#help-10

1 messages · Page 42 of 1

grand garden
#

do you know how to add $1$ and $\frac{1}{2}$?

warm shaleBOT
#

alshfik

stiff saffron
#

nope

grand garden
#

hmm

stiff saffron
#

1.5? 💀

grand garden
#

good!

stiff saffron
#

really??

grand garden
#

yes, 1/2=0.5

stiff saffron
#

I didn't thought the answer could be that easy

#

then

#

$1,5x\ge1$

warm shaleBOT
#

by_melody

stiff saffron
#

?

grand garden
#

ye

#

divide both sides by...?

stiff saffron
#

ok then it's, 0,66666???

stiff saffron
grand garden
#

indeed

stiff saffron
#

could be 2/3?

grand garden
#

yep!

#

your done now, the solution is all real $x$ such that $x\geq \frac{2}{3}$

warm shaleBOT
#

alshfik

grand garden
#

also what book did you get this problem from?

stiff saffron
#

my teacher

#

I don't know where he got the book from or whatever, I think he wrote it, but I'm not sure

grand garden
#

oh nice

#

which grade

stiff saffron
#

5th

grand garden
#

er, how old are you

stiff saffron
#

17

#

the next year I go to sixth grade and the next to that straight to college

#

or university, however you'd like to call it

grand garden
#

well, tell your teacher your not familiar with fraction operations, or just look it up online

#

pretty important skill

stiff saffron
#

yeap, I keep that on mind

#

that was pretty hard

#

anyway, thank you

grand garden
#

alright, if you're done you can close a help channel with .close

#

i thikn

stiff saffron
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @stiff saffron

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

warped flume
#

heyy

obtuse pebbleBOT
warped flume
#

i checked my answer and it's the same as the answer key in terms of numerical value

#

i just can't seem to put the denominator in the form the question wants

high lily
#

multiply numerator and denom by e^3

#

to rid yourself of that negative exponent and get that sought after 1

obtuse pebbleBOT
#

@warped flume Has your question been resolved?

warped flume
obtuse pebbleBOT
#
Channel closed

Closed by @warped flume

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

slender kindle
#

Let x^2 -x(m-3) +m=0 (m E r) be a quadratic equation, find the value of m such that the eqn has real and distinct roots

slender kindle
#

ik u jus have to make D>0 and solve further

#

but my question is; Whats wrong with imposing another condition namely f(-b/2a)<0 (since a>0, the graph is open upwards and its lowest point ie the vertex is below x axis)

#

and then take the intersection

slender kindle
#

my soln;
a=1, b=3-m, c=m
D>0
(3-m)^2 -4m>0
m E (-infinite,1) U (9, +infinite)

When i impose f(-b/2a)<0;
[(m-3)/2]^2 +(m-3)/2.(3-m) +m<0
We get m<0
and m E (-infinite,0)

slender kindle
#

when i take the intersection, m E (-infinite,0)

#

which is clearly wrong

#

well why

#

m E (-infinite,1) U (9, +infinite) => this is the correct ans

timid silo
slender kindle
#

hmm?

timid silo
# slender kindle hmm?

to find f(-b/2a) don't put values of a, b, c use them as variables the solve the equation in the end put their values .. that would simplify it..

slender kindle
#

ill jus check for mistakes

timid silo
slender kindle
#

alright

timid silo
#

and you'll get the condition b^2/4a>c

slender kindle
#

ohhh yes i got it

#

wow

#

am doing multiplication wrong

#

wtf

slender kindle
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @slender kindle

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

solemn cliff
#

can somebody help with this?

obtuse pebbleBOT
royal basin
#

which part?

#

part c looks sus thonk

solemn cliff
#

a and b ;-;

royal basin
#

have you done polynomial long division before?

solemn cliff
#

nope this is my first time

royal basin
devout sable
solemn cliff
#

nvm im brainded

undone swan
#

Umm

#

Can I ask a math question?

#

It’s for my math hw

royal basin
#

@undone swan open your own channel and ask there.

undone swan
#

How do you do that?

wooden cipher
undone swan
#

There is no 0 under

solemn cliff
plain stag
#

This is the 2nd person I've seen take the graphic too literally

stable rain
#

HAHAAHA

obtuse pebbleBOT
#

@solemn cliff Has your question been resolved?

#
Channel closed

Closed by @solemn cliff

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stable rain
#

!15min

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

devout sable
#

if x,y are ur axis in old graph the let X, Y be ur axis for the transformation. find a relation between x->X and y->Y

spiral blaze
#

is it (x-2)^2+2x-1 ?

