#help-10

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sage dagger
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obtuse pebbleBOT
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daring topaz
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Always struggled with matrices, but this one has my brain going wacky.
Can I get an explanation to how to complete this?

alpine raven
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can you give full context ?

viral blade
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Without a calculator the solution I know involves eigenvalues

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Presumably find $T^{10}S_0$

warm shaleBOT
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monikanicity

viral blade
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find the eigenvalues and eigenvectors of T and write S_0 in terms of the eigenvectors

daring topaz
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Cheers

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woeful wraith
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I need help

obtuse pebbleBOT
earnest elk
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What is your question?

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You just ask, don’t ask to ask

obtuse pebbleBOT
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@woeful wraith Has your question been resolved?

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obtuse pebbleBOT
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stiff tusk
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Domain of x

obtuse pebbleBOT
stiff tusk
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Ping me

proven zephyr
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,,\frac{(x - 1)(x + 2)^2}{-1 - x} = 0

warm shaleBOT
proven zephyr
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find the possible values first, (gtg eat, brb in prob 30 min or 40 min)

stiff tusk
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I am able to find some of it

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,w ((x-1)/(-1-x))(x+1)²<0

stiff tusk
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x ∈ (-∞,-2) ∪ (-2,-1) ∪ (1,∞)

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Explain please

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Domain of x ?

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<@&286206848099549185>

obtuse pebbleBOT
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@stiff tusk Has your question been resolved?

warm shaleBOT
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jimmy1234

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jimmy1234

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jimmy1234

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shell hull
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Is my solution correct?

obtuse pebbleBOT
royal basin
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not quite since you want A to be an infinite union of intervals while yours looks like it stops at n

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where n is not known

obtuse pebbleBOT
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@shell hull Has your question been resolved?

timid silo
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i think the first interval isnt quite correct

shell hull
timid silo
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doesnt it have to be from 1 to 1/2? (and then switch order for all of them, smaller number first)

timid silo
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next interval should be (1/3, 1/2) shouldnt it?

obtuse pebbleBOT
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timid silo
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.reopen

shell hull
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.Reopen

obtuse pebbleBOT
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timid silo
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well the problem with the n is, you dont really specity what it is

shell hull
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I'm really confused

timid silo
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$(\frac12, 1) \cup (\frac13, \frac12) \cup (\frac14, \frac13) \cup ...$

warm shaleBOT
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rbit ✨

timid silo
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you dont need the n, just make it dotted and it will be clear its infinite

shell hull
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OK but isn't this correct?

royal basin
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no

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your sum stops

flint tartan
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try using that big union notation instead ?

shell hull
royal basin
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if you had put ${}\cup \dots$ after it, you would have written down an infinite sum

warm shaleBOT
royal basin
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er

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infinite union

shell hull
royal basin
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because you are writing down a finite union and not an infinite one...

shell hull
royal basin
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......

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i'm not getting through to you, am i

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no, the set of natural numbers is not finite.

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but there is a difference between "union of n things, where n is some natural number" and "union of infinitely many things"

shell hull
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I understood to some extent, thank you

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opal sequoia
obtuse pebbleBOT
opal sequoia
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i need help

obtuse pebbleBOT
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@opal sequoia Has your question been resolved?

opal sequoia
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<@&286206848099549185>

opal sequoia
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<@&286206848099549185>

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molten compass
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Does the logic of directional derivatives reconcile with ordinary single-variable calculus?

Like in multivariable we can find the maximum rate of change and its direction using the gradient vector.
In single variable, consider like y = f(x) = 2x^2+7x. At x = -3, dy/dx = -5. But the gradient vector for f is 4x+7. So at x = -3, we have -5. But what's the 'direction' here?

molten compass
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or I might just be talking rubbish tbh, as no direction is possible I guess

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yeah nvm ignore me 😅

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fallow tusk
obtuse pebbleBOT
fallow tusk
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not very sure about this

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i'm guessing the last one isn't?

rotund rune
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a geometric series has a common ratio

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see which one you can modify to get a common ratio

fallow tusk
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hmm what do you mean by common ratio

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like the increment is constant?

rotund rune
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a, ar, ar^2, ar^3

high lily
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a_(n+1)/a_n should be a constant if you have a geometric sequence/series

rotund rune
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ye

fallow tusk
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okay so i'm guessing the first one wouldn't work because that's (4/29)^n and you cant separate that into a and r

rotund rune
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the first one is a geometric series

high lily
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a_(n+1)/a_n

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go through this process if needed

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in fact i'd recommend that you actually do that for all 4

rotund rune
fallow tusk
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1, 4/29, 16/841

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couldnt you do that for all of them tho?

rotund rune
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is the ratio constant then?

fallow tusk
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always multiplies by 4/29 from what I can tell

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then yes

warm shaleBOT
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nichoals

rotund rune
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so basically, looking from this, you can see that r = 4/29, meaning it's a geometric series

fallow tusk
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hmm but what would a be? just 1?

rotund rune
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you can try n = 0, 1, 2, 3 for the other 3 options or you can try to modify the series to immediately notice whether it has a constant ratio or not

rotund rune
fallow tusk
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oh right because constant

rotund rune
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the second option is pretty obv tbh

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the third one as well (hint: you can't divide by 0)

fallow tusk
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yeah about the 3rd one

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if an element of the series/sequence is undefined does that mean it's not a series/sequence?

rotund rune
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imagine this: you have undefined as the first term in option three. assuming it's a geometric series, how would you find the sum then?

fallow tusk
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oh yeah true

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but what about a sequence? it doesn't need a sum it just needs a trend

rotund rune
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then it is defined

fallow tusk
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what about n greater than or equal to 0?

rotund rune
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whatd happen if n=0?

fallow tusk
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oh wait 0 isnt a natural number

rotund rune
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oh wait
ignore the N then

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i forgot lmao

fallow tusk
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well the first term would be undefined

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but everything else would work

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can't type today geez

rotund rune
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it won't be counted as a sequence

obtuse pebbleBOT
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@fallow tusk Has your question been resolved?

