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1 messages · Page 62 of 1
if you really want you can do ln x and get 0.25 × ln x
then have (ln x)/4
Hmmm okay
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Need some help on 2 permutation and combination questions with explanation,
-
There are 3 trays of sushi. The first has 3 pieces of A, the 2nd has 2 pieces and the last has 4 pieces. Find the number of ways to choose at least 1 sushi from any of the trays
-
In a class, students form groups which consist of 4 or 5 students each. In how many ways can the project work groups be formed if the class size of a particular class is 17?
answer to the qn 1 is 59, answer to qn 2 is 35735700
Ok so looking at Q1, the very simplified example to start with is how many ways are there to pick a piece of sushi from the first tray?
3?
Yeah, and then how many ways are there to pick 2 pieces of sushi from the first tray?
the sushi's are identical in each tray
my bad for not mentioning that
I know the way to solve it is (number of ways without restrictions) - (number of ways where no sushi is chosen) = (number of ways at least 1 sushi is chosen)
Yep
but I'm not sure how to go about from there
So number of ways to pick 0 is 1 right?
yep
I'm not sure if I quite understand the question then
Oh wait I see it I think
Ok so now we need to find the number of ways without restriction
yeah
Looking at tray 1
What are your differetn options for amount of sushi picked?
(0 is allowed as we are ignoring that for now)
so 4?
Yep, and then tray 3 is 5
Ok, so does it make sense that the total number of ways to pick from all 3 is 4 x 3 x 5?
ohh ok
yeah...
Ok first lets look at the group composition
Which combinations of groups of 4 and 5, will sum such that every student is in a group?
3 groups of 4, 1 group of 5
Yep exactly
So we only need to worry about one combination
Ok let me do some calculations
im guessing either the answer is wrong or I've been trying to solve the question wrongly the past few hours
which one u still need help with
qn 2
okay
answer is apparently 35735700 but I can't seem to get that number
well it has to be 3 groups of 4 and 1 group of 5
yep
^^ tried this way
so first you choose group of 5 with 17c5
wait if im correct this answer should be 6x too much
yeah
you have to divide by 3! for the order of the groups of 4
since it doesnt matter which group of 4 you are in
but in questions that give a certain number with a specific number of people in a group, why is it unecessary to divide as well?
wdym
eg. in how many ways can 6 different articles be subdivided into groups of 2 articles each?
this answer is just 6c2 x 4c2 x 2c2
👍
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Anyone help w these?
all of them
?
well in 3 i) u just have to prove that at least any two angles are the same using angle facts e.g alternate angles are the same or opposite angels on a intersection are the same
@ancient lantern
Here
Ye
do u understand this
I'm trying
Similar
ok then yh, just prove any two angles are equal
And for 3 ii?
is ND = DA?
It doesn't say
well i think its only true if so, but idk how to word it
if its been awhile just @ the helpers roll
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i am from germany so sry if my english on the paper is weird. But well i am cs student and we are learning proofs and i am hardstuck on this ... they didn't even show it properly in a lecture and the book also doesn't really show how to proof something, i don't even know if i got the notations right in my "try". I learned about logic but this one just feels a bit different
proving this is the task
as you've written down, 2 sets A and B are equivalent if and only if A is a subset of B and B is a subset of A
what is the overline? complement or something?
complement yeah
ok. lets take $x\in\overline{M\cup N}$. Then we know that $x$ is not in $M\cup N$
Denascite
we want to show that $x$ is in $\overline M \cap \overline N$. That means we want to show that $x\in\overline M$ and $x\in\overline N$
Denascite
yeah i can follow 🤔
when is x in overline M
when it's not in M
ok. so that's where we want to get
we know that x is not in MuN
how do we get to where we want
when we show that x is not in M and not in N at the same time
lets just show one of them for now, the other is then essentially the same
we know: x is not in MuN
we want: x is not in M
what does it mean if x is not in MuN
it's part of everything else but MuN
and what is MuN?
not x?
