#serious-discussion
1 messages · Page 347 of 1
oh yo same, except I eat it with the soil!
Likeeee
Margherita pizza is so bomb though

hot sauce in d 🥀
actually i agree
On pizza is nuts
YES look at the other stuff
margeritta pizza is the goat
idk i ain a chef i js thought its a food tier list
at least I agree with the SSS picks
I have a billion food tierlists
pesto is goated
ngl tomatoes could be a bit higher
@deep mango nice hs chem test btw
ugh im so full i cant think about food rn
im def getting blocked
@timid bronze im gonna do this
hol up imma also do it cus why not
when do I stop becoming a peasant and underling and I can post images?
icl zohrans fake smile creeps me out
This is super thorough
he has a very "hello fellow kids" media presence
who does?
zohran
nyc mayor
he looks goofy
Welcome to politicians
use a knife
Youve never cut pizza with scissors
??
not all politicians do this, some of them just aura farm
nope
I cut pizza with scissors
dude
Woah. Wild
Who cuts PIZZA with SCISSORS like PAPER
like trump?
Kitchen scissors
still using a knife is better
trump doesnt aura farm. except for when he got shot i guess
more accuracy
that's what I was referring to, other times hes just a goober
yeah
goat cheese on pizza?!
its popular
interesting
I should have said that I'm afraid of everyone here
boo
😱
Its great...
WHAT
everyone is scary
@deep mango
Ong
W H A T
I don't like melted cheese for the most part
😱 scary image
Tbf a lot of these Italian foods I can't try cz of pork
Tiramisu #1 yep
I can't stand most cheap cheeses tbh
AMERICAN CHEESE
the fuck
I MEAN. LIKE LIQUID CHEESE
Never tried
oh yeah ew
MELTED CHEESE IN PASTA CAN BE GOOD
its just melty, thats all
im just saying melted cheese is better than the alternative
True
but very cheap and is synthetic
sliced cheese is revolting
Depends on the cheese
no.
I just cannot stand cold cheese (the block or preshredded bs)
WYM
lasaga
lasagna is literally just a fattener, nothing else
any other pasta is better
I've tried lasgna but not lasgna soup yet
Type shit
pesto is literally the jack of all trades of pasta
its good at everything
this is good 👍
Albondigas is also a soup I wanna try but
A lot of places make it with pork 😭
I for whatever reason don't get the obssession of miku and teto, I have no idea why
So I have to make tht myself too
albondiga to me isn't a soup 
Oh rlly
it's the spanish word for meatballs
Spaghetti all'assassina is my favorite type of pasta tho
Sorry if I was spreading misinformation
I WANNA TRY IT
BUT I haven't yet
I hope it impresses me
im feeling sleepy
you can't burn it so it will never ever taste bad
Sleep
GONNA FUCK UP HIS SLEEP SCHEDULE
Oops didnt mean for caps to be on
well this looks odd
what does "chovying" mean
no i must resist
Idk what TZ they are in but I assume everyone in the US is in EST 😭
indeed
Sleeping at 8 pm nawt baddd
anyway thanks
no worries
that would be a long hug
Lmaoooo
True
I hate it when I'm having a nightmare or dream tht I wanna finish but then I get rudely interrupted
Like last night I had a bad fucking unfinished nightmare
Erm, what?
But then I got interrupted by the cold air ;-;
reze arc was so good
I didn't even see that 😭
How do you even milk hoaxes?
aki is my favorite character now
yes
ME TOO
Me too*
everyone is scary here, Idk why
like aki is lowkey kinda weak and thats what makes him cool
Am I scary
sort of
i used to say like this too and im used to it now
._.
I'm not :3
Eventually you'll be the horror too
oh you are the complete opposite of what you think you are, your parents should've tought you better
Am I scary >~<
aki is the only responsible adult in part 1
actually not too much
Yay
ur cool
also he’s so real
suremark is lowkey really scary
ur kinda scary
He gets angry very easily
this is very wrong
suremark has the patience of a saint
And he's rude to kids
scary immediately
Nuh uh
roar
You need to see how mean he is to amukh and Arti
