#serious-discussion
1 messages · Page 174 of 1
😔
by azazal and said
yeye
how
:3
like 4 clicks maximum in the level
you mean easy level
yeah
also nice structuring
i respect fellow rectangle haters
:3 tbh
:3
:3
I miss my best friend
no I miss the good old memories
but time flies
we rarely talk now


long
send me a fr
ill accept it later once i finsih daily
i meant on discord
I don't want to bother or anything but does anyone know math? and that he is between 17 and 20 years old? To help me with math please?
Hi, mathcord. I'm a 15 year old currently stusdying in secondary school. However, the math teachers in my school are completely useless and I have learnt nothing from them. Hence, I decided to take my learning to here, this server, in the hopes that someone has the patience to teach me. I believe I have potential and I believe in myself. I am patient, diligent, and willing to learn
why such a specific age range
the fact that you learned nothing from your teachers is not an indication that they are useless
you can take your learning here because you want to accelerate your learning, and this is a good place for that, and also you don't really need a mentor
but not becuase you find your teachers bad and just want a new teacher
I have been having such hard imposter syndrome with my math knowledge. I have bits and chunks of knowledge from linear algebra, multivariate calculus, and basic analysis and I constantly am learning more and I know that is what matters but I struggle to keep motivation sometimes.
Probably not the best time or place but I wanted to put it somewhere
And regarding the age that I say, I'm new to socializing, I'm not so good that let's say that's why an environment that they have an age like that? Could it be comfortable?
I'm 17 years old
Thank god I am 13 years and 1 minute old
ermmmmmm you’ve been on discord illegally
or they're lying on the internet, tough call
i’m joking
because I found it funny
😮
When she
Hi guys! I have a question. What do you think is better in terms of job prospects, a double major in math and stats or a masters in applied math?
Masters
Employers don’t necessarily care what its in all the time
For the most part math wont give any more jobs then a stats major would give
And a masters is just another cert that employers would like to see
Keep this a secret 🤫
if convenient can someone tldr the proof that sqrt(2) is irrational
got it
basically
2=a^2/b^2
2b^2=a^2 so a^2 is even so a is even
2a^2=b^2 so b^2 is even so b is even
sqrt(2)=a/b in the simplest form, yet they are not coprime so contradiction
not true
2=a^2/b^2 does not imply that 2a^2=b^2
let a/b be rational in the simplest form. does this mean a and b have to be coprime integers
yes
a and b must be coprime otherwise we may find a factor
up to this part the proof is correct, but you can also deduce something about a more than the fact that it's even
a^2 is divisible by 2. a cant be a multiple of sqrt(2). 'a' has to be divisible by 2.
are these right or
if a^2 is even and we know that a must be even
what else can we deduce about a^2
sqrt(2)b=a?
if we multiply an even number by an even number
what else can we deduce about the product besides "it's even"
e1=2x, e2=2y, e1*e2=2x*2y=4xy, e1*e2 is divisible by 4
correct
so a^2 is divisible by 4
now what can we deduce of b^2 with this new information (and hence also b)
b^2 is also even
why?
if a^2=2b^2, and a^2 is divisible by four, then 2b^2 is too, meaning 4n=2b^2, and 2n=b^2, b^2 is even
your notation on "4xy" is a bit strange but i got it
you're saying that if a^2 is divisible by 4 then we have that a^2=4n for some natural number
and then 4n=2b^2 so hence 2n=b^2 and hence b^2 is even
now what happens if b^2 is also even
b^2 is even, hence b^2 =2n. since b is an integer, its not sqrt(2), so b has to be divisible by 2
and hence, a and b are not coprime so we arrive at a contradiction
thank you 🐱 🍞
Hello for the Julia users here what packages do you use for plotting?
I've been using pyplot in the past but I find it quite unreliable and slow at times
Do you just mean Plots?
I would ask in the Julia server, but I think plotting speed depends on the backend
Personally I'm used to Julia not being a plotter
Because of the precompile times
Nah I mean pyplot which calls matplotlib (very slow)
But yea good shout I'll probably go to the julia server
Math Life
Middle School Sad
High School Sadder
College Saddest
Indeed math comes before middle school

Hello, my girlfriend will start her 3th undergraduate year, she is a bit lost if she should go in academia or applicatives math in industry, how can i make her try out applied math to see if she like it ?
there exists things like kaggle, cryptohack, etc... but i wonder if that is appropriate, is there something heavy with differential equation ?
She can look at neural networks
Ok
Ok so kaggle should be a good idea or i'm missing kaggle's topic ?