what is the set MuN
M combined with N
which elements are in that set
everything in M + everything in N
if an element is in MuN, then it is in M or in N
ahh i oversaw that little detail
it's like the logical or and the other one is like the logical and
for x
yes essentially
so i can convert it to the logical one, proof it and then convert it back?
if you do the conversion correctly, yes
x is in -(M v N)
then i do de morgans of the bracket
x is in -M and -N
i wanted the screenshot to be posted first
well lets not do MvN. "set or set" is nonsense
the logical or is for statements, not sets
well if we know that x is not in M u N
then we already know (MuN)\x
i get the set operators but i just can't figure out of to work with them
the logic operators are so much easier to work with
$M\cup N$ is a set. $x\in M\cup N$ is a statement
Denascite
try to write everything in terms of "x in ..." and "not(x in ...)"
ah ok so earlier my mistake was not using the correct terms?
this one, yes
that's what you want to show
x is in compl(MuN)
not(x in MuN)
not(x in M or x in N)
not(x in M) and not(x in N)
x in comp(M) and x in comp(N)
x in comp(M) n comp(N)
the transition from or to and seems a bit odd to me
that is de morgan
i get the rest but how does or become and once it splits
not(A or B) = not(A) and not(B)
what how did they not teach us that
what do you think de morgan is
ohhh
wait you used the same de morgan from logic
i am just not allowed to write it like that
with v
ok i kinda get it, now i just need to try the right side myself
ah ok i see, but i can just write the or with normal language and it works
oh like in programming i have to write it twice like x in M or x in N
yes
(of course informally this stuff is fine. just you know, gotta stay correct for proofs)
yeah that's important, the professors told us to be very precise in this subject
x is in comp(M) and x is in comp(N)
not(x is in M) and not(x is in M)
not (x is in M or x is in N)
not ( x is in MuN)
x is in not(M u N)
x is in comp (M u N)
that should be the right side
(which are the same steps as I did, just other direction)
is this the case for most proofs?
no
dont worry about not seeing it. its also very good that you correctly produced the correct steps
it was because of this
yes
usually to show that sets are the same we need to show that each is a subset of the other and the directions are usually different
sure I just didn't have that symbol ready to write
ah ok thx a lot dude, you explained it very clearly
youre welcome
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Why does the way they factored out the bottom here not make sense? they have -2sin^2 theta
I only see cos^2theta and -sin^2theta which I made to cos(2theta)
Is it just a different identity?
just using cos^2=1-sin^2
Ahh ok - I see that. is it wrong/better to use one or the other? I got the same answer using double angle
Yeah that's what I'm wondering as far as finding my tangents now - is that denominator easier to find the zeros for my dx/dtheta tangent ? gonna try with my equation too
i mean just try and see which one seems like less algebra
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Ann if you are still out there, my battery died but I could still really use some help with the p-adics
oh thanks! i'm still not certain exactly how i would go about this problem with the geometric series
let me grab a picture from the book real quick
$\sum_n p^{2n} =\frac{1}{1-p^2}$
$\sum_n p^{2n} =\frac{1}{1-p^2}$
multiply the whole sum by 2
i'm so lost, im so sorry! we were introduced to p-adics a week ago in my intro to math experimentation class and I have forgot everything about sums and series from calc 2
how can i pull a 2 out of the whole sum if there are terms in the sum with a coefficient of 1?
$\sum 2p^{2n}=2\sum p^{2n}$
Toby
split the sum as in dena's message
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@timid silo Has your question been resolved?
What was the original problem?
@timid silo
You just need to multiply the remainder by 2
Since the division you did was technically by (x-0.5), your remainder term is -2.5/(x-0.5) which is equivalent to -5/(2x-1)
Yeah, everything you did is right except the remainder should be -5
$$\frac{8x^3-20x^+2x-2}{2x-1}$$
$$=\frac{4x^3-10x+x-1}{x-\frac{1}{2}}$$
tatpoj
This is what you did before you did the division, right?