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quick kayak
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Hey all

obtuse pebbleBOT
quick kayak
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I'm trying to find an example for a solution to a question like "Define T : R3 -> R2, T=Ax, find the vector under T whose image is b". Basically, I'm wondering how to find the answers to "find the image under T" for matrices which don't map to the same dimensionality

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Since I can't use an augmented matrix

royal basin
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eh?

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you're given a map T : R^3 -> R^2 defined by T(x) = Ax, and you're given some b ∈ R^2, and you are asked to find all x ∈ R^3 s.t. T(x) = b?

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@quick kayak do i understand your problem correctly

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@quick kayak Has your question been resolved?

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peak cape
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Can someone explain what am I doing wrong here. Thanks in advance

timid silo
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ayo

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is 3 the right answer

lyric ember
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ye

timid silo
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yeeee

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then i did it correctly

wet drift
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4/100 * 255 2 * 15 /10 30/10 = 3

obtuse pebbleBOT
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@peak cape Has your question been resolved?

peak cape
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No

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@obtuse pebble no

peak cape
earnest elk
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oh my bad my bad

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i am so sorry

peak cape
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Np

obtuse pebbleBOT
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@peak cape Has your question been resolved?

obtuse pebbleBOT
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@peak cape Has your question been resolved?

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past tartan
#

From https://en.wikipedia.org/wiki/Projectile_motion#Angle_θ_required_to_hit_coordinate_(x,_y) I can find the angle needed to hit a coordinate with a projectile.
${\displaystyle \theta =\arctan {\left({\frac {v^{2}\pm {\sqrt {v^{4}-g(gx^{2}+2yv^{2})}}}{gx}}\right)}}$
How do I change the equation to include Stokes drag with a moving target? With stokes drag the position is calculated with ${\displaystyle t={\frac {1}{\mu }}\left(1+{\frac {\mu }{g}}v_{y0}+W\left(-\left(1+{\frac {\mu }{g}}v_{y0}\right)e^{-\left(1+{\frac {\mu }{g}}v_{y0}\right)}\right)\right)}$, so I tried to solve this for theta. But I don't know where to go from there

warm shaleBOT
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InCrIpTiOn
Compile Error! Click the errors reaction for more information.
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past tartan
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I messed up

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it works ig

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p + Vt is the equation for the moving target, btw. cos(theta)*v is the vertical component only

obtuse pebbleBOT
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@past tartan Has your question been resolved?

obtuse pebbleBOT
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@past tartan Has your question been resolved?

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storm harness
#

I need help in general learning the, metodo de sustitucion, metodo de igualacion, metodo de reduccion, Im not sure what its called in english but i understand both languages

robust sleet
obtuse pebbleBOT
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@storm harness Has your question been resolved?

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deep ravine
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Am i doing this correctly?

obtuse pebbleBOT
mental plaza
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aye aye

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wassup

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eh

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this is chemistry

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alr

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hm

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they gave

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percentage mass

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use that a

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And

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find the no of mol

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and for simplest ratio

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divide by the smallest

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njmber if mola

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mole

deep ravine
mental plaza
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why is there

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a decimal point

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at the beginning

deep ravine
mental plaza
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nah it’s fine

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u can just

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use the percentages

deep ravine
mental plaza
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why are u

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multiplying them

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alr so

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to find mol

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it’s mass/Ar

deep ravine
mental plaza
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relative

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atomic mass

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mass number basically

obtuse pebbleBOT
#

@deep ravine Has your question been resolved?

obtuse pebbleBOT
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meager trail
obtuse pebbleBOT
meager trail
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i’m confused at the very bottom part

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how do we go from cos(a)=0 to cos(2n-1)pi/2

bold bane
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They are including the coterminal angles.

obtuse pebbleBOT
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@meager trail Has your question been resolved?

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real cobalt
#

can someone exploin how to solve this, 8x−2=−9+7x

ocean nexus
real cobalt
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yes

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yell its a multi step eqaution problem according to the paper the question is on so it might nit be

ocean nexus
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does it say solve for x?