Kaggle gives you datasets to train models on them
Kaggle also has very good tutorials
Order some books
why jump straight into that
If there is will there is a way
i am interested in set theory aswell sir
how is that relevant to my question
order theory is too niche of a subject to be focusing on if you haven't learned any of the main subjects yet
I just wanted to understand Zorn lemma that I saw in elementary set theory book but I dont know what a poset or a chain is
it's also mostly just covered in book as needed from what ive seen
then read this book...
so did you just jump to the part about zorn’s lemma or did you read everything before it?
be careful with your wording 😭😭
id say its unfair to call it merely “context” when it defines everything needed to understand the statement of zorn’s
thats what those pages before zorn’s are for
I thought you were taking calculus
precalc is ezpz if you used calc 
there is cofinality, topology section but idt its related to zorn
is cofinality unskippable btw?
i’m bad at it it’s hard for me
I need to put more effort
i would say dont skip any section
Are you studying set theory 
I thought set theory is the basics for proof writing and logic
I don't think cofinality is needed to understand Zorn, but it comes up in set theory a lot
not a whole book worth no
The proofs and logic part of set theory is small
Just basic constructions like ordered pairs, Cartesian product, disjoint unions, etc
And construction of some number systems
is cardinality of infinite well ordered sets essential?
alephs
what would be the pre reqs for set theory
nothing
When I'm doing complex algebra and the number looks a little too random 
5 is not a prime
for set theory yes
how does the cardinality of real nums compare to integers and naturals, what is continuum hypo
cardinality of real nums is greater than cardinality of integers, which is equal to cardinality of naturals
continuum hypo states that there is no set whose cardinality is between that of integers and reals
What is time?
Every moment of it is moving but what is moving exactly?
If we were to quantify time, then where is time?
If time is relative, then if motion is relative, then we are all looking at things from our relative perspective
So how can we determine that what we see is the same as the others?
Why is there time?
very random philosophical questions lol
Like shouldn't our world be static? Where is this continuous pushing of motion happening?
you don't see what others are seeing
I'm doing the pushing

how to calculate cardinality of a R and Z
The continuous pushing of motion is happening on a very small scale and then being amplified by causality to a large scale
I think the better word for it is
Why are movements in constant motion at all, why fundamentally?
But why does the minute motiom happen in the first place?
Not all movements are in constant motion
Relative or irrelative they are in motion to something
idk why forces cause things to move but it seems like the presence of forces cause things to move around
Lmao

but even if theres no force and everything remains motionless
will time still exist?
So what is time?
or if time still has any purpose?
Calculate?
you can compare them
Hello where u from
you can prove that the cardinality of Z is the smallest infinite cardinality
i am peruvian , wbu
but cardinality of naturals is smaller though
naturals is same cardinality as Z actually
0,1,-1,2,-2,3,-3,...
this is bijection between set of naturals and integers
0 -> 0
1 -> 1
2 -> -1
3 -> 2
4 -> -2
5 -> 3
6 -> -3
....
sure
to clarify: all "same cardinality" means is "there exists a bijection"
we can assign natural numbers to integers in a way that each natural number gets mapped to unique integer
more specifically, if there is an injection from A to B, that means |B| ≥ |A|
one to one correspondance or something
yep
by a theorem of cantor and the axiom of choice, this is equivalent to there being a surjection from B to A
cantor theo?
It's called the cantor Schroeder Bernstein theorem
oh, i know it just under the name schroeder bernstein
cantor first published it but without proof
mathematicians worked different back then frfr
what about rational p/q numbers (Q)
same cardinality as ℕ and ℤ
(one to one)
its a "zigzag" method
first note that there is a bijection between ℕ and ℤ²
by just "spiraling" around the coordinate plane
wdym
there is some fancy letter c that stands for the cardinality of R
now we imagine this bijection, but instead of being from n to a point (a, b)
it's from n to a/b
but we "skip duplicates"
for example, the points (1, 1) and (2, 2) correspond to the same rational
1/1 and 2/2
so we would just "skip" 2/2 in our bijection
similar for, say, (1, 2) and (2, 4)
why spiral
why not
you could make it different, but spiral works well for the purpose of demonstration
is cardinality of complex numbers same as real
yes
yes
in general, cardinality of A is same as cardinality of A^n for infinite sets A
more generally, any sets of bounded-length lists of elements from the same infinite set will have the same cardinality
complex numbers are just finite lists of real numbers
since they all have the form a + bi
speciifcally, theyre lists of size 2
(a, b) -> a + bi is the obvious bijection between R^2 and C
this is a very important fact for theoretical computer science, among other things
a moment, is cantor theorem same as schroders bernstein theo
Cantor's Theorem is a different thing.