And then you end up with
$4x^2-8x-3-\frac{2.5}{x+\frac{1}{2}}$
tatpoj
But, really you weren't dividing by x+1/2. You were dividing by 2x+1
So if we multiply the last term by 2/2 we get
$4x^2-8x-3-\frac{5}{2x+1}$
tatpoj
okay
You can continue factoring 8x^3-12x^2+6x-1
How do you know what you can use?
Like, why did you use 1 last time?
Do you know the rational root theorem? Or sometimes it's called the rational zero test, or something like that
So use that. What are the possible rational zeroes of 8x^3-12x^2+6x-1 ?
That's not all
No, the numerator has to be a factor of 1, and the denominator has to be a factor of 8
So you could have 1, -1, 1/2, -1/2, 1/4, -1/4, 1/8, or -1/8
No, but like, if 1/4 is the zero, it would correspond to a factor of (4x-1), for example, not (x-1/4)
So you'd have to do the multiplying and dividing thing we did up here
Yeah, synthetic division only works with things of the form (x-a)
So you have to "cheat" it a little to make it work
Or just use long division. But your directions say to use Horner so 🤷
8x^2-8x-2 ?
Should be 4x^2-4x+1
Yes
Because $\frac{8x^3-12x^2+6x-1}{2x-1} = \frac{4x^3-6x^2+3x-\frac{1}{2}}{x-\frac{1}{2}}$
tatpoj
This only works because you divided the numerator and denominator each by 2
You can't just divide the denominator by 2, that changes the result
Yeah, looks good
So then so far you have (x-1)(2x-1)(4x^2-4x+1)
Oh, okay yeah
It's because we did this
We really wanted to divide by 2x-1, but synthetic division only works with something of the form (x+-a)
But really the factor was 2x-1 all along
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Hi
@carmine widget Has your question been resolved?
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So it is synthesis of ammonia
How many moles of ammonia are there is 10.63 g ammonia
Hydrogen has a molar mass of 1.01 g/mol
Lemme check
,calc 10.63/(14.01 + 3(1.01))
Result:
0.62382629107981
0.9362
Sure
And then multiply that by 2.02
I wonder if intermediate rounding screwed you over
Maybe you need to put it all into one equation
Turn it into moles first
Because the equation uses moles
And then stoich
And then convert back to grams
i got this
6.05⋅1019
molecules
@fierce lagoon whats the coeffiencent of h2o
is it 1
You dont need H2O
ik but i want to knoiw what it is
There's no H2O in the synthesis of NH3
You don't need H2O at all
It's utterly useless
Okay I feel like that's cut off
Because no water should be produced in the synthesis of ammonia
Well that's hella important
not sure how to find this
I'm missing information
Since O2 is the Limiting, you use stoich with the moles of oxygen
so my clacualtion is wrong
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HELP QUADRATIC FUNCTIONS ON A GRAPH
YES QUADRATIC FUNCTIONS ON A GRAPH WHAT?
VERTEX FORM STANDARD FORM AND CONVERTING STANDARD TO VERTEX AND VICE VERSA
WATCH VIDEOS
not this
pls
no
i have four other homeworks to do broo plsss
If you don't have a specific problem you are stuck on, you are wasting people's time
So you should close this and watch videos
i do have a specfici problem
yeah, show us
And the goal is?
y=(x+2)^2 - 1
lol
y=x^2 +2x -3
(this one is being converted to vertex form
y= -2x^2 +12x -10
this one is being converted to vertex as well
y=1 (x-1)^2 -5 (this one being converted to standard
do you know how to find the vertex of that quadratic?
which one
of x^2 +2x -3
ok thats a quadratic equation correct
yeah
first
idk but that one they plug y as 0 first
then found two numbers when mutliply give -3 but added give 2
then the factorize thing
i would send a picture but my phone is dead
anyone know chem ?
you can factor the quadratic to find the roots, then find the axis of symmetry, then find the vertex
rlly need some help
the aos is always the x coordinate right
yes
I would use this equation
vertex x-coordinate is -b/2a
then use that x coordinate to find the y value
here it is
so x cordinate is -b/2a got it
and plug that into x to find y
and you got the vertex
but how would u find the intercepts for both x and y
how?