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(8x - 7x) - 2 + 2 = + 2 - 9 + 7x - 7x
x - 2 + 2 = + 2 - 9 + (7x - 7x)
x (- 2 + 2) = + 2 -9 + 0
x + 0 = (+2 -9) + 0
x + 0 = -7 + 0
x = -7

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I bracket the numbers I am subtracting in the next step to make it more understable

real cobalt
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it just says solve the equation sorry i forgot i asked for help

ocean nexus
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huh

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arent you finding x

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?

real cobalt
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ig

ocean nexus
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ok well its x = -7 then

real cobalt
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but the way u solved is kind of ocmplicated

ocean nexus
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do you want me to shorten it?

real cobalt
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this is what a calculator did

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i was wondering why they flipped it over

ocean nexus
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ya i just did more beginner steps

ocean nexus
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and add

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to the other side

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subtract on one side and add to the other side of the equal sign

real cobalt
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i get it but when they did x -2 = -9 why did they move 2 to the other side so it could be - 9 + 2

ocean nexus
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bc you want x to be alone

real cobalt
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hmm

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ok

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tysm

ocean nexus
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you are just trying to find x not x - 2

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yw

real cobalt
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i understand it

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ig im finding x

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.close

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pale gazelle
obtuse pebbleBOT
pale gazelle
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could someone help with this differential eq? i know its not exact and ive tried to figure out the integrating factor

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but the difference in signs keeps bugging me out

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if i can figure out how to type in latex here maybe i can show you guys where im stuck haha

rigid pine
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Try a integrating factor of the form x^ay^b.

pale gazelle
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oh hmm ive been trying one that only involves x

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and thought i got close

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ill try it that way

rigid pine
pale gazelle
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woah

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ive been trying to get to that integrating factor naturally haha

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what text is that? @rigid pine

rigid pine
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Ordinary Differential Equations by Morris Tenenbaum and Harry Pollard.

pale gazelle
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thank you :)

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ill attempt it once more

obtuse pebbleBOT
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final elm
#

hey

obtuse pebbleBOT
final elm
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what is going on here

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are they sequences or series

obtuse pebbleBOT
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@final elm Has your question been resolved?

obtuse pebbleBOT
#

@final elm Has your question been resolved?

daring compass
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it says "sequences" because they are sequences

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so, in your words, what does it mean for a sequence to converge?

obtuse pebbleBOT
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@final elm Has your question been resolved?

final elm
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its confusing

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it goes from n=1 to infinity

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which is a summation

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so i think sequence is a typo

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but im not positive

daring compass
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no, I don't think they're summations

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if they are, then some weird notations are being used

daring compass
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if they were series, I would expect summation notation, not the curly brackets

final elm
daring compass
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what does it mean for a sequence to converge?

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(by the way, can I ask- are the answer choices selected supposed to be your answer choices or the correct answer choices?)

final elm
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a sequence converges when you plug in infinity and u get a constant i think

daring compass
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yeah more or less. as you bring in later and later terms, they approach a specific (finite) number

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same idea as a limit

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so which of the given choices approaches a particular value?

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let's start with I

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as n increases, what happens to the values of that sequence?

final elm
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the top goes back and forth

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between -1 and 1

daring compass
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yup

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and the bottom?

final elm
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bigger and bigger

daring compass
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good. So if the top stays between -1 and 1, and the bottom gets bigger without bound, what happens to the overall quotient

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?

final elm
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uh

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itll get closer to zero?

daring compass
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yes!

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so does it converge?

final elm
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yeah?

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yeah

daring compass
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yeah

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ok, thinking about II:

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what happens there?

final elm
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i understand II can u help me with III

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i used geometric series test

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but its a sequence

daring compass
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yeah

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i like to use a trick in these kinds of things where in any sum, if one term grows much faster than the others, you can throw the rest out

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what i mean is, 2^n + 3^n, for very large n, might as well just be 3^n

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do you see what i mean?

obtuse pebbleBOT
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pale gazelle
obtuse pebbleBOT
pale gazelle
#

can anyone help with how to go about finding an integrating factor for this?

#

i keep getting stuck :(

rigid pine
#

Write in the form P(x, y) dx + Q(x, y) dy = 0.
y dx + (x - x^2 y) dy = 0
The check for exactness is P_y = Q_x. But P_y = 1 and Q_x = 1 - 2xy.
Notice that P_y - Q_x = 2xy. I would now consult my integrating factors sheet.

#

I find that (10.73) yields a function of xy.

#

I find that (xy)^(-2) is a integrating factor.

obtuse pebbleBOT
#

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pale gazelle
#

tysm :) )

#

you're making my life so much easier today

obtuse pebbleBOT
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peak dust
#

Total Class 30
I have attended (X) classes
If I attend 60% Classes I will get 6 marks
If I attend 90% classes I will get 10 marks.

this is the challenge . But I can't figure out how can I get the number for (X) ?
please help me

obtuse pebbleBOT
#

@peak dust Has your question been resolved?

earnest elk
#

There isn’t sufficient info

obtuse pebbleBOT
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lofty zealot
obtuse pebbleBOT
lofty zealot
#

I understand part a), but im confused how to start part b)

quaint glen
#

Well, use the hint. What does happen to the equation c_0f_0+c_1f_1+c_2f_2=0 when x=0, 1, and 2?

#

It should be pretty easy to see what the equation will look like for these equations if you've already done a, its just plugging shit in

haughty coyote
#

The most common method to show a family of functions is linearly independent is to just evaluate it for specific values

lofty zealot
#

ah i see, if i plug in 0, 1, 2 then c0, c1, c2 must be equivalent to zero respectively; idk why but i thought that values > 2 would somehow change my result

#

is c just f(x) = c_x ??

obtuse pebbleBOT
#

@lofty zealot Has your question been resolved?

lofty zealot
#

any pointers for 5d ; - ;

obtuse pebbleBOT
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deep dirge
#

.reopen

obtuse pebbleBOT
deep dirge
#

Help i don't know how to do this.

