help-10

[gritty carbon]

perfect

and if we know part of B's angle is 120

then what is the other part of B's angle?

[low frost]

60

[gritty carbon]

perfect

[low frost]

So that means ABC would be 60

[gritty carbon]

okay

correct

now we need to find the angle

ACB

i think you can do that one

[low frost]

50

[gritty carbon]

yep

so with that information

what do you think angle ACD is ?

remember the straight lines

[low frost]

120?

[gritty carbon]

not quite

[low frost]

Hmm

130?

[gritty carbon]

perfect

the entire straight line

adds up to 180 degrees

therefore, 50 + (something) = 180

which is 130, correct

[low frost]

Okay

[gritty carbon]

https://media.discordapp.net/attachments/903430332324405288/1044948194842394634/unknown.png

it will always add up to 180

notice how in this image, 45 and 135, add up to 180

[low frost]

Yes

[minor hamlet]

Exterior angle C is the sum of two interior angles, 70 and 50

[gritty carbon]

it's better to not teach shortcuts when he isn't comfortable with the absolute basics

or she

and the other interior angle isn't 50

don't know where you're getting that from

or you're talking about the newly found one

[minor hamlet]

Meant to say 60

[gritty carbon]

sorry

yeah but okay

[minor hamlet]

Read it as 50

[gritty carbon]

anyway

if the op isn't familiar with angles of straight lines

teaching shortcuts isn't going to help

but thanks anyway

in all honesty i forgot that as well haha

[low frost]

[gritty carbon]

don't get confused meir

just remember the basics

an angle on a straight line, will always be what??

[low frost]

180

[gritty carbon]

what is the angle of c here meir

[low frost]

147

[minor hamlet]

127

[gritty carbon]

not quite

doctor my bro

with all due respect, not asking you haha

[minor hamlet]

Oh, nvm, I should leave

[gritty carbon]

i'm trying to get him/her to think for themselves

[low frost]

Oops

My bad

Lolol

[gritty carbon]

what's the angle of x here?

[low frost]

97

[gritty carbon]

yes

https://media.discordapp.net/attachments/903430332324405288/1044944253496856707/IMG_0010.png?width=1440&height=665

lets do this one

what's the angle of x?

[low frost]

Hm

45?

[gritty carbon]

why do you think 45?

[low frost]

No

Wait

[gritty carbon]

don't get the 50 involved

[low frost]

35?

[gritty carbon]

it's not relevant for solving x

just look at the x

look at the 95

what do we know about the sum of those two?

[low frost]

They will add up to 95?

[minor hamlet]

Hold on, if I may interrupt, Meir, I'm curious about your way of thinking

[gritty carbon]

that's a silly question

[minor hamlet]

Tell me how you are getting these numbers

[low frost]

I got 35° because I added 35 50 and 95 together = 180

But I’m pretty sure that’s wrong

[gritty carbon]

okay so

let me give you one more question

i see why you're doing that

[low frost]

Okay

[gritty carbon]

but have a look at this

solve for x, and solve for y

[low frost]

Um

[gritty carbon]

the problem is that you think they're all connected

[low frost]

I’m not quite sure

[gritty carbon]

they're not

these two problems, are ones you've already solved

just break them up into their own sections

cut the line in half

imagine these were separated

[low frost]

X = 118? And y=150

?

[gritty carbon]

yes

i think you got confused when i said all angles on a straight line must add up to 180

what i meant by that was

any angle on a straight line will be 180

[low frost]

So

[gritty carbon]

these are all 180

[low frost]

If you were to break up the lines each one would 180

[gritty carbon]

https://media.discordapp.net/attachments/903430332324405288/1044944253496856707/IMG_0010.png

so what would x be ?

[low frost]

Hm

[gritty carbon]

imagine all of this wasn't there

all you knew was that there is a straight line

[low frost]

Okay

[gritty carbon]

and you know that there was an angle on this straight line

and a line dividing this angle

an angle on a straight line is what?

[low frost]

180

[gritty carbon]

so x + 95 needs to equal what?

[low frost]

180

Which would make x 85

[gritty carbon]

yes

[low frost]

Ok

And y would be 45?

[gritty carbon]

yes

[low frost]

That’s what I thought originally

[gritty carbon]

the biggest issue is that you're not too comfortable with how angles work

[low frost]

Yeah they aren’t my strong suit

[gritty carbon]

are you familiar with what the term right angle means?

[low frost]

Yes

An angle that is 90

[gritty carbon]

right

so what does a right angle look like

[low frost]

looks like a capital L

[gritty carbon]

yeah

so imagine

that angle

was extended by 90 degrees

what would that look like?

[low frost]

A straight line

[gritty carbon]

exactly

anyway

i gotta go

but i feel as though your understanding improved a little

if you need a little more help, send me a friend req and i can help you when i'm free

[low frost]

Okay

Thank you so much

[obtuse pebble]

@low frost Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[stiff shoal]

hi

[stiff shoal]

tìm m để hạng ma trận A bằng 3 >>>>> Finding M for Rank A = 3.

how can I do that?