#

<@&286206848099549185>

obtuse pebbleBOT
#

@spiral blaze Has your question been resolved?

obtuse pebbleBOT
#

@spiral blaze Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

manic flame
#

Hello everyone, I'm Fia, learning game theory. Nice to meet you all. I tried to find help and end up to this channel. So, actually I have a problem that maybe anyone interest to help me solve it, tysm in advance 😊

manic flame
obtuse pebbleBOT
#

@manic flame Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
#

I need help pls

obtuse pebbleBOT
timid silo
#

I should show this

manic flame
timid silo
obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

No

#

<@&286206848099549185>

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @tiny echo

Use .reopen if this was a mistake.

timid silo
#

.reopen

obtuse pebbleBOT
#

timid silo
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @tiny echo

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cobalt sundial
#

How does gcse and a level grading work in the uk? I know it's not math but I wanted to know and this is probably the best place to ask

cobalt sundial
#

I'm in year 9 and I want to know what to aim for

kind hawk
#

well a global server is probably not the best place to ask. how about your ask your teacher?

cobalt sundial
#

Alr

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @cobalt sundial

Use .reopen if this was a mistake.

cobalt sundial
#

I'll ask google

devout solar
#

shoulda tried that first

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

west gale
#

Guys, it's very hard for me to turn word problems into equations. I'm really struggling, what aids can i do to improve?

sacred root
#

Well I had the same problem as well

#

To fix this I just imagined my self in the question

#

Like if the question says "Ram goes and buys and apple..." I would just imagine my self going and buying apple

west gale
sacred root
#

Hs??

west gale
#

High school

sacred root
#

Noo

#

U from india ??

west gale
#

I'm in grade 12

west gale
sacred root
#

Jee aspirant ??

dim patio
west gale
#

Not at all

sacred root
#

Ok so neet?

west gale
#

Nope

sacred root
#

Anyways

#

Ok

west gale
#

I'm preparing for iitm bs qualifiers

#

Yk tht?

sacred root
#

Nah

#

Ful form

west gale
#

You prep.. For jee?

sacred root
#

I'm in 10th gona soon

west gale
#

Oh

#

You know that iit madras online degree?

sacred root
#

Ohhh!!

#

I've heard of it

#

Ye

#

Nice you prep for that

#

??

west gale
#

Yeh

#

I've exams on 16th

#

But still struggling with word problems

sacred root
#

Well no can help sry, btw best of luck

#

Just try hard

dim patio
obtuse pebbleBOT
#

@west gale Has your question been resolved?

#
Channel closed

Closed by @west gale

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

unique spear
#

How do straight lines help me in this question…

royal basin
#

draw horizontal lines passing through the corners of this zigzag shape

#

the ones at which the 280° and x° angles are marked

unique spear
#

Sorry, but this is an image and I can’t draw physically, but I’m assuming you meant something like this?

royal basin
#

no that is not what i meant at all

#

those look like vertical lines not horizontal lines

unique spear
#

Wrong channel

timid silo
#

Oops sorry

unique spear
#

It’s occupied

royal basin
#

@timid silo please open your own channel

timid silo
#

Ye

radiant jolt
radiant jolt
#

bukan....

unique spear
radiant jolt
unique spear
radiant jolt
unique spear
#

sekarang nak buat apa?

unique spear
radiant jolt
#

Perhatikan sudut dalam garisan yang terbentuk

#

Mana saja sudut-sudut yang sama besarnya.

unique spear
radiant jolt
#

Cuba perhatikan sudut2 berselang-seli

#

Kan sama besarnya tu.

unique spear
#

ya

#

Kedua-dua sudut ni?

radiant jolt
#

Yang lain

unique spear
#

x = 34

radiant jolt
#

Itu belum diketahui besar sudutnya

unique spear
#

304*

#

saya buat kesilapan maaf

#

terima kasih

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @unique spear

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

turbid sail
#

how would you find the power series representation for this function?

haughty coyote
#

Bring yourself back to the known series of 1/1-x

solar trellis
#

But there's a cube?

haughty coyote
#

(1/1-x)^3 = (1+(-x))^(-3), which can be expanded

turbid sail
#

what now?

#

does is become (x/2)^3(n+1)

#

?

haughty coyote
solar trellis
haughty coyote
#

Forgot a -

turbid sail
#

where?

haughty coyote
turbid sail
#

Oh

haughty coyote
#

Not you. You did something correct but hardly useful

turbid sail
#

one question

#

is this true

solar trellis
#

Nah

haughty coyote
#

Not at all. That's like saying (a+b)^2 = a^2 + b^2, but generalised

turbid sail
#

I see

haughty coyote
#

You forget all the "middle" terms

turbid sail
#

then what am i supposed to do

#

how do i deal with series raised to powers?

turbid sail
#

okay..

#

I want to know how this guy reached such a conclusion

#

hold on

#

No steps are provided….

haughty coyote
#

In the formula in the middle, for negative exponents, most of the factorial cancels out most of the numerator. Here, what's left is n(n-1) it seems

obtuse pebbleBOT
#

@turbid sail Has your question been resolved?

#
Channel closed

Closed by @turbid sail

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lime phoenix
#

I know very little from mathematics, but I am a programmer for 2 years now, and my logical brain is functioning arguably good.

