help-10

[timid silo]

@timid silo

[kindred oasis]

.close

[obtuse pebble]

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[vernal linden]

B What is the standard equation of the circle?

5 Circle with radius 5, and center (-5, -1)

[vernal linden]

How do i write the equation

[stable rain]

for some circle centered on

h,k

of radii r

[vernal linden]

the center is at (-5,-1)

[stable rain]

yes

sub that in

[vernal linden]

https://www.youtube.com/watch?v=iX5UgArMyiI

this video has two points

should i also have two point

[stable rain]

u already do

its

[wild swallow]

weak

[stable rain]

this

[wild swallow]

you cant even do it yourself

[stable rain]

what

im not u ok

im a

common mob

[vernal linden]

?

[stable rain]

common tier lv 1 goddess :c

[wild swallow]

you dont need two points i think

[stable rain]

LOL

[wild swallow]

you already have the centre and radius

[wild swallow]

so you can just sub into here

[stable rain]

or here

[vernal linden]

so (x--5)^2 + (y--1)^2 = 5^2

[wild swallow]

mhm

but

simplify those double negative signs

[vernal linden]

(x+5)^2 + (y+1)^2 = 5^2

[stable rain]

amazing

[vernal linden]

but shouldn't i follow the formula

[wild swallow]

whats the formula

[stable rain]

what

[vernal linden]

the formula has minus in it

[stable rain]

formula?

[wild swallow]

no thats just

[stable rain]

yea but -- simplifies to +

[vernal linden]

this one

[wild swallow]

there because you gotta subtract

doesnt mean you need to keep it

[vernal linden]

oh

[wild swallow]

just simplify

[vernal linden]

so i cant leave it with two negative

[wild swallow]

well

you can

but

[stable rain]

its kinda weird

[wild swallow]

what you consider as simplified depends on your own taste ig

[vernal linden]

lol

thx yall

[stable rain]

❤️

[wild swallow]

,w radius and centre of (x+5)^2 + (y+1)^2 = 5^2

[stable rain]

bru dont

do random stuff

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 夢雪#2250

[wild swallow]

there we go

[vernal linden]

?

[wild swallow]

as verification

[vernal linden]

what was all that

[wild swallow]

wolfram has checked your answer

[stable rain]

it was mistakes

[vernal linden]

oh

[stable rain]

well

[vernal linden]

had me confused there

[stable rain]

wolfram sometimes get it wrong tho

like if u use

[wild swallow]

dw i was just

[stable rain]

,w answer to everything

[wild swallow]

operating the matrix

nah thats right

[stable rain]

but ye, urs is right

[vernal linden]

hmm i see

one more question

how can i be better in math

kinda weird question

[wild swallow]

its different for everyone

we probably cant give you a concrete answer

[vernal linden]

any advice

[wild swallow]

nothing in particular

im not the person to ask for advice unfortunately

[vernal linden]

lol thx

[wild swallow]

np

[vernal linden]

C  State all 4 vertices of the ellipse.

6    (x2)/25 + (y2)/9 = 1

(5,0),(-5,0),(0,3),(0,-3)

can i write it like that

[wild swallow]

yis

[vernal linden]

yes

[vernal linden]

[(x+2)2 / 9] - [(y-2)2 / 16] = 1

can i write that the center is (h,k)

State the center of the conic. was the the question

[obtuse pebble]

@vernal linden Has your question been resolved?

[vernal linden]

could you help me please

[stable rain]

whats

a conic

[vernal linden]

conic is double-napped cone is sliced by a plane.

[vernal linden]

that's a conic

[obtuse pebble]

@vernal linden Has your question been resolved?

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[dense wyvern]

I need help

[dense wyvern]

I'm really confused on this one

When I feel like i figure it out

And it just changed

[astral ivy]

Do you know how exponents work?

[dense wyvern]

kinda

[tardy epoch]

https://www.cuemath.com/algebra/exponent-rules/

[obtuse pebble]

@dense wyvern Has your question been resolved?

[obtuse pebble]

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[timid silo]

Uh so I’m doing a physics expirement and my results seem off?

[timid silo]

Talking about the acceleration

Can somebody double check my calculations

[tardy epoch]

you can just use the calculator here

,calc 2^2 + 3 * 5

[warm shale]

Result:

19

[timid silo]

Huh

How did u get that

[tardy epoch]

just an example

[timid silo]

Oh

[uneven palm]

how did you find acceleration before finding the velocity?

[timid silo]

I am using a calculator but the answers still seem off

[timid silo]

Oh

Haha

Wait

[uneven palm]

acceleration = velocity / time

fyi

[timid silo]

I do have the velocity

All I need is the initial velocity

In my kinematic equation

And that’s 0

I wrote the equations I am using up top

[uneven palm]

okay..