Pls help me

m is a11

I turn m to Rows 1 to Rows3

<@&286206848099549185> Anyone here.

hi

<@&286206848099549185> liitle help pls.

🙂

,help

[warm shale]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[stiff shoal]

hi

[cloud berry]

can you translate

[stiff shoal]

yes

[stiff shoal]

Finding M for Rank A = 3.

[cloud berry]

sorry i can't help coz rank of matrices is not in my syllabus

[stiff shoal]

what math are you studying?

[cloud berry]

in 12th grade

[stiff shoal]

thanks.

[stiff shoal]

Wow. You study linear algebra in 12th grade U.S.A

[cloud berry]

no in INDIA

[stiff shoal]

Finding M for Rank A = 3. This math is about Linear Algenra.

[stiff shoal]

ok. Thanks.

[stiff shoal]

Do you have plan to study in Viet Nam University?

[cloud berry]

I'm preparing for IIT-JEE

and studying in foreign universities is out of my budget

[stiff shoal]

oh. What an university will you study in India?

[cloud berry]

maybe IIT-Bomaby or IIT-Delhi

[stiff shoal]

wow. It is so cool.

[stiff shoal]

You study It for computer sciences, coding, internet, etc

I study It in Viet Nam University.

[cloud berry]

WOW but we're wasting time of each other

|| i may sound rude but only 50 days are left for my enterance exam :(||

||i was just here for some hard questions||

[stiff shoal]

It is not rude. It is fine. You have 50 days left. You need preparing your exam. 🙂

[stiff shoal]

You study English, or Hindi program on It course.

[cloud berry]

in english

but can study in hindi also

pls ask such in DM this place is for problem solving

[stiff shoal]

ok

[timid silo]

properties of Matrices and Determinants and their algebra not complete Linear Algebra

[stiff shoal]

oh.

[stiff shoal]

@timid silo You help me this one.

[timid silo]

😔 don't know about rank

[stiff shoal]

What grade are you?

[timid silo]

i have completed 12th trying for college

[stiff shoal]

oh

[stiff shoal]

Did you study calculus?

[timid silo]

yes

[stiff shoal]

College means University?

[timid silo]

yes

[stiff shoal]

What is different Pre-Calculus and Calculus?

[timid silo]

Pre-calculus is Functions, Limits,Continuity, Differentiability some Vector 3-D and Matrices Determinants, Conic Section too

and Inverse trigonometry

Calculus is in two parts Differential and Integral

[stiff shoal]

I study Calculus on university tomorrow. I think it is so difficult to study it. 😢

[timid silo]

If you follow logically and have conceptual understanding then it won't be

[stiff shoal]

Some of my college said:" Dim is so important in calculus."

[timid silo]

https://www.youtube.com/channel/UC2SxJnPvn6-dr-KV9pos0zg

try this channel

[stiff shoal]

what is this?

[timid silo]

it's for the other guy

he was asking for tough questions

related to his exam

[stiff shoal]

ok

[stiff shoal]

https://en.wikipedia.org/wiki/Derivative

[stiff shoal]

<@&286206848099549185> I need someone help this one. Pls

[obtuse pebble]

@stiff shoal Has your question been resolved?

[spiral knot]

you need to prove that the rows are independent

[stiff shoal]

thanks

[spiral knot]

you know the rest Right ?

[spiral knot]

anytime

[stiff shoal]

no

[stiff shoal]

I solved it

[spiral knot]

you need to prove that
$\begin{bmatrix}
m \ 1 \ 1
\end{bmatrix}
\ne
\alpha
\begin{bmatrix}
1 \ 2 \ 3
\end{bmatrix}
+
\beta
\begin{bmatrix}
1 \ 3 \ 6
\end{bmatrix}$

[warm shale]

Mehdi_Moulati

[stiff shoal]

this is not equation.

[stiff shoal]

@spiral knot

Finding M for Rank A = 3

[spiral knot]

so solve the system :

$m \ne \alpha + \beta$

$1 = 2*\alpha + 3*\beta$

$1 = 3*\alpha + 6*\beta$

find the value of alpha and beta

[warm shale]

Mehdi_Moulati

[stiff shoal]

what is this?

This problem exercise is on Linear Algebra.

[stiff shoal]

what is the rest Right?

[spiral knot]

i know bro

if you solve this system

you will find when that matrix is Rank = 3

[stiff shoal]

another method?

[spiral knot]

i found that the matrix is rank 3 if $m\ne \frac{2}{3}$

[warm shale]

Mehdi_Moulati

[stiff shoal]

how to do that?

[stiff shoal]

It is the shortcut, and tricks.

I preparing my mid-term exam on monday.

[spiral knot]

try to solve this system

[stiff shoal]

try to solve this system is the book of linear algebra?

