help-10

[mental zephyr]

okay

[royal basin]

this can be simplified

to make calculations easier

to 12x - 720

[mental zephyr]

do i factor the expression?

[mental zephyr]

of this

[royal basin]

no, unless you REALLY want to and REALLY want to overthink and overcomplicate.

[mental zephyr]

yeah i wont

next?

[royal basin]

well let's look at the problem again

we now have P(x) = 12x - 720 for part a

part b now asks for the profit from 100 ensaymadas

so now you need to evaluate P(100)

[mental zephyr]

okay

[obtuse pebble]

@mental zephyr Has your question been resolved?

[mental zephyr]

back

[mental zephyr]

how will i evalute this again

@royal basin

[royal basin]

you have your profit function now

P(x) = 12x - 720

P(100) = ?

[mental zephyr]

uh?

[royal basin]

if x=100 then 12x-720 = ?

[mental zephyr]

-8640?

wha

[royal basin]

???

x isn't the multiplication symbol

[mental zephyr]

then what’s the answerr

[royal basin]

12*100 - 720...

idk how else to explain it

[mental zephyr]

sooo

@royal basin what next

is that the answer orr

[royal basin]

well no, you need to do the arithmetic to calculate 12*100 - 720

i spelled everything out for you as best i could, and yet that was still not enough

[hexed blaze]

i think you should use more simple word as he claims he isn't good at english either
such as
you put 100 into x and do the math

[royal basin]

i already did put 100 into x

[mental zephyr]

480?

[royal basin]

congratulations

[mental zephyr]

how should i do part c @royal basin

[royal basin]

find x such that 12x-720=600

[hexed blaze]

you put 600 into the letter P(x) and find x

[mental zephyr]

so the answer is 110

@hexed blaze ?

[hexed blaze]

yes

110 is the answer

[mental zephyr]

12x - 720 = 600 moving the constant to right which makes it 12x - 600 + 720 then add which makes it 12 x 1320 then divide both sides x = 110

thank u all

[obtuse pebble]

@mental zephyr Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tight shale]

Hello, i need help with this question, im stuck at the begginning of it and its factorial numbers

[timid silo]

Take a calculator and solve lol

[tight shale]

🤦‍♂️

[hexed agate]

Take the common stuff out

4! (1 + 5 + 6)

[tight shale]

whwre did 1 come from

and wheres 3

[quaint lily]

write the factorial out in full

and you'll see that you can factor out the 4!

[timid silo]

wait u made a mistake

4!(1+5+6*5)

not only 6

[hexed agate]

Uh my bad

[limber mason]

ignore my language

4 and 5! cancels out, now see what "numbers" can't be crossed out for 6!/3!

[timid silo]

properties of factorials tells us that $(n+1)! = n! * (n+1)$ so

$5!=4!*5$

and

$6!=5! * 6 = 4! * 5* 6$

[warm shale]

Analytic Continuation of zeta

[limber mason]

[tight shale]

What

[timid silo]

$5!=5*(4321)=54!$

[warm shale]

Analytic Continuation of zeta

[timid silo]

this is another way u can think of it

or more generally stated as

$(n+1)! = (n+1) * n * (n-1) *.... *1=(n+1) * n!$

[warm shale]

Analytic Continuation of zeta

[tight shale]

Yeah i know that i just didnt get how i solve this problem where you add multiple facotirals and then divide into another some

[timid silo]

do u get how the factoring works?

[timid silo]

this step

[tight shale]

Isnt it multiplying with numbers beford it

[quaint lily]

yes

[tight shale]

i think i get it

so is it 36/25

[quaint lily]

no

[tight shale]

Oh

[quaint lily]

you can check with a calculator

[timid silo]

no

[tight shale]

then i didnt get it

[timid silo]

cross check the result

[tight shale]

calculators just show factorials of single number

[timid silo]

4! /3! is not 1

[tight shale]

is it 4

[timid silo]

yes

[tight shale]

Yeah so what do i do with that 4

[timid silo]

coz 4!=3! * 4

so 3! cancels out

[timid silo]

4*(36) /25

[tight shale]

Ah so 144/25

?

