silo
inner terrace
#

so for x+a

#

x-y+2z + a

timid silo
#

no, my notation might be a bit misleading because I reuse the same variable

#

but it should be (x+a)-(y+b)+2(z+c)

inner terrace
#

wait what

#

could you rewrite the F((x,y,z) + (a,b,c))

timid silo
#

$F((a,b,c)+(d,e,f))=F(a+d,b+e,c+f)=((a+d)-(b+e)+2(c+f),\ldots,)$

warm shaleBOT
timid silo
#

ie, in the definition, use x=a+d, y=b+c, z=c+f

inner terrace
#

how do I go further than that tho?

#

((a + d) - (b+e) + 2(c + f), (3(a + d) + (b + e) - (c + f), (4(a + d) + (c + f))

#

is this right

#

@timid silo

timid silo
#

yeah

#

now split up the a,b,c terms into one vector, and then d,e,f into the other

boreal vale
#

hi What is the derivative of this function?

inner terrace
boreal vale
#

oh Thank you

inner terrace
#

((a - b + 2c) + (d - e + 2f), (3a + b - c) + (3d + e - f), (4a + c) + (4d + f))

timid silo
#

now thats equal to F(a,b,c)+F(d,e,f)

#

which shows addition

boreal vale
#

but it is not polynomials?

timid silo
inner terrace
#

((a - b + 2c), (3a + b - c), (4a + c)) + ((d - e + 2f), (3d + e - f), (4d + f)) =

boreal vale
#

a ok

inner terrace
#

is that my next step?

timid silo
#

yup

inner terrace
#

and does that prove the preservation of addition

timid silo
#

yes it does

#

you can do something similar for multiplication

inner terrace
#

but here it does something else

timid silo
#

wdym? its what you did except with different variable names

inner terrace
#

but the final step is different

#

on the left side you can clearly see the map given

#

nevermind.

#

I feel stupid

#

.close

obtuse pebbleBOT
#
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lone vault
obtuse pebbleBOT
lone vault
#

how do i do this?

#

this is not a test, just online hw

tardy epoch
#

Use
$P(X < n) = 1 - P(X \ge n)$

warm shaleBOT
#

riemann

lone vault
#

lambda is 20 here?

tardy epoch
#

what's the mean of a poisson distribution?

lone vault
#

E(x) = 20

#

thats what im thkinking

obtuse pebbleBOT
#

@lone vault Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
#
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sinful eagle
#
  1. What is vectors U”=AB, v= AC, w=AD.
  2. What is area abc
  3. Equation for planet II, with dots a,b,c.
  4. Volym of pyramid abcd.
sinful eagle
#

Question to 1. All those are vectors.

#

While A, B, C D are dots.

#

Anyone?

#

A=(1,2,2), B=2,4,3, C=4,8,4 and D=3.5.5 are 4 dots in r^3

#

U=ab= (1,2,2)(2,4,3) = (2-1), 4-2, 3-2

#

=1,2,1

#

I think?

#

Hmm

#

🤔

#

V=AC just do vector end -start vector

#

3,6,2

#

W=AD= 2,3,3

#

Ok think i got it.

#

Then at question 2…

#

Area of triangel is height times base/ 2

#

Hmm

#

I know of height dots but is base U vector working?

#

<@&286206848099549185>

#

Hi at question 2. How do I figure out area of triangel ABC

obtuse pebbleBOT
#

@sinful eagle Has your question been resolved?

sinful eagle
#

How do I know area of triangle with 3 dots?

#

hmm

#

Ah i use herons formula

#

.close

obtuse pebbleBOT
#
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dull oyster
#

when a number is divided by 342 it gives reminder of 47 .when the same number is divided by 19 what will be its reminder

chrome mesa
#

just test using any number that gives a reminder of 47 when divided by 342 (or realize the significance of the value of 342/19)

dull oyster
#

yea i found the answer its 9

#

but thanks

obtuse pebbleBOT
#

@dull oyster Has your question been resolved?

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old tapir
obtuse pebbleBOT
rose parcel
#

oh sorry xd

old tapir
obtuse pebbleBOT
#

@old tapir Has your question been resolved?