i could kinda see it but look at this
yes, correct
well that was what was in the video
idk it any other way
think of it like this
y + ____= (x^2 +2x + ____ ) - 3
y + 1 = (x^2 +2x + 1)-3
y = (x^2+2x+1) - 4
we added something to the RHS so we needed to add it to the LHS
Something in response to this, it's an equation so it needs to be balance. Just imagine like scales, whatever you do to one side, you need to apply to the other to keep the sides balance. So when you added 1 in the parentheses, you need to add 1 on the other side to balance the sides
and when you add the 1 to both sides it cancels out from the left
what do you mean cancels out?
y + 1 = (x^2 +2x + 1)-3
-1 ...................... ...........-1
y = (x^2+2x+1) - 4
but in the second line the one isnt on the left side but it was on the right
-3 + 1 to -4
the +1 in the parenthesis needs to stay because we need to turn the (x^2 +2x + 1) into (x+1)^2
well where does the one from y+1 go
we subtracted 1 from both sides
y + 1 - 1 = (x^2 +2x + 1)-3 - 1
y = (x^2+2x+1) - 4
OHHH
a
a is 1
ok
also im confused about this one too the 2 is positive but how did it become negative
@limpid hill Has your question been resolved?
whas the question
this is it
and also why do we go down 8 units instead of 4 here
brooo
someone respond
<@&286206848099549185>
oh sorry
i was
looking elsewhere
bsaically
vertex of a parabola is when
the (x+h)^2 term
is 0
so x=-h
what?
<@&286206848099549185>
idk how to explain sory
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Closed due to the original message being deleted
Would I prove this using AAS for the triangles to show XD = XE = XF?
And using CPCTC?
And I do not know how to prove Ray n contains point X
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How do you factorise x^2+4x−12?
<@&286206848099549185>
what
Need help with showing ray n contains point X
(x+6)(x-2)
Don't give out answers
(x+a)(x+b)
a + b = 4
ab = -12
oh
i didnt know how to give a hint for that tho
also i kinda felt like it was a joke
question
_ _
ight
People can struggle with conceptualization
thanks
I'm in seventh so like
this would be too easy for you tbh
Lol literally people in my Calc 3 class struggle with factorization 💀
fr
Dw
Ah okay
Factorization for whatever reason seems hard for even high school seniors
thanks for the help
Np
sku
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why did you do the same thing twice
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can some one help me please?
Please don't occupy multiple help channels.
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Hey guys! I was wondering about the warnsdorff's heuristic, notably in regards to it's use in the knight's tour. I have an understanding of the general idea (starting from any initial position on the board, move the knight to the square with the lowest possible moves) but I don't understand at all the mathematics behind it and I was hoping someone could guide me onto a good direction to research for myself or to give me an overview of the mathematics.
(I've used the warnsdorff path for myself on multiple knight's tours and i'm sure it works but i don't know WHY it works and that irks me quite a bit because I have no clue where to go to find out why).
Thank you in advance! :D
Btw please ping me if you're going to respond, would be highly appreciated :D
@teal birch Has your question been resolved?
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I would like help as soon as possible, this is a timed homework assignment and only got 20 minutes left
Wait
I just need to know the inequalities to graph
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Hey I’m having trouble solving number 23!
<@&286206848099549185>
It's the setting up thats getting me. I understand that if we were to only look at it in the x y axis, we can get a figure and use that to find the bounds
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Wouldn't Option D also be correct?