[uneven palm]

well did you use this to find your acceleration?

[timid silo]

No we are using the kinematic equations

[uneven palm]

ohh I see

well you may just want to double check your calculations if you think they're off

I can't rly tell

[timid silo]

This is an example of one of the calculations I did

Just realized the variable a might be confusing

The a is my average time and the x is my acceleration

Lol

It seems right?

Does it make sense in a real world context

Is it something to do with me having delta y rather than x

But delta x is 0 and that makes all the accelerations 0

So that makes no sense

<@&286206848099549185>

[uneven palm]

@timid silo you may want to consider joining the physics server in #old-network

more chances of success

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

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[plucky remnant]

i cant figure out how to write in the form ax^n

[fossil crag]

rip my explanation didn't work did it ?

[pliant warren]

hellooo

[plucky remnant]

i thought it did,, and then i realised that i had definitely done something wrong

[pliant warren]

you can either bring the square root to the numerator and then spread the power

or spread the power first and bring the square root up

[pliant warren]

do you have working?

[plucky remnant]

nvm ive done it thanks tho

.close

[obtuse pebble]

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[mortal forge]

how do i solve this?

[plain stag]

There are 15 problems there, which one is "this"

[tardy epoch]

https://www.cuemath.com/algebra/exponent-rules/

[timid silo]

use the properties of the exponents

[obtuse pebble]

@mortal forge Has your question been resolved?

[obtuse pebble]

@mortal forge Has your question been resolved?

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[dawn sedge]

Kind of don't really understand

[uneven palm]

can you find the rate of change, in miles per minute?

[dawn sedge]

not really

[uneven palm]

so they've given you that the train travels 6 miles in 3 minutes

so based on that, how can we find how many miles it travels in 1 minute?

[dawn sedge]

you mean 5 minutes?

Or is it like a sub question

[uneven palm]

well that's the later question

yeah

[dawn sedge]

Ok ok

[uneven palm]

first I want to make sure you understand rate of change

so that you can create the equation

have you done similar questions like this?

[dawn sedge]

I have not really learned this concept in school

So no, I haven't

[uneven palm]

hmm

[dawn sedge]

you see im a 7th grader

like started 7th grade

[uneven palm]

oh okay

[dawn sedge]

like 2 weeks in

[uneven palm]

alright so let's make this a fraction, 6 miles /3 minutes.. now we want to find how many miles in 1 minute

so all we have to do is divide the numbers

and we get 2 miles in 1 minute

do you see how?

[dawn sedge]

Yes yes

6 divided by 3 = 2

[uneven palm]

great

so for the equation

you want the form y = mx, where m is the rate of change (we just found it)

do you think you can make the equation?

[dawn sedge]

m = 2 miles

??

[uneven palm]

yup

[dawn sedge]

ok

[uneven palm]

substitute that in, and it's y=2x

basically right

x is the number of minutes, y is the number of miles

[dawn sedge]

Alright

[uneven palm]

so it's 2 times the number of mintues (x)

to get y the number of miles

because remember we found that it travels 2 miles per minute

[dawn sedge]

mhm

[uneven palm]

so yea

tell me if u have any questions

im not sure if i explained that well, it's a lot better when you learn these things in school first lol

[dawn sedge]

Ikr, its very complicated like this is like a assigment that never ends

its continous

So just to make sure Y = 10 miles?

Am i right or wrong?

@uneven palm

[uneven palm]

in 5 minutes, yep

[dawn sedge]

Bruh, it says it counted as wrong

Thats kind of like

Goofy

[uneven palm]

can you show me what you entered?

[dawn sedge]

I can't

It doesn't have those previous

buttons

[uneven palm]

uhh

what'd you put as your equation

[dawn sedge]

idk

Im like stressed

its been 2 hours since I been doing this assignment

[uneven palm]

gl

feel free to ask more questions

[dawn sedge]

yea thanks

you mind if I ask in dms?

@uneven palm

[uneven palm]

no sorry

[dawn sedge]

alright

@uneven palm

kind of stuck on this

[uneven palm]

vertical angles are congruent

and h is vertical to?

[dawn sedge]

No idea

Like I said, these questions are out of my reach

[astral ivy]

@dawn sedge totally not out of your reach

you have two crossed lines

[timid silo]

oh opposite angles?

[astral ivy]

would you agree that the angle on the top is equal to the angle on the bottom?

[obtuse pebble]

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[minor zinc]

I don’t understand this question

[obtuse pebble]

@minor zinc Has your question been resolved?

[minor zinc]

<@&286206848099549185>

[minor zinc]

<@&286206848099549185>

[obtuse pebble]

@minor zinc Has your question been resolved?