#

<@&286206848099549185>

#

.close

obtuse pebbleBOT
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quaint dust
obtuse pebbleBOT
quaint dust
#

hello can anyone help me with this one

placid nova
#

in sin/cos how would i cancel the arguement of 2pi/(pi/2)

#

<@&286206848099549185>

quaint dust
#

my answer is different from wolfram and i cant seem to find the difference

#

oops sorry for interrupting

#

this is from wolfram

#

and mine is this

obtuse pebbleBOT
#

@quaint dust Has your question been resolved?

floral void
#

this*

obtuse pebbleBOT
#

@quaint dust Has your question been resolved?

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sacred cove
obtuse pebbleBOT
sacred cove
#

for a question like this can anyone explain to me why what i have done wouldnt work?

#

I've put it into many calculators and havnt been able to get a reasonable answer

warm shaleBOT
wild swallow
#

apart from the fact that this is a terribly inefficient way of calculating the eigenvalues

#

have you actually tried calculating what they are?

sacred cove
wild swallow
#

,w {{2, -1-i, -1+i}, {1, -1+i, -1-i}, {2, 2, 2}}^-1 {{-1/40, 0, 1/40},{1/40, -1/20, 0}, {0, 1/20, -1/40}} {{2, -1-i, -1+i}, {1, -1+i, -1-i}, {2, 2, 2}}

wild swallow
#

?

sacred cove
#

i tried putting into wolfram alpha and it didnt work for me

#

thanks!

wild swallow
#

well

#

still

#

this is not how you'd calculate the eigenvalues

#

this method is horribly inefficient

sacred cove
wild swallow
#

?

sacred cove
#

I did A = PDP^-1

#

But you just multiplied all three together

#

oh nvm

wild swallow
#

D = P^-1 AP

sacred cove
#

ohh right yeah that makes sense

#

thanks

wild swallow
#

except

#

you arent reading what im saying

#

this is not the way you'd calculate the eigenvalues

sacred cove
wild swallow
#

well

#

do you really want to invert a 3x3 matrix by hand?

#

if you had no calculator

sacred cove
#

nah i guess that wouldnt be efficient

wild swallow
#

your method would just be suffering

#

you know the vectors are eigenvectors

#

literally multiply A by the eigenvectors

#

calculate even just a single entry

#

and see what multiple it is

#

,w -1/40 * 2 + 0 * 1 + 1/40 * 2

wild swallow
#

its 0 so the eigenvalue of the first vector is 0

sacred cove
#

nvm

#

ill try it for the other ones see if i get the same answer

wild swallow
#

,w 0 * (-1-i) + 1/20 * (-1+i) + -1/40 * 2

sacred cove
#

ig that makes a lot more sense

wild swallow
#

divide by 2 and you get the eigenvalue

fast atlas
#

,w 5x²=3

wild swallow
sacred cove
wild swallow
#

i calculated the last entry of A * (-1-i, -1+i, 2)

sacred cove
#

why do we need to do that?

wild swallow
#

so you should get 2λ

#

divide by 2 to get λ

sacred cove
wild swallow
#

Av = λv

#

A(-1-i, -1+i, 2) = λ(-1-i, -1+i, 2)

#

last entry is 2λ

sacred cove
#

so that 2 on the end makes it 2λ?

wild swallow
#

well if you distribute the λ inside

#

you get A(-1-i, -1+i, 2) = ((-1-i)λ, (-1+i)λ, 2λ)

#

clearly you dont want to figure out what dividing by a complex number should be

#

so you calculate the last entry of A(-1-i, -1+i, 2) to get 2λ

sacred cove
#

ohh right i think i understand it ill try to do that since that seems a lot better

#

thanks a lot for your help

sacred cove
#

do you know if they are wrong or i am wrong?

wild swallow
#

im not sure how 0 = (-2-i)/40 = -2i/40

#

none of those equations are true

sacred cove
#

hmm right

#

yeah my friend got that as the answer and he solved the same equation too

sacred cove
wild swallow
#

<@&268886789983436800>

wild swallow
#

thats a bit much

sacred cove
#

yeah lol

wild swallow
#

you couldve just started by moving P and P^-1 to the other side

#

and gotten D = P^-1 AP

#

that gives you D directly

sacred cove
#

yeah true lol

wild swallow
#

but anyway directly calculating Av is much faster

sacred cove
#

yeah alright thanks again

obtuse pebbleBOT
#

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obtuse pebbleBOT
final thunder
#

What’s this

zenith raft
#

can't?

#

that doesn't sound like good advertising

final thunder
final thunder
zenith raft
#

idk

#

probably not haha

final thunder
#

Do I like ping the mods

zenith raft
#

maybeee

final thunder
#

<@&268886789983436800>

obtuse pebbleBOT
#

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plucky patio
#

What are the transformations that make S into C?

plucky patio
#

There's some sort of stretch of a factor of -2

#

but there seems to be another transformation

#

<@&286206848099549185>

obtuse pebbleBOT
#

@plucky patio Has your question been resolved?

obtuse pebbleBOT
#

@plucky patio Has your question been resolved?

obtuse pebbleBOT
#

@plucky patio Has your question been resolved?

obtuse pebbleBOT
#

@plucky patio Has your question been resolved?

obtuse pebbleBOT
#

@plucky patio Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

for concavity, do u get ur critical numbers from the 2nd derivative

sleek mural
#

How is #7 true?