Cantor's theorem is uncountability of the reals
i said "a theorem of cantor" earlier referring to cantor-schroeder-bernstein
not cantor's theorem
or more generally |P(A)| > |A|
P(a)?
power set, i.e. set of all subsets
ahh
Time is just an illusion. If we can cause a chemical reaction to react faster then does that mean time has gone faster from their perspective? Why do we feel like so much time has passed when we sleep but in reality, it is just one hour? Does that mean the brain perceives time differently so everyone perceives time differently? If you are alone in the universe with nothing except darkness then how do you know you are in motion, how do you know what time is it? There is nothing like a system clock in the universe so how do we know exactly how much time has passed? Time is invented by humans to make things easier!!!
@zinc dock i finished up my (horribly inefficient) python code, and it seems to corroborate my hypothesis that you only get powers of 2
i think it wouldnt be hard to prove even
ig the nice thing is that its very easy to adapt the code to only allow for two term sums
although i think for that specific case theres probably a better implementation

Huh
Interesting
What happens if you limit it to only two?
Yes
But time is but a creation of us in this constant progression in linear motion, so why do we have this linear motion to begin with?
Or if you look at things from a 3D down to a 2D perspective, and you imagine a room with infinite many of them from different times, what keeps them transitioning from one room to the room after that? In essence, why are we experiencing linear progression, where has "time" gone?
ill fix the code for that and lyk
Neat
What is that constant progression in linear motion
2, 3, 4, 8, 9 then all numbers >= 11
which is quick to prove
show that 11, 12, 13 an in by hand
then we can show by strong induction that all n >= 14 are in
n-2 and n-3 are both in so n = (n-2) + 2 = (n-3) + 3 and so n is in
perhaps something interesting happens if instead of not having a unique sum you just say no sum ?
Maybe
shall i try that with two term sums or any length do you think ?
i can do both but which first
Well you keep progressing forward in in what we call time in a linear direction
so where does this progression come from?
Uhh
Which would be easier to adapt the original code from?
both super easy
I guess from things where we reference time to that is things that have about constant rate of change
It is because of chemical reactions, life is a chemical reaction, thought is a chemical reaction, light is a chemical reaction, and photosynthesis is a chemical reaction.... If chemical reactions stop then time will stop as well
ok two terms is a bit more erratic, but still looks kinda regular
For example, clock and celestial bodies
2, 3, 4, 8, 9, 14, 15, 20, 21, 26, 27, 32, 33, 38, 39, 44, 45, 50, 51, 56, 57, 62, 63, 68, 69, 74, 75, 80, 81, 86, 87, 92, 93, 98, 99, 104, 105, 110, 111, 116, 117, 122, 123, 128, 129, 134, 135, 140, 141, 146, 147, 152, 153, 158, 159, 164, 165, 170, 171, 176, 177, 182, 183, 188, 189, 194, 195, 200, 201, 206, 207, 212, 213, 218, 219, 224, 225, 230, 231, 236, 237, 242, 243, 248, 249, 254, 255, 260, 261, 266, 267, 272, 273, 278, 279, 284, 285, 290, 291, 296
@zinc dock
It is
Weirdly enough without the '4' term
[2, 3, 4, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 2, 3, 8, 9, 14, 15, 20, 21, 26]
ah yeah
So anything with observable change
I dont know enough modular arithmetic techniques to wager why this would be the case but its interesting nonetheless
Yeah, if nothing changes then time doesn't exist
https://oeis.org/A244151/list limiting it to only two terms is also pretty interesting
O lmao
i was kind of hoping for something more chaotic haha
alas
was fun to do some coding
Looking on the pattern database, adding 1 to the list of allowed numbers is definitely a bit more chaotic https://oeis.org/A033627
Makes me want to find the overlap between the normal primes and this set
these are all the numbers 1 mod 3
besides 2
if you look each term to the next is +3
In my defense i just woke up 
happens to the best of us
That's unfortunate
Figured I could find a non-terminating parallel to the normal primes
maybe looking at k-terms is more interesting
like k=3 maybe
[1, 2, 3, 4, 5, 13, 14, 15, 25, 26, 27, 37, 38, 48, 49, 50, 60, 61, 71, 72, 73, 83, 84, 94, 95, 96, 106, 107, 117, 118, 119, 129, 130, 140, 141, 142, 152, 153, 163, 164, 165, 175, 176, 186, 187, 188, 198, 199, 209, 210, 211, 221, 222, 232, 233, 234, 244, 245, 255, 256, 257, 267, 268, 278, 279, 280, 290, 291, 301, 302, 303, 313, 314, 324, 325, 326, 336, 337, 347, 348, 349, 359, 360, 370, 371, 372, 382, 383, 393, 394, 395, 405, 406, 416, 417, 418, 428, 429, 439, 440]
i believe this should be right for 3 term sums
whatcha playing with
even weirder it repeats mod 23
#math-discussion message original inspiration
https://oeis.org/A033627 basically this
the terms i just posted are for sum of three terms instead of two tho
interesting, they show that it has a nice generating function for k=2, does the k=3 have a nice form? Can we write down the GF for k in general?