[obtuse pebble]

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[oblique iris]

i'm stumped on this

[oblique iris]

i used the exact same integral i used to get mass but with y included to find the first moment about the x axis but its wrong

same for the y axis moment

anyone got any ideas

this is finding mass

this is the first moment about the x axis

any ideas

?

[obtuse pebble]

@oblique iris Has your question been resolved?

[obtuse pebble]

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[sullen raptor]

I found fx to be (-2x+7)e^(-1x^2-3y^2+7x+5y)

fy to be (-6y+5)e^(-1x^2-3y^2+7x+5y)

fxx to be (4x^2+28x+51)e^(-1x^2-3y^2+7x+5y)

fyy to be (36y^2-60y+19)e^(-1x^2-3y^2+7x+5y)

fxy and fyx to be (2x+7)(-6y+5)e^(-1x^2-3y^2+7x+5y)

I used fx and fy, equaled them to 0 and solved the system of equations to find the critical point (-7/2 , 5/6)

And then used the formula for discriminant which is D = fxx (-7/2 , 5/6) * fyy (-7/2 , 5/6) - (fxy (-7/2 , 5/6))^2

But I get a really small number of -7.1947 * 10^-60 which doesnt make any sense

Which part am I doing wrong? Please help thank you!

[obtuse pebble]

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[sullen raptor]

.reopen

[obtuse pebble]

✅

[sullen raptor]

<@&286206848099549185>

[obtuse pebble]

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[obtuse pebble]

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[surreal shell]

Anyone that can help parse this definition?

[tardy epoch]

chapter 8 http://math.ucdavis.edu/~linear/67/mat67_course_notes.pdf

8.1 builds up to taht

[surreal shell]

I see

Makes sense

Are these notes rigorous?

[tardy epoch]

yes?

[obtuse pebble]

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[obtuse pebble]

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[tardy epoch]

credit to @high lily

[high lily]

bad notation

[past jungle]

so i cant divide it by 7 to simplify

[high lily]

that /7 there is uncessary, its presence makes it wrong

[past jungle]

but that dosnt work

?

[summer stone]

not but they can simplify it (by removing the 7)

[tardy epoch]

you need quotient rule

[high lily]

if you wanted to explicitly indicate dividing numerator and denom by 7

you'd write something like

[tardy epoch]

OR divide and differentiate the 3 terms

[high lily]

but that's unecessary

[tardy epoch]

the latter is what i'd do

[high lily]

going from the original to the right, that is clearly implied so you don't really needed to write it at this level

simplest would be to split into 3 fractions and power rule each one

but that doesn't work
because again, you committed the same crime as you did originally
the one i told you doesn't work because its illegal math

[past jungle]

so i divide everything by 7x^2

😭

[summer stone]

right, u can use negative exponents to make it easier for u, just as long as u turn them back to non-negative ones after differentiating

[high lily]

if by

so i divide everything by 7x^2
you mean split into 3 fractions, what do you have after doing that

[past jungle]

-14^10->-2x^8 --- 70x^5->10x^3 --- 21->0?

[high lily]

no

$\frac{21}{7x^2} \neq 0$

[warm shale]

ℝamonov

[past jungle]

3x^-2

[high lily]

yes

and differentiate each term

[high lily]

no

[past jungle]

did i mess up the 3x^-2

[high lily]

your derivative of 3x^-2 is incorrect

[past jungle]

is it positive?

+6x^-1

[high lily]

which part?

no

show me the full application of power rule

[past jungle]

whats the power rule

[high lily]

the rule that you're supposedly trying to apply when differentiating these things

[past jungle]

i multiply whatever is left of the x by the power then minus 1 from the power

oh

so it becomes +6x^-3

?

[high lily]

no

i multiply whatever is left of the x by the power
how is that getting you 6

[past jungle]

im magically turning the negative to a positive

[high lily]

don't dothat

[past jungle]

xD

thank you!

.close

[obtuse pebble]

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[humble umbra]

When you're finding the local and end behavior, is it important to include the x and y intercept for the local behavior ? (Pre-calc question)

[stable rain]

i mean

if u know those i guess u shld mention it

[humble umbra]

so with a question like this where I
need to find the local and end behavior, because I can find the intercepts, I should?

ignore that.

Can someone explain end and local behavior to me

[obtuse pebble]

@humble umbra Has your question been resolved?

[stable rain]

,w end behaviour

hm

[obtuse pebble]

@humble umbra Has your question been resolved?

[viral blade]

I'm not quite sure what local behavior is

End behavior is what values the function takes on as you make x really big or really small (negative)

[obtuse pebble]

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[strange heron]

<@&286206848099549185> can somebody please help me?

[wild swallow]

!15m

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[strange heron]

i need help with the last four questions

[devout sable]

👌 lol

what have you tried so far?

[obtuse pebble]

@strange heron Has your question been resolved?