[timid silo]

yes

[tight shale]

Hm

What i dont get is how do i solve

is it like this?

[quaint lily]

factor out 3! on the numerator and denominator

[tight shale]

6?

[quaint lily]

?

[tight shale]

sigh

ah i think i gwt now

let me see if it works

nOo why did you delete it

[quaint lily]

try it yourself first

[tight shale]

Well i cant comprehend right now

ok i didnt get why it has a +1 next to 5

[quaint lily]

where?

[tight shale]

isnt it

4!(5+1+6.5)

numerator

[quaint lily]

no

[tight shale]

but someone said it was

[quaint lily]

this?

[tight shale]

yes

[quaint lily]

• means times, not a decimal point

e.g. 4*3 = 12

[tight shale]

. IS TIMES

4.3=12

[quaint lily]

in this context, * is times

[tight shale]

well okay
why it has 5+1

[tight shale]

.

[quaint lily]

expand it out

and it becomes 4!+5!+6!

[tight shale]

5+1 is 5! ?

[quaint lily]

no

use distributive property

[tight shale]

How do we do that

My brain is melting

[quaint lily]

e.g.

[tight shale]

there is no x here

[quaint lily]

first two lines

[tight shale]

ok wait let me try

[quaint lily]

i'm showing you what distributive property is

[tight shale]

but wait

[quaint lily]

4! = 4!*1

[tight shale]

i still dont know Why is it 1+5

[quaint lily]

5! = 5*4!

[tight shale]

Why is it not 4*3

if 5! = 5*4!

isnt
4! = 4*3!

4 times 3!

[quaint lily]

because you are factoring out a 4!

[quaint lily]

yes

[tight shale]

Why am i factoring out 4

[quaint lily]

that's if you want to factor out a 4!

[tight shale]

so is it like this?

[quaint lily]

try factoring out a 3! on the numerator and denominator

then you can cancel them

[tight shale]

did i do right

[quaint lily]

denominator is incorrect

[tight shale]

but it becomes 26

25

ok waot how do i do the numerator

[quaint lily]

factor out a 3!

[tight shale]

ok lete try

yeah i cant

[tight shale]

wait

like this?

[quaint lily]

close

[tight shale]

What do i change

[quaint lily]

3! times what is 3!?

6! = what times 3!?

[tight shale]

e timsz

2!

?

[tight shale]

4+5?

[quaint lily]

4⋅5⋅6

[tight shale]

oh

so wait

hm

so what did i do wrong

[quaint lily]

you didn't factor out the 3! correctly for the denominator

use the distributive property to confirm your answer

[tight shale]

Hm

like this?

[quaint lily]

not yet

[tight shale]

HM

did i make it better or worse

[quaint lily]

oh theres no 6! in the denominator

sorry

[tight shale]

what

[quaint lily]

this is closer

the denominator was 3!+4!+5!

[tight shale]

brih

bruh

ok waot

[quaint lily]

here

[tight shale]

why is there plus one next to 4

[quaint lily]

distribute it and it equates to 3!+4!+5!

3!(1)+3!(4)+3!(5*4) = 3!+4!+5!

[tight shale]

I still dont understand

ah

[quaint lily]

3! times 1 is 3!

[tight shale]

Now i undrrstand

[quaint lily]

in other words

expand the brackets

[tight shale]

yes i get it now

[quaint lily]

now cancel out the common factor

[tight shale]

3?

[quaint lily]

3!

3! divided by 3!

you have the same value on the numerator and denominator

[tight shale]

waig i dodnt grt it agai

let me test on another problem

to see if it worms

[quaint lily]

how would to solve this?

5 times 2 divided by 2

the 2's cancel out

[tight shale]

i know tjag

[quaint lily]

same applies here

[tight shale]

then why dont we cancel out

5.4

[quaint lily]

when you cancel the 3! the values are being added

[tight shale]

what

[quaint lily]

becomes

[tight shale]

why dont we cancel them out before we solve them

[quaint lily]

?

