help-10

[crisp dune]

How do u do “d”?

[novel knoll]

Same way you did b. and c.

[gilded needle]

it's a continuous random variable

[crisp dune]

Why is it equal to 0?

[gilded needle]

what happens if you integrate f(u) from 0.8 to 0.8?

[obtuse pebble]

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[unique vessel]

Can someone clarify if this is correct?

[obtuse pebble]

@unique vessel Has your question been resolved?

[obtuse pebble]

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[turbid cedar]

the question is to find the eigenvalues and eigenvectors of the matrix A

i'm having a problem with the last relation

<@&286206848099549185>

[warm canopy]

Problems how

Eh they probs mean 3(2,-1,0)

Hard to tell without A

[obtuse pebble]

@turbid cedar Has your question been resolved?

[turbid cedar]

only says that A is a 3x3 matrix

just that

[obtuse pebble]

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[obtuse pebble]

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[timid silo]

how do I solve x-1/x^2 = 10^-1

[proven zephyr]

multiply both sides by x^2 to get rid of the fraction

[timid silo]

ok

x-1 = 10^-1 x^2

[proven zephyr]

subtract (x-1) from both sides

[timid silo]

0= 10^-1 x^2 - x-1

[proven zephyr]

remove the brackets

i dont mean like that

i mean like.. - (x - y) = - x + y

[timid silo]

0= 10^-1 x^2 - x+1

[proven zephyr]

yes

now you have a quadratic

do you know the quadratic formula?

[timid silo]

yes

[proven zephyr]

ok good

[timid silo]

wait

the

10^-1

[proven zephyr]

turn it into a fraction if you want

[timid silo]

has -9

ok

[proven zephyr]

wait what

[timid silo]

with the -1

nvm

im tripping

😂

its giving (-1 +/- sqrt -0.6 ) / 0.2

but it's supposed to be (10 +/- sqrt 60) / 2

nvm

when done correctly it gives error

x = (-1 +/- sqrt -1^2 - 4 (1/10) (1)) / 2(1/10)

this doesnt work

@proven zephyr you there?

[proven zephyr]

nope

i was not

wdym it gives error

[timid silo]

x = (-1 +/- sqrt -1^2 - 4 (1/10) (1)) / 2(1/10)

it doesnt work

[proven zephyr]

why?

[timid silo]

because it's giving me an error

in the calculator

[proven zephyr]

did you put brackets on (-1)^2 ?

[timid silo]

yes

and no

i tried both

both give an error

[proven zephyr]

hmm

ok

move everything to the left side then

subtract (10^-1 x^2 - x+1) from the right side

hehe

[timid silo]

ok

no

i tried something

it works now

sqrt 15 -5

[proven zephyr]

hmm

i got 5 - sqrt 15 🙂

and 5 + sqrt15

[timid silo]

yes

thats one of the answers i gave

5 +/- sqrt 15

[proven zephyr]

yes

should be correct

[timid silo]

ok

thanks

.close

[obtuse pebble]

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[rigid pine]

Of course not, it's not to do with complex numbers. 😆

You've verified the base case but don't have a line for the case you're assuming to be true.

[timid silo]

so, where does the k come from, when you have been using n?

well thats actually not the main problem. So if you just plug k+1 into the sum without yet looking at the right side, what can you do first?

so the sum from i=1 to k+1

its a sum, so
1²+2²+3²+4²+...+k²+(k+1)²
how about we split the sum up:
now take the same sum, but just from i=1 to k, and then just add (k+1)² to that term

thats the general idea for these kinds of sum induction proofs

not quite, just ignore this right side for now, just look at the sum term

yeah, and now split it up like i said

this is the idea, can you see why this is true?

you can only assume that this formula holds for k, but not for k+1 (you want to prove it for k+1)

now you can try applying the formula, but the one for k

yeah, but so for we only looked at the left hand side

now look at this sum, what can you replace it with, using the formula for k

yeah, just the one from i=1 to k

yes

but this only works because its k, and not k+1, remember that

if you write out the left sum, its:
1²+2²+3²+4²+...+k²+(k+1)²
because the i goes from 1 to k+1

now i just took the last one, the (k+1)², and put it outside the big sum, then the i will just go from 1 to k

yes you got the right principle, but i think you copied the formula wrong

and then just try proving that this is in fact the bottom formula (its a bit tricky i must say)

i would just treat both of these as an equation and show that this equation is true

you could first of all divide both sides by (k+1) making it much easier

and then maybe expand both sides and youll see that they are equal

where does the - come from?

just referring to this part, if you would write them next to each other

[obtuse pebble]

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[prisma lintel]

Im having hard times on this question

(p(x) -> q(x) ∨ ~r(x) = ~p(x) ∨ q(x) ∨ ~r(x) = ~(p(x) ∧ q(x)) ∨ ~r(x) = (Cp(x) ∩ Cq(x)) U Cr(x)

I gor stuck on the last part what i need to do with the values Vp,Vq,Vr?