In my carrier, my plan is to learn Machine Learning from scratch. for that I will need to know Math like a boss.
But I also love mathematics and have a passion for it from the bottom of my heart.

I know that there are a ton of subdivisions of math fields but what do you suggest for me to learn first?

What are the necessary fields that Every mathematician MUST know?
How can I find the my path?

kind hawk
#

machine learning is a shitload of linear algebra

lime phoenix
kind hawk
#

multivariable calculus

lofty jay
#

calculus, stats

#

could use https://mml-book.com/ as a reference

obtuse pebbleBOT
#

@lime phoenix Has your question been resolved?

#
Channel closed

Closed by @lime phoenix

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

latent dove
obtuse pebbleBOT
latent dove
#

So here when they say count all the affine linear sub spaces, they are just asking us to list all the possible linear subspaces then find the equivalence class of every element in the original vector space with the equivalence relation?

kind hawk
#

yes

#

I hope the vector spaces you have are finite

#

well you don't actually have to list them. you just have to say how many there are

latent dove
#

I don’t think I quite understand the question tho

#

So we have to do it for a vector space (F_2)^3 where F_2 is the integers mod 2

#

This space has 16 subspaces

#

Now for each one of those subspaces we have to find the equivalence classes and add all the numbers up?

kind hawk
#

yes

#

you can do it for each dimension tho

#

all 1-dimensional subspaces are essentially the same

#

etc

latent dove
#

or is it that for every subspace T, we count the number of equivalence classes

kind hawk
#

for each fixed subspace T, we count the number of equivalence classes

#

then we sum that up over all T

latent dove
kind hawk
#

good. how many 1-dim subspaces are there

latent dove
#

7

#

so there are 28 affine subspaces in the 1-dimensional case?

kind hawk
#

yes. next 2-dim

latent dove
#

there are 7 2-dim subspaces

#

are there only 2 affine subspaces per subspace?

#

so 14 in total

#

so there are a total of 8 + 28 + 14 + 1 (0-dim + 1-dim + 2-dim + 3-dim) affine subspaces?

kind hawk
#

sounds correct

latent dove
#

ok thank you so much

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @latent dove

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

olive creek
obtuse pebbleBOT
olive creek
#

Help

#

@onyx warren

#

Bot

onyx warren
#

Can you the fuck not

olive creek
#

Your dad

#

@onyx warren

little warren
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @little warren

Use .reopen if this was a mistake.

olive creek
#

HELP

little warren
#

reopen once you respect everyone

#

until then don't open something to get help if you disrespect others

olive creek
#

Ok

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fierce helm
#

hi there. i am confused about the reasoning for the part in the green box

fierce helm
#

can someone help explain that please?

lethal sand
#

chain rule basically

fierce helm
#

i thought if it was implicit differentiation then derivative of v^2 with respect to y would be 2v*dy no?

lethal sand
#

v is dependent on y, hence the derivative of v^2 wrt y is the derivative of v^2 wrt v times the derivative of v wrt y

lethal sand
#

implicit differentiation is really just another fancy way of saying chain rule in this case, really. But either way, it would still be 2v*dv/dy

fierce helm
#

ohhhhhhhh

#

i think i got it

#

okay that makes a lot more sense

#

tyty

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @fierce helm

Use .reopen if this was a mistake.

fierce helm
#

.reopen

obtuse pebbleBOT
#

fierce helm
#

sorry i had one more followup

#

wait mb. sorry about that

#

there was a typo in my notes

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @fierce helm

Use .reopen if this was a mistake.

little warren
#

the formula is (u²)' = 2.u'.u

#

so it makes sense

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lusty sandal
#

(4x^(3) * y + 28x^(2)*y^(2) - 36 * y^(2))/12x^(4)*y^(4)

lusty sandal
#

how do i solve

#

$ (4x^(3) * y + 28x^(2)y^(2) - 36 y^(2))/12x^(4)*y^(4)

#

changing channels

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @lusty sandal

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lean yew
#

(8/1000)^2/3 = 4/100

obtuse pebbleBOT
lean yew
#

Is this corect?

#

Like is this true?

spiral whale
#

$\sqrt[3]{\frac{8}{1000}^2}$

warm shaleBOT
#

AvenirSeducatorul

lean yew
#

Yes I did like that

#

Then after solving it I got the result 4/100

timid silo
#

It should be

#

4/10

lean yew
#

it is 8^2/1000^2

#

the bot didn't generate that right

timid silo
#

oh I thought it's 8^2/1000

lean yew
#

then it is right?

#

4/100?

timid silo
#

yeah

timid silo
lean yew
#

yeah but i'm glad I got the good result anyways

#

ty for helping

timid silo
#

nice

obtuse pebbleBOT
#

@lean yew Has your question been resolved?

spiral whale
#

$(2.25)^{-\frac{3}{2}}$

warm shaleBOT
#

AvenirSeducatorul

lean yew
spiral whale
#

$\frac{8}{27}$

warm shaleBOT
#

AvenirSeducatorul

lean yew
warped cosmos
#

our friend did this is this ok?