[tight shale]

Like why did you make 4.5 20 instead of cancelling them

[quaint lily]

because 4*5 is 20

[tight shale]

And 5.2 is 10

[quaint lily]

yes

[tight shale]

Yeah

so why did you cancel 2 in 5.2 but not 4.t

5

[quaint lily]

do you cancel the 2's out here?

[tight shale]

yes

do we not?

[tight shale]

hm

[tight shale]

Okay.

well what about this

do i cancel 9s

[quaint lily]

no

[tight shale]

Oh so i did it wrong

then how do i do it

[quaint lily]

factor out 9!

then cancel it

[tight shale]

do i facotr it out like

9.8!?

[tight shale]

i dodnt get it

why is it 10+1

[quaint lily]

expand it and it becomes 10!+9!

[tight shale]

my brain is sweating

i cant understabd

[quaint lily]

distributive property

[tight shale]

Hm

Yeah i dont underatanx

all i can think is #TBBSweep

is hm

its 11?

[quaint lily]

yes

[tight shale]

so like

10!/9! is

10.9!/9! and then you canxel out 9s its 10

?

@quaint lily

[quaint lily]

yes

[tight shale]

ah ok so

11!-12!/12-11!

what about this

[obtuse pebble]

@tight shale Has your question been resolved?

[tight shale]

no

[proven zephyr]

hello

still need help?

[thin pine]

do you need help?

[tight shale]

yes

i still do

[thin pine]

this is question

?

[tight shale]

yes i hace been on that question for 3 hours

[thin pine]

do you know how to factor?

[tight shale]

uh

like

3!?

[thin pine]

lets start with basics

do you know what 5! means

?

[tight shale]

yes

5.4.3.2.1

[thin pine]

ok

factor this:

(5+5*6)

do you know how to factor this?

and solve?

[tight shale]

6!?

[thin pine]

no

factor out the 5

[tight shale]

how

[thin pine]

(5+5*6)

->

[tight shale]

5!+6!?

[thin pine]

no

watch

[tight shale]

Ok

[thin pine]

(5+5.6)

->

(5.1 + 5.6)

->

5 . (1 + 6)

->

5 . 7

->

35

do you see how I got the answer?

[tight shale]

Ah now i get it

[thin pine]

ok

knowing that all factorials

are

1.2.3.4.....x

factor this like I did:

6 + 6.8 + 6.1

[tight shale]

Oh

ok let me try

6.(8+6+1)?

[thin pine]

continnue

[tight shale]

Jm

6.16?

15

[thin pine]

no

[tight shale]

?

but 8 plus 6 plus 1 is 15

[thin pine]

where did you get the 6 in (8 + 6 + 1)

[tight shale]

uh..

From

6+6.8+6.1?

[thin pine]

ya which one

of those

[tight shale]

Like onws with .

ones

with .

[thin pine]

this would be if I gave you:

6.6 + 6.8 + 6.1

but i gave you

6 + 6.8 + 6.1

is 6 times 6 = 6?

[tight shale]

no

[thin pine]

ok redo my question then

[tight shale]

ok

[thin pine]

what is the answer

[tight shale]

hm

I dont know

[thin pine]

6 = 6 times 1 correct

?

[tight shale]

yes

[thin pine]

ok

so

[tight shale]

6.1+6.8+6.1?

[thin pine]

6 + 6.8 + 6.1

ok... go on

[tight shale]

60?

[thin pine]

yes!

nice job!

[tight shale]

woo my brain is increasing in size

[thin pine]

:D

ok

[tight shale]

but..

now what do i do

[thin pine]

im getting to the question

we gotta build to get there

ok now:

try this one:

3.3.4 + 3.4.5 + 2.4.3

[tight shale]

Ok wait

120?

no?

[thin pine]

show me steps

[tight shale]

3.3 9 and 9.4 is 36

Do i not do likw that

[thin pine]

no

use factoring

no calculator

[tight shale]

oh

[thin pine]

which number is in all of these

[tight shale]

hm

3

and 4

[thin pine]

ok

start with 3

show me how you factor out three

[tight shale]

Hm

[thin pine]

like we did here

[tight shale]

What does factor out mean btw

ah yes

[thin pine]

so theres a common factor

and "factor out" means to seperate the number from the others

sort of organize the equation

[tight shale]

3.(3.4+4.5+2.4) ??