[obtuse pebble]

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[trim ivy]

why is there no local minima for this function on the interval [-4,4]? The abs min is at f(4) = -18 so why can't the local min be at f(-4) = -10?

[obtuse pebble]

@trim ivy Has your question been resolved?

[trim ivy]

<@&286206848099549185>

[viral blade]

I think they're weirdly saying it doesn't count as a local minimum because the function doesn't flatten out and rise again

If you were to extend the function to all reals that point wouldn't be a local min

They probably should have gone with your suggestion tho

Both endpoints should probably be counted as local mins

[trim ivy]

so f(-4) and f(4) would be considered as the local min?

[viral blade]

Probably they should be yeah

Or no sorry

Local maxes

Since all the points "around" them are smaller

At least on the interval where the functions actually defined

[trim ivy]

ok, i kinda understand it better now. thanks a lot

.close

[obtuse pebble]

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[viral blade]

Np

[obtuse pebble]

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[rain dirge]

help how can i find this

[slim lake]

it will be a piece wise graph

so first identify the "domain" ie. the region where the curve actually has a value

then for each "piece" determine what the function is, clearly on all of these they are straight lines so are going to be off the form mx+c

and then find m and c for each line

While final step is to display it nicely

Something like this but specific to the function here

so instead of |x| put f(x)

np bro gl

[rain dirge]

ty ty bye

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[obtuse pebble]

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[devout sable]

why did i read it as tikz lol

[obtuse pebble]

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[green abyss]

Question 37. No idea how to proof II and III correct or incorrect

[hoary oyster]

can i have help please

[green abyss]

No piss off

[hoary oyster]

ok sorry

[lethal sand]

for III, just plug in and check if w and 2w are equal

or what you can do is to prove that it is not equal unless w is 0

which is in your case, false

and similarly, for II, just plug w in and rationalise and simplify everything

[obtuse pebble]

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[rocky acorn]

need help with this one

[obtuse pebble]

@rocky acorn Has your question been resolved?

[gloomy valve]

You can mark nodes (instead of edges) by realizing that if you mark some node x as used, then its parent edge has been used. So an idea would be to run a backtracking DFS and mark all used nodes on the way. For example, if your DFS currently visited the path "1 2 3 5", where 5 is a leaf node, and nodes 1 & 2 have been marked already, then you can form a new disjoint subpath by taking "2 3 5" (because only the parent edges of 1 & 2 have been used already, so the path going through 2,3,5 wasn't used yet)

[obtuse pebble]

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[ruby ravine]

Probably a dumb question, but how can I get alpha in terms of f(x)?

[ruby ravine]

I could not do it by moving terms around and factoring stuff

[high lily]

multiply both sides by 1-a^2
rearrange to general form,
apply quadratic formula

[ruby ravine]

Oh okay, that didn't cross my mind at all. Thanks for the help!

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[obtuse pebble]

Please don't occupy multiple help channels.

[coarse forum]

can anyone help me with 4

[tidal hawk]

hihii

do u know the formula for volume

of a cone

[coarse forum]

Yea

volume is 1/3 x pi x radius^2 x height

[tidal hawk]

ya

so that’s equal to 2513

since u know radius

u can solve for height

[coarse forum]

ohhh

thanks so much

[tidal hawk]

welcc!

[rocky acorn]

wait set S ,i.e a set of paths is given and out of those i need a subset

[coarse forum]

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[digital wolf]

I need help for the first question, 20.82. The answers are at the bottom of the page but I don’t understand how to get those answers

[digital wolf]

Answer is 3.7 x 10^-6 btw

I’ve found that changing the sound intensity formula’s area to be pi r^2 instead of 4 pi r^2 gives me the right answer but I don’t understand why that change was made

[obtuse pebble]

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[obtuse pebble]

@digital wolf Has your question been resolved?

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[onyx spoke]

hi im new

[onyx spoke]

can someone help me with algebra 1

[pliant warren]

i can try

what algebra 1?

[nocturne minnow]

Read #❓how-to-get-help

[obtuse pebble]

@onyx spoke Has your question been resolved?

[stable rain]

u shld just

ask ur Q

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[timid silo]

I'm doing my homework and I don't remember how to do equivalent expressions and was hoping to be walked through it

[whole spindle]

ok so basically you know how a negative exponent flips it on the fraction right

so like 1/x^-3 is equal to x^3

and how x^-3 is equal to 1/x^3

[timid silo]

no..