you need to see how much of chipotles bs he puts up with
I don't trust you, you keep watching me
Ok true
idk if its you, you aren't half bad
Trying to decipher wtf this means
👁️ 👄 👁️
bunker made me ragequit from life
take your time
real
SEE
I don't get it button
its an alberti cypher, you just have to get the right key to solve it
they should make more pills bubblegum pink
for short
i made the sensible decision and left bunker 
and other fun colors
you are very scary to me
i just lurk bunker
have you seen his math? anyone would be scared
Same 😭 I think I only stayed there for like 2 months
whose math?
Then was like nope
real and true
deltoid
that's been happening more frequently to me lately for some odd reason 
oh send it thru dms if you want
Nooo
both getting more nightmares and getting them interrupted
just wait a few minutes hes probably gonna post some here
alright
higher! is not scary
ur the opposite of scary
Higher is definitely scary though
"Higher" gives doxxer vibes
Me when mango (epic)
We're just saying words
I hope they don't pin the message I sent
higher is chill
I am not just saying words!
Higher is always watching 👁️
Then what else are you doing
Keep higher!
higher! is goated
Nothing? 😭 I was just making a joke between variations of his user
BOOT = ING = higher
unless if you’re a seal 
I'll make sure to stop doing my homework
it's alright 
I hope your nightmares aren't the product of stressors within your life right now :c
. . .
im shocked i still haven’t gotten vactive back yet
wait lemme check something
you can get it back right now if you pay me ten dollars 
@latent edge They want to hear about your math
Have a 5h energy instead like a true red-blooded patriot
stop?
oii, do your homework 
;-; Fuck physics hw
WHY THE F**K IS MICHEAL JACKSON LYRICS GOING ON IN THE CHAT WHILE IM PLAYING RAINBOW SIX SEIGE
i will pay u -100000 dollars to get it back
physics is peak
Prepare for a number theory lesson with your instructor nDeltoid
(It was too difficult I couldn't grasp)
I already learned the entirety of number theory for competition math
nothing too hard will happen
Oo
okay yeah im technically not supposed to be telling you this but youre blacklisted from vactive for the time being because the bot thinks youre a bot. its a new feature that we're testing out where the bot is trained to detect suspicious activity and prevents certain accounts from getting active. since the rule for going from no role to active is the same rule for going from emeritus to very active, it applies to members like you too. ill probably get around to making a pull request adjusting its behavior for emeritus members soon.
I meant Oo
Nws
did u just call me a bot
You are a bot
i didnt, the bot did
what 😭
r u pulling my leg
you can check #『bot-and-website』 for the relevant logs
tfw
Bot looking aahh Roblox avatar egg head
Wait you're dead ass?
I thougth you were jk'ing 😭
whats L
(no but i bet suremark will be scrolling through that channel for a while now 😹)
A finite extension field of Q_l
like does the bot detect it if you are spamming a bunch of the same message
im going to kill u
i still havent at all gotten to look at adic stuffs 
it does but it just bans you, it doesnt blacklist you from active or anything lol
Calm down unc
ok then dw let me delete
i was scrolling for like 5 minutes bro
i see
LMFAOO
LMFAO
LMFAO
Do you know how to relate a number field with its character?
I'm so glad Super Matroid doesn't know who I rly am
u just don’t appreciate art
no and im way too sleepy to try rn 😭
isn't that the egg for the hunt event?
No, I'm talking about this
real
I see it
Essentially what you do is use Kronecker Weber
is that... nvm
what’s writing with that
wrong*
Well I forgot to say (abelian) number fields over Q
stupid autocorrect
In general it's not so easy
Looks like an egg
Do I need to set you up a spherical integral
its a sphere…