Depends on the question, I guess
But yeah option D would be equivalent to B for whatever function f is
lol ye
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could someone explain to me how the equation above was changed to the equation below
common denom
add 6 to both sides and factor out the y', then divide by the stuff that doesn't contain a y' on the left
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I simply couldn't prove it
I tryed some stuff
1 sec
Excuse my writing
I don't think antg is useful here
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hey
where do the curves intersect?
the bounds are where they intersect: x^3 = x
how do I find that
subtract x and factor
yeah, there are 2 areas
x=0 or x= 1 or -1
Maybe the mean the combined area?
yes
let's just consider the area between 0 and 1, if you want the area of both areas just multiply the answer by 2
so, which function is bigger on the interval 0 to 1?
a function f is odd if f(-x) = -f(x) for all x
ohhh
in other words: you can rotate a point on the graph by 180 degrees around the origin and the point will still be on the graph
but which function is bigger on the interval?
hi I’m back
well want to find the area, which is always positive
so you need to integrate over 1 function minus the other
,w graph y = x, y = x^3
what function is bigger for 0 <= x <= 1
@mental plaza Has your question been resolved?
Jelle
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that's not what you need
what yall need is jesus
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What does -> mean in first order logic and can someone give me an example of a real world activities -> can be used in
Like q->p
"if the kettle is boiling it has water"
Can -(r^p) be translated to something cannot be both the colour red and purple?
It means the first part is false or the second part is true.
A → B means that if A is true, then B has to be true as well.
So, if A is false, it doesn't have to do anything extra.
Wouldn’t it mean everything in the brackets is false?
If B is true, well, A is fine either way.
I'm talking about the → part you started with, not the ¬(r ∧ p).
Oh ok
It's like a promise.
If A happens, B will happen too.
If A happens, B has to happen.
If A doesn't happen, it doesn't matter.
Ok thanks
¬ means everything but this.
So, ¬(r ∧ p) means it can be anything except red and purple at the same time.
So, it could be red but not purple.
It could be green.
With DeMorgan's, ¬(r ∧ p) ≡ ¬r ∨ ¬p.
So, it's either not red or it's not purple or neither one.
K thanks
No problem.
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the one above
@timid silo Has your question been resolved?
What is your question @timid silo
the one above in the photo
What did you not understand ?
@timid silo Has your question been resolved?
I think I have the answer, but I only have reasoning, not necessarily a proof
say
When taking limits to infinity, it’s important to consider the rate of increase
Of all the term, n, n^2, 2^n, 3^n, and 5^n, 5^n will always come out on top as the fastest grower
Eventually 5^n overtakes all of the other terms
Here’s a rule of thumb: a quadratic function (like n^2) eventually overtake a linear function (n)
And exponential functions( like 2, 3, and 5^n) eventually overtake quadratic functions
You with me so far?
You understand everything and agree with everything?
im quite confused honestly
Okok that’s good u told me
we havent been thought that many things on limits so far
i was thinking about the limit being 0
by trying to show concrete examples of n and seeing that there are decreasing fractions
I think it’s actually 3/6
Because those are the coefficient of the biggest, fastest growing functions
Coefficients of 5^n
OHHHHHHH
My bad my bad
thats why i couldnt understand where 5^n appeared
Lol
Actually, kind of the same reasoning there
(1/2)^n is a kind of exponential that goes to zero
And it grows smaller way faster than a linear function grows bigger
yes
yes
This problem I can actually use a proof, but idk if u guys learn lhopital’s rule or not
Lhopital’s rule basically compares the growth of functions, and finds the net growth so to speak, but let’s just stick with reasons not proofs
thats the only thing i can think about regarding this exercise
Yes result is zero
Point is. Exponential growth, either smaller ir bigger, are faster than a lot of things
So they usually overtake them and, in the end, determine the “net growth” either being growing bigger or growing smaller
R u helping or getting help? Plz claim ur own help channel
$0 \leq \frac{1}{2} \leq 1$
Surv
Thats why lim 1/2^n = 0
Facts ^^
yes but i was confused by the multiplication by n which by substituion will lead to an indeterminate
But also (1/2)^n goes to zero faster than n goes to infinity. (1/2)^n wins
YUSSS
lets go
SUCESSSSSS
finally

thanks bro
Np bro
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I dont understand this problem (its 2^N not 2N)
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halp me
I don't understand this picture
what is x + h=
how do they conclude that is the length of h?
etc
x+h is basically an arbitrary point picked
the distance from x+h to x is, logically, x+h-x = h
I don't get it
say you have a graph y with a point (x, f(x))
say with a,b instead, f(x) confusing
then, you pick an arbitrary point with distance h from x, which would mean that point is (x+h, f(x+h))
what...