[thin pine]

yes!!!!

[tight shale]

Woo a 7 percent increased cranium size

[thin pine]

ok now do we still have any similiar numbers in the addition part?

[tight shale]

4

[thin pine]

yep

can you show me factor out a 4?

[tight shale]

So i remove 4 too?

[thin pine]

yep

you certainly can

[tight shale]

what about 3

[thin pine]

do the same thing you did before

[tight shale]

4.(3+5+2)?

[thin pine]

4.3.(3+5+2)

remember you have to keep the three there

[tight shale]

Oh

okay

[thin pine]

simplify?

[tight shale]

so its like 12(3+5+2?

did i simplfy?

[thin pine]

yep

now what is the inside

[tight shale]

10

[thin pine]

yep

so simplify futher?

[tight shale]

ah so its

10.12?

[thin pine]

yep

[tight shale]

120?

[thin pine]

yep

ok now we're going to work o n the problem

[tight shale]

Oh so i was correct

Why didnt we end it there

[thin pine]

i thought you just used a calculator

and made sure you are doing steps right

[tight shale]

Oh okau

y

[thin pine]

im not sure what this was either

ok so heres the problem

[tight shale]

ok

[thin pine]

$\frac{4!+5!+6!}{3!+4!+5!}$

[warm shale]

! matthewzz

[thin pine]

correct?

[tight shale]

Hm

yes

[thin pine]

ok so write out the multiplication expantion

ok the top and bottom

its going to be a little big

[tight shale]

Wait so do i do numeratoe and denominator seperatly

[thin pine]

yep

or rather

i can ask you this

what numbers do 5! and 7! have in common

in their 1.2.3.... expansion

[tight shale]

4?

[thin pine]

yep

anything else?

[tight shale]

3?

[thin pine]

yep

what else

[tight shale]

1?

2?

5?

[thin pine]

yes

yes

anything else?

[tight shale]

No

[thin pine]

good

so factor this please:

4!+ 5!

last practice problem i promise

show me steps

[tight shale]

5.4.3! ?

[thin pine]

nope

[tight shale]

Hm

[thin pine]

where'd your adition go?

[tight shale]

Idk disapear

Hm how do i do that

[thin pine]

expand both 4! and 5! out

[tight shale]

ah

ok

so like

[thin pine]

1.2.3.4 + 1.2.3.4.5

[tight shale]

yes

wait

[thin pine]

what numbers above 1 do they have in common?

[tight shale]

2 3 4

[thin pine]

ok factor those out

[tight shale]

like this

2.3.4.(5)?

[thin pine]

nope

[tight shale]

Hm

then like what

[thin pine]

what about the left side

[tight shale]

wdym

[thin pine]

1.2.3.4 + 1.2.3.4.5

=>

[tight shale]

4.3.2.(5+1?

[thin pine]

2.3.4 (1 + 1.5)

yep

what is 4.3.2 equal to?

[tight shale]

do i have to wrtie 1+1.5 ¥=

[tight shale]

24

[thin pine]

no 1+5 is fine

no

what else

think !

"!"

[tight shale]

ah

4.3!?

No?

[thin pine]

no

4.3.2 = 4!

[tight shale]

Hm

[thin pine]

correct?

do you see how?

[tight shale]

yes

oh yes

[thin pine]

4.3.2 = 4.3.2.1 = 4!

[tight shale]

i get it

[thin pine]

so we have

[brisk grove]

using * for multiplication is more common

maybe do that

[tight shale]

oKay.

[thin pine]

discord plays with the astrics

idk how to get around

lets just stick to "."

[brisk grove]

1 * 2 * 3 * 4

[tight shale]

sure

[brisk grove]

spaces

[thin pine]

ah w/e

its fine

ok ali

so for 4! + 5!

we now have

[tight shale]

Alisculispres*

[thin pine]

4! . (1 + 5)

correct?

[tight shale]

wait

why is there plus 1

[thin pine]

look here

[quaint lily]

alternatively, you can use ⋅

[tight shale]

ok waiy

[thin pine]

@tight shale

[tight shale]

wait

[thin pine]

4!+5!

