#help-10

1 messages · Page 62 of 1

warm shaleBOT
#

Denascite

loud tangle
#

if you really want you can do ln x and get 0.25 × ln x
then have (ln x)/4

glad stag
#

Hmmm okay

obtuse pebbleBOT
#

@glad stag Has your question been resolved?

glad stag
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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fervent girder
#

Need some help on 2 permutation and combination questions with explanation,

  1. There are 3 trays of sushi. The first has 3 pieces of A, the 2nd has 2 pieces and the last has 4 pieces. Find the number of ways to choose at least 1 sushi from any of the trays

  2. In a class, students form groups which consist of 4 or 5 students each. In how many ways can the project work groups be formed if the class size of a particular class is 17?

fervent girder
#

answer to the qn 1 is 59, answer to qn 2 is 35735700

sweet cobalt
#

Ok so looking at Q1, the very simplified example to start with is how many ways are there to pick a piece of sushi from the first tray?

fervent girder
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3?

sweet cobalt
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Yeah, and then how many ways are there to pick 2 pieces of sushi from the first tray?

fervent girder
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my bad for not mentioning that

sweet cobalt
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ah ok sure sorry

#

Let me have another think

fervent girder
#

I know the way to solve it is (number of ways without restrictions) - (number of ways where no sushi is chosen) = (number of ways at least 1 sushi is chosen)

sweet cobalt
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Yep

fervent girder
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but I'm not sure how to go about from there

sweet cobalt
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So number of ways to pick 0 is 1 right?

fervent girder
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yep

sweet cobalt
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I'm not sure if I quite understand the question then

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Oh wait I see it I think

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Ok so now we need to find the number of ways without restriction

fervent girder
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yeah

sweet cobalt
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Looking at tray 1

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What are your differetn options for amount of sushi picked?

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(0 is allowed as we are ignoring that for now)

fervent girder
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so 4?

sweet cobalt
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Yes

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What about tray 2?

fervent girder
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3

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5*

sweet cobalt
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Yep, and then tray 3 is 5

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Ok, so does it make sense that the total number of ways to pick from all 3 is 4 x 3 x 5?

fervent girder
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ohh ok

sweet cobalt
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So 4 x 3 x 5 = 60

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60 - 1 =59?

fervent girder
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I kept seeing it as 3 x 4 x 2

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yeah

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what abt qn 2?

sweet cobalt
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Yeah I did that at first, its always a pain to remember 0 lol

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Let me have a look

sweet cobalt
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Ok first lets look at the group composition

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Which combinations of groups of 4 and 5, will sum such that every student is in a group?

fervent girder
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3 groups of 4, 1 group of 5

sweet cobalt
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Yep exactly

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So we only need to worry about one combination

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Ok let me do some calculations

fervent girder
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alright

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what I tried was 17C4 x 13C4 x 9C4 x 5C5, but I didn't get the answer

sweet cobalt
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Yeah I also just tried that

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I also tried 17!/(4!)^3x(5!)

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But that was also wrong

fervent girder
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im guessing either the answer is wrong or I've been trying to solve the question wrongly the past few hours

timid silo
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which one u still need help with

fervent girder
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qn 2

timid silo
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okay

fervent girder
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answer is apparently 35735700 but I can't seem to get that number

timid silo
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well it has to be 3 groups of 4 and 1 group of 5

fervent girder
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yep

timid silo
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so first you choose group of 5 with 17c5

timid silo
fervent girder
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oh wait what

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yeah it is

timid silo
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yeah

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you have to divide by 3! for the order of the groups of 4

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since it doesnt matter which group of 4 you are in

fervent girder
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but in questions that give a certain number with a specific number of people in a group, why is it unecessary to divide as well?

timid silo
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wdym

fervent girder
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eg. in how many ways can 6 different articles be subdivided into groups of 2 articles each?

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this answer is just 6c2 x 4c2 x 2c2

timid silo
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taht would be 6c2 * 4c2 *2c2 /3!

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?

fervent girder
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ohhhhh

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ok yeah ur right

timid silo
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👍

fervent girder
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tysm,ur my saviour

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🥲

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ty @sweet cobalt for ur help with qn 1 =D

#

.close

obtuse pebbleBOT
#
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ancient lantern
obtuse pebbleBOT
ancient lantern
#

Anyone help w these?

twin lotus
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all of them

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?

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well in 3 i) u just have to prove that at least any two angles are the same using angle facts e.g alternate angles are the same or opposite angels on a intersection are the same

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@ancient lantern

ancient lantern
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Here

ancient lantern
ancient lantern
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I'm trying

twin lotus
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is it asking if the two triangles are similar/congruent?