rn I'm just sitting in the event stage doing literally nothing lol
Still looking like an egg
this is a powerful egg phobia
that’s a topological egg 
true
Every abelian number field over Q can be seen in a cyclotomic extension
I'm just bored @timid bronze
Then the next step is the isomorphism between the Galois group of the cyclotomic extension and (Z/mZ)^x
from there you can consider characters from (Z/mZ)^x -> C^x
Now from the theorem above you essentially identify the abelian extensions with some subgroup of this guy
For example take Q(zeta_8)/Q
consider the character given by chi(1)=1, chi(3)=-1,chi(5)=-1 and finally chi(7)=1
Then you look at the kernel of such a character
In this case it's {1,7}
Now you look at the fixed field of this
7 corresponds to sigma_7 which is complex conjugation
This tells you that the field is real
where's mi ipad
and quadratic
NO where's mi ipad
Learn math with him it's interesting
since phi(8)/2 = 4/2 = 2
With some effort you can check that the field is Q(sqrt(2))
lovely
yeah that's field theory and some fancy character theory so far
okay now you might ask where is the number theory
Okay so a classic question you can ask given a number field K is classify its primes
Given a prime p over Q how does it change when you look at this number field K over Q
thats the class number thing right 
uhh what do you mean by this
class numbers tell you if the ring of integer is UFD or not
it could break into several prime ideals.
measures the failure of UFDness
Right yeah but how do you pinpoint that exactly
oh ok so no then
The idea the original isomorphism we had earlier
Galois group of zeta_n over Q
the isomorphism is given by sigma_k: zeta_n -> zeta^k_n right
Factor f(x) modulo p in Fp[x] is what I do
assuming
you have to elaborate on that
where in K=Q(a), a has minimal polynomial f(x) that is an element of Z[x]
not exactly
I see... what was my issue?
the issue is you don't know the ring of integer beforehand
so this might tell you false info when you take modulo p
Good thing is it works for almost all primes
I see, it only works for most primes, those dividing the discriminant.
yup
but what I'm showing is another way to get the same info
Let's take an easier example for demonstration
Take Q(zeta_4)/Q = Q(i)/Q
From earlier discussion this has Galois group isomorphic to (Z/4Z)^x
mmhmm
okay now let's look at Dirichlet characters
(Z/4Z)^x has 2 elements so we should also expect 2 characters
One of which is the trivial character and the other is quadratic in nature
Given by chi(1)=1, chi(3)=-1
yep
Yeah now the golden key is realizing that from the isomorphism you can relate Frob_p in Gal(Q(i)/Q) with p
so chi(Frob_p) = chi(p) for unramified p
OHHH
now we look back
for primes p = 1 mod 4
plug in the formula
you get chi(Frob_p) = ?
chi(Frob_p) = 1?
P splits in Q(i)
-1?
yeah and what does that correspond to?
p is inert in Q(i)
:)
you can check this one is ramified
but remember this thing only works when p is unramified
as its not coprime with 4
there's also a result to keep in mind if you get chi(p)=0 this tells you that p is unramified
and sure enough 2 is not coprime with 4 as you mentioned so there we have it
yeah you can do similar things with more complicated examples as long as you are working over Q and your number field is abelian
If your number field is not abelian then you forget about it
You need more machinery to handle these
does a laptop do?
No I mean math tools
i quite do
Just any arbitrary number field K and keeping stuff abelian
yeah for this the answer is not far off from the story over Q
yeah but it requires more care to get the right arithmetic object
Essentially you want to play the same game. Over Q we had (Z/mZ)^x and so the task is to somehow generalize this group
So that it works for our needs
I will not get into the details cuz it might be too much lmao
But essentially that's what you do in class field theory

