#help-10

1 messages Ā· Page 39 of 1

dull hornet
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atleast i did it without the help of google 🤣

teal turret
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Yea gj

dull hornet
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now i gotta find its yā€

obtuse pebbleBOT
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@dull hornet Has your question been resolved?

dull hornet
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am i doing it right?

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should i expand it next?

obtuse pebbleBOT
#

@dull hornet Has your question been resolved?

obtuse pebbleBOT
#
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torpid crescent
#

can you simplify $\prod_{n=0}^{t}(1-a_n)$?

warm shaleBOT
#

Alexandria

alpine raven
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i dont think you can

torpid crescent
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like for example in terms of $\prod_{n=0}^{t}a_n$

warm shaleBOT
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Alexandria

alpine raven
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no

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or something you can do :
$\prod a_n (1-\frac{1}{a_n})$

warm shaleBOT
#

ļ¼Øļ½…ļ½’ļ½…ļ½Œļ½“

alpine raven
#

$\prod a_n \prod(1-\frac{1}{a_n})$

warm shaleBOT
#

ļ¼Øļ½…ļ½’ļ½…ļ½Œļ½“

alpine raven
torpid crescent
#

eh oki

obtuse pebbleBOT
#

@torpid crescent Has your question been resolved?

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bright meadow
obtuse pebbleBOT
bright meadow
#

Simple question i cant quite do

tidal hawk
#

u can integrate to find dy/dx and then sub ur coordinates and =4 to find the c then integrate again

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and then sub once more

bright meadow
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So integrate to get ((3x + 2)^2/3)/2

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And then substitute the coordinates with gradient 4

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And then integrate again?

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Why not integrate twice at the start?

tidal hawk
tidal hawk
bright meadow
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Yeah i forgot the c

tidal hawk
#

u can’t integrate it again if u don’t find the value of it

bright meadow
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Ah that makes sense

tidal hawk
#

yayaya catbread

bright meadow
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Alr done found c as 4.2

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And now integrate again

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Alr i think i get it now and can do the rest

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Ty for the help

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Wait one question

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This could be a dumb question but

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Oh wait nvm

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I misread

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I understand everything now

#

.close

obtuse pebbleBOT
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shadow lava
obtuse pebbleBOT
high lily
#

multiply both sides by y/8

shadow lava
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Oooo

shadow lava
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Are they called something special?

versed cave
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Try it

shadow lava
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I’m familiar with conjugate to cancel something but I think this is different

high lily
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its supposedly a lot simpler

versed cave
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Yeah, just try it, something nice should happen with the fractions

high lily
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taking the reciprocal can be the result of multiplying/dividing both sides by stuff

chrome mesa
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y/8y isn't 8

high lily
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how did you get y=8

shadow lava
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Oh so there is no special term in math for this method?

high lily
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multpiing both sides by same ting

chrome mesa
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if a/b = c/d, then b/a = d/c

versed cave
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If you don't like this approach, you can also think of it like doing ^-1 on both sides

Or if you don't like this either, there's an intuitive way:
You have two values that are the same (this is what an equation is)
So if you divide 1 by those two values (aka take the reciprocal), you'll get the same result on both sides

shadow lava
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Oops

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Wouldn’t it be like this?

misty flame
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Jessie what the fuck happened

versed cave
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bro on the left it simplifies to ||1/8||

shadow lava
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Sorry lol still drinking my coffee this morning

versed cave
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yes that's it

shadow lava
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I think I finally got it

shadow lava
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Or ā€œcancel the reciprocalā€ for short?

high lily
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you can just call it taking the reciprocal of each side

shadow lava
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OK

high lily
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multiplication property of equality is just what can be used to justify it

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which seemed to be what you wanted

shadow lava
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ā€œInverseā€ is not the same as ā€œreciprocalā€, is it?

warm canopy
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multiplicative inverse is the same as reciprocal, but there are other kinds of inverses

high lily
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don't get too hung up on names

shadow lava
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Just curious when you take a university level math course do you follow absolutely everything word by word and letter by letter written on the board quite easily? Or does some stuff not connect right away? And need to take photo of the board to review later on?