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in question 3 i

ancient lantern
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Similar

twin lotus
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ok then yh, just prove any two angles are equal

ancient lantern
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And for 3 ii?

twin lotus
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is ND = DA?

ancient lantern
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It doesn't say

twin lotus
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well i think its only true if so, but idk how to word it

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if its been awhile just @ the helpers roll

obtuse pebbleBOT
#

@ancient lantern Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

i am from germany so sry if my english on the paper is weird. But well i am cs student and we are learning proofs and i am hardstuck on this ... they didn't even show it properly in a lecture and the book also doesn't really show how to proof something, i don't even know if i got the notations right in my "try". I learned about logic but this one just feels a bit different

timid silo
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proving this is the task

keen tiger
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as you've written down, 2 sets A and B are equivalent if and only if A is a subset of B and B is a subset of A

kind hawk
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what is the overline? complement or something?

timid silo
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complement yeah

kind hawk
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ok. lets take $x\in\overline{M\cup N}$. Then we know that $x$ is not in $M\cup N$

warm shaleBOT
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Denascite

kind hawk
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we want to show that $x$ is in $\overline M \cap \overline N$. That means we want to show that $x\in\overline M$ and $x\in\overline N$

warm shaleBOT
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Denascite

timid silo
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yeah i can follow 🤔

kind hawk
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when is x in overline M

timid silo
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when it's not in M

kind hawk
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ok. so that's where we want to get

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we know that x is not in MuN

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how do we get to where we want

timid silo
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when we show that x is not in M and not in N at the same time

kind hawk
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lets just show one of them for now, the other is then essentially the same

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we know: x is not in MuN
we want: x is not in M

timid silo
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so do i need to start with the right side?

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x is not in M when it's in -M

kind hawk
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what does it mean if x is not in MuN

timid silo
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it's part of everything else but MuN

kind hawk
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and what is MuN?

timid silo
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not x?

kind hawk
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what is the set MuN

timid silo
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M combined with N

kind hawk
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which elements are in that set

timid silo
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everything in M + everything in N

kind hawk
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if an element is in MuN, then it is in M or in N

timid silo
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ahh i oversaw that little detail

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it's like the logical or and the other one is like the logical and

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for x

kind hawk
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yes essentially

timid silo
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can i use the logical rules to proof it now?

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De Morgans

kind hawk
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yes

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(this is essentially the set version of de morgan)

timid silo
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so i can convert it to the logical one, proof it and then convert it back?

kind hawk
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if you do the conversion correctly, yes

timid silo
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x is in -(M v N)
then i do de morgans of the bracket
x is in -M and -N

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i wanted the screenshot to be posted first

kind hawk
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well lets not do MvN. "set or set" is nonsense

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the logical or is for statements, not sets

timid silo
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well if we know that x is not in M u N

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then we already know (MuN)\x

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i get the set operators but i just can't figure out of to work with them

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the logic operators are so much easier to work with

kind hawk
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$M\cup N$ is a set. $x\in M\cup N$ is a statement

warm shaleBOT
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Denascite

kind hawk
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try to write everything in terms of "x in ..." and "not(x in ...)"

timid silo
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ah ok so earlier my mistake was not using the correct terms?

kind hawk
timid silo
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x is in -(M u N)

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then x is in -M n -N

kind hawk
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that's what you want to show

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x is in compl(MuN)
not(x in MuN)
not(x in M or x in N)
not(x in M) and not(x in N)
x in comp(M) and x in comp(N)
x in comp(M) n comp(N)

timid silo
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the transition from or to and seems a bit odd to me

kind hawk
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that is de morgan

timid silo
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i get the rest but how does or become and once it splits

kind hawk
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not(A or B) = not(A) and not(B)

timid silo
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what how did they not teach us that

kind hawk
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what do you think de morgan is

timid silo
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ohhh

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wait you used the same de morgan from logic

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i am just not allowed to write it like that

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with v

kind hawk
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writing MvN is wrong

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v is not defined for sets

timid silo
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ok i kinda get it, now i just need to try the right side myself

timid silo
kind hawk
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well yes if you do it properly

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but stuff like "M or N" or "x in M or N" are false

timid silo
kind hawk
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yes

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(of course informally this stuff is fine. just you know, gotta stay correct for proofs)

timid silo
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yeah that's important, the professors told us to be very precise in this subject

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x is in comp(M) and x is in comp(N)
not(x is in M) and not(x is in M)
not (x is in M or x is in N)
not ( x is in MuN)

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x is in not(M u N)

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x is in comp (M u N)

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that should be the right side

kind hawk
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(which are the same steps as I did, just other direction)

timid silo
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is this the case for most proofs?

kind hawk
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no

timid silo
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ohh yeah my bad

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i get it

kind hawk
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dont worry about not seeing it. its also very good that you correctly produced the correct steps

timid silo
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it was because of this

kind hawk
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yes

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usually to show that sets are the same we need to show that each is a subset of the other and the directions are usually different

timid silo
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¬ can i use this instead of the not

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i can use both right?

kind hawk
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sure I just didn't have that symbol ready to write

timid silo
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ah ok thx a lot dude, you explained it very clearly

kind hawk
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youre welcome

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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marble hamlet
obtuse pebbleBOT
marble hamlet
#

Why does the way they factored out the bottom here not make sense? they have -2sin^2 theta

#

I only see cos^2theta and -sin^2theta which I made to cos(2theta)

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Is it just a different identity?

timid silo
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just using cos^2=1-sin^2

marble hamlet
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Ahh ok - I see that. is it wrong/better to use one or the other? I got the same answer using double angle

timid silo
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Doesnt matter

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Although sometimes one might be easier than other

marble hamlet
#

Yeah that's what I'm wondering as far as finding my tangents now - is that denominator easier to find the zeros for my dx/dtheta tangent ? gonna try with my equation too

timid silo
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i mean just try and see which one seems like less algebra

marble hamlet
#

true that - thank you much for explaining this!

