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#help-10
obtuse pebbleBOT
Available help channel!
brisk radish
hi
brisk radish
i am new in this server
tight bison
what is your question?
merry geode
i am new in this server
obtuse pebbleBOT
@brisk radish Has your question been resolved?
obtuse pebbleBOT
@brisk radish Has your question been resolved?
warm shaleBOT
kartheek
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uneven plinth
So, we want to prove that the slope of the secant line on the interval [2,3] is greater than the slope of the secant line on the interval [1,2] when f''(x) > 0. I get that upwards concavity would mean that the slope of that secant line gets bigger the farther along the line you go (right?), but i'm not sure how to prove this mathematically
obtuse pebbleBOT
So, we want to prove that the slope of the secant line on the interval [2,3] is...
@uneven plinth Has your question been resolved?
uneven plinth
<@&286206848099549185>
uneven plinth
Applying the mean value theorem here, all I'm able to get conceptually is that f'(c1) = f(3) - f(2), and f'(c2) = f(2)-f(1). We're trying to prove (f(3) - f(2)) > (f(2) - f(1)) on an open interval (0,4) that is concave up ( slope of tan line increasing, implying that the function is increasing for greater values of x)
how can I prove, that for a function with a second derivative greater than 0 over an interval (a,b), f(x) > f(y) when x > y
or am i proving that f'(x) > f'(y) when x>y
or am i misunderstanding this?
uneven plinth
obtuse pebbleBOT
@uneven plinth Has your question been resolved?
uneven plinth
.close
red stag
I know that (mv^2)/2 is the formula for Kinetic energy, but what would be the formula for Kinetic energy but if the body had initial velocity as well?
obtuse pebbleBOT
I know that (mv^2)/2 is the formula for Kinetic energy, but what would be the fo...
warm canopy
? The v in that formula stands for "the current velocity"
red stag
Yeah
I rephrased my question
But I dont have at
Oh
Wait
Isnt at just the final velocity?
warm canopy
Sounds like an XY problem
red stag
Well yeah, but doesnt it equal the current velocity?
Because I dont have acceleration and time
warm canopy
hard yacht
Guys for the love of god ive been struggling to answer these 2 questions for a homework may someone please explain to me? they are applied statistics
obtuse pebbleBOT
Guys for the love of god ive been struggling to answer these 2 questions for a h...
hard yacht
The probability that at a filling station one has to wait more than 5 minutes for the service is 0.15. Given the waiting time is ξ∼Exp(λ) find the probability that we are served in 3 minutes after arrival.
λ= ?
P(ξ<3)= ?
and this question
The air control informs the pilot of an aircraft about the altitude of the centre of the air corridor of height 110 metres where the aircraft should fly. The deviation, in metres, of the altitude of the aircraft from the given altitude is normally distributed with mean 0 metres, and standard deviation 50 metres.
Find the probability that the aircraft flies in the air corridor.
Find the probability that the aircraft flies above the air corridor.
<@&286206848099549185>
obtuse pebbleBOT
@hard yacht Has your question been resolved?
obtuse pebbleBOT
Available help channel!
celest mantle
obtuse pebbleBOT
https://gyazo.com/6442ade3718caf58b6f26a50415df894
celest mantle
can someone explain this for me
fierce lagoon
Find the common difference
celest mantle
4 is the difference
celest mantle
-4?
celest mantle
yea
fierce lagoon
You can find when n=0
celest mantle
and you always write N after the differnece?
fierce lagoon
$$a_1 = -4n + a_0$$
$$43 = -4(1) + a_0$$
What would a0 be
Oh bruh the bot is dead
fierce lagoon
and you always write N after the differnece?
Yes
celest mantle
and then the 53?
celest mantle
LMAO
celest mantle
a_0?
fierce lagoon
a sub 0
I can't do subscripts the bot is dead
So
a_0 is a variable to denote the 0th term of the sequence
celest mantle
oh so the one before?
fierce lagoon
Yes
celest mantle
should i just remember the difference
fierce lagoon
The one before 49
fierce lagoon
Well no there's a formula for finding the 0th term
celest mantle
is it always the one before the highest or wtvr
celest mantle
a_n = dn + a_0
i got no clue what this is about
fierce lagoon
when n = 1, a_n = a_1 = 49
fierce lagoon
i got no clue what this is about
The literal definition of a geometric series
So if n = 1
celest mantle
-4(1)
fierce lagoon
a_1 = d(1) + a_0
You know what d is:
49 = -4(1) + a_0
It's just algebra at this point
The bot seems to wanna die so
lethal chasm
obtuse pebbleBOT
distant moth
I would draw the graph and vheck
lethal chasm
Okay thanks
obtuse pebbleBOT
@lethal chasm Has your question been resolved?