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I’m wondering if I am the only one.. or very common with math…

high lily
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depends on what you already know

shadow lava
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True

warm canopy
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its unlikely anyone will spend their whole maths career understanding everything immediately

high lily
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unless they're prodigies like terrance

shadow lava
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Even for stuff I thought I knew, if the professor explains it differently I will want to understand the thought process.. so it seems every math class there is always something new to learn or observe, at least for me there is!

rough knoll
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Am learning derivatives and only recently learned that x^-1 can be written as 1/x.

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Everyone else thought this was basic knowledge and didn't question it, I was the only one stumped when the teacher did that.

shadow lava
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But where it really confuses me is seeing f^-1(x)

shadow lava
rough knoll
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I'd rather not even think about that. Lol

shadow lava
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Some mathematicians refuse to write inverse functions this way

rough knoll
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If your questions are answered you can close this. šŸ‘

shadow lava
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I think they use another symbol can’t remember which one

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Okie

warm canopy
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in general, ^-1 denotes some kind of inverse, usually of a function. it can be confusing that it can also mean multiplicative inverse and just a general function inverse

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but if you view multiplying as a function it makes a bit more sense

warm canopy
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you can view say the number 5 as a function that takes a number and multiplies it by 5, then the function that "undoes that" is multiplying by 1/5 = 5^-1

shadow lava
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I blame it on lack of foresight with whoever started writing the f^-1 to begin with lol.. too late to change it now

rough knoll
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What happens if the numerator is different? Like 2/5³?

warm canopy
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you'll often see the same notation used for different things in maths, sometimes those different things are secretly the same thing, sometimes you just need to figure out what the notation means from context

shadow lava
rough knoll
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1/x² = x^-2, so then 2/x² = ??

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2x^-2?

warm canopy
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yes

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typo

rough knoll
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28x²y⁶ = 28/(x^-2)(y^-6)??

shadow lava
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This is true too?

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Nice

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Math is so rad

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So many hidden secrets

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It’s like playing a puzzle game

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.close

obtuse pebbleBOT
#
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hidden fable
obtuse pebbleBOT
hidden fable
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I don't understand how to do this

final thunder
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what’s the meaning of the m before the angle?

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Is it just a notation I’ve never seen before?

hidden fable
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Idk, I think so tho, it looks like the letters that actually matter are a&b

final thunder
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Ok so do you know the theorem about verticals angles

hidden fable
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No, I don't know much abt this

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(I think m stands for measure, for measure of angle (letter))

final thunder
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These two are verticle angles

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Vertical angles are angles that are opposite of each other when two lines cross. Vertical angles are. congruent, meaning that they have the same angle measure.

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I just copied from Google

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So then what can you with the given info?

hidden fable
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Still nothing tbh, I knew they were opposites but didn't know that it was a theroum

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I think it is solved and the answer is 14, am I right?

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<@&286206848099549185>

obtuse pebbleBOT
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@hidden fable Has your question been resolved?

hidden fable
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12?šŸ˜‚

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Your wrong

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It was 14

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.close

obtuse pebbleBOT
#
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timid silo
#

how many rows and column are in a matrix to represent a hexagon

timid silo
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Please explain.

alpine raven
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how are matrices and hexagon linked ?

timid silo
timid silo
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A friend sent.

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I checked the question on Google and it is from a book "Larson geometry, student 1st edition".

timid silo
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@alpine raven

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<@&286206848099549185>

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
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fossil crag
#

hello, be careful as (b^2)^14 is not a coefficient in b^14

somber spade
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can someone dm me & help w this shit

fossil crag
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no problem

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and after that you'll realize that you can take r = 15 as well as r = 7, it doesn't matter

obtuse pebbleBOT
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placid totem
obtuse pebbleBOT
placid totem
#

Im not sure how to continue this problem

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Do I insert the un derived function into F

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And then the derived one into FĀ“

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or?

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<@&286206848099549185>

obtuse pebbleBOT
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@placid totem Has your question been resolved?

placid totem
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I am I like

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Not the only who doesnt understand the question at all

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Like Am I dumb or is the question very abstract?