#

.close

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bleak eagle
#

Ann if you are still out there, my battery died but I could still really use some help with the p-adics

timid silo
bleak eagle
#

oh thanks! i'm still not certain exactly how i would go about this problem with the geometric series

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let me grab a picture from the book real quick

timid silo
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$\sum_n p^{2n} =\frac{1}{1-p^2}$

bleak eagle
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$\sum_n p^{2n} =\frac{1}{1-p^2}$

warm shaleBOT
#

goobybalooby

bleak eagle
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right, but how can I deal with the 2 and 4x7 in front of the other two sums?

timid silo
#

multiply the whole sum by 2

bleak eagle
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i'm so lost, im so sorry! we were introduced to p-adics a week ago in my intro to math experimentation class and I have forgot everything about sums and series from calc 2

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how can i pull a 2 out of the whole sum if there are terms in the sum with a coefficient of 1?

timid silo
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$\sum 2p^{2n}=2\sum p^{2n}$

warm shaleBOT
timid silo
bleak eagle
#

wait, i got it!

#

sums to 333/16

#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
#

@timid silo Has your question been resolved?

daring rock
#

What was the original problem?

#

@timid silo

#

You just need to multiply the remainder by 2

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Since the division you did was technically by (x-0.5), your remainder term is -2.5/(x-0.5) which is equivalent to -5/(2x-1)

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Yeah, everything you did is right except the remainder should be -5

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$$\frac{8x^3-20x^+2x-2}{2x-1}$$
$$=\frac{4x^3-10x+x-1}{x-\frac{1}{2}}$$

warm shaleBOT
#

tatpoj

daring rock
#

This is what you did before you did the division, right?

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And then you end up with

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$4x^2-8x-3-\frac{2.5}{x+\frac{1}{2}}$

warm shaleBOT
#

tatpoj

daring rock
#

But, really you weren't dividing by x+1/2. You were dividing by 2x+1

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So if we multiply the last term by 2/2 we get

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$4x^2-8x-3-\frac{5}{2x+1}$

warm shaleBOT
#

tatpoj

daring rock
#

okay

#

You can continue factoring 8x^3-12x^2+6x-1

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How do you know what you can use?

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Like, why did you use 1 last time?

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Do you know the rational root theorem? Or sometimes it's called the rational zero test, or something like that

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So use that. What are the possible rational zeroes of 8x^3-12x^2+6x-1 ?

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That's not all

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No, the numerator has to be a factor of 1, and the denominator has to be a factor of 8

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So you could have 1, -1, 1/2, -1/2, 1/4, -1/4, 1/8, or -1/8

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No, but like, if 1/4 is the zero, it would correspond to a factor of (4x-1), for example, not (x-1/4)

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So you'd have to do the multiplying and dividing thing we did up here

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Yeah, synthetic division only works with things of the form (x-a)

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So you have to "cheat" it a little to make it work

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Or just use long division. But your directions say to use Horner so 🤷

#

8x^2-8x-2 ?

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Should be 4x^2-4x+1

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Yes

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Because $\frac{8x^3-12x^2+6x-1}{2x-1} = \frac{4x^3-6x^2+3x-\frac{1}{2}}{x-\frac{1}{2}}$

warm shaleBOT
#

tatpoj

daring rock
#

This only works because you divided the numerator and denominator each by 2

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You can't just divide the denominator by 2, that changes the result

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Yeah, looks good

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So then so far you have (x-1)(2x-1)(4x^2-4x+1)

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Oh, okay yeah

daring rock
#

We really wanted to divide by 2x-1, but synthetic division only works with something of the form (x+-a)

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But really the factor was 2x-1 all along

obtuse pebbleBOT
#
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carmine widget
#

Hi

obtuse pebbleBOT
carmine widget
#

I need some help with a Simpson's Rule question

obtuse pebbleBOT
#

@carmine widget Has your question been resolved?

carmine widget
#

<@&286206848099549185>

#

.close

obtuse pebbleBOT
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young atlas
obtuse pebbleBOT
fierce lagoon
#

What's your chemical reaction

#

@young atlas

#

Is it a synthesis reaction

young atlas
fierce lagoon
#

So it is synthesis of ammonia

young atlas
#

hows my number wrong

fierce lagoon
#

How many moles of ammonia are there is 10.63 g ammonia

young atlas
#

v

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0.6242 mol

fierce lagoon
#

Hydrogen has a molar mass of 1.01 g/mol

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Lemme check

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,calc 10.63/(14.01 + 3(1.01))

warm shaleBOT
#

Result:

0.62382629107981
fierce lagoon
#

Okay

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So how many moles of H2 is needed to produce 0.6242 mol NH3

young atlas
#

0.9362

fierce lagoon
#

Sure

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And then multiply that by 2.02

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I wonder if intermediate rounding screwed you over

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Maybe you need to put it all into one equation

young atlas
#

1.89

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got it

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need help with this part too

fierce lagoon
#

You do the same thing

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Stochiometry

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But with unfriendly numbers

young atlas
#

so

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where do i start

fierce lagoon
#

Turn it into moles first

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Because the equation uses moles

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And then stoich

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And then convert back to grams

young atlas
#

i got this

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6.05⋅1019
molecules

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@fierce lagoon whats the coeffiencent of h2o

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is it 1

fierce lagoon
#

You dont need H2O

young atlas
#

ik but i want to knoiw what it is

fierce lagoon
#

There's no H2O in the synthesis of NH3

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You don't need H2O at all

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It's utterly useless

young atlas
#

for this

fierce lagoon
#

Okay I feel like that's cut off

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Because no water should be produced in the synthesis of ammonia

young atlas
#

no its a different question

fierce lagoon
#

Well that's hella important

young atlas
fierce lagoon
#

I'm missing information

young atlas
#

this is it

fierce lagoon
#

Since O2 is the Limiting, you use stoich with the moles of oxygen

fierce lagoon
#

It is 1

young atlas
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so .760/3*1

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its not right tho

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I got .25 mol

fierce lagoon
#

Uh

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Noo...

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.760/3 is not 0.25

young atlas
#

so my clacualtion is wrong

fierce lagoon
#

Yes

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It's wrong

young atlas
#

?

#

u sure ?

young atlas
#

<@&286206848099549185>

#

.close

obtuse pebbleBOT
#
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limpid hill
#

HELP QUADRATIC FUNCTIONS ON A GRAPH

obtuse pebbleBOT
visual epoch
#

YES QUADRATIC FUNCTIONS ON A GRAPH WHAT?

limpid hill
#

VERTEX FORM STANDARD FORM AND CONVERTING STANDARD TO VERTEX AND VICE VERSA

nocturne minnow
#

WATCH VIDEOS

limpid hill
#

pls

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no

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i have four other homeworks to do broo plsss

nocturne minnow
#

If you don't have a specific problem you are stuck on, you are wasting people's time

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So you should close this and watch videos

limpid hill
#

i do have a specfici problem

visual epoch
#

yeah, show us

limpid hill
#

watch watch watch

#

my phone died

#

i will send the questions

#

y= -2(x-1)^2 +3

#

one

nocturne minnow
#

And the goal is?

limpid hill
#

y=(x+2)^2 - 1

limpid hill
#

im not done yet

#

y= +x^2 +2x - 8

visual epoch
limpid hill
#

y=x^2 +2x -3

#

(this one is being converted to vertex form

#

y= -2x^2 +12x -10

#

this one is being converted to vertex as well

#

y=1 (x-1)^2 -5 (this one being converted to standard

idle thunder
#

do you know how to find the vertex of that quadratic?

limpid hill
#

the others without bracket are bingegd graph

#

graphed

idle thunder
#

of x^2 +2x -3

limpid hill
#

ok thats a quadratic equation correct

idle thunder
limpid hill
#

first

#

idk but that one they plug y as 0 first

#

then found two numbers when mutliply give -3 but added give 2

#

then the factorize thing

#

i would send a picture but my phone is dead

young atlas
#

anyone know chem ?

idle thunder
#

you can factor the quadratic to find the roots, then find the axis of symmetry, then find the vertex

young atlas
#

rlly need some help

limpid hill
idle thunder
#

I would use this equation

#

vertex x-coordinate is -b/2a

limpid hill
idle thunder
#

then use that x coordinate to find the y value

limpid hill
#

here it is

limpid hill
#

and plug that into x to find y

#

and you got the vertex

idle thunder
#

yeah

#

then you know vertex form from there

limpid hill
#

but how would u find the intercepts for both x and y

limpid hill
#

i could kinda see it but look at this

idle thunder
limpid hill
#

my book has y= (x^2 +2x ) - 3

#

so in the space would be 1^2 right

idle thunder
#

oh you're doing it by completing the square

#

🥸

idle thunder
limpid hill
#

idk it any other way

idle thunder
#

because the third term to find the square is (b/2)^2

#

so 1 is correct

limpid hill
#

but look

#

y= (x^2 + 2x +1)-4

#

how does the 4 come in

#

and where did the square go

idle thunder
#

think of it like this

#

y + ____= (x^2 +2x + ____ ) - 3

#

y + 1 = (x^2 +2x + 1)-3

#

y = (x^2+2x+1) - 4

#

we added something to the RHS so we needed to add it to the LHS

limpid hill
#

ahh

#

and it cancels out from the left

nocturne minnow
limpid hill
idle thunder
#

what do you mean cancels out?