@timid bronze YOU CAN COME BACK NOW! WE ARE DONE WITH OUR BEAUTIFUL MATH DISSCUSSION!
btw im curious did u study number theory before?
yes, a little bit but yes
the one made for high schoolers
nope
to understand a bit yes

I know sets, coprime
elements
and int rings
...
sorry
I do know modular arithmetic too
It's okay next time don't use chatgpt for mathematics
If you don't understand what I say sometimes just let me know I can explain
Do you really understand isomorphisms
the concept yes
Its just equality if you squint hard enough
ok tell me what you understand
its a structure-preserving translation between two objects
sets with the same number of elements are isomorphic
Have you seen groups before?
quotient groups?
yes?
and take multiplication to be our operation
yes?
yes.
why
I can't contribute meaningfully
But nah, I went to go do something
I realized I was wrong as it doesn't have inverses.
:(
its not a group
that's right it is not
but say you are given one move to make it a group and that move is shrinking your set
yes?
Obviously if you shrink down to 1 element it is a group but that's not interesting
What's the largest set you can shrink Z to in order to make it a group?
can you check for me why is this a group?
first three (closure, associativity, identity) work for all ints with mult operation
and 1 has its inverse that's an int (1) and -1 has its inverse that's an int (-1)
yeah groups are really nice
:)
yeah now we want to classify the symmetries of this thing
you can see that if you draw a line in half
then you can reflect the butterfly
right in the vertical middle
yes?
alright anything else?
nope?
You're 13?
yes?
Damn
anyways
well you can do "nothing"
doing nothing still preserves the shape of this butterfly
I guess so
so it is a valid symmetry
I see
okay great let's use r to denote the reflection symmetry
and 1 to be the "do nothing" symmetry
yes?
so in total we have 2 symmetries right
ur cooked
when i was 10 i lowk was on real analysis
so
like
he gotta lock in
ok buddy
mhmm
right let's put them in a set {1,r}
now observe this: what happens if we do r twice?
you know you take your butterfly and reflect twice
its no longer symettrical
huh
No need to compare my friend
this is just ironic i was nowhere near that
hes very far ahead for 13
okay so say this is the butterfly (left|right)
yes?
Very well then
if you do one reflection what happens
the right is on the left
u just get back to where u are
shut up please
this is confusing to read
is it (right|left) or (left|right)?
left right?
I do...
when you reflect twice it's the same as doing nothing
oohh
yeah the way you write this mathematically is like this: r^2 = 1
oh
I thought it would be something like x = 0 mod 2
mhm...
lol this is also something similar actually we will get to that
okay but here's the gist
in our previous group we had {1,-1}
you verified this was a group and said 1 is the identity
and (-1)^2 = 1
right?
yep
okay now in this new group we made let's call it the "butterfly symmetry group"
we have {1,r}
1 is the identity
and r^2 = 1
right?
yes.
so what we conclude from this
yes
and the set is {r^2, r}?
yeah you can write it like this if you want
I see...
yep?
same as in they have same number of elements
and the way the 2 groups interact are identical
yes.
a fancy term to say they are the same in math is isomorphic
i do a lot
we had 2 different ways to make the same group
this is very neat
geometry and number theory intertwine 🤯
yeah lmao
lol
okay you mentioned mod 2 arithmetic earlier
yes
yes
okay let's look at this under addition
basically i want to say that we can just take the elements {0,1} in this group
mmhmm
since anything will just collapse to these two numbers modulo 2
yep
okay great
what is the identity here?
it's either 0 or 1 so you have a 50/50 chance lmao
0?
a+0 =a
to what?
just add 1+1 and take mod 2
its 0
:)
2 elements and one of the elements goes back to identity when you do it twice
so this group is also isomorphic to the other two groups we discussed
one equation is a regular one, one is from mod arithmetic, and one is a representation of geometry
what college concepts run on isomorphism btw?
@timid bronze i did it
or use it?
that would be abstract algebra
i see
if you are curious I can give you a book to read which I think is somewhat readable
like linear algebra?
yes you also take linear algebra
I may read it soon
do send but