So this converges to the integer powers of two as k → ∞?
Ohh you mean specifically k terms
yh
That's actually pretty interesting
This gives me an interesting (albeit a bit more complicated) idea
That being to see what numbers are invariant on k
As in like
Given P_k = the set of additive primes derived via k terms, determining the set S where each element in S is also an element of P_k for all natural numbers k
(P_1 is just ℕ)
that's neat, can we change the rule some how so it's only powers of 3 or something analogous, since it sort of looks like the unique base 2 representation is what's causing it, so might have to be modified slightly like powers of 3 times 1 or 2 maybe
is discrete math hard
it seems like changing the starting values might be able to achieve this
if i start with [1, 5] in the set then i get two a(n+1) = 3a(n) + 2 and b(n+1) = 3b(n) - 2 in the set with a(1) = 9 and b(1) = 11
which is kinda 3^n
i would suspect just 1
but obv thats a total guess
Actually
Wait nvm
I was gonna say "you can't represent the k+1th term in P_k" but that would make it an element of P_k
So it's at least 1 and 2
All numbers less than or equal to k are automatically in P_k by default as well
This feels like a number theory problem (knows absolutely no number theory)
3 is also in the set if we're not starting from 1
feels too closely related to goldbach, probably not easily doable
Really?
I mean it's involving "primes" but they seem relatively unrelated to normal primes
I don't know what you're doing tbh
like set of primes that isn't a sum of previous primes in the set?
the set Sn contains 1, ..., n
the set Sn contains any number not expressible as the sum of n distinct elements of Sn
Okay so
We define a set P_k to be the set of all natural numbers greater than one which cannot be created by summing k distinct elements of P_k
We're figuring out if any numbers are common elements of P_k for all natural numbers k
i think its easy to prove that its just 1,2,3
the definition sounds too circular to me
its a recursive definition yes
It makes more sense if you think about it iteratively
here's how its stated on oeis for 3 term sum
a(n) = least positive integer > a(n-1) and not of the form a(i) + a(j) + a(k) for 1 <= i < j < k <= n.
and for 2 term sum
0-additive sequence: not the sum of any previous pair.
I'm not sure this uniquely defines P_k though
howso?
like there may be multiple self consistent definitions that satisfy that definition
i think the 'least positive' part seen the 3 term def resolves that
P_2 is empty and we start at n = 2
2 cannot be summed from two elements nothing, thus 2 ∈ P_2
3 also can't be summed from two elements of P_2 since two elements don't exist, therefore 3 ∈ P_2
2 + 3 ≠ 4, therefore 4 ∈ P_2
But 5 is able to be summed from two numbers in P_2, that being 2 and 3
Therefore it is not an element of P_2
And so on
how do you know it can't be done with a set of naturals excluding 2
doesn't smell right to me
How do you know that this defines a unique set: "a set P_k to be the set of all natural numbers greater than one which cannot be created by summing k distinct elements of P_k"
by def start with 1, ...,n in the set
if you start with the empty set then the least positive integer that is not the sum of n distinct terms in the set is 1
then 2 then ... up to n because until you have 1,...,n in the set you do not have n distinct terms
the least positive part is key
that's a different definition
anyhow k+1 is not in Pk for any k>=2 because 1 and k are by def in Pk
therefore union Pk, k=1 to inf is {1,2}
I dont think i know enough math to equivocate the two definitions
to answer you question about persisting values
But numerically they seem to give identical results
Huh
oh wait lol brain fart moment
you're assuming more than you've originally defined, you don't necessarily need to construct your set iteratively in the way you have
well I'm not trying to get on your case here I just didn't know what you were doing at all and still not sure I do lol
Fair enough
reading back, I guess I was thinking you were talking about prime numbers but you aren't really just calling elements of these sets as "prime" right?
I was calling these "additive primes" because their definition is kinda like normal primes if you squint
oh ok, I thought you were adding literal primes to the set if they weren't a sum of primes
I think I'm on the same page now lol
Lol
Because with normal primes they're in the set of primes (we'll just call N because P is taken i guess) iff they cannot be represented as a product of at least two elements of N
Doing "at least two elements" for adding instead of "specifically k elements" just gives you the powers of two but this seemed more interesting
Pk contains 1, ..., k(k+1)/2 - 1
let X = union Pk, k = 2 to inf
1, 2 in X
know that for all k >= k' where k'(k'+1)/2 - 1 >= n, n in Pk
so want to know when n > k(k+1)/2 - 1
0 > k^2 + k - 2n - 2
(-1 + sqrt(9 + 8n))/2 > k
so n in X iff for all 2 <= k < (-1 + sqrt(9 + 8n))/2, n in Pk
👀👀
we know that Pk has 1, ..., k(k+1)/2 - 1 becuase the smallest k-sum of elements in Pk is 1 + 2 + ... + k = k(k+1)/2
so all numbers less than that must also be in Pk
to show that X is just {1, 2} we want to show that
for all n
exists k with 2 <= k < (-1 + sqrt(9 + 8n))/2
where n = a1 + ... + ak some 1 <= ai <= k(k+1)/2 - 1 and ai = aj iff i = j
it feels like that MUST be true
some kind of strong induction
but seems messy
I think we can do it, working on it
Surely you'd just have to prove that for some m, k+m is not an element of P_k
Because that would imply that no number greater than or equal to m is in the final set
And you could just individually do the rest
i dont follow
I guess if it's gonna be easy for you to prove then we might as well generalize to something like whatever works $$\bigcup_{k\ge n}P_k = {1,2,\dots,\frac{n(n+1)}{2}-1}$$
Mero
something like that
do you mean intersection ?