How do i apply them in the problem to get what the question wants?

[obtuse pebble]

@prisma lintel Has your question been resolved?

[oblique sage]

@prisma lintel you can ping helpers now if you want

[prisma lintel]

<@&286206848099549185>

[prisma lintel]

.close

[obtuse pebble]

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[worldly narwhal]

why did they multiply 5x^2-3 with 2?

[worldly narwhal]

im just learning this

and im unsure of why they picked 2 specifically to get -30x^2

[slow fulcrum]

wel

what is (x+y)^2

expand it

[worldly narwhal]

where did you get (x+y)^2?

[slow fulcrum]

well i'm just showing you when you expand

in this case it would be $(5x^2 - 3x)^2$

[warm shale]

dabbingpotato

[worldly narwhal]

yeah how did you get that?

in this video,

he multiples by 2

but i have no idea why

is it so that he gets -30 in the end/

like if i used a number like

3

i'd get something else

[slow fulcrum]

when you expand (x+y)^2 you get x^2 + 2xy + y^2

[worldly narwhal]

i'd get -45

right

but we are not using that method

[slow fulcrum]

why not?

[worldly narwhal]

that's substitituion

right

im using perfect squares

pattern

[slow fulcrum]

its the same lol

[worldly narwhal]

i'm on khan academy bro

[slow fulcrum]

yes i know

[worldly narwhal]

there's 3 diff ways they're teaching it

and i wanna learn the 3

ik u can just do that one

but they want me to learn this way for now

with perfect squares

u could also do gcf method

but im trying to learn this other one theyre teaching

[timid silo]

You can let x² to be t

[slow fulcrum]

wdym, you have to multiply by 2 regardless of that method you are using

[worldly narwhal]

is it always 2?

cuz i remember he said twice product something

[slow fulcrum]

yes its always 2

[timid silo]

And then divide the coefficient of t with 2

[worldly narwhal]

and that's how u know u did it right?

[slow fulcrum]

when you are doing (x+y)^2 its always going to be 2

[obtuse pebble]

@worldly narwhal Has your question been resolved?

[obtuse pebble]

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[stiff pawn]

Find a and b
If 2<x<3 then a<-4x<b

[viscid violet]

You should find the range of -4x on the first inequality.

[obtuse pebble]

@stiff pawn Has your question been resolved?

[obtuse pebble]

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[steady patrol]

hello

[steady patrol]

im basicly teachint a grade 10 student

and im grade 9

dont ask its a summer job

anyway

i have no idea how to do inequalities

although i have a pretty good idea of them

may you help?

[prisma lintel]

Are you studying functions?

[steady patrol]

no.

still

i have a good background on functions

but what does functions have to do with this?

also may we call

?

[prisma lintel]

Graphing problems. But inequalities are easy. You solve them almost the same as equations(The ones that do not have a denominator), you just need to follow some basic properties and determine the values that will satisfy

Let's get example number 3

I can't see the picture

It's blured

[steady patrol]

shit

wait

its the compressor thingy

is it good now?

[prisma lintel]

yeah

[steady patrol]

question 16 btw

not 17

can we call?

[prisma lintel]

I can't rn

[steady patrol]

ok

so

what do i do now

i literally have no clue how to start lmfao

[prisma lintel]

Ill teach you how to do it and then you peform

[steady patrol]

ok

[prisma lintel]

Alright, think inequalities mathematical operations how does not accept all values, it's usefull when you want to find values that need to fit in a condition,

Let's get a inequalitie 2x+3 > x+1

So here is a very simple example, You want to find values of "x," that if replaced will validade the sentence

To solve that you need to isolate the x since is the value you want to find out so let's solve it

[steady patrol]

ye but we got 2 variables in the equation i have

[prisma lintel]

We will get there

You can't peform two variable inequalities if you don't know the basics

Ill teach you just hold on

[steady patrol]

i know the basics dude

[prisma lintel]

...

[steady patrol]

i said i know how to do inequalities just i dont know how to do 2 variables

ok sorry

finish

[prisma lintel]

Im confused

Do you know or not?

[steady patrol]

i know the basics

like this

[steady patrol]

.

idk how to solve the 2 variables one

[prisma lintel]

You know rules like "Multiplying a inequation per minus make the sign turn around"

[prisma lintel]

In two variable like that you need to isolate the Y

[steady patrol]

yeah

[prisma lintel]

That's why i asked you if you know about functions

[steady patrol]

no

i know very little abt functions

can we pls call? itll be so much easier to under4

understand

[prisma lintel]

Ill give you a suggestion, you won't be able to advance

[steady patrol]

ok

[prisma lintel]

You need to learn function first

[steady patrol]

dude im just teaching it

i just need the answer to the question and how to do it yk

wait

what do they mean by

"unwanted regions"

in the question

[prisma lintel]

What is a unwanted region?