I'll def read this sunday
yeah have fun then

now you
let me teach you about cohomology of arithmetic groups
jk
am scard
i do have a question tho
I was looking at functions that converge on the unit circle, like $\sum_{n=0}^{\infty}{z^{q^n}}:q\in\mathbb{Z}^{\geq2}$
Yeatte
and I saw a few symmetries in it, but I was wondering, for a function f(z), with certain 'nice' properties, I was wondering if instead of going from f(z) -> symmetries(f(z)), If its possible to go the other way? and also if it's a one to one relation
idk what you are trying to say here
Good one
https://www.shadertoy.com/view/tltcWf
^here's one that converges.
so you are basically looking at lacunary functions
like, If I have a group (probably a certain kind of group ig given that i have the restriction of complex numbers), can I always be able to find a function f over the complex numbers where that has those symmetries? like with the sum above, f(ze^(2ipi/(q-1))e^(-2ipi/(q-1)) = f(z) as a symmetry, and f(z^)^ = f(z) as another
okay okay
so given a g in G you are interested in functions f(g.x) = f(x)?
g.x here is the group action on your set
ye
right then I have a lot to say about this

let's start with easy examples
You can view the cosine function as an example of this
Do you see how?
you can do better than translations but you are on the right track yeah
cos(x)=cos(-x)
yeah there is also this guy yup
let's work with R for now
ok
I think complex conjugation doesnt work
okay let's use T for translation
and S for reflection
So we have these actions on R: Tx = x+2pi and Sx = -x
so far so good?
yep
yep
and STS = ?
yup
-((-x)+2pi) = x- 2pi
yeah exactly
So this group G is generated by two elements S and T such that it satisfies the properties we discussed above
this G has a name and it's called the infinite dihedral group for obvious reasons if you've seen dihedral groups before
yeah the infinite guy naturally gives you the sinusoidal functions
you can see that one of the sinusoidal functions is invariant on the whole group
but one of them is only invariant under translations
only one of the dihedral groups?
the infinite one?
yes we are still talking about the dihedral group
notice that cosine is even right
yep
so cos(Sx) = cos(x)
and obviously it is invariant under translation
that's the whole thing
meanwhile sine is odd
it's very common to attach a factor in front of the resultant for these cases
Like sine gives you a minus sign whenever you do S right
yep
cox(x) = x
so this motivates you to cook up a character chi: G -> {1,-1}
where it outputs 1 for T and -1 otherwise
Then your sine function will look like sin(g.x) = chi(g) sin(x)
cool right
ye
yeah this POV gives you more meaning for these things
why are people so smart
I find it really fascinating
I rmemeber needed an outside thing for the lacunary thing as well 
yeah there we go lmao
we can cook up a fundamental domain for these functions
you already know [0,2pi] works for translations
but in this case we need to shrink it a bit
what would that be
I haven't heard of a fundamental domain, what is it?
is that like a minimal one or smthn?
Analysts regularly exploit symmetry to study and break down functions
Fourier analysis is basically that
do you know what is an orbit?
no
intuitively yeah it's a minimal set where anything else is generated by just applying elements of G to the set
oh I think i heard of that idea then
just like how with translations the fundamental domain is [0,2pi]
anything will just be a copy of this guy

h
if I combine the S and the T, I feel like i can shrink the fundy domain quite a bit
[0,pi/2]?
I’m fr
My parents’ relationship has gone to shit
All my mom can talk about rn is a divorce
And she has nothing good to say about my dad
Take an F in X. F is a fundamental domain if it satisfies these two properties:
- for all x in X, there exists a g in G s.t g.x is in F
- If x_1,x_2 are in the interior of F and g.x_1 = x_2 for some g in G then x_1 = x_2
That is very sad