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<@&286206848099549185>

obtuse pebbleBOT
#

@placid totem Has your question been resolved?

obtuse pebbleBOT
#

@placid totem Has your question been resolved?

obtuse pebbleBOT
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hardy widget
#

Set the radicand to be ||non-negative||

fading quest
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try to solve for x

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it should be |x|<=11 for the 3rd step there when you are dealing with inequalities as when you are taking the square root, one of these square roots are essentially dividing by -11 which would switch the inequality sign

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where |x| us the absolute value of x

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so you get $x\geq -11$ and $x\leq 11$

warm shaleBOT
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Duh Hello

fading quest
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so when working with inequalities absolute values are much easier to use

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pretty sure u wont there. honestly need to think for a while. never encountered this myself

obtuse pebbleBOT
#
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fading quest
#

no worries, and ye just checked you do not need to worry about it for odd exponents

obtuse pebbleBOT
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kind flame
obtuse pebbleBOT
kind flame
#

Can someone help me with this

abstract flame
#

go to discussion or somewhere not help lol

tardy epoch
kind flame
tardy epoch
obtuse pebbleBOT
#

@kind flame Has your question been resolved?

obtuse pebbleBOT
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lunar vapor
#

Yo so I'm doing linear equations and i got a bad teacher this year so we don't have notes, also we haven't received the answers for any homework. I'm not sure if my homework answers are correct, and I don't know what I'm doing, i got three tests this week, two on Wednesday which is math and history and one on Friday for science which is pretty stressful, i can only study maximum 2 hours per day since my days are full for other important things, I'm looking for a helper who is fast, simple, and can help me get the job done, I've been here before and the last helper didn't know English that well so I was stressed and took a 2 hours break and came back. I need help going over the pre review test sheet, I'd be nice if you can voice call and we can talk since I learn better that way.

lunar vapor
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<@&286206848099549185>

brisk grove
#

!15m

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

brisk grove
#

I would help but I have to go to sleep soon

lunar vapor
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Bruh

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Please

brisk grove
#

What do you mean please? I literally have to go soon

lunar vapor
brisk grove
#

and why would you ping me for this?

lunar vapor
#

I don't understand this

brisk grove
#

!15m

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

brisk grove
#

Can you read this simple line that says "Please do not ping or DM individual users about your question."

lunar vapor
#

But

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I was quotaiting you

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Please jelp

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Help

warm canopy
lunar vapor
#

I'm being serious

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Please

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I can't learn by video

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I watched the video

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And still don't get it

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Been 15 minutes

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<@&286206848099549185>

timid silo
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not a helper but maybe I can help

lunar vapor
#

Yes

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I know slope formula

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Pretty sure they already gave the slope

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No?

timid silo
timid silo
lunar vapor
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This is simple

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I know this the most

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Out of all of them

timid silo
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Oh wait the question is asking for y intercept and x intercept

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Pretty sure you would put x as 0 to solve for y and y as 0 to solve for x, and just problem solve to figure it out

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5x + 15y + 22 = 0

lunar vapor
#

Damn bro

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Imma just go watch one piece if this doesn't work out

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Alright

obtuse pebbleBOT
#

@lunar vapor Has your question been resolved?

lunar vapor
#

No

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<@&286206848099549185>

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It didn't work

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I still don't get it

candid palm
#

ok lets see

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what do you need help with?

lunar vapor
#

@candid palm

candid palm
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ok

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so can you graph each thing?

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or is it the graphing that's confusing?

timid silo
lunar vapor
candid palm
#

well the intersection of the two graphs is where x and y will both work

lunar vapor
#

Ok

lunar vapor
#

Like what are the steps

candid palm
#

well, you draw both graphs

lunar vapor
#

To complete this question

candid palm
#

and then where they intersect, that's where the two equations are solved

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the x and y coordinates are your solutions for x and y

lunar vapor
#

Please give me a moment to pray

candid palm
#

šŸ™

lunar vapor
#

BRO

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PLEASE

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VOICE CALL

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I don't understand this shit

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I'm fucking stressed

candid palm
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can't vc sorry

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ik math is tough

lunar vapor
#

Ok

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Can you

lunar vapor
#

Math used to be my favourite and most easiest subject

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IT'S MY TEACHER

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MY NEW TEACHER IS THE PROBLEM

candid palm
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yeah bad teachers can ruin a subject

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ok so these graphs are linear, which means they are straight lines

lunar vapor
#

READ THIS

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SHE SAID IT TWICE

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ON BOTH REVIEW SHEETS

candid palm
#

dang that sucks

lunar vapor
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Btw this is for history class