#

and we did it like this

obtuse pebbleBOT
#

@lean yew Has your question been resolved?

obtuse pebbleBOT
#

@lean yew Has your question been resolved?

lean yew
#

hello?

#

anyone there?

#

<@&286206848099549185>

dusk charm
lean yew
#

no bro not this

lean yew
lean yew
dusk charm
lean yew
#

thanks

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @lean yew

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

north egret
#

If converting m2 to dm2 = x100. is m-2 to dm-2 = x0.01?

idle thunder
#

huh

obtuse pebbleBOT
#

@north egret Has your question been resolved?

#
Channel closed

Closed by @north egret

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shell harness
#

I looked up a few khan academy videos because I am VERY far behind in my understanding of math, but I'm failing to understand how I can combine these two functions to find (f+g)(x) ? do I plug -2 into f(x) to get an output there? (Ignore the identify the graph part, its a two part question im on part 1)

twin sapphire
#

so the definition of addition for functions is actually simple

#

if you have f and g two functions

#

f+g is a new function

#

such that

#

for all x, (f+g)(x) = f(x)+g(x)

#

so here f+g is the function that for x in input gives x²-2 in output

shell harness
#

ahhh okay I think that makes sense

#

so f+g = x^2-2

twin sapphire
#

in some sense yeah

#

but dont forget that a function isnt an expression in terms of x

shell harness
#

right, its like an operation that gives an output, I think

twin sapphire
#

yeah

twin sapphire
#

also a function is defined given its input and output domains

#

its not only how it transforms the input

#

but also what inputs are allowed

#

and what are the outputs

#

here its not given

#

but we can assume both input and outputs are real numbers

obtuse pebbleBOT
#

@shell harness Has your question been resolved?

#
Channel closed

Closed by @shell harness

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torn terrace
#

can i get some help

obtuse pebbleBOT
torn terrace
#

I have a GED test coming up and Im practicing for it. I am not good at math at all, and I would just like to know how to solve 512x243 on paper

#

like, step by step

#

maybe someone could demonstrate it using paint.net?

rigid lintel
#

a youtube video would probably help you more

torn terrace
#

Well do you at least know how I would solve this step by step? @rigid lintel

rigid lintel
#

bring the exponent inside the brackets and group 3 and 2

#

= 2^13 * 3^7

torn terrace
rigid lintel
obtuse pebbleBOT
#

@torn terrace Has your question been resolved?

#
Channel closed

Closed by @torn terrace

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

magic night
#

Hi there, I need help with question B, I'm just not sure what they ask of me to do

magic night
#

do i assume they want me to rewrite the question as:

y = -f(1/4(x+1)^2)+2

#

and then graph it?

peak shuttle
#

plug 1/4(x+1) into function f

#

-((1/4(x+1))^2) + 2

obtuse pebbleBOT
#

@magic night Has your question been resolved?

#
Channel closed

Closed by @magic night

Use .reopen if this was a mistake.

magic night
obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hushed tapir
#

Hi

obtuse pebbleBOT
hushed tapir
#

Okay so

#

3$ per 1k views capped at 850k (YouTube form) how much is that

#

And how do I solve it

rigid lintel
#

3 * 850

hushed tapir
#

So $2550?

#

Damn

peak shuttle
#

yeah, 850000/1000 * 3

hushed tapir
#

Okay so

#

I’m getting 1% of that

#

How much do I get?

peak shuttle
#

*0.01

hushed tapir
#

?

peak shuttle
#

what's the decimal equivalent of 1%

hushed tapir
#

Tf

#

I’m dumb

#

Explain

peak shuttle
#

1% = 0.01

hushed tapir
#

How do I solve it

peak shuttle
#

so multiply a value by 0.01 would give you the 1% of that value

hushed tapir
#

😭?

peak shuttle
#

what do you not understand

hushed tapir
#

How do I solve with a calculator

peak shuttle
#

you multiply the value by 0.01 to get 1% of that value

hushed tapir
#

And the value is?

#

I’m not English

#

Explain I want to learn

peak shuttle
#

literally what i said

#

you multiply the value by 0.01 to get 1% of that value

hushed tapir
#

I DONT KNOW WHAT THAT MEANS

#

Aghh

peak shuttle
#

do you know 1% of 1

hushed tapir
#

I get 2550?