opal otter
Hi
I have an assigment of the following. Ignore the danish text. I need to explain how happens from step 2 to 3 and 4. Then i need to argue for why tangents in x_0 and -x_0 always will be parallel with each other
obtuse pebbleBOT
Hi
I have an assigment of the following. Ignore the danish text. I need to expl...
opal otter
opal otter
How about the step from 2 to 3?
opal otter
But, how
dark mango
yes
opal otter
So. the functions are basically the same, right?
opal otter
Wow, okay. Thank you so much, man
manic vigil
obtuse pebbleBOT
manic vigil
I need help completing these two questions
cedar lichen
What have you tried
cedar lichen
Do you know any formulae involving the coefficient of friction, μ?
cedar lichen
What is it?
manic vigil
0
visual epoch
32 - ? = 0?
manic vigil
32 sire
visual epoch
then that's friction
there's no other vertical force acting on your object other than gravity, right?
manic vigil
Yeah
visual epoch
then I think for this one, your normal force (upward force) should be equal to your downward force
should be either the weight or gravity, which do you think?
then you just find the coefficient when you plug it into the formula
friction / F_n
manic vigil
should be either the weight or gravity, which do you think?
Gravity?
manic vigil
then you just find the coefficient when you plug it into the formula
K thanks
visual epoch
the weight of the object
so, 9.81 * your given mass
9.81 being your given g value
visual epoch
refer to the formula
manic vigil
Alright appreciate it
obtuse pebbleBOT
@manic vigil Has your question been resolved?
mental sphinx
OABC is a rectangle, X is on ASB, I need to find vector OX by u v and w
obtuse pebbleBOT
OABC is a rectangle, X is on ASB, I need to find vector OX by u v and w
mental sphinx
I know that |u|=|w|=1
|v| = 2
uv = 0, wv = 0, wu = 0.
but i dont know from where to start
obtuse pebbleBOT
@mental sphinx Has your question been resolved?
dull shoal
hi, i need help with this question( the part to explain ):
obtuse pebbleBOT
hi, i need help with this question( the part to explain ):
stable rain
eh
prob say its strictly increasing or decreasing over some interval
using f' n f''
obtuse pebbleBOT
@dull shoal Has your question been resolved?
obtuse pebbleBOT
cedar lichen
1/(2 + x)²(2 - x)² = the expression in the integral
Multiply both sides by (2 + x)²(2 - x)²
You found B and D by letting x = 2 and x = -2?
Now let x be other things
Like 0 and 1
cedar lichen
How'd you get 9A
obtuse pebbleBOT
@forest crag Has your question been resolved?
obtuse pebbleBOT
@forest crag Has your question been resolved?
timid silo
Is this good, im thinking in this situation a must equal to b for the equation to hold and thats only in zero
obtuse pebbleBOT
Is this good, im thinking in this situation a must equal to b for the equation t...
solar hornet
this is not congruent for all x! I read it wrong
stable rain
im so lost
timid silo
Wish i would know how to express myself on english
Ill try tho but maybe i wont be understood
Okay so in the equation i have 1sqrt of something + 4 sqrt of somethinf = to 5*sqrt of something
solar hornet
yeah
timid silo
Yes so
solar hornet
you could cube both sides tho?
stable rain
so mayb i would say
cbrt (something_1) cbrt(something_2)
to kinda differentiate
but like
just use the original thing lol
introducing too many vars is a bit messy after awhile
stable rain
timid silo
Ye that one
solar hornet
I don't see a simple identity here
timid silo
Im p sure a and b must be equal
stable rain
it defn doesnt hold
no what
oh wait the coe of the first is 1
i read it as 3
lol
stable rain
I don't see a simple identity here
anyway this
timid silo
Ye my bad in writting there
stable rain
na that my bad
solar hornet
but lo and behold, wolfram says solutions are a=0 and b=0 lol
if we take the third row
solar hornet
Not sure man, looks like you got lucky in this case.