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For math class

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WE DONT EVEN HAVE NOTES

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HAHAHA

candid palm
#

yeah

lunar vapor
#

Bro

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I went up to the enriched student

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Which are the students in advanced math

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I showed them this sheet

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Review sheet that we're doing rn

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And none of them understand

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What the fuck this is

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Yet somehow you understand it

candid palm
#

i go to a math school...

lunar vapor
#

.

candid palm
#

so...........

lunar vapor
#

School only for math?

candid palm
#

well other subjects

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but mostly math

lunar vapor
#

I woke up early at 6 because school bus

candid palm
#

ok so do you know how to plot the graphs?

lunar vapor
#

I got 3 tests this week

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2 on Wednesday

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Math and history

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And one on Friday

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Science

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I was sick during the weekends

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my head is hurting

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It's 9 pm

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This is my last day to study for math because I need some time for history

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And i still don't understand this shit

candid palm
#

ok ill try to help

lunar vapor
#

God

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Help

candid palm
#

so do you know how to graph the right side?

lunar vapor
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I'm about to fall asleep

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I'm very tired

lunar vapor
candid palm
#

ok

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so you can start

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by just plugging in values for x

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so for 0, let's say

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-3x + 2

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plug in 0 for x

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and you get -3(0) + 2

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= 2

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so then you know the point (0, 2) is on your graph

lunar vapor
#

Ok

candid palm
#

does that make sense?

lunar vapor
#

So

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2 is my y intercept

candid palm
#

yes

lunar vapor
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And we don't got x

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So it's 0

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Ok

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Simple

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Ok

candid palm
#

so

lunar vapor
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So I put 0,2

candid palm
#

yes

lunar vapor
#

I go theree

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Ok

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OK

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MAYBE I WAS STRESSING MYSELF

candid palm
#

maybe

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now

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what's your slope

lunar vapor
#

Ok

#

Done

#

-3x

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-3 is my slope

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@candid palm

candid palm
#

oh the point (0, 2) is on the graph

lunar vapor
#

Btw the faster we get this done the better because I get a better sleep to study for tomorrow

candid palm
#

not (0, -2)

lunar vapor
#

Oh ok

candid palm
#

-3 is the right slope

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so now you have this:

lunar vapor
#

Good?

candid palm
#

good

#

remove the (0, -2)

lunar vapor
#

I dis

candid palm
#

should look like this

lunar vapor
#

Did

candid palm
#

ok

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so the red line is your graph

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now on to the next graph

lunar vapor
#

How do I know which side it is going

candid palm
#

well the slope is -3

lunar vapor
#

So it's this vertical or horizontal?

candid palm
#

rise over run

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so we know every -3 we go vertically

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we will go 1 horizontally

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and negative slope means downwards

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so for the second graph

lunar vapor
#

How do I graph that

candid palm
#

we can plug in numbers for y

lunar vapor
#

I'm confused

candid palm
#

well the image above is the graph

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for the first graph

lunar vapor
#

Yeah

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But how do I make the line

candid palm
#

well

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go down 3

lunar vapor
#

How do I know which way

candid palm
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and right 1

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because the slope is -3 right?

lunar vapor
#

Yes

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But

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Do I go straight down

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3

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Where is the other

candid palm
#

well slope is rise/run

lunar vapor
#

I'm sorry I wasn't taught this

candid palm
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so we know that for every 3 you go down

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ok

lunar vapor
#

Please tell me how

candid palm
#

rise / run

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is the change in the vertical

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over the change in the horizontal

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so a slope of -3

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means that rise/run = -3

lunar vapor
#

Could you graph it and show me how you go do it

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Like where you stop

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Till -3?

candid palm
#

ok so you see (0, 0)?

lunar vapor
#

Yes

candid palm
#

so the slope is 2 right

lunar vapor
#

Why

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Like how do I know

candid palm
#

so on the left

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we have the equation

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y = 2x

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and the number before the x

lunar vapor
candid palm
#

is the slope

lunar vapor
#

Like this?

candid palm
#

well

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the slope in the other problem is -3

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so from -2

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you go down 3

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to -1

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and then from 0

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you go right 1

#

to 1

#

so you should have the point (1, -1)

lunar vapor
#

-2 x or y

candid palm
#

sorry im not understanding

lunar vapor
#

Just tell me the trick

#

Don't tell me where it is

#

Tell me how you find where it is

candid palm
#

ok starting from 0, 2

#

you have a slope of -

#

3

#

-3

lunar vapor
#

Ok

#

Yes

candid palm
#

ok

#

and the slope is the (change in the vertical / change in the horizontal)

lunar vapor
#

Ok

candid palm
#

which means

#

that -3 = (vertical change / horizontal change)

#

so vertical change is -3 and horizontal change is

#

1

#

because -3/1 is -3

lunar vapor
#

Good?