[spiral knot]

$\begin{bmatrix}
m \ 1 \ 1
\end{bmatrix}

\alpha
\begin{bmatrix}
1 \ 2 \ 3
\end{bmatrix}
+
\beta
\begin{bmatrix}
1 \ 3 \6
\end{bmatrix}$

[warm shale]

Mehdi_Moulati

[spiral knot]

so

we have that row 2 and 3 are indepentent

okay ?

[stiff shoal]

yes

[spiral knot]

so the rank >= 2

[stiff shoal]

yes

[spiral knot]

so we need to prove that the rows 1,2,3 are independent

so if we prove that
Row1 isn't equal to m*Row2 + k*Row3 where m and k are constant

the rank will be equal to 3

for example
if row1 = row2 + row3 then those rows are not independent

[stiff shoal]

This exercise is the matrix. Is This one relative with the vector, and the equation?

[spiral knot]

the system of equation could be transform to matrix

look

(m 1 1)

is the first row in your matrix

1 2 3 is the second row

1 3 6 is the third

[stiff shoal]

oh

[spiral knot]

$\begin{bmatrix}
m \ 1 \ 1
\end{bmatrix}

\alpha
\begin{bmatrix}
1 \ 2 \ 3
\end{bmatrix}
+
\beta
\begin{bmatrix}
1 \ 3 \6
\end{bmatrix}$

[warm shale]

Mehdi_Moulati

[spiral knot]

if we find that this is true

then row1 = alpha * row2 + beta row3

so the row 1,2 and 3 are dependent

[stiff shoal]

how can we find this is true for finding m rank 1,2,3?

[spiral knot]

first of all multiply alpha and beta by its row

[warm shale]

Mehdi_Moulati

$\begin{bmatrix}
 m \\ 1 \\ 1 
\end{bmatrix}
=
\begin{bmatrix}
 \alpha \\ 2\alpha \\ 3 \alpha
\end{bmatrix}
+
\begin{bmatrix}
 \beta\\ 3\beta \\6\beta 
\end{bmatrix}$

[spiral knot]

than make the sum of two vectors in the right

[warm shale]

Mehdi_Moulati

$\begin{bmatrix}
 m \\ 1 \\ 1 
\end{bmatrix}
=
\begin{bmatrix}
 \alpha + \beta\\ 
2\alpha + 3\beta\\ 
3 \alpha +  6\beta
\end{bmatrix}$

[spiral knot]

is it clear ?

[stiff shoal]

yes. I think AX=B

A (m,1,1) = X (a,2a,3a) + B (B,3B,6B)

[spiral knot]

you can replace alpha and beta by x and y

A = XB + YC

A = (m,1,1)
B = (1,2,3)
C = (1,3,6)

[warm shale]

Mehdi_Moulati

$\begin{bmatrix}
 m \\ 1 \\ 1 
\end{bmatrix}
=
\begin{bmatrix}
 X+ Y\\ 
2X + 3Y \\ 
3X +  6Y
\end{bmatrix}$

[spiral knot]

use the row number 2 and row number 3 to find the value of X and Y

[stiff shoal]

You mean 2+3=5?

3+6=9

[spiral knot]

no

[stiff shoal]

2-3=1

3-6=-3

[spiral knot]

multiply the second row by 2

[warm shale]

Mehdi_Moulati

$\begin{bmatrix}
 m \\ 2 \\ 1 
\end{bmatrix}
=
\begin{bmatrix}
 X+ Y\\ 
4X + 6Y \\ 
3X +  6Y
\end{bmatrix}$

[spiral knot]

if you subtract the second row from the third

you will find the value of X

[warm shale]

Mehdi_Moulati

[spiral knot]

so X = 1

[stiff shoal]

3x-4x = -x, 6y - 6y = 0

[spiral knot]

yeah

now if we replace x by 1 (in the third row ) 1 = 3X + 6Y

we will get the value of Y

[stiff shoal]

1 = 3 (1) + 6 Y

1 = 3 + 6 y

1-3 = 6y

-2=6y

-2 / 6 = y

-3 = y

[spiral knot]

no

y = -1/3

[warm shale]

Mehdi_Moulati

[spiral knot]

now since we have values of X and Y we can find the value of m

[stiff shoal]

m = 1 + -1/3

m = 2/3.

[spiral knot]

correct

so if m = 2/3 then A = B + -C/3

then A,B and C will not be independent

[stiff shoal]

What is different between independent, and dependent in this picture?

[stiff shoal]

I have question for m

[spiral knot]

let say i have 3 vectors (A,B and C)

if A,B and C are dependent then i could write one of them using 2 other vector

if A = (1,1,1) ,B = (1,2,1) , C = (2,3,2)

C = A + B

so A , B and C are dependent

and since A and B are independent

the rank of the matrix will be 2

same thing with our problem

if m = 2/3 than A will be depend on B and C (A = B + (-1/3) C ) => rank =2

but i want rank = 3

so m must not equal to 2/3

[stiff shoal]

if m is in everywhere on matrix 3x3

M is not a11.