This method shouldn't have worked for you.
But stuff like this happens when zeros appear in solutions..
solar hornet
make sure you ask your teacher how to actually solve this! yw
timid silo
I will, it was actually one year on the tests
timid silo
but lo and behold, wolfram says solutions are a=0 and b=0 lol
We kinda missunderstood each other at this part
timid silo
I didnt
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
vapid snow
obtuse pebbleBOT
vapid snow
how would they both be in the 4rth quad?
vapid snow
Draw a triangle in the 4th quadrant
would the triangle be the cos one ?
where would the sin one go ?
fierce lagoon
Sine is also part of the triangle
obtuse pebbleBOT
@vapid snow Has your question been resolved?
vapid snow
wdym by that?
drowsy nest
your diagram is wrong
you wrote 11 and 37
its 12 and 37
and you labeled 37 at the wrong spot
and you have to draw 2 of those diagrams
one for sin(x) and other for cos(y)
vapid snow
ohh
drowsy nest
wait
no you labeled 37 in the right spot
im the one whose wrong
its just the 11 thats wrong
hold on
vapid snow
but 11 adjacent
drowsy nest
for sin(x) = -12/37
draw that triangle alone
sin is opposite / hypothenuse
opposite = 12 and hypothenuse is 37
dont mix the two. dont draw triangle for sin(x) and cos(y) in one diagram
vapid snow
is the unkown angle the thing u put in for the formula?
vapid snow
unknown angle?
or side i mean
vapid snow
did you draw both of the diagrams?
drowsy nest
ya
its better to label angles x and y
not theta
since its sin(x) and not sin(theta)
vapid snow
yea true
drowsy nest
for the first diagram you have y angle for theta
you can find the hypothenuse
and from the triangle sin(y) and cos(y)
for the second one you can find sin(x) and cos(x)
vapid snow
then would i find that angle ?
drowsy nest
you would have to solve for all of them
and yes you would then be able to find tan(x-y)
cause tan(x) = sin(x)/cos(x) and tan(y) = sin(y)/cos(y)
vapid snow
when u get the sides
it doesnt have a whole number
so would i leave it as sqrt(3842)
?
drowsy nest
ya
vapid snow
oh dont worry about that
our teacher uses a generator
one time we had to graph in the trillions
drowsy nest
no your squaring the terms
its x^2 + (-12)^2 = 37^2
the negative becomes a positive
since its squared
vapid snow
ohh i see
drowsy nest
ya
tan(x) = sin(x)/cos(x) and tan(y) = sin(y)/cos(y)
wait
for the first one you wrote it wrong
cos = adjacent/hypothenuse
you wrong 61 as y coordinate instead of hypothenuse
drowsy nest
something doesnt seem right
you should be getting tan(y) for the first graph and tan(x) for the second graph
you have the tan(x) and tan(y) written wrong at the bottom
they should the the other way around
drowsy nest
i hate working with numbers like that but okay
drowsy nest
do what?
drowsy nest
this image you posted looks correct
to simplify that you use algebra
you already did the owkr
wprl
work
vapid snow
.close
obtuse pebbleBOT
vapid snow
obtuse pebbleBOT
Available help channel!
vapid snow
obtuse pebbleBOT
drowsy nest
are you trying to prove that the right side equals the left
vapid snow
yea
dark mango
bro listed every trig formula 💀
vapid snow
i dont think i could use
this is the one my teacher gave
so this is all we need to know
but i cant use corelated
cause the denominator is 4
dark mango
what is the original equation
dark mango
sin(x) = 1-2sin^2(pi/4 - x/2) ?
vapid snow
yea
drowsy nest
maybe sin(x-y) would be useful
dark mango
thats not how i'd do it
drowsy nest
nevermind i wouldnt do it like that
dark mango
💀
drowsy nest
if you used it then you would introduce a cos term
drowsy nest
but theres a pi/4
dark mango
sin^2(theta) = (1-cos(2theta)) / 2
@vapid snow half angle and use the fact that cos(pi/2 - x) = sin(x)
drowsy nest
ohh okay
vapid snow
<@673726599299858460> half angle and use the fact that cos(pi/2 - x) = sin(x)
wait wdym by half angle?