#

@candid palm

candid palm
#

uh

#

if you look at these two points, the distance between them vertically is 3, and the horizontal distance is 1, which is what we want

sage mirage
#

Can one of you guys help me solve for c?

candid palm
#

@sage mirage this channel is in use, try the open channels

sage mirage
#

Okay. Thanks

lunar vapor
candid palm
#

@lunar vapor so you start from 0, 2 which is a point on your graph

#

and you go down 3 and right 1

#

because down three is -3 and right 1 is 1

#

whichh means your slope is -3/1

#

= -3

#

which is what you want

lunar vapor
#

Bro

#

Does this really matter?

#

Like

#

I don't understand

#

My graph is smaller

candid palm
#

ok you can label the points on your graph

#

so like every time theres a box

#

you can label the point

#

that should make it easier

lunar vapor
#

Ok label vertically 3

#

?

candid palm
#

well like this

lunar vapor
#

9:22 pm for me rn

#

So let's hurry this up

#

Can't sleep bad again

candid palm
lunar vapor
#

Ok

#

But

#

Where do I put them

candid palm
#

uh

#

like where the axis are?

lunar vapor
#

Look

#

We got 0,2

#

Right

#

But

#

Where do I make a line

#

To where

#

I don't understand

#

This

lunar vapor
candid palm
#

yes

#

from (0, 2)

lunar vapor
#

I think I did it

candid palm
#

uh

lunar vapor
#

@candid palm

#

Let's get this shit done

#

?

candid palm
#

ok lets see

lunar vapor
#

Ok bro we running out of time

#

Next question we go!

candid palm
lunar vapor
#

Yes

#

I did that

#

Moving on

#

Let's go

candid palm
#

ok

#

next graph?

lunar vapor
#

Now it's one of these

#

I had trouble with this one

#

With the other helpers

#

So maybe you can help

candid palm
#

can you move the 15y to the other side

lunar vapor
#

Ok

#

Why?

#

Why can't I not move the other ones

#

Why does Y have to move?

#

Isn't that racist?

candid palm
#

well you want the form y = mx + b where m is the slope

#

y = mx + b is the general form

#

b is the y intercept

lunar vapor
#

But Y should stay where it's at

candid palm
#

well its an equation

lunar vapor
#

So Y in this case would be?

#

Like what's 15y

#

Y intercept?

#

What is it

candid palm
#

the y intercept is the number

#

so 22

lunar vapor
#

@candid palm

#

Time

#

Alright

#

Why 22?

#

Why is Y 22

#

Tf

#

Wgy

#

What is 0?

#

I thought 0 is Y

candid palm
#

ok ignore that

lunar vapor
#

?

candid palm
#

we have 5x+15y+22 = 0

#

or 5x + 22 = -15y

#

then divide by 15 on both sides

#

-x/3 + 22/-15 = y

#

so your slope is -1/3

#

your y intercept is 22/-15

#

and your x intercept is -4.4

lunar vapor
#

Ok

#

Give me a minute

#

Ill ping you

#

Imma do some work myself

#

To figure this shit

candid palm
#

k

#

you should definitely sleep well though

#

sleep is most important for brain activity

timid silo
#

damn over 300 messages

candid palm
#

yup

timid silo
#

@lunar vapor if your teacher is really that shit you should try getting ahead on subjects and getting exposure on them before your teacher teaches them to you

#

could help

lunar vapor
lunar vapor
timid silo
#

ask for the syllabus

lunar vapor
#

I need to understand this

#

I had to skip my sports classes today

#

Just to understand this math shit

#

Tomorrow I got classes again

#

I can't skip it

#

So I need to finish it now

#

To learn

lunar vapor
#

I got the answer

#

Tell me if it's right

timid silo
#

what's tha quesiton

#

question

lunar vapor
#

Y= 0.33x + 1.46

timid silo
#

what are you looking for

#

oh

lunar vapor
#

Slope

#

X intercept

#

Y intercept

#

Is slope 5 or is that wrong?