[steady patrol]

yeah

thats my question

[prisma lintel]

Is the regions that cover values the function can't assume

[steady patrol]

uh

ik i sound rlly dumb

but

idk what that means

[prisma lintel]

That's what im trying to tell you for over 5min now. First of all you need to study function before doin this question. Otherwise youll get confused like you are rn

Search about linear functions,

They are very easy to learn

[steady patrol]

like f(x) = 4x+9?

i know that

then u do

f(7) = 4(7) + 9

[prisma lintel]

Alright so do you know how to dra the graph of the wanted and unwanted regions?

[steady patrol]

i think

[steady patrol]

hell no

[prisma lintel]

Nvm, call me on dms ill teach you the basics

[steady patrol]

i think u gotta add me

i sent u a dm

[prisma lintel]

hold on

[steady patrol]

alright back

also

literlaly thank u so much

ik im rlly annoying

[obtuse pebble]

@steady patrol Has your question been resolved?

[obtuse pebble]

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[timid silo]

Yoo I have another dumb algebra question

[atomic hornet]

What is it?

[timid silo]

So say I have an associated matrix F to a linear transformation and the base of the images of the linear transformation

[rigid agate]

,rccw

[timid silo]

And I need to find whether a vector v = (-9,1,10) € the image space

I have issues understanding the solution for the 4938482 time

What is happening here

The linear application is R4 -> R3

[forest yacht]

if it's in the image, then it's the linear combination of the base

[timid silo]

I would have done it completely differently but it doesnt work

[timid silo]

Why? Im getting dumber and dumber and missing obvious stuff

Cant I like, use the images of the base I have inside F and make a system of equations, then finding x y z w, which would be the components whose image is v?

[forest yacht]

if a set of vectors are the bases of a vector space, then every vector in that vector space is a linear combination of the bases. That's what basis is right?

[forest yacht]

wdym by image of components?

[timid silo]

omfg

Im so dumb lmao

[timid silo]

Like I have the given vector v

The columns of F are the images of the base vectors right

So I could perhaps use those since v = x(baseVector1) + y (baseVector2)…

I think?

[forest yacht]

the image of the transformation/matrix is the set of base vectors

[forest yacht]

but this is correct

[timid silo]

So that should work as well?

Most likely I’ve calculated wrongly

I tend to overcomplicate solutions

[forest yacht]

I guess you want to solve the simultaneous equation by treating the coefficients as a matrix?

[forest yacht]

how about just show me your work?

[timid silo]

Ye the coefficients would like be the vector in R4 whose image is v

I mean x y z w

[timid silo]

Throw the paper But ill redo real quick

Oh wait

Yeah I made a mistake

I mean I think this works too

Like if I prove there exists a vector whose image is v through F, then v must € Im(F) right

But its so much more complicated ehh

[forest yacht]

yeah it should work, but (-1,0,1) and (0,3,3) are linear combination of (3,1,-2) and (2,1,-3)

so you don't need z and w

[timid silo]

Ohh I see

Okay yeah that makes sense

Poor me

Thanks 🙂

.close

[obtuse pebble]

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[forest yacht]

let h(2)=a, g(a)=b, then the aim is f(b)

[timid silo]

I'm confused

I think it's the last one

But I'm not sure

[forest yacht]

first, what is h(2)?

[timid silo]

2/x?

[forest yacht]

h(x)=1/x, so h(2)=1/2 right?

[timid silo]

Oh

Yeah

root 2x would be root 4x?

[forest yacht]

then the second layer, g(h(2))=g(1/2)=root(2*1/2) since g(x)=root(2x)

[timid silo]

Yeah

I'm not sure how I'd solve it

[forest yacht]

so g(1/2)=1

that is f(g(1/2))=f(1)

[timid silo]

Yes

Yeah

So do we just solve for f(1)?

[forest yacht]

that's right

[timid silo]

So f = 0?

[forest yacht]

yeah

[timid silo]

So, 0 would be the final answer, correct?

[forest yacht]

yes

[timid silo]

Great, tysm!

.close

[obtuse pebble]

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[urban otter]

https://cdn.discordapp.com/attachments/486566132665286666/1011705258495455343/unknown.png

[urban otter]

im being asked which asymptotes the function has, the vertical asymptotes were pretty self explanatory, but im not sure how to find the slant asymptote of a function like this

(the answer is D)

oh cauchy's formulas, right

.close

[obtuse pebble]

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[celest mantle]

Help

[timid silo]

yea?

[celest mantle]

its sending

[uneven palm]

[vale prawn]

What's the probability that any new calculator will not be faulty?

[celest mantle]

idk would it be .63

[vale prawn]

So now you should be able to fill in the blanks

[celest mantle]

oh i didnt know it was that easy

[vale prawn]

And you seem to understand how to multiply the probabilities together

Yeah! lol

[celest mantle]

so wait for the 2nd question would u add everything except 0.63 x 0.63

[vale prawn]

What do you mean "add everything?"