#

y + 1 = (x^2 +2x + 1)-3
-1 ...................... ...........-1
y = (x^2+2x+1) - 4

limpid hill
#

but in the second line the one isnt on the left side but it was on the right

#

-3 + 1 to -4

idle thunder
limpid hill
idle thunder
#

we subtracted 1 from both sides

#

y + 1 - 1 = (x^2 +2x + 1)-3 - 1

#

y = (x^2+2x+1) - 4

limpid hill
#

OHHH

#

a

#

a is 1

#

ok

#

also im confused about this one too the 2 is positive but how did it become negative

obtuse pebbleBOT
#

@limpid hill Has your question been resolved?

limpid hill
#

<@&286206848099549185>

#

someone pls help

#

its been a while

timid silo
limpid hill
#

and also why do we go down 8 units instead of 4 here

#

brooo

#

someone respond

#

<@&286206848099549185>

timid silo
#

i was

#

looking elsewhere

#

bsaically

#

vertex of a parabola is when

#

the (x+h)^2 term

#

is 0

#

so x=-h

#

what?

limpid hill
#

wait

#

i dont understand

limpid hill
#

<@&286206848099549185>

timid silo
#

idk how to explain sory

obtuse pebbleBOT
#

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sleek sinew
#

Would I prove this using AAS for the triangles to show XD = XE = XF?

#

And using CPCTC?

#

And I do not know how to prove Ray n contains point X

obtuse pebbleBOT
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brazen agate
#

How do you factorise x^2+4x−12?

obtuse pebbleBOT
sleek sinew
#

<@&286206848099549185>

timid silo
#

what

sleek sinew
#

Need help with showing ray n contains point X

timid silo
fierce lagoon
fierce lagoon
timid silo
#

i didnt know how to give a hint for that tho

#

also i kinda felt like it was a joke

#

question

fierce lagoon
brazen agate
fierce lagoon
#

People can struggle with conceptualization

brazen agate
#

thanks

brazen agate
#

this would be too easy for you tbh

fierce lagoon
#

Lol literally people in my Calc 3 class struggle with factorization 💀

timid silo
#

fr

fierce lagoon
#

Dw

fierce lagoon
#

Factorization for whatever reason seems hard for even high school seniors

fierce lagoon
#

Np

mental plaza
#

it’s the 1+1 ppl

#

o-O

obtuse pebbleBOT
#

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obtuse pebbleBOT
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meager bison
obtuse pebbleBOT
#

Please don't occupy multiple help channels.

timid silo
#

why did you do the same thing twice

meager bison
#

i didnt know

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.close

obtuse pebbleBOT
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meager bison
#

can some one help me please?

obtuse pebbleBOT
#

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teal birch
#

Hey guys! I was wondering about the warnsdorff's heuristic, notably in regards to it's use in the knight's tour. I have an understanding of the general idea (starting from any initial position on the board, move the knight to the square with the lowest possible moves) but I don't understand at all the mathematics behind it and I was hoping someone could guide me onto a good direction to research for myself or to give me an overview of the mathematics.
(I've used the warnsdorff path for myself on multiple knight's tours and i'm sure it works but i don't know WHY it works and that irks me quite a bit because I have no clue where to go to find out why).
Thank you in advance! :D

teal birch
#

Btw please ping me if you're going to respond, would be highly appreciated :D

obtuse pebbleBOT
#

@teal birch Has your question been resolved?

teal birch
#

.close

obtuse pebbleBOT
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grizzled bay
obtuse pebbleBOT
grizzled bay
#

I would like help as soon as possible, this is a timed homework assignment and only got 20 minutes left

olive swan
#

Wait

grizzled bay
#

I just need to know the inequalities to graph

olive swan
#

20000 in mutual funds

#

and 40000 in cd

grizzled bay
#

@olive swan 4600 in returns?

#

.close

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pale maple
obtuse pebbleBOT
pale maple
#

Hey I’m having trouble solving number 23!

#

<@&286206848099549185>

#

It's the setting up thats getting me. I understand that if we were to only look at it in the x y axis, we can get a figure and use that to find the bounds

obtuse pebbleBOT
#

@pale maple Has your question been resolved?

pale maple
#

.close

obtuse pebbleBOT
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stoic condor
#

Wouldn't Option D also be correct?

obtuse pebbleBOT
daring rock
#

Depends on the question, I guess

#

But yeah option D would be equivalent to B for whatever function f is

stable rain
#

lol ye

obtuse pebbleBOT
#

@stoic condor Has your question been resolved?

obtuse pebbleBOT
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undone ember
obtuse pebbleBOT
undone ember
#

could someone explain to me how the equation above was changed to the equation below

mental plaza
#

common denom

spice citrus
#

add 6 to both sides and factor out the y', then divide by the stuff that doesn't contain a y' on the left

undone ember
#

oh

#

i got it thank you

#

.close

obtuse pebbleBOT
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sacred totem
obtuse pebbleBOT
next reef
#