timid silo
#

i'm too lazy to do that math out

candid palm
#

the slope is 0.33

#

or 1/3

lunar vapor
#

K

#

So 0.33

#

Damn

candid palm
#

well -1/3

lunar vapor
#

The other helpers lied to me

#

Wtf

candid palm
#

uh

lunar vapor
#

Y intercept is 1.46

#

?

candid palm
#

-1.46

lunar vapor
#

Wtf

candid palm
#

idk what to say man

lunar vapor
#

Hpw

#

Hpw

#

How

#

Oh

#

You fucking changed it

candid palm
#

wdym dude

lunar vapor
#

You brought 22 to the other side

#

Which makes it a negative

timid silo
#

ya that's what you gotta do

candid palm
#

ye

timid silo
#

to isolate the y

lunar vapor
#

Kk

#

Kk

#

So

#

How you find x intercept now

candid palm
#

5x + 15y = -22

lunar vapor
#

K

#

What's x intercept

candid palm
#

well

#

you want to isolate the y

#

so it would be 5x + 22 = -15y

#

so then divide by -15 on both sides

lunar vapor
#

Replace Y with 0?

candid palm
#

the slope is then -1/3

#

and the y intercept is (22/-15)

lunar vapor
#

Nono

#

I have the y

#

Intercept

#

And slope

candid palm
#

well you want the y by itself

lunar vapor
#

Now I need the fucking x intercept

candid palm
#

ok

#

the x intercept

#

replace the y with 0

#

and solve for x

lunar vapor
#

PRECISELY

candid palm
#

but you want the simplified equation

lunar vapor
#

WAIT

candid palm
#

so (-1/3)x + 22/-15 = y

lunar vapor
#

I'LL DO IT AND TELL ME IF IT'S RIGHT

#

OK?

#

I NEED TO LEARN MYSELF

candid palm
#

This is your equation: (-1/3)x + 22/-15 = y

#

now plug in 0 for y and solve for x

#

you got this!

lunar vapor
#

Fuck this class honestly

candid palm
#

yeah ik

lunar vapor
#

If I had good teachers i would get to harvard

timid silo
lunar vapor
#

No

timid silo
#

yet everyone isn't a millionaire

#

so focus on your math problem

lunar vapor
#

You don't need school to be a millionaire

timid silo
#

Ik

#

drop down a class if its hard

#

or get a tutor

lunar vapor
#

Dude

#

It's the teacher

timid silo
#

key-word

lunar vapor
#

I told you bro

timid silo
#

was

lunar vapor
#

Teacher

timid silo
#

It's okay

#

All you gotta do is deal with it and next year is calm

#

If the teacher is really that bad just realize bad grades aren't your fault and accept some lower grades

lunar vapor
#

This year is the hardest year

#

Apparently

#

CollĆØges look at this grade the most

timid silo
#

what grade

lunar vapor
#

But I can't talk much now, i need to focus

timid silo
#

bro i think you're talking a bit too much when you have some math problems to be solving

lunar vapor
#

I can't lack sleep

timid silo
#

yeah

lunar vapor
#

Ok

#

X intercept is 4.42 @candid palm

#

Correct me while I work on the next one

candid palm
#

aight so everything is correct, except the x intercept is negative

#

so -4.42

#

because the slope is negative in the first place

#

so then all of your steps afterwards are correct

lunar vapor
#

No

#

I moved 0.33 over to 0

#

And subtract

#

It turned negative

candid palm
#

well

#

the 0.33 should be a -0.33 in the original equation

#

(-1/3)x + 22/-15 = y

#

(-1/3)x + 22/-15 = 0

#

22/-15 = (-1/3)x

#

then divide 22/-15

lunar vapor
#

I thought we were bringing 22 to the other side

candid palm
#

sorry i gtg history essay

lunar vapor
#

Bro wait

#

Tell me this

#

Wait bro

#

DON'T LEAVE ME HERE BRO

#

NOOOOOOOOOOOOOO

#

FUCK

#

FUCK

#

FUCK

#

<@&286206848099549185>

#

NOOOOOOO

#

I was SOOO CLOSE

#

Ehh

lunar vapor
#

Ok

#

I figured it out

#

Thank you

#

Fuck man

#

It's probably lack of sleep that made me like this

#

I'll go sleep now

#

Dms

#

.archive

#

Bruh

#

This is my own private help channel

#

Go make your own

sage mirage
#

Oh ok

lunar vapor
#

And say that

obtuse pebbleBOT
#

@lunar vapor Has your question been resolved?