OH I read that wrong!

[celest mantle]

so like .37 x .63x .37 .37 + .63 x 0.37?

[vale prawn]

Well it's asking for both calculators to not be faulty

(.37*.37) is the chance for both to be faulty

[celest mantle]

ohh i read the nf as faulty

ye i meant would i add everythingh except .37 x .37

[vale prawn]

And in fact, think about it this way

You've already calculated the chance for 2 to be faulty

So what's NOT that probability?

[celest mantle]

so .37x.63 + .63 x .37 x .63 x .63

[vale prawn]

Yeah

[celest mantle]

is it like 0.325 continuing

[fickle turret]

Or just 1- P ("two faulty")

[celest mantle]

i never got tho why youd add 1 - p i dont get that

[vale prawn]

1 is 100%. You will always get a calculator that is either faulty or not

[celest mantle]

ye

[vale prawn]

And you've gotten the chance to get 2 faultys

[celest mantle]

ye

[vale prawn]

Everything else is 100% - P

[celest mantle]

whats P

[fickle turret]

Probability

[celest mantle]

ye but so does it not have a number

like a value

[fickle turret]

P is the number you calculated in a)

[celest mantle]

so what 1-(.37x.37)

[fickle turret]

Yes

[celest mantle]

but that gives me like 0.8

0.8....

[vale prawn]

Yeah, try calculating this again

[celest mantle]

aight wait

[vale prawn]

You may have entered something wrong

[fickle turret]

Leave out the may

[celest mantle]

i still get .3256....

[vale prawn]

Are you using parentheses

[fickle turret]

0.6*0.6>0.32

[celest mantle]

where would i need to use parentheses

[celest mantle]

on this

[vale prawn]

(.37 * .63) + (.37 * .63) + (.63 * .63)

[celest mantle]

i never had the second plus

[vale prawn]

That would be it

[celest mantle]

why would there be a 2nd one

[vale prawn]

Well you're adding up 3 events

Namely, the three events that aren't 2*faulty

[celest mantle]

oh so it wouldve been 4 if we added the faulty ones?

like there are 4 total?

[vale prawn]

Yeah, if you draw 2 calculators, there will be 4 possible outcomes

[celest mantle]

ye

[vale prawn]

Both faulty, neither faulty, first faulty, second faulty

We know the chances for each

[celest mantle]

ye

[vale prawn]

We want to add all probabilities that aren't "both faulty"

[celest mantle]

oh i think i get it

aight ima try C

is it .4662

[vale prawn]

Yep!

[celest mantle]

and last one D is .3969

[vale prawn]

Correct!

[celest mantle]

oh ok cool ty

ill send the other page so long but i dont think i need help

would the answers be A is 0.0324 B is 0.6724 and C is 0.2952

[vale prawn]

Yep!

[celest mantle]

my last page

is it right

[vale prawn]

Where'd you get 5/18?

[celest mantle]

1/6 x 5/6 + 5/6 x 1/6

oh wait

its just 5/36

?

[vale prawn]

Yeah

[celest mantle]

ok cool man ty for the help bro

.close

[obtuse pebble]

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[obtuse pebble]

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[timid silo]

Could anyone tell me what the 3/2 means

[timid silo]

In y=3sin3/2x

[nocturne minnow]

The value to help find period

[timid silo]

Perfect thanks man!

[obtuse pebble]

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[dull thicket]

does anybody know how to fix this?

[dull thicket]

i was trying to make a boxplot

[obtuse pebble]

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[dull thicket]

<@&286206848099549185>

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[proven zephyr]

i think the question means factored in the form of
ax^2 + bx + c
(ax + p)(ax +q)/a
pq = ac
p + q = b

find all possible numbers for pq

which is just factors of ac

which is just -6

the factors added together is a possible integer for p

[obtuse pebble]

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[timid silo]

how do i get the value of the angle?

[timid silo]

this is the first way i’ve tried it but im unsure

[proven zephyr]

have you learned the sine rule?

and maybe dont turn the square roots to decimals

[timid silo]

i don’t recall

[proven zephyr]

hmmm

we know that DCB is a 45 45 90 triangle

yeah idk

nvm

[timid silo]

🥲

[timid silo]

i see

[obtuse pebble]

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[eager knot]

I don't know how to solve a limit if it has two functions in the middle of it

[violet sentinel]

hi there

[eager knot]

hello mr. llama

[violet sentinel]

there are some rules with limits

one moment

take a look at the constant multiple law and the difference law

those are your keys 🙂

[eager knot]

should I have these memorized for calc1?

or is it supposed to be intuitive

[violet sentinel]

it's good to know for sure!

they're not too hard

Taking time to understand these will make your life easier with limits for sure

[eager knot]

thank you

[violet sentinel]

yep for sure!