I'm really bad at math

[onyx spoke]

same here

[whole spindle]

ok dont worry ill explain it

[timid silo]

ok

[whole spindle]

ok so when you have a negative exponent on the numerator (top) of the fraction, you bring it to the bottom of the fraction (denominator) which clears the negative from the exponent

ill find a picture

whenever you have a negative exponent you want to flip it on the fraction to clear the negative

[timid silo]

Ohh ok

[whole spindle]

yes so in your example, it is 6^-3 on top so you want to move that to the bottom and on the bottom fraction it is 3^-2, so you move it to the top

thats your problem so

so 6^3 times 6^2 is basically just 6^5 because you add the exponents

[timid silo]

Okay so just add the exponents not the whole number

[whole spindle]

and then just multiply the 3 through to the exponents

so 3^6 / 6^15

but yes basically those are the negative exponent rules

[timid silo]

Okay this helped so much thank you

[whole spindle]

i hope that helped

great!

[timid silo]

:)

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[twilit forge]

According to a survey result, 79.6% of respondents favored the gun law, 77.8% favored the death penalty for those convicted of murder and 62.7% were in favor of both. What is the probability that a randomly selected respondent was in favor of either the gun law or the death penalty for persons convicted of murder?

[twilit forge]

how can I solve this one?

[royal basin]

venn diagram

[twilit forge]

will this be 79.6 - 62.7 + 77.8 - 62.7?

[royal basin]

wha

eh?

that does not sound right at all...

wait

sounds like you interpreted or as meaning exclusive or

[twilit forge]

I don't exactly know what should I do

[onyx spoke]

plz dont come after me but i need help to and i think this easy for u guys

[stable rain]

stay in ur channel

[royal basin]

i told you to make a venn diagram but you seem to have not done that

[twilit forge]

I have

[royal basin]

then show your diagram

[twilit forge]

oh will it be

79.6 + 77.8 - 62.7

does it look like this?

[obtuse pebble]

@twilit forge Has your question been resolved?

[twilit forge]

A group of volunteers for a clinical trial consists of 88 women and 77 men. 28 of the women and 39 of the men have high blood pressure. If one of the volunteers is selected at random find the probability that the person has high blood pressure given that it is a woman.

is this 28 : (88 + 77)

[obtuse pebble]

@twilit forge Has your question been resolved?

[obtuse pebble]

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[rustic kindle]

could someone help with this

[obtuse pebble]

@rustic kindle Has your question been resolved?

[lunar locust]

If you know that the answer doesn't depend on the relative orientations, you can assume that it touches the diagonals

Or is at nearly the same orientation

In which case remember to double count the perimeter of the thin zone

Side, not perimeter, sorry

@rustic kindle

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[deep elk]

can someone explain how you simplify the top into the bottom expression

[knotty crow]

Use $\cos ( 2\theta) = 2\cos^{2} \theta - 1$ and expand.

[warm shale]

Modus

[obtuse pebble]

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[buoyant zealot]

what does absolute convergence of a series mean graphically?
why are we interested in checking for absolute convergence?

[buoyant zealot]

i just know the definition but dont see the point

[rigid lintel]

it means wiggly line doesnt go to infinity

absolute convergence is important for certain things later

and absolute convergence is a "stronger" statement

[hardy widget]

Riemann rearrangement theorem also

[rigid lintel]

absolute classic

[buoyant zealot]

and conditioned convergence graphically means?

it also doesnt tend to inf

[rigid lintel]

wiggly line doesnt go to infinity but absolute value of wiggly line make it go infinity

[buoyant zealot]

oh

cool thanks

👌

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[buoyant zealot]

caveman math with gijs

top explanation lol+

[rigid lintel]

lol

[obtuse pebble]

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[hallow hatch]

Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the probability that the length $DG$ is less than or equal to $1.$

[hallow hatch]

how do i do this

[warm shale]

banan|crab

[wild swallow]

draw a diagram

[hallow hatch]

what diagram

[royal shard]

a diagram about your task

[hallow hatch]

@wild swallow

wheres the area where DG will be less than 1

[buoyant zealot]

draw a line that is length 1 away from D

[hallow hatch]

problem is i dont know where that line is

[buoyant zealot]

cuz the line is circular

of radius 1

[wild swallow]

all those points which are within a distance of 1 from D are exactly those points which lie in a disc of radius 1 centred at D

[buoyant zealot]

then it becomes an area problem

[hallow hatch]

ah

where does this disc span tho?

[royal shard]

we want to know the propability of a point landing in the semicircle

that is calculated by $P=\frac{A_{semi-circle}}{A_{triangle}}$

[warm shale]

~Martin

[hallow hatch]

gotcha thanks

[royal shard]

for the triangle, we have A=0.5 * 3 * h
we can get h by using sine
sin(60°)=h/3

[hallow hatch]

is the area around 3.9

[royal shard]

for the circle, we have A=pi*r^2
for the semicircle we do (60/360)*A
so we get pi/6

i would advise you dont calculate the area

[hallow hatch]

ah

[royal shard]

you will get rounding error

[hallow hatch]

gotcha

so

$\frac{\frac{\pi}{6}}{\frac{h}{3}}$

[warm shale]

banan|crab

[crimson scroll]

hi

can I ask for help ?