obtuse pebbleBOT
#
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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paper anvil
#

I need help

obtuse pebbleBOT
paper anvil
#

cansomeone please help

#

hello

devout sable
paper anvil
#

right now im studying alegebra in university and they gave us a bunch of algebra questions and i guess im fucked but here goes

fast pond
#

(here goes) NOTHING

paper anvil
#
    5+9 = 4x
#

these are two seperate questions

#

oh yea and could you show the steps as well ?

devout sable
#

what are you asked to do here

#

find x?

paper anvil
#

yes

#

@devout sable show the steps

devout sable
#

look up one step equations

#

you’ll get idea on how to solve such kind

paper anvil
abstract flame
#

use cramer's rule

#

jk

paper anvil
#

what is cramers rule

abstract flame
#

ignore what I said

paper anvil
#

ok

#

Can someone help

abstract flame
#

so for the first one

#

you want to isolate x

#

how can you do that

paper anvil
#

what do you mean by that

#

remove it ?

abstract flame
#

no

paper anvil
#

then ?

abstract flame
#

you want it to give you x=something

#

eventually

#

so the left hand side should only have x

paper anvil
#

like bring the x to the other side ?

abstract flame
#

no

#

you can keep it there

paper anvil
#

then ?

abstract flame
#

just move everything else to the other side

paper anvil
#

move what exactly ?

abstract flame
#

first the +3

paper anvil
#

ok so bring the +3 to the right hand side ?

abstract flame
#

exactly

#

how would you do that

paper anvil
#

the right hand side is the = sign part

#

right?

abstract flame
#

lhs=rhs

paper anvil
#

what?

abstract flame
#

rhs is to the right of =

paper anvil
#

what is rhs

abstract flame
#

right hand side

paper anvil
#

ok

abstract flame
#

right now rhs=6

#

and you want to bring the +3 to the rhs

#

how do you do that?

#

šŸ’€

paper anvil
#

idk how do you do that

#

you show arrows ?

#

how?

#

drag it and erase it on the left hand side ?

paper anvil
abstract flame
#

you can do an operation to both sides of the equation at the same time

#

and that will preserve the equality

paper anvil
#

bro what

abstract flame
#

what operation can you do to the lhs to remove the 3?

paper anvil
#

speak english

abstract flame
#

ok

paper anvil
#

whats an operation

abstract flame
#

like +2

#

or -3

paper anvil
#

so like +10 ?

#

like that

abstract flame
#

yeah like that

paper anvil
#

ok

abstract flame
#

but you want one that gets rid of the +3 from lhs

paper anvil
#

so what do i do for that

abstract flame
#

what is the opposite of +3

paper anvil
#

2?

abstract flame
#

no

#

it's -3

#

do you see why?

paper anvil
#

how?

abstract flame
#

+3-3=0

paper anvil
#

oh i see

abstract flame
#

mhm

#

so try doing -3 to both sides of your equation

#

what do you get?

paper anvil
#

wait so if im bringing the +3 to the other side it becomes (-)?

abstract flame
#

yup

#

you got it

paper anvil
#

so 6-3?

abstract flame
#

and what's that?

paper anvil
#

or -3+6?

#

which one ?

abstract flame
#

same thing

paper anvil
#

oh ok

#

so thats 3

abstract flame
#

ok

paper anvil
#

but now what

abstract flame
#

so you have 2x=3 now

paper anvil
#

i have 2x= 3 now ?

abstract flame
#

right?