[eager knot]

I'll try to solve it with those

[violet sentinel]

cool

get back to me w/ what you think the answer is 🙂

[obtuse pebble]

@eager knot Has your question been resolved?

[eager knot]

this is gonna take me a long time
gonna try on my own for a whiel

.close

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[nocturne trail]

Hi um i have a question on how to find the x intercept of the parabola of x^2-5x+3

[mint tendon]

thats basically the roots

[nocturne trail]

um what is the roots sorry im new to quad eqations

[devout sable]

It basically means find where your given expression =0

[nocturne trail]

i have 0=x^2-5x+3

[violet sentinel]

yep good start!

now is x^2-5x+3 factorable?

[nocturne trail]

no

[violet sentinel]

good

so what's our next option?

what tool can we use?

[nocturne trail]

uh make it {(x-5/2)^2 - 25/4 }+ 3

im not sure really

[violet sentinel]

quadratic formula 🙂

do you know it?

[nocturne trail]

uh yeah

[pliant dragon]

I need help I just got a cas graphing calculator and wanted to know when I can find a good e-text book for Website that’s gives me so graphs go dry and some activity’s to do with cas can anyone help me

[violet sentinel]

@pliant dragon this channel is occupied. Please visit #❓how-to-get-help

@nocturne trail the quadratic equation will tell us our roots

[nocturne trail]

so the eqution is -5 +/- (square root)13 ?

[violet sentinel]

all over 2a 🙂

don't forget that

[nocturne trail]

oh yeah

so

how do i ge x intercept from that

btw i have to get 2 x intercepts

oh wait

ooooooooooo

[violet sentinel]

lol there ya go!

looks correct to me 🙂

[nocturne trail]

thanks man

your a life saer

[violet sentinel]

yep np

[nocturne trail]

have a good day

[violet sentinel]

you too!

@nocturne trail if you don't mind, can you type .close to close the channel so someone else can use it? 🙂

[nocturne trail]

oh my bad

.close

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[teal creek]

hi what would u equal and what would be the reasoning behind it?

[teal creek]

<@&286206848099549185>

[oblique sage]

Hi so your first step is to read the rules 👍🏻

!15min

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[teal creek]

sorry

im sorry

i wont do it again

could someone please still help me with my question?

[oblique sage]

Be patient

[storm rampart]

Rip

[teal creek]

wdym by rip

what would u equal and what would the reasoning be for it?

[rancid lance]

u is 24 because in rhombus *diagonals are angle bisectors *

[teal creek]

so it would be

u = 24(diagonals of a rhombus bisect angles)

?

[rancid lance]

yes

[teal creek]

ok thank you

.close

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[stark pike]

hi, may i ask how do i solve for this $a(x+p)^2$

[warm shale]

leewchaha

[stark pike]

Do i have to multiply the a into (x+p)^2 or do i do (x+p)^2 first then multiply a. Or does doing any of this make a difference

[versed cave]

what do you mean by "solve"? That's an expression, did you mean to write an equation? Are you solving for x?

[stark pike]

"expand it" if thats the correct word to use

[versed cave]

Oh ok!

Remeber the order of operations

exponents come before multiplication

[stark pike]

oh i see

[versed cave]

So, first expand (x + p)², and then multiply what you get by a

[stark pike]

oh PEMDAS, i remember now

thanks alot!

[versed cave]

[stark pike]

have a nice dayy

.close

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[stark pike]

May i know how do I divide $7x/5 by 2$

[warm shale]

leewchaha

[stark pike]

what i know is that i have to change it into this. 7x/5 * 1/2

then i proceed to change the denominator

so it goes something like this 14x/10 * 5/10

then i have no idea how i should continue

or if im doing all of this correct at all

[versed cave]

For multiplications between fractions multiply the numerators and the denominators

$\frac a b \cdot \frac c d = \frac{ac}{bd}$

[wild swallow]

how do you divide 7/5 by 2

[warm shale]

Nonna

[versed cave]

You might be confusing this from sum and subtraction of fractions, where the denominators must be the same?

[stark pike]

7/5 * 1/2 = 14/10 * 5/10 no?

[stark pike]

oh

OH

im so sorry

[wild swallow]

^what Nonna said

[stark pike]

got it

[versed cave]

haha that's ok, you don't have to be sorry

[stark pike]

thanks alot !

its been months since ive did maths, trying to pick it back up since im starting my college

[versed cave]

Nice, gl!

[stark pike]

thanks !

[wild swallow]

everyone starts from somewhere

gl

[stark pike]

thank you~

[obtuse pebble]

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[wet saddle]

is my answer right for this question?

[obtuse pebble]

@wet saddle Has your question been resolved?

[wet saddle]

<@&286206848099549185>

[obtuse pebble]

@wet saddle Has your question been resolved?

[wet saddle]

<@&286206848099549185>

is my answer right for this question?