#

Or am I dumb

peak shuttle
#

what is 1% of 1

hushed tapir
#

0.1

peak shuttle
#

it's 0.01

#

1/100

#

a percent sign is basically 1/100

hushed tapir
#

Yes

peak shuttle
#

so multiply 1 by 1/100

#

that's how you get 1% of 1

#

right?

hushed tapir
#

Idk

peak shuttle
#

so you have 2550 dollars

#

multiply it by 1/100

#

2550 * 1/100

#

what do you get

#

at 1%

hushed tapir
#

Fuck

#

Um

#

No clue

#

<@&286206848099549185>

#

Ooops

hushed tapir
obtuse pebbleBOT
#

@hushed tapir Has your question been resolved?

gloomy plover
#

You have $3 per every 1k views, and you can have a max of 850k. 3*850=$2550

hushed tapir
#

Doesn’t seem correct

gloomy plover
#

1% of what?

hushed tapir
#

$2550

hushed tapir
gloomy plover
#

1%=0.01, $2500*0.01=$25. Multiplying by 1% is the same as dividing by 100.

hushed tapir
#

Ok thanks

hushed tapir
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @hushed tapir

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

agile robin
obtuse pebbleBOT
agile robin
#

This bothers me

#

Du is -sinx we don’t have that so I multiply by negative -1 inside and outside so essentially I’m not changing anything and am able to put in du

#

Answer is -ln tho

#

What am I doing wrong

twin sapphire
#

why do you have 2 minus signs on your third line?

#

you justified one but not the other

agile robin
#

Wdym I said I multiply - inside and outside so essentially I’m multi plying by 1

#

On third line

twin sapphire
#

okay but take it slowly

#

take line 2

#

multiply by (-1)(-1)

#

identify dv = -sin(x)dx

#

and replace

agile robin
#

Oh like this

#

Ty

soft marten
#

would i be able to ask a question here?

agile robin
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @agile robin

Use .reopen if this was a mistake.

agile robin
twin sapphire
#

itll be better

#

and also for ur future questions

neat trellis
#

Hello, where can I find material on thermodynamics, it's just that I'm having a hard time understanding it

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bold nest
#

Am I supposed to try to show that this is cauchy in b?

obtuse pebbleBOT
#

@bold nest Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

woven creek
obtuse pebbleBOT
woven creek
#

please helping me

hardy widget
#

,w derivative of tan x

warm shaleBOT
hardy widget
#

@woven creek idk if you remembered the derivative incorrectly in part (a) but here

woven creek
#

my a is eight but b and c is wrong\

hardy widget
#

wait nvm I can't read lol

#

I saw a negative

#

ok lemme check part b

#

yeah the first part is wrong, idk if you thought $\sec 0=0$ or smthn

warm shaleBOT
#

Civil Service Exam is good

hardy widget
#

sec 0 = 1 btw

#

I can't rlly guess what you did for the second one either

#

You're going to need to explain to me how you got those answers for me to help

woven creek
#

my phone hs no storage space

#

i cant take a picture aaaaaaaaaaaaaaaaaaaa

hardy widget
#

oop

woven creek
#

i just plugged them into f' the chart

#

pls help

#

what do do ido

hardy widget
#

maybe check your work over?

woven creek
#

Please it's due in 8 minutes

hardy widget
#

,rotate

warm shaleBOT
hardy widget
#

$\tan 0=0 \implies f(\tan 0)=-5$, not $0$.

warm shaleBOT
#

Civil Service Exam is good

hardy widget
#

oh I see what you're doing

#

$f(\tan x) \neq f(\tan x) \tan x$

warm shaleBOT
#

Civil Service Exam is good

woven creek
#

what do i do

#

5 minuttes letf

hardy widget
#

So for instance, $F'(0)=$\sec^2 0 f(\tan 0)=f(0)=-5$.

warm shaleBOT
#

Civil Service Exam is good
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

woven creek
#

so the answer is -5

hardy widget
#

for the first one, yes

#

for the second one, I'll leave you to do that on your own

#

it's the same logic

woven creek
#

i dont understadnthe seond one

hardy widget
#

it's the same logic as the first one, so what don't you understand about the first one?

woven creek
#

-10

#

thank you

#

have a good day

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @woven creek

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

uneven otter
#

When Im calculating the price of kWh. I simply do kWh * cost of kWh right? So for example my appliance uses 40 watts then converting it to kw will be 0.04 and 0.96 kWh per day and the price is $1 per kWh. I just simply do 0.96 * 1?

sage iron
uneven otter
#

to the conversion?

#

from watts to kWh?

sage iron
#

0.96 kWh per day and the price is $1 per kWh. I just simply do 0.96 * 1?

uneven otter
#

Write 0.96 in fraction form?

#

I dont get it

sage iron
#

write the units as a fraction instead of using the word "per"

uneven otter
#

Uh I dont get it

#

Shit.

sage iron
uneven otter
#

What exactly do I write in fraction corm

#

form

#

You said instead of using "per"

sage iron
#

I just simply do 0.96 * 1?

what do you get if you do
0.96 kWh/day x $1/kWh

uneven otter
#

$0.96/day?

sage iron
#

exactly

uneven otter
#

Yes but now look at thus

sage iron
#

is that what you want?

uneven otter
#

I was calculating online

#

And got some else

sage iron
#

what did you get

uneven otter
#

Why did I get 1.04 in the first one

#

Omg because it says per day not per kWh.