What is even your doubt?

sacred totem
#

I simply couldn't prove it

#

I tryed some stuff

#

1 sec

#

Excuse my writing

#

I don't think antg is useful here

obtuse pebbleBOT
#

@sacred totem Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
#
Channel closed

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sacred totem
#

. reopen

obtuse pebbleBOT
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mental plaza
#

hey

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

mental plaza
#

oh crap

#

I forgot to close

#

okay

#

how do I do 4

spice citrus
#

where do the curves intersect?

mental plaza
#

exactly

#

that’s the thing

#

they didn’t give bounds

#

idk

spice citrus
#

the bounds are where they intersect: x^3 = x

mental plaza
#

how do I find that

spice citrus
#

subtract x and factor

mental plaza
#

oh right

#

wait so

#

x(x^2-1)=0

spice citrus
#

yeah, there are 2 areas

mental plaza
#

x=0 or x= 1 or -1

spice citrus
#

Maybe the mean the combined area?

#

yes

#

let's just consider the area between 0 and 1, if you want the area of both areas just multiply the answer by 2

#

so, which function is bigger on the interval 0 to 1?

mental plaza
#

oh wait

#

how do u know the area from -1 to 0 is the same from 0 to 1

spice citrus
#

because both functions are odd

#

so the areas have rotational symmetry

mental plaza
#

oh

#

what do u mean by both fn are odd

spice citrus
#

a function f is odd if f(-x) = -f(x) for all x

mental plaza
#

ohhh

spice citrus
#

in other words: you can rotate a point on the graph by 180 degrees around the origin and the point will still be on the graph

#

but which function is bigger on the interval?

mental plaza
#

oh

#

wdym

mental plaza
spice citrus
#

well want to find the area, which is always positive

#

so you need to integrate over 1 function minus the other

#

,w graph y = x, y = x^3

spice citrus
#

what function is bigger for 0 <= x <= 1

obtuse pebbleBOT
#

@mental plaza Has your question been resolved?

mental plaza
#

y=x

spice citrus
#

yes

#

so what we need is $\int_{0}^{1}\left(x-x^{3}\right)dx$

warm shaleBOT
spice citrus
#

because x is bigger, we subtract x^3 from x

#

otherwise the area would be negative

mental plaza
#

OHHHH

#

do we need a graph this to see that x >x^3

#

from 0 to 1

obtuse pebbleBOT
#
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maiden pollen
obtuse pebbleBOT
maiden pollen
#

what yall need is jesus

spice citrus
#

do you have a question or not?

#

related to maths

obtuse pebbleBOT
#

@maiden pollen Has your question been resolved?

obtuse pebbleBOT
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elfin lagoon
#

What does -> mean in first order logic and can someone give me an example of a real world activities -> can be used in

elfin lagoon
#

Like q->p

drifting wraith
#

"if the kettle is boiling it has water"

elfin lagoon
#

Can -(r^p) be translated to something cannot be both the colour red and purple?

scarlet gale
#

A → B means that if A is true, then B has to be true as well.

#

So, if A is false, it doesn't have to do anything extra.

elfin lagoon
scarlet gale
#

If B is true, well, A is fine either way.

#

I'm talking about the → part you started with, not the ¬(r ∧ p).

elfin lagoon
#

Oh ok

scarlet gale
#

It's like a promise.

#

If A happens, B will happen too.

#

If A happens, B has to happen.

#

If A doesn't happen, it doesn't matter.

elfin lagoon
#

Ok thanks

scarlet gale
#

¬ means everything but this.

#

So, ¬(r ∧ p) means it can be anything except red and purple at the same time.

#

So, it could be red but not purple.

#

It could be green.

#

With DeMorgan's, ¬(r ∧ p) ≡ ¬r ∨ ¬p.

#

So, it's either not red or it's not purple or neither one.

elfin lagoon
#

K thanks

scarlet gale
#

No problem.

obtuse pebbleBOT
#

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timid silo
obtuse pebbleBOT
timid silo
#

the one above

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

clever vigil
#

What is your question @timid silo

timid silo
#

the one above in the photo

clever vigil
#

What did you not understand ?

timid silo
#

i dont know how to calxulate that

#

by substitution with infinity its indeterminate

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

solemn osprey
timid silo
#

say

solemn osprey
#

When taking limits to infinity, it’s important to consider the rate of increase

#

Of all the term, n, n^2, 2^n, 3^n, and 5^n, 5^n will always come out on top as the fastest grower

#

Eventually 5^n overtakes all of the other terms

#

Here’s a rule of thumb: a quadratic function (like n^2) eventually overtake a linear function (n)

#

And exponential functions( like 2, 3, and 5^n) eventually overtake quadratic functions

#

You with me so far?

timid silo
#

yes

#

i think so :))

solemn osprey
#

You understand everything and agree with everything?