[royal shard]

for the triangle, we have
A=3 * h /2
sin(60°)=h/3 => h=3*sin(60°)
therefore
A=(9/2)*sin(60°)

[crimson scroll]

it's just a small 10th grade problem

[royal shard]

@crimson scroll #❓how-to-get-help

[crimson scroll]

oh okay ima wait till u finish

thanks man

[hallow hatch]

i dunno that the answer would be such a weird number

what would the simplified fraction be

[hallow hatch]

thats a weird frac

lol

[obtuse pebble]

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[obtuse pebble]

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[green sedge]

Do I have to cross multiply then sum up the 3 things separately ?

[solar trellis]

No but you can

There will only be 2 terms

[fervent cradle]

that works

[green sedge]

Thanks in advance

[obtuse pebble]

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[fervent cradle]

wow that is a dreadful photo

[sleek sinew]

How do i use angle 3 to help me solve this?

Ok i will reupload

Nvm i got it

.closw

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[fervent cradle]

what's f(x+h)

work that out first

[obtuse pebble]

@uncut fulcrum Has your question been resolved?

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[visual hatch]

HEllo

[visual hatch]

oop

Alr problems

This may seem Alot and I have tried

[dawn pollen]

ok so part one in this, what are the two points you are given?

[visual hatch]

f(6)=7 and f(3)=2

thats the whole problem btw

theres no additional information

[dawn pollen]

if f(6)=7, what is x and what is y

[visual hatch]

uh

7 is x ?

[dawn pollen]

7 is y

[visual hatch]

OH

so x is 6/7 ?

[dawn pollen]

f(x)=y

[visual hatch]

or 7/6 q w q

[dawn pollen]

x is 6

[visual hatch]

oh

[dawn pollen]

re this

[visual hatch]

f(x) = y so x is 6 and y is 7

[dawn pollen]

yup

[visual hatch]

So for finding f(x) it's x ?

[dawn pollen]

wdym?

[visual hatch]

Ahh im getting confused

[dawn pollen]

this is right. now can you find it for the f(3)=2

what’s x and what is y

[visual hatch]

x is 3 and y is 2 ?

im so confuesd

[dawn pollen]

yess

so you have two points. can you find the slope now?

[visual hatch]

I can try

5/3 ?

[dawn pollen]

yesss

now from that, can you create the equation

find what the y intercept is

[visual hatch]

but were only finsiding f(x_

[dawn pollen]

using point slope

[visual hatch]

f(x)*

[dawn pollen]

for a linear function I believe you need f(x)=mx+b where b is y intercept

so you need y intercept

[visual hatch]

oh right

f(x)=5/3x+b ?

because m is te slope

[dawn pollen]

yes, but now we need b

[visual hatch]

and for that we set x to 0 right ?

so b = 0 ?

[dawn pollen]

well, first I’d put in point slope form

[visual hatch]

whats point slope form again

my teach didnt give notes for that

[dawn pollen]

replace x with 0

[visual hatch]

ok...

done!

[dawn pollen]

ok! what is your equation

[visual hatch]

but wbt y1-y=0-5/3x

[dawn pollen]

wait what

[visual hatch]

Didi I do it wrong ?

[dawn pollen]

replace y1 with one y cord of a point and x1 with a the x coord of that

and m with slope

[visual hatch]

ok

[dawn pollen]

what do you get?

[visual hatch]

2-y=-5 ?

[dawn pollen]

y-2=5/3(x-3)

do you get that?

[visual hatch]

yah...

but we make x 0

so 0-5

y-2=-5

[dawn pollen]

no so 0-3

not 0-5

but yes

[visual hatch]

what ?

no its -5

[dawn pollen]

yes that is correct

[visual hatch]

5/3 x -3 is -15/3

okey

so for f(x) it is uh

[dawn pollen]

no wait we’re not quite done

[dawn pollen]

solve for y?

[visual hatch]

we still finding b right ?

y=-3

[dawn pollen]

y-2=-5

correct ok

that’s your b

and you have slope

[dawn pollen]

now this!

[visual hatch]

😮

[dawn pollen]

hmm?

[visual hatch]

so our equation is

f(x)=5/3x-3

right ?

[dawn pollen]

yes!!

(I think unless I totally messed up)

[visual hatch]

so how do we get f(x)

[dawn pollen]

wdym?

you have your equation

[visual hatch]

is that f(x)

?

or do we have to simplfy or what not

[dawn pollen]

yup f(x) is 5/3x-3

[visual hatch]

ok so f(-3) + f(10)

is next question

wud that be f(7)

and we take our equation and multiply by 7

[dawn pollen]

no, you replace 7 with x

[visual hatch]

what ?

im confused

wdym

[visual hatch]

number 2

hewwo ?