#

Im stupid asf

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @uneven otter

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

buoyant horizon
obtuse pebbleBOT
buoyant horizon
#

I get the first one

#

and the last one I subsistuted the first y value in

#

however i don't get cos(theta)

#

to find the terms in terms of theta

hardy widget
#

Consider the Pythagorean theorem for (c)

buoyant horizon
#

would that be considered a trig raatio

hardy widget
#

fervent lake
#

cos(phi) = cos(90-theta).....

buoyant horizon
#

The question indicates to use trignometric ratios and in terms of theta

hardy widget
#

Consider the Pythagorean theorem for (c)

#

this was never the final answer nor the full solution

#

it was a hint.

buoyant horizon
#

Ye I get the hint

hardy widget
#

ok, what did you do with it?

buoyant horizon
#

2^2 + y^2 = z^2

hardy widget
#

ok

#

so now you have that you need to find $z^2$ as a trig ratio

warm shaleBOT
#

Civil Service Exam is good

hardy widget
#

and it's pretty obvious you can ||find z as a trig ratio then just square the result||

buoyant horizon
#

2^2 + (2*tan(theta))^2 = z^2

#

4+(4*tan^2(theta)=z^2

hardy widget
#

eh ig you can do that too

#

then use pythagorean identities

buoyant horizon
#

4(1+tan^2(theta)) = z^2

hardy widget
#

🤷‍♂️

buoyant horizon
#

Ok but

#

I alrady haave that

#

My question was for b

hardy widget
#

oh I thought you meant how it simplifies tbh

#

oop lol

buoyant horizon
#

Could you tell me about cos(theta)

hardy widget
#

you can apply the ||cofunction between sin and cos||

buoyant horizon
#

what does phi represent?

hardy widget
#

it's a variable, just like $\theta$.

warm shaleBOT
#

Civil Service Exam is good

hardy widget
#

$\phi$: this is phi.

warm shaleBOT
#

Civil Service Exam is good

buoyant horizon
#

so it's unknown?

hardy widget
buoyant horizon
#

oh wait

#

phi and theta are different

#

why is cos(phi) = cos(90-theta)

#

could you explain?

hardy widget
#

sum of angles in a triangle

buoyant horizon
#

alright thank you

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @buoyant horizon

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

unreal quartz
#

whats 10+10?

obtuse pebbleBOT
dim patio
#

Your level?

unreal quartz
#

im grade 7

#

but whats 10+10

dim patio
#

Are you trolling or what

unreal quartz
#

no

#

alr fine

#

heres my question

dim patio
#

Welp, then I guess the answer is too direct to get help

unreal quartz
#

what is 4 to the power of 2014

#

and is there any easier way to do it

dim patio
#

No...

#

You're clearly trolling

unreal quartz
#

bro 💀

#

wdym im trolling

#

i would be arrested if i was trolling

#

bc in sydney

#

police are investigating

dim patio
unreal quartz
#

what is the last digit

#

of 4 of the power of 2014

dim patio
unreal quartz
#

yes

#

on my book

unreal quartz
#

alr its 6

#

@dim patio how to close

#

this channel

dim patio
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @dim patio

Use .reopen if this was a mistake.

unreal quartz
#

.close

dim patio
#

I already done it for you

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

grim crater
#

is there a way to do this integral without a calculator

fierce lagoon
#

Suffer

#

That's how

#

You would suffer

obtuse pebbleBOT
#

@grim crater Has your question been resolved?

#
Channel closed

Closed by @grim crater

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

polar trout
#

hello, i need help

obtuse pebbleBOT
polar trout
#

<@&286206848099549185>

timid silo
#

It's unreadable

polar trout
#

im sorry, wait i'll upload a better one

#

A video posted on YouTube initially had 80 views as soon as it was posted. The total number of views to date has been increasing exponentially according to the exponential growth function y=80e^0.2t, where t represents time measured in days since the video was posted. How many days does it take until 2500 people have viewed this video?

spiral ether
#

can you set up an equation using the information in the question?

polar trout
#

how do we find the time?

spiral ether
#

you set up an equation

#

that's the first thing you do

polar trout
#

f(x)= 80(1+0.2)^t

spiral ether
#

because the base of the exponent isn't e here

polar trout
#

2500= 80(1+0.2)^t

spiral ether
#

but $e^{0.2 t} \ne (1 + 0.2)^t$

warm shaleBOT
#

findingsouth

spiral ether
polar trout
#

then what is e on y=80e^0.2t

spiral ether
#

it comes from compound interest, like in banks

#

so if you pay 1/2 * 100% = 50% interest twice a year, and you start with 1 dollar, you'll get (1 + 1/2)^2 = 2.25 dollars

polar trout
#

wait, what?

spiral ether
spiral ether
polar trout
#

yes, it looks complicated 😅

spiral ether
#

yeah, just remember that e comes up all the time in maths

#

you might be thinking "who cares?" but maths is there to make you a better thinker and to expand your mind, even though in practice it's not often this way

#

anyway, 2500/80 = (1+0.2)^t gives ln(2500/80) = t ln(1 + 0.2) using the power rule for logarithms

obtuse pebbleBOT
#

@polar trout Has your question been resolved?