[spiral knot]

like this ?
$\begin{bmatrix}
1 & m & m\
m & m & m\
m & m & m
\end{bmatrix}$

[stiff shoal]

M is in each places. It is the example

yes. I mean that

We use the formula A = XB + CY likes this in m

[spiral knot]

yeah

[stiff shoal]

A = 1,1,1 B = 1,m,3 C = 1, 3, 6 like this

B = XA +CY

[spiral knot]

yeah

the same method

before this

you need to verifier if A depend on C or not

[stiff shoal]

1,m,3 B = 1,1,1 X + 1,3,6 Y

[stiff shoal]

how can I verify A depend on C or not?

[spiral knot]

the same method

A=XC

if it is true then A depend on C

[stiff shoal]

A = 0 dependent to C?

[spiral knot]

if A is a null vector ?

yeah because X = 0

what did you find for this A=XC ?

[stiff shoal]

wait for it

[stiff shoal]

How can I mutiply rows 2

[spiral knot]

it's not always 2

i multiply by 2 to have 6y in the second rows

because 6y is already in the third

so if i subtract the second row from the third will help me to find the value of X

are you trying with this "A= CX",right ?

[stiff shoal]

rows 2: m = 1x +3y

[stiff shoal]

You try to teach this formula.

I think it is useful (tricks, and shortcut instead gauss-jordan elimation) for the multiplies choices on middle-term test on monday.

[spiral knot]

you made a mistake in the Second Rows

[stiff shoal]

m = 1 + 3y is in the First Rows?

[spiral knot]

when you substract the first row from the second

[warm shale]

Mehdi_Moulati

[spiral knot]

$\begin{bmatrix}
1 \ m - 1\ 3 - 1
\end{bmatrix}

\begin{bmatrix}
X+ Y\
(X-X) + (3Y - Y) \
(X-X) + (6Y - Y)
\end{bmatrix}$

[warm shale]

Mehdi_Moulati

[spiral knot]

just read about "gauss-jordan elimation"

anything you did to the right side you must do it to the left side

the second line = the second line minus the first line

the third line = the third line minus the first line

so the result is :
$\begin{bmatrix}
1 \ m - 1\ 2
\end{bmatrix}

\begin{bmatrix}
X+ Y\
2Y \
5Y
\end{bmatrix}$

[warm shale]

Mehdi_Moulati

[stiff shoal]

mutiply rows?

[spiral knot]

X + 3Y - (X + Y) = 2Y and m - (1) = m-1

X + 6Y - (X+Y) = 5Y and 3 - (1) = 2

[spiral knot]

you missed to substract 1 form m in the second line

[stiff shoal]

I see

[spiral knot]

so we have 5Y = 2 in the third line

so Y = 2/5

now replace y by its value to get the value of m

[stiff shoal]

how about x?

[spiral knot]

our concern is the value of m

[stiff shoal]

m=-4/5

[spiral knot]

m - 1 = 2Y
= 2 * 2/5 = 4/5
so
m - 1 = 4/5 <=> m = 4/5 + 1
= 9 / 5

so the matrix is rank = 3 when m not equal 9/5

[stiff shoal]

Is It independent?

[spiral knot]

A,B and C dependent if m = 9/5

so A,B and C are independent if m not equal to 9/5

[stiff shoal]

what is rank 2?

[stiff shoal]

what is rank 3?

[spiral knot]

the rank is "how much vectors of a matrix are independent"

[stiff shoal]

You mean the matrix is rank = 3 when m not equal 9/5 (so A,B and C are independent if m not equal to 9/5)

[spiral knot]

yeah

[stiff shoal]

do you have the graph on another link

I want to see what they go

This is the tough for me. Finding m, a on rank, or inverse

[stiff shoal]

ok. thank you so much.

It is 1:45 A.M. I need to sleep on bed.

.close

[obtuse pebble]

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Closed by @stiff shoal

Use .reopen if this was a mistake.

[stiff shoal]

.reopen

[obtuse pebble]

✅

[stiff shoal]

.close

[obtuse pebble]

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[vagrant compass]

i dont understand the last steep

step

[thick fog]

the cross product basically distributes and it is anticommutative so they flipped the signs

also a cross a is 0

[vagrant compass]

i dont understand

[open sorrel]

use the linearity of cross products and the geometric definition of cross producs to see.

[vagrant compass]

...

[open sorrel]

if you can't get that with mental calculations, you will expand it on paper at least once in your life to see

[obtuse pebble]

@vagrant compass Has your question been resolved?

[obtuse pebble]

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[barren trench]

[]

[barren trench]

am i missing something or can this not be simplified more

u could do *7x to make 14x but the answe its asking for theres no 14x as an option

[timid silo]

x can be cancelled

2/7 is the simplest form

[barren trench]

oh xD ngl forgot abt canceling out

.close

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still parcel]

@drifting badger kan du hjælpe?

[obtuse pebble]

@still parcel Has your question been resolved?