#

Doesn’t the line in the middle also have to be congruent?

buoyant hawk
#

for finding the diriv of this can i foil bfore i take the diriv of do i have to use product

obtuse pebbleBOT
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ornate ivy
#

A motel owner observed that when a room at $60 per day, all 80 rooms of the motel are occupied. For each $4 increase in price, one more room is vacant. Each occupied room costs an additional $20 per day to maintain.

a) Find the demand function,p, the price charges each room per day, as a function of x, the number of rooms occupied.

b) Find the profit function

c) find the price he charges a room per day so he can maximize profit.😭

obtuse pebbleBOT
#

@ornate ivy Has your question been resolved?

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#

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vagrant obsidian
obtuse pebbleBOT
vagrant obsidian
#

Walk me through all the steps

#

Thanks

high lily
#

think about d^2 * what? = 2d^5

#

repeat for all the other terms

vagrant obsidian
#

Hey

vagrant obsidian
high lily
#

?

vagrant obsidian
#

Sorry I’m a bit slow today

#

What do I do again

#

Simple words pls

high lily
#

what don't you understand about what i wrote

#

you already wrote that d^2 out front

#

implying that you somehow know that d^2 is a factor of all these terms

#

think about the expression when multiplied to d^2 gives the first term 2d^5

vagrant obsidian
high lily
#

as represented by
d^2 * what = 2d^5

#

solve that for what

vagrant obsidian
#

Ok

high lily
#

i'd use the bot, but its down

vagrant obsidian
high lily
#

not what i asked for

vagrant obsidian
#

O

#

What did u ask for

high lily
#

d^2 * what = 2d^5

vagrant obsidian
high lily
#

have you ever solved any equations before?

vagrant obsidian
high lily
#

apply the same principle here

#

I'm assuming you'd be able to solve something like
5x = 7
this is no different

vagrant obsidian
#

D^2x2= 2d^5

#

???

high lily
#

no

vagrant obsidian
#

??????????????

high lily
#

how would you solve for x in
5x = 7

vagrant obsidian
#

Divide by both sides

#

By 5

high lily
#

yes

vagrant obsidian
#

5 cancels out

#

7/5

high lily
#

yes.

vagrant obsidian
#

??

high lily
#

yes

#

apply that exact same principle

#

on the left side, you have
d^2 multiplied to k,
what would you divide both sides by to isolate/solve for k?

vagrant obsidian
#

d%2

#

d^2*

high lily
#

yes

vagrant obsidian
#

Yes

#

D^2 divided by 2d^5

high lily
#

no

vagrant obsidian
#

????

#

What do I do

high lily
#

why are you dividing d^2 by 2d^5

vagrant obsidian
#

Divide on both sides

high lily
#

did you divide 5 by 7 for 5x = 7?

vagrant obsidian
#

Yes

high lily
#

no you did not

#

order of division matters

#

you divided both sides by 5

vagrant obsidian
#

Yes

high lily
#

7/5 is 7 divided by 5

#

not 5 divided by 7

vagrant obsidian
#

O

#

Oops

#

I meant the opposite

#

So what ur saying is I’m doing the opposite?

high lily
#

you're not accurately representing what you're doing

vagrant obsidian
#

Yea

#

Cause I don’t really understand what you want me to do

high lily
#

my instructions were excessively broken down intended to be extremely simple

#

you shouldn't need to think to hard about them

#

after dividing both sides by d^2,

#

can you simplify that fraction

vagrant obsidian
#

O

high lily
#

using exponent laws

#

what's with

O
are you implying that you didn't have that?

vagrant obsidian
#

So what do I do for my original question?

high lily
#

can you simplify that fraction
using exponent laws

vagrant obsidian
#

2d^3

high lily
#

yes

#

d^2 when multiplied to 2d^3 gives 2d^5
factoring d^2 out from 2d^5 leaves you with 2d^3

#

and same idea for the other terms

#

d^2 * what = 16d^4

#

etc

vagrant obsidian
#

The same

#

Right

high lily
#

yes,

#

and simplify

vagrant obsidian
#

16d^2

#

@high lily

high lily
#

yes, 16d^4/d^2 = 16d^2

vagrant obsidian
#

So do I add a “+” or “-“

#

When plugging in

high lily
#

depends on the sign that's there

#

(and personal preference assuming you're referring to the -4d^3)

#

you can consider
d^2 * what = -4d^3 directly

#

or write a = sign and then consider
d^2 * what = 4d^3

vagrant obsidian
#

@high lily

high lily
#

because the original term is (+)16d^4

#

consider the basics of the distributive property

#

would you be able to factorise
ab + ac?

vagrant obsidian
#

Oh

#

Wait imma do the entire thing and you tell me if it’s right or wrong

#

Nvm

#

I’m back

#

@high lily what do I do next

#

Factoring?

high lily
#

identify more common factors if they exist

#

if you identified the gcd/hcf at the start, that would've been more efficient

vagrant obsidian
obtuse pebbleBOT
#

@vagrant obsidian Has your question been resolved?