all right, makes sense ye
hold up
interior of F
i see why making interior of F distinction is necessary now
ye it doesn cover the pi/2 to 3pi/2 part
I would need the cos(x+pi) = -cos(x) thing to do that, which we didn't list as our syms
then should we change the translation thing to this and have another chi for it?
yeah if you take 3pi/4 i think then it doesnt quite work
if you want to make it [0,pi/2]?
yeah
yeah you'd need to change how you set your symmetries
you can take T to be x->x+1
but then you have to add some constants to make stuff work nicely right
yeah
but yeah it doesn't matter what you take it is going to be the dihedral group again
yep
Maybe as a fun exercise think about other examples with different groups
Maybe try the cyclic group with n elements or the normal dihedral group
see what you get


I feel like z^k would be nice
(ze^(2ipi/k))^k = z^k when k = 1,2,3...
compelx nums tho, stretching can work
(az)^k a^(-k) = z^k
a fundamental domain for that, when allowing stuff outside f(z), feels like there isn't one?
if we don't, then z^2 would be the normal dihedral group then i think
as for cyclic, just z^k = f(z) then (over the ocmplex numbers)
whose fundamental domain would be an infinite pizza slice from r = 0 to inf and theta from 0 to 2pi/k then? 

,, a^{x\partial_x}f(x) = f(ax) \ a^{x\partial_x -k}(x^k) = a^{-k}(ax)^k = a^{-k+k}x^k = x^k
Yeatte

$T(f)(x) = f(x)$ where T is symmstery vs $ f(g.x) = p(g)f(x)$ such that g is symmetry 
Yeatte
Maths
So, the derivative uses a modification of the mean value theorum.
ye
So, did you figure out the disc thing?
me trying to remember what the disc thing is...
Lacunary functions?
ah those, im still thinking about them, the thing in #math-discussion seems to be tantentially related
I'm still working on these sign transforms. I've been working out derivatives. Which I losted the formula for and am finding it again.
I found it though, yay//
I think thats wrong
i think add 1 after
So then it's (4(2+1))/2) +1 ?
You dont need the extra paranthesis but yes
Right, I add them just to simplify it
U made ur account dec25th 2025
yes?
I chat frequently here, I'm not an advertiser
I'll just delete the post if you want
Yea ion think u can sell stuff here. But if u deleted it it's fine.
it's just funny cuz of the ram epidemic
Lol is there rlly
anyways gn
Alr man gn
too less seasoning
u cray 🤣
CHROMAKOPIA
true
i only learned it for normed vector spaces but i guess you can weaken the condition and the proof holds yeah