?

hello

anone

.close

[obtuse pebble]

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[sonic ether]

hello

.reopen

[obtuse pebble]

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[uneven remnant]

How can I answer this question in radical terms? I can't find a source that helps me online.
"Jessie wants to drive from his house to school. From home, Jessie drives north 8 miles, and then turns east and drives 4 miles. He turns north again and drives 5 more miles and then turns east and drives 1 mile.

a) How far is he from his home? Leave your answer in the simplest radical terms.

[obtuse pebble]

@uneven remnant Has your question been resolved?

[uneven remnant]

<@&286206848099549185>

[cedar lichen]

What have you tried

[uneven remnant]

I got what I think are the coordinates though it never says if it needs to be in miles

I just plotted how much he moved in any direction per mile

but I don't know how to transfer that to radicals

[cedar lichen]

I think it's implicit that the units are in miles

[uneven remnant]

yeah

[cedar lichen]

Can you draw a picture of the situation?

[uneven remnant]

well I have his final coordinates if that helps

I can draw a picture but itll take a minute

his final coordinates were 13,5

from 0,0

[cedar lichen]

So what's the distance from his house to (13, 5)?

[uneven remnant]

my bad, I got the coordinates swapped

total distance is 13.9

[cedar lichen]

How'd you get 13.9?

[uneven remnant]

distance formula

[cedar lichen]

Which is what? Don't simplify it

[uneven remnant]

d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)

how do I put my result into simplest radical form though

I don't have any trouble getting distance

[cedar lichen]

Plug in the values into the formula

[uneven remnant]

yeah I did

[cedar lichen]

Simplify until you just have the square root of a number

[uneven remnant]

ohh

so I need to run back the result

ok

I got sqrt(194)

put that into a calculator and it matches

thank you @cedar lichen !

[cedar lichen]

Np, but check if you can simplify that further

[uneven remnant]

oh yeah I think I can

[cedar lichen]

No, it can't. The prime factorization is 2 * 97, so there's no squares to pull out

I wasnt sure if it could or not, which is why I said to check

[uneven remnant]

yeah I just checked myself

well that's all for that question

thank you!

.close

[obtuse pebble]

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[timid silo]

How do I do 2

[obtuse pebble]

Please don't occupy multiple help channels.

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

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[drifting nova]

Why is limit as x approached 90 from the right tan x equal to - infinity rather than 1

[candid sigil]

tg x = sin x/cos x

[drifting nova]

wouldnt that just make it undefined

because cos is 0 at 90

[candid sigil]

yes

[drifting nova]

why does it say the answer is negative infinity

[high lily]

but were talking about limits here, not the value of tan(90°)

approaching 90° from the right, tan(x) approaches -inf

and although technically the limit doesn't exist, expressing it as -inf is more meaningful

[drifting nova]

How can I do this without seeing the graph

[high lily]

know your trig functions

and/or consider \
as $x\to 90\deg, \frac{\sin(x)}{\cos(x)} \to \frac{1}{0^-}$

[drifting nova]

whats the dash after the 0

[high lily]

minus sign -

(but i suppose that still requires you to have decent knowledge of trig functions)

as $x\to 90^{+} \deg, \frac{\sin(x)}{\cos(x)} \to \frac{1}{0^-}$

[warm shale]

ℝamonov
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[drifting nova]

I understand that when its at 90, its divided by 0, but when it approaches from the right of 90, why would that approach infinity if at 180 degrees, tan is 0

[candid sigil]

0/-1

[drifting nova]

=0

[high lily]

why do you care about what's happening at 180°

and how is that relevant here

[drifting nova]

Good point, how would I know what tan is directly to the right here? And to the left?

[high lily]

know your trig functions

consider the cosine of something slightly above 90°

[drifting nova]

Ok

You can use the cos sum of angles formula and use it with cos 45 + 60

[high lily]

overthinking

what's cos(90°)?

[drifting nova]

I dont know off the top of the dome what cos 91 is but I know that the grpah of cosine is typically between 1 and -1

at 90 cos is 0

[high lily]

what would you expect from something like cos(90.001°)?

will that be close to 0?

[drifting nova]

Yup

[high lily]

and what quadrant is 90.001° in

[drifting nova]

2nd

[high lily]

so will cos(90.001°) be positive or negative

[drifting nova]

negative

[high lily]

yes

and cos(90.00...[crapton of zeroes]...1°)
will be negative and really close to 0 right?

[drifting nova]

Yup

[high lily]

which is what 0^- is denoating

as x approaches 90° from the right, cos(x) would approach 0 from the left/below

[drifting nova]

This makes so much sense now

Thanks

[high lily]

visually

[obtuse pebble]

@drifting nova Has your question been resolved?