obtuse pebbleBOT
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cobalt hatch
#

can anyone help

obtuse pebbleBOT
cobalt hatch
#

multiplication of polynomials

abstract flame
#

just try expanding it

reef grotto
#

distribute

#

or wait

#

what are you even supposed to do lmao

cobalt hatch
#

get the product

nocturne minnow
reef grotto
obtuse pebbleBOT
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timid silo
#

hello. i am a bit confused about how newton discovered calculus (or leibeniz). So as i understand newton discovered calculus but i mean finding the integral of a function or its derviviative seems pretty easy. was newton the first person to use an integral and everyone freaked out. It seems like someone just randomly performing a dervitive could of discovered that it would give you the instantenous rate of change.

timid silo
#

was newton instrumentla in proving that the integral or deriviative acctually gave you iroc or area under the graph?

#

or was he seriously the first person to guy "ah yes, if I bring down the 2 here (x^2) and make it 2x, the new function gives me the iroc, brillant, I am so intelligent"

#

if so that is fucking insane lmao.

#

no way on earth he was the first one to use a derviviative like that.

royal basin
#

finding the integral or the derivative of a function seems pretty easy.

calculus wasn't built in a day.

#

you're standing on the shoulders of giants

#

so of course looking down at the basics such things seem easy

#

calculus itself required a conceptual leap, perhaps more than one, to become what it is today.

timid silo
#

definitely but i feel like anyone would be interested in bringing down a 2 in my example and seeing what it produces.

#

im just having trouble accepting that no one for milenia thought to do that

royal basin
#

people did not really think about functions the same way back then as we do

timid silo
#

what do you mean by that.

#

accutally ill search it up

#

wait but before i do that. was he actually the first person to do that.

true granite
#

the power rule and derivatives weren’t found by coincidence

timid silo
#

sure but that doesnt neccesarily they couldnt be found by coincidence.

#

just be observing the two functions, someone might discover that type of relationship

true granite
#

you could even argue they were created

timid silo
true granite
#

back then, instantaneous rate of change made no sense

timid silo
#

what do you mean by that. so for like x^2, people found it bizzare to question what the iroc was at different points.

#

is there a book on this

#

like the history of calculus

#

no actual math beyond like hs math

#

jsut explaining simple development in math

true granite
#

there’s actually a really good video from 3b1b’s SoME2

#

let me look it up

timid silo
#

sick thank you

#

sorry for seeming condencsing btw. no intention of that. just hard to accept fucking issac netwon, smartest dude alive, discovered simple rules and everyone priases him. m

true granite
#

not really simple at the time

#

designing the first car must have been hard, but look how many different cars we have now

#

what seems so simple today might not have been simple in the past

#

specially when you’re a pioneer in what you’re doing

timid silo
#

i definitely get that, but something so trivial like the power rule being discovered so late in humanities course seems so strange

royal basin
#

well i mean you could say the same thing for quadratic equations or something

#

it also kind of matters what language you have at your disposal to express various ideas

#

compare:

"Half of the sum of one and the unknown minus one-sixth of the difference of the same unknown and nine equals eleven."

vs

(x+1)/2 - (x-9)/6 = 11

#

contrived example but one is much easier to work with than the other

timid silo
# royal basin well i mean you could say the same thing for quadratic equations or something

i feel like it would be much more difficult to find the quadratic equation. applying the power rule to a simple function seems extremely simple. comparing the original and derived function also seems very simple. compared to the quadratic equation, which is much more difficult to randomly stumble upon, the power rule seems like something that someone a bit curious would eventually test. But like you said, if the notion of functions isn't the same as it is today, than it would be much more difficult to observe in my example.

#

the quadratic equation is the super big thing, with a lot of variables, who would randomly mix and match numbers to produce that.

#

bringing down a 2 in x^2, i think babies would be curious to see what that would produce.

#

boyers history of calculus

#

so yeah it seems like there were people before newton. newton just seemed to have a rigrous proof for it.

#

thank you everyone

#

and yeah it seems like anyone before this descartes guy probably could never have randomly discovered power rule.

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

bleak sable
#

Hello

#

I need help

obtuse pebbleBOT
#
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bleak sable
obtuse pebbleBOT
bleak sable
#

I don't get why y is in absolute value

ancient marlin
#

if y were negative in original equation, would y^6 be negative

bleak sable
#

Oh yeah rigt

#

rightttt

ancient marlin
#

don't have to do it for x^4 because it's still squared even after it came out of root

#

so it would be redundant that's all

#

generally, sqrt(x^2) = |x|

bleak sable
#

Thank you so much!

ancient marlin
#

np

obtuse pebbleBOT
#

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dark mango
#

.close

obtuse pebbleBOT
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twin helm
obtuse pebbleBOT
twin helm
#

I've found that nullity is 1, but I don't know how to find the multiple

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left mesa
#

help..

obtuse pebbleBOT
left mesa
#

its c right? im kinda doubting it since its m^2 not x^2 in the given

#

<@&286206848099549185>

twin helm
#

probably D then

#

although that's extremely weird

obtuse pebbleBOT
# left mesa <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

left mesa
#

oh because its asking for the value of x? instead of the value of m?