Ah, the Hanna-Barbera theorem
topological vector space mfs coming up with 45 adjectives for their spaces instead of just studying banach spaces like normal people
LMAO
Monkeys can regularly beat humans at certain tests requiring intelligence
Like memorization
You may think they are funny but they merely evolved in a different direction
who is making these
why dont they just start naming their spaces by the axioms themselves
like T_n spaces
i dont think T_n spaces are a good example of naming scheme
Apes
Yeah, point set topology is one of my favourite branches of mathematics, but this stuff is just deranged:
The worst part is that according to this, the Arens-Fort space is a perfectly normal topological space
The T_something ones are all Hausdorff, but I only know this when I've taught point set topology recently
Well, the T_0 and T_1 ones aren't Hausdorff, but you know what I mean
I wonder who even studies T_0 spaces specifically? The T_1 class at least has the Zariski topology as a representative that's actually used.
Yep, T_0 is "given any two points, one of them has a neigbhorhood not containng the other" (but you don't necessarily know which one).
T_1 is "given any two points, each of them has a neighbhorhood not containing the other", and is equivalent to singletons being closed
I love these so much haha
T_2/Hausdorff is "any two distinct points have disjoint neigborhoods" and is the only separation property worth remembering unless you're some kind of sicko
(and yes, I am some kind of sicko)
apparently the zariski topology on the spectrum of a ring is often not T_1
specifically when not every prime ideal is maximal
I hadn't gotten far enough in alg or diff top yet to see but is there any areas where knowing a particular space has those properties is important? I mean my goals are knots and associates surgeries but I don't remember seeing anything regarding them in the texts Ive been digging in and out of and I've always wondered that
in Spec R a point is closed iff the prime is maximal most primes aren’t so their closures contain larger primes singletons fail to be closed hence the Zariski topology is typically not T_1
I don't know much about algebraic or difftop, but I can't imagine separation issues coming up there very often.
I kinda felt that way too. Ok
most of them don't come up very often anywhere, other than Hausdorff.
You usually don’t see it because manifolds and knots in them are Hausdorff by assumption It only starts to matter when you study moduli or character spaces where non T_1 behavior actually carries information
i got sniped
honourable for a reason
Ah gotcha. I was wondering why there was a reason for those types of classifications. That was before I realized that topology permeates so many other areas of math lol
Yeah, other than Hausdorff (without which you have all sorts of very pathological unintuitive behaviour), the next big thing is metrizability, but that's often not something you can have.
So the other separation axioms are sort of intended to give you a substitute for the kind of things you'd easily get out of metrizability.
(the Urysohn Lemma being a big example)
So that basically means they come up in niche situations suited to a particular kind of spaces studied in a particular kind of area (and topological methods come up in a lot of areas)
the next big thing after Hausdorff is normality/T4 id say
Fair
indeed
I guess it's not surprising that at some point it would emerge from anything in number theory... Not that I know much about it.
Then I read how generating functions can be used to construct a topological space. But then I guess that's more algebraic anyway.
-sigh-
It reminds me a little of this talk I went to years ago by one of my old profs, I forget wtf she was doin maybe I can find the paper. But she used some sort of stacking technique with higher dimensional structures to also create manifolds. Her jam was fibrations (omg phone stop). There's so much topology to learn ._.
mfw closure of {0} is the entire space

Now that I think about it, feels like the type of manifolds she was carving out was something similar to the grassmannian
... The more I think about it, the more that .makes sense...
Ugh y I doin this early in the morning. I want pancakes
interesting
Yeah it was nuts it's like she took slices or something from a number of hypercubes and when she stacked them a particular way it created some sort of manifold structure. I could be very wrong tho, this was back in like 2912
2012 LOL
I'm so cooked
I don’t see enough seasoning
@solar hawk You’re allergic to all of this
@jagged forge Am I right
I like the cucumbers or serving
Something*
How come there’s no slowmode in discussy 2?
2912 was a great year
Yeah, there definitely should be
6 hours or thereabouts
Not a lot of people talk here
only ally the fish talks here
Only Achilleus bullies people
Also why am I a FISH
Are you calling me boring
fish here symbolises a free person
Fish
who can swim through the vast ocean
Crazy work
i'm just being kind
Mhm…
LMAO
Would you eat muffins that had veggies in it
Ewwww noooo
Why
Why would anyone do such a thing
You wouldn’t taste the vegetables
I could just eat one of those
Veggie smoothies Suremark said
But he said it’s as
Ass
I can confirm veggie smoothies are ass
Especially celery ones
Veggies are so good
Idk how kids don’t like them.
i think those are zucchinis
i was talking about meal replacement drinks like soylent
zucchini bread is pretty goated
You need to try homemade zucchini noodles
They’re bomb
zucchini noodles? don’t think i’ve heard of that
actually i feel like that’s something jay would make
zucchini noodles sounds like it shouldnt work but it does
Egg drop soup
IT DOESSS
I have it with pesto
And
Charred cherry tomatoes on top
Like... sauteed?
@sonic field You both should try since it’s a low carb option
i think jay made it before actually now that i read chat logs lol
that looks awesome
Whatever you wanna do. I personally like them a bit charred
So like a tiny bit burnt
i had pad thai with konjac noodles last week but i think the noodles were overcooked cuz they were mushy sadly…


also compelx conjugation