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#
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summer rain
obtuse pebbleBOT
summer rain
#

what are the angles

#

I really need this or I'll fail😭

fierce lagoon
#

wy would you fail

summer rain
#

I just failed the first quarter

#

I need to do better this time

#

<@&286206848099549185>

uneven kayak
#

$\angle{DCB} = \angle{5} = 124$ as a cross angle

warm shaleBOT
#

! Promi !

uneven kayak
#

$\angle{4} + \angle{5} = 180$ so $\angle{4} = 180 - 124 = 56$

#

$\angle{2} + \angle{1} = 90$

warm shaleBOT
#

! Promi !

#

! Promi !

summer rain
#

how about angle 3 and 4?

uneven kayak
#

XD

#

Or im wrong

summer rain
#

there is acutally

#

angle DCA

uneven kayak
#

ok i confused it with 1

summer rain
warm shaleBOT
#

! Promi !

summer rain
#

sooo because angle 4 is a central angle that means the arc has the same measurement or degree

uneven kayak
#

sum of angles 4 and 5 is 180 degrees

#

so u can find angle 4

summer rain
#

ohhhh ok ok I get it

uneven kayak
#

$\angle{2} = \angle{3}$

warm shaleBOT
#

! Promi !

uneven kayak
#

as $CD = CA = R$

warm shaleBOT
#

! Promi !

summer rain
#

so angle 3 is equal to 34 degrees?

uneven kayak
#

i confused angle 1 with 4

#

so we have to still find 2

summer rain
#

ohh okay

uneven kayak
#

$180 = \angle{2} + {\angle{4} + \angle{3}$

warm shaleBOT
#

! Promi !
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

uneven kayak
#

as the sum of angles of a triagnle equals 180

#

Thus $\angle{2} = \angle{3} = 62$

warm shaleBOT
#

! Promi !

uneven kayak
#

Finally angle 1 equals 90 - angle 2

#

$\angle{1} = 28$

warm shaleBOT
#

! Promi !

summer rain
#

but then angles 2 and 1 makes a right angle so does that means 28

#

ohhh I got it

summer rain
#

THANK YOU SO MUCHH

summer rain
#

ok nvm its alr

#

thanks again!

#

.close

obtuse pebbleBOT
#
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willow briar
#

Could I get help with this

obtuse pebbleBOT
willow briar
arctic ravine
#

take a limit

#

as x->infinity

willow briar
#

Ok

arctic ravine
#

or you can type it into desmos

#

but itll be easier for the limit

#

for example 1) f(x) goes to infinity as x goes to infinity

willow briar
#

Ok

arctic ravine
#

but might be worth checking what happens at negative infinity too

solar hornet
#

if you find the zero points, that's where it touches the x axis

#

if highest power coefficient is positive, it goes to positive infinity

#

otherwise it's negative infinity

willow briar
#

True but how would I go about make the shape

solar hornet
#

when you have x^2 it's a parabola, x^3 it's like the wave thing, x^4 it has another "groove"

#

it's best when you have the zero points, then you can just draw a "wave" over them

willow briar
#

Ok would the wave be the answer?

solar hornet
#

you just describe the end behavior

#

no need for specifics, so you can say, it starts at negative infinity, one goes up, goes down, then goes up to positive infinity

#

like in the first example, x^3 has positive coefficient, so on the left side it starts from the negative infinity, and on the right side it goes to positive infinity

willow briar
#

I think I get it

arctic ravine
#

if youre claiming that the end behavior adheres to the parent graph of the highest degree a proof may be required but i would agree

solar hornet
#

by domination highest power decides where the limit goes

#

you can show it by taking the limit but I don't think it's necessary here

arctic ravine
#

fair enough

solar hornet
#

but when the power is even and coefficient is positive, it also start at positive infinity from the left side

arctic ravine
#

Might be worth mentioning that if he takes the derivative he can find the inflection points

#

so hes not guessing where the line curves

#

for part 2

solar hornet
#

i mean, we did stuff like this in school before we learned limits

arctic ravine
#

yeah but depending on teacher

#

might need proof for that

#

especially in higher level math

solar hornet
#

you don't need to take the derivative, you can just use equations for parabolas

#

doesn't look like higher math to me tbh

arctic ravine
#

for question 7 and 8 its essential he takes the derivative

#

to find the points of inflection

zenith raft
#

no it's not lol?

arctic ravine
#

i mean he could guess

#

but that would be kind of ruining the point of doing the math

#

because he wouldnt be doing it lol

zenith raft
#

people usually learn how to plot things like f(x) = 2x^2 - 3 long before they learn derivatives lol

solar hornet
#

it's something like an introduction to graphs/functions*, learning the intuition and doing it manually

arctic ravine
#

oh i see he may not know derivatives yet

#

my bad

#

then he plugs in a lot of values i guess

zenith raft
#

a parabola is uniquely determined by 3 points...

willow briar
#

Y’all so smart omg😭

arctic ravine
#

depends what type of math you are doing

#

that is not always true layla

willow briar
#

Ok so basically I just find 3 points and grpah correct??