[tight shale]

i am looking there

[thin pine]

4! + 5!

=>

1.2.3.4 + 1.2.3.4.5
=>
2.3.4 . (1 + 1.5)

[tight shale]

Oh yes

[thin pine]

=>

4! . (1 + 5)

[tight shale]

yes

[thin pine]

so 4! was our factor

since we ended up being able to take out 2,3, and 4

[tight shale]

yes yes

[thin pine]

and 2.3.4 = 4!

$\frac{4!+5!+6!}{3!+4!+5!}$

[warm shale]

! matthewzz

[thin pine]

so back to the problem

[tight shale]

Oh no this again

[thin pine]

looking at the numerator

what can we take out?

[tight shale]

4 and 5?

[thin pine]

we can take a 5 out of 4! ?

[tight shale]

Wait 4?

[thin pine]

4! = 4.3.2.1

yep

ok actually

[tight shale]

just 4?

[thin pine]

lets look at the denominator first

[tight shale]

Ok

[thin pine]

no

so for the denominator

$\frac{4!+5!+6!}{3!+4!+5!}$

[tight shale]

3

[warm shale]

! matthewzz

[thin pine]

yep

anything else?

[tight shale]

no

[thin pine]

can we take out 2?

from 3! and 4! and 5! ?

[tight shale]

Yes

[thin pine]

ok so lets expand it out

3! + 4! + 5!

= 3.2.1 + 4.3.2.1 + 5.4.3.2.1

= 3.(2.1. + 4.2.1 +5.4.2.1)

[tight shale]

what about 2s

[thin pine]

show me

the next step

[tight shale]

3.2(1+4.1+5.4.1?

[thin pine]

great

what is 3.2 =?

[tight shale]

6.13?

wait

6

wait

3!

?

[thin pine]

yep!

so show me the factored form of the denominator

[thin pine]

go one step futher

[tight shale]

3!(25?

[thin pine]

yep

ok so now we have

$\frac{4!+5!+6!}{3!(25)}$

[warm shale]

! matthewzz

[thin pine]

correct?

[tight shale]

Oh yes

[thin pine]

can we take out 3! from the top aswell?

[tight shale]

now numerator?

yes

[thin pine]

ok show me the factor

of 4! + 5! + 6!

where we take out 3!

[tight shale]

2.3.4 + 2.3.4.5 + 2.3.4.5.6?

[thin pine]

ok now factor

the 3!

[tight shale]

Ok

3!(4+4.5+4.5.6?

[thin pine]

3!(4+4.5+4.5.6)

yes

so now we have

[tight shale]

now i facotr 4?

[thin pine]

wait a sec!

[tight shale]

okay

[thin pine]

we now have

$\frac{3!(4 + 45 + 45*6)}{3!(25)}$

correct?

[warm shale]

! matthewzz

[tight shale]

yes

[thin pine]

can we cancel anything?

[tight shale]

3?

[thin pine]

yes

what else

[tight shale]

4?

[thin pine]

no

since 3! = 3.2

[tight shale]

Then wuat

[thin pine]

we can cancel a 3 and a 2 from top and bottom

[tight shale]

theres only 3 tho

[thin pine]

its 3!

3! = 3.2

[tight shale]

3!

yes

so we cancel 3!?

[thin pine]

yes

[tight shale]

ok now we solve up?

numerator

?

[thin pine]

after we cancel

what is the simplification

[tight shale]

144/25

[thin pine]

yes

that is your answer

[tight shale]

Wow.. thank you

[thin pine]

do you understand how we cancel 3!

[warm shale]

! matthewzz

[thin pine]

is the same as

[tight shale]

Wait

[thin pine]

correct?

[tight shale]

oh yes..

[thin pine]

oops

$\frac{3!(4 + 4 * 5 + 4 * 5 * 6)}{3!(25)}$

[warm shale]

! matthewzz

[thin pine]

is the same as

$\frac{3 * 2 (4 + 4 * 5 + 4* 5 * 6)}{3 * 2(25)}$

[warm shale]

! matthewzz

[thin pine]

right?