[obtuse pebble]

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[thick oracle]

a) A stack of 100 sheets is 12 mm high. Give a rule that relates the stack height (in mm) to the number of sheets.

b) Ten 1 euro coins stacked on top of each other have a height of 24 mm. give a rule that relates the number of coins to the height of the stack (in mm).

[thick oracle]

At a) is it y=100/12 x

?

And at b) y= 24/10 x

?

[obtuse pebble]

@thick oracle Has your question been resolved?

[dawn pollen]

i think it’s actually flipped, or 12/100

but besides that it sounds right to me

[obtuse pebble]

@thick oracle Has your question been resolved?

[thick oracle]

Any other opinions?

[obtuse pebble]

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[obtuse pebble]

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[frail marten]

Hello how is the variance calculated here

[obtuse pebble]

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[ocean cave]

are you able to find the area of this parallelogram by doing
10 x 8 x sin(70)?

[royal basin]

yes but don't use the letter x for multiplication

[ocean cave]

what do i use instead?

*?

[spiral ether]

yeah

or \cdot in LaTeX

[ocean cave]

ah okay

[spiral ether]

for example: $10! = 10 \cdot 9 \cdot 8 \cdot 7 \cdots 1$

[warm shale]

findingsouth

[spiral ether]

with variables we can just write them next to each other like $A = \frac{1}{2}ab \sin C$

[warm shale]

findingsouth

[ocean cave]

okay

[spiral ether]

and the A is the area of a triangle

so you have the right answer (sorry I read too fast)

[ocean cave]

yeah that i know

Thanks!

.close

[obtuse pebble]

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[timid silo]

THE PROBLEM:
An item is being sold for s amount of money. Your job is to figure out whether it's worth it to buy and re-sell this item for profit.
You only get 88% of what you sell the item for.
You are supplied with the 10 most recent selling prices of said item.

MY PROPOSED SOLUTION:
Figure out the mean of the 10 most recent selling prices. This is what you'll be listing the item for.
Then multiply that by 0.88 to get your earnings.
Finally, subtract s to calculate your profit.

EXAMPLE:
The item's price: 9.77
10 most recent selling prices: {12.26, 14.66, 9.68, 13.40, 12.50, 15.00, 11.99, 10.08, 15.20, 12.32}
The mean: 12.41
Your earnings: 12.41 * 0.88 = 10.9208
Profit: 10.9208 - 9.77 = +1.1508

Could someone please check to see if my logic makes sense?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

<@&286206848099549185> this question shouldn't be that big of a deal. It's just a confirmation.

[obtuse pebble]

@timid silo Has your question been resolved?

[glossy basalt]

looks good to me

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

kk cool

[obtuse pebble]

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[honest sonnet]

I don't really like trignometry.

If $cos(\frac{B}{C})=\frac{1}{2}(m + \frac{1}{m}$

[warm shale]

daysling

[honest sonnet]

oops wrong

I don't really like trignometry.

If $cos(\frac{B}{3})=\frac{1}{2}(m + \frac{1}{m})$
Prove that $cos(B)=\frac{1}{2}(m + \frac{1}{m})$

[warm shale]

daysling

[honest sonnet]

$cos(B)=\frac{1}{2}(m^3 + \frac{1}{m^3})$*

[warm shale]

daysling

[honest sonnet]

So, What I've done is

[\frac{1}{2}(m^3 + \frac{1}{m^3}]
[= \frac{1}{2}(m + \frac{1}{m})(m^2 - m.\frac{1}{m} + \frac{1}{m^2}]

[warm shale]

daysling

[honest sonnet]

and got $cos(\frac{B}{3})((m^2 - m.\frac{1}{m} + \frac{1}{m^2})$

[warm shale]

daysling

[honest sonnet]

$cos(\frac{B}{3})((m^2 + \frac{1}{m^2} - 1)$

[warm shale]

daysling

[honest sonnet]

I don't know what to do after this

[obtuse pebble]

@honest sonnet Has your question been resolved?

[obtuse pebble]

@honest sonnet Has your question been resolved?

[honest sonnet]

<@&286206848099549185>

[glossy basalt]

did you learn
cos(3x)=4cos³(x)-3cos(x)

[glossy basalt]

i think they have to use this, @honest sonnet

[honest sonnet]

Yeah we did

[glossy basalt]

then your approach is correct!

you'll just have to use cos²(B/3)

in terms of m

[obtuse pebble]

@honest sonnet Has your question been resolved?

[obtuse pebble]

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[slate warren]

i was wondering but couldnt find it anywhere, how would i write 3^x in log form?

[slate warren]

so it would be the inverse of 3^x

i know that if i have e.g. 3^x=7 i can write it like log3(7)=x

but if there is no equal sign what do i do?