[obtuse pebble]

@still parcel Has your question been resolved?

[still parcel]

How

[obtuse pebble]

@still parcel Has your question been resolved?

[hybrid gull]

?

[obtuse pebble]

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[frozen aurora]

Hi I need help learning factoring. Would anyone be able to help me? I've been trying to study by myself but I am stuck, I don't get it.

[hybrid gull]

Do you have example problems?

You can find tutorials on factoring on YT

[frozen aurora]

I have a sample of the exam I will do

[frozen aurora]

I've been doing those

[hybrid gull]

That’s good

[frozen aurora]

But I am stuck.

Anyway

If it is not possible it is okay

I'll keep trying 🙂

[hybrid gull]

You’re good 🙂

Feel free to send examples

Maybe try some

[frozen aurora]

This is my test. I failed.

I scored 25%

I need 65%

[tardy epoch]

can you just screenshot and upload

[frozen aurora]

Oh the PDF didn't work?

I'll send photos

[hybrid gull]

Do one at a time 👍

[tardy epoch]

that's correct?

[hybrid gull]

1 is correct

[frozen aurora]

Sorry

I'll send just the incorrect onse

ones

[hybrid gull]

It looks like you’re getting these right, you just need to go as far as you can

[frozen aurora]

Like these ones here are the ones I really get lost

[hybrid gull]

Ideally you have work we can check, but the idea here is to create a common denominator after you factor

[frozen aurora]

Like simplify more?

[hybrid gull]

Here this is just algebra, less so factoring

[hybrid gull]

Factor more, yes

[frozen aurora]

I see

I don't know multiplication table so I always get lost

Anyway

[frozen aurora]

Do you guys think you could help me understanding this kind of equation?

.close

[obtuse pebble]

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[wide jackal]

How would I differentiate this?

[hybrid gull]

Do you have any ideas? You have one function divided by another

[wide jackal]

Yeh i was using quotient rule

But idk if I can simplify my answer further

[hybrid gull]

Do you have work?

[hybrid gull]

Refer to this

[warm shale]

tushar

[obtuse pebble]

@wide jackal Has your question been resolved?

[wide jackal]

OH LMFAO IM SO DUMB

TY

[obtuse pebble]

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[near timber]

I found R(x) and know R=px but that’s it

[obtuse pebble]

@near timber Has your question been resolved?

[near timber]

<@&286206848099549185>

[obtuse pebble]

@near timber Has your question been resolved?

[near timber]

NOOO AHHHH

.close

[obtuse pebble]

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[dawn helm]

Figure out the smallest non-negative integer r so that:

3^43 + 17 ≡ r (modulo 16)

I don't know where to start, please help

[lilac pebble]

Try using loga

Logs*

Look into what logs does to r

Think about what base you should use

[dawn helm]

I know the start is 3^4 = 81 ≡ 1 (mod 16)

but I dont know how to continue

[obtuse pebble]

@dawn helm Has your question been resolved?

[obtuse pebble]

@dawn helm Has your question been resolved?

[obtuse pebble]

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[tacit briar]

Two $6$-sided dice, one red and one green, are rolled. What is the probability that the red die shows an odd number and the green die shows a number that is a perfect square?

[tacit briar]

i got 1/9 for this question

P(red die shows an odd number) = 1/2

P(green die shows a perfect square) = 8/36

multiply both together to get 1/9

[gilded needle]

how did you get 8/36

[tacit briar]

is anything in my approach wrong?

[tacit briar]

by creating the 36 outcomes of the 2 die. by doing that i get pairs (1, 1), (1, 4), (2, 2), (3, 3), (4, 1), (4, 4), (5, 5), and (6, 6) as perfect squares

which adds up to 8

[gilded needle]

no

[tacit briar]

and there is a total of 36 outcomes

whats wrong about this?

[gilded needle]

that's not what P(green die shows a perfect square) means

green die is just one die

not the sum of two dice

[tacit briar]

oh snap

would it just be 1 and 4?

[gilded needle]

yep

[tacit briar]

ohhhhhhhh

im stupid

which is 2/6

[gilded needle]

nah, you just misinterpreted

[tacit briar]

multiply that by 1/2

[gilded needle]

yep

[tacit briar]

to get 1/6

yeah i misinterpreted

[gilded needle]

1/6 is correct

assuming the two dice rolls are independent

which is a natural assumption

[obtuse pebble]

@tacit briar Has your question been resolved?

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[mortal sun]

where is the 4 coming from on the far right side?

[cloud berry]

54 + 3* 54 = 4* 54

[dark mango]

what

[mortal sun]

where did 45 come from

oh

[cloud berry]

😅

[dark mango]

what are u trying to do in the first place here ?

[mortal sun]

why is it 54 + 3*54

oh wait nvm

im stupid

got it thanks

.close

[obtuse pebble]

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[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

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[smoky trout]

Can someone help me

[timid silo]

have you tried something?