[tight shale]

yes

[thin pine]

is the same as

$\frac{6 * (4 + 4 * 5 + 4* 5 * 6)}{6 * (25)}$

[warm shale]

! matthewzz

[tight shale]

hm

yes

[thin pine]

so we can cancel 6 from top and bottom

right?

[tight shale]

true

[thin pine]

do you understand that?

[tight shale]

yes

[thin pine]

so therefore we can also cancel factorials (!)

[tight shale]

yes

[thin pine]

$\frac{3!(4 + 4 * 5 + 4 * 5 * 6)}{3!(25)}$

[warm shale]

! matthewzz

[thin pine]

that is why we cancelled the 3! from top and bottom

[tight shale]

Yes yes i understand

[thin pine]

which gives you the 144/25

there you are

[tight shale]

It does..

[thin pine]

have a good night

[tight shale]

You sir are a big brain

Thank you

[thin pine]

no my brain is tiny

[tight shale]

Wait ur sleeping?

[thin pine]

peanut brain compared to others here

[thin pine]

?

[tight shale]

well i understood atleadt

you zaid goodnight

[thin pine]

its 4am for me

im doing hw and got sidetracked

[tight shale]

Oh okay. goodnight

thank you

[thin pine]

please type ".close"

@tight shale

[tight shale]

Yes ok

.close

[obtuse pebble]

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[obtuse pebble]

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[slate bison]

I'm trying to create a 2X2 matrix U which needs to satisfy these 3 conditions mentioned bellow:
Is there any possible technique that I can apply here, I've used the gram-Schmidt process, but it isn't working

[timid silo]

have you tried just multiplying these out and get a system of equations? with condition 2 alone you already know what a and c is

[slate bison]

Yes I've tried that, and the system of equation seems like this which doesn't satisfy condition 3

here it is

[timid silo]

hmm, then it seems kinda impossible to me

[slate bison]

do you know any possible technique that I can try?

[timid silo]

i dont think theres anything you can do, from condition 1 and 2 alone you already know what a b c and d have to be, if that doesnt fit condition 3 it has to be impossible

[obtuse pebble]

@slate bison Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[naive quiver]

Why does my book say that ✓((-5)^2) is an irrational number??? How? It's 5

[high lily]

show exactly what the book is saying

[naive quiver]

Ok holup

Which of the following are rational and irrational numbers

[royal basin]

so

it ASKS you

it does not CLAIM that sqrt((-5)^2) is irrational

[naive quiver]

Yes holdup

OH NVM

I opened up the wrong answers page 😭😭😭😭

.close

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[gaunt raven]

y'all this looks seemingly easy but I'm dang stumped

[stable rain]

what part and whatve u tried

[gaunt raven]

I just can't find how many adults and how many children

it said 5 more children than adults but like

[stable rain]

so last part, whatve u gotten so far?

[gaunt raven]

I tried using substitution for this but it's not working for me probably bc I'm using it wrong

[stable rain]

can u show ur working

[gaunt raven]

it was in decimals and in negatives which just doesn't make sense

[gaunt raven]

I wrote it in a physical book and I don't have a camera nearby atm

[stable rain]

anyway

so what did u get for b

[gaunt raven]

15a + 10(c + 5) = 550

= 550

forgot to add that my bad

[stable rain]

so uve that and what was ur first equation

[gaunt raven]

c = a + 5

[stable rain]

ok so then what happens when u do substitution

[gaunt raven]

that's the part I'm confused on

I don't know how to properly substitute it

[stable rain]

so uve this

[stable rain]

u can take each c u see over here and replace it with a+5

[gaunt raven]

I have a feeling this whole equation is wrong

[stable rain]

its correct

anyway normally u just move on with the question first

[gaunt raven]

so like 15a + 10((a + 5) + 5) = 550?

[stable rain]

yes

[gaunt raven]

hmm let me try

I got 19.8

[stable rain]

show ur working

[gaunt raven]

I'm sorry I have to go

sorry for bothering you

.close

[obtuse pebble]

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[timid silo]

where’s my mistake?