<@&286206848099549185>

[wet saddle]

<@&286206848099549185>

[wet saddle]

<@&286206848099549185>

<@&286206848099549185> pls man i been waiting for 2 hours

[wet saddle]

<@&286206848099549185>

3 hours now

[elfin kite]

lmao

[wet saddle]

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[upbeat yacht]

Can a Vector Space be always divided in sub eigenspaces*? (I hope I'm using the terminology correctly)

[upbeat yacht]

Because at first glance I would say no, since that would mean that every vector can become an eigenvector with the right eigenvalue (except for the Zero vector of course)

[kind hawk]

in general no

for some matrices you can write the vector space as a sum of the eigenspaces but in general you can't

in fact you can do it if the matrix is diagonalizable

[upbeat yacht]

Oooh ok, thank you a lot

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[night egret]

i got a final percent of 99.492

would that be 99.5 percentile?

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[vestal surge]

Hello, could I ask how you would go about finding the quartiles from a bar chart?

[vestal surge]

Would I list the frequencies in ascending order and do it that way?

Also how would I find the minimum and maximum value from a histogram (with frequency density on the y axis against class width on the x axis)

[vale prawn]

Quartiles are just as they sound; they split the count into 4 equal "piles." Just find out your total count, divide by four, and start taking from the bottom until you reach that number, then continue

[vestal surge]

So in a question such as this

Sum is 35

35/4 is 8.75

So lower quartile seems to be between 1 and 2

I’m not sure I understand exactly

I know what you mean by dividing by 4 and then adding up and I could do that but if it was with ranges

Then I could do interpolation or something

But here I’m not sure what to do

<@&286206848099549185>

[obtuse pebble]

@vestal surge Has your question been resolved?

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@vestal surge Has your question been resolved?

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[violet sentinel]

Hi there! I just need a second pair of eyes to tell me if this makes logical sense and the proof is sound:

[violet sentinel]

also I just saw a typo so ignore that lol

[wary vigil]

i don't understand why being coprime means that you can write it as ax + by = 1

[brave bramble]

If gcd(a,b) = 1, there exists an x,y in Z such that ax + by = 1

Which, you might be saying haha. Up to you how you want to use the language

Otherwise it looks good

[violet sentinel]

Thanks for the tip, I'll add it 🙂

[violet sentinel]

It's just in the definition of gcd

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[weak hamlet]

How do you add parallel vectors in opposite directions?

[timid silo]

wdym how do you add? can you show the specific problem if you have one?

[weak hamlet]

That's the question "How do you add parallel vectors in opposite directions?"

Google isn't being straight and we don't even have a teacher

[timid silo]

that's incredibly vague

not sure what the question wants but might the answer just be "adding their components x with each other and their components y with each other"

[weak hamlet]

I'll just put that, it's just a sub using stuff on TPT

ty

[obtuse pebble]

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[sour verge]

can i say x^(3/2) = (1/x)^(-2/3) ?

[nocturne minnow]

No

[sour verge]

i want to make the power 2/3

actually

i think i got the reciprocal power wrong

any idea how i can simplify (x^(3/2))*((-1/x)^(2/3))

?

actually doing somehing like

[versed cave]

not -2/3

x^(3/2)= (1/x)^(-3/2)

What's the problem you are trying to solve? what's the original question?

[sour verge]

actually this is part of the answer

i was trying to solve dy/dx = (x+y)/2y

[versed cave]

What do you mean by "solve"?

[sour verge]

find solution

of the de

don't worry it isn't a self made question 😅

[versed cave]

I don't know how DEs work, but I can help you if all you need is to simplify that

$x^{\frac 3 2} \cdot \left(-\frac 1 x\right)^{\frac 2 3}$

[warm shale]

Nonna

[versed cave]

Is this what you need to simplify?

[sour verge]

ya

can't i be further simplified ?

or i can raise power by 6 on both the sides of my equation i am getting

[versed cave]

This can be simplified

$x^{\frac 3 2} \cdot \sqrt[3]{\left(-\frac 1 x\right)^2}$

[warm shale]

Nonna

[versed cave]

Do you agree that this is the same thing yes?

[sour verge]

yes

[versed cave]

Since that -1/x is squared, we can ignore that - sign

[sour verge]

sorry i will continue this later actually i gotta go

[obtuse pebble]

@sour verge Has your question been resolved?

[sour verge]

thanks for the help 🙂

[versed cave]

$x^{\frac 3 2} \cdot \left(\frac 1 x\right)^{\frac 2 3}$

[warm shale]

Nonna

[versed cave]

I didn't really help ahah

[sour verge]

np

atleast you gave your time

[versed cave]

But to continue you can set the exponent of the fraction to -2/3 and flip the fraction, then you have the same base and you can sum the exponents, and you are done

[sour verge]

i think this can work

thanks

[versed cave]

Bye!