drowsy nest
teacher didnt include half angle identity on the formula sheet
dark mango
did they include double angle
dark mango
i dont think i could use
i cant read this its too small
vapid snow
oh my bad lemme get a better shot
dark mango
im sure they included either half angle or double angle in a list of trig identities
drowsy nest
yeah they included double angel
dark mango
yes
vapid snow
ohhh
vapid snow
but ig id use the initial one
dark mango
cos(2x) = 1-2sin^2(x) is the same as sin^2(theta) = (1-cos(2theta)) / 2
just rearranged
making sin^2(x) the subject
vapid snow
oh i see
vapid snow
yeah they included double angel
yo bro
i think im almost done
but
the math may math
but its a little weird
any thoughts ?
dark mango
vapid snow
oh no
dark mango
why ?
vapid snow
the teacher said
dark mango
yea that ruins everything
vapid snow
Xd
dark mango
notice cos(pi/2 - x) = sin(x)
vapid snow
notice cos(pi/2 - x) = sin(x)
yea
vapid snow
notice cos(pi/2 - x) = sin(x)
is this not the x tho?
the whole thing in the bracket
dark mango
2 * (pi/4 - x/2) = pi/2 - x
dark mango
is this not the x tho?
no? x is x
vapid snow
cos(pi/2 - x) is the exact same as sin(x)
I think im confused on how to subsitute the x into this
dark mango
What substitution ????
if you see cos(pi/2 - x) you can replace it with sin(x)
thats all its saying
you are overcomplicating this
vapid snow
bet thanks
dark mango
just write the question on a new page and send an image
dark mango
ok so this turns into
1 - 2( )
wait
let me use latex
testing $1 - 2(\frac{1-cos(2(\frac{pi}{4} - \frac{x}{2}))}{2})$
ignore
vapid snow
alr lol
dark mango
using half angle identity we get
$1 - 2(\frac{1-cos(2(\frac{pi}{4} - \frac{x}{2}))}{2})$
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
dark mango
notice $cos(\frac{pi}{2} - x)$ is equal to $sin(x)$
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
warm shaleBOT
cantprogram
dark mango
sorry i multiplied wrong lol
vapid snow
damn ur a genius
dark mango
damn ur a genius
not really I think u just over complicated it
vapid snow
it was at the top step
warm shaleBOT
cantprogram
dark mango
?
dark mango
its just using $sin(\theta) = \frac{1-cos(2\theta)}{2}$
warm shaleBOT
cantprogram
dark mango
i had the 2 out of the bracket
I see
yeah you have to multiply the argument of sin
by two
vapid snow
yea
dark mango
ok you can .close
dark mango
👍
vapid snow
.close
violet sentinel
hi did you see your mistake?
stone bone
minus
shadow estuary
wait
stone bone
you didnt carry it over
shadow estuary
there isnt a - in the identity?
stone bone
well you subtracted the sines but your answer added em
violet sentinel
$sin(\frac{3pi}{4}) \neq -\frac{sqrt{2}}{2}$
warm shaleBOT
MellowDramaLlama
violet sentinel
oh well you get the idea lol
shadow estuary
wait no i dont
violet sentinel
it's positive
shadow estuary
positive sqrt 2/2?
violet sentinel
yep!
shadow estuary
but isnt there a - in the actual identity?
stone bone
yes
shadow estuary
violet sentinel
yeah you're right
shadow estuary
wait so what did i do wrong
stone bone
why in your formula you got -root2/2*1/2 but its positive in your ans
should be -root6 minus root2
make sense?
shadow estuary
i think i did it right
nocturne minnow
should be -root6 minus root2
Factored out a negative to get -(sqrt(6) + sqrt(2))
violet sentinel
why in your formula you got -root2/2*1/2 but its positive in your ans
I think he's right... sin(3pi/4) = sqrt(2)/2, and sin(pi/6) = 1/2
stone bone
oh i see! didnt see it out on the side
shadow estuary
shadow estuary
no i did something wrong
violet sentinel
it's 4 on the bottom
stone bone
@shadow estuary its correct!
shadow estuary
no its not
nocturne minnow
Who is saying it's wrong?
shadow estuary
when i used a calculator for the original
stone bone
is your negative outside the divisor?
violet sentinel
you are correct 🙂
shadow estuary
it said i was wrong when i put it in earlier lmao
must have entered something in wrong ig
thx for helping me
violet sentinel
yeah you might have
nocturne minnow
when i used a calculator for the original
Are you in degree or radian mode?