[quaint glen]

what is r

[thick oracle]

abcd looks like a square

right

[timid silo]

it says

[smoky trout]

Yes

[quaint glen]

no like

[pliant compass]

radius I guess

[smoky trout]

Square is 6

[quaint glen]

what geometric part

of the shape is r

[quaint glen]

where does it say that

[smoky trout]

R= radius

[timid silo]

tell me what are your thoughts

[thick oracle]

is abcd a square or not

[smoky trout]

Its a square

[thick oracle]

good

[smoky trout]

Im clueless

[thick oracle]

if you know the radius

[smoky trout]

Radius is 6

[thick oracle]

what can you find in a circle?

[pliant compass]

Right there

[timid silo]

why?

[smoky trout]

BRO😭😭

i cant understand maths

idek whats the formula

[timid silo]

give it a try

it's not that hard

[smoky trout]

where do i even start bruh😭

[thick oracle]

i'll tell you

[smoky trout]

deadass just have the number 6

[thick oracle]

answer this

[smoky trout]

area? 😭🧍‍♀️

[thick oracle]

yes

very good

so whats the area

[smoky trout]

6?

[thick oracle]

no

[tranquil quiver]

you can start by recognising what the shaded area is composed of

[timid silo]

try to find the area of the circle

[tranquil quiver]

given the area of the circle and the area of the square could you find the shaded area @smoky trout ?

[smoky trout]

thats what im trying to understand

idk how to do that

[tranquil quiver]

lets try this

[thick oracle]

look

[tranquil quiver]

what if the top half of the circle is part of the shaded area

[smoky trout]

OH

3? 😭😭

am i dumb

[tranquil quiver]

you need to slow down

before jumping into numbers and calculations

[smoky trout]

ok ok pk

[tranquil quiver]

understand what you are doing

[smoky trout]

yes

[fair monolith]

do u know how to calculate the area of a circle

[smoky trout]

yes im listening sorry

[smoky trout]

NO😭😭

[tranquil quiver]

so say the top half of the circle is included in the shaded area

[fair monolith]

do you know how to calculate the area of a square

[tranquil quiver]

then what shape is the shaded area

[smoky trout]

ok yes

[smoky trout]

A square

[fair monolith]

notice how a part of the circle is in the square

[tranquil quiver]

exactly

[timid silo]

let one person to explain it for him

[fair monolith]

alr

[tranquil quiver]

and calculating the area of a square is quite easy right?

[smoky trout]

its just sxs right

[tranquil quiver]

so if you could calculate the area of the part we temporaily added (top of the circle)

[tranquil quiver]

yep

[tranquil quiver]

and then subtract this from the area of the square

you would have the shaded area

does that make sense?

[smoky trout]

but all i have is the radius of the circle

[tranquil quiver]

we will get there

[smoky trout]

so how do get the area of the square😭

[tranquil quiver]

so first we need to find the side length of the square right?

[smoky trout]

yes

[tranquil quiver]

now in the picture what can you see about the bottom side

one of the sides of the square is just the diameter of the circle right

[smoky trout]

wait so would the sides be 6? 🧍‍♀️

[thick oracle]

no

[tranquil quiver]

not quite

[thick oracle]

here

[tranquil quiver]

the bottom side is the diameter of the circle right?

[smoky trout]

God😭

[thick oracle]

maybe this helps

[tranquil quiver]

@smoky trout

do you understand this part

[smoky trout]

right

i think

[tranquil quiver]

and do you know the relationship between diameter and radius in a circle

[smoky trout]

no😭😭

[tranquil quiver]

okay

[smoky trout]

it’s because i did online school for gr 8 and i never joined casses

classes

[fair monolith]

oh.

[tranquil quiver]

radius is from the midpoint to the edge

[smoky trout]

so now im in grade 9 and have no idea how to do basics

[tranquil quiver]

and the diameter is just 2 times the radius

[smoky trout]

ok ok

[fair monolith]

id recommend that u solidify your knowledge on areas of figures after this

[tranquil quiver]

yeah notice if u draw a line from the centre to any edge it will be the same length

[tranquil quiver]

so from radius u can find the diameter just need to multiply it by 2

[fair monolith]

straight line*

[tranquil quiver]

ah i gotta go for dinner someone else help 😔

[smoky trout]

so the diameter of the circle is 12

[fair monolith]

k

yeah

[tranquil quiver]

yep and so is the side length of the square

good luck

[smoky trout]

so the sides are 12

[fair monolith]

yeah

so what's the area of the square

[smoky trout]

144?