[sour verge]

bye have a great day

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[late flax]

how do I get the y-intercept

<@&286206848099549185>

[slow fulcrum]

you can get y intercept when x is 0

plug 0 in for

x

,rotate

[late flax]

I only have 2 numbers tho

70x and 7.7 y

@slow fulcrum

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[timid silo]

Someone help me with this problem

[obtuse pebble]

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[proven zephyr]

@timid silo

[proven zephyr]

example

[warm shale]

help

[proven zephyr]

what can i do with this

[stable rain]

(a+b)^2=a^2+2ab+b^2
let a^2+b^2=7
let 2ab=2sqrt12
ab=sqrt12
a=sqrt4, b=sqrt3
sqrt(7-2sqrt(12))=sqrt((sqrt4+sqrt3)^2)=sqrt4+sqrt3

god it looks bad sry idk latex

i shld learn it

[proven zephyr]

yeah, you should

[versed cave]

There's a great cheatsheet in #resources

[stable rain]

got it?

[stable rain]

woo cool ty

[nocturne minnow]

I just google it

[stable rain]

like google integration latex? or whatevers relavent?

[nocturne minnow]

Things that are relevant. Like if I need to make a fraction, as an example, I would google, "latex fraction" and one of the first results, is this

So $\frac{12}{37}$

[warm shale]

dldh06

[proven zephyr]

,,\sqrt{7-2\sqrt{12}}=\sqrt{(\sqrt{4}+\sqrt{3})^2)}= \sqrt{4}+\sqrt{3}

[nocturne minnow]

Use curly braces for sqrt

$\sqrt{7-2\sqrt{12}}=\sqrt{(\sqrt{4}+\sqrt{3})^2}= \sqrt{4}+\sqrt{3}$

[warm shale]

help

dldh06

[proven zephyr]

ok ok

ohh hok

ok ok

i get it

owo

ty

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[smoky zenith]

How did they get from 2(x+h)^2 to 2(x^2+xh+h^2)
?

[nocturne minnow]

Do you know how to do (x + 2)^2?

[smoky zenith]

(x+2)(x+2)?

[obsidian isle]

Can you expand?

[nocturne minnow]

Do you know how to FOIL/distribute?

[smoky zenith]

yes

so you distribute 2 then foil?

if i could only just see the work behind this equation, i think i could get the concept

i just need the paper work for the simplification from 2(x+h)^2 to 2(x^2+2xh+h^2) and i think i could get the concept

[warm canopy]

Just foil (x+h)(x+h)

[smoky zenith]

i mean, i find it better when i can see the paper work so i can find the pattern/work flow through the numbers and just duplicate it,
i mean thats how i learned math and it worked so far so..

[obtuse pebble]

@smoky zenith Has your question been resolved?

[obtuse pebble]

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[bold wren]

would 1 be the correct answer for this?

[limber mason]

plot them on desmos or something

then apply restrictions

[fierce lagoon]

Set the denominators of each partition equal to 0, solve for x

And then plug in 3 into both partitions and check to see if the upper partition equals the lower partition

[limber mason]

oh yeah if you work it out with calculator, try to find the assmptotes

[bold wren]

Ah okay

Thank you

[fierce lagoon]

Not just asymptotes

The limit has to exist at x = 3 and f(3) has to equal that limit

[limber mason]

that's the next part, but finding assymptotes should be the first step

[obtuse pebble]

@bold wren Has your question been resolved?

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[hasty sandal]

The 5th term in an arithmatic sequence is 2 and the 23rd is 54. What is the 29th?

[vale prawn]

Well, do you know what an "arithmetic" sequence is?

[hasty sandal]

Mhm

its a sequence with a constant difference, right?

[vale prawn]

Correct!

[hasty sandal]

ooo ok- thanks!

for the difference I got 26/9, im just not sure how to turn it into an equation

[vale prawn]

Is it necessary to be an equation?

[hasty sandal]

ohh wait I don't think so

but i need to find the starting term

to plug it in and find the value, i think?

The answer is supposed to be 214/3, im just not sure how to get there

im not sure how they got this equation

ohh wait- I think i understand now, sorry!

[vale prawn]

Ope, ok!

[hasty sandal]

im still not sure how to find the first term, but i think it works without it?

[vale prawn]

Probably not always necessary to know t1

[hasty sandal]

oo ok- tysm!

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[obtuse pebble]

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[red raft]

hello anyone can explain how it is 13.4? I have tried the constant acceleration formula in where V_0 is missing but i yet dont get it.

[nocturne minnow]

Post your work

[red raft]

I gave up at the end, but my work is just messy, sorry about that.

[nocturne minnow]

My suggestion, use the 3rd equation

[red raft]

I don't seem to get it

[nocturne minnow]

Vf^2

[red raft]

Ohhhh

Is this the correct set up?

[nocturne minnow]

Yes

[red raft]

where did i mess up

i know i have to get 13.4 m/s

[nocturne minnow]

slows at a rate of 20 m/s^2

What sign is slowing down?

[red raft]

negativr

?