timid silo
#

im quite confused honestly

solemn osprey
#

Okok that’s good u told me

timid silo
#

we havent been thought that many things on limits so far

#

i was thinking about the limit being 0

#

by trying to show concrete examples of n and seeing that there are decreasing fractions

solemn osprey
#

I think it’s actually 3/6

#

Because those are the coefficient of the biggest, fastest growing functions

#

Coefficients of 5^n

timid silo
#

wait wait

#

oh

#

we are not talking

#

about the same exercise

solemn osprey
#

OHHHHHHH

timid silo
#

im trying to do the first one in the photo

#

:))) lmao

solemn osprey
#

My bad my bad

timid silo
#

thats why i couldnt understand where 5^n appeared

solemn osprey
#

Lol

#

Actually, kind of the same reasoning there

#

(1/2)^n is a kind of exponential that goes to zero

#

And it grows smaller way faster than a linear function grows bigger

timid silo
#

yes

solemn osprey
#

So the net growth

#

Of n * (1/2)^n is zero

#

U understand? Agree?

timid silo
#

yes

solemn osprey
#

This problem I can actually use a proof, but idk if u guys learn lhopital’s rule or not

timid silo
#

no we havent

#

would the final result be 0 ?

solemn osprey
#

Lhopital’s rule basically compares the growth of functions, and finds the net growth so to speak, but let’s just stick with reasons not proofs

timid silo
#

thats the only thing i can think about regarding this exercise

solemn osprey
#

Yes result is zero

timid silo
#

at least i got that

#

:)))

solemn osprey
#

Point is. Exponential growth, either smaller ir bigger, are faster than a lot of things

#

So they usually overtake them and, in the end, determine the “net growth” either being growing bigger or growing smaller

#

R u helping or getting help? Plz claim ur own help channel

clever vigil
#

$0 \leq \frac{1}{2} \leq 1$

warm shaleBOT
clever vigil
#

Thats why lim 1/2^n = 0

solemn osprey
#

Facts ^^

timid silo
#

yes but i was confused by the multiplication by n which by substituion will lead to an indeterminate

solemn osprey
#

But also (1/2)^n goes to zero faster than n goes to infinity. (1/2)^n wins

timid silo
#

oh

#

i think i get it

solemn osprey
#

YUSSS

timid silo
#

lets go

solemn osprey
#

SUCESSSSSS

timid silo
#

finally

solemn osprey
timid silo
#

thanks bro

solemn osprey
#

Np bro

timid silo
#

.close

obtuse pebbleBOT
#
Channel closed

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lofty wraith
#

I dont understand this problem (its 2^N not 2N)

obtuse pebbleBOT
#

@lofty wraith Has your question been resolved?

lofty wraith
#

<@&286206848099549185>

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obtuse pebbleBOT
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unique anchor
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halp me

obtuse pebbleBOT
unique anchor
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I don't understand this picture

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what is x + h=

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how do they conclude that is the length of h?

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etc

rotund rune
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x+h is basically an arbitrary point picked

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the distance from x+h to x is, logically, x+h-x = h

unique anchor
rotund rune
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say you have a graph y with a point (x, f(x))

unique anchor
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say with a,b instead, f(x) confusing

rotund rune
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then, you pick an arbitrary point with distance h from x, which would mean that point is (x+h, f(x+h))

rotund rune
unique anchor
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isn't it just supposed to say f(x+h)?

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why the -f(x)

rotund rune
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f(x+h)-f(x) means the distance between f(x+h) and f(x)

unique anchor
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oh

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true

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What does it mean "derivative of f at x" is it same as derivative of f(x)?

rotund rune
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derivative of f at x means we're deriving f wrt to x

unique anchor
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explain like you would to a 5 year old

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i not smartie

rotund rune
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what...

unique anchor
obtuse pebbleBOT
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@unique anchor Has your question been resolved?

obtuse pebbleBOT
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@unique anchor Has your question been resolved?

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silver plover
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dont understand how they got to the answers tbh

spice citrus
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if it's a field there needs to be an additive identity, in the case of R\Q that should be 0, but 0 is an element of Q, thus not an element of R\Q

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for iii: the multiplicative identity is 1, the multiplicative inverse of a is the number b, such that for b in Z, a * b is the multiplicative identity, but 2 * 0.5 = 1 and 0.5 isn't an element of Z

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for iv: the additive inverse of a is b, if a + b = 0, because 0 is the additive identity, but if a = 1 for example then 1 + b = 0 => b = -1, which is not on the interval

silver plover
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i see that makes sense

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sacred verge
obtuse pebbleBOT
sacred verge
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I don’t get what is the question looking for?

royal basin
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sort the values from smallest to largest

sacred verge
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In option a

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Are they already sorted so

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What about c option, how can we make all the ratios the same?