[fair monolith]

yeah

now notice how half of the circle is in the square part

so we'll have to subtract a half of the area of the circle

cause the half of the circle in the square is not shaded

[smoky trout]

so divide 144 by 2

[fair monolith]

no not like that

do you know the formula for area of a circle

[smoky trout]

A=r2

? 😭

im guessing atp

[fair monolith]

R2?

its pi times r squared

where r is the radius

so in this case the radius is 6

so what would the area be

[smoky trout]

okay yes

😁

IDK

[fair monolith]

the radius is 6

[smoky trout]

yes

[fair monolith]

what is 6 squared

[smoky trout]

36

NO

wait

[fair monolith]

yea

[smoky trout]

oh yes it is

[fair monolith]

so the area is pi times 36

[smoky trout]

nvm

[fair monolith]

and cause half the circle is in the square

[smoky trout]

tf is pi💀

[fair monolith]

3.14

22/7

$\pi$

[warm shale]

satvik.

[fair monolith]

that thing

[smoky trout]

yes okay

[strong atlas]

i need some help with a puzzle

[fair monolith]

@strong atlas #❓how-to-get-help

this channel is already taken

[smoky trout]

is this the answer?

[fair monolith]

no that's the area of the circle

[smoky trout]

OHHH

[fair monolith]

you need to divide it by 2 to get the area of half the circle

and then

subtract it from 144 cause the half of the circle is not included in the square

so your final answer would be

$144 - ((\pi 36)/2)$

[warm shale]

satvik.

[fair monolith]

the pi and 36 are being multiplied together

and the whole thing is being divided by 2

[smoky trout]

god😭😭

okay

i needa fr study after this

[fair monolith]

ok

[smoky trout]

thank you tho

sm

[fair monolith]

np

close the channel with .close

[smoky trout]

pkay okay i will

im just writing the notes quickly

.close

[obtuse pebble]

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[sage dagger]

for part B, how do i use sides bc and ab to find phi and theta

[sage dagger]

do i just use pythagoras on bc and ab

to get hyp

[dark mango]

dude i told u how to do this before lol

[sage dagger]

yeah lmfao

but

wtf do i do with hypotenus

[dark mango]

huh?

you can use pythag yeah

[sage dagger]

2.4 is hypotenuse for the bc

so itll be the same for ab right

[dark mango]

,w root(20)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by cantprogram#3779

[sage dagger]

oops

i forgot to add squared

mb

[dark mango]

what line are u referring to

[sage dagger]

so 4.4cm is the hypotenuse for this

[dark mango]

yeah

[sage dagger]

do we also find the angle for bc?

[dark mango]

leave it as root(20) when ur doing ur calculations so u dont have rounding errors

[dark mango]

BCD ?

wait

[dark mango]

i mean

yea

find that and the other one

next to theta

and then just do 90 - (angle1 + angle2)

we went over this lol

[sage dagger]

wouldnt this angle be the same as angle AD

[dark mango]

yes

AD isnt an angle but ik what u mean

[sage dagger]

so i just find phi first then to find bd

[dark mango]

what

just do 90 - (2phi)

[sage dagger]

ok

am i using inverse tan then

to find angle

[dark mango]

yeah i guess

u didnt need hypotenuse then actually lol

[sage dagger]

oh right

26.5 is the angle

[dark mango]

cool

[sage dagger]

so 37

ight cool

ty

also

for c

do you think im supposed to find x

or the whole adjacent side

[obtuse pebble]

@sage dagger Has your question been resolved?

[dark mango]

well if the questions asking to find the value of x you find x lol

[obtuse pebble]

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[obtuse pebble]

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[obtuse pebble]

@little lynx Has your question been resolved?

[obtuse pebble]

@little lynx Has your question been resolved?

[little lynx]

<@&286206848099549185>

<@&286206848099549185>

[solar hornet]

@little lynx hey, what class is this? is it about combinatorics, sets or..?

[little lynx]

Combinations and permutation

[solar hornet]

aight you just need to use the formula

[little lynx]

There are repetitions tho

[solar hornet]

does that matter?

two d's are just two letters

and you are selecting 5 letters, it doesn't say they have to be different

[little lynx]

So if abcc
Then abc with first c
And abc with second c
Considered one or two?

[solar hornet]

i think each letter is an nth element, and you are looking for a combination of these elements

regardless of what they are. I might be wrong tho

[little lynx]

So one or two

😅

[little lynx]

This

@solar hornet 🥺

<@&286206848099549185>

[solar hornet]

two

ok you know what, I think I'm wrong

I need to check

so order doesn't matter, and repetitions aren't allowed I guess

because in the example you gave:
Then abc with first c
And abc with second c
I don't see how we could present a result showing two selections were different

[severe dune]

Since if we list the letters as pcinnndd

There are 3 factorial ways of arranging the n's and 2factorial ways of arranging the d s

So you will have to divide by this at some point

So if we assume all 8 elements are differnt

We have 8x7x6x5x4 or 8factoeial/3factorial 8P3 ways of picking 5 numbers

Bur since dicpn isn't distinct from icpnd we are overocuntinf

So we're counting 3 factorial times more outcomes for n

And 2 rimes for d

So divide by these

To get 8 factorial / (3 factoeila x 3factoejal x 2 factorial)/5 factorial

You might find these helpful

Have a read

@little lynx

[little lynx]

!close

.close

[obtuse pebble]

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[ruby mantle]

My friend showed how to prove 2=0 and idk where's the mistake 💀

[obtuse pebble]

@ruby mantle Has your question been resolved?