46 c is supposed to be the answer

and photomath shows this

you forgot to put a minus sign there

damn it

thank you

.close

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[dark linden]

hi

[dark linden]

I need help

A company has bought a production machine for 489000 DKK. The value of the production equipment is depreciated at a flat rate of DKK 55000 per year.

a) Set up a linear model V(x)=a*x+b describing the value of the production equipment x years after the purchase.

DKK is the valuta in my country

[pastel nimbus]

ok so the input for the model is the year number

and the output is the value

a is the rate of deprecation and b would be the original value

[dark linden]

so A is 55000 DKK

and b is 489000 dkk?

[pastel nimbus]

it deprecates tho

the value goes down

[dark linden]

so were gonna substract?

[pastel nimbus]

yeah the slope would be negative

[dark linden]

so V(x)=55000 - 489000

I mean -

[pastel nimbus]

that would just keep it at a constant value

[dark linden]

hmm

What should I do?

[pastel nimbus]

i think it would help to look on desmos

[dark linden]

What is desmos exactly

[pastel nimbus]

like a function is something that transforms some input into an output based off a model

you can graph it

desmos allows you to graph it and see

[dark linden]

so I just write the function?

[pastel nimbus]

yeah

then you can see whether it's right

[dark linden]

Is it something u download?

[pastel nimbus]

it's a website

[dark linden]

so Im gonna write V(x)=55000-489000

?

[pastel nimbus]

yeah

and you will see why that's wrong

[dark linden]

idk how to use it lol

[pastel nimbus]

idk but let me try explaining it to you differently

here is agraph

what this means is that at year 0, the value of the widget is 5 dollars

[pastel nimbus]

then, at year 1, the value should be 5-3 = 2

that corresponds with my graph

[dark linden]

the graph doesnt evolve

[pastel nimbus]

the graph should start at 489000 and go down by 55000 every year

[dark linden]

nope doesnt show anything

weird

[pastel nimbus]

you have to put an x somewhere

that would be for your slope

[dark linden]

well

f(x)-55000+489000

isnt that right?

I think thats the model

[pastel nimbus]

you are closer

think about how you would make it go down by the 55k every year

[dark linden]

by making a graph?

[pastel nimbus]

you would have to add the x somewhere

[dark linden]

oh after

-55000

=

?

[pastel nimbus]

yeah

there you go

[dark linden]

YESS

Thank you man

I know how to do it

but I sometimes have trouble understanding what the question actually is referring to

ight I got 1 more question

The monthly cost of producing x units of product A is described by

C(x)=20x+7000

a) Determine the production quantity x when the monthly cost is 12000 DKK.

<@&286206848099549185>

[old temple]

Isn't that just setting C(x) = 12000 = 20x+7000 and solving for x by re-arragement?

[dark linden]

I think so

But how am I gonna solve x

[old temple]

you isolate it by itself on one side

so first subtract 7000 from both sides, then divide by 20 from both sides

then you'll get a number = x

[dark linden]

well 12000 divided by 20 is 600

and 7000 is 350

i dont get it

[old temple]

alright, now subtract both sides by 350

[dark linden]

11650

and 0'

i mean 11650

[old temple]

ok wait so by dividing the equation by 20 you have done this:

how can you get x by itself now?

[dark linden]

divided 350 with 600?

or put 12000 in x place

or substract 600 with 350

which equals 250

[old temple]

there you go!

so: 250 = x

x is in this case the production quantity, so for a cost of 12000, you had to have produced 250 units

[dark linden]

I see now

but we got a problem

[old temple]

to see if you understood it, try the same question but instead of 12000 try 13000

[dark linden]

Didnt u say I have to substract both sides with 7000?

[old temple]

you can either subtract both sides by 7000 and then divide by two, or divide by two first like you did and then substract by 350

[dark linden]

are you 100% sure that the answer is 250?

[old temple]

if you wanna check, take the original equation and use x = 250

[dark linden]

Now I get it thank you

now let me try your question

13000=20x+7000

divide both sides with 20

650 - 350 = 300

which is x

is that correct?