#
Channel closed

Closed by @polar trout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lean pilot
#

hi so i asked this question before, but i just wanted clarification on this property of multivariate normal distributions

lean pilot
#

we've got this, and this was the working out for the proof

#

but i wanted to ask why E(ZZ^T) = I_n

#

the expected value of Z is obvious, what about ZZ^T

obtuse pebbleBOT
#

@lean pilot Has your question been resolved?

lean pilot
#

<@&286206848099549185>

obtuse pebbleBOT
#

@lean pilot Has your question been resolved?

obtuse pebbleBOT
#

@lean pilot Has your question been resolved?

obtuse pebbleBOT
#

@lean pilot Has your question been resolved?

obtuse pebbleBOT
#

@lean pilot Has your question been resolved?

timid silo
obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

real pebble
#

hey, in my laplace transform question, it includes sinh(2t), the laplace table shows it as being omega/s^2-omega^2 (we havent done any examples with any sinh or cosh) im confused as to why when its sinh its a -, but when its regular sin its +?

real pebble
#

never done A-levels, got in through a foundation and this is my second year and i dont remember ever having to use sinh/cosh for anything, so dont know anything about these functions

obtuse pebbleBOT
#

@real pebble Has your question been resolved?

obtuse pebbleBOT
#

@real pebble Has your question been resolved?

obtuse pebbleBOT
#

@real pebble Has your question been resolved?

obtuse pebbleBOT
#

@real pebble Has your question been resolved?

real pebble
#

<@&286206848099549185> ....

shut tulip
#

jeez u waited abt 4 hours just for that one questions sheesh

amber elbow
#

@real pebble do you know what sinh t is?

#

it follows from linear combination of laplace transforms and of laplace transfrom of e^(at)

#

ill leave sinh(at)=(1/2)*[e^(at)-e^(-at)]

obtuse pebbleBOT
#

@real pebble Has your question been resolved?

real pebble
real pebble
obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

simple stone
#

62.403 divided by 8.5

obtuse pebbleBOT
simple stone
#

i need answer pls

peak shuttle
#

Use a calculator

simple stone
#

bet

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @simple stone

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
#

if annual interest rate=18%,deposit period=2years and simple interest=$1620, find the principle and the amount.

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

timid silo
#

if annual interest rate=18%,deposit period=2years and simple interest=$1620, find the principle and the amount.

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dreamy scroll
#

ok so now i dunno how these happened

obtuse pebbleBOT
dreamy scroll
#

im confused

#

this part in particular

tranquil arch
dreamy scroll
#

ok leme process what im seeing

#

why did 3x^2 get splitted like that instead of being (12x^2 - 3x^3)^2

tepid depot
timid silo
#

they just rewrote 3 * x² * (4-x)² into 3 * (4-x)² * x²

dreamy scroll
#

is that applicable for all other possible examples of that nature?

tepid depot
#

yes

dreamy scroll
#

icic

#

ty

tepid depot
#

but its quite unnecessary

dreamy scroll
#

how so?

tepid depot
#

both ways of writing it would get you the same answer

dreamy scroll
#

but this is easier to understand right

tepid depot
#

if you think its easier then you should do it that way

dreamy scroll
#

you had me at easier XD tysm

#

but let say the denominator is different

#

cant its still be written that way?

timid silo
#

Yes it's the commutative law

dreamy scroll
#

icic

#

tyty

#

ill be back again later with more questions haha

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @dreamy scroll

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
#

someone help #help-11 they've been waiting so long

stable rain
#

LOL

timid silo
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @forest gale

Use .reopen if this was a mistake.

stable rain
#

using ur channel

#

to help another

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

austere eagle
#

Hi can someone please help me with high school probability questions?

austere eagle
#

I am willing to pay for help

#

I have many basic questions I need help with, ranging from stuff like binomial distributions to normal distributions and some sampling etc

#

Worded questions are not complex but I struggle with the probability math itself

proven zephyr
stable rain
#

just ask

#

ur many basic Qs here

#

n ull get em answered

#

for

#

$0

halcyon plover
#

Get a teacher then

stable rain
#

ye

#

if u wanna pay

#

lol

fickle turret
tepid depot
#

i will pay on his behalf

stable rain
#

🥣

tepid depot
#

bro some people fr doing college math when they cant even square an equation

#

🧌

stable rain
#

HAHHAHA

#

WHY R U SAYIN IT HERE

#

just like me tho

obtuse pebbleBOT
#

@austere eagle Has your question been resolved?