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Such as only, cos or only sin

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@royal basin

royal basin
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yes, in a they are already sorted

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for b you might want to know that sin(x) = cos(90°-x)

obtuse pebbleBOT
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@sacred verge Has your question been resolved?

obtuse pebbleBOT
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slim leaf
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You can try putting some values of n to observe if its increasing/decreasing

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Then use induction

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Okay so assume a_(n+1) >= a_(n) for some n

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You have to show a_(n+2) >= a_(n+1)

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Oh decreasing

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Yes

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Mb

sacred verge
obtuse pebbleBOT
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@timid silo Has your question been resolved?

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slim leaf
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@timid silo Sorry for the late reply but it seems induction is long.

slim leaf
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You can try rationalizing and then you'll come to $\frac{1}{(n) \sqrt{n+1} + (n+1) \sqrt{n}}$

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@timid silo Well I hope you see what Im trying to say

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And then it should follow easily without induction that the sequence is decreasing

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fickle niche
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Hello, i have a question about when calculing delta

fickle niche
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i have x - 1, how to calculate delta ?

untold flax
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what do you mean by delta

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delta represents change generally

fickle niche
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this

untold flax
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why'd your denominato rchange from x + x to x + 1

fickle niche
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no its x + 1

untold flax
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ok

fickle niche
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i wrote bad in the first line

untold flax
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also I still don't see a delta here

fickle niche
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but i need to solve the inequation

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and for that i need to find delta

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to calculate x

untold flax
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this is a delta

fickle niche
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yeah

untold flax
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you don't need delta to calculate x

fickle niche
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b2 - 4 . ac

untold flax
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oh discriminant

fickle niche
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yeah

untold flax
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you still don't need that

fickle niche
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so how

untold flax
# fickle niche

ok so we have 2 cases, when x = -1 and when x is not equal to -1

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when x is not equal to negative 1 we can just mutliply by x + 1

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wait sorry what I mean to say is

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it's not defined at x = -1

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after you multiply by x + 1 what do you get

fickle niche
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i understand the x cant be equal to + 1 but what do i need to do

untold flax
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get it in the form of ax^2 + bx + c

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because we can solve those

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to do that we need to remove denominator though

fickle niche
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but we dont have a b c

untold flax
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so how do we do that

untold flax
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we need to get it in the form ax^2 + bx + c where a, b and c are real numbers

fickle niche
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ok and what is b

untold flax
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b is the coefficient of x

fickle niche
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so 1

untold flax
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you're skipping a step though

fickle niche
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and to find a coefficent that we dont have

untold flax
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we haven't got it in the form yet

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multiply by x + 1 first

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on both sides

fickle niche
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i dont understand

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ohh ok

untold flax
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ye just to get rid of denominator

fickle niche
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both sides ?

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so where the 0 is right

untold flax
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ye

sturdy meteor
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Ummm wait do u guys allow middle schoolers in here

fickle niche
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on the x2 + x i need to multiply by x + 1 ?

untold flax
untold flax
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just need to get rid of denominator

fickle niche
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ohhh i understand

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so i did that

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now

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?

sturdy meteor
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soo is it fine

untold flax
sturdy meteor
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ok i guess it's fine

untold flax
fickle niche
untold flax
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I know

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but look at what I wrote

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does that make sense

fickle niche
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why does it not

untold flax
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hm

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1 * (x+1) = x+ 1

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0 * (x+1) doesn't

fickle niche
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oh you mean i could do that from the beginning ?

untold flax
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no

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well you could've

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I'm saying that what you wrote is wrong

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you multiplied the left side corectly, not the right side

fickle niche
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so its 0? on the right

untold flax
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yes

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anything times 0 is 0

fickle niche
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why

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ohhh okay

untold flax
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so isntead you have x^2 + x <= 0

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do you know how to solve this

fickle niche
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ohh right

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now ?

untold flax
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eh

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why'd you flip the sign

fickle niche
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oook i shouldnt

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ok so now?

untold flax
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factor the left hand side

fickle niche
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how

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ax2 + bx + c ?

untold flax
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just factor

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we don't need to use ax^2 + bx + c formula because it factors easily

fickle niche
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x . (x + 1) ?

untold flax
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yes

fickle niche
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now i need to do that tab

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the sign tab

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but i need to put the impossible (from factor x)

untold flax
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it's irrelevant in this case

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since it's less than or equal to

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what's x less than or equal to

fickle niche
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0

untold flax
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there you go

fickle niche
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its that right ?

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well thanks for your help!

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have a nice day

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.close

obtuse pebbleBOT
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sour jungle
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Could anyone help me solve this integral?

obtuse pebbleBOT
sour jungle
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I'm not sure how to go about this.

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Those are 3D vectors on the top and bottom

kindred bear
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hello

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i need help

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i have an exam tommorow

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its on algebera

sage geode
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Post your question in an available help channel

stray yew
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how do i graph y=-4x^2

sage geode
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Post your question in an available help channel

stray yew
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how do i know whoch one is available

sage geode
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There are 3 available channels below them

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24, 25 and 32

sour jungle
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ugh

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.close

obtuse pebbleBOT
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last crow
#

hi