If n is not an element of P_k for any k then n is by definition not in X
and if k+m is not an element of P_k then we can substitute k+1 into k
Thus m+1 is also not in X
still not getting it
yeah
I think I see a way to do it
no nevermind lmao
k + m is not in P_k for all k ⇒ (k+1) + m is not in P_(k+1) for all k
x is not in P_k for some value of k ⇒ x is not in X by definition
By induction
k + m is not in P_k for all k ⇒ (k+n) + m is not in P_(k+n) for all k
Thus
k + m is not in P_k for all k ⇒ m + n is not in X for n = 0, 1, 2, ...
I think
there is no m such that k + m is not in Pk for all k
eventaully k + m < k(k+1)/2
and then k + m in Pk
Oh true
probably obvious fact, the only triangular number that can be in the set is 1 since P_k doesn't contain k(k+1)/2
Define $a_i^k = i$ for $1 \le i \le k$ \ \
For $n \ge k$ define $$S_k^n = \left{ \sum_{j=1}^k a_{i_j}^k , \mid , 1 \le i_1 < i_2 < \dots < i_k \le n \right}$$
this is the set of all $k$-sums of the first $n$ terms of the sequence \ \
For $n > k$ define $a_{n+1}^k = \mathrm{min} \left{ \mathbb{N} \setminus S_k^n \cap \left(a_n^k, \infty\right)\right}$. In words this is 'the minimum integer that is not a $k$-sum of the first $n$ terms of $\left(a_i\right)$ that is greater than the $n$-th term'. \ \
Define $P_k = \left{a_i^k , \mid , i \in \mathbb{N}\right}$ and $X_n = \bigcap_{k \ge n} P_k$
can we write a formula for the next element in P_k after k(k+1)/2 -1
i think probably
it would be nice, then we could try to say for some n, it lies in one of those "windows"
This is a lot cleaner than i thought this would be
between k(k+1)/2-1 and the next element
or at least, that's the approach I'm thinking of trying
i think it might be k(k+1)(k-1)/2 + 1
for k=3 it's 13 does that work
yes
nice
works for k=4 too
here was my thinking
we have 1, ..., k(k+1)/2 -1 in the set
if we think of starting a1, ..., ak as 1, ..., k we know we get k(k+1)/2
we can move ak up one at a time through to k(k+1)/2 - 1
and because we move ak by 1 each time we will not miss any numbers
then we can move a(k-1) up to k(k+1)/2 - 2
and so on until we get to a1 at k(k+1)/2 - k
and so we have found sums all the way up to k(k+1)/2 - k + k(k+1)/2 - (k-1) + ... + k(k+1)/2 - 1
and that is the maximum sum we can achieve with numbers available
so the number after that must be in the set
and that sum evaluates to (k-1)k(k+1)/2
My pattern recognition is telling me we should be putting this in terms of permutations
Like this is 3 × (k+1 choose 3) + 1
sounds reasonable, cool
Seems similar to the binomial distribution kinda
ohh hmm
k(k+1)/2 is just k+1 choose 2
We're dealing with combinations of numbers in a way so it seems relevant partially at least
at this point I think we just need to say for f(k) = k(k+1)/2 - 1 and g(k) = k(k+1)(k-1)/2 + 1 that we need to show g(k)-f(k+1) is positive and that will show that the lower bound of the k+1 "window" overlaps with the upper bound of the kth window.
so we get coverage for all n
since g is cubic, it's a finite check
we know it eventually overtakes the quadratic
Hmm
Swapping k for x, wouldn't it only be less than zero when 0.47068 < x < 2.34292 or x < -1.8136?