mental plaza
#

wtf

final thunder
#

More likely to be a typo imo

mental plaza
#

yeye

twin helm
#

yea i agree

#

otherwise it seems much more like a reading comprehension question

left mesa
#

ok then the answer is c?

mental plaza
#

I mean

final thunder
#

Yeah it would be that

mental plaza
#

if the cher is evil and is testing ur attention to details in the qn

#

it would be

#

D

#

but most prob C

left mesa
#

meh its ok if im wrong i still have + points bec of our last quiz lol

final thunder
#

This question is too ambiguous for you to be penalised for that

left mesa
#

fr ok ty ❤️

twin helm
#

I would put D personally

#

because you have plausible deniability

left mesa
#

we did had the quarter test first before the long test and i do remember subtly that the answer is not none of the above lol or maybe im just remembering that wrongly 🥲

#

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obtuse pebbleBOT
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fast heath
#

a bit confused about part (b)

obtuse pebbleBOT
fast heath
#

i did (1.5-0) × 1/10
because i assumed since it's |x| it'd be up til 0?

which is wrong according to the marking scheme, and i don't really understand why. i need the answer for doing (c) so i wanna be sure how (b) is calculated first!

obtuse pebbleBOT
#

@fast heath Has your question been resolved?

fast heath
#

<@&286206848099549185>

#

would really appreciate the help asap bc i've a test today 😅 i'd like to clear this doubt

fast heath
#

.close

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bleak sable
#

How do I proceed? Idk what's the use of the given 44 weeks

bleak sable
obtuse pebbleBOT
#

@bleak sable Has your question been resolved?

bleak sable
#

<@&286206848099549185>

obtuse pebbleBOT
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@bleak sable Has your question been resolved?

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obtuse pebbleBOT
#

@uncut fulcrum Has your question been resolved?

wooden sand
#

What were your attempts?

#

How did you try these questions?

#

Perhaps we can find out where you lack understanding

#

Hmm... I'm assuming you don't have the epsilon delta definition, so

#

Intuitively, 1 divided by a very large number gives a very small number

#

As this denominator goes to infinity

#

1/denominator goes to 0

#

Oh you do? Nice!

real prawn
#

says there that lim_{x-> -4^+} (floor(H(x)) = -1

wooden sand
#

Use the epsilon delta for a limit to infinity

real prawn
#

doesn't make much sense

wooden sand
#

Flip the inequality

#

And then use the definition for right hand lim

real prawn
#

on [-9,6] H(x) = sin(x)/x

#

to me that's what it looks like hmm

wooden sand
#

You know that the function goes to infinity on the right of 6

#

So for all M in the positive reals

#

There exists an f(x) that's bigger than it

real prawn
#

hmm, i'm wrong but i think it's something involving sine

wooden sand
#

For any x in the open interval from 6 to 6+delta

#

So flip the f(x)<M, and try to get a epsilon delta that bounds 1/f(x) within positive epsilon

#

And you done

#

Right hand limit to zero from aboce

#

I don't know the functional form for that, so I can't think of an epsilon delta

#

For 4

#

Do the top and bottom limits

#

If they exist, use the quotient rule

real prawn
#

factor out the x^6 and pull it out of the square root, split the fraction into two fractions, the 2nd fraction will go to zero because the denimonator dominates the numerator.
the first fraction will go to -2/3

#

after you pull x^6 out of the square root the denominator will look like this:
$$ x^3 \cdot \sqrt{9 + \frac{1}{x^6} } $$

warm shaleBOT
#

agilepotato
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

real prawn
#

if you want to practice latex, you can use https://mathb.in/ (there are other latex online compilers too)

real prawn
#

@uncut fulcrum the limit of a product is the product of the limits

#

on b) they just pull out a 1/x^2 and then they identify it as an indeterminate form: infinity times zero https://en.wikipedia.org/wiki/Limit_of_a_function#Properties

In mathematics, the limit of a function is a fundamental concept in calculus and analysis concerning the behavior of that function near a particular input.
Formal definitions, first devised in the early 19th century, are given below. Informally, a function f assigns an output f(x) to every input x. We say that the function has a limit L at an in...

drifting swan
#

GOOD MORNING, COULD YOU PLEASE HELP ME WITH THE FOLLOWING EXERCISE?

#

a bucket with water rotates in the form of a conical pendulum, suspended from the ceiling by a rope of 2 meters whose angle with the vertical is 30 degrees. If the bucket is dripping, find the radius of the circle described by the drops on the floor 4 meters below the ceiling.

#

Sorry

real prawn
drifting swan
#

I got the wrong channel

obtuse pebbleBOT
#

@uncut fulcrum Has your question been resolved?

real prawn
#

here's 6 more solutions to point 3)

obtuse pebbleBOT
#

@uncut fulcrum Has your question been resolved?

obtuse pebbleBOT
#
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ivory cargo
#

i have to find the limit of the function, which i have done like this: And is the function continious for all x? i answered no hence x=0 is in the domain. Furthermore, can we choose a value c=h(0,0) so that the function becomes continious for R^2

ivory cargo
obtuse pebbleBOT
#

@ivory cargo Has your question been resolved?