What does f(x+h) - f(x) mean?
isn't it just supposed to say f(x+h)?
why the -f(x)
f(x+h)-f(x) means the distance between f(x+h) and f(x)
oh
true
What does it mean "derivative of f at x" is it same as derivative of f(x)?
derivative of f at x means we're deriving f wrt to x
what...
it means explain more simple?
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dont understand how they got to the answers tbh
if it's a field there needs to be an additive identity, in the case of R\Q that should be 0, but 0 is an element of Q, thus not an element of R\Q
for iii: the multiplicative identity is 1, the multiplicative inverse of a is the number b, such that for b in Z, a * b is the multiplicative identity, but 2 * 0.5 = 1 and 0.5 isn't an element of Z
for iv: the additive inverse of a is b, if a + b = 0, because 0 is the additive identity, but if a = 1 for example then 1 + b = 0 => b = -1, which is not on the interval
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I don’t get what is the question looking for?
sort the values from smallest to largest
In option a
Are they already sorted so
What about c option, how can we make all the ratios the same?
Such as only, cos or only sin
@royal basin
yes, in a they are already sorted
for b you might want to know that sin(x) = cos(90°-x)
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You can try putting some values of n to observe if its increasing/decreasing
Then use induction
Okay so assume a_(n+1) >= a_(n) for some n
You have to show a_(n+2) >= a_(n+1)
Oh decreasing
Yes
Mb
What about c
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@timid silo Sorry for the late reply but it seems induction is long.
You can try rationalizing and then you'll come to $\frac{1}{(n) \sqrt{n+1} + (n+1) \sqrt{n}}$
@timid silo Well I hope you see what Im trying to say
And then it should follow easily without induction that the sequence is decreasing
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Hello, i have a question about when calculing delta
i have x - 1, how to calculate delta ?
why'd your denominato rchange from x + x to x + 1
no its x + 1
ok
i wrote bad in the first line
also I still don't see a delta here
but i need to solve the inequation
and for that i need to find delta
to calculate x
this is a delta
yeah
? there's no delta there though
you don't need delta to calculate x
b2 - 4 . ac
oh discriminant
yeah
you still don't need that
so how
ok so we have 2 cases, when x = -1 and when x is not equal to -1
when x is not equal to negative 1 we can just mutliply by x + 1
wait sorry what I mean to say is
it's not defined at x = -1
after you multiply by x + 1 what do you get
i understand the x cant be equal to + 1 but what do i need to do
get it in the form of ax^2 + bx + c
because we can solve those
to do that we need to remove denominator though
but we dont have a b c
so how do we do that
no not literally, they just repeesent the coefficents
we need to get it in the form ax^2 + bx + c where a, b and c are real numbers
ok and what is b
b is the coefficient of x
so 1
you're skipping a step though
and to find a coefficent that we dont have
ye just to get rid of denominator
ye
Ummm wait do u guys allow middle schoolers in here
on the x2 + x i need to multiply by x + 1 ?
if you're above 13 then yeah
no why
just need to get rid of denominator
yes well I am almost 14 years old.
soo is it fine
0 * (x + 1) = x+1 ? 🤔
ok i guess it's fine
yes it's fine then
i got rid of the denominator
why does it not
oh you mean i could do that from the beginning ?
no
well you could've
I'm saying that what you wrote is wrong
you multiplied the left side corectly, not the right side
so its 0? on the right
factor the left hand side
yes
now i need to do that tab
the sign tab
but i need to put the impossible (from factor x)
it's irrelevant in this case
since it's less than or equal to
what's x less than or equal to
0
there you go
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Could anyone help me solve this integral?
Post your question in an available help channel
how do i graph y=-4x^2
Post your question in an available help channel
how do i know whoch one is available
You see the #❓how-to-get-help and the help-forum?
There are 3 available channels below them
24, 25 and 32
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hi