#
Channel closed

Closed by @austere eagle

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timid silo
#

help pls how do we solve this the answer has to be 7

oak glen
#

You have three unknowns you need to solve for. Can you set up three equations?

timid silo
#

idk what are they

halcyon plover
#

Do you know properties of parallelograms?

timid silo
#

no i dont

halcyon plover
#

Do you know the formula of its perimeter?

timid silo
#

how would i know 😭

#

im dumb

old dagger
#

Is 3x-2=x-w+1 correct?

halcyon plover
#

Your teacher must've teach you before bringing up this question

timid silo
#

ikk she didnt

high lily
#

have you done any course on geometry before this?

timid silo
#

who me?

high lily
#

yes, you

timid silo
#

no

high lily
#

was this the only question in this section that involved geometry?

timid silo
#

yeah

high lily
#

i suppose it would be a good idea to start by looking up on properties of a parallelogram

#

and basic geometry terms like perimeter

timid silo
old dagger
#

The length of AD = BC and AB = DC

timid silo
#

yeah right

#

ik what is the answer but idk how do i solve it

#

the answer is 7

old dagger
#

U will get 3 equation

#

With 3variables

timid silo
#

what are they

old dagger
#

Another one is perimeter

timid silo
#

perimeter is 22?

old dagger
#

Yes

#

Uk wht is the meaning of perimeter?

timid silo
#

yes i do

old dagger
#

Ok good

#

So u get the 3 equation?

timid silo
#

yeah ig

old dagger
#

Show me

timid silo
old dagger
#

Umm

old dagger
#

Meaning*

timid silo
#

yes

old dagger
#

So wht is value of AD BC AB DC

timid silo
#

180؟

#

?*

old dagger
#

No

#

In terms of x y and w

timid silo
#

x=8?

old dagger
#

No

#

U dont need to find the values first

timid silo
#

what

old dagger
#

U need to find the equation first

#

Like a + b = 1

timid silo
#

how would i find it

old dagger
#

Do u learn systems of equations before?

timid silo
#

no

old dagger
#

Umm

#

U should learn it before sloving this kind of question bro

#

Solving*

timid silo
#

yes ik but she said its a challenge i dont have to do it but i really wanna do it cuz i wanna get bonus marks

old dagger
#

Owh

#

But u better understand the concept first before doing it

timid silo
#

ikr

old dagger
#

Why dont u google first

#

Learn the basic

timid silo
#

alr i will

#

mm do u know how to solve it?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

#
Channel closed

Closed by @jagged plank

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

junior pebble
#

Tan(less than 90) = cot ?

obtuse pebbleBOT
junior pebble
#

Cot(less than 90) = tan ?

#

If the value of theta is less than 90, it'll change right ?

weary delta
#

No, that’s not correct almost anywhere, just at one point 45 degrees

junior pebble
#

What do you mean

weary delta
#

Tangent of angles smaller than 90 degrees isn’t equal to the cotangent of that same angle

junior pebble
#

Can you give an example

#

@weary delta

weary delta
#

Sure. Tangent of 0 degrees is 0. Cotangent of 0 degrees is not even defined but it heads off to infinity

junior pebble
#

Oooh

#

So you mean it cant always be vice versa

weary delta
#

The thing you said is almost never correct

#

There is one singular angle that satisfies tanx = cotx, 0 <= x <= 90

junior pebble
#

Still 0degree is in the trigno table, is there another example

weary delta
#

45

junior pebble
#

Hmm

weary delta
#

Try 30, you’ll see it’s not right

junior pebble
#

Oh yeahh

#

Wait

#

If tan70 can be written as cot90-70

#

So its always subtracted by 90 to covert

#

Right ?

#

Or can there be exceptions

#

@weary delta

weary delta
#

$\tan{(\frac{\pi}{2} - \theta)} = \cot{(\theta)}$

warm shaleBOT
#

Learath2

weary delta
#

This is the rule

#

It works for all theta

junior pebble
#

Can i take pie as 22/7 ?

weary delta
#

Oh, that’s theta measured in radians

#

If you want the same rule in degrees, just use 90 instead of pi/2

junior pebble
#

And will it be acurate

#

So does it mean if tan26=cot-64

#

@weary delta

weary delta
#

No, tan26 = cot64

#

To go from cot to tan, subtract the angle from 90. 90 - 64 = 26

junior pebble
#

Is it cuz on the 1st quadrant, cot is positive ?

junior pebble
#

Oh yeahh

#

Do have to multiple 90 with 90 for every conversion or just for tan and cot

#

@weary delta am so sorry to ping you so many times

#

@solid lion pls help

#

@timid silo

#

help

timid silo
#

If you are asking whether tan(x) = cot(x), where x < 90°, then no.

#

There are some values for which that will work but not all.

junior pebble
timid silo
#

Where x is in degrees.

timid silo
junior pebble
#

I dont uderstand