ivory cargo
#

<@&286206848099549185>

ivory cargo
#

maybe today

#

maybe tomorrow

ivory cargo
#

going strong

#

<@&286206848099549185>

ivory cargo
#

ay yo boys, can i have som <@&286206848099549185>

#

@jaunty stream

#

<@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185>

#

almost two hours

#

nice we are really going strong

#

<@&286206848099549185>

coral epoch
#

nvm

#

hold on

#

sorry this is above my skill

ivory cargo
#

sadge

obtuse pebbleBOT
#

@ivory cargo Has your question been resolved?

obtuse pebbleBOT
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dreamy summit
#

can someone help apply finite difference formula for edge detection?

dreamy summit
#

with discretization step 1

#

fomula for finite difference

obtuse pebbleBOT
#

@dreamy summit Has your question been resolved?

dreamy summit
#

.close

obtuse pebbleBOT
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inner marlin
#

Hi

obtuse pebbleBOT
inner marlin
#

I am having an issue trying to find the angle as i keep finding different answers

#

and i am not sure which is correct

#

i found many solutions online which says that the angle <ACD is also <DMB

#

which results into two different answers

#

using the cosine rule

obtuse pebbleBOT
#

@inner marlin Has your question been resolved?

inner marlin
#

i end up with 51 degrees with <ACD and <ABD and 62 with <DMB

#

and technically <ACD is also <DAC as triangle CDA is isosceles

#

.close

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elder cosmos
#

Hi there, still trying to figure out the following

elder cosmos
#

I need to find that angle... using the law of SIN

#

driving me nuts...

sage geode
#

BDC angle?

elder cosmos
#

yes

sage geode
#

First you need to find BD

#

Using the law of cosines

obtuse pebbleBOT
#

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sullen terrace
#

1,2,3,4,5

Basically all of them

obtuse pebbleBOT
stable rain
#

bit small

sullen terrace
#

The 2nd one

#

Discrete mathematics is pain

#

But the only way to be a data scientist

rigid lintel
#

embrace the pain

#

which question is the problem exactly

sullen terrace
#

Every single

#

I only attended 4 classes and the teacher slammed me with this

obtuse pebbleBOT
#

@sullen terrace Has your question been resolved?

sullen terrace
#

No

sullen terrace
#

I am talking to a bot 😭

obtuse pebbleBOT
#

@sullen terrace Has your question been resolved?

obtuse pebbleBOT
#

@sullen terrace Has your question been resolved?

dire imp
#

Since you have two Boolean variables per expression (p and q) then you’re going to evaluate the 4 cases

dire imp
# sullen terrace 1,2,3,4,5 Basically all of them

For the second one use demomorgan’s law to distribute a negative into each one of the statements. Take each expression such as “go to graduate school” as a variable and then solve from there. Treat all instances of “or” and “and” as logical operators

obtuse pebbleBOT
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timber zinc
#

hi, i need help with complex limit

obtuse pebbleBOT
timber zinc
#

when i try to factor it it doesn't give cancelable values

#

and i can't use l'hopitals rule

knotty crow
#

factor of both denominator and numerator is 1 + i

timber zinc
#

i get this for the numerator

obtuse pebbleBOT
#

@timber zinc Has your question been resolved?

obtuse pebbleBOT
#

@timber zinc Has your question been resolved?

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silent imp
#

how would u do the derivatve of this i said use product rule

#

AHH

final thunder
#

It’s just power rule

nova stump
#

and linearity of derivatives

silent imp
#

😡

nova stump
#

you can distribute the -1/3 to both terms in the parenthesis

#

and compute the derivatives separately

silent imp
nova stump
#

no

#

$f(x) = 1/3x^{-3} +1/3x^6$

#

sorry forgot a negative sign

#

$f(x) = -1/3x^{-3} +1/3x^6$

warm shaleBOT
#

colin davis

nova stump
#

now you can do power rule on the terms separately

#

$f'(x) = (-1/3x^{-3})' + (1/3x^6)'$

warm shaleBOT
#

colin davis

silent imp
final thunder
#

$\frac{d}{dx} \left( -\frac{1}{3}(x^{-3} - x^6) \right) = -\frac{1}{3} \left( \frac{d}{dx} (x^{-3}) + \frac{d}{dx} (x^6) \right)$

silent imp
#

x^-3 on top

warm shaleBOT
nova stump
#

it is on top

final thunder
#

You can also do this

nova stump
#

just that i typed it ambiguously

silent imp
nova stump
#

derivative is a linear transformation

#

in this case you can use that to say the derivative of a sum is equal to the sum of the individual derivative

#

and that a derivative of a function times a constant is equal to a constant times the derivative of the function

silent imp
#

multiply

#

i mean

nova stump
#

if you think carefully, using the product rule with a constant is the same thing, but it makes your life harder

silent imp
#

.....34%

#

....56%

#

....78%

#

...100%

#

i look on youtube

nova stump
#

Thnk about it this way

#

product rule says

#

$d/dx (f(x)*g(x)) = f'(x)g(x) + f(x)g'(x)$

warm shaleBOT
#

colin davis

nova stump
#

if f is a constant, then f' is zero, so the first term is 0

#

then we get f(x)g'(x)

#

which is the constant times the derivative of the other function

obtuse pebbleBOT
#

@silent imp Has your question been resolved?

obtuse pebbleBOT
#
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frosty shale
#

How do I do #28 and #29?

obtuse pebbleBOT
gloomy valve
#

well whats the property of an odd function?

frosty shale