[snow pewter]

line 6, I believe

iirc, it isn't i= √-1

but rather i² = -1

so you get that i= ±√-1

I'm not entirely sure though

[drifting badger]

That is true, yes

[ruby mantle]

ohhh ic

.close

[obtuse pebble]

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[boreal cipher]

!help

[boreal cipher]

A piece of rope is 4 2/7 metres long. It has to be cut into pieces of length 2/3
metres long. How many FULL pieces can be cut?

Struggling with this

um

[cloud berry]

4 2/7 = 30/7

(30/7)/(2/3)

(30/7)*(3/2)

= 90/14

[boreal cipher]

90/14

so 5

[cloud berry]

yeah

[boreal cipher]

Nop

6.42857142857

[cloud berry]

6

[boreal cipher]

But i am not allowed a calculator for that question

[cloud berry]

use division manually

[boreal cipher]

so write it down

[cloud berry]

i don't hv phone

[boreal cipher]

Huh

id just do

[cloud berry]

can you write 90/14 in mixed fraction

[boreal cipher]

14|90

14 goes into 90 six times
leftover of 6
6.4

6 6/14

I tried to simplify it but it didnt make sense

[cloud berry]

6/14 is less than 1

[boreal cipher]

Six full pieces can be CUT

[cloud berry]

so 6 is the ans

yeah

we're messing it up

[boreal cipher]

whats the median

I know its between 5 and 8

[lyric ember]

for all the values?

or for the 2nd row

[boreal cipher]

just the whole stem and leaf

Whats the median

[cloud berry]

2(MEAN) + MODE = 3(MEDIAN)

[boreal cipher]

What

[cloud berry]

find MEAN and MODE

and then apply this formula

[boreal cipher]

There was an easier way

Of just crossing out the smallest and largest

[lethal pier]

so do that

[cloud berry]

is this data is grouped or ungrouped i don't understand what's written

[boreal cipher]

I have and now i have to find inebetween 5 nad 8

and 8

[lethal pier]

(5+8)/2

[boreal cipher]

13/2 = 6.5

[lethal pier]

(25+28)/2

its stem and leaf

[boreal cipher]

53/2 = 26.5

[cloud berry]

whats stem and leaf ???

[boreal cipher]

A type of diagram that represents information

Um i think i screwed up on this

it was acutally

4x+41 = 96

Frakc

Nvm i worked it out lol

Would the mean to | 5,8,8,8,11,12,14,15,16,20,21,28,29,34
Mean = 16.4

[obtuse pebble]

@boreal cipher Has your question been resolved?

[obtuse pebble]

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[timid silo]

6^2-3^2=x^2

[tough hull]

So as you can see when there are two triangles with x on one side and y on the other u do cross multiply with 1 number given in each however in the second pic there are 2 numbers given in addition to x and y so what would u do

[timid silo]

it's easy do Pythagoras rules

[tough hull]

Yeah but it's usually x2 = something2 + something2 not subtraction

[timid silo]

pic1?

[tough hull]

It's not loading for u ?

[timid silo]

8^2 - 6^2 = y^2

[tough hull]

No cuz that'll equal 28 power root

But it will work if we take away the ^2

So weird

I checked the answers

[timid silo]

6/8 = x/6

6/8 = 3/y

its true

because its angel same

[tough hull]

Yeah that's the correct answer

We have 4 and 4.5

[timid silo]

good

[spring trail]

so u r not understanding the minus?

[tough hull]

That equation isn't needed here

At least from my mind

[spring trail]

so u think

u can do it without pythagorean thorem?

[tough hull]

Umm idk but I know I understand whatever the triangle thing thats coming in the exam what I don't understand is

[spring trail]

is?

[spring trail]

i feel like u dont understand the pythagorean theorem

[tough hull]

I looked at other questions and their answers and the triangles in the circle never add up to 180 at least not in these questions

[spring trail]

do u know what the hypotenuse is?

[spring trail]

probly a mistake

[strong atlas]

whenever a triangle is made in a circle with diameter as base,the angle opposite to the centre is a right angle

[tough hull]

Yeah but how do I find the 2 other angles that keep getting mentioned in the chapter if there's no 180 to be subtracted from

[spring trail]

look at 3 a

can u find beta?

look at the triangle with 42 beta and the other think which is (alpha + something)

that alpha + something is actually 90; if u havent studied it let it be; u'll get it later

[tough hull]

Ok so since 90 - 42 is 48

[spring trail]

or watch

https://www.youtube.com/watch?v=ATPJredjPuY

[spring trail]

yep

[tough hull]

What abt the other number

Or angle

[spring trail]

then in the left side triangle, it is actually isosceles

look at it well

[bold bane]

Use the arc measure.

[tough hull]

Yeah yeah but how did they calculate it

I mean I know the answer is 50 I checked