#

Graph

zenith raft
solar hornet
#

how is a parabola defined by more than 3 points, isn't that by it's definition

zenith raft
#

certainly not by definition but what i said is true?

arctic ravine
#

take complex numbers into consideration

zenith raft
#

???

solar hornet
#

@willow briar have you seen those?

#

if it's something you guys were doing, I think it's easier to do it that way

#

but you can sketch a parabola without those

#

(don't look at the rightmost column)

willow briar
#

Ok thanks man

obtuse pebbleBOT
#

@willow briar Has your question been resolved?

obtuse pebbleBOT
#
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timid silo
#

I’m not sure as to how I’d covert this non monic quadratic into the form they have asked there. My understanding so far is that you’d need to take out a linear factor from the quadratic, but I’m not sure how to totally rearrange it into that form.

timid silo
#

Not sure how acceptable this is

tardy epoch
#

You can't just turn a 1 into a 0

#

What's 3x * 1

timid silo
#

3x

#

oh wait i think I might've got it

#

if I take 3x out of the brackets and keep it as 3x(x+1), I have to have another term which ends up simplifying the equation to -7x as it is originally

#

so it would become 3x(x+1)-10x+5

#

👍

#

.close

obtuse pebbleBOT
#
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icy cape
#

ax/b - cx/2 = d

obtuse pebbleBOT
icy cape
#

How do I solve for x in terms of other pronumerals

copper spade
#

@icy cape take x common

royal basin
#

notice that your equation is $\frac{a}{b} x - \frac{c}{2} x = d$

warm shaleBOT
copper spade
#

nvm latex pro here u take over

icy cape
#

I notice

#

but i am not sure on what to do next

copper spade
#

Take x common

icy cape
#

X common?

copper spade
#

Yes

icy cape
#

Common HDF?

copper spade
#

Like ax+bx = x(a+b)

icy cape
#

how abt the denominators

#

tho

#

one is b and other is 2

#

do we cross them

#

to the other numerators

copper spade
#

No need to worry coz the question says to express x in terms of other poly

icy cape
#

then how shall i write it

#

do I just leave the denominators as is

#

but connected

copper spade
#

Your wish, you can take lcm Or you can leave it as it is

icy cape
#

so ax - cx/b - 2 = d

#

right

#

x (a - c)/b - 2 = d

royal basin
#

no

copper spade
icy cape
#

why

royal basin
#

subtracting two fractions doesnt mean just subtracting their tops and bottoms

copper spade
#

Ye

royal basin
#

it's $\paren{\frac{a}{b} - \frac{c}{2}}x = d$

warm shaleBOT
royal basin
#

also do not try to do everything at once

icy cape
#

what the sus

icy cape
#

I see

royal basin
#

it is okay to do one thing at a time, i.e. first factor out x, then worry about subtracting the fractions.

#

and it is now that we can actually focus on simplifying $\frac{a}{b} - \frac{c}{2}$

warm shaleBOT
icy cape
#

ok

timid silo
#

How do i pronounce ur username, is it evbama almkhls?

icy cape
#

ye

#

s

#

actually its Aw

#

Awbama

copper spade
#

@icy cape focus on ur meth problem first lol

royal basin
#

i'm not sure OP has a methamphetamine problem.

#

that, or it was an unfortunate typo.

icy cape
#

who is op

royal basin
#

original poster

#

in this case, you.

icy cape
#

ok

copper spade
timid silo
#

Over powered

royal basin
#

OP can stand for a bunch of things, but the way i used it, it means what i said it means.

#

anyway! let's stay on topic.

icy cape
timid silo
royal basin
#

@timid silo @copper spade -> #chill

royal basin
icy cape
#

but the problem is the denominator

royal basin
#

what's the problem with it?

icy cape
#

the denominators are not equal

royal basin
#

yeah, and?

#

do you know how to address that issue?

icy cape
#

we gotta make them equal

#

by multiplying

#

hmmm

#

perhaps

#

CB/2B