Thus for all integers k > 2 it must be positive
yeah
hello
we need the gap to be larger than 1 after a certain point which is the finite check I mentioned
since that ensures we're really grabbing integers, we only care about it after 2
but I think this generalizes to the other case I mentioned earlier too
Yea
if exists k s.t. k(k+1)/2 <= n <= (k-1)k(k+1)/2 then n is not in Pk and thus not in X
certainly exists k st k(k+1)/2 <= n < (k+1)(k+2)/2 and (k-1)k(k+1)/2 >= (k+1)(k+2)/2 for all k >= 3
so we need to check 3 <= n < 6 i.e. n = 3, 4, 5
3 is not in P2, 5 is not in P2
4 is in X
X = {1,2,4}
and yeah i think this result also shows your generalisation
nice stuff !
might write this up more formally quite a fun series of results
I think this is a cool idea, maybe we can push further with stars and bars slightly modified so that we can list more distinct elements
also kinda reminds me of the chicken mcnugget theorem
oh yeah
I have never heard of that theorem but that sounds beautiful
do you have any particular thoughts or just spitballing
I'm thinking to force the distinctness we can subtract 1, 2, ... from each set of "stars" between the "bars"
past that just spitballing
I don't think that's sufficient to get it to work either except for special cases
Weird thought
Probably unrelated but the sum over all k of n choose k is 2ⁿ and yet that original sequence before we last modified it included all the powers of two (and the number three)
i think it only had three because i started with [2,3]
if you start with [1,2] then it would just be powers of 2

1 + 2 = 3 and is the biggest sum you can do so then 4 is in
Yea
if you think about binary any these are 001, 010 and 100
so if you all any length sums you can get all binary number that are 3 digits
then the next number you cannot get is 1000 which is 8
and so on
Yea
Any number with more than one 1 in it could only be gotten by addition, so they're excluded
Everything else can't be
these are when you allow sums of length at most h
and you can see with each increase you approach the sequence of powers of 2
who is Eliza
who is apoplecyappendix
isnt that your friend or something
what lol
thats weird
identity theft
perhaps
no but seriously
is this like
real
why would someone evem do that
if you dont know them
whats the point
maybe it’s someone u know trolling
very suspicious
her pronouns are she/her so im guessing its a woman
they didnt bother having the same pronouns as you
if they were trying to copy your account
again most likely someone you know pulling your leg
In certain places I’ve heard a lot of stereotypes associated with like category theory/type theory/functional programming people being trans. Does anyone know where these stereotypes came from?
@neat lintel weird, i had u in my dream for the 1st time ever in my life
Oh
Me too like about 15min ago
Wow
I kinda forgot the details but u were trying to avoid to pay
I see
It's like magic no one notices you
And u were in the back part of the train
And as the dream goes on, we were now on a bus instead of a train
I see
And when the conductor came I paid my fare and finally he started to notice you but you still can't pay I forgot why so I just paid for you. My payment was a whole bill and he hadn't given the change yet so he charged both of us for it
Oh
Hey I know this isn’t math related but can someone help me solve a Highschool level chem question in DMs?
Just spill the question
Right here
I sent it in chill cuz I can’t send images in here
Oh an image
I gotta do verification and shi not dealing with that
What's the test about
Maths
I hope one of the questions will be like: in a 50 question test with 5 options, the chance that one option appears 5 times in a row is....
that's why I never have mcq question on my exam or if I were to give one, it will be either 30 choices or just 5 choice but 1 question.
what would be a classic example of proving something by PHP? is social network a clear example or is there an essier one
(every user needs to he friends at least with someone I think)
Not "classic" but fun problem:
Consider a size pq+1 poset. There is a size p+1 chain or a size q+1 antichain.
||Apply PHP on the function that sends x to the length of the longest chain starting at x||
this was what I meant btw
Lol this white cat going out of hands
what you think is harder:
quals problems or IMO problems?
IMO IMO qual as harder than quals
are you sure?
is anyone here taking/taken RA courses?
why not ask the question directly
my questions are more the progress of the person when he took that class, I'm having a hard as a freshman and I wanted to ask others what was their progress like with assignments and such
it's not a 1 liner
Ask it anyways. Lots of people here have taken or are taking RA courses, but none of them can answer any questions or address any concerns you might have because none of us know what your question/concern is.
write it and copy paste it each time someone ask you what ur question is
eventually you would need to write it
Anyone have an opinion on Zorich's analysis I & II?
I've been looking for a thorough & rigorous RA book. There are many, but life is brief 🙂
Idk if rigurous but I personally like The big book of real analysis, I have checked zorich but only slightly, I havent taken ra yet formally so I can’t say
Seems nice, thanks for sharing
it's a standard analysis text in eastern europe
it's not the toughest of the books, but should feature everything you care about in real analysis
I see. What's an example of a tougher book?
well I think Amann and Escher anal I and II is pretty rigurous but idk
the way you abbreviated analysis
you can prolly get more rigorous I guess, havent taken ra yet
just go with zorich
Alright, thanks a bunch!