obtuse pebbleBOT
Available help channel!
bright karma
obtuse pebbleBOT
bright karma
I am trying to understand how the asymptotes of a hyperbola are derived, above is the derivation for such
I am stuck on how (a^2)/(x^2) approach zero as x approaches infinity
is this due to the denominator becoming so large that the product of the fraction is so small that it can be said to be zero?
and thus has no affect on the term outside the brackets as the product just becoming proportionally bigger on that term? (on the therefore line)
bright karma
is that an identity? I am not very familiar with limits
solar hornet
are you sure this proof is correct? it doesn't make sense to me lol
solar hornet
ok ok I think I get it
because that x in there still goes to infinity
but that's what an asymptote is in this case
bright karma
the asymptote on a hyperbola, a general form for such
in tewrms of a, b and x
well the two asymptotes and their equations
bright karma
ah so it is sort of an identity?
solar hornet
yes
if you take something finite and divide it into infinitely many parts, you are left with nothing
bright karma
is this due to the divisor being infinitely large though, such that the product of the fraction ends up getting closer and closer to zero and thus can be assumed to be zero due to how miniscule the decimal product would be?
sorry im just trying to understand why
solar hornet
yes, it's not assumed to be zero, it's approximately zero
bright karma
okay, tysm for ur help man
solar hornet
when x goes to infinity, that line gets closer and closer to x axis
technically from what I know, the point at infinity doesn't exist, ie the exact value of f(inf) doesn't exist
but the limit does, and it's exactly zero
while the value of the function at that point, is approximately zero
it's not equal to zero
bright karma
yeah because its constantly decreasing with the asymptote at y = 0, but never reaching such, however, getting very very close
solar hornet
intimately close
bright karma
ahhh yeah thats a good interpretation, because you can see how small it gets visually
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
wise imp
please help
obtuse pebbleBOT
wise imp
ye ok sorry
spring trail
.close the channel
obtuse pebbleBOT
Available help channel!
proper nimbus
.help
obtuse pebbleBOT
Commands:
clopen: .close, .reopen, .solved, .unsolved
consensus: .poll
factoids: .tag
help: .help
Type .help <command name> for more info on a command.
obtuse pebbleBOT
Can someone help me with algebra
proper nimbus
teal turret
What are u having trouble on
proper nimbus
getting the final measure of m<ZIL
I dont have a protractor so its making the entire process very difficult
teal turret
Angle bisector essentially splits the angle into 2 equal measure angles
obtuse pebbleBOT
@proper nimbus Has your question been resolved?
shadow estuary
idk where to start on this problem
obtuse pebbleBOT
idk where to start on this problem
obtuse pebbleBOT
scenic sundial
forest sequoia
I need help…. please?
dark mango
obtuse pebbleBOT
Available help channel!
wanton dagger
How could I do this?
obtuse pebbleBOT
How could I do this?
warm shaleBOT
royal basin
^
wanton dagger
Thx
obtuse pebbleBOT
Available help channel!
tepid urchin
I do second derivatives to find inflection points? same way as I do critical points on the first derivative
obtuse pebbleBOT
I do second derivatives to find inflection points? same way as I do critical poi...
civic zealot
I do second derivatives to find inflection points? same way as I do critical poi...
yes
timid silo
Hey, so I'm trying to understand a little more about statistical transformations.
obtuse pebbleBOT
Hey, so I'm trying to understand a little more about statistical transformations...
timid silo
So, in the Statistics course I'm taking, they provide examples of transformations by replacing y with log(y) in power regressions, and replacing x and y with log(x) and log(y) for exponential models, respectively.
But you can also transform in other ways, such as taking the square root of the y and/or x-values, squaring them, and other transformations.
My question is, how do you know which transformation to use?
kind hawk
experience, trial and error
timid silo
Obviously you can use a calculator to calculate which model best represents the data, but I don't know how to do this as well without a calculator.
So...
trail musk
Whatever looks the prettiest when you graph it
timid silo
You just gotta brute force it until you figure out which one best represents the data?
I don't know if they'll have me transforming equations on the AP test, that's really my biggest concern. I know how they're supposed to work, it's just figuring out which one.
But since there's no clear-cut way, that... well, that sucks.