[old temple]

yep, you got it

[dark linden]

Ight thank you

[old temple]

nws

[dark linden]

I got one last question

which is harder

Let me check it real quick

For a good A, the relationship between demand and price is determined by the function
d(x)=-4x+2900 , 0≤x≤400
where x denotes the quantity demanded and d(x) denotes the corresponding price.
The relationship between supply and price for the same good A is determined by the function
s(x)=3x+1500 , 0≤x≤400

where x denotes the quantity supplied and s(x) denotes the corresponding price.
The equilibrium quantity is defined as the quantity for which supply and demand are equal. The equilibrium price is the price belonging to the equilibrium quantity.

Determine the equilibrium quantity and the equilibrium price of good A.

NB! The intermediate calculations must be shown.
The graphs for d and s are shown in the coordinate system.

Arent we gonna say

f(x) =-4x+2900=3x+1500?

to find the equilibrium set?

the graph shows its 2100

but I have to solve how

[old temple]

move the x terms to one side, and all the non-x terms to the other first, and tell me what you get

[obtuse pebble]

@dark linden Has your question been resolved?

[dark linden]

Ight so we got

-4x + 3x

which is 7x

cuz - * + = +

then we got the numbers

which is 2900 + 1500

= 4400

[dark linden]

is that correct?

-4x + 3x can also be -1

idk

Just got from Dinner sorry for not answering before

hold on no its wrong

were gonna say 2900 - 1500

which is 1400

and then we got 7x

or no idk got confused

[old temple]

yeah ur nearly there. 1400 = 7x, now divide both sides by 2

[dark linden]

700

and 7x is 3.5

[old temple]

sorry i meant divide by 7

[dark linden]

xd

[old temple]

since u want to isolate x

[dark linden]

ight

3.5

so 7 divided by 2 is 3.5

[old temple]

no divide the original by 7 instead of 2

[dark linden]

its 200

[old temple]

so x = 200

[dark linden]

but thats wrong

sorry its right

[old temple]

wait lemme graph ur function cause ive been doing it on a whim

[dark linden]

looked at y instead of x

[dark linden]

its true lol dont have to

[old temple]

ah ok

do you get the logic tho

[dark linden]

yeah I do

[old temple]

u have to try to isolate x by using a series of subtractions, additions, multiplications and divisions

aite nice then

[dark linden]

Do you know how to write the proof

Like I have to write the solving on word

but Idk how ot

to

[dark linden]

is this way acceptable?

[old temple]

200= x i think you meant on ur last line

[dark linden]

oh yeah

so like this?

[old temple]

Yep, all good

[dark linden]

Thank you

Just started highschool

I want to work in a real estate

Like I love math but its confusing sometimes

[obtuse pebble]

@dark linden Has your question been resolved?

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[twin shard]

How would I simplify this?

[devout sable]

Firstly let 2x +1 = u

So x = (u-1)/2

[twin shard]

Yeah

[obtuse pebble]

@twin shard Has your question been resolved?

[twin shard]

<@&286206848099549185>

Where did you go 😂

[obtuse pebble]

@twin shard Has your question been resolved?

[obtuse pebble]

@twin shard Has your question been resolved?

[robust sleet]

(2x+1)*((2x+1)^(-3/2)+x(2x+1)^(-5/2)) as numerator

[obtuse pebble]

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[patent stump]

Hi can someone help me out with this question

[wild swallow]

what is the definition of the operator

you haven't given the full question

[obtuse pebble]

@patent stump Has your question been resolved?

[patent stump]

One second

Here is the whole question

[wild swallow]

right i see

have you filled in the table

[patent stump]

I did but it was wrong also

because I didn't understand how to fill it

[wild swallow]

right

do you know how to fill the P square Q column at least

[patent stump]

yes

but here it is not given whether square box is AND, OR, CONDITIONAL OR BICONDITIONAL

OPERATIONS

[wild swallow]

yes it's possible none of them

that's the point of the later part

[patent stump]

I'm lost even more

now

[wild swallow]

the square isn't one of the of those logical operators

[patent stump]

makes sense

[wild swallow]

it's currently just defined by that truth table

[patent stump]

yes