which book explains hairy ball theorem
It's proved on page 210 here https://mtaylor.web.unc.edu/wp-content/uploads/sites/16915/2018/04/analmv.pdf as a consequence of Stoke's theorem. Any differential geometry book would cover it
UNC?
Like Lee's Intro to Smooth Manifolds
is lees intro a well regarded introductory reference?
I personally think it is very detailed
too detailed for a novice, but I appreciate detail
Taylor's book is too little detail, but it is useful as a guide
kind of like a list of important/cool topics
well i like too much complex anal
thanks a lot! that's a saver
maybe I can't see all of it either
np!
and how is the journal? do you have subscription?
uh
it doesn't really ask me to subscribe
wait
lemme test something
yea, it was my adblocker LOL
i see, i was able to see the article as you sent be at the first time, but then i refresh the web, it disappear
but that's an inspiring article!
wait, nvm
it's a
opening in a pirvate tab does the trick ig
oh... didn't know that
thinking about that time i was in school in the chem lab with a teacher and like 15 other girls (p.e. teacher was absent, most of the boys went up to the library and i wasn't allowed to switch rooms for some reason) and, from what i gathered, the girls were watching disturbing horror movie scenes or something like that?
my reasoning is mostly based off of one girl that bragged about watching jigsaw when she was eight or something like that (and similar comments from her, i forgot what she said tbh)
and its like... what
why is "watching disturbing horror movies" a personality aspect they specifically only show when there aren't boys around
why did the girl watch jigsaw when she was eight 😭
was i even reading the situation correctly????
who bets how many dollars 50 coins of my country value?
ill bet 50 coins of your country it values 50 coins of your country
If the world was ending tomorrow, what would you do today?
Commit minor felonies
Analytic number theory
LADR
if i were not aware i would just do my everyday shit
if I was aware, why tell lmao
wouldnt want the world to end while everyone thinks ur crazy
tell my family I love them
The
reacts
why the reacts
did you know that Michael Rosen Beichton, also known as "Narwhal Knight" used the pointy thing of a narwhal to impale his coworker in the arctic
He was last seen pieced in 10 places, all fatal wounds.
it's a sad answer!
not a bad one, but it makes me feel sad
it didn't have to be sad!
it's worse than "if you were going to die tomorrow"
cause if the world ends everyone dies
bumping this so I can farm more answers...
yeah if the world really were to end tomorrow I would be peaceful to everyone
it would be bad to argue
like a sniper but you load using the bar thing
yeah like humans have done a lot of harm to the planet
too edgy, I know
sorry
if im going down the mosquitos are coming with me
no you have a fair point
Does anyone come to communicate
Where
@north topaz whose fyre
no natural number is equinumerous to a proper subset of itself?
does equinumerousity imply same cardinality?
does it imply injectivity and surjectivity?
I was just looking for a pidgeonhole definition but how are the equivalence relations involved?
someone on another server
I'm sure the book explains what equinumerous means
How hard is the ODE section in Kreyszig Adv Engg Maths, if anyone's done it? I mean, is it mostly plug and chug or harder? Wanna plan how long it might take....
commit major felonies
Commit augmented felonies
Album: 或る街の白昼夢
Composer: Ichiokuen-P/dezzy
Like every single hard drug but mainly DMT
Hmm
Actually i think I trust myself to survive the end of the world, so maybe just a lot of DMT
i would spend time with my family
lmao
i dont think those drug interactions are a smart idea
better to focus on one
||D Medical Therapy||
not at the same time!
also not every single
it would be like
cocaine -> heroin -> dmt i think? thats probably it
heroin last would be smarter
both cocaine and dmt do not last very long
i heard!
You also listen to Kano? 🧐
Kano is love, Kano is life
And maybe you notice what my pfp is
Yeah, I have noticed 😂
Really
I figured dmt would be a long thing
Oh well
pure dmt is about 30 mins maybe
if you mix it with some inhibitor (ayahuasca), it lasts longer
It's not like I know how the world is going to end. Id rather be pretty out of it when it does
MAO inhibitors
its actually quite interesting
you can (often legally!) buy the mimosa plant, which contains dmt
What are your favorite songs?
but you have to consume beta carbolines with it
otherwise the dmt wont enter the bloodstream and thus brain
Thanks loch
though to note buying the plant for dmt is illegal
it has other uses
there was a guy in germany who imported like 20kg of mimosa root monthly
claimed its for "dying shirts"
which is a use
but police got suspicious
he kinda ruined it for everyone
dmt being illegal is literally NO FUN ALLOWED
I guess several world end scenarios begin with police states
Maybe I should be careful
I listen a lot of her songs but to pick one then It is stella-rium
I also like that MV
Which one?