.close
tepid urchin
optimization problems \0/ wooooooooooooooooooooooooooooooooooooooooooooooo
tepid urchin
1200 is the surface area max volume
1200=x^2+4xy
1200-x^2/4x = y
?=x^2 * (1200-x^2/4x)
derivitive of that
2x+ (4x^2-8x-1200)/(4x)
2x+ (4x^2-8x-1200)/(4x) =0
*4x
8x^2+4x^2-8x-1200 = 0
/4
3x^2+2x-300 = 0
quadratic formula has a negitive number in the square root, what did I do wrong
<@&286206848099549185>
tepid urchin
what?
tepid urchin
why
royal glacier
You just said you substituted y back in
royal glacier
You forgot to multiply 4x with y
The 4x in the numberator and 4x in the denominator would cancel out
royal glacier
4x²???
tepid urchin
for the dirivitive i assume
royal glacier
Ok wait i am really not getting what youre trying to optimise
Are you trying to optimise x?
tepid urchin
royal glacier
Thats better
royal glacier
?=x^2 * (1200-x^2/4x)
This is a multiplication then, you are right
However you did the derivative wrong
tepid urchin
quotiant rule?
royal glacier
Yes
tepid urchin
a
royal glacier
Cancel out one of the x's and use the quotient rule
tepid urchin
what i do wrong
royal glacier
what i do wrong
You replaced the * with +
tepid urchin
wym
royal glacier
And used the sum rule
tepid urchin
where?
tepid urchin
how do a cancle an x
tepid urchin
what about the 1200
royal glacier
$$x² • \frac{1200-x²}{4x}$$
warm shaleBOT
5lttrz
white marsh
A student wants to determine the number of zeros for each of the given equations.
The equation x²+4x+3=0 has ? zeros.
The equation -x²+3x=0 has ? zeros
obtuse pebbleBOT
A student wants to determine the number of zeros for each of the given equations...
white marsh
.close
shell mauve
Looking for help
obtuse pebbleBOT
Looking for help
shell mauve
Topic is Exponential notation
thick oracle
you can post the problem
shell mauve
No like
The instructions
I multiply 1 eight times
Them the answer I get from multiplying 1 and 8 is the answer?
earnest elk
Not multiplying 1 and 8
Multiply 1 by itself 8 times
That would be the answer
Yes
shell mauve
Also
How do I make 50 Into a exponential notation
Or any numbers more than 50
I use continues division?
And divide 50 into primes
Until I get 1?
Then I multiply the 2
All the 2
Right?
Then 2 Raised to the power of blah blah blah right?
obtuse pebbleBOT
@shell mauve Has your question been resolved?
obtuse pebbleBOT
@shell mauve Has your question been resolved?
shell mauve
No
obtuse pebbleBOT
@shell mauve Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
jaunty shell
$(E): \frac{(x+1)^2}{9} + \frac{(y-2)^2}{b^2} = 1$
obtuse pebbleBOT
$(E): \frac{(x+1)^2}{9} + \frac{(y-2)^2}{b^2} = 1$
jaunty shell
$(E): \frac{(x+1)^2}{9} + \frac{(y-2)^2}{b^2} = 1$
can anyone help me find b
given x= -1
chrome sapphire
it looks like you’re dealing with an ellipse function. if you understand what b represents, you can try to solve for it with trig
obtuse pebbleBOT
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undone ember
obtuse pebbleBOT
undone ember
how do i simplify my answer from this to that
is there a simpler way where i dont over complicate things
pulsar sun
.close
undone ember
??
old mist
how do i simplify my answer from this to that
you made a mistake in the second to last line, you can't put the three inside like that, what you should do is combine the 3x-1 and get rid of the root, keeping 3/2
obtuse pebbleBOT
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fallow dust
Solve for x
obtuse pebbleBOT
Solve for x
fallow dust
$(log(10x^2))(log(x))=1$
warm shaleBOT
ManNotHot
obtuse pebbleBOT
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rustic sage
Hi
rustic sage
can someone explain to me how this turned to this?
I know that the derivative of tan is sec 2 x but what is the other stuff?
pine sail
So they've used two major rules there.
Chain rule.
Quotient rule.
If the names sound unfamiliar, check them out and I'm sure you'll get what's going on.
rustic sage
If the names sound unfamiliar, check them out and I'm sure you'll get what's goi...