[nocturne minnow]

Yes

[red raft]

ooooooHHHHHHHHHHHHHHHHH

I DID IT

god i have to pay attention on the wording

also how did you know to use that formula

[nocturne minnow]

Well, I looked up kinematic equations because I forgot them, and based on the given info, it gave acceleration, distance, v0 (initial velocity) and the 10 m/s, which I could have assumed as some number, but with those 3 given numbers, the only equation that fit was that one

[red raft]

did you know the initial velocity because it said that it was the same as initially?

[nocturne minnow]

Wait

[red raft]

I dont think it gave the initial velocity... thats what we were looking for. I assumed it was 10 m/s from the start and got it wrong

[nocturne minnow]

The initial velocity is what you're finding

Because $v_0$ is notation for initial velocity

[warm shale]

dldh06

[red raft]

Am I confusing your wording here, when you mentioned that it "it gave acceleration, distance,v0 and 10 m/s

i assumed you meant like it gave it to you off the bat lol

[nocturne minnow]

So what I'm saying is, the question for sure gave the terms v0, acceleration, and distance, but it didn't mention vf, so that was still in the air. Because I knew v0, acceleration, and distance were the only variables involved, it only left that equation

Yes, there are other equations that has v0, vf, acceleration, but those also have time involved which was not given

[red raft]

so you just said that it didn't mention final velocity but for me, it did because it said that it was 10m/s in the same direction as initially. so for me, this is the final velocity. Am I getting the V0 confused with VF?

Sorry for the dumb questions

[nocturne minnow]

I'm saying it didn't directly say the term "final velocity"

All the other terms were directly stated

[obtuse pebble]

@red raft Has your question been resolved?

[red raft]

ohhh ok

thanks

[obtuse pebble]

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[winged aspen]

What I would do first is find the total time for it to reach the ground.

Then find final velocity when t= total time-1.2

[winged aspen]

Subbing 1.2 into the formula means that’s its velocity after 1.2 seconds has passed. Not 1.2 seconds left in the fall.

[red raft]

Okay let me do that and I'll get back to you.

What formula should I use. I'm thinking of using t= (v-v0)/a

Derived from thus

[winged aspen]

Do you know the SUVAT formulas?

[red raft]

I don't know what SUVAT means but if you are talking about the ones the text book gives me, like these?

[winged aspen]

These are formulas for constant acceleration

[red raft]

i know i have distance so i might need to use (x-x0)

[winged aspen]

Yeah it’s the same formulas

Just different variables

So use your second formula to find total time

Then use your 1st formula to find final velocity at (total time-1.92)

[red raft]

Thank you I will do that rn and I'll get back to you with my work.

[obtuse pebble]

@red raft Has your question been resolved?

[red raft]

This is what I got . .

[winged aspen]

Velocity can be negative

Cause your taking upwards as positive. Which is why your acceleration is negative

[red raft]

Acceleration is negative because it's going down?

[winged aspen]

yeah cause its accelerating down

So is your velocity cause its moving down

[red raft]

So is it correct?

[winged aspen]

yeah seems fine

[red raft]

When it asks how fast it's going does it want speed or velocity

[winged aspen]

speed

[red raft]

So it's positive

[winged aspen]

yes

[red raft]

So no sign

Kk

Hell yeah thanks sorry it took forever I appreciate you.

[winged aspen]

[red raft]

Let the cats live forever

.close

[obtuse pebble]

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[copper slate]

Apologies for the improvised drawing, but how do you find the percentage within this area? (Standard deviation)

[copper slate]

To simplify it into words,

I need to find the percentage of everything to the left of standard deviation of -3

[plain stag]

If you have access to software, it's a simple numeric integral

It's a common enough calculation that there exist tables that give you the area to the left of a certain point

[obtuse pebble]

@copper slate Has your question been resolved?

[copper slate]

Is it possible to solve only knowing the mean, the standard deviation and a singular value?

[limber mason]

yes

[copper slate]

may you walk me through it, if possible?

[limber mason]

first, think about what the standard deviation is

like, what does it really show or tell you

[copper slate]

well, to add-on, we were not provided with any z table, if that changes anything

The info is:
Mean: 27
Standard deviation: 7

[limber mason]

you have the mean and an x value to plug in equations

[copper slate]

So, if I did

z = (13-7)/27

which is 0.22 repeating,

[limber mason]

ok, first define what you want to solve first

[copper slate]

need to find everything in this area

everything to the left of standard deviation -2

-2, sorry

[limber mason]

yes, and what "units" or thing, would this answer be

like, a numeric value? a percentage? a ratio?

[copper slate]

percentage

what percentage of the standard distribution bell curve

resides within the shaded area

[limber mason]

yep, you know how the first SD of the left and right makes up 50% right?

[copper slate]

ye

well 68% or whatever

[limber mason]

wait, I need some refreshing

yes

68%

now, half of that is to the right side

if you want the 2nd S.D of both left and right, what would it be?