Stella-rium. It has a MV 
Ah, yes, this used to be my banner when I had nitro

kawaii
welcome
my roles here are not fake
also i always get my name is a boy name and pfp
doesn't mean im a boy
so you are a girl
yes
ok so can you help me in maths
what are unit digits
what does that mean
that is what i am asking
you mean a math help?
yes
well i told you where to get help
I'd like to help you but i got meeting in 5 minutes lol

try get a help from #❓how-to-get-help
and show them the full content
ok fine thanks

can you tell me what is unit digit
u know i dont have much time... i got an exam to prepare for
which class are u in?
it is new
u know about digits?
and about places...like unit place tens place or so?
so the digit at unit place is what we call unit digit...its just a short phrase for that
eg in 1234567 the unit digit is 7
in my book this is the question
you hate helping or hate ask for help
no i hate the help channels
u know how to square a number?
yes
but would u like to calulate the square of 4567398293?
ok let me see
why tho you asked for it
see...maths is not just calculation
ok
81
so canu write 81 as 80+1?
i got this method mam told it to us
ok
see u have to argue that why does it happen..feeling dont help in math solid proves and reasoning do
lets write a no. AB where A and B are its digits
ok
now u can write it as A*10 + B
...in python we use * (asterisk for multiply sign)
ok
can u write it as i told?
now u know about variables and algebra?
yes
so i am gonna tell u a identity about square of (a+b+c+d+e+f...and so on)
i mean square of sum of any no. of variables
ok
u know how to do (a+b)? tell me
like
...ok i know i am boring
just lemme tell u straight ahead
(u will learn all this whenu grow up)
br
--> just square the unit digit and report its unit digit
mean what you were telling me was for grown ups
like in 834579794...do square of 4 then u get 16...6 is ur answer
yup...but u could have shown off it to ur friends ands teacher
jsut square the unit digit
6521
for unit digit of square of 81...just square 1...u get 1...tell me the unit digit of this no. that will be one
so 1 is the ans right
yes
...whyd u ask?
cant u see my pronouns?
you can help me in maths
...sorry to say but i dont find enough time to use discord
and i am thinking of leaving discord soon
can i ask u something?
---> U have a gf?
... koi ni... but whenever u get one just take good care of her... maybe she can change u in a way u like... (i am just so happy todya)
bruh
hi
did someone leave you
hi
technically you can have a girlfriend in 8th grade
get one in uni
no point to have one in high school gotta lock in
i don’t recommend it
I advise against it really
just saying technically
😭
same
but if u guys love each other enough u can still make things work
yes
of course
gotta get ur prioties straight
i have... she is my priority
what yr u in
i think i should have joined a philosophy server
me
yes i know u would laugh at me... i am only a high schooler...11th grade
if i were u avoid having a girlfriend from like past yr 7 or 8 u need to lock in
you have 1 year left
then u can do wahtever u want
just work ur ass off now then ur good
i am 8 so this is kinda adult talk so i am leaving thankyou
WHAT
wthhhh
don’t ping mods yet
Are you joking about being 8?
i mean its good uve joined a maths discord at 8 i guess
a gf is not a adult talk
I need the truth; you’re at risk of being banned right now
yup its appreciable
no...he said he is in 8TH grade
not here
could be a typo
You can’t even ban him bruv
soture
i think it is possible but u cant put too much aside for her specifiallyy until high schools done if ur missing like 2 days of work thats a no no always gotta be ahead
true
that’s fair
i wouldnt recomend tho still
@patent bone edit your message so it doesn’t look like you’re actually 8 😭😭
fr
well I somehow manage...and we guys understand each other...
no, i can’t
are you working hard
if so youll be fine
you can manage both
...it seems to me yes
cos i have to work hard... Ihave a purpose in life
and it is her
she is my purpose
and if i cant get to spend my life with her... if i cant feed her... if i cant make her dreams true myself... then there is no purpose of living
i wouldnt look at it like that
and basically this is how i see life as
dont 😵 if she doesnt like u at a certain point u have other purposes aswell
alr mb
how old are you dude 😭
actually i am younger than what it seems...15
but still i have experienced too much of life
funny
and im a year infront of my age
i am immature i know... but sometimes i just cant let things go
i wanna tell her how much i love her
but when i see her... i just forget everything
sometimes i just wanna hug her and cry
have u joined a philosophy server yet ?
no...would u recommend any
what year u in?
10
great
bye*
Reality <—— 2 light years ——> People
Theres never a help channel open.....
There’s 5
What?
Nice pfp
It's not defined though. We don't know what sigma is [\sum_{n=0}^{\infty} \int_1^{\infty} \frac{e^x}{\varsigma(x)} \dd x]
I should also change the d from a $d$ to a $\dd$
Kepe
you need more context
I use the multivariable taylor expansion as my pfp on WhatsApp
I guess that's better