#

yes

paper anvil
#

then

#

what

abstract flame
#

you want to get the 2 to the rhs

paper anvil
#

so 3-2x ?

abstract flame
#

no

#

you want to keep the x on the lhs

#

and only move the 2 away

paper anvil
#

so x= 3-2 ?

abstract flame
#

but addition and subtraction isn't enough to do that

paper anvil
#

so x = 1 ?

abstract flame
#

you need division

paper anvil
#

so x = 3 /2?

abstract flame
#

šŸ‘

#

that's your answer

paper anvil
#

oh i see thanks

abstract flame
#

also remember

#

plug it back in to the original equation

#

after you get the answer

paper anvil
#

oh i see thanks got it

abstract flame
#

to double check

paper anvil
#

ok

obtuse pebbleBOT
#

@paper anvil Has your question been resolved?

obtuse pebbleBOT
#
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spring frost
#

So basically

obtuse pebbleBOT
spring frost
#

is equal to 63

#

and I dont understand how that equals 63

#

because 3^-2 = 1/9

#

and 7/(1/9) is not 63

#

can someone explain?

brittle blaze
spring frost
#

one second

spring frost
#

thanks

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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devout elm
#

can someone help me factor this

obtuse pebbleBOT
devout elm
#

i got 8/2x-1 , but webassign said its wrong

timid silo
#

what exactly are you factoring??

devout elm
#

the goal is to simplify as much as possible

timid silo
#

okay so you should get

devout elm
#

by factoring and other stuff

timid silo
#

oh okay

#

I would probably

#

just add them up, expand everything

timid silo
devout elm
#

its a bit messy

obtuse pebbleBOT
#

@devout elm Has your question been resolved?

devout elm
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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stable rain
#

HALP

obtuse pebbleBOT
stable rain
#

i was lookin at khan on jordans lemma

#

for point c, how can there be a positive constant MR where lim R->inf (MR) = 0

#

like could ive an eg of that

#

also isnt M a series then? not a constant

obtuse pebbleBOT
#

@stable rain Has your question been resolved?

finite flame
stable rain
#

i din draw it

#

its 2 beautiful for me

feral sentinel
#

hello goddess

#

u are my saviour

#

ur the most perfect person

#

to exist

stable rain
#

HAHHAHA

#

THANKS

obtuse pebbleBOT
#

@stable rain Has your question been resolved?

#
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candid dust
#

help

obtuse pebbleBOT
candid dust
#

The instructions says Tell whether or not the given binomial is a difference of two squares

#

like example

#

a^2 - 121

#

am i gonna solve it and answer it?

urban patrol
#

well you can identify it as a difference of squares then factor it

#

And then is enough proof to support your claim

candid dust
#

ahh

#

i get it now

#

ty

#

.close

obtuse pebbleBOT
#
Channel closed

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jaunty bear
#

this again

obtuse pebbleBOT
jaunty bear
#

i understand everything but the answer

devout sable
#

not again

urban patrol
#

Sqrt2/2

#

If you rationalize

jaunty bear
#

ik but the book says the answer is 1/2 sqrt2

#

i got Sqrt2/2

urban patrol
#

same thing

#

1/2 times sqrt2?

devout sable
urban patrol
#

Sqrt(2)/2 or 1/2(sqrt2)

#

Same thing

obtuse pebbleBOT
#

@jaunty bear Has your question been resolved?

#
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scarlet relic
#

30 b

obtuse pebbleBOT
scarlet relic
#

I think something is missing

#

<@&286206848099549185>

#

Bro helpers what a scam

stable rain
#

agreed

high lily
#

there is insufficient info

scarlet relic
#

Ye thanks

#

.close

obtuse pebbleBOT
#
Channel closed

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solemn mason
#

Help.

obtuse pebbleBOT
stable rain
#

no.

solemn mason
#

How do I solve x2 + 2x = 4x + 8?

stable rain
#

jk

#

group like terms

solemn mason
#

I think it's nature root oe some shit

stable rain
#

then use quadratic formula

solemn mason
#

How do I find a nature

#

Idk I forgoršŸ’€

devout sable
#

wait x2=x^2?

solemn mason
#

yes sorry

#

x²

devout sable
#

oh okay

solemn mason
#

Okay so

#

x² + 2x - 4x - 8 = 0?

devout sable
#

$x= \frac{-b\pm{\sqrt{b^{2} - 4ac}}}{2a}$

warm shaleBOT
devout sable
solemn mason
#

okay so

#

stay with me

#

I need to simplify it yes?

stable rain
#

yes

#

group like terms