Ohhh, thanks a lot
I get how the quotient rule was implemented and it made sense
but where was the chain rule used here?
nvm
Thanks a lot
.close
rustic sage
.
rustic sage
If the names sound unfamiliar, check them out and I'm sure you'll get what's goi...
when I tried solving it I got this
obtuse pebbleBOT
when I tried solving it I got this
rustic sage
not the same answer
obtuse pebbleBOT
@rustic sage Has your question been resolved?
obtuse pebbleBOT
@rustic sage Has your question been resolved?
rustic sage
.
timid silo
when I tried solving it I got this
d(tan(1/x)/dx = (sec²(1/x))(-1/x²)
rustic sage
d(tan(1/x)/dx = (sec²(1/x))(-1/x²)
but why (-1/x²)?
old smelt
If you have 5 dice, what is the chance that exactly 2 dice land on the same number?
obtuse pebbleBOT
If you have 5 dice, what is the chance that exactly 2 dice land on the same numb...
solar trellis
Binomial distribution
merry geode
Choose the remaining numbers
thick roost
Binomial distribution
So it would be this?
p = 1/6 (The chance to roll any given number per dice from 1 through 6)
n = 5 (The number of dice being rolled)
The number of possible values of successes k is then: k = 2 (Since we want 2 dice to match, and 3 dice to not match)
The resulting probability P is: P = 0.0353458 (The chance for 2 dice to be equal out of 5 dice)
solar trellis
Times 6
old smelt
How can I get the exact number tho using nCr or nPr or something
cause Im taking a combinatorics course
thick roost
Times 6
Since we are interested in the probability that exactly 2 dice are equal (rather than the probability for any 2 dice to be equal), we can subtract the probability that 3 dice are equal from 6 x P. This changes the answer only slightly to be equal to approximately 0.0342263, or less than 4%.
old smelt
cause the percentage doesnt help me cause thats not what the course is about
solar trellis
Times 6 for each value the 2 equal die can take
solar trellis
Since we are interested in the probability that exactly 2 dice are equal (rather...
Seems wrong
solar trellis
cause the percentage doesnt help me cause thats not what the course is about
Well that was the question
old smelt
mb on the question
solar trellis
If you wanna know how many such ways you can roll 5 die, multiply the probability by the total number of ways you can roll 5 die
old smelt
let me make meself more clear
thick roost
Seems wrong
Ah, yes. I did not fully comprehend the question. The probability of exactly 2 dice out of 5 dice being equal to the same number is approximately 0.0434783. This is achieved by multiplying the total number of possible combinations over all 6^5 possible results by the total number of possible combinations over only those 3125 possible results where two dice are matching and 3 dice are not. I also feel we can talk about this in DMs, as to not disturb the question.
old smelt
Reposting the question:
If you have 5 dice, what is the chance that exactly 2 dice land on the same number?
Note: Im looking for the exact number as im taking a combinatorics course. Ive been able to solve similar questions using nCr, but im not sure how to apply it in this case. However I assume it involves the principle of inclusion and exclusion
drifting wraith
axe that's literally the same thing
4 numbers
6c4
4 ways to double
6c4 × 4
5! / 2 ways to shuffle
3600
old smelt
I dont get how I struggle so much with them
cause I know its always the same thing
but I just cant get it right when applying it
drifting wraith
it's something to do with how boring it is for you
the brain rejects boring things, but non boring things are fine
that's why you know song lyrics, it's not "rhyming helps duh"
you kinda have to think that this is real or good or something
"i'm neutral this is not bad not good" may not cut it
obtuse pebbleBOT
@old smelt Has your question been resolved?
old smelt
yeah but im not like negative to it I just cant get the applying part correctly
Its not that its boring I dont find it boring I just dont know where to start
Everytime there is a new question Im just as lost
Got it
obtuse pebbleBOT
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old smelt
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frank creek
which side of an equation should you start with?
obtuse pebbleBOT
which side of an equation should you start with?
timber fox
whatever you're feeling on the day
sometimes im a lefty others im a righty
but in all seriousness, solving for a positive x normally ends up well, provided that you are solving for x
makes it easier
warm canopy
Wow look at the high and mighty centrist 😤
timber fox
robust sleet
Doeidnjdfiriiww
dense lodge
When u work out magnitude of a it doesn’t seem to work? Not sure what else to do
unborn canyon
i know its 6 but idk why
obtuse pebbleBOT
i know its 6 but idk why
tardy epoch
i know its 6 but